1if you help me with any of these math problems i will love you forever!!!!! please!!!!!!?
442931
1. 17\nfirst you add 8 to both sides & u'll get 2x=34. Then you divide both sides by 2 & u'll get x=34/2 which is x=17.\n2. 5\nsubtract 5 from both sides (the bars enclosing 20 are the absolute vale bars which means that 20 "loses" the negative sign). u'll get 3x=15. then divide both sides by 3. so, x=15/3 which is 5.\n3. 5\nsubtract 12 from both sides. u'll get 4x=20. then divide both sides by 4. so x=20/4 which is x=5.\n4. -6\nsubtract 16 from both sides. u'll get 8x=-48. then divide both sides by 8 & u'll get x=-48/8 which is -6.\n\nhope this helps (& good luck)
448711
51,336\n\nNext time just type your math problem into at google search and it will do the math for you!\n\nLink below.
202506
I can help, I've taken College Algebra, Calc. I, Calc. II and I've also taken many other math courses, and I'm also studying to be a computer programmer, so if you need help you can contact me at assassin7262002@yahoo.com
323178
What would you like to know?\n\nTry here for whatever it is...\nhttp://www.math.com/homeworkhelp/HotSubjects_decimals.html
343331
What math test do you take?  I'm in Algebra 1 and I only remember 1 question.  It's impossible.\n\nSomeone has a total of 100 coins in dimes and quarters.  The total value adds up to $14.05. How many quarters does she have?\n\nA) 27 (I chose this-it's a dollar off)\nB) 40\nC) 56\nD) 79 (I forget-it's way too high)\n\nWell, that's all I have.  Bye bye!\n\nThanks to the guy who solved that.  I won't get a zero now!
143344
If you need to help I am a tutor in math.  please contact me
856067
1)1,8,27,64,125\n  x^3 = 1^3, 2^3, 3^3, 4^3, 5^3\n\n2)9, 13, 15, 19, 21, 25\n a(n)+ n-2 = {a(n-1) +a(n+1)}/2\n\n3)00001, 00011, 00101, 00111, 01001\n  1,3,5,7,9 in binary\n\n4)17,23,5,18,20,25,21,9,15,16\nok, your teacher is an ass for this one..  heres the breakdown\nq is the 17th letter, w is the 23 letter, e, r, t, y, u, i, o, p\nthe top row of a standard U.S. keyboard. i think i earned 10 points for that one alone\n\n\n5)\nFOUR\nF I V E\nN I N E\n\nR=0\nF=2\nI=3\nN=5\nE=6\nU=7\nV=8\nO=9\n\n2970 + 2386 = 5356\nDONE.  Hope this works for you
520168
Try this:\n\nhttp://www.algebra.com/
970878
OOOOOOOOOh i LUV LUVLUVLUV challenge 24!!!! ok her are some ideas:\n7,2,2,1=(7-1)(2+2)\n6,8,2,1=(8/4)(6*1)              ***All taken from Challenge 24 cards\n3,3,6,2=(3+3)(6-2)                     (single digit)\n9,2,5,1=(9-1)(5-2)\n~* ah what the heck i dont have time to finish this. I'llget back to you later, soon. and for future reference, DO buy challenge 24 cardsand so you can use them often. the only annoying thing is, it doesnt come w/anser key u have to figure it out yourself:(
152888
I'm in Algebra 1 (I go to an online high school). I would be glad to help you if I can.
969084
OMG a math riddle I cant seem to answer!!!! :-)  Awesome. I cant sleep because now i want to knwo the anwer. And so i continue to try and solve it.\n\nBest i can come up with is 113  or 240 or 50-something..\nAlso maybe another number in the 100-n-teens\n\nI did find a 1-3-4 pattern aasuming the next number in 1-3-4-1 was a 3 but was unsure of how to continue it. (its1230 in the moring here)\n\nAnd again another possible patter 1-3-4-8 next number would be 16.\n\nI know some may not even know how I came up with these, but I love math and I love a challenge. I have been trying to find any possible correlation in the numbers that I can. \n\nHope someone figures it out. I know I cant wait to see the answer.
771776
http://mathforum.org/dr.math/\n\nThis is Ask Dr. Math, a website that can offer help for general math through Algebra and beyond. There are other good websites for math out online, type in keywords,  homework  math help and see all that you come up with. Eventually you will find one that can walk you through most problems. Good luck.
886843
(1)\nh = 3\nk = 4\n5 = a(0-3)² + 4\n5 = 9a + 4\n1 = 9a\n(1/9) = a\n\nY = (1/9)(x - 3)² + 4\n\n(3)\nY = (¼)x² + 4x -  7\nY = (¼)(x²+16x) - 7\n\n x² +16x = x² + 16x + (16/2)² - (16/2)²\n     = [x + (16/2)]² - (16/2)\n     = (x + 8)² - 8²\n     = (x + 8)² - 64\n\nY = (¼)[(x + 8)² - 64] - 7\nY = (¼)(x + 8)² - 16 - 7\nY = (¼)(x + 8)² - 23
702610
I'll try to help... \n\nFirst, I'm going to leave out all the x-terms, but just imagine they are there:\n\n.................. ........ ......4/5 56/25 -156/125 -1028/625\n5 ... -4 ... 9 ) 4 ... 8 ... -8 ... 4 ... 1 ... -8\n................... 4 .-16/5 36/5\n...................------------------\n................... ......56/5 -76/5 4\n................... ......56/5 -224/25 504/25\n................... ......-------------- -----------\n................... ............. -156/25 -404/25 1\n................... ............. -156/25 624/125 -1404/125\n................... ............. ------------------- ----------------\n................... ............. ........... -1028/125 1529/125 -8\n................... ............. ........... -1028/125 4112/625 -9252/625\n................... ............. ........... ------------- --------------- --------------\n................... ............. ................. .......... 3553/625 4252/625\n\nIf I did it correctly (which there is no guarantee), I get the answer as:\n\n(4/5)x^3 + (56/25)x^2 - (156/125)x - 1028/625)\nwith a remainder of:\n[ (3553/625)x + 4252/625 ] / (5x^2 -4x+9)\n\nHowever, with all those fractions I probably made a mistake somewhere... your math teacher is a masochist!
806420
Go to their website and you might be able to get the answers. Or if you have the book, they have all of the odd answers in the back of the book.  (Or if you have an older sibling who's really good at math, they can help a lot!)
477961
MEE!!!! times 999,999,999,999,999,999,999
937250
PROBLEM 1:\nBobby is 3 years old.  His sister Nancy is four more than six times as old as Bobby.  How old is Nancy?\n\nPROBLEM 2:\nThe pizza parlor cuts large pizzas into 6 slices and small pizzas into 4 slices.  If Ryan buys 3 large pizzas and a small pizza, how many total slices will he have?\n\nPROBLEM 3:\nThere are 3 hexagons and a square drawn on a piece of paper.  How many total sides are there?\n\nPROBLEM 4:\nWhat is the base-10 equivalent of 34 base-6?\n\nPROBLEM 5:\nAdult tickets are $6 each and child tickets are $4 each.  How much will it cost for a family of 3 adults and 1 child?