x^1/2 + y = 11 and y^1/2 +x = 7, Find x & y answer with full process?
443349
We are given:\nx^1/2 + y = 11 ---- eqn. 1\ny^1/2 + x = 7 ----- eqn. 2\n\nLet a = x^1/2. Therefore x = a^2\nLet b = y^1/2. Therefore, y = b^2\n\na + b^2 = 11 ==== eqn. 3\na^2 + b = 7 ==== eqn. 4\n\nSub. (3) into eqn. (4):\n\n=> (11 - b^2)^2 + b = 7\n=> 121 - 22b^2 + b^4 + b = 7\n=> b^4 - 22b^2 + b + 114 = 0\n\nUsing trial and error, we can arrive that (b-3) is a factor.\nTherefore, by factorisation:\n=> b^4 - 22b^2 + b + 114 = 0\n=> (b-3) (b^3 +3b^2 - 13b - 38)=0\nTherefore, b = 3  (there are no other possible root values for b because the cubic equation lies completely above the x-axis.)\n\nSince b = 3, therefore, y = 9. And back into eqn. 1, x= 4.
472370
-11a + 7 < -12a + 18 \n a + 7 < 18            .( Added 12a to both sides)\n a < 11                .(Subtracted 7 from both sides)\n\na < 11 (FINAL answer- a is less than 11)
836116
Let x and y be your numbers.  Your equations, therefore, are the following:\n\nx+y = 72\nx-y = 12\n\nDo you need to actually solve for x and y as well, or just set up the equations?  If you also need to solve, then write your two equations one on top of the other, then subtract to get an equation in one term only:\n\nx + y = 72\nx - y = 12\n----------------\n0x + 2y = 60\n\nSo, 2y = 60, which means y = 30\n\nNow substitute y=30 into one of the original equations to solve for x:\n\nx + y = 72\nx + 30 = 72\nx = 72  30 = 42\n\nSo your two numbers are 30 and 42\n\n~ ♥ ~
792411
put y = 7 and x =4 and solve for c\nwe get 7 = 16+c or c = -9
858227
Multiply it out, mayhaps.\n\nx^2 +x + y - y^2\n\nWhich is also\nx(x + 1) + y(1-y)\n\nWhy does this question have four answers below, ALL OF WHICH STATE THE SAME THING?
961234
Let x = y^(1/3)\nx^2 - 9x + 8 = 0\n(x - 8)(x - 1) = 0\nx = 8 or 1\ny^(1/3) = 8 or 1\ny = 2 or 1
780055
1/x + y\n______\nx + y\n\nMultiply the top and bottom by x\n= \n1 + xy\n______\nx^2 + xy\n\n\n(x-1)/x divided by ((x^2 -1)/(x+4)\n= (x-1)/x times (x+4)/(x^2 -1)\nFactor x^2 -1 = (x-1)(x+1)\nYou can cancel the (x-1)'s leaving you with\n(x+4)/[x(x+1)]\n\nNote:  For the first problem, if you meant\n1/(x+y)\n______\nx + y\nthen the answer is 1/(x+y)^2
223472
x - 1 / x + 3 = x + 2 / x - 4\nx-1/x-x-2/x = -3-4\n-1/x-2/x = -7\n-3/x = -7\n7x = 3\nx=3/7
94721
y= 2x + 11 and y=-x + 5 \n\n2x + 11 = -x + 5\n3x + 11 = 5\n3x = -6\nx = -2\n\ny = -(-2) + 5\ny = 2 + 5\ny = 7\n\n(-2, 7)
732691
The first problem is easy\nx=7/2 or x=3 and 1/2\n\nand for the second it is still pretty easy\nJust put in 0 for y or x which ever one you want to find\nLets find y first...so you put 0 in for x\n\n4(0)+5y=10\n5y=10     divide both sides by 5\ny=2\n\nThen find x....so put 0 in for y\n\n4x+5(0)=10\n4x=10       divide both sides by 4\nx=10/4      then simplfy\nx=5/2\n\nx=5/2    y=2\n\n\nohhhhhhhhhhh my bad I thought they were 2 different problems....well if they are 2 different problems im right....if they are 1 whole problem then the other people are right....
581691
if by this you mean\n\n((x^2)/2) - ((7x)/4) = (-3/2)\n\nMultiply everything by 4\n\n2x^2 - 7x = -6\n2x^2 - 7x + 6 = 0\n(x - 2)(2x - 3) = 0\nx = 2 or (3/2)\n\nANS : x = 2 or (3/2)
741076
1/x+3/x+2=7\nMultiply by x getting:\n1+3+2x =7x\n4-5x =0\n0x* -5x +4 =0\n\n7/2x+2/x-1=4\nMultiply by 2x getting:\n7 +4 -2x =8x\n11-10x = 0\n0x* -10x +11 = 0\n\nx*+7x+2=2x+4\nx* +7x -2x +2 -4=0\nx* +5x -2 = 0\n\n4x*-3x=2x*+7 \n4x* -2x*-3x -7 =0\n2x*-3x-7 =0\n\n2x+3/x-1=x/4\nMultiply by x getting:\n2x* +3 -2x = x*/4\n2x* - x*/4 -2x +2=0\n2.25x* -2x +2 = 0\n\nThere, its done simply by multiplying and transposing terms to get what you want. You can move any term from one side of the equation to the other as long as you change its sign fro minus to plus or plus to minus.
848564
Substitute 2x-1 for y in the middle part, you get:\nx^2 + x -6(2x-1) = 2x-1\nThis you can reduce to a quadratic equation for x.
60538
if [ -7x + x^2 =0 ]\nthe you will get y = 7/x
871875
x+y=-7\nxy=60\n\n(x+y)^2=x^2+2xy+y^2\n49=x^2+y^2+120\n-71=x^2+y^2\nx^2>=0 and y^2>=0\nso I don't think there is a solution\n\nif their sum is -7 and their product is -60... then 5 and -12 are your numbers
816596
x-11=2(-7)\nx=11-14\nx=-3\n\nCheck:\n  -1/7 (-3-11)=(-1/7)(-14)=2 OK\n\nOr did you mean\n\n-1/(7(x-11))=2    Then\n-1=14(x-11)\nx=11 - 1/14\nx=10 13/14\n\nCheck:\n  -1/(7/-1/14))=14/7=2   OK
246990
(7,5) and (11,9)\n\nlet them be (x1,y1) and (x2,y2)\n\nslope of line is (y2-y1)/(x2-x1)\n\nthus slope is (9-5)/(11-7) = 4/4 = 1\n\nequation of line is given by the formulae\n\n(y-y1)=slope*(x-x1)\nor\n(y-y2)=slope*(x-x2)\n\nso equation can be...\n\n(y-5)=1*(x-7) that is x-y=2\n\nor\n\n(y-9)=1*(x-11) that is x-y=2\n\nsee its the same in both cases !\n\nthe required equation is x-y=2 !!!