explain each situation...discuss all forces that apply?
451552
without wheels ,frition becomes a greater factor,downforce and down hill force are still always there
230448
dipole-dipole\nhydrogen bonds\nlondon forces\n\nde nada
1119730
ahh, good theory problem...\nlet's see, there's energy, friction, force (normal, tension, as well as the other ones mentioned), gravitation, mass, pendulum motion, gotta be more that I've missed, but no doubt someone'll be here to correct me.
171054
why is the reason.\nwhat is the action.
680834
A force is a push or pull upon an object resulting from the object's interaction with another object.\n\nThe formula is F=ma, where F= force, m=mass, a=acceleration
193077
Force=Mass x Acceleration\n\nSo Acceleration = Force/Mass\n\nHope this helps
800064
For these problems, it would be helpful to draw a free-body diagram to represent all the forces on this problem.  Here you have 4:\n\n1) Weight in the vertical direction going down, let's denote it W\n2) Force, moving in the x-direction, denote it F_1\n3) frictional force, moving opposite of Force, denote it F_2\n4) Normal force, perpendicular place of contact (opposite direction of W), denote it N\n\nNow use Newton's 2nd law to write equations in each direction:\n\ny-direction: \nN - W =0 (because the block does not move in the y-direction).  Therefore:\n\nN = W, where W = m*g\n\nx-direction:\nF_1 - F_2 = 0 [because the block is just about to move when F_1 is applied].  Therefore:\n\nF_1 = F_2, where F_2 = u*N\n\nMaking the necessary substitutions for F_1 and N, you get:\n\n30 = u*(4.4)(9.8).  Solving for u, you get --------->\n\nu = 0.7\n\n--------\n\nHope this helps
710706
Gravity, friction and centrifigul.  Don't forget various applications of force = leverage, pulleys.
813186
a counterbalancing force or system of forces.
225230
there are only 2\n\n1 is that you have to apply a force, and 2 is that something has to happen ie. movement
83052
Forces occur in pairs. Newtons third law.\nIf this is the case the forces exist as equal and opposite.\n [Fo ]=[-Fi]\nNet force = Fo minus Fi= zero!\n  Moving forces can be directional and vectorial.\nAlso they change continueously during the motion till they Atenuate at the end of their cycle.To identify the force you have to identify the power that has cause the motion of the mass and the direction of interaction. The power causing the motion is always equal to the magnetude of the force multiplied by the the speed that the force moves.\n\nCurvilenear motion indicates that the power of two moving masses interact and cause the two masses to move around a common pivot point. Thus the masses are locked together into an orbit forming a composite mass structure.In that case the moving masses experience a curved path.\nThan you have to understand what is  a circle. A circle consists of an infinite integral of short straight lines, and each straight line having different direction.\n\nDont feel bad if you cant fully understand why. . I dont find it easy myself.
1002012
http://www.answers.com/gravitational+force?gwp=11&ver=1.1.2.381&method=3\nhttp://en.wikipedia.org/wiki/Gravitational_force\nhttp://scienceworld.wolfram.com/physics/GravitationalForce.html\nhttp://dept.physics.upenn.edu/courses/gladney/mathphys/subsection4_1_4.html\nhttp://en.wikipedia.org/wiki/Gravity\nhttp://www.explorelearning.com/index.cfm?method=cResource.dspView&ResourceID=411\nhttp://theory.uwinnipeg.ca/physics/circ/node7.html\nhttp://dept.physics.upenn.edu/courses/gladney/mathphys/java/sect5/subsection5_1_1.html\nhttp://www.physics.teleactivities.net/forces/gravity.html\n\nhope this helps\nplz give me 10 pts
833368
find the force of her weight. \nthat should be the answer
710050
You have to ad the forces and show the resulting force. The equilibrium force will have the same magnitude and opposite direction (neutralizing all 5 forces)\n\nThink of the 1 force going North, the second one going East, the 3 going S, the 4 going W and the 5  NNE.\n\n2& 4 neutralize each other, so do not worry about them\n\n1 + 3 = 20 N 270 degrees\n\n5 = 25 N 0 deg + 43.3 N 90 deg  (50 cos 60 = 25, 50 sin 60 = 43.3)\n\nso the NS component will be 43.3 - 20 = 23.3 N 90 degrees\nand the EW will be 25N 0 deg\n\nThe resulting force will then be  34.17 =sqrt(23.3^2+25^2)\nwith direction 43 degrees (arctan[23.3/25])\n\nThe magnitude of the 6th force will then be 34.17 N and will have a direction of 223 degrees (opposite the 43 degrees one 43+180)\n\nyou can only arithmetically add forces that are in the same direction (or substract forces that have opposite direction).
532631
Communication is the most positive tool to almost all conflicts.  Sit down in a neutral location and put your concerns out on the table, in a constructive way.  Don't use judgmental words or make accusations unless you have concrete facts to back them up.  If possible have a third person involved who is completely unbiased to either side, and most importantly go in to the conversation with an open mind, be willing to except whatever blame may be yours.
145884
Newtons 3rd Law,\nFor every action, there is an equal and opposite reaction.\n\nSo all of the instances given, there is both an action and reaction force occuring.
49314
Sorry, but with the time you spent typing these questions you could of looked them up in your physics book or googled them.  Sometimes getting others to do your leg work isn't always the best answer to a problem.  Good Luck in your new class!