what is the value of each variable?
540710
x=5*sin20=1.7\n\ny=5*cos20=4.7
133024
y = 0.\n\nETA: That's if we're to assume that the value of x is constant between the equations.
757845
x  y\n0 0\n1 -1/5\n-5 1
813845
A variable is used when ANY number can fit into the equation.  For instance, for the speed equation (s = d/t, where s is speed, d is distance, and t is time),  any number we choose for d, and any number we choose for t will give us s.  A variable is just that, something that vaires.
3995
Yes: there is 1 range value for each domain value\n\nThe domain values are the first numbers in each pair.  For each of them, -2, -1, 0, and 3, there is one range value.
730496
iteration1: a = 3, b = 2\niteration2: a = 13, b = 8\niteration3: a = 51, b = 30\nloop exit:  a = 81, b = 30 // condition a = a + b executed before exit
119401
Yes, it's a function.  Each x-value has only 1 y-value.
200150
for all of those, all u do is set once variable at a time equal to zero. for instance..\n\n-x+0=2\n-x=2  <--- multiply x and 2 by -1\nx=2\n\nthen..\n\n0+y=2\ny=2
808852
Sorry to say, you better pass on this data set.  \n\nNote that each row of numbers totals 100, as these are percentages, so the variables are correlated, and have limited application.\n\nI think your professor wants two of the variables to be somewhat independent, meaning one is not a function of the other.  Such as gas mileage and price, for example, if you had a list of automobile makes.\n\nRatio variables are those in which the ratio of two of the numbers have meaning, such as miles per gallon, for example.  If car A gets 15 mpg and car B gets 20 mpg, you can take the ratio of the two: 15/20 and compute 0.75, meaning car A gets 75% of the mileage of car B.
693011
You get one variable all by itself on one side of an equation.  Then you take what that variable equals, and replace the same variable in another equation with that answer.  easier to show with an example.  Suppose\n\n2x + 3y = 19\n\nx + y = 7\n\nSubtract x from both sides of the second equation to get y = 7 - x\n\nThen replace the y in the first equation with (7-x):\n\n2x + 3(7-x) = 19\n\nDo this out: 2x + 21 - 3x = 19\n\n-1x + 21 = 19\n\n-1x = -2\n\nx = 2\n\nThen plug in 2 for x and find y: 2 + y = 7\n\ny = 5
1047890
class C\n{\npublic:\nenum { NUM_VALUES = 10 };\n\nprivate:\ndouble m_values[NUM_VALUES];\n\npublic:\n// Sets the number stored at index i in m_values to v\nvoid SetValue(int i, double v) throw( std::exception )\n{\nif ( i < 0 || i >= NUM_VALUES ) throw std::exception("Index out of range");\nm_values[i] = v;\n}\n\n// Gets the number stored at index i in m_values\ndouble GetValue(int i) const throw( std::exception )\n{\nif ( i < 0 || i >= NUM_VALUES ) throw std::exception("Index out of range");\nreturn m_values[i];\n}\n\n    // Returns the mean of the numbers stored in m_values\n    double GetMean(void) const \n    {\n        double sum = 0;\n        for ( int i = 0; i < NUM_VALUES; i ++ ) sum += m_values[i];\n        return sum / NUM_VALUES;\n    }\n\n    // Returns the sample standard deviation of the numbers stored in m_values\n    double GetStandardDeviation(void) const \n    {\n        double mean = GetMean();\n        double sum = 0;\n        for ( int i = 0; i < NUM_VALUES; i ++ ) sum += (m_values[i]-mean)*(m_values[i]-mean);\n        return sqrt(sum/(NUM_VALUES-1));\n    }\n};
875702
can't you just loop through the array, have a variable for smallest number and one for position. \n\nthen in the loop, if current array value < than variable set the variable = to the current array value and set the variable pos = pos in the array\n\nthat way, when the loop ends, your two variables will hold the smallest value and the position in the array of that value,\n\nhope that's what you're after\n\ngood luck  :¬)
935764
u get all the values from an input table or something...assign the inputs to variables..code the update button to input those variable values into the database
755691
U have to use JavaScript for calculations.\nThere is a function 'eval' in JavaScript that takes the operators and operands as input and returns the result.\n\nE.g:  eval(7*5), it will return 35.
199081
Sorry, but I think you need to do this yourself.  Here are some guidelines though; give them a try.\n1.  Make a line drawing so you can see the info you're given and the path to the required answer.\n2.  Make a list of ALL the related formulae you were given.  Check each one against the given data; if you find one in which you have all the variables EXCEPT one, substitute and solve for the unknown.\n3.  Sometimes, you may have to use one formula to find a variable and THEN use that in ANOTHER formula to arrive at your ansver.\n\nGood luck!!
901623
a variable in maths?\nA variable in algebra is a letter used to replace a number. Such as x. Most commonly x, y, and n are used but any letter in the alphabet can be used.\n\nAnd if you're talking about science, then a variable is anything that could change the results in an experiment.
735121
y varies kx\n30 = .... wait a minute this question is impossible to do lol, u need to know two sets of values ( y, x).. either you said the question wrongly or the person who made it is dumb