The condensed structural formula of 5-butyldecane?
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See number 28:\nhttp://elchem.kaist.ac.kr/jhkwak/OkanaganPdb97/molecule/alkane.htm
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Hi , this is both a simple and hard question to answer. Because the actual list is truly endless. The reason it is endless is because they are made up of many other simplier compounds.\n\nAliphatic also means compounds that are not unsaturated ring compounds. IE they need to have all their bonds used up and saturated.\n\nThe base compounds for the alkanes are:\nMethane----> CH4\nEthane------> CH3-CH3\nPropane----> CH3-CH2-CH3\nButane------> CH3-(CH2)2-CH3\nPentane----> CH3-(CH2)3-CH3\nHexane----> CH3-(CH2)4-CH3\nHeptane---> CH3-(CH2)5-CH3\nOctane----> CH3-(CH2)6-CH3\nNonane---> CH3-(CH2)7-CH3\nDecane---> CH3-(CH2)8-CH3\nNote: (CH2)number = the number of CH2 units So, (CH2)8 means there are 8 CH2 units in the chain. etc.\nNow from these base compounds you can make an endless number of different compounds. From this point we are talking Organic Chemical Nomenclature. IE the way chemists name organic compounds.\n\nas an example:\n         CH3\nCH3-C-CH3\n         CH3\nStarting with the longest chain which has 3 carbons in it. The parent chain will be propane. It also has 2 Methyl groups (CH3) connected to the second carbon.\n\nSo we name this compound :\n\n2-Dimethyl-Propane.  where the number 2 means the second carbon and the Di means the 2 methyl groups.\n\nSo as you can see the number of aliphatic compounds is nearly endless.\n\nIf you need more help on chemical nomenclature ask and I will see what I can do to help.
818694
Well number 10 is\n\n(Z)-3,4-dimethylhept-3-ene\n\n14,15 and 15 and 17.... Need to be drawn out.\n\nGood Luck!
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1 st isomer of a compound = n-(name of compound)\n2 nd isomer = iso-(")\n3 rd isomer = neo-(")\nFor example \nBUTANE C5H12\nIsomers of BUTANE\nn-BUTANE\nCH3-CH2-CH2-CH2-CH3\n\nISO-BUTANE\n   CH3\n     |\nCH3-CH-CH2-CH3\n\nNEO-BUTANE\n   CH3\n     |\nCH3-C-CH3\n     |\n   CH3
63905
This may not be entirely correct, but I'm fairly certain that 2, 2 dichloropentane would be a five carbon hydrocarbon. The second carbon (from left or right, it doesn't matter) would have two chlorines attached to it, rather than two hydrogens. \n\nSo, this structure would be: CH3 - CCl2 - CH2 - CH2 - CH3.
1187641
they have the formula R2SiO\nwhere R is methy of ethyl group
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the formula is CH3CH2OH,the structural formula for ethyl alcohol. The molecular formula is C2H5OH\n\nOh sorry!the answer should be: CnH2n+1OH(general formula)
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C4H10 n-Butane CCCC -30.0 000106-97-8
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A 1,2-diol would form.\n\nEthene would form ethan-1,2-diol, (CH2OH)2.
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tert-Butyl isobutyrate ~ 143.7g/mol\nethyl isocrotonate = 114g/mole isocroronate acid = 86g/mole, ethyl = 29, -1 for the H on the acid.\n\nPlease check my math
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formula is C15H31COONa\n\nthere are single bonds between th 15 C atoms and also between C and H.\nyou can see the structure here www.kcpc.usyd.edu.au/discovery
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http://www.olysun.com/Chem_121/Soln.html\n\n\ncc
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1\na) H2C = CH - CH2 - CH2 - CH = CH2\n ( 1,6-hexadiene )\n\nb) H2FC - CHF - CFH2\n ( 1,2,3-Trifluoropropane )\n\nc) H3C - CH2 - CH2 - CH2OH\n  ( 1-Butanol )\n\nd) H3C - CH2 - CH2 - CHO\n  ( Butanal )\n\n2.\na) Usually FeBr3 is used in addition to Br2 to brominate benzene, but for this:\n\nProduct: Bromobenzene\n\nb) \nProduct: Ethyl butanoate\n\nc) Dunno this one.\n\nd) \nProduct: 1,2-Dichloropropane
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Of the choices you listed above, then Alkane is the answer.  There are other compounds which fit this description, for example the cycloalkanes which is a sub-group of alkanes.\n\nThese are also called aliphatic compounds and saturated hydrocarbons.
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Here is a model image of a carbon molecule:\nhttp://www.lloydminsterheavyoil.com/carbon.jpg
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its cis 1,4 polyisoprene(polymer)\n\nH2C=C(CH2)-CH=CH2
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.........CH3\n..........|\nCH3 - C  - CH2 - CH2 - CH2 - CH3\n.........      |\n........      CH3\n\nPlease ignore the full stops in the above image (which i had to insert to get the correct spacing).\n\nI hope that this helps you.