One More MATHEMATICAL riddle?
549518
How about...\n\n( 3 + (3/7) ) * 7 = 24\n\nThat would be like (21/7 + 3/7)... which is (24/7)... times 7 = 24.
527221
The answer is 2x+7 with a remainder of 32
42951
The next line is 312211. First line : 1\nSecond line describes the first line : One-one (11)\nThird line describes the second line : Two-ones(21)'\nFourth line describes the third line : One-two, One-one (1211).\n\nEtc.\n\nSo, the sixth line would be 3 one's, two two's, and one one = 312211
176413
Great puzzle, took me awhile to make it to f=1, g=4. The letters are from a-i: 9,8,7,2,6,1,4,5,3.\n\nPlugged in this is: (9 * 87 + 2/6) / (14 + 5/3) or (783 + 1/3) / (15 + 2/3) which equals 50.\n\nAnswer logged Sunday, March 12th, 3:20 pm with no other valid answers yet. Sorry to have to write that, but I've seen people change their answers too many times in the past.
304995
1{p+5}/u-6\n\nThe 1 can be distributed into the {p+5}\n\n{p+5}/u-6
1046657
1+1 = 2 OR if you watched A hitch-hikers guide to the galaxy the answer would be 42.
809813
Seen this riddle at least 2 times already... getting old.... \n\nanswer is the other coin is the nickle and the first one is a quarter...
55179
hold on let me look at that for a minute....(dya hate math like this as much as i do?)\n\n(1,4) is one for sure\nyea thats' the only one!!!
527706
B is the only one.\n\nA has 9 which can be divided by 3\nC has 15 also divisible by 3\nD has 40, divisible by 5, 8, 10, 4, 20, and 2
513314
this is a good riddle
974937
please complete the equation
1072717
The riddle is to turn the following into a correct statement with one extra line:\n5+5+5+5=555\n\nYou put an extra line on the first plus sign to make it look like a 4.  The answer is therefore:\n545+5+5=555
1146358
I’m not seeing how this is solvable.  I’m getting two possible answers.\n\nBut here’s how you should work the problem.  \n\nFirst of all, I think you pretty much have to assume that the x,y < 10.\n\nSo we know that Bill can’t tell what his two numbers are just by looking at the product.  As it turns out, there are very few products that allow this to happen: they are 12,16,18,24,36.  So you factor out all the number pairs that would make those products, and the sums are 7,8 (twice), 9, 10(twice), 11(twice), 12, and 13.\n\nSo we know that Albert is seeing one of those sums.  If he sees 7, then he knows that the only way for his numbers to add up to 7, and multiply up to either 12, 16, 18, 24, or 36 is for the numbers to be 3 and 4.  But he says nothing.  Therefore, he isn’t seeing 7.  Neither is he seeing 9, 12 or 13, for the same reason.  So, now we know the sum must be either 8,10, or 11.  And now Bill knows that.\n\nSo, if Bill were seeing 12 as the product, he would know that the numbers were 2 and 6, since they add up to 8.  But he says nothing, so he’s not seeing 12.  Likewise, if he were seeing 18, he would know that the numbers have to be 2 and 9.  But he doesn’t, so he’s not seeing 18, and he can’t be seeing 36 either.  So that means he must be seeing either 16 or 24.\n\nAnd now Albert knows this, so either Albert is seeing a sum of 8, and knows that the numbers are 4 and 4, or he’s seeing 11, and the numbers are 3 and 8.  I just don’t know how to eliminate either of those options.
1102516
by any chance is this a question from your maths homework? lol :D\n\nI cant work it out myself because to put it simple, im crap at maths.
225658
You may have miss-typed the riddle!\nThe question should be:\n8 _ 4 9 1 _ _ 10 3 2 0\nIf that is the case then the answer is:\n8 5 4 9 1 7 6 10 3 2 0\n\nReason: This list of numbers is in alphabetical order
57033
the answer is 3 because a-b|a-b & a-b|a so a-b|b
159634
well lets seeee.... 1 + 3 = 4 and 4 + 6 = 10, so next would be 10 + 9 = ... well i'll just leave that part to you!!