what is the ideal mechanical advantage of an inclined plane 3 m high abd 15 m long?
539427
the mechanical advantage of an inclined plane is obtained by dividing its length(slope) by its height.\nthus the mechanical advantage of the given inclined plane is 15/3 .that is 5.it may be mentioned here that since mechanical advantage is a ratio it doesn't have any units
772547
Increase your elevation or find a court with less gravitational force.   It's  a physics thing.
459581
Your question is unclear about what set of assumptions you want to use. You seem to imply a perfectly constructed stool, with a perfectly centered force, using incompressible material. You want the stool to have no mass, and you imply that you want to use statics to solve this problem. Strictly applying statics, this system is indeterminate, NOT the ridiculous answer of 0 [N] in two legs and W/2 [N] in the others. There are only 3 equations of equilibrium here, 1 for vertical forces and 2 for moments. Since you have four legs, this system cannot be solved by statics alone. Treating the stool as a deformable structure, you can use geometric compatibility to get a fourth equation. I challenge you to find a competently built stool that has 0 [N] in any leg (a physical stool built of real materials), or an incompetently built stool with 0 [N] in any two legs (unstable system that is obviously not static). The answer indicated as "correct" requires an incorrect application of statics. A large part of studying physics is learning when to use a particular tool, and the physical limits of that tool.\n\nedit: \nI am perfectly aware of what a zero force member is, and there are no zero force members here. You can only find zero force by statics if the structure is determinate, which is not true in this case.\n\nI completely agree with the PowerPoint presentation (definitely not a proof BTW). "But if one leg does not touch the floor, the force in it is zero. If one leg is zero, then the opposite leg is also zero by moment equilibrium. The two remaining legs carry all of the load = 90 pounds/leg. All four legs must be designed to carry the 90 pounds (since any two legs could be loaded)." only applies if the premise is satisfied, namely "if one leg does not touch the floor". I assure you, the normal idea of a four-legged stool requires all four legs to touch. Notice they finish off the calculation using a 45 lb/leg design load, not 90 lb/leg.\n\nI did not call you ridiculous; I rarely resort to name-calling. Please use the built-in spell checker.
584655
45 degrees is the best angle in theory.\n\nIn practice you may have a adjust a little to compensate for air resistance and wind factor.
806769
Since mechanical advantage is the factor by which a mechanism multiplies the force put into it, a mech. ad. of 3 means that whatever force is put into it, the output force will be 3 times that. For your problem:\n\noutput force = 3 * input force = 3*5 = 15 N\n\nI'm sorry, but I don't have an answer for the second part of your question. You might want to submit it as a separate question though, it will probably get some answers that way.\n\nI hope this helps!
280562
The definition of Mechanical Advantage is "The ratio of the output force produced by a machine to the applied input force."\n\nWhen you add more rope segments, you have to do less work to move an object held by a pulley, because each segment of rope is doing a piece of the work.\n\nSay you have a 100lb weight, held by 4 sections of pulley.  Each section is holding 25 lbs (including the section you're holding onto), so you're only doing 25 lbs of work.  The MA is 4.\n\nSo the answer is, "the number of rope segments".\n\nNote this is the ideal mechanical advantage.  The true MA is reduced by things like friction in the ropes.
42921
optimum angle for distance is 45 degrees \nspeed: fucking fast
459122
the side length is 2\nso the altitude should be 3^(1/2)\ngood luck
350288
You question is incomplete....or at least requires more information, as it is, it is too general.\n\nWhat are the conditions are are talking about here?\nAre both balls pushed with some constant force?  As they rolled down an incline?  Are they already in motion?\n\nWhat type of surface are they on?  A smooth (frictionless) surface?  A rough surface where friction needs to be taken into account?  Are both balls solid, hollow, one each?\n\nThey are many many variables which need to be taken into account, you cannot just say "big" and "small" and get an accurate answer.\n\nAnd by "greater distance" do you mean translational displacement, or angular displacement?
939533
I would use conservation of energy.\nx is the distance traveled on the ramp\nthe forces at work are:\nGravity.  The potential energy will be\nsin(5)*m*g*x\n\nFriction:\n.48*cos(5)*m*g*x\n\nSince there are no brakes all of the kinetic energy will be lost to friction and the potential energy gain:\n\n.5*m*v^2=\n.48*cos(5)*m*g*x+sin(5)*m*g*x\nnote that m divides out\nI get 110 m\n\nj
1095052
inclined plane, wheel and axle, screw, lever, pulley, and wedge\nisn't a screw a version of an inclined plane?
252449
3,212 ft (979 m) high
27384
IMA is ideal mechanical advantage. A screw with closely spaced threads has a greater IMA than a screw with threads spaced farter apart. The reason is that for a screw with threads a distance p apart, a full rotation of the screw moves the screw in or out by p. If you are doing the same motion and moving a smaller distance, the IMA is greater. The IMA also depends on the length of the lever arm used to turn the screw. The full equation for IMA for a screw is:\n\nIMA = 2(pi)L/p,\n\nwhere L is the length of the lever arm, and p is the thread pitch.
1165190
6' 3'' is a real good height to have.
196467
I built mine a foot taller than my largest peice of equipment. this way i can safely drive in all equipmet without snagging,
1170770
Which one.\nThey range from statical scales to efficient, low friction machines.
448243
minimal. \npower to weight ratio is significantly more important, as is wing design (the "lift" it can generate).\nplacement only concerns the weight distribution.