What´s the velocity Earth travels in space (Translation movement ) ?
448267
the average orbital velocity of earth is 29.783 km/s.\n\nhttp://en.wikipedia.org/wiki/Earth
97099
Please take a look at:\n\nhttp://en.wikipedia.org/wiki/Orbital_velocity
1080064
There is no relative motion between us and the Earth. And contrary to what others have said already, that the Earth moves really slowly, well Im sorry, that is incorrect. The Earth actually moves incredibly fast - approximately 30 km/s relative to the Sun and the Galaxy.
954912
It averages between 91 and 94 million miles. You can check this by multiplying the speed of light (186,000 miles per second) by the time it takes light to reach the Earth (8 min, 16 sec.)\n\n30 NOV 06, 1711 hrs, GMT.
630060
Speed of.. gravity? :S
53782
The Earth rotates on its axis at 1000 miles per hour (1600 kph). It orbits around the Sun at an average speed of around 67,250 miles per hour (107,600 kph). The Sun, in turn, is orbiting around the centre of the galaxy at a speed of 540,000 miles per hour. So the combined speed through space of the Earth and the Sun is 607,250 miles per hour. But there´s more - our Galaxy is also hurtling through space at a speed of 360,000 miles per hour. The combined motion of the Earth, Sun and Galaxy means that we are about twenty three and a quarter million miles away from where we were in space this time yesterday.\n\n  The Solar Sytem is believed to be about 4.5 billion years old but it's constituent parts were undoubtedly moving even before that. It is predicted\nthat our Milky Way galaxy will collide with the Andromeda galaxy in, roughly, 5 billion years.
750537
acceleration = v^2/r or v*v/r (this is m/s^2 so divide by 9.81 to get g's)\n\nwhere v is the velocity\n\nr is the radius\n\nBe careful, think about the one g the pilot feels from the pull of the earth. ;)
739905
Which velocity? The Eath is spinning at a rate of 1 revolution/ 24 hours (about 18 miles per second) and whizzing around the Sun at about 66,600 mph. Also the Eath is moving with the entire galaxy through space.
809683
The surface speed of the Earth's rotation at the equator is 465.11 m/s, while the average orbital speed is 29783 m/s, a good 6 times faster.  The orbital circumference would be 2AU*pi, where AU is the astronomical unit, the distance from the Earth to the Sun, or 149597870691 m.  So the circumference is 2*149597870691*pi = 939951143084 m, or 584058562 miles, which is very close to your answer; you probably just rounded differently or used a different value for AU.
473407
An object in motion remains in motion unless it is acted upon by an outside force.  Say you're traveling in a train going 200 miles an hour, jumping on a trampoline.  Before you jump, both you and the train are moving 200 miles an hour forward.  When you jump, you'll begin moving upward at about 5 mph, but you'll still be going 200 mph forward as well, just like the train.  When you come back down, you'll meet the trampoline exactly where you left, because you, the train, and the trampoline have all been moving forward at the exact same speed.  Here's another example:  The circumference of the earth is around 24,000 miles, and the earth completes one revolution per day.  That means that, in one day, you travel in a 24,000 mile circle, yet you don't feel that you are moving because everything else is moving at the exact same speed.
58016
The thrust is irrelevant. This is a conservation of angular momentum problem so all you need is the momentum of the planes. When calculating the angular momentum of the earth, you need to multiply by a factor of 2/5 to make up for the fact that the earth is solid and not all of the mass is at the surface.\n\nyou can do the math yourself.
964882
It depends where on Earth you are.\nAt the North Pole, you're not moving at all (at least in this frame of reference - you're still moving with the Earth round the Sun, with the Sun round the Milky Way, and so on), just spinning on your axis.\n\nAt the Equator, you travel the circumference of the Earth, approximately 40,075km, in 23 hours 56 minutes (a siderial day), giving you a speed of 1674 km/h or 1,040 mph.\n\nAt other points, your speed will be somewhere in between.
256497
around 1/6th that of earth so around 1.64m/s
392981
Is the speed at which it travels.
751049
First find Vo:  Vo^2 = Rg/sin(28)  Where R = range & 8 = theta\n\nUsing your numbers, Vo = 41.523 m/s\n\nImpulse = change in momentum ----> Ft = mVo---> F = mVo/t\n\nSo, F = (.0431kg*41.523m/s)/.00438sec = 408.59 N\n\nVoila!
515286
I once wrote a simple program to simulate orbital motion. It went something like this:\n\nX=0\nY=7000\nVX=7.5\nVY=0\nLABEL:\nR=SQRT(X*X+Y*Y)\nAX=-398600*X/R/R/R\nAY=-398600*Y/R/R/R\nVX=VX+AX\nVY=VY+AY\nX=X+VX\nY=Y+VY\nPLOT X,Y\nGOTO LABEL\n\nIt was originally in BASIC, but the above is pseudo code. The number 398600 is the Earth's gravity parameter, which is basically the mass of the Earth multiplied by the universal gravitational constant, so this program simulates Earth's gravity. The object starts 7000 km from the center of the Earth traveling at 7.5 km/s. Gravity varies as the inverse square of distance. The X component is just negative X divided by R cubed and the Y component is negative Y divided by R cubed. Use these to calculate the X and Y acceleration, use the X and Y acceleration to calculate the X and Y velocity, use the X and Y velocity to calculate the new position in the X,Y plane. Then use the new X and Y position to start over and keep doing this to plot the path of the object.
169817
The moon's orbit is nearly circular and traverses 13.2 degrees along this orbit over the course of a day. Its orbital velocity varies from 0.964 to 1.076 (mean 1.023) kilometers/sec (multiply the mean by 86,400 to get the number of km/day traveled. Multiply by 0.62137 to convert to miles). See the provided links for any additional information you may be looking for.