I need help on this Calculus question...?
546337
Didn´t your mama tell you not to get your answers from your friends??? If you are like me, you don´t have any friends that can answer that one anyway!  Cheaters never prosper!! (theoretically)
554917
try Liethold's book...thats our txtbook in school for calculus.
120626
There's a derivatives tutorial on the following page:\n\nhttp://www.karlscalculus.org/calculus.html#s4
392166
Try this guy:\n\nhttp://dli.taft.cc.ca.us/mathvideo/Calculus/Calculas.htm
247689
Use analytical trig (hint: sin function).  That should give you the answer you are looking for.
435388
damnt i should have paid attention calculus...\n\nlet pam...pam...breat....dimension......carry the one.....as x approaches zero......carry  the two....hold on...\n\nthis could take a while.
434625
You are trying to find d/dt (0.51) ...\n\n0.51 -> alpha [ which inturn points "CONSTANT" ]\n\nDerivative of a constant is zero\n\nso d/dt (alpha) = 0
99672
honestly....good luck\n\ntry www.mathworld.com\n\ndo a search for differential equations, i think that would be your best bet...but that can get confusing...good luck
713982
use logarthmic differentiation\n\ny = x^(1/x)\n\nln(y) = (1/x)* ln(x)\n\ndiff w.r.t x\n\n(1/y) (dy/dx) = (1/x)*(1/x) +ln(x)*(-1/x^2)\n\n(dy/dx) = { y/(x^2) }  [ 1 - ln(x) ]\n\nsubstitute for y
618077
go to www.curnaturecalculus.com  They have all the answers.\n\nSplooch!
801052
It seems you are asking for f'(2)?  in which case, we have\nf'(x) = 1/(1+x^4)so that f'(2) = 1/9\n\nSteve
546678
Hopefully you'll find this site helpful.\n\nhttp://www.sosmath.com/calculus/calculus.html\n\nThere is a lot of information and example problems on limits and derivatives.  Good luck with your calculus class!
766685
You need to differentiate the equation y=2x^2. \n\ndy/dx = 4x therfore the gradient at x=3 = 4*x = 12
1048691
(r*x)*(-sin(x))+(cos(x))*(r)+\n(0)*(lnrsin(x))+(r)*(cot(x)) \n\nfor the cot(x) you end up for the derivative of lnrsin(x) is (1/sin(x)) *cos(x)=cot(x)\n\nsorry it cut off on the top. hopefully this works
953139
f'(x)=(4/3)x^(1/3) +(4/3)x^(-2/3)
108610
If look to the integrator more deeply, one finds that 1/x is the derivative of ln(x).\nThen this question comes up: \nWhat is the integration of uu'dx?\n\nObviously the answer is u^2/2.\n\nSo our answer is (ln(x))^2/4+c.
994382
The quick answer is to take the derivative of f(x) ...\n\nf'(x) = 2 (2x - 4) 2 = 4 (2x - 4)\n\n... and evaluate it at x = 4\nto get a slope for the tangent line of\nf'(4) = 16.  [Ask if you need to know\nwhy / how to do this.]\n\nNow you want the equation of a line through (4, 16) with slope 16.  That would be\n\n(y - 16) = 16 (x - 4)\n\nor\n\ny = 16 x - 48\n\nCheck: it has slope 16 and passes through (4, 16).