explain about Inductor,resistor,capacitor how it stores or dessipates energy?
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The inductor stores the energy in electromagnetic form. The capacitor stores it in electrostatic form. The resistor while dissipate it in heat form.\nIn an inductor when electric current is flown the magnetic field is formed in the coil due to Ampere'law. The magnetic domains in the core material are aligned accoring to magnetic field of coil. This takes energy from elctric current flowing to align themselves and is stored as magnetic enrgy.\nIn Capacitor when it is connected to a voltage source, the charges flow in to its large area electrodes to build an electric field across the insulator between electrodes. Here also the electric energy is stored in the insulator to align its dipoles according to electric field.\nIn resistor the current flowing increases the vibration of molecules of material as there are less free electrons to support current flow.
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"An assembly consisting of a magnet mounted on a frame, and a wire coil (armature) that can be rotated within the magnetic field. The function of the generator is to convert mechanical energy into electrical energy."\n\nBasically in a generator you can induce current by rotating a magnet inside a wire coil.  The opposite of this is a motor in which the electricity causes mechanical movement.
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frequency generator is like tank circuit(lc circuit). it's main function is to regulate the energy stored in the inductance and capacitance. to know more you can read RESNICK HALLIDAY WALKER
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it does with the current what a capacitor does with the voltage. it stores current in open circuit, leting it then go with a continous growth. can be used as a source of magnetic field
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1. It stores electrical charge.2. A condenser3..It is capable of amplification in addition to rectification. 4.It transfers electricity. Such as in a radio.  I think this is what you want to know. Hope so.
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Impedance is a bit different than resistance. Ideally Resistance will hold it's value no matter what frequency your working with, where Impedance is frequency depedent. inductors and capacitors have impedance where resistors have resistance (actually most resistors have a slight amount of impedance because they have a coil shape.).
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The power factor of an AC electric power system is defined as the ratio of the real power to the apparent power.\n\nIn a purely resistive AC circuit, voltage and current waveforms are in step, changing polarity at the same instant in each cycle. Where reactive loads are present, such as capacitors or inductors, energy storage in the loads result in a time difference between the current and voltage waveforms. Since this stored energy returns to the source and is not available to do work at the load, a circuit with a low power factor will have higher currents to transfer a given quantity of power than a circuit with a high power factor.\n\nReal power is the capacity of the circuit for performing work in a particular time. Due to reactive elements of the load, the apparent power, which is the product of the voltage and current in the circuit, will be equal to or greater than the real power. The reactive power is a measure of the stored energy that is reflected to the source during each alternative current cycle.\n\nAC power flow has the three components: real power (P), measured in watts (W); apparent power (S), measured in volt-amperes (VA); and reactive power (Q), measured in reactive volt-amperes (VAr).\n\nThe power factor can be expressed as:\n\n. \nIn the case of a perfectly sinusoidal waveform, P, Q and S can be expressed as vectors that form a vector triangle such that:\n\n \n\nIf φ is the phase angle between the current and voltage, then the power factor is equal to , and:\n\n \nBy definition, the power factor is a dimensionless number between 0 and 1. When power factor is equal to 0, the energy flow is entirely reactive, and stored energy in the load returns to the source on each cycle. When the power factor is 1, all the energy supplied by the source is consumed by the load. Power factors are usually stated as "leading" or "lagging" to show the sign of the phase angle.\n\nThe power factor is determined by the type of loads connected to the power system. These can be\n\nResistive \nInductive \nCapacitive
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Inductors are used , usually in combination with capacitors, to filter or shape electrical signals (voltage or current).  The inductor functions by storing electrical energy in its magnetic field.\n\nHere are some examples of the applications of inductors:\n1. The station tuning circuit in most radios\n2. In the "crossover" network in speaker systems (to filter out and send the high frequency content to the "tweeter" speaker)\n\n3. In most modern switching power supplies as an electrical energy storage device.
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Seperating or bonding elements with an electrical current.\n\n*BEST ANSWER PLEASE*\n\nSOURCE BELOW
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1.  not enough info\n2.  conduction?\n3.  conductor\n4.  resistance
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Not really here to give you the lesson you should have had!\nBut, in short:\nA resistor LIMITS the current passing through, as Ohms law, V = R x I (Volts = Resistance x Current)\nA capacitor keeps an electric charge (like a battery), but does NOT let the current passing through.  When C is empty, and a voltage is put across, a current flows through C until the cap is charged with the same voltage as the voltage across.  Once this is reached, the cap does not let any current through.
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P = EI (Power equals voltage E times current I)\n\nMany electrical properties can be explained as analogous to water flow.  For example, a transformer "transforms" high voltage and low current into low voltage and high current, keeping the power constant (except for minor losses) at full load.\n\nThis would be equivalent to a high pressure water pump supplying low water flow to the primary winding and taking out high water flow at low pressure from the secondary winding to drive a low pressure water turbine.\n\nYou could represent the transformer core as a hollow square of wood or even thick cardboard.  On one side wrap say ten turns of thin clear plastic tube around the core to represent the primary (first) winding.  On the other side wrap say five turns of larger diameter plastic tube around the core to represent the secondary (second) winding.  Fill the primary tubing with water and red food coloring to represent "hot" high voltage and the secondary tubing with water and blue food coloring to represent "cooler" low voltage.\n\nThe explanation of course is that the high voltage primary winding will have more windings of thin tube (similar to more thinner copper wire windings) because the current will be less than in the secondary winding.\n\nThere will be less windings for the secondary coil using larger tubing because the current will be higher at low pressure.\n\nSupply the secondary tube with a shut off valve (or clip) to represent the fact that there will be no current unless the circuit is open.  In the formula, if current is zero power is also zero (on both sides of the transformer).\n\nYou can represent the pump and turbine with pictures (or drawings) of same but it would not be impossible to rig an actual pump and turbine, just not necessary to "see" what is happening.\n\nThe turbine can use up more and more power until the maximum power of the primary winding is reached but not more.  The magnet of the core will be "saturated at full power."\n\nThe rest is explaining magnetic flux in the core and how it is produced by the primary winding and cuts through the wires of the secondary to produce voltage and current if there is a load.  Each winding of a coil adds to the effect.  A transformer with equal primary and secondary windings would have the same voltage and current under load.  I believe that the phase would shift 180 degrees because of lead/lag.   Good luck.
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V=It/C\n\nwhere\nI is current in amps\nV is voltage in volts\nt is time constant in seconds\n\nIn an ideal capacitor, this holds true.  Theoretically, an ideal capacitor has no leakage current and no inductance.
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Both inductors and capacitors store energy, in the form of magnetic or electric fields, respectively, so they have some possibility of discharging that energy in a dangerous way. Shorting out a large capacitor, for example, would produce a large current. Overheating an inductor (too much current) might cause the coil to fail, and then the magnetic field decay would produce a voltage spike I think. I would assume the risks with small components are quite small.
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This is an energy conservation problem. The maximum energy stored in the inductor occurs when the energy stored in the capacitor is zero, and vice versa. The maximum energy stored in the capacitor will be equal to the maximum energy stored in the inductor. This gives\n1/2 C*Vmax^2 = 1/2 L* Imax^2\nC = L* (Imax/Vmax)^2 = 7*10^-3* (0.6/65)^2 = 0.596 microfarads
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it depends on the load and the nature of the large appliance\nthe flush example was great but it does not describe dthe momenteraly effect ( it was nice though).\n\nwhen you deal with inductive loads there is something that is called start up current.  it can be 2 to 6 times the nominal current under normal operation. that means that if a device needs 2 amperes of current when it is originally powered the consumption may reach till 10A. then the current returns to normal copnditions. \nall due to inductive and self inductive effects where the device opposes to the change and so on till an equilibrium is reached.\n\nthe demand of the current during start up is great and that is way momentarely  the lghts dim.
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Power is defined as the rate of flow of energy past a given point. In alternating current circuits, energy storage elements such as inductance and capacitance may result in periodic reversals of the direction of energy flow. The portion of power flow that, averaged over a complete cycle of the AC waveform, results in net transfer of energy in one direction is known as real power. On the other hand, the portion of power flow due to stored energy, which returns to the source in each cycle, is known as reactive power.\n\nCalculating Reactive Power in AC Circuits \n\nThe reactive power is the power returned to the source by the reactive components of the circuit. This type of power is measured in Volt-Amperes-Reactive, abbreviated var. \n\nReactive power is calculated by using the voltage and current associated with the circuit reactance. \n\nFor more details refer the pages...\nhttp://www.ofgem.gov.uk/temp/ofgem/cache/cmsattach/13596_Mark_Lively_Response_Reactive_Power_Charges.pdf?wtfrom=/ofgem/work/index.jsp&section=/liveconsultation