what is dipole moment and how to measure it?
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IF YOU DON'T UNDERSTAND MY ANSWER.....FOLLOW THIS LINK ;\n\nhttp://en.wikipedia.org/wiki/Dipole\n\nA dipole (Greek: di(s) = double and polos = pivot) is a pair of electric charges or magnetic poles of equal magnitude but opposite polarity (opposite electronic charges), separated by some, usually small, distance. Dipoles can be characterized by their DIPOLE MOMENT : A VECTOR QUANTITY WITH A MAGNITUDE EQUAL TO THE PRODUCT OF THE CHARGE OR MAGNETIC STRENGTH OF ONE OF THE POLES AND THE DISTANCE SEPARATING THE TWO POLES. The direction of the dipole moment corresponds, for electric dipoles, to the direction from the negative to the positive charge. For magnetic dipoles, the dipole moment points from the magnetic south to the magnetic north pole — confusingly, the "north" and "south" convention for magnetic dipoles is the opposite of that used to describe the Earth's geographic and magnetic poles, so that the Earth's geomagnetic north pole is the south pole of its dipole moment. Because of the absence of magnetic monopoles, magnetic dipoles are actually created by current loops or by quantum-mechanical spin.\n\nSince the direction of an electric field is defined as the direction of the force on a positive charge, electric field lines point away from a positive charge and toward a negative charge.\n\nWhen placed in an electric or magnetic field, equal but opposite forces arise on each side of the dipole creating a torque τ:\n\nτ = p x E  (for an electric dipole moment p) (measured in coulomb-meters)\n\nor\n\nτ = m x B = u0m x H  (for a magnetic dipole moment m) (measured in ampere-square meters).\n\nThe resulting torque will tend to align the dipole with the applied field.
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Angle measurement, which is the meaurement behind latitude and longitude (the angle being at the center of the earth) are measured in degrees to start with, but to get the measurement more precise, degrees are divided into minutes, and the minutes are divided into seconds.  (Nothing to do with time measurement, except that a degree has 60 minutes, and a minute has sixty seconds).  So 54 35' 45.6" reads 54 degrees, 35 minutes, 45.6 seconds.
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The presence of an electric field is tested by placing a unit charge at a point. \n\nIf the charge experiences a force, we say that there exists an electric field.\n\nThe field is measured by the force experienced by the unit charge.\n\nSimilarly, a magnetic field is tested by a wire circuit of very small area.\n\nBut the difference is that, here, we measure the rotational effect of this test circuit and not mere force.\n\nThe test circuit has its highest moment in a particular orientation of the area.\n\nThe side (upper side and lower side) of the test circuit also affects the direction of moment. \n\nIf the test circuit placed in a point and if it experience different moment for different orientation, we infer that there is a magnetic field.\n\nThe field is measured by the highest moment experienced by the test circuit.\n\nEarlier we used the concept of free unit north pole; since no single pole exists now the measurement is base on free test circuit, which is more and real fundamental concept.
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Dipole moment is a vector quantity. It is the vectorial sum of all the bond moments in the molecule. \n\nIf the molecule is symmetrical and the bond moments are cancelled by each other then the dipole moment is zero.\n\nIn case of SO3, the dipole moment is zero because the molecule is trigonal planar.\n\nWhereas the BrF5 is square pyramidal and hence has some dipole moment. The Flourine present above the square plane causes this dipole moment.
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ummm, i dont understand what ur asking, but if u wanna know how its generated, it has something to do with positive ions of a molecule flowing in one direction, and negative ions flowing in either the same of opposite direction forming direct and indirect currents, or at least that's what i think it is
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It is true for individual bonds, but not for molecules.\nThe dipole moment of the molecule will depend on the geometry of the polar covalent bonds. E.g. CF4 has 4 polar bonds but they arranged so that the sum of their dipole moments is zero and the molecule has actually no dipole moment.
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polar means that the electron cloud is not even, and yields a slight negative charge to one side, and postive charge to the other side, it is call a dipo moment.\n\nNon polar means that the electron cloud is evenly balanced and no dipo moment is formed.\n\nNaCl, table salt is polar, and will go into solution with a polar solvent such as water.\n\nMethane, CH4 is non polar and will not go into solution with a polar solvent, but will with a non-polar solvent.\n\nThis is matters alot in chemistry, since electron reactions are the bases for all chemical bonds and reactions.\n\nRead more , and you will understand better, good luck
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Assuming you want to know what causes van der Waals force: it's a collective term for three different electromagnetic dipol/quadrupol effects:
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You should be able to measure all three, in both cases.. limited only by the sensitivity and accuracy of your instruments.\n\nwhen a particle with mass moves past you, or you move past it, the force excerted by gravity between you and the particle changes with distance. Of course you need to have a mass too. and your instruments need to be good enough to distinguish these forces from other gravitational and other kind of forces.\n\nIf a charged particle moves, it produces a magnetic field. this is the same effect as seen in a elecromagned where moving elecrons produce magnetic fields.\n\nif a charged particle moves past you, and you have a detector that is based on charge too, you will notice an increase or decrease in attractive or repulsive force between your detector and the charged particle as the distance between the both changes. again this force is miniscule and is easily confused with other stray forces including the above gravitational ones.
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Sign conventions.  Mass is always positive, and that's the deciding factor for angular momentum.  Magnetic moment involves charge, and electrons are negatively charged, so it ends up being anti-parallel.  But, this is just an arbitrary convention, so don't get too worked up over it.  Yes, it's important for keeping your ps and qs straight in doing physics, but it's not of any major physical significance.  \n\nIf we'd decided to call electrons "positive" and protons "negative", then the magnetic moment for an electron would be parallel to the angular momentum.
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It is a device to determine or measure the presence of electrostatic charges in an object.\nIt consists of a metal case within which, and near its center, is supported in a vertical position a well-insulated metal strip to the top of which is attached a narrow strip of thin foil, preferably of gold leaf.
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Check here:\nhttp://en.wikipedia.org/wiki/Dielectric_spectroscopy#Electronic_polarization\nhttp://www.psrc.usm.edu/mauritz/dilect.html
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Measure its capacitance.  Many multimeters have this capability.  If the body is not a two-terminal device (e.g., a capacitor), measure the capacitance from the body to a ground plane.  Then measure its voltage with a very high-impedance voltmeter.  The act of measuring will drain off some charge, so you have to take a reading quickly.  The charge in Coulombs is V*C, where V is voltage in volts, C is capacitance in Farads.
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well, the magnetic dipole moment of a loop is given by mu = I*A where I is the current and A is the area of the loop.  so, to maximize the area for a given perimeter, i think you want a circular loop.\n\nhttp://www.faculty.fairfield.edu/jmac/ther/superlatives.htm\n\nas for whether to make a single loop or lots of loops, consider how much area you get for a wire of length L.  the circumference of a circle is C = 2*pi*r, and the area is A = pi*r^2.  solve the first equation for r and plug it into the formula for area, and you get A = C^2/4pi.  here C is simply the length of wire you use.\n\nso, if you make N loops of length L, then you get a total effective area of N*A.  but, if you make a single loop of length N*L, then you get a total area of (N*L)^2/4pi = N^2 * A, which is a factor of N more area than the case with N loops.  \n\nit's because of the r-squared term in the area - as you increase the amount of wire, the area goes up like the square of the length of wire.  whereas if you just add extra loops, it only goes up linearly with the length of wire.\n\ncheers!
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1 Find the current flowing in the lamp.   P  = VI\n2 Look up the charge on an electron.     q\n\nDivide 1  by 2  which will give you the number of electrons flowing per second.      n  =  I/q
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For a moment of inertia I, an angular acceleration A and a torque T we have T = IA.\n\nThe moment of inertia is equal to the mass of an object multiplied by the square of a representative length called the radius of gyration, which is in fact the root-mean-square distance of its elements from the axis of rotation. If the axis of rotation passes through the vertical part of the Y section then the elements of the section will be symmetrical around the axis of rotation and the root-mean-square distances can be measured and the radius of gyration could be calculated.
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F = KM1M2/r^2\n\nwhere K is the constant, M1 and M2 are the magnetic moments, and r is the distance between them.