what is the modulus of rigidity?
97093
For rigid elastic bodies, which we try to stretch or compress using a force F, it is found that :\n\n Shearing stress is directly proportional to shearing strain.\n \n Hence, the ratio of shearing stress to the shearing strain is called the rigidity modulus.\n\n Shearing stress is = Force / Area\n\n Shearing Strain = change in dimension (d) / original dimension (D)\n\n Hence rigidity modulus (n) is given as follows :\n\n n =  (F/A) / (d/D)\n\n I hope that answers your question.
355325
Newtons, or sometimes kilograms
72896
Newtons is the unit for measure of force
276222
If I consider a rectangular box of length L and breadth B and mass M. Then Moment of Inertia of the box is :\n\n          I = M * [(L^2)+(B^2)] / 12\n\n      (Notation : x^2 denotes square of x)\n\n  So, for a cube, put L = B = a (say)\n\n    Then,\n           \n        I for cube = M * (a^2) / 6\n\n    (Notation : x^2 denotes square of x)\n\n I hope that this answer satisfies your query.
576519
tensile strength = (2*P)/(pi*t*d)\nwhere; P =maximum load you get from the machine(kPa); pi = 3.14; t = thickness/height of specimen (m) and d = diameter of specimen(m)
902708
Try \n1. http://en.wikipedia.org/wiki/Eccentricity_%28mathematics%29\n\n2. http://mathworld.wolfram.com/Eccentricity.html
31430
The amount of torque applied is force * length.  At 1 cm from the hinge, a 5 N force provides 5 Ncm of torque.  At 85cm, you would have 85 times as much torque, or 425Ncm.
731116
Spring constant: k = 4π²m/T² = 4π²(.712)/(2*.685)² = 14.976 N/m\n\nω = √(k/m) = 4.58625 rad/sec\n\nVmax = Aω = .102*4.58625 = .4678 m/s
281995
Is it elasticity? Try to solve the problem with some formula below:\nYoung's Modulus(Y)=Stress/Strain\n=(F/A)/(dl/L) \nwhere, F=force applied, \nA=cross sectional area, \ndl=leangth increase and L=total lenght.\nBulk Modulus(B)\n=dP/(dV/V) \nwhere P=pressure and V=volume.
113113
Think of this as an even power function.  Look at the graph of y=-x^2.  Looks like an arch.  So does y=-x^4.  Now you just need to calculate the other parts of this function to match your initial, final, and maximum.  The expression you will be using is y=-(ax+c)^2+b.  The 'a' will change the "roundness" and the 'b' will change the maximum.  The 'c' will change the horizontal position.
774877
The equation doesn't differ for different springs, only the value of spring stiffness k does. A different value of k means the deflection x resulting from a given force Fm will differ also since Fm = k*x.
904937
ref\n\nhttp://www.cem.msu.edu/~reusch/VirtualText/polymers.htm
495016
This is more of a physics question...\nd final = .5*a*t^2 + v*t + d\nv final = a*t + v\nd is displacement, v is velocity, a is acceleration.\nEnjoy.
947584
Within the elastic limit of any material it is seen that the stress in the material is directly proportional to the strain. \nHence the constant for the proportinality is called Youngs Mdulus (E). The unit of Youngs Modulus is N/mm^2 or MPa(Mega Pascals) or PSI(Pounds per sq. inch) same as the unit of stress.\n\nAlso it may be referred as Stress/Strain= Youngs Modulus.\n\nUsage of youngs modulus:\n----------------------------------\nStress is not a straight measurable quanitity, but engineers are very curious to evaluate stresses in a loaded material to check if it can withstand the design load or applied load. Strain is a measurable quantity (strain gages can measure strains) and once strain is measured the stress can be deduced by multiplying with the youngs modulus.
710153
Usually psi (pounds per square inch).\n\nAloha
701523
Good ? fernando,\n\nI thought about this problem and remembered blowing up balloons long, long ago in my childhood.  (It actually is easier to blow when the balloon gets larger).  \n\nReason: the material stretches in the larger balloon and becomes thinner, so the elastic modulus is inversely proportional to size.  Ergo, when the 2 are connected, air will flow from the smaller to the larger, since the smaller one has more pressure.\n\nI realize this is not a formal proof, but it will have to do for now!
740030
f = uN\n198 = u*(55*9.8)\nu = 0.367 for static\n\nf = uN\n175 = u*(55*9.8)\nu = 0.325 for kenetic