How do you solve: (x^2-5x+6)(x^2-5x+5)?
445755
are you simplifying? if so, here's your answer:\n\n(x^2-5x+6)(x^2-5x+5)=\nx^4-5x^3+5x^2-5x^3+25x^2-25x+6x^2-30x+30=\nx^4-10x^3+36x^2-55x+30\n\nwtf cranger, i got it right! what do you mean by CORRECT? check the bottom line
840880
assuming your expression equals 0\nx^2-25-0\n(x+5)(x-5)=0\nx=5 or -5
838051
5(x – 2)^2 = 3\n(x – 2)^2 =3/5\nx -2 =+- sqrt(3/5)\nx=2+- sqrt(3/5)
1053403
Write it as:\n2x^2-4x+3x-6\n=2x[x-2]+3[x-2]\n=[2x+3][x-2]\nSimple middle-term factorisation!!!
1108240
2(x-5)^2 = 3\ndivide by 2:  (x - 5)^2 = 3/2\nsquare root: (x - 5) = +/- root(6)/2\nadd 5: x = 5 +/- root(6)/2
38332
(x-2)/(x^2-2x-15)+(x+2)/(5-x)\n(x-2)/((x+3)(x-5))+(x+2)/(5-x)\n(x-2)/((x+3)(x-5))+(-2-x)(x+3)/(x-5)(x+3)\n\n[(x-2) + (x+3)(-2-x)] / [(x+3)(x-5)]\n\nANSWER :\n(x^2+4x+8)/((x+3)(5-x))
705297
6x -2x -6 =5\n6x -2x = 11\n4x = 11\nx = 11/4
938878
x^2 - 2(3-x^2)\nDistribute the -2\nx^2 + (-2)(3) + (-2)(-x^2)\nSimplify\n= x^2 - 6 + 2x^2\nCombine like terms\n= 3x^2 - 6
695355
-5 -2(x+3) + 7x\n= -5 -2x -6 + 7x\n= -11 -2x + 7x\n= 5x - 11
590600
x^2-36\n=>x^2-6x+6x-36\n=>x(x-6)+6(x-6)\n=>(x-6)(x+6)\n\nThus, x^2-36=(x-6)(x+6)
846617
You would set your two equations equal to each other to solve:\n\ny = 2x-6\ny = x² + 5x + 6\n\nSo, 2x-6 = x² + 5x + 6\n\nSubtract 2x from both sides:\n\n-6 = x² + 3x + 6\n\nAdd 6 to both sides:\n\n0 = x² + 3x + 12\n\nNow you can factor or use quadratic formula to solve for x.  (I don't see any way that this can be factored, unfortunately, so we'll have to use the ol' quadratic formula.)\n\nx = [ -3 ± √ (3*3 - 4*1*12) ] ÷ 2*1 = \n\n[ -3 ± √ (-39) ] ÷ 2\n\nThis equation has complex roots, but no real roots.  Therefore in your real plane these two graphs do not intersect.\n\n.
78222
4x^2 - 11x + 6 \n= 4x^2 - 8x - 3x + 6\n= 4x(x-2) - 3 (x-2)\n= (4x-3) (x-2)
984158
The general approach is to move the x's to one side of the equation and the numbers to the other side, then solve for x. In your example:\n\n5x - 6 = 4x -+ 8\nFirst step: move 4x to left side. Since you can subtract the same amount from both sides of an equation the detailed step looks like this:\n5x - 6 - 4x = 4x + 8 - 4x\nor, in short form,\n5x - 4x - 6 = 8\n\nThen, move the 6 to the other side by adding 6 to both sides:\n5x - 4x - 6 + 6 = 8 + 6\nor, in short form:\n5x - 4x = 8 + 6\n\nThen, reduce both sides of the equation:\nx = 14\n\nHope this helps!
1106533
1) 6(x-4)(x-2)\n= 6(x^2 - 2x - 4x +8)\n= 6(x^2 - 6x + 8)\n= 6x^2 - 36x + 48\n\n2) (x+7)(x+4)-(x+3)(x+2)\n= (x^2 + 4x + 7x + 28) - (x^2 + 2x + 3x + 6)\n= (x^2 + 11x + 28) - (x^2 + 5x + 6)\n= x^2 + 11x + 28 - x^2 - 5x - 6\n= 6x + 22
198322
1. x^+6x-5=0\n\n2. 3x^+10x+8=17x-2\n(x-6)(x+1)\n\n3. x^+3x-40=0\n(x-5)(x+8)\n\n4. x^=10x-24\n(x-6)(x-4)\n\n5. p^+15p+25=6p+5\n(p+5)(p+4)
148627
(-2x^2 +5x-1)-(3x^2-4x-6)\n\nYou distribute the negative to each term in the second expression, then you add the two. - (3x^2-4x-6) negative to the 3x^2 is -3x^2, negative to the -4x is positive 4x, and negative to the -6 is positive 6. so then you have \n(-2x^2+5x-1) + (-3x^2+4x+6). -2x^2 and -3x^2 is -5x^2, 5x and + 4x is (+)9x, and -1 and 6 is 5. so you have \n-5x^2 + 9x + 5.\nI love doing these problems! :)
946842
1.solve by factoring:\nx^2 -5x +x-5 =0\nx(x-5)+1(x-5)=0\n(x+1)(x-5)=0\n=> either x-5=0 => x=5\nor x+1 =0 => x=-1\n\n2. by using qudrt formula:\nfor ax^2+bx+c=0\nx = [-b+-sqrt[b^2 -4ac]]/2a\nhere a=1, b=-4, c=-5\ntherefore x= [4+-sqrt[16+20]]/2\nx=[4+-6]/2\n=>\nx=[4+6]/2=5 and x=[4-6]/2=-1