what does ohm's law describe in terms of electronic circuits?
543060
I'd say that you already know.  If my memory serves (at 6 AM) it is an equation where you can determine the unknown if you have two values.  The equation can be expresssed multiple ways.  Ohms are given in impedance or interference/resistance, and I think the other values are volts(or watts) and amperage (amps).  Whether it's home, commercial or electronics, the law applies to the flow  of electron in any circuit.
272621
v=voltage\no=ohm\nm=milliammeter\n\na tester which test those mentioned aboved. don't use it in measuring resistance(ohms) when the circuit is still connected to a source (voltage)
597402
let the resistances be r1 and r2.\nwe know the equation for power'p' is p=V*I\nV-Voltage applied,\nI-current in the circuit,\nby ohms law,\nV=IR\nsubstitute the value of V in power,\nwe get P=I^2*R  \nif the resistances  are in series then the value of R is,\nR=r1+r2.\nso the power dissipated when the resistance in series is,\np=I^2*(r1+r2),\nsimillarly power dissipated when the resistances are in parallel is\np=I^2*((r1*r2)/(r1+r2))
892848
One of the most frequently used is E=IR    ;E =voltage    I=current   R= resistance. U can change this every way depending on the unknown.\n    Good luck
480559
An ohm-meter measures the resistance by applying a voltage across the component. The current flowing through the component is measured, and a little bit of Computation of the form R=V/I would give the resistance.  \n\nIf a voltage is already supplied, then the ohm-meter may read erroneously or may even get screw**.
965339
The resistance (ohms) is zero in a superconducting circuit.  Such a circuit will not create a current but will maintain indefinetly a current made in it. Approaching a steady magnet near a superconducting material will induce a current in it. There are projects for accumulating electricity in superconducting loops of many kilometers diameter for peak hours of electricity consommation.
855540
The circuit has a time constant which is calculated as\nT=L/R\n\nThe circuit will have the equation\nfor current of:\n\ni(t)=(Vs/R)*e^(-t/T)\nWhere\nVs is the supply voltage\ne is Euler's constant\n\nj
51700
Definitions of inductance on the Web:\n\n    * The property of a circuit or circuit element that opposes a change in current flow, thus causing current changes to lag behind voltage changes. It is measured in henrys.\n      http://www.birnbach.com/TechnicalInformation/glossary/I.htm\n\n    * The property of an electric circuit that opposes a change in current flow.\n      http://www.customautosounds.com/faq.html\n\n    * (L) In general, the ability of a conductor to produce a magnetic field. In particular, magnetic flux divided by current, measured in henries (H). L=F/I. Or, the voltage (back emf) a conductor generates divided by rate of change of current in that conductor (self inductance) or another conductor (mutual inductance). L= -V/(dI/dt), where dI/dt is the rate of current change.\n      http://www.rcmicroflight.com/library/glossary.asp
948861
Ok, i am an electronics teacher, but it will be very lengthy and cumbersome to explain, because you have to go as deep as electrons and positive and negative charges, so i can advise you to go to www.wikipedia.com and you will find a satisfactory answer.
31337
It is DC voltage.\n\nhttp://www.ecs.umass.edu/ece/allerton/papers1999/36/
122484
Analog: a device in which data are represented by continuously variable, measurable, physical quantities, such as length, width, voltage, or pressure. In computer terms its voltage. in otherwords an analog signal can be 1,2,7,8.12,31 volts etc. in digital computers the value is off or on (usually thought of as 0 or 1) and represented by a voltage of 0 volts or 5 volts.. 0 being off (0) and 5 volts being on (1) some digital electronics work at a lower 3.3 volt for on but its the same thing 3.3 volts = on (1). so when you see something like 10110111 which is 8 bits or a byte in computer terms the computer has some electronics part inside it that actually has 5volt,0volt,5volt,5volt,0volt,5volt,5volt,5volt on it if you were to mesaure it with a meter. Most computer parts are simple on and off swithes called transistors and the thing that makes them amazing is that there can be millions of transistors on a single chip all going from 0 volts to 5 volts as things happen in the computer.
100752
There are two relavent formulas,\nOhms Law: V = R*I\nwhere V is the voltage, R is the resistance, and I is the current.  Also,\nPower = V*I\n\nIf we know that power is 150 watts, then,\n150 = V * I,\nbut what is the current (I)?\n\nWe know the resistance is 95 ohms,\nV = 95*I --> I = V / 95\nSo plugging back into the power equation,\nP = V^2 / R \n150 = V^2 / 95 --> V = sqrt(150 * 95)\nso V = 119.4 volts --> 120 volts
879048
Resistance = Voltage / Current\n= 1.4/0.8\n= 1.75 ohms.
223400
Electronic engineering (sometimes synonymous with Electrical engineering) is a professional engineering discipline that deals with the emission, behavior, and effects of electrons (as in electron tubes and transistors) and with electronic devices, systems or equipment.
964185
I sense that you have no clue what you're doing. Tell me I'm wrong.\n\nFor DC circuits, Ohm's law says: V = I * R, voltage equals current times resistance.\n\nYour circuit will consist of a battery (voltage source) and a load (resistance) plus the wires to connect them and the meter(s).\n\nIdeally you will test one battery at a time. That way the load will be identical (including the small resistance of the wires).\n\nBatteries typically have two ratings: voltage and capacity.\nVoltage is measured in volts and this decreases as the battery discharges. Capacity is measured in amp hours (current multiplied by time) which specifies how long the battery can deliver a current.\n\nAssuming the circuit resistance is constant (reasonable assumption for your purposes), when you connect the battery to the load, the voltage (independent variable) will cause a current (dependent variable) to flow. As the battery discharges, the voltage will decrease, and the current will correspondingly decrease. You will need a watch or timer as well. Time zero will be when you first connect the battery. Measure the battery voltage at that instant and at intervals. Depending on the load and how fast the battery discharges should determine how frequently you take measurements.\n\nmsg me when you have the data if you need help analyzing it.
786148
Electronic engineering - circuit analysis:\n\nSolving a circuit for the current and voltage according to Kirchhoff's Laws and these device equations:\nResistor   : v = R * i\nCapacitor: i = C * dv/dt\nInductor   : v = L * di/dt\n\nAnything complicated you generally solve by using the Laplace transform, in which case the above equations simplify to\nfor V,I = Laplace transforms of v,i:\nResistor   : V = RI\nCapacitor: I = sCV\nInductor   : V = sL\n\nThen you solve the system of equations for V,I and apply a reverse Laplace transform.
38228
By ohms law\nV = IR\n  = 3 amp * 3 ohms\n  = 9 amps/ohm\n  = 9 volt(since amp/ohm is given a special name volt)\nThe volt, symbol V, is named after the Italian scientist Alessandro Volta, who invented the voltaic cell and the electric capacitor.