can you do k=j=x=1 in java this results to k=1?
552933
depends on what version of java you are using, if that doesn't work, simply do it by line:\n\nk = 1;
223041
uh..... no. Unless I am missing something, you substitute the 3 for 'x' and the 2 for 'y' and get 3+(3 x 2) = 3 + 6 = 9
958370
We wish to show that:\n[k=1, n]∑kk! = (n+1)! - 1\n\nClearly, this is true for n=1, since 1*1! = 2! - 1 = 1. Suppose it is true for some n. Then for n+1:\n[k=1, n+1]∑kk!\n(n+1)*(n+1)! + [k=1, n]∑kk!\n(n+1)*(n+1)! + (n+1)! - 1\n(n+2)*(n+1)! - 1\n(n+2)! - 1\n\nWhich is what we would get if we substituted n+1 for n in our formula. So by induction, the formula holds for all n. Q.E.D.
730496
iteration1: a = 3, b = 2\niteration2: a = 13, b = 8\niteration3: a = 51, b = 30\nloop exit:  a = 81, b = 30 // condition a = a + b executed before exit
44938
Let \nBlue = x\nYellow = y\n\nThen:\n2x + y = Green   [Given]
254641
I'm not exactly sure what you're asking, but it sounds like you're just solving for k(x).  There is not enough information to get a numerical value for k, if that's what you want.\n\ny=-2k\n-2k=2*x^2-3x+1\nk(x) = -x^2+(3/2)x-1/2\n\n\nOr, if you're trying to do what Ossininger said:\n\nk = 2*(-2)^2-3*(-2)+1 = 8+6+1 = 15
910422
no \n3x-1>1 \n3x>2 \nx>2/3
871837
Yes.\n\nSkew symmetry means that A^T=-A where A^T is the transpose of A. If (a_ij ) are the entries of A, this will say that\na_ji=-a_ij.\nWith i=j,\na_ii=-a_ii,\nso \na_ii=0.
325892
= 1-{1-[1-(0)]}\n= 1-{1-[1]}\n= 1-{0}\n= 1
846187
if you are using a "while" or "do while" loop\n\nwhile ((x1 - x0) > 0.001)\n{\n//your code here\n}\n\nor you can do this\n\ndo\n{\n//your code here\n}\nwhile ((x1 - x0) > 0.001);
710895
J = set of integers = { .... -3., -2, -1, 0, 1, 2, 3, ...}\n\nX = 10 in Roman numerals
379711
Easy Homework?\n\na=2, b=1, k=2, j=5, n=3.\n2^2=1^2 (mod 3), and 2=5 (mod 3) but 2^5=2 (mod 3) and 1^5=1 (mod 3), so 2^5 is not 1^5 (mod 3).
121013
if it is in binary, 1 + 1 = 10
599364
x^2 + x = x(x+1)\n\nIt can be simplified to x(x+1).
602540
x + 3 >  8 ==> x >  8 - 3  ==> x > 5\nx - 4 < -2 ==> x < -2 + 4 ==> x < 2\n\nAnswer... not possible.
717483
1\nbecause u have mentioned that 1=5 so 5=1 and it cant = 9
738298
[k+2]=13\nk+2-2=13-2\n       k=11