4a^2b^3=8a^3bc???factor??
443950
Is the = really a minus?  If so, the GCF of each term is\n4a^2b, because the GCF of 4 and 8 is 4, and the GCF of variables has the lower of the exponents of each variable.\n\nDivide each term by this GCF (when you divide, subtract the exponents) and write the GCF outside () with the division answer inside (distributive property in reverse)\n\n4a^2b(b^2 - 2ac)
417593
no because 8n^2 - 72p^2 can still be factored\n8 is the common factor \n8(n^2-9p^2)\n8(n-3p)(n+3p)
168388
a^5b^5\nTo multiply numbers that have the same base, you add the exponents:\n\na4b2 x ab3= a(4+1) x b(2+3)= a5 x b5= a5b5 or a^5b^5
1045152
You want to basically simplify the expression through taking out a common factor of each term in that expression:\n\nso 4 goes into both 4a and 16\nso 4(a+4) I believe would be the correct answer. \nDon't get mad if I'm wrong.
661698
2b^4(4-3b)=0\n\nb=0\nb= (4/3)
709650
Go for it... ask some questions and I'll try and help.  However, be forewarned, I like to give people the *method* to solve a problem, so they can do it later on their own.  You will rarely find me just giving out answers.  Hope that is okay.\n\nIn your example:\n64 - 40ab\n\nThe best you can do is factor out a common factor from 64 and 40.  Both of these numbers are divisible by 8 (8 x 8 and 8 x 5)... that means you get:\n\n8(8 - 5ab)\n\nSince 8 and 5 share no further common factors, you can't factor them any further.  Also, a and b are only part of the second number, so you can't factor those...  the answer is:\n8(8 - 5ab)
786830
a(sqrt)8-3(sqrt)2a^2 =2a(sqrt)2-3a(sqrt)2                                      =(sqrt)2(2a-3a)=- a(sqrt)2
1099108
I think its 8a^4b^3+6a^3b^5-2a^3b^4
810076
11^(0.35+7) = 3 this is a contradiction\n\nx=3 is a solution but the rest is just a mess.\n\nDo you have any idea of what you are doing?
610613
In 6ab + 4a + 3b + 2, we group the first 2 terms and the last 2 terms:\n\n6ab + 4a + 3b + 2 =\n(6ab + 4a) + (3b + 2)\nthen factor out the common factor 2a in (6ab + 4a)\n(Note: to factor out is the same as dividing each term with the common factor)\n\nwe get:\n2a(3b + 2) + (3b + 2)\nNotice that in each term of the above we have a common factor of (3b + 2)\nBy dividing each term by (3b + 2) or factoring out (3b + 2) we have:\n(3b + 2)(2a + 1)
965399
8(w+4)=w^3+2w^2-8w\n<=> w^3 + 2w^2 -16w - 32 = 0\n<=> w^2(w+2) -16(w+2) = 0\n<=> (w^2 - 16)*(w+2) = 0\n<=> (w-4)*(w+4)*(w+2) = 0
924187
= 16ab/20ab^2\n= 4/5b // 16 and 20 can be reduced by 4, and an a and a b cancels out\n\n3*3*3*3*3 = 3^5\n3*3 = 3^2\n3^5/3^2 = 3^3\n= 3*3*3
503153
(x+7)(x+3)\n(x-11)(x+2)\nforget this one.  its AC factoring though\nthis ones AC too
827919
a = 0.5bc^2\n\n2a = bc^2\n\n2a/c^2 = b
1164229
(3c-3d)(4c-4d)\n=3c*4c -3c*4d-3d*4c+3d*4d\n=12c^2 - 12cd - 12cd +12d^2\n=12c^2 - 24cd + 12d^2 (you can stop here or continue like following)\n=12 *(c^2-2cd+d^2)\n=12 *(c-d)^2\n\nJust remember: \n\n1) (A+B)(C+D) = AC + AD + BC +BD\n\n2) A^2 - 2AB + B^2 = (A-B)^2\n\nGood luck!
508006
x^2 + 4bx + 2b=0\n(x+2b)^2 - 4b^2 + 2b = 0\n(x+2b)^2 = 4b^2 - 2b\n(x+2b) = SQRT(4b^2 - 2b)\nx = [SQRT(4b^2 - 2b)]-2b\n\n3x^2 -bx +1=0\n3(x^2 - (b/3)x + (1/3)) = 0\nx^2 - (b/3)x + (1/3) = 0\n(x-(b/6))^2 -(b/6)^2 + (1/3) = 0\n(x-(b/6))^2 = (b/6)^2 - (1/3)\nx-(b/6) = SQRT[b^2/36 - 12/36]\nx-(b/6) = [SQRT{^2 - 12)] / 6\nx = {[SQRT{^2 - 12)]+b} / 6\n\nb^2x^2 - 2bx + c^2= 0\n(bx)^2 - 2(bx) + c^2 = 0\n(bx-1)^2 - 1 + c^2 = 0\n(bx-1)^2 = 1 - c^2\nbx-1 = SQRT(1-c^2)\nbx = SQRT(1-c^2)+1\nx = [SQRT(1-c^2)+1]/b
271749
Yes.\n\n1.Let A = B\n\n2.Thus, by definition, A2 = AB (A2 = A squared)\n\n3.Add A2 to each side:\n\n2A2 = A2 + AB\n\n4.Subtract 2AB from each side:\n\n2A2 - 2AB = A2 + AB - 2AB, which in turn is the same as:\n\n2A2 - 2AB = A2 - AB\n\n5.Factor (A2 - AB) out of each side:\n\n2 (A2 - AB) = 1 (A2 - AB)\n\n6.Divide each side by (A2 - AB):\n\n2 (A2 - AB)    =    1 (A2 - AB)\n             _________        _________\n   (A2 - AB)    (A2 - AB)\n\n7.The result:\n\n2 = 1\n\nPS:  Obviously there is a clear logical error embedded in this. :)