Math help!! OMG please!!!?
542416
5x^2-2x-3 = 0\n\nX= (-b(+or-) sqrt B^2-4ac)/2c\n\nX= -(-2)+ (sqrt4-4*5*-3)/-6 or,\n\nX= (-(-2) - (sqrt4-4*5*-3))/-6\n\nX=  (2+ 8)/-6,\n\nX= -5/3\n\nOr\n\nX = 2-8/(-6) = 1
619087
#1. /=divided?????????\n1.=5.6\n2.=22qt\n3.=85/100 and reduce\n4.=Does not make sense\nJust answering for fun.
1001971
[(16x*2-25) / (24x*2-30x)] / [(8x*2-2x-15) / (6x*2-7x-3)]\n= [(16x*2-25) / (24x*2-30x)] [(6x*2-7x-3) / (8x*2-2x-15)\n= [(16x*2-25) (6x*2-7x-30] / [(24x*2-30x) (8x*2-2x-15)]\n= [(4x-5) (4x+5) (3x+1) (2x-3)] / [(6x) (4x-5) (4x+5) (2x-3)]\n= (3x+1) / 6x
987327
Find a number X such that  2X = (X/2) + 99\n\nmultiply both sides by 2 to get  4X = X + 198\nsubtract X from both sides to get 3X = 198\ndivide both sides by 3 to get X = 66\n\ncheck work\n2*66 = 132\n66/2 + 99 = 132
202280
http://www.aaamath.com/ Try this. Hope it works!!
945939
Divide the 3 by the 7 either by hand or calculator. It turns out to be 0.4285714 . Rounded to 3 places would be 0.429 .\n....._________\n . 7/ 3.0000-----&#92; 0.42857\n....-28\n.....____\n........20\n.......-14\n......._____\n...........60\n..........-56\n.........._____\n.............40\n............-35\n............_____\n...............50\n..............-49 etc. Place a line under each number that is subtracted , subtract and bring down a zero (0). This should give you an idea how to proceed. Hope it is not too confusing, but it is difficult to show math problems in this format.
627277
(^^you forgot 41)\n25\n\n2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97
945604
1.adding-2f-7\n-6f-2f+7-7<2f-2f-9-7\n-8f<-16\ndividing by -8\nx>2\n\n2.5/8g-4>2/3g+6\nadding 4\n5/8g>2/3g+10\nmultiplying by 24\n15g>16g+240\nadding -16g\n-g>240\ndividing by -1\ng<-240\n\n3.sum incomplete\n\n4.-2 1/9d+3/5<-3 2/9d-4 2/5\n-19/9d+3/5<-29/9d-22/5\nmultiplying by45\n-95d+27<-145d-198\nadding 145d\n50d+27<-198\nadding -27\n50d<-225\ndividng by 50\nd<-5 1/2
703752
simply subtract 7 from both sides. This leave you with\n\nx<_3
448711
51,336\n\nNext time just type your math problem into at google search and it will do the math for you!\n\nLink below.
343331
What math test do you take?  I'm in Algebra 1 and I only remember 1 question.  It's impossible.\n\nSomeone has a total of 100 coins in dimes and quarters.  The total value adds up to $14.05. How many quarters does she have?\n\nA) 27 (I chose this-it's a dollar off)\nB) 40\nC) 56\nD) 79 (I forget-it's way too high)\n\nWell, that's all I have.  Bye bye!\n\nThanks to the guy who solved that.  I won't get a zero now!
281150
Next time just type your math equation into Google and it will do the math for you.\n\n15
1067
ummmm... i cant count that high. let me grab my calculator. i calculate 3 as the answer. ;) lol
859897
***************\nQUESTION 1\n***************\nOn the first question, we first have to find the equation that we will be solving for.  \n\nAssume that x is one integer.\nWe know that x+1 is the other integer because they are consecutive.\n\nSo we now put the wording into an equation\n1/3(x + (x+1)) = x - 5\n\nNow we solve the equation\n1/3(2x + 1) = x - 5\n2/3x + 1/3 = x - 5\n16/3 = 1/3x\n16 = x\n17 = x + 1\n\nOur two integers are 16 and 17.\n\nNow we check our answer.\n1/3 of 33 = 11 & 16 - 5 = 11 We are good! :)\n\n\n***************\nQUESTION 2\n***************\nEvery hour, Amy and Randy together walked 3.6 + 4.2 km apart from each other.\n\n3.6 + 4.2 = 7.8\n\nSo, every hour they will be 7.8 more km apart from each other.  We only want 10 minutes though, and there are 60 minutes in an hour. To get how far apart they will be in 10 minutes, we take:\n7.8 * 10/60 = 1.3\n\nRandy and Amy will be 1.3 km apart after 10 minutes.\n\nWe are done! :)
530853
So where's that starting point?  Either we start (yesterday) with Mary having $785.63 we subtract $57. and $125. for 603.63.  Then we add $57.25 for a total of 660.88 (B) \nOR\nwe start we $785.63 (today) anb subtract $57. and $125 for $603.63 (C).  The $57.25 doesn't matter cause Mary did that yesterday....
957682
half it then times it by 2! that will give u the answer
1135408
OH NOES THIS IS LIKE A MATH PROBLEM!!!! i can't handle any more variables :( sry.\n\n\nhahahaha.