VOLUME OF TRIANGLE(FORMULA).please help?
536573
for area of any triangle---1/2*(b*h)  .... and for equilateral triangle---(square root of 3)/4 (a raise to 2) \nand volume of anything is area mult by height---i guess thats how u do it\nwhere \nb=base length\nh=height\na=side length for equilateral triangle
471779
We use the formula  area = (1/2)bc.sin(A)\n\nThe formula above can be "proven" easily by definition that a triangle's area is just 1/2 x "base" x "height".\nNote in above, base = b. and height = c sinA. \nIts one way of looking at it. Draw a diagram.\n\nWe'll use that and some basic trigonometry to prove "Hero's formula".  \n\nAnd sin(A) = 2 sin(A/2).cos(A/2)    \n\nSo area = bc.sin(A/2).cos(A/2)\n\nNext we find expressions for cos(A/2) and sin(A/2) in terms of \ns, a, b, c, where a, b, c are the sides of the triangle and s is \nthe semi-perimeter.\n\nSo  s = (a+b+c)/2\n\n                                    \ncos(A) \n\n=   2cos^2(A/2) - 1 \n\n= [ b^2 + c^2 - a^2 ] / [2bc]\n\nSo,\n                                  \n2cos^2(A/2) \n\n= 1 + [ b^2 + c^2 - a^2 ] / [2bc]\n\n= [(b+c)^2 - a^2 ]/[2bc] = [(b+c-a)(b+c+a)]/[2bc]\n\n= [(2s-2a)2s ]/[2bc]                          \n\nSo,\n              \ncos^2(A/2) =  [s(s-a)] / [bc]\n\n                                   b^2 + c^2 - a^2\nNext, \n\ncos(A) \n\n= 1 - 2 sin^2(A/2) \n\n= [b^2 + c^2 - a^2] / [2bc]\n\nSo,\n\n2sin^2(A/2) = 1 - [b^2 + c^2 - a^2] / [2bc]\n\n2sin^2(A/2) = [a^2 - (b-c)^2] / [2bc]\n\n2sin^2(A/2) = [(a-b+c)(a+b-c)] / [2bc]\n\n2sin^2(A/2) = [(2s-2b)(2s-2c)] / [2bc]\n \nHence,                                 \n                                    \nsin^2(A/2)  = [(s-b)(s-c)] / [bc] \n\n                                    \nWe can now return to the formula for the area of the triangle using the above:\n\n(1/2)bc.sin(A) = bc.sin(A/2).cos(A/2) \n\n(1/2)bc.sin(A) = [bc.sqrt[s(s-a)(s-b(s-c)]/[bc]\n\n(1/2)bc.sin(A) = sqrt[s(s-a)(s-b)(s-c)]\n\nDone.\n\nNote : The dots "." mean nothing just "spacing".\nRegards
894614
PV=nRT\nP= (nRT)/V  (1st eq)\n\nn,R,T u know.\n\nV >>>\nDensity = mass/ volume\n2.3 = .00446 *10^3/Volume\n\nrearrange and ull get volume.............and then put that into the first equation.............and voila
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the formula for volume of a cylinder is V = h * pi * r^2.\nAlternatively, the surface area is A = h * pi * r * 2.\n\nSo, if you have either the surface area or the volume, you can calculate for the height.\n\nH = Volume / pi * r^2\nH = Area / pi * r * 2
680192
The area of a triangle is 1/2 the base time the height.\n\nA=1/2bh\nA=1/2(10)(4)\nA=(5)(4)\nA=20 units^2
116020
Volume = pi*r^2*h\n\nWhere pi = 3.14.159...\nr = raduis of cylinder in feet\nh = height of cylinder in feet
891617
The triangle area formula is\n\nA = 1/2 b h\n\na = 1/2(5)(2)\n\nA = 5/2(2)\n\nA = 10/2\n\nA = 5\n\nThe area of the triangle is 5 feet\n\nThe answer is " a "\n\n- - - - - - - - - - - -s-
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The volume V=abc\nSurfce area S=2(ab+bc+ca)\nTherefore,2/S(1/a+1/b+1/c)\n=2/2(ab+bc+ca )](ab+bc+ca)/abc\n=1/abc=1/V proved
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Measurements (In distance I'm assuming) would give you volume.\n\nMass / Volume = Density\n\nIf you have volume & density, you can rewrite the equation:\n\nMass = Volume * Density
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Volume of a prism or cylinder = Area of the base (a circle in this case) * Height\n\nV = pi*r^2 * h,  (V=volume, r=radius=diameter/2, h=height)\nV = pi*0.75^2 * 9\nV = 15.9 ft^3
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Since you said ratio of a:b:c, not sides equal a, b and c, there is a formula, and of course a, b and c must be given. Given a, b and c, find their product. Divide the desired volume V by the product and take the cube root X of the result. Multiply a, b and c by X. The result is the 3 sides of the box with volume V.\nExpressed algebraically, \nX=(V/(a*b*c))^(1/3)\na1=a*X, b1=b*X, c1=c*X\n\nExample: I want a box with sides in the ratio 2:3:7 and volume = 65.2. \n2 * 3 * 7 = 42\n65.2/42 = 1.552381\n1.552381^(1/3) = 1.157887\n1.157887 * [2, 3, 7] = [2.315773, 3.47366, 8.105207]\n2.315773 * 3.47366 * 8.105207 = 65.19999
29575
well, the formula for the volume of a cone is 1/3 * base * height.\n\nthe trick to doing this is to find the volume of the large cone, then subtract the volume of the small cone.  what's leftover will be the tumbler-shaped volume.  plug in numbers for the height and base for both the large and small cones, and then subtract. voila!
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sorry i made a mistake....this is correct...\ndivide the base by 2.  Now you have a right triangle.  the height is the same, but the base is now 3.  pygathora (spelling, whatever) theorm is A squared + B squared = C squared.  c is the side opposite the right angle, a and b are the other sides.  so 3 squared + 4 squared is 9 + 16 = 25. The square root of 25 is 5, so that is the length of the side.  the volume = area of base times height.  Area of a triangle is 1/2 base times height.  so 3 (one half of 6) times 4 = 12.  times this by height of 8 = 96 cubic units. largest rectangular side is the 6 (the longest side) times 8 = 48 units squared. hope this helped.  the lateral area is the area of the sides added together. so C times 8 = 40 (area of one side)  add the other side of equal area (the C from the second triangle we got when we split the first one) 40 + 40 = 80.  Add the third side of length 6 times 8 = 48.  80 + 48 is 128 (in units squared).  or all sides added up 5 + 5 + 6 = 16 times 8 = 128.
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V=(4/3)*pi*r^3\n\nwhere r is the radius of the sphere and V is volume.
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Surface Area=sqrt{3}a^2\n    Volume =(1/12)sqrt(2)a^3\nhttp://en.wikipedia.org/wiki/Tetrahedron
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haha I was just working on my geometry homework and we're doing that right now.. the formula for the volume of a prism is: V=Bh, where B=the area of the base and h=the height of the prism.. that's the equation for ALL prisms..\n\nthe equation for the volume of a cylinder is V=pi(r^2)h\nso it's pi times the radius squared times the height\n\nthe equation for the circumference of a circle is C=2(pi)r\nso 2 times pi times the radius
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The surface area:\nS = 0.5*(B1+B2)*Hs  +  A1 + A2\nWhere B1 & B2 are the perimeters of the 2 bases\n      Hs = Slant height\n      A1 & A2 are the areas of the 2 bases\n\nThe volume:\nV = (1/3)*h*(A1+A2+ sqrt(A1*A2))\nWhere h = the height of the truncated tetrahedron