How do you throw a ball at a distance and that ball to return to the same point as it was thrown?
553125
There are two ways.\n\n1. This is the most likely way.  On a day with no wind, throw the ball straight up.  This is quite unlikely and requires a lot of skills.\n\n2. This one is impossible.  Throw the ball so hard that it goes around the Earth once before coming down.  Humans just don't have the power to do this.
150577
Throwing a Football is a combination of grip on the ball,  arm speed velocity, and proper angle technique.\n\nYour fingers should hold onto the laces.  Many QB's grip the ball with their pinky, ring, and middle finger holding on to the laces, with their index finger and thumb just on the ball.\n\nWhen throwing, you want a bring the ball up to shoulder level and equal to the ear level.  Your shoulders should be turned to the target or person you are throwing towards.\n\nThe release of the ball is a foward in a 90% angle of your throwing arm while your non throwing shoulder moves backward.  You should step into your throw as well.\n\nWhen you release the ball, your hand should almost be pointing at its target.  \n\nThe motion is similar to a Pitcher in Baseball in which the body moves in the direction of the target.
636210
emm throwin a ball around?? u must become the ball, get to know the ball, be its best friend, become on. or get lessons or something. sorry :( no one answered ur q so i thought id give it a go
639693
Practice throwing shorter distances first and make sure you're throwing it straight.  If you do it correctly, it usually has an "S" flight trajectory.  If you're right handed, it starts of to the right and then comes back left.  Make sure you're throwing straight and then start throwing harder and harder.  Once you can stand there and throw it pretty hard (and straight), then start getting a one step start and use your body along w/ your arm.  Once you master that, Get a running start and put your body into it.  The main thing is making sure that you throw it straight.  You're maximum distance will come on a straight throw.
644478
1)Start by modelling the speed of a ball in one direction; take into account friction force (negative drag) that is equivalent to negative acceleration. Loop until speed is equal or less than to zero. Then, stop.\n\n2) Do Exactly the same, now in a 2-D space: model how'd the would move given an initial vector speed.\n\n3) Model a "Hit" on a ball: given an instant (vector) speed plus a "Hit Vector", compute the resultant vector; then use that vector as the initial speed again.\n\n4) develop a "Hit?" function that returns true if the difference between the centers of the balls is less than the diameter, or if the center of the ball is closer than a radius to a wall (the stick can be thought of as another ball)\n5) Every time Hit? is true, recompute vector speed for every involved ball.\nVoila! you have your game. Let me know if it's useful and the results.
565453
I don't believe you. Even if you can, can you just throw it or you can throw curve balls, change up, fast balls, fork ball up, etc. What I mean is that can you really strike a guy out with a 98mph fast ball or you can just a throw a ball at 98 mph? 2 different things .
175741
Take several steps back to the left or right of the ball.Left to curve right and right to curve left.Line yourself up at a 45 degree angle with the ball.Strike just to the opposite of the side your kicking from and sweep your leg through in an upswing motion.The longer the distance the better you can curve it. Try to get yur foot under the ball for more heighth which means a better curve.
1035016
first you pick up the eight ball and you will throw it
175800
To throw a ball 90 mph you are measuring speed not distance. You do not need to reach a certain distance, just a certain rate (distance/time).
392970
one ball on the pitch, but you might have 4 extras on the side lines for throwings and if the ball gets flat.\nt
471340
No one else noticed, did they?\nI hope you haven't turned in your extra credit answer about football yet.  The one you chose is wrong!!\n\nYou have to throw the ball in front of the receiver.  If the receiver is 25 yards away from the quarterback [it makes the math easier] and the quarterback throws a pass 50mph [a great arm], it will take 1 second to travel 25 yards.  The receiver will travel 4.5 yards to the left in that second.  To meet at the same place, the quarterback must throw to where the receiver will be in one second, 4.5 yards to the left.\n\nIf you're confused, draw a chart.  Show where the quarterback, receiver, and ball are right now, when the ball is thrown.  Then show where the receiever will be in one second.  That's where the ball has to be in one second.
461302
So far, you have a starting position and an ending position.  If this were a physics question, you'd also need numbers like the mass of the ball and the initial launch velocity.\n\nIn general the equation of motion is given by\n\ns = s0 + v0t + at^2\n\nwhere you need or have the final position (which we have), initial position (which we have), initial speed (which we're looking for, gravity (a known constant), and the time in flight (which we can find using other equations).  Generally, things will go up and down parabolically, not in a straight line, so we need more information about this to answer your question.\n\nNow if you're just looking at a straight line path, then you can use some trig to find at least the angle to the ball (you can't find the speed if you're assuming straight line travel).  In this case, if the person is 1.7 m, and he is standing 5.8 m from the basket that is 3.05 m away, you have a right triangle where the horizontal leg is 5.8 m and the vertical leg is 4.1 m (the difference between the height of the basket and the player, assuming that the ball is thrown from 1.7 m above the ground).  Using the tangent function, you can find that angle:\n\ntan x = opposite side / adjacent side\n= 4.1 / 5.8\n= 0.7069\nx = 35.26 degrees\n\nBut again, laws of motion dictate that the ball follow a parabola to the basket.  But at least we can say that the launch angle has to be at least 35.26 degrees.
1033468
2.36 m s^-1 to 2 d p\n\nWe split the launch velocity of the ball into a vertical and a horizontal component.\nHorizontal component = 19.8 * cos(49.1) = 12.9639 m/s\nVertical component = 19.8 * sin(49.1) = 14.9659 m/s\n\nGravity accelerates the ball vertically with the acceleration -9.8 m s^-2 (negative because the pull of gravity is downwards while the ball is moving upwards to start with)\n\nThe vertical distance from the ball to the ground after time t is given by the formula s = u * t + (g * t^2) / 2 where: u = initial velocity, g = acceleration of gravity, t = time elapsed\n\nWhen the ball returns to the ground, s = 0\nTherefore the time taken for the ball to return to the ground is given by\nu * t + (g * t^2)/2 = 0 Substitute values\n14.9659 * t - (9.8 / 2) * t^2 = 0 Remove brackets, divide by t, rearrange\n4.9 * t = 14.9659\nt = 3.05427 s\n\nDuring that time the ball will travel horizontally \ns = u * t where s is distance in m, u is velocity in m s^-1, t is time in sec\nDistance travelled horizontally is 12.9639 * 3.05427 = 39.5953 m\n\nThe player has to run 46.8 - 39.5953 m = 7.20475 m in 3.05427 s\nHis speed must therefore be 2.35891 m s^-1
495640
This might sound dumb, but try going out to the driving range and moving your back foot backwards a couple of inches...\nI don't mean feet further apart, I mean that your body will actually be turned slightly in a clockwise direction.\nit will change the angle of impact with the ball, and that will change the spin you unknowingly place on the ball.  \nThis isn't a guaranteed solution, but that's how I fixed mine.
923711
well, it is easier to show, but here we go.\na)hold the ball in your left hand, with your right hand on top. you left foor should be pointed towards the spot you wanna serve, your right foot is parallel to the back line. your two feet should be like 6 inches or more apart.\nb)take a step back with your right foot, at the same time pulling your right hand STRAIGHT BACK...not down and around. \nc)throw the ball with your left hand up in the air high enough for swinging hand to be at the top point of it's reach. \nd) swing at the ball with your right hand, with a REALLY strong hand. (and open hand, like you were giving the ball a strong highfive.)\nwhat you do with your left hand is poit in the air the place you want it to go while doing C.\nfollow through with your left and right hands.\n\nmost of it is just asking your coach, or a volleyball playing friend for help.
777143
Make sure to toss straight up and swing when it is at it's highest point it will take several try but as long as you toss straight up and hit the ball hard through the middle it will go over.
468114
english makes the object ball throw as well as changing the path on it and the cue ball it depends on the end result of where you want the two balls to go best way to find out is table Time and experimentation