what is y= the square root of x-2?
537199
got to math.com, click on calculators and click on solve equations.....it'll do the math for ya
460242
ur answer is [sqrt(3) - sqrt(7)].it can written as sqrt[x +/- 2*sqrt[y]] when x=a^2 + b^2 and y=a*b is equal to sqrt(a) +/- sqrt(b)
727314
From y = x2 to y = x2 - 6 is: shift the graph 6 units 'down'.\nFrom y = x2 to (x + 5)^2 is: shift the graph 5 units 'to the left'.\n\nTh
813596
Okay, the goal here is to get values of x that fit the equation.  These are not like easy linear ones, they have x^2 in them.  We can still solve them.  \n\nx^2=16\nWhat is the reverse sign of the square?  It's the square root.  Square root both sides and get\nx=sq(16)\nSo x=+/-4\nBoth work because (-4)^2 becomes 16 as well.  Those are your answers.\n\n\n2x(x+3)=0\nThe goal here is to make this equation equal zero.  Do you see how there are two "factors?"  Things that are multiplied together?  Well, to equal zero, one of them must equal zero.  Either one can equal zero, so you have different solutions that work.\n\nTake 2x:\n2x=0\nx=0\n\nNow x+3:\nx+3=0\nx=-3\nSo\nx=0,-3\n\n\nHere we have to "factor" this equation:  Find two things that, when multiplied together, equal this.  y^2 and 8y both have y, so factor out the y and get:\ny(y+8) \nWe can do as we did before, and get\ny=0\nand \ny+8=0, so\ny=-8\nOur answers are\ny=0,-8\n\nThe next two are harder:\n\nFirst bring the 28 over to the other side:\n\nx^2+3x-28=0  \n\nThe factored form of this actually has two factors, but none with just x.  To factor this, we need two factors of -28.  When one of them is multiplied by x and added to the other one multiplied by x, they equal 3x.  Now, a negative times a positive is a negative so we are looking for one positive and one negative factor of 28.  Let's try these two:\n\n7 and -4.\n7(-4)=-28\n7x+(-4x) = 7x-4x=3x!\n\n-4 and 7 are our factors, so:\n(x+7)(x-4) is our factored form.  Solve the components:\nx+7=0\nx=-7\n\nx-4=0\nx=4\n\n x=-7,4 are our two answers.\n\n\n\n2x^2+9x-5\n\n\nThe next one is similar, but more complicated.  We have a 2x^2.  No matter.  We need to find two factors of -5, and one of them will be multiplied by 2x instead of x.  The only factors of -5 are +/-1, and +/-5.  It looks like the 5 will be positive since 9x is fairly big and positive.  Let's try -1 and 5:\n2x(5)=10x\nx(-1)=-x\n10x+(-x)= 10x-x=9x!\n\nSo 2x will be multiplied by 5, and x by -1.  In factored form, this is:\n\n (2x-1)(x+5)\n\nBecause you use FOIL (first outside, inside last) so the 2x is not multiplied by -1, but by 5.  Now solve these components.\n\n2x-1=0\n2x=1\nx=1/2\n\nx+5=0\nx=-5\nSo\n x=1/2, -5 are our two answers. \n\nAll done.  Hope this helps.
593847
The answer is zero isn't it?  The square root of (7 squared) is 7.  If you minus 14 you get -7. Add another 7, brings you up to zero.
1031543
There is no exact square root but it is\n\n7414.85009963114
803771
sq.rt of x*y = Sq.rt X * sq.rt. Y\n\nIt can be proven that:\n √(x*y) = √x * √y\n\nConsider the first part → √(x*y).\nTwo number values, one is x and the other is y, they are multiplied together.  You then take the square root of this result.\n\nConsider the second part → √x * √y.\nYou take the square root of x and y and then you multiply the results together.\nIt can be shown that the results of the first part is the same as the result of the second part.
444240
-y=2-x\n\ny=x-2\n\nslope is 1\ny intercept is (0,-2)
51084
Just as the reciprocal of the number 2 is 1/2, or 0.5, the reciprocal of the square root of 2 is the square root of 1/2.  This is represented numerically as 0.707106781186...  Try it again, this time using numbers which will yield whole-number results.  For example, take the number 64.  The reciprocal of 64 is 1/64 or 0.015625.  The square root of 64 is 8, and the reciprocal of 8 is 1/8 or 0.125.  Note that the square root of 0.015625 is 0.125.
762368
NB! sqrt(x)=x^½ \n2*(2+1)^½ / -5*(2+3)^½<=>\n( 2*(3)^½*(5)^½ )/(-5*5)<=>\n( -2*(3*5)^½ )/25<=>\n( -2(15)^½ )/25<=>\n-2( 3*5/5*5*5*5)^½<=>\n-2(3/5*5*5)^½= -sqrt(3/5)*2/5\n=========================
817379
y=(x^2-3x)^2\ny=x^4-9x^2\nAnd then I'm confused.
17917
let me give you the distance formula: the square root of ( [X2 - X1]squared + [Y2 - Y1]squared )\n\nwhat are X2 and Y1 and stuff like that?  well, your coordinates are (-7,6) and (-1,1).  You assign one set of coordinates (it doesn't matter wich) to be x1 and y1.  the other set will be x2 and y2.  So, for example, in the point (-7,6) your -7 would be x1 and your 6 would be y1.  then your -1 would be x2 and your - would be y2.  make sense?  so once you have assigned your x1, x2, y1, and y2, then you just plug them into the distance formula:\n\nthe square root of ( [-1 - -7]squared + [1-6]squared ).\n\nyou solve that, and there's your answer!  I would use a scientific calculator to do the squaring and square rooting, and I assume you know which buttons do that.
706596
You'd have to use the chain rule for the square root, then the quotient rule for what's inside.\n\nf ' (x) = (1/2) [(2x³ - 7) / (4x + 1)]^(-1/2) times the derivative of the radicand.\nFor that, the quotient rule gives:\n[6x²(4x + 1) - 4(2x³ - 7)] / (4x + 1)²\n\nThere's most likely some simplifying to be done, but that should get you on the right path.\n\nGood luck!
431382
let the 2 numbers be x and y :\n\nx - y=23----A\nxy = -120 ---B\nx = -120/y\n\nsubstituting x in A:\n-120/y - y = 23 \n-120/y - y2/y = 23\n-120/y - 23 = y2/y\n-120/y - 23/y = y2/y \n-120-23/y = y\n-120 - 23 = y2\n0 = y2 + 23 + 120\nsolving the quadratic equation by the formula;\ny = -b (sq.root) b2-4ac/ 2a\n\ny= -8 and x is 15\nand then 15-(-8) = 23 \n         15x(-8) = -120
707539
x = (y^2 + 2y -1) / 2\ndx=ydy+dy\n1=(y + 1 )dy/dx\ndy/dx=1/(y+1)\nd2y/dx2 = -1 / (y+1)^2
875144
you have to take the square root of each side, then just simplyfy\n\nx = 1.2472191289247
562312
Greg is correct for what you posted, but is that 2 after the y supposed to be superscripted as in y-squared? If that's the case:\n\ny^2 = 9.6\ny = sqrt(9.6) = 3.098