4/12 of the 315 members of a book club are male. How many are female?
438798
if 4/12 of 315.\n\nso divide 315 into 12 groups and the total number of people in each group r = 26.25 \n\nnow u take 4 groups of 26.25 members. that means u multiply 4*26.25 = 105.\n\nthen u take 105 and subtract it by 315 cuz there r 315 people in the book club right?\nso its 315- 105 = 210 females in the book club!
569184
The boys and girls club?
895952
5 girls and 1 boy\n\nHowever, after re-reading your question and the other responses. I have noticed something in the wording of your question. In the main body you have the ratio ... girls to boys... which would leave mine correct. On the other hand, in the explanations section you have the ratio .... boys to girls which would require the reverse of 5 boys and 1 girl.  Thought, I would point out that situation in your varying reponses.
233027
There are 8! different arrangements (permutations) of the 8 friends.\n\nThere are 4! different arrangements of the 4 boys.\n\nThere are 5 different locations where the leftmost boy can sit when the 4 boys sit together.\n\nTherefore, there are 5*4! (or 5!) arrangements of the boys where all the boys sit together.  But there are also 4! arrangements of the 4 girls in the remaining slots.  So there are 5!*4! arrangements where the 4 boys sit together.\n\nSince there are 8! arrangements overall, the probability of all boys sitting together is (5!*4!)/8!.\n\nSimilarly, if the boys sit to the left and the girls sit to the right, then the probability is (4!*4!)/8!.\n\nInterestingly, this last answer is also the same probability as boy-girl-boy-girl-boy-girl-boy-girl and also the probability of girl-boy-girl-boy-girl-boy-girl-boy.  Therefore, the probability of alternating seats is (2*4!*4!)/8!.\n\nRecall that n! (read n-factorial) is n*(n-1)*(n-2)*...*3*2*1.
792310
Number of Committees with all 3 women = 97C2 (as all 3 women are in so there is only the 2 men to choose out of the remaining 97)\nTotal number of possible committees = 100C5 (Any 5 people out of 100)\n\nSo probability of committee having all 3 women = 97C2/100C5\n= 97!/(95! * 2!) * (95! * 5!)/100!\n= (97! * 5!) /(2 *100!) (because 2! = 2)\n\nProbability that a woman is chairperson = 3/5\n\nSo probability that the committee includes all 3 women and has one of the women as chairperson = 3/5 *(97! * 5!) /(2 *100!)\n= (3 * 97! * 4!) /(2 *100!) (because 5! = 5 * 4!) QED
421178
Probably under 3,000-4,000. My fraternity had alone 120 chapters
232535
Slightly higher for females than males. They said the ratio was 1.2
911673
this is easy....\n\n3/4 of 32000 = 3/4 times 32000 = 3 * 8000 = 24000 women\n\ntotal is 32000 and women are 24000 of that, which leaves 8000 to be men!
1106234
I believe that this is apparent, because girls are more interested & apply themselves more in the classroom than guys...  this is only speaking of the majority of females in the classroom.  Study's have proven this to be true, although in the college world it seems that there are more men who recieve degrees in mathematics, engineering, computer sciences... women still out perform men in the overall percentage of degrees handed out.\n\nIn an article released at the Annual American Psychological Association Convention, after testing many girls and boys, researchers found that "[g]irls outperformed boys" and are "better than boys in successive processing across all the age groups."
525452
I'm guessing here... but I have to go with the number of enlisted (both officers and enlisted personnel) females. Pretty smart eh?
901323
There are (10 choose 3) = 120 possible committees that can be created.  To get one of all women, select one of the six women first, one of the five left next, and then one of four.  The order you choose should not matter so divide by 3!.  So there are 6*5*4/3! = 20 possible all women committees.\n\n20/120 = 1/6
518990
perhaps you should improve your question to get improved answers, but based on what you have asked, I would assume it's a simple probability box situation, and the answer would be 7! which equals 5040.\n\nYou have seven books, and seven possible places\n\n{1} {2} {3} {4} {5} {6} {7}\n\nyou can arrange those in 7 different places, ie:\n\nin your first row, you can have either books 1-7, in row two you can either have books 1-7, less the book you already included, this gives the following breakdown:\n\n7 options (any book any where)\n6 options (any remaining book anywhere)\n5 options (any remaining book anywhere)\n4 options (any remaining book anywhere)\n3 options (any remaining book anywhere)\n2 options (any remaining book anywhere)\n1 option (remaining book only has one place)\n\nTherefore:\n\n7*6*5*4*3*2*1 = 7! = 5040.
856003
male to female ratio of total US population: 0.97\nmale to female ratio at birth in US: 1.05\n\nNo offense, but rowdyowl's answer simply isn't right. I think he is just using general reasoning without having the data or technical biological information to reach the correct conclusion.
819356
There are 67 female representatives in the House.\n\nThere are 14 senators\n\nThat makes a total of 81 females in congress at the moment (I dont know how many total)
1110566
A) GUYS - AT LEAST 3 TIMES/WK\nB) DOLLS - AT LEAST 12 TIMES/WK
557998
According to a 2004 survey, men account for 50.25% of the world and women are at 49.75%.
388148
All seniors with at least 2 girls means either 2 girls and 2 boy or 3 girls and 1 boy or 4 girls and 0 boys.  There are not 4 senior girls so the last cannot occur.\nC(3,2)C(3,2) = 3*3 = 9\nC(3,3)C(3,1) = 1*3 = 3\n9 + 3 = 12\nThe total possible ways of picking 4 people is\nC(12,4) = 495\n12/495 = .024242\nb)\nmore girls than boys means 3 girls and 1 boy or 4 girls and 0 boys\nC(7,3)(C(5,1) = 35*5 = 175\nC(7,4) = 35\n175+35 = 210\n210/435 = .424242