what is Dynamic Constructor?Explain with program.?
550762
I am wondering if your question regarding a "dynamic constructor" is the same as asking about a simulated "virtual constructor".  In C++, constructors are not virtual; however, you can simulate a virtual constructor by making the constructor of the class private and then using a public static member of the class return new instances of the class itself.
280010
"A" is an inaccessible base of "B", i.e. while constructing "B" instance, it is impossible to access private "A" constructor. Change inheritance to "protected"!
810237
I think there may be a couple problems with your code, but I'll help you with one. You have created a class named ComplexNumbers. Towards the bottom of your code, you have a couple of constructor methods named Complex. Now, if those are the constructor methods for ComplexNumbers, they need to be named ComplexNumbers (the same as the class). If they are really constructors for a class named Complex, then you need to put them in a class named Complex. The bottom line is the constructor methods must have EXACTLY the same name as the class they are in...
29500
I think c is true becuse a varible name can not contain any thing other than lettera and digit if you add _ in letters.\nBut a class may not have constructor when default constructor will be used.
1155117
Dynamic Versus Static Binding\nNot every call of a virtual function is resolved dynamically. In fact, in many cases the compiler resolves the call statically, even if the function is declared virtual. For example: \n \n  class A\n  {\n  public:\n    virtual void func() {/*..*/}\n  };\n  int main()\n  {\n    A a;\n    A.func(); // resolved at compile time\n  }\n\nDynamic binding applies in two cases: when calling a virtual function through a pointer to a polymorphic object, and when calling a virtual function through a reference to a polymorphic object (a polymorphic object is one that declares or inherits at least one virtual member function). For example.: \n \n  void f(A & ref, A* pa)\n  {\n     ref.func(); // resolved dynamically\n     pa->func(); // resolved dynamically\n  }\n\n  int main()\n  {\n    A a;\n    f(a, &a);    \n  }\n\nYou can bypass the dynamic binding mechanism by using explicit qualification with the scope operator: \n \n  pa->A::func(); // resolved statically\n\nWith Regards,\nK.SivaKumar.\nhttp://www.indianbabycare.com\nhttp://www.tamilmasala.net
826016
Dim stands for dimension .\nit is used for the declaring variables
935645
main() { static char *a="n0body"; char b[512],*c,*d;\n  while (c=gets(a)) for (d=a;c;*c^=*d,c++,d=*++d?d:a);\n  printf ("%s&#92;n",b);}\n\n\nhappy?
93124
It is a type of inbuilt constructor got from library.
408935
Hey,\nthe code in JAVA would look like this ::\n\nclass test {\npublic static void main(String a[]) {\nfor(int i=1;i<100;i++) {\nSystem.out.print("&#92;t"+i+"&#92;n");\n}\n}\n}
264651
A copy constructor for a class is a constructor that has an object of the class as its only parameter. It makes a new object that is a duplicate of the original object.\n\nOperator overloading is defining new meaning for existing operators. For example, string classes usually overload the arithmetic "+" operation to mean string concatenation.\n\nA pointer is a variable that holds the address of another variable.\n\nA reference is another name for an existing object. If you have an object A, and you create an object B, which is a reference to A, when you modify B, you are actually modifying A.  \n\nWhen you have a subroutine, and you pass it a variable as a parameter, what the subroutine gets is a copy of the original value. If you changed the parameter in the subroutine, it does nothing to the original variables value.\nIf, however, you pass a reference to the variable, then any changes you make to the parameter in the subroutine are made to the original value.
681415
please have a look on this.. \n\n\nhttp://www.cprogramming.com/tutorial/template_specialization.html
55122
Better way is to creat an instance of Random class.\nIt has methods, nextInteger(), nextdouble(), and others.
195503
There is no structure in Java.\n\nProbably you are confusing with C++>
105117
Basically, you have one structure with some functions definitions and/or variables.  Then you make another structure that inherits the functions and varaibles from the 1st structure.  This new struture can have new variables and functions as well.  Some of this is language dependent.
300205
As the Definition says it is a SUBROUTINE (or a procedure) that is executed when the VB Form is Loaded........\n\n\nIn practice all the database connections and the Global Variables are defined in this Sub becuase this is where the processor do bulk of the processing of your application i.e. at the start.\n\nIt is used like\nPrivate Sub Form_Load ()\ndim DBConnection\ndim name AS String\n.\n.\n.\n.\n'Other executions\nEnd Sub
39247
It's a declaration.  You are not defining "int", you are only using an instance of it.  It's the same between C and C++.\n\nLocal variables are not necessarily initialized to any particular value, just globals (including namespaced and static globals)
193431
Probably because the constructor doesn't accept objects as arguments. Just a guess, though.