please help, thank you..show work so i can verify answers?
449967
Hi! The name of the island suggests we should find the treasure using graphs! :)\n\nLet us assume first that point A lies on the west of point D. Consider the point A to be the origin. Thus point D will lie on the X-axis and the straight lines A-B and D-C would be parallel to Y-axis. Draw the graph on paper choosing an appropriate scale, say 1 cm=10 paces. In the solution, I'm finding the points as your REAL coordinates if you are on the island itself.\n\nWe've been given the distances BD, AC, AD; find the distances AB and DC using Pythagoras theorem. They come out to be 180 and 100 paces respectively. Since we took A to be the origin, the coordinates of point B are (0,180) and for C are (240,100). The coordinates of A and D are (0,0) and (240,0).\n\nHaving found the points B, D, A, C, we can now find the equation of the lines BD and AC using the Two-Point formula. They come out to be:\n\nline BD: y=(-3/4)x + 180\nline AC: y=(5/12)x\n\nThese two lines intersect at the point E. Find the point E by equating y in both cases. Then find 'x', and put it in any one equation to find 'y'. E comes out to: (1080/7,540/7).\n\nSince the road is the X-axis itself, the distance of E from the road is its' x-coordinate: 1080/7 paces ~= 154.28.\n\nHalf the distance from E to the road is 540/7 paces, approx 77.14 paces. So the treasure is buried at a distance of a little more than 77 paces and little less than 78 paces from point E towards the road.
158047
Pretty slick, RED\n\nYou came on pretending that "someone else" had a problem and even gave out a wrong answer on purpose.  Clever!\n\nI can see through that, you just wanted people to give you the right answer without giving you the whole "Do your own homework" speech.\n\nNice! Score one for you.  Unless, of course, I am giving waaaay too much credit for such an ingenious plan.  In which case, x=2, not 24.
958614
#1.)-----------------------------------\n  \n25b^ -20by + 4y^\n\nMultiply 1st and 3rd term together to get 100b^y^.\n\nFactor 100b^y^ into two factors whose sum = the middle term of -20by.\n\n1by   X 100by\n2by   X 50by\n4by   X 25by\n5by   X 20by\n10by X 10 by   ....................BINGO!\n\n-10by + (-10by) = - 20by   &   (-10by)(-10by) = 100by\n\nThis is a really kewl factor by grouping trick, I LOVE it!\n\nBring down the first term of: (25b^)\n\nNext, write the SMALLER of the two factors 1st.  Followed by the LARGER of the two factors.  In this case, they're both the same, so it doesn't matter which one goes first: (-10by)\n\nFinally, bring down the third term of: (+4y^)\n\n25b^ -10by -10by + 4y^\n\nNow, lets factor by grouping! \nFactor out the GCFs.\nGCF#1 = 5b\nGCF#2 = -2y\n\n(25b^ -10by) + (-10by +4y^)\n5b(5b - 2y) -2y(5b - 2y)\n\nGCF#3 = (5b - 2y)\n\n(5b - 2y)(5b - 2y)\n\nSimplifies further as: (5b - 2y)^   ....Whatdayaknow?! \n.......................................................................................................It's a Perfect Square Trinomial.\n\n#2.)------------------------------------------------------------------\n\n100 - 9b^\n\nAh, the difference of two perfect squares.\n\n---------------------------------------------\n\nFORMULA:\na^ - b^ = (a-b)(a+b)\n\n---------------------------------\n\nSOLUTION:\n100 - 9b^\n(10)^ - (3b)^\n\n-----------------------\n\nANSWER:\n(10-3b)(10+3b)
1099389
try searching for other questions which have the answers.  man, i've seen this question thousands of times, makes me wonder if its from the same person or homework
903092
1) b)\n\n2) [H2O]^2 / 2[H2] [O2]\n  \n   [NO]^2 / [N2] [O2]\n\n3) b)\n\n4) b)
16382
See Answer 4 on the source page below
1132233
this question will require calcs using logarithm.\nhence will take time
443281
1.) A - 0.6666666\n2.) C - $12.26\n3.) B - 0.308\n4.) C - 19.87\n5.) A - $.65
898860
First one: d= - 1\n\nEDIT: the rest I'm too lazy to do. Do your own homework! =D
932261
hey there is a good website to check your work \nits www.webmath.com i use it all the time
919714
If you can't find the answers online then you're not looking very hard.  I typed #6 into the Yahoo search bar and I got a bunch of explanations.  Do your homework, you might learn something.
247689
Use analytical trig (hint: sin function).  That should give you the answer you are looking for.
849743
This is the third time that this question has been asked!?!?!\n\nIt's a tough one, too.\n\nI'm taking it to work with me and asking my colleges to help me out on it.\n\nBut someone "did" crack this CHALLENGE Question.\n\nSo here's the answer. . .\n\nhttp://answers.yahoo.com/question/index;_ylt=AvnsMpyNhtwrHV1JVMvXrE4jzKIX?qid=20061130045858AAB57A7\n\nANSWER:  ABCDEFGHJ = 25,693,148\n\nA=2\nB=5 \nC=6\nD=9\nE=7\nF=3\nG=1\nH=4\nJ=8
534750
1/2 + 1/2b + 2b^2 + 6bc + c^2\n\n(1/4b)(1/4b) + 4bc + (bc)(bc)\n1/2 + 1/4b +1/4b + b^2 +4bc + b^2 + c^2 + 2bc\n1/2 + 1/2 + 2b^2 + 6bc + c^2\n\nI think this is right... email me if I'm wrong?
863581
You have a couple of typos, I think.  As for the "proof", dividing by x - y is dividing by zero.  That is a no-no.  (In other words, a * 0 = b * 0 does not imply a = b.)
58231
http://www.studentquestions.com/homework_ans/4244.html
305859
Do your own homework - I did mine already.  ;o)