how is the least count of an instrument calculated?
550259
Definition: The least count is that smallest unit of measurement which an instrument can take precisely (i.e., without any estimations, such as eye-estimation, etc.).\nOr,\nLeast count is the lower limit of precise measurement from a given instrument. Using an instrument, one can not precisely measure a quantity smaller than the least count of that instrument.\n\nExamples: If a meter-scale has millimeter divisions on it, the least count is 1 mm (so, one can't measure a length shorter than 1 mm from this scale). If a voltmeter dial has one volt divisions on it, the least count is 1 V. If a digital ammeter has a display like 0.000 (four digits), its least count is 0.001 A.\n\nMethod to calculate least count: If an instrument has main scale and vernier scale (e.g., the slide-callipers, the screw gauge, etc.), the least count may be calculated using the following formula:\nLeast count = M/N,\nwhere, M = Value of one (smallest) division on main scale (least count of main scale, in fact), and N is the number of divisions on the vernier scale.\nIf in a common slide-callipers the value of one division on main scale is 1 mm and the vernier scale of is divided into 10 equal divisions and thus the least count of the instrument is [M/N = 1/10], or, 0.1 mm.
825400
Two words:\nStill Counting
756047
When its actual length is at least a number plus a half but less than the next higher number.
706696
EDIT:  Left_Field is right, n = no of periods.  Corrections below\n\n\nIt is done by calculus.  Continuous compounding is\n\nA = lim(n->∞) P*(1+r/n)^nt\n\n= lim(n->∞) P*[(1+r/n)^n]^t\n\nlim(n->∞) (1+r/n)^n = e^r, e is the base of the natural logs\n\nA = P*[e^r]t = P*e^rt
1134542
The minimum is just a random signature.  That's good enough for most personal things.\n\nFor a business and if you want to play it more safe, add\n\n"For Deposit Only\nThe account number\nThe signature and/or the business name"
462713
Few is a relative term.  It can be 3 or 4, but it can also be hundreds.  ie..My dog has a few fleas (exact quantity unknown)
860146
The first value represents the (average) Minimun length recorded, the second the Average and the last the Maximum measured values. \nLength............141,5 mm..........161,5 mm..........181,1 mm. \nCircumference..117,5 mm.........127, 3 mm.........137,8 mm.\nKensey data are quite old. These statistic is the last one.
388021
Depending on the item and the cost of the item but normally it is only a misdemanor   but it is still on your record
8105
It should be the same methodology... the eps will be diluted by more expensing, and the number will be lower.
807986
1 I did this using Excel and got 92 withdrawals and the last withdrawal was R1156.15\n\nI'll do it the manual way:\n\n1.1) A = 108706.86 \nr = 15% pa = 1.25% per month = 0.0125\nW = 2000\n\nAfter 1 month\nA1 = A(1 + r) - W \n= A*1.0125 - W\n\nAfter 2 months\nA2 = A1 (1 + r) - W \n= A1*1.025 - W\n= (A*1.0125 - W)*1.025 - W\n= A*(1.0125)² - W*1.025 - W\n\nAfter 3 months\nA3 = A2 *1.025 - W\n= A*(1.0125)³ - W*(1.0125)² - W*1.025 - W\n\nSo after n months\n\nAn = A*(1.0125)ⁿ - W*(1.0125)^(n-1) - .... -  W*(1.0125)² - W*1.025 - W\n= A*(1.0125)ⁿ - W[(1.0125)ⁿ - 1]/(1.0125  - 1)\n= 108706.86*(1.0125)ⁿ - 2000*[(1.0125)ⁿ - 1]/(1.0125  - 1)\n\nNow we need to find the LEAST integer value of n for which \nAn ≤ 0\nie 108706.86*(1.0125)ⁿ - 2000*[(1.0125)ⁿ - 1]/(0.0125) ≤ 0\nie 108706.86*(1.0125)ⁿ ≤ 2000*[(1.0125)ⁿ - 1]/\nie 108706.86 ≤ 2000*[1 - (1.0125)^(-n)](0.0125)\nie 1 - (1.0125)^(-n) ≥ 108706.86 *(0.0125)/2000\nie 1 - 108706.86 *(0.0125)/2000 ≥ (1.0125)^(-n)\nie Log [1 - 108706.86 *(0.0125)/2000] ≥ -n log (1.0125)\nn ≤ -Log [1 - 108706.86 *(0.0125)/2000] /log (1.0125)\n= 91.58\nSo A91 is still positive and she will get 92 withdrawals\n\n1.2) When n = 91: A91 = last payment less interest (ie interest will need to be calculated on it before payout\n\nA91 = 108706.86*(1.0125)^91 - 2000*[(1.0125)^91 - 1]/0.0125\n= 1142.70 (nearest cent)\nAdd next month's interest and this will be the final payout.\nOne month's interest added tio amount left (for 92nd month) = 1142.70 * (1.0125) = 1156.98 \n\nSo by calculation she will get 92 payouuts with the last payout being R1156.98 (difference is truncation errors in the actual process as shown on Excel as it rounds every month while this did a direct calculation but still very very close
595633
When you are dividing by something you are trying to find out how many of a certain amount (say, 3) is in another amount (say, 12). The result for my example, is of course 4, since 3 goes into the number 12 four times.\n\nNow the number 0 is nothing, literally. So if you're dividing into, say 12, you're wondering how much nothing is in 12. That's just not possible, because 12 is all "something".\n\nI hope that's clear enough...I tried.\n\nEdit: The guy above me is wrong.
236101
permutation?\n\ni'm not sure what you mean by "see how many it is."
152305
It is a formula based upon past earnings and years of work.  To recieve anything there is a minimum amount of work that has to have been performed first in terms of calendar quarters of work.  That number is pretty low I believe.  Social Security sends a notice each year of how much money that would be.
135876
Least Count is the smallest time period that can be measured with the watch. For example, if I have a seconds watch with 120 divisions on the scale, least count is 0.5 seconds.
780468
The only thing I can come up with off the top of my head is that you can use least common factors to determine the lowest common denominator for adding/subtracting fractions.  For example, 2/15 + 5/36 ... the lowest common denominator is 3*5*3*2*2 = 180 (using the least common factors of 15 = 3*5 and 36 = 3*3*2*2).  Not terribly "real life" but a "real application" nonetheless.
194972
There is definitely a formula, but I can't figure it out exactly.  In the later rounds, you can usually add what money is left and divide it by the number of cases and get apretty much what will be offered.
921908
1\n\njust do a little bit of trial you will see that the smaller number you use it nears 1.