how do you find the measure of an arc on a circle?
450833
join the 2 pointz frm da arc vit da radius.measure out da value of da angle forned here.then substitute da values 4 this formula:  2*pie*radius/da angle u measured\n\nhappy solvin!
534712
Actually sometimes. A secant passes through a circle at two points, a tangent at one. You COULD have a secant hit the tangent at a point other than the point of tangency, and there is indeed a theorem around for determining the relative lengths of lines and so forth, but many questions dealing with area and arc length put the vertex at the point of tangency for simplicity's sake.
508595
You have two ways:\nOld one: Thomson divide the arc into strips at equal intervals and solve each.\nNew one: Integrate from y=0, first root to y=0 second root
408251
Measure the diameter and multiply by pi (3.1415)
634060
The length of one side of the rectangle can be related to the Circumference of the circle.\nTo get the perimeter of a circle, called the circumference of the circle, one simply has to multiply 2 times pi (about 3.14) times the radius of the particular circle. \nThe circumference of a circle can be calculated from its diameter using the formula:\nc = πd\nOr, substituting the radius for the diameter:\nc = 2πr\nWhere r is the radius and d is the diameter of the circle, and π (the Greek letter pi) is the constant 3.141 592 653 589 793...
746090
If you want to draw a straight line the same length as the circumference of the circle then first you must measure the radius of the circle. This is the straight-line distance between the centre of the circle and the edge.\n\nThen multiply the length you found for the radius by 2π. This will give you the length of the circumference. i.e:\n\nC = 2πr\n\nTake a ruler and draw a straight line with the same length as the circumference you have just worked out.
1031322
Perimeter of a circle = 2 *pi* radius or = pi *diameter\n\nFrom your picture the diameter of that semicircle = 8 \n\nso the perimeter of the circle = 8 * pi\n\nperimeter of semicircle (half circle) = 8*pi / 2 = 4* pi\n\nAlso, you can find the radius of the circle = diameter/2 = 8/2= 4\n\nThe Width of that rectangular = 1+ radius = 1+4 = 5\n\nThe two bottom short edges = the length of the rectangular - diameter of the semicircle = 10-8=2\n \nThe perimeter of the shaded area = Length of the rectangular + 2 * width  +  two bottom short edges + perimeter of the  semicircle = 10+2*5+2+4*pi=22 + 4* pi\n\nthe answer is a.\n\nHave fun !
160871
Divide 34 by PI...that will give you the diameter.\n\nDiameter = Circumference / PI
389433
If you're asking how to do it: Just take the total number of degrees of the angle, divide by two, and there you go, you know the measurements of the 2 equal angles.\nanswered by Fading Away...\n\nAngle bisector Theorem.\n\nIf you are a Geometry student who knows constructions, locate a radi from your vertex and draw an arc. Choose another radii on that new arc that you just drew(That is more than half the arc) from the point where your newly drawn arc intersects the segment. Draw another arc. Repeat process on opposite side. Draw bisectore from vertex through intersection of two arcs.\n\nHope that helps!\nAnswered by Emily\n\n\n\nThis was asked and answered 13 hours ago, click this link.\nhttp://answers.yahoo.com/question/;_ylt=Al6hLACuaPLouhbP7BmwxcIjzKIX?qid=1006041024466
714881
First, you take a REALLY BIG tape measure and measure around the whole earth at the equator.  That gives you the circumference of the two dimensional circle defined by the equator.  Divide that number by pi.  Then divide the resulting quotient by 2.  Now you have the radius.\n\nIf you don't have a tape measure that big, and your mom won't give you the recipe for pi, you can try a different method.  Check out this method to get the circumference:  http://staff.imsa.edu/science/astro/astrometry/ground1.html\n\nThe Greek had of the library of Alexandria did it more than two thousand years ago.  All you have to do it get to Egypt at noon on the 21st of June for two years in a row.  And you have to find two wells.  \n\nOnce you have the curcumference, you can use my recipe for pi.  (3.160484) Once again, divide the circumference of the earth by pi, and then by 2.\n\nHope this helps.
945543
A short element of the curve is dL=sqrt(dr^2+(r*dt)^2), r*dt elementary length of the arc with radius r and polar angle t (your theta), dr elementary increase of r for dt.\nThus dL=sqrt(r’^2+r^2)*dt.\nIf  r=a*(1-cost), then dL=a*sqrt((sint)^2+(1-cost)^2)=a*sqrt(2)*sqrt(1-cost)*dt. \nFortunately 1-cost=2*(sin(t/2))^2 or dL=2a*sin(t/2)*dt, L=-4a*cos(t/2) for t=0 until 2pi, thus L=-4*a*(-1-1)=8*a – Oh! check it poor kid!\nIf r=(sin(t/2))^2=0.5*(1-cost), then a=0.5 for t=0 until pi. It must be done likewise. Thus L=-4*0.5*(0-1)=2
303304
Use the well known formulas that relate the radius and diameter of a circle to its circumfrence.\n\nC = pi * D\nC = 2 * pi * R\n\nFor pi, you can use 3.14 or 22/7, or whatever value your teacher wants you to use.
1143102
Example - you'll need to apply it to your own endpoints.\n\nA circle is described on the line joining (-2,5)and(3,4) as diameter, find its equation:\n\nThe equation for a circle is:\n(x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center and r is the radius\n\nIt is easiest to find the center first. it is the midpoint of the line and the slope is constant:\nh = x1-[(x1-x2)/2] = 3 - 5/2 = 1/2\nk = y1-[(y1-y2)/2] = 5 - 1/2 = 4.5\n\nNow, find the radius using the distance formula to find the distance between the center and the endpoint or by using a right triangle where dx and dy are the lengths of the legs. I prefer the latter, but they are pretty much the same:\ndx^2 + dy^2 = r^2\nr^2 = (5/2)^2 + (1/2)^2= 26/4 = 13/2\nBy substituing back into the equation for a circle:\n(x-.5)^2 + (y-4.5)^2 = (6.5)^2 = 42.25
436643
If the shape is a quadrilateral, the measures of its opposite angles WOULD add up to 180 degrees.  This is because the measure of an inscribed angle (an angle with vertex on the circle) is half the measure of its intercepted arc.  Between the two opposite angles, their combined arc is the whole circle which measures 360 degrees.  So the sum of the inscribed angles is half of that, or 180.
418892
Since O is the center, this problem becomes fairly straightforward.  First, assuming <BOA = 94 degrees (not sure which of the four angles at O is 94 degrees, but say it's <BOA.  This means that the arc from B to A is also 94 degrees.  And since the chord from A to C goes through the center, it means it is a diameter.  This means that the arc from A to C is 180 degrees (half of the circle).  So that means that the arc from B to C has to be 86 degrees (180 - 94, because part of that arc from A to B is 94, the rest must add up to 180).  So now you have to use what your teacher told you about when the angle is on the circle.  Namely, that the angle on the circle (the inscribed angle) is half of the arc measure (intercepted arc).  So if the arc measure is 86 degrees, the angle must be 43 degrees.\n\nEdit: I just saw that it was <COD, not <BOA, but they are congruent because the are vertical angles, so nothing changes.
657525
If you have the equation of the curve then integrate it on the lower and upper limits of the variable. In some cases you can find devide the identical parts and find out area of a single identical part and multiply by the number of parts made (sine wave).\n\nIf shape is a simple square circle etc you can find area by simple formula.
488009
Formula:arc length = radius * angle inscribed by arc, \n\nor:\n\nS=r*theta\n\nIf you know the arc length already, take a protractor and measure the distance in degrees between the two end points.\nConvert angle to radians by multiplying by pi/180, and then plug it into the equation and solve for r.