Simultaneous equation?
450302
3y+2x=12\n2x=-3y+12\nx= -3/2y+6\nx=-3/2(x-1)+6\n =-3/2x-(-3/2)+6\n = -3/2x+15/2\n5/2x=15/2\nx= 3\n\ny= -3/2y+6-1\n5/2y= 5\ny= 2
896553
4x^2+8x-x-2\n(4x-1)(x+2)
279825
I'll assume that you're looking for a solution to the system of equations, or an ordered pair which solves both equations at the same time.  Solving both equations for y tells you that y=(x-5)/2.  In other words, it is the exact same line.  When we have the same line in a system of equations, it is known as coincident lines, which means that there is an infinite number of solutions to the system of equations.
881909
No, I don't think you are right.  I assume this is a system of simultaneous equations and you're trying to find a solution set.\n\n4x - 12y = 5\n-x + 3y = -1\n\nFirst, multiply the second equation by 4 on both sides, giving\n\n4x - 12y = 5\n-4x + 12y = -4\n\nNext, add the two equations, giving\n\n4x-4x +12y -12y = 5 -4\n0x + 0y = 1\n\nThere are no solutions (x,y) for which this is true, so the solution set is the empty set.\n\nTaking the solution set you've determined, (5,0), putting that into the first equation gives\n4*5 -12 * 0 = 5\n20 -0 = 5 or 20 = 5, which is not true, so (5,0) cannot possibly be a solution.\n\nYou've made several errors, as follows:\n\n4x-12y=5  OK\n-x+3y= -1 OK\n\n-x=3y+-1 NO!, should be -x = -3y + -1 or x = 3y +1\n4(3y+-1)-12y=5 OK\n12y+-4-12=5 NO!, should be 12y -4 -12y = 5 or -4 = 5 \n0y=1 I have no idea how you got this\ny=0 NO!, if 0y =1, y is not 0, there is no y such that 0y =1\n-x=12y+5  I have no idea how you got this\n-x=12(0)+5 I understand how you got this, but y does not equal 0\n-x=0+5 OK\n-x=-5 previously you had -x = 0 + 5 , which was wrong but if it was right, you should get x = -5, not -x = -5\n\nOMG
589722
Step 1: Solve one equation for one variable in terms of the other.\nStep 2: Plug that into the other equation and solve for the second variable.\nStep 3: Plug the second variable into the first equation and solve for the first variable.
464039
Your equation would be:\n\n= ((1/p) - (1/q))/(1/pq)\n\n= ((q - p)/pq) * pq\n\n= q - p\n\nHope I am clear.
1172866
this can be a problem to you if you don't know anything about simultaneous equation or if u don't know how to form simultaneous equation. another thing is u should at  least have an  idea about chemistry. look\n  \nm1v1+m2v2=MV.............1\nm1+m2=total volume after dilution=150Lt..............2\n now\n              take m1 is the initial conc of saline soln=32%=0.32\n                   ''  v1                      volume                 =?\n                 m2 is the conc of water =0\n                 v2 is the volume of water =?\n               M is the final conc of the soln = 20%=0.20\n                V is the final volume of the soln obtained after mixing=150Lt\n\nnow\n             0.32v1+0*v2=0.2*150......................1\n\n             v1+v2=150.................2\nfrom eqn 1\n                      0.32v1=30\n           so v1= 93.75Lt's\n   so the remaining amount is of water\n                v2=150-93.75=56.25lts\nso you need 56.25litres of water and 93.75litres of 32%saline to prepare the solution you need.\n\nif you have these solution just try to mix at that proportion then u will tell me.
679588
Multiply it out...\n2y+6y+24x-24y-6x\nThen combine\n-16y+18x OR\n18x-16y
531205
2 + 2 = 4\n\nthats all I got
697874
Multiply or divide all components in one question to set the variables in the opposite questions to cancel out if you added the two problems together by combining like terms. For example:\n2x + 3y = -13  and 4x + y = -1\n\nTo keep this simple I will multiply all the components of the 2x + 3y = -13 equation by negative 2, resulting in:\n\n-4x - 6y = 26\n\nThen add the new equation to the other equation 4x + y = -1\n\n-4x -6y = 26\n4x + y = -1\n----------------\n0x -5y = 25  which simplifies to y = -5\n\nInsert the value found for y back into one of the original eqations and solve for x\n\n2x + 3(-5) = -13\n\n2x + -15 = -13\n\n2x = 2\n\nx = 1\n\nYour end result is x =1 and y = -5
159612
Multiple the first equation by two\n-10x-8y = -22\n10x +y = -6  (second equation)\n\neliminate x\n\n-7y = -28\ny = 4\n\n10x + 4 = -6\n10x = -10\nx = -1
60599
This is not an equation.  Its garbage.  Both side of the equation have to equal each other.\n-35=.000075 this does not compute
990847
isolate the variable\n\n-7x+1+8x=x+1\n-7x+8x=x\nx=x\nx=1\n\nthe answer is c) 1\nnow give me 10 points please!!!
908374
Okay, the goal for solving simultaneous equations is to isolate one variable, so rearrange one of the equations (it doesn't matter which one) until you get either x or y alone on one side.\n\n5x - 2y = 10\n5x - 2y + 2y = 10 + 2y (if you do something to one side, do it to the other)\n5x = 10 + 2y\n5x/5 = (10 + 2y) / 5\nx = (10+2y)/5\n\nThen, plug this new value for x (the right side of the equation) into the other equation, hence the "substitution."\n3x + 2y = 6\n3 ((10+2y)/5) + 2y = 6\n(30 + 60y)/5 + 2y = 6\n6 + 12y + 2y = 6\n14y = 0\ny = 0\n\nNow, solve for x by substituting this y value back into one of the equations.\n\n5x - 2y = 10\n5x - 2(0) = 10\n5x = 10\nx=2\n\nSo, x=2 and y=0
408554
yes. take out an x \nyou answer should be x(x+3)
561262
u jammed the equation together.\ndo u mean\n6x^3 + ( 6/x - 2 * x^2 - x/3x2 - 3x + 3)\nits really hard to see ur question. can u write it out with spaces...\nhurry up i am waiting... lol
724411
Sure...\n\nfirst we want to combine like terms on each side of the equals sign.  Think of the equals like the balance point on a scale... you can do anything on one side as long as you match it (keep it balanced) on the other!\n\nso we want to combine the variables and the constants...\n\n8a - 3a + 4 = -a -4 + 2\n5a + 4 = -a - 2\n\nnow we want all the variables on one side, and constants on the other:\n\n5a -(-a) + 4 - 4 = -a-(-a) - 2 - 4\n5a + a = -2 - 4\n6a = -6\n\nnow we just divide by 6 to get a alone:\n\n6a/6 = -6/6\na = -1\n\nHope this helps! :)