How do you convert binary numbers to decimals in Visual Basic 6?
545790
Check this url\n\nhttp://www.planet-source-code.com/vb/scripts/ShowCode.asp?txtCodeId=50775&lngWId=1
383056
what kind of program are you doing?? all i know is visual basic stuff
34052
I do not know a preprogrammed utility to do this, but can point you in the direction that you might need to go.  See the reference below for the math and an on-line converter:
1083786
Are you looking at computer code?  B indicates binary base and D indicates decimal.\nB100 = 1*2^2 + 0*2^1 + 0*2^0.\nD1000 is one-thousand.
32238
If you write the codes for 16 digits in binary out -\n\n0000 - 0\n0001 - 1\n0010 - 2\n0011 - 3\n0100 - 4\n0101 - 5\n0110 - 6\n0111 - 7\n1000 - 8\n1001 - 9\n1010 - A\n1011 - B\n1100 - C\n1101 - D\n1110 - E\n1111 - F\n\nThen take 3E7C, match the four digits on the chart:\n\n0011 1110 0111 1100 =\n\n11111001111100\n\nThats hex to binary conversion, to decimal, you just add your exponents of two, reading binary number from right to left:\n\n2^2 + 2^3 + 2^4 + 2^5 + 2^6 + 2^9 + 2^10 + 2^11 + 2^12\n\n= \n\n15996\n\nI admit there's a more direct path to the number, but rememebring the way above allows you do any decimal/binary/hex conversion neededed, so its all I've remembered.
80562
Relatively easy way\n\n0.008895478\n0.012222453\n\nmultiply both by 100 (ie, move decimal point two spaces to the right):\n\n0.8895478\n1.2222453\n\nObviously first one is less.
359204
100 which is the binary equivalent of 4 if you are considering those 2 numbers to be added binary numbers
69075
A double variable will only store numeric data.  You need to convert the text value into a number.  To do this you can use the CDbl function.  You will get an error, however, if the value in text1.text is not numeric.  I suggest using the following:     \nIf IsNumeric(text1.Text) Then a = CDbl(text1.Text)
315839
keep a table of binary 4 bit equivalents 0 1 2 ... F of hexadecimal degits.\nconvert each 4 bits of your binary no. to equivalent hex. no looking the table.\n\nyou got the answer
846962
Binary is base two. The decimal system we use is base 10.\nThe earliest computers used base two because there are only two states - on or off, (1 or 0).\n\nIn our system we have 1s place, 10s place, 100s place etc.\nin base two, there is 2^0, 2^1, 2^2, 2^3  or 1's, 2's, 4's, 8's place.\n\nthe number 5 is written 1 in 1s place and 1 in 4s place\nso 5 is 101 in base 2.
1143912
There's no such site, as far as I'm aware.\nI don't think it's possible to convert from VB to C, because it would be too difficult (READ: impossible!) to do such a thing (they are too different programing languages, one is compiled, one interpreted...). You'd better try to understand the algorithm(s) in the programs and rewrite the code!
429263
basic numbers are numbers 0-9
796435
Hello,\n\nWell, I havent used VB 6 for a long time (i using c++ now) but if I not mistaken it does write integer and infact any data type (including the ones you may have created yourself) to files...\n\nIt'd be better if you could post your code.\n\n[]s
1118192
I don't use vb.net myself (C# I use).\n\nIf you want to keep the 0's in the front though, it has to be a string, not an integer.\n\nYou convert it over to integer, add the next number, then cast it back to string, and pad the length to the desired number of 0's\n\nPseudo code:\n\nLicenseNoNum = CastToInt(LicenseNostr)\nLicenseNoNum = LicenseNoNum + 1\nLicenseNoStr = CastToStr(LicenseNoNum)\nWhile LicenseNoStr(Length) < 8\nLicenseNoStr = '0' + LicenseNoStr.\n\nYou could also just store it as an integer, and perform the cast for printing, which might be all you were looking for.
930802
not necessary to have whole numbers...you can have decimals like 2.79 5.5 3.2 like these..all these depends on the key you used to represent the data
623394
IsNumeric will tell you if a value being passed into it can be converted into a number, were you to try to run Decimal.Parse on it. You might use it like this:\n\nFunction Translate(Foo as String) As Decimal\n    if IsNumeric(Foo) = True then\n      Return Decimal.Parse(Foo)\n    Else\n      Return 0\n    End if\nEnd Function
743647
Dim i, total As Integer\ntotal = 0\nFor i = 0 To Integer.Parse(TextBox1.Text) Step 2\n     total += i\nNext\nMsgBox(total.ToString())