what is the ratio if there are 147 males and 263 females in one class?
436703
263 divided by 147= \n1.78911564625850340136054\n(1.79) females per male.
628558
Given the fcat you only described the total number of people in the room. You will have to use varaibles (unless you were already given those numbers).\n\nE=A/25 + B/25 + C/25..... depedning on how many characteristics you would like to seperate\n\nE stands for the greek sigma meaning sum, just put n=25 underneath it.\n\nThis is likley a probability question.
710730
1.Let the no.of boys in the family be x+1\nTherefore,each boy has x brothers(excluding the boy himself)  and x sisters\nSo the number of girls in the family is x\nTherefore each girl has x-1 sisters(excluding herslef,of course) and as assumed x+1 brothers\nBut by the problem,\n(x-1)=(x+1)/2\n+.2x-2=x+1\n2x-x=1+2\n+.x=3\nTherefore there are 3 sosters amd 4 boys in the family and the no. of children is 7.\nso A is correct\n2>Let the no. of children who lost 1 teddybear each be x\nTherefore,the no of children who lost two teddy bears each is 32-x\nAccording to the problem\nx+2(32-x)56\n=>x+64-2x=56 \nor x=8\nTherefore,8 children lost one teddy bear each\nA is correct
968185
First the probability that a family of 4 is all girls is:\n1/16 (and the chance that they are not is 15/16).\n\nRather than figuring the chance of at least one family having this arrangement, figure the probability that *none* of the families do.  Then subtract from 1.\n\nThe answer will be 1 - (15/16)^10\nor about 47.6%\n\nIt's not a simple multiplication by n... if it were, then with 16 families you should have a 100% chance.  And with 32 families you would have a 200% chance.  That logic would be correct if you couldn't repeat a combination, but you can.  Just because family A has four boys, for example, doesn't mean family B can't also have four boys.\n\nLabel the 10 families as A, B, C, D, ... , I, J.  The probability that A has four girls is 1/16.  The probability that B has four girls is 1/16, etc.\n\nThe chance that *none* of them have four girls is 15/16 x 15/16 x 15/16 x ... x 15/16.  This is (15/16)^10 or about 52.4%.  Therefore the chance that at least one of them has four girls is 100 - 52.4 or 47.6%
37197
If 4/15 are male, then 11/15 are female.  11 divided by 15 = .733¯ (repeating)  Multiply that decimal by the total number of members (315) and your answer is 231 females.
388148
All seniors with at least 2 girls means either 2 girls and 2 boy or 3 girls and 1 boy or 4 girls and 0 boys.  There are not 4 senior girls so the last cannot occur.\nC(3,2)C(3,2) = 3*3 = 9\nC(3,3)C(3,1) = 1*3 = 3\n9 + 3 = 12\nThe total possible ways of picking 4 people is\nC(12,4) = 495\n12/495 = .024242\nb)\nmore girls than boys means 3 girls and 1 boy or 4 girls and 0 boys\nC(7,3)(C(5,1) = 35*5 = 175\nC(7,4) = 35\n175+35 = 210\n210/435 = .424242
227352
About two million.\n\n(600,000 males above 18 plus women and children.)
812841
Given 5 children there are 2^5 or 32 possible combinations of girls and boys.  Since there is only one combination with all boys that leaves 31 combinations containing at least 1 girl.  Therefore the probability is 31/32.
725814
This is a very difficult counting problem.  I will show one possible grouping and count the number of ways it can be done.\n\nTo put just 1 boy in group 1, there are 10 ways to pick the boy and "combination of 15 things taken 4 at a time" ways to pick the girls.  This is 10 * (15*14*13*12 / 1*2*3*4) = 10*1365 = 13650 ways to pick 4 girls and 1 boy.\n-----------------\nThere are many grouping scenarios; let us start with 1 boy, 1 boy, 1 boy, 2 boys, 5 boys.\n\nWe know there are 13650 ways to pick a single boy for group 1.\n\nTo then pick a single boy for group 2 from the remaining children, there are 9*(11*10*9*8 / 1*2*3*4) = 9 * 330 = 2970 ways.\n\nIf a single boy is then selected for group 3, there are 8 * (7*6*5*4 / 1*2*3*4) = 8*35 = 280 ways.\n\nGroup 4 must have at least 2 boys.  There are 7 boys left, and we must choose 2 of them.  So there are 7*6/1*2 = 21 ways to choose those boys with the remaining girls.\n\nThe last group would have 5 boys.\n\nSo just for this one possible way of grouping - 1 boy, 1 boy, 1 boy, 2 boys, 5 boys, there are \n13650 * 2970 * 280 * 21 * 1 = 238,378,140,000 ways to arrange them.\n\nTHIS MAY NOT BE THE CORRECT FIGURE FOR THIS GROUPING SCENARIO - THERE MAY BE DUPLICATES, IN WHICH CASE THIS FIGURE IS TOO HIGH.  I did not know how to remove them from the figure.  The 13650 is correct for the first, but then we need to look at how many ways are there to grab 4&1, 4&1, 3&2, 0&5 from the remaining children.\n\n\nWe must also account for other grouping scenarios, such as 2, 2, 2, 2, 2 boys; 1,1,2,2,4 boys; 1,1,1,3,4 boys; 1,2,2,2,3 boys, and some others.  For each of these grouping possibilities, the above such calculations would have to be done.  The sum of all the grouping possibilities is the total.\n\nSo this is a very difficult counting problem.  I would think you should search for more tools from your professor/teacher, or book.  There may be some more advanced way of saving time rather than go through each grouping scenario one at a time; though that will give the correct answer.
889674
No, since the size of the class is the product of the size of each group times the number of groups.
978079
Each match eliminates exactly 1 person. That is, there's a bijection between matches and contestants eliminated. Since there are n-1 contestants eliminated, the total number of matches is just:\n\nM(n) = n - 1
538202
total no: of players = 14\nno: of left handed players = 6,\nno: of right handed players = 14 - 6 = 8\n\ntherefore, ratio of left handed players to right handed players = 6/8 = 3/4 = 0.75
744327
If the probability of haveng either a boy or a girl is equal, then the ration of boys to girls will be 1:1
539255
umm ... i don't think this question is about fairness. sorry girls. it's about math.\n\nAnyways. You have the ratios\n\nM : B : M : G\n\n1/3 : 2/3 : 2/3 : 1/3\n\nSince there's exactly 1 boy and 1 girl, you can add up the Mom ratios to get\n\nM : B : G\n\n1 : 2/3 : 1/3\n\nThis is equivalent to\n\n1/2 : 1/3 : 1/6\n\nSo the Mom gets 1/2, Boy gets 1/3, and the Girl gets 1/6 of the inheritance.
545283
there are two groups of 2 people , so take those 2 people as 1 unit. so there are total 8 units.\nthus number of ways to be arranged is 8! , that is 40320.
1162527
Because you are looking for the number of girls in relationship to the total class, you have to figure out what proportion of the total are girls. Out of every 9 students, 4 are boys and 5 are girls, so 5/9 of the students are girls.\n\nG/45=5/9\n\nSolve for G.
191228
I thought there were more females in the world too, but surprisingly enough, that's actually not true.  As of 2005, there are an estimated 6,446,131,400 people on earth, with a sex ratio of 1.01 male(s) per female, so there are about 63 million more males than females in the world.  (did I do that math right, or should it be 6.3 million more?)