What is the good order to put balls in a billiards triangle?
545976
R= red Y= yellow B= black;\n\n     R\n    Y Y\n   R B R\n  Y R Y Y \n R Y R Y R\n\n or if they are numbered\nput the ones <8 (1 to 7) instead of the reds (R) and the ones bigger then 8 in the yellow's place. The * will replace the Black (B).\n\nexample:\n\n          (1)\n       (9) (10)\n      (2) (8) (3)\n   (11) (4) (12) (13) \n  (5) (14) (6) (15) (7)
204125
Three sizes of balls. The largest are for Billiards, played on a table with no pockets and using only three balls. This is the old "gentleman's game." Points for number of caroms and ability to tap certain balls.\n\nPocket billiards. The middle size. 8-ball, rotation, pea-pool, nine-ball, are all forms of pocket billiards. Points generally made by sinking certain balls according to the type of game played.\n\nSnooker. The smallest size. The table is larger and the pockets are smaller than on a pocket billiards table. See the rules of American or Canadian snooker for how to play.\n\nA pool hall will choose the balls that are longest lasting and makes for the best customer experience. A family place may go for a smaller ball and larger pockets, a skill centered location will follow international rules. Home players often go for economy.\n\nFun Facts about billiards: http://www.bca-pool.com/play/funfacts.shtml
1065918
To get your answers, imagine what has to happen.  \n\na) First, you have to pick 1 of the 4 white balls out of the 12 balls there.\n\n2nd, you have to pick 1 of the 3 white balls left out of the 11 balls there.\n\nSo, in order to get a red and then a red, you need to get 4 out of 12 followed by 3 out of 11 or 4/12 times 3/11 or 12/132 = 1/22.\n\nb) First, how many ways can 5 people line up?  5!.  How many ways are correct (assuming they all have different names, only 1).  So, the prob is 1/5! or 1/120.
314372
I think I have the answer.  Make three groups of three balls.  Now, take any two groups and place one group on one side, and the other group on the other side.  If the balance indicates that the groups are equal, then set aside those balls.  Take the remaining group of three balls and place any one on one side, and another on the other side, leaving the third on the table.  If both balls are even, then the one on the table is the heaviest.  Now for the different scenarios.  Going back one step, if the scale indicates that one side is heavier, then that ball is heavier, and you've found the heaviest.  When placing the groups of three balls on the scale, basically the same procedure is used.  If one group is heavier, take that group and set aside all other groups.  Then place one ball on each side and find if the scale is balanced.  If it is, then the one on the table is the heaviest etc.
623194
I always use LePro tis on my cues...they are hard and may work for you.  They are inexpensive and you can get them from Meuller (on-line or catalog), or probably any good billiards store near you.
461066
Make sure your feet are pointing in the right direction first of all... keep your shoulders pointing towards where you want to serve it.  Then you have to make sure your serving grip is right, otherwise you will just push the ball over.  Once you figure that out, count off two slow counts (1....2....)and at 2 you should be at the top of your swing going on your way down behind your head.  On 3 you should have already started to swing up from behind your head.  Pronate your wrist at the top of your swing, and follow through over the front of your body.  Also a lot of practice on the ball toss is always usefull.  You can figure out different types of spins and change the speed depending a lot on the toss, and how you follow through.
1103719
# 4 Types of games (carom and pocket)\n\n    * 4.1 Straight billiards or straight rail\n    * 4.2 Balkline\n    * 4.3 Three cushion billiards\n    * 4.4 Eight ball\n    * 4.5 Nine ball\n    * 4.6 One pocket\n    * 4.7 Bank pool\n    * 4.8 Snooker\n\nFor the rules and a lot more information on pool see the article.
921586
Video games can sometimes help with strategy.  For example, it can give you ideas for how to run out a rack, pattern play, etc.  For the actual execution of the stroke, it does nothing whatsoever.  There are only three things that you as the shooter can control at the pool table: Angle, Speed, and Spin.  So, as I tell my students, "Cover your A.S.S."  The angle of the shot is already prescribed.  Spin is where your cue tip will contact the cue ball.  Speed control is actually more than 1/3 of your pool game.  All a video game will do is give you someone else's idea of what "slow" and "fast" means.  If I had to guess what percentage a video game helps your real game, I'd say around 5%.  There's nothing wrong with playing computer games, but don't make a mental link between them and the real thing.  M.D.-BCA Instructor/Referee.
991890
Try the 2-2 pattern. it's the best way. The 3 is done with that criss-cross pattern, but the 2-2 allows you to continue the circle, just make it have a big radius
1184894
It depends on the game you are playing, but there are two very popular games played on the standard pool table.  Eight ball features15 balls one being the black eight ball, seven solids and seven stripes.  The object is to sink all of your balls (either solid or stripes) in any of the six pockets before sinking the eight ball.  A player may continue shooting until he misses a ball.  If a shot cannot be made, then it is to the players advantage to "hook" his opponant leaving the cue ball in a spot where a shot is difficult or impossible, thus regaining control of the game.\n\nNine ball is played with the balls numbered 1 through 9.  The object is to sink each ball in numerical order, sinking the nine ball last.  Each ball is worth one point, the nine is worth two.  In competative pool, players have to reach a certain number of points before their opponant. In tournament play it often goes by games won-like the first to win eleven games, as opposed to recording points.  A player may win the game early if they sink the nineball using the numbered ball they are hitting.  For example if I am shooting the one ball, I can hit the one into the nine and pocket it, winning the game.  Strategy is important in nineball, along with cueball control.  It is a great game to play to practice banking, hooking, and cueball control.\n\nBesides these two games there are other variations that can be found, and many bars have their own house rules. In an unfamiliar place it is a good idea to check what the rules are before play.
934116
In Yahoo Pool, here is how you shoot:\nWhen shooting the cue ball, use the left mouse button to move the cue stick \n     around the cue ball. When you have positioned the cue stick where you want,\n     click and hold the right mouse button. Pull back on the mouse until you have\n      the desired power (displayed on the right side of the table). Let go of the right \n     mouse button to take your shot. To move the cue ball when you have ball in hand,\n     simply left-click the cue ball and drag it to the desired spot and drop it. \n     For more precise aiming you may use the arrow keys to line up your shot as well. \nHope this helps, and good luck!
103557
8/5 the initial iteration (triangle)
437879
in 9 ball you have to hit the lowest numbered ball 1st or it is a ball in hand fall.if you scratch.if you dont hit a rail after you contact the lowest number ball with either the cue ball or the object ball. in 8 ball you have ball in hand if...you dont hit one of your balls and a rail.you scratch.
356709
We think that the thing to do is weigh six balls against six balls, but if you think about it, this would give us no information the only different ball. As we already know that one side will be heavier than the other. \n\nSo that the following plan can be followed, let us number the balls from 1 to 12. For the first weighing let us put on the left pan balls 1,2,3,4 and on the right pan balls 5,6,7,8. \n\nThere are two possibilities. Either they balance, or they don't. If they balance, then the different balls is in the group 9,10,11,12. So for our second weighing we would put 1,2 in the left pan and 9,10 on the right. If these balance then the different ball is either 11 or 12. \n\nWeigh ball 1 against 11. If they balance, the different ball is number 12. If they do not balance, then 11 is the different ball. \n\nIf 1,2 vs 9,10 do not balance, then the different ball is either 9 or 10. Again, weigh 1 against 9. If they balance, the different ball is number 10, otherwise it is number 9. \n\nThat was the easy part. \n\nWhat if the first weighing 1,2,3,4 vs 5,6,7,8 does not balance? Then any one of these balls could be the different ball. Now, in order to proceed, we must keep track of which side is heavy for each of the following weighings. \n\nSuppose that 5,6,7,8 is the heavy side. We now weigh 1,5,6 against 2,7,8. If they balance, then the ball is either 3 or 4. Weigh 4 against 9, a known good ball. If they balance then the different ball is 3, otherwise it is 4. \n\nNow, if 1,5,6 vs 2,7,8 does not balance, and 2,7,8 is the heavy side, then either 7 or 8 is a different, heavy ball, or 1 is a different, light ball. \n\nFor the third weighing, weigh 7 against 8. Whichever side is heavy is the different ball. If they balance, then 1 is the different ball. Should the weighing of 1,5, 6 vs 2,7,8 show 1,5,6 to be the heavy side, then either 5 or 6 is a different heavy ball or 2 is a light different ball. Weigh 5 against 6. The heavier one is the different ball. If they balance, then 2 is a different light ball.
714707
put out your right hand onto the table finger tips touching the tables but palm up, rest the stick between your thumb and fore finger about 30cm from the tip. use your other hand to push the stick forward, whilst aiming at the ball. \n*put a bit of talc where the stick rests on your hand- it makes it easier*
884452
Let's assume that the cue ball is traveling in the +x-direction\n\nConservation of energy says\n\n0.5*m*v1^2 = 0.5*m*v2^2 + 0.5*m*v3^2\n\nwith the condition that all the masses are equal this reduces to\n\n(1): v1^1 = v2^2 + v3^2\n\nI'll assume that v2 is the speed of the 8-ball and v3 is the speed, after collision, of the cue ball.\n\nConservation of momentum says\n\nm*v1 = m*v2*cos(q) + m*v3*cos(a)\n0 = m*v2*sin(q) - m*v3*sin(a)\n\nfor the x and y directions, respectively. Here q is the angle that the 8-ball moves away at (35 deg) and a is the angle that the cue ball moves away at. These reduce to\n\n(2): v1 = v2*cos(q) + v3*cos(a)\n(3): v2*sin(q) = v3*sin(a)\n\nWe now have the three expression (1), (2), and (3) for which to solve we can solve for the angle a.\n\nFrom expression (3)\n\nv3 = v2*sin(q)/sin(a)\n\ninserting this into equation (2)\n\nv1 = v2*cos(q) + v2*sin(q)/tan(a)\n\nTaking these two expression and plugging them into equation 1.\n\nv2^2*(cos(q) + sin(q)/tan(a))^2 = v2^2 + v2^2*(sin(q)/sin(a))^2\n\nfrom which we can eliminate v2 to get and expression just in terms of the angles. Expanding this expression we have\n\ncos(q)^2 +sin(q)^2/tan(a)^2 +2*sin(q)*cos(q)/tan(a) = 1 + sin(q)^2/sin(a)^2\n\nrearranging terms and using sin(x)^2 + cos(x)^2 = 1 we have\n\n-sin(q)^2 + sin(q)^2/tan(a)^2 + 2*sin(q)*cos(q)/tan(a) = sin(q)^2/sin(a)^2\n\nmultiplying by sin(a)^2\n\n-sin(q)^2*sin(a)^2 + sin(q)^2*cos(a)^2 + 2*sin(q)*cos(q)*sin(a)*cos(a) = sin(q)^2\n\ncollecting terms\n\nsin(q)^2*(cos(a)^2 - sin(a)^2 - 1) + 2*sin(q)*cos(q)*sin(a)*cos(a) = 0\n\nwhich becomes\n\n-2*sin(q)^2*sin(a)^2 = -2*sin(q)*cos(q)*sin(a)*cos(a)\n\nseparating the a and q terms and simplifying\n\ntan(a) = 1/tan(q)\n\nwhich is readily solved for the a, the angle at which the cue ball moves after the collision.
724623
don't knock the 8-ball in until last, unless you're playing straight pool........ keep your eye-level as low as possible, use a smooth stroke.