Then wat is - 25 P is 1 Q - & - 4 (b) P of a C -??? you guys are fast lol?
547805
25 percent is 1 quarter and 4 (basic) points of a compass
219072
Well, we have a+b+c=-98, ab+ac+bc=-33, and abc=-1 (this comes from expaning (x-a)(x-b)(x-c)=x^3 +98x^2 -33x+1). Hence, \n\n(a+1)(b+1)(c+1)=\nabc+ab+ac+bc+a+b+c+1\n=(-1)+(-33)+(-98)+1=-131\nand \n\n1/a+1/b+1/c=\n(bc+ac+ab)/abc=\n(-33)/(-1)=33.
139386
(X-c) here represents the number you are going to devide with. c can take any value here.\nLet you have to devide with (x-5) , then c will be 5.\nAnd if you have to devide with (x+10) then c will be -10. As (x-(-10))=(x+10).\nThe remaider therum says, If you devide a polynomial, P(x) by (x-c) then the remainder will be P(c).\nIf you want a proof of this theorum,\nlet, the divisor of divison of P(x) by (x-c) is A and remainder is B.\nSo P(x)=A*(x-c)+B.\nSo P(c)=A*(c-c)+b\nor, B=P(c) which is the remainder, I hope this will clear your concept.
1050252
a+b/c\n= -6+(-4)/-2\n= -10/-2\n=5
503348
No, the previous answer is wrong.\n\nGroup it like this:\n\n2p + pq -6q -3q^2\n\nthen factor like this:\np(2+q) -3q(2+q)\n\nfactor out the 2+q to get:\n(2+q)(p-3q)\n\nFOIL it out and you will see it is correct.
909020
Recall the distributive property: a(b+c) = ab +ac\nUse this on the second part of your equation where a = -2, b = p and c = 1.\n-2(p+1) = -2p + (-2)(1) = -2p -2\n\nSo 3p - 2(p+1) = 3p - 2p - 2 = p - 2
429835
ok, u have to use distance formula\n\nsqrt[(-4-(-7))^2+(c-7)^2]=5   \nsquare both sides\n[(-4-(-7))^2+(c-7)^2]=25      \nadd the stuff in the parentesies\n[(-3)^2+(c-7)^2]=25           \nexponents\n9+(c-7)^2=25                  \nsubtract from both sides\n(c-7)^2=16                    \nsquare root both sides\nc-7= +/-4                     \nadd to both sides\nc=11 or c=3
915896
if ur question is 4*565*(56c55)\nthen it is\np=4*565*1   (because 56c55=56!/55!1!)\np=2260\nelse \nmadness
622612
Joel, you need some help.  This is one of the easiest questions I have ever heard!  You should know this, man!  You're gonna fail your test if you keep cheating on here and don't actually figure out how it works.  Good luck, brotha'\n\nL = -2 or L(x) = -2
837784
1) -2 x (2/5 -2p)\n    =4/5+4p            after multiplying through by -2\n\n2) 1 x (9/20 -p)\n    =9/20-p              after multiplying through by +1\n\nThis has started you off you should be able to solve now!
963964
P=(1,2,1) Q=(1,5,5)\n\nThe parameterisation X(t) with parameter t generates all points on the line (or line segment, for 0<=t<=1)\nwith X(0)=P, X(1)=Q :\n\nX(t) = t*P + (1-t)*Q\n       =t*(1,2,1) +(1-t)*(1,5,5)\n(multiplying in, which is generally not needed)\n       = (1, 5-3t, 5-4t)
843943
4, 0, -2, -2, 0\n\nFigure it out! Don't be lazy!
622196
bc when u have 2 and you take 4 away from it, you are negative 2--- think of it like this: 2-4=-2
905278
Cool.  Just recall what our place value number system means.\n\n0 is in the 1s col, so it's absent\n3 is in the 10s col, so c = 1\n1 is in 100s, so a =2\n4 is in 1000s, so d =3\n2 is in 10,000s so b=4
860947
sqrt ( -1 * -1 ) doesn't equal sqrt(-1) * sqrt(-1).\n\nanother example:\n\nsqrt ( 5 * 5 ) = sqrt ( 25) = 5\n\nbut it doesn't equal sqrt(5) * sqrt(5) because this is an irrational answer..\n\nhope this helps
139621
Ran into a little difficulty, I can't find my math editor.\n\nBut here goes:\nx = (-b +,- SQRT(b^2 - 4ac))/2a\na = 3, b = -5, c = 2;\nx = (-(-5) +,- SQRT(25 - 24))/ 6\nx = (5 + 1) / 6; x = (5 - 1) / 6\nx = (1, 2/3)\nThis would have looked a lot better if I had my math editor!!!\n\nClarification: I solved your quadratic equation using the quadratic formula.\n\nMashi below simplified your quadratic equation, which you don't need the quadratic formula to do. Substitute the values of x I obtained by solving into the simplified equation, they will equal 0
565724
25=4(4x)\n25=16x\n25/16=x\nx=25/16\nx=1.5625