How long a pole would you need to to move the Earth?
537662
I assume this is an analysis of Archimedes' famous quote "Give me a place to stand, and I will move the Earth."  Unfortunately, while this is mathematically sound, it is practically impossible!\n\nLet me explain.  Say that the pole has a length L.  We'll place the Earth at one end, a person at the other end, and a fulcrum at a distance D from the Earth.  If the Earth exerts a force F_E and the person exerts a force F_0, then we have the equation\n\nF_E * D = F_0 * (L-D)\n\nThis was proved by Archimedes, of course.  We know that an object of mass M exerts a gravitational force of F = M g, where g = 9.81 m/s^2.  The Earth has a mass M_E = 5.9742 x 10^24 kg, and an average person has a mass M_0 = 70 kg.  This gives the the equation\n\n5.9742 x 10^24 * D = 70 * (L-D)\n\nso that L/D = 8.53457 x 10^22.  The length of the pole L depends on the location D where the fulcrum is placed.\n\nUnfortunately, this ratio is impractically large: If we place the fulcrum at a distance of D = 2 micrometers (which is slightly smaller than a strand of spider web), then the pole must be a length of L = 16.3 light-years.  This is farther in distance than the fartest known star!
925006
Since the magnitude of the acceleration is v^2/r, and the radius of the Earth is approximately 4000 miles (21120000 ft), you would have to solve the following equation: v^2/21120000=32\nv^2=675840000\nv=25997feet per second  or\nv=4.92 miles per second
225964
Depends where on Earth you are standing.  At the equator, it's just over 1000 miles per hour.  At either pole, it's virtually zero.
343251
Yes the earth would move but not that anyone would notice.\n\nEvery time you push off from the earth, the earth moves \nat a velocity equity to -your_velocity* your_mass/earth_mass.\n\n6 billion people would be less than 600  tons while the earth is about 5,972,000,000,000,000,000,000 tons
66810
Earth ranges from 7,926 miles to 7900 miles, depending on your location.\n\nThis is approximately 12,756km
990768
The Earth would weigh the same. The material you used to build the wall would come from the earth, yet just be relocated.
184255
The best thing would be a copper wire attached to a metal bar into the earth. Other choice would be the gorund wire in an electrical outlet (careful not to hit live wires) or to a rubber mat on a concrete floor
1164152
The earth rotates about its axis.  Obviously at the poles, there is no speed to the rotation at all.  At the equator, the circumference of the earth is about 25,000 miles and it rotates once per 24 hours, so the speed would have to be 25,000/24 = 1041.67 mph.  Depending on where you are between the equator and the pole, you'll get a speed of between 0 and 1041.67 mph.
240810
Earth is 12,742 kilometers (7,900 miles) in diameter. That's how far you would have to tunnel to dig to the other side of the Earth!\n\nThe circumference of the earth at the equator is 24,901.55 miles (40,075.16 kilometers).
1114726
How fast does the Earth rotate?\n\nIn round numbers the Earth is 25,000 miles around the equator, so 25,000 miles in 24 hours is 1,042 MPH.\nBut 1 foot from the pole, the distance around the earth is only 2*1*PI=6.28 feet which is 6.28/5280 or 0.00119 miles. That distance in 24 hours is 0.00005 MPH. At any latitude, the distance around the Earth is 25,000*cos(latitude). For example, at 30 degrees latitude the circumference is 25,000*cos(30)=25,000*0.866 or 21,651 miles. That distance in 24 hours is 902 MPH.\n\nIf the Earth rotated at 10,000 PRM, not only would we all be thrown off, but the Earth would tear itself apart. That is REALLY fast.
126028
Currently, the earth's north magnetic pole moves about 40 kilometers per year.  The rate has varied considerably; it was only 10 km per year a century ago.
849468
gravity at the earth's surface = 9.80 m/s^2
1169146
At least 12 feet.\nI could be wrong though.
981532
If you assume it is possible and of course it isn't but.... \nIf we also assume that there is no terminal velocity and that our momentum would take us past the centre and carry us to the other side. our velocity would be zero at the start and at the end and would reach maximum at the centre it would be V=(T x G) / D where V is velocity T is time G is acceleration due to Gravity (9.8 metres per second per second) and D is distance (12,756.32 kilometres). By moving the various components in this equation you should be able to find all the needed figures. The total time would be determined by found by finding the time needed to reach the centre of the Earth and then doubling it as the time needed to decelerate is the same as acceleration
459122
the side length is 2\nso the altitude should be 3^(1/2)\ngood luck
610006
The Earth's axial tilt varies between 21.5° and 24.5° with a 41,000 year periodicity (currently decreasing: 24.049 in 3300 BC, 23.443 in 1973, 23.439 in 2000), while the direction of the tilt gradually undergoes precession, moving in a slow circle over a period of about 25,800 years. However, other factors may change the axial tilt of Earth.
476223
The Earth rotates once in 24 hours, and its (equatorial) radius is 3,963 miles (6,378 km). As with the Moon, the rotational speed starts at zero at either geographic pole and increases as you head toward the equator, where it reaches its maximum of about 1038 mi/hr (1669 km/hr). At 45 degrees north or south latitude, the rotational speed is about 0.7 of this maximum speed.