Math equation that I need help solving?
539048
Your mixture has four parts: three parts Blue Sand and one part Yellow Sand.\n\nAssume that you have 100 pounds of this mixture.  It would contain 75 pounds Blue Sand and 25 pounds Yellow Sand.\n\n75 pounds of Blue sand costs $861.75 (75 * 11.49)\n25 pounds of Yellow sand costs $199.75 (25 * 7.99)\n\nSo 100 pounds of the mixture costs $1061.50 (861.75 + 199.75)\n\nAt this rate, one pound costs $10.615.\n\nWith $25, you can afford 2.355 pounds of the mixture (25 / 10.615)
263286
the problem you presented above can be represented as,\n\n(8x^8/2x^2) + (16x^6/2x^2) - (12x^3/2x^2)\n\nthen you can simply divide each of the term\nyou'll get\n\n4x^6 + 8x^4 - 6x
928663
Are you asking for help or an answer?\n\nTake any 2 equations and multiply all of the terms or one or both by numbers that will make one of the terms in each equation have the same coefficient. Now subtract one from the other and the term will disappear. Now take the resulting equation and do the same with it against the third. Keep doing this until you are down to one term and solve for the variable. Now substitute the variable into the equation and solve for the other variables.
636051
x=4\n\nplease solve...\n\n8-(1) :-) ;-(
851212
hmm im not quite in college yet, but i hope to be help.\ndo you know the values for f, h, v, and a?\nif you do, id substitute it in.\nthen square both sides. \nand then solve.
247689
Use analytical trig (hint: sin function).  That should give you the answer you are looking for.
240687
4m+H-(4m-h) =\n4m+H-4m+h=\n4m-4m+H+h=\n0+H+h=\nH+h
924424
The equations:\n(a+b)^2=a^2+2ab+b^2\nA^2-B^2=(A+B)(A-B)\nJames Chan's solutions were right.
904672
let u = x^2 + 1, then you have du = 2xdx, => dx = 1/2x du,\n\nsubstitute back you are on the way  to solve it
663777
SOrry, I can't help you. If I had the formulas I could do it, but there is no way I remember that off the top of my head! Good luck
893823
Use the quadratic equation \n\nt = -b + or - sqr(b^2 - 4ac)/2a\n\nyour equation is already in the form:\n\nat^2 + bt + c = 0\n\njust plug in the variables and solve for t twice
685042
A=2LW+2LH+2WH\n\nA-2LW=2LW-2LW+2LH+2WH\n\nA-2LW=2LH/2L+2WH\n\nA-2LW\n------------ = 2WH\n    2L\n\nA-2LW ~~~(1)  ~~~~~~(1)\n------------  -------- = 2WH   --------\n    2L~~~~~ (2W) ~~~~~(2W)\n\nA - 2LW\n------------- = H\n    2L(2W)
117786
Well, there isn't really anything to "solve", since it's not an equation.  If you want to simplify, it depends what your original terms are.  Is the question\n\na)  2x^2 + 4/2x  ?\nIf so, then the only simplification is 2x^2 + 2/x.\n\nb) (2x^2 + 4) / 2x ?\nIn this case, the simplification is (x^2 + 2) / x.\n\nI hope this answers your question!  Good luck.
720847
Use logarithms. If you haven't learned them yet, it just helps to solve equations with powers.\na = b^x\nlna = ln(b^x) = xlnb\nx = lna/lnb\nx = ln(10)/ln(32.6087)\nx = 0.6607928852\nYou can use your calculator to check. I guarentee that it works.
209966
Set up an equation:\n\n72 = .6 * X\n\n72/.6 = X\n\nX = 120
490656
Make Y=0\nyou have to have m and x though to solve b\nExample:\nY=mx+b\n0=3(4)+b\n0=12+b\n -12 on both sides of equal sign\n-12=b\nhope this helped!
750949
I'm not sure of the exact equations, but I know the side that's 4 times longer should be 4 + x, and the one side should be x.  Then using the Pathagorem thm., x^2+ ?^2= (4+ x)^2\n\nI'm just not sure how to find the third side.\n\nHope that helps :/