how fast does a bullet travel?
435379
different bullets have different velocities.  What kind of bullet do you want to know about?
158383
You have to shoot it from a far enough distance not to make it go farther than the half meter the bullet would cause it to go.It would also depend on where you hit the tin can. That would have an effect on it's travel.
487788
you're talking .223 here aren't you.  the heavier bullet will retain more energy than a lighter bullet.  imagine getting hit with a ping pong ball, a marble and a ball bearing, each traveling about 100 mph.  the ball bearing will hurt more because it has more energy in its weight.\n\nhowever, the benefits of a lighter bullet is that it will go faster and will drop less at shorter to medium ranges.  the ligher bullets are good for varmint shooting.  the heavier bullets are good for larger animals.
365737
Assuming you fire parallel to the ground, then the bullet will be at its maximum horizontal velocity when it leaves the barrel, and will be at minimum vertical velocity.  The bullet cannot increase in horizontal speed once it has left the barrel, as there is nothing to make it accelerate.\n\nDue to air resistance, the horizontal velocity will decrease as the bullet travels further and further.  The vertical velocity will increase, as the gravity of the Earth "attracts" the bullet.
1114818
The vectorial sum of the two speeds. If the bullet is fired straight foreward, simply add the speeds. If fired straight back, subtract.\n\nThe setup of your question seems to work with ordinary speed bullets and vehicles, so relativistic effects can be ignored along with  friction.
991014
Ballistic Coefficient 1 \nHere, you enter a known velocity for your bullet, and then either a second velocity or a time value followed by the distance travelled by the bullet for that second velocity or time value. Use the combo box to tell the program which value you wish to use. When you click on the calculate button, the other value (velocity or time) will be calculated and displayed. The resultant Ballistic Coefficient will be that coefficient for the drag function selected in the Shooting Parameters window. For example, if G1 is the currently selected drag function, enter 2600 ft./sec. for Velocity 1, 2500 ft./sec. for Velocity 2, leave time blank, Specify 'Use Velocity 2' for Select, and 20 yards for distance. Click on the calculate button and a G1 Ballistic Coefficient of 0.178 will be displayed. You will also see that the time to travel those 20 yards is 0.02353 seconds. The computation also incorporates the weather parameters currently defined in the Shooting Parameters window. The formula for this is as follows: \n\nbc = [Cd(mach)](pi)(rho)(Vavg)(Vavg) / [(8)(a)] \n\nwhere, \n\nbc = ballistic coefficient \nCd = drag function \nmach = mach number (bullet velocity / speed of sound) \nrho = atmospheric density \nVavg = average bullet velocity, (V1 + V2) / 2 \na = constant bullet acceleration over the interval \n\n\nif you know V2 then: \n\ntime = distance / Vavg \n\nif you know time then, \n\nV2 = (2)(distance / time) - V1 \n\nand, \n\na = (v1-V2) / time \n\nNote that the speed of sound as well as atmospheric density is a function of weather parameters. \n\nBallistic Coefficient 2 \nThis calculation computes the ballistic coefficient when the bullet diameter, bullet weight, and form factor are known. Some early ballistics techniques allowed the determination of a form factor from charts where you could match the shape of your bullet to known shapes and extract a form factor for a particular drag function (see Hatcher's Notebook). The formula used here is: \n\nbc= weight / [(form factor)(diameter)(diameter)]
1164981
I think you have left off part of the question. The speed of a ball is a vector. When you hit the ball, the vector points upward and forward. Gravity pulls the vector downward. Small forces (air friction, etc.) retard the total speed, but assume those can be ignored.\n\nAt some point, the pull of gravity will pull the vector to point down instead of up. That's the maximum height. The horizontal component of the speed vector should not change (given our assumptions). It still goes forward at the initial velocity. However, The vertical component is instantaenously at zero. In a moment, the ball will start to accelerate vertically and the vector will continue to pull down below the horizontal line becuase of the force of gravity.\n\nIf this were not true, the ball would reach maximum height and then just drop from the sky (0 overall velocity) which you know it does not do.\n\nSo of your choices, probably equal to initial or ever so slightly les than initial would be the best.\n\nThe same thing happens if you drop, say, a ball from 10 feet and fire a bullet from a height of 10 feet. The both hit the ground at the same time.The fact that the bullet is speeding horizontally doesn't affect gravity pulling on it vertically. (yeah small effects like curvature of the Earth, wind resistance, etc. being ignored).
786520
The muzzle velocity of the paint ball gun is higher. \nhttp://en.wikipedia.org/wiki/Muzzle_velocity
446056
about 138-172 MPH\n\nYou can determine this when you take the reasding of the baseball bat being swung rather than the ball speed. It usually falls in between 138-172MPH
449616
Some Googling says that a 9mm bullet weighs about 8 grams (convenient!) and has a muzzle velocity of about 360 m/s.
462704
Some guy in Australia just invented a gun which fires one million rounds in a minute, or over 15,000 each second (its called Metal Storm and it's nuts).\nTrust me, bullets will be around for a while.
1127089
If time was stopped, and forces like gravity didn't pull the bullet to the ground, it should be sitting there in mid air and you would be able to touch it.\n\nIt would probably be very hot from the friction from the air and firing it.
1166991
Maybe.\n\nBullets travel at a speed that is on the order of magntude with the speed of sound -- about 700 m.p.h. or about 1000 feet per second.\n\nAssuming that you begin to dodge at the sight of the muzzle flash and further assuming that you spot the muzzle flash from a sufficient distance, you can dodge the bullet.\n\nAssuming the bullet was heading straight for your heart when shot, you would need to move approximately 12 inches to dodge the bullet.  Most people can accelerate their torso as about 1 foot per sec ^2.  Distance = 1/2 acceleration x t ^ 2\n\nSolving for time: t = sqrt 2 = 1.4 seconds\n\nSo the bullet would need to fired from about 1400 feet away to enable a successful dodge.\n\nAlternatively, you could dodge a bullet shot from closer range, if you can watch the movement of the shooter trigger finger and judge the firing point on the trigger.
1159509
It is fairly easy to silence a firearm but understand you can truly only silence a bullet that is traveling less than the speed of sound.  Any bullet traveling faster than that has it's own sonic boom which sounds like a crack down range.  That you cannot silence.  Sub-sonic cartridges are designed for slower velocities which will allow for true silencing.  At sea level, I believe the speed of sound to be around 750 miles per hour which translates to ~1100 feet per second.  The rest of the answers are true enough... just like adding a muffler.
757769
Here's how to solve this.\nThe velocity is a vector, and right-angle components of velocity operate independently.\nThe bullet is fired with 2000 ft/s horizontal velocity but zero vertical velocity. So you know the horizontal and vertical components of velocity at the instant the bullet leaves the barrel.\n\nHowever, once it leaves the gun's barrel, the bullet experiences no horizontal forces, but vertically it is acted upon by gravity.\n\nSo: 1) how long does it take for the bullet to fall 5 ft, starting with zero vertical velocity? (hint: s = 1/2 a t^2\n\n2) Once you figure out how long until the bullet hits the ground, then figure out how far the bullet has travelled horizontally during that time, given 2000 m/s initial horizontal velocity and no horizontal forces.\n\nDoes this help?
623745
M1 has muzzle velocity of 2800 ft/sec according pattonhq.com and  2,837 ft/s according to the wikipedia article\n\nM14 rifle has an initial velocity of 2,800 feet per second \naccording to both.\n\nM1903 bullet had an initial velocity of 2,700 feet per second (wikipedia.org)
1102976
a) It will decrease in speed as soon as the accelerative force of the explosive gas ceases to be greater than the drag of the gun barrel or the air or other media it passes through. This could mean that it begins to slow down in the barrel, or soon after leaving it. Certainly, after a few feet from the gun barrel one would expect the gases from the gun to be dissipated and the bullet to begin to be dragged by the air. However, the reduction in speed of a high velocity bullet could be negligible for seconds after firing.\n\nb) As soon as the bullet leaves the barrel it will begin to drop towards the earth. The formula for this is: \ndistance =0.5*acceleration*(time-squared)\n\nAcceleration at sea level is 9.81 metres per second per second. Thus it will take almost exactly 2 seconds for the bullet to drop the 20 metres from your firing platform. (square root of [20/(0.5*9.81)]  )\n\nc) See b above. The bullet is acted upon by gravity at all times. It is only prevented from being accelerated downwards by a force equal or greater to its weight pushing it up. In your example the gun barrel supports it until the bullet leaves the barrel, then begins to fall. Even if you pointed the gun straight up, the bullet will be slowed by gravity as soon as it leaves the barrel and gases behind, gradually slowing to a stop and falling back to land on your head.\n\nIf the bullet had enough horizontal velocity to make it to the horizon within two seconds, it would have acheived the required "escape velocity" to leave or orbit the earth, always falling but never landing. As the horizon at sea level is eight miles away this would need a speed of 28,800 miles per hour or 46,340 kilometers per hour. \n\nThe speed of sound is c.1,220 km/hour, so this would be 38 times the speed of sound!\nThe muzzle velocity of most military calibres is c.700metres/second or 2, 520 km/h or twice the speed of sound.\n\nThus in the two seconds it takes the bullet to fall to earth it would have carried some 1,400 metres.\n\nd) Very much so!