six of the 14 players were left-handed.what was the ratio of the left-handed players to the right-handed playe
538202
total no: of players = 14\nno: of left handed players = 6,\nno: of right handed players = 14 - 6 = 8\n\ntherefore, ratio of left handed players to right handed players = 6/8 = 3/4 = 0.75
724427
1024 matches. This should be on the mathematic section. Everyone know that an elimination match would always require <number of player> - 1 to finish. \n\nThe simple logic is actually: We're gonna create 1024 losers, how could we create 1024 losers with less than 1024 match? Can't have 1024 losers with only several matches.\n\nEach player would play the match 10 times (2^10 = 1024), and exactly one player would play 11 matches. (to complete up the 1025 players)
309464
53 active players per team.. multiplied by 32 teams.. do the math
369748
7 players per team in the game and many alternates that you can switch in and out. i'm not really sure how many alternates you can have but i think maybe up to 14 or something.
182775
there are 6 place for 15 student so:-\n\n15*14*13*12*11*10=answer\n\nor simply use combination since the arrangement is not important\n\n15C6
777142
there are too many players
996641
Arsenal  15 players\nFollowed by \nChelsea 14\nMilan 13
219403
the ratio is 4:3. For every four games they played at home, they played three on the road. To find a ratio you have to determine what the lowest common denominator is (in this case it's four) and divide both numbers by it. Also you have to pay close attention to the way the question is worded. It's 4:3 because you asked the ratio of HOME games to AWAY games. If you had asked the ratio of AWAY games to HOME games, then the answer would have been 3:4.
905499
6 = spades in the bidding declared\n\n1 = zero in a small slam
1110357
11 players.. not sure how many extras..
1096921
I don't have the time to get the answer for you but maybe you do - here are the winning numbers: http://www.flalottery.com/exptkt/l6.htm  Good luck!
582152
************CRICKET************\nIT HAS 1+1+1+1+1+1+1+1+1+1+1=11 PLAYERS ONE SIDE.\nTHE OTHER SIDE ALSO HAS 1+1+1+1+1+1+1+1+1+1+1=11 PLAYERS.\nTHEY PLAY THE GAME IN FRONT OF 1+1+1=3 STUMPS.\nTHE PITCH IS 1+1+\n\n\n\n22 YARDS LENGTH.THE OTHER SIDE OF THE PITCH,,SORRY IT REACHED I PARAGRAPH.;-)
850801
good lord! only 4 players in that league? how do you have so many players, lol. good trade though
1138951
A team will only lose if they have less than 7 players. That means 5 red cards (or 4 red cards and a player injured leaving the pitch - that has happened)
40944
Six play on a side at a time absent someone out for a penalty, typically a goalie, two defensemen, a left wing, right wing and center.  I think the NHL roster limit is 18
287185
I will answer this with real math.\n\n64 teams times 6 rounds equals 384. 1(amount of times to get the whole tournament right)divided by 384 equals:\n\n%0.00206 to get the whole tournament right.
194085
In the experiment of choosing a committee of 6 from a group of 8 women and 7 men,\n\nTotal no. of possible choices \n= no. of ways in which the 6 members of the committee can be chosen from the total 15\n==> n = C(15,6)\n==> n = 15*14*13*12*11*10/6*5*4*3*2*1\n==> n = 7*13*11*5\n==> n = 5005\n\nLet "A" be the event of choosing the committee with 3 women and 3 men\n\nFor Event "A"\n\n---------- Men----Women---Total\nAvailable---8-------7------15\nTo Choose---3-------3-------6\nChoices----C(8,3)-C(7,3)--C(15,6)\n\nNo. of favorable choices\n= (no. of ways in which the 3 men can be chosen from the total 8) * (no. of ways in which the 3 wommen can be chosen from the total 7) \n==> m(a) = C(8,3) * C(7,3)\n==> m(a) = 8*7*6/3*2*1 * 7*6*5/3*2*1\n==> m(a) = 8*7 * 7*5\n==> m(a) = 1960\n\nProbabilty of choosing the committe with 3 women and 3 men \n==> Probability of occurance of event "A" = m(a)/n\n==> P(A) = 1960/5005\n==> P(A) = 392/1001\n\n\nhttp://www.futureaccountant.com/probability/study-notes/\n\nhttp://www.schoolingkids.com/