How do you factor (a2 square-4) step by step please?
540085
(a-2)(a+2)  \n(difference of squares)
267409
(-b + or - the square root of (b squared - 4AC)) divided by 2A
631400
Factor out the y:\n\n(a-2) * y = c\n\nThen divide both sides by (a-2):\n\ny = c / (a-2)
914755
your equation must be like x^2-3x-6 and your trying to factor this\n\n2 numbers say a and b must multiply to make -6 and add to make -3 so a*b=-3 and a+b=-6\n but i can't think on any that fits this criteria so you must use the quadratic equation\n\nx= [-b +-squareroot(b^2-4ac)]/2a\nwhere a=1 b=-3 and c=-6\nx= 3+-squareroot(9-4(1)(-6))/2\n\nx=(3+squareroot(33))/2 and x= 3-squareroot(33)/2\n\nin decimals x=4.3723 and x=-1.3723
81890
it's not factored completely if you leave it as a^2-25 so the proper answer is 5(a-5)(a+5)
781910
not possible to factor easily ... try the quadratic formula.
297635
you can factor this easily\n2 numbers that add to -8  and multiply to -33    (-11 and 3)\n so then u just    do  (x-11)(x+3)    and  if the product=0, then 1 of them has to equal 0. so either x-11=0 so x=11      or x+3=0   and x=-3. so      the 2 answerz are     11,-3. you should try to do it yourself first instead of just askin for answers. if you cant easily factor it, then use the quadratic equation\n\nx = [-b +-   sqrt (b^2 - 4ac)]  / 2a\n\nand put in the values of a, b, c. in this case a is 1, b is -8  and c is -33. so you can do\nx = 8+- sqrt (8^2 - 4 (1) (-33))   /  2\n  = 8+- sqrt (64 +132) / 2\n  = 8+- sqrt (196) / 2\n  = 8+- 14 / 2\n  = 4+-7\n  = 4+7           or        4-7\n  =  11     or  -3
418401
While looking for easier ways to do things with factors, I realized there might be a commonality between the left side and the right side.\n\nfactor a 2 out of the left side...\n2(17x-3.8) = (17x-3.8)(x+12.5)\n\ndivide both sides by (17x-3.8)...\n2 = x+12.5\n\nsubtract 12.5 from both sides...\n-10.5 = x\n\nAnd there you have it.  x = -10.5\n\n\nAnother possible approach would have been to do what the second answerer suggested, but use "completing the square" instead of the quadratic formula.
259003
Use the quadratic formula.  It works everytime!\nx = (-b plus or minus sprt(b^2 - 4ac))/2\nwhere\nax^2 + bx + c = 0\nSome of these will factor, however not all of them will.
1049820
The quadratic formula:\nx= -b(+/-) the square root of (b squared - 4ac), all of this over 2a
825052
The first step would be to try to factor the equation, so you'd want to get all of the terms on the left side of the equation:\nx^2 + 4x -3 = 0\n\nSince this won't easily factor, you need to use a different method.  I'm sure someone will suggest the quadratic equation, which is fine _if you can remember it_.  I much prefer an alternate method, "completing the square," because it's intuitive enough that you can remember how to work out the process even if you forget the steps.\n\n1. Start by moving the constant to the right side of the equation:\nx^2 + 4x = 3\n\n2. Then divide the coefficient of x (in this case, 4) by two and square it, adding it to both sides of the equation:\nx^2 + 4x + 4 = 7\n\n3. Factor the left side of the equation to (x + a)^2, where 'a' will be the number you just squared:\n(x + 2)^2 = 7\n\n4. Take the square root of both sides, remembering that you'll have both a positive and a negative root:\nx + 2 = +/- (sqrt)7\n\n5. Move the constant on the left to the right, and you have your two solutions:\nx = -2 +/- (sqrt)7
810284
i got 2x^2-x-3 R -4\n\nfirst divide 2x+5 into 4x^3+8x^2-11x-19 and you get 2x^2 then you subtract and your left with -2x^2-11x-19 and then you divide that by 2x+5 and you get -x add that to 2x^2 and you get 2x^2 - x then you subtract from your original and get -6x-19then divide 2x+5 into that and you get -3 ((2x^2-x-3)) multiply that by 2x+5 and you subtract from -6x-19 and you get -4 you cant divide 2x+5 into that so -4 is your remainder
165354
To factor x^2 - 100 by the difference of 2 squares, figure out what times itself = x^2, and what times itself = 100\n\nThen put the two answers (x and 10) in binomials like this:\n\n(x+10)(x-10)\n\nWhen you multiply this out by FOIL (at least that's what we call it), the -10x and the 10x "cancel out" and all that's left is x^2 - 100
972642
(A^2+2ab+b^2)/(a+b) + (a^2-b^2)/(a-b) + (a-b)/(a+b)/(a^2-b^2)/a+b)\n(a+b)^2/(a+b)+(a+b)(a-b)/(a-b)+ (a-b)/(a+b)*(a+b)/(a^2-b^2)\na+b+a+b+(a-b)/((a+b)(a-b))\n2a+2b+1/(a-b)\n\nif I got all the ( ) in the right places.
896553
4x^2+8x-x-2\n(4x-1)(x+2)
821200
(x²+4x+4) / (2x-3) / (x²-4) / (2x²-7x+6)\n\nYou have 4 terms and three divisions, so it's a little unclear if you mean (a/b) / (c/d) or what.  I will try to help to the extent I can.\n\nLet's assume you mean:\n\n[ (x²+4x+4) / (2x-3) ] / [ (x²-4) / (2x²-7x+6) ]\n\nFactor your x² equations to see if you can cancel terms:\n\nx²+4x+4 = (x+2)(x+2)\nx²-4 = (x+2)(x-2)\n2x²-7x+6 = (2x-3)(x-2)\n\nWoohoo - things are looking good!  Now we can rewrite our original problem using these factors:\n\n[ (x²+4x+4) / (2x-3) ] / [ (x²-4) / (2x²-7x+6) ] = \n\n[ (x+2)(x+2) / (2x-3) ] / [ (x+2)(x-2) / (2x-3)(x-2) ] =\n \n[ (x+2)(x+2) / (2x-3) ] * [ (2x-3)(x-2) / (x+2)(x-2) ] =\n\nnotice we can cancel out three terms: (2x-3), (x-2) and (x+2)\n\n[ (x+2)(x+2) / (2x-3) ] * [ (2x-3)(x-2) / (x+2)(x-2) ] =\n\n(x+2)\n\nHope that helped!\n\n~ ♥ ~
283601
1) First we move all the factors with x to one side, and the ones without x to the other.  Result will be:\n\n4x/3 - 2x + x = 3/2 + 1/5\n\n2)  Then, we factor out an x from the left side and get:\n\nx(4/3 - 2 + 1) = 3/2 + 1/5\n\n3)  Calculate the actual numbers on both sides\n\nx(4/3 - 6/3 + 3/3) = 15/10 + 2/10\nx(1/3) = 17/10\n\n4)  Divide both sides by 1/3 and get a final result of...\n\nx = (17/10)/(1/3)\nx = (10/17)*(3/1)\nx = 30/17\n\n5)  Comform that I PWN n00bs.  And... I'm pretty sure I pwn n00bs.  Therefor, we are done!  ^-^