Can you help me with my daughter's math homework? There are 2 story problems . Thanks!?
539212
#1 is yes, because when you divide a number into a number that's twice as big, you always get 2.\n\n#2 1/2 = 2/4 = 3/6 = 4/8 = 5/10 etc.  You will notice that the bottom is always twice the top.
586753
1. p1=3.0atm        \n   v1=15mL\n   p2=2.5atm\n   v2=?\n\n(3.0x15)/2.5=18mL\n\n2.t1=(-35+273)=238       \n  v1=75.0mL\n  t2=(25+273)=298\n  v2=?\n\n(298x75.0)/238=93.9mL\n\ni think it's right. i hope it helps.
195201
i think u typed the question wrong, can u please correct it and if u have 2 unknowns, please give 2 equations, else u cant get a definite solution
837784
1) -2 x (2/5 -2p)\n    =4/5+4p            after multiplying through by -2\n\n2) 1 x (9/20 -p)\n    =9/20-p              after multiplying through by +1\n\nThis has started you off you should be able to solve now!
1131661
That problem is the way you state the question.  They each paid $15 * 3 = $45.  Her returned $5, so the total paid to the store is $40.\n\nNow each got one dollar back, so they paid in $14*3 = $42, and the one boy has the extra $2 which needs to be split.  There is no extra dollar:  $42 - $2 = $40!!
789977
1.  15\n2.   a.  y=(2x-3)^2 + 4\n      b. (3/2;4)
729325
Problem one's answer is 1 inch as you guessed.\n\nProblem two, the answer is : 24 by 36 feet\nHere is how to get it...\nAs seen in the previous problem, each inch on the paper is 2 feet in real dimensions.\nso we just multiply each inch by 2.
930340
PROBLEM 1:\n\nsqrt(x^3) = 8\n\nSquare both sides:\nx^3 = 64\n\nNow take the cuberoot of both sides:\nx = cuberoot(64)\n\nSolve:\nx = 4\n\nPROBLEM 2:\n\ncuberoot(x^2) =4 \n\nCube both sides:\nx^2 = 4^3\n\nSimplify:\nx^2 = 64\n\nTake the square root of both sides:\nx = ±8
343331
What math test do you take?  I'm in Algebra 1 and I only remember 1 question.  It's impossible.\n\nSomeone has a total of 100 coins in dimes and quarters.  The total value adds up to $14.05. How many quarters does she have?\n\nA) 27 (I chose this-it's a dollar off)\nB) 40\nC) 56\nD) 79 (I forget-it's way too high)\n\nWell, that's all I have.  Bye bye!\n\nThanks to the guy who solved that.  I won't get a zero now!
1094708
Let the first car had an average x and the second y\n\nThen,\nthe first car moved 25x miles in that week\nand the second moved 20y miles\n\nNow\nx+y = 45, and\n25x+20y=975\n\nSolve the equations baby, and you are through!\n\nvisit this amazing site called www.mathguru.com for ample practice exercises all solved step-by-step... with voice and all.. its awesome
992192
1. second\n2. first\n3. 4100\n4. mary
858552
Have you tried these?  Surely you've been told that division by 0 isn't possible, so there's your answer for 7.  I'm not doing any others on Yahoo answers (too many at once), but if you really need help and are willing to do as much as possible for yourself I'll help you if you email h_chalker@yahoo.com.au, but nasty Maths teachers like me won't just hand you 7 answers on a plate!
898860
First one: d= - 1\n\nEDIT: the rest I'm too lazy to do. Do your own homework! =D
1020883
i am sure you can find a math tutor that will be happy to help you when you explain what the problem is.\n\nso what IS the problem, anyway?
1129355
Question 1:\n\n\n(-2)^2=(-2)(-2)=4\n4 * 4=16\n\n8(-2)=-16\n\n16-16=0\n\n3(-2)=-6\n0-6+6=0\n\nanswer:  zero\n\nQuestion 2:\n1/3* 3^6=3^5=243\n\nQuestion 3:\n30+825*30/1000+30*15/100\n=30+8,25 *3+4,5\n=59,25\n\n\nQuestion 4:\n598/100*100/26=23\n\nQuestion 5:\n4/5+3/4=16/20+15/20=31/20= 1,55
22859
Subract the two terms on the left giving:\n-2t < 16\n\nAdd 2t to both sides giving\n0 < 16 + 2t\n\nSubtract 16 from both sides\n\n-16 < 2t\n\nDivide both sides by 2\n\n-8 < t
221530
Add them together and divide by 5.\n\nWow. I could seriously have you people do my homework for me. Every night. I'll type out the problems and see how you all do. :P JP