What is difference between Wire Rods and Deformed Bars?
546131
A deformed bar is one that has a pattern/marking rolled into them which helps the concrete get a grip on the bar.\n\nWire rods are smooth bars used where an element of 'sliding' is expected i.e. in expansion joints.\n\nHope this helps
896679
A mature tree trunk may support a greater force than a fine steel wire but intuitively we feel that steel is stronger than wood. To predict the forces which a structure of any size, made of any material, can sustain without failing, we need the concept of mechanical stress.\n\nThe definition of stress originates in two observations of the behaviour of a one-dimensional body subject to uniaxial loading, for example, a steel wire under uniaxial tension:\n\n   1. When the wire is pulled, it stretches. Up to a certain load, the stretch ratio (current length / initial length) is proportional to the load divided by the cross-sectional area of the wire. We therefore define the stress as σ = F/A.\n   2. Failure occurs when the load exceeds a critical value for the material, the tensile strength multiplied by the cross-sectional area of the wire, Fc = σt A.\n\nThese observations suggest that the quantity that affects the deformation and failure of materials is stress.\n\nIn the more general setting of continuum mechanics, stress is a measure of the internal distribution of force per unit area that balances and reacts to the external loads or boundary conditions applied to a body. Stress is an example of a type of quantity called a second-order tensor. In three dimensions, a second-order tensor can be represented by a 3×3 square matrix (containing nine components). However, in the absence of body moments, the stress tensor is symmetric and can be fully specified by six components. These six components are sometimes written in Voigt notation as a 6×1 column matrix which is often, misleadingly, called the stress vector.
1181391
if you statically charge some sort of object, a glass rod works very well, by rubbing it on material in one direction only then hold it next to a stream of water the water should be repelled and bend away from it.
200245
Torsion bars do have a rating. Its based on a couple of variables though. Weight of vehicle, suspension travel distance, length and diameter of torsion bar. Performance parts listed by a manufacture though for a particular make, model are mostly listed from whats tested and what works. Then they only tell you the diameter of what they found to work in any particular application. The formula for figuring all this out will drive yah nuts though. So best to contact a supplier tech support and ask them whats best for your particular idea of usage to get the right torsion bar. They've done the math.
219770
Resistance is the physical property of an element that impedes the flow of current.  Here are the basics for a wire:\n\nResistance, R, of a wire is influenced by three main things: (1) the resistivity, p, of the wire, (2) the length, L, of the wire, and (3) the cross-section area, A, of the wire.  The relationship looks like this...\n\nR = (p*L)/A\n\nIncrease the resistivity or length and you increase the resistance.  Increase the cross-sectional area and you decrease the resistance.  Those are the basics anyway.  Hope this helps.
879011
They are called shape memory alloys, the best example to show the class is a length of wire that you have bent and twisted, get a cigarette lighter and watch it straighten back out to its original state.\n\nTry asking this company for a sample;\nhttp://www.memry.com
665946
sorry but folding rods suck cause they\nbreak easily and dont cast very far\n\nfor the beginner i would recomend a zebco 303 combo\nwith a two piece rod\n\neasy to learn on and takes up very little space
911225
Engineering, plastics, metals. reinforcing bars.
471231
If the bundle diameter is the same and the individual wires are round in cross-section, then obviously the area of wire metal in the cross section is less in the bundle than in the solid wire so the bundle has a higher resistance. But let's say you mean that the bundle is enough larger in diameter that the metal areas of both cross sections are equal as assumed by answer 2. Suppose there are N strands in the bundle and the solid wire has a resistance R. Then each strand's resistance is N*R. Contrary to answer 2 (if I am reading it correctly), it makes no difference if the individual wires are connected side-by-side or not, as long as they are connected together at each end. Connecting them thus in parallel makes the bundle's resistance equal to R. Since the strands are identical in resistance and therefore carry the same current, the voltage at any distance along one strand is exactly the same as at the same distance along any other strand. Connect them together at that point and what happens? No change in current flow because no change in voltage, and therefore no change in resistance.
769351
this question was on this yr's midyear exam, ill give u a clue.\nyou need to seperate the forces acting on the wire into two types \n1) acting horizontally (the force to the left equals the force to the right)\n2)acting vertically (the force to the bottom {or the normal force = 20 *9.8} equals the force to the top)\n\nequate them both and you should get the answer
1000294
Well, the horizontal fraction bar is called a "vinculum" but the slanted version is called a "solidus."\n\nEDITED TO ADD: dax is right, btw... the word "solidus" applies to any use of a "slash."  Also, the word "vinculum" applies to any placement of a bar over mathematical symbols in order to group them, like the horizontal bar part of the radical ("square root") symbol (√), or the bar placed over the repeating numbers of a decimal expression.
8894
Metal rod bent and welded. Hooks welded to the ring hold the net.
362646
it is very simple ,just make sure that all the eyes on the rod are aligned making sure that the joints are tight but do not force the sections together as they are nearly impossible to seperate if forced together,attach reel to handle and start to thread line through rod rings but make sure line is around bale arm and line will rerieve to reel when wound in if you do not do this then whole rod will have to be re-threaded,when line is out of top ring you can then attach float and weights and hook,hope this has helped,any more questions do not be afraid to ask
1125300
Bar graphs are better for comparing data from a single event or circumstance. Line graphs are better for things over time.
179742
Various springs (flat or helical) deflect linearly with load and resistance of certain wires (nichrome, etc.) varies linearly with length.  If your experiment allows or expects large deflections you may be able to combine the spring/resistors into a circuit that calibrates force/deflection/resistance-reading suitable for measurement on an ohmmeter or perhaps a strip chart recorder.  Good luck.
770874
Basically strain may be defined as the change in the original dimension (may be linear, areial, volumetric) to its original dimension\nLogarithmic strain: It may be defined as the equal deformation in the body regarding to the loading on to it.\nPlastic strain: It may be defined as the deformation occured in a body which cannot be restored.\nTrue stress: It is the actual resistance offered by the body due to the actual loading on to it.\nReverse Loading: When the upward pressure is more than that of the downward load then that struture may be subjected to reverse loading
890320
Thermal conductivity: \nCopper: \n9.2*10-2 (kcal/sec)/((m^2)(Cdegree/meter))\nAluminum: \n4.9*10-2 (kcal/sec)/((m^2)(Cdegree/meter))\n\nWe need to assume the rods don't loose any heat to the surroundings. Therefore the kcals conducted through both rods is equal. To calculate the heat conducted per second by the copper, multiply its conductivity, \n\n9.2*10-2 (kcal/sec)/((m^2)(Cdegree/meter)),\ntimes (A*50Cdegree/.88 m).\n\nSet that expression equal to aluminum's conductivity times A*50Cdegree/L. Simplify and solve for L.\n\nEdit: I don't know why the conductivity lines are truncated. Maybe Yahoo is making sure it is compatible with any screen resolution. Anyway, the truncated lines, that I see, should end with \n")(Cdegree/meter))".