what is the area formula for a rhombus?
542660
Rhombus\n\ns = side length of rhombus\nh = height of rhombus \nd1 = long diagonal of rhombus\nd2 = short diagonal of rhombus \n\nArea = hs\n         = s2 sin A\n         = s2 sin B\n         = (½) d1d2
814915
Area = ½ ab SinC\n Area = ½(55)(29) Sin 61º\n Area = ½(1595) Sin 61º\n Area = 797∙5 Sin 61º\n Area = 797∙5(0∙874 619 707)\n Area = 697∙509 2165\n Area ≈ 697∙51 square units.
404470
a) AX = 2.25 cm.\n\nb) area AXY upon area ABC = 0.5625\n\nc) area AXY upon area trapezium XYCB = 0.4375
457596
Surface area:\nCylinder(lateral):2 times pie times radius times height\ncylinder(total): 2 times pie times radiuse times height + 2 times pie radius squared\nTriangular prism(total): find the area of every side and add all together to get surface area(hint:area of a triangle=1/2bh or bh/2)\nCone(lateral):pie times radius times length\nCone(total):pie times radius times length + pie squared\npyramid(total):find area of ever side and add all together \narea of a triangle=1/2bh bottom of the pyramid is length times width
826650
area =\n\nx^2 + 2x\n\ncost ($) =\n \n( x^2 + 2x ) * 20\n\n_
332600
to find areas of parallelograms use the formula: \n\nA = base×height.
952353
The curved surface area is 2*pi*r*h\n\nor 2*3.142*27*12 sq cms\n\nand 2*3.142*17*35 sq mms\n\nyou can do the rest
272748
Okay I will prove it.\n   there are 2 extreme cases of kite:\n  (i)when both sides become equal:\n      then it becomes a rhombus and area is .5*d1*d2\n  (ii) when one side is zero :\n      then it becomes a triangle and its area 1/2*b*h\nsatisfies the formula for kite (try drawing it)\n   Now the variation of area with the diff of sides is a smooth function must have a formula that satisfies both extremes. 1/2d1d2 satisfies the condition.\n   Assume that there is one more function satisfying the given criteria.It must have same value at all pts since area  \nis a unique entity.2 functions have the same graph and hence they must be identical.This proves that no other answer exists.
513696
The area equation of a circle is pi r^2. And, a circle has an arc measure of 360. Since the shaded region has that of 40, it would be 40/360 = 1/9 of a circle.\nA = 1/9 pi r^2 = 59\npi r^2 = 59 x 9\nr^2 = 59x9/pi\nr = sqrt 59 x 9/pi = 13! =)
850259
here:http://www.cut-the-knot.org/Curriculum/Geometry/AreaOfParallelogram.shtml
71096
let area be A\nwidth be W\nlength be L\nnow area of rectangle is = length * breadth \n    A = L * B\n  L = A/B\n L = 3x (squared) +14x+8 / x+4\n   = (3x+2)(x+4) / (x+4)\n   = 3x+2
698384
It depends how you draw out the rhombus, but what ever area it covers, It will be less then the area of the page.
955861
area: l*w = 256\n-> 4w*w = 256\n->w(sqaure) = 64\n->w=8 (width)\n->l = 4w = 4*8 = 32(length). \n\nThere you go.
241144
to calculate the area of a 2-dimensional space you always multiply length x width, or in this case height\n\nC
820928
I am guessing that you want to know how big one of the sections are, so that's what I will try to determine.\n\nThe first step is to find the surface area of the hemisphere with a radius of 18 meters:\nThe surface area of a sphere, with r as the radius, is: A = (4)(π)(r²). Since this is a hemisphere, we can divide the expression equal to the surface area by 2, leaving us: A = (2)(π)(r²).\nA = 2(π)(18²) = 2(π)(324) = 648(π)\n\nSince we know that the surface area of the hemisphere is 648π m², we can divide this by 12 to find out the surface area of one of the sections:\n648π / 12 = 54π meters² ≈ 169.65 meters²
857420
Area of what?\n\nRectangle = b×h\nSquare = l^2\nTrapezium = ½(l+b)h\nEllipse = πlb\nCircle = πr2 \nTriangle = ½b×h
863802
area=(1/2)d1*d2\n=(1/2)*28*13\n=14*13\n=182 sft