Why does this math play work?...?
550093
OK, CREATIVE, here's how it works:\n\nFirst let's think of what we mean by writing a number as follows:  "4321". \n\nWe mean the number is [(4X1000) + (3x100) + (2X10) + 1X1)]. \n\nIn other words, the number is the sum of four thousands, three hundreds, two tens, and one ones.\n\nWe'll call your word sequence of directions the "sequence", for short. What I intend to do is derive the number 1755 or 1756, as appropriate, because that is the key to how the sequence works. The multiplication that the sequence calls out just serves to positions numbers in the columns so that the last three digits of the answer become, in order, the chocolate number, the first age digit, and the second age digit.\n\nAlso To help simplify things, let's name the numbers 1755 & 1756, the "adjuster", because they "adjust" the sequence so that when we subtact our birth year, we arrive at the desired three-digit answer!\n\nNow let's write the sequence of steps you outlined as an equation, where n = the number of times we eat chocolate, and 19xy represents the year of birth (YOB).\n\n(By the way, the sequence doesn't work if you were born before 1901 or after 1999, but we when finish here, you'll have the tools to fix it to work for either the 19th or 21st centuries! YEAH!) :-)\n\nSo here's the sequence written as an equation:\n\n\n{[100(n) + 250] + 1756} - 19xy = nTO\n\nWhere we've assigned "T" as in "T"ens column, as the first digit in the age, and "O" as in "O"nes column, as the second digit. So the answer to the equation is properly "nTO".\n  \ndouble check the equation by going back and reading what the sequence spells-out.\n\nNotice that whatever (n) is, the first term of the equation, 100(n), will always create, in the hundreds (third) column, the number we chose for (n)!!!\n\nAHAW! - we've already cracked part of the trick!  We know we have to choose our "adjuster" such that it cancels-out any other numbers appearing in the hundreds column! The "n" gets preserved because its the first digit of the answer!\n\nSimple - eh?\n\nFor now, lets assign the adjuster the value ABCD, where the alphabet letters represent the numbers we need to derive. \n\nUsing our terminology and chain, we can re-write the equation as a column of numbers to be added and subtracted as follows:\n   \n             0n00\n             0250\n             ABCD \n             19xy(-)\n            ______\n             0nTO               \n \nNote: The lead zero's in rows one, two, and the answer row are put there to try and line-up the columns correctly when they appear on the yahoo! answer site, which otherwise moves them out of position because it "left justifies" all columns. By the same token, normally the minus sign for the "19xy", which is to be subtracted, would appear in front, instead of behind, but in so doing  the program mis-aligns the columns. Also note that the alphabet letters do not line-up accurately with the numbers. Readers will have to mentally correct for these mis-alignments.  Sorry!\n\n\nHang on!  We're almost there!  The hard part's done, it's all down  hill from here!  :-)\n\nNow let's plug in to the columns the numbers for an easy case, say a ten-year old born in 1996, then work backwords and see what numbers result for the "ABCD".\n\nplugging in age 10, YOB of 1996, then the desired answer is n10. Go back and put in the answer line.\n\n Then see how the columns look. we have:\n    For the ones column,        D-6=0,      so D=6\n    For the tens column,       5+C-9=1,     so C=5          \n    For the hundreds column,  n+2+B-9=n     so B=7\n    For the thousands column,    A-1=0      so A=1\n\nSo  ABCD = 1756  QED  (Quid Erat Demenstradum - what we wanted to demonstrate, as the Romans used to say!)\n\nNow you can have some fun and derive the "1755" adju
233014
U R RIGHTT..HOW DID YA GET IT..PLZ CAN YA EXPLAIN..I'VE BEEN TRYING THIS PROBLEM FROM A LONGTIME.EVEN DE CALCULATOR SAYS ITZ "4"..I KNOW DE CALCULATORS WRONG TOO..PLZZ DO EXPLAIN IT TO ME ASAP
709282
Quick Math-Mind Games
262906
First of all, you know that the total money collected was 57444 * 2, which is 114888.\n\nNext, you know that you have only 202 prizes.  Of those, three of them were valued: 2000, 1500 and 1000.  Keep in mind that after those three prizes, there are 199 prizes left, I'll get to that later.\n\nThe first three prizes will take a total of 4500 from the initial pot of 114888.\n\nNow, since each following prize is 5 less than the one before it, it is a summation of the next 199 prizes starting at an initial prize value of 1000 minus 5.  (Remember, each following was 5 less than the one before it.)\n\nSo, the summation is the sum of each value of the equation: (1000 - (5 * x)) where x starts at the value of 1 and increases to 199.  So this is the sum of: 995 + 990 + 985 + ... + 5.  The result of which is 99500.\n\nSo, 99500 + 4500 is the total amount paid out in prizes, being 104000.  Subtracting that from the initial intake of funds on $2 tickets leaves a total pure profit of 10888.\n\nNot a bad profit, it was almost like asking about one out of six of those people to just 'give' you one dollar. :)
735829
Because it's incredibly difficult to "understand" things that are completely untrue. Go ahead, give it a try. Try to "understand" that 1+1=3. Not so easy, is it?
841719
sorry for laughing but I know everything can be used with math. Those rockets, how long is goes up, where it lands the wind , angle bla/bla
164117
This seems like a sort of ridiculous thing to ask here. Why not just do a search for math trivia? Here is a link for example that I found right away.
487526
Sounds like a Math/Science type question to me. Why are you posting it here?\n\nBesides, I have the the slightest idea.
512413
i assume you want a demonstration of the use of numbers and math in daily life... try these\n\n1. suppose brand a of candy sells for 2.37 for an 8 oz bag and brand b sells for 3.05 for a 11 oz bag ask audience which is a better deal ?, why ?, how can we compare the 2 brands to get a definite answer ? Now you introduce the idea of unit price which is $amount/weight do this for each brand. The smaller value for the two brands is the better unit price or the better deal.\n\nfind three different size circles. measure for each one the distance around the circle and the distance across the center of it write these values down for each circle.  Now for each pair of measurements divide the around value by the across value. ask the audience to compare the three quotients and note anything unusual.  what will happen is that no matter the size of the circle distance around/distance across is the same value about 3.14159. now state that pi is the ratio of dist. around / dist. across for a circle and is the same regardless of size of circle
741881
i do indeed, the same thing is at mysticball.com - i answered the following to that question and it applies to this one also:\n\nit doesn't, the answer is predetermined before you even think of one, all you're doing is using the mathematical equation it tells you to to arrive at a certain number containing the predetermined symbol.\n\nalthough each time you play the symbol sheet to the left is different, you will see that every number on that sheet that is a multiple of 9 is the same symbol - 9, 18, 27, etc etc.\n\nbecause the result of the equation you do will ALWAYS be a multiple of 9 the symbol you 'picked' will be the same regardless of which number you choose at the start because every number on there that is a multiple of 9 has that symbol.\n\nit's just basic math, nothing exciting.
807146
Excuse me, but where is the following example?  But, it must be fraction work right?
1053962
I am assuming this is an "I hate math so I'm gonna complain about its lack of relevance" question and not a real question, but I'll answer it anyway.  I can't tell you every use of it, I suppose I've seen several, but here's one I see a lot.  If you have an object thrown in a trajectory, and you need to know when it will cross a certain height, or when it will be going a certain speed (I dunno, in case you're lobbing hand grenades or missiles someday when you're bored), the quadratic equation will come up in the solution, and it will give you BOTH of the answers, one for when the object is on the way up and one for when it's on the way down.
538111
yeah.....!!!! just calculate it!!! lol
771356
you flip it whenever multiplying or dividing by a negative.  The first case would NOT flip it.  The second case would flip it.
997488
The explanation is really simple, really!\n\nOkay, take a look at the mystic ball chart right now. Take a look at the numbers 0, 9, 18, 27, 36, 45, 54, 63, 72, and 81. They are all the same symbol, right? And they are all multiples of 9! Now, before doing anything, just click on the mystic ball. You'll notice that the symbol that pops up is the same symbol that the numbers mentioned above show. Click on the blue link to try it all again. You should get another sheet with different symbols. Now, look at the very same numbers that you looked at before. They all share the same symbol, but now it is a different one, right?\n\nThis is the trick. No matter what number you choose from 0 to 99, the final answer will always be a multiple of 9. Try it out yourself! Go through each number and figure out what the final number of each number would be. Figure out what the final symbol would be, too. You will see that no matter what number you choose, the same symbol will keep popping up.\n\nIf you want the equation, it would be 10a + b - (a+b). 'a' represents the first digit of the number you chose, and 'b' represents the second digit of the number you chose. '10a + b' represents the number as a whole (for example, let's choose the number 32. a = 3, b = 2. 10(3) + 2 = 32. Make sense?). the '- (a+b)' part represents the time when you add the digits together and subtract it from the original number to get your final answer. After reducing the equation, you get 9a, which is why the answers all come out to be a multiple of 9.\n\nHopefully this makes sense!
611639
do the math moron!!!!!!
156986
First, I am not sure why you call this factoring. This is not factoring. \n\nThink of it this way. If each of the teams play each other once, there are G1=[N^2-N]/2 games. To see that this is true, just compute either \n\nN choose 2 = N!/[(N-2)!2!]=[N^2-N]/2 \n\nor \n\nmake a matrix with the N teams as both rows and columns. Every element of the matrix constitutes a game between two teams, one in the corresponding row and one in the corresponding column. One has to disregard the N diagonal elements, because a team cannot play itself, so there are a total of N^2-N games in the matrix, without the diagonal. Since this includes games when A plays B as well as B plays A, we have to divide by 2, to get again [N^2-N]/2.\n\nIf each of the teams play each other 2 times, there are G2=N^2-N games. To see this, just imagine the matrix of team-labelled columns and rows again, and subtract the diagonals again, so that both the games between A and B and between B and A are included, for a total of 2 games between each pair of teams. The number of elements in the matrix is N^2-N, ignoring the diagonal elements again. \n\nFor the teams to play each other 3 times, they can just play the one game schedule, and then the 2 game schedule, for a total of 3 times between each pair of teams, so:\n\nG3=G1+G2=(3/2)*[N^2-N]\n\nFor N=7, this is just 1.5*[49-7]=1.5*42=63.\n\nThere are 63 total games played.