explain to me what the name "Equality 7-2521" symbolize?
553183
the name "Equality 7-2521" symbolizes equality through the hardships they faced with being seperated without any individual names
421595
Do you mean 69?  The sign for Pieces looks like "69".
1157090
It's the symbol for factorial.  It means multiply the number n by n-1, then by n-2, etc. until you get to 1, e.g., 5! = 5*4*3*2*1.  Also, 0! is defined as 1.
716500
no, but I've never heard of 831 as I love you. It is 143 for the number of letters in the words.\nI've not heard of anything starting with a 6.\nMaybe you mean\n86 means you're done, or we are outta here.  \nor\n360 means I love you back, or right back at you.
923278
Yes, \n1:1 means 1 and by convention, \nthis means 1 to 1 matching i.e.same \nimplying  'same dimensions as the other'\nSimple...Got it?
829663
ॐ is the "om" or "aum" symbol, which represents God, who is graceful.  Ok, that's a stretch, but it's the closest I have.  ;-)
318473
according to my book 'angel numbers' by doreen virtue\n\n222 means "have faith. everything's going to  be all right. don't worry about anything, as this situation is resolving itself beautifully for everyone involved."
263271
0061 or +61\n  say hi to them for me!
150867
Your question makes no sense. There is no equal sign. What do you want to solve for? Why so many powers (a^b means a to the power of b)?
1061702
every time i've asked a teacher this, they've told me that its an even number.  The only reason i can come up with is that it is found between  two odd numbers. (-1 and 1)
150167
(a) 111100111101\n(b) 110001011
109283
It stands for \nWindows eXPeriance
909352
This question has been asked so many times!?!?!\n\nGood challenge question!\n\nIt's a tough one, too.\n\nI'm taking it to work with me and asking my colleges to help me out on it.\n\nSomeone "did" crack this CHALLENGE Question.\n\nSo here's the answer. . .\n\nhttp://answers.yahoo.com/question/index;_ylt=AvnsMpyNhtwrHV1JVMvXrE4jzKIX?qid=20061130045858AAB57A7\n\nANSWER:  ABCDEFGHJ = 25,693,148\n\nA=2\nB=5 \nC=6\nD=9\nE=7\nF=3\nG=1\nH=4\nJ=8
280437
Based on minimal search, you may have an illegal form.\n\nYYYYDD would give you 200617\nYYYYDY would give you 2006Fri\nYYYYDDD might give you nothing, might give you 2006DDD, or 200617D or 2006017.\n\nIn cases like this, try the emperical method. Test it and see what you get.
609300
This is more of a word problem or a riddle than a math problem.\n\nThe answer is 7 (SEVEN).  Remove its first letter and it becomes EVEN!
151956
Exponentiation is usually taken to bind more strongly than addition, so 10^n+1 is usually interpreted as (10^n)+1.  You intended 10^(n+1).\n\nLet Rep(7, 10, n) be the "repunit" the integer the base 10 representation of which is n seven's.  You wish to prove by Mathematical Induction that the statement P(n) defined as\n\ndefine: P(n) states Sum{i = 1 to n}{Rep(7, 10, i)} = (7/81)*[10^(n+1) - (9*n) - 10]\n\nholds for all positive integers n = 1, 2, 3, ....\n\n\nFirst prove the lemma that Rep(7, 10, i) = "i seven's in base ten" = Sum{k = 0 to i-1}{7 * (10^k)} = 7 * ((10^i - 1) / 9) for positive integer i = 1, 2, 3, ... either by the formula for the sum of a geometric progression or by Mathematical Induction. :-)\n\n\nNow consider the statement P(1).  The left hand side of the equality is Sum{i = 1 to 1}{Rep(7, 10, i)} = Rep(7, 10, i) = 7.  The right hand side of the equality is (7/81)*[10^(1+1) - (9*1) - 10] = (7/81)*(100 - 9 - 10) = (7/81)*81 = 7.  The left hand side equals the right hand side so P(1) is true.\n\nNow let m be a positive integer m >= 1 and assume the statement P(m) is true with the goal of proving that the P(m+1) must then also be true.  For the statement P(m+1) the left hand side of the equality is\n\nSum{i = 1 to m+1}{Rep(7, 10, i)} = Sum{i = 1 to m}{Rep(7, 10, i)}  +  Rep(7, 10, m+1)\n= Sum{i = 1 to m}{Rep(7, 10, i)}  +  7 * ((10^(m+1) - 1) / 9)      # by the lemma\n= (7/81)*[10^(m+1) - (9*m) - 10]  +  7 * ((10^(m+1) - 1) / 9)      # by the assumption of P(m)\n= (7/81)*[10^(m+1) - (9*m) - 10]  +  7 * (9 * (10^(m+1) - 1) / 81) # multiply both numerator and denominator of right addend by 9\n= (7/81)*[ (10^(m+1) - (9*m) - 10)  +  (9 * (10^(m+1) - 1)) ]      # "undistribute" common factor of 7/81\n= (7/81)*[ (10^(m+1) - (9*m) - 10)  +  (9 * 10^(m+1) - 9) ]        # distribute multiplication by 9\n= (7/81)*[ ( 10^(m+1) + 9*10^(m+1) ) - 9*m - 9 - 10 ]              # addition is commutative and associative\n= (7/81)*[ 10 * 10^(m+1) - 9*(m+1) - 10 ]                          # more distributuve law\n= (7/81)*[ 10^((m+1)+1) - 9*(m+1) - 10 ]                           # definition of exponentiation\n= right hand side of the equality of P(m+1)\n\nThus both P(1) is true and "for all integers m >= 1, P(m) implies P(m+1)" is true.  You can knock over the first domino and each domino when it falls will knock over the next.  So by Mathematical Induction "for all integers n >= 1, P(n)" is true and all of the dominoes eventually fall.
401168
The 7 would be referring to the 7 rays of God Qualities: God Power/Will (blue), God Wisdom (yellow), God Love (pink), God Vision (green), God Peace (purple and gold), God Purity (white) and God Freedom (violet). \n\nThese correspond with our 7 main chakras.