How do you write 4,651,213 in Babylonian Numeration.?
449331
We have to ask how many units, how many 60s, how many 60^2s, how many 60^3s, how many 60^4s, etc are there in 4651213? \n\n60^2 = 3600\n60^3 = 216000\n60^4 = 12960000\n\nClearly 4651213 is less than 12960000 so it is a 4-digit number\n\n21 x 216000 = 4536000\n32 x 3600 = 115200\n0 x 60 = 0\n13 x 1 = 13\n\nI dont know what the symbols were for 21 32 and 13 but if we use the hexadecimal notation D = 13 and extend it to \nL = 21 and W = 32 then we can write the answer as LWOD\n\nADDENDUM\n\nTheir number system has only two basic elements, the first of which is clear on examining the first nine numbers: \n\n| || ||| |||| ||||| |||||| ||||||| |||||||| |||||||||\n\nEvidently, these nine numbers are all constructed of a single element, a mark easily gouged with one twist of a stick in the soft clay, and the number of times this element is repeated is the number represented. \n\nThe numbers 10, 20, 30, 40, 50, are represented by the symbols: \n\n< << <<< <<<< <<<<< \n\nHowever they did not have a symbol for zero\n\n<<| <<<|| - <|||\n\nis the nearest I can get
403722
1,11,21,1211,111221....\n\n312211,13112221,1113213211\n\n\nBTW i love this riddle, i use it on for my chess team for brain warm-ups
364224
multiply the numerators (top numbers) together put that number on top, multiply the denomonators (bottom) together, put that number on the bottom---   5/8 times 4/7 is 20/56
475680
0 = 0^3\n1 = 1^3\n8 = 2^3\nand so on..\n125 = 5^3\n216 = 6^3\n\nSo it's 216
1157976
0000, 0001, 0002, 0003, 0004, 0005, 0006, 0007, 0008, 0009, 0010, 0011... etc, etc  untill u get to 9998, 9999\n\ntry it out, might take a long time but one combination will work :))
884048
n+n+2+n+4=201\n3n+6=201\nadding -6\n3n=195\ndividing by 3\nn=65\nthe numbersare 65,67 and 69
1098310
There are lots of them.  The easy way is to multiply 5 times 6 times 7.  This number is divisible by 5, 6, and 7.  So -- just add two to it.\n\nThis is 212.\n\nYou want another?  How about 2102?  210000000002?\n422? 420002?\n\nI got a million of 'em.
966369
I think you mean 56 thousandths with the "th" in it... then that would be .056 otherwise it is 56,000.\n\nHope I helped!
804536
1 + 7 + 7(6) + 42(5) + 210(4) + 840(3) + 2520(2) + 5040(1) = 13,700
889816
1/rt3 *1/rt2-1/rt3\n[1/rt3](1/rt2-1)\n[1/rt3](1-rt2/rt2)\nrationalising\n[(1-rt2)*rt6]/6
881801
... 27, 26, 676, 678, 677, 458329, 458331, 458330, ...\n\nThis is sequence A059417 in the Online Encyclopedia of Integer Sequences.\n\nSquare, Add 2, Subtract 1, repeat...
772626
The number is 41312432.\n\nThe "4" is in the 1st anf fifth space. 4_ _ _ _4_ _\nThe "1" is in the 2nd and 4rth space_1_ 1_ _ _ _\nThe "3" is in the 3rd and 7th space _ _ 3_ _ _3_\nThe "2" is in the 5th and 8th space_ _ _ _ 2 _ _2\n\nDon't know any way to show steps other than the way I did here...\n\nBTW the number 23421314 also satisfies the requirements.
927448
A way to write numbers (usualy big numbers)\nImagine number 480,000,000\nIt is 4,8 * 100,000,000\nYou can write it as 4,8*10^8 or simply 4,8E8\n3 452 000 000= 3,452E9\n\nIt is very easy to multiply these numbers
61276
100101111\nThat is:\n256+32+8+4+2+1
656598
try seeing OEIS: http://www.research.att.com/~njas/sequences/?q=1%2C+1%2C+3%2C+5%2C+11%2C+21%2C+43&sort=0&fmt=0&language=english&go=Search\n\neverytime you had an integer sequence problem, you could check there, most of the time, they had an entry of the possible sequence there.\n\nthe most possible answer to your question is perhaps the \nJacobsthal sequence: a(n) = a(n-1) + 2a(n-2). \n\nwhich gives the sequence\n0, 1, 1, 3, 5, 11, 21, 43, 85, 171, 341, 683, 1365, 2731, 5461, 10923, 21845, 43691, 87381, 174763, 349525, 699051, 1398101, 2796203, 5592405, 11184811, 22369621, 44739243, 89478485, 178956971, 357913941, 715827883, 1431655765, 2863311531, ....
635110
For doing squares of numbbers ending with 5, here it is\n\ntake the numbers before 5 and multiply it by its next number and write product followed by 25 e.g.\n65*65 = (6*(6+1)) and 25 = 6*7 and 25 = 4225
347575
By adding a single line to the first '+' you can make it into a '4'. So...\n\n545 + 5 = 550