Find the value of Theta in degrees and radians by using a calculator!!!?
535427
To do this, you have to do sin^-1 * decimal. Because Yahoo Answers only displays up to .0145, I'll do sin^-1 * .0145, which would be about 0.8308
824139
All you need to do is enter these on a scientific or graphing calculator.  Make sure it is in degree mode.  For the second part use the 2nd or shift button to get sin^-1 etc
705201
mcdelta theta\nm=1 kg(by default)\nc=4.2 J/degree/kg\ndelta theta= 75\ne=1*75*4.2\n  =315 j
706522
It's often handy to draw yourself out a little sketch.  From it you can see the location of the given point.\n\nTo identify the angle the given point makes with the x-axis and the y-axis use trigonometry.  Switch to radians.\n tan Θ = opp./ adj.\n Θ = tan^-1 opp./ adj.\n Θ = tan^-1 (-0∙4425./ -0∙8968)\n Θ = tan^-1 (-0∙493 210 52)\n Θ =  0∙458 370 613 rad.\n    This is the value of the angle below the x-axis.  You need to include the angle above the x-axis, which is 180º or π radians.\n Θ =  0∙458 370 613 rad. + π rad.\n Θ =  (0∙458 370 613 + 3∙14) rad.\n Θ =  3∙598 370 613 rad.\n Θ ≈  3∙6 rad.
830100
'x= rcost\ny=rsint\n\nand r= sqrt(x^2+y^2)\nt=arctan(y/x)\nso\nif x=2, and y=2, then r= sqrqt(4+4)=sqrt(8)\nand t=arctan(2/2) = arctan(1) = pi/4
855395
1 + jwt = 1 + 4.8j\nLet r = √(1² + 4.8²) = √(24.04) = 2√(6.01)\n\nSo 1 + 4.8j = m(1/m + j *4.8/m)\n\nSo cos θ = 1/r and sin θ = 4.8/r OR tan θ = 4.8\n\nSo θ ≈ 1.3654 rad\n\nSo 1 + 4.8j = 2√(6.01)(cos(arctan(4.8)) + j sin(arctan(4.8)))\n\n≈ 4.903 (cos(1.3654) + j sin(1.3654))
83972
R*exp(i*theta) = R [ cos(theta) +i*sin(theta) ]\nthis is the polar representation (raduis R ,angle theta) transformed to the cartisienne form (X=R cos(theta), Y=R sin(theta))  where i is imaginary to matk that y is perpendic to x\n\nR=1 theta=pi/2\nexp(i*pi/2) = cos(pi/2) + i sin(pi/2)\nexp(i*pi/2) = 0 +i *1 =i\n\nso i=exp(i*pi/2)=e^(i*pi/2)    where e=2.7818281828\ni^i=e^(i*pi/2)^i\ni^i=e^(i^2*pi/2)\ni^i=exp(-pi/2)\n=0.207879576
610143
I think ur right cos^2(theta) should be cos(theta). then the answer would be perfect.
156129
The sine of an angle is equal to the opposite leg over the Hypotenuse,\n\nsin(theta) = opp/ hyp\n\nSo to solve for the angle, theta, take the arc sin of opp/hyp.\narcsin(opp/hyp) = arcsin(.7071) = theta = 45 degrees.\n\narcsin essentially undos what sin does to the angle to allow you to reverse the process.\nArcsin is more commonly seen on calculators as sin^-1
973993
Let E be the raduis of the earth\nLet r be the actual radius of the circle in the plane\nLet S be the radius of the circle on the sphere\nLet θ be the angular separation of the centre of the circle on the sphere to the circle in degrees\n\nThus θ = πθ/180 radians\n\nThen C = 2πr\nr = E*sinθ → C = 2πE*sinθ\nAlso S = E*πθ/180 → E = 180*S/(πθ)\n\nThus C = 2π*sinθ*180*S/(πθ)\nie C = 360Ssinθ/θ \nwhere S = radius on sphere and θ is the angular separation (at the centre of the sphere) between the centre of the circle and any point on its circumference, expressed in degrees
166573
:)\nNice trick question.\nYou should mention that the whole 'equations' reads:\n2 times (pi) radians = 360 degrees (measuring angles).\ntherefore (pi) radians equales 180 degrees (half circle)\nBut the number (pi) is same old 3.14......
948099
+90° rotation (ie 90° anticlockwise)\nA = (0, -5) → (-5, 0)\nB = (1, 9) → (-9, 1)\nC = (8, 9) → (-9, 8)\nD = (-3, -1) → (1, -3)\n\n-90° rotation (ie 90° clockwise)\n\nA = (0, -5) → (5, 0)\nB = (1, 9) → (9, -1)\nC = (8, 9) → (9, -8)\nD = (-3, -1) → (-1, 3)
902054
1 Degree=2*pi/360 Radian.\n\nsin 30=sin(pi/6)Radian.\n\n(1 Degree=0.01745329 Radian.\n30degree=30*2*pi/360 Radian.\n\n30degree=30*pi/180 Radian.\n\nsin 30=sin(30*pi/180)Radian\nsin 30=sin(pi/6) Radian..)\n\n(360 degrees=2*pi*Radian\n\n1 radian=360/2*pi\n\n1 Radian=57.29577951 degrees.)\n\n(One radian is the angle subtended at the center of a circle by an arc of circumference that is equal in length to the radius of the circle.\n\nIn terms of a circle it can be seen as the ratio of the length of the arc subtended by two radii to the radius of the circle. )
850990
In this case involving trigonometric operation on angles, you will need to carry the error over to your operation results. What I mean by that is:\n\nYou have an angle known only to 1 degree of precision, i.e.\n\nθ = 32° ± 1°\n\nTherefore, when you compute Cos (32°) = 0.848 \n\nYou will also need to perform the trig operation including the error:\n\nCos(31°) = 0.857 and Cos(33°) = 0.839\n\nSo your measurement is 0.848 ± 0.009 or 0.85 ± 0.01 depending on how many significant digits you want to keep.
945543
A short element of the curve is dL=sqrt(dr^2+(r*dt)^2), r*dt elementary length of the arc with radius r and polar angle t (your theta), dr elementary increase of r for dt.\nThus dL=sqrt(r’^2+r^2)*dt.\nIf  r=a*(1-cost), then dL=a*sqrt((sint)^2+(1-cost)^2)=a*sqrt(2)*sqrt(1-cost)*dt. \nFortunately 1-cost=2*(sin(t/2))^2 or dL=2a*sin(t/2)*dt, L=-4a*cos(t/2) for t=0 until 2pi, thus L=-4*a*(-1-1)=8*a – Oh! check it poor kid!\nIf r=(sin(t/2))^2=0.5*(1-cost), then a=0.5 for t=0 until pi. It must be done likewise. Thus L=-4*0.5*(0-1)=2
523009
sine is positive and sec is negative so that means that theta is in the second quadrant.\ncosine and tangent are bot negative.\ncos(theta) = -sqrt(3)/2\ntan(theta) = -1/sqrt(3) = -sqrt(3)/3
27656
I used the acronym sohcahtoa to remeber that sin=opp/hyp cos=adjacent/hyp and tan=opp/adj, so you have a angle you want to measure the degree of that angle, using the lengths of the sides of the triangle opposite, adjacent and hypotenuse and then using your calculater you divide the lengths and hit the button sin-1, cos-1 or tan-1 key, also cot=1/tan, hope that helps