What kind of intermoelcular forces are in glucose?
544702
Intermolecular forces are forces between two separate molecules.  In the case of glucose there are several polar bonds in the molecule between oxygen atoms and hydrogen atoms.  These bonds have permanent dipoles that will allow glucose molecules to "stick" to each other via hydrogen bonding between the partially negatively charged oxygen atoms on one molecule and the partially positively charged hydrogen atoms on another molecule.\n\nanother type of force between glucose molecules is dispersion forces (sometimes called London dispersion forces).  Dispersion forces are intermolecular forces felt between all types atoms and molecules and are due to temporary dipoles created when electron clouds distort each other.\n\nHydrogen bonds and dispersion forces are attractive forces that hold glucose molecules to each other but there are also repulsive forces between the nuclei of one molecule and the nuclei of the other molecules (there is a similar repulsion by the electrons because like charges repel).  The attractive forces are the strongest forces at longer distances, but the repulsive forces keep the molecules apart when they get very close to each other.
950410
Mainly H-bonding (intermolecular forces)
115621
since glucose is a monosaccharide, it is a simple sugar with a formula of C6H12O6. Now, to make glucose very easily, here's a hint. Since glucose is a product of photosynthesis (along with oxygen) just get a plant, put it under a UV light, and voila, glucose. The chemical formula for photosynthesis is (6)H2O + (6) CO2 + Light = C6H12O6 + (6)O2
741504
Vapor Pressure of Solutions\n\nA. \n\nAmount of the sugar present = 10.0g/ (342) = 0.0292397661 mol\nAmount of water present = 200g/ (18) = 11.11111111 mol\nThus, X(H2O), which signifies the fraction of water present,\n= 11.11111111/ (11.11111111 + 0.0292397661)\n= 0.9973753281\nAt 25 deg Celsius,\nVapor Pressure of Water is then = 0.9973753281 x 23.8\n                                                      = 23.73753281 Torr.\n\n\nB.\n\nAmount of Calcium Chloride = 49.4g/ (40.1) = 1.2319202 mol\nAmount of water = 150g/ (18) = 8.333333333 mol\nThus, X(H2O), which signifies the fraction of water present,\n= 8.333333333/ (8.333333333 + 1.2319202 )\n= 0.8712088294\nVapor Pressure of Water is then = 0.8712088294 x 23.8\n                                                      = 20.73477014 Torr.\n\n\nFREEZING POINT DEPRESSION/BOILING POINT ELEVATION OF SOLUTIONS\n\nA - NOTE: T(f) signifies T with the small f at its bottom right. Similarly, b(f) is an 'f' with a small f at its bottom right.\n\ndT(f) = change in freezing point\n\nChange in dT(f) = 5.48 - 3.77 = 1.71\nTherefore, from {c}\nb(f), which signifies the molality,\n= 1.71/ 5.12 = 0.333984375\n\nSince molality = (Amount of solute added)/ (mass of solvent/ kg),\n\nAmount of solute added = [500 x 10^(-3)]x(0.333984375)\n                                        = 0.1669921875mol\n\nThus, Mr of the unknown compound is 20.0/ (0.1669921875)\n= 119.7660819\n\nB\n\nChange in T(b) = (0.51) x {54.6/ [0.997x400x10^(-3)]}\n                         = 69.82447342\nsince  dT(f) = K x b(f) and\nmolality = (Amount of solute added)/ (mass of solvent/ kg).\n\nI am afraid I do not know how to proceed from here for I am not sure of the method to find the normal boiling point of a solution.
846025
assume that we have N mols of glucose in the 5% solution and S mols of albumin in the 5% solution....:\nwe know that the weight percent of an solution find by the following equation:{ ( mols of matter * molecular weight of matter)/100 Grams of the final solution}\nit means that:\nfor glucose: 5%=(N*180000)/100--->5=N*180000--->N=180000/5=36000(mols)\nfor albumin: 5%=(S*45000)/100--->5=S*45000--->S=45000/5=9000(mols)
573070
Water, sugar water, then salt water.\n\nSalt dissolves into 2 ions Na+ and Cl- per molecule, whereas sugar only dissolves into one sugar molecue. The greater the number of particles in solution, the lower the freezing point goes.
742243
Dont you mean how a molecule of glucose releases energy in a cell....any which way you look at it...refer to Kreb's Cycle in your Biology textbook!
841760
Glucose. Hydrolysis of sucrose (cane sugar) gives glucose + fructose; of lactose gives glucose + galactose; of maltose gives glucose.
732966
Any carbon atom which has 4 different groups bonded to it will be a chiral centre. There are 4 such atoms in the glucose molecule, though it can be hard to make that out when it's in a ring.\n\nThe links below may help.
117205
The molecular weight of glucose is 120.\n120 grams of glucose in 1 liter of water is 1 molar.\ndivide 120 grams by 10^-9, mix that in 1 Liter if water and the result is 1nM. Multiply 120*10^-9 by 125 and dilute to 1L, thats 125nM. About 15mG glucose in 1ml H20.
950149
D-glucose (or just glucose, or dextrose) is the "normal" carbohydrate that biochemistry uses as both energy and as a building block for starches, cellulose etc.  \nL-glucose is it's "non-superimposable mirror image".  It is the left-handed version of glucose (if you can accept the notion that it is "right handed"\nL-glucose plays no biochemical role that I know of.
582636
Try dissolving sugar in water then freezing it this is a solid solution. The solute is the sugar and the water is the solvent
478436
Intra>>>>>>Forces among atoms of the molecule.\nInter>>>>>>Forces between a molecule and its surrounding molecules.
875722
ribose or deoxyribose sugars and phosphates
880710
basicaly carbohydrate is struturally divided into two form which are 1 monosaccharides e.g glucose. and 2 disaccharides e.g sucrose. \n STRUTURAL FORMULAR FOR MONOSACCHARIDES E.G GLUCOSE IS\n                                            H                       \n                                                                 \n                                            C=O                       \n                                                                              \n                                            C\n                                             \n                                      H---C---OH\n                                             \n                                   HO---C---H\n                                             \n                                     H ---C---OH\n                                                  \n                                     H----C---OH\n                                               \n                                              CH2OH\n                                               \nALL THE CARBON( C) ARE ON A SRAIGHT LINE.
693940
Made up of two glucose isomers.\n\nEntirely carbon, oxygen and hydrogen
844758
Using the Michaelis-Menten equation.\n\nMore details on teh attached link\n\nhttp://www.le.ac.uk/by/teach/biochemweb/tutorials/michment2print.html\n\nGood luck