what is the formula to determine the surface of a pyramid?
547584
the surface area is (1/2 X perimeter of base X slant height)\nthe total surface area is ((1/2 X perimeter of base X slant height) + (area of base))
619584
Do you mean inside area of triangle ?\n\nArea= 1/2 (base)(height)
422511
if u kno the base and height.. then area= (base x height)/2\n\nif the triangle is scalar,\nthen :\n\nfirst find s, using hero's formula\n\ns= (a+b+c)/2   .... where a,b,c are the sides of triangle.\n\nthen , area = squareroot(s x (s-a) x (s-b) x (s-c)
192399
In the front?  You have to consider the whole cube to find volume.  Volume = base area * height  You could find the surface area of one side, but you'd need to know the side length.
287728
Surface Area = [Base Area] +\n1/2 × Perimeter × [Side Length]\n\nVolume = 1/3 × [Base Area] × Height\n\nThe Surface Area has two parts: the area of the sides (the Lateral Area) and the area of the base (the Base Area). \n\nThe Base Area depends on the shape, there are different formulas for triangle, square, etc. \n\nBut the Lateral Area is surprisingly simple. Just multiply the perimeter by the side length and divide by 2. This is because the sides are always triangles and the triangle formula is base times height divided by 2
303035
If the triangle is a right triangle, you can find the other side by Py's Th and then by the formula,(A=1/2bh).\nIf it is not, you should know the angle they make each other or an adjacent angle. Only if, you can find the area by sine laws or cosine laws.
45249
Let S be a surface in three-dimensional space ( R^3 ) and let f be a function defined on this surface. To describe the surface, we will choose a parameterization of the surface by two variables which we shall call u and v. (For instance, if f is a sphere, u and v might be the latitude and longitude.) In terms of this parameterization, the function f can be expressed as a function of u and v. Then the integral of f with respect to the surface area is usually notated as \n\nSurface Integral S[f(u,v)d^2 A]\n\nJust as with the ordinary integral, this quantity may be understood as a limit of sums.1 To form an approximating sum, we subdivide the surface S into a miniscule pieces, multiply the area of each piece by the value of f at a point located inside that piece, sum over all the miniscule pieces into which we have subdivided the surface. The limiting value of these sums as the size of the pieces shrinks to zero is the integral with respect to surface area. \nTo compute this quantity, one may use the following formula to convert it to a double integral: \n\n\nIf the surface is described as the graph of a function , then we may also use the following formula:
811463
The surface area of any prism equals the sum of the areas of its faces, which include the floor, roof and walls. Because the floor and the roof of a prism have the same shape, the surface area can always be found as follows:\ncall the 'floor' the 'base'. The height of the prism = 'H'.\nThe surface area of a prism = 2 × area of base  +  perimeter of base × H\n\nexamples:\n\nRectangular based prism:\nBase shape: Rectangle, length 'L' and width 'W'\nArea of base: L  × W\nPerimeter of base: 2(L+W)\nSurface area = 2LW + 2(L+W)H\n \nCircular based prism\nBase shape: Circle, radius 'R'\nArea of base: pR²\nPerimeter of base: 2pR\nSurface area = 2pR² + 2pRH\n\nTriangular based prism\nBase shape: Triangle: base 'b', height 'h', and sides S1, S2 and S3 \nArea of base: ½b×h\nPerimeter of base: S1+ S2 + S3\nSurface area = bh + (S1+ S2 + S3)H\n\nAs for lateral area of a cone , If r is the radius of the base, h is the altitude, and l is the length between the vertex and a point on the base circle \nlateral area pi rl=pi r x sq.root of r to the power 2 + sq.root of h to the power of 2\n or try this site- http://www.mathepower.com\n\nThe lateral area of a prism is the sum of the areas of the lateral faces (all the ... How many lateral faces does this prism have?\nWhat is the area of each \n\nelse there are many sites to giv better details matching ur specific figure ...try google for search..all luck..
517439
you can express the area as the sum of the areas of the 4 inner triangles which are each 1/2 base x height.  Each base is an edge of the quadrilateral.  The height can be determined in 2 ways and you will need both to solve the system of equations:\nfor example: to determine the height of APD, recognizwe that the height line splits APD into 2 right triangles.    Call the point where the height line intersects AD point E. The edge AD will be split between the 2 tringles proportionally:  AE = 24/69  AD and DE = 45/69 AD.  Now you can determine the height in terms of AD using pythagorean theorum.  Go from there...\n\nTry this site...
529872
Easy H*D*W    H=Height D=Depth W=Width *= times\n\nUse the units cubed, if it is meters use m^3 as the unit of measurement
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The formula for surface area of a sphere is \nA = 4*pi(r^2)\n64 pi = 4*pi(r^2)\nwhich means r^2 = 16 or r = 4\nVolume of a sphere is \nV = (4/3)*pi (r^3)\nV = (4/3)*pi (4^3)\nV = (4/3)*pi (64)\nV = (256/3)*pi
768235
surface area = (2 * pi * r^2) + (2 * pi * r * h)\nh = 5, surface area = 100 (put in units later)\n\n100 = (2 * pi * r^2) + (2 * pi * r * 5)\n2pi*r^2 + 10pi*r - 100 = 0\n\nNow bring in the best equation in the world. (Quadratic Formula)\nx = (-b +- sqrt(b^2 - 4ac)) / 2a\n\nr = (-10pi +- sqrt(100pi^2 + 800pi) / 4pi\n\nThrow the negative out, because length cannot be negative.\n\nr ~ 2.21cm
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Well... a slightly advanced method is that you should fist realize that a triangle drawn through these three points will have an area = 0\n\nformula for area of a triangle is:\n        \n| a1 b1 1 |\n| a2 b2 1 |  x 1/2 = A\n| a3 b3 1 |\n\nWhere (a1,b1) ; (a2,b2) and (a3,b3) are the 3 vertices of the triangle.\n{Sorry --- no better way to represent a matrix here...}\n\nor; A = 1/2 [ a1(b2-b3) - b1(a2-a3) + (a2.b3 - a3.b2) ]\n\nHere; A = 0 ; a1=-5; b1=1 : a2=1; b2=p and a3=4; b3=-2\n\ntherefore; 0 = 1/2 [ -5(p+2) - (1-4) + (-2 - 4p)]\nor;        0 = [-5p -10 + 3 -2 -4p]\nor;        0 = -9p -9\nor;       9p = -9\n\n=> p = -1\n\nAnother method would be to find the line through two given points and pass the line through the third point... but that is slightly lengthy.... \n\nIf you have any doubt; feel free to ask me.
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V = h*pi*r^2\n\nThere h - height\nr - radius of foundation\nV - volume
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V(pyramid) = 1/3 * b * h\n= 1/3 * (13 *12) * 15\n= 780
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Are you looking for someone to do your homework?\nGeometry is very simple. There are three basic shapes, The sphere, Triangle and the Square. Learn that a circle is nothing more than a shadow of a sphere and that shadow is but a line. The angle is your point of view. To solve for X you must know two of the three. X is only unknown for a very short time. There are 10 dimensions. Length, width, height, area, volume, weight, mass, velocity, time, and infinity. Any math problem may be solved if two or more dimensions are known. The lowest common denominator is two and if two of anything is known the third dimension will be also known.\nie. a triangle with equal sides is composed of 3, 60 degree angles, 60 + 60 + 60 = 180 degrees. Knowing that half of a circle which is half of a sphere multiply by the common denominator of 2 and 360 appears which is a sign for infinity, through in any of the dimensions given  such as volume, mass, velocity, etc. any problem can be solved. Linear problems are solved with the triangle also. For every side there is the other. Make the triangle square or draw a square and divided it in two by a linear line from the opposing corner. Solve the problem L x W x H and you have area. Divide the area of the square by two and you have the area of the triangle. Pi is infinity, in math it is 3.14 and then some. Pi is also the Greek word for the Egyption (word) hieroglift of the lazy 8 which is a symbol for infinity also, it is a mineral we call magnetite. Magnetite in crystal form is in the shape of tetrahedron which we know as a pyramid times 2. The numeral 8 is an Aribic number which means 4 + 4. It is not of any quincedence that a pyramid has four faces. The mystery of the pyramids has been solved by Paul Einstein. Geometry is fun if you know how it came to be.
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A = base * height\n\nbase = 8\n\nslant height = 6\nto get the actuall height, we use trig\n\nthink of 6 as the hypotenuse\n\nsin 30 = height / slant height\n\nor height = sin30 * 6\n\nheight = 3\n\ntherefore area = 8 * 3 = 24