how do you determine the dimensions of a cylinder if you have the volume.  We know pixr2xh = volume, wont work
448895
Volume, V = 2πrh...\n\nSince there is only one equation, but two unknowns...\n\nyou must supply the value of one unknown (you must decide on a pre-determined value. You either decide the value for the radius of the cylinder or its height) to solve for the other dimension.
566632
once you have the dimensions for the aquarium.\nyou'll want to find the volume of it.\n\nVolume = length x width x heigth\n\nconvert the volume into ounces (can be done using any website that does conversions)\n\nAnd divide that by 8...and you have your answer
315840
Surface Area of a Cylinder = 2 pi r 2 + 2 pi r h\n\n(h is the height of the cylinder, r is the radius of the top) \n\nSurface Area = Areas of top and bottom +Area of the side \n\nSurface Area = 2(Area of top) + (perimeter of top)* height \n\nSurface Area = 2(pi r 2) + (2 pi r)* h \n\nIn words, the easiest way is to think of a can. The surface area is the areas of all the parts needed to cover the can. That's the top, the bottom, and the paper label that wraps around the middle. \n\nYou can find the area of the top (or the bottom). That's the formula for area of a circle (pi r2). Since there is both a top and a bottom, that gets multiplied by two. \n\nThe side is like the label of the can. If you peel it off and lay it flat it will be a rectangle. The area of a rectangle is the product of the two sides. One side is the height of the can, the other side is the perimeter of the circle, since the label wraps once around the can. So the area of the rectangle is (2 pi r)* h. \n\nAdd those two parts together and you have the formula for the surface area of a cylinder. \n\nSurface Area = 2(pi r 2) + (2 pi r)* h
361907
If the tank is a cylinder, the Volume is πr²h.  If you get the volume in cubic feet, multiply by 7.5 to get gallons.
765627
C=2(Pi)r or diameter times Pi\nI don't know how to solve the problem cause not enough info is given. Does it say what C equals?\n\nv = lwh . H stands for the height. Does it say what v equals?\n\na= 1/2h(b1+b2) b1 is base 1. Does it say waht the area is?\n\nProvide more info please. :)
289591
Volume = area x height\n\n3 inches = 0.25 foot\n\nArea = Pi x d'2 /4 = 3.1416 x 0.25 x 0.25 / 4\nArea = 0.0049\n\nVolume = Area x height\nVolume = 0.0049 x 10 = 0.4908 cubic feet\n \n1 cubic feet = 7.48 gallons  \n\nVolume in gallons = 0.4908 x 7.48 = 3.67 gallons
969061
The only thing you need to figure that out is the height of the (i presume) circular cup. Just estimate it as a cylinder, or use some simple calculus to add a sloped cup.\n\nAnyways, the volume of a cylinder is pi*r^2 * h. or A * h  where A is the surface of the water.\n\nThe next problem is converting fl. oz to a volume in terms of distance measurements. I find this easiest to do in metric units, although if you spend some time you can figure it out in oz.\n\nso 1 US fluid ounce = 29.5735297 ml\n\n1 ml = 1 cubic cm.\n\nthus\n\n16 US fluid ounces = 473.176475 ml = 473.18 cubic centimeters.\n\n473.18 = A * h.\n\nSimply put in the height in centimeters and you've got the area.\n\nI don't know of any statistics about the average car cup holder dimensions although if you take a guess and imagine the one in your car, i'm sure it'll be close.
864957
diameter is 70 means radius=35\nlenth=130\nso if it is the volume4 u want\n\nitssimply 2*3.14*35*130\n\nif not so question is in complete
529872
Easy H*D*W    H=Height D=Depth W=Width *= times\n\nUse the units cubed, if it is meters use m^3 as the unit of measurement
594911
Radius of the cylinder = 225 mm / 2 = 112.5 mm\n\nThe length is given in metres, so work in metres \n112.5 mm = 0.1125 m \n\nCross sectional area of cylinder = pi * r^2 = 0.03976078... sq m\n\nVolume = length * cross sectional area \n= 1 m * 0.03976078 sq m = 0.03976078 cu m\n1 cu m = 1000 litres\ntherefore volume = 39.8 litres to 3 s f
1142473
The volume of a cylinder equals the (area of the base)*height = π r2h
425258
volume = height X width x depth\nv = h x w x d\nv= 11 x 16 x 24\nv= 4224 inches^3 ( inches cubed )
651714
Homework?\nOK, only a hint. Consider a cylinder made of the circle and with a height dh. What is the volume of this cylinder? \n\nNow displace the cylinder along the path over dh, etc.
522898
Imagine you unraveled the cylinder, the middle would turn into a rectangle, right? so to find the surface area, take the height of the cylinder and multiply it by the circumference of the circles at the bases, then add in the area of the circles. Circumference is 2(pi)r and area is (pi)r^2.
475972
The volume of a cylinder is given by\n\nV = pi*r^2*h\n\nAnd the surface area of a cylinder is given by\n\nSA = 2*pi*r^2 + 2*pi*r*h\n= 2*pi*r(r + h)\n\nNow, we don't have enough information to specifically find either the radii or heights - we only have a volume.  But we can still work with that based on the fact that the cylinders are similar.\n\nIf the cylinders are similar, their measurements are proportional.  In other words, the radii are proportional and the heights are proportional (r1/r2 = h1/h2 and r1/h1 = r2/h2).  So let's just assume that the larger cylinder has a radius of 3 and a height of 3 (plug in to the volume formula and it works out to 27*pi cm^3, but for the sake of this argument, we'll ignore the pi for now).  For the smaller cylinder to be similar, it would have to have a radius of 2 and a height of 2 (again ignoring pi).\n\nThe surface area of the larger cylinder is then\n\nSA = 2*pi*r(r + h)\n= 2*pi*3(3 + 3)\n= 36*pi\n\nAnd the smaller one would have a surface area of\nSA = 2*pi*r(r + h)\n= 2*pi*2(2 + 2)\n= 16*pi\n\nSo your ratio would then be 36*pi / 16*pi = 9/4.  (If we went back and corrected out radii and heights for pi, they would have all cancelled out by this step.)\n\nNow, what if my initial assumption was wrong and the radii and heights weren't 2 and 3?  Well, we can still work with that, but we'd end up with the same ratio of 9/4.  If the smaller cylinder had a height of 4, then the radius would have to be sqrt(2) for the volume to work out to be 8.  So the ratio of radius to height would be sqrt(2)/4.  Because the two cylinders are similar, this ratio must hold for the larger one.\n\n(Crazy math warning!)\nSo r/h = sqrt(2)/4, so r = h*sqrt(2)/4.  We can find the radius and height of the larger cylinder now:\n\nV = pi*r^2*h\n27 = pi*(h*sqrt(2)/4)^2*h\n27 = pi*(h^2/8)*h\n27 = (pi*h^3)/8\n216 = pi*h^3   <-  we'll drop the pi at this point - same reason as before\n216 = h^3\nh = 6\n\nr = h*sqrt(2)/4\n= 6*sqrt(2)/4\n= 3*sqrt(2)/2\n\nNow let's compare surface areas of the two:\n\nSA(big) = 2*pi*r(r + h)\n= 2*pi*(3*sqrt(2)/2)(3*sqrt(2)/2 + 6)\n= (3*pi*sqrt(2))(3*sqrt(2)/2 + 6)\n= 9*pi + 18*pi*sqrt(2)\n= 9*pi(1 + 2sqrt(2))\n\nSA(small) = 2*pi*r(r + h)\n= 2*pi*(sqrt(2))(sqrt(2) + 4)\n= 4*pi + 8*pi*sqrt(2)\n= 4*pi(1 + 2sqrt(2))\n\nAnd if you took this ratio of big to small, you have 9*pi(1+2sqrt(2)) / 4*pi(1+2sqrt(2)) = 9/4!\n\nSo my original assumption is right, and the ratio turns out to be 9/4 for these two cylinders.\n\nNow I used cylinders for this (I have no idea why), but it turns out that it works for any solid.  There's a relationship among these measurements - if we compare cubes:\n\nRatio of a side = s1/s2\nRatio of area = (s1)^2/(s2)^2\nRatio of volume = (s1)^3/(s2)^3\n\nSo for our case, the ratio of the area can be found by taking the cube root of the ratio of volumes, and then squaring it - 9/4.
875857
find what?...the dimensions of the box with the most volume?\n\nArea = w^2 + 4wh = 1100 cm^2\nh = (1100 - w^2 ) / 4w\n\nVolume = h w^2 =\nV = w^2 * (1100 - w^2 ) / 4w \nV = w (1100 - w^2 ) / 4\nV = 275w - (w^3)/4\ndV/dw = 275 - (3/4)w^2\nlet dV/dw = 0\n(3/4)w^2 = 275\n\nw = 19.15 cm\nh = 9.57 cm
969797
Let the radius of the sphere be R.\nLet x be the radius of the cylinder.\nThen height of half of the cylinder= sqrt(R^2-x^2)\n\nTotal surface area of cylinder = 2*pi*x^2 +2*pi*h, so\nS=2*pi*x^2 +2*pi*2*(R^2-x^2)^.5  [Eq I]\ndS/dx=4*pi*x + 4*pi*.5*(-2x)(R^2-x^2)^-.5\n=4*pi*x - 4*pi*x/(R^2-x^2)^.5\n=4*pi*x(R^2-x^2)-4*pi*x =0\nR^2-x^2-1=0\nx^2=R^2-1\nx=+ or - sqrt (R2-1)\nPlug these values of x into [EQ I] to get answer.