what are the steps of the sliding filament theory?
85291
In the absence of calcium ions, tropomyosin blocks access to the mysosin binding site of actin. When calcium binds to troponin, the positions of troponin and tropomyosin are altered on the the thin flament and myosin then has access to its binding site on actin.\n\nMyosin hydolyzes ATP and undergoes a conformational change into a high-energy state. The head group of myosin binds to actin forming a cross-bridge between the thick and thin filaments. The energy stored by myosin is released, and ADP and inorganic phosphate dissociate from myosin. The resulting relaxation of the myosin molecule entails rotation of the globular head, which induces longitudinal sliding of the filaments.\n\nWhen the calcium level decreases, troponin locks tropomyosin in the blocking position and the thin filament slides back to the resting state.
284573
good link below\n\nhttp://en.wikipedia.org/wiki/Kinetic_theory
848443
when u will draw ur inclined plane and mass on it there r different forces acting in it \nfirst force will be directly perpendicular to the ground level i.e. Fg=mg\nsecond force acting is mgcos(theta) which is perpendicular to hypotenuse of the inclined and makes up Fn=mgcos(theta)\nthen another component parallel to the hyp. of the inclined \nwhich equals mgsin(theta) which goes down the ramp\nand  then u can\nequal the force going down with the frictional force\nmgsin(theta)-(mew)mgcos(theta)=ma\n(as we know frictional force is (mew)Fn=(mew)mgcos(theta) )\nsolve by putting values\nmew=0.146    ans
1119730
ahh, good theory problem...\nlet's see, there's energy, friction, force (normal, tension, as well as the other ones mentioned), gravitation, mass, pendulum motion, gotta be more that I've missed, but no doubt someone'll be here to correct me.
975858
1. potential\n2. kinetic\n3. it left at 0\n4. friction\n5. the greater the mass, the less  distance\n\nYour source of errors and improvements must come from your lab
730275
It's called 'impulse' and any good, lower division, physics book will have an explanation of what it is and how it works.\n\n\nDoug
856335
Here are the key things you need to know:\n\nForces acting on the small box:\n- gravity attracting its mass (pulling it downward)\n- large box (pushing it upward)\n- friction force between the two boxes (pushing it forward)\n\nForces acting on the large box:\n- gravity attracting its mass (pulling it downward)\n- the weight of the small box (= the force of gravity on the small box) (pushing it downward)\n- friction force between the two boxes (pushing it backward)\n- friction force between the large box and the underlying surface (pushing it backward)\n- the horizontal force (pushing it forward)\n\nFirst, treat the two boxes as a single mass, resting on the surface and being accelerated by the horizontal force. Calculate the force of friction between the large box and the surface (remembering that the weight of both boxes is acting to push it against the underlying surface). Calculate the force needed to both overcome this friction and to accelerate the mass of the two boxes at the specified rate (the second part of this requires the formula F = ma). That is the horizontal force.\n\nNow calculate the amount of force required to accelerate the small box at this rate. (Use F = ma again.) Divide this force by the weight of the small box to find the minimum coefficient of friction that will allow the large box to apply this force to the small box.\n\nIf you understand all this, you should be able to draw the two diagrams and answer the questions.\nGood luck!
238922
Howstuffworks has good diagrams and explanations that may help you.  Good luck.
221019
Have a look at the reference for an explanation of Bragg's Law\n\nIf the surface plane is plane 0, the next one plane 1 etc.\n\nThe path difference (PD) between plane 0 and plane 1 is 2d sin theta = 1.01 lambda\n\nThe PD between plane 0 and plane a is 2ad sin theta = 1.01*a*lambda\n\nCancellation occurs when the waves are out of phase by half a wavelength, i.e. the path difference is lambda times [an integer (whole number) plus 0.5]\n\nSo we’re looking for a vale of a where 1.01*a = integer + 0.5\n\nSuitable values are plane 50 (PD = 50.5), plane 150 (PD = 151.5), plane 250, 350 etc.\n\nTip: Don't get into X-ray crystallography, it'll drive you nuts!
225726
Check out this web site. It has the steps shown on a pic.\n\nhttp://www.paperhall.org/exhibits/pmp/paperline.jpg
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Detailed information as well as equations are available on the following page : \n\nhttp://www.jwave.vt.edu/crcd/kriz/modules/module06/formulation/edge_formulation.html
954062
put an arm perpindicular on the shaft, put another arm pinned to the first, and slide the second through a sleeve.\n\njust like an old fasioned steam engine turned linear movement (piston) into rotary(drive wheel
826484
Bernoulli Effects\n\nSee how to demonstrate it here --> http://www.physics.umn.edu/outreach/pforce/Bernoulli.html
797314
this guy explains it as easily as can be explained\n\nhttp://www.newton.dep.anl.gov/askasci/chem99/chem99297.htm
1021771
Check out these lesson plans -- on the third page, they show a schematic which will give you an idea of what has happened:\n\nhttp://www.nbtc.cornell.edu/mainstreetscience/kitlib/getlessonplan.php?id=55\n\nhttp://www.psrc.usm.edu/org/Polymer%20Demos/Pdf/slime.pdf
751590
1. Changing roughness - make the surface smoother\n\n2. Instead of sliding surfaces together, you can add rollers between the surfaces, thus changing over to rolling friction.\n\n3. By adding a thin layer of oil or even water between two objects, you convert the sliding friction to fluid friction. This lubrication is used in many applications to reduce wear and to make the sliding much easier.
604852
Here are a couple of web sites that approach this in different ways. \n\nhttp://www.circletrack.com/techarticles/84199/\n\nhttp://www.diracdelta.co.uk/science/source/e/n/engine%20excitation%20mechanisms/source.html\n\nHope these help.