Catapult & Egg Toss (Physics)?
441196
Build a mini trebuchet!  Build a mini trebuchet!\nGive egg LOTS and LOTS of padding!
960148
check this site out. it is not a true catapult but a trebuche.\nkind of the same thing but better. \nhttp://www.ripcord.ws/plans/plans.html
933767
As I understand it a trebuchet is a giant catapult, yes?\nSo all the potential energy is contained within the springs, or twisted ropes or rubber bands or whatever holds the arm down.\nThis sounds to complicated without more info.\n You could get an approx answer by measuring the kinetic energy of the stone when it is released + the kinetic energy of the Trebuchet when it rolls back wards + the energy converted to heat by friction. The total will be the potential energy.
835262
1- gravity , elastic forces (as in bows and catapults), Archimedes' push   - In Galileo time was discovered air pressure (Torricelli experiment) \n\n2- Mass \n\n3- Forces add up for the same mass, then acceleration also adds up :   F1 is force from friend 1, A1 is acceleration/thrust  given by him  \nF1= m.A1 \nF2= m.A2\n\nF1 + F2 = m. (A1 + A2)
611013
Oh good grief.  If it's anything like what I've just done it'll include velocity, centrepetal forces, magnetic fields, friction, gravity, forces generally, working out the mass of something and the speed at which it will fall, balances with pivot points, static electricity, AC & DC electricity, transformers, vectors and so on and so on.  It's quite hard but it's maths based so if you like maths, you should be ok.  I wish you luck.
609873
Mythbusters did this using a paper cone weighted at the tip so it fell 'point down'.  \n\nOn impact the cone tip will crush dissipating the energy.  Foam (particularly shredded) or other padding around the egg will stop the egg breaking when the cone falls over after impact.\n\nRemember the point is to dissipate the energy not just stop the egg hitting something hard - simple but effective.
397135
The weight of the object is irrelevant unless one is taking into account air resistance. This is because the net force on the object is the force of gravity, so we have ma = -mg, or a = -g, which is all we need to know for the vertical kinematics equations. The only thing we need to know for the horizontal equation is the initial horizontal speed of the package.\nIf, on the other hand, one was concerned with air resistance, one would also need to know approximate air density and cross-sectional area of the object, as well as be able to numerically solve a nonlinear ordinary differential equation (the frictional force is proportional to some function of velocity) so I doubt this is what you wanted.
716994
Final Examination Physics 104 19 May 1977 Attention: in this ...\nThe pipe turns vertically upwards as shown in the sketch; the vertical part has a smaller ... Dick, together with his suit, has a mass of 175 kg, and Jane, ...\nwww.iit.edu/~johnsonp/exams104/final190577.html - 31k - Cached - Similar pages\nNewton's Laws Applications Review - Q#13-Q#21 Answers\nSince there are two forces pulling upwards and since the sign is hanging ... (0.250 kg)•ax = Ftens - 0.25 N. Analyzing the Fy forces on the 50-g mass yields ...\ngbs.glenbrook.k12.il.us/academics/gbssci/phys/chemphys/reviews/u8breview/u8ans2.html - 28k - Cached - Similar pages\nNewton's Laws Review\nIf a football is moving upwards and rightwards towards the peak of its ... A 0.250-kg rightward moving air track glider decreases its speed from 0.872 m/s ...\ngbs.glenbrook.k12.il.us/Academics/gbssci/phys/chemphys/reviews/u8areview/u8aprint.html - 32k - Cached - Similar pages\n[ More results from gbs.glenbrook.k12.il.us ]\n[PDF]\nPHYS 1002 Physics 1 (Fundamentals) – Semester 1, 2006\nFile Format: PDF/Adobe Acrobat - View as HTML\nof mass, torque and static equilibrium. You will also learn the concept of momentum, energy, ... 0.250 kg, m. 2. = 0.375 kg, g = 9.81 ms ...\nwww.physics.usyd.edu.au/ugrad/jphys/1002_mod2_mech.pdf - Similar pages\nThe Physics Classroom\nNote that the vertical forces balance but the horizontal, forces do not. The net force is 129.9 N, right - 60 N, left. The mass is 20 kg (Fgrav/g); ...\nwww.physicsclassroom.com/Class/vectors/U3L3d.html - 31k - Cached - Similar pages\n[PDF]\n∑ ∑\nFile Format: PDF/Adobe Acrobat - View as HTML\nvalue in the upwards direction. (b) For no vertical acceleration we have: ... 6 A ball having a mass of 0.250 Kg is held at point A against a spring which ...\nwww.physics.villanova.edu/faculty/shaw/2400/tests/s97all4.pdf - Similar pages\n[PDF]\nPhysics 2400 Test #2 (8:30 Class) Spring 2002\nFile Format: PDF/Adobe Acrobat - View as HTML\n3 (a) A boy's toy cannon fires a 0.250 (kg) rubber ball vertically. ... When the cannon is fired, compressed gas below the ball exerts an upwards force, F ...\nwww.physics.villanova.edu/faculty/shaw/2400/tests/s02all2.pdf
743695
conclusion-my hypothesis were that\n              - in warm water egg sinks\n              -in salt water egg floats\n              -in water and salt water mixed together egg suspends but actually floats\nafter trials I found that my hypothesis were correct.
551475
You could start by calculating the initial velocity and launch angle required for each distance and then design your catapult to meet those requirements. The below simulator can help with making the velocity and angle determinations.\n\nhttp://www.lcse.umn.edu/specs/labs/catapult/practice.html\n\n\nPersonally I would try to get an idea of what I needed to build from calculations. Then build something that I thought was over kill, and include adjust ability. Then I would figure out how far back the arm had to be pulled to give me the desired distances by trial and error. Getting the calculations to match real world conditions could get complicated.
417118
The experiment which you have suggested (although incompletely) is a classic method of verifying Bernoulli's equation, and it consists of hanging two balls in the air by strings, reasonably close to each other and blowing air through the gap between them. \n\nSound as the logic behind the experiment may be, it is in fact quite simple to perform the experiment incorrectly. One way in which this can be done is by blowing directly at the balls, which has the undesirable effect of pushing them in a haphazard direction. Hence, while blowing, keep in mind that you do not let your blows land on the surfaces of the balls. The air should strictly pass through the gap. \n \nThe other reason could be heavy balls. \n\nYou are best off using pingpong balls, with their surfaces spaced about 5-7 centimeters ( 2-3 inches) apart.
886536
If only birds really could fly in vacuums, but this is physics class world, not real world, so...\n\nIn the x direction the fish has a velocity of 18 m/s\nThis won't change according to Newton's laws.\n\nWe are interested in knowing how fast the fish is going when it hits the ground....I assume the bird dropped it.\n\nWhen the bird is carrying it it has 0 velocity in the y direction.\n\nWe know the height it falls from and the acceleration so we can use the equation below to find the final velocity in the y direction\n\nv = sqrt[V^2 + 2hg]  where V is the initial velocity in the y direction so\n\nv = sqrt[2*5.4*9.81]\nv = 10.293 m/s\n\nWe use the pythagorean theorem to add the vectors \n\nspeed = sqrt[18^2 + 10.293^2]\nspeed = 20.735 m/s
498603
Eggman is good except for one point: velocity is a vector not a scalar.  He was right that velocity was a speed and direction.  He just used the wrong term.\n\nAnother example would be that of a pendulum.  When the pendulum bob is at the peaks on either side, it is experiencing acceleration, but it has zero velocity for the instant it is at either peak.\n\nThis is actually the same as throwing a ball up in the air, and the ball stops for an instant at the very top of its path.  The only difference is the pendulum keeps going.  The point is, the peaks of a pendulum, and the peak of a ball being thrown straight up into the air are really the same thing happening.
391825
i believe you might find these 2 links useful, http://www.sunward1.com/woodkits.htm and http://www.redstoneprojects.com/trebuchetstore/build_a_catapult.html
64492
Increase the drag, or resistance by enlarging the surface area. The parachute is a simple solution. \n\nHave you thought of making a whirly-bird/helicopter-type device to slow down the fall of the egg? Balsa wood angled correctly should be able to produce simple a rotary blade that would slow down the decent of your egg. Keep me informed.
667831
I watched Mythbusters do this.\n\nIf you dismiss Jamie's rule-bending by lowering it with string, Adam managed it by making a cone out of paper, weighting the point and putting the egg between two inflated rubber gloves.\n\nThe nose crumpled dissipating the energy with the gloves cushioning the egg when it fell sideways.\n\n\nAny variation on this theme would work - let me know if you need more.\n\nEnjoy.
921378
Projectiles without the presence of air pressure creates a parabolic trajectory (path taken by a projectile).\n\n^_^