the lengths of 3 sides of a triangle are 7 cm 11cm and 16 cm. Describe the triangle as acute right or obtuse?
545927
A right angled triangle with short sides of 7cm and 11cm would have a long side (hypotenuse) of √(7²+11²)\nSo the square of the length of the longest side would be \n49 + 121 = 170 \n16² = 256, so this side is too long to make a right-angled triangle - the two short sides would have to open up a bit - making an angle greater than 90°...\n\nI have heard of a right angled triangle, but acute and obtuse are used to describe angles, in my experience...\nAs the internal angles in a triangle sum to 180°, clearly if one angle is obtuse or 90°, the other two must be acute.\nThe question may be referring to one specific angle in the triangle - so the answer is here, anyway!
155406
By definition,hypotenuse is the side opposite the right angle. So it has to be a right angled triangle.
735406
Hint: the three side are equal long.\n\nTh
723227
<R= 52* 180-83-45=52. because 3 <s of a triangle is 180.\n\nLaw of Sins:\nSin A / a = Sin B / b = Sin C/ c\n\n(sin 52)/ 18 = (sin 45)/ q\ncross multiply\n[ 18 x (sin 45) ] / (sin 52) = q\nq= 16.1 so about 16\n\n(sin 52)/ 18 = (sin 83)/ p\ncross multiply\n[ 18(sin 83) ] / (sin 52) = p\np=22.67 so about 23\n\nthere!\n<R = 52*\nq= 16\np= 23
797707
See the picture:\n\nhttp://mudandmuck.com/str2/sin&cos.jpg\n\nThe two triangles in the picture are equivalent.  (Same angles, and one side of each we know to be the same (hypotenuse=1), so all the sides have the same absolute length, only their signs are different.)
726903
since the sum of two  angles is equal to the one angle it  imlies the third angle is 90 degree since \nbecause:\nLet the angles be a,b,c now a+b=c therefore a+b+c=180 now a+b=c therefore 2c=180 this implies c=90 degrees. therefore it is a right triangle hence the measure of the third side according to pythagoras therom is square root of the sum of the squares of both sides
776894
The sum of the three angles of a triangle is 2 right angles.So ,if one of its angle is one right angle,then the sum of the other two angles would be one right angle,which makes it impossible for another angle to be a eight angle.
633404
ANSWER: \n34 metres\n\nEXPLANATION:\nLet one leg be 'x' units long. \nThen hypotanuse = 2 metres + 2*(length of leg) = (2 + 2x) metres.\nThe other leg is 30 metres.\nIn right angled triangle using Pythagorus' theorem\n(Hypotanuse)^2 = (One leg)^2 + (Another leg)^2\nor (2 + 2x)^2 = x^2 + 30^2\nor 4 + 8x + 4x^2 - x^2 - 30^2 = 0\nor 3x^2 + 8x - 896 = 0\nor 3x^2 + 56x - 48x - 896 = 0\nor x(3x + 56) -16x(3x + 56) = 0\nor (x - 16)(3x + 56) = 0\n\nTherefore x = 16 [as x = -56/3 is inadmissible ('x' being length of a side have to be positive)]\nHence the hypotanuse = 2 + 2*16 = 34 metres
721808
If you are trying to make a triangle out of three equal lengths, all you do is devide 180 by 3.....and taddaaa you get your angles.\n\nIf does not matter how long each side is.
1053705
The legs of a triangle have the lengths 5 and 12.  What is the  length of the hypotenuse? Answer: 13\n\nThe legs of a triangle have the lengths 7 and 11.  What is the  length of the hypotenuse? Answer: sqrt(170)\n\nThe length of the hypotenuse of a triangle is 25.  One of the legs has length 24.  What is the length of the other leg? Answer:7\n\nThe length of the hypotenuse of a triangle is 15.  One of the legs has length 12.  What is the length of the other leg? Answer: 9\n\nThe length of the hypotenuse of a right isosceles triangle is 8.  What is the length of the two legs? Answer: 4sqrt(2)
12258
sorry i made a mistake....this is correct...\ndivide the base by 2.  Now you have a right triangle.  the height is the same, but the base is now 3.  pygathora (spelling, whatever) theorm is A squared + B squared = C squared.  c is the side opposite the right angle, a and b are the other sides.  so 3 squared + 4 squared is 9 + 16 = 25. The square root of 25 is 5, so that is the length of the side.  the volume = area of base times height.  Area of a triangle is 1/2 base times height.  so 3 (one half of 6) times 4 = 12.  times this by height of 8 = 96 cubic units. largest rectangular side is the 6 (the longest side) times 8 = 48 units squared. hope this helped.  the lateral area is the area of the sides added together. so C times 8 = 40 (area of one side)  add the other side of equal area (the C from the second triangle we got when we split the first one) 40 + 40 = 80.  Add the third side of length 6 times 8 = 48.  80 + 48 is 128 (in units squared).  or all sides added up 5 + 5 + 6 = 16 times 8 = 128.
876350
Sorry, but your question doesn't make sense.  Maybe you mean the midpoint of one of the sides of a right triangle.
899919
16.72 inches squared.\n\n\nDivide an equilateral triangle into two equal right triangles (meaning, draw the height).  The right triangles will have angles of 30, 60, 90, right (an equilateral triangle has 3 60 degree angles)?\n\nThe ratio of the sides in such a right triangle (the smallest leg being a) is a:a(sq(3)):2a, where 2a is the hypotenuse and a(sq(3)) is the other leg.\n\nThe "other leg" in this case is the height.  So a, half of the length of the side of the whole equilateral triangle, is 5.382/sq(3).\n\nMultiply this by 2 to get the whole length of the side.  We have our base and height.\n\n\nThe area of an equilateral triangle is 1/2bh.  b=2(5.382)/sq(3)\nh=5.382\n\nPlug those in and you get 16.72.
385120
When you are trying to find out various measurements of a right triangle (angle measurements or lengths of sides). Try this mnemonic (memory device):\n\nSaddle Our Horses\nCanter Away Happily\nTo Other Adventures
699841
Three are three angles in a triangle which all add up to exactly 180 degrees.
730817
Define the lengths of the smallest triangle:\nAP = ½ AC\nAQ = ½ AB\n\nSquare the equations:\nAP^2 = ¼ AC^2\nAQ^2 = ¼ AB^2\n\nPythagorean theorem for smallest triangle:\nAP^2 + AQ^2 = PQ^2\n\nSubstitute:\n ¼ AC^2 + ¼ AB^2= PQ^2\n\nMultiply by 4:\nAB^2 + AC^2 = 4PQ^2\n\nPythagorean theorem for triangles ABP and ACQ:\nAP^2 + AB^2 = BP^2\nAQ^2 + AC^2 = CQ^2\n\nAdd the two equations:\nBP^2 + CQ^2 = AP^2 + AQ^2 + AC^2 + AB^2 \n\nSubstitute:\nBP^2 + CQ^2 = PQ^2 + AC^2 + AB^2\n\nSubstitute:\nBP^2 + CQ^2 = PQ^2 + 4PQ^2\n\nTherefore:\nBP^2 + CQ^2 = 5PQ^2\n\n\nIf you get stumped with this type problem, sometimes it helps to start at the end and work backwards...
1000630
Pythagoras Theorem asserts that for a right triangle with short sides of length a and b and long side of length c \na2 + b2 = c2 \n\nor c2-a2 = b2 \n\nhere is a link with all the necessary thing you have to know about this theorem . I hope it helps , just read it carefully and everything is going to be fine :)