Serious answer ONLY! If 2 equal opposing forces are pulling - is the center of this activity at zero lbs. ft?
547508
No. \nThe system is static and the sum of the forces equal zero, but there definately are forces flowing through the bar.  Replace the bar with a piece of plastic and then what happens.  The system is no longer in equilbruim, becomes dynamic and the plastic gets torn to shreads.  The same would be true if say you used a piece of wire.  Just because something is not moving does not mean there are no forces flowing through it.
907263
my answer might be childish,but one can understand it easily\nThe gravitational force of earth acting at any point on its surface has a direction towards center of earth.Every matter on the surface is pulled towards the center of earth with this gravitational force.\ndo u know the value of this sticking force acting on every one kg of matter on earth--it is about 10N
230014
We shall apply logic and find answer.\n\nForce is a push or pull.\nWhen A pushes or pulls B, in Physics, we say A exerts a force on B\nWhen A exerts a force on B, three things may happen. 1. B is accelerated.  2. B is moving with constant velocity. 3. B is in rest.\n\nB is accelerated if no other forces except the one exerted by A acts on B. The other two happens when some other forces also act or not even a single force acts. \n \nWe shall consider the first case in which B is acted on by a force exerted by A.\n\nThere are three things which cannot be ignored when we speak of a force.\n1. “A” the one which exerts a force\n2. ‘The Force’ that acts on B.\n3. “B” the one on which the force acts. When the concept of force is understood “B” can a point.\n\n  The statement, “The force acts on B” implies that A is the cause of the force. \n\nHow can A apply a force? Physics answers, ‘Because it has energy to do so,’\n\nWhat happens to A and B when it exerts a force on B\nWhen there are no other forces except the one exerted by A on B, A looses energy and B gains energy.\n\nAs long as A exerts force on B, B is in motion (accelerated) by the force  \nIn Physics we say when a force acts, the one on which the force acts gains energy and the one that exerts the force looses energy and it is seen the gain and loss are equal.\n\n In cases 2 and 3, if we remove the extra forces acting on them the situation reduces to case 1 and the principle persists.
121693
cmon...dont u know basic physics...just calculate the resultant of these 2 forces\nanswer= [(132)^2 + (181)^2]^1/2\nif this makes sense!!
784797
Suppose there is load and two men are pulling it in one direction each one giving a force of 5N.\n\nIn the language of vector, two vectors of magnitude 5 are acting in the same direction,\n\nThe resultant is a vector of magnitude 10N in the same direction. \n\nIf they are pulling it in opposite direction the load will not move.\n\nIn this case the two vectors of equal magnitude are acting in opposite direction.\n\nThe resultant of these two vectors is zero.
524636
If the forces are both acting in the same direction, add them together. = 65 Newtons
955246
If you were right at the center then the symmetry of the situation would mean that you'd be weightless since the gravitational force would be balanced all around.  \n\nSimilar situation if you were just a little off the center.  Most of it would balance except for a little bit.  Think about starting at the earth's surface and moving to the center.  You'd start at your weight and become zero at the center.  Assuming continuity and noting the nice behaviour of gravity then it must decrease in a smooth fashion.  If you continued through your hole to the opposite side you'd weigh the same but in the opposite direction, always pointing towards the center.
830124
Nothin would happen.\nIf you consider two bodies the earth (name it E) and a large mass (m). \ninitially M rests on E. and you lift mass M. the force used to lift it will also act on E.\nAlso if you consider the mass M and E. as a system force exerted on dropping M would be internal and since internal forces do not cause acc. the Earth will not get unbalanced.\n\nThats good for us isn't it...
737218
Given a rotating hub or wheel all the centrifugal forces are along the radii from every point on the hub to the center. Because of circular symmetry, all the these forces will cancel; one pointing up is cancelled by one pointing down. Therefore the net external force is zero; there is no way the linear motion is influenced.
128964
No it is not equal. As we move upwards that is in altitude the gravitational pull decreases.If we go in more depth the the pull decreses. Moving towards the equator also decreases this pull of gravity. It is least at the poles. But for convenience we take the average of all these which comes out to be 9.8.This is also called the acceleration due to gravity.
912606
The simple answer is that the vector sum of the forces acting on an object must be zero if the object is to remain in "equilibrium" or in other words to have constant velocity.
432088
*copied from previous post\n\nYour question is unclear about what set of assumptions you want to use. You seem to imply a perfectly constructed stool, with a perfectly centered force, using incompressible material. You want the stool to have no mass, and you imply that you want to use statics to solve this problem. Strictly applying statics, this system is indeterminate, NOT the ridiculous answer of 0 [N] in two legs and W/2 [N] in the others. There are only 3 equations of equilibrium here, 1 for vertical forces and 2 for moments. Since you have four legs, this system cannot be solved by statics alone. Treating the stool as a deformable structure, you can use geometric compatibility to get a fourth equation. I challenge you to find a competently built stool that has 0 [N] in any leg (a physical stool built of real materials), or an incompetently built stool with 0 [N] in any two legs (unstable system that is obviously not static). The answer indicated as "correct" requires an incorrect application of statics. A large part of studying physics is learning when to use a particular tool, and the physical limits of that tool.
173724
If it is a fixed pulley, you need the same force as the weight of the load which is 9.8*0.2 Newtons (9.8 is the acc. due to gravity and 0.2kg is the mass of the load) or simply 200gf (where gf is gram force). Now you can tell one half of this number.\n\nAlternately, if you have a movable pulley, the force required is half the weight of the load, i.e., 100gf.  You can tell one half of this number too.\n\nIf you need to find the difference between fixed and movable pulleys, look up a physics text (or science text), I am not totally familiar with the schooling system here.   Otherwise, Google should show you pictures of fixed and movable pulleys.
1169884
There is no single place on the rope where one person's energy is changed to the other person's energy.  The entire length of rope holds both person's pulling power with the tension of opposite pulling forces.
37677
its not really a type of force it's just a force that is balanced... like it's in equalibrium because it has another force of equal magnitude going in the opposite direction. such as if there was a 5N force pushing into a wall, it's a balanced force because the system is in equilibrium and the wall is pushing back with a force of 5N.  or if you were pulling on a rope with 8N and it was a balanced force, that would mean that someone else was also pulling with 8N and you aren't going anywhere.\n\nWhen the forces are balanced, that means that there is no net force. this means that whatever the forces are acting on is not experiencing any acceleration, so it's either at rest or moving with a constant velocity(no acceleration).
514076
It's true - gravity pulls harder (i.e. more force) on a more massive (i.e. heavier) object. BUT that object is harder to accelerate - it has more interia. The two effects cancel each other out.\n\nClearly you don't like equations, but putting it in numbers can help:\n\nIf a 1kg object is pulled towards the earth, what will be the force, and what will be the acceleration?\nForce = mass * earth's gravitational field strength\nso Force = 1kg * 9.81N/kg\nForce = 9.81N (or 10N, roughly)\n\nAcceleration = Force / Mass\nSo Acc'n = 9.81N / 1kg = 9.81 m/s^2\n\nNow consider the same for a 10kg object:\n\nForce is now 98.1N (or 100N, roughly)\nSo Acc'n = 98.1N / 10kg = 9.81 m/s^2\n\nSo the acceleration is the same.
977670
If they pull with equal force, then noone will win (assuming the rope isn't moving at the start) if the forces are slightly unequal, then there will be acceleration and someone will win