half the square root of twice a number is 5. find the number.?
539012
1/2 * sqrt(2x) = 5\n\nsqrt(2x) = 10\nsqrt(2x)^2 = 10^2\n2x = 100\nx = 50
797591
2...... 2....... 2 (2 is the square root)\nx  =17 .. +  ..10\ndo the same for the next one\nu can solve the equation ,I know u can
726721
2 = 2000 * 5\n\n2 = 10000\n\n2/2 = 10000/2\n\n1 = 5000
1144250
2) new-old divided by old\n3) find the square root first\n4) i think its 184... not sure\n5) Distribute 3 to 4x and 4 to get 12x+12 and the 2 tho 5x and 9 to get: 12x+12+10x+18-12 Then simplify (I'm not gonna do all ur work 4 u!)
256804
5x^2  -10 x +5\ncan be factorised into (x-1)(5x-5)\nsimplified to 5(x-1)(x-1)\n\nthus square root of given sum becomes square root of \n5(x-1)^2\n\nwhich is (x-1)*5^1/2
107941
64(sqrt7*sqrt5)/4*sqrt7\n(64/4=16 and sqrt7 is cancelled)\ntherefore, the answer is 16*sqrt5
522997
ok, lets say that Sqrt() means square root \n\nSqrt(2x-5)=13   , elevate both sides of the equation to square\n (Sqrt(2x-5))^2 = 13^2  , the square root and the square power cancell each other, so\n\n(2x-5) = 169\n2x = 164, x = 82\n\nThe second one is the same, only that you have to leave the square root alone in the left side of the equation\n\nsqrt(3x-5)+7 = 3 , \nsqrt(3x-5) = -4\n\nand do the same as the first one\n\n3x-5 = 16\nx = 7\n\nthe last one is a bit harder cause there's an 'x' outside of the square root, and you do it like this\n\nsqrt(x+2) = x - 4    , elevate both sides to the square\n\n(x+2) = (x-4)^2    , and do the special product \n(x-4)^2 = x^2 -8x + 16 , then you get\n\n(x+2) = x^2 - 8x + 16 ,  this is a quadratic equation, take it to the general form\n\nx^2 -9x + 14 = 0    and factorize\n\n(x-7)(x-2) = 0  then you get\n\nx1 = 7 and x2 = 2 \n\nthat's it, if you have doubts contact me
372531
first simplify the square root of 1/25.\nthe square root of 1 is one, and the square root of 25 is 5.  that leaves it to 1/5.  then multiply 5 to it - 5 X 1/5 = 1.\ngood luck!
117989
do it like grade 5 - 1 see - \n[X-(1/5X)^2] sqrt\n    (1/5X)^2 \n     1/25 (2X) \n[X-1/25(2X)]sqrt\nX=4 , understand
858963
The answer is actually much more complex than one would think! The correct answer though is ...\n\n((2^n)(n-.5)!)/(2(.5!))\n\nThat looks kind of messy, so in English that is "2 to the n times n minus 1 half factorial over 2 times 1 half factorial."\n\nPlugging in 1,3,5,7 for n on a graphing calculator, we get 1,3,15,105, which are the correct first four terms in the sequence.
651147
The easiest way to find the number half-way between two numbers is to simply find the average of the two numbers.  In other words, add the numbers together and divide by 2.\n\nIn your example, -5 1/5 + 8 2/3, after finding a common denominator and reducing, is equal to 1 and 11/15.  To find what number you need to add to -5 1/5 to get this number, simply subtract them.  (Answer is 6 14/15)
545883
(a^2  - 5) * (a^2  - 2)
258864
there is a method of getting the square root of any number!!\n\nfirst, group the digits in two's, starting from the decimal pt.\n\n1'23'45'43'21.00'00\n\nThen, do the ff:\n1.Get the sq.root or the nearest sq.root of the first group of digits (sqrt3=1, sqrt5=2), that is the first digit of your square root.\n2. Square that number and subtract it from the first group of digits. Bring down the first digit of the next pair of digits.\n3. Multiply the digits of your sq.root by 2 and use this as the divisor of the numbers you brought down. this will be the next digit of your sq.root. Put it next to the previous digit.\n4. then, multiply, and subtract, just like in division. Bring down the next digit of the pair.\n5. Square the so far last digit of the sq.root, and subtract this from the brought-down number.\n6. Repeat the steps until the right decimal pt.\n\nThus,\n\nsqrt1'23'45'43'21\n\nsqrt1 = 1 (1st digit)\n1x1 = 1\n1 - 1 = 0\nBring down 2\n\n1x2 = 2\n2/2 = 1 (2nd digit)\n1x2 = 2\n2-2 = 0\nbring down 3\n1² = 1\n3-1 = 2\nBring down 4\n\n11x2 = 22\n24/22 = 1 (3rd digit)\n1x22 = 22\n24-22 = 2\nbring down 5\n1²=1\n25-1=24\nBring down 4\n\n111x2=222\n244/222=1 (4th digit)\n1x222=222\n244-222=22\nBring down 3\n1²=1\n223-1=222\nBring down 2\n\n1111x2=2222\n2222/2222=1 (5th digit)\n1x2222=2222\n2222-2222=0\nBring down 1\n1²=1\n1-1=0 STOP..\n\nThe answer is 11111.^_^
935133
Ok, take it back.\n\nFlip the 6, turn it into a 9.  Move it over to the right hand side, move the 2 to an exponent over the 7.\n\n7^2 = 49.\n\nThat's it.
54004
11\n\n\n11 multiplied by 11 equals 121. So, the square root of 121 is 11.
590233
Hint:\nDo a simple substitution u = x-5\nWhich means x = u + 5\n\nYou should get\n\n(2/5)(x-5)^(5/2) + 2(x-5)^(3/2) + C
223105
Without calculators it's not easy but you find the number that multiplied by itself equals your number.  For instance the square root of 25 is 5 because 5 times 5=25.  16 is 4... 4 times 4=16