Is anyone good at math, i have an equation I need to solve for another variable?
545305
Re-writing the equation: 9*Q^2-8*Q+(50-P)=0. Comparing with standard form of quadratic: A*X^2+B*X+C=0, A=9, B=-8, C=(50-P). Sridharacharya's formula for solving the standard equation is \nX= {-B+sqrt(B^2-4*A*C)}/(2*A) or {-B-sqrt(B^2-4*A*C)}/(2*A).\nWith this formula 'Q' can be expressed as a function of 'P' as:\n     Q = [2{2+sqrt(9*P-446)}]/9 or [2{2-sqrt(9*P-446)}]/9.
908083
Tried to do it algebraically, that was a booger.\n\nI plugged that into mathematica and it gave me an error normally generated when the inverse of a function is needed to represent a solution and the solution variable occurs in more than one argument of that function.\n\nThat one might not have a solution?
974937
please complete the equation
101802
I don't think there is a unique solution for it. You have more unknown variables than the equations.
589722
Step 1: Solve one equation for one variable in terms of the other.\nStep 2: Plug that into the other equation and solve for the second variable.\nStep 3: Plug the second variable into the first equation and solve for the first variable.
29264
Yuo can't solve this.Because it is a formula and not an equation..If u assign some value equal to this formula such as 0 u have the solution.
819984
restate the first equation in terms of y:\n\ny = 12 - x\n\nNow substitute this in for y in the second equation:\n\n2x² + 3(12 - x)² = 7x(12 - x)\n\nNow, multiply it out and solve for x:\n\n2x² + 3(144 - 24x + x²) = 84x - 7x²\n2x² + 3x² + 7x² - 72x - 84x + 432 = 0\n12x² - 156x + 432 = 0\n12(x² - 13x + 36) = 0\nx² - 13x + 36 = 0\n(x - 9)(x - 4) = 0\n\nx = 9 or 4\n\nSo, {x,y} = {9,3} or {4,8}
990847
isolate the variable\n\n-7x+1+8x=x+1\n-7x+8x=x\nx=x\nx=1\n\nthe answer is c) 1\nnow give me 10 points please!!!
1144396
you would take the 2x-4y=3 and solve for a variable, such as x=(3-4y)/3   you now have what x equals and you sub that into the other equation so you now have 2[(3-4y)/3]-3y=0 and you should be able to solve that equation
978722
You can't, algebraically.  You have two equations and three variables.  Sorry.  You need one more equation, such as a = b.
224079
try this site... it shows step by step how to go about sloving these equations, good luck:
913056
The trick here is to find three equations where three of the variables are expressed functions of another variable. \nSo for example we could express x, y and w functions of z\nIf you add the first equation to the third and substract the second, you'll find: y= -3-z. We'll call this new equation A\nIf you add the second and the fourth equation and replace y by its value found in (A), you'll have: w= 7/4 + 1/4 z, which we'll call (B)\nNow take the first equation and replace w and y by their value from (A) and (B): \nx= -17/2 -7/2 z, this is the equation (C).\nNow that you have your three equations A,B and C you can substitute them in one of the four initial equations, for example the third one. You'll find:\nz=1\ny= -4\nw=2\nx= -12\nThis is not the entire solution (you have to detail how to get to A, B and C) but you should be able to do it (I don't want to be the only one working here!)
366751
make x the width, and solve the two equations (the one given, and the one assumed about the rectangle where l*w=A)
923416
Sometimes I like math.  What you need to do is add 1 to both sides of the equation for x=3y-1\nyou will be left with (x+1)=3y you should then divide the 3 from both sides... afterwards you will have (x+1)divided by 3 equals y or (X+1)/3=y\nFor the other part x+2y=9 you should substitute (x+1)/3 for the "y"\nNow solve x + 2((x+1)/3)=9\nx+(2x/3) +(1/3)=9\ntake from there
1017997
The equations are wrongor insufficient. Post the correct data if you want me to help/ Alternately, you could also message me.
893823
Use the quadratic equation \n\nt = -b + or - sqr(b^2 - 4ac)/2a\n\nyour equation is already in the form:\n\nat^2 + bt + c = 0\n\njust plug in the variables and solve for t twice
838286
well Honestly dear Megan i don't think its correct , coz equation should have ONE " = " \n\nit must be something like this \n-4r ² ± 21r=r+13\n\nGood Luck