How can we use Sine, Cosine, and Tangent in real life?
552070
The only way you can use those in real life if you become a geometry teacher and it does not help us in real life.
1094719
It's quite dificult to explain trigonometry this way, so it;s better for you to have an electronic teacher, this teacher is at your service day or night, sun or rain and  you could find it\n\nhttp://aleph0.clarku.edu/~djoyce/java/trig/\n\nhttp://www.sosmath.com/trig/trig.html\n\nhttp://fergusmurray.members.beeb.net/trig.htm\n\nhttp://mathworld.wolfram.com/Trigonometry.html\n\ngood luck
324968
its just triangle mathe. remember soh -cah -toa... sine =opposite side/hypotenuse,  cosine=adjacent side/hypotenuse, tangent= opposite side/adjacent side....cosecant(hypotenuse/opposite side) is the opposite of sine, secant(hypotenuse/adjacent side) is the opposite of cosine and cotangent(adjacent side/opposite side) is the opposite of tangent
1024676
For a simple wheel, you would use the formula.. \n\n(sin2 x)^2+(cos x)^2 =1\n\nsimilarly, every arc or every line drawn is formed of lines whose distance depends on the adjacent line or your screen size. (/2 or /4or some ration of it for position)
303020
The half-angle formula for tangent is:\n\ntan(x/2) = sin(x)/(1+cos(x))\n\npi/8 is not a very easy angle to work with, but pi/4 is. So let x = pi/4 in that half-angle formula it'll give you tan(pi/8).
1176396
sin=opposite/hypotenuse\ncos=adjacent/hypotenuse\ntan=opposite/adjacent
717403
There is only 2 ways to know an angle\n1. Know the other two angles \n2. know the length of 2 sides\nSince you don't know the other two angles, you need to use one of your trig functions, the only way to do this is to memorize the tables for sin, cos and tan for as many angles as you can manage, and then use your memorized chart once you figure out what ratio you are using.
835259
I'll give you a hint and let you try to figure out the rest yourself (unless someone else tells you the exact answer). =)\n\nUse your trig identities:\n\ntan A = sinA/cosA\n\ncot A = 1/tanA or cot A = cosA/sinA
282780
1.sin(2x)=2sin(x)cos(x)\n2.tan(x)=sin(x)/cos(x)\n3.cos(x)=(1-sin^{2}(x))^(1/2)\n\nwe can use (3) in (2) and (1) to eliminate cos(x). Then substitute sin(x)=y:\n\n1.sin(2x)=2y.(1-y^{2})^(1/2)\n2.tan(x)= y/(1-y^{2})^(1/2)\n\ntherefore,\n\nf(y)=2y(1-y^{2})^{1/2}\n     +y/(1-y^{2})^{1/2}\n\nI hope that's what you wanted.
225717
Yes. Think of the trignometric circle (radius = 1 and centered at the orgin (x=0, y=0). The so called tangent, is the line x=1 (that *is* tangent to this circle). The numeric value that we call tangent of an angle (alfa) is the y value of the intercept of a line passing thru the origin and forming an angle = alfa with the x-axis.\nIn other words, draw a trignometric circle and a verticle line tangent given by x=1. Draw another line forming an angle w/ the horizontal axis and passing thru the origin an stretch it so that it crosses that line. The height of the point of intercept of these two lines is the value of the tangent.\n \nThe co-tangent is the same but w/ y=1.\n \nEdit:\nThe secant is the distance from the origin to the intercept in the explanation above. Since it is a segment of the diameter, it is over a line that separates the trig circle, and is thus a secant.\n\nCheck out this link (skip the beginning of the page):\nhttp://www.npcts.edu/math/PreCalculus/Transcendental/Trigonometric/Definition/index.html
538675
For Sine 105- Perpendicular/Hypotenuse\n\nFor Cosine 105- Base/Hypotenuse\n\nFor Tangent 105- Perpendicular/Base\n\n\n* Perpindicular, base and hypotenuse are the three sides of the triangle.
984494
sine opposite/hypotenuse\ncosine adjacent/hypotenuse\ntangent opposite/adjacent
1092612
In quadrant one, sine, cosine, and tangent are positive. In quadrant two, sine is positive, and cosine and tangent are negative. In quadrant three, tangent is positive, and sine and cosine are negative. And in quadrant four, cosine is positive, and sine and tangent are negative.\n\nQuadrant 1 – Sin(+) Cos(+) Tan(+)\nQuadrant 2 – Sin(+) Cos(–) Tan(–)\nQuadrant 3 – Sin(–) Cos(–) Tan(+)\nQuadrant 4 – Sin(–) Cos(+) Tan(–)
564843
1) you can calculate distances and areas, which is very helpful in real life when buying ground\n\n2) you can calculate circles in triangles and rectangles, which is the twodimensional variant of dense packing of atoms in chemistry (crystals)\n\n3) you learn the angle functions, which you can use in physics for polar coordinats and optics and in astronomy for describing the positon of stars
956162
It depends on which leg you know the length of.  If it's the "adjacent"leg--the one that, along with the hypotenuse, forms the angle--then remember that the cosine of an angle is defined as the length of the adjacent angle divided by the length of the hypotenuse.\n\nIf it's the "opposite" leg--the one that isn't part of the angle--then you use the fact that the sine is defined as the length of the opposite leg divided by the length of the hypotenuse.\n\nEither way, you use the inverse trig functions on your calculator to find the angle.
510441
Divide both sides by cosX. We get 8sinX = 4. Now divide both sides by 8, then reduce. We get sinX = 1/2.\n\nThere are two solutions when looking at the sine curve:\n\nx = pi/6\nx = (5*pi)/6\n\nits very easy, make an honest effort to understand trig, and when you do the payoffs are exponential!
251440
memorize simple rules and try to derive the hard ones from simple ones and then to be fast then memorize the diffucult rules.Trigonometry is simple if you know basic El-Cebir well