x²+10x-128 = 0       solve quadratic equation?
538044
hmmm...very tough one!\n\nill sovle by the formula!\n       _________\n-b +- V (b^2)-4ab\n------------------\n       2a\n       _________\n-10 +-V 100+512\n------------------\n       2\n\n       _________\n-10 +-V 612\n------------------\n       2\n\n-10 +- 24.7\n------------\n     2\n\n14.7/2\n\n34.7/2\n\n(7.35, 17.35)
586490
x²+2ax+(a²-b²-c²)=0\n\nhere, I will change: \na = m\nb = n\nc = o\nso that you will not get confuse.\nit will be :x²+2mx+(m²-n²-0²)=0\n\nto make sure that the equation is always real\nwe have to look at b²-4ac (you know this right?)solution:\n\nb²-4ac = 4m²-4(m²-n²-o²)\n=4m²-4m²+4n²+4o²\n=4n²+4o²\n\nhere you see, if a negative number is squared, it would be a positive number eg (-2)²=4\neven if n and o is negative,they will be positive when squared. so we got 4(n²+o²)>=0, it is proven that the roots are always real.\n\nif you still can't understand this, message me
175133
2x-1(xsquared-x+10)squared
574841
-2(x+10)=3(2x-4)\n-2x-20 = 6x-12\n-2x = 6x+8\n-8x = 8\nx = -1
530142
use the quadratic equation:\nx=-b +/- the square root of b^2 - 4ac all over 2a\na=1,b=7,c=10 so plug it in\nx=-7 +/- the square root of 49-40 all over 2\n-7 +3 = -4 divided by 2 x=-2\n-7-3=-10 divided by 2 = -5\nso x = -2 or x=-5
429058
x==(-b+/-sqrt(b^2-4ac))/(2a).
832845
you need to add +1\nso that the equation can be represented as a perfect square\nx^2 - 2x + 1 = (x - 1) (x - 1) = (x - 1)^2\n\nthis is called solving by perfecting the square\nto do this, make sure that the coefficient of the first term is 1.\nThen, divide the coefficient of the middle term by 2,\nthen square the whole thing.\n\nIn this case, the coefficient of the middle term is -2\n-2 / 2 = -1\n(-1)^2 = +1
770289
It's the difference between two perfect squares.  Take the square root of 16 and x squared.  Then a minus sign and the square root of 25.  Put parentheses around all of that. Write it again, and change the minus sign to a plus sign.  You will set each group in parentheses equal to zero.  There will be 2 equations.  Solve for x.  X will have 2 solutions.
44408
5x2 = 9 − x\n\n5x2 + x − 9 = 0\n\nIt is a quadratic equation with\na = 5, b = 1, c = -9
756992
Don't you just love the quadratic equation?\n\nThe first thing you got to do is get the given equation into the correct form, and in order to do that you have to combine all like terms. Since there are no like terms yet you have to do some math first.\n\n-2.0^2 = 4.0because neg * neg = pos\n\nNow you have 2 like terms 4.0 and 0.5 combine to get 4.5. Your eqution should look like this:\n\nf(t)=10t + 4.5 since you need at^2 + bt^2 + c just insert t^2. Now your equation will look like this:\n\nf(t)=t^2 + 10t + 4.5\n\nAnd just in case you need the quadratic equation:\n\nt= -b + or - sqr(b^2 - 4ac) / 2a\n\noh yeah and a = 1
735202
You mean find solutions for x when 2x^2+12x+18=0.\n\n  First we can divide thru by 2 just to make it simpler.\n x^2+6x+9=0 , then factor and get\n(x+3)^2=0\nso x=3.
852286
if it x - 4x/(x+1) = 4/(x+1)\nthen x(x+1) - 4x = 4\nor x^2-3x + 4 = 0\n\nthis is quadratic and so 2 solutions so Megan is right\n\nyou do not have tro evaluate
670824
There are 2 ways to solve for this \n\n1. Separating the x^2\n\n2. Quadratic Formula\n   ax^2 + bx + c = 0\n x = (-b + or - sqrt(b^2 - 4ac))/2a\n http://www.1728.com/quadrtc.gif\n\n\nSolving it by separating x^2\n\na. First separate x^2\n(x + ?)(x +?)\n\nb. Now we have to figure out the 2 variables that would give us 4x and -12 when we multiply them out. notice, that 4 is positive so the larger number has to be Positive.\n\n-12 = 12 * -1   12x + -1x = 11x\n-12 = 6 * -2    6x + -2x = 4x\n-12 = 4 * -3    4x + -3x = x\n\ntherefore the 2 variables would be 6 and -2\n\n(x + 6)(x - 2) = 0\nSo x, would be either -6, or 2\n---------------------------------------------  \n2. SOLVING USING THE QUADRATIC FORMULA\nThis one is way easier\n\nax^2 + bx + c = 0\nx^2 + 4x - 12 = 0\n\n x = (-b + or - sqrt(b^2 - 4ac))/2a\n x = (-4 + or - sqrt(4^2 - 4*1*-12))/2*1\n\n x = (-4 + or - 8)/2\n x = (-4 + 8)/2 = 2\n\n x - (-4 - 8)/2 = -6
5554
Solving the problem stepwise -\n(x - 8 ) ( x - 2 )\n= x(x-2) - 8(x-2)\n=x^2-2x-8x+2\n=x^2-10x+2\n\nThese two sites will help you for the concepts.
839760
The roots are 0 and -16/5\n\nTo solve any quadratic equation eg. ax^2+bx+c, you can apply formula x= (-b+-sqrt(b^2-4ac))/2a
1172065
if it is a quadratic (ax^2 + bx + c) then put it into the quadratic equation. that automatically will give you 0, 1, or 2 real answers. the equation is: x = [-b +/- (square root of b^2 - 4*a*c)] / 2a\n\nif (b^2 - 4*a*c) is negative, you have no real solutions. if it is zero, you have one real solution. if it is positive, you have 2 real solutions.\n\nthen, if for example you get  x=4 and x= -2, your factors are (x-4) and (x+2)
618060
this would multiply out to be 4x^2-9\n\nif you let the expression be equal to 0, then x would be positive or negative 3/2 because either (2x+3) = 0 or (2x-3) = 0, and just solve for x