How can I prove radical 2 it`s an irational number?
547302
Let radical 2 be a rational no. in the form of p/q.(p & q are int.,having no common factor & q iz not equal to 0)\nRdical 2 =p/q\n2 = p^2/q^2\np^2 = 2*q^2     (p^2 iz even, then p iz alzo even)\nLet p=2m\nThen p^2=4m^2\n     2q^2=4m^2      (p^2=2*q^2)\n     q^2 =2m^2   (q^2 iz even,then q iz even)\nBut p iz even & q iz even mean that 2 iz a common factor of p & q.Thi contradictz the above ztatement that p and q have no common factor.\nHence Radical 2  iz irrational.\n(PLZ- Ignore my "z'" az there iz an error in my board)
945958
(2n-1) * (2n-2) * (2n-3) * (2n-4)... * 3 * 2 * 1\n\nJust like any other factorial.
98145
the square root of 2 is 1.4142
712419
2 over 1 is 2:1 (2 to 1)
794328
By "Vactorial" I assume you mean "factorial"?  Then you can just as well say (2n)! / (n!)^2 for the right hand side.\n\nI wasted an hour of my life trying induction to prove this but I'm going around in circles.  The ravages of aging...
978758
There's a mathematical riddle that claims to "prove" 1 = 2, but if you examine it closely enough, it turns out to be dividing by 0.  Sorry I csn't remember the riddle.
475481
if you mean √24*√8 then it is\n√(4*6)*√(4*2)=\n√4*√6*√4*√2=\n2√6*2√2=\n4√(3*2)*√2=\n4√3*√2*√2=\n4√3*2=\n8√3
752580
It just takes foiling-\n\n(5*2)+(5*5i)+(-3i*2) +(-3i*5i)\n(10)+(25i)+(-6i)+(-15*i^2)\ni^2=-1\nso...\n25+19i\n\nTo those who have said that you can't simplify it past 10 + 19i - 15i^2, that isn't correct considering that since i is the square root of -1, i^2 is -1. That's why you can simplify -15i^2 to 15, thus making it 10+19i+15, or 25+19i
774933
if the numbers are both under a radical...divide the numbers...put answer under radical...if perfect square or contain a perfect square... simplify\nsqrt(4)/sqrt(2) = sqrt (4/2) =sqrt 2\nsqrt(36)/sqrt(9) = sqrt(36/9)=sqrt 4 =2
311472
i can prove that\n' a = x [true for some a's and x's]\na+a = a+x [add a to both sides]\n2a = a+x [a+a = 2a]\n2a-2x = a+x-2x [subtract 2x from both sides]\n2(a-x) = a+x-2x [2a-2x = 2(a-x)]\n2(a-x) = a-x [x-2x = -x]\n2 = 1 [divide both sides by a-x] ' is wrong\nbecause if we assume that a=x, we can't divide by a-x which is 0!!!! there is no way anyone can prove that 2=1!!!! don't even try:)\n\nalso, the one with 2^0 and 1^0\nany number ^0 is 1, does it mean that 1=2=3=4=5=6=7=8=9=...\nalso, for example 2^2=4 but (-2)^2=4 too, does it mean that 2=-2????? NO!!!
1010848
First of all, u do not need Lagrange's identity to prove it. u just need to expand everything.\n\nSo, u want to use Lagrange's identity, fine. set a^m=a^2, a^n=x^2, substitute these into the Lagrange's identity and u get exactly [a^{(m+n)/2}+b*y]^(2) + [y*{a^(m/2)} - {a^(n/2)}*b]^(2) without even needing to do anything else.\n\nThis is not called proving!
865479
First of all is the radical in the numerator over just the 10 or over the entire 10y^3?\n\nThe only this you can factor out and cancel is a radical 2 on the top and bottom.  Other than that, you can't really simplify this problem.  Are you sure you wrote it down correctly?
138792
To simplify (or reduce) a radical: \n\n1.  find the largest perfect square which will divide evenly into the number under your radical sign.  This means that when you divide, you get no remainders, no decimals, no fractions.\n\nReduce:  the largest perfect square that divides evenly into 48 is 16. \n\n \n\n If the number under your radical cannot be divided evenly by any of the perfect squares, your radical is already in simplest form and cannot be reduced further.\n \n \n\n\n2.  write the number appearing under your radical as the product (multiplication) of the perfect square and your answer from dividing.\n\n\n \n\n3.  give each number in the product its own radical sign.\n\n\n \n\n4.  reduce the "perfect" radical which you have now created.\n\n\n\n5.  you now have your answer.
966048
(3ab^2)(3ab)^2\n(3ab^2)(9a^2b^2)\n27a^3b^4
56508
first, do 2 to the 12th power (exponents take precedent over multiplication) which is 4096. Then multiply that by 86 and get 352256.  It's quite simple, really.
650764
Remember that i^2 is -1 so\n-3i+2(-1)-2+i=-4-2i
596727
Figure out what other number times itself equals your number.  That's its square root.