The formula for relating degree and radin measure is given by?
545911
2pi rad=360deg\n==> x rad = (360*x)/2pi deg\n\nConversely,\n360 deg = 2pi rad\n==> x deg = (2pi*x)/360 rad
904043
One variable is related to another by a function involving constant terms and terms of 1st order or higher.
958486
Rs=Im*Rm/Is\n\nRs*Is = Im*Rm\nRm= (Rs*Is)/Im\n\nc=(8.85*10^-12)(K)(A/d)\nc*d = (8.85*10^-12)(K)(A)\nd= [8.85*10^-12)(K)(A)]/c\n\ny=mx+b\nb=y/(mx)\n\nx= (y-b)/m\n\nLm=(Lt-L1-L2)/2\n\nE=Q/C\n\n1/Rt - 1/R2 = 1/R1
848345
I assume that this is s = (a-rl) / (1-r).\n\nFirst, multiply both sides of the equation by 1-r.\ns(1-r) = a-rl\n\nUse the distributive property on s(1-r)\ns-sr = a-rl\n\nGet the r terms on one side of the equation and the others opposite it.\nrl-sr = a-s\n\nUse the distributive property to factor out the r.\nr(l-s) = a-s\n\nDivide both sides by l-s\n\nr = (a-s) / (l-s)
694639
From the second equation:\n\np/(1+p)=r\np=r(p+1)\np=rp+r\np-rp=r\np(1-r)=r\np=r/(1-r) which is not equivalent to p=(r-1)/r
975361
d=nt2/p\npd=2nt\np=2nt/d
584250
In statistics:\n\nmu = average = (sum of all values) / (total # of values)
610173
Radians are based on pi.  A radian is equivalent to 1/(2pi).  Because it is just a ratio of another constant, it isn't based on a physical standard unlike feet, meters, etc.\n\nIt's just like degrees.  A degree is 1/360th of a complete circle, but nobody needs to define 360 with a physical object.  We all know what 360 is.  Similarly we know what 2pi is (it's the circumference of a unit circle).
456513
A=pi*x*y \n\nwhere x is small radius from centre to circumference and y is large radius from centre to circumference.
432008
t=rho/(sqr((1-rho^2)/(n-2)))\nwhere:\n\nrho: correlation coefficient\nn: number of observations
733701
let us denote the marginal density of X_i by f_i, that is the density of X_1 is f_1.\nlet us denote the density of the triplet (X_1, X_2 X_3) by f.\n\nas X_1, X_2, X_3 are stochasticaly independent,\n\nf(x_1, x_2, x_3) = f_1(x_1)  * f_2(x_2) *  f3(x_3)\n\nlet g be a bounded borelian function on R ^3\n\nset:\nphi(x_1, x_2, x_3) = (x_1 + x_2 + x_3) ^ 2 / 6\n\nE(g o phi (X_1, X_2, X_3)) = &#92;int g o phi(x_1, x_2, x_3) f(x_1, x_2, x_3) dx_1 dx_2 dx_3\n\n = &#92;int g( ( x_1 + x_2 + x_3) ^ 2 / 6) f(x_1, x_2, x_3) dx_1dx_2dx_3\n\nthen you may conclude using Fubini theorem
223260
uhmm well degrees are the measure of the angle on the curve and minutes and seconds are the radian form of degree measurement ...i don't know what they're really symbolic of... a clock?
880121
Yes, you need to convert relative standard derivation to standard derivation first. Use relative standard derivation times the mean.\n\nIn the question, I didnt see anything about number of measurements, so there's no way we can tell n. Since we dont know the number of measurements, we cant tell which distribution, Students' T  or normal distribution, we should use. Look into the questions again, with this much info, we cant do nothing here.
598177
First by frobenius method, you can easily obtain the series expansion of the first order of bessel function. The coefficients of series expansion of this function help you to find the degree. And you need to know that the asymptotic forms of Bessel functions are relevant to the gamma functions.  (z/2)^(-n) J_n(z)~1/gamma(n+1) is a degree of 1 \nIf you need to show that you need to use the asymptotic expansion of gamma function which can be also obtained by using the frobenius method. But you can also use the stirling formula which approximates to the gamma function. \nThen take the limit of the rho=n^n e^{-n}/log(a_n) as n goes to infinity. a_n: is the coefficient of the series expansion of bessel function , rho is the order. You will see that rho is going to be equal to 1. Hadamard's theorem will help you to understand how you define the order(rho) as above.\n \nAll routines in matlab, fortran are written using these mathematics. By the way, it is not a simple question. Good luck:)
477523
The no of degrees of freedom for a chi-square distribution ia n-1
35682
pi doesn't equal 22/7 or 3.14.  those are just approximates, but fairly close approximates.\n\npi is how many radians there are in a half a circle-approximately 22/7 or 3.1415 radians.  a radian is the degree where the radius of the circle equals the outside segment of the circle at that degree.  (about 59 or so degrees if i remember correctly)
375635
Kp=Kc(RT)n\na.Kp=Kc(RT)-1/2\nb.Kp=KcRT\nc.Kp=KcRT\nd.Kp=Kc(RT)2