Find a value for k so that 9m^2 - kn^2 will have the factors 3m + 7n and 3m -7n?
552266
that is like a^2-b^2=(a-b)*(a+b), so:\n9m^2-kn^2 must be equal to (3m+7n)*(3m-7n)=(9m^2-49n^2)\n<=> 9m^2-kn^2=9m^2-49n^2\n<=> 9m^2-9m^2+49n^2=kn^2 (we can do this because 9m^2>0)\n<=> 49n^2=kn^2 (also, because n^2>0, it can be divided with itself at both sides so we result in:)\n<=> 49=k
774014
2^3+2*2^2-3(2)-10=8+8- 6 -10 =0\nTherefore x-2 is a factor of the given polynomial
690127
First pull out a common factor in each term.\n\n4y(2n^2 +9n +10)\n\nThen break down the binomial.\n\n4y (2n + 5) (n + 2)\n\nVoila!
781910
not possible to factor easily ... try the quadratic formula.
648589
m varies directly with n means\nm = kn\n144 = k(8)\nk = 144/8\nk = 18
254834
if you use quadratic formula you get the factors of \n\nx= ( ( 3 +/- square rt.(5) ) / -6 )
226307
= 24 k^2   +  6 k^3 +  18k^2  - 54 k^3\n= 42k^2 - 48 k^3\n= 6k^2 (7 - 8k)\n\nif 6k^2 (7 - 8k)=0\n7 - 8k=0\n8k=7\nk=7/8
1017358
K = a^2 * sqrt(3)/4\nK = 16^2 * sqrt(3)/4\nK = (256/4) * sqrt(3)\nK = 64sqrt(3)\n\nANS : 64sqrt(3)cm^2 or 108.8cm^2
810321
you will need to use the quadratic formula since you cannot easily find factors\nfrom the given equation above a=1  b= -7  c=7 (where a,b,c are the co-effiecients of the given eqn respectively)\n\nusing the quadratic formula x= -b(plus or minus) under the square root sign(bsquared- 4ac) all divided by 2a\n\nthen x= -(-7) (plus or minus) under square root sign (-7)(-7) - 4 (1*7) divided by 2(1)\n\nx= 7+ or - square root 49-(4*7) /2\n\nx=7+ root of 49-28 all divided by 2\n\nx=7 +or - root of 21 all divided by 2\n\nx=7+ 4.58 divided by 2\nthen x=5.79=5.8\nor\nx=7-4.58 divided by 2\nx=1.21=1.2\ntherefore\nx=1.2, x=1.8\ni ope u understand wat i ve done\nthe needed symbols and signs arent availabe that is y i wrote sum of the words out\nall the best
1016411
factors\n1=1\n2=2x1\n3=3x1\n4=2x2=4x1\n5=5x1\n6=3x2=6x1\n7=7x1\n8=2x2x2=4x2\n9=3x3=9x1\n10=5x2=10x1\nMultiples\n\n1=1,2,3,4,5,6.......\n2=2,4,6,8,10,\n3=3,6,9,12,15\n4=4,8,12,16\n5=5,10,15,20\n6=6,12,18,24\n7=7,14,21,28\n8=8,16,24,32\n9=9,18,27,36\n10=10,20,30,40
766363
YES...\n\n(7x+1)(x^2+1)=???\n\nyou could use these steps,\n1. multiply the first terms of the given factors, consider the signs\n(7x) * (x^2) = 7x^3\n\n2. multiply the inner terms of the given factors, consider the signs\n(1) * (x^2) = x^2\n\n3. multiply the outer terms of the given factors, consider the signs\n(7x) * (1) = 7x\n\n4. multiply the last  terms of the given factors, consider the signs\n(1) * (1) = 1\n\n5. then add these answers, simply write as one equation, considering the signs\n7x^3 + x^2 + 7x + 1\n\n6. if it happens that there are like terms, simply the equation by adding (or subtracting, whatever is applicable) these\n\nanswer: 7x^3 + x^2 + 7x + 1\n\n\nANOTHER METHOD:\n-you could simply distribute (multiply) the terms in the first factor on the terms on the second factor...\n\n\nfor (2x+6)(x-10) equals 2x-60\n1. first terms: 2x^2\n2. inner terms : 6x\n3. outer terms: -20x\n4. last terms: -60\n\nwriting in one equation: 2x^2+6x-20x-60\nsimplifying like terms: 2x^2-14x-60\nwe can further simplify this by dividing the equation by 2\n\nanswer: x^2-7x-30
256079
x(x^2 -9)= x (x-3)(x+3)
352698
7 & 103\n\nYou can go here to find the prime factors for any number:\nhttp://www.acme.com/software/factor/
716901
You can use polynomial long division to find the value of k. Be very careful! For the first expression, after dividing the numerator by the denominator a remainder of  8 - 4k  is obtained. Set this equal to zero to find the desired value of k.\n\nTo review polynomial long division, see:\n\nhttp://en.wikipedia.org/wiki/Polynomial_long_division
830444
d.) 2m^2(6m^6+3m^4+7)
801198
k + 9 = 6k - 66\n5 k = 9+66 = 75\nk = 15
606164
E = k*q/r^2\n\nk = 9 * 10^9\n \nq = 21 * 10^-6\n\nr = .7