how do you do this problum it dealing with factor the expression. x sqaured - 20x +225?
550263
it's a no solution problem. Unless you change the 20x to 30x, it's unsolvable.
791576
I'm going to assume the placement of parenthesis.\n(x^2 – 3x + 2)/(8x - 8) ÷ (x^2 – 4)/(5x +10)\n\nStep 1: Flip the second fraction, so that you have multiplication instead of division.\n(x^2 – 3x + 2)/(8x - 8) * (5x +10)/(x^2 – 4)\n\nStep 2: Factor.\nx^2 – 3x + 2 = (x - 2)(x - 1)\n8x - 8 = 8(x-1)\n5x +10 = 5(x + 2)\nx^2 – 4 = for a^2 - b^2, the factors are (a + b)(a - b). So: (x + 2)(x -2)\n\n(x - 2)(x - 1) / 8(x-1) * 5(x + 2) / (x + 2)(x -2)\n\nStep 3: Cancel out, multiply\n(x - 2) / 8 * 5 / (x -2)\n5 / 8 (solution!)
820839
x+4+x= -20\nFirst collect like terms.\n2x+4= -20\nGet rid of the 4. Subtract 4 to both sides.\n2x+4-4= -20-4\n2x= -24\nIsolate the x. Divide both sides by 2.\n2x/2= -24/2\nx= -12
283601
1) First we move all the factors with x to one side, and the ones without x to the other.  Result will be:\n\n4x/3 - 2x + x = 3/2 + 1/5\n\n2)  Then, we factor out an x from the left side and get:\n\nx(4/3 - 2 + 1) = 3/2 + 1/5\n\n3)  Calculate the actual numbers on both sides\n\nx(4/3 - 6/3 + 3/3) = 15/10 + 2/10\nx(1/3) = 17/10\n\n4)  Divide both sides by 1/3 and get a final result of...\n\nx = (17/10)/(1/3)\nx = (10/17)*(3/1)\nx = 30/17\n\n5)  Comform that I PWN n00bs.  And... I'm pretty sure I pwn n00bs.  Therefor, we are done!  ^-^
389436
5x4+4+4+5+4/2\n=20+4+4+5+2\n=35
919174
first multiply the first two factors and multiply the product by the third factor\n\nTo multiply something complicated like (4x + 6)(5x - 3)(15 - x), just do FOIL on two of the binomials and then distribute the answer onto the remaining binomial
528350
(5x + 4)(6x + 4)\n30x^2 + 20x + 24x + 16\n30x^2 + 44x + 16\nANS : 16
607601
I think you set the equation to zero then you have to factor it.  Go to the link below if you wanna know how to do it. OR look your your math book.
951977
-60 + 20x = 24x +72\n-60 = 4x +72\n-132 = 4x\n-33 =x
684474
You have to factor each part first, then cross off (cancel) identical factors from the numerator and denominator of either expression.  If the factors are exact opposites, like x-8 and 8-x, cancel and put a -1 in the numerator.\n\n\nIn your example only the first expression is factorable:\n(x-8)(x+3)/(2x)(3+x) times 5x^2/(8-x)\n\nThe (x-8) cancels the (8-x) to become -1, then (x+3) cancels the (3+x), and the x from the (2x) cancels one of the x's from (5x^2)\n \nAnswer: -5x over 2
837603
factor a 2 out of the first two terms\n2(x^2-x)-40\ncomplete the square\n2(x^2-x+1/4)-40-1/2\n2(x-1/2)^2-40.5\nthe vertex is at x=.5    y= -40.5
665603
you put (x+2) in for x in the equation first\n\n((x+2)^3)+(2(x+2)^2)-4\n\nthen simplify \n\nx^3 + 8x^2 + 20x + 12\n\nand multiply the entire thing by 3\n\n3(x^3 + 8x^2 + 20x + 12)\n\n3x^3 + 24x^2 + 60x + 36
993104
take the equation x^2 - 7x + 12 and do the following  (x ) (x) now...see that there is a - and a + in the equation....you need to do this ( x -  ) ( x - ) 'cause you put the minus in the first factor in the second factor you take the - and the + and multiply them....So you get (x- ) (x -) the other 2 terms for each equation comes from the 7x and the 12.  What you do is to find 2 numbers that multiplied gives you 12 and added give you 7....The numbers are 3 and 4 ...Then put them into your factors (x-3)(x-4).\n\nFor the other 2 equations you do the same process\n\n(x^2 - 8x + 7) = (x-  ) (x-  ). In this one, you have to find 2 numbers that multiplied give you 7 and added give you 8. They are 1 and 7. Then (x^2 - 8x + 7) = (x- 1 ) (x- 7 ).\n\nw^2 - 8w + 15 = (w - ) (w- ). As you saw in one and two, three is the same....so the factors are 3 and 5. Then, w^2 - 8w + 15 = (w -3 ) (w-5 )\n\nFor the solve...\n1. x^2 - 6x = 0\n2. x^2 - 2x - 3 = 0\n\nTHe 1 is like this...you have to complete your quadratic equation then you do the following x^2 - 6x = 0 --> x^2 - 6x + 9 =0+ 9...The 9 in the right side was added in order to keep the two sides equal...IN the left side you got a perfect quadratic equation, hence it will be (x-3)^2= 9....Now you pass the 9 of right to the left ...then it will be [(x-3)^2]-9=0\n\n\nThe other equation x^2 - 2x - 3 = 0....This one is quite simple, it is the same as the part 1...The difference is that when you find the factors, they will be 2 numbers that multiplied give you 3 but substracted gives you 2.....The #s are 3 and 1....Here is the thing....when you break the equation into factors, you will have the following (x- ) (x+ )...Since you have a -2 that means that it is the -3 and the +1...Hence your factors will be the following (x-3)(x+1)
282749
You will need to place the parentheses at the proper places. To help you out, I have assumed where they will be and solved it. Please confirm if these are correct. If not, rewrite the problem and I will try to solve it.\n\nThe text you find in between the steps is an explantion of what I have done...\n\n(7x/(x^2 + 4x)) divided by (35x^2/ x+4). This is my assumption.\n\nRewriting the problem in mathematical form\n= (7x/(x^2 + 4x))/(35x^2/ x+4)\n\n\nDividing by a fraction is the same as multiplying by its reciprocal\n= (7x/(x^2+4x)))*((x+4)/35x^2)\n\nRewriting after moving out the dommon factor in the denominator of the first fraction. [x^2+4x = x(x+4)]\n= (7x/(x(x+4)))/35x^2/(x+4) .)\n\nCanceling out the common terms in the numerator and denominator. Here it is (x+4)\n= (7x/x)*(1/(35x^2))\n\nCanceling out more terms. Here it is x\n= 7/(35x^2)\n\nCanceling out more terms. Here the number 7\n= 1/5x^2\n\nThis will be the final answer.
958467
Replace x with 2:\nf(2)=2^3-4(2)^2+14(2)-20\nf(2)=8-16+28-20\nf(2)=-8+8\nf(2)=0
875144
you have to take the square root of each side, then just simplyfy\n\nx = 1.2472191289247
165354
To factor x^2 - 100 by the difference of 2 squares, figure out what times itself = x^2, and what times itself = 100\n\nThen put the two answers (x and 10) in binomials like this:\n\n(x+10)(x-10)\n\nWhen you multiply this out by FOIL (at least that's what we call it), the -10x and the 10x "cancel out" and all that's left is x^2 - 100