what happenes to the Vce parameter when heat is applied on transistor ?
90104
If the transistor is stabilized in some circuitry, heat should not affect it too much. A simple amplifier using voltage divider biasing is very stable, whereas simply feeding a signal into the base with the B-E junction forward biased will be very unstable. In the first situation, the stability factor can be made to equal 5. In the second example the stability factor will approximate the beta of the transistor. (Lower S => more stable)
25244
What type of resistance--thermal, electral, or what?\n\nBoth are generally determined by the bandwidth of free electrons if any are present.  In electrical, it can also deal with impurities in the material.  In thermal, it can have to do with the irregularity of the molecular structure, the density of the solid, and the heat capacity of the molecules.
80597
V = IR\nV---Voltage\nI--current\nR--- resistance\nIts also called ohm's law
871859
Nominal voltage required for excitation of a circuit.\n\n- - - - - - -s-
765543
try\nhttp://www.dir.ca.gov/title8/2395_42.html\nsection b\n\nGrounds are also tied to the cold water pipes and gas pipes.\nmake sure all circuits are dry and checked with a insulation resistor tester (megger).Readings above 2 Mega Ohms should be OK.
529607
If you have access to the Journal of Applied Physics, this should help:\nhttp://scitation.aip.org/getabs/servlet/GetabsServlet?prog=normal&id=JAPIAU000076000009005380000001&idtype=cvips&gifs=yes
1046550
Remember the equation v/i=r, Keep the voltage constant over all the areas. If the resistance goes up, then the current goes down.\nIf you have zero ohms, you have a short. IF you have infinite resistance, you have a break.  This seems general, but this is a great help for most of the electronics applications you will need. \nIf you want more you will need to give us more info.
95109
This might help\n\nhttp://www.ttec.co.tt/consumertips/conserveelectricity/default.htm
1045585
no, but usually when they do a die shrink, they also lower the voltage requirement (example: from 2.7v to 1.8v), which means less power.
27798
NiCads in general electronic applications are typically designed to NOT get hot, since the heat destroys the NiCad battery, can damage electronics and causes lawsuits when users get burned from the hot battery.  Some devices like radio-controlled cars are high-drain applications that generate a lot of heat, so the batteries for these devices are designed for their specific use.\n\nBatteries get hot when they charge due to the high current going into them.  The faster they charge, typically the hotter they get.  When the battery discharges during use, the same thing happens, the battery gets hotter as more current is drawn from the battery.  \n\nWithout knowing anything else, my guess is that high current draw from the battery cells is causing them to heat up.  This can be due to a defective battery, a battery not designed for the way you are using it or your modification damaged the battery or is otherwise causing excessive current drain.\n\nAlso, increasing the supply voltage can drive more current through the device, so it may just be that the higher voltage is drawing more current.\n\nI’m not sure how the device is shutting down, so I can’t say why it’s doing that.  Note that the voltage at which a device stops working is the voltage seen by the device itself.  If you remove the battery from the device and measure the voltage, you will get a different voltage than if you measure the voltage at the precise moment the device shuts down.  This is especially true for high current drain applications, which appears to be what’s happening with your batteries. \n\nPlacing the NiCad’s in the freezer won't help.  They’ll have to warm up to work properly anyway.
418331
Possibly "statistical fluctuations in charge generation" as mentioned in ref. 1. From ref. 2, which refers to "fundamental limits imposed by charge generation statistics", I get the impression that these variations may be an irreducible error source.
938353
When heated the electrons move from the ground state to an exicited state.  They are unstable here and return to the ground state giving off energy in the form of a specific color.  Different energy levels will produce different colors
1186584
The hotter the surface gets the more resistance. It is a solid state item.
105269
Hi!\n    Actually I dont know the answer for ur question but i want  to know the answer from u. If you have any info abt "Gallium Arsendie Technology" please send me the details. \n        Thank U
773086
w = -(P x deltaV). Delta V is final V minus inital V (which you get by using the PV=nRT equation at each temperature). so -(3 x -11.8) = +35.39.\n\ndelta E = q + w. So add the q you got and the w you get.\n\ndelta H = delta E + (P delta V). \n\nThere ya go. hope this helps
744659
Assume it's a PNP transistor. (if it's NPN, all polarities are reversed and the result is the same). A + increase in the base voltage will increase the current flow through the  collector - which will cause the voltage drop to increase across the load resistor - which means the collector end of the load will fall in voltage- exactly 180 degree phase reversal from the base if the load is purely resisitve (if it is inductive or capacitive, it will NOT be 180 degree out of phase with the base, since the base voltage is controlling the collector CURRENT flow.
219925
Look at it this way. When you configure an amplifier as a common emitter, the emitter goes to ground. When a signal enters the base, it increases the emitter current. This causes a corresponding increase in the collector current. This makes the collector resistor drop _more_ voltage, producing less voltage in the load.\n\nSo consider the extreme cases. If no signal is present on the base, the transistor is effectively "off" and all the voltage at the collector resistor is avaialble to the load.\n\nThe other extreme case is if so much signal is at the base, the transistor saturates "on" -- then the collector will be at, say, 0.2V or so and the collector resistor will drop almost all the voltage, leaving nothing for the load.\n\nSo you can see that a lot of signal produces a little voltage, and no (or a little) signal produces a lot of voltage. Phase inversion!