what is the inverse of  y=2x-3?
446101
switch the y and x\n\nx = 2y - 3\n\nThen solve for y\n\nx + 3 = 2y\n\n(x+3)/2 = y\n\nnow you have the inverse.
1169467
y = x^2 + 5x - 3\n2y=3x - 2\n----------------\n2y = 2x^2 + 10x - 6\n2y = 3x - 2\n-----------------------\n    0 = 2x^2 + 7x - 4\n=>2x^2 + 7x - 4 =0\n=>2x^2 + 8x - x - 4 = 0\n=>2x(x + 4) -1(x+4) = 0\n=> (2x - 1)(x + 4) = 0\ntherefore 2x - 1 = 0 => x = 1/2 or \nx + 4 = 0 or x = -4\nx = - 4 or 1/2  \ngot it?
758594
2. The equation is (y-y1)/(y1-y2)=(x-x1)/(x1-x2)\n=>(y+2)(-2-0)=(x+1)(-1-0)\n=>(y+2)(-2)=(x+1)(-1)\n=>-y-2=-2x-2\n=>-y+2x=0=> 2x-y=0 which is the required equn.\n3.The equation is (y-4)(4+4)=(x-0)/(0-4)\n=>y-4/8 =x/-4\n=>8x=-4y+16  or,8x+4y-16=0  o4 2x+y-4=0 is the reqd.equation\n4.the eqn. is (y+3)/(-3-3)= (x+2)/(-2-0)\n=>(y+3)/-6=(x+2)/-2\n=>-6x-12=-2y-6\n=>-8x+2y-6=0 or,-4x+y-4=0 which is the equired equation
677039
(1) { -2x-y-z=0\n(2) { -x-2y-z=0\n(3) { -x-y-2z=0\n\nLet's look at (2):\n-x-2y-z=0 => x=-2y-z\nNow at (3):\n-x-y-2z=0 => x=-y-2z\nNow we can see that\n-2y-z=-y-2z => *** y=z ***\n\nNow let's put these values into (1):\n-2x-y-z=0 => -2x-y-y=0 => -2x-2y=0 => 2x=-2y => *** x=-y ***\n\nFor now, we know that x=-y=-z\nLet's put all of what we know into (2), and express everything using 'x':\n-x-2y-z=0 => -x-(-2x)-(-x)=0 => -x+2x+x=0 => 2x=0 => *** x=0 ***\n\nThus, x=0 => y=-0=0 => z=0\nSo the only solution is (0,0,0).\n\nGood luck!
164756
Easy!\n\n2x+2y=2 \n3x-y=1\n\nTake the second equation and isolate the single "y":\n\n3x - y = 1 becomes 3x - 1 = y (without going into how)\n\nSubstitute "3x - 1" in the first equation so it reads:\n\n2x+2(3x - 1)=2\n\nSimplify:\n\n2x + 6x - 2 = 2\n8x - 2 = 2\n8x = 4\nx = 1/2\n\nEarlier, we saw that y = 3x - 1, so:\n\ny = 3(1/2) - 1\ny = 3/2 - 1\ny = 1/2\n\nThere may be another way (less involved) that I've forgotten, but you can check each of those values for x and y in both equations to make sure they work.
272177
multiply both sides by 3 and you'll get\n3x-3*4=-2*(y-9)\n\n3x-12=-2y+18\n-2y+18=3x-12\n-2y=3x-12-18\n-2y=3x-30  divide both sides by -2\n\ny = (-3/2)x + 15
207006
you can generalize further --> y = -2x
201836
inverse of 1/2 = 2/1 = 2\n\nunless you have X^(1/2) = sqrt(X)
745743
For the first problem, subtract 2/3x on both sides:\n6y=-2/3x+1\n\nDivide 6 on both sides:\ny=-2/18x+1/6\ny=-1/9x+1/6\nSlope:-1/9\n\nFor the other problem, the inverse of -1/3 is 3:\n-1/(-1/3)\n-1*-3=3
809908
2(y-3) = y-6\n\nThis is what you are supposed to calculate : a value for the y, such that the equation holds.\n\nfor instance try y = 1\n\n2(1-3) = 1-6\n2 - 6 = 1- 6\nand you see that this is not so, thus y=1 is not a solution.\n\nthe standard way to solve is : move all y''s to the left of the=, and all numbers to the right of the =\n\n2(y-3) = y - 6\n2y - 6 = y - 6\n2y -y - 6 = -6 ( move left y to the right, sign changes )\n2y - y = -6 + 6 moved left -6 to right, change sign\n\ny = 0. ( adding the 2y - y together, and the -6 + 6\n\nso the solution is y = o
699742
-(3x+y)(3x-y)\n-(9x^2-y^2)\ny^2-9x^2
146086
2x+y=6 => y=6-2x \n3x+y=1 => 3x+(6-2x)=1 => x+6=1 => x=-5\ny=6-(2*-5) => y=16\n\nx=-5\ny=16
813582
the inverse function is\n\nh =  [3(R-1)]/2\n\ntake the original function, switch the placement of the (h) and the (R) and solve for (h). \n\nat 6'0'', Reach = 7'6''\nat 6'6'', Reach = 8'3''
870259
You can do it by hand or with a calculator. Either way, it would look like this:\n\n2x + y = 3 \n(move the 2x to the right side of the equation, so only y is on the left side)\ny = 3 - 2x\n\nNow put 1, 2, 3, etc. in for x, and see what y equals:\n\nwhen x=1, y=1\nwhen x=2, y=(-1)\nwhen x=3, y=(-3)\nand so on.....\n\nNow put these values into a table:\n\nx --- y\n1 --- 1\n2 --- (-1)\n3 --- (-3)
232592
2x = 3y - 4y + 5 - 2\n2x = -y + 3\n2x + y = 3
417188
y=Asin(2x)+Bcos(2x)+(x/4)\n\nNow you get to determine why.
932187
y = 3/2 (-4) -2 = -12/2 - 2 = -6 -2 =  -8\n\n(x,y) = (4,-8)