how many #s on a credit card?
451025
Probably around 50 or so, if you include all that stuff on the back such as the phone number to call for customer service and such.  For just the CC#, it's usually 15-16 digits.
1071317
There are exactly 343 combinations.  I can list them all, but others have already cluttered this thread quite well on their own.  ^.^\n\nYou can think of the solution set as a series of tiered combinations.  These would start with those sets beginning with a $50 bill, which can contain up to 2 x $50,  2 x $20, 5 x $10, etc. which I believe someone has started already in this thread.  Or group them as pairs, triplets, etc. with the equation 50j+20k+10l+5m+1n=100, which may be a bit easier for calculations.  Or a convergent series, where A=(ways to form $5), B=(ways to form $10, including A-sets), etc.  With any method, find the different combinations for each set, then add them all up.\n\nDoing this is still tedious and prone to mistakes, and thus probably not much of an improvement over manually listing all of the combinations one by one.  It can also quickly become an insane exercise for larger values (for example, add the $2 bill, or find change for $200, or even worse).  So instead of trying to think this problem through mathematically, I found it much easier to think it through as a programming problem.  It lends itself very readily to a simple recursive subroutine using the following pseudocode:\n\nmake an empty stack\nset total combinations to 0\ncall CheckCurrency\nprint total combinations found\n\nrecursive subroutine CheckCurrency\n- if total currency in stack = 100\n- - add 1 to the total combinations\n- - (optional: display stack contents)\n- - end recursion\n- if total currency in stack > 100\n- - end recursion\n- if total currency in stack < 100, then\n- - for each valid denomination (50,20,10,5,1)\n- - - if the denomination < = smallest denomination in the stack\n- - - - push it to the stack\n- - - - call CheckCurrency\n- - - - pop it from the stack\nend of subroutine\n\nThis required only a few minutes to design, another few minutes to code, another few minutes to debug, less than 2 seconds to run, and has the wonderful bonus of being able to display every single combination if desired.  It would also be trivial to modify it so that, for example, you can find all combinations if you also include the $2 bill.  (The answer is:  4562 combinations.)  Or to find all combinations totalling $200.  (The answer is: 2930 combinations.)\n\nThe line that checks if the denomination is less than or equal to the smallest denomination currently in the stack is present to avoid a common mistake:  We want the total combinations, not total permutations.  Otherwise, the stack "50 20 20 10" would be counted differently than the stacks "50 20 10 20" and "50 10 20 20", and even "10 20 20 50".  The total permutations is much, much greater, especially if you consider each bill as unique.  Five $20 dollar bills alone have 5!=120 permutations because, after all, they are all completely different $20 bills.  Imagine the number of permutations of 100 x $1 bills, and everything in between.  o.O
1038531
an imeasurable amount of numbers come after 2, regardless whether you are counting up or counting down, if during counting is what you mean.\n\ncounting up eg: 2.00000000000280222\ncounting down eg: 1.92222224025
1110740
I -1 digit\nLOVE - 4 digits\nYOU - 3 digits
692386
There are 9 with one digit, 90 with two digits, 900 with 3 digits, and 1 with 4 digits.  So 9(1) + 90(2) + 900(3) + 1(4) = 2893.\n\nSorry about my earlier answer, my brain was off or something!
1104685
Not many.....just keep enough cash on you to last you a few days, asit shouldn't take long for your real checks to come in.( I hope you told them to start your checks with the number 1000...some stores also have a policy about not taking checks at all with a number of less than 500 or 1000.)
1098310
There are lots of them.  The easy way is to multiply 5 times 6 times 7.  This number is divisible by 5, 6, and 7.  So -- just add two to it.\n\nThis is 212.\n\nYou want another?  How about 2102?  210000000002?\n422? 420002?\n\nI got a million of 'em.
631136
Total 20 nines (2 in 99) are there in 0 to 100.\n\n9, 19, 29, 39, 49, 59, 69, 79, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99
389226
The formula you are talking about looks at the combined balance.  Basically they look at all of your credit limits combined.  You don't want to be using too high of a percentage of this total balance, but I'd say 24% is perfectly fine.  Your limit on individual cards is not really a factor.  Also, having too many credit cards can negatively affect your credit score.  Typically you want to limit your number of credit cards to 2-3.
292290
Before I learned how to repair my credit.......ZERO....now that I have cleaned my credit and did it on my own.......let's just say I have more than I need and I use them all and all are at zero balances. Always pay in full. They aren't getting a red cent of interest off of me. If you must really know......5 visa, 10 mastercard, 1 discover, and 5 american express.
779807
Yiu would first decide how many decimal places you are going to consider.  The usual is 3.  Then work it from there...;
803028
Too many cards will hurt your credit rating.  They look at your available limits (i.e. what you could borrow); if it's too high, the rating is lower.\n\nThey look at payment history.  Just have one or two cards, use them for purchases, and pay them off regularly.  That will build your credit history and resultant credit rating.
1038063
If there was only one digit, there would be 10 (0-9)\nTwo digits, 100 (00-99)\nThree digits, 1000 (000-999)\n\nHey, there might be a pattern here\n\nSo 10 digits, 10,000,000,000 (0000000000-9999999999)
165298
100 - You only have 1 choice for the first digit (7) times 10 choices for the second digit (0 thru 9) times 10 choices for the third digit (0 thru 9). 1 X 10 X 10 = 100. Another way of looking at it is your choices are from 700 thru 799, which is 100 choices.
985465
OOHHH! OHHH!!! I KNOW THE ANSWER TO THIS!!! ok, there is an equation for this, it's    n(n-1)/2.\n\nSo, if there are 100 "techies" then put 100 into the equation.\n\n100(100-1)/2------the equation\n100(99)/2------simplified\n9900/2------- 100*99\n4950-----THE ANSWER!!!\n\nSo, there would be 4950 cards exchanged!\n\nTHIS IS THE ANSWER, I PROMISE YOU!
520658
#24,#99,#16,or #20\nWho knows?
545123
12 to 1  less than 2 .....12 to 5 for number over a 7