what should be the velocity of water through the filtration media of a Dual Media Filter?
541057
The best answer would come from the manufacturer.
601468
The answer is (d) if this is the question:\n\nInitially the tank is full.  The outlet pipe is opened.  When the water in the tank is 3/4th full, both inlet pipes are opened.  Calculate the fractional level of the water in the tank after 2:05 hr.\n\nSince inlet A and outlet C cancel each other out at 50L/hr, only need to consider inlet B at 25L/hr.  Since 2:05 hr is the same as 2.083 hr (5 min = 0.083 hr), the amount of water added by inlet B is 25L/hr * 2.083 hr = 52.08 L.  Will use 52 L in the calculation.\nThe total amount of water in the tank after 2:05 hr is the initial 750 L + 52 L = 802 L.\nThe fraction level of the water is 802 L / 1000 L = 0.802\nSince 4/5 = 0.8 the answer is (d).
505475
"Direct Transfer-Immersion\nMembrane Filtrartion - open system\nMembrane Filtrartion by Millipore Steritest Methodä -a closed system"
791045
The volumetric flow rate is proportional to the pressure at the bottom (which is rho*gh, or density times gravity times fluid height) and to the area of the orifice (which is pi*r^2, where r is the radius, 1 mm = 0.001 m).  There is a valve constant involved, which you can assume is equal to 1 if you're not given additional information.
288332
I'm surprised that whomever tested it didn't also recommend a filtering system.  You're probably looking at buying a reverse-osmosis filtering system with a carbon-block add-on.  You'll spend upwards of $500 but it will allow you to drink your water again.\n\nReverse osmosis works by forcing the water molecules through tiny pores--anything larger than the water molecule is "brushed off".  (That's not a great description but the best I can do w/o coffee.)\n\nYour local home improvement center can walk you through the steps of choosing and installing.  I did mine myself in about 4 hours.  And if *I* can do it, you can.  ;-)
56978
water, water and more water
1140416
you need to employ th ebournoulli equation and the fanninf (or darcy ) friction factor equation ... \n\nThe Darcy-Weisbach Equation for pressure loss due to friction (in the SI metric system) is:\n\nΔP = 4f(L/D)(ρ v2)/(2 gc)\n\nwhere: \nΔP = pressure loss in Pascals \nf = Fanning friction factor (dimensionless) from Moody's diagram \nL = pipe length in meters \nD = pipe diameter in meters \nρ = fluid density in kilograms per cubic meter \nv = fluid velocity in meters per second \ngc = gravitational conversion constant = 1 (kg-m)/(N-s2) in the SI metric system\n\nAnd for head loss due to friction, the equation is:\n\nΔh = f(L/D)(v2)/(2 g)\n\nwhere: \nΔh = head loss in meters \nf = friction factor (dimensionless) \nL = pipe length in meters \nD = pipe diameter in meters \nv = fluid velocity in meters per second \ng = local gravitational acceleration of 9.807 m/s2
67284
well the formula is the square root of 3kT/m  where k is the boltzman constant(1.38066 x 10^-23 J/K) T is in Kelvin so you would have to convert(just add 273 to the temp in Celcius) so your T is 290K and m is the mass. the mass can be found using the density of water(1000 kg/m3) the formula for density is d=m/V and V can be found by using the volume of a sphere, 4/3(pi)r^3 oh, and don't forget to convert the nanometers into meters, then cut the diameter in half for radius.\nusing this information to get you started, you should be able to do it yourself. so you should try it first before reading further :) im sure you were familiar with all of those formulas, you just need to remember to think of things all at once so you can put them together.\n\nok, so we start with the rms velocity formula. first problem is that we need mass. ok, lets solve for mass using density. oh right, we need volume, ok, lets solve for volume then:\nwe need to make the diameter into meters, so thats 1.0 x 10^-8 meters. now we cut this in half to get the radius(r) so that's 5.0 x 10^-9.\nV=(4/3)(pi)r^3\nV=(4/3)(3.14159)(5 x 10^-9)^3\nV=5.236 x 10^-25 m^3\nnow we have volume, so using the density of water(1000 kg/m3), we can solve for mass:\nd=m/V\n1000=m/(5.236 x 10^-25)\nm=5.236 x 10^-22 kg\nok, now we have mass, so we can use our original rms velocity formula and solve for velocity. *sigh* finally.\n\nv(rms)= sqrt[3kT/m]\nv(rms)= sqrt[3(1.38066 x 10^-23)(290)/(5.236 x 10^-22)]\nv(rms)= 22.94 m/s\n\ni would check my math if i were you though, i tend to make stupid calculator errors. the concepts are there though :p
919335
If a molecule of the water is moving at 2m/s through the hose, it is because of the nozzle, not despite it. That molecule travels through the nozzle at 2m/s.
580603
stick it in a tank of water then measure the water displaced.archemedes law
880092
A filter with 2 xtals in it is called a Half-Lattice filter. You can cascade two of these, or use a Full-Lattice filter to employ 4 xtals.\nI hope this helps you out.
425236
I've worked with flowmeters for 20+ years and have never heard of this... what medium are you trying to measure?
1063906
You're confusing resistance with pressure. If indeed there is a difference in voltage between A and B then there will be flow.\nThink of a tank filled with water held a few feet above another tank that has a pipe joining the two. Water will flow to the lower container thru the pipe. In this case the pipe has no resistance, which means water flows at maximum possible speed.\nIf both tanks are at the same level, then, sure, there will be no water flow. That's not how the problem was stated, however.
702125
Write down all relevant variables, and units:\nV = volume in mm^3\nt = time in min\nx = edge length in mm\n\nWhat down what you are told:\ndx/dt = 0.49\nV = x^3\n\nWrite down what you want:\ndV/dt\n\nTo get dV/dt, we need dV/dx and dx/dt. The second one is 0.49, and the first one can be gotten by differentiating the volume equation: dV/dx = 3x^2. Substitute in x = 6.7, and the final answer is \n3*6.7^2 * 0.49 = 65.9883 mm^3 / min (decreasing)
168920
This is ultrasonic, not electromagnetic, so C is irrelevant.  The equation is:\nF=V/L where V=sound velocity in water (~1475 m/s), F=frequency in Hz, L=wavelength (0.0003 m)\nResult is you need 4.9 MHz or higher.
459258
start with computation of molarity of solution:\nM_BaOH = (51.24g/ MW BAOH)/ 1.2 L\n\nthen \nusing M1V1 = M2V2\nM_BaOH (x) = (0.1) (1L)\nsolve for x
208038
You can use R.O. (Reverse Osmosis) filters.\nThe last filter diameter should be smaller than 0.0001 micron so that stuffs like sugar, herbicide, pesticide,\nsalt, sugar, metal ion cannot get through. \nYou will get purist and healthy water.