How far beyond the planet does Earth's gravitational pull extend?
452926
The theoretical answer is infinity as people have stated.\n\nThe practical answer is that it extends until another body's influence makes earths influence negligible.  Example, jupiter's satellites are not strongly effected by earth in any way.
620070
On earth 9.8N = 1kg, but that is just because the earth's acceleration due to gravity is 9.8m/s².\n\nTo find the gravitational pull of the sun (like 9.8 for the earth) just use the formula g = GM/r², where G is the gravitational constant (6.67x10^-11), M the mass of the sun (1.9891x10^30 kg), r the radius of the sun (6.95x10^8m).
25445
The earth is APPROXIMATELY round due to gravitational forces.
297729
You are correct, but the effects are so insignificant, it doesnt nearly matter.\n\nAll object in the universe have a gravitational attraction to one another.\nTake the Earth and bowling ball example,\nThe Earth exerts a force on the bowling ball, and the bowling ball exerts a force on the Earth.  Both on these forces cause the other object to accelerate towards a common center of mass.  In the case of the Earth's gravitational force on the bowling ball, the force is huge in comparison to the bowling ball's force exerted on the Earth, so much so that we can easily neglect the 2nd force.\n\nLets look at some numbers.....\nIf we say the Earth has a mass of 5.9742 E24 kg and say we will say we have a very heavy bowling ball with a mass of 1000 kg, then we can calculate the gravitaional force between them if we know the distance.  Lets estimate their centers of mass are 6380 (~larger than radius of Earth), we can calculate the gravitational force to be,\nF_g = (G*M*m)/r^2\nF_g = 9789.58 Newtons, which would cause an acceleration of 9.7895 mm/s^2 for the bowling ball and a miniscule 1.63 E-21 m/s^2 for Earth.  To put that in perspective of just how slow acceleration is, if you were to accelerated you car from at a constant acceleration of 1.63 E-21 m/s^2, it would take you about 86500000000000 YEARS to go from 0 to 10 miles per hour!  I think for simplicity sake, Newton did all right.\n\nEDIT:\nYes, the bowling ball very much so does pull on the Earth.  How is the "universe" to know which object is suppose to be the planet and which is the bowling ball?  ALL objects in the universe have a gravititational attraction to ALL other objects.  The Earth pulls in the bowling ball, and the bowling ball pulls on the Earth.  There are 2 equal forces pointed in opposite directions, therefroe momentum is conserved (which is a physical LAW).
195652
the earth is a oblate spheroid....we do not fall to the edges because of the gravitational pull...
396604
dr_islam_safwat is exactly correct, as far as he goes. The problem is that Kepler's 3rd law does not tell you how far Neptune is from the Sun, it only tells you how much farther from the Sun it is than the Earth. The real trick to to find out how far the Earth is from the Sun. Actually, knowing the absolute between any two planets would be enough information, because then Kepler's 3rd law could then be used to find all the other absolute distances from the ratios.
541450
The diameter of the Earth's orbit around the Sun is about 300,000,000 kilometers
312204
"If the earth were a hundredth of an inch closer to the sun, we would burn to death and if it were one hundredth farther from the sun, we would freeze to death"\n\nHA HA HA HA HA HA LOL ROTFL\n\nThat's what you get for reading fairy tale books instead of science books... actually the earth is at 152 million km from the sun at aphelion and 148 million at perihelion (6 million km closer) ... get a clue!!
303004
I've just read that the gravity on the sun is 28 times greater than the Earth.\n\nIt is gravity that keeps satellites and space stations in an orbit around the Earth, at least if that orbit does not intersect the Earth, because then they would crash, and if that orbit isn't too low above the Earth, because then they'd be slowed down by friction with the outermost layers of the atmosphere of the Earth, and then they'd fall down after all. Gravity also keeps the Moon in its orbit around the Earth, and the Earth and the other planets and comets and asteroids in an orbit around the Sun, and the Sun in an orbit around the centre of the Milky Way Galaxy.
250088
Larger planet has a stronger gravitational pull than a smaller planet.
652664
The length of the earth's orbit (orbital circumference) is 924,375,700 kilometres according to wikipedia.
110744
Short answer: usam da inverse square law Jar Jar!\n\nLong answer:\n\nNewton simplified things by picturing all of a planets mass gathered in a single point in the center of the planet and the surface as a point on a certain distance from that center of mass. So the gravitationall pull (F) on a body (m) at a distance (r) from the mass (M) can be calculated using this equation:\n\nF=G*((M*m)/r^2)\n\nwhere G is the gravitational constant (6.67 * 10^-11 Nm^2kg^-2)\nEarths (equatorial) radius is 6.378 * 10^6 meters and its mass is\n5.974 * 10^24 kilogrammes\nSo lets test this on a dude weighing 100 kg:\n\n6.668 * 10^-11*((5.974*10^24 * 100)/4.068*10^13)\n==>\n6.668 * 10^-11*(5.974*10^26 /4.068*10^13)\n==>\n6.67 * 10^-11* 1.424*10^13 \n=\n979 N (what I got in my calculator)\n\nSo earth pulls on a guy, with the mass 100 kg, with the force of 979 Newtons. That means 9.79 N/kg, earths gravitational force (g). This should also mean that a mass dropped from a small height should accelerate at the rate of 9.79 m/s^2. It´s a simple experiment to do but where I am the value of g is actually 9.82. This is because I am closer to the earths center. Earth bulges out at the equator because of its rotation. I am farther north. But still a simple experiment can be done to validate this calculation. \nSo if the earths mass was 3 times greater than g shoud be 3 times greater. Right? You betcha. And I have already shown that moving closer to earths center increases g. Moving twice as far from the center should decrease g by half. Right? Wrong! Now what? We where so close. Oh man...\ng is reduced to a quarter if we increase the radius by 2. This is because of the inverse square law, a very important law in astronomy. It means that the apparent brightness of a light source is inversely proportional to the square of its distance. This also aplies to gravitational fields. Double the distance, divide by 4.\nSo lets put this all together. You should be able to do it yourself by now. I got 734 N or 75 % of the dudes weight on earth. And the reason he doesn´t weigh more than on earth is because of the inverse square law. Eventhough the new world is three times as massive we still moved twice as far away from the center. So take the weight of your astronaut, multiply by 3 and divide by 4.
20069
It depends a lot on how high above the water your eyes are and how tall the distant object is.\n\nThe radius of the Earth at the equator is 6378135 meters.  Assume your eyes are 2 meters above sea-level, and the distant object is at sea-level.\n\nYou have a right triangle, where the longer leg is the radius of the Earth, and the hypotenuse is 6378315 + 2.  The shorter leg is the distance to the horizon.\n\nThe distance to the horizon = √(6378317^2 - 6378315^2) = 5051 meters, or about 3 miles.\n\n\nIf the distant object is 2 meters above sea-level, then it'll disappear when it's another 3 miles past the horizon, or 6 miles from you.
343175
the surface of earth moves at a very high speed. (~ 1674 km/h)\n\n(2 * pi * 6400 km)/ 24 hours\n\nBut the atmosphere surrounding the earth also moves with same speed. So it keeps us dragging the person who jumps and make sure he falls "vertically" at the same place.\n\nIf there is no atmosphere around a planet and if you jump there from helicopter, you can feel the difference.\nOn this planet, if you jump from ground, you will move along with planet because of Newton's first law. (similar to throwing a ball up in a travelling car. the ball will travel along with car)
128964
No it is not equal. As we move upwards that is in altitude the gravitational pull decreases.If we go in more depth the the pull decreses. Moving towards the equator also decreases this pull of gravity. It is least at the poles. But for convenience we take the average of all these which comes out to be 9.8.This is also called the acceleration due to gravity.
122865
The gravitational pull of the earth pulls the waves up and down while the earth is rotating.
223615
if only you could bring planet to standstill then  it would surely hit sun.the movement of planet around sun create a centrifugal force resisting gravitational pull.