Where can i access the statisitcal analysis of minority test scores versus majority student scores?
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that's a good question
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For the United States, the US Census has kept track.  For official undergraduate and graduate school statistics by year and field of study, go to the site below:
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try your national statistics office
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Try your state department of education.  This should be public information.
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http://nces.ed.gov/surveys/pss/privateschoolsearch/
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www.audiencedialogue.org/stats.html\n\nwww.allmath.com
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Here is the link to their site.\n\nhttp://www.masters.org/en_US/scores/index2.html?refresh
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http://www.statistics.gov.uk/
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There are lots of ways to do this. Most of them assume a distribution to the data, that is, sort of a histogram of the scores. So for example, a bell curve (also called a normal distribution or a Gaussian distribution) is a very common curve to grade on. It is not that fair in some ways, because it is symmetric, and students on the bottom of the curve might feel short changed. If you have a group of very good students, or a group of very bad students, things can be a bit distorted.  \n\n\nSome of the methods are pretty technical. But there might be some easy ways to do this. \n\nThe first method sort of automates the procedure described by the previous answers. It has the advantage that if anyone asks, you can tell them you really DID use a normal distribution curve and here are the parameters involved etc. I do not know if this is an important consideration in this situation for you, however, or not. \n \nIn comment 2., a number of other methods are mentioned, particularly in the references, but I suspect these might be too technical for your needs. \n\n1. Try just sorting the students into groups and then assigning grades to each group. Sort the student's grades, smallest to largest. Then suppose you want to give out grades A, B, C, D, and F. This method depends on knowing where the middle is, and what standard deviation is. \n\nFor the middle: try taking an arithmetic average. Just add up all the scores Xj, and divide by the number of students N. Something like : \n\nM=Sum Xj/N\n\nFor the standard deviation: This is a bit trickier, but not too bad with a computer or calculator. Take each score, subtract off the arithmetic average from the score, square the resulting number and add all these numbers, dividing by N-1. Something like:\n\nSD=Sum [(Xj-M)^2]/(N-1)\n\n\nIf you can't do this yourself easily, there are calculators to do this on the internet. For example, look at web sites in references 1 and 2.\n\nThen go to the third web site in the references (ref 3) and type in your values for mean and SD. \n\n\nSuppose that you find mean =60 and SD=10. Then type it in the spaces in the web calculator. \n\nEntering different values in the calculator will tell you what proportion of students are in a category. So suppose you decide that all students with grades less than 40 will get an F. Type in 40 on the calculator, and then you find that this corresponds to a shaded area on the curve of 0.022750. This means that 2.275% of the students will be assigned an F. \n\nTake the bottom 2.3% of the students and give them an F.\n\nThen suppose you decide that scores from 40 to 50 should get a D. Type in the spaces in the calculator, that you want the area between 40 and 50. The calculator tells you that this area is 0.135905. \n\nTake the next 13.6 % and give them a D. \n\nSuppose you decide that the scores between 50 and 60 will get a C. Type into the website calculator, you want the area between 50 and 60. The calculator tells you the area is 0.341345. \n\nTake the next 34% and give them a C. \n\nSuppose you decide that the students with scores between 60 (the average remember) and say 70 should get a B. Into the web calculator, look for the area beween 60 and 70. The calculator tells you the area is .341345 again. \n\nSo take the next 34% and give them a B. \n\nSuppose you decide that all students with a score above 70 should get an A. In the web calculator, look for the area above 70 and you find that the area is 0.158655. \n\n\nThe top 16% get an A. \n\nNotice this is still sort of arbitrary, since you are deciding what is an F, a D, a C, a B and an A. But you are using the normal distribution to help you a bit. \n\nYou can play around with this quite a bit. You can make it so the same number of students who get an F get an A, and same number who get a D get a B. However, even though it is done on a "curve", it is all still quite arbitrary. You really do not need the web calculator except to help you get a feel for
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http://www.math.unb.ca/~knight/BasicStat/u-test.htm\nhttp://www.lifesciences.napier.ac.uk/teaching/MB/MannWhit.html\nhttp://www.texasoft.com/winkmann.html\nhttp://www.statsdirect.com/help/nonparametric_methods/mwt.htm\nhttp://eatworms.swmed.edu/~leon/stats/utest.html
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http://www.census.gov/\n\nIt's there somewhere
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www.scholastic.com/\nfamilymatters/\nparentguides/\nstandardizedtests.htm\n\nwww.med-dso.eu.dodea.edu/\ntesting.pdf
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I think your high school would be the one that has those.  I don't think high school stats are 'reported' to anyone, therefore I HIGHLY doubt there is a database out there containing these stats.  Your best bet is to contact the school or your old coach.
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http://www.socialresearchmethods.net/kb/statcorr.htm\n\n\ngo here...
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http://www.publicdata.com
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Here from the horses mouth so to speak.  Stats Can is the leading Canadian authority on statistics and here is their page on it for teachers.  \n\nThis should answer any questions you have.
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Why are you trying to get us to do your homework? :-)  If you have access to medical journals (from the hospital computer or library search the New England Journal of Medicine there have been plenty of studies on the value of diversity among health professionals, also JAMA has a few.