The general formula for an ester is:?
541840
eters are organic compounds that replace the hydrogen atom
384774
CH3CH2OH\n\nC ~ 12\nO ~ 16\nH ~ 1\n\n2*C + 1*O + 6 * H = 2*12 + 1*16 + 6*1 = 46 g/mol
758773
6O2 + C6H12O6 ---> 6CO2 + 6H2O
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2C12H22O11 +24O2 ---> 24CO2 +22H2O\na)F\nb)F\nc)T\nd)F\ne)T\nf)T
297119
Chemisty, A Formula For Answers
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ALUMINUM ACETATE BASIC \n\nFormula: Al2O(C2H3O2)4.H2O
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CuSO4•5H20\nThe dot notation denotes the hydrate.
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2KOH=>K(2)O+H(2)O\n\nFeO+C=>CO+Fe\n\nCa+2AlCl=>CaCl(2)+2Al\n\nP(2)O(5)+3H(2)O=>2H(3)PO(4)\n\n2KI+Pb(NO3)2=>2KNO(3)+PbI(2)
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Oleic acid ((Z)-9-octadecenoic acid) + Br2 ---> 9,10-dibromooctadecanoic acid \n\nOr: \n\nC18H34O2 + Br2 ----> C18H34O2Br2
802465
carboxylic acid, as represented by -(C=O)-OH. For more info, check the source.
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.........CH3\n..........|\nCH3 - C  - CH2 - CH2 - CH2 - CH3\n.........      |\n........      CH3\n\nPlease ignore the full stops in the above image (which i had to insert to get the correct spacing).\n\nI hope that this helps you.
571092
Esterification is the general name for a chemical reaction in which two chemicals (typically an alcohol and an acid) form an ester as the reaction product. These are commonly used as fragrance or flavour agents.\n\nExamples of esterification reactions include:\n\nHeating to reflux an acid (usually, but not always a carboxylic acid) and an alcohol in the presence of an catalyst forms the ester and water byproduct which can be removed to force the equibilibrium across to the desired products. This method is called Fischer esterification \nFor example, esterification of acetic acid in excess ethanol in the presence of sulfuric acid results in an ester (ethyl acetate). \nH3C-COOH + HO-CH2-CH3     →     H3C-COO-CH2-CH3 + H2O (with the presence of conc.sulfuric acid)\n\nthe reaction of an alkali carboxylate and an alcohol. For example, the reaction of sodium acetate with ethanol. \nH3C-COO- Na+ + HO-CH2-CH3 + H+ → H3C-COO-CH2-CH3 + H2O\n\nThe reaction of a silver carboxylate with a halogenoalkane (presumably driven by the insolubility of the silver halide). \nH3C-CO2-Ag+ + Cl-CH2-CH3 → H3C-COO-CH2-CH3 + AgCl\n\nThe reaction of a carboxylic acid halogenide (which is also called acyl halide) with an alcohol/phenol. \nH3C-COCl + HO-CH2-CH3 → H3C-COO-CH2-CH3 + H-Cl\n\nThe reaction of a carboxylic acid anhydride with an alcohol. (This method is used to synthesize aspirin) \nH3C-CO-O-CO-CH3 + HO-CH2-CH3 → H3C-COO-CH2-CH3 + H3C-COOH
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I don know exactly what you are looking for, but these two will help you on the way:\n\nhttp://en.wikipedia.org/wiki/Ketone\nhttp://en.wikipedia.org/wiki/Ester
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CH3COOH + NAOH =.CH3COONA +H2O
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My IUPAC spelling has gone a bit rusty, but here we go:\n\nn-hexanal \nCH3-CH2-CH2-CH2-CH2-CHO\n\n4-methyl-pentanal\nCH(CH3)2-CH2-CH2-CHO\n\n3-methyl-pentanal\nCH3-CH2-CH(CH3)-CH2-CHO\n\n2-methyl-pentanal\nCH3-CH2-CH2-CH(CH3)-CHO\n\n2,3-dimethyl-butanal\nCH(CH3)2-CH(CH3)-CHO\n\n2,2-dimethyl-butanal\nCH3-CH2-C(CH3)2-CHO\n\n2-ethyl-butanal (might be 3-carbonyl-pentane instead?)\n(CH3-CH2)2-CH-CHO
434220
tert-Butyl isobutyrate ~ 143.7g/mol\nethyl isocrotonate = 114g/mole isocroronate acid = 86g/mole, ethyl = 29, -1 for the H on the acid.\n\nPlease check my math
627842
If you write your ester like this, C2H5COOH, it is not an ester, but a carboxylic acid.\n\nIf you write it as, CH3C00CH3, then it is the ester methyl ethanoate that is made of ethanoic acid and methanol.\n\nIf you write it as, HCOOC2H5, then it is the ester ethyl methanoate that is made of methanoic acid and ethanol.