The insertion point of deltoid is?
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(A) ... i confirmed with wikipedia\nV-shaped deltoid tubercle on the middle of the lateral aspect of the shaft of the humerus.
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http://www.edugraphics.net/gh-human_anatomy/gh235.htm
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http://pubs.acs.org/cgi-bin/abstract.cgi/jafcau/1953/1/i03/f-pdf/f_jf60003a008.pdf?sessid=6006l3
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Acute : a<90 d angles, 1st quadrant angles.\nObtuse :  a>90 90 d angles, >1st quadrant angles.
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Quadrilateral..........D is the correct answer.....
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insert here with an arrow :]]
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The arched middle part of the human foot between the toes and the ankle
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Yeah where's angle 1 and 2.\nBut remember the angle opposite the longest side has the greastest measurement.
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there are lots of medical devices taking ideas from trigonometry.\none simple example is hip prostheses..the angle at which it should be designed implanted and all are decided by trignometric techniques. I can give you more examples if you r really interested
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The shoulder or pectoral girdle consists of articulations between the clavicle, scapula and the proximal end of the humerus. Simply the joint.\n\nShoulder is the general term we use every day which consists of the muscles of deltoid and trapezius.
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Orthocentre = point where altitudes intersect (An altitude is the line from the vertex to the opposite side (extended if necessary))\n\nIncentre = centre of the incircle = point where perpendicular bisectors of each of the sides intersect. \nRadius of incircle = √[(s-a)(s-b)(s-c)/s] where s = semiperimeter\n\nCentroid = point where medians meet (Median is the line joining a vertex to the midpoint of the opposite sides) The centroid is the centre of gravity of the triangle and the centroid divides each median in the ratio 2:1 On a numberplane the centroid of a triangle is the point which is at the average of the sum of the three x- and y-coordinates of its vertices)\n\nOne other is:\nCircumcentre = centre of the circumcircle = point where angular bisectors meet.\nDiameter of circumcircle = a/sinA = b /sinB = c/sinC
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dy/dx = (dy/dt)/(dx/dt)\ndy/dt = 1/(2√t)\ndx/dt = 1\n\ndy/dx = 1/(2√t)\nx=t\ny=√t\n\nSubstituting t=1/4:\n\ndy/dx = 1\nx = 1/4\ny = 1/2\n\nUsing point-slope form:\n\ny-1/2 = 1(x-1/4)\n\nSimplifying:\n\ny=x+1/4
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becausre it is th ulbnar nerve being hit  at the groove of the base of the numerus bone. This "pun" plays on the similarity of the terms "humerous" and the bone's actual name, "humerus"
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To allow positive and negative motion so that you can bend the elbow or the leg.  Gotta have one to push and one to pull it back.
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Here is a website for Facts about INSERTION\n\nhttp://opbs.okstate.edu/~Melcher/MG/MGW3/MG32211.html\n\n\nHere is a website for facts about DELETION\n\nhttp://opbs.okstate.edu/~melcher/mg/mgw1/MG1214.html\n\nHere is a website for Facts on Replacement\n\nhttp://www.pubmedcentral.nih.gov/articlerender.fcgi?artid=544006\n\n\nI Hope all of this inforation is what you were looking for!!!
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Centered on the point of the collar.
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its the point which you are rotating the object around