plz help, i have algebra homework and i can't figure it out i've been working for 2 hours, any1 plz help
554172
Um...\n\n2(-X) + 3(-X) + X + 8\n\n-2X - 3X + X + 8\n\n-5X + X + 8\n\n-4X + 8\n\n8 - 4X
1151667
I am not sure what class you are taking, this question can be important for anything from algebra to calculus, and beyond.\n\n0.) This is kind of cheating, but usually, an exercise in the book uses something from the section that you just did.  So try to make sense of it in terms of that.  Like if you were doing quadratic equations, and the problem has an exponent of 4 or 6, think of how you could change that to a square. Example: you've just learned how to factor the difference of two squares, and the problem they give you is (x^6-25)=0.  You don't need to freak out and say "What do I do with a six?  Think about how to write the problem as something you know. Well, if you just learned how to  factor the difference of two squares, then try to find the difference of two squares.  Notice that x^6=(x^3)^2, so you get (x^3-5)(x^3+5)=0.  The solution is the cubic root of plus or minus 5. \n\nDon't be too quick to start writing stuff.  Read the problem.  Take a deep breath.  Stop and think of what the answer might look like when you are done, and also how you would know you are done.  Now see what steps you can take to get there. \n\n1.) For many expressions there is a standard form to write the expression.  This is helpful in order to see if two expressions that look different are the same.  This is the reason proper fractions are prefer ed to improper fractions, square factors are factored out from radical signs, polynomials are written in descending order.\n\n2.)Parentheses are your Friend.  When in doubt, more is better, you can always take them out later.\n\n3) Remember: My Dear Aunt Sally.  If there are no parentheses, then multiplication is the first operation, followed by division, addition and subtraction.  More complicated operations are done before less complicated, so trig functions and exponents take precedence. \n\nBe careful with trig functions and exponents.  An exponent after the argument means the argument is exponentiated first.  If you are supposed to exponentiate the result, then the exponent goes after the trig function name.\n\n4.) My favorite trick is to underline similar terms,  I will use a different number of lines for each term.  I might use one line for variables with a power of 4, two lines for variables with a power of two, wavy lines, zigzag lines.  This is a shortcut, which allows me to simplify more than one thing at a time.  I also use these underlines to group things, also you can vary your grouping symbols, parentheses, braces, brackets.  These techniques are also useful when there are nested parantheses.\n\n5.)  A quick and easy check for your work is to substitute numbers into your original expression and your final answer.  Pick easy numbers, like zero, -1, 1.  Sometimes larger numbers make more sense.  Like if I have a denominator of 23 I might pick 46 as a substitution.  Be sure to try several numbers, bith positive and negative.\n\n6.) Don't be afraid of baby steps.  The answer may not be immediately obvious, and you might need to try different arrangements of things before you see a simplification.\n\nI hope these steps are helpful, and by the way, I learned calculus before calculators became common.  I think that graphing things by hand and factoring help me see patterns that I would miss when using a calculator.  Also, I just make more mistakes with a calculator.\n\nCould just be because I am a fossil, but use the techniques that are most comfortable for you.
70409
Go back to math class and figure it out!
950092
Do a Yahoo search.  Enter "Homework help, math."  There are bunches of web sites.  Good luck.
771776
http://mathforum.org/dr.math/\n\nThis is Ask Dr. Math, a website that can offer help for general math through Algebra and beyond. There are other good websites for math out online, type in keywords,  homework  math help and see all that you come up with. Eventually you will find one that can walk you through most problems. Good luck.
1102516
by any chance is this a question from your maths homework? lol :D\n\nI cant work it out myself because to put it simple, im crap at maths.
271001
9 hrs and 38 min. You worked 14  min from 7-8. then from 8-2 is 9 hrs. You worked 24 min from5-6 so you add it up.\n9hrs+ 14min+24 min= 9hrs and 38 min.
189233
The problem with this type of algebra problem is that it's hard to know the syntax (grammar) of the problem if it's just written out in words. For example, is it 2x - 9, all over x, or is x the denominator only for 9? It's confusing!So in the future, to make it clear, use brackets like this:\n\n****IF I am reading your problem CORRECTLY****, I would write it as:\n(((2x-(9/x))^2)-4) - (((x-(7/x))^2)-4) = ?\n\nBut put aside the whole brackets thing for a minute. \n\nNow, normally, it helps to break down the math probelem into parts, but it looks like you're learning to do exponents. If this is the case, you must have learned that exponents allow you to work certain problems quicker without having to break down the problem into small parts and solving them seperately. To remember what those exponent rules are, try both the links at the bottom of this post. You'll use exponent rules all through your life, so know them!
893957
well darling ;\nimagine this like that\n\ny^2 + ( a+b)y + ab \nyou need to find " a+b " & " ab" \nin our function \na+b = 16 & ab = 64 \n( y + a)( y + b) \n( y + 8 ) ( y + 8)\n{ ' 8 + 8 = 16 '   &  ' 8 * 8 = 64 ' }\nso\n( y + 8)^2\n\nGood Luck sweetheart.
807552
ok first you have to distribute on each side, remember to watch the (-) (+) signs.\n\n- 4 (x + 2) - 11 = 2 (- 2x -3) - 13\n_________________________\n  -8x + (-8) - 11= - 4x -6 - 13\n\nnow that you are done distributing the 4 and 2, you must start isolating the X's, I like the x on the left, and so will work it that way. it makes no difference though....if you like it on the right, that is fine too. so I will start with the 4, and remember whatever you do to one side you must do to the other. \n\n    -8x + (- 8) - 11 = -4x - 6 - 13\n    +4x                     +4x\n__________________________\n     -4x + (-8) -11= - 6 -13\n\nremembering you cannot subtract with positive and negative numbers  so be careful of the signs and change/change the subtraction to plus signs. so let's do that next.\n\n  -4x + (-8)  + (-11)= -6 + (-13 )\n\nnow that you have changed the signs as above, do the operations on both sides.\n\n   -4x + (-19) = (-19)\n\nnow yo umust further isolate the X, so move the (-19) from left to right, again what you do to one side you must do to the other.\n\n    -4x + (-19) = (-19)\n             +19     + 19\n________________\n              -4x  = 0\n\nnow divide out the  -4, which into zero is zero, therefore x= 0, thus any number plugged in for the x would result in an "x=0" answer. \n\nhope this helped, for more help ask yahoo answers, or try www.purplemath.com, it is a great math site!
968026
I got   3(x² - 5x + 4) or 3( x - 4 )( x - 1 )\n\nLet me show you my work...\n\n3( x - 2 )² - 3(x - 2) - 6\n\nSimplify\n\n3( x -2 )( x - 2 ) - 3( x- 2 ) - 6\n\nDistribute\n\n3( x² - 4x + 4) - 3x + 6 - 6\n\nDistribute and Simplify\n\n3x² - 12x + 12 - 3x\n\nSimplify\n\n3x² - 15x + 12\n\nYou can now simplify by factoring out 3\n\n3(x² - 5x + 4)\nor\n3( x - 4 )( x - 1 )
195201
i think u typed the question wrong, can u please correct it and if u have 2 unknowns, please give 2 equations, else u cant get a definite solution
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Try going to this website. The will explain it step by step and you can ask all the math questions you want. www.algebra.com
395445
Your looking for the time they work together so let (x) the time they work together .the rate should be A=15,B=5 then the work should be A=x/15 and B=x/5 since your looking for the time...solve for it cause I'm not giving you all the answers. it should look like this \n\nx/15+x/5= the time they work together...\n\n(Next time listen to your teachers)
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It *is* awfully hard to write algebra expressions on Yahoo Answers, isn't it? Oh well, we do what we can.\n\nAddressing your first question, let's write it out like a long division problem.  You'll have to imagine the horizontal bar above the larger polynomial, because I can't format it properly here:\n\nx^2 + 3x - 2  )  x^4 + x^3 - 5x^2 + 13x - 6\n\nOur first step is to look at the first term in each polynomial, and divide the smaller into the larger.  x^4 / x^2 = x^2, so the first term we write in our quotient (above the bar) is x^2.  You can write it directly above the x^4, if you wish, or above the 5x^2 term, your preference.\n\nNow, we're going to multiply that "partial quotient" by the entire divisor (x^2 + 3x - 2), which gives us x^4 + 3x^3 - 2x^2.  Write that "partial product" below the first three terms of the original dividend (x^4 + x^3 - 5x^2).  Our next step is to subtract the partial product: (x^4 + x^3 - 5x^2) - (x^4 + 3x^3 - 2x^2) = -2x^3 - 3x^2.  We then drop down the next term from the dividend, the 13x term, and repeat:\n\n-2x^3 / x^2 = -2x (add that term to our quotient)\n\n-2x * (x^2 + 3x - 2) = -2x^3 - 6x^2 + 4x\n\n(-2x^3 - 3x^2 + 13x) - (-2x^3 - 6x^2 + 4x) = 3x^2 + 9x\n\nFinally, we drop down the last term from the dividend, -6, and repeat once more.  I'm sorry that I can't write this out the way your math book can... I really hope Yahoo Answers creates some sort of way of inputting formulas, or at least monospacing text entry!\n\n3x^2 / x^2 = 3 (so we add a +3 term to our quotient)\n\n3 * (x^2 + 3x - 2) = 3x^2 + 9x - 6\n\n(3x^2 + 9x - 6) - (3x^2 + 9x - 6) = 0... no remainder!\n\nSo our final quotient is x^2 - 2x + 3, with no remainder.\n===\nNow, when doing the 2nd problem, you'll want to write the larger polynomial, the dividend, as x^4 - 3x^3 + 0x^2 + 6x - 5.  We incorporate that extra 0x^2 term so that we never find ourselves trying to subtract unlike terms.\n\nSorry there's no better way to write this out on Yahoo Answers.  Hope that helped anyway!
268888
I think I can do this one...I'll get right back to you when I figure it out... *grabs a pen and paper...and also tries to figure out why people are answering, saying simply that they can't or won't answer your question*\n\nEDIT...k, here's what I got...not sure if I understood what your question was asking, so I may be mistaken...\n\nm=h(x)-2x\nk=(2-3h(x))/6x
895063
Google the word algebra help.  Purple math is great, but there are other sites also.  I am sorry I do not have the names at the moment.