How do you calculate the R.A.M? (with example)?
440454
the R.A.M. is the average mass of an atom of an element, taking account of its natural isotopes & their percentage abundance.\neg: the R.A.M. of CaCl2  :\n     the exam paper will give you the the R.A.M. s of Calcium-40 & Chlorine - 35.5,so the answer is,\n         = (1*40)+(2 * 35.5)\n         = 40+71\n         = 111\n     hope this helped.Cheerz!
432008
t=rho/(sqr((1-rho^2)/(n-2)))\nwhere:\n\nrho: correlation coefficient\nn: number of observations
840437
Well, I can see that one possible solution is r = 0, and my calculator says the other answer is r = 0.0809394063, so hopefully that helps...
1147102
pi*(r^2)\n\nIt doesn't matter which unit you use, just make sure you're consistent.
983612
First swap the variables, then solve for R again.\n\nv = (21/2) - (1/64)R^2\nR^2 = -64v + 672\nR = ±√(-64v + 672)
848345
I assume that this is s = (a-rl) / (1-r).\n\nFirst, multiply both sides of the equation by 1-r.\ns(1-r) = a-rl\n\nUse the distributive property on s(1-r)\ns-sr = a-rl\n\nGet the r terms on one side of the equation and the others opposite it.\nrl-sr = a-s\n\nUse the distributive property to factor out the r.\nr(l-s) = a-s\n\nDivide both sides by l-s\n\nr = (a-s) / (l-s)
437832
Homework.\n\nSuppose a1*x+a2*Tx+..+am*T^(m-1)x=0.\n\nApply T^(m-1) to get a1=0.\nApply T^(m-2) to get a2=0, etc.
847480
Q = m * Cp * DeltaT.\n\nPlug the numbers in.  Get Cp from your book.
854485
The formula cannot be rearranged to give r in terms of n, FV and A. So, you must solve numerically by trial & error. Here's an example.\n\nIf FV = 4000, A = 1000 and n = 5 find r.\n\n[ 1 - (1 + r)^-5 ] / r = 4.\n\nTry r = 0.05: left side = 4.3, so choose a bigger r.\n\nTry r = 0.1: get 3.8, so choose a smaller r.\n\nFor your next choice you can use the average of 0.05 and 0.1 = 0.075. But, because 3.8 is closer to 4 than 4.3 is, choose a slightly bigger value: 0.08.\n\nWith r =0.08 get 3.9927\n\nContinue to the required number of decimals: 0.0793 or 7.93%.\n\nYou can also use the WIMS calculator. Enter\n\nf(x) = (1-(1+x)^-5)/x-4\n\nselect: show the curve, and search for roots to get\n\nx = 0.0793082611605
153995
F=m*a\na=F/m = 3.5 x 10^7N/(2.0x10^6kg) = 17.5 m/s^2 or 1.8g
728641
acceleration can be found using\na=(m1-m2)g/(m1+m2) = 3*9.8/5 = 5.88 m/s^2
2521
You need to know the magnitude, the link below will give you the formula.
540368
a=1\nar=3\ntherefore r=3/a\n         r=3/1\n  therefore common difference r =3
120843
R^2 (root mean square) is just a statistical measure of how well your data lines up. Anything over .99 is near perfect.
825103
No, you add exponents when you multiply, so you would have\n5*(-4)r^(2-3) = \n-20r^-1 = -20/r
740779
use pv=nrt and you can get the answers
656507
Use the law of sines\n\nn/sin(N)=m/sin(M)\n\nso \n\nm = n*sin(M)/sin(N)\n\nPlug in the values and use your calculator.