How do you do these two math problems? What's the difference? Please write everything out! (the process)?
436598
Remember that a factorial is basically the product of that number, that number - 1, all the way down to 1.\n\n1. (n-1)(n-2)(n-3)(n-4)(n-5)...1\n---------------------------------\n(n-4)(n-5)...1\n\nCancel the (n-4) and everything after.\n\nANSWER : (n-1)(n-2)(n-3)\n\n2. (n+6)(n+5)(n+4)(n+3)...1\n---------------------------\n(n+3)(n+2)...1\n\nCancel the (n+3) and everything after\n\nANSWER : (n+6)(n+5)(n+4)\n\nEDIT : Lattisrectum, keep in mind that (n-4)! is (n-4)(n-5)(n-6)... all the way to 1, not (n-4)(n-3)... :)
381290
I have an iterative method that is good for at least 80% of these types of problems.\n\nFirst, write down the series.\n\nNext, above the line you just wrote, write the difference between each pair of elements. In this case, it will be 1, 2, 4, 8, .... In this case, the answer is obvious - they are powers of two. The next one in the differences line should be 16, so the next on the original line should be 15+16=31. This will allow you to get any member in the sequence.\n\nIf the first order of differences doesn't give rise to a discernable pattern, try the differences of differences and so on.
813994
the first one is (x+10)(x+8)\nand the second one is your second answer
30751
The Edifier has it right, but darned if I can follow the notation. You really need to see this written out like a textbook to understand what's going on.\n\nClick the link below in "sources" to see the answer hosted at my website www.calculus-help.com. Right now, Yahoo! answers, as far as I can tell, doesn't allow graphics, which makes it tricky to answer ANY math questions.\n\nPlease don't post math answers, guys, if the poster knows the answer but can't get there, and you get something completely different.
236405
its easy to do the math.\n\n10*10*10*10 for the first one so 10000\n\n\n10*10*10*10*10 for the second one which is 100000\n\ndiffrent posibilities
286401
Oh, come on. I answered your first one, and now you flood the board with your homework? Are you really that lazy to think it's easier to post your homework here? These problems are all the same, with different numbers. Do it yourself, I already showed you how.
400083
The first one does 1/40 of the job per minute.\nThe second one does 1/x of the job per minute.\n\nThe first one worked for 10 minutes.\nThe second one worked for 10+50 = 60 minutes.\n\nOne job was completed.\n\nThat is all you need to know to solve for x.\n\nHere is your equation:\n10/40 + 10/x + 50/x = 1\n\nSolve for x as follows:\n10/40 + (10/x + 50/x) = 1\n10/40 + 60/x = 1\n60/x = 1 - 10/40\n60/x = 3/4\n60(4) = 3x\n240 = 3x\nx = 80\n\nIt would take printer2 80 minutes to do it alone.\n\nSanity check- plug your answer into the original equation:\nDoes 10/40 + 10/80 + 50/80 = 1?\nHmmm, looks like 10/40 = 20/80\nso (20 + 10 + 50)/80 = 1?\nYes.  So your answer is right.
1135375
Write two fractions on the board , column A  and  B.\n\nWhich is greater A or B or are they equal.   Choose teams.Keep score.\n\nYou(as the teacher) can easily tell the answer quickly:  \nA .......... C\n--- vs---- -----\nB ...........D\n\nIf AxD is greater the correct answer is A\nifBxC is greater the correct answer is B
748308
Need to say what you are doing with the problem: solving for x, solving for y, other?\ny=(3/2)x+(7/4)
954300
ok\nso its factoring.this is hella easy.10x+40 is 10(x+4)\nso the answer is 10(x+4)there you go
954500
1) you need to know what product and sum means. sum is addition and product is multiplication. Difference is subtraction.\n(10*6)-(7+8)\n\n2). Square has 4 equal sides. If the perimeter is 36 divide that by 4 and there is your answer.\n\n3). You need to know the hundreths place. tenths (.1) hundreths (.01)\n\n4). 1/4? that is 25%\n\n5). standard form is written like 1.000X10^x
151115
Would you please type your entire math question the way it is presented in your book? Your description is not enough for anyone to answer you correctly. Thanks!
625162
Try dictionary.com, m-w.com, or one of the thousand other good dictionary websites on the web, as for problems, try search on http://mathforum.org/
85581
P = (  )\nE =  *\nM =  times\nD =  /\nA =  +\nS =  -\n\nPlease Exuse My Dear Aunt Sally\n\nDo these steps in order, if the problem doesn't have one of them just skip over it.\nI hoped I helped.
919968
I hate my son's middle school homework, too.  It's not like the problems I had in my day.  The answer to this kind of question is something like I wrote below.  \n\nThought:  Looks like a subtraction problem.\nInfo:  Start time and duration.\nPlan: Write a math sentence or equation.\nSolution: Answer
189233
The problem with this type of algebra problem is that it's hard to know the syntax (grammar) of the problem if it's just written out in words. For example, is it 2x - 9, all over x, or is x the denominator only for 9? It's confusing!So in the future, to make it clear, use brackets like this:\n\n****IF I am reading your problem CORRECTLY****, I would write it as:\n(((2x-(9/x))^2)-4) - (((x-(7/x))^2)-4) = ?\n\nBut put aside the whole brackets thing for a minute. \n\nNow, normally, it helps to break down the math probelem into parts, but it looks like you're learning to do exponents. If this is the case, you must have learned that exponents allow you to work certain problems quicker without having to break down the problem into small parts and solving them seperately. To remember what those exponent rules are, try both the links at the bottom of this post. You'll use exponent rules all through your life, so know them!
616629
First of all, change this:\n\n<p>Enter first numerator: <input type=text name=num1 size=20></p>\n<p>Enter first numerator: <input type=text name=num2 size=20></p>\n<p>Enter second denomenator: <input type=text name=num1 size=20></p>\n<p>Enter second denomenator: <input type=text name=num2 size=20></p>\n\n\nto this:\n\n<p>Enter first numerator: <input type=text name=num1 size=20></p>\n<p>Enter first denomenator: <input type=text name=num2 size=20></p>\n<p>Enter second numerator: <input type=text name=num3 size=20></p>\n<p>Enter second denomenator: <input type=text name=num4 size=20></p>\n\nThen based on the operation selected, implement the proper logic there (its basic math) and then your program will work.\n\nGood luck!!