If magnetic flux is measured in Webers,than magnetic field intensity is = seconds per meter squared?
437468
Magnetic flux is measured in Webers.\nLooking at the link below, we can translate Webers into other units:\nWebers = Volts x seconds\nWebers = watts/amps x seconds\nWebers = joules/seconds/amps x seconds\nWebers = joules/amps\nor an amount of energy per unit current.\nMagnetic field strength is measured in amps/meter:\nthe more amps, the more field strength\nthe farther you are from the wire(s) generating the magnetic field, the less field strength\n\nIf you consider Einstein's equations, Maxwells' equations, and the Lorentz transformation, then you see that a magnetic field can also be thought of as what an electric field looks like when you move past the electric field as very fast (appreciable percentage of speed of light) speeds.
890895
depends on charge density, configuration of layers, solar activity, magnetic field, etc\nf_{critical} = 9 x10^-3 /sqrt{N}, where N is electron density per cm^3\n\nIt's around 1-4MHz
702587
It won't be easy to calculate.  You can easily calculate the strength of the magnetic field of the electromagnet with the current and the number of turns.  But it's harder to know the field strength of the bar magnet, and even harder to calculate the force produced by the interaction between the fields.  Once you got that force, it's easy to compare that to the gravitational force on the mass of the bar magnet.  It's probably easier just to build it and try it.  All you really need is a coil of wire and a current.\n\nOnce you have the apparatus, borrow an instrument to measure the fields.  I'd have more fun with a ball bearing on a circular (non-magnetic) track, timing the current to make the ball move around the track, like a cyclotron.
805635
it is generated through an AC generator which contains one rotor an two magnatic poles.\nin deatil:-\nwhen a coil of soft magnetic substance moves in a magnetic field it cuts the flux of magnatic field and as a result of it and the equation EMF=b*l*v AC current produces\nwhere b is magnatic strength,l is lenth of coil v is velocity or rotational velocity of coil in magnetic field
1065070
Exactly 299,792,458 meters per second (m/s). I say exactly because at one point the official length of a meter was modified slightly to make c come out to a even number of meters per second, rather than having some annoying decimal places.\n\nStill, most people prefer to round up to 300,000,000 m/s.
539149
A bit rusty, but here it goes - I beleive they subtract fro m the net magnetization. If some of the ions are anti-aligned it is called ferrimagnetic. If the ions anti-align completely it is called antiferrmagnetic.
1093605
The meter is the length of the path traveled by light in vacuum during a time interval of 1/299 792 458 of a second.
737153
Starting from rest, the electron will have a kinetic energy of 25 electron volts (eV) after passing through the electric field.  One eV = 1.602*10^−19 J, and the kinetic energy (neglecting relativistic effects, which are not important here) is 0.5*m*s^2, where m is the rest mass of the electron, and v is its speed.\n\nWe have, therefore:\n\n25 eV * 1.602*10^−19 J/eV = 0.5*9.11*10^-31 kg * s^2\n\ns^2 = 8.79*10^12 (m/s)^2\n\ns = 2.96*10^6 m/s\n\nThe force on a particle with charge q, moving with vector velocity V in a magnetic field B is given by:\n\nF = qV x B\n\nwhere "x" means the vector cross product.\n\nIf, as it seems in this case, the velocity vector and magnetic field vector are perpendicular to one another, then  the magnitude of the force is simply given by the ordinary algebraic product of the charge, the magnitude of the velocity (i.e., the speed), and the magnitude of the magnetic field, so:\n\n|F| = q*|V|*|B|\n\n|F| = 1.60*10^-19 C * 2.96*10^6 m/s * 0.5 T \n\n|F| = 2.37*10^-13 N\n\n(It helps to know that 1 tesla = 1 kg/(sec*coulomb) here).\n\n \nThe force vector is oriented perpendicular to both the velocity and the magnetic field.  However, there are still two possible directions that satisfy this condition.  The ambiguity can be resolved by using the "right hand rule":  point your index finger along the direction of the velocity vector, and your middle finger along the direction of the magnetic field.  Your thumb will then point in the direction of the force vector.  You'll have to figure out how this applies to what I assume was the figure provided with your problem.\n\n\n\nTo determine the radius of the electron's orbit, we equate the magnetic force with the centripital force:\n\nq*|V|*|B| = (m*|v|^2)/r\n\nr = (m*|v|^2)/(q*|V|*|B|)\n\nr = (m*|v|)/(q*|B|)\n\nr = (9.11*10^-31 kg * 2.96*10^6 m/s)/(1.60*10^-19 C * 0.5 T)\n\nr = 3.38*10^-5 m
827354
The magnetic field of Earth is caused by molten iron rotating around in the core.  The lines of magnetic flux follow the right-hand rule (RHR).  Curve the fingers of your right hand into a loose fist and extend your thumb upward.\n\nAs the molten iron swirls around in the direction of your curled fingers, the flux is emitted in the direction of your extended thumb.  The flux is created because the swirling molten iron creates an electrical current that follows the swirl.  That current, like a current going through a coil, creates the magnetic flux.\n\nA flux is simply a line of force and that force, like all forces, has direction.  In this case, the force points outward in the direction of your thumb.  That's called the magnetic north pole, by convention.  \n\nHowever, because the magnetic flux exits the Earth at this pole it really is the south pole.  This can be verified because the north pole of a compass needle will point north and, as you well know, north is attracted to south.  Thus, the magnetic north pole is really the south pole...argh...physics is so complicated.\n\nAs to why like poles repel and dissimilar poles attract, blame in on the direction of the forces...the flux of that magnetic current.  (Magnetism does not really flow, but the forces act as though it does.)  Two similar poles either push each other away (e.g., two south poles) or pull away from each other (e.g., two north poles) because the forces are toward or away from the two magnets respectively.  Two dissimilar poles attract each other because the alligned forces pull one toward the other when they are all in the same direction.  [See source.]
890360
I have already answered part 1. in another question you've asked. I think you probably didn't use the right units (like cm needs to be convered to meters) and got the wrong answer.\n\nNow for part 2:\n\nInduced EMF, ℰ = -L(di/dt)\n\nwhere i is the current and L is the inductance\n\nWe are given that the magnitude of the induced current,\n\ndi = 47 mA\n\nand the oscillation frequency is 100 Hz. This means that dt = 1/f = 0.01 sec\n\nWe have L = 8.44 × 10-^3 henries from before\n\nSo |ℰ| = L(di/dt) = -(8.44 × 10-^3)(0.047)/(0.01) = 0.0397 volts\n\n------------------------------------------------------\n\nNow part 3 has to do with mutual inductance:\n\nVs = VpNs / Np\n\nwhere \n\nVs is the voltage across the secondary inductor, \nVp is the voltage across the primary inductor (the one connected to a power source), \nNs is the number of turns in the secondary inductor, and \nNp is the number of turns in the primary inductor. \n\nTherefore Vp = VsNp/Ns and Vs = 0.0397 volts as calculated before, so\n\nVp = (0.0397)(197)/(2920) = 0.00268 volts
152758
The measure magnetic fields with a magnetometer.
864791
A.) 3.02891 seconds\nB.) 290.1 m/s\n\nTrust me... =)
310895
Magnetic flux \nweber: Wb = V s = W s/A = m^2 kg/s^2 A \n\nMagnetic flux density, magnetic induction \ntesla: T = Wb/m^2 = kg/s^2 A
910705
Hello, here is what you need:\n\nEnergy = Planck Constant * Frequency\n\nE = h * f\n\nh = 66.26 x 10^-34 Joule second
781372
"The flux through an element of area perpendicular to the direction of magnetic field is given by the product of the magnetic field density and the area element. More generally, magnetic flux is defined by a scalar product of the magnetic field density and the area element vector. Gauss's law for magnetism, which is one of the four Maxwell's equations, states that the total magnetic flux through a closed surface is zero. This law is a consequence of the empirical observation that magnetic monopoles do not exist or are not measurable."\n\nThis, and much more, including equations, are on Wikipedia:\nhttp://en.wikipedia.org/wiki/Magnetic_flux\n\nHope this helps!
819211
Only 70% of the power flux reaches the surface ot the earth.\nThe electric field is defined a Newton per unit charge..\nThe power flux from the sun is really radiation power its Usually measured in Joules per second per meter^2. \nVolt per meter is = to force per unit distance. Its resulting units are kg /sec^2. which is not equal to joules/sec/meter^2.
1124301
Are you trying to figure out when it stops? \n\nIf so, look at your units:\n\nYou have meters per second squared, and meters per second... To get to seconds you're going to invert the meters per second squared and then multiply... \n\nYour answer is 7 seconds.