Find the area of a square with a diagnol 9(square root)2?
554136
Sorry for the look of this, but showing numbers to a power is hard.\n\nUse formula for triange a2 + b2 = c2.  \n(That is a squared plus b squared equals c squared).\n\nSince it is a square a = b  and you already know c=9 so:\n\n 2 * (a squared) = 9 squared * square root 2 squared.\n2 * (a squared) = 81 * 2\ndivide both sides by 2\na squred = 81\na = square root of 81\na = 9\nthe araa of a square is a side squared, so\narea = 9 * 9\narea =81
643955
x=9\n\nx^(3/2) = 27\n squaring both sides\n\nx^3= (27)^2=729\n\nx=729^(1/3)\n\nx=9
700498
Is something missing here? If you just want 4*sqrt(81)\nthe answer is 4*9 = 36
937424
Area = pi r^2\nd Area/ dr = 2 pi r\n\nd Area = 2 pi r dr\n\nGiven d Area = 2 dr,  so substitute to get 2 dr = 2 pi r dr\n\n1 = pi r\n\n1/pi = r
1117258
Area of a square = L * L\n\nArea of A = x * x ..........(1)\nArea of B = y *y  ..........(2)\n  \n y = x -1               ..........(3)\n\nA = 4 * B              ...........(4)\n\nSubstitute (1) & (2) into (4) gives:\n\nx^2 = 4 y^2           ...........(5)\n\nSub. (3) into (5)\n\nx^2 = 4 (x-1) ^2\n\nSolve:\n\nx^2 = 4( x^2 -2x +1)\nx^2 = 4x^2 -8x +4\nOr\n\n3x^2 - 8x +4 =0\n\nSecond order eq.\n\nx1,x2= [+8 +- Sqr(8^2 - 4*3*4)]/(2*3)\n\nx1,x2 = [8+-4]/6\n\nx1 = 2   &  x2 = 4/6\n\nThen\ny1 = 2-1 =1   & y2 = 4/6 -1 = -2/6 ( illogical )\n\nthen\n\nx= 2  and y = 1
53126
area = 1/2 x base x height
870643
roughtly:   2 x (30cm)sqaured = 2 x 900cm2 = 1800cm2
609578
definitely 63 square inches. The formula to find the area of a triangle is A=(1/2) x base x height. That is 0.5 times base times height. So, if you plug in the numbers, you get\n0.5 x 14 x 9 square inches\n(0.5 x 14) x 9 square inches\n(7) x 9 square inches\n63 square inches\n\nMake sure that whenever you look for the area of the triangle, the problem tells you that the numbers are the height and base.\n\nYes, 24 is correct.
868538
the sides are 9 and 12 units long.  Here is the algebra:\narea: a=xy=108\nperimiter:p=2x+2y=42\n                     -2y   -2y\n               =(2x=42-2y)/2\n               =x=(-y+21)\nsubstitute that back into the area formula:\n(-y+21)(y)=108\n0=-y^2+21y-108\nuse the quadratic formulat to get the roots 9,12
860580
just divide the inside by a perfect square (i.e. 4,9,16) and write it like this\n(this is the first problem you have)\nV(3X9) because 3X9=27\ntake the square root of the perfect square and move it to the outside\n3V3\nwhen you already have a number outside the radical, multiply it by the number you just simplified from the inside of the radical\n3V32\n3V(16X2)\n3X4V2\n12V2
774933
if the numbers are both under a radical...divide the numbers...put answer under radical...if perfect square or contain a perfect square... simplify\nsqrt(4)/sqrt(2) = sqrt (4/2) =sqrt 2\nsqrt(36)/sqrt(9) = sqrt(36/9)=sqrt 4 =2
596727
Figure out what other number times itself equals your number.  That's its square root.
664238
x = 9*sqrt3 + sqrt2 = (3^2)+(3^1/2) + sqrt2 = 3^(5/2)+ 2^(1/2)= 17
535346
I'm not sure if this is the whole question, but I will interpret it as if it ended with a ) in place of the [exp...\n\n9(x^3)N - 12(x^4)(N^2) - 9(x^2)N
594683
To find area you multiply the length times the width. It's pretty easy once you know
157873
The diagonal will be equal to the square root of 2 multiplied by the length of a side of the square.
975485
H*W= area\nheight times width\n\none side has a height of 8 and its width is 9 thus the area would be 72