what is 5(x-9) to the 5th power minus twice the square of pi?
535045
What is x ?\n\nYour expression is {5(x-9)}^(5-2*pi*pi)\n\nWhat is x ?
886343
1/9(x-1)^9 evaluated from 0 to 2.\n\n1/9(1)^9 - 1/9(-1)^9 = 1/9 + 1/9 = 2/9\n\nIf I didn't screw up.
771896
expand x^2-6x+9 = 5\nor x^2-6x+4 =0
801012
inverse square root of a number say"x" is\nx^[-(1/2)]
267044
The square root of pi is about 1.772. So the negative square root would be -1.772. I don't believe infinity has a square root, though.
22440
Well, the power is of course 99, but if you are looking for the coefficient, it is -5050.  Since terms that are constant multiples of X^99 must be multiples of all X's except for one, one simply adds the second terms in each binomial {-1,-2,...,-100}.  The sum is -5050
19421
X^5 = 98\n=> ln(X^5) = ln98\n=> 5lnX = ln98\n=> lnX = (ln98)/5\n=> X = e^((ln98)/5)\nX = 2.50175752714084352...
689918
use  power rule and product rule\nf'(x)=[1/5]*5*x^4 + 2x(x^2-x-9)+ \n(x^2+9)(2x-1) + 0=\n\nx^4 + 2x^3 - 2x^2 -18x + 2x^3 - x^2 +18x -9 =\n\nx^4 + 4x^3 - 3x^2 -9
710762
If you mean 6 raised to the power of negative pi, that would be 6 raised to the power of -3.1416. That computed to 0.0036. Used a scientific calculator, but you could do it with logarithms also.
972861
x(x+5)=36\nx^2+5x-36=0\n(x+9)(x-4)=0\nx=4\n\nwhere x is width of rectangle\nthus width of rectangle is 4\nlength is 9
502841
You cannot take the positive square root of a negative number. The expression (2 - 5/2) is a complex number.
422025
It looks like everyone else read your .5 as a 5:\n\n10 to power of .5 = square root of 10 = 3.162278\n\ne^-3 = 0.049787\n\ne^2 = 7.389056\n\n5^ -2.7 = 0.012965\n\ne is the exponential constant, ln(e) = 1
958505
x={-(-4) (+/-)√[(-4)^2 - 4(1)(-5)]}/(2(1))\n x= 4(+-)6/2\n x=5,   x=-1\n\nCheck:\n with x=5,  5^2-4(5)-5=25-20-5=0  OK\n with x=-1   (-1)^2 -4(-1) -5 = 1+4-5=0  OK
105888
square root(pi) = 1.77245385
626215
5/3 find the sq. root of 25/9
256079
x(x^2 -9)= x (x-3)(x+3)
855294
x = 9 or -10\n\nTake the square root of both sides of your equation, to get the following:\n\n| x+1 | = 10\n\nNotice I used the absolute value signs around x+1 ... that's because x+1 can equal either 10 or -10.  Why?  Because 10² = 100 and so does (-10)² = 100.\n\nSo, continuing on with showing our work:\n\nx+1 = 10 or x+1 = -10\n\nx+1 = 10  → x = 10-1 = 9\nx+1 = -10 → x = -10-1 = -11\n\nHope that helped!\n\n~ ♥ ~