Suppose A and B represent polynomials. If A+B=3x squared+2x-2 and A-B= -x squared+4x-8,whats A  And B?
551906
Add each equation\nA + B = 3x^2 + 2x - 2\nA - B = -x^2 + 4x - 8\n2A = 2x^2 + 6x - 10\nDivide each side by 2\nA = x^2 + 3x - 5\nNow plug into one of the original equations to get B\nB = 3x^2 + 2x - 2 - (x^2 + 3x - 5)\nB = 2x^2 - x + 3
360700
a = 1, b = 2, n = 3:\n\n1^2 = 1 = 4 = 2^2 (mod 3) but clearly 1 != 2 (mod 3)
817835
x^3-x^2+3x-1\nx+4&#92;x^4+3x^3-x^2+11x-4\n      -(x^4+4x^3)\n              -x^3-x^2\n            -(-x^3-4x^2)\n                       3x^2+11x\n                     -(3x^2+12x)\n                                   -x-4\n                                 -(-x-4)\n                                         0\nx^4+3x^3-x^2+11x-4=(x+4)(x^3-x^2+3x-1)
774020
3x^2(5x^2 – 2x + 6) – 2x(x^2 + 3x + 9)\n15x^4-6x^3+18x^2-2x^3-6x^2-18x\n15x^4-8x^3+12x^2-18x\nx(15x^3-8x^2+12x-18)
924424
The equations:\n(a+b)^2=a^2+2ab+b^2\nA^2-B^2=(A+B)(A-B)\nJames Chan's solutions were right.
217742
i know it....\n\nsee (a-b) squared = a squared - 2ab + b squared\n\nand (b-a) squared = a squared - 2ab + b squared\n\nthey are equal !\n\nso we can write (a-b) squared = (b-a) squared.\n\nso that means a-b=b-a.\n\nnow put a=1, b=1.5\n\nso 1-1.5=1.5-1\nso 1+1=1.5+1.5\n\nthats ur answer !!!! 1+1=3 !!!\n\nMY 10 pts please.\n\n-------------------------------\n\nanonymus. ur correct. the method i told is wrong. bcause if it had been correct, 1+1 would really be equal to 3 ! its just a fun question with a fun answer.
508006
x^2 + 4bx + 2b=0\n(x+2b)^2 - 4b^2 + 2b = 0\n(x+2b)^2 = 4b^2 - 2b\n(x+2b) = SQRT(4b^2 - 2b)\nx = [SQRT(4b^2 - 2b)]-2b\n\n3x^2 -bx +1=0\n3(x^2 - (b/3)x + (1/3)) = 0\nx^2 - (b/3)x + (1/3) = 0\n(x-(b/6))^2 -(b/6)^2 + (1/3) = 0\n(x-(b/6))^2 = (b/6)^2 - (1/3)\nx-(b/6) = SQRT[b^2/36 - 12/36]\nx-(b/6) = [SQRT{^2 - 12)] / 6\nx = {[SQRT{^2 - 12)]+b} / 6\n\nb^2x^2 - 2bx + c^2= 0\n(bx)^2 - 2(bx) + c^2 = 0\n(bx-1)^2 - 1 + c^2 = 0\n(bx-1)^2 = 1 - c^2\nbx-1 = SQRT(1-c^2)\nbx = SQRT(1-c^2)+1\nx = [SQRT(1-c^2)+1]/b
771358
3x + 4 < x + 8\n2x < 4\nx < 2\n\n{x | x < 2}
913473
Are you missing a plus sign and parentheses around a+b?  If so, then\n(a^2 -2ab + b^2) = (a-b)(a-b) = (a-b)^2\nYou cannot cancel anything, so \n(a^2 -2ab + b^2)/(a+b) does not simplify.\nYou may wish to write it as (a-b)^2 /(a+b)\n\nIf you are not missing a plus sign or parentheses, then\na^2 - 2ab b^2 = a^2 - 2ab^3\nYou can factor out an a.\n= a(a-b^3)  This does not factor, so you cannot simplify.\nDivide this by a and you get a - b^3\nNow add b\nAnswer: a - 2b^3 + b
940135
Use factoring.\nx2-2x-8=0\n(x-4)(x+2)=0\nso\nx-4=0 and x+2=0\nsolve\nx=4 and x=-2
896553
4x^2+8x-x-2\n(4x-1)(x+2)
817461
a^4 - b^4\n\n= (a^2 + b^2)(a^2 - b^2)\n\n= (a^2 + b^2)(a + b)(a - b)
219026
x^3+4x+1\n\n(3x^4+2x^3+12x^2+11x+2)=\n=(3x+2)*(x^3+4x+1)
730173
x = (-b +/- sqrt(b^2 - 4ac))/2a\n\nwhere a= 1, b= -6 , c=8\n\nx1 = (6 + sqrt(36 - 32))/2 = 4\nx2 = (6 - sqrt4)/2 = 2
790277
ill give it a shot - im not sure , anyways i got 2 answers..\n\n(1st)\n\n(3-x)x+2 = 2 (x^2-2)\n\n3x-x^2+6-2x = 2x^2-4\n\nx-x^2+6 = 2x^2-4\n\nx-1/x+6 = 2/x-4\n\nx-1+6x = 2-4x\n\nx+4x+6x = 2+1\n\n11x = 3\n\nx = 3/11\n\n\n(2nd possible answer)\n\n\n(3-x)x+2 = 2 (x^2-2)\n\n3x-x^2+6-2x = 2x^2-4\n\nx-x^2+6 = 2x^2-4\n\nx-1/x+6 = 2/x-4\n\nx-1+6/x = 2-4/x\n\n-5 = -2/x\n\n-5x = -2\n\nx = -2+5\n\nx = 3
117698
so that x=4+ or - 3i\nthen transpose 4 to left\nx-4=+/- 3i square both sides\nthat's x^2-8x+16=-9\ntranspose -9 to left side\nx^2-8x+25=0
1053464
if you want to simplify it \n\nit is 3x - 4x + 4 = -x + 4