what is the perimeter of a trianglewhich sides measure 6,8,and 10inches?
448522
Are you serious? 6+8+10=24
598751
L=length w=width\n\nSo L=3w\n\nThe formula for perimeter is 2L+2W=P\nNow, you just plug in the variables and solve\n\n2(3W)+2W=64 --multiply 2 time 3W\n6W+2W=64    --add 6W and 2W\n8W=64    --Divide 8 on each side\nW=8\n\nWidth is 8 units\n\n--hope that helped
845226
If the square has an area of 36 sq. units, then each side is sqrt(36) or 6.  This means that the common side of the triangle is 6 units.  Since it is an equilateral triangle, then all three sides are 6 units, so the perimeter of the triangle is 6 * 3, or 18 units.
678410
Let y = the length of the base and x = the length of one of the equal legs.\nThe perimeter is the sum of all of the sides, so \nP = x + x + y or P = 2x + y\nThe leg is 8 less than 4 times the base translates into\nx = 4y - 8\nNow\nP = 2x + y\n29 = 2(4y-8) + y\n29 = 8y - 16 + y\n45 = 9y\ny = 45/9\ny = 5\nYou're looking for the length of the equal legs, so you need to find x.\nx = 4y-8\nx = 4(5) - 8\nx = 12cm
906875
The trick is turning the word problem into equations.\n(Key: length = l; width = w)\n\nThey tell you the length is 3 feet more than twice the width, so:\nl = 2w + 3\n\nThen they tell you the perimeter (which is twice the width and twice the length) is 36, so:\n2l + 2w = 36\n\nYou should be able to take it from there.
1068661
Perimeter of the triangle multiplied by the height of the prism.
572270
triangle area = 1/2(height * width)\n\ncircle area = pi * radius^2
789618
a) 24 in.\n\nSince a square has four sides...  You must add six for each side (i.e. 6 + 6 + 6 + 6) to get perimeter.
897859
I find this an interesting question, and I suspect there are several possible methods for solving it.  However, I recommend we deal with it straightforwardly by solving for, say, the base length, height ... any 'variables' found within these polygons' area formulas.\n\nThe understanding here is that both polygons are regular polygons (the triangle is therefore equilateral, the hexagon has 6 equal-length sides, etc.).\n\nThe most creative solutions (and least mathematical) would probably involve cutting up one of the shapes and "re-gluing" it to form the other, thereby gaining some hint at the relationship between their perimeters.\n\nI normally prefer straight math, and would recall:\n\n A(triangle) = (1/2) base * height\n A(hexagon) = ([3sqrt(3)]/2) (side)^2\n\nBut let's "logic" our way through this one first.  Think of the hexagon as being composed of 6 equilateral triangles, each containing 1/6 of the overall area.  Because the original hexagon had an area in 1:1 ratio with the given triangle, we now can state:\n\n Area (SmallTriangle) = (1/6) (BigTriangle)\n\nRecalling a particular theorem concerning similar polygons ("The ratio of their areas will be the square of the ratio of their sides"), we can take this further:\n\n Ratio of BigTri:SmallTri Areas = 6:1\n\nSo,\n\n Ratio of BigTri:SmallTri Sides = sqrt(6):1\n\nPicture now how the small triangles would be "glued together" to form their parent hexagon.  Only the "outside side" would contribute to the hexagon's perimeter ... SIX such sides would be needed.  In short:\n\n Ratio of hexagon perimeter:BigTri perimeter = 6sqrt(6):1\n\nHope this (is correct and) helps!
434240
Generally, midpoints divide the lengths into half. So then, the whole perimeter of LMN is 1/2 of ABC. So the ratio is 1/2.\n\nYou can pick two CORRESPONDING sides, and their ratio is still 1/2. To find the area, there's a formula:\n\n(Side 1/Side 2)^2\n\n(One length of LMN/One length of ABC)^2\n= (1/2)^2\n= (1^2)/(2^2)\n= (1)/(2*2)\n= 1/4\n\nNote: one length of LMN doesn't have to be 1 and another length of ABC doesn't have to be 2. They can share common multiples, but you end up simplifying to ratio 1/2.\n\nratio of perimeter of triangles LMN to ABC is 1/2\nratio of areas of triangles LMN to ABC is 1/4
108321
The length is 10 miles and the width is 8 miles.\n\nOkay... this is what you do:\n\nLet w = width\nLet w + 2 = length, because the length is 2 miles larger than the width.\n\nArea = (Length)(Width)\n80 = (w+2)(w)\n80 = w^2 + 2w\n0 = w^2 + 2w - 80\n0 = (w+10)(w-8)\nw = - 10 miles or 8 miles. Since there is no such thing as a negative distance, it's 8 miles.\nw + 2 = length, so...\n8 + 2 = length\n10 = length
219885
triangle- 3side\nquadrilateral- 4side\npentagon- 5side\nhexagon- 6side\nheptagon- 7side\noctagon- 8side\nnonagon- 9side\ndecagon- 10side\ndodecagon- 12side\nicosagon- 20side
501756
length x width = area\n3 x 6 = 18
865958
The perimeter is 8.32 Inches\n\nThe answer is 8.32 inch\n\n- - - - - - - s-
966422
The area of an equilateral triangle is\nA = (1/4)sqrt(3) * a^2, where a is the length of the side.\nSince the triangle is equilateral, you know that the length of each side is 10/3.\nThe area is\nA = (1/4)sqrt(3) (10/3)^2\nA = (1/4)sqrt(3) (100/9)\nA = (25/9)sqrt(3)
755315
1) Do you mean equilateral or scalene?  You can only answer this if it is a regular, equilateral (all sides the same).\n\nLet S be the length of one side.  Then the perimeter is given by the formula\nPerimeter = 3S = 74 cm.\n3S = 74\n\nDivide both sides by 3:\nS = 74/3\nS = 24 2/3 cm\n\nEach side of the equilaterlal triangle is 24 2/3 cm.\n\n2) The perimeter of a rectangle is 2(W + L) = 48 cm\nYou are also told that the width is 1/3 the length.  In other words:\n3W = L\nPerimeter = 2(W + 3W)\nPerimeter = 2(4W)\n48 = 8W\nW = 6 cm\nL = 3W = 3(6) = 18 cm.\n\nSo the width is 6 cm, the length is 18 cm.\n\n3) A regular hexagon has six sides that are all the same.\nThe formula for the perimeter is 6S = 96 cm.\n6S = 96\n\nDivide both sides by 6:\nS = 96 / 6\nS = 12 cm\n\nSo each side of the regular hexagon is 12 cm.
669681
1.  Area of rt triangle whose leg is 6ft and whose\n    hypotenuse is 10ft?\n\n    Area = 24 sq. ft.  \n\n  Explanation:\n\n    First we need to find the other leg's length...\n    Using Pythagorean Theorem,\n    \n    c**2=a**2+b**2 \n       \n    where c is the hypotenuse, a is one leg, and \n    b is the other leg.\n\n    So, 100 = 36 + b**2;  b**2 = 100-36 = 64; therefore b=8.\n    Now, Area = 1/2(base*height) since the base is one leg\n    (we'll say it is a) and the height is the other leg \n    (therefore we'll name it b) \n    the Area = 1/2(8*6) = 1/2(48)= 24 sq. ft.\n\n2.   The hypotenuse is approx. 4.9 meters.\n    \n  Explanation:\n     \n     Using Pythagorean Theorem: c**2=a**2+b**2 we find that\n     c**2 = (3.5)(3.5) + (3.5)(3.5)\n     c**2 = 12.25 + 12.25\n     c**2 = 24.25\n     c = sq. rt. (24.25)\n     c = 4.9244 meters\n     hypotenuse is approx. 4.9 meters.\n\n3. hypotenuse is approx. 20 inches long.\n\n  Explanation: Area = 1/2(x)**2 \n               where x is length of one leg.\n\n     x**2 = 2*Area;\n     x**2 = 2*98\n     x**2 = 196\n     x = sq. rt. (196)\n     x = 14 inches\n\n     Now, to find length of hypotenuse, we use the\n     Pythagorean Theorem:\n\n     c**2 = a**2 + b**2; since a=b this can be rewritten so\n     c**2 = 2(a)**2\n     c**2 = 2(14)**2 -- Remember 14 is the length of a leg.\n     c**2 = 2(196)\n     c**2 = 392\n     c    = sq. rt. (392)\n     c = 19.7989\n     c is approx. 20 inches long.\n\n\n4.   The researcher will climb approx. 10 meters \n     to reach the crack.\n\n   Explanation:\n      \n      Using the Pythagorean Theorem: c**2 = a**2 + b**2\n      If we set a = 24, then c**2 = (24)**2 + b**2,\n      but we also know that c + b = 36 \n      which means c = 36 - b.\n\n      So to solve for this we need to set\n      (36-b)**2 = (24)**2 + b**2\n      1296-72b + b**2 = (24)**2 + b**2\n      1296 - 72b = (24)**2\n      1296 - 72b = 576\n      -72b = 576 - 1296\n      -72b = -720\n         b = -720/-72\n         b = 10 \n\n      And now we have our 10 meters the researcher \n      must climb to reach the crack in the tree.\n\n\n6.    Approximately a 42 inch stick is the longest stick\n      that will fit in a box that is 24 in X 30 in X 18 in.\n\n  Explanation:\n\n      First use Pythagorean Theorem to find the diagonal\n      inside the rectangle of 24 in X 30 in.\n\n      c**2 = (24)**2 + (30)**2\n      c**2 = 576 + 900\n      c**2 = 1476\n      c = approx. 38.418 in. -- we will call it 38 in.\n\n      Now, use Pythagorean Theorem to find the diagonal\n      inside the "new and invisible" rectangle that is \n      38 in. X 18 in.\n\n      c**2 = (38)**2 + (18)**2\n      c**2 = 1476 + 324\n      c**2 = 1800\n      c = sq. rt. (1800)\n      c is approx. 42.43 in.  \n      \n      We will call "c" 42 inches long.