What is the firing velocity of a 9mm bullet?
449616
Some Googling says that a 9mm bullet weighs about 8 grams (convenient!) and has a muzzle velocity of about 360 m/s.
1159509
It is fairly easy to silence a firearm but understand you can truly only silence a bullet that is traveling less than the speed of sound.  Any bullet traveling faster than that has it's own sonic boom which sounds like a crack down range.  That you cannot silence.  Sub-sonic cartridges are designed for slower velocities which will allow for true silencing.  At sea level, I believe the speed of sound to be around 750 miles per hour which translates to ~1100 feet per second.  The rest of the answers are true enough... just like adding a muffler.
711377
Bound's hubby here: \n\nThe name or designation given to a cartridge identifies two pieces of critical information about the cartridge: the bore diameter of the projectile and the name of the cartridge. It is kinda like shopping for a suit: business versus leisure, wide lapel versus narrow lapel, or single breasted versus double breasted.\n\nThe number represents the diameter of the bullet. That is the easy part! Bullet diameters can be identified by decimal diameter (.22, .25, .27, .28, .30, .32, .33, .35, .40, etc.) or by the metric diameter (5.45mm, 6 mm, 7mm, 8mm, 9mm, 10mm, 11 mm, etc.). Sometimes, if the diameter is metric, it will suggest the cartridge is of European origin, but not always the case.\n\nThe name will indicate two things: the designer/originator of the cartridge, and whether the cartridge is a magnum or not. Each cartridge design is unique, and is intended to exploit the cases volume which can affect the powder burn rate. Generally, cartridges of the same bore diameter and different designer are not interchangeable ... to do so (if the cartridge fits the chamber of the rifle) could be courting disaster.\n\nGenerally, you want to select a rifle and cartridge adequate for the game you are hunting. You can use the game and cartridge selector (linked below) to help in your cartridge selection!\n\nGood luck!
923444
Short Answer: \n\nvert comp = .161 meters\nhori comp = .936 meters                        \n\nLong Answer:\n\nMb=mass of bullet\nMp= mass of pendulum\nv=velocity of bullet\ng=9.81 m/s/s\nh=vertical displacement\n\n\nBy conversation of momentum:\n\nmomentum of pendulum with bullet=momentum of flying bullet\n\nsqrt(2*g*h)(Mb+Mp)=Mb*v= (28/1000)*230=6.44 \n\nsolving that you can find h=0.161 meters\n\n\nBy the distance formula:\n\nsqrt(2.8^2+0^2)=sqrt( (2.8-0.161)^2 + (horizontal position)^2)=2.8\n\nsolving that you can find horizontal position = 0.936 m
389111
depends what you talking about. It can be in either inches or mm  There are other means of Caliber (see below)
282533
Muzzle velocity is the speed of a projectile leaving the barrel of a gun.\n\nMeasured in feet per second. \n\nIt is used as a comparison between similar projectiles, such as ammunition for a gun.
484626
Any question you can ask in the realm of handgunning will generate a host of opinions -- none of which may be the same.  The 9mm is a fast round but may overpenetrate in the area of self defense but this may happen if you use a + P load in 38 caliber.  I usually carry a 357 revolver (which of course also fires 38's) since I don't have to worry about a safety if I have to use it.  For a long time the 38 was the preferred round by many law enforcement agencies before the 40 and the 45 ACP came into favor.  The drawback for the 38 is it is primarily a revolver round while the 9mm is used mainly in autoloading pistols.  It is also used by the NATO forces.  Many people like the idea of having 10 or more rounds that can cycle through and fire quickly as is the case with the 9mm -- assuming your pistol doesn't jam!  With a 38, you are limited to 5 or 6 rounds from a revolver and your ablity to reload quickly with a speedloader you trust and are proficient in using.  As far as stopping power, both are fine rounds and vary according to what kind you get (higher pressure +P loads, jacketed hollow points, etc.) and where you place the shots.  Both are fine rounds for out on the range.  If either round hits a person, I doubt it will tickle!  Both have been around a long time, since about 1902 and are among the most common cartridges made so finding ammo in either caliber is easy no matter where you go.  I think both are fine rounds, as I have fired both.  The recoil of both is about the same in my opinion.
887139
Momentum is the direct result of the following Newtonian Law of Inertia\nAny object in motion remains in motion and any object at rest remains at rest (unless a net force acts upon the object)\nMomentum (p) is the mass (m) of the object times its velocity (v).\np = mv\n\nForce (F) and Newtons Second Law can be derive from a change in momentum.  That is (t is time)\nF = delta p/delta t \nF = delta (m*v) / dt\nwe usually say m is constant so\nF = m * v/dt\nF =  ma    (a is acceleration or a change in v/time)\n\nNewtons third law is also based on momentum.  "For every action there is an equal, yet opposite, reaction."\n\nSo...  When a gun is fired what we see is the bullet propelled forward and the gun (and gun holder) propelled back.  Both received the same Force but because the gun and person holding it are much more massive than the bullet, the bullet will travel much faster. \ne.g F1 is the force on the bullet which is the same as the force on the person F2\nF1 = F2\ndelta p1/dt = delta p2/dt\nm1v1/dt = m2v2/dt\nm1v1 =m2v2\nImagine the bullet is 1 gram and a 180 lbs (~8182 grams) person shot the bullet...  The avg v on the kick back will be about 1/8182 of the v of the bullet...  Lucky for the shooter.
651389
While I don't discuss whether or not I have any other weapon than a Peacemaker, I wouldn't carry under a 9mm Luger, But I prefer the .45 ACP round, because if I would ever have to drop a bad guy or a mountain lion I want them to stay down.  That being said I would think the .357 mag would do about the same, since I've never compared the ballistics
965199
Firing the weapon vertically...\n\nV^2 = Vo^2 + 2gh\n0 = 600^2 + 2(-9.81)h\nh = 18.348 km ; where h is the maximum height reached by the bullet\n\nThe work done by firing this bullet to reach the max height is...\n\nW = mgh\nW = (5 gf) (9.81 m/s^2) (18.348 km)\n\nBTW, 5 gf? What the fcuk is that? I'll just assume this as 5 grams.\n\nW = 900 N-m or Joules\n\nPower is the rate of doing work. Power therefore is equal to...\n\nP = W x bullets fired per min.\nP = 900 x 250 bullets / 60 secs\nPower = 3,750 Joules per sec or watts.
365737
Assuming you fire parallel to the ground, then the bullet will be at its maximum horizontal velocity when it leaves the barrel, and will be at minimum vertical velocity.  The bullet cannot increase in horizontal speed once it has left the barrel, as there is nothing to make it accelerate.\n\nDue to air resistance, the horizontal velocity will decrease as the bullet travels further and further.  The vertical velocity will increase, as the gravity of the Earth "attracts" the bullet.
821414
The bullet's vertical motion is governed by the vertical forces only and not governed by horizontal and vice versa.\nIn each case the bullet's vertical motion is governed by gravity acting on itself. The gravity force gives an acceleration of 9.81 met/sec squared. Both have the same distance to go through and both have a initial vertical velocity of 0. Therefore they both reach at the same time, neglecting air friction.
944006
a) Initial velocity, u , of the bullet as it hits target=1200m/s\n    final velocity, v, as it emerges =850m/s\n    distance traversed,s = thickness of target\n                                   =30cm\n                                   =0.30m\n\nv^2-u^2=2as\n\n850^2-1200^2=2a*0.30\n722500-1440000=0.6a\n-717500=0.6a\na=-717500/.6\n  =-1,195,833m/s^2\n\nv=u+at\n\n850=1200+(-1,195,833)t\n1,195,833t=1200-850\n               t=350/1,195,833    \n                =2.93*10^-4  s\n\n              \nb) F=ma\n mass of bullet, m=25grams or 0.025kg\n\nF=0.025*1,195,833\n  =29,896N\n\nc)Initial momentum of bullet=25*1200\n                                         =30,000\nInitial momentum of target=350*0\n                                          =0\n\nFinal momentum of bullet=25*850\n                                         =21,250\nFinal momentum of target=350v\n\nBased on conservation of momentum:\n\nInitial momentum of the system=Final momentum of the system\n\nSubstitute known values:\n\n30,000+0=21,250+350v\n350v=30,000-21,250\nv=8750/350\n  =25m/s
438210
It really depends on what you mean by "better".  A .45 will have more stopping power but it will be more expensive, harder to conceal and have a bit more kick.  The 9mm, being smaller, will be easier to conceal and have less kick and is generally less expensive (both the gun and the ammo) but it is considered minimal in terms of actual stopping power.  It will probably be adequate for most personal defense purposes, but there have been many police reports of criminals hit by a 9mm who go on fighting.\n\n(With regard to military use, noted above: there are many who object to the change which was made more to standardize with European allies in NATO than for any practical purposes.  The .45 was developed for fighting in the Phillipines prior to WWI where the original .38 round was not adequate to stop the suicidal Moro fighters.  The .38 has similar balistics to the 9mm.  Similar objections are made to the switch to the .223 caliber M16 from the .308 caliber M1.)
109907
You can look at the ballistics statistics or go to the manufacturer. it also depends on what distance you are wanting too look at.
729938
I prefer a 9mm\n\nCoach
1089941
SKU: item_120025  \nModel: SW9VE \nCaliber: 9mm \nCapacity: 10+1 Rounds \nBarrel Length: 4" \nFront Sight: Dot Front Sight \nRear Sight: Fixed \nFiring System: Striker \nGrip: Plastic Grip \nExternal Safety: N/A \nFrame: Large \nFinish: Two-Tone \nOverall Length: 7 1/4" \nMaterial: Polymer \nWeight Empty: 24.7 oz.\n\n\nNo External Safety !!!