How to find the watts of an appliance?
448724
On nearly every appliance, there is a label, usually somewhere near where the AC cord enters the body of the appliance, or on the bottom, which states the electrical draw of the appliance.  If it is not listed in watts, then it will be listed in 'AMPS' or just 'A'.  To determine the wattage of an appliance if it gives you the draw in amps, you just need to do some simple math.  (amps) * (line voltage) = (watts).  So, if an appliance says that it draws 3 amps, and it is plugged into a standard north american outlet, which is 120 volts, then 3 * 120 = 360 watts.  If it is a 240v appliance, and draws 3 amps, then 3 * 240 = 720 watts.\n\nHope this helps...
657313
W/m*K = Watt/(meter*Kelvin)\n\nPower per unit length per unit temperature\n\nWhere power is defined as energy per unit time.
422407
Multiply by 1000. Example: 1kw (k=1000) = 1000 watts.
725119
I kept reading anyway.\n\nThe heater is already telling you the power consumption.\n900W = 0.9 kW\nTherefore running the heater for one hour uses 0.9 kWH.\n\nYour formula is wrong. Watt/1000  * cost/kWH = cost per hour\n\nFor heaters, it is true that Volts * Amps = Watts.\nTherefore if you know the supply is 120V and the power is 900W, you can calculate that the current load is 7.5 A.
414310
You cannot determine KWH usage with AC in that way.\n\nIf you looked at the voltage, it would be a sinewave.\nIf you could look at the current, it might also be a sinewave, but it is very unlikely that it would be in perfect phase with the voltage.\n\nOnly if the current and the voltage are in perfect phase with each other can you determine watts by multiplying current times voltage.\n\nThe arithmetic you are suggesting will work only when the power factor is exactly 1.00, which could be close to correct if the load is all incandescent lighting, but will not be correct if the load is inductive, such as electric motors, or capacitive.\n\nTo measure power usage, you will need a watt-hour meter, similar to what the utility companies provide.\n\nThe following source (found via Google) explains it:\n\n"A common misconception is that power is simply the product of voltage times current, implying that any ammeter can be used to determine power usage. This is only true in  a few special cases."
141377
It depends on where you live.  The cost of electricity on the power grid ranges from about 4 cents per kilowatt hour in Kentucky to about 14 cents per kilowatt-hour in New York City.   You would need to find out what the cost per kilowatt hour is where you live and multiply that by the number of kilowatt-hours you would use in a month.\n\nTo determine the number of kilowatt-hours you would use in a month, multiply the power (in watts) of each appliance by the number of hours that appliance is being used and divide this by 1000.  For example if you use eight 100-watt light bulbs an average of 5 hours a day than, they would account for 8 x 100 x 5 x 30 (days in a month) = 15000 watts/1000=15 kilowatt-hours.  If you don't know how many watts the appliance uses, multiply the number of amps by the voltage the appliance uses; but it is easier just to check the table in the link below to find a typical power useage for each of your appliances.\n\nOnce you've totaled the number of kilowatt hours used (watts x hours used / 1000) for each appliance, multiply that total by the cost per kilowatt-hour in your area.\n\nThe biggest influences on your electric costs or usually the water heater and heat and air, and possibly the oven if it is used a lot.  Using a space heater a lot can effect it a lot.
38663
1 horsepower ≈ 745.700 W (rounded up from 745.69987158227022 W)
346550
kingbodonti is correct...\n\nPower in watts = Work in joules / time in seconds\n\nPower = 1,000 joules/50 seconds\n\nPower = 20 watts ANSWER
1041665
When 1 Joule of energy is spent in 1 second, the power is said to be 1 Watt.\nIn everyday household use, Watt is used to measure the power of electrical appliances. That is to say, if an appliance is labeled as 220W, it means that the appliance spends 220 Joules of energy(electrical) every second.
530227
.05 kwh\n\n100w/2/1000=.05
886279
ohms law...\n\nfind total wattage \ntimes cost per kwh\n so\n21 x 220 =\n4620 watts per hr\nx 5.8 cents per 1k watts per hr
820591
Add the loads in amperes of each of the appliances on that circuit.  Make sure that the total is less than the ampere rating of the circuit breaker.  You should probably only use about 3/4 of the amperes the circuit breaker is rated for.  For example, a 20 Amp breaker should only be loaded with about 15 Amps.\n\nIf only the wattage of an appliance is given, divide the wattage by the voltage to obtain the amperes.  For example, a toaster may draw 1200 watts.  1200 watts / 120 V = 10 Amps.  A light bulb may draw 60 watts.  60 watts / 120 V = .5 Amps.
621263
Now See\nA typical monitor has  about 60 watts to consume to show the display.\nAnd a CPU Adapter takes 10-12 watts.\nThe normal speakers with woofer if you add take 5 watts.\nAdd these quantities Total Watts = 60+12+5=77\n\nConvert above value In KWh (Kilo Watt Hour) electrical units\nBecause we have to calculate the unit consumption hourly.\nKWh= 77/1000 = 0.077 unit\nThis figure is for the whole hours comsumption in kwh unit, because utility companies multiply the unit consumed into price/unit.\nsimply price = units * (price/unit)\n             = 0.077 * ? your price\ne.g.         = 0.077 * (20 cents/unit)\nprice for 1 hour = 0.0154 dollar\nprice for 24 hours = 0.0154 * 24\ntotal price a day  = 0.3696 cent\nHow much power you consumed in 24 hours\n= .077*24 = 1.848 Kilo Watts\nnearly 2 units per day 24hours.\n\n\nhttp://360.yahoo.com/jcbroogley
175366
961 kcal=1118 watts\nI=P/E\nWich come out to about 22.6 amps.\nSo you would have to go with the 32.8 amp fuse. Also the math I did was based on 100% efficiency. So the 32.8 amp fuse would also make up for that.
914617
Hi there:\n\nYou can estimate your power consumption using calculations for posted " average" ratings for all the parts of your computer, however, nothing is real, and the power supply rating has nothing to do with the power you are actually using.\n Only the electrical meter on the main line is of any value...\n\nI have answered this question in different forms a few times, and a typical answer is listed below:\n\nHow can you find out how many Watts your PCs power supply uses?\n\nLet's say in an hour, how many watts have been used...\n \n\n\nBest Answer - Chosen By Voters\n\nHi there:\nI looked at the answers above, and only one, CJMT had any inkling of the correct answer \n\n- The only way to know is to MEASURE IT!\nYou can calculate thousands of calculations all day, but until you actually measure YOUR own computer, you are just guessing!\n\nNew power supplies now come WITH and actual Wattage power meter, which is on the back or mounted on a front panel with a plug in cable. Some Motherboards, have a power meter built in as well, and, considering these " new and improved" features, it clearly shows that you are among thousands of computer users who are interested in this factor...\n\nIn the " old " days, you would just get a power " Clamp on " meter of some sort, and clamp over ONE wire of the AC power cord ( this is a bit difficult with normal computer power cords, so you plug in an extension which has the the wires separated, and clamp the meter over ONE of the wires.)\n\nNow you can purchase easy-to-use plug in-the-wall meters that have digital readouts. \n\nSimple.\n\nYOU MUST actually measure your wattage - for example, if you have an 800 WATT power supply, this means nothing, except that the power supply " CAN " supply 800 Watts if it " has to " -- you could actually only be using 289 Watts of the available 800.\n\nIn order to really know what your " computer " is costing in terms of power, you should plug in the monitor, the CPU box, the speakers, the printer, the modems, power adapters etc. etc. TO A POWER BAR, and then measure the actual total to the wall plug.\n\nListed below are links on the web to typical measuring tools that are commonly available. You can check out stores and electronics and computer outlets in your area, once you know what you are looking for. If you know an electronics guy or a hydro guy, he could just let you use a clamp meter in a few seconds to get a reading, and save yourself a few bucks - but the $30 home units would come in handy to measure anything in \nthe whole house -- well worth it !\n\n\nPower Supplies with WATT METERS\nhttp://www.highpowersupply.com/product-ps-hpc480102df.html\nhttp://www.newegg.com/product/product.asp?item=N82E16817171001\n\nKill a Watt Meter\n\nhttp://www.gooddeals.com/shopexd.asp_Q_id_E_119\n\nBriggs and Stratton Meter\n\nhttp://www.northerntool.com/webapp/wcs/stores/servlet/NTEprodprint?productId=200326720&p\n\nrnbr=1704700&storeId=6970&catalogId=4006970&langId=-1\n\nSAFE HOME 3 products\nhttp://www.safehomeproducts.com/shp2/shpsearch.asp?source=adwords&kw=wattage+meter\n\nProfessional Watt meters\nhttp://www.testequipmentdepot.com/amprobe/clampmeters/digitalac.htm\nhttp://www.testequipmentdepot.com/fluke/currentclamps/330series.htm\nhttp://www.testequipmentdepot.com/hioki/clampmeters/3280.htm\n\nThere are hundreds of other models and manufacturers available, and since millions of people are interested in actually knowing where the high cost of power is being used in their homes, I expect to see hundreds of more products available\nat lower and lower prices as manufacturing gears up.\n\nHope this helps\n\nrobin
129261
Kilowatts  Equations\nDirect Current  =        I x E/1000\nAC / 1phase 115v or 120v =I x E x PF/1000\nAC / 1phase 208,230, or 240v= I x E x PF/1000\nAC 3 phase All Voltages     =    I x E x 1.73/1000\n\nE = Voltage \nI = Amps \nPF = Power Factor
616652
Most generators are rated in watts. If you have a 50 amp circuit, then 110 volts x 50 amps = 5500 watts. You do not want to run the generator past 80% of its duty cycle, so a 6000 watt gen should be the best.\nHope the formula helps\nYou can also figure out how many watts a microwave will need. I it takes 10 amps at start up then 10 x 110 = 1100 watts.\nThus a 60 watt light bulb would take 60/110= .54 amps