Toss a coin inside an airplane, it comes down at exactly our hand whereas it should fall behind?
450879
This is the same situation in a train or bus. The answers above are correct. Both you and the coin have velocity relative to the ground right when you throw it up. A similar situation happens when a skateboarder jumps up from his/her skateboard and still lands on the skateboad. Now, the coin would be behind if, while in the air the airplane accelerates which would mean that you would then have a greater velocity than the coin.
729735
both are the same if it is drop at the same height because the gravity speed is 10 ms-2 (9.81ms-2 more accurate)
789777
The feather is wider and has to push a larger amount of air out of its way while falling, which requires more force. The faster the feather falls, the faster the air has to get out of the way, which means it has to be accelerated away, via F=ma. At some point, the force required to accelerate this air out of the feather's way balances the force of gravity. The same happens for the pebble, but since it's smaller, a smaller amount of air has to be accelerated, so the force is small until the pebble is falling so fast that air has to be accelerated out of its way very quickly (large a) and so it also reaches a terminal velocity, but a faster one.
462363
It only depends on the local position of the toilet.\nThe coriolis force is not involved here.
1024308
Friction aside, think of it like this:\nwhen the bullet is fired it has a certain amount of speed.  every second that speed is being reduced by gravity by 9.8 m/s.  So when it reaches as far up as it will go it stops because gravity has subtracted 9.8 from from the original speed every second until the speed is 0.  Like taking out money from an account.  So now you can spend all the money you have-it's got potential.  Then it starts moving toward earth.  gravity is still working at the same rate. so it picks up speed at the same rate that it lost it last time. And it's the same distance, so it'll take the same amount of time.  So now you're depositing the money into a different account.   You only have the money you took out of the first account, so that's how much the second account will have.\nI hope that explains it for you.
250759
Remember, momentum is affected by mass.  The fly's mass makes it easier to dissipate the inertia.  So it seems that the fly could crash into the front, but not likely. Of course, most people are worrying about other things at the time, so no specific measurements have been taken!  The air inside has mass also, so in effect the car and the air mass have become one unit, in which the fly is also a small part.  When it stops, it helps everything else stop.
1003574
the dominoes will reach a terminal velocity.. based upon their weight and the friction of the air as they fall... just like dropping one from an airplane.. and having it always large face downward (not edgewise)
433903
The ball will reach a maximum height, then the velocity of gravity (9.8 meters/second) would cause it to travel downward until another force acts upon it (according to Newton's laws of motion). However, this does not account for other forces, such as air resistance. The rate at which the ball falls and the air resistance acting upon it will depend on the properties of the ball (surface area, weight, etc.). If the ball is inside a vacuum, it is said to be in free fall (as the only force acting upon it is gravity) and there is no other force acting upon it. If the ball is allowed to fall long enough, it will reach a point of terminal velocity, where it cannot fall any faster (the force of air resistance will equal the weight of the object)
1186075
It depends on the speed of the plane V and the radius of the circle R. The centripetal acceleration (acceleration of the plane toward the center of the circle) is V^2/R. If V is in ft/sec and R is in ft, the answer is in ft/sec^2. If this number is greater than gravitational acceleration (32 ft/sec^2) the passengers stay in their seats; if less than G they fall out of their seats, and if equal to G they are in free fall and can easily drift from their seats. Google "vomit comet" for a practical illustration of the principle.
744445
Galileo postulated  the "feather drop" which states that when a feather and a stone are dropped from the same height, both objects will hit the ground at the same time.  \n\nWe see that the feather and a stone fall at different rates when dropped from a certain height because there is air resistance.  The feather will be affected by the air when falling and reaching terminal velocity before the stone will.  Therefore, the feather will fall more slowly than the stone.  \n\nHowever, if somehow we were to remove the air and then drop the feather and the stone, both the feather and the stone will fall and hit the ground at exactly the same time.  Since gravity will cause the same acceleration in both objects (feather and the stone) of 9.80 m/s^2 downwards, both objects will accelerate uniformly at the same rate towards the ground.  Hence, both objects will hit the ground at the same time, as long as we are able to ignore air resistance.
1108579
NO!!!\n\n\nThey dont fall with the same velocity, \n\nThere is a maximum /terminal velocity an object can attain while moving in a fluid. (in our case - air).\n\nAnother force acts on bullet in a direction opposite to that of g. \n\nThis force = 6 * pi * n * r * v \n\nr - radius of object,\nn - coeff of viscocity\nv - terminal velocity.\n\n\nThus the velocity with which the bullet will return to earth would be much less. (but still large enough )
365397
OK, relativity DOES NOT come into play here, because the velocities involved are not remotely high enough.\n\nYou are talking, it seems, about an object being projected up into the air and falling back to earth.  This must occur below escape velocity or it would leave the earth.  Relativistic speeds are far, far, far, far higher than that.  So, your question is in fact not related to relativity in any way, as much as you seem to think it is. SO I will answer your question 'normally'.\n\nWhen the object is projected upwards, it possesses a certain amount of kinetic energy whcih, as it rises, it converted into potential energy which increases with height.  When the KE finally runs out, the object will peak and as gravity, which exists by the way, will pull it down the PE will be converted back into KE and thus motion, in a downward direction in this case.\n\nAll I can say after this is to stand under it and maybe after it hits, you'll understand a little better.
1157115
No, it falls back down at its terminal velocity(maybe), which is slower than the muzzle velocity because of drag.\n\nThe bullet leaves the gun with a given amount of kinetic energy: 1/2*m*v^2 where m is the mass of the bullet and v is its initial velocity.\n\nAir has non-zero viscosity, which is a resistance to shear forces.  When the bullet flies through the air, it drags air along with it.  This gives some of the bullet's energy surrounding air, reducing the bullet's velocity and kinitic energy.  Drag forces between fluids and solids occur in the direction opposite their relative motion.  (If the fluid is stationary and the bullet is moving, the drag is in the opposite direction of the bullet's motion.  If the fluid is moving and the object is stationary, the drag on the solid is in the direction of the fluid motion.)\n\nSimultaneously with drag, gravity is applying a force toward earth.  This too reduces the bullet's velocity and kinetic energy.  However, as the bullet flies higher into the air it gains an equal amount of potential energy from gravity.\n\nThe net result is that the bullet is always losing energy in flight because of drag.  This means that the amount of potential energy at the top is less than the initial kinetic energy, and it is thus impossible for the bullet to be going at the same speed it was shot when it hits the ground.\n\nThe fastest an object will fall under the influence of gravity is the terminal velocity.  At this velocity, the force of drag (which increases with the size of the object's profile, the viscosity and density of the fluid, and the relative velocity of the solid and the fluid) exactly balances the gravitational force.
712405
It wouldn't have to go out into space to let the earth "slide by" underneath it. You'd just have to use fixed point to calculate by to prove that the helicopter has remained in the same place. Otherwise it will seem that it has flown very slowly from Sussex to Scotland.\n\nGood old Einstein's relativity wanders through here, because to someone on the grond, the helicopter would be flying away instead of staying fixed while to somebody up on the International Space Station, for example, there would be a helicopter maintaining its position relative to the ISS and "floating" over the earth.
611220
This is about conservation of momentum. Any object on a rotating (and for our experiment atmosphere-less) planet has the same rotational momentum and angular velocity  as the surface. If it jups up, it will increase the radius, and therefore reduce the angular velocity, so it will land further behind.
81552
If you disregard air resistance, both land at the same time.\n\nThe Earth's gravitational pull affects everything equally.
309973
It depends on where you are doing the experiment. It is a universal law that all objects fall with the same acceleration in a gravitational field regardless of their mass thus reaching the ground together if they are released from the same height but things like air resistance may change things dramatically causing the feather to fall much more slowly than for example hammer.