( ) (a+10)=a^2+8a-2... show work find the binomial to complete please show ur work thank?
550823
wow, if you typed in the question correctly, it's going to be tough to solve...maybe even impossible, are you sure that the result isn't supposed to be a^2 +8a -20?  (perhaps you left off the zero at the end of the two??)\n\nif that's the case, then the answer is (a-2)(a+10)=a^2+8a-20\nhere's how to get this answer, and again, i'm making the assumption that 2 should be 20 instead...\n\nyou know from (a+10) ... = a^2... that you're going to need something multiplied by a that gives a^2, so the only possible choice is a\n\nnow you have (a   )(a+10)=a^2 +8a -20 since the 20 has a negative sign before it, you know that something times a positive 10 needs to give a minus 20, so -2 works.  and conveniently when you have (a-2)(a+10) you get a^2 +8a -20.  \n\nuse the FOIL method (first, outer, inner, last)\n\nthe first terms (a and a) multiplied is a^2, then the outer (a and 10) gives 10a  then the inner (-2 and a) gives -2a and the last (-2 and 10) gives -20 \n\na^2 + 10a -2a -20 is the same as a^2 +8a -20.
774014
2^3+2*2^2-3(2)-10=8+8- 6 -10 =0\nTherefore x-2 is a factor of the given polynomial
911039
12x^2-10x-8\n=2(6x^2-5x-4)\nsplitting the middle term -5 into\n-8 and +3 so that the sum is -5 and\nthe product is -24\n=2(6x^2-8x+3x-4)\n=2(2x+1)(3x-4)
3037
This is not presented as an equation, so the goal appears to be to combine the rational expression --> x+10 \nThat's all you can do with the question as it is written.
735754
just plug the numbers in.  if y=8, and x=2, \nits 8=a(2^2)\nso 8=a(4)\nso a=2.\nhope that helps!
269006
Ask your friends if they can find the error in the following proof.\n(it's obviously not right, but it looks cool!)\n\na=b\na+1 = b+1\n(a+1)^2 = (b+1)^2\na^2 + 2a +1 = b^2 + 2b +1\ncancel the ones and rearrange\na^2 - b^2 = 2(b-a)\n(a+b)(a-b) = 2(b-a)\ntherefore a+b = -2\nPick numbers for a and b\nand look!! 5 + 7 = -2\nThus shown.\nLOL
387267
Factor a^2 + 8a + 16\na^2 + 8a + 16 = \n(a+4)(a+4) =\n(a+4)^2\nNow \n(a^2)+8a+16-(b^2)\n= (a+4)^2 - b^2\nThis is a difference of squares.\n(a+4+b)(a+4-b)
38366
I think this is the answer\n\na^2-2ab-b^2\n-a^2(b-b^2)\n= -a^2
62277
first, distribute the 2a to the things in the parentheses:\n\n5a + (2a * 5 - 2a * b)\n\nthen, follow pemdas:\n\n5a + 10a - 2ab\n\nwhich equals:\n\n15a - 2ab
749939
Nobody can help you because it's false.\n\nLet a1 = 1, a2 = 4, b1 = 2, b2 = 3, and n = 7\nThen a1 + a2 = 5, b1 + b2 = 5\nBut a1*a2 = 4, while b1*b2 = 6.\n\nYou are talking about modular arithmetic, right?
847698
Are you looking for help on how to do these so that you can do them on your own, or are you just here looking for answers? \n\nb² - 3b - 10 = (b-5)(b+2)\n\n15x³ - 29x² + 8x =\nx(15x² - 29x + 8) =\nx(5x-8)(3x-1)\n\na² - b² + 9a - 9b =\n(a+b)(a-b) + 9(a-b) = \n(a+b+9)(a-b)\n\n-5b + 35 =\n-5(b+7)
980081
That isn't an algebra 'problem'. Perhaps you were asked to expand it?\nIn which case, (8-√10)(5-√10) = 8*5 - 5√10 - 8√10 + √10*√10 = 40 - 13√10 + 10 = 50 - 13√10.
130182
The difference of two sqares can always be factored in the form of a^2 – b^2 = (a+b)(a-b)\n\nSo it follows that a^2 – 9 = (a+3)(a-3) So now you have\n\n(a+3)(a-3)(4a)\n-----------------\n(8a)(a-3)\n\nCancel out the (a-3) in the top and bottom, and also the a’s in the 4a & 8a.  Also, the 4 cancels with the 8 and leaves a 2 in the denominator.  So your simplified answer is\n\n(a+3)/2
16175
=9x^2+6x+1\n\nsince (a+b)^2=a^2+2ab+b^2\n\nhttp://www.algebrahelp.com/lessons/
574841
-2(x+10)=3(2x-4)\n-2x-20 = 6x-12\n-2x = 6x+8\n-8x = 8\nx = -1
249039
6\n\nx^2 - 10 = 4x +2\nx^2 -4x - 12 = 0\n(x-6)(x+2) = 0\nx = 6 or x = -2\n The Positive # is 6
1047514
x^3 + 5x^2 - 8 divided by x -1 is:\n\nx^2 + 6x + 8\n\nor...\n(x + 2) (x + 4)\n\ndon't listen to byh. sorry I can't show you HOW to do the problem. I just couldn't figure out how to in type.