A vertex of a secant-tangent angle is a point on the circle sometimes, always, or never?
534712
Actually sometimes. A secant passes through a circle at two points, a tangent at one. You COULD have a secant hit the tangent at a point other than the point of tangency, and there is indeed a theorem around for determining the relative lengths of lines and so forth, but many questions dealing with area and arc length put the vertex at the point of tangency for simplicity's sake.
263870
When we draw a circle with a compass, we keep the angle between the two legs constant.\n\nA  ray from the  top most point on the rainbow  to our eye makes an angle to the horizotal direction. Theory says this angle is a constant.\n\nImagine the ray as one leg of long compass and the horizontal direction as another leg which points the center.Keeping the angle constant when the compass is rotated an arc is formed.   \n\n Mathematically we say that the locus of all such points is an arc of a circle.\n\nIf water particle were present on all points on the arc we see a continuous arc of a rain bow.\n\nDuring cloudy  night we can see a full circle of rainbow \naround moon with moon as center.
418892
Since O is the center, this problem becomes fairly straightforward.  First, assuming <BOA = 94 degrees (not sure which of the four angles at O is 94 degrees, but say it's <BOA.  This means that the arc from B to A is also 94 degrees.  And since the chord from A to C goes through the center, it means it is a diameter.  This means that the arc from A to C is 180 degrees (half of the circle).  So that means that the arc from B to C has to be 86 degrees (180 - 94, because part of that arc from A to B is 94, the rest must add up to 180).  So now you have to use what your teacher told you about when the angle is on the circle.  Namely, that the angle on the circle (the inscribed angle) is half of the arc measure (intercepted arc).  So if the arc measure is 86 degrees, the angle must be 43 degrees.\n\nEdit: I just saw that it was <COD, not <BOA, but they are congruent because the are vertical angles, so nothing changes.
918264
IF you mean like an ordered pair it is a point on a graph.  An example is:  (x,y)  so you can have (3,5)  or (-7,-88)  Otherwise I'm not sure what you're talking about.
830426
The crux of this problem is for you to realize that the given angles are "complementary pairs", which add up to 90 degrees.\n\nYou are expected to know that the "co-function" of angle A gives the same value as the "function" of angle A's complement.\n\nSpecifically:\n\n cos(A) = sin(90-A)\n\nA graphical way of looking at this statement is that "cosine and sine are the same function, but offset by 90 degrees!"  We call that "out of phase by pi/2 or 90 degrees."\n\nThe same works for tangent and its co-function:\n\n tan(A) = cot(90-A)\n\nSo the answer to the second problem is 0.\n\nIf one of the fuctions in the first problem had been sin, the quotient would have been 1.  However, that's not the case, and I leave the upper problem as an exercise for another Answerer.\n\n Hope this helps!
778977
No.\n\nTriangles on things like spheres can have angles greater than 180 degrees.  There are also other surfaces where the opposite is true.\n\nHowever on flat sheets of paper (technical word is plane) the sum of the angles in any triangle is equal to 180 degrees.
602663
No, a line cannot intersect a circle in at most one point, unless you're talking about tangent. A line can be tangent to a circle at only one point.
826387
A circle is the locus of a point which moves in a plane in such a way that its distance from a given fixed point is always constant.\n         The fixed point is called the centre & the constant distance is called the radius of the circle.\n           \n          A circle with centre O & radius r is denoted by C(O,r) !!!
149999
A regular n-gon has the centers of its inscribed and circumscribed circles the same point. If you draw segments from this center to each of the vertex, you will get n number of radii and n number of triangles, which are all congruent. Using derivation you will arrive at the conclusion that\nA = .5aP or A = .5ans where\nA is the area, a is the apothem, s is the side and P is the perimeter\na =2A/ns\nThe radius is acquired by\nsin [180degrees(n - 2)/n] = a/r\nr = a/sin[180degrees(n - 2)/n]
317974
Every point in the x,y plane has a unique set of Cartesian (rectangular) coordinates.\nSince no ray has a unique angle measure, (e.g. 30 and 390, -330, etc. all look like the same # of degrees) Polar Coordinates are not unique.
1043194
Angles are formed by two rays that begin at the same point or the union of two rays with a common endpoint, called the vertex\n\nThey are measured in \ndegrees (360 = complete circle), \nminutes ' (60 minutes in one degree) and \nseconds " (60 seconds in one minute)
806325
360 degrees because only zero degree or 360 degrees places the angle in the same quadrant. if u are asking multiples of then the answer would be a finite number i.e. 360 degrees.\n\nexplaination:\ntake a circle and hold its radius at the circumference, now move it round the circle with its center point fixed. it will come at the same place only after 360 degrees, or it will substend the same angle as it was when u started the movement.
867091
The x-intercepts occur at x =0, x =4/3, and x=-2. The root x =0 has multiplicity 3, which is odd, so at that point the graph should be tangent to the x-axis, cross the x-axis, and have an inflection point there. The root x = -2 has multiplicity 2, which is even, so the graph should be tangent to but not cross the x-axis there. The root x = 4/3 is simple, so at that point the curve should cross the x-axis without being tangent to it. All of this conclusion is consistent with the graph, should you use a graphing calculator or whathaveyou.
706522
It's often handy to draw yourself out a little sketch.  From it you can see the location of the given point.\n\nTo identify the angle the given point makes with the x-axis and the y-axis use trigonometry.  Switch to radians.\n tan Θ = opp./ adj.\n Θ = tan^-1 opp./ adj.\n Θ = tan^-1 (-0∙4425./ -0∙8968)\n Θ = tan^-1 (-0∙493 210 52)\n Θ =  0∙458 370 613 rad.\n    This is the value of the angle below the x-axis.  You need to include the angle above the x-axis, which is 180º or π radians.\n Θ =  0∙458 370 613 rad. + π rad.\n Θ =  (0∙458 370 613 + 3∙14) rad.\n Θ =  3∙598 370 613 rad.\n Θ ≈  3∙6 rad.
150933
What do you call the line that intersects a circle in only 1 point?
324968
its just triangle mathe. remember soh -cah -toa... sine =opposite side/hypotenuse,  cosine=adjacent side/hypotenuse, tangent= opposite side/adjacent side....cosecant(hypotenuse/opposite side) is the opposite of sine, secant(hypotenuse/adjacent side) is the opposite of cosine and cotangent(adjacent side/opposite side) is the opposite of tangent
777666
Well, each angle has whatever value it happens to have. The only limitation is that the values can't be negative or greater than 360 degrees, and the total for all of the angles must be the appropriate value for a polygon with that number of sides (180 degrees for a triangle, 360 for a quadrilateral, 540 for a pentagon, etc. ... in general, 180 (n-2), where n is the number of sides).\n\nBecause you say it is a concave polygon, you are indicating that at least one angle exceeds 180 degrees. Obviously, this can't be a triangle (since the sum of ALL the angles of a triangle equals 180 degrees). But it can be any other polygon. The fact that one angle exceeds 180 degrees does not change the criteria given above (each angle greater than 0 and less than 360, and the sum of the angles being appropriate for the number of sides of the polygon).