find the domain rational expression 3x^2-2x+1 over x^2+3?
445923
The domain of a polynomial function is all reals.\n\nThe domain of a rational function is limited by the domains of its numerator and denominator, and the denominator cannot equal 0. \n\nSince this is a rational function of polynomial functions, the domain could only be restricted by having the denominator being equal to 0. But the range of the denominator is y >= 3. Since there is no value of of x that can make the denominator equal to 0, the domain of the entire function is all reals.
572493
=x(x^3-2)\n--> x=0 or x=2^(1/3) or -2^(1/3)
926616
2x+3<6x-1\n2x-6x<-1-3 \n-4x<-4\nx>1
968502
Domain\n(-∞, ∞)\n\nRange\n[-3, ∞)
761571
1.(4x+1)(16x^2-4x+1)\n\n2.(1-5x)(1+5x+25x^2)\n\n3.(2xy^2+3)(4x^2y^4-6xy^2+9)\n\n4.b^3(a^3-b^3)\nb^3(a-b)(a^2+ab+b^2)\n\n5.(3x-2y)(9x^2+6xy+4y^2)
123892
3(x – 2)^2 – 3(x – 2) – 6\n3((x-2)^2 - (x-2) -2)\n3(x^2-4x+4-x+2-2)\n3(x^2-5x+4)\n\n3(x-4)(x-1)\n\nYay!!
562954
You simply divide each term in the polynomial by that integer.. For your example here it goes..\n\n(3x^2+8x-2) divided by 2 \n\n> {3(x^2)/2} + {8x/2} - {2/2}\n\n>> Answer: 1.5 x^2 + 4x -1    or   (3/2)x^2 + 4x -1
971390
{3XY^2M/1}-{2M/[X^-1Y^-1]^2\n+{[4X^2Y^2]/M^-1}-\n(3X^(3Y)^(3M)^-1/(XYM)^-2
110508
(x^2+5) / (x^3+15-2x^2+1)^2\non [0,1]
896553
4x^2+8x-x-2\n(4x-1)(x+2)
919554
Factor out 3.\n3(x^2+2x+1)=0\n3(x+1)^2=0\nThe only answer then is x=-1 to make the expression equal 0.
617827
3x^3y^2z^4\n\nbecause you divide the exponents by 4, but do the fourth root of the coefficient 81
780298
first u distribute the - to the stuff in the parenthesis so you have\n7x^2-3+x^2\nthen combine like terms\n8x^2-3
157955
9*9\n=(3^2)(3^2)\n=3^(2+2)\n=3^(4)\n=3*3*3*3\n=(3*3)*(3*3)\n=(9)(9)\n=1(9*9)\n=1(9+9+9+9+9+9+9+9+9)\n=1(18+18+18+18+9)\n=1(36+36+9)\n=1(72+9)\n=1(81)\n=1*81\n=81\nFINALLY, I GOT IT!\nThe answer to this complex rational algebraic problem is 81\n\nDuh!  ;-p
693529
3x^2 - 192\n3(x^2 - 64)\n3 (x+8) (x-8)
652975
(x+4)/[(3x-1)(3x+1)]-\n(x-2)/(3x+1)=\n\n[(x+4)-(3x-1)(x-2)]/\n[(3x-1)(3x+1)]=\n\n[x+4-3x^2+6x+x-2]/\n[9x^2-1]=\n\n[-3x^2+8x+2]/[9x^2-1]
554172
Um...\n\n2(-X) + 3(-X) + X + 8\n\n-2X - 3X + X + 8\n\n-5X + X + 8\n\n-4X + 8\n\n8 - 4X