What is the olmpyics pool size?
444850
The dimensions of an Olympic pool are required to be 25 metres by 50 metres.\n\nAccording to the rules of FINA.org, an Olympic pool should be 50 m long by 8 times 2.5 meter lanes with 2.5m outside lanes 1 and 8 (so 10*2.5 = 25m) - minimum depth 2m.
687791
If the data is fed directly to a NetworkStream, it is impossible to determine its size. So you need hte CyrptoSteam to do so...\n\nThe solution is using the MemoryStream object. By feeding the output of the CryptoStream to a MemoryStream instead of directly to the NetworkStream, you can determine the encrypted data length of the message, and then easily move the data into a byte array for sending out the NetworkStream.\n\nThe MemoryStream object is linked to the CryptoStream, placing the output of the encrypted data directly into the MemoryStream. The MemoryStream can then be converted to a byte array using the GetBytes() method, and the length of the encrypted data is determined using the Length property of the MemoryStream (which must be typecast to an int).
365033
Pool tables come in 4 sizes  6, 7, 8, and 9 feet... professionals use 9 foot tables ... like on espn2
735064
That sounds familiar... Think I'm working on it now! But I don't remember q. It is n in my book. In which case, q (if I'm thinking right) is the number of samples. Then again what's up with the ^'s? If np was > 10, then it meant that the distribution was approx. normal. You might be ahead of me right now...
502903
4.0\n1600\n\ngood luck, mate.
23547
78.75\n\ntimes .035 x 750 x 3
327092
www.poolandspa.com\n\nGood Resource
966473
1024 x 1024 though it is industry standard to round to 1 million
830280
377387664 Bytes = 0.351469650864601 GigaBytes\n\nCheck this link to calculate further:\nhttp://www.matisse.net/bitcalc/?input_amount=377387664&input_units=bytes&notation=legacy
500588
A regulation size pool table is 4 1/2 x 9 feet.
888646
around 24 sq inches, if its a 4x6 card
432318
You should include version for all these sizes:\n640 x 480\n800 x 600\n1024 x 768\n1152 x 864\n\nSee Digital Blasphemy for and example:\nhttp://www.digitalblasphemy.com
116087
keeping with the same unit fractor harry is correct.\n \n .2 ml
358814
width of pool = 32\nwidth of fence therefore = 32 + 7 + 7 = 46\nlength of pool = 18\nlength of fence therefore = 18 + 7 + 7 = 32\n\nperimeter = 2(width) + 2(length)\np = 2(46) + 2(32)\np = 92 + 64\np = 156\n\n156 feet of fencing is needed.
942173
64 meg is the way to go... try tiger direct. X
499636
Look here:\nhttp://www.posc.org/Specifications/Epicentre_V30/DataModel/LogicalDictionary/StandardValues/projected_2d_coordinate_system.html\n\n\nhttp://www.ldeo.columbia.edu/res/pi/MB-System/html/mbmosaic.html
380874
Or 7:3 if the number of coins