what is x-y=2 in slope intercept form?
444240
-y=2-x\n\ny=x-2\n\nslope is 1\ny intercept is (0,-2)
621346
y=mx+b (this is known as the standard form of linear equations)\n\nm=slope\nx=x values\ny=y values\nb= y-intercept\n\nso the answer for you question is:\n\nslope = -1\ny-intercept = -3\n\nEXPLANATION:\n\ny = mx + b\ny = -x-3\n\nm= -1   and    b = -3\n \nslope = m    and   y-intercept = b\n\nthus, the slope is -1 and the y-intercept is -3\n\n\nNote: the slope is rise/run (rise over run) -- to make a graph use the y-intercept and the slope -- once you have the slope and the y-intercept, making this graph should be easy because it's a linear graph -- but if you still don't get it ask your teacher\n\n\nthus, the slope is not a-1 -----there is no "a"
845966
There are several ways to do this, but since you mention y-intercept, we'll go that way.\n\nYou should know the formula y = mx + b.  In that formula "m" is the slope.  You are given a point (x,y).  Plug in all three of those numbers, and solve for "b".  Here you'd have\n12 = 2*4 + b\n12 = 8 + b\n4 = b\n"b" is the y-intercept, which here is 4.\n\nGo back and plug "m" and "b" into the formula.\nYour answer is y = 2x + 4.
25053
i don't understand your question too well because it isn't a question but i answer with\nslope intercept form(replace y with F(x)\nmakes it in function notation\nY=mx+b\nm is the slope rise over run\nx is the variable that you can plug in\nb is where the line crosses the y axis\n\nstart with a point on the y axis that is the the y intercept(b)\n\nfrom there do a slope\nexample: y=1/4x+2\n\n\n+++++++++!++++++++++ \n+++++++++!++++++++++ \n+++++++++!+++x++++++ \n+++++++++x++++++++++ start with a point at 2y\n+++++x+++!++++++++++ \n-----------------+ ------------- then move up one and right 4\n+++++++++!++++++++++ \n+++++++++!++++++++++ and a dot down one and left 4\n+++++++++!++++++++++ \n+++++++++!++++++++++ and connect the points, then you would have graphed a segment of the line and just extend that and you solve the problem for your graph
892240
Slope is Y2 -Y1 divided by X2 - X1\n\nIn your example, Y2= 12\n                            Y2= -7\n                             X2= 0\n                            X1=-2\nSo... \n(12-(-7)) / (0-(-2))= 19 / 2 = 9.5\n\nThe slope of the line is 9.5
304476
y = x^2-5x\n0 = x^2-5x\n\nx^2-5x = 0\n\nx(x-5) = 0\n\nx = 0 or x = 5\n\nx-intercepts : (0,0) and (5,0)\n\nANSWER : two
317632
slope = 1/5\ny-intercept = 2\nx intercept = -10
523552
It's already in slope and y-intercept form...  y = mx + b, so slope (m) = 7, y-int (b) = 0
947280
y = (2/3)x + 3\nThis is in slope intercept form, y = mx + b\nm = 2/3 is your slope and b = 3 is the y-intercept.\nStart by placing a dot at (0,3)\nSince your slope is 2/3, that means you move up 2 and to the right by 3.  Place a new dot there.  You may repeat this step if you wish.  \nConnect the points with a straight line.
845468
Y-intercepts :   .5\n\nX-intercept:   1\n\nAssymptote at x = 2
911257
slope:-8. y-intercept:-7. Whatever number is in front of the x is always the slope. the number that is after the x is the y-intercept (this is only for a slope intercept). Good luck and choose me as the best answer please :)
743965
If you can find the slope, you use the formula\n\ny - y1 = m(x-x1) where y and x are in general and y1 and x1 are the x and y values from ONE point. Pick either, it doesn't matter. So...\n\nThe slope is -2.\n\ny - 8 = -2 (x - - 2)\n\ny-8 = -2x - 4\n\ny = -2x + 4
704179
An equation in slope-intercept form is y = mx + b\nIn the equation, m = slope and b = y-intercept\n\nUsing the equation given\ny=-3/2x+6\ny = mx + b\n\nWe know that the slope is -3/2.  That would be m.\nWe know the y-intercept is 6.  That would be b.\n\nNow we have to find the x-intercept.\n\nTo get the x-intercept, we will set y = 0 and solve the equation for x.\ny=-3/2x+6\nSubstitute 0 for y\n0=-3/2x+6\nAdd 3/2x to both sides\n3/2x = 6\nMultiply both sides by 2/3\n2/3*3/2x = 6*2/3\nx = 4\nThe x-intercept is 4.\n\nSlope =  -3/2. \ny-intercept = 6.\nx-intercept = 4.
498526
The value of y at the y-intercept (b), which is the point at which the line intersects the y-axis, is -9, and the slope (m) is -3. Following, the y=mx+b or slope-intercept form, the equation is y=-3x-9.
105029
slope: 1; intercept: 2\n\nslope: -1; intercept: -3\n\nslope: -5/4; intercept: 20\n\ny = mx + b, where m, the coefficient of "x" is the slope and "b" is the y-intercept.  If you solve the equations for y it's pretty easy to figure out both.\n\nHope that helps.
887226
x,y intercepts are\n9-y=+/-(x-2)^2\ny intercept bysetting x=0 will be (0,9)\nx intercept by setting y=0\n9=+/-(x-2)^2\nx-2=3x=5\nx-2=-3\nx=-1\nx intercepts(-1,0) and (5,0)\nvertex=(2,9)
787261
Let the 2 points be (x1,y1)  and  (x2,y2)\n\neqn of line s given by\n\n(y-y1)/(y2-y1) = (x-x1)/(x2-x1)\n\nwhere  (y2-y1)/(x2-x1) is the slope of line