What type of reaction is the rections between zinc and HCl to produce H2 gas? What is the balanced equation?
454861
Zn + 2HCl---> zncl2 + H2\nIt is a displacement reaction. Zinc is more reactive then Hydrogen and is capable of displacing it from Hydrogen Chloride.
810526
when metal react with acid, you will get hydrogen and salt...\nfor example, Zink (Zn) react with hydrochloric acid (HCl):\nZn + 2HCl --> ZnCl2 + H2\n\ni'm sorry i cant give you ALL possible ways in getting H2...\nbut this acid-metal reaction should be easy and cheap enough...
889082
If the white powder is sodium carbonate, when you react it with HCl, you will get carbon dioxide gas given off as one of the products of the reaction.. this gas is odorless.\n\nIf the white powder is Zinc Sulphide, when you react it with HCl, you will get sulphur dioxide gas given off as one of the products of the reaction, this gas smells like rotten eggs and is toxic.\n\nAs for the Zinc Gold mixture, you can use different methods of extraction.. both have different melting points.. you can melt the metal with the lower melting point and pour it off, or you can add a strong acid such as Sulphuric Acid to react with the mixture... Pure Gold will not react to the mixture,  all the Zinc will  react (in presence of enough acid) and become a salt that is soluble in water... then you just filter the gold out from the solution
733447
Br+H20--->HBr+O\n\nNi(II)O+H20--->Ni+H202\n\nKO2+H2O--->KOH + H2\n\nHope that helps.
326922
Another easy reaction:\n\nMg(s) + HNO3 ===========> Mg(NO3)2 + H2 (g)\n\nMagnesium reacts rapidly with nitric acid to make magnesium nitrate and hydrogen gas
148175
The correct balanced equation is:\n2ZnS + 3O2 --> 2ZnO + 2SO2\nThis is BALANCED\nMr chemistry teacher, you didnt balance your equation,...and i'm in the ninth grade
962694
Tehe answer is:\nAg + HNO3 -> AgNO3 + H\nAgNO3 + KBr -> AgBr + KNO3
223710
Start by balancing Al, then Cl. Al is already  balanced, so when you balance Cl everything is easy from their. \nYou final amswer will be:\n3HCl + Al(OH)3 ----> 3H2O + AlCl3
19390
Zinc hydroxide - ZnOH2.
161405
The elements Hydrogen (H+) and Chlorine (Cl-) to make HCl (aka hydrochloric acid)
119628
So, usually the best way to do these is to just fiddle with them until you get them right, but for the sake of it, let's go with a systematic approach using algebra.  First we assign a variable in front of each of the terms on the left and right like:\n\nx Pb  +  y H2O  +  z O2  -->  a Pb(OH)2\n\nSo now we'll write down equations to make sure that we have the same numbers of both sides of each *element*.  I'll do this by writing down the variable in front of each compound in your equation (so x, y z and a) and then multiplying those by the number of times an element exists in that compound.  (So when I'm writing the equation for hydrogen, the H20 term will be 2*y, because y is the coefficient in front of H20 and H occurs twice in that compound).\n\nRemember, the number of any element on the reactants (left) side equals the number of that element on the products (right) side.\n\nFor Pb: x = a, because Pb shows up only once on each side with a subscript of 1, those two compounds will have to be present in the same molar amounts.\n\nFor Hydrogen: 2y = 2a\n\nFor Oxygen: y + 2*z = 2 * a\n\nSo now we have three equations:\n\nx = y\ny = a\ny + 2z = 2a\n\nBut four unknowns, which is fine because we'll just solve for them in terms of one of the variables and then simply choose the last variable to make all the numbers nice.  So solving the equations in terms of a:\n\nx = a\ny = a\nz = (2a - y)/2 = (2a - a)/2 = a/2\n\nSo now we have x, y and z in terms of a free parameter, a.  We'll just choose a = 2, for example, to make x, y and z all turn out as integers.  So now we've chosen:\n\nx = 2\ny = 2\nz = 1\na = 2\n\nSo the balanced equation is:\n\n2 Pb + 2 H2O + O2 --> 2 Pb(OH)2\n\nMake sense?
407430
n of Zn~ 2,5/65,4= 0,038 mole\nso, number of moles of H 0.076 (1 mol H20 has 2 mols H)\nPV=nRT\n1*V=0.076*22.4\nV = 1.70 L
802803
The answer is:\n2Al(HCO3)3  -------> Al2(CO3)3  +  3CO2  +  3H20\n\nThe equation is now fully balanced as you have\n2 moles of Al on each side\n6 moles of H on each side\n6 moles of C on each side\n18 moles of O on each side\n\nHope that helps!
837250
The equation doesn't balance.  There's no hydrogen on the right side.  But, assuming that you ended up with H2 gas on the right (I don't think that reaction works real-world, but whatever), the main thing you need to look at is the chlorine.  It's Cl2 on one side and Cl3 on the other.  That means that you must have a total number of chlorine atoms which is a multiple of 6.  Try balancing the equation with 6 chlorine atoms and see what you get:\n3CuCl2 + 3H2O + 2Al -----> 2AlCl3 + 3 CuO + 3H2
250762
2 HCl + CaCO3 ----> CaCl2 + H2O + CO2
461008
Li + H2O = LiOH + H2 + Heat\n\nThis is an exothermic reaction to raise the temperature of system so high that H2 reacts with atmospheric oxygen to give water with the reaction\n\n2H2 + O2 = 2H2O\nThe formation of water vapors is a side reaction of the above reaction.\n\nLi is alkali metal and all alkali metals react in the same pattern.
605005
NaHCO3(s) + CH3COOH(aq) → CH3COONa(aq) + CO2(g) + H2O(l) \nThis is the real chemical reaction.