can anyone help me?why is 1=0?
436555
1=0 when reference to derivatives in calculus or when in reference to places numbers are from 0 - 9 \nthen they are repeated. etc 1_0 1_1 1_2 .. you get the idea. \n Any way first place is  = 0
936579
your question seems to be incomplete.\nso far....\nwidth=x\nlength= 2x-1
391334
2&#92;2=-2&#92;2\n1=-1\ntherefore the answer is -1.
404608
that is incomplete because you are missing one parenthesis. But x=0 is a correct answer.
332996
Zero - is it positive or negative?
797453
you set the bottom of the equation equal to 0. So x^2 - x = 0, which leads to two cases. The first one is x = 0. The second one is x-1 = 0, or x = 1.
797702
Since there is no = sign in that equation, I assumne it should be equal to zero.  If that is the case then m= -1/8
197379
x is anything less than 1.\n4 x1=4 so 1 cannot be the answer (unless the < had a line underneath it)\n4x0=0 which is less than 4\n4x -2= -8
134065
Your statement translates to the following algebraic equation.\na+b=a-b=a*b\nSolving a+b=a-b, we get b = 0; \nSubstituting b=0 and solving a+b=a*b, we get a = 0;\nSo the two numbers are zeroes.
622612
Joel, you need some help.  This is one of the easiest questions I have ever heard!  You should know this, man!  You're gonna fail your test if you keep cheating on here and don't actually figure out how it works.  Good luck, brotha'\n\nL = -2 or L(x) = -2
1056055
1) You should try making a flow-chart to see the issues here...\n\n2) Your comparison:  if %1==%1 (and also for %2) will ALWAYS BE TRUE and will never get to parts of your code!
230249
you just add the inputs, and the result (the least significant digit) is the answer you need:\n\n0+0+0=0\n0+1+0=1+0+0=0+0+1=1\n1+1+0=0+1+1=1+0+1=10 ->0\n1+1+1=11 ->1\n\nIf you like to solve it by boolean 1+digit adding, then,\nlet you entries be a,b,c\nr1=a.not(b)+b.not(a)\nr=r1.not(c)+c.not(r1)\nwhere . means and
604013
there is no answer becuase it is impossible to divide by 0
501645
I too failed math but to me this is a logic question:\n0+0=0\nWhat else cloud it be?
168972
Your question does not make sense. x cannot be less than or equal to 0 and less than or equal to 7 unless it is less than or equal to 0, which I do not think you mean. \n\nI think you mean 0<=x<=7\n\nThe rest of the question makes no sense. \n\nAnd it really smells like a homework problem. Try thinking for a change.
882621
My old math teacher showed me this.\n\nSince A=B, then A-B=0, and you can't divide by 0
930650
cos(0) = 1. so you can plug in x = 0 to get the limit as 0*1 = 0