The slope of a line paralell to AB, A(-4,2) and B(4,2)?
442472
If the line is parallel then it must have an equal slope. Therefore the parallel line would also have a slope of 0.
953083
let your given point be P(a,b,c...) and your slope be a direction given by a vector V(v,w,x,....).  I'm assuming you want a vector equation of a line?  You can get to any point on the line by starting at P and moving some distance m (maybe negative) in the direction V.  So any point R(r,s,t,...) on the line is given by\n\nR = P + mV, where m is some real number.\n\nFor example, in 2 dimensions, the line y = (2/3)x + 1 has a y-intercept at (0,1).  Let that be P.  The slope 2/3 is the vector (3,2).  The point (2, 7/3) is on the line, and the equation\n\n(2, 7/3) = (0,1) + m(3,2) works when m = 2/3.  m/√13 is the distance you go along the line from P to R.
427569
Substitute into the standard slope intercept equation. (y = mX+b)\n\n-4=(3/5)2+b\n-4=(6/5)+b\nb=-4/(6/5) \nb=-10/3\n\nThe equation is y = (3/5)x - (10/3)
811970
ok so parallel lines mean they have the same slopes so u know \n-13=(y-15)/(4-3)\n  remember slope is rise/run or the change in y / change in x\n\nso -13 =y-15  y=-13+15 or   y=2
312375
M is the slope which you get by subtracting y coordinates and x coordinates IN THE SAME ORDER, and then dividing.  In your first example, change in y is 6-4 = 2, change in x is 0.5-0 = 0.5.  Then divide change in y by change in x, 2 by 0.5, to get M = 4.  \n\nThen pick one of the points, say the second.  y - 4 = 4(x - 0).  Then do just a little algebra.\ny - 4 = 4(x - 0)\ny = 4x + 4.\n\nSome special cases.  Your 2nd pair have the same x coordinate, so the line is vertical, and the equation is x = 6.  In your 3rd pair the y coordinates are the same so the line is horizontal, y = 2.\n\nSince the slope is a fraction, change in y over change in x, you need to be able to do fraction arithmetic.
787261
Let the 2 points be (x1,y1)  and  (x2,y2)\n\neqn of line s given by\n\n(y-y1)/(y2-y1) = (x-x1)/(x2-x1)\n\nwhere  (y2-y1)/(x2-x1) is the slope of line
892240
Slope is Y2 -Y1 divided by X2 - X1\n\nIn your example, Y2= 12\n                            Y2= -7\n                             X2= 0\n                            X1=-2\nSo... \n(12-(-7)) / (0-(-2))= 19 / 2 = 9.5\n\nThe slope of the line is 9.5
759458
parallel means the slopes will be the same, so our new line can me found using the point-slope formula:\n\ny - y1 = m(x - x1)\ny - (-4) = (1/2)(x - 2)\ny + 4 = (1/2)x - 1\ny = (1/2)x - 5
881416
Slope intercept form:  y=mx+b where m= the slope and b= the y-intercept.\n\ny=2x-4
885688
slope m=(y1-y2)/(x1-x2)\n          m=(1--1)/(3-3)\n          m=2/0    which gives us a singularity,\nthat is, a vertical line.
856807
Yes that will be correct because after you isolate the (y) in other words put it in slope inercect form it would be \ny=2x+4 \nm=2\nb=4
814480
The slope-intercept form of a line is\ny = mx + b, where m is the slope and b is the y-intercept.
910261
Slope = m\n= y2-y1&#92;x2-x1 \n= -4-6/-3-2\n = -10&#92;-5\n=2\n\nnote: / means divided by\n\nthe slope of y= 2&#92;3x-4 is 2&#92;3
903948
find the slopes of both lines and if there answers are opposite recipricals, then they are parrallel\n\nheres adn ex:\nslope = 2 and -1/2\n\nin other workds, if you multiply the two slopes, u should get -1
695994
The eqaution of the line is\ny-y1 =m(x-x1)\ny-0 = -3[x-(-4)]\ny-0 = -3(x+4)\ny= -3x-12
975217
Line AC = 6, line BC= 2x+2, line AB=x+1\nSo 2x + 2 = 6\n2x = 4\nx = 2 <-- option C
826422
Find the slope of the line that connects those points.