How much does the Earth weigh?
441441
Be careful not to confuse the concept of weight with the concept of mass. The Earth's weight would depend on the acceleration due to gravity (Here on Earth we call it 'little g' and it's 9.8 m/s squared) on the enormous planet with a huge bathroom scale that you could set the whole planet Earth on. The Earth's mass doesn't change (except for increasing steadily due to cosmic dust accumulation) when you move it from gravitational field to gravitational field.  Likewise your weight changes when you walk on the moon, but your mass stays the same. It's the different acceleration due to gravity  (The moon's instead of the Earth's) that changes your weight.
39089
75 newtons (around 17 pounds)....the moon's gravitational pull is only about 1/6 that of earth.
1149852
Black holes contain mass which, when in the presence of a gravitational field (presumably other than its own), has a weight.  This weight would depend entirely upon the mass of the black hole, of course.  The question would be the equivalent of asking, "How much does Earth weigh?"  Well, how much does it weigh when its mass is placed upon what, Earth?  (Typically, this is what is assumed, so:  Yes.)\n\nAs an example, the (presumed) black hole in the Cygnus X-1 binary is estimated to be from 7 to 13 solar masses, placing its "weight" (if weighed on Earth) anywhere from 1.4x10^31 to 2.6x10^31 kilograms.
175307
The garden mole weighs about 250 grams. Multiply by Avogadros number 6x10^23 to get 1.5x10^23 kg. The mass of the earth is 6x10^24 kg.\n\nA mole of moles is therefore only 2.5% of the mass of the earth.
407850
If one could actually weigh the Earth, the answer would be yes because the mass has increased over the past millions years due to falling of metorites onto the Earth's surface. I forget how many metorites fall onto the Earth each day but it is in the thousands. Most burn up in the atmosphere, but the atmosphere is part of the Earth and the resulting material is added to the balance of the mass.
924812
The mass of the sun is 330,000 times that of the earth. It is about half again as dense as water.
59746
the sun weighs approximatly 2.0 * 10^30 kg\n\nto abisdad2004's answer i believe the site has a typo, they probably meant to the 30th power
406753
The average radius of the Earth is about 6378.1 kilometers, or abnout 6378100 meters.\nCompared to this, a few hundred meters doesnt make a significant difference.\n\nFor reference, the mass of the Earth is about 5.9742 E24 kilograms.\nG = 6.67 E-11\n\nThe gravitational acceleration on the surface of Earth (r = r_E = 6378100 m) is,\ng = G*M / r^2 = about 9.795 m/s^2\nIs the object is now 1 km above the surface of Earth (1000 meters higher), the gravitational acceleration is about 9.792 m/s^2, just .003 m/s^2 smaller, barely noticible.
86906
Check this site out,\nhttp://www.onlineconversion.com/weight_on_other_planets.htm\nand/or this one,\nhttp://www.daviddarling.info/encyclopedia/W/weight.html
975661
Depending on which reference you go by, it is in the vicinity of 6.0 X 10^24 kilograms.  \n\nSince, 1 kilogram = 0.00110231131 short tons we can say that the earth weighs approximately 6.61386787 x 10^21 short tons.
787952
The force of attraction is given by Newton's law, F = G* m1*m2/r^2, where G = universal gravitational constant, 6.67 * 10^-11 N*m^2/kg^2.  You have the two masses, and the radius of earth is the distance r.  Your weight is the same as the gravitational force.
948
33.3 lbs\n\nThe moon's gravity is 1/6 that of earth.
620070
On earth 9.8N = 1kg, but that is just because the earth's acceleration due to gravity is 9.8m/s².\n\nTo find the gravitational pull of the sun (like 9.8 for the earth) just use the formula g = GM/r², where G is the gravitational constant (6.67x10^-11), M the mass of the sun (1.9891x10^30 kg), r the radius of the sun (6.95x10^8m).
915700
Earth's gravity accelerates objects at a rate of 9.8 m/s/s.  G is the gravitational constant.  You can figure this out by dropping any object, measuring the speed it was moving when it passes a certain point, and how long it took.\n\nForce = G * mass1 * mass2 /distance^2 is the equation that newton came up with explain how gravity worked.\n\nSince the mass of an object on the earth that you would drop to measure this is so small, we can ignore it, so we end up with the equation of \n\n9.8 = (G * Mass of Earth) / (Earth's radius ^2)\n\nThe earth's radius is about 6,360 km.  Convert that into meters and you get 6360000 meters.\n\nThe gravitational constant is a tricky thing to figure out but some guy named Cavendish figured it out.  Read about it http://www.leydenscience.org/physics/gravitation/cavend.htm\n\nNow we know that G = 6.67 x 10^-11 m^3/kg/s^2 so now plug in all the numbers and you get\n\n9.8 = (6.67 x 10^-11 * Earth's Mass) / 6360000^2\n\n6360000^2 = 4.04496 x 10^13\n\nso \n9.8 = (6.67 x 10^-11 * Earth's Mass) / 4.04496 x 10^13\n\nWe want to get Earth's Mass on it's own side so multiply both sides by 4.04496 x 10^13 and you get:\n\n4.04496 x 10^13 * 9.8 = 6.67 x 10^-11 * Earth's Mass\n\nDivide both sides by the gravitational constant of 6.67 x 10^-11 and you get \nEarth's Mass = (4.04496x10^13 * 9.8)/ 6.67 x 10^-11\n\nPlug that all into a scientific calculator and you get for the Earth's mass about\n5.94311964 x 10^24 kilograms\n\nAnd that's how they did it back in the 17th century.  Heh neato I figured out the mass of the earth.  Never did that before.
101436
The mass of the Earth is roughly 5.9742 E24 kilograms.\n\nWhy the need for such an accurate number?
781957
Approximately the mass of 2 billion solar masses.\n\np.s. Weight is a function of something in a gravitational field, what you really are asking about is mass.
1041394
Actually, the term "weight of the earth" has no real meaning.  The mass of the earth can be calculated, but weight and mass are not the same thing.  Weight is usually used to express the apparent mass of an object in the Earth's gravitational field at the planet surface.  To speak of the Earth's weight is to try to speak of the Earth's apparent mass in relation to itself and its own gravitational field.  It's like asking how far a point is from itself.  It has no meaningful answer.  If your science teacher put this question to you in terms of weight instead of mass, they should go back to coaching PE or something.