.. k here's 1:... How many sides does a box have.......................?
543061
2........inside and outside.....\n\nmuahahahahahahahahaha
872092
It is always understandable when a student feels overwhelmed by "word problems" because they are often presented in an intimidating manner.  If only they could be FUN again ... if YOU wrote the problem, I believe you might find it fun!  :-)\n\nBut let's allow ourselves some joy once we uncover all the unknowns in this problem.  Perhaps we'll get results from converting "written words" into "mathematical expressions."\n\nWhat's most important is that you understand the shape involved (think "shoe box") and how the "openings" are placed (think "windows" on three faces of the shoe box).  All the openings are understood to be identical.\n\nUsing only the letter X -- which stands for the length of an opening -- we can indeed come up with expressions for every other dimension of the container, as well as the openings.\n\nX = Opening LENGTH (given)\nX-2 = Opening HEIGHT ("length is 2 more than height")\n\n2X+8 = Container LENGTH ("8 more than twice X")\n3 = Container HEIGHT (given)\nX+2 = Container WIDTH ("2 more than length of opening")\n\nThe surface area of the container's sides (minus the three openings) is given as 300 square meters.  The equation is also given as 2 (sides) + 2 (front/back) + 2 (top/bottom) - 3 (openings), so let's just set these equal:\n\n300 = 2 (sides) + 2 (front/back) + 2 (top/bottom) - 3 (openings)\n\nAll we need to do is to write, and then substitute, expressions for the areas in parentheses.\n\nSide area = length * height = 3 (2X+8) = 6X + 24\nFront or back area = width * height = 3 * (X+2) = 3X + 6\nTop or bottom area = length * width = (2X+8) * (X+2)\n____________________________ = 2X^2 + 12X + 16\nOpening area = length * height = X (X-2) = X^2 - 2X\n\nTime to substitute:\n\n300 = 2 (6X+24) + 2 (3X+6) + 2 (2X^2+12X+16) - 3 (X^2-2X)\n\nNow that this (long) equation has been written, it is necessary to solve for X, since we need that value in order to calculate what the problem asks for:  The area of each element.\n\nCollect like terms:\n\n300 = 2 (6X+24) + 2 (3X+6) + 2 (2X^2+12X+16) - 3 (X^2-2X)\n300 = 12X + 48 + 6X + 12 + 4X^2 + 24X + 32 - 3X^2 + 6X\n300 = X^2 + 48X + 92\nX^2 + 48X - 208 = 0\n\nWhat we hope is that the trinomial on the right-hand side of this equation is able to be factored easily!  Does it?\nMy approach is to factor '-208' and see whether I can 'build' the linear term's coefficient ('48') from the factors.\n\n-208 = -2 * 104 = -2 * 2 * 52 = -2 * 2 * 2 * 26 = -2 * 2 * 2 * 2 * 13\n\nCan we group these factors into (one positive, one negative) numbers that produce 48 when added together?  Yes!\n\n(-2*2) + (2*2*13) = -4 + 52 = 48\n\nWe got lucky ... the '-4' and '52' provide the perfect pair of factors needed to create a 48 (through addition), so we can now factor.\n\n0 = (X-4)(X+52)\n\nThings are getting better still, because only one of the zeros (some call them 'roots') from the right-hand side will be positive.  The zeros are 4 and -52, and we will only choose the 4, since it represents a physical measurement of length (of an opening).\n\nWe can go back to the expressions above and substitute X=4.\n\nSide area = 6X + 24 = 6(4)+24 = 48 sq. m\nFront/back area = 3X + 6 = 3(4)+6 = 18 sq. m\nTop/bottom area = 2X^2+12X+16 = 2(4^2)+12(4)+16 = 96 sq. m\nOpening area = X^2 - 2X = 4^2-2(4) = 8 sq. m\n\nI hope this helps!
844185
square-ish in shape\ncome in different sizes\nmany varieties
879458
Answer 1:\nf(6)= 726\nAnswer 2:\nyes\n\n(If you ask it again I promise not to answer.)
1092713
triskaidecagon\n\nor a 13-sided polygon, haha.\n\nCheck the source for polygon names from 1-20 sides  :)
287514
number of doors\n\ncoupe = 2\nsedan = 4
306191
a) cube...final answer
667352
octagons have 8\npolygons with "x" sides will have "x" axes of symmetry
841437
Draw a picture - a square with corners (0,0), (2,0), (0,2), (2,2), showing the range of possible values for x and y.\nNow, what part of that square has the difference < 1? Its a hexagon to be precise; its the entire square except for a little triangle at the top left, and a little triangle at the bottom right. The two sloping sides go from (0,1) to (1,2) and (1,0) to (2,1).\nThose triangles each have area 1*1/2 = 0.5, so area 1 combined.\nSo the total area left is 4-1 = 3, so the answer is 3/4.
854520
I assume they are looking for an equation?\n\ny = x\n\nwhere y is the row and x is the number of boxes...
790039
Units help. \nWhat are the dimensions of a standard pallet\nWhat are the dimensions of a standard 40' container (2 what high?)\n18 per layer of what?\n20x2 of what?\nTherefore 40 what? Pallets?\n\nYou'll get some answers if you answer those questions.
268663
If you fold a piece of paper in half 4 times, then you  have 16 segments. Each segment has 4 holes, so the number of holes is 4x16\n\n4 x 16 = 64 holes
636579
Okay, I got something really different, but it might be wrong, I used tangents and stuff to figure it out, and I assumed a dodecagon had 12 sides, but I might be wrong. Anyways, I got 38.4 for the perimeter, and 115.2 for the area.
819588
number of atoms (of each element) on one side equals the other side.
786782
The first letter can be any one of the 5 letters\nThe second one can be any of the 4 remaining letters\nand so on\n\nSo the answer is 5 x 4 x 3 x 2 x 1 = 120 different ways\n\nIf two of the letters are the same (eg green) then divide by (2 x 1) to give 60\n\nIf three of the letters are the same (eg eerie) then divide by (3 x 2 x 1) to give 20\n\nIf there are two pairs of letters (eg yuppy) then divide by (2 x 1) x (2 x 1) to give 30
647274
1/6 coz there r 6 sides on  a die  i dunno
459931
a nine-sided polygon???  can't wait to see other answers...