(r+8)^2=r^2+16^2           WORK OUT PLEASE!!!?
547879
(r+8)(r+8)=r^2 + 256\nr^2 + 16r + 64 = r^2 +256\n16r = 192\nr = 12
701733
4r^2 -8r+3= 0\n\ntwo numbers that add to -8 and multiple to (3*4)= 12 \n\nwhich is -6 and -2\n\nso 4r^2 -2r-6r+3\n\n2r(2r-1) - 3( 2r-1)\n\n2r-3 = 0 and 2r-1= 0\n\nr= 3/2 and r= 1/2
815860
Hello Dear \n\n- Take " √ " of eachsides\n√16y^2 =  √ 25 \n± (4y = 5)\ny = ± 5/4\n\nGood Luck dear.
706305
R^2=A^2+B^2 -2(A*B)cos(180-acute angle)
783870
7x^2+16x over (x-2)(x+2)(x+3)
896553
4x^2+8x-x-2\n(4x-1)(x+2)
929777
we have x^2+y^2 = r^2 for polar coordinates'\n\nx = r cos t\ny = r sin t\n\nwe need to eliminate t ( t for theta as I cannot key in theta)\n\n1st get in terms of cos sin\n\nr = 8/(4+ cos t)\n\n4r + r cos t = 8\n\nbut r cos t = x\n\nso 4r = 8- x\nsquare both sides\n16r^2 = 64+x^2-16x\n\nusing r^2 = x^2 + y^2\n\n16(x^2+y^2) = 64 + x^2 -16x\n\n16x^2+16y^2 = 64 + x^2 - 16x\nor \ntarnsferring RHS to left \n\n15x^2+16x+16y^2- 64 = 0
470404
((a^2 - b^2)/8a) X ((4a^3)/(a + b)^2))\n(4a^3(a^2 - b^2))/(8a(a + b)^2)\n((4a^3)/(8a)) * ((a^2 - b^2)/(a + b)^2)\n((a^(3 - 1))/2) * (((a - b)(a + b))/((a + b)(a + b)))\n((a^2)/2) * ((a - b)/(a + b))\n\nANS : ((a^2)(a - b))/(2(a + b))\n\nOn your problem, here is where you went wrong\n\nTo make it easier, you should had kept your problem in\n\n(4a^3(a - b))/(8a(a + b)) form, then had done this\n\n((4a^3)/(8a)) * ((a - b)/(a + b))\n\n(4/8)(a^(3 - 1))((a - b)/(a + b))\n(1/2)(a^2)((a - b)/(a + b))\n((a^2)(a - b))/(a + b)
162777
4(3x+2)-2(x-8) = -2x\n\n(12x+8)-(2x-16) = -2x\n\n12x+8-2x+16 = -2x\n\n12x-2x+2x+8+16 = 0\n\n12x+24 = 0\n\n12x = -24\n\nx  = -2 Answer.\n\nCheck by subst. the value of x\nto the original equation:\n\n4(3x+2)-2(x-8) = -2x\nSubst: x = -2\n4[3(-2)+2]-2[-2-8] ?=? -2(-2)\n4[-6+2]-2[-10] ?=? 4\n4[-4]+20 ?=? 4\n-16+20 ?=? 4\n4 = 4  Check
814891
a^2 - 2ab + b^2 = (a - b) ^2\n\nthen...\n\n(a - b)^2 / (a + b) = (a -b) (a - b) / (a + b)
1657
20x^2 + 15x - 8x -6 = 20x^2 + 7x - 6
972642
(A^2+2ab+b^2)/(a+b) + (a^2-b^2)/(a-b) + (a-b)/(a+b)/(a^2-b^2)/a+b)\n(a+b)^2/(a+b)+(a+b)(a-b)/(a-b)+ (a-b)/(a+b)*(a+b)/(a^2-b^2)\na+b+a+b+(a-b)/((a+b)(a-b))\n2a+2b+1/(a-b)\n\nif I got all the ( ) in the right places.
648512
r^2 + 16r + 64 = r^2 + 784\n16r = 720\nr = 45
79707
16 - 3(8-3)squared / 2\n\n1. 16-3x(8-3)²÷2\n2. 16-3x(5)²÷2\n3. 16-3x25÷2\n4. 16-37.5\n5. -21.5
658148
given 4a^2-12ab+9b^2\n    =(2a)^2-2(2a)(3b)+(3a)^2\n    =(2a-3b)^2
800533
Well dear Kristi \n\nthe answer is \n( 9r - 2s )^2 \n{ as you know ( a - b )^2 = a^2 -2ab+ b^2 \n81r^2 - 36rs + 4s^2\na = 9r , b = 2s , so \na^2 = (9r)^2 = 81r^2 \nb^2 = (2s)^2 = 4s^2 \n-2ab = (-2)(9r)(2s) = -36rs  } \n\nGood Luck Darling
271990
x^2-2xy+4xz-8yz=\n(x^2-2xy) + (4xz-8yz)=\nx(x-2y) +4z(x-2y)=\n(x-2y)(x+4z)