What is in a standard deck of cards?
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Four suits of 13 cards each; two red suits diamonds, hearts, and two balck suitsspades and clubs, ace through ten, jack queen and king in each suit.
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go 2 toppscards.com\n\n\n\n        this will help\n\n                                                               kingar1
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Personally, I use the Rider Waite deck. It is my preference, because that is the one that I originally started using, and am comfortable with it. My friend uses The Fairy Oracle Deck. The graphics on the cards are very pretty. There are so many different decks out there, but I prefer to stay with Rider Waite and keep it less complicated!\n\nUniversal Waite Decks have the same pics on the cards, and the colors are better. The Universal Waite deck is a more modern version of the Rider Waite deck.
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upper deck and fleer.com too depends on what kind of cards
305226
Oh definately Element. They came out with a new HELIUM DECK its supposed to be an extremely new light deck. Representing skater man, rock on. Shread til youre DEAD!
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lib tech is prolly the strongest board you can get. they also have pop that lasts a very long time. they are pretty hard to snap too. i like habitats and alien workshop. plan B are also good decks.
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http://www.cardsmadeeasy.com/
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The answer is 3/26.  There are 6 red face cards out of 52 total cards.
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apparently each tarot deck is personal to its "handler" and they share a bond with each other.\nso I'm not sure if anyone would want to give it to you, even if they do, you might not want to accept it ?\n\nbetter safe than sorry ,I'd go with the Barnes and noble suggestion though\n\ngood luck
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Here are some code snippets that might be useful.\nNote: I wrote these down, did _not_ compile them, or test them.\n\nThe deck of cards is a array of 52 unsigned integers,\nThey can take a value of 0-52.\n\n//Create an array to hold the deck:\n\nunsigned int Deck[52];\n\nfor(unsigned int i = 0; 1 < 52; i++)\n{\n   Deck[i] = i;\n}\n\n// Shuffle the deck\nsrand(); // Initialize the random number generator\n\nunsigned int temp;\n\n// The shuffle works this way. First round, every card gets a chance\n// to be in slot 51. Second round, each of the remaining cards gets a \n// chance to be in slot 50, third round etc.\n\n\n// Note: This method allows an array value to be swapped with itself, i.e. not moved, which is what you want to get all possible shufflings of the deck.\nfor(unsigned int j = 52; 0< j; j--)\n{\n   // Generate an index in the range 0-j\n   unsigned int k = rand( void ) % (j);\n\n   temp = Deck[k];\n   Deck[k] = Deck[j-1];\n   Deck[j-1] = temp;\n}\n\n///////////////////////////////////\n\nunsigned int GetFaceValueOfCard(unsigned int n)\n{\n  return Deck[n] % 13 + 1;    // Returns a value 1-13\n}\n\n// If you want to get fancy:\n\nchar GetSuitOfCard(unsigned int n)\n{\n   char Suit[4] = "HDCS";\n   return Suit[n/13];\n}
170642
Here is the catagory: Toys & Hobbies--> TV, Movie, Character Toys--> Pokemon --> Trading Cards
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Bicycle is the brand name of the cards. There were 53 which means he was cheating and died for it. (Sorry to spoil your fun with the answer :)
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For those who don't know Math24 (like me)\n\nA standard Math 24 card consists of four digits arranged radially around the center of the card. \n\n(See the 2nd link to see what the cards look like.)\n \nThe number (and color) of dots in the corner of a card indicates the difficulty (and point value) of that particular card. Cards are double-sided, with a different set of numbers on each side.\n\nA card is solved by using all four digits on the card exactly once to form a total of 24, using addition, subtraction, multiplication, and/or division. Digits may be used in any order, and any result from a previous mathematical operation can be used in a future operation for that card. For example, a card with the digits 2, 3, 6, and 9 could be solved by stating that 6-3=3, 3+9=12, and 12x2=24. There is often more than one answer to a card. A second solution could be that 9x3=27, 6/2=3, and 27-3=24.\n\nEach digit on the card must be used exactly once in an answer. The solution to the above card could not be 3+9=12, 12x2=24, as the digit 6 is completely unused. Also, the solution could not be 2x6=12, 12-3=9, 9+9=18, 18+6=24, as the number six is used twice.\n\nCards are divided into three levels of difficulty. One-dot cards (with a single white dot in each corner) are often solved by simple addition, or contain three digits that can make 24, plus a 1 (in which case any other digit could be multiplied or divided by 1 to create the same digit). Two-dot cards (with two red dots) are slightly more difficult, and often require more multiplication and division than one-dot cards. Three-dot cards (with three yellow dots) are the most difficult cards, often having only one solution. In most decks of Math 24 cards, the ratio of one-dot cards to two-dot cards to three-dot cards is 1:2:1.\n\nIn all versions, the loop of the digit 9 is filled in with red, so that it is distinguished from the digit 6.\n\n==\n\n2 2 2 2: [(2 x 2) + 2 - 2] ! = 24\n3 3 3 3: [(3 x 3) x 3] - 3 = 24\n4 4 4 4: (4 x 4) + 4 + 4 = 24\n5 5 5 5: (5 x 5) - (5/5) = 24\n6 6 6 6: (6 x 6) - (6 + 6) = 24\n8 8 8 8: [8/ {(8 + 8)/8}] ! = 24\n9 9 9 9: (9 + 9) + sqrt 9 + sqrt 9 = 24\n\n(I do not know if the square root sign or the factorial sign are allowed, Teachers may say "too difficult for this age-group")\n\nSomebody asked about 3 3 8 8 recently and I came up with the following answers:\n\n3 3 8 8: [8 / (8 - 3 - 3)] ! = 24\n3 3 8 8: [8 / (3 - 8/3)]  = 24\n\nand if other base maths than base 10 are allowed: how about:\n\nbase 9: 3 + 3 + 8 + 8 = 2 (9s) + 4 units = 24\nbase 11: 3^3 - 8/8 = 2 (11s) + 4 units = 24\nbase 12: 3^3 + 8/8 = 2 (12s) + 4 units = 24\n\nBut some easy examples with 2 solutions would be:\n\n1 1 4 7: (4 - 1) x (7 + 1) = 24  OR (7 - 1) x (4 x 1 = 24\n1 3 4 5: (4 - 1) x (5 + 3) = 24  OR (3 + 1) + (4 x 5) = 24\n1 3 4 7: (7 x 3) + (4 - 1) = 24 OR (7 x 4) - (3 + 1) = 24\n2 3 5 7: (5 x 3) + (7 + 2) = 24 OR (3 x 7) + (5 - 2) = 24 \n2 6 8 9: (2 x 8) x (9 / 6) = 24 OR (2 x 9) x (8 / 6) = 24 or if factorials are allowed: 6 + 2 x (9! / 8!) = 24
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P(queen)= 4/52 = 1/13\nP(red card)= 26/52 = 1/2\nP(black face card) = 6/52 = 3/26
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I really think that element or zero decks give the most pop and they are preety strong. I like element and zero. It really depends about your trucks also.
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Sorry annmariet14, but you're wrong.\n\nTarot cards were NEVER a card game. They were always what they are now.\n\nThe 52 card deck that you use for card games derived from Tarot cards as a way for readers to hide what they were doing to avoid being burned at the stake.\n\nIn answer to the question, you can trust the cards if they are read by a reputable reader.
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This site has build your own deck kits:\nhttp://www.roarockit.com/