what will e the density of 1.6gH2 with 15000mL Volume collected at 25degreeC and 700mm corected to STP?
446884
to calculate the density you don't need to worry about the temprature and pressure if you already know the volume, as you do.\n\ndensity = mass per unit volume   \n\nit's standard units are g/cm^3\nyou volume is in mL, but that is fine since 1mL=1cm\n\ndensity = 1.6/15000\n=1.07x10^-4 g/cm^3
946085
Denstiy = Weight / Volume\n\naccording to the source, which may be incorrect, the density of gelatin is approximately 1.006 g/cm^3\n\nhowever, this must be converted to g/in^3\n\n1.006 g/cm^3 x (1 / .3937^3) = 16.5 g/in^3\n\n16.5 = weight / 1 in^3\n\nWeight = 16.5 x 1 =  16.5 g
178060
Use the formula: Density equals Mass divided by Volume\n\nor\n\nD=M/V\n\nSo we plug in numbers from your question:\n\nD = 23g/25 cm^3\nD = 0.92 g/cm^3\n\nor .92 grams per cubic centimeter.
1150459
Density is mass per volume... so divide the 2 kg by 240 cm3 and you will get your answer.
65002
Density = 5,515 kg/m³
27271
I hope you didn't use the other answer for your homework because those are not density values. They are mass values for a specific volume. There is a big difference. \n\nThe density of gneiss is:  2.6 - 2.9
201711
well you use the ideal gas law pv=nrt. STP means temperature is 25 degrees = 298K and P=1atm = 101325Pa. you have 1g and to convert that to molar mass, you would divide by the molar mass so 1/28 (i think molar mass of N is 14?). so then you do v=nrt/p = 298 (8.314)/28 (101325) = somethin\n\nfor the CH4, you know the volume and temp and pressure. you have to find n. so you put V = 0.0172m^3 (cuz 1000L = 1m^3). and temp and pressure are same, so n=pv/rt. and  once you get n (number of mols) you convert it to mass by multiplying by the molar mass (i think 16) and you get some number.\n\nhope u get it, sorry i didnt do the calculations. let me know if u need more help or whatever. laterz
561933
Density is mass divided by volume. 25 divided by 5 = 5 g/mL.\n\nDensity = 5 g/mL.
26577
The molar volume is the volume occupied by one mole of ideal gas at STP. Its value is:\n\n22.414 L mol¯1\n\nIt is actually known to several more decimal places but the number above should prove sufficient.This value has been known for about 200 years and it is not a constant of nature like, say, the charge on the electron. If we had picked a diffeent standard temperature, then the molar volume would be different.\n\nUsing PV = nRT, you can calculate the value for molar volume. V is the unknown and n = 1.00 mol. Set P and T to their standard values and use R = 0.08206.
562762
MDF typically has a density of 600-800 kg/m³\n\ntherefore, taking a value of 700 kg/m³ -\n\n1*1*0.006*700 = 4.2 kg/m2\n\nis that near enough?
239849
.7M x 20mL = .25M x (Volume of new IA solution)\nVol = (.7 x 20) / .25\nVol= 56mL
67284
well the formula is the square root of 3kT/m  where k is the boltzman constant(1.38066 x 10^-23 J/K) T is in Kelvin so you would have to convert(just add 273 to the temp in Celcius) so your T is 290K and m is the mass. the mass can be found using the density of water(1000 kg/m3) the formula for density is d=m/V and V can be found by using the volume of a sphere, 4/3(pi)r^3 oh, and don't forget to convert the nanometers into meters, then cut the diameter in half for radius.\nusing this information to get you started, you should be able to do it yourself. so you should try it first before reading further :) im sure you were familiar with all of those formulas, you just need to remember to think of things all at once so you can put them together.\n\nok, so we start with the rms velocity formula. first problem is that we need mass. ok, lets solve for mass using density. oh right, we need volume, ok, lets solve for volume then:\nwe need to make the diameter into meters, so thats 1.0 x 10^-8 meters. now we cut this in half to get the radius(r) so that's 5.0 x 10^-9.\nV=(4/3)(pi)r^3\nV=(4/3)(3.14159)(5 x 10^-9)^3\nV=5.236 x 10^-25 m^3\nnow we have volume, so using the density of water(1000 kg/m3), we can solve for mass:\nd=m/V\n1000=m/(5.236 x 10^-25)\nm=5.236 x 10^-22 kg\nok, now we have mass, so we can use our original rms velocity formula and solve for velocity. *sigh* finally.\n\nv(rms)= sqrt[3kT/m]\nv(rms)= sqrt[3(1.38066 x 10^-23)(290)/(5.236 x 10^-22)]\nv(rms)= 22.94 m/s\n\ni would check my math if i were you though, i tend to make stupid calculator errors. the concepts are there though :p
893077
Density is mass over volume.\n\np = m/v\n1.74 = m/43.5\n1.74 * 43.5 = 75.69 (mass)\n\n75.69 g
964974
This sounds more like arithmetic than math, except that the last 2 questions also involve units of measurement. Without doing the arithmetic, I'll tell you that the answer to #2 will be density in g/ml. (Yes, answerer 3, you can divide g by ml; what you can't do is add/subtract dissimilar units!) The answer to #3 will be volume in cm^3.
703593
The density will be the same no matter how much you have. It is less than 1 because it floats in water. A gallon of gas weighs 6 pounds. A gallon of water weighs 8 pounds. So  it is around 6/8 or .75 That was just an estimate.\n\nI just checked in a reference and it says .66g/ml
468007
At STP, 1 mole of Ne will occupy 22.4 liters\nT1 =273\nP1=760 torr\nV1=22.4 L\nn1=1\n\nT2=300\nP2=750\nn2=2.3 moles\nV2=?\n\n(P1 V1)/ (n1 T1) = (P2 V2)/ (n2 T2)\n\nSubstitute u will get V2= 57.37 L (check this again)\nThis is the solution...\nIs it clear?
806996
the moles of O2  : 4/32 = 0.125\nthe volume occupied by O2 at STP : V = n*22.4 = 0.125 * 22.4 =2.8L