what is the answer to 5x^2+2=-7x?
447170
Change form to: \n\n5x^2 + 7x + 2 = 0 \n\nand use the quadratic formula. Or plot the graph of: \n\ny = 5x^2 + 7x + 2 \n\nand find the x-axis intersects. \n\nOr just do this: \n\n5x^2 + 7x + 2 = 0 \n\n5x^2 + 5x + 2x + 2 = 0 \n\n5x(x + 1) + 2(x + 1) = 0 \n\n(x + 1)(5x + 2) = 0 \n\nHence, \n\nx(1) = - 1 \n\nand \n\nx(2) = (-2)/5 \n\nsince one of the brackets has to equal zero to equal the left hand side. \n\nHope it's understandable and that it helped.
814352
(12x^2 +16x) - (12x-7)- (4x-5)\n12x^2 +16x -12x +7 -4x +5\n\n12x^2+12\n\nthat is what I got....\nI think you might be able to put 12 on the other side of the = sign and turn it into 12x^2 = -12 and then since both sides have 12 in common you can divide both sides by 12 and you will have x^2 = -1 then you can add 1 to both sides and you will have x^2 +1 but I think I'm getting off track by that point....it's been a while since I had to do this stuff.
314638
7\n\ny-2x=5x\n\ny-2x+2x=5x+2x\n\ny=5x+2x\n\ny=7x\n\n7=slope
808574
4x^2-4x= -7\n4x^2-4x+7=0\nx=(4+/-√(4^2-4*4*7))/8\nx=(4+/-√(16-112))/8\nx=4+/-√(-96))/8\nx=(1/2)(1+/-√6 i)\nx=1/2+(1/2)√6 i\nx=1/2-(1/2)√6 i
896553
4x^2+8x-x-2\n(4x-1)(x+2)
1149949
multiply both sides by the reciprocal of the coefficient of x:\n\n(-7/4)(-4/7)x=(-7/4)(2/5)\n\nx=(-7/10)
887085
First, I multiplied the first equation by 2 and the second one by -5 in order to make it easy for me to cancel out both x's.\n2(-5x+7y=-40)\n-5(-2x+4y=-16)\n\n-10x+14y=-80\n10x+-20y=80\n\nNow, you can actually cancel out the x's and the constants at the end.\n\n-6y=0\ny=0\n\nNow you plug y=0 into one of the equations to find x.\n\n-5x + 7(0) = -40\n-5x +0 = -40\n-5x = -40\nx = 8\n\n(0,8) is the answer.
17048
= x^2 - 7x + 4x -28\n= x^2 - 3x - 28
754459
3x^2-5X-2=0 \n(3x+1)(x-2)=0\n3x+1=0\n x=-1/3\n\nx-2=0\nx=2
1097258
It is (-2)^2 * (2)^-2\nIt can be simplified as (-2)^2 / (2)^2\n= (-2)*(-2) / (2)*(2)\n= 4 / 4\n= 1\n\nSo the cotrrect answer is 1
210403
8x-5x+3=x-7+10\n8x-5x+3-x=-7+10\n8x-5x-x=-7+10-3\n3x-x=3-3\n2x=0
1133153
7 - 2[4-6+2x] - 8+ x=6\n\n7 - 2[-2+2x] - 8 +x =6\n7 + 4 - 4x - 8 + x =6\n3 - 3x = 6\nx = -1\n\nDon't listen to the math goober - plug the value in and check it.
1054159
First, get rid of the brackets (multiply the terms inside the brackets by -1):\n\n7-2x^2 +2x -2 -2x -5 +2x^2\n\nCollect like terms:\n\n2x^2 -2x^2 +2x -2x +7-2-5 = 0\n\nIt's easy to see the sum is zero.
177871
7x- 3x= -2\n4x=-2\nx=-2/4\nx=-1/2
98037
2. Take the square root of both sides, thereby negating the ^2 and giving 10. Then solve for 5x=10.
301645
If you have an equation like 5x^2 + 7x - 6 = 0:\n\nGet the x^2 term by itself\nx^2 + 7x/5 - 6/5 = 0\n\nMove the constant to the other side\nx^2 + 7x/5 = 6/5\n\nTake half of the coefficient for the x term and square it: half of 7/5 is 7/10, squared is 49/100. Add this to both sides of the equation\n\nx^2 + 7x/5 + 49/100 = 6/5 + 49/100\nx^2 + 7x/5 + 49/100 = 169/100\n\nThe left side is a perfect square trinomial - factor it\n(x + 7/10)^2 = 169/100\n\nTake the square root of both sides and solve for x\nx + 7/10 = +/- 13/10\nx = -7/10 +/- 13/10\nx = 6/10 or -20/10\nx = 0.6 or -2
912242
2-10x=3x^2+3x-7x-7\n2-10x=3x^2-4x-7\n0=3x^2+6x-9\n0=3(x^2+2x-3)\n0=(x+3)(x-1)\nx=-3 and 1