find gcf for (6y^2-3y)(y+7) i say 3y am i close.....i am trying?
549705
The factor 6y^2-3y can be factored further as 3y(2y-1).  Note that 3, a prime, becomes a purely scalar factor to the product of all three terms.\n\nThe gcf would be a monomial that divides into each of the three factors y, (2y-1) and (y+7).  But these are relatively prime (none can be divided into the others).  The only common factor of all three is 1.  This specifically means that y is not the gcf, and therefore 3y isn't the gcf, either.\n\nThis is analogous to a number being the product of 3 (or four) prime numbers.  Since none can divide into the others, the gcf of the product is 1.
373486
10y - 3 = -10 + 6y\n    + 3 =  +3 <-- subtract 3 from both sides  \n-------------------\n10y = -7 + 6y\n-6y =    - 6y <-- subtract 6y from both sides\n---------------\n4y = -7\n--   --\n4  =  4 <-- divide both sides by 4\n\ny = -7/4
149255
2y-3+5+4y-10=3y-8+6y+12\n\n6y - 8 = 9y + 4\n\n-8 = 3y + 4\n\n-12 = 3y\n\ny = (-12/3)\n\nANSWER : y = -4
831999
y = (x+3)(x-1)(x-2) = x^3 - 7x + 6
791030
3x – 2y = 6\n3x = 6 + 2y\nx = 2 + 2/3y
810099
Use distribution to simplify...\n\n6f + 27 = -7 + f\n\nNow isolate the variable and solve.
960995
I'm going to assume that you "forgot" to include parentheses.\n3/(y^2 -3y +2) + 7/(y^2 -1)\nFactor each denominator.\ny^2 - 3y + 2 = (y-2)(y-1)\ny^2 - 1 = (y-1)(y+1)\nYour common denominator (CD) will be (y-2)(y-1)(y+1)\nThe first term is missing the (y+1) part, so you need to multiply the numerator and denominator by (y+1)\n[3/(y^2 -3y +2)] (y+1)/(y+1) = 3(y+1)/[(y-2)(y-1)(y+1)]\n= (3y +3)/[(y-2)(y-1)(y+1)]\nThe second term is missing the (y-2) part.\n7/(y^2 -1) = 7(y-2)/[(y-2)(y-1)(y+1)]\n= (7y-14)/[(y-2)(y-1)(y+1)]\nWe now have a common denominator, so we can add the numerators.\n(3y +3)/[(y-2)(y-1)(y+1)] + (7y-14)/[(y-2)(y-1)(y+1)]\n= (3y + 3 + 7y - 14)/[(y-2)(y-1)(y+1)]\n= (10y -11)/[(y-2)(y-1)(y+1)]
567982
2*4y*3y-4x*7y=24y-4y*7y\n\nDo your order of operations. There are no brackets, parentheses, or exponents; skip directly to multiplication and division.\n\n24y^2-28xy=24y-28xy\n\nThen clear one side, making it equal to zero.\n\n24y^2-28xy-24y+28xy=0\n24y^2-24y=0\n\nThen, factor.\n24y(y-1)=0\n\nNow, y can equal 0 or 1.\n\n24*0(0-1)=0\n24*1(1-1)=0\n\nThe value of x is irrelevant.
1068964
simplify expression: -2(y+3)+6(y+1)\n\nsimply distribute then add.
438642
x=3y+7\nx=3(0)+7\nx=7\nHope this helps! ^^\nalso the y intercept is like this:\nx=3y+7\n0=3y+7\n-7=3y\n-2.23333...=y
594665
21+7*3\n35=7*5\n70=7*5*2\n\nthe only thing in all 3 is 7 so the GCF=7
706243
-2y+3=7y-42\n-2y+3-3=7y-42-3\n-2y=7y-45\n-2y-7y=7y-7y-45\n-9y=-45\n-9y/-9=-45/-9\ny=5
203610
b, that's just me doing it in my head.\n3y = -6x + 12\ny = -2x + 4\n\n3y = -6x + 36\ny = -2 + 12\n\nIt's been a while since I've been in a math class, did I do this right?
638546
6-2y=7y+13\nor,-2y-7y=13-6\nor,-9y=9\nor,y=-1
200143
Answering...\n\nSteps:\n1. Determine tha numbers/variables that are common to both terms.\n2. Use the greatest of these factors (GCF).\n3. Factor out the GCF.\n4. What are left, put them inside the parenthesis.\n\nTherefore:\n1. Common factor: 2\n2. GCF: 2\n3. and...\n4. 2(6y^2 - 5) ANSWER
1065375
5 = 7y - [4 + (3y - 2)]\n5 = 7y - (2 + 3y)\n5 = 4y - 2\n7 = 4y\ny = 7/4
246754
6y^2, this leaves 6y^2(1-2y+6y^2)