A prism has a volume of 24 cubic inches. What is the volume of a pyramid with the same base area and same heig
553954
Base times height gives the volume of the prism.\nVolume of prramid= 1/3 x base x height =1/3 x 24=8 cubic inches.
691993
density=mass/volume\n5.3=371/v\n0.014cm cubed=v\napproximately
192399
In the front?  You have to consider the whole cube to find volume.  Volume = base area * height  You could find the surface area of one side, but you'd need to know the side length.
765627
C=2(Pi)r or diameter times Pi\nI don't know how to solve the problem cause not enough info is given. Does it say what C equals?\n\nv = lwh . H stands for the height. Does it say what v equals?\n\na= 1/2h(b1+b2) b1 is base 1. Does it say waht the area is?\n\nProvide more info please. :)
625137
Volume is L * W * H ... if the Volumen is 1000^3 and it's a cube, then L, W and H all = 1000cm\n\nDuh.
138294
It would be a pentagonal pyramid because its base would have 5 edges (10 divided by 2 = 5). Prisms and pyramids are alike because with the exception of their bases, all other faces are the same shape (triangles for pyramids, rectangles for (right) prisms.
872528
1.) The cylinder with the lowest surface area per unit volume will be cubelike. \n\nSurface area for a cylinder is 2πr^2 + 2πrh, where the 2πr^2 is for the base, and 2πrh is for the tube itself.\n\nOn a similar cube, the base would be 2 sides (top and bottom), and the tube would be remaining 4 sides. Thus, for a cubelike cylinder, 2πrh will equal 2 * 2πr^2 (since the tube accounts for twice the area as the base).\n\n2πrh = 2 * 2πr^2\nh = 2r (h/r = 2 for your ratio)\n\nV = πr^2h = 2πr^3\n1000 = 2πr^3\n500 / π = r^3 = 159.15\nr = 5.419 cm, so h = 10.838 cm\n\nSA = 2πr^2 + 2πrh = 2πr^2 + 4πr^2 = 6πr^2\n6πr^2 = 553.52 cm^2 \n\nCheck:\nr = 5.418\nV = πr^2h = 1000\nh = 1000 / π * (5.418 ^2) = 10.844\nSA = 2πr^2 + 2πrh = 2π (5.418 ^2) + 2π (5.418 * 10.844) = 553.60\n\nr = 5.42\nV = πr^2h = 1000\nh = 1000 / π * (5.42 ^2) = 10.836\nSA = 2πr^2 + 2πrh = 2π (5.42 ^2) + 2π (5.42 * 10.836) = 553.56\n\nWithout the diagram, it'll be hard to answer 2 and 3.
18353
There are many possibilities, but the one using whole numbers is a pyramid with a square base that is 3cm. on each side and has a height of 10cm.\n\nVolume = (length x width x height)/3
325762
Volume of pyramid = 1/3 x base area x height\nArea of trapezoid = 1/2 x sum of parallel sides x height\n1/3 x [1/2 x (20 + 28) x h] x 36 = 3168\n...\nh = 11 cm.
811463
The surface area of any prism equals the sum of the areas of its faces, which include the floor, roof and walls. Because the floor and the roof of a prism have the same shape, the surface area can always be found as follows:\ncall the 'floor' the 'base'. The height of the prism = 'H'.\nThe surface area of a prism = 2 × area of base  +  perimeter of base × H\n\nexamples:\n\nRectangular based prism:\nBase shape: Rectangle, length 'L' and width 'W'\nArea of base: L  × W\nPerimeter of base: 2(L+W)\nSurface area = 2LW + 2(L+W)H\n \nCircular based prism\nBase shape: Circle, radius 'R'\nArea of base: pR²\nPerimeter of base: 2pR\nSurface area = 2pR² + 2pRH\n\nTriangular based prism\nBase shape: Triangle: base 'b', height 'h', and sides S1, S2 and S3 \nArea of base: ½b×h\nPerimeter of base: S1+ S2 + S3\nSurface area = bh + (S1+ S2 + S3)H\n\nAs for lateral area of a cone , If r is the radius of the base, h is the altitude, and l is the length between the vertex and a point on the base circle \nlateral area pi rl=pi r x sq.root of r to the power 2 + sq.root of h to the power of 2\n or try this site- http://www.mathepower.com\n\nThe lateral area of a prism is the sum of the areas of the lateral faces (all the ... How many lateral faces does this prism have?\nWhat is the area of each \n\nelse there are many sites to giv better details matching ur specific figure ...try google for search..all luck..
10703
Volume of a pyramid = (1/3)(area of base, which is a square) * height\nSo 30cm^3 = (1/3) (s^2)(h) Multiply by 3 to clear the fraction --> \n90cm^2 = s^2(h)\n\nNow the problem is that we have one equation for two unknowns. We cannot arrive at one definite solution because there are infinite possibilities. \nSo we can get some possible dimensions by assigning a value to one dimension and then working out the other one. \n\nFor example, if the sides of the botom are 1 cm, then the height is 90\nIf the sides are each 3, then the area of the base is 9 and the height is 10.
342254
The volume V of the sphere is the sum of the volumes of all the "almost pyramids" with bases B1, B2, B3,........\n\nV = 1/3B1r + 1/3B2r + 1/3B3r + 1/3B4r + ........\nV = 1/3r( B1 +B2 + B3 + B4 + ......)\n\nThe sum of the bases is the surface area (S.A.) of the sphere. The volume V is 4/3¶3. Substituting,\n\n4/3¶r3 = 1/3r * S.A.\n\nTo solve for the surface area, multiply both sides by 3/r.\n\n3/r * 4/3¶r3 = 3/r * 1/3r * S.A.\n4¶r2 = S.A.\n\nSphere Surface Area Formula:\nThe surface area SA of a sphere with radius r is 4¶r2.\nS.A. = 4¶r2
374445
sphere has no vertices\n\narea of prism is:\n (area of base)*2 + (perimeter of base)*height.
421382
a pyramid. 3 sides and the bottom is 4 sides. but only 3 corners.
508516
Surface Area Formulas\nIn general, the surface area is the sum of all the areas of all the shapes that cover the surface of the object.\n\nCube | Rectangular Prism | Prism | Sphere | Cylinder | Units\n\n\nNote: "ab" means "a" multiplied by "b". "a2" means "a squared", which is the same as "a" times "a".\nBe careful!! Units count. Use the same units for all measurements. Examples\n  Surface Area of a Cube = 6 a 2  \n\n\n (a is the length of the side of each edge of the cube) \n\nIn words, the surface area of a cube is the area of the six squares that cover it. The area of one of them is a*a, or a 2 . Since these are all the same, you can multiply one of them by six, so the surface area of a cube is 6 times one of the sides squared. \n\n \n\nSurface Area of a Rectangular Prism = 2ab + 2bc + 2ac  \n\n (a, b, and c are the lengths of the 3 sides) \n\nIn words, the surface area of a rectangular prism is the are of the six rectangles that cover it. But we don't have to figure out all six because we know that the top and bottom are the same, the front and back are the same, and the left and right sides are the same. \n\nThe area of the top and bottom (side lengths a and c) = a*c. Since there are two of them, you get 2ac. The front and back have side lengths of b and c. The area of one of them is b*c, and there are two of them, so the surface area of those two is 2bc. The left and right side have side lengths of a and b, so the surface area of one of them is a*b. Again, there are two of them, so their combined surface area is 2ab. \n\n  Surface Area of Any Prism \n\n\n  (b is the shape of the ends) \n\nSurface Area = Lateral area + Area of two ends \n\n(Lateral area) = (perimeter of shape b) * L \n\nSurface Area = (perimeter of shape b) * L+ 2*(Area of shape b) \n\n  Surface Area of a Sphere = 4 pi r 2  \n\n\n (r is radius of circle) \n\n  Surface Area of a Cylinder = 2 pi r 2 + 2 pi r h \n\n\n (h is the height of the cylinder, r is the radius of the top) \n\nSurface Area = Areas of top and bottom +Area of the side \n\nSurface Area = 2(Area of top) + (perimeter of top)* height \n\nSurface Area = 2(pi r 2) + (2 pi r)* h \n\nIn words, the easiest way is to think of a can. The surface area is the areas of all the parts needed to cover the can. That's the top, the bottom, and the paper label that wraps around the middle. \n\nYou can find the area of the top (or the bottom). That's the formula for area of a circle (pi r2). Since there is both a top and a bottom, that gets multiplied by two. \n\nThe side is like the label of the can. If you peel it off and lay it flat it will be a rectangle. The area of a rectangle is the product of the two sides. One side is the height of the can, the other side is the perimeter of the circle, since the label wraps once around the can. So the area of the rectangle is (2 pi r)* h. \n\nAdd those two parts together and you have the formula for the surface area of a cylinder. \n\nSurface Area = 2(pi r 2) + (2 pi r)* h \n\n  \n\n\nTip! Don't forget the units.  \n\n\nThese equations will give you correct answers if you keep the units straight. For example - to find the surface area of a cube with sides of 5 inches, the equation is: \n\nSurface Area = 6*(5 inches)2 \n\n= 6*(25 square inches) \n\n= 150 sq. inches
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tsniperx\n2 months ago\n\nVolume of one block cube = 10cm*10cm*10cm = 1000cm^3\nVolume of two block cube = 2000 cm^3\nVolume of one sphere = (4/3)*pi*r^3 = (4/3)*pi*(5cm)^3\nVolume of one sphere= 523.59877 cm^3\n\nno spheres= Volume of clay / Volume of sphere= 2000cm^3 / 523.59877cm^3\nNo spheres must be integer = 3 spheres
663486
Diagram here:\n\nhttp://mathworld.wolfram.com/TriangularPrism.html\n\nto solve for its volume, calculate for the area of the triangle bottom and multiply it by the height of the prism.\n\nTo compute for surface area, compute for the area of the 3 rectangular faces and add the area of the 2 triangular faces.