what is the square root of -4?
435410
2i or -2i, where i = sqrt(-1)\n\nIf you haven't learned imaginary numbers, then your answer would be that the sqrt(-4) is not a real number.
793181
sqrt(x+4)=3\nx+4=9\nx=9-4\nx=5\n\ns
1066492
x = -4\n10points thank u!
283638
sqrt(25)=5 or -5. To verify it:\n\n5*5=25 checks\n-5*-5=25 checks\n\nboth work.\n\nan important thing to remember while square-rooting a number is that the root can be both positive or negative, as two negatives multiply up to a positive.
941657
Nah, sorry, but something in your thinking is incorrect.  You seem to be saying that if you add the square root of 3 four times, you want to get 9.  That's not right.  If you take sqrt(3)^4, you WILL get 9.   Taking the fourth root of a number is not like dividing a pie into four pieces.
325592
You need to first find 2 numbers that multiplies to give you a -4 and adds to give you a negative 3.  -4 and 1 work.\n(p^2 -4) (p^2+1) = 0\n\nThen, set them both = to 0.\np^2-4 = 0\np^2 = 4\np = 2\n\nand P^2 +1 = o\nP^2 = -1\nP = the square root of -1, also known as i\n\nFINAL ANSWER: P = 2, and i
21852
Square Root of negative 11\n= √-11\n= √(11 * (-1))\n= √(11 * i                       since √-1 = i.\n= 3.31662479035539984911493273i
799963
If you are asking if the negative cubed root of 64 is 8, then no it is wrong.  The cubed root of 64 is 4, so your answer should be negative 4.   4*4*4 is equal 64, so taking the cubed root would be 4.     Taking the square root is like multiplying to the (1/2) power, so taking the cubed root is like multiplying to the (1/3) power.  So 64^(1/3) is equal to 4.  then the negative of that answer is -4.
898700
x = 4 ==> (x - 4) = 0\nx = -2 ==> (x + 2) = 0\n(x - 4)(x + 2) = 0\nx^2 - 2x - 8 = 0
929526
4x^2 - 16 = 0\n4(x^2 - 4) = 0\nx^2 - 4 = 0\n(x - 2)(x + 2) = 0\n\nANS : x = 2 or -2
267044
The square root of pi is about 1.772. So the negative square root would be -1.772. I don't believe infinity has a square root, though.
284143
j * sqrt(pi)\n\nj = i; which is imaginary number which is sqrt(-1)\nsqrt is "square root"
544837
I squared the 7 to start with and got 49.  I am also only showing the addition version, you can do the subtraction later yourself.\n\n(-7 + sqrt(49 - 4(9)(-1)))/2(9)\n(-7 + sqrt(49 - -36))/18\n(-7 + sqrt(49 + 36))/18\n(-7 + sqrt(85))/18\n\nand I think that that is it.  You cannot simplify the square root.
834259
sq root of X-1 cannot come out to be negative...\nso...x-1>0 or x-1 = 0\n       x>1     or x=1\nDomain: {x|xer, x > or = 1 }\nRange: {y|yer, y> or = 0}
775585
-5+-sqr(25-4(2)(-9))/4\n-5+-sqr(97)/4\n1.21 and -3.71
89471
idk wat the square root is.... the square root of a negative is not a negative though... a negative times a negative is a positive.... also, this is the 4th ? i have answered of urs
804695
If I got it, your problem is.........\n\n4+/- sq root -12\n_______________\n           2\n\n\n\nThen:   4+/- 2i sq root 3\n            _____________\n                  2\n\n\nSimplify to:    2+/-  i sq root 3