How do I create a equation for a pyramid made of cards?
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You can use a pyramid of cards to teach coordinate geometry (tessellations).  You can use it to teach Pascal's Triangle (permutations & combinations)
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You need to know the base and the height of the shapes. \n\ntrapeziod: average of two bases x height\nparallelogram: base x height\ntriangle: 1/2 x base x height\n\nOr if you know how to use the sin, cos, tan, then you only need to know a few sides to calculate the base and the heights.
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make a common denominator\n\na/b - c/d = a*d/b*d - c*b/d*b = (a*d-c*b)/b*d
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some calculators can do this\n\nmathematica software will do it
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12X^2+x-6\n Remember FOIL
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Always, always, always draw a picture if you are having trouble.  Or do an image-search to look at for reference.  Ok, here goes:\n\nA pyramid with a square base will have 4 equal triangular faces, leaning in to meet at a point.  First find the area of the base, that's the easiest.  It's width^2.  In this case, 15.5^2 = 240.25\n\nNow to find the area of one of the triangular faces.  The height of the pyramid is from the point at the top straight down to the center of the square.  If you were to go from this point out to the side, you would be drawing a line from the center of the square to the midpoint of the base of one of the triangular faces.\n\nSo you've created a right-triangle with a height that is the height of the pyramid (19.3), a base that is 1/2 the width of the square base (15.5/2 = 7.75), and solving for the hypotenuse will give you the "actual" height of one of the triangles (if you were to stand it up straight), otherwise knows as the slant height.\n\nUsing pythagorean theorem, 19.3^2 + 7.75^2 = c^2; c = approx 20.798, the height of one of the triangles.\n\nNow you have all the information you need to find the area of a triangle.  The formula for that is 1/2*base*height.  You just found the height, and the base will be the width of the square-base of your pyramid (again, try to picture it).\n\n1/2*15.5*20.798 = approx 161.1845\nThere are 4 of these, so 161.1845*4 = 644.738\nAdd that to the area of the square base, 240.25\n\n644.738 + 240.25 = 884.988 -- this is approximate since I rounded earlier.
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First get it straight. Algebra and probability are 2 very different things! Now:\n\n1. There are 12 marbels, so,\na) purple then red = (1/12)*(3/12)=1/48\nb) red then green = (3/12)*(3/12) = 1/16\nc) 2 greens = (3/12)*(3/12) = 1/16\nd) 2 reds = (3/12)*(3/12) = 1/16\ne) purple then green = (1/12)*(3/12)=1/48\nf) red then yellow = (3/12)*(5/12) = 5/48\n\n2. There are 9 total marbles, so:\na) purple then white = (3/9)*(1/8) = 1/24\nb) white then green = ((1/9)*(1/8) = 1/72\nc) 2 purples = (3/9)*(2/8) = 1/12\nd) 2 yellow = (4/9)*(3/8) = 1/6\ne) yellow then purple = (4/9)*(3/8) = 1/6\nf)yellow then purple = (4/9)*(3/8) = 1/6\ng) green then white = (1/9)*(1/8) = 1/72\n\n13. Red card is 1/2 and club is 1/4, add them = 3/4\n14. Dimond is 1/4 ans spade is 1/4, add them = 1/2\n15. face card is 12/52 and a 2 is 4/52, add them = 16/52\n16. A 7 is 4/52 and a 9 is 4/52, add them = 8/52\n17. Red card is 26/52 and a king of spades is 1/52 = 27/52\n18. Heart is 13/52 and quuen od diamonds is 1/52 = 14/52
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Try this website www.algebrahelp.com/calculators/equation/3dgraphing/pg2.htm
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Find the area of the triangular base, then multiply that by (1/3) times height.\nThe formula is (1/3)*(area of base)*(height)\nSay the triangular base has base = 3 and height 4.\nArea of triangle = (1/2)(3)(4) = 6\nSay the height of the pyramid is 10.\nThe volume is  \n(1/3)(6)(10) = 20
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The mode is the data point that appears the most often. From the problem statement, there's a single mode, 5. So, since there are 3 cards, then at least 2 of the cards must be 5. (If all 3 cards are different, then there would be 3 modes.)\n\nSo the cards are 5, 5, and x. (x could be 5 without changing the mode). Now, look at the mean. To find the mean, add up all the values, and divide by the number of values. So add 5 + 5 + x to get x + 10, and divide that by 3. That expression must equal 8.\n\nSo, you now have an equation to solve: (x + 10) / 3 = 8. Solve it as you normally would:\n\nmultiply both sides by 3 to get x + 10 = 24\nsubtract 10 from both sides to get x = 14.\n\nSo the 3 cards are 5, 5, and 14. The mode is 5, and the mean is (5 + 5 + 14) / 3 = 24 / 3 = 8.
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Try this:\nhttp://www.wtamu.edu/academic/anns/mps/math/mathlab/beg_algebra/beg_alg_tut9_bar.htm
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You are on the right track.\nThis a geometrical problem that requires drawings.\nCheck this link http://departments.kings.edu/chemlab/chemlab_v2/packgeo.html\n\nI'll get back to you later \n\nso later it is\n\n3--------R=r(1+2/3^.5)\n7--------R=3r\n19------R=5r\n37------R=7r\n61------R=9r
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hi \nquestions are easy but need to draw it. it seems not posible here. \nphonecardgalery@yahoo.com
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some formulas that can help :\nhttp://www.eskridgeinc.com/support/formulas.html
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Use a calculator and raise it to the 1/3 power.\nDon't try to do it by hand...
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SA = 5as + 5sh\n\nwhere\na = apothem length \ns = side length\nn = #sides\nh = height\n\nDo the math.
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Use FOIL\n(3 - 2sqrt3)^2\n(3)(3) + (3)(-2sqrt3)  + (-3sqrt3)(3) + (-2sqrt3)(-2sqrt3)\n= 9 - 6sqrt3 - 6sqrt3 + 4*3\n= 21 - 12sqrt(3)