How do you test a chemical to see if it is a sulfate or a hydrocloride?
542835
Test for sulphate\nIt is best to perform the wet test\nNow add salt:sodium carbonate in the ratio 1:3 in a beaker and dilute it with 20cc of water. Next heat it for 10-20 minutes, and then let it cool, now filter the extract. The extraxt(filtrate) is called Soda Extract or Sodium Carbonate Extract\n\n1) For sulphate\nAcidify some extract with HCl acid and add Barium Chloride\nWhite colour means sulphate\n2) for Cl\nAcidify extract with nitric acid and add silver nitrate, white means chlorine
716763
depending on what kind of ions, you can use a spectrometer.\n\nOr a titration with a color change to see how much of a reactant it takes to consume all of the ions.
87390
There are several possible answers to this question, depending on what resources you have available to you.  If the solution you are measuring is known to contain only potassium carbonate dissoved in water, you can measure the potassium concentration by either atomic emission or atomic absorption methods and calculate to concentration of the potassium carbonate.  You could measure the carbonate concentration by titration or colormetric methods and calculate the potassium carbonate concentration.  Or you could simply evaporate a known quantity of the water to dryness, weigh the residue and calculate the concentration from those numbers.  \n\nIf you have other compounds in the solution, the last option, gravimetric, pretty much disappears.  The first two options are still practical, unless the other compounds contain potassium or carbonate.  Then, things get a little more complex.
497593
Test it for esteroids
446329
Take a water sample to your pool store. They will test the water and tell you exactly what you need chemically to put in your pool.
806753
Are there any tests you can run? Usually if you mix a substance with something else, the product has different chemical and physical properties than the initial substance.\nFor example, let's say that you would mix isoamyl acetate with "X" the product will have certain carachteristics gained only after it was mixed with "X".... I don't know how much this will help...\n\nLook it up on the internet, I am sure you'll find something.\nGood luck.
900769
Chemically it is MgSo4 or Magnesium Sulfate. I would ask for this or write it down and hope the other person has a minium education in chemistry ....
210155
The current way would be ion chromatography.  There are older less reliable methods.  You test for the calcium separate form the anions.  The calcium can also be donw by ICP or AA.
1045839
GOLD-PLATINUM-PALLADIUM TEST\n\nSelect ore samples suspected to contain Gold-Platinum-Palladium and use concentrates equal to the size of one navy bean or pea. Place the concentrates in a clean test tube and add 1cc Nitric Acid and 3cc Hydrochloric Acid, (this a solution named Aqua Regia which is used regularly when testing.) Boil this over a lamp flame for about 5 to 8 minutes. Should this Aqua Regia solution contain Gold-Platinum-Palladium then the following tests will react with various colors, (good idea to practice on known samples of Gold-Platinum-Palladium for color and reaction identification and become familiar to them.)\n\nTest for Gold (Au).\n\nPrepare a solution for Stannous Chloride for each 8 hour period as this solution does not hold up under extended time periods. Dissolving Metallic Tin (Sn) in Hydrochloric Acid (HC1), where the resulted solution will be called Stannous Chloride (SnC1). Place about 2cc of HC1 in a clean test tube and add 1 or 2 small bit pieces of Metallic Tin to the test tube and bring this to a slight boil. You now have Stannous Chloride (SnC1).\n\nNow begin the gold test by making a spot test with freshly made Stannous Chloride by placing a piece of filter paper onto a clean piece of glass and place one drop of Aqua Regia solution in the center of the filter paper, and then add to this mixture one drop of freshly made Stannous Chloride solution. If gold is present there will show up on the filter paper a purple or rose colored spot when the filter paper has dried; the darker the color the more gold will be present; for low grade ore the spot color will appear plainer. Should the filter paper dry out completely, then add 1 more drop of Stannous Chloride solution to the filter paper to bring out the color.\n\nTEST FOR PLATINUM (Pt)\n\nBegin the test for Platinum (Pt) by placing 20 drops of Aqua Regia solution onto a clean porcelain evaporating dish and boil this over a lamp flame until it is dry, then allow this to remain over the lamp flame for about an extended one second.\n\nPlace the dish where it can cool for a few minutes so as not to break the dish. After cooling, place 4cc of distilled water, (or water free from Chlorine), and reheat just to the boiling point. Filter this solution onto another clean porcelain evaporating dish. Add to this dish, Potassium Iodide equal to one grain of rice. Warm this solution slightly over the lamp flame and observe the color that appears. The results for this test will show if Platinum (Pt) is present as the solution will begin to turn to a light or dark rose color within a few minutes time.\n\nThe more Platinum present in the solution, (ore sample), the quicker and darker the color will appear.\n\nSulphides and other impurities, most likely will give a red color to the solution and will be mistaken for the rose color, if so, then boil off about one-half of the solution to quicken the evaporation process. Then let the porcelain dish set until completely dry, then add a few drops of clean plain water, (no chlorine water). The result will then be a bright rose color, and should there be Sulphides or other impurities in the solution they will appear as colorless. If this solution should appear red, then add a few cc’s of plain water to dilute the dark rose color to a lighter rose color, then you have Platinum (Pt).\n\nTesting for Palladium(Pd).\n\nIn the test for Platinum (Pt), upon adding Potassium Iodide (KI) and warming the procedure, if Palladium (Pd) is present in the sample ore, the solution will turn a dark color or black, which depends upon the amount of Palladium (Pd) present. The more Palladium (Pd) present, the darker the color will be, and also there will be a black precipitate in the bottom of the porcelain dish, which when adding an excess of Potassium Iodide (KI) will dissolve giving a wine-red color appearance.
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First take 30ml of 1% starch solution and add 6 ml of concentrated HCL acid and distribute them into six test tubes labeled as 'A' TO 'F'. Place them in boiling water bath and take them out at various time intervals like 0', 1', 5', 10', 13' and 15' minutes respectively.\n\nDivide the tubes content into three tubes and do iodine, Fehlings and Benedicts tests in the fractions.\n\nyou can do osazone test in the 15' minute fraction for the conformation of the presence of glucose.\n\nCompare the color developed in different tubes.  It clearly shows difference
43703
How about the red fountain experiment with acids and litmus solutions? mail me at pr4kane@yahoo.com for furhter details on it. u can try electroplating,bleaching by chlorine/so2,the brown ring test with sulphuric acid etc.
857117
Run a borax bead test...for info see:\nhttp://en.wikipedia/wiki/borax_bead_test\n\nOr, iron ppts out as its hydroxide...a flocculent ppt... in basic soln, while sodium does not. Dissolve some in water and slowly add NaOH soln, watching for ppt.  This is only good if you are CERTAIN that spl contains only Fe or Na.
1079987
No safe way to do it.  Distillation perhaps, but that's not safe as sulphate fumes are not that good for you.  \n\nGrab the stock bottle and make up a fresh solution.
213299
SUN's got it right. Iodine is for starch, and biuret is for proteins (or polypeptides that have at least two peptide bonds).\nWhen these indicators react, we can us a spectrophotometer to quantitate how much of whatever substance you're testing for is present.
754842
thats not so hard... all you have to do is titrate it against an acidic solution of known concentration that has a mole ratio of 1:1with sls. add a indicator ( phenolphthaleine) to find the endpoint and that should do it.
945837
Sulphide at th correct pH will precipitate NiS before MnS.\n\nIn your case, and excess of ammonia will form a soluble Ni complex and only precipitate Mn as the hydroxide. On boiling the Mn(OH)2 will probably oxidise to black MnO2.\n\nAding NaOH to both in excess will dissolve Al(OH)3 but Mn(OH)2 so you could use this test to tell the respective chlorides apart.
1084118
Try Copper Test by points