what is 54 farenhight in degress?
435595
54 F = 12 Celcius (which is also 285 Kelvin)\n\nFrom Fahrenheit to Celcius subtract 32 and then devide by 1.8.
394628
P = 2l +2w\nP>54 = 2(12) + 2x\n54 = 24 +2x\n54-24 = 2x\n30 = 2x\nx= 30/2\nx =15\n\nso at least 15 inches such that perimeter should be equal to greater than 54
924813
(288^2)/(2*32.2) is the maximum height.\nat time 288/32.2 seconds\nit hits ground at time time   t+576/32.2, where t is obtained from\n45=288+.5*32.2*t^2
695797
Assuming that 0.5% means 0.5% of the way straight down, or 0.5% of 90 degrees = 0.45 degrees, and that gravity is neglected due to its insignificance over that short a time, and that 90 mph = 132 fps,\n\nx = 132t cos 0.45\ny = 5 -132t sin 0.45\n\nwhen x = 56, t is approximately 0.425 sec and y is approx. 4.56 ft
77127
50 K = -369.670040167004 F\n\n\nF= ((K-273.15)*1.8)+32
112740
Actually 56% is 56/100, then if you simplify it you will have 28/50 then 14/25 (each step divided by 2 if you prefer it slower)
98237
1) 29 and 31\n2) 41 and 43
736214
The first one is 29.16.  Divide 21.60 into 100 then multiply by 35, you get 7.56 and add that to 21.60 giving you 29.16
139385
Since the wavelength of green light is 530nm and  red light is 630nm (I'm generalizing),\nv = 0.17c = 0.17 × (3 × <10 to the 5th power> ) × (60 × 60) = 185 × <10 to the 6th power> kph.\nSo unless the fine is a percentage of one cent per mile per hour over the speed limit, it's gonna be steep.
738383
-0.217     0.1794     -0.32\n-0.5         0              -0.5\n-0.102     0.0256     0.0256
110772
0.58 (with a horizontal bar right above the 58)
159520
55m 450mm\n\nOk so I'm not a surveyor, but here goes. The slope is the "rise over the run". In this case, the rise is .450 meters and the run is 55m. So the slope is .450/55 = .008 meters.\n\nNow the "depression angle" -- well the slope is the tangent of the angle, so the inverse tangent of .008 should give you the angle. My calculator says about 0.47 degrees.\n\nBut again, I'm an electrical engineer, not a surveyor, so I'm not 100% sure these terms mean what I think they mean!
786456
a) 2900 * (54 + 0.29 v)\nb) 9 * 2900/v\nc) 2900 * (54 + 0.29 v + 9/v)\nv = 5.57
119984
there is 0.0254 in one inch.
707126
Congruency: f/L=h/H, where L=50, f=18, H=4.8, h=H*f/L=1.728 cm is image’s height;
600668
If it is 0 deg Centigrade i.e. 32 deg Farrenheit and double the cold i.e. 16 deg F mening -8.9 deg Centigrade
304646
According to the data given\nv= 340 m/s\nf = 28 waves.sec,\nv=fλ \n340=28λ\nAnd Hence\nλ=12.14 m to .08 m