if taster male & female in heterozygous form are crossed. what will be % of male tasters in progeny?
535507
why would iy be other than a 50% male 50% female distribution as the most likely outcome?
577414
sooo, i only share 50% of my DNA with my dad, whom i actually look like; and you want to tell me that this ape has more in common with me than my dad: whose genes i actually have?  your logic is screwed up.
638300
The answer is D because dad is hemizygous dominant and mom is heterozygous since both are normal. The kid got the Xt from mom and Y from dad. The kid couldn't get the bad gene from dad because if dad had it to give, then dad wouldn't be normal.
639406
When Mendel began to scientifically analyze "heredity", he concluded that each parent (mother + father) donates an "allele" for a characteristic (trait) in question.\n\nA lettering system was used: Capital letters indicated that the allele is DOMINANT; lower-case letters indicate that the allele is RECESSIVE.  This is the case for 22 of the 23 chromosome pairs in humans.  The 23rd pair are called the sex chromosomes.  Females (mother) always donate an "X" allele; fathers can donate either an "X" or a "Y" allele.\n\nIf a person's genotype for their sex is "XX", this means two things.  1: Both X's are the same (in other words, X and X are identical).  Identical alleles are called HOMOZYGOUS.  2: A human who is "XX" is female.\n\nA human who is "XY" is male.  "X" allele and "Y" allele are DIFFERENT.  Thus, they called HETEROZYGOUS.  We refer to men as being "heterozygous" in that a male's SEX alleles, 'X' and 'Y' are different.\n\nLet us say "B" is the dominant allele for brown eyes, and "b" is the recessive allele that can result in blue eyes.  A person who is "Bb" is heterozygous (B is a different allele than b).  A person's who genotype is Bb is likely to have brown eyes.  A person who is "BB" is HOMOZYGOUS (1st B is identical to the 2nd B) and will definitely have brown eyes.  A person who is "bb" is HOMOZYGOUS (1st allele 'b' is identical to the 2nd allele, 'b') for the recessive allele; this person will have blue eyes.
933813
I have no hard facts, but i seem to think the chance is about 50/50. I know of more then one family with more then one gay child.\n\nI also know of boy/girl twins, one is a lesbian and the other is gay.
696673
well certain genes on the chromosomes will be transfered to different ones which means the gamits produced in meiosis will have different genes than the parent and it will be a mixed half not a normal half
97181
half \nedit read question wrong it 2/3 of black will be heter\n\nOkay the question is What fraction of the BLACK f2 is expected to be heter And since 1/4 is Homozygous Black and 1/2 are heterzygous black.. so 2/3 Of the BlACK f2 will be heterzygous.
1008817
The mechanism for an abnormal amount of X or Y is called nondisjunction in meiosis of cellular division. However there is no possible way for a man to father only one gender.\n\nHaving only a Y is not enough DNA for viable offspring, so the gamete automatically aborts.\n\nHaving only an X results in a female with a condition called Turner's Syndrome. This will not cause a phenomenon of having only boys or only girls because the female does not choose the gender anyway.\n\nThe only possible way for a man to have a higher possibility of having boys is if he has an extra Y chromosome (XYY) caused by nondisjunction. Then the chances that the offspring is a girl is 33% and the chances of having a boy is 67%.\n\nAnd in case you were wondering, a male with XYY has Kleinfelter's syndrome and is infertile.\n\nAlso, you're saying that you have examples from literature, which may not be reality. It's highly unlikely that a father has 15 children of the same gender. I'd say literature tends to exagerate :)
190009
yeah like the first person says. it all depends because there are dominant and recesive genes or chromosomes or whatever, and i think green is dominant, but if you get get 2 blues they dominate over 1 green, i think that is how it works.
592798
Say it's a recessive gene.  Heterosexual parents without the expressed trait each contribute one allele.  Voila!  Gay kid from straight parents!  How does the recessive gene go on, you ask?  Siblings who only receive one allele.  (Do'h!)\n\nWell, there's one way of demonstrating flawed logic (or in your case, abysmal ignorance).
152790
Both parent were heterozygous
121961
bud_leaf_... answered it for me, but generally, if you put all of the generation on a pedigree (a family tree that lists similar traits), the carrier always passes the genes on to the offsspring. because the carrier gences are both recessive, if the person mates with another carrier, or a victim the offspring WILL get the disease, unless if it is genetically altered. if the carrier mates it a non carrier with  dominant gene (example, Tt) the offspring will be a carrier. If the mate does not have the disease with both dominant(TT) the offspring will either not be a carrier, or be a carrier. but with the case of hemophelia,it is a sex-linked disease, so the males will be more likely to get it because they have ONLY ONE X CHROMOSOME, WHILE FEMALES HAVE TWO, WHERE THE SECOND  X ACTS AS A BACKUP. THe females will be carriers, while, sadly, the males will be victims. That is a example of a SEX-LINKED DISEASE. It really depends on what type the disease is, though (sex-linked, or just genetic)
352274
it depends if youre asking about a sex-linked trait or not.  if a sex-linked trait is in question, then the mother gives the son her x chromosome that has one copy of all the genes on her x chromosomes, the father will contribute the y chromosome.  however, if the trait is x-linked and the father expresses it then there's no way to pass it on to his son as he is only passing on his y chromosome.  if it't not sex linked then it's just a random luck of the draw on which genes that kid will get.
221778
Homozygous red-eyed female: X^W X^W\nWhite-eyed male: X^w Y\n\nF1:\n\n------ X^W --------- X^W\n--------------------------\nX^w | X^W X^w --- X^W X^w\n----|\nY --| X^W Y ------ X^W Y\n\nGenotype: 2 X^W X^w : 2 X^W Y (1:1)\nPhenotype: 100% of offspring have red eyes.\n\nF2:\n\n------ X^W --------- X^w\n--------------------------\nX^W | X^W X^W --- X^W X^w\n----|\nY --| X^W Y ------ X^w Y\n\nGenotype: 1 X^W X^W : 1 X^W X^w : 1 X^W Y : 1 X^w Y\n\n1 of each.
875716
probably none, but its depends on which parents genes are more dominant
905475
A. You have co-dominance in a heterozygous match, so the off spring ratio would not be the normal heterozygous, but would come out as a homozygous cross.\n\nB. Call your recessive allele, a. If you did the cross with a non-recessive you would have 1/4 homozygous,aa, progeny. Lethals, when homozygous, will die. You can see that messes with the Mendelian ratio.
890847
Fertilization, because one allele from each mate is coming together.