What is 119 divided by 32 in fraction form?
544625
3 and 23/32nds\nor simply\n119/32
567481
80\n\n729=9^3 and 64=4^3  Use the proportion 9^2/4^2 = 81/16 = 405/x\n\nx=80
324383
The question is set up as:\n\n   3\n   -\n   4\n--------\n   24\n\nOr, more clearly (3/4)/24\n\n\nBy bringing the denominator to the top and converting it to a fraction, we get:\n\n\n3     1\n-  x  -\n4     24\n\nOr 3/4 x 1/24\n\nWhich equals\n\n1\n--\n32\n\n1/32
668527
Using Roman numerals!  Twelve would be\n\nXII\n\nIf you cut that in half using a horizontal line, the top half looks like VII, which is 7.
318849
Ok, first you turn them into improper fractions.\n4 3/4 turns into 19/4\n2 1/12 turns into 25/12\n1 1/8 turns into 9/8\n\nThey all have to have the same denominator which would be 24. 19/4 turns into 114/24. 25/12 would be 50/24. 9/8 would be 27/24. Now they all have the same denominator you add them to get 191/24 which is the same as 7&23/24.
428067
159.99*0.4=\n\n63.996
896080
96 x 20% = 19.20\n\nor \n\n96 x 0.2 = 19.20\n(20% = 20/100 = 0.2)
750996
5 1/4 = (5*4+1)/4 = 21/4\n12 1/5 = 12*5+1 / 5 = 61/5\n\n(21/4) / (61/5) is the same as (21/4) * (5/61)\n\ntherefore the answer is : (21*5) / (4*61) = 105/244
43395
216 / .9 = 240\n\nCheck : 90% of 240\n        .9  x 240 = 216
69132
F=5/9C+32\nSubtract 32 from each side\nF-32=5/9C+32-32=\nF-32=5/9C\nDivide each side by 5/9 (multiply by 9/5)\n(F-32)/(5/9)=(5/9)/(5/9)C\n=(F-32)/(5/9)=1C=C\nSo\nC=(F-32)/(5/9)\nwhich, as I said before is like multiplying by 9/5,\nso it equals 9/5(F-32)\ndistribut the (9/5) to the F and the 32\nC=(9/5)F+(9/5)32=\nC=(9/5)F+57.6\nconvert to decimal if you want\nC=1.8F+57.6
950233
You should change alll of them into improper fractions.....so.....\n\n216/72-103/72\n\nYour answer should equal\n93/72 or 1 21/72 or 1 7/24\n\nHope this helps!
146936
(32 + 18 - 45 x 3) / 5 - 7 x 2 = ?\n\n-31
519904
(n/4 + 11) - 11 = 31-11 (Sub. 11 from both sides.)\nn/4 * 4 = (31-11) *4 (Mult. both sides by 4\nn = (20) *4\nn=80
572405
This is the way you find them all\n100 = 1 x 100 = 2 x 50 = 4 x 25 = 5 x 20 = 10 x 10\nFind yourself the dividers of 360 and 300.
619477
well, if you don't have to use them all... convert 1 4/15 to an improper fraction:  \n\n15/15 +4/15 = 19/15\n\nnow, look for the least common denominator for all the fractions- it's 30, so convert all fractions to fractions with 30 in the denominator:\n\n19/15 * (2/2) = 38/30\n\n1/2 * (15/15) = 15/30\n2/3 *(10/10) = 20/30\n6/10 * (3/3) = 18/30\n\nNotice that 20/30 + 18/30  = 19/30\n\nso the answer is 2/3 + 6/10 = 1 4/15
950154
26/52*25/51\n=1/2*(25/51)\n25/102
1046303
32\n\nf(x) = 19x^2 - 116x + 192 \n\nf(1) =95\nf(2) = 36\nf(3) = 15\nf(4) = 32\n\n(Hey trikrikru, how is M(x) defined for random x?  ...like your answer tho...)\nThe rest of you need to justify your answers!!\nAnyMouse, that's true but boring unfortunately.\nLet's all find the most outrageously true reason folks!\n\nWait!  I change my answer to 0 because if:\n\nf(1) =95\nf(2) = 36\nf(3) = 15\nf(4) = 0     THEN...\n\nf(x) = -1 1/3 x^4  +   8 x^3  +   4 1/3 x^2  -   108 x^1  +   192\n\n\n\n.......well, this is the Mathematics thread, isn't it???????????\n\nHey, maybe the next number is N, where N is anything you want!!!\n\nThen\n\nf(x) = 192 - 97C(x,1) + 38C(x,2) - [32 - N]C(x,4)\n\nwhere C(a,b) = a! / [(a-b)! b!] , the combination of a things taken b at a time.\n\nIf anyone can prove this, I'm going to ask the question and the first to answer it properly, etc, etc, etc, .