What is the average height the football reaches on a punt?
553237
It depends on the circumstances and the punter.  For a professional, it would be about 60-70 feet.
107569
Same as all the others....\nThe field is often called the gridiron because the markings on the field resemble a grill. The game is played on a rectangular field 120 yards (110 metres) long by 53 1/3 yards (49 metres) wide. The longer boundary lines are sidelines, while the shorter boundary lines are end lines. Near each end of the field is a goal line; they are 100 yards apart. A scoring area called an end zone extends 10 yards beyond each goal line to each end line.\n\nYard lines cross the field every 5 yards, and are numbered from each goal line to the 50-yard line, or midfield (similar to a typical rugby league field). Two rows of lines, known as hash marks parallel the side lines near the middle of the field. All plays start with the ball on or between the hash marks.\n\nAt the back of each end zone are two goal posts (also called uprights) that are 18.5 feet apart. The posts are connected by a crossbar 10 feet from the ground. Successful kicks must go above the crossbar and between the uprights. (At many fields the uprights and crossbar are attached by a curved bar to a post outside the field of play, to reduce the chance of players running into the supports.)
152173
The answer depends if you are talking about an inside linebacker, or an outside linebacker.  Inside linebackers don't have to be quite as tall an quick because their primary responsibility is to stop the run between the tackles and drop into the passing lanes.  This means if you are 6'0 its ok, but the NFL likes size.  If you are an outide linebacker you are expected to rush the quarterback and you are taking on larger lineman and tight ends.  Therefore being taller is at a premium because if you don't get to the quarterback you can get those hands up and deflect a pass.  An outside linebacker also has outside containment on sweep plays unless the type of defense dictates otherwise.  So about 6'2 and 250lbs on average with about a 4.5 second 40 time is about ideal.  Obviously the faster the and bigger the better.  But these are the benchmarks for the majority of NFL scouts, hope this helps.
1059334
A football FIELD in the American game is 120 yards long by 160 feet wide. 100 yards from goalline to goalline with 10 yard end zones. the markings on the field and the goalpost width depend on what level of play is involved. High school goal posts are 23'4" wide, NCAA and NFL are 18'6" wide. The Canadian game has a 110 yard field with 25 yard deep end zones. Also in Canada, the goalposts are on the goalline and not the endline. Canadian football is a 12 man game instead of 11.
308532
The length of the touch line must be greater than the length of the goal line. \n\nLength: minimum 90 m (100 yds) maximum 120 m (130 yds) \n\nWidth: minimum 45 m (50 yds) maximum 90 m (100 yds) \n\nInternational Matches \n\nLength: minimum 100 m (110 yds) maximum 110 m (120 yds) \n\nWidth: minimum 64 m (70 yds) maximum 75 m (80 yds)
716892
PROGRESSION OF SCORING VALUES\n\nGoalsGoals\n              FromAfter\n              Field TDs\nSeasonSafetyTDs<FG><PAT> Length of the Game+\n 1883  1 2 2  4  2-45 <A>\n 1884  2 4 5  2  2-45 <B>*\n 1897  2 4 5  2  2-35 <C>*\n 1904  2 5 4  1  2-35 <D>\n 1909  2 5 3  1  2-30 <E>\n 1912  2 6 3  1  4-15 <F>\n 1958 1-2 6 31-2-2# 1-2-2 <G>\n 1988 2-1 6 31-2-2@ 1-2-2 <H>\n\nLength of the games: Halves 1883-1908; quarters since 1909\n\n*In 1885, teams could receive points by being deliberately drawn offside…\nwith an additional point being awarded for each subsequent offense.\nIn addition, points could be awarded for slugging, members of the opposing team.\n\n#Teams scoring touchdowns, were given the option--on the conversion--of kicking\nfor a single point or running the ball across the goal line or completing a\npassing for two points.\n\n@Defensive units were now awarded two points with the return of a fumble\nor a blocked PAT kick.
629543
PITCH--22 YARDS.\n\nGROUND HAS 160 METERS DIA. APPROXIMAYELY.
894864
http://en.wikipedia.org/wiki/Darts#Height_and_distance
328260
On an average pitch (115 yds * 75 yds) about 14.36 laps.\n\n\nEdit; That would be a 'proper' football (ie. soccer) pitch ; )
893603
illegal touching on the punter
740312
NFL - 10' height 18'6" width
956481
im not sure what you need but im guessing that you need to be fast, tell (over 6') and probably be able to catch 9 of 10 balls thrown to you..it all depends on your football team though.  If they are good then their standards would be a little higher.
1156466
It is \nBREHME Andreas (FRG) 85' on penalty
999997
I think you stay in the US. Don't be shame, I live in the US too and I am glad that we have one more person finds this game interested. \n\nDimensions \nThe field of play must be rectangular. The length of the touch line must be greater than the length of the goal line. \n\nLength: minimum 90 m (100 yds), maximum 120 m (130 yds) Width: minimum 45 m (50 yds), maximum 90 m (100 yds) \n\n\nInternational Matches \nLength: minimum 100 m (110 yds), maximum 110 m (120 yds) Width: minimum 64 m (70 yds), maximum 75 m (80 yds) \n\nThe half circle is penalty arc and really does not serve anything.
1131175
There is a rule that when a penalty kick is taken every player must be at least 10 yards away from the ball. The semi-circle is just for measuring that distance
1032709
Become 6'5" and 240 pounds. Most of the guys with big guns in football are also physcially big. If you are under six feet in height and you are throwing that far, then that's pretty good. You may try to find a book or website on throwing mechanics to see if you are doing the right thing. There's a link below. Hope it helps.
507444
A: The ball will be at a height of 6ft when y=6\nSo -16t^2+32t=6 dividing by -2\n8t^2-16t+3 =0\nSolving for t\nt1 = (16+sqrt(256 - 4*8*3)/(2*8) = 1.790569415\nt2 = (16-sqrt(256 - 4*8*3)/(2*8) = 0.209430585\nB: Put y = 5\n\nSo -16t^2+32t=5\n   16t^2 - 32 t +5 = 0\n\nt1 = (32+sqrt(1024 - 4*16*5)/(2*16) = 1.829156198\nt2 = (32-sqrt(1024 - 4*16*3)/(2*16) = 0.170843802\nThe kicker distance from the goal \nEither 8.54219012 ft \n   Or 91.4578099 ft  ( the right answer )