Out of 1 hour, What is (.2) converted into minute increments?
440612
Out of 1 hour, (.2) is (12) converted into minute increments.
893508
here:\nclass time\n{\n   int t;\n   public:\n   time() : t(0) {} \n   time(int x) : t(x) {}\n   time(int m, int s) : t(m*60+s) {}\n   int m() {return t/60;}\n   int s()  {return t%60;}\n   operator int () {return t;}\n};
834683
YES!  YOU GO GIRL!!!! :-)\n\n1/4 hr = 2/8 hr\n\nSo, 2/8 + 5/8 = 7/8!\n\nYay for you!\n\n~ ♥ ~
223758
I assume those are interval values and not actual times of day.\n\nTo average them, break them down into seconds, average the seconds, and then put that number back in HH:MM:SS format.\n\nIn this case:\n0:12:35 => 755 seconds\n0:02:10 => 130 seconds\n0:09:05 => 540 seconds\n\n(755 + 130 + 540) / 3 = 475 seconds\n\n475 seconds = 0:07:55
676280
given\nt=# of hours past midday(meaning 12:00pm I assume)\n =15:00-12:00=3\n\nD=3.5\n\nso\n\nthe simplied equation becomes\n1.5*A -.5*A*k=-2\nthere are alot of solutions to this problem...\nfor example \nif k=1, A=-2\nif k=2, A=-4... \nmore information is needed to narrow the solution to only two numbers.\nDoes it tell you the depth at midday(t=0, D=?)
81780
TIME(HOUR(A1)+16, MINUTE(A1), SECOND(A1)) \n\nworked fine for me when I had A1 as\n\n="04:00"\n\n(Note the equal sign and quotation marks.)
683869
0.01 is already decimal..\nif you want 0.01%, it should be 0.01/100=0.0001
716921
0.009 \n\n0.018 \n\n0.027\n\n0.036
18386
Are those times?  As in, one hour, 24 minutes, and 43 seconds?  In that case, I would say that 1:24:43 minus 1:22:05 is 0:02:38.  You come up with this answer by subtracting the first numbers (1-1), then the second numbers (24-22), and then the third numbers (43-05).  This way, you're subtracting hours from hours, minutes from minutes, and seconds from seconds - they have to match up.
1088959
multiply the time by 1.5
478761
100,000,000,000,001 or one could give it to you in scientifi notation with a rounding error 10.0 E13
957344
t=2.512 seconds\n\n10.3=0.5(0+8.2)t\nTherefore \n\n1 = 4.1t/10.3\n\n1/t = 4.1/10.3\n\nt = 10.3/4.1 = 2.512 seconds
214863
I can do this with a couple formulas. Let's say your seconds field is A1. Make field B1 this formula:\n\n=INT(A1/60)\n\nThat will give you the total number of minutes. Then make C1 this formula:\n\n=sum(a1-(b1*60))\n\nThat will give you the leftover seconds. There is probably a cleaner way to do this, but I only know what I taught myself.
698011
The error is +/- 0.01.\n\nThe value then is: 6.02 +/- 0.01
1099051
01:01:42 PM\nhr:min:sec.\n\nTo distinguish between am and pm is if the hour number is larger than 12 it's pm. Just subtract the hour and you get the normal hour.\n\nIf it's smaller than 12 it's am
2556
You're really close! The answer is actually 1:03:11. You were off one minute because you forgot to borrow a minute from the 34 so you could subtract the seconds.
1081620
First of all, lets just look at 12 hrs, as it will be the same for the next twelve:\n\nThe minute hand revolves around the clock at 1 rev per 60 minutes, the hour hand revolves around at 1 rev per 60•12 minutes.  Knowing that after 60 minutes the minute hand is back to where it started we can say that 2π≡0.  We want to rewrite the above relations to give us the positions as a value of time.  This can be done by assuming that t is time (in minutes) and using m=2π/60t (minute hand) and h=2π/(12•60)t (hour hand).  \nTherefore we want to solve m=h+2πk for some integer 0≤k≤10.  The reason that we don't have k go to 11 is because if you think about it, the hour and minute hand never cross during the 11th hour, they keep getting closer, but then at 12:00 (during the 12th hour) they meet.\n\nThus 2π/60t=2π/(12•60)t+2πk ==>> 12t=t+720k ==>>11t=720k ==>> t=720/11k.\n\nNow, this is the time after 12:00 (midnight or noon, I don't care they; are the same). \nThese times are:\n\n12:00 (k=0)\n1:60/11=1:05:300/11≈1:05:27.27 (k=1)\n2:10:600/11≈2:10:54.55\n3:16:240/11≈3:16:21.81\n4:21:540/11≈4:21:49.09\n5:27:180/11≈5:27:16.36\n6:32:480/11≈6:32:43.64\n7:38:120/11≈7:38:10.91\n8:43:420/11≈8:43:38.18\n9:49:60/11≈9:49:05.45\n10:54:360/11≈10:54:32.73\n\nI decided to give you the second values as fractions also, since they can't be given accurately by a terminating decimal.