Multiplying rational expressions?
545170
ok\nI am guessing they are two different fractions?\nso you can cancel out with the same method of cross multiplication\nso it would be\nwait is the 14s = 14x is that what you meant?\nthen it would be\n2x/6 *  7a/5y^3\nso then you have\n14xa/30y^3\nwhich simplifies t:\n7xa/15y^3\n\nIf you can, can you make the question clearer so I can verify the answer
92952
(8x+3)(4x+3)\n32x2+24x+24x+9\n32x2+48x+9
17334
Geometric -- multiplying the previous term by 4
947283
You can do this using "synthetic division"\n....... ______________________\nx - 5 ) x^4 - 0x^3 - 3x^2 + 0x + 6\n\nI'm going to simplify this leaving out the x-terms and only showing the coefficients, but just imagine they are there:\n\n.............. 1 . 5 .22 110\n1 -5 ) 1 . 0 .-3 . 0 . 6\n......... 1. -5\n......... ------\n.............. 5 .-3\n.............. 5 -25\n.............. -------\n................... 22. 0\n....... ........... 22 -110\n....... ............----------\n....... ........ ........ 110  6\n....... ........ ........ 110 -550\n....... ........ ........ ------------\n....... ........ ........ ....... 556\n\nSo if I did it correctly the answer should be:\n1 5 22 110 remainder 556\n\nThis equates to:\n(x^3 + 5x^2 + 22x + 110) + 556/(x-5)
521556
Rational expressions are just fractions with variables in them. The process for adding and subtracting is the same as with fractions. First, you want to find the least common denominator, which in this problem would be 20n. Then you multiply the numerator and denominator of each term with whatever it takes to transform the denominator into the desired common denominator.\n\n1/5n=4/20n, -3/4=-15n/20n, 7/10n=14/20n\n\nNow you can combine the numerators over the common denominator:\n\n(4 - 15n +14)/20n, simplifies to (18-15n)/20n\n\nThat's all you do.
889816
1/rt3 *1/rt2-1/rt3\n[1/rt3](1/rt2-1)\n[1/rt3](1-rt2/rt2)\nrationalising\n[(1-rt2)*rt6]/6
780298
first u distribute the - to the stuff in the parenthesis so you have\n7x^2-3+x^2\nthen combine like terms\n8x^2-3
193745
1.25 * 10^-3 * 8 * 10^-5\n\n(1.25 * 8) * (10^-3 * 10^-5)\n\n(10^1) * (10^-8)\n\nANSWER : 1.0 * 10^-7
211814
2x^2 +3x-6 well that is as simple as it can get unless you have a number for the variable x
386814
They are correct.  Observe the order of operations or PEMDAS\n\nParenthesis\nExponents\nMultiplication-Division\nAddition-Subtraction\n\nso first multiply   -89 * 658 =   -58562\nThen add 2   =                    -58560\nThen add 6   =                    -58554\nThen subtract 89 (or add -89) =   -58643
96233
+5,+12, -5, -12, +3.3
774020
3x^2(5x^2 – 2x + 6) – 2x(x^2 + 3x + 9)\n15x^4-6x^3+18x^2-2x^3-6x^2-18x\n15x^4-8x^3+12x^2-18x\nx(15x^3-8x^2+12x-18)
771358
3x + 4 < x + 8\n2x < 4\nx < 2\n\n{x | x < 2}
650513
shoot me if i am wrong but product means multiply...  so wouldn't the answer be to multiply your n terms together...\n\nwithout further information i can't give you a formula\n\nare you trying to multiply the first n terms from 1 to n???\n\ndo you have a series with a formula that describes each of the terms???\n\nin short be specific...   or any answer you will get to this question will likely be too general or just plain wrong
863644
take out 4x first\n4x(x2-6x+8)\n4x(x-4)(x-2)
93533
Well, the sum of two terms thing is stupid, but oh well. (You can immediatly make it (x-5)(x-9))\nx^2-9x-5x+45=x(x-9)-5(x-9) --> (x-5)(x-9)
855741
(5z^3m + 2)^2, multiply it out yourself to check.