Using an open-top box contruct a 6 by 8 foot rectabular cardboard by cuttin out equal squares at each corner a
438309
You are taking away x feet on each side.\nThus, the length is 6-2x and the width is 8-2x and the height is x.\nV = Lwh\nV = (6-2x)(8-2x)x
159881
Use cardboard, clay, or sugar cubs.  Cardoard would be the easiest.
353670
in an envelope with a piece of cardboard protecting both sides. so that it is sandwiched.
170524
if its not going to hold a bird, clip every few wires and bend them down so it looks like the top of a paperclip, you could put diapers, and cards and anything in them depending on how many you fold over.
671808
4 sides and corners in a square
137083
usually rectangular-4 0f each suite
421499
At one time Office Depot sold plastic box just for this purpose.  It may be kind of spendy though, depending on your purpose.  I've seen and used a shoe box.  Use wrapping paper to dress it up, cut a slot in the top and let the entries begin.
801034
Here's the answer: (I'm assuming the top of the box is counted in the area)---------   x = side of square base, h = height, S = surface area, P = perimeter length\n\nS = 2x^2 + 4xh\n\nP = 8x + 4h ---->  h = (P-8x)/4  Substituting,\n\nS = 2x^2 + 4*x*(P-8x)/4 = Px - 6x^2\n\nFor your particular case where P = 120 cm,\n\nS = (120x - 6x^2) cm^2
240663
Since you didn't say anything about the length of the tube or strips, I assume you're aligning the unknown longest side with the unknown length of the tube.\nThe largest square that can fit in this circle is that with sides of 3*Sqrt(2)", so you can fit 4 in width-wise and 22 in by thickness for a total of 88 strips. But there's some space left over on the sides. You can squeeze in 4 more strips on the side of the lengthwise strips for a total of 92 strips.\nBut there's more space in the tube outside the square which can hold even more wood.
262893
get a big chunk of cardboard, draw "a tuxedo" in pencil then cover the words with the duct tape.
336949
i'd use some kind of bucket (cardboard) or one of those one gallon ice cream containers...cardboards easy to draw on and staple stuff to. and u can cut a slot in it if you want to open it up for a better view/easier access/whatever
839435
Yes, they are cardboard, and rectangular.
645334
for a cube with 6 faces, the edges would be 8
185786
Measure one side of a rectangle, then an adjacient one.  Multiply them together.  A = B * H
47718
So you've got an eight-sided figure and each side is 72-feet.  If you draw horizontal and vertical lines from each vertex (the angles where sides meet) to the other side of the octagon, you'll see that the octagon can be split up into one large square (in the center), four rectangles (up, down, left and right), and four triangles (in the corners).  You following me?  Get out a pencil and get to it!  Okay.  So what are lengths of your square's sides?  You'll note that the square has 72-foot sides, just like the original octagon.  Since you know how to find the area of the square, you're on your way.\n\nNext.  you have four rectangles, each with a length of 72-feet, but the short end - the width, how do we figure out the width of the rectangle?  Okay.  Look at your triangles.  Each triangle has one side of 72 feet - the side which is the outside of the octagon - and then two equal sides - it's an isosceles triangle with a 90-degree angle.\n\nOkay, time to call on pythagoras.  Pythagorean theorem states that a^2 + b^2 = c^2.  What that means is this: If you take the length of sides a and b (the ones we don't know) and square them, and add them together, the answer will be 72-squared (side C).  Too bad I'm not there with you to make this part easier to understand.  We know that a and b are equal in this case because our triangle is isosceles.  Therefore, 2x^2 is equal to 72^2.  This gives us a messy equation wherein our answer is, x is ROUGHLY equal to 51 feet.\n\nSo.  You have a square with sides 72 feet long.  You have 4 rectangles each with length 72 and width 51.  You have 4 triangles each with base 51 feet and height 72 feet.  You know that squares and rectangles have an area equal to length times width, and triangles have an area equal to one-half base times height.\n\nCalculate the area for your 9 figures and add them together.  THAT will be the square footage of your octagon.\n\nWhat... did you think I was going to do it ALL for you?
433433
47 X 672 = 31,584 divided by 6 = 5,264 boxes
238652
Assuming you have a rectangular object, then L x H x W will work. For other shapes you need something else. See sources.