how do you get the little dot in degrees?
443083
well in word click on add symbol@!!!
956604
Try it out in the lewis-dot diagram\n      ..        ..\nH-O-Ca-O-H\n      ..        ..
236610
If you mean what temperature on an absolute scale would be 10% of 0 degrees centigrade on that absolute scale, one would convert degrees centigrade to Kelvin by adding 273.15 and take 10% of that, which would be 27.315 Kelvin, or -245.835 degrees centigrade. This is not a naturally occuring temperature anywhere on Earth.\nIf you were referring to the layperson's application of percentage, then you would take 10% of 0 to get 0 degrees centigrade. However, there is no empirical motivation to do this.
956315
The simplest way is to cut it into five slices, each with an arc of 72 degrees (or 2*pi/5 radians). You could probably also figure out a way to cut it into strips so that each strip has equal area, but that would be significantly more complicated.
115436
With a Magnetometer. See below for more detail.
205070
360 degrees = 2 pi radians\nimplies \n180 degrees = pi radians\n180 degrees/pi radians = 1 (Or) pi radians/180 degrees = 1\n\nTo convert radians to degrees multiply the given data in radians with 1 which will not alter its value.\nNext replace 1 with the expression having radians in the denominator and simplify the expression.  \n\n4 radians \n = 4pi radians x 1\n = 4pi radians x (180 degrees/pi radians)\n = 4 x 180 degrees\n = 720 degrees\n\n\nhttp://www.schoolingkids.com/\nhttp://www.futureaccountant.com/
216745
One unit kelvin, or 5/9 degree farenheit
932035
assuming you are using a calculator, turn your calculator to degree mode or if by hand coverting from radians to degrees use this formula:\n180 degrees/pi=1 radian
111333
Begin by subtracting 32 from the Fahrenheit number. \nDivide the answer by 9. \nThen multiply that answer by 5.
960482
about -36 degrees centigrade
1102612
If the antenna is mounted the best way is to use a plumbob and a bubble level gauge. Or just the bubble level gauge with degree increments labeled. another way is to use a compass and a square against the front of the antenna. Hope this helps.
483791
0°C = 32°F\nSo instead of going with 0°C, go with 32°F, so that would be 32 * 2 = 64°F or about 18°C\n\nBut if you are talking about 0°F, which is about -18°C, double that and you get -32°F\n\nSo you either get about 18°C or -32°F
1008143
Use the Dot product as for 2D vectors\nA . B = |A||B|cos(angle)\ncos(angle) = dot product divided by the product of the magnitude of the vectors\nUse inverse cosine to find the angle.\nExample:\nA = 4i + 4j + 2k (i,j, and k are unit vectors in x,y,z respectively)\nB = 2i + 3j + 5k\n\nA.B = (2)(4) + (4)(3) + (2)(5) = 8 + 12 + 10 =20\n|A| = sqrt of (4x4 + 4x4 + 2x2) = sqrt of (36) = 6\n|B| = sqrt of (2x2 + 3x3 + 5x5) = sqrt of (38) =~ 6.16\n\ncos(angle) =  20/(6x6.16) = 20/36.96 = 0.54\nThe angle = arccos(.54) = 57 degrees\n\nThere is plenty of stuff here:\nhttp://mathworld.wolfram.com/topics/VectorAlgebra.html\n\nor start with Wikipedia \nhttp://en.wikipedia.org/wiki/Dot_product
278728
If it is for a science project, web sites may or nmay not have the answers....that is all part of a project, to figure it out for yourself, develop your own theories, hypothesis, etc.\n\nI will say it all depends on the temperature....beyond that you're on your own.
477711
The interior and exterior angle add up to 180 degrees; so far the smallest would be 180 - 110 = 70 degrees.  But since there are 5 angles in a pentagon, we have to first make sure that the unknown angle of the pentagon is not larger than 110 (making it's supplement, the exterior angle, smaller than 70 degrees.\n\nDraw a pentagon on your scratch paper (it doesn't have to be perfect) and pick one of the vertices (the "corners" where the sides meet).  If you draw a line from that vertex to all of the other vertices, you see that you've divided the pentagon into 3 triangles.  Since each triangle has 180 degrees, the whole pentagon has angles that add up to 3 x 180 or 540 degrees.  From the four angles you've been told (85 + 90 + 95 + 110 = 380) you can figure out that the fifth angle has to be 160 degrees (540 - 380 = 160).  So the exterior angle that matches up with that angle is 180 - 160 = 20 degrees and choice B. is correct!
100101
Use a calculator, add all three together (be sure to include the negatives) and then multiply by the number of temperatures.
873172
u can get them with the help of second and higher derivatives.\ninflection point is there where the second derivative is zero.