Units for enzyme activity?????
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Enzymatic activity can be quantatively define, but it is very specific, depend on what kind of emzyme reaction and what experimental approach to access it.
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Use this webpage...use the drop down menu to choose different units....good luck!\n\nhttp://www.matweb.com/tools/conversion.asp
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The answer is c.\nC12H22O11+12O2-->12CO2+11H2O
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http://www.biologymad.com/master.html?http://www.biologymad.com/Enzymes/enzymes.htm\n\nhttp://www.tvdsb.on.ca/westmin/science/sbi3a1/digest/enzymes.htm\n\nhttp://www.activescience-gsk.com/miniweb/content/enzymes/how_do.htm\n\nI use these websites with my students...it has some basic enzyme info.\n\nAn enzyme is active only when there is substrate present. So therefore, the rate of activity will increase when thre is "something to do!"
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Newtons is the unit for measure of force
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Well, H202 would be the substrate....and I forget what enzyme degrades H2O2........its in the peroxisome i think...
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C12H22O11+12O2-------12CO2+11H2O+E
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I dont know if this will help but here is a web site I found!\n\nhttp://www.biochemj.org/bj/119/0017/1190017.pdf
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do ur experiment, plot graph enzyme activity Vs. concentration.........from the graph the highest enzyme activity divide by half....draw a line to the graph that u PLOT and from there scroll down to the X-axis and here u are , u get the IC50 value.the concentration is Ur IC50 value.
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http://ajpregu.physiology.org/cgi/content/full/280/5/R1388
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1) b)\n\n2) [H2O]^2 / 2[H2] [O2]\n  \n   [NO]^2 / [N2] [O2]\n\n3) b)\n\n4) b)
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Mg is neseccary for the catalytic reaction. A lot of enzymes have an ion in their catalyitic center which usually co-ordinate the reacting groups.
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http://genchem.chem.wisc.edu/sstutorial/FunChem.htm
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divide 200g by the molecular weight of KCL and then divide that by .8
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Heparin comes in various concentrations\n1u /cc\n10u /cc\n100u /cc and many others\n\nALL YOU HAVE TO DO IS USE THE FOLLOWING\n\nDesired units &#92; concentration\n\nif you want to give 12 units and you have 10u /cc\nthen the answer is 12/10 =1.2cc
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2 MnO4-(aq ) + 5 H2C2O4(aq ) + 6 H3O+(aq ) --> 2Mn2+(aq ) + 10 CO2(aq ) + 14 H2O
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http://www.chembio.uoguelph.ca/educmat/Chm258/enzplots.htm\n\nsee if that site helps any.  If not.  I can give you a very confused book answer from my Biochemical Calculations text.  It might be hard to explain online though, sorry.  The text I use (as a graduate student--biotechnology) is Biochemical Calculation 2nd Ed. by Irwin H. Segel, it's a great book.