which spherical objects will have greatest buoyant force when submerged in fluid, 13.5g aluminum, 56.5g lead,?
86433
Assuming no external force, the obivous choice is 56.5g because the bouyant force is equal to mass*gravity
480070
Good question, oil and gasoline will both be floating above the water, but which one is going to be floating on top the other is a hard one, i'm still searching....\n\n\nI can't find nothing on oil and gasoline, my guess would be that gasoline will float on top of everything.\n\nSo, water then oil then gasoline. It might depend on type of oil too. The best way to find out is to get a clear jar, get some oil and gasoline, see which one floats!\n\nAnd here's some concepts of buoyancy nad density, also gravity...\n\nAny object placed in water has to contend with two forces, gravity and buoyancy. Gravity is the natural pull of an object toward the center of the earth. Gravity tends to pull a boat down into the water. So what keeps it from sinking? Buoyancy acts as an opposite force to gravity and pushes the object up. Archimedes' Principle says that an object immersed in water is buoyed up by a force equal to the density of the water it displaces. The buoyancy of an object is dependent on its density and the density of the material surrounding it. Density is the relationship between mass and volume.
332727
I would assume that lead pellets would be heavier than aluminum. Try placing them in a liquid which is buoyant for aluminum and the lead should fall to the bottom. Thick Veg Oil or something? A magnet might work too. Not sure though.
974729
Gravity. Water doesn't seek its own level on the Space Station, it forms a ball-shaped blob.
684710
A piece of iron has a density greater than water. Thus it will sink when the weight of the volume of water displaced by the piece of iron is less than the weight of the piece of iron. If iron is shaped, or used to make a ship,  the iron ship will float if the total volume of water displaced by the part of the ship in the water weighs more than the total weight of the iron used to make the iron ship. Thus, the upward force of buoyancy is greater than, or equal to,the downward force of gravity and the ship stays afloat.\n\nThis is called Archimedes's principle of buoyancy and it is fundamental to the design of all ships and heated air balloons.TWH
154782
I'm pretty sure that it is an upward force because the buoyant force would be the force of the liquid, right? The boat(example of an object) would be pushed downward because of gravity, and the water would push back upward. It would be kind of like the ground pushing back upward on your feet.
828338
Use Archimedes Principal to answer this question:\n\n"The buoyant force is equal to the weight of the displaced fluid."\n\nThus, in air, the net force is equal to the statue's true weight minus the buoyant force.\n\n190 N = W - Fb\n\nThe statue's weight, W, is simply the density of the brass times its volume times gravity, and the buoyant force is equal to the density of the air times the statue's volume times gravity:\n\n190 N = d-brass * g * V - d-air * g * V\n\nRe-writing this expression provides the volume:\n\nV = 190 N / (d-brass * g - d-air * g)\n\nFrom Google, I found that the following typical densities (air is assumed to be taken at sea-level):\n\nd-brass = 8400 kg/m^3\nd-air = 1.2255 kg/m^3\nd-water = 1000 kg/m^3\n\nSubstituting these values provides:\n\nV = 190 N / (8400 * 9.8 - 1.2255 * 9.8)\n\nV = .00231 m^3\n\nWhen the statue is submerged in water, we again use Archimedes Principal to find its apparent weight:\n\nW = d-brass * g * V - d-water * g * V\n\nW = (.0231)*(9.8)(8400 - 1000)\n\nW = 167.4 N\n\nGood Luck :)
1123435
Hi, its not gravity but a force opposite to gravity that prevents a boat from sinking and keeps an airplane in the air. Sorry, but I forgot the name of the force, I think it begins with a B. O, the second person said it- Buoyancy.
383803
hey! the force acting on these spheres is the buoyant force.  buoyant force is equal to the weight of the liquid displaced by the immersed object.As in this case the weight of both spheres is the same [m*g i.e(1kg*9.8m/s2)] the buoyant force will also be the same.hence none of them "appears to lose" and both appear same.get that??!
470314
the specific gravity of water is 1.
442513
The gravitational force holds it into a spherical shape.
903478
fat content\n\n\nthe fattier it is, the more it'll float
412802
p=F/A \n\nSo, you have the pressure of the atmosphere pluss the weight of the water above you.  Which is usually figured as a cylinder.  Hope that helps.
208900
Specific gravity.\n\nPure water has a density of 1 (the mass of 1 cubic centimetre of pure water is precisely 1 gramme), if something was twice as heavy as water (i.e. it has twice the mass) it would have a specific gravity of 2, 6 times as heavy and the SG would be 6.  If something was half as light as water it's SG would be 0.5 and so on.
121559
Buoyancy is basically the weight of the displaced water.  Assuming that a 55 gallon drum displaces essentially 55 gallons of freshwater.  Assuming roughly 8.33lbs/gallon, you would need 458 pounds to counteract the buoyancy.  \n\nYou also need to take into consideration the weight of the drum itself as well, and subtract that from the overall weight needed (provided that you've taken into account the buoyancy of the drum itself on the first calculation).\n\nIf you can get an accurate volume of water displaced by the entire drum if it were submersed, then you can figure the weight of the water displaced, and subtract the weight of the drum from the weight of the displaced water. That will provide you with the weight needed to counteract the buoyancy.
952124
1. The bouyant force of the water on the object is the difference in the reading, i.e. BF=(.0554-.0370)g\n                                   =0.0184gN\n\nBased on Archimedes' Principle, BF =Volume*Density of water displaced.\n \n0.018g=Volume*1000g\nVolume=.018/1000\n            =1.8*10^-5m3\n\n2. Density of Object=Mass/Volume\n                                =.0554/1.8*10^-5\n                                =3078kg/m3
963983
There are many ways to do this problem.  The best way to probably handle density, and perhaps mass even, is using Archimedes principle of buoyancy.  You can find a detailed discussion on www.wikipedia.com and search for Archimedes or buoyancy.  The main idea is that "the weight of the displaced fluid is directly proportional to the volume of the displaced fluid".  \n\ngood luck!