Can you figure out this pattern?
545435
I would think 34 because I see a pattern at the end\n19 - 5 = 14\n14 + 20 = 34(You cant subtract unless your looking for integers which then would be -6 because:\n14 - 14 = 0 + 6 = 6 and you put the negative sign)
608711
i think it's a parabola.. im not sure. u should try plotting it on a graph.. substitute  the x and y values and see what form comes out..
872957
Look at them carefully, find out the diff between each number and it should be obvious.\n\nEquations?
723136
<3\n\nIt's an arrow pointing to the left, followed by the number 3.  Enjoy!
735406
Hint: the three side are equal long.\n\nTh
292709
The first term is 7C0 d^7 (2e)^0\nThe second is 7C1 d^6 (2e)^1\nThe third is 7C2 d^5 (2e)^2\nThe fourth is 7C3 d^4 (2e)^3\nSee how the pattern works -\n\nThe fifth term is 7C4 d^3 (2e)^4\n\n7C4 = 35; (2e)^4 = 16e^4; 35 times 16 = 560\n\nSo it simplifies to 560 d^3 e^4.
176413
Great puzzle, took me awhile to make it to f=1, g=4. The letters are from a-i: 9,8,7,2,6,1,4,5,3.\n\nPlugged in this is: (9 * 87 + 2/6) / (14 + 5/3) or (783 + 1/3) / (15 + 2/3) which equals 50.\n\nAnswer logged Sunday, March 12th, 3:20 pm with no other valid answers yet. Sorry to have to write that, but I've seen people change their answers too many times in the past.
33544
Here you go:\n\nhttp://home.att.net/~dexter.a.hansen/pattern/pat7.htm
747450
Sounds like Combinatorics.  Combinations, permutations, a bit of graph theory, discrete math, I usually describe it as "Advanced Counting".
180692
perhaps roman numerals
337947
You need a stringing machine, then it depends on what kind of machine you have. Would really need more details.\nStringing pattern can normally be figured out or taken from the previous set of strings.
383543
For a moment, I thought that Gabrielwyl had the correct pattern, then I noticed a mistake in for n=14. If there are 14 people, you should sit in the 13th spot.\n\nThen I checked gulabo's answer, and he did a good job of trying to find an expression to the pattern, except that it doesn't work. He wrote, "So, if n is even just SIT AT FIRST POSITION." Not true. You can check it yourself. His expression for if n = an odd integer is also incorrect.\n\n\n\nAnyways, the pattern for n people (yourself included) is to sit at the listed position. It's similiar to Gabrielwyl's except with the mistake corrected, and the pattern defined.\n\nN.Pos\n------\n1.1\n2.1\n3.3\n4.1\n5.3\n6.5\n7.7\n8.1\n9.3\n10.5\n...\n14.13\n15.15\n16.1\n...\n30.29\n31.31\n32.1\n...\n63.63\n64.1\n...\nn=2^n+x : 1+2x\nn=2^k : 1\n\n\nSo here's the strategy. It's simple:\n\nLet:\n\nn = # of knights including you\nk = an integer >=0\nx = an integer such that 1 <= x < 2^k\n\n1. For every n=2^k where k is an interger>=0, you must sit in the first seat to win.\n\n2. For every interger, n=2^n+x, you must sit in the seat # (1+2x).
889463
A pattern in numbers.  i.e. - 1,1,2,3,5,8,13,etc (add each number to previous number to get next number)
669748
Just think a bit to locate the pattern by lookinh the first four terms.\nYou either get a common fifference or common ratio, ie you get AP or GP.\n\nIf the series is in fraction and above two does not comes, take reciprocal and see for common diffrence, Harmonic Pogression.\n\nIn word problem you have to figure out the pattern first, then apply formula...hope it helps!
853314
HOLY SH*T..........it works......i did it three times.......i dont know how they did it......\n\nand i came up with a different number and i different symbol every time...
886083
You need to tell more about what these squares look like
679910
Knit one\nPurl two\nslip next stitch\nPurl single stitch over next two