what is moment magnitude?
553608
The moment magnitude scale was introduced in 1979 by Tom Hanks and Hiroo Kanamori as a successor to the Richter scale and is used by seismologists to compare the energy released by earthquakes. The moment magnitude Mw is a dimensionless number defined by\n\n \nwhere M0 is the seismic moment.\n\nAn increase of 1 step on this logarithmic scale corresponds to a 101.5 = 31.6 times increase in the amount of energy released, and an increase of 2 steps corresponds to a 103 = 1000 times increase in energy.\n\nThe constants in the equation are chosen so that estimates of moment magnitude roughly agree with estimates using other scales such as the Richter magnitude scale. One advantage of the moment magnitude scale is that, unlike other magnitude scales, it does not saturate at the upper end. That is, there is no particular value beyond which all large earthquakes have about the same magnitude. For this reason, moment magnitude is now the most often used estimate of large earthquake magnitudes. The USGS does not use this scale for earthquakes with a magnitude of less than 3.5.
719219
Umbrella\ninside/outside\nelectricity\nNewton  (new ton)\n550 + /+= 554
909738
It will rotate about the center of mass O at d/2\ncalculate the moment or inertia about  O, include both mass and both rods. see link for formulas if you don't know how\nhttp://en.wikipedia.org/wiki/Moment_of_inertia\nThe formula for KE is also there
955176
Force - Newtons\nMass - Kilograms\nAcceleration - metres per second
852750
T=I*w’, T=16 torque, w’= angular acceleration, I=1.2/1000; In time t (SECONDS) its angular speed w=w’*t;\nOr w’=w/t or w’=T/I; thus w/t=T/I or I*w=T*t is angular momentum, & w=T*t/I
922680
The moment of inertia of a sphere is:\n\n(2/5)* M * R^2\n\nFor a hollow sphere (spherical shell) you can subtract the hollow part from the sphere part, but since the M (mass) term will change based on diameter it is easier to substitute:\n\nM = p * 4/3 * PI * R^3     (p = density)\n\nSo.. in the end you get  I = 0.5333 p ( R2^5 - R1^5 ) \n\nWhere R2 = Outer Radius, R1 = Inner Radius
875957
Currently, the scientific community uses the MKS system for most engineering, and beginning physics:\n\n      M = Meters (Length)\n      K = Kilograms (Mass)\n      S = Seconds (Time)\n\n...the answer is KILOGRAMS.
234732
X times Y^Z\nexample\n1 x 10^8.3 = magnitude 8.3 quake
218119
Sign conventions.  Mass is always positive, and that's the deciding factor for angular momentum.  Magnetic moment involves charge, and electrons are negatively charged, so it ends up being anti-parallel.  But, this is just an arbitrary convention, so don't get too worked up over it.  Yes, it's important for keeping your ps and qs straight in doing physics, but it's not of any major physical significance.  \n\nIf we'd decided to call electrons "positive" and protons "negative", then the magnetic moment for an electron would be parallel to the angular momentum.
233618
1 mass\n2 magnitude of separation
849662
The moment of inertia of an object is given as:\n\nI = volume integral of (r² dm)\n\n(I have no good way of writing this, so check the wikipedia link below of more info). Wikipedia also has a list of moments of inertia, which I've included below. It provides the moment of inertia for a disk as:\n\nI = (1/2) * M * R²\n\nAs for calculating it step by step, note that if the mass is evenly distributed throughout the disk, then the density of the disk is equal to its mass divided by its volume:\n\nrho = M / (pi * R² * h)\n\nThe infintesimal dm can be expressed as:\n\ndm = rho * dV\n\ndm = M / (pi * R² * h) * r * d-theta * dr * h\n\ndm = M / (pi * R²) * r * d-theta * dr\n\nThus, the moment of inertia is given as:\n\nI = int(int(M / (pi * R²) * r^3, r=0..R),theta=0..2pi)\n\n(again, I don't have a good way to express this - its a double integral of M / (pi * R²) * r^3 * dr * d-theta, where r goes from 0 to R and theta goes from 0 to 2pi). This reduces to:\n\nI = int(M / (pi * R²) * r^3 * 2pi, r=0..R)\n\nI = M/(pi * R²) * (1/4)*R^4 * 2pi\n\nI = M/(R²) * (1/2)*R^4\n\nI = (1/2) * M * R²\n\nSo that's how you find the moment of inertia. Now, substituting your values into this expression provides:\n\nI = (1/2)(41 kg) (18.8 cm * 1 m/100 cm)²\n\nI = .7246 kg-m²\n\nThat's it! :)
591057
Torque is also known as moment, and its unit is Nm (Newton meter)\nThe formula: torque = Fd, where\nF is the applied force\nd is the distance from the fulcrum to the line of force.\n\nVisualize a circle, with the fulcrum as the center. Let its radius be d, and F is a tangent of the circle perpendicular to its radius.\n\nAs torque = Fd, the longer the length of the pedal arm, the greater the amount of torque applied to the wheel.
463421
KE = mv\nWrong: energy <> momentum\n\n2y = (2 m)cos(kx)\nRight: a lenght =  lenghth x a number between -1 and +1\n\nvf = vi + ax\nWrong: x should be t\n\ndensity = volume/mass\nWrong: fraction should be inverse
1169599
The radius of gyration is defined in ref. 1 as the length "... obtained by dividing the moment of inertia I by the mass of the object M and taking the square root". In other words, it's the R that satisfies I = M*R^2. The mass of the solar system can be reasonably assumed to be roughly constant in the short term (if we agree on which bodies are planets, asteroids, etc.) but the moment of inertia varies, as does the center of mass about which I is measured, due to orbital motions of the planets. \nIf numbers related to the sun alone are any help: The sun's mass is 1.99E30 kg (ref. 2) which is 99.8% of the total solar-system mass. The sun's moment of inertia (ref. 3) is 0.059, given as the ratio I/(M*R^2) where R in this context is the radius of the sun. Thus the radius of gyration of the sun is 1/SQRT(0.059) times its actual radius = 0.2429 * 695000 km = 168800 km.
792387
sum of clockwise moments=sum of anticlockwise moments\n                             200N*1m = F*4m\n                            200Nm/4m=F\n\nForce then should be 50N
918805
Time And Relative Dimension In Space
1120774
WHAT IS M\np (momentum)=m (mass)* v(velocity)\nsquare root of momentmum will be the product of the square root of mass into square root of velocity