luminous intensity can be expressed in si as derived unit  consisting of?
446087
It is the energy emitted per unit time; the power. \n\nTherefore, its dimensional formula is Mass x Length^2 / Time^3.\n\nOr ML^2T^(-3).
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E is normally expressed as joules (kilogram-meters per second^2)\n\nSo the mass is in Kg, and the speed of light is in Meters/Sec
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9.109 3826(16) × 10−31 kg (Kilograms)\n1⁄1836.152 672 61(85) amu  (Atomic mass units) \n0.510 998 918(44) MeV/c2 (Mega electonvolts/coloumb squared)
659164
Intensity.\n\nThats the word that describes "how much" light there is, or as you put it, how many light lines there are at a point at the same time.\n\nThe analogous property for materials is density, as you have described for water. true you cannot put 2 tons of water in the same space occupied by 1 ton of water, however if you cool water to 4 degrees celcius or increase pressure, you can hold slighty more than 1 ton in the same space as you are increasing the *density* of water\n\nYou can increase the intensity of light by throwing more light in the same area, either by increasing the number of sources or by increasing the power of the one source, (increase current in that light bulb or throw in more firewood for eg)\n\nIf you thing of light as photons, then intensity is defined as the number of photons striking a surface per unit area per unit time. you can also think of Intensity as brightness, they are directly related.\n\nas you go away from a source the photons spread out and there are fewer photons per unit area: reduced intesity/brightness, infact Intensity falls off as the square of the distance from the source.\n\nIntensity is not limited like density is, as in: in the same amount of space, you can have any intensity you like, there is no limit, just keep adding light sources. however if you try it practically, you will hit a limit, when you are not able to fit anymore light sources into the space, or when you are unable to supply any more energy.\n\nThe standard unit for measuring intensity is candela(cd), which is defines as lumens/steridian, which can roughly be translated as energy per unit volume in a particular direction.
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(I)fundamental units:  those units which are the quantities which are independent of each other. All other quantities may be expressed in these units. It turns out that the number of fundamental units is 7. They are:\n(a)length (metre; m)\n(b)mass (kilogram, kg)\n(c)time (second, s)\n(d)luminous intensity (candela, cd)\n(e)electric intensity (ampere, A)\n(f)amount of substance (mole, mol)\n(g)thermodynamic temperature (Kelvin, K)
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density=__g/ml   that means density equals __grams per millileter
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The equation is just for the angle of a particular wavelength. Not for resolution. Say 250nm,300nm look like 2 lines and not one. \nI think you want to look up diffraction limits. \nSimple experiment is to compare a CD rom and DVD see how they split wavelengths.
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Joules\n\nThis is taken as standard
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1 light year = 9.46x10^15 meters\n1 meter = 39.37 inches\n\nSo set it up as fractions until you get the units you want.  You know you want inches on top, so start with those.\n\n39.37inches/1meter * 9.46x10^15meter/1 light year\n\nThe meters cancel out and you get 3.72x10^17 inches per light year
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In the 76th edition it is Chapter 10 of the CRC - "Line Spectra of the Elements".  You may need to convert the numbers given to the units you desire.
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For blue light'\nd Sin th = 2W        W is wave length\nFor a minimum \nd Sin th = (2n+1)W'/2\nSo,  2W=(2n+1)W'/2\nW'=4W/(2n+1)\n  =1440/(2n+1)\nBy putting various values for n , I find that only for the valu n=1, W' is within the vivible range,\nW'=480 nm
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SI unit for length is 'meter'
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This is an awfully vague question.  I'm guessing that you're asking about how a 3D drawing program calculates the brightness of a given pixel in the final 2D display.  There are really an awful lot of variables to account for in this decision.  There's the distance from the light source, the brightness of that source, the material the light is passing through, the reflectivity of the surface the pixel belongs to, etc.  So there is not really any simple way to calculate intensity.  But the essence of calculating intensity is based on the notion that light intensity decreases according to the square of the distance.  So an object is 1/4 as bright when the distance to the light is doubled.\n\nHope this helps.
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Photosensitive resistors (or Light Intensity / Light Dependant Resistors) vary according to the amount of light that falls on the actual resistor.  \n\nThe included source below expresses resistance as:\nResistance = 500 / (Light Intensity) Kohm\n\nI think this can vary with the particular LDR used though.
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Isn't it 72/(4*pi*r^2) = 0.637 lux\n\noops the answer is 8 it's just 72 cd/3^2 = 8\n\nmy original answer is for 72 lumen
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use the properties of equalities and inequalities.\n(subraction,additon,multiplication,division).
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Depends on the system of units.\n\nIn SI all forms of energy are measured in Joules.\n\nThe Joule is a derived unit not a fundamental one - 1 Joule = 1 kilgramme metre^2/second^2.