What does the chemical structure of C7H17 look like?
449545
Well, I can't completely answer this question.\n\nBut I would assume that the structure of anything would appear like the 'anything'.\n\nSo the chemical structure of C7H17 appears as C7H17.\n\nI do not know about the extra hydrogen.\n\nSorry if it's not useful, but it's all I got.
1068373
If you know you're dealing with an organic compound, you take the formula weight and divide by 12.  This gives the number of carbon atoms.  You look at the remainder and determine if it could be the number of hydrogen atoms.  Alkanes have 2n + 2 hydrogen atoms (where n = number of carbons).  Alkenes have 2n and alkynes have 2n - 1.
908225
Go to this site and it will show you structures of a whole bunch of molecules with Carbon and without, by formula and by name, kind of mess around with it for a while. http://www.chem.purdue.edu/gchelp/molecules/index.html
231898
There are a few isomers possible.\n\nEssentially there are two C's double-bonded, with either 2H's off one C and 2Br's off the other C.\nOr 1H and 1Br off each C
759497
1) determine the mass of carbon, hydrogen and oxygen.\ncarbon: 7.432 g x (12 / 44) = 2.027 g\nhydrogen: 4.057 g x (2 / 18) = 0.451 g\noxygen: 3.383 - 2.027 - .451 = 0.905 g\n\n2) convert to moles.\ncarbon: 2.027 / 12 = 0.169 mol\nhydrogen: 0.451 / 1 = 0.451 mol\noxygen: 0.905 / 16 = 0.0566 mol\n\n3) divide each molar amount by the lowest value to obtain small integers\ncarbon: 0.169 / 0.0566 = 3\nhydrogen: 0.451  / 0.0566 = 8\noxygen: 0.0566 / 0.0566 = 1\n\nThe empirical formula of the substance is (C3H8O)n\nThe atomic masses add up to 60, which is also the molar mass of the compound. Therefore n=1 and we find C3H8O
904652
CH3CH2C(CH3)3.\nI guess you forgot to type the C before the parenthesis. If you didn't forget, then none of the answers is correct (you would be missing a carbon atom).\n\nChem-man I would have contacted you in private about this but you do not give us the option to e-mail you. I have seen several of your answers prompting askers to verify your answer through echemistryhelp. I checked the website and it is not a free one; you post a question and pay for the answer. I'd say that this is a form of indirect advertisement  which is against the community guidelines. Please refrain from doing that or I will have to report you.
900829
H      H       H\n         |        |        |\nH --- C --- C --- C --- H\n         |        |        |\n        H      OH    H\n\nsince the functional group is on the 2nd carbon, the answer is (c)
452333
its cis 1,4 polyisoprene(polymer)\n\nH2C=C(CH2)-CH=CH2
800173
carboxly and amine groups.\n\nCheck out, http://en.wikipedia.org/wiki/Amino_acid for more info about amino acids and what the structure looks like.
443303
It only has 7 valence electrons :)\n\nRival
1127301
I leave the H's:\nC-C-C-C-O butanol-2\nC-C-CO-C  butanol-2\nC-O-C-C-C propyloxy methane\nnot shown: isopropyloxy methane\nC-C-O-C-C ethoxy ethane
774737
An alkane follows the formula CnH2n+2 (n=any real number), meaning for every carbon, there are 2 hydrogens.  Of the choices, C7H16 is an alkane.
260431
R-O-CH3 \n\n R is any carbon based group. I wish I had chem draw on this computer, but the structure is actually bent due to the symmetry (this involves group theory - a linear algebra based idea in quantum mechanics) of the orbitals involved in bonding. Its bent for the same reasons that water is bent, now your teachers may say that water is bent due to electronic repulsions but if thats true how come they draw the lone pairs so close to eachother??? Its because its not true, and its part of VSEPR theory which is just a practicle method of teaching structure to people who dont know too much physics, math, and chemistry.
172042
C4H9N3O2 For the structure goto http://www.cwu.edu/~chem/courses/chem388488f00/coulombe/CREATINE1.GIF
940983
I believe it would be:\n\nNe\nCH3Br\nCH3CN\nCH3OH\n\nthe -OH is the strongest of these because of hydrogen bonding
644051
See if this article has a diagram\n\nhttp://jchemed.chem.wisc.edu/Journal/Issues/1999/Apr/abs542.html
807050
B(OH)3\n\nThe following link has a neat picture of what the molecule could look like.