How to graph absolute value graphs?
442406
Make a table of values.  Then plot the points.  Your graph should be a "V" shape (not a parabola which is U shaped)---whether upright, sideways, or downwards.
821475
graph both the graphs as though they were of equality and not inequality and after wards shade the relevant portion
610991
http://www.cc.ysu.edu/~dmsewell/hwp.cgi\n\nDo the chart.
160190
the second part is graph thy.
686219
1,24 24,1 2,12 12,2 3,8 8,3 4,6 6,4 -1,-24 -24,-1 -2,-12   \n-12,-2 -3,-8 -8,-3 -4,-6 -6,-4 and if x and y don't have to be intergers, there are basicly an infaninte number of possibilitys, such as 1/2,48 1/3,72 1/4,96..... so on, and the negatives. I hope x and y must be intergers, or you're stuck. easiest way is to graph it, or put like y=24/x or x=24/y. Not much help, but it's right.
706415
Push the Y= button.  Add the abs function to the beginning of your expression, and a ) at the end.  Then push Graph or Trace.
971807
(0,0)\n(3,0)\ndraw the graphs and then find them out!\nif u can't, then mail me!
922643
It depends on the graph. If the values of each notch differ by x, then the interval is x.\n\nJust look at two numbers on adjacent notches, and subtract.
794327
A pretty trivial one would be f(x) = absolute value of x and g(x) = -x\n\nf(g(x)) = abs (-x) = x\n\nbut g(f(x)) = - (abs x) = -x
463925
I am not sure that I follow what you are asking. Are you looking for the above items to be charted as variables on your graph?\n\nPerhaps if you post additional details in your question, it would help us.
179915
There will be a vertical asymptote at x=0. When x values get increasingly closer to zero from the right, the graph approaches infinity. When the x values approach 0 from the left, the graph approaches negative infinity.\n\nSimilarly, there is also a horizontal asymptote at y=4. As x approaches infinity, the graph approaches 4 (1/infinity + 4 = 4). Also, as x approaches negative infinity, the graph also approaches 4 (1/negative infinitive + 4 = 4).
72398
I found a nice and simple online grapher at http://www.walterzorn.com/grapher/grapher_e.htm
324857
Found a good diagram here\nhttp://www.laynetworks.com/Block%20diagram%20of%20the%20Pentium.htm
168710
http://www.graphcalc.com/
369137
Check out how you can use the COM Interop for excel so you should be able to use the graphing capability of excel. There are a few third party tools like .net charting\n\nhttp://www.dotnetcharting.com/?aspnetban\n\nits bascially an addon to the .net framework to give the ability to create graphs
332981
Depends:\n\nYou can have as many as needed.  As an example I can have a horizontal axis with time variable in increments of years, a variable T.\nThen I can have 1 or 43 or whatever number of bar graphs coming out of each year as x1, x2, x3, etc. to represent maybe toy sales of x1=# cars, x2=# dolls, x3=# balloons, etc. as different colored bars.\n\nAs for a line graph if it is a single line like the number line it usually will have only one variable represented.
819957
Start with a graph of:\nf(x) = x\n\nThat's a straight line going through the origin with a slope of 1.  It should look like a 45 degree angle if you draw it correctly.\n\nNow to transform this to:\nf(x) = | x |\n\nYou have to think of each value smaller than 0.  Rather than -1, for example, you'll have 1.  Rather than -2, you'll have 2, etc.  This is like "mirroring" the graph that is below the x-axis so that it is above the x-axis.\n\nThis results in a "V" shape.  A slope of -1 down to the origin, then a slope of 1 from the origin.\n\nFinally:\nf(x) = | x | - 2\n\nFor every value that results, you now subtract 2.  For example, x = 0, gives -2, rather than 0.  This is true for every point x, making every point y smaller by 2.  It would look like you shifted the whole graph down 2 units.\n\nSo it would be "V" like before, but it would go down at a slope of -1, cross the x-axis at -2, and continue to (0, -2).  Then it would slope up (m=1) through the x-axis at 2 and continue upward.\n\nYou can go to the first link and type 'abs(x) - 2' in the box.  The resulting graph is shown as the 2nd link.