how is weight and volume percentage calculated?
439725
the weight or volume percentage of one type of molecule in a compound?\n\nWeight Percentage\nthe weight of the individual molecule (atomic weight or atomic mass) divided by the total weight of the compound and then multipled by 100.\n\nH2O\nweight of H=1, weight of O=16\n%H=((1x2)/18)x100= 11.11% (1x2 because there are two Hs)\n%O=(16/18)x100= 88.89%\n\nVolume Percentage\nthe weight of the individual molecule divided by the total volume of the compound and then multipled by 100.
373349
Volume = 1/48 * 1*1 = 1/48 cu ft\ndensity = 480 pounds per cu ft\n\nmass = density*volume = 480* 1/48 lb = 10 lb
910910
Firstly, please forgive me for not having a periodic table at hand. :)\n\nSecondly, please forgive yourself as even the most advanced scientists in the world sometimes forget how to do this calculation.\n\nThirdly, it is such a simple calculation, that it is no wonder that it is so easily forgotten.\n\n1.5% solution (mass/volume) means 1.5 g of KBr in 100 ml of solution\n\nIt's that simple. :)\n\nEnjoy your science. :)\n\nSincerely,\n\nCurtis
422227
In your example, the concentration of the solution weight/weight would be (presuming the 100 ml is water, thus 100g) would be 10.7% (12 g solute/112 g total solution).
588958
the weight will be according 2 density of the material \n\nfor example for water 1  liter wighs 1 kg
754188
you divide the mass by the volume\n1.2.14 g/cm^3\n2..82 g/cm^3\ngood luck!
732533
D = M/V\n\nDensity= Mass/Volume
884618
Yeah, exactly like what Steven Procter said.\n\nIn short, the formula is something like this:\na/b x 100 = c %\n\na/b is the decimal number that you will get by dividing a over b.  In your case, a = 40,400 and b = 324,800.  \n\nc % is the percentage you gain after multiplying the decimal number you obtain with 100.\n\nHope you understand.
344825
density is mass divided by volume - so if you know the volume and the density, then you multiply them to get the mass  (which is synonomous with weight)
95798
I'm thinking concentration, but your question is worded sort of oddly... Does that fit with what you've been learning????  It's usually percent by mass I think...
470447
You need to know the specific gravity of the weight.  (Specific gravity is weight per unit of volume, typically expressed in grams per milliliter).  The specific gravity of water is generally accepted as 1 (meaning that it weighs 1 gram per milliliter).  The equation to determine volume of water displaced would be:\n\n[10g/(S.G. of the weight)] X 1 = Vol. of water displaced\n\nNotes:\nS.G. is short for Specific Gravity\n\nThe 1 in the equation is the S.G. of water.\n\nIn actuality, the S.G. of water varies with temperature, so you may need to adjust the S.G. of water to the correct value if the problem gives you that information.\n\nThe answer will be volume of water in grams.
43647
Let the mass of the girl be m\nLet her net volume be v\ndensity in air = d\n\nSince 97% of her body is beneath water, so volume equal to 97m/100 is displaced and weight of 97m/100 mass is balanced by buoyant force. \n\nSo, here mass density remains the same = d = m/v\n\nBut her weight density = (mg- [97mg/100])/v\n                       =  3mg/100v\n                       =  3% of weight density in air
894614
PV=nRT\nP= (nRT)/V  (1st eq)\n\nn,R,T u know.\n\nV >>>\nDensity = mass/ volume\n2.3 = .00446 *10^3/Volume\n\nrearrange and ull get volume.............and then put that into the first equation.............and voila
1030347
Density = Mass / Volume\n\n4.3 = 43 / Volume\n\nVolume = 43/4.3\n\nVolume = 10 cu cm\n\n* Assume your density's dimension is 4.3 g/(cu cm)
945711
In the given case, the extra .05g/ml is attributable to the acetic acid.\nDivide 100 by the percentage of the %age the vinegar is stated at, then multiply the .05 by the result and add 1.  That'll give you the weight (density) for a 100% solution.  Take it from there.
120873
D= M/V\n\nIts a formula used to calulated to density (thinkness) of an object by dividing the Mass of an object by its volume. In this case, you can use the water displacement method that displaces (water) from its orignal volume by adding an object (marble). Using a balancer, measure and record the weight of graduated cylinder(ml), before and after the addition of water. Subtract the weight of the cylinder with water from the cyliner's weight and you will get the mass. You have to pay attention to how much the water displacement after adding the marble. record the volumes before and after (if ness). This will solve for volume. Once this is accomplished, you would have no problem finding the density.
1121653
density=mass/volume or something like that, so if u have the density and the volume (aproximations ofcourse) u can find the mass\n\ni think! lol