1/a a monomial? If not, what is it?
553656
No, a monomial is a type of polynomial.\nA monomial is a polynomial with only one term.\nPolynomials can only have non-negative integers as exponents.\n1/a = a^(-1)\nThe exponent is negative.\nThus, this is not a polynomial, which implies that it is not a monomial.
439000
Since you cannot factor any binomial to form a monomial, the only factoring you can do is by "common monomial factoring". After that, cancel like factors, but if there are no common factors, that means you cannot factor it anymore.\nExample:\n\n(3x - 3)/(2x - 2)\nyou can get common monomial factors for each:\n3(x - 1)/2(x - 1)\ncancel the common factors\n3/2\n\n(4x² - 6x)/(2x + 10)\n= 2x(2x - 3)/2(x + 5)\n= x(2x - 3)/(x + 5)\n\n(x + 3)/(x + 5)\n---> this cannot be simplified anymore\n\n^_^
465550
Do you mean "zero of a polynomial?" If so, then read on...\n\nA zero of a polynomial is the value or values of the variable (usually x) that cause the polynomial to equal zero.\n\nExample 1: The zero of the monomial 3*x is 0 because 3*0 is zero.\n\nExample 2: The binomial x + 2 has it's zero at x = -2 because if you substitute -2 in place of x, then you get \n---> -2 + 2 = 0.\nTherefore, -2 is the zero of the given binomial.\n\nExample 3: Find the zeros of the trinomial x^2 - x - 6. That is, solve x^2 - x - 6 = 0. If you factor the trinomial, then you get \n---> (x + 2)(x - 3) = 0. \nIn this problem there are two possibilities. Either \n---> x + 2 = 0  or  x - 3 = 0. \nSolving each gives x = -2 or x = 3. Therefore, the zeros of the given trinomial are -2 and 3. \n\nIf you substitute -2 into the given trinomial, then you have the following:\nx^2 - x - 6 \n= (-2)^2 - (-2) - 6 \n= 4 + 2 - 6\n= 6 - 6\n= 0 \n\nIf you substitute 3 into the given trinomial, then you have the following:\nx^2 - x - 6 \n= (3)^2 - (3) - 6 \n= 9 - 3 - 6\n= 6 - 6\n= 0 \n\nThere are no other values of x that will cause our given trinomial to equal zero.\n\nDefinitions\nA monomial is a polynomial with one term.\nA binomial is a polynomial with two terms.\nA trinomial is a polynomial with three terms.\nA polynomial with more than three terms is just called a polynomial.\n\nNote: If you graph a polynomial, then the graph will touch or cross the x-axis at the zeros of the polynomial. Zeros of a polynomial are also called solutions, roots, and, in some cases, x-intercepts.
534496
I think this says\n\n(x^3 - x)/(x^2 - 1)\n\nIf that's the case, then\n\n(x^3 - x)/(x^2 - 1) = x(x^2 - 1)/(x^2 - 1)\n= x
1109416
3/x  + 1    the way you put it..
101183
-1<(or equal to)X <(or equal to)6
763483
If u're asking about boolean "v", then it represents the "OR" function. (And the "reversed v" i.e. "^" represents the "AND" function);\n\n0 v 0 = 0\n0 v 1 = 1\n1 v 0 = 1\n1 v 1 = 1
165420
"Look up the word 'divide'. You cannot divide something by either 0 or 1, ever."\n\nHow about you try a MATHEMATICAL definition of divide.  In math, division by n is defined as multiplication by the inverse of n (usually denoted n^-1 but I'll call it 1/n due to the lack of superscripts).  You are absolutely right that you can't divide by zero.  However, it has nothing to do with splitting into parts.  The multiplicative inverse of n is defined as the number 1/n such that n*(1/n) = 1.  It is a property of 0 that anything times 0 equals 0, therefore the multiplicative inverse of n canot exist.  Thus it is impossible to divide by 0.\n\nDividing by 1, however, is a perfectly legitimate mathematical operation although it tends to be unproductive.  Because 1x1=1, the multiplicative inverse of 1 is 1.  From the definitions above, division by 1 is the same as multiplication by 1, which is most certainly an acceptable mathematical opperation.
107302
If you mean N=(mn)/(m-n)\nThen m=[mn/N]+n\n\nIf you mean N=[mn/m]-n\nThen m=(mn)/(N+n)
535956
A1 k is 0 because the expression got short circuited.  Since i and j are non zero values, the value of the || will always be true, so the right side does not need to be evaluated and k is never incremented.\n\nA2 when you switched to put the || first, no short circuiting can occur (since i and j are non zero, k still needs to be evaluated because of the &&).  The value of m is non-determinate in both cases.
890832
Gary, that's a good one, but one mistake...\nyou said that a=b, thus you cannot divide by (a-b) b/c that equals zero, and you cant divide by zero.
187658
it's defined \n\n0^0=0
901198
answer is 3s. any no. multiply by 1 is the no. itself.
646401
it's the inverse x^-1=1/x
902613
I just plugged this into my calculator.\n\n[1, 0, 2, 0, 2, 0 | 0\n0, 1, -3, 0, -2, 0 | 0\n0, 0, 0, 1, -1, 0 | 0\n0, 0, 0, 0, 0, 1 | 0\n0, 0, 0, 0, 0, 0 | 1 ]\n\nTake it however you want.
664470
Since 1/(a+b+x)=1/a+1/b+1/x\nSo 1/(a+b+x) - 1/x =1/a+1/b\nSo (x-a-b-x)/(x(a+b+x)) = (a+b)/ab\nSo -(a+b)/(a+x+b)=(a+b)/ab\nSo -1/(x(a+b+x))= 1/ab\nSo x(a+b+x) = - ab\nSo x^2+ (a+b)*x + ab =0\nAnalyzing :\n(x+a)(x+b)=0\nEither x = -a\nOr     x + -b
925217
a=48 squared to the monomial power of X