how do factorise this sum:-2ab-4a-6b=?
550482
-2a(b+2)-6b=\nor\n-2(ab+2a+3b)
531417
(a+b)(b^6-ab^5+a^2b^4-a^3b^3+a^4b^2-a^5b+a^6)\nGood Night, and Good Luck!
503348
No, the previous answer is wrong.\n\nGroup it like this:\n\n2p + pq -6q -3q^2\n\nthen factor like this:\np(2+q) -3q(2+q)\n\nfactor out the 2+q to get:\n(2+q)(p-3q)\n\nFOIL it out and you will see it is correct.
843943
4, 0, -2, -2, 0\n\nFigure it out! Don't be lazy!
81890
it's not factored completely if you leave it as a^2-25 so the proper answer is 5(a-5)(a+5)
337108
6b + 24a + 45\n= 3*2*b + 3*8*a + 3*15\n= 3(2b + 8a + 15)
828991
(a^2 -2ab + b^2) = (a-b)(a-b) = (a-b)^2\nYou cannot cancel anything, so \n(a^2 -2ab + b^2)/(a+b) does not simplify.\nYou cannot solve for anything because you do not have an equation.
139883
(a+b)(a-b) \n= a^2 - ab + ba - b^2\n= a^2 - b^2 -ab +ab\n= a^2 - b^2
814891
a^2 - 2ab + b^2 = (a - b) ^2\n\nthen...\n\n(a - b)^2 / (a + b) = (a -b) (a - b) / (a + b)
825318
(a^2 -2ab + b^2) = (a-b)(a-b) = (a-b)^2\nYou cannot cancel anything, so \n(a^2 -2ab + b^2)/(a+b) does not simplify.\n\nYou may wish to write it as (a-b)^2 /(a+b)
929178
4(-2)² + 8(-2) + 3(-2) + 6\n= 4(4) - 16 - 6 + 6\n= 16 - 16 + 6 - 6 = 0
917375
b^2 + 6b -16 = 0\n(b+8)(b-2)=0\nb+8=0\nb=-8\n\nb-2=0\nb=2
600095
You can factor out 15bc^2\n15bc^2(5b + 4c^4)
747277
5a+6b-3a+b=?\nSimplified= (2a+7b=?)  or (2a = -7b) or (7b = -2a)\nThey are all the same\n\n15x-3y-7x-4y=?\nSimplified = (8x-7y=?)  or (8x = 7y) or (-8x = -7y)\n\n15m-17n-23m+25n=?\nSimplified -8m+8n=? or (8n=8m) or (n=m)
1099108
I think its 8a^4b^3+6a^3b^5-2a^3b^4
534750
1/2 + 1/2b + 2b^2 + 6bc + c^2\n\n(1/4b)(1/4b) + 4bc + (bc)(bc)\n1/2 + 1/4b +1/4b + b^2 +4bc + b^2 + c^2 + 2bc\n1/2 + 1/2 + 2b^2 + 6bc + c^2\n\nI think this is right... email me if I'm wrong?
815517
OK First you take out the common factor which is y. After you have done that.you have (y^2-12y+36). After this, it becomes simple factoring. The answer is\ny(y-6)(y-6)\nor also known as y(y-6)^2