What is the molarity of sea water. All of the salt is NaCl. Density is 1.02 grams per cubic centimeter?
439952
You can find in "Chemical Engineer's Handbook", from Perry-Chilton, graphics for density of water + NaCl solution vs. %w/w of NaCl. The NaCl concentration is 3.5%
1175894
1 cubic metre is 1000 dm3, which is 1000 L3 which, if its at 25C (density of water 1), the WEIGHT is 1000kg.\nNote weight and mass are not the same thing.
782227
Density is a measure of mass per volume. Same amount of water; sugar water is denser. Weigh; salt is NaCl, sugar is a more complex and heavier molecule. Formula for glucose. C6 H12 O6. Denser.\n\nNo. sugar water is denser than salt water. Period.
1117056
The ocean is essential for life on Earth, and also helps make the climate fairly moderate. However, although the ocean contains 1,370 million cubic kilometres (334 million cubic miles) of water, humans can’t survive by drinking from it—it is too salty.\n\nTo a chemist, ‘salt’ refers to a wide range of chemicals where a metal is combined with a non-metal. Ordinary common salt is a compound formed when the metal sodium combines with the non-metal chlorine—sodium chloride. This contains electrically charged atoms, called ions, that attract each other, resulting in a fairly hard crystal. When salt dissolves, these ions separate. Sodium and chloride ions are the main ions in seawater, but not the only ones. The salty seas benefit man, because the ocean provides many useful minerals for our industries.
923875
Salt water is denser than fresh water.
231158
.20 m Na2SO4, .20 m NaCl, .10 m BaCl2, .10 m glucose
271556
In addition to the fact that at 4 degrees celcius, water has an absolute density of EXACTLY 1 g/cc, at 0 degrees, it is in equilibrium with its solid phase (ice) which has a density of LESS than 1 g/cc due to its open cage like crystal structure. So, its exact density at 0 degrees is impossible to standardise.
851515
the easy answer is that it is less dense, but if you want the real answer, it is most dense at 4C, here is a graph\n\nhttp://www.piercecollege.edu/offices/weather/water.html
178060
Use the formula: Density equals Mass divided by Volume\n\nor\n\nD=M/V\n\nSo we plug in numbers from your question:\n\nD = 23g/25 cm^3\nD = 0.92 g/cm^3\n\nor .92 grams per cubic centimeter.
249474
The mass of 1 cm^3 of water is 1 gramme.  Therefore, 100 cm^3 of water will have a mass of 100 g. If you add 150 g of sugar (or salt or anything else that does not produce an explosion or gives off a gas) the total mass will be 250 g.\n\nIf you had asked what is the total volume, that would have been a completely different situation.
775473
a)M. wt of sucrose = 342 \n1 mole of sucrose weighs 342 g\n342 g of sucrose in 1000 ml is 1M soln\n.342 g of sucrose in 1ml is 1M soln\n(.342 x 150 ) = 51.3 g will give 150 ml of 1M soln \nb)sucrose dissolves into water as sucrose. so its osmolarity is same as molarity.\n3a)0.9 % mass/volume\nor 0.9g NaCl in 100 ml of water\nor 9g NaCl in 1000 ml of water\nM.wt of NaCl = 58.5\nmolarity is 9/58.5 = 0.154 M\n3b) NaCl dissociates into two parts (Na+  & Cl-)on dissolving. so it gives osmolarity of 2*(0.154)= 0.308\n3c)for NaCl , vant hoff factor is 2.\nM = 0.154M /L\nR= 62.3637 L · mmHg · K-1 · mol-1 \nT= 298\nosmotic pressure = i *M*R*T = 5723.98 mmHg\n4a)1000 mL of solution weighs 1026.8 grams. it contains 0.703 moles of NaCl, which'll weigh 0.703 *58.5=41.125grams . so the rest of solution is water, i.e, 1026.8 - 41.125 =985.675 g is water\nthe moles of water is 985.675 / 18 (mol.wt.of water) = 54.76\nso the mole/mole percent of NaCl is  (0.703/54.76) * 100=1.283%\n4b) i think its molal not molar as molar is already given. so here goes\n1 litre weighs 1.0268kgand contains 0.703 moles NaCl\nmoles/kgof solution  = 0.703/1.0268 = 0.685\n5a) delta T = 178.8 - 177.3 =1.5 = i* 37.8*molality\nmolality is moles of sulfur/kg of solution\nmoles of sulfur = 0.1g/Mwt\nmolality is = [0.1g/Mwt]/[ 0.01kg camphor +0.001 kg of  S] (im converting grams to kg)\nwe assume i =1, because camphor is a nonelectrolyte\nso, equation becomes,\n1.5 = i* 37.8*molality\n      = 37.8 *[0.1g/Mwt]/[ 0.01kg camphor +0.0001 kg of  S]\n       = 37.8 *[0.1g/Mwt]/[ 0.0101kg ]\nso M wt of S  = 37.8 *[0.1g]/[ 0.0101kg *1.5] =249.5 \n5b)  the atomic weight of atomic sulphur is 32.. so , number of atoms in a molecule in this case is 249.5/32 =7.79 or approx 8\nso each of the molecules of sulfur in this case has 8atoms of sulfur
859821
2.2 gram\nu can calculate it by the molarity formulae
784999
.15 M solution of NaCl means .15 moles of NaCl (solute) in 1000g of water (solvent).\ntherefore, to make 250 ml (or g) solution [ as density of H2O is 1]\nmoles of NaCl required = .15/4 = .0375 moles \n& moles = given wt * molecular wt \nso, given wt (or required wt in this case)= moles/ molecular wt. = .0375/58.1 = 645.4388 * 10^-6 g
854783
Normal saline is 0.9% NaCl.   This means that it contains;\n\n0.9 Grams/100mls of sodium chloride or 9 grams/liter.  \nOr, 900mg/100 ml= 9mg/ml of sodium chloride\n\nDid you mean how many mg of NaCl??\n\nIncidently this equals 154 meq Na+ per liter
359119
look at column 7.  all of the densities appear there in grams/cm3.\n\nhttp://www.science.co.il/PTelements.asp
802841
I assume you are talking about ordinary table salt, sodium chloride (NaCl).  \n\nThe molecular mass of NaCl is 58.44 gm/mol.  One gram of NaCl therefore contains:\n\n1 gm / (58.44 gm/mol)= 1.711*10^-2 moles\n\nEach mole of Na is equal to one "equivalent" because Na forms ions that have a charge of +1, so for Na+:\n\n1.711*10^-2 moles = 1.711*10^-2 equivalents = 17.11 milliequivalents
165558
Sodium and Chlorine. Na+ and Cl- are the main ones. \n\nThe others include K+, Ca2+, Mg2+, SO42- ,H+ and  OH-\n\nThe reference gives the relative amounts of the main ions in sea water.