in how many different ways can a panel of 5 on off light switches be set if no to side by side can be off?
548184
1.yes yes yes yes yes\n2.yes yes yes yes no\n3.yes yes yes no yes\n4.yes yes no yes yes\n5.yes no yes yes yes\n6.no yes yes yes yes\n\n7.no yes no yes yes\n8.no yes no yes no\n9.no yes yes no yes\n10.yes no yes no yes\n11.yes no yes yes no\n12.yes yes no yes no\n\nHope i didn't miss any.
28379
Switch on the first switch, leave it on for a minute, then turn it off. Switch on the second switch, leaving the third untouched - and go into the room. If the light is off, touch the lightbulb to see if it's warm. If it is, that means the first switch controlled the bulb. If the light is on, that means the second switch controls the bulb. If the light is off, and the bulb is cool, that means the third switch controls it :)
692549
control panels> power option
650589
If the  six surfaces of the room are fixed with 100% reflecting mirrors than after the switch off of the bulb the room will be in lights. If you do not switch off the bulb the light energy in the room will be increasing and at time it will go to threshold to blast of ....
333620
Turn on the first light switch for a while. Then turn it off and turn the third light switch on, then enter the room. If the light is on, it is the third switch. If the light is off and cold, it is the second switch. If the light is off, but warm, it is the first switch.
998751
-j is correct.\nBulb 64 is ON at the end (changed 7 times by persons 1, 2, 4, 8, 16, 32, and 64).\nThe 10 light bulbs that are ON at the end were changed an odd number of times, which are light bulbs 1 (changed 1 time), 4 (3 times), 9 (3 times), 16 (5 times), 25 (3 times), 36 (9 times), 49 (3 times), 64 (7 times), 81 (5 times) and 100 (9 times).
243832
Since it is only 16 options, you can just use a logic circuit. If it were more it would be best to convert each bit to analog with a summing op-amp circuit and have each bit input resistor double the last value. Then the two values could be fed into a comparator. A special logic circuit would need to be added for the equal [same as below] which would then logically override the comparator output for a 1 or 0 meaning L or G. \n[it would do this by making the outputs: \nG = comparator_output and not E  \nL = not comparator_output and not e]\n\nTo make the logic circuit you will need a bunch of logic gates. You can do everything with a slew of two input nor gates, or you can get some ands, ors, xors, and inverters of as many as 4 inputs each. That is up to you. \n\nTo figure out how to hook them up you need to draw a grid that is 4x4, down the side label it with the first number AB possible values:00,01,10,11 across the top label it with the second number CD possible values:00,01,10,11.\n\nNow in the grid fill in what output you want, presumably you will have three outputs, E,L, and G. E would be diagnal from top left to bottom right. The six above and right are Gs, and the six below and left are Ls.\n\nLike this except straight and with lines:\nAB  CD:00,01,10,11\n00      E  G  G  G\n01      L  E  G  G\n10      L  L  E  G\n11      L  L  L  E\n\nnow take each area that you can can and work it into the logic equation. For example the Es are two xor gates ANDed together. \nE = ((a xor c) and (b xor d)) [this is kind of by definition of equals there was no real trick here]\n\nthen you can see the top-right four Gs can easily be singled out with:\nG(1)=(c and (not a))  [that is c is 1 and a is 0]\n\nnow you can do the same for the Ls on the bottom left:\nL(1)=(a and (not c))\n\nNow you can pick up the straglers one at a time or as a group. for example the AB/CD=11/10 is an L, and so is the entire bottom row where ab=11 except for the E which is already known. so you could do this:\n\nL(2)=(a and b and c and (not d)) [to pick it up alone]\nor \nL(2)=(a and b and (not e)) [which gets some other Ls you already got which is fine since you are going to and all the Ls together later to get the final L]\n\nnow you need L(3) and then pick up G(2) and G(3) the same way. After that the final step is to or them all together:\n\nL= L(1) or L(2) or L(3) [same for Gs]\n\nNow you can take the rules for modifying and simplifying the gates down to only 2-input nors if you want, or you can keep all the various gates and hook them all up. \n\nIf you really want to get fancy then you can send the output to an alphanumeric LED and actually print the letter, but that is a whole nother task. \n\nEach segment would then be either always on, always off, or some logical combination of the three outputs G and E [since the L segments would always be on]
1096868
If I did the math right there are ten numbers 0,1,2,3,4,5,6,7,8,9\n\nThey must be put in a group of four. Thats 10 to the fourth power. So thats about ........  10,000 possible combonations. If your asking the possible combonation to a lock....... Well good luck unloking it.
270429
I use switchboard, they're not all available though.  :(
802190
HMM.  Maybe if you turn on switch A and leave it for about 2-3 minutes. Then turn it off.\nThen turn on switch b and head upstairs.\nThe light controlled by switch b will still be on.\n\nThe light controlled by switch A will be off but still warm to the touch.\n\nThe light controlled by switch C will be cold.\n\nThink that will do it?
181250
The light will be on/off
115772
Yes, a double-pole switch opens and closes two wires of the same circuit, or two independent circuits.  I believe electro-fogey was thinking of double-throw switches.
1097551
At work we just got motion sensitive switches.  If there isn't any movement for so long, the lights turn themselves off.  Saves a bunch on electricity.  Of course they automatically turn themselves back on when we walk through.
1101885
This is a perfect question for the section called 'corporations'.\n\nThe answer is 'NO'. Even though you leave the light switch on, the burned out bulb breaks the circuit and uses no electricity.
1072750
turn on the first 2 switches  let them sit for a little while.  then turn on the 1st and 3rd switch.    go into the room right away, if the bulb is hot but off that means it was the 2nd one (because the switch is now off but it had to be on)  if the bulb is cold still (not really hot) it was the third one because the light just turned on and the 1st one didn't turn it on at all  if it is not on and the bulb is not hot at all it was the fourth because you never touched that switch  it was on and hot then it was the first because it was on long enough for the bulb to get hot.  \n\nso... when only the 1st and 3rd swith was on (after turning off 2)\n1=if it was on and hot\n2=if it was off and hot\n3=if it was on but cold\n4=if it was off and cold
587901
get one of those electrical outlet timers that are used for turing lights on etc.. and lock it in the closet with your router, and or pc
327294
Some lights are on a timer to save electricity.