Is there a way to get to 25 by just using the numbers 2, 4, 6, 8 each once and basic operations (+-*/)?
442864
6 2/8 *4  becomes (6 1/4)*4 or 6.25*4=25\n\nShould view it as an elementary school fraction:  6 AND 2 eighths times 4 is 25.
149171
1,365\n\nor 15!/(11! * 4!)\n\nie n!/[k! * (n-k)!]
885437
The last two digits are '25'. \n\n(This is the same for ANY integer power of 5 greater than 1).\n\nThe calculator won't give you the answer since it is not accurate enough.
970878
OOOOOOOOOh i LUV LUVLUVLUV challenge 24!!!! ok her are some ideas:\n7,2,2,1=(7-1)(2+2)\n6,8,2,1=(8/4)(6*1)              ***All taken from Challenge 24 cards\n3,3,6,2=(3+3)(6-2)                     (single digit)\n9,2,5,1=(9-1)(5-2)\n~* ah what the heck i dont have time to finish this. I'llget back to you later, soon. and for future reference, DO buy challenge 24 cardsand so you can use them often. the only annoying thing is, it doesnt come w/anser key u have to figure it out yourself:(
676273
Do Alt + (A number) 14\n(It has to be a number in the numeric pad, remember to have 'Num Lock' on)\nIt gets ♫\n\nTry it with other numbers \n\n1 to 66\n☺☻♥♦♣♠•◘○◙\n♂♀♪♫☼►◄↕‼¶\n§▬↨↑↓→←∟↔▲\n▼ !"#$%&'(\n)*+,-./012\n3456789:;<\n=>?@AB\n\n91 to 99\n[&#92;]^_`abc\n\n121 to 255\nyz{|}~⌂Çüé\nâäàåçêëèïî\nìÄÅÉæÆôöòû\nùÿÖÜ¢£¥₧ƒá\níóúñÑªº¿⌐¬\n½¼¡«»░▒▓│┤\n╡╢╖╕╣║╗╝╜╛\n┐└┴┬├─┼╞╟╚\n╔╩╦╠═╬╧╨╤╥\n╙╘╒╓╫╪┘┌█▄\n▌▐▀αßΓπΣσµ\nτΦΘΩδ∞φε∩≡\n±≥≤⌠⌡÷≈°∙·\n√ⁿ²■
352166
8\ntake away o from top and you're left with o on bottom - half - nothing\nor i guess 10 could work, too (or any double digit ending in 0) take away the first number and you're left with 0
955082
I think you just take the numbers and plug them in where the letters are and find your result.  Ie.  every time you see an a in the question, write -2 instead and then work it out...
909986
the successive differences are -6 , -7 , -8 \n\nso next number is =-25
300260
Alright, I've got two answers using the four basic operations:\n\n(14 - 6) * 3\n\nand\n\n(6/(1-(3/4)))\n\nIf you allow other operations, there are a few more answers (! is the factorial symbol : 4! = 4*3*2*1, 3! = 3*2*1, etc)\n\n4*1*sqrt(36)\n(3*6-14)!\n16*3-4!
16992
Adding 36 and 24 and subtracting 9 can easily be done in your head if you have graduated from elementary school.  Why someone couldn't is beyond me.
166754
Just have a variable called max and min\nfor the first number then enter just set that to max and min\nthen for each additional number\nif num > max then max=num\nif num < min and num <> -99 then min=num
464956
use each number once and only once...\n\n2*3+4*5=26   \n\nThis is too easy.  Give us a hard one!\n...come on...?
622069
Above answer is ok except for not using the -- operator:\nNeed to start at 10 and to decrement i use the statement:\n\ni--;\n\nThis changes the problem somewhat.  Another problem in the first answer is that fact is not initialized, so it will always equal zero resulting in a division by zero error.
571951
Start at 2, and eliminate every second number after that.\nThen start at 3, and eliminate every third number after that.\n4 will already have been eliminated in step 1.\nStart at 5, and eliminate every fifth number after that.\nContinue this way.  The numbers left uneliminated are prime.
596283
add them up like this \n4+2+(-3)+6+5+(-3)+(-2)+0+(-1)+(-4)+3\ndivide the result by 11 because that is how many numbers there are in your list.  That will be your answer!
464745
Can we only use the number once?\n\n9+5+26-26=14\n\n9*5-26-5=14
965314
Not sure why u can't do these yourself but 1) = -360 \n2) -12\n3)-56.8\n4)-45\n5)1328\n6)-144\n7)-.5\n8)25\n9)11\n Those should be right