How to measure a voltage & watts of an appliances?What instrument Im going to use and how to use it?
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By reading many of the answers of this particular question I come to realize this is the blind leading the blind. I am afraid someone is going to get killed. Forget about the fact that you cannot measure current by simply taking ammeter probes and measuring across. If you do not already know this then you have no business in this world attempting to directly measure electricity. And the people supplying this erroneous information are well on the road to becoming toast…………
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vernier callipers \nmeasuring weights\nmagnet bars\nIC tester\nvoltmeter\nammmeter\nenergy meter\nMultimeter\nDC Power Supply \nFunction Generator \nDigital Multimeter \nOscilloscope \npower wires\nBreadboard\nresitors \ncapacitors\nvoltage divider and current divider circuits
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Measure a suitable mass of liquid in say a Styrofoam cup (let's say 100 g). Place thermometer in cup along with heating coil. Be sure that resistance heater does not touch the sides of cup or the thermometer. Have ammeter in series with the resistance heater and voltmeter in parallel. Turn on heater and note the current, voltage and time to reach say 10 deg C above the starting temperature. Electrical energy in = heat energy gained by the system. Electrical energy = current x voltage x time (in seconds). Heat gained = specific heat of liquid x change in temperature x mass of liquid.
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EMF200 Gauss Meter \nRemote Infrared (IR) Thermometer \nmotion detector
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The energy rating of electrcal appliances is now displayed on the gizzmo.\nA being the best and e being the worst.\nTry and get one that has an A rating as it will cost less to run and will not cause the power stations to emit so much CO2
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A voltmeter and an ammeter will provide the input power. You will need some form of dynamometer to measure output power.\n\nOutput power divided by input power yields efficiency.
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There are very simple way of checking this type of thefts. Switch off the source it self, and check if your energy meter is still working/ revolving. If yes, it means that your doubt is correct. disconnect that load first by calling the experts of the system. and then check further.
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It's simple do this job. First of all you need to set your volt meter to a specific voltage level. Like if you want to check voltage of batteries, it ranges between 1.5 to 14 volts. So set your volt meter dail to DC (Direct Current) with this voltage specification.\nFor checking voltage in your house, its a 110-120 V or 220-240 V. This depends on your location. So now you have to set the dail to AC (Alternating current. THe symbol of AC is " ~ ".\n\nI', also a site here. It would solve the job definitly.\n\n\nhttp://www.ehow.com/how_16767_voltmeter.html
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I use a power inverter.
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Calculate the electricity.
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if you live in the US\n110V for most appliances\n220v/110v for bigger ones\nif you live over in Europe \n220V
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u can try www.hotstuffworks.com which can guide u to the basics of any latest electrical instrument/appliances.its a site of great help..best of luck..
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at uniform voltage  \n\nConverting Watts to Amps\n-----------------------------------------\nThe conversion of Watts to Amps is governed by the equation Amps = Watts/Volts\n\nFor example 12 watts/12 volts = 1 amp\n-----------------------------------------\n\nConverting Amps to Watts\n\nThe conversion of Amps to Watts is governed by the equation Watts = Amps x Volts\n\nFor example 1 amp * 115 volts = 115 watts\n--------------------------------------------\n\nfind out how many Amps your monitor needs (see power supply if it has a seperate one.) multiply by 115 or 120 to get the wattage....and that would be how many watt-hrs your monitor uses.
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markey watts = volts x amps , only for a Direct Current device. For AC, which we use in our wall outlets, there is another quantity called the power factor which is the cosine of the phase lag between the voltage and the current:\n\nwatts = volts x amps x powerfactor
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You could use a resistor in series for the voltmeter and a shunt resistor in parallel with the ammeter.  You can also use a signal amplifier to transform the input signal to one that is within the range of the meter.  If it is a panel type meter, do not forget to change the scale behind the meter.\n\nJeffM
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It depends on the applied voltage.  Divide the voltage by the resistance which gives you the amperage.  Now multiply the amperage  with the voltage, and that is your wattage.\nW = V²/R\nThis is straight forward for DC; with AC things become a little more difficult, as because of the fluctuation of the voltage, the average is only .707 of the nominal voltage.
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first u check u power cord