find the missing value in this proportion?
448435
Do you mean\n\nx/12 = (5 1/2)/8?\n\nIf that's the case, then\n8x = 12*5 1/2\n8x = 66\nx = 66/8\n= 33/4
380269
Probably a divide by zero error.
708630
This is a two proportional test. So we define the hypotheses first:\n\nlet delta = p1 - p2, where p1 = proportion of first sample in favour and p2 = proportion of second sample in favour.\n\nH0: No difference between the two samples, so that delta = 0\nH1: There is a difference between the samples, so that delta =/ (does not equal) 0\n\nFirst we find delta = p1 - p2, where p1 = X1/n1 = 40/50 = 0.8, and p2 = X2/n2 = 30/50 = 0.6\nSo that delta = 0.8 - 0.6 = 0.2\n\nThe test statistic is Z where Z = delta / s.e.(delta), so we need to calculate s.e.(delta). There are two different s.e.(delta) calculations, one which assumes that the variance between the two proportion differs and one which assumes that it's the same. A test which assumes the variance is the same is most common and is the test which is most likely asked of you. For this, we need to combine the data of the two samples to find a single estimation of the proportion;\n\np = X1+X2 / n1+n2 = 40+30 / 50+50 = 70/100 = 0.7\n\nNow for s.e.(delta) = square root of [{p(1 - p)}/n1 + {p(1 - p)}/n2] = square root of [(0.7 x 0.3)/50 + (0.7 x 0.3)/50] = 0.09165 \n\nThe test statistic can now be calculated;\nZ = delta / s.e.(delta) = 0.2 / 0.09165 = 2.18\n\nNow a p-value has to be obtained from this Z value. A statistically program or a statistical table needs to be used to obtain this. Using a graphically calculator a p-value of 0.029096 is obtained. Since this value is less than 0.05, we reject the null hypothesis (H0) and accept the alternate hypotheses that there is a difference in proportion in favour of the plan between the two samples.
477479
I'm not sure which of the two variables is relevant here so I'll assume that you want to know [Total Missed] as a percentage of Session.\n\nCreate a MS query using the table that includes your data. In one of the columns, instead of dragging one of the fields from the table, enter the formula ([Total Missed]/Session). You need the brackets because "Total Missed" contains a space. Be sure to add a condition so you aren't dividing by 0.\n\nAccess will name the column Expr1:([Total Missed]/Session)\n\nIf you look at the query using the SQL view, it will look something like this:\n\nSELECT ([Total Missed]/Session) AS Expr1\nFROM [Table Name]\nWHERE ((([Table Name].Session)>0));
736840
Sounds like a homework problem.  Not going to give you the answer, but I will tell you how to get it.  A percentage is a part of the whol.  In order to get the percentage, you have to divide the part by the whole.  For instance, 80/100 would be 80%.  Therefore 80 is 80% of 100.  That one is simple, but the concept remains the same regardless of the problem.  That means you simply take the part (42.5 million) and divide it by the whole amount to get the percentage.
52113
19/4, 4 3/4, 4.75\n\nPick one.
398683
Use log you will find\n\nor put\n\nx=3.597285024\n\nIts done
303069
Do a confidence interval calculation and see if the confidence level for the data you've collected is above that required for 98%.\n\nI can show you how but given your other questions, it's clear you haven't really done any work on this yet and you're just looking to get someone to do your homework for you.\n\nLet me know if you still can't do it after you've tried a while, and I might help you out.
780025
x ≤ 5\n\n-- - - - - - -s-
417435
either 12.667 if the 16 is negative\nor  18
698011
The error is +/- 0.01.\n\nThe value then is: 6.02 +/- 0.01
209560
P=(V^2)/R\nP=(150^2)/11=2045.45
1127129
you should be able to get the total through a "x" but otherwise, check the site
974937
please complete the equation
949845
hmm..well this might be an easy fix if you have a calculator\n\nsimply multiply the total by 0.1.  the answer will be 10 percent of the total.\n\nhope this helps\n\nexample: 132.00  x 0.1 = 13.20    which is 10%
947255
Let X be mean fill of container. \n\nThe distribution is X~N(16, 1.5) i.e. it is normally distributed as stated in the question.\n\nWant to find P(X>17), so standardise.\nP(X>17) = P(Z>(17-16)/(1.5/2)) = P(Z>1.33)\n\nThen you look up your normal table. The answer is approximately 0.09.
858579
No.\n\nFirst you have to find out how many were unsold. Since you know the number sold, subtract that from the total to find out how many were not sold.\n\nTo find the percentage, then divide the number unsold by the total, and multiply by 100.