I need clarification on the use of Modifier 26 for Radiological Procedures.?
542879
If I understand you correctly there is no technician involved.  I would check with the facility that owns the equipment.  If they are billing for the technical component then all you can bill is the professional. (26 modifier)\nIf they aren't billing at all then you can bill without the modifier.  The insurance companies allow a set amount for each CPT code and they divide that amount if the tech and prof are billed separately.
582063
Yes and no. It depends how you look at the question.\n\nIf yes: 10% of 267 = 26.7 and 267-26.7 = 240.3 therefore 250 falls within the 10%\n\nIf no: 10% of 267 = 26.7 and the difference between 250 and 26.7 is greater than 10%
326064
You can find some links here. \nhttp://www.ask.com/web?q=3D%20conformal%20radiation%20therapy\n\nGood luck with the therapy.
379771
http://www.mikeholt.com/mojonewsarchive/EC-HTML/HTML/WyeTransformerCalculations~20030916.htm
214548
You should use DOD Specification 5200.28-M, for the degaussing and destruction of high-density media.\n\nhttp://all.net/books/standards/remnants/standards.html
1098758
I would first check into the schools accreditation. Is it recognized by the various national radiology organizations? If not, your degree wouldn't be worth anything more than the paper it's printed on!
249245
The usual unit is REMs or Sieverts. Both REMs and Sieverts are based on how human bodies absorb radiation and have a fairly complex definition involving absorption of different types of radiation by specific tissue types.  Other units, used for describing radioactive materials themselves, like Curies, are based on how much radioactive material is present, or what the rate of production of different types of radiation is.  \n\nHere's a good link on Sieverts:\n\nhttp://en.wikipedia.org/wiki/Sievert
114899
There's a great tutorial/newsletter on using the RAD Video Tools to do just that.  I've included the link below.  It's a free download and the steps are well explained by PapaJohn.
941865
It is quite reliable when properly applied.  It can't be trusted when:\n\n(1) it is applied so far in the past that it is extreme extrapolation of limited data.\n\n(2) the sample and its food source were radiation-protected.\n\n(3) the sample came from a situation or time where the C14/C12 ratio was different from what it is today, or is unknown.\n\nFor all these reasons, the farther back in time you try to read, the less reliable the dating.
1067486
64. or 72, depending on what type
739938
is a meter for measuring total patient radiotherapy \nBelow are websites to look at for more info hope it helps good luck!!!\n\nhttp://www.osti.gov/energycitations/product.biblio.jsp?osti_id=20547028\n\nwww.thermo.com/com/cda/product/detail/0,1055,19650,00.html\n\nwww.jacmp.org/journal/include/getdoc.php?id=2951&article=159&mode=pdf \n\nwww.medscape.com/medline/abstract/16143797
73838
Its' probably a rounding error. It would depend on which masses for the elements you use, how precise you want to be.
523086
If it is of the appropriate diagnostic quality.\n\nThe job of the radiographer (radiologic technologist) is to use the minimum amount of radiation necessary to produce an image that provides enough information to confirm a diagnosis. How technically good it is in terms of density, contrast or sharpness, or how aesthetically pleasing it looks is secondary (although important).\n\nThere are a few other rather important technical issues - are the patient details shown and are they correct? Is an orientation marker shown and is it correct? Is the field delineated, thus indicating that the radiographer took particular care to minumise the irradiation of the patient, etc etc. The list goes on and on. \n\nUltimately it is good training, skills and professionalism coupled with experience that produces a good x-ray.
1068949
a mixture of barium-133 and cesium-137\n\nhttp://www.orau.org/ptp/collection/nuclearmedicine/mockiodinekit.htm
1031853
The radiation length for Al is 24 cm, for Pb 0.56 cm. To reduce the beam to 10% we need 2.3 radiation lengths, 55 cm of Al or 1.3 cm of Pb. \n\nNo idea how your  attenuation coefficients relate to my radiation lengths. A radiation length is the length of material needed to attenuate the beam by 1/e, that is to 0.368 of the original intensity.\n\nGood luck!
745886
Consider radiotherapy. For the right dosage to be prescribed to a patient, physics knowledge is needed for example the intensity of gamma ray radiotherapy, etc. A certified radiotherapist can be a person with a background in applied physics. \n\nAnother example would be the user of the physics of sound waves in obstetric ultrasound scans. There is also the physics of radioactive decay, used to select substance like iodide to be ingested by patients for detections of thyroid problems.\n\nThis are only a few examples. There are countless applications of physics in the medical field.\n\nPerhaps the following reference on medical physics will help:
26445
ER = extended release\nHCT(Z) = Hydrochlrothaizide\nHCT(S) = Head CT scan\nSR = I'm stupmed.....\nInj = injection