longitude line 180 degrees from the Prime Meridian(3 words)(21 letters long)?
538013
it is the International Date Line
139083
infact i am not clear about you question. even though i am trying to clear your doubt. ok\nyou can specify the geographical coordinations like the following exaple.\n\nfor example if you want to specify the end point of a line in 35°45'56.8" and the distance of 25 from the start point  you can enter\n@25<35d45' 56.8"\n\nnote: no space between @ to "\n\nfor degree use d\nfor minut use '\nfor second use "
8108
to find out what's on the opposite side of the globe, take the latitude and longitude of where you start, and apply the following transformation:\n\nlatitude:  change north to south, south to north\nlongitude:  add or subtract 180 degrees\n\nrotterdam is at 51 degrees 55' N latitude and 4 degrees 29' E longitude.  so, directly across the globe is the point at 51 deg 55' S, 175 deg 31' W longitude, which according to google maps, is about 350 miles southeast of the southern tip of new zealand.
995072
The first point is not at exactly 210 degrees.  It is a little over 212 degrees.\n\nThe second point (3,3) is obviously at 45 degrees, not 30 degrees.\n\nThe distance between (-8, -5) and (3, 3) is\nsqrt((-8 - 3)^2 + (-5 - 3)^2) = sqrt((-11)^2 + (-8)^2) = sqrt(121 + 64)\n = sqrt(185)\n\nThe original angle from (3,3) to (-8, -5) is\natan2(-8 - 3, -5 - 3) = atan2(-11, -8) = 180 degrees + arctan(8/11)\ncounterclockwise.\n\nThe clockwise rotation subtracts thirty degrees from that, so in the final coordinate system the original (-8, -5) is sqrt(185) magnitude in the 150 degrees + arctan(8/11) direction from the new origin at the original (3,3).\n\nLuckily, sin( arctan(8/11) ) = 8 / sqrt(8^2 + 11^2) = 8 / sqrt(185)\nand cos( arctan(8/11) ) = 11 / sqrt(185).\n\nWe have the "new" x is\n\nsqrt(185) cos(150deg. + arctan(8/11)) =\n = sqrt(185) ( cos( 150 deg) cos ( arctan(8/11) ) - sin( 150 deg ) sin( arctan(8/11) ) )\n = 11 cos(150 deg) - 8 sin(150 deg)\n = 11 (-sqrt(3)/2) - 8 (1/2)\n = -(1/2)(8 + 11 sqrt(3)) or approx. - 13.526\n\nand the "new" y is:\n\nsqrt(185) sin(150deg. + arctan(8/11)) =\n = sqrt(185) ( sin( 150 deg ) cos ( arctan(8/11) ) + cos( 150 deg ) sin( arctan(8/11) ) )\n = 11 sin( 150 deg ) + 8 cos( 150 deg )\n = 11 (1/2) + 8 (- sqrt(3) / 2)\n = (1/2)(11 - 8 sqrt(3)) or approx. -1.428\n\nwhich makes sense, as the original slightly over 212 degrees after the rotation is slightly over 212 - 30 = 182 degrees, so both quantities are negative with the magnitude of x large and the magnitude of y small.\n\nCheck: "new x"^2 + "new y"^2 =\n = ( -(1/2)(8 + 11 sqrt(3)) )^2 + ( (1/2)(11 - 8sqrt(3)) )^2\n = (1/4)( 8^2 + 2*8*11 sqrt(3) + 3*11^2 + 11^2 - 2*11*8 sqrt(3) + 3*8^2)\n = (1/4)( 4 (8^2 + 11^2) )\n = 185 as it should be.\n\nCheck: atan2("new x", "new y") = 180 degrees + arctan("new y" / "new x")\n\n"new y" / "new x" =\n = (11 - 8sqrt(3)) / (- 8 - 11sqrt(3))\n = (11 - 8sqrt(3)) (- 8 + 11sqrt(3)) / ( (-8)^2 - (11sqrt(3))^2 )\n = (-88 + 121sqrt(3) + 64sqrt(3) - 88*3) / (64 - 121*3)\n = (- 352 + 185sqrt(3)) / -299 or approx. 0.105587\nwith arctan 6.02737\nand expected value arctan(8/11) - 30 or approx. 6.02737\nso this checks out, too.\n\nChanged coordinates:\n\n( -(1/2)(8 + 11 sqrt(3)), (1/2)(11 - 8 sqrt(3)) ) or approx ( - 13.526, -1.428 )
269726
International Dateline\n\nGood luck with your homework.
91856
15 degrees.  If you look at timezones they pretty well match up with 15 degrees of longitude.
236515
map quest dude\n2826.65 miles
561548
Latitude:  6° 51' South  \nLongitude:  39° 18' East
850855
360 -- 180 East and 180 West
352596
There are 8 compass directions with 3 letters:\n\nNNE, NNW\nSSE, SSW\nENE, ESE\nWNW, WSW\n\nTwo of those start with E, so you'll still need to figure out what goes in the other direction for the N or S.
623360
greenwich england is zero long and the equator is zero lat\n\nhttp://www.satsig.net/maps/lat-long-finder.htm
180149
The International Date Line is an imaginary north-south line (at the 180th meridian) in the Pacific Ocean at which the date changes. The east side of the IDL is a calendar day earlier than the west side. The actual IDL used is not a straight line, but zigzags around certain populated areas.\n\nThe Equator is an imaginary line, running east to west, that is the origin for latitude. It is drawn exactly half way between the northern and southern hemispheres, where latitude measures 0 degrees.\n\nThe Prime Meridian is the imaginary line, running from north to south, that is used as the origin for measuring longitude. It is an imaginary line drawn through all locations where longitude is 0 degrees.
903023
M (-7, -3) is the midpoint of segment PQ and the coordinates of Q are (6, -3).\nLet the co-ordinates of P be (x,y).\nThen, (-7,-3) = ((x+6)/2, (y-3)/2)\n=>(x+6)/2 => -7 , (y-3)/2 = -3\n=>(x+6) => -14 , (y-3) = -6\n=>x => -14-6 , y = -6+3\n=>x => -20 , y = -3\n\nSo, co-ordinates of point p are (-20, -3)\n\nAll the best
148276
It is a line starting at the North Pole going through Royal Greenwich Observatory in Greenwich, England, and to the South Pole. It ends at both Poles. If you continue the line past either Pole onto the other side of the world it becomes the 180th meridian. See the info and link below.\n\nFrom Wikipedia\nThe Prime Meridian is the meridian (line of longitude) passing through the Royal Greenwich Observatory, Greenwich, England; it is the meridian at which longitude is 0 degrees. The prime meridian separates the eastern and western hemispheres. \n\nThe 180th meridian, on the opposite side of the world from the Prime Meridian, conveniently passes almost entirely through ocean. This line is used as the basis for the International Date Line, with some modifications.
956042
0 Latitude is the Equator, and 0 Longitude is the Prime Meridian.  The Equator is the latitude line that is always closest to the sun, no matter what time of year.  The Prime Meridian is where the time zones start.  Try googling it for more information.
393529
567.95 miles\ni looked it up on map quest
866702
180 degrees =  pi  radians\n\n305 degrees\n=  (305/180)  *   pi\n=  (61/36) pi