5)Suppose you travel north for 65 kilometers then travel east 75 kilometers. How far are you from your starti
543300
Use the quadratic formula. a^2 + b^2 = c^2. 65^2 + 75^2 = c^2. You get 99.247166206396039345852328631456.
779319
The distance travel is going to be 1/2 mile.   How far away are you are from the beginining of the first 1/4 mile could vary depending on how straight of a line you traveled and which angle you turned once you stopped but the maxium distance can not be greater than 1/2 mile (perfectly striaght line).  So C and D can not be correct.  A and B can be correct.  Being a perfectly straight road is not very possible then A is correct.  But if this is for your math class then most likely B is what the teacher is looking for.
458976
The answers for these questions:\n\nAnswer 1: (c) 27 meters\nAnswer 2: (d) .5 km\n\nAlthough the answer to 2nd question should be 0.4 kms, but I reckon it's just approximate. \n\nYou can email me for further help by clicking Contact Nitro in my answers profile.
782101
East bound speed=x, in 5 hours 5x\nWest                     =x+6,             5x+30\n10x+30=240\nx=21 miles per hour.\nEast=21\nwest=27\nVR
942078
This is Geography? miles = 20(hrs_up+10/60)=60hrs_up\n200/60=40hrs_up\nhrs_up=5/60 hours \ndistance = 60*5/60 = 5 miles
847424
d= v .t\n> d = 50 km/hr (18 min)\n>d = 50 km/60 min (18min)\nd= 50 km (18)/60\nd =900 km/60\nd = 15 km >>the distance travelled\n\nIf you walk at an average of 3 miles per hour (approximately 4.8 km/hr) at a distance of 15 km:\nt= d/v\n=15 km/4.8 km/hr\nt = 3.125 hrs or (3 hours and 7.5 minutes)>>the time you need to walk on 15 km at the speed of 4.8 km/hr.♥
454473
Depends on how fast your going.  It's 794 million miles away!  So divide that by how fast you want to go and you'll know.
1098175
Go to http://www.theaa.com/travelwatch/planner_main.jsp\nput in your start end points. this will give the distance. Assuming you walk 30km per day simply divide distance by 30
453482
Speed = Distance/Time\nDistance = Speed x Time\nDistance traversed = 48 x 2.5 = 120 miles\nDistance Remaining - 146 - 120 = 26 miles.
1169705
The answer is about 4.26 miles.\n\n7500 * 3 = 22500 feet / 5,280 feet in a mile = 4.26136 miles
557602
This is how you solve it. Use dimmensional canellation, but you will have to do it twice and subtract the difference\n\nA. (5 miles/1)  *   (1 hr/55 mi)  * (60 min/1 hr)\n   =5.45 minutes\n \n   \nB. (5 miles/1)*  (1 hr/65 miles) * (60 min/1 hr)\n   =4.6 minutes\n    \nYou saved 1.2 minutes. Not much at all. Which is what they say, speeding only saved 2 or so minutes in a 15-20 minute trip. BUt it tears the bejesus out of your engine
998475
4.28 billion km or\n2.66 billion miles )
76426
88+90+76=254\n254/4=63.5\n63.5km/hr\n\nTrust me...you would only use the 90km once in your calculation. You are adding the total km traveled. Then you divide it by the total time. I promise that this answer is correct.
456688
You'd have to go around the Cape Horn.  \n\nAnd I can't answer the question because I don't know how fast you're going.
799226
They travelled a total of 476 miles in 4 hours.  So together they are travelling (476/4) mph or 119 mph.\n\nSo you have two equations:\nJ + S = 119\nJ - S = 5\n\n2J = 124\nJ = 62 mph\nS = 57 mph
10487
1,000,000,000,000km\n621,371,192,237miles
869579
let the height of cliff be h\nthen \ndistance of first ship =x\ndistance of first ship =x+500\nnow \n1.h/x=tan 24\n2.h/(x+500)=tan 15\nfrom 1\nx=hcot24\nfrom 2\nx=hcot15-500\ntherefore\nh(cot15-cot24)=500\nh=336.47