a + 4 a for a = 2    evaluate the expression?
447627
a + 4a where a = 2 ?\n\nif so, then...\n\n2 + (4)2\n\n2 + 8\n\n10\n\nThe answer is 10.
853794
Evaluate the expression after the ∑ for each of k = 1, 2, ..., up to 6, and add them:\n\n[ 1 + (-1)^1 ] 2^-1 +\n[ 1 + (-1)^2 ] 2^-2 +\n[ 1 + (-1)^3 ] 2^-3 +\n[ 1 + (-1)^4 ] 2^-4 +\n[ 1 + (-1)^5 ] 2^-5 +\n[ 1 + (-1)^6 ] 2^-6\n\nNow use (-1)^1 = -1, (-1)^2 = (-1) × (-1) = 1, ... to get\n\n[ 1 + (-1) ] 2^-1 +\n[ 1 + (1) ] 2^-2 +\n[ 1 + (-1) ] 2^-3 +\n[ 1 + (1) ] 2^-4 +\n[ 1 + (-1) ] 2^-5 +\n[ 1 + (1) ] 2^-6\n\n=\n\n[ 0 ] 2^-1 +\n[ 2 ] 2^-2 +\n[ 0 ] 2^-3 +\n[ 2 ] 2^-4 +\n[ 0 ] 2^-5 +\n[ 2 ] 2^-6\n\n= 2 × 2^-2 + 2 × 2^-4 + 2 × 2^-6\n\nUsing a^m × a^n = a^(m + n), simplify the exponents, to get\n\n2^-1 + 2^-3 + 2^-5 \n= 1 / 2 + 1 / 8 + 1 / 32\n= 16 / 32 + 4 / 32 + 1 / 32 \n= 21 / 32
1046507
[2x/(x+3)(x-3)]*[(x-3)/4(x)]\ncancelling 2 and x-3 we will get\n=x/(x+3)2(x)\nsimplify we will get\n=x/(2x^2+6x)
735754
just plug the numbers in.  if y=8, and x=2, \nits 8=a(2^2)\nso 8=a(4)\nso a=2.\nhope that helps!
896553
4x^2+8x-x-2\n(4x-1)(x+2)
321475
*(2x/(x^2-4)) + (5/2-x) - (1/2+x)\n*(2x/(x^2-4)) + (5/2-x)((2+x)/(2+x)) - (1/2+x)((2-x)/(2-x))\n*(2x/(x^2-4)) + (10+5x)/(4-x^2) - (2-x)/(4-x^2)\n*(2x/(x^2-4)) + (8+6x)/(4-x^2)\n\nyou should be able to get it from there
875476
(a + b - c)(a + b + c)\n((a+b)+c)((a+b)-c)\n(a+b)^2-c^2\na^2+2ab+b^2-c^2
1157065
(x+5)(2x^2+4x+2)\nx(2x^2+4x+2)+5(2x^2+4x+2)\n2x^3+4x^2+2x+10x^2+20x+10\n2x^3+14x^2+22x+10
524296
in C1:\n=A1*b1-b1\n\nin E4:\n=if(Upper(D4)="L",C4,if(Upper(D4)="W",B4,"D4 not L or W"))\n\nin A5:\n=E4+2\n\nIf I have understood correctly...\n\nJeez! my answer was truncated!  Here is is so that you can see it but don't include the linebreak!\nin E4:\n=if(Upper(D4)="L",C4,\nif(Upper(D4)="W",B4,"D4 not L or W"))
302848
Probably easier to show by example.\n4x2+8-:-4-1 (-:- = divide)\nmultiply any numbers first, then divide, then add and subtract.\n\nYou could add brackets in if that helps you.\n(4x2)+(8-:-4)-1 = 9
757614
4 (x^2 + 3X -4)\n4(x+4)(X-1)
879176
= x(x+3) + 4(x+3)\n= x^2 + 3x +4x + 12\n= x^2 +7x + 12
771836
Simple substitution.\n\n5(3) - 2(2) + 4(4)\n15 - 4 + 16\n27
597439
=[(4+3x)/x] + (2/3)[(5+3x)/x]\n=[(4+3x)/x] + [(10+6x)/3x]\n=[(12+9x+10x+6x)/3x]\n=[(15x+22)/3x]
1066820
If 'a' is a root of 2x^2=3x-4, then 2 a^2=3a - 4.\ni.e. a^2=(3a - 4)/2\n\nNow consider 4 a^3\n4 a^3\n= 4a(a^2)\n= 4a(3a - 4)/2\n= 2a(3a-4)\n= 6a^2 - 8a\n= 6(3a-4)/2 - 8a\n= a - 12\nQED
953799
[8+(2*4)]*3 =48 =16*3=30+18=48, just this first expression none of the others
972642
(A^2+2ab+b^2)/(a+b) + (a^2-b^2)/(a-b) + (a-b)/(a+b)/(a^2-b^2)/a+b)\n(a+b)^2/(a+b)+(a+b)(a-b)/(a-b)+ (a-b)/(a+b)*(a+b)/(a^2-b^2)\na+b+a+b+(a-b)/((a+b)(a-b))\n2a+2b+1/(a-b)\n\nif I got all the ( ) in the right places.