how does depth affect the pressure of water????
548733
Pressure increases with depth ,each 10 meters 1 atmosphere\nto calculate the pressure for a certain depth use the formula.\nPa= (depth/10)+1\nwhere Pa is the pressure\nExample at 20 meters\nPa= (20/10)+1\nPa= 2+1= 3 Atmospheres
806210
PSI is pounds per square inch.  If you know how many square inch the 8000 pounds of force is applied on, then you can derive a pressure by dividing the force by the surface area.\n\nContrary to the previous answerer, I do not believe that at a mere 14.7 psi, the atmospheric pressure at sea level, is going to change anything significantly on a 8000 lbs load.
770625
I'm sorry, i have to correct some of the misunderstandings posted above here.\n\nTHE WEIGHT DOES NOT, I REPEAT, DOES NOT CHANGE IN WATER.   weight is a term in physics for the interaction of gravitational forces on a masseous object.  Does the mass of the object change in water?  NO.  Does the mass of the earth change when an object enters water?  NO.  Therefore the weight is the same.\n\nWhy do objects feel lighter in water?  the difference in net force is the answer.  Weight still pulls down equally... However, the water creates a boyent force which counteracts a percentage of the weight (depending on the object submerged.  roughly counteracts 40% for humans, different for other objects).  In this way, while the weight is the same, the downward force of the object is less.  That's the confusion point for almost everyone who's answered so far.
901583
Each 1033.23 centimeters of fresh water adds 1 atmosphere of pressure.\n\nHere is why:\n\n1 atmosphere of pressure is equal to 14.696 pounds per square inch, which is the same as saying 1033.23 grams per square centimeter.\n\nEach CUBIC centimeter of water has a mass of 1 gram, because 1cm^3 = 1mL which is by definition 1g of pure water (and fresh water has little to no impurities).  That means a 1033.23-cm tall column of water 1cm by 1cm will have a mass of 1033.23 grams, all pressing down on 1 square cm area at the bottom -- that column will be exerting 1 atmosphere of pressure on the bottom area of 1 square centimeter.\n\nThe area at the bottom does not matter, since as you increase the AREA you increase the VOLUME (thus the MASS) by the same ratio as long as the water column stays the same height -- but it is easier to imagine based on a 1cm x 1cm column.\n\n1033.23 centimeters = 33.9 feet.\n\nSo what we need to do to solve your question, is figure out how much pressure IN ADDITION TO THE ATMOSPHEREIC PRESSURE, must be supplied by the water:\n\n3.5 atm - 0.9atm = 2.6 atm \n\n2.6 atm * 1033cm/atm = 2686.4 cm\n\nSo, at 2686.4 cm (26.864 meters, or 88.14 feet) the water will be adding 2.5 atmospheres of pressure to the 0.9 atmospheres pressure provided by the atmosphere itself, for a total of 3.5 atmospheres of pressure.\n\nBTW, there is a way to work it out without all the "american" units (feet and pounds, just using the metric unit of force which is a Newton) but I'm so used to doing it in "american" units that this way is quicker for me...
89038
Also pressure from cold water sinking in some areas, thus causing it to rise in others, such as the Peruvian coastline (produces La Niña), the ac5tion of prevailing winds on both warm and oold surface waters.  Also water entering the oceans from large rivers such as the Amazon and Mississippi, and also salt concentration (dense water sinking).\n\nTidal currents are caused by the combined effects of the sun and the moon, the strongest when their effects combine.\n\nHeat and cold also affect water density, causing the ocean suface to be higher in hot areas and depressed in cold areas.\n\nGenerally these effects keep water circulating.  Some lack of movement is possible where all are missing from a given area, such as the Sargasso Sea.
92719
Let's consider a deep-sea diver. The pressure pushing on the diver is less at shallow depths than at greater depths. This is because at shallow depths, there is a shorter column on water above the diver than there would be at greater depths. But the pressure the diver feels is not just felt from above! The force is transmitted through the fluid and pushes the diver from all directions, even from below. \n\nPressure within the Earth can be thought of the same way that we think of water pressure on a diver. Under the surface of the ocean, you are under pressure from all directions because of the weight of the column of water above you. Within the Earth, an object is under pressure from all directions due to the weight of the column of rock above the object. This pressure is often called confining pressure, because it is the push from all directions that tends to confine material to the smallest possible volume (space).
580111
the density or any other property of an object sinking in water does not immediately change.  at some point the ball might rust, but that's another argument.\n\nthe force acting on the ball as it sinks will grow exponentially with respect to depth, but the ball itself will be no different at the bottom of Marianna's Trench or the bottom of a drinking glass.\n\nPS, the earth's crust is no more than 30 miles thick in the thickest places, with about 7 miles in the deepest place in the ocean, so you cannot have a hundred miles of depth in any ocean.  good idea though!
1025160
I'm not sure why you asked twice, however, i'll try for a best answer on both of them lol.\n\nIf i understand your situation correctly, you have a pond (with no inlet or outlet), a boat with no leaks floating in the pond, and ice inside the boat.\n\nThe water level of the pond will not change at all as the ice melts. The water level in the pond would only change if mass were added or removed from the boat. A boat displaces an amount of water equal to the total weight of that boat. A change in ice melting from ice to water does not change its weight. Therefore no change.
109177
i believe its because the boiling point of water is only 212 at normal atmospheric pressure, so if the pressure is changed the boiling point does too.
110828
Archimedes said: When an object is submerged in water, there is a buoyant force upwards on it that is equivalent to the weight of the water displaced. \n\nSo if you have a heavy object underwater, and it is displacing water, its net weight will be less than when it is in air, displacing air, which is much lighter, so has a much smaller buoyant effect.
84852
The depth of the water determines what wavelength wave can pass through it.  Deeper water passes longer waves, which can contain more energy than shorter ones.  When a wave gets into progressively shallower water it bunches up, rises, crests and finally breaks.
135904
sinks deeper.  The ship is displacing the water, not the ping pong balls.  Add ANYTHING to the ship and it will sink deeper, not rise.\n\nPS: Thumbs nose at B-redsoxer.
398749
The pressure of the water going through the hose is increased by narrowing the hole from which it leaves.  So when the hole is small, there is more force pushing the water out of the hose, so it travels farther.\n\nIt's like a big bucket of water, where if there is a tiny hole near the bottom, a tiny stream shoots out for a good distance, but as the bucket empties, the stream shoots less and less far, because the weight of the water pushing it lessens as the water leaves the bucket.\n\nAnd, if the hole suddenly enlarges, the stream gets bigger but shoots out less far, because more volume is allowed into the stream so what pressure there is does not force the stream as far and the water in the bucket is lost sooner and so it loses pressure sooner....
782970
The expansion ratio is 9.8/8 = 1.225, so that is also the pressure ratio compared to 1 atmosphere (101325 Pa)---> P = 101325*1.225 = 124123 Pa\n\nAssuming atmospheric pressure at the surface of the water, the depth to cause the additional .225 atm = .225*10.33m/atm = 2.324 m\n\nSummary:\n1) 2.324 m\n2) 124123 Pa
433818
Water provides more force than air because it is\ndenser and thus has more mass:\n\nF = ma \n\nd = m / volume
717304
The pressure of the deep sea would implode causing the water level to be the same, the salt in the ocean would cause the settlement of the water. if you dropped the ball in fresh water it would rise, but the deeper you go the pressure would implode it.
508799
That depends on the depth. For each 27.68" of liquid water, there is an increase of 1 psi. This would be affected slightly by anything disolved in the water, such as salt in the oceans. Water vapor in the atmosphere is also sometimes included in the term hydrosphere. Pressure at the Earth's surface is figured as 14.7 psi in common usage, which accounts for the difference in psi(a) and psi(g) data.