If I travel south at 8mph for 2.25 min, then east at 8mph for 3 min, how long will a direct route take at 8mph
535960
The speed has no part in the solution, as it is the same for all three paths. So, you draw a triangly with legs 2.25 and 3 in lenght. the solution is the lenght of the hypotenusa formed. the answer is 3.75 min.
893501
44.44444 mph.  If the distance of one leg is x miles, then you drove a total of 2x miles in (x/40 + x/50) hours.  Divide the total distance driven by the total time spent driving, and you get 200/9, or 44.444... mph
754657
The time taken is (200 miles divided by 185 mph) plus 5 minutes.  Divide 200 miles by that time to get the average speed.  Obviously, it's going to be less than 185 mph by around 1/12th
861588
Average speed = (8+8.5)/2=16.5/2 = 8.25 m/s\nTotal distance = 8.25x99=816.75m\nTime taken for 1st Lap = 816.75/(2x8) = 51 sec\nTime taken for 2nd Lap = 816.75/(2x8.5) = 48 sec
1022304
Point A and Point B are 600 miles apart. A train leaves Point A travelling toward Point B at 5:30AM at a constant speed of 65 kph. Another train leaves Point B heading toward Point A at 6:20AM at a constant speed of 40 kph. What time do the two trains meet?1 kilometer = 0.6214 miles\n\nx=kilometers     5/6(50 minutes/60 minutes)*65= 54.166...km\nx=.6214 (600 miles)\nx=372.84 kilometers apart\n5/6(50 minutes/60 minutes)*65= 54.166...km\n372.84-54.17= 318.67km between the 2 trains at 6:20\nthats as far as I can get (I don't remember how to do this... hope this helps!)
1024302
Cruising Range:\nLand at 25 MPH: 300 Miles\nWater at 2600 RPM: 7 Hours\nCruising Speed:\nLand: 20 to 30 MPH\nWater: 6 MPH\nMaximum Speed Forward:\nLand: 45 MPH\nWater: 8.2 MPH\nMaximum Speed Reverse:\nLand: 12 MPH\nWater: 4.5 MPH
130382
It will take you 10 hours. \n\nIf you ride only 2 km ever hour, then after one hour you will be 2 km closer to your destination. Take 20 and divide it by 2, and that gives you 10 hours. \n\nIt doesn't matter for your question, but that's a pretty slow bike! A person could walk faster than that.
931765
1. d=t, any form of d=t+b would be parallel. b = any number. That is a line.\n\n2. d=t would also work here.\n\n3. Well if you go 60 MPH and you wnat to know how many miles a minute you can go convert using (60miles/hour)*(1hour/60minutes) and you get 1mile/minute. If you need feet, 1 mile is 5280 feet, so 5280 feet/minute
685470
the speed = distance/time
729421
OK what you need to remember about any problem like this is the formula Distance Traveled=Rate of Travel * Length of Time Traveled, (D=R * T).  As long as you have two of those values, you can calculate the third.  You know the distance, and you know the rate or travel.  To calculate the Time, you get it by itself on one side of the equation.  Divide both sides of the equation by R (rate), like this:\n      D = R * T\ndivide both sides by R\n     D / R = (R * T) /R\nthe R's on the right side will divide out and leave you with\n     D / R = T\nNow you plug in the values for D and R\nFor train A\n     D = 1000 (miles)\n     R = 125 (mph)\nso  T= 1000/125 = 8 hours\nYou know the time is expressed in hours, because your units divide out just like numbers do.  Your are taking miles and dividing them by miles per hour, and that leaves you with hours.\nIf you add in the stops the train makes (2 stops, 15 minutes each) you would add 30 minutes, or 0.5 hours to the total time, it takes Train A 8.5 hours to go from Station 1 to Station 2.\n\nDoing the same thing with Train B...\nT = D / R\nT = 1000 / 100  (Train B is travelling the same distance, 1000 miles, and travelling at 100mph.)\nSolve the equation and you get T = 10 hours, and adding in one stop of 15 minutes (or .25 hours), you get 10.25 hours.\n\nSo, Train A gets there first.  Even if Train B doesn't make it's stop until near the very end of the run, Train A gets to the station in 8.5 hours, and even without any stops, at 100 mph, Train B is still 1.75 hours out of the station at that point.\n\nIt's a useful formula to learn and understand, you can apply in many different situations.\n\nGood luck.
36001
A: 56 mph x 1.5 hours = 84 miles\n\n\nB: Distance = 100 total miles - 84 miles = 16 miles.\nTime = 30 minutes = 0.5 hours.\n\nAverage speed = 16 miles / 0.5 hours = 32 miles per hour.\n\n\nC: Total trip miles = 100 miles\nTotal time = 2 hours (1 hour 30 minutes for first leg, 30 minutes for final leg)\n\nAverage speed = 100 miles / 2 hours = 50 miles per hour.
739505
Do you mean how far did the traveler travel?\n\nIf the traveler traveled 400 miles at a speed of 70mph, then the travel time at this speed is:\nTravel time @ 70mph = 400/ 70\nTravel time @ 70mph = 5∙714 285 714 hours.\n\nTotal travel time is 6 hours (given).\n 6 - 5∙714 285 714 = 0∙285 714 285 hours @ 60mph.\nDistance = Speed x time\nDistance = 60 x 0∙285 714 285\nDistance = 17∙142 857 14\n\nTotal distance = 600 +  17∙142 857 14\nTotal distance = 617∙142 857 14\nTotal distance ≈ 617∙14
100012
A would take 22 minutes to get to 15 miles and 32 minutes to get to 20 miles. Unfortunately, there's insufficient information to be precise on B's journey. Did he spin off before the start?.. or at which point en route? Guessing it, I would say A arrived at 15 miles and at the 20 miles point first. NB. I have had to make certain assumptions in your question to arrive at this answer (eg I asumed A slows down to 40mph after 4 miles?)
337691
if the question is: If it takes 3 hours to travel 24 miles downstream and 6 hours to travel UPstream, how fast is the current? then,\nlets call the travelling speed Vt and the current speed Vc\ndownstream we have Vt+Vc=24miles/3hours=8mph\nupstream we have Vt-Vc=24/6=4mph\nto solve the system of two equations we can add the equations and get 2Vt=12, Vt=6mph\nVc=8-6=6-4=2mph\nThe current is 2mph fast.
481716
distance = 160miles\nave. speed = 50mph\n\n160/50 = 3.2 hours or 3hours and 12 minutes\n\nfor the guy to arrive at exactly 11:30am\n\n(11:30) - (3hours12minutes) = 8:18am\n\nANSWER: 8:18am
735212
I'm going to use minutes instead of hours.\nWe know that on the first trip, D = 120S (D=distance, S=Speed of first trip).\nWe know that one the second trip, D = 90(S+6).\n\nTherefore 120S = 90S + 540, or 30S = 540, and S = 18kph.\nTherefore the distance is 36 kilometers.\nChecking, 24(1.5) for the second trip also = 36.
619270
it is about 493.72 miles apart and it would take about 8 hours to get there