Can the amp rating of a Bosch automotive relay be determined by the part number?
449143
yep.the p/n tells you everything about the part. go to bosch.com to learn more.
923631
Yes.You have to appropriately reduce the rating and use it at low voltage low current applications.
960408
http://www.eas.asu.edu/~holbert/ece201/kvl.html
1185964
Have you the original lead?...if so you'll be able to get the power rating etc and see if your local electrical retailer can help.
1133319
check your owners manual ,if you don't have one. the internet is a great place for information. otherwize your local dealer will have the needed info.  as a rule plugs are .020 an points are .012-.016 thousands of an inch.  good luck
200245
Torsion bars do have a rating. Its based on a couple of variables though. Weight of vehicle, suspension travel distance, length and diameter of torsion bar. Performance parts listed by a manufacture though for a particular make, model are mostly listed from whats tested and what works. Then they only tell you the diameter of what they found to work in any particular application. The formula for figuring all this out will drive yah nuts though. So best to contact a supplier tech support and ask them whats best for your particular idea of usage to get the right torsion bar. They've done the math.
913471
In a purely resistive circuit, the power factor (PF) is 1 and you *can't* adjust it.\n\nAnd, since this is the 3'rd time you've asked the question and gotten the same answer from one other person and myself, do you even know what 'Power Factor' *is*?\n\n\nDoug
934641
If a voltage spec (v volts) is given on the resistor, then the power\nrating, p = v^2/r  ( r = resistance in ohm, you already know).\n\nIf v is not given then the only way is to connect the resistor to the poles of a battery cell via an Ammeter, and see the electric current measurement in ampere (say, i amperes).\n\nThen p = i^2 x r  (p, in watts).
775866
I don't think you can do that. you need the number of amps and the power factor for that device.
846168
v1/v2 = n1/n2\n\nrefer to "Electric Machinary Fundamentals"\n by Chapman
450685
The manufacturer's name will be on the spec's plate. go online and see if they can fill your needs.
409039
Just google the IC number + datasheet and you should be able to find the data sheets for most of those components.  If you read the sheet properly, it will tell you what the internal circuit is.
418101
You need the internal resistance. Then based on the amperage due to load you can figure the I^2R loss in watts for the battery.\n\nThe internal resistance can be determined by adding a resistive load to the battery and monitoring the voltage. The point at which the voltage starts to drop equals the internal resistance of the battery.
1029495
It is impossible to tell from the information given.  YOu need to know the power factor and efficiency too.  \n\nAt full load of a motor that big it is likely to be 95% efficiency and have power factor of probably 0.8.  \n\nIF (!!) that is true, then the current is (75 hp * 746 W/hp)/(480  V *sqrt(3))/0.95/0.8 Amps (rms)\n\nNotice I've considered a wye-connected motor too - that's where the sqrt(3) comes from.  I also get 90 A (like the previous guy)!
126809
first the back plate give you the rated of the motor,the coil risistance calculated by 4/1.1 is the resistance of coil in work that diffrent from that calculated in V/I methodes becuse in 4/1.1 the effect of armature reaction and armature back voltage therefore the coil resistance calculated in V/I is the right means 4.6 ohm,\nto calculate the turke (T=Po/w) where Po:output power wich approx. equil input power (100% effecency)=V/I,(( w=2*pie*N N:speed in rps
499954
Please use the name plate and find current at the voltage used or kva.  the NEC 2005 has a three phase 220 volt motor at 96 amps also you need to rate the motor a 125% so you need #3 copper wire rated at 125 amps (THHN) DO NOT USE A CIRCUIT BREAKER LARGER THAN 125 AMPS. YOU ALSO NEED A MOTOR OVERLOAD RATED 96AMP.  IN THE CONTACTOR RATED NEMA CLASS 2
1062318
Perhaps the link will help.  At a minimum, you risk voiding your warrant if you use other that the voltage and frequency required on the unit name plates.  At worse you risk injury and a possible fire if you really don't know what you are doing.  Good luck.