What is the molecular structure for dichloromethane?
436740
CH2Cl2\nThe molecule shape is tetraedric with the carbon in the middle
635418
CH3CH2CH2CH3 + CL2 -hV--> \nCH3CH2(CL)CHCH3 + HCL ..\n\nwhat are the ways to get the CL at the end of the chain..so that\n\nCH3CH2CH2CH2CL + 2NA + CLCH2CH2CH2CH3\n--->CH3--------CH3\n\nThat's a radical reaction, the chlorination of an alkane with chlorine in UV light. The intermediate is a carbon radical and secondary radicals are more stable than primary. There are also more secondary carbons on this molecule. So probability and reaction kinetics dictates that the primary alkyl halide will be a minor product.\n\nI guess, if this were my synthesis, I'd:\n\n1. Put the glucose in HCl to cleave the anomers it likes to make.\n\n2. Esterify the carboxlic acid with whatever's available (Fisher esterification with MeOH, for example)\n\n3. Reduce the ester with Diisobutyl aluminium hydride (DIBALH)\n\n4. React the aldehyde with 1 equivalent of Ethyl Magnesium Bromide (Grignard)\n\n5. Reduce the hydroxy groups with a Barton-McCombie deoxygenation, although I've never seen it done in a case like this.\n\nThen again:\n\nI'd go to the stockroom and save my research advisor a lot of money. :)
883229
PCl5, or phosphorus pentachloride, has a trigonal bipyramidal structure. A photo of the structure of this molecule is shown below:\n\nhttp://en.wikipedia.org/wiki/Phosphorus_pentachloride\n\nBrF5, or bromine pentafluoride, has a square pyramidal structure: a link to this molecule is shown below as well:\n\nhttp://www.chemistry.ccsu.edu/crundwell/Galleries/VSEPR/brf5.html\n\nBecause PCl5 has a trigonal bipyramidal structure, there is no net dipole moment since the molecule is symmetric around the central phosphorus atom.\n\nBrF5, on the other hand, does have a dipole moment due to the asymmetric structure. The absence of a sixth fluorine atom prevents the structure from becoming octahedral, which would be symmetrical in the structure of BrF6.\n\nSo in short, the differences between the two are as follows:\n\nPCl5=no dipole moment\nBrF5=dipole moment\n\nHope this helps!
768102
p,p-dichloro diphenyl trichloroethane
920400
C10H8.\n\nIt is like two benzene rings that share a common side.
956021
You should go to thewebsite:- chemistry.arizona.com\nu will find your answer.\nor also log on towebsite:-http://www.eol.ucar.edu/~beaton/ChemWeb/images/molemap.gif
37368
You'll need to read (or cut and paste) some of the facts behind those carbon compounds.\n\nXav covered the pure carbon compounds.\n\nMethol seems to be the odd man out, a simple alcohol better known as methanol - CH3OH. \n\nC60Br24 is brominated buckminster fullerene rather than the pure carbon molecule. It will have brom atoms sticking out from the soccer ball shape.\n\nMolecule or crystal models usually come as stick (or stick and ball) models, or as calotte model with spherical balls intersecting. The stick model emphasizes the chemical bonds you know from structural formula of organic molecules and the location of the atom core, whereas the calotte model signifies the extend of the electron cloud surrounding the atom core.
580069
Tetrahedral arrangement at the methyl carbon. (4 bonding pairs, no lone pairs)\nTrigonal planar arrangement at the carbonyl carbon. (3 bonding pairs, no lone pairs)\nBent arrangement at the single-bonded oxygen. (2 bonding pairs, 2 lone pairs)
937026
thank you for this question (I love hybridization questions)\nFirst: ClO2 ??? Actually this is an ion → ClO2 -\nO= 6e-*2 = 12e-\nCl= 7e-*1= 7e-\n+1e-\ntotal= 20e-\nHowever, they all need an octet\n3*8e- = 24e-\n24e- - 20 e- = 4e-/2 = 2 simple bonds\nCl is the central atom, therefore, it must bond twice (one with each O)\ntherefore you require two semifilled orbitals\nNeutral Cl:\n[Ne]-(↑↓)-(↑↓)(↑↓)(↑_)\n-----3s2-///----3p5-----\nCl atom has 7 valence shell electrons by itself, so when it bonds it does one coordinated bond of the two it does, this means Cl looses one of its valence shell electron and gives it to one O atom: now it has 6 and not 7 valence electrons. So we have to check the orbitals again (with Cl atom without one 1 electron)\n[Ne]-(↑↓)-(↑↓)(↑_)(↑_)\n-----3s2-///----3p4------\nNow we have the 2 semifilled orbitals we needed!!\nNow hybridize\n[Ne]-(↑↓)(↑↓)(↑_)(↑_)\n----///--------sp3--------\nThe 2 filled orbitals are the 2 non-bonding pairs of electrons of Cl atom\nThen, your answer is sp3, with a an angular molecular geometry (just like water)
957221
The naming is correct. But the molecule can't exist as described. The Chlor-atom must be attached to the methyl-particle, which is attached to the 3-chloro pentane molecule at the 3rd Carbon-atom.
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There are three possible answers:\n\n1,1-diiodoethylene, which is I2C=CH2\ncis-1,2-diiodoethylene, which is IHC=CHI, with both iodines on the same side\ntrans-1,2-diiodoethylene, which is also IHC=CHI, with the iodines on opposite sides of the molecule
782126
The molecular mass of Iodomethane (CH3I) is 141.94 g/mol.\n\n1g/141.94g/mol = 0.007 moles.\n\n.007 x 6.02 x 10^23 = 4.21 x 10^21 molecules.
445447
1-chloropropane, because chlorine has a higher value of electronegativity.
922867
Check out that link.  It has a picture that shows how it looks like: the grey Al atom is in the center, and 3 green Cl atoms are around it in a triangular arrangement.
665955
it must be polar because the structure is tetrahedral with a lone pair at one corner of the tetrahedron and Cl atoms at the  rest three corners. so the individual As-Cl bond moments are not cancelled bcoz of the asymmetry of the molecule and the net polarity cant be zero.
1154935
methyl3-benzoyloxy-8-methyl-8-azabicyclo [3.2.1]octane-4-carboxylate  (thats the systematic name)\n\nFormula: C17H21NO4
14441
Since propane has three carbon atoms the isomers could be\n\nCl(CH2)-CH2-CH3\nor\nCH3-CH(Cl)-CH3\nThe isomerism in it is structural or position isomerism.\n\n\nThe reaction is as under\n             SN2  \nC3H9 + Cl2 --------------> monochloropropane\n\nThe mechanism is Nucleophilic Substitution. It is usually SN1 that is Unimolecular substitution.