How do you find the density of air exhaled?
540563
weigh the graduated cylinder full with water.\ninvert the cylinder (still full) in a tub of water.\nblow bubbles into the cyliner to find the volume of the air you blew in.\nremove and reweigh the cyliner.\n\nit may be a little tricky, but it's not too bad.
980362
you cant you have to have mass and volume to find density
894614
PV=nRT\nP= (nRT)/V  (1st eq)\n\nn,R,T u know.\n\nV >>>\nDensity = mass/ volume\n2.3 = .00446 *10^3/Volume\n\nrearrange and ull get volume.............and then put that into the first equation.............and voila
349502
Find the weight the object (with a precision scales) and its volume (put it in water and look at the amount displaced).\n\nCalculate the density = weight (in gram) / volume (in milliliter)\n\nYou will find a number lying between 19.3 (density of pure gold) and 8.92 (density of pure copper). Say you found 18 gram/ml\n\nThen the amount of gold is   (18-8.92)/(19.3-8,92) = 87.5% gold
280201
Density = mass/volume
74771
hecka!!  damn.  i miss california.\n\nwhat you have to do is realize that this question is asking about the volume of a rectangular shape that is 1 meter by 1 meter by X meters, where X is the height of the column.\n\nso, you know the density.. density is defined as mass divided by volume.  and you know the weight.. which is mass times acceleration.  here the acceleration is the acceleration of gravity "g" = 9.8 m/s^2.  \n\nso you can do a little algebra to get the equation volume = mass / density \nvolume = weight / (acceleration * density)\n\nyou know the weight (100,000 N), the acceleration (9.8 m/s^2) and the density (1.2 kg/m^3).  plug those numbers in and you get the VOLUME of the atmosphere, and since you know 2 of the dimensions of the box (it is 1 square meter across the bottom face, remember) you can figure out the 3rd pretty easily.\n\nsince this is your homework i wont just tell you the answer, but you should be pretty much able to crank it out from here.
802793
To find the density of this gas you have to use the ideal gas law with the molar mass and the density in it. molar mass=density * the gas constant, R,  * the temperature in Kelvin.  To find kelvin, add 273 to the temperature in Celsius. Example: 27+273=300. To find the pressure in atmospheres, divide the 723 Torr by 760, because there is 760 Torr in one atmosphere.  Then manipulate the equation so it looks like density = the molar mass * the pressure in atmospheres/ .0821 L*atm/mol*K (which is R) * the temperature in Kelvin.  Find the molar mass of the sulfur hexaflouride, 146.1 grams per mole, and plug in the numbers.  The answer should be 5.641 grams per Liter.
145449
The density of air, ρ (Greek: rho) (air density), is the mass per unit volume of Earth's atmosphere, and is a useful value in aeronautics. In the SI system it is measured as the number of kilograms of air in a cubic meter (kg/m3). At sea level and at 20 °C dry air has a density of approximately 1.2 kg/m3. varying with pressure and temperature. Air density and air pressure decrease with increasing altitude.\n\nThe formula for the density of air is given by:\n\n P=p/R*T\nwhere ρ is the air density, p is pressure, R is the gas constant, and T is temperature.\n\nThe individual gas constant R for dry air is:\n\n R( dry air )=287.05J/kg*K\nTherefore:\n\nAt standard temperature and pressure (0 °C and 101.325 kPa), dry air has a density of ρSTP = 1.293 kg/m3. \nAt standard ambient temperature and pressure (25 °C and 100 kPa) dry air has a density of ρSATP = 1.168 kg/m3. \n[edit]\nEffect of water vapor\nFor moist air, the partial pressure of the water vapor must be considered as well. In this case, the density of the air is the sum of the density of the dry air and the density of the water vapor:\nP=pdry air /Rdry air*T+p water vapour/R water vapour*T\n \nThe gas constant for water vapor is:\nR water vapour=461.495 J/kg*K\n \nEffects of altitude\nTo calculate the density of air as a function of altitude, one requires additional parameters. They are listed below, along with their values according to the International Standard Atmosphere, using the universal gas constant instead of the specific one:\n\nsea level atmospheric pressure p0 = 101325 Pa = 1013.25 mbar or hPa = 101.325 kPa (= 101325 kg/(m*s2)) \nsea level standard temperature T0 = 288.15 K \nEarth-surface gravitational acceleration g = 9.80665 m/s2. \ndry adiabatic lapse rate L = −0.0065 K/m \nuniversal gas constant R = 8.31447 J/(mol·K) \nmolecular weight of dry air M = 0.0289644 kg/mol \nTemperature at altitude h metres above sea level is given by the following formula (only valid below the tropopause):\n\n T=To+L*H\nImportance of temperature\nThe below table demonstrates that the properties of air change significantly with temperature.\n\nTable — speed of sound in air c, density of air ρ, acoustic impedance Z vs. temperature °C\n\nImpact of temperature \n°C c in m/s ρ in kg/m³ Z in Pa·s/m \n- 10 325.4 1.341 436.5 \n- 5 328.5 1.316 432.4 \n0 331.5 1.293 428.3 \n+ 5 334.5 1.269 424.5 \n+ 10 337.5 1.247 420.7 \n+ 15 340.5 1.225 417.0 \n+ 20 343.4 1.204 413.5 \n+ 25 346.3 1.184 410.0 \n+ 30 349.2 1.164 406.6
273925
The simplest way is spectography. if you are speaking of a breathalizer test it is via conductivity.
757137
Volume of the balloon * density of the gas = mass of gas in the balloon
881707
Determining the mass is trivial: just weigh the block.  For the density, you will need to know the volume, which will require some measuring with a ruler.  Then divide the mass by the volume for your answer.
120873
D= M/V\n\nIts a formula used to calulated to density (thinkness) of an object by dividing the Mass of an object by its volume. In this case, you can use the water displacement method that displaces (water) from its orignal volume by adding an object (marble). Using a balancer, measure and record the weight of graduated cylinder(ml), before and after the addition of water. Subtract the weight of the cylinder with water from the cyliner's weight and you will get the mass. You have to pay attention to how much the water displacement after adding the marble. record the volumes before and after (if ness). This will solve for volume. Once this is accomplished, you would have no problem finding the density.
187568
You can come up with a molecular weight of air - use the percentages of the different molecules comprising air and the molecular weight of the components.  The answer is around 29 g/mol (I think).
58191
Density - 1.151 \nNot easy to find
172574
AP Physics is phun, dont let anyone tell you otherwise.\n\nFirst, find the volume of the balloon.\nThe volume of a sphere = 4/3 pi * r^3\nyou are given the radius, so this should be no problem.\n\nOnce you know the volume of the balloon, find how much Helium and air it would take to fill it.\nYou could do this two ways, (the Physics way or the Chemistry way) either by using the molar masses of the gasses....or using the densities of the gasses, the density way is probably easier, but you either need to have those given to you or you can look them up and assume what temperature the experiement is taking place at.\nYou need to find the masses of each of the gasses.\n\nThe lifting force of the balloon will equal the difference in the upward and downward forces acting on it.  The downward force is the force of the Helium's weight, the upward for is the weight of the air that the balloon is displacing (we ignore the weight of the ballooon).\n\nIf you want to believe wikipedia,\nthe density of air at 20 degrees C = 1.204 kg/m^3,\n\none mole of Helium = 4.00 grams.\nAt STP 1 mole of Helium would have a volume of about 22.4 Liters.
184965
The density of the human body is very near the density of water.  Personally, I float when my lungs are full and I sink when I exhale.  I think that water's density of 1000 kg/m3 is a good estimate of my density.\n\nI weigh about 75 kg (take your weight in pounds divided by 2.2)\n\nSo this means my volume is 75kg/(1000kg/m3) = 0.075 cubic meters.
139840
The formula for either is P=rho*g*h, where rho is the density of the material (mass per unit volume) and g is acceleration of gravity, and h is the depth of the material at which you are measuring the pressure. \n\nPressure is a force per unit area. If force are unbalanced, then one gets acceleration of something i.e., something moves, by Newton's second law, F=ma.