algerba 2........ 6^(-.2x)-3=7,,,... 7log (base of 5)x-3=15?
545001
1. 6^(-.2x)=10\n(-.2x)ln(6)=ln(10)\nx=-5*ln(6)/ln(10)\n\n2. 7log_5(x)=18\nlog_5(x)=18/7\nx=5^(18/7)
976913
Please show your exponents using the ^ operator:  It will make these problems much clearer.  Also, I would have put this in 'Mathematics' rather than Chemistry.\n\nFirst equation:\n(6s^5)(2s^2) \n\nGroup your integer coefficients:\n6*2 = 12\n\nGroup your s terms:\ns^5 * s^2 = s^7 (multiplying like bases, just add the exponents)\n\nSecond equation:\n(3s^4)(4s^3)\n\nMultiply integers:\n3 * 4 = 12\n\nMultiply s terms (add exponents):\ns^4 * s^3 = s^7\n\nSo your answers should both be:\n12 s^7
893261
15a = 3(3a+8)\n15a=9a+24\n15a-9a=24\n6a=24\na=4
674167
Solve this by using logarithms\nlog((1/5)^2x) = log(625)\n2x*log(1/5) = log(625)  Product Rule\n2x = log(625)/log(1/5)\n2x = -4\nx = -2\n\ntosmith
829854
Use logarithms to bring exponents down where you can deal with them.  Since the natural log is base e, that's the way to go here.\n\ne^5x = 7\n\n5x = ln 7\n\nand solve from there.
486697
You do not need to use logs.\n27 can be written in base 3\n27 = 3^3\nTherefore,\n27^4 = (3^3)^4\nMultiply the exponents to get\n27^4 = 3^12\nThus, your equation is not\n3^x = 3^12\nWhenever the bases are the same, then the exponents are equal.\nTherefore,\nx = 12
808003
Do you know your log identities?  That would help you here a lot!\n\nUse these log identities to solve your problems:\n\n. log(a) + log(b) = log(ab)\n. log(a) - log(b) = log(a/b)\n. c*log(a) = log(a^c)\n\nSo, for problem 1 (I'm assuming the "a" means that "a" is your base) we get the following:\n\nlog a(y+5)+2log a (x+1) =\nloga(y+5) + loga((x+1)²) =\nloga((y+5)(x+1)²)  \n\nProblem 2:\n\nIn(x+5)-In(3)=In(x-3)\nln((x+5)/3) = ln(x-3)\n(x+5) / 3 = x-3\nx + 5 = 3x - 9\n2x = 14\nx = 7\n\nProblem 3:\n\n3^x+5=9^x\n\nIs 3 raised to the power of x only, or to the power of x+5?  It's hard to tell, and it does matter to the solution.\n\n~ ♥ ~
484284
4x-7=2x+15\n4x-2x=15+7\n2x=22\nx=11\n\nto check your work\n4(11)-7=2(11)+15\n44-7=22+15\n37=37
33091
3m(-6m-2m^2 p - 10p) = 3m(-6m) - (3m)(2m^2 p)- 3m(10p)\n= -18m^2- 6m^2 p - 30mp
712942
x^6 - 6x^5 + 15x^4 - 30x^3 + 15x^2 - 6x + 1 = 0\nx^6 - 6x^5 + 15x^4 - 20x^3 + 15x^2 - 6x + 1 - 10x^3 = 0\nSo (x - 1)^6 - 10x^3 = 0\nSo ((x - 1)²)³ - (³√10x)³ = 0\n\nSo ((x - 1)² - ³√10x)((x - 1)^4 + ³√10x((x - 1)² + ³√100x²) = 0\n\nSo ((x - 1)^4 + ³√10x((x - 1)² + ³√100x²) = 0 N0 real roots (Min value near x = 0.2 just more than 0.87)\n\nOR (x - 1)² - ³√10x = 0 \nie x² - (2 + ³√10)x + 1 = 0\nie x = ½[(2 + ³√10) ± √(4 + 4³√10 + ³√100 - 4)\n= ½[(2 + ³√10) ± √(4³√10 + ³√100)]\n\nSOLUTION\nx = ½[(2 + ³√10) ± √(4³√10 + ³√100)]
45378
a) -6(a+5b)-3(-7b-a)\n=-6a-30b+21b+3a\n=-3b-9a\n\nb)6(a+2b)+8a-16b\n=6a+12b+8a-16b\n=14a-4b
534868
7\nbecause\n6m+5=47\n.....-5 -5\n   6m=42 (divide each side by 6 and u get 7 {42/6 =7)
8473
7t+15 > 3t-13\n4t > -28\nt > -7
1133153
7 - 2[4-6+2x] - 8+ x=6\n\n7 - 2[-2+2x] - 8 +x =6\n7 + 4 - 4x - 8 + x =6\n3 - 3x = 6\nx = -1\n\nDon't listen to the math goober - plug the value in and check it.
1021030
7= 2x + 6\n=> 7 - 6 = 2x\n=> 1 = 2x\n=> x = 1/2 = 0.5\ni got the required equation like this:\n7 is more than twice a number increased by 6\n7=                      2x                         +                6\n\njust translated ur words into numbers ,mathematical signs and a variable.\nthink u got my point?\ncheck ur answer if u have any inur text book.
245399
log base (1/5) of 78125 = -7\n\nlog|(1/5) 78125=-7
747277
5a+6b-3a+b=?\nSimplified= (2a+7b=?)  or (2a = -7b) or (7b = -2a)\nThey are all the same\n\n15x-3y-7x-4y=?\nSimplified = (8x-7y=?)  or (8x = 7y) or (-8x = -7y)\n\n15m-17n-23m+25n=?\nSimplified -8m+8n=? or (8n=8m) or (n=m)