Does anyone know the formula to find the slope of a line?
454789
y=mx+b\n\n"m" is the slope, and "b" is the y axis. Best wishes in your studies!
267671
First find its slope using the formula slope=(y2 - y1)/(x2 - x1) where x2 = the second x-coordinate, etc.\n\nslope = (-5 - 5)/(4 - -2) = -10/6 = -5/3\n\nthen choose either point and use the form for an equation of a line:  y - y1 = slope(x - x1)\n\nso either y - 5 = -5/3(x - -2)  [which becomes (x+2)]  or\n\ny - -5 which is y + 5 = -5/3(x-4)
206717
Slope = 1/4\n\nSlope is the "change in y" divided by the "change in x" (AKA "rise" over "run").\n\n(x1, y1) = (1, 3)\n(x2, y2) = (5, 4)\n\nThus:\n\nm (slope) = "delta y"/"delta x"\nm = (y2 - y1)/(x2 - x1)\nm = (4 - 3)/(5 - 1)\nm = 1/4
408060
To find the slope, you always have to set the equation as y=mx+b.  That equation is called the slope-intercept form.  "m" is the slope and b is the y-intercept.\nNow, to find the slope, try to get y alone.\n1. Subtract 2x from both sides.  You'll get: -8y=-2x+7\n2. Divide both sides by -8.  You'll get: y=(1/4)x+(-7/8)\nSo, the equation is y=(1/4)x-(7/8) and the slope is (1/4).
653148
All equations for a line will have the form:\n\ny = mx + b,\n\nwhere x & y are coordinates, m is your slope, and b is your y-intercept.\n\nTherefore, substituting in your slope and y intercept, you get:\n\ny = -2/3x + 4\n\nThis equation can then be used to graph the line, since given any x, the corresponding y can be found. :)
749030
y = m (x-x1) + y1\nm=slope (so m=2)\nx1 and y1 are the coordinates. Just plug your numbers in and expand the m(x-x1) part.
554784
x=(1--2)  or (1+2)\ny=(5-3)\n\ny/x=slope\nx=3\ny=2\nslope is 2/3
814480
The slope-intercept form of a line is\ny = mx + b, where m is the slope and b is the y-intercept.
509875
We use point slope to find the equation for the line:\n\ny - y1 = m(x - x1)         Initial Equation\ny - 7 = 3(x - 2)           substitute\ny - 7 = 3x - 6             distribute\ny = 3x + 1                 Add 7 to each side to solve for y\n\nNow that we have the equation for the line, we want to know where the line crosses the x axis.  That means we put 0 in for y and solve for x.\n\n0 = 3x + 1      Initial equation with 0 substituted for y\n-1 = 3x         Subtract one from each side\n-1/3 = x        Divide each side by 3.\n\nDone - the answer is (d) -1/3
1088418
Equation/Formula for Point slope equation is y = mx + b wherein b is the y intercept and m is the slope.\n\n1. y intercept = -3\n    slope = 4\n\n2. y intercept = 4\n    slope = -3\n\n3. y intercept = 0\n    slope = 3\n\n4. you must simplify this one. The solution is:\n\n(step by step)\n\nIsolate the y     4/5y = -1/2x + 1\ncancel the fraction beside y  (5/4)4/5y = -1/2x(5/4) + 1 (5/4)\nand then it becomes    y = -5/8x + 1 1/4\n\nso then the y intercept is = 1 1/4 (--one and one over four)\nand the slope is = -5/8\n\n*when looking for the slope, do not inclued the variable "x" in your answer :)\n\nI hope this helped :)
775556
*Note that when the line is vertical the slope is undefined.\nVertical lines have the form x = c.\nTherefore, since this line passes through (2, -3), the x value is 2, and the equation for this line is simply x = 2.\n\nhttp://www.wtamu.edu/academic/anns/mps/math/mathlab/int_algebra/int_alg_tut15_slope.htm\n\nhttp://math.about.com/library/weekly/aa120502a.htm
1101719
Step 1: Find the slope of the line x-2y = 2.  Call it m. \n\nStep 2: Find the derivative f'(x) of the function f(x) = (x-1)/(x+1).\n\nStep 3: Find all values of x where f'(x) = m.\n\nStep 4: For each such value, find its corresponding y-coordinate by setting y=f(x), and then find the equation of the line that goes through that point with slope m.\n\nGood luck!
194847
Im not gonna give u the answer, coz u wont learn otherwise, but i can tell you how to solve it...\n\nWell, remember that the standard equation for a line is \n\ny = mx + c\n\nwhere m is the slope of the line... Now, there is a relation between the slopes of two lines if they are parallel, look it up yourself...\n\nSo u have the slope of the line whose equation u need to find... U also have a point thru which it passes... Another representation of the equation of a line is...\n\ny - y1 = m(x - x1)\n\nwhere x,y are the variables for the eqn, m is the slope of the line, and x1, y1 are the (x,y) co-ordinates of a point thru which the line passes...\n\nYouve got all the stuff, throw it in, and wolla...
1163751
If you are given the slope(m) and a point on the line(x1, y1) you can write the equation of the line.\n\nYou take the y-intercept equation\ny =m*x + b and substitute x1 and y1 for x and y and get\ny1 = m*x1 + b    \nnow solve for b\nb = (y1-m*x1)\nsubstite b = (y1-m*x1) into the y-intercept equation\ny =m*x +(y1-m*x1)\nsubtract y1 from both sides of the equation\ny -y1 = m*x -m*x1\nbecomes the point-slope formula\ny -y1 =m*(x-x1)
97021
Using the points you can work out the slope. That is 0.\nThen use one set of points and the slope to work out the equation of a line formula which is:   \n         y-y1=m(x-x1)\nm is the slope \n       y+4=0(x-11)\n       y+4=0\n       y=-4
91103
x=-3 is the equation for the line.\n\ny=mx+b where m is slope and b is y-intercept.\n\nm=change in y/change in x= [(-3)-1]/[(-3)-(-3)]\nm=-4/0\nWhen you divide by zero the answer is undefined, so slope is undefined.\n\nOnly vertical lines have undefined slopes, so the equation for the line is x=-3. This means that no matter what value you pick for y, x will be equal to -3.
845789
the formula equation for point-slope form is:  y-y1= m(x-x1)...the person that answer b4 me is a dipsh*t......\n\nall u need to do now is substitute (plug-in) the given info....\n\ny-5= m(x+4)\n\nto find m (slope)...well f*ck it, ill do it for you...\n\nm=-3/10\n\nTHEREFORE:  the final point slope equation that passes thru (-4,5) and (6,2) is..... y-5= -3/10(x+4)\n\n\nyour welcome