If r varies inversly as t and r=18 when t= -3, what is r when t= -11?
445500
(18)(-3)=(-11)r\n-54=(-11)r\n54/11=r
57698
m/-3=-9\nm=(-3)x(-9)\nm=27
302542
4t - 7 = 10t - 25\n4t - 7 - 10t = - 25\n4t - 10t = 7 - 25\n(4 - 10)t = -18\n-6t = -18\nt = 3
1135408
OH NOES THIS IS LIKE A MATH PROBLEM!!!! i can't handle any more variables :( sry.\n\n\nhahahaha.
298073
ok so when u divide  stuff like that, u just subtract the exponents.  \nr^-3 s^5 t^2\n---------------\nr^2 s t^-2\n\nso for the r, the new exponent would be r^(-3-2) = r^-5\nfor the s, s^(5-1) = s^4.  (s by itself is equal to s^1.)\nfor the t, t^(2-[-2]) = t^4\nso the new expression is  r^-5 s^4 t^4. \nand if you really wanted to, u could rewrite r^-5 as 1/r^5. cuz thatz how negative exponents work. (x^-2 = 1/x^2)\nso then the final answer would be s^4t^4/r^5.\nhope this helps. let me know if u need more help
189735
-11/12+(-10/12)=-21/12=-7/4
874116
-7,-10,-13 by putting n= 1 2 and 3
589588
T1 = 2\n\nT2= 4\n\n>d= T2-T1\n=4-2\n2.\n\nT4= 8\n\nT3=6\n\n>d=T4-T3\n=8-6\n=2.\n\nGet it?
677134
14+r-1+6=56\n19+r=56            <-------Combine like terms\n19+r-19=56-19      <-------Subtract 19 from both sides to get r by itslef\nr=37
870658
If 1/R=1/r1+1/r2 you can convert the equation conveniently/        1/R=(r1+r2)/r1r2  Or,R=(r1r2)/(r1+r2)  [by inversing] ,Now just put the values of r1 and r2 and you get the value of R.That was the way we were solving 50 years back when we were in college and remember, calculator was not invented at that time.
710485
1 + (18-7n) = -9\nCombine 1 and 18\n19 - 7n = -9\nSubtract 19 from each side\n-7n = -28\nDivide both sides by -7\nn = -28/-7\nReduce\nn = 4
998093
The original problem:\n    -11 ( 3/2 ) ( 0.12 ( -12 ) )\nSolving for the innermost quantity:\n    -11 ( 3/2 ) ( -1.44 )\nThe two negatives cancel each other out:\n    11 x ( 3/2 ) x 1.44\nBasic multiplication:\n    23.76
452540
At r = infinity, E(infinity) = 0.\n\nAt r = R, E(R) = constant/R.\n\nThe change is\n\nE(infinity) - E(R) = 0 - constant/R =  - constant/R.\n\nDon't drop the negative sign.
477554
If you assume that at the bottom left corner the coordinates are i = 0, j= 0. and at the other end (18,0).\nT has to be:\nT = 18/7.5\n\nFor Y coordinate, it must be zero:\n12t - 5t^2 = 0\nt = 0, or 12/5\n\nso 12/5 = 18/7.5 which is at the bottom right (18,0) and proves the question.
472370
-11a + 7 < -12a + 18 \n a + 7 < 18            .( Added 12a to both sides)\n a < 11                .(Subtracted 7 from both sides)\n\na < 11 (FINAL answer- a is less than 11)
540368
a=1\nar=3\ntherefore r=3/a\n         r=3/1\n  therefore common difference r =3
12533
r/3 + 7 = -4\nr/3 = -11\nr = -33