n*n+18n+56 factor trinomial?
443949
Use quadratic formula and do your own homework.
84658
i got it!\n\nit's 3(2c+7)(c-4d)(c+d)!!!!\n\n6c^3 + 21c^2 - 18dc^2 - 63cd - 24cd^2 - 84d^2\nfirst we take out factor 3:\n3(2c^3 + 7c^2 - 6dc^2 - 21cd - 8cd^2 - 28d^2)\nthen we take out (2c+7) from each pain inside the parenthesses:\n3[(2c+7)c^2 - (2c+7)3cd - (2c+7)4d^2)]\nwe take (2c+7) out:\n3(2c+7)[c^2 - 3cd - 4d^2]\nwe factor [c^2 - 3cd - 4d^2] trinomially:\nc^2 - 3cd - 4d^2 = (c-4d)(c+d)\nthen we get:\n3(2c+7)(c-4d)(c+d)\n\nam i right??\n\n:) yeah i didn't believe myself...\nbut if u really write down all your factors, it's much more easier to take them out. and it WAS fun :))
316451
the numbers are \n 2+6+18= 26\n 2*6*18= 216
114428
seriously? okay: P = 2(18) + 3(24) = 36 + 72 = 108 in
703982
1.\n3x + 6/((x + 1)(x + 2)) Factor 3 out of the top.\n[3(x + 2)]/[(x + 1)(x + 2)] x+2's cancel\n3/(x + 1) <-- This is simplified.\n\nI don't have the energy to do the other ones right now.  :/
1139003
(n/(n - 3)) + (5/(2n - 6))\n(n/(n - 3)) + (5/(2(n - 3)))\nMultiply everything by 2(n - 3)\n(2n + 5)/(2n - 6)
503153
(x+7)(x+3)\n(x-11)(x+2)\nforget this one.  its AC factoring though\nthis ones AC too
1166207
2[w+ {2w+8}]= 64\n3w+8 = 32\nw= 8 \nyour are right
417593
no because 8n^2 - 72p^2 can still be factored\n8 is the common factor \n8(n^2-9p^2)\n8(n-3p)(n+3p)
250266
The fourth term in a sixth order binomial expansion has a coefficient given by 6 choose 3. This is because we need to consider all rows of Pascal's triangle beginning with row zero, column zero. 6 choose 3 falls on row 6 column 3 and is 6!/(3!*3!)=20. This factor will then be multiplied by x^3 as well as (-2y)^3. Together the fourth term will be:\n\n-160x^3y^3
23824
3n - 16 < or equal to 8n + 29\nSubract both sides by 3n.\n-16 < or equal to 5n +29\nSubtract both sides by 29.\n-45 < or equal to 5n\n-9 < or equal to n\nn > or equal to -9
802282
(n + 3)(2n + 3) = (n + 2)^2 + (n 2)2^2\nFirst use FOIL to simplify\n2n^2 + 3n + 6n + 9 = n^2 + 2n + 2n + 4 + n^4\nCombine like terms on each side\n2n^2 + 9n + 9 = n^4 + n^2 + 4n + 4\nMove everything over to one side.\nn^4 - n^2 - 5n - 5 = 0\nFactor.\n(x+1)(x^3 -x^2 -5) = 0\nThat means x+1 = 0 or x^3 -x^2 -5 = 0\nx+1 = 0 when x = -1\nx^3 -x^2 -5 = 0 when  = 2.1163
921580
The factor of 8 and 56 is 8.\n8v+56\n=8(v+7)           [This is because when 8v and 56 are divided by 8,\n                         the remainer is v and 7 respectively]
300929
r is probably 27 and t is 8. Here's my reasoning:\n\n18 * 18 * 18 = r * r * t\n5832/r = r * t\nLets factorize 5832\n5832 = 27 * 27 * 8\nAnd Since 27 > 8, it can be accepted as the solution.\n\nI don't know if this is the correct way of doing it. Anyway, in my opinion worth a shot.
436598
Remember that a factorial is basically the product of that number, that number - 1, all the way down to 1.\n\n1. (n-1)(n-2)(n-3)(n-4)(n-5)...1\n---------------------------------\n(n-4)(n-5)...1\n\nCancel the (n-4) and everything after.\n\nANSWER : (n-1)(n-2)(n-3)\n\n2. (n+6)(n+5)(n+4)(n+3)...1\n---------------------------\n(n+3)(n+2)...1\n\nCancel the (n+3) and everything after\n\nANSWER : (n+6)(n+5)(n+4)\n\nEDIT : Lattisrectum, keep in mind that (n-4)! is (n-4)(n-5)(n-6)... all the way to 1, not (n-4)(n-3)... :)
338536
3(6) + 7 = 24\n18 + 7 = 24\n\n25 = 24\n\nNo.
775090
You have to find the two polynomials that when multiplied by each other will equal the trinomial.\n\nx2 + 8x - 9\n\n(x + 9) (x - 1)\n\nx*x + -1x + 9x -9\n\nx2 + 8x - 9