The mass spectrum of a pure sample of a noble gas has peaks at the ffg m/z values.?
438665
Its not pure...there is not a noble gas that would give a m/z at 10 or 11.\na molecule with bond angles of 90 would be SF6\n\nIf you have collected this mass spec it could also be a result from background interference.  Subtract you background and see what happens.
312552
A two-color three-photon ionization technique, using two pulsed dye lasers, was employed to explore the high-lying energy levels of U I. A number of new U I levels in the 34 290--35 120-cm/sup -1/ region was observed.^Uncertainty in the assignment of J values to some levels known from earlier studies was also reduced or removed.\n\nHUH? Is that what you want?\n\nEDIT\nAbstract. Two-colour resonance ionization spectroscopy was used for identification of 240 new levels of 238U in the energy range of 38 500 to 41 200 cm-1. A precision of +or-0.03 cm-1 (1 SD) for the energies was obtained by using laser-induced fluorescence signals of I2 for spectral calibration. The angular momentum quantum number, J, was uniquely assigned for 134 of these levels by using angular momentum selection rules. \n\nThats a little more specific\nAnd some more\n\nAbstract. Visible and infrared absorption measurements on the  ion in tetragonal zircon-type matrix  are reported and analysed in terms of the standard parametrization scheme. The observed 17 main peaks and a number of less intense lines have been assigned and fitted to most of the 32 allowed electric dipole transitions with the root mean square error equal to . The free-ion parameters obtained for the model Hamiltonian, , ,  and , as well as the corresponding crystal-field parameters, , , ,  and , agree fairly well with the initial theoretical estimations. The results are discussed in relation to the previous spectroscopic study on the scheelite-type matrix .
734854
I'm going to cheat a little bit in both cases by just referring back to the nearest noble gas.  That itself may be acceptable for your purposes (it's how most chemists list them because things past that point are usually of no interest)... if you need, I'll pass on the underlying noble gas configuations too.\n\n13:  [Ne] 3s2 3p1\n33:  [Ar] 4s2 3d10 4p3\n\nBasically, the electrons usually fill up the shells just as you see the elements arranged on the periodic table.  Group 1 and 2 (the two columns on the left) are the s shell, and the number of the s shell is indicated by the row number.  Group 13 through 18 (the six columns on the right) are the p shell; its number is also the same as the row number.  The middle stretch are d orbitals, and they're so expensive energetically that the ones on each row are orbitals from one shell down.  That chart is handy for all kinds of things!\n\nHope that helps!
844942
Phase - gas \nDensity  (0 °C, 101.325 kPa)\n9.73 g/L \nMelting point  202 K\n(-71 °C, -96 °F) \nBoiling point 211.3 K\n(-61.7 °C, -79.1 °F) \nCritical point 377 K, 6.28 MPa \nHeat of fusion 3.247 kJ·mol−1 \nHeat of vaporization 18.10 kJ·mol−1 \nHeat capacity (25 °C) 20.786 J·mol−1·K−1 \nVapor pressure P/Pa 1 10 100 1 k 10 k 100 k \nat T/K 110 121 134 152 176 211 \n \nAtomic properties \nCrystal structure cubic face centered \nOxidation states 0 \nElectronegativity no data (Pauling scale) \nIonization energies 1st: 1037 kJ/mol \nAtomic radius (calc.) 120 pm \nCovalent radius 145 pm \nMiscellaneous \nMagnetic ordering non-magnetic \nThermal conductivity (300 K) 3.61 mW·m−1·K−1 \nCAS registry number 10043-92-2 \nSelected isotopes \nIsotopes of radon iso NA half-life DM DE (MeV) DP \n211Rn syn 14.6 h Epsilon 2.892 211At \nAlpha 5.965 207Po \n222Rn 100% 3.824 d Alpha 5.590 218Po \n \n\n\nthis is what wikipedia had to say. hope it helps!
956102
Here is the equation\n\n(246,92)U ---> (4,2)He + (242,90)Th + 2Gamma
948794
protons is the atomic number\nvalence electrons corresponds to this:\nGroup 1 (I) (alkali metals) :1\nGroup 2 (II) (alkaline earth metals) :2\nGroups 3-12 (transition metals) :1 or 2\nGroup 13 (III) (boron group) :3\nGroup 14 (IV) (carbon group) :4\nGroup 15 (V) (nitrogen group) :5\nGroup 17 (VII) (halogens) :7\nGroup 18 (VIII or 0) (noble gases) :8\n\n\nEvery element in the top row (the first period) has one orbital for its electrons. All of the elements in the second row (the second period) have two orbitals for their electrons. It goes down the periodic table like that. At this time, the maximum number of electron orbitals or electron shells for any element is seven.
538049
Yes.  In fact protons even from two different elements are indistinguishable.  This is a fundamental property that is quite interesting, and it results in some very odd behavior.
906779
the ans should be C...because..if a gas that diffuses faster than KR...means tat the gas has a smaller molar mass than Kr...since is diffuse faster than 2.29 times..therefore the molar mass will be 83.8 / 2.29 = 36.6\n\n\n83.8 is Mr of Kr
430403
i presume you have the energy values for the different levels?\n\nif so you use the equation E=hc/lamda to find the wavelength for each energy transition in the series.\n\nThe red line will be about 575nm and the purple line will be about 375nm.
722015
it is a noble gas, but just because something isnt solid doesnt meanits a nonmetal. metals all become gasses at high temperature. the metals are on the left side of the periodic tabl and the non metals arre on the right. xenon is all the way on the right so its a non metal.\n\nhttp://en.wikipedia.org/wiki/Periodic_table#Standard_periodic_table
758277
the amount of electrons in an atom.\n\nif you're going to use noble gas configuration, you would use the noble gas and then continue the configurations.\n\nex. i want the configuration of... flourine (F)\nfor noble gas configuration i would say: (He) 2s 2 2p 6\n\nthe parenthasese is actually a bracket, and the numbers that are spaced should be in the upper righthand corner of the letter before it.
512153
The mean van der Waals diameter of water has been reported as identical with that of isoelectronic neon (2.82 Å) [112]. Molecular model values and intermediate peak radial distribution data indicates however that it is somewhat greater (~3.2Å). The molecule is clearly not spherical, however, with about a ±5% variation in van der Waals diameter dependent on the axis chosen; approximately tetrahedrally placed slight indentations being apparent opposite the (putative) electron pairs.
842499
First of all, look on your periodic table.  Somewhere there should be a listing for atomic mass.  Usually it's either at the very bottom of the square for that element or in a separate table.  That is how much that atom weighs in amu, or atomic mass units.  A molecule weighs as much as all the atoms in it put together.\n\nA guy named Avogadro came up with a number called Avogadro's number (modest character, wasn't he?) or a mole.  A mole is 6.023 * 10^23.  There are exactly one mole of amus in a gram.  Atoms are commonly measured in moles in the lab as well, since the actual number of atoms is usually way too high to work with conveniently.\n\nSo to answer your question, the number of atoms in a sample is (6.023 * 10^23 * the number of grams)/the atomic mass.  The number of molecules is (6.023 * 10^23 * the number of grams)/the sum of the atomic masses of the component atoms (also called the molecular mass).  But most of the time, amounts are reported in moles, and the number of moles is simply the number of grams/the atomic or molecular mass.\n\nI hope that made sense to you.
546865
First, it seems to have only 2 isotopes.  \n\nYou need to take each mass and multiply by its percentage.  Then add the two resulting numbers together.  You then have the weighted average mass for the element, or average atomic mass.  This weighted average atomic mass is the one reported on the periodic table of elements.\n\n35 x 40%\n+\n37 x 60%
81728
Diatomic, but not all diatomic gases are Halogens
62704
Atomic Mass: 58.9332 Amu
788892
OF2 (~104), NF3(~107), CF4 (~109.5),  BF3 (120), BeF2(~180)