how many electrons dos gallium have?
446055
Electrons per shell 2, 8, 18, 3
192645
I learned that Silicon and Gallium Arsenide are both compounded semiconductors because they each have been doped with elements that make the semiconductor either have electrons as the majority carriers or holes, in either case.  An elemental semiconductor would be carbon, since in its pure elemental state it is a resistor and has neither surplus holes or electrons--it is a semiconductor naturally.
747161
Answer:  SIX electrons\n\nI drew a diagram for you: http://server6.theimagehosting.com/image.php?img=untitled.34c.JPG\n\nElectron Configuration of Fe: 1s2 2s2 2p6 3s2 3p6 4s2 3d6 \n\nExplanation:  As you can see in the electron configuration above, there are 6 electrons in 3d orbitals of Fe in its ground state.
563557
Metals have 1 or 2 or 3 electrons in their outer shell. Non metals have 4, 5, 6, 7 or 8 electrons in their outer shell. (Strictly speaking, elements with 4 electrons in their outer shell are semi-metals or metalloids.)
470003
First you need to compare the standard reduction potentials of each half-reaction. (See URL below if you don't have values.) The more positive value will be the reduction half-equation and must therefore be the cathode (and the positive terminal for a voltaic cell). The other half equation will be the oxidation half-equation, and must therefore be the anode (and the negative terminal). You need to reverse this equation. Before you can add the two half-equations together, you must ensure that each half-equation has the same number of electrons.\n\na) has a problem; it is not balanced. Either the silver atom on the right hand side should have a single positive charge OR there should be 2 electrons on the left hand side.\n\nb) The MnO2 reduction half-equation has a more positive value than AgBr reduction half-equation, therefore is the cathode etc ie\n\nReduction: MnO2 + 4H^+ + 2e^- = Mn^2+ + 4H2O (Cathode, +ve)\nOxidation: Ag + Br^- =  AgBr + e^-           (Anode, -ve)\n\nNow multiply the oxidation half-equation by 2 so that the number of electrons in each half equation is the same: \n\n2Ag + 2Br^- =  2AgBr + 2e^-\nMnO2 + 4H^+ + 2e^- = Mn^2+ + 4H2O \n---------------------------------\n2Ag + 2Br^- + MnO2 + 4H^+ =  2AgBr + Mn^2+ + 4H2O \n\nNote: the electrons cancel out.\n\nc)  i hope that the above will allow you to complete this one on you own.
773257
Re:  For Helium, the "2" is called the atomic number and it means that Helium has 2, protons, 2 nuetrons and 2 electrons.\n\nFor Lawrencium (Lr) it should show 103 as its atomic number.  That means that Lr has 103 protons, 103 neutrons and 103 electrons.  \n\nThe 2, 8, 18, 32, 32, 8, 3 numbers are showing electrons per shell (different subject) but you'll see that if you added all the numbers 2+ 8+ 18+ 32+ 32+ 8+ 3 = 103.  103 is the total number of electrons Lr has.   \n\n____________________________________________\n\n\n\n\nFor a Normal Neutral Atom, the number of protons (p+), neutrons (n) and electrons (e-) are all the same. \n\nJust look up the atomic number from the periodic table to determine them.\n\nFor example:\n\nC: 6p, 6n, and 6e-.\nN: 7p, 7n, and 7e-.\nK: 19p, 19n, and 19e-.\n\nNow, Determine the number of p, n, and e- for Ca.\n\n\n\n\n\n\nIf you guessed, 20p, 20n, and 20e-, you are Correct!\n\n\nNote that, if you add the number of the atom's p and n you will get the Mass number (Z). \n\nThe periodic table shows Z of calcium as 40.078 because 20p + 20n = 40 (amu) \n\nAnother Example: Oxygen, having atomic number of 8, will have:\n8p, 8n, and 8e-. This means that Oxygen will have the mass number of 16 because; p + n = Mass number (Z).\n\n______________________________...\n\nFor Isotopes:\nIsotopes are atoms that have same number of protons but different number of neutrons.\n\nYou've already seen that normal Carbon has: 6p, 6n, and 6e-.\n\nThis normal carbon is called "Carbon-12". The "12" denotes its Mass number (Z). Which is p + n.\n\nThere are isotopes of Carbons and one of them are Carbon-13. Since you already know that Carbon must have 6p, Carbon-13 has 7n. 13 - 6 = 7. The number of the electrons are still the same as number of proton. \n\nIn another words, simply subtract the number of protons from mass number to determine the number of neutrons.\n\nNow, determine the number of p, n and e- of Fluorine-19:\n\n\n\n\n\nIf you guessed 9p, 10n, and 9e-, you are Correct!\n\n______________________________...\n\nFinally, there are ions. Ions means that an atom has either gained or lost electrons. Keep in mind that eletrons are NEGATIVE in nature (e-) and when an atom Gains e-, it becomes More negative.\n\nFor example: Fluoride ion, F- means that it has GAINED one electron compared to its neutral F state. Therefore;\n\nF has 9p, 9n, and 9e-, But F- has 9p, 9n, and TEN e-.\n\nO has 8p, 8n, and 8e-, But O2- has 8p, 8n and TEN e-, because O2- means that it has Gained 2 more electrons than its normal O state. \n\nNow, determine the p, n and e- for P3-.\n\n\n\n\n\nIf you guessed 15p, 15n, and 18e- you are Correct!\n\nFor atoms that have positive charges (cation), remember that they LOSE e- to become positive. So, Li+ has 3p, 3n and 2e-. \n______________________________...\n\nKeep in mind that you need to know how to combine all three of the ideas mentioned above. For example, you may be requested to determine the p, n and e- of Magnesium-25 ion. \nYou need to know that since Magnesium is in Group IIA, it will turn into 2+ ion. Therefore Magnesium-25 ion will have 12p, 13n, and 10e-. \n\nI hope this answers your question. Good luck!
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Use the Nernst equation:\ndE = dE0 - 0.0592 V/n ln [C]^c [D]^d /([A]^a [B]^b)\n\nn is the number of electrons involved, 2 in this case.\nTherefore we have in all cases:\n dE = dE0 - 0.0296 V ln [Sn2+] /([Fe2+]\nFurthermore we use the standard electrode potentials to calculate  dE0 \nSn2+(aq) + 2e- -> Sn(s) -0.14 V\nFe2+(aq) + 2e- -> Fe(s) -0.41 V\nTherefore dE0 = 0.41 - 0.14 = 0.27 V\na) The concentration are 1 M/L and we have dE = 0.27 V\nb) dE = 0.27 - 0.0296 ln 0.01/0.2 = 0.27 + 0.09 = 0.36 V\nc) dE = 0.27 - 0.0296 ln 0.4/0.005 = 0.27 - 0.13 = 0.14 V\n\nOnly in the last case the reaction moves to the left: the concentration of Sn2+ is the highest.\n\nYou can take a look here for explanations and examples:\n\nhttp://www.science.uwaterloo.ca/~cchieh/cact/c123/nernsteq.html
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In some cases, yes, depending on what other elements are combined, however a mixture of gallium arsenide is found in almost every color.
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14 of each\n\nhttp://www.webelements.com/webelements/elements/text/Ag/ionz.html
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Photoelectron energy (E) is given by\n\nE = W - hc/L\n\nWhere W is the work function of the metal and L is the excitation wavelength.
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magnesium (Mg)? 1s²2s²2px²2py²2pz²3s² = 1s^2 2s^2 2p^6 3s^2\n\nthere are three kinds of p orbitals, px, py,pz,difference in geometry but all are capable of holding 2 electrons.\n\n*** \nfor those ppl thinking about fluorine, first of all, it has 2 x 6 = 12 electrons, not 9 (^^). Fluorine has five 2p electrons, this element has six; also, this element has two valance electrons (the outmost 3s orbital), not seven. So definitely NOT fluorine, I can guarantee u that. \n***
220550
Sc, scandium, can drop 3 electrons to have the same electron configuration as Argon (Ar). Sc in its normal state has 3 electrons in its 4th shell. By dropping those 3, it can be "happy" with a full valence electron shell. Therefore, it becomes Sc 3+.
891589
None of the first two row elements can exceed 8 valance electrons.\n\nCarbon can make four covalent bonds. Oxygen (typically) only makes two covalent bonds since it already has two lone pairs. And hydrogen can only ever have one bond.
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They would lose electrons.  metals lose electrons to obtain there octet.  \n\nNa, K would lose 1 electron\n\nMg and Ca would lose 2.\n\n\nwhoever said Ca would gain an electron is an idiot
1090457
a the number of outer electron that will bond with other atoms to fill thei valence shells
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http://www.webelements.com/webelements/elements/media/kossel-pics/Xe.jpg\nYou can find that:\n1st shell: 2 electrons\n2nd shell: 8 electrons\n3rd shell: 18 electrons\n4th shell: 18 electrons\n5th shell: 8 electrons\nGround state electron configuration:  [Kr].4d10.5s2.5p6 \nShell structure:  2.8.18.18.8 \nTerm symbol:   1S0
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im not quite sure what you are asking, but valence electrons depend on the group the element is found in on the periodic table.  if tis group 1 then there is 1 valence electron. group 2 elements have 2 valence electrons. etc.