What are the four bases? Never figured it out!?
447599
1. fist base : kissing & holding hands\n2. second base : is getting more closer to each other : french kissing, and so on\n3. third base : touching each other getting naked and so on\n4. forth base : making love\n\nHope i helped!
277740
Ok, well you just asked why it equals 1 instead of 1, did you mean why doesn't it = 0?\n\nHere's why:\n\nThe basic rules of exponents when the bases are the same is that in multiplication, you add the exponents and in division, you subtract them.  So think of (x^n)/(x^n).  You would subtract n - n = 0, leaving x^0.  Also, with (x^n)/(x^n), anything divided by itself is one, so x^0 is 1.
497522
1)single\n2)double\n3)triple\n4)HR\n5)error\n6)wild pitch\n7)passed ball\n8)steal home\n9)balk\n\nkinda cheap to count the 4 different types of hits but I couldn't think of any other way to get 9. \n Squeeze play wouldn't work because with 2 outs you'd only need to get the out at first and inning is over and if he makes it to first then it's a single so it's no different.\n Sac Fly?  there are 2 outs though someone else already pointed that out.\n \nWhat about catcher's interference?  Does the man on third get a base or do you have to be forced to move to get to on that type of play?\n\nhmmm...that's all I can think of right now.
878989
Baseball is easier to understand....\n\nIt's the dating cycle. \n1st Base - Who are you? What do you want? Where do you think you're going? Dinner and chit chat. Perhaps a good night kiss if you're lucky.\n\n2nd Base - Getting to know each other more. A night out of dining, dancing, theatre followed by some petting. Perhaps even heavy petty - but that might be going too fast.\n\n3rd Base - More dating followed by heavy petting. \n\nHome Run - Guess.... :)
941657
Nah, sorry, but something in your thinking is incorrect.  You seem to be saying that if you add the square root of 3 four times, you want to get 9.  That's not right.  If you take sqrt(3)^4, you WILL get 9.   Taking the fourth root of a number is not like dividing a pie into four pieces.
762271
Let the base be k.\n\n13 base k  = k + 3.\n38 base k = 3k + 8.\n41 base k = 4k + 1.\n\nNow use the Pythagorean Theorem.\n\n(k+3)^2 + (3k + 8)^2  = (4k + 1)^2\n\nk^2 + 6k + 9 + 9k^2 + 48k + 64 = 16k^2 + 8k + 1\n10k^2 + 54k + 73 = 16k^2 + 8k + 1\n0 = 6k^2 - 46k - 72\n0 = 3k^2 - 23k - 36\n0 = (3k + 4)(k - 9)\n\nk = -4/3, or k = 9.\n\nThe base must be base 9.\n\nLet's check:\n\n13 base 9 = 12 base 10.\n38 base 9 = 35 base 10\n41 base 9 = 37 base 10\n\n\n12^2 = 144, 35^2 = 1225, 37^2 = 1369\n144 + 1225 = 1369.\n\nIt works!
706413
7\n\nUnless you are using base 6 or base 7.  In base 6, 2 plus 5 is 11; in base 7, it is 10.
1085307
It's a trapezoid.  The base is 9 (11-2) and the top is 3 (8-5).  The height is 4 (5-1).\n\nThe area is the average of the bases x the height.\n\nSo that is (9+3)/2 x 4\n\n= 6 x 4\n= 24 sq. units.
676752
Answers:\n\n1) B    Area = 1/2 base times altitude\n\n2) D   s= 3t  So R = 3t + 2t = 5t  \n\n3) D  Add the 4 values together and divide by 4. Make sure \n      you know how to add fractions.\n\n4) C  \n\n5) C  Change 2 and 1/4 to improper fraction 9/4. Then  \n      divide 36 by 9/4. 36/(9/4) = 36x4/9 = 16
233014
U R RIGHTT..HOW DID YA GET IT..PLZ CAN YA EXPLAIN..I'VE BEEN TRYING THIS PROBLEM FROM A LONGTIME.EVEN DE CALCULATOR SAYS ITZ "4"..I KNOW DE CALCULATORS WRONG TOO..PLZZ DO EXPLAIN IT TO ME ASAP
994376
You place all 9 squares. There are 9! ways to place the pieces(without being concerned about each pieces orientation)\nFor each of the 9!, each piece can be rotated into 9 positions. So there are going to be 4^9 possiblities.\n\nOnce you find the correct solution, you can rotate the entire puzzle 90 degrees 4 times.\n\nso the correct number is 9!* 4^9 /4\n9!*4^8\n= 23,781,703,680\n\nNOTE--To the people who are answering 9!*4^9\nWhat would the possible solutions be if there was only one piece?\nWould it be 1!*4^1 =4\nNo, it would be 1/4 of that.\n\nIf there is a similar puzzle of NxN size\nthe solution would be (N^2)! *4^(N^2 -1)
960942
I'll give you some hints, but I won't answer them for you:\n1) The difference between terms (2, 4, 8, ...)\n2) 1, 4, 9, 16... and 1, 8, 27, 64... \n3) 1!, 2!, 3!...\n4) perhaps look at every other term...\n5) n! and n^2\n6) The difference between terms (1, 3, 6, 10, ... , 1+2+3+..+n)\n7) Look at these as base 7 number (12 base 7 = 9, 22 base 7 = 16, etc.)
315179
In soccer, lacrosse, etc.: 4-4-3... 4 indicates the number of forwards. The second 4 indicates the number of midfielders. The 3 indicate the number of defensemen. Because there are ten players (excluding the goalie) 4-4-3, etc., is an incorrect combination. It would have to be: 3-4-3, 4-3-3, etc. Thanks!\n\n____________________________________________________\n\nIn Baseball: 4-4-3, 6-4-3, etc. is the numbers of the positions involved during a double play. The number of each position is as follows.\n\n1- Pitcher\n2- Catcher\n3- 1st Baseman 1B\n4- 2nd Baseman 2B\n5- 3rd Baseman 3B\n6- Shortstop SS\n7- Left Fielder\n8- Center Fielder\n9- Right Fielder\n\nFor example, a 6-4-3 double play would be a ground ball to the SS, SS throws to the 2B as second for the first out, and the 2B throws to the 1B for the second out.\n\nIf the number is something like 6-6-3, it means that the SS fields the ball, touches second base for the first out, and throws the the 1B for the second out.\n\nHopefully this clears things up for you. Glad to be a help!
772626
The number is 41312432.\n\nThe "4" is in the 1st anf fifth space. 4_ _ _ _4_ _\nThe "1" is in the 2nd and 4rth space_1_ 1_ _ _ _\nThe "3" is in the 3rd and 7th space _ _ 3_ _ _3_\nThe "2" is in the 5th and 8th space_ _ _ _ 2 _ _2\n\nDon't know any way to show steps other than the way I did here...\n\nBTW the number 23421314 also satisfies the requirements.
1014906
1234(base 8)\n=1*8^3+2*8^2+3*8^1+4*8^0\n=1*512+2*64+3*8+4*1\n=512+128+24+4\n=668
313541
first base - kissing\nsecond base - above the waist touching\nthird base - below the waist touching\nthere is no fourth base - it is called a homerun and it is intercourse\n\nThis is trivia from the fifties BTW
868968
1. Call the area A, the base b, and the height h.\n\nA = (1/2)bh\n\n2. Call the area A and the height h. The bases are already a and b.\n\nA = (1/2)h(a + b)\n\n3. c^2 + d > e\n\nThese are right.