barium hydroxide ,when mixed with water ,gives a strongly basic solution.but iron(3)hydroxide ,when mixed?
537646
The thing is that iron III hydroxide isn't soluble in water.  It just sits there and doesn't make many hydroxide ions, which are necessary for a strongly basic solution.  Barium hydroxide, however, is soluble and breaks up into barium ions and hydroxide ions, giving a strongly basic solution.
1025655
Think of the net ionic equation which is occuring.\nSince both the HCl and Ca(OH)3 are dissolved in aqueous solution, broken into ions, just focus on the H+ and OH- part of it first.\n\nH+(aq) + OH-(aq) --> H2O(l)\nThe Hydronium ion and the Hydroxide ion react to form water.\nWhat is left over are the Ca+2 and Cl- ion which drop out of the net ionic eqaution since they form the very soluble compound, Calcium Chloride (CaCl2).\n\n2 HCl (aq) + Ca(OH)2 (aq) --> 2 H2O (l) + CaCl2 (aq)
630844
Barium sulfate is insoluble, so will not form an electrically conducting solution. It will, however, conduct electricity if molten.  It melts at 1350°C (2462°F). \n\nI hope that helps. If not, please re post.
112589
If you are talking of iron(III) phosphate, then it should be FePO4. For iron(II) phosphate, it should be Fe3(PO4)2. Both are possible but iron(III) phosphate is more thermodynamically stable.
426896
BaCO_3+HCl - BaCl_2+CO_2+H_2_O\n\nbalance it
861717
2 HNO3(aq) + Sr(OH)2(aq) --> Sr(NO3)2 (aq) + 2 H2O\n\n2 H3PO4(aq) + 3 Ba(OH)2(aq) --> Ba3(PO4)2 (cr)* + 6 H2O\n\n* Barium Phosphate will precipiate out of an aqueous solution in this reaction
908510
It should be Fe2+ + 2OH- --> Fe(OH)2 since you not only need to balance the elements but you also need to balance the charges.
829125
I dont understand what you mean by "correcting certain formulas", but it appears Fe bears +1 oxidation state, if oxygen is -2. However, Fe does not bear such oxidation state, normally; it can bear 0, +2, +3, +4 and +6. With oxygen, what you will get, most likely, are FeO and Fe2O3. So, I would expect the the compound was a mixture of iron metal and one/several of these oxides. It appears that your compound could be 1:1 mixture of iron and iron(II) oxide.\n\nIf the question states that the compound was pure, check your calculation again; if you have done nothing wrong, the compound could be iron(II) peroxide [iron bears +2, oxygen bears -1]; it's not stable [I'm not sure whether it exists or not], or the strange iron(I) oxide [again, never seen this compound before, not sure it actually exists or not].
103867
NaClO + 2FeSO4 + H2O -> NaCl + 2 Fe(3+) + 2 (SO4)(2-) + 2 OH(1-)
744922
HClO2 + Ba(OH)2 -> BaClO2 + H2O\n\n2(NH4)3PO4 + 3Ca(NO3)2 -> 6(NH4)(NO3) + Ca3(PO4)2\n\nFinished and balanced.
324126
The salt that is formed is Barium sulphate, which simply has low solubility in water (or acid or bases - you need a chelating agent for the Barium to dissolve it again). There is  no other significant reaction (like redox or altering pH).
809057
First of all, basic solutions contain more Hydroxide ions OH- than hydronium ions H3O+ (also known as H+)\n\nAny substances that when dissolved (ionized) in water and produces OH- ions are basic: NaOH becoes Na+ and OH-. NaOH is thus basic\n\nWe know that only weak bases/acids will produce a salt through neutralization which will affect the pH of the solution. For example, the conjugate acid of NH3 is NH4+. NH4+ can react will H2O to form NH3 and H3O+. Therefor, the solution will be more acidic. So we can conclude that positve charged ion can make the solution more acidic and negatively charged ions will make the solution more basic.\n\nHope this helps.
168285
Some elements have differing soluability depending on their oxidation state.  If the hydroxide of one oxidation state is insoluable but another oxidation state is soluable, then it would act as a test for oxidation state.\n\nAnother possible way for sodium hydroxide to act as a test for oxidation state is if the element in question has different colors in different oxidation states in basic pH.
108960
Rust is the common name for a very common compound, iron oxide. Iron oxide, the chemical Fe2O3, is common because iron combines very readily with oxygen -- so readily, in fact, that pure iron is only rarely found in nature. Iron (or steel) rusting is an example of corrosion -- an electrochemical process involving an anode (a piece of metal that readily gives up electrons), an electrolyte (a liquid that helps electrons move) and a cathode (a piece of metal that readily accepts electrons). When a piece of metal corrodes, the electrolyte helps provide oxygen to the anode. As oxygen combines with the metal, electrons are liberated. When they flow through the electrolyte to the cathode, the metal of the anode disappears, swept away by the electrical flow or converted into metal cations in a form such as rust.\n\nFor iron to become iron oxide, three things are required: iron, water and oxygen. Here's what happens when the three get together:\n\nWhen a drop of water hits an iron object, two things begin to happen almost immediately. First, the water, a good electrolyte, combines with carbon dioxide in the air to form a weak carbonic acid, an even better electrolyte. As the acid is formed and the iron dissolved, some of the water will begin to break down into its component pieces -- hydrogen and oxygen. The free oxygen and dissolved iron bond into iron oxide, in the process freeing electrons. The electrons liberated from the anode portion of the iron flow to the cathode, which may be a piece of a metal less electrically reactive than iron, or another point on the piece of iron itself.\n\nThe chemical compounds found in liquids like acid rain, seawater and the salt-loaded spray from snow-belt roads make them better electrolytes than pure water, allowing their presence to speed the process of rusting on iron and other forms of corrosion on other metals.
794784
OH- is the hydroxide ion. H2O is water and H3O+ is hydronium ions also known as H+
822075
For any reaction between a strong base (potassium hydroxide) and a strong acid (nitric acid) the end result is the neutralization of the acid and base to produce water.  The net ionic reaction will always be the same and show the reaction of the acid (H+) with the base (OH-) to form water.  Therefore,\n\nH+  +  OH-  --->  H2O
634552
an ion with both acidic and basic part