Show for n>=2    1+1/2  +1/3  +      +1/n  cannot  integer?
451479
hav u ever heard of the Principle of Mthematical Induction ?\nthat could solve ur problem in a jiffy!!\n\nHowever if u havn't, dont worry!!\n\nNote that, the sum in ur series(i.e. 1+1/2+1/3+...+1/n),where n>=2, is always less than 2, but greater than 1. so it can't b an integer.\nwanna know why?\ntry cramming up some theorems about Sequence & series of real numbers!! its a regulation part of any under-graduate level Real analysis course.
840916
i know how it's done. in the theorm, every number is one higher than stated (ex. 1=2, 2=3, 3=4, etc) since it's 2+2, it's actually 3+3. and if 3+3 =6, and 6=7, then the resulting equation is 2+2=7
1027362
(1+2)/2=3/2\n1+(2/2)=2
403642
just remeber, if you want to know if any number is divisible by 4 just check to see if the last two digets are divisible by 4... that should greatly help in solving this problem\n\nNow if you would please, stop asking all of your homework questions
952696
n + (n - 5) + (n + 6) \n3n + 1
115335
4.\n\nThink about it... 1+1+1+1= 4\n1+1=2\n1+1+1= 3\n1+1+1+1=....4\nHence:\n\n1+1+1+1= 4\n\nor:\n\n3+1= 4\nand\n4+0= 4
250692
1+1+1+1+1+1+1+1+1+1+1+1+1=13\n 1+1+1+1+1+1+1+1+1+1+3=13\n 1+1+1+1+1+1+1+6=13\n 1+1+1+1+1+1+1+1+5=13\n 1+1+11=13\n 3+3+3+3+1=13\n 3+3+6+1=13\n 3+3+5+1+1=13\n 3+6+1+1+1+1=13\n 3+5+1+1+1+1+1=13\n 5+1+1+1+1+1+1+1+1=13\n 5+5+3=13\n 5+5+1+1+1=13\n 5+6+1+1=13\n 11+1+1=13
1119698
5 > x+1/-3 > 0\n5 > x-1/3 > 0\n5 1/3 > x > 1/3
677729
2/3 the number that is not a variable
926880
(1+1)-2*3/2^2+2\n\nWithout useing Order of Operations: 2\n\nWith Order of Operations: 2.5
277593
In your case use your fingers bye the way 2+2 = 4
884322
(x+2)/(x+2)(x+3)=\n1/x+3
315642
4\n\n1 + 1 + 1 + 1= 4
688567
1 + 2 = 3\n3 + 4 = 7\n7 + 6 = 13\n13+ 8 = 21\n21+ 10= 31\n31+ 12= 43
619527
1st step: try for n = 1\n\nThen 1*2^1 = 2 and\n(1-1)*2^(1+1)+2 = 2\n\n2nd step: Assume true for n, show true for n+1.\n\nThen sum(i=1 to n) = (n-1)*2^(n+1)+2\nThen for n+1:\n\n(n-1)*2^(n+1)+2 + (n+1)2^(n+1)\n= (n-1 + n+1)2^(n+1)+2\n= 2n2^(n+1)+2\n= n2^(n+2)+2\n= ((n+1) - 1)*2^((n+1)+1) + 2\n\nThus it works.
1023705
2 + 2 / 2 =\n2 + 1 = 3
961655
Yes, I can.  Quite simple actually.\n\nBut ask yourself if you know what these words mean:\n\n- integer\n- sum\n- difference\n- product  (think mathematics, not retail)\n- quotient