b*b-8b+20 factor trinomial?
451186
Almost but not quite.
10440
It would be a trinomial because \n\nTrinomial is a polynomial with three terms which are not like terms. The following are all trinomials: x2 + 2x - 3, 3x5 - 8x4 + x3, and a2b + 13x + c.\n\nhttp://www.mathwords.com/t/trinomial.htm\nhttp://mathworld.wolfram.com/Trinomial.html
96233
+5,+12, -5, -12, +3.3
85841
How about this? Straight multiplying gives you the following:\n\n18b^3/b^2\n\nb^3 = bxbxb\nb^2 = bxb\n\nYou have 3 bs on top and 2 on bottom. Whenever you have the same number on top and bottom, it cancels out. Since there are 2 bs on bottom, 2 of the ones on the top cancel out as well. This leaves you with 18b.\n\nDid that help at all?
694817
f-8-3f = 3-7f+4\nf-3f+7f = 8+3+4\n8f-3f = 15\n5f = 15\nf=15/5\nf=3
924187
= 16ab/20ab^2\n= 4/5b // 16 and 20 can be reduced by 4, and an a and a b cancels out\n\n3*3*3*3*3 = 3^5\n3*3 = 3^2\n3^5/3^2 = 3^3\n= 3*3*3
92952
(8x+3)(4x+3)\n32x2+24x+24x+9\n32x2+48x+9
930308
x=[2+/-rt(4+60)]/2\n=[2+/-8]/2\n=-3 or 5\nso the factors are\n(x+3)(x-5)
263576
22+2 = 24\n8+8+8 = 24\n3^3-3 = 24
884233
1. 6(n+2) to expand you consider the expression inside parentheses as a unit and perform the indicated operation--multiplying by 6---to the whole expression, like so: 6xn=6n+6x2=12. The expansion is 6n+12.\n2. 5B+20 To factor means to do the opposite of expanding.Here you need to seek a number which can be divided evenly into both terms---5B and 20---5 works  5B/5=B and 20/5=4.Putting the 5 outside parentheses and the remaining terms inside yields 5(B+4)
854026
Step 1: Calculate the "grouping" number: 10 × 6 = 60\n\nStep 2: Find 2 numbers whose product is 60 and whose sum is 19. Writing 60 = 1 × 60 = 2 × 30 = 3 × 20 = 4 × 15 = 5 × 12 = 6 × 10, we see that 4 + 15 = 19, so the two required numbers are 4 and 15 (or 15 and 4).\n\nStep 3: Write 19 x = 4 x + 15 x\n\nStep 4: Rewrite the whole trinomial, and factor by grouping:\n\n10 x² + 19 x + 6\n= 10 x² + ( 4 x + 15 x ) + 6\n= ( 10 x² + 4 x ) + ( 15 x + 6 )\n= 2 x ( 5 x + 2 ) + 3 ( 5 x + 2 )\n= ( 2 x + 3 ) ( 5 x + 2 )\n\nAlternatively, you can use 19 = 15 + 4:\n\n10 x² + 19 x + 6 \n= 10 x² + 15 x + 4x + 6\n= 5 x ( 2 x + 3 ) + 2 ( x + 3 )\n= ( 5 x + 2 ) ( 2 x + 3 )
284229
First you have to arrange it so the powers of x count down, which they already do.  I think you have to also get the leading coefficient = 1, but I'm not sure - better check on that.  It is a second-degree trinomial b/c there are 3 terms (tri=3, trinomial) and the highest power of x is 2 (2nd degree).
751075
Yes, you've got half the equation right. It should look like this:\nx = n+20
958614
#1.)-----------------------------------\n  \n25b^ -20by + 4y^\n\nMultiply 1st and 3rd term together to get 100b^y^.\n\nFactor 100b^y^ into two factors whose sum = the middle term of -20by.\n\n1by   X 100by\n2by   X 50by\n4by   X 25by\n5by   X 20by\n10by X 10 by   ....................BINGO!\n\n-10by + (-10by) = - 20by   &   (-10by)(-10by) = 100by\n\nThis is a really kewl factor by grouping trick, I LOVE it!\n\nBring down the first term of: (25b^)\n\nNext, write the SMALLER of the two factors 1st.  Followed by the LARGER of the two factors.  In this case, they're both the same, so it doesn't matter which one goes first: (-10by)\n\nFinally, bring down the third term of: (+4y^)\n\n25b^ -10by -10by + 4y^\n\nNow, lets factor by grouping! \nFactor out the GCFs.\nGCF#1 = 5b\nGCF#2 = -2y\n\n(25b^ -10by) + (-10by +4y^)\n5b(5b - 2y) -2y(5b - 2y)\n\nGCF#3 = (5b - 2y)\n\n(5b - 2y)(5b - 2y)\n\nSimplifies further as: (5b - 2y)^   ....Whatdayaknow?! \n.......................................................................................................It's a Perfect Square Trinomial.\n\n#2.)------------------------------------------------------------------\n\n100 - 9b^\n\nAh, the difference of two perfect squares.\n\n---------------------------------------------\n\nFORMULA:\na^ - b^ = (a-b)(a+b)\n\n---------------------------------\n\nSOLUTION:\n100 - 9b^\n(10)^ - (3b)^\n\n-----------------------\n\nANSWER:\n(10-3b)(10+3b)
916165
Sorry, there isn't one.  If you meant "3x + 9" instead of 3x, then x + 3 is a common factor.
515056
I will write them as ordered pairs.\n17: (1,17) and (-1,-17)\n-24: (-1,24), (1,-24), (2,-12), (-2,12), (3,-8), (-3,8), (4,-6), and (-4,6)\nNow try the other two.\nHint: 18 will have 6 factor pairs, and -18 will have 5 factor pairs.
917375
b^2 + 6b -16 = 0\n(b+8)(b-2)=0\nb+8=0\nb=-8\n\nb-2=0\nb=2