how to calculate WPM?
444526
A "word" is typically 5 letters.  So 20 words will equal 100 letters.
379771
http://www.mikeholt.com/mojonewsarchive/EC-HTML/HTML/WyeTransformerCalculations~20030916.htm
1124301
Are you trying to figure out when it stops? \n\nIf so, look at your units:\n\nYou have meters per second squared, and meters per second... To get to seconds you're going to invert the meters per second squared and then multiply... \n\nYour answer is 7 seconds.
864388
some formulas that can help :\nhttp://www.eskridgeinc.com/support/formulas.html
1132233
this question will require calcs using logarithm.\nhence will take time
831091
w = mg\n(w is weight, m is mass, g is acceleration due to gravity (9.8m/s^2))\n :. m = w/g\n        = 300 / 9.8\n        = 30.6 kg
545136
8 PM tomorrow.  http://www.timeanddate.com/worldclock/ will help you with such things.
140062
L x W = Area\n\nCheater
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0.0161 sec - 0.0115 sec = 0.0046 sec\n\n2 meters / 0.0046 sec = 434.8 m/sec
587882
FORMULA: speed = frequency * wavelenght (sorry cant get symbols to work on yahoo)\n\n(1) 0.2= 1/0.5 * w   ...(as f=1/T)\n=> 0.2=2w\n=> w=0.1\n\n(2) s= 25*(10^8) * 0.12    ...(12cm= 0.12m)\n=> s= 3*10^8\n=> s= 300000000 m/s\n\n(3) 2= f * 0.5\n=> f= 2/0.5\n=> f= 8\n\n8 waves strike dock each second.\n\npretty easy questions.
954922
440=Vr(t+30)\n(Vr+Vb)t=440+(Vb-Vr)30\nTotal time elasped is 1hour\nRate of stream Vr=440yards per hour
847480
Q = m * Cp * DeltaT.\n\nPlug the numbers in.  Get Cp from your book.
887472
If L = Length\nW = width\nPerimeter = P = L + L + W + W\nP = 2L + 2W ... (1)\n\nBut in this question \nL - 5 = 3W\nL = 3W + 5 ... (2)\n\nSubstitute this value of L in (1)\nP = 2(3W + 5) + 2W\n\nP = 46\n46 = 2(3W + 5) + 2W\n46 = 6W + 10 + 2W\n46 - 10 = 6W + 2W\n36 = 8W\nW = 36/8\nW = 4.5 cm\n\nSubstitute this value of W in (2)\nL = 3W + 5\nL = 3(4.5) + 5\nL = 13.5 + 5\nL = 18.5cm\n\nCheck ...1\nP = 2L + 2W\n46 = 2(18.5) + 2(4.5)\n46 = 37 + 9\n46 = 46!\n\nCheck ... 2\nL - 5 = 3W\n18.5 - 5 = 3(4.5)\n13.5 = 13.5!
958697
10.4 m/sec\n\nV(t) = (30+a*t) m/sec\n\nwhere a = - 9.8m/sec^2\n\nV(2) = (30 - 09.8*2) m/sec\n\nV(2) = 30-19.6 = 10.4 m/sec
216773
Average Power = Work/Time\nWork=Force*Distance\nDistance=2*pi*radius=2*pi*(0.31 m)=(1.95 m)\nAverage Power = ((25 N)*(1.95 m))/(1.6 s)=30.4 W
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t=2.512 seconds\n\n10.3=0.5(0+8.2)t\nTherefore \n\n1 = 4.1t/10.3\n\n1/t = 4.1/10.3\n\nt = 10.3/4.1 = 2.512 seconds
958888
Use the formula:\nQ (heat) = Cp (Heat Capacity) * delta T (Change in Temperature)