I want proof that 2+2=5?
454426
i have a great logical reasoning for that.... here goes:\n1. there are two 2s, so you overlap them, making just one two. \n2. take the plus sign out for a second.\n2 1/2. the plus sign consists of 2 sticks, one horizantal and one vertical. \n3. the vertical came become a one and place it on the left of the 2. ( it makes 12)\n4. the other horizantal line can be used as a minus sign. \n5. Now, in the equal sign, it consists of two lines, both horizantal. \n5 1/2. if you leave one, and make the other diagonal, and attach in together, it makes a seven. \n6. so.. so far, it's is like this: 12-7=?\n7. ultimately, the answers five\nso there you have it, it sounds a little weird and strange, but it's really impossible to have a logical reasoning for 2+2=5... hehe
700473
(x^5 + y^5) =  (x+y)(x^4 - x^3*y + x^2*y^2 - x*y^3 + y^4).
904926
5+-V92\nquadratic formula
301417
I'll try. I gave this proof to THREE people already:\n\nTake any two ordinary constants. (e.g. x and y)\nMake them alike, as in x = y = any non-zero number (in this case, 2)\nMultiply each by y, but x works equally well (y²=xy).\nSubtract x² from each equation (y²-x² = xy-x²).\nFactor y²-x² into (y+x)(y-x) to make ((y-x)(y+x) = xy-x²).\nFactor xy-x² into x(y-x) to make ((y-x)(y+x) = x(y-x)).\nDivide by (y-x) to get (y+x=x).\nSubtract x from both sides of this equation to get y=0.\nThis means that y=0.\n\nbut since, y equaled 2 in the first case, that means 2 = 0.\nIf you multiply this equation by 2.5, you get 5 = 0.\n\nSince 0 + 0 = 0, you can plug in 2 for the first two zeroes, and five for the last one, and then, TA DA! 2 + 2 = 5.\n\nP.S., this proof has a little falsity in it. you can't divide by (y-x) because that is zero!
104805
2+2=1 (mod 3)\n\nNothing is flawed.\nIn natural numbers we always have 2+2=4.\n\nPS.\nJust as a joke for mathematical analysis students:\n2+2=5 for sufficiently large values of 2
19885
(5) x (2x^2-3x+5) I think
352513
true! Its fairly obvious by definition:\n\nfor example:\n2*5 = 5 + 5 = 2+2+2+2+2\n\nAn easier way to see this is through an invention by John Napier called Napier's Bones. He converted all complicated multiplications into simple addition
855741
(5z^3m + 2)^2, multiply it out yourself to check.
277593
In your case use your fingers bye the way 2+2 = 4
811163
(2 * 20) - 35 + 5 = 10
954015
I answered this question a few weeks ago. The answer is to draw a forward slash (/) through the equal (=) sign changing it to a not equal sign. This gives the true inequality\n5+5+5 not = 555.:
493260
Knowing what a proof is, is the first step in answering this question. From what I am familiar with...\n\nA proof is: a set of logical steps acquired through deductive (therefore, not making any giant leaps in logic, unless by definition), and hence, empirically (from the evidence provided) resulting in a direct equivalence (being, among other types of equivalence, but primarily, in permutation,  multiplicative/additively & negatively/positively & even/odd... meta-mathematically) of states, that's shortest distance is (in absolute terms), either infinity, zero, and/or, also, one.\n\nReally, the attempted 'proof' of 2 + 2 = 5 is based on a distorted type of Trigonometry, which was in essence the source of today's Calculus (just try to draw Tangent or Secant without running into the idea of Calculus' derivative & integral, respectively), and actually is the result of any additive equavalence of any two numbers' to being alike to any number, (because measuring hypotenuse of a given sides is essentially multiplicative, hence partially irrational). \n\n(Which makes me wonder... is there a 2 * 2 = 5 equivalent? and the answer is a resounding, yes! But first the 'proof' as written by Charles Seife.)\n\nLet a & b each be equal to 1. Since a ^ b are equal,\n\nb^2 = ab ...(eq.1)\n\nSince a equals itself, it is obvious that \n\na^2 = a^2  ...(eq.2)\n\nSubtract equation 1 from equation 2. This yeilds\n\n(a^2) - (b^2) = (a^2)-ab ...(eq. 3)\n\nWe can factor both sides of the equation; (a^2)-ab equals a(a-b). Likewise, (a^2)-(b^2) equals (a + b)(a - b) (Nothing fishy is going on here. Ths statement is perfectly true. Plug in numbers and see for yourself!) Substituting into the equation 3 , we get\n\n(a+b)(a-b) = a (a-b) ...(eq.5)\n\nSo far, so good. Now divide both sides of the equation by (a-b) and we get\n\na + b = a  ...(eq.5)\n\nb = 0 ...(eq.6)\n\nBut we set b to 1 at the very beginning of this proof, so this means that\n\n1 = 0 ...(eq.7)\n\n ...Anyways, getting that far gives us the jist of the proof, later in the proof, Charles Seife goes on to prove that Winston Churchill was a carrot! if you want to know how that is possible, I recommend you read the book.\n\nFrom equation 7, add a number to either side and get it equal to any other number, one greater than itself.\n\nMultiplying equation 7 after adding to it, and one can get: any number is equal to any other number. \n\nHence, conceptually, any number is equal to zero, and, theoretically, that includes infinity. But that's also the reason why when you divide by zero, it is 'Undefined.' Which, consequentially, is what is happening in this equation... just subsistute 1 into equation 3 and one will see that we are dividing by zero in equation 5. \n\nThis is what lead to the invention of calculus. Really, from here this segways into Hilbert Space... but that is best left for another entry, hopefully, on the actual subject of quantazation.\n\nThat's all I have time for... \n\nTHIS PROOF IS BY DEFINITION INCORRECT, but it provides a good tool as of why we define things in mathematics the way we do.\n\nA good question to ask from here would be (based on my previous tangent):\n\nDoes 1/3 plus 1/3 plus 1/3 = 1?\nOr, does it equal just zero point nine repeating?
709230
1) because\nf(-5)=-5+7 =2
1025267
Here is how:\n\n6+6+3\n6+5+4\n5+5+5\n\nnow change the first two around until you have all the possiblities.
269006
Ask your friends if they can find the error in the following proof.\n(it's obviously not right, but it looks cool!)\n\na=b\na+1 = b+1\n(a+1)^2 = (b+1)^2\na^2 + 2a +1 = b^2 + 2b +1\ncancel the ones and rearrange\na^2 - b^2 = 2(b-a)\n(a+b)(a-b) = 2(b-a)\ntherefore a+b = -2\nPick numbers for a and b\nand look!! 5 + 7 = -2\nThus shown.\nLOL
256804
5x^2  -10 x +5\ncan be factorised into (x-1)(5x-5)\nsimplified to 5(x-1)(x-1)\n\nthus square root of given sum becomes square root of \n5(x-1)^2\n\nwhich is (x-1)*5^1/2
771554
(x+5)(x-5)\n(x)^2-(5)^2\n=x^2-25