a pole stands erect on the ground. find the angle of elevation of the sun.?
536617
As the pole and its shadows are of the same length, we can let this value be x.\n\nopposite = length of the pole\nadjacent = shadow of the pole\n\ntan A = opp/adj = x/x = 1\nA = 45 degrees\n\nwhere A = angle of elevation
171237
You take one of those compass-like dealios, which are like two sticks joined at a fulcrum. You point one end at the horizon and the other at the object in the sky you are measuring the height of. Then, if angle isn't automatically indicated on your instrument (i.e. you are cheap like me and just use a compass) then you take a protractor to your compass and measure the angle.
841975
u can pray to god to give u d equation to calculate d intensity of d sun with snow also
767544
Let r=the earth's radius and h=your height.\n\nDraw a right triangle ABC, where AC = length r, BC = length r+h, and <A is the right angle and angle C is very small.  C is the center of the earth, and BA is tangent to the earth.  BA is the distance from your head to the horizon.  By Pythagoreas' theorem, \n\nlength(BA) = sqrt((r+h)^2 - r^2)\n= sqrt(2rh + h^2).
150981
The north pole is +90 degrees, or 90 degrees north; south pole is -90 degrees, or 90 degrees south.
1163276
The angle the vehicle was traveling
983012
Your book,the reading table,the trees,themountins,a monument,a fridge or an airconditioner ll contain right angle.Actually there is a branch of mathematics known as Trigonmetry which helps us to find the exact mesurements of high structures without actually measuring it with the help of the right angle they form with the ground
1114860
when sun is some what perpendicular(not exactly) to it there will a shadow.measure it using the ruler(since it will be smaller).now measure the length of the shadow of the ruler.comparing the length of shadow of ruler and the building we can find the height..
110612
2x\nwhen the side opposite the 30 degree angle is x\nand the side opp the 60 degree angle is x(root3)
486759
You're trying to find the vertical angle, angle of site and site.  (But your overall goal is to find the elevation of the guns)\n\nRange and charge
459122
the side length is 2\nso the altitude should be 3^(1/2)\ngood luck
932500
I don't know any good math websites but I do know how to solve this.  b would be the side adjacent to the 40 degree angle and a is the side opposite it.\n\nTangent = opposite leg/adjacent leg so\ntan 40 = 15/b\n\nb tan 40 = 15\n\nb = 15 / tan 40
1128048
Regarding your edit... y = 90º is wrong. All the rest have shown the process, and they are right. With tthat figure, y = 108º
90362
Guess if you note the altitude of the sun at noon each day, mid summer will be the day it climbs highest in the sky, and mid winter would be when the sun is the lowest in the sky. Spring and fall are when the sun climbs to the lattitude you're at, and then you add or subtract 23.5 degrees (the tilt of the earth) to get the altitudes of the sun at summer and winter.\n\nSo if you know you're at lattitude 45 degrees, measure the altitude of the sun each day at noon, and you'll be in mid summer when the sun is at 68.5 degrees and in mid winter when the sun is at an altitude of 21.5 degrees.
189082
If this isn't a math question and you don't want to buy a tool and you don't have a protractor, there should be a leveled board on the ground, and your tilted board should be long enough to reach it. Mark the ground board where the tilted board touches it. Mark a point on the tilted board (the higher it is the more accurate your answer will be), drop a plumb line from there to the ground board, and mark where it touches. Measure the length from the bottom of the tilted board to the upper plumb-line mark (call it "A") and the distance between the two marks on the ground board (call that "B"). The cosine of the angle you want is B/A. Many calculators will give you the angle (using an arc-cosine function).
856174
You need two right triangles, I've attached a diagram...\nhttp://img247.imageshack.us/img247/7576/bldgny3.gif\n\nThe bottom triangle has an angle of depression of 20°.  We know the opposite side is 30m (same height as the window, assuming a level street).  We want to figure the adjacent side 'A', being the distance across the street.\n\nFrom the SOH-CAH-TOA mnemonic --> Tan(angle) = Opposite/Adjacent.\n\nSo tan(20°) = 30/A\n\nSolving for A:\nA = 30/tan(20°)\nA ≈ 82.4m\n\nNow we look at the top triangle.  The angle of elevation is 50°.  We now know the adjacent side is 82.4m.  We need to determine the opposite side 'O'.\n\nAgain, tan(50°) = O/82.4\n\nSolving for O:\nO = tan(50°) * 82.4\nO ≈ 98.2m\n\nThe total height of the building is the sum of the two heights (30m to the window and 98.2m to the roof).\n\nSo the building is approximately 128.2m tall.
1017799
V = area of base times height\nheight = 14\nbase = 3*3*pi = 9pi\nV = 14*9pi\nV = 126pi\nV = 395.8