how can half of thirteen be eight (In different number system)?
78901
If we translate to a different base, let's call it base a, 13 will then equal 1 x a + 3. Let us set that equal to 16 or 2 x 8.\n\n16 = 1 x a + 3\n13 = a\n\nSo 13 in base thirteen equals two times eight (in both base ten and thirteen)
595135
88 x 132 = (87+1)x132=87x132 + 1 x132=N +132\n87 x 132= N-0
113395
8 = 2*2*2\n12 = 2*2*3\n52 = 2*2*13\n\nSo it's 2*2 = 4
189182
You use cross multiplication.\n1/2, 5/8, 6/*, 3/4 \n\nYou multiply the numerator of one fraction to the denominator of the other fraction you're comparing it with. For example, you cross multiply 1/2 and 5/8.\n\n1*8 = 8 so lets say 1/2 got 8\n5*2= 10 so 5/8 got 10. Therefore, 5/8 is greater than 1/2
892661
8 numbers can be placed  in 8! ways.\nExchange the three two's gives no new numbers, so divide by 3!\nExchange the two six's gives no new numbers, so divide by 2!\n8! / ( 3! x 2! ) = 1680\n\nTh
872336
3/8y=12\n3/8y/3/8=12/3/8\n3/8y(8/3)=12/1(8/3)\ny=32\nCheck: 3/8(32/1)=12\nRemember that when dividing by a fraction, the divisor must be inverted
961314
easy the number is found as such \n\n21 = 3*7\n\n27 = 3^3 \n\n33 = 3 *11\n\n55 = 5 *11\n\nIn order that a number must be divisble by these, it must contain \nall factors. if you look for the samllest avoid repetition \n\n3^3 , 5, 11  =1385\n\nand you add 5 \n\nso the number is 1390
623996
2y is equal to thirteen
884297
Grab a caluclator and add.\nLet's see...the whole numbers are\n52 + 6 + 5 + 4 + 8 + 12 + 10 + 13 + 12 + 15 + 7 + 26 = 170\nNow add the fractions\n1/2 + 1/2 + 1/2 + 3/4 + 1/2 + 1/2 = 1 + 1/2 + 3/4 + 1 = 3 1/4\n170 + 3 1/4 = 173 1/4
328998
Well, I doubt any sixth grader knows of the floor function :)\n\nHow about 8/(3-(8/3))?\n\n3 - 8/3 = 1/3\n8/(1/3) is the same as 8*3 = 24\n\nP.S. Anyone ever played 24? It's a pretty similar game, where you get four numbers and have to make them equal 24 with these rules. Very fun :)
891593
ok look if the #, 538 last # is even then it is divisible by 2. And the rule for 3 is you add up all the digits 5+3+8=16, and if that #, 16, is divisible by 3 then the whole # is divisible by3. The rule for 5 is if the #, 538, ends in a 0 or 5. The rule for 6 is add up all the digits again 5+3+8= 16 and if 16 is divisible by 6 then the whole # is divisible by 6. And the rule for 10 is if the # ends in a 0!! \ngood luck
1117885
23\n\nAny number exactly divisible by three can be represented just using the three. Any number that yields a remainder of 1 when divided by three and is at least 13 can be represented as 13 plus some number of 3s. Any number that yields a remainder of two when divided by three and is at least 26 can be represented as 13+13+some number of threes. Because all numbers must have a remainder of either 0, 1, or 2 when divided by 3, all numbers at least 26 can be represented with one of these schemes. It is easily seen that adding the ability to include more than two 13s, or any number of sixes, adds no additional power to the system. Therefore, the greatest number not representable would be the largest number less than 26 and having a remainder of 2 when divided by three. This number is 23.
106335
81 because you take the first number of them both first you take the 8 and put it in front and then you take the 1 and you put them together and what do you have 81! (please pick me it took me forever to write that out.)
321657
To divide 6 by 3/8 you should:\n\nMultiply by the reciprocal of the second number (flip it). This means, \n\n6/1 x 8/3.  This equals: 48/3\n\n48/3= 16.\n\nThis works with all problems in which you must divide by a fraction. Flip the second number and multiply the first one by it.
375926
The last digit of the powers of 2 follow a definite pattern, which is 2, 4, 8, 6, and then again 2, 4, 8, 6 etc. \n\nTo find the answer, simply take 51 mod 4, (which happens to be 3), and the third number in the list is 8. The answer is therefore 8.
98061
13-5=8\n17-12=5\n15-8=7\nthe answer is seven.
890798
depends which average\n\nalthough probably the mean \n\nin order to do this you need to add up the 3 numbers and then divide by the amount of numbers\n\n13 + 9+ 8 = ?\n\nthen divide that total by 3\n\nfor the medium \n\nyou need to put the numbers in order so 8 9 13 and find the middle number\n\n\nthe other average is mode but you can only use this if there is more than one of the same number. It is the most common number