How many possible ways can you arrange ABCDEF??
438356
Number of ways to arrange ABCDEF = 6! since all of the letters are distinct.\n\nNumber of ways to arrange TOYOTA = 6!/(2!2!) since there are two T's and two O's.
99929
AbC and Abc (only two types).
450313
10 percoset should do the trick\nThis is a joke....just in case you are dumb enough to try it.lol
697965
every number from 0 to 10\n\nplus placed in alphabetical order
378327
I don't think there's space here for me to do it how you,  but i'll get you started.\n\nFirst do all the combinations that start with F\nFirst, FL\nFLASH\nFLAHS\nFLSAH\nFLSHA\nFLHAS\nFLHSA\n\nDo it sysematically. FLA then FLS then FLH\nNow FA\nFALSH\nFALHS\nFASHL\nFASLH\nFAHLS\nFAHSL\n\nAnd just keep doing this, working systematically through every letter. \n\nHope this helps.
789066
Firstly, it has to start with either a 1 or a 2, and end with a 2 or a 6. So we just take each case one at a time.\n1..2: that leaves 23556, so there are 5!/2! ways, ie 60 ways.\n1..6: that leaves 22355, so there are 5!/(2!2!) ways, ie 30 ways.\n2..2: that leaves 13556, so there are 5!/2! ways, ie 60 ways.\n2..6: that leaves 12355, so there are 5!/2! ways, ie 60 ways.\n\nNote that in each case there are 5! ways of arranging the other 5 numbers, but we need to divide by 2 if there is a pair of repeated numbers.\nThat gives a total of 210.\n\n(note that both of the other answers given so far are wrong - its not 360, because that person has forgotten they have to be even; and its not 120. They counted 2x2 possibilities for the first and last digits which is correct, but one of those cases already uses both 2s, so you *don't* want to divide by 2 in the end for that particular case (you're not counting them twice are you!)\nTheres really no other way of doing it than splitting them into cases like I did.
172875
Obviously you are doing homework and don't want to figure it out yourself.  It is easy, just write them out.  Obviously you can disregard the B, because there is no choice (both dominant).  Now do all the combinations with a "A" and then double your answer to get the "a".\nACD\nACd\nAcD\nAcd\nThat is four combinations.  Double it for "a" and you get \n\nEIGHT\n\nTyping out the question is harder once you learn the rules.
895848
The opposite\n\ne.g. \nto cancel 5, add -5 to both sides\nto cancel x², add -x² to both sides\nto cancel -12x, add 12x to both sides\netc.
666462
ZOTTF (0 1 2 3 4)\n\nNEXT:\n\nFSSENT... (5 6 7 8 9 10...)
542271
ABC its easy as 123, ABC, 123. \nGO MICHAEL!!!!!!!!!!
982139
Here it is:\nhttp://www.abccactus.com/index_1.htm
545283
there are two groups of 2 people , so take those 2 people as 1 unit. so there are total 8 units.\nthus number of ways to be arranged is 8! , that is 40320.
813964
♥    since i cant put it together i will show u wut 2 type step by step\n\n1.  &\n2.  hearts\n3.  ;   \n\njust put all of those together and make sure hearts is lowercase
331637
hahaha. do it yourself. ill start you off.\nfirst write out the 5 possibilities of the first letter. then for each letter, write out the 4 possibilities of the 2nd letter. then for each of those combinations, write out the 3 possibilities of the 3rd letter and for each of those write otu the 2 possibilities of the 4th letter and then theres only 1 possibility of the last letter for each of them.\n\nF L A S H\nF L A H S\nF L S A H\nF L S H A\nF L H A S\nF L H S A\nF A L S H\nF A L H S\nF A S L H\nF A S H L\nF A H L S\nF A H S L\nF S L A H\nF S L H A\nF S A L H\nF S A H L\nF S H L A\nF S H A L\nF H L A S\nF H L S A\nF H A L S\nF H A S L\nF H S L A\nF H S A L\n\nL F\n  A\n  S\n  H\n\nA F\n  L\n  S\n  H\n\nS F\n  L\n  A\n  H\n\nH F\n  L\n  A\n  S
1128099
Yes, there are many ways,  if you can't get it to work using everyones answers - send it to me I will convert it for you. zqizzy@yahoo.com
940694
Im assuming that by using the word 'groups', (plural) you are not allowed all four in one group as a solution.\nSo, if the counters are the same, then 2 ways:\n1, 1, 1, 1 \nand\n2, 2\n\nIf the counters are different, then 4 ways.  (If the counters are:\na, b, c, d then:\nab,cd\nac,bd\nad, bc\na, b, c, d. )\n\nIf this is for a 3rd grader then the former is probably what they are looking for, but I can't really know that.  The latter seems a little complicated for the average 3rd grader.
990622
if you know permutation/combination..the answer is easy to understand...\n\nlike 23C23+23C22+23C21+......+23C1