What is the name of this complex ion called "Fe(H2O)5(OH)2+".?
540870
Ferric monohydroxide pentahydrate ion\n\nor\n\nIron (III) monohydroxide pentahydrate ion
256406
4Fe3+ + 9O2 ->  6Fe2O3
599313
Refer to the electrohemical series (see source).  The answer depends on whether the conditions are such that iron is oxidized to Fe2+ or Fe3+.  In the case of iron metal being oxidized to Fe2+, the correct order is:\n\nMg, Zn, Fe, Sn, Pb
1008973
HF+ KOH  ---> KF +H2O can also be written as \nH+F- + K+OH- . ---> K+F- + H2O\nWe can canel out K+ and F-  since they appear on both side of the equation.  Thus the net ionic equation is H + OH ---> H2O.  The answer is D.
191092
zinc (Zn) sulfate (SO4) penta (5) hydrate (H2O)  so it would be zinc sulfate pentahydrate
733223
Fe3+,  I-\n\nNa+,PO43-\n\nK+,CrO42-\n\nCo3+, MnO4-
1061585
This is an ionic compound.  The (SO4) group has a negative 2 charge on the entire group.  It is called Sulfate ion.  The magnesium is the balancing positive charge (+2).\n\nAs a solid, the compound is a crystal.  When dissolved in water, The Mg+2 ions separate from the (SO4)-2 ions.\n\nThe compound is usually called Magnesium Sulfate.\n\nWith no water of hydration it is called anhydrous Magnesium Sulfate.  With 7 molecules of hydrated water in the cyrstals, it is called Epson salts (Magnesium Sulfate heptahydrate).
136772
It's a simple ion. There are carbonite, carbonate, and hypercarbonate ions as well, I'm guessing, that differ only in the number of oxygen atoms present in the ion. For example, for an ion named "hypo-something-ite" with 1 oxygen atom:\n\nhypo-something-ite: 1 oxygen atom\nsomething-ite: 2 oxygen atoms\nsomething-ate: 3 oxygen atoms\nhyper-something-ate: 4 oxygen atoms\n\nThis is what I remember from my high school chemistry courses, so I hope my memory isn't flawed.
405980
Felix\n\nFe= chemical formula for iron\nLix = roman for "59"
799504
FeS + 2HBr --> FeBr2 + H2S\nFe2+ + S2- + 2H+ + 2Br- --> Fe2+ + 2Br- + H2S\n2H+ + S2- --> H2S\n\nK2CO3 + CuCl2 --> 2KCl + CuCO3\n2K+ + CO32- + Cu2+ + 2Cl- --> 2K+ + 2Cl- + CuCO3\nCu2+ + CO32- --> CuCO3\n\npeace\nvixklen
62572
The concentration of hydrogen ion [H] and the concentration of hydroxide ion [OH] in any aqueous solution are related by an equalibrium expression, which is H2O in equalibrium with H+ and OH-.  There is an equalibrium constant associated with this Kw = 1.0 x 10^14 at 25 degrees Celcius.  [H] and [OH] are related.  Kw = [H]*[OH].  The simple and less technical answer is that as one concentration goes up say, [H], the concentration of the other [OH] goes down.
374219
For the cell reaction: FeO(s) + H2(g) = Fe(s) + H2O(l) \n\nDG0(298 K) = DGf0 Fe(s) + DGf0 H2O(l) – DGf0 FeO(s) – DGf0 H2(g)\n\nFrom any table of Thermodynamic Properties:\nDGf0 Fe(s) = 0 KJ/mol\nDGf0 H2O(l) = -237.192 KJ/mol\nDGf0 FeO(s) = -251.4 KJ/mol\nDGf0 H2(g) = 0 KJ/mol\n\nThen: \nDG0(298 K) = 14.204 KJ/mol\n\nFurthermore: E0 = -DG0/(nF) = -14204/(2 x 96500) = -0.074 V vs NHE (normal hydrogen electrode), where n: number of electrons in each half reaction (FeO/Fe and 2H+/H2, n=2) and F is the Faraday constant (96500 C/mol).
918374
Fe2O3 -- Fe+O2\n\nthis is the balanced form\n\n2(Fe2O3)--- 4Fe+3O2\nwithout the parentheses
752683
a) sulfur tetrafluoride\nb) molybdenum tetrachloride\nc) cobaltous sulfide or cobalt sulfide\nd) SnO\ne) ferric chloride\nf) CrO3\n\nComment: the above names are the ones you're most likely to encounter in industry or in a real-world laboratory.  Few chemists out here would call FeCl3 "iron three chloride"!\n\nOh, I know, your teacher probably expects "sulfur (IV) fluoride, molybdenum (IV) chloride, cobalt (II) sulfide, and iron (III) chloride..."
294058
FeCl3 is a Lewis acid, because the Iron loses electron density because of the chlorines. So it complexes with the lone pair in water on the oxygen atom. In doing so, a proton is released from the water, which then complexes with the other water molecules to make H30+
116824
The hydroxonium ions H3O+ or simply H+ ions
825401
First of all I assume  Na2Co3 should be Na2CO3.\n\nFe(CO)5 + 4NaOH = Na2Fe(CO)4 + Na2CO3+ 2H2O\n\nFirst, balance out the metals (Na and Fe) then C, which was already balanced. Then I chose to balance out H and which automatically balanced out O.