how do i calculate serum albumin using--C1V1=C2V...?
446836
Concentation 1 x volume 1 = conc 2 x volume 2.\n\nYoure are probably using it to find total blood volume with a known volume of 'marker' albumin.  \nThe marker concentration x its volume = the concentration after dilution x the amount of diluent(the blood volume)
683950
M1V1=M2V2\nie... 0.24*40.11=M2*0.55\nM2=17.50\nMOLARITY=                                                (MOLECULAR WT/GIVEN WT)*(1000/VOLUMWEOF THE SOLUTION IN MILILITERS)\nIF U CAN SUSBSTITUTE THE VOLUME OF THE SOLUTION THEN U CAN FIND OUT THE MOLECULAR WT\nhope u know how to find out the molar mass fr molecular wt.
585636
Do you have looked PubMed? "http://www.ncbi.nlm.nih.gov" There are 36 article for serum albumin and dansyly glycine. Maybe you can try to find it experimentally.
869862
I dont understand what r u doing with "p*v/t"; but if assume ideal gas behavior, PV = nRT, so P = nRT/V [n is number of moles, R is ideal gas constant, T is temperature, V is volume of the flask, P is the pressure]
342141
ok well, the equation is balanced so you need equal moles of Ag and Cl to make the products. They give you the concentration and volume of Ag, so you can find the amount of moles by multiplying 0.104mol/L * 0.0272L = 0.0028288 mols of Ag. so 0.0028288 mols of Cl were there originally. and you have the volume of water, so you divide moles by volume and you get the concentration. 0.0028288 mols/0.025L = 0.113152 M. \n\nanother way to do it is the easy way, use c1v1 = c2v2. you have c1 = 0.104M, v1 = 27.2mL, v2 = 25mL, so you can find c2. you dont have to worry about units in this case so its easier. \n\nhope this helped. let me know if u need more help. laterz
961485
1 V\n2 C\n3 vc\n4 vc\n5 c\n6 c\n7 v\n8 vc
837288
Use the formula M1V1=M2V2\n\nThat is the first Molarity times the first volume are equal to the second Molarity times the second Voume.\n\n.2098M x70mL = .662M x V2\n\nSolve for V2.\n\n(.2098 X 70)/.622 = V2\n\nV2 = 23.61mL NaOH to titrate the solution to neutrality.
397497
I would use the ideal gas law...more specifically...the combined ideal gas law...\n\nP1*V1/T1 = P2*V2/T2
961793
Call it (CxHyOz)\nMass of C = 12x\nMass of H = 2y\nMass of O = 16z\n-----------------------\nIts molecular weight M = 12x + 2y + 16z = 90\n\nPercentage of C: (12x / M) *100% = 26.7% <-> 12x = 90 * 26.7 / 100 <-> 12x = 24 <-> x = 2\n\nYou can do the same with H and O to find y = 2 and z = 4.\n\nThe formula is, hence, C2H2O4.
282912
By serum protein electrophoresis, or by subtracting Serum albumin value from serum total protein value
265173
You are correct using the formula:\n\nC1*V1 = C2 * V2\n\nwhere C is the concentration and V is the volume.\n\n\nNow, you know that you want a concentration of 0.39M solution of NaCl in a 100 ml sample.\n\nSo, the equation should read:\n\n0.82 * V1 = 0.39 * .1 L\n\n0.82*V1 = 0.039\n\nV1 = .047L\n\nso, take 47 ml of the .82M NaCl and dilute it up to 100 mL.  That will give you the 0.39 M NaCl.
844758
Using the Michaelis-Menten equation.\n\nMore details on teh attached link\n\nhttp://www.le.ac.uk/by/teach/biochemweb/tutorials/michment2print.html\n\nGood luck
755177
1. Make sure that HCl is standardized.\n2. Write the balance equation:\n\nCa(OH)2 + 2HCl ---> CaCl2 + 2H2O\n\n- this means that 1 mole of Ca(OH)2 reacts for every 2 moles of HCl\n\n3. Get the number of moles of HCl reacted by multiplying the volume used to react Ca(OH)2 by the actual concentration of HCl (value from standardization). Divide the result by 2 - and this is now your moles Ca(OH)2.\n\n4. Get the molar solubility of Ca(OH)2 by dividing its number of moles by its volume. Unit is in gram per liter.
778184
PV=nRT\n\nn is doubled.\nT, V same.\nR is constant\n\n=>P has to be doubled to validate the eqn.
524296
in C1:\n=A1*b1-b1\n\nin E4:\n=if(Upper(D4)="L",C4,if(Upper(D4)="W",B4,"D4 not L or W"))\n\nin A5:\n=E4+2\n\nIf I have understood correctly...\n\nJeez! my answer was truncated!  Here is is so that you can see it but don't include the linebreak!\nin E4:\n=if(Upper(D4)="L",C4,\nif(Upper(D4)="W",B4,"D4 not L or W"))
983043
A=ebc\n\nWhere A is absorbance (no units, since A = log10 P0 / P )\n\ne is the molar absorbtivity with units of L mol-1 cm-1,\n\nb is the path length of the sample - that is, the path length of the cuvette in which the sample is contained. We will express this measurement in centimetres.cm\n\nc is the concentration of the compound in solution, expressed in mol L-1\n\nNow, you know why there is no unit for "A".
178984
To do this, you need to employ the ideal of PV=nRT.  You have the values for P, V, R, and T.  Plug those into the equation to find moles.  Then, plug the number of moles in with STP values, and solve for Volume at STP.  That's it.