Can anyone help me with this math question ?????
451162
"The answer if four" -Rodney Dangerfield in "Back to School"
971574
This is a proportioal problem\n\nMultiply the means\n\nmultiply the extremes\n\n- - - - - - -\n\nx = the amount of men\n\n4 / 7 = x / 28\n\nthe means = 7x\n\nThe extremes = 4 x 28\n\n- - - - - - - - - - - - - - -\n\n7x = 4 x 28\n\n7x = 112\n\n7x / 7 = 112 / 7\n\nx = 16\n\nThe answer there are 16 men\n\n- - - - - - s-
352026
I would like to be able to give you the answer but I don't think I would be doing you a favour.  If you are to get practice in division, it is better for you to work it out on your own.  Does your teacher know that you are getting homework answers here on Yahoo?
467967
this is probably not a perfect answer but this site may give you some clues.\n\nhttp://www.gomath.com/Questions/question.php?question=4751\n\naltrnatively type 'prove v*v = 2gr*r/s+v0*v0-2gr' into a search engine and see what comes up.
958757
So lets start with the first one. Make a division problem with 9.0 on the outside and 0.9 on the inside. 9.0 does not go into 0 but does go into nine. Raise the decimal and the answer is ten. It's a bit difficult to explain but here's your answers and when you go in next time ask your teacher for help::\n1. 10 \n2. 8\n3. 4.7\n4. 3.2\nOkay theres a few for you and you should be able to figure out the rest. For the next part you take what x is equal to and divide it by 1.2. So for\n13. 40.8/1.2=34\nAnd do the same for the rest!!\nGood luck!
437783
1) 1, 2, 3 and 6\n2) 1, 2, 2m\n3) 1\n4) 1, 3\n\n5) 5/9 (55/99) > (45/99) 5/11\n6) 2/3 (8/12) < (9/12) 3/4\n7) 4/5 (32/40) < (35/40) 7/8\n8) 1/3 (4/12) = (4/12) 4/12
917052
16/24....it's really not that hard...you should be able to solve it on your own.\nps. you might want to simplify it down to 2/3.
448711
51,336\n\nNext time just type your math problem into at google search and it will do the math for you!\n\nLink below.
947480
Do your own homework . \n\nI'll help you anyway since you probably haven't done your homework in ages.\n\n\n1.3\n2.$234,896\n3.$625\n4.$2.00\n5.$10.00
347406
Dude, so simple.\n\nYou need to find a # that is the lowest multiple of both 3 and 2.\n\nSo 1/2 + 1/3 changes to X/6 + X/6\n\nTo find out the top # you do the same thing that you did w/ the bottom #\n\n1 x 3   1 x 2     3     2      5\n----- + -----  = --- + ---  = ---\n2 x 3   3 x 2     6     6      6\n\nHay, if I help som 1 cheet, than I show them how to the problem, ok?\n\nJackmac :P~
880981
Sorry, but your question is written very poorly.  You might want to try looking at how some of the other math questions are written out, then rewriting your questions so that it makes more sense.
714589
x/(x+3) - 2(x-1)/(x+3)(x+2)\n\nx(x+2) - 2 (x-1)\n--------------------\n   (x+3) (x+2)\n\n\nx^2 +2\n----------\n(x+3)(x+2)
913268
Snow, i am sorry but i have no idea! i have some suggestions for helpful websites, though\n\ntry mathforum.org/dr.math/\n\nsorry i could not be more help ful!!! good luck
691205
is this a mathematical question
53373
Here are a few sites you can check out:\nhttp://www.freemathhelp.com/\nhttp://www.mathgoodies.com/\n\nHope these sites can help you..
1076304
(1) 1.3\n(4) 4\n(5) Right\n(6) 0\n(7) 0\n(8)0\n(9)12
903397
You might try asking this question under "Mathematics."