Pre-calc math problem?
440729
Try this:\nAssuming the rectangle is centered within the half circle, draw a line from the center of the flat edge of the half circle (should also be the center of one edge of the rectangle) to one of the corners of the rectangle that is touching the edge of the circle.  That line has a length equal to the radius of 10.  By drawing this line you have also formed a 30-60-90 triangle inside the rectangle.  So, the triangle you have just created has a hypotenuse equal to 10 but the sides are unknown.  However, knowing that a 30-60-90 triangle has sides with a relationship of 1, 2, square root of 3, we use the method of similar triangles to  solve for the sides.  The shortest side of the 30-60-90 triangle is thus equal to 5 (this is also equal to the width of the rectangle), the other side is equal to 5*square root of 3 (the length of the rectangle will be two times this value), and the hypotenuse is 10. So the width of the rectangle is 5 and the length is 10*square root 3, so the area of the rectangle is 50*square root 3=86.6
1162372
120\nx.25\n------\n3000\n\n~~move decemal point over two places so the answer is 30.00 or can be written 30~~
909143
take out the x\nx(a-b)=6\nx=6/(a-b)
1136463
It's been a while since I had calculus, but I think it's something like this:\n\nYou'd have to take the integral from 0 to k (treat k as a constant). When you have that, take that value (which is equivalent to the area) and set it equal to 3. Then, algebraically, solve for k.
838481
Well hey, you need help, ask the teacher! I know how to do this, with help from my nerdy Calculus BC friend, but it's really not that hard once you think about it...
1110742
12 simply place the 1 where the x is\n\n(1+3)(1+2)\n4*3\n12
715412
The - before the parenthases negates the signs of whats in there.\nx-(4-x)=0 becomes x-4+x=0 \nAdd the 4 to both sides and add the x's together.\nx-4+x=0 becomes 2x=4\nDivide both sides by 2.\n2x=4 becomes x=2.\nTo check plug the 2 in for x.\n2-(4-2)=0 becomes 2-2=0
60538
if [ -7x + x^2 =0 ]\nthe you will get y = 7/x
780960
I also have difficulty typing this thypes of math problems.  First, simplify the ax^2+bx+c parts in the first half to (x+c)(x+c) looking things first.  So...\n\n[(x-3)(x-1)]} is the first part.  With the bottom of the second half, divide by 3, so that you get 3(x+1).  Now line everything up like so...\n\n(x+1)(x+3)(x-3)\n_____________\n3(x-3)(x-1)(x+1)\n\nNow do the cancellations and you get the right answer...\n(x+3)\n____\n3\n\nSorry for not working to convention, but it was easier to type it that way.
233014
U R RIGHTT..HOW DID YA GET IT..PLZ CAN YA EXPLAIN..I'VE BEEN TRYING THIS PROBLEM FROM A LONGTIME.EVEN DE CALCULATOR SAYS ITZ "4"..I KNOW DE CALCULATORS WRONG TOO..PLZZ DO EXPLAIN IT TO ME ASAP
101082
(x-1)/4 > 3\nx-1 > 12\nx > 13
875394
Very understandable....I just posted a question about my pre-calculus homework and i didnt ask for the answer, i just need help finding how to get it....i'd like to know how to do it myself, i dont just want someone to tell me the answer....does me no good @ all!
146354
x square-12x-85\nI think?
615045
[x/(x+2)]\n= [1/(1+(2/x))] --- divide the numerator & denominator by x.\n\nAs x approaches +ve infinity, 2/x approaches 0.\nSo [x/(x+2)] approaches 1.
851464
that is a really simple question, so if you have a calculator you should be able to get it, otherwise, it is your homework and I refuse to give you an answer to your homework. I would actually HELP you to get the answer if you asked for HELP doing it.\n\n-EA
1020883
i am sure you can find a math tutor that will be happy to help you when you explain what the problem is.\n\nso what IS the problem, anyway?
622612
Joel, you need some help.  This is one of the easiest questions I have ever heard!  You should know this, man!  You're gonna fail your test if you keep cheating on here and don't actually figure out how it works.  Good luck, brotha'\n\nL = -2 or L(x) = -2