Question about TI-89 Titanium graphing calculator- How do you switch to the polar coordinate system?
443117
well ive got a TI-83, but i don't think there'e much differnce b/w the two\nI think you go to "mode" and find "Pol" click enter and uve got it.
30751
The Edifier has it right, but darned if I can follow the notation. You really need to see this written out like a textbook to understand what's going on.\n\nClick the link below in "sources" to see the answer hosted at my website www.calculus-help.com. Right now, Yahoo! answers, as far as I can tell, doesn't allow graphics, which makes it tricky to answer ANY math questions.\n\nPlease don't post math answers, guys, if the poster knows the answer but can't get there, and you get something completely different.
51949
The cartesian coordinate system is the (x,y) system that we are used to using when plotting graphs and solving equations. Graphically, you move over x units horizontally and up y units vertically from the origin.\n\nThe polar coordinate system is the (r,theta) system which is based on circles rather than rectangles. The important thing to note is that r is a distance, whereas theta is an angle. Graphically, you have an origin and you move out r units horizontally and then you rotate by theta degrees. Usually take r>0 or r=0.\n\nThe two coordinate systems are connected by the simple equations:\n\nx=r*cos(theta)\ny=r*sin(theta)
713581
I am assuming that you are rotating about th z-axis so your new x-axis is rotated counterclockwise 45 degrees to the old x axis.  Call the new axes x2 and y2.  Call the original ones x1 and y1 than aof any rotation angle 'a' :\n\nx2 = x1 * cos(a) + y1 * sin(a)\ny2 = y1 * cos(a) - y1 * sin(a)\n\nFor your specific case where a = 45 degrees:\n\nx 2 = (x1 + y1)/sqrt(2)\ny2 = (y1 - x1)/sqrt(2)
380208
You got it dude, try there:\n\nhttp://www.ticalc.org/pub/v200/
1175462
Graph the equations. They should look like a big "U". The axis of symmetry is an imaginary line going right through the vertex and splits the graph in half. The point at where the axis crosses the x axis is what the axis of symmetry is. \n\nPlugging in is easy. make a chart for x. Now choose like 4 different easy values to put into the equation as x. 0,1,2,3. Use your calculator to find the answers, and make a separate side of the chart as y. the answers you get are your y's. Then you graph it. \n\nI don't have a calculator right now, so I'm leaving that to you.
997106
It is possible to numerically calculate integrals on an 83, but it takes the calculater some time because it literally adds up the area under the curve. You have to plot the function in the y =. Then press CALC (2nd TRACE), choose option 7, enter the lower limit, enter the upper limit. The TI-83 only does definate integrals.
940825
If this calculator has a data port. USE IT.\nTI sells USB/SERIAL cables that lets the user download software/text/OS updates straight to calc.\n\nhttp://education.ti.com/educationportal/sites/US/productCategory/us_connectivitycables.html
642641
please rewrite the formula in proper notation...i cannot tell where (x-10) is in relation to the argument of cos.\n\nis it y = 5 + 2*cos[pi/4*(x-10)]\nor y = 5 + [2*cos(pi/4)]*(x-10)??\n\nOk, here you go.  Since cos is 2pi periodic, then the argument will be 2pi periodic where, 0<pi/4*(x-10)<2pi, or\n0<x-10<8.  Which means for every time you add 8 radians to x, you will be at the exact location on the unit circle that you started.  Therefore, you are getting correct values for x (9.2936, 10.7064, etc.),but the question asks for the FIRST positive values.  Subtract 8 from each of your answers until you are at the lowest possible positive number.  (In this case you only subtract 8 once.)
831652
you've got your four quadrants\n\n1st: x-y axis plus plus >>>>>> plus\n2nd; negative plus>>>>negative\n3rd; negative negative>>>plus\n4th; plus negative>>>negative\n\nfor trig;  all,sine,tan,cos\n\ni hope that this helps
824139
All you need to do is enter these on a scientific or graphing calculator.  Make sure it is in degree mode.  For the second part use the 2nd or shift button to get sin^-1 etc
405955
If you are reflecting across the y axis, x becomes -x.\n\nIf you are reflecting across the x axis, y becomes -y.\n\nIf you are reflecting about the origin, both x and y change sign.\n\nIs that what you are looking for?
765813
There's a pretty good online grapher at http://id.mind.net/~zona/ezGraph/ezGraph.html that you can use.  It works basically like a graphing calculator.\n\nIt appears this function should be an upside-down sign curve with an amplitude of 10 and a vertical shift of 9, which means the center of the graph will be at 9, it will go up to 19 and down to -1.  It's not 100% clear what you mean by what you have written after sin.  If you mean the sine of 2pi/15 times x (since the minus zero is irrelevent), you would have a period of 15, so you'd complete 1 complete cycle at 15 radians; the halfway point would be 7.5 radians.
179147
ur ques should be\ny = sq root x + 8 ryt?\nknow i leave it to u to find the grapg of the sq. root func ok\ntalking about the translation, c lets take y = sq r x\nnow when x = 0 then y is also = 0\nbut now if we add 8 to it ie y = sq r x +8, then at x = o y=8\nthats the trtanslation\nthat means the whole graph shifts by 8 unit on the +y axis
816872
Best to plot this on a piece of graph paper; "+i" is  to the right' , "+j" is upwards, "-i" is to the left, "-j" is downwards, all with respect to the origin.\n\n1. Draw the vectors on the graph paper. "u" is in the second quadrant (i is neg and j is pos). "v" is in the fourth quadrant, with (i is pos, j neg) . There are two answers to this question, since you could go from u to v or from u to v in the opposite direction. I always take the angle from zero to "u" and add it to the angle from 0 to "v".  For "u", the tangent of the angle to the vertical axis is 1/4, then angle = 14%. So the angle from zero degrees to the vert axis = 90, and "u"s angle from zero degrees is 90 + 14 = 104 degrees. For "v", the tangent of the angle to the horizontal axis is 4/3 = 1.333.. and the angle = 53 degrees. Therefore the angle from "u" to "v" is 104 + 53 = 157 degrees. (the other answer is 360 degrees - 157 degrees = 203 degrees if you rotate in the other direction).\n\n2. Again use graph paper. 240 degrees is 30 degrees less that 270 degrees (the vertical axis, down) draw a line 10 graph units long. It will be in the third quadrant where i and j will both be negative. At this point you can use a polar to rectangular converter, or do it by hand. By hand: the i side of the triangle formed with the down axis can be found by saying sin(angle) = i/10, and cos(angle) = j/10. The angle is 30 degrees (from vert downwards). so sin(30) = 0.5, and, cos(30) = 0.866; thus i= 0.5 and j = 0.866 (ignoring pos/neg). Since the vector is in the third quadrant, both i and j are negative.\nAnswer = -0.5i -0.866j\n\nHope this helps!
728902
This can be done easily using a scientific calculator or there are many angular / decimal tables in Trig text books or many machinists handbooks or machinists guides.\n\nwww.industrialpress.com/en/tabid/63/Default.aspx
96716
Turn it any number of degrees!\nMaybe you mean only 0 or 360 degrees, because the 'T' or 't' has no rotation symmetry.