what is the size of a 40 inch tv with an aspect ratio of 16:9?
87655
From the Pythogorean Theorum, the square of the width plus the  square of the height must equal the square of the diagonal:\n1) w^2 + h^2 = 40^2\n\nBut the ratio of the width to the height must be 16/9:\n2) w/h = 16/9\n\nUse equation 2 to solve for either w or h (I'll solve for w):\n3) w = (16*h)/9\n\nNow substitute the value you got for w in equation 3 back into equation 1 and solve for h:\n4) ((16*h)/9)^2 + h^2 = 40^2\n   ...\n   h = 19.61\n\nOnce you have h, substitute this value into equation 3 to get w:\n5) w = (16*19.61)/9\n   w = 34.86\n\nNow you have your answer. The width of the screen is 34.86" and the height of the screen is 19.61".\n\nYou can check your answer by substituting the values for w and h into equation 1 to make sure the sum of their squares really do equal 40^2 (they won't be exactly 40^2 because of rounding errors, but they will be very close).
47187
Just got a tube 26" Widescreen HD.  It is 20" deep.  Look for the word panel in the advertisements. Find out costs of installation before you go too far. Get one with the tuner built in.  Other wise you will have to purchase the tuner for $150-200.  I love mine.  The picture is incredible.
795619
The 16:9 is the ratio of the sides.  So one side is x high, and the other is 16x/9 long.\n\nThe 42 is the hypoteneuse of a right triangle with sides x and 16x/9, so just plug-n-chug:\n\nx² + (16x/9) ² = 42 ²\n\nx² + 256x ² / 81 = 1764\n\n81x² + 256x ² = 142,884\n\n337x ² = 142,884\n\nx ² = 142,884 ÷ 337\n\nx = √ (142,884 ÷ 337) = height  ≈ 20.6 in.\n\nwidth = (16/9) * √ (142,884 ÷ 337) ≈ 36.6 in.\n\n~ ♥ ~
667237
just change your system resolution.. that will change the size you see
168619
48" x 40" is a standard size pallet.
1119096
they mean the film was in super wide screen, 16:9 or what every but your tv is 4:3...so they have to cut the edges off
998698
5'4"=64"\n1"=2.54cm\n\n64x2.54=162cm
940058
once updated it should be 1024x768, but the truth is it should only be limited by the resolution that your monitor can handle without making things too small that you can see them or too big that webpages wont properly fit on the screen.
126485
How big should my television be? \nWhat most people really mean by this question is, "what size should my screen be?" \nMany studies show that the Critical Viewing Distance (CVD) in simulating a "movie"-like experience yields a viewing angle between 25 and 30 degrees, or about two times the picture width for 16:9 displays. The CVD basically is the maximum distance at which the smallest picture details can be discerned. In a recent article in "Widescreen Review" (V11, N10, Issue 65, Oct 2002), Greg Rogers notes that the limit of angular discrimination for normal vision is 1/60 degree. Using that as an assumption, he provides the following formula to calculate the CVD: \n\n\nCVD (in PH) = 3438 / (# of pixels per PH)\n\nwhere PH is the picture height in pixels. If you do the math for a standard NTSC television, this generally means that you're going to need to sit back about 7 times the picture height in order to reduce the appearance of scan lines. Unfortunately, this also severely limits the viewing angle. \nAnother problem is that manufacturers use the diagonal measurement of a screen in advertising. This makes the screen sound much bigger than it really is. It also makes it hard to figure out the proper ratios when buying a new television. \n\nHere are a couple of simple multipliers to use in the calculation of seating distances from the screen. Any distance less than the optimum allows the viewer to see presentation artifacts and can cause eye and muscle fatigue. Also, don't sit too much farther away than indicated or you're wasting the screen real estate. \n\nMy ratios are derived using information that normally applies to the height of a television screen. Since most manuals and stores have no idea how tall a screen is (and most people don't carry a tape measure), it is easier to use calculations that rely on the diagonal measurement. The diagonal size of a screen is always available in the marketing literature. \n\n\nCalculating the optimal seating distance using screen size\nFor standard televisions (4:3 aspect ratio, 480i signal)\nMultiply the diagonal measurement (in inches) by 4.3. \nFor HDTV (16:9 aspect ratio, 1080i signal)\nMultiply the screen diagonal measurement (again, in inches) by 1.57. \n\nCalculating the optimal diagonal screen size using the seating distance\nFor standard televisions (4:3 aspect ratio, 480i signal)\nDivide the distance you sit from your television (in inches) by 4.3. \nFor HDTV (16:9 aspect ratio, 1080i signal)\nDivide the distance you sit from your television (in inches) by 1.57. \nYou can use these numbers to avoid being sold a screen that is far too large for your seating area (the most common mistake in television purchases). \n\n\nSizing a 16:9 set to replace a 4:3 standard television\nIf you're buying a 16:9 set to replace a 4:3 set, multiply the diagonal screen size of your current set by 1.22. This will give you the 16:9 diagonal screen size you would need to buy such that the height of the new screen is no less than your existing screen. However, you should always use the seating distance as the ultimate decider. If the seating calculation indicates a smaller screen than the screen height calculation, then get the smaller screen.
789595
Cool present if she watches TV. I quite fancy a small flat screen. Our current telly is huge. I'll show your question to my daughters and see if they take the hint.
885827
Well, the quoted size of a monitor measures its diagonal. \n\nA 22 inch 16:9 monitor would have dimensions of 19.17 x 10.78\nor 207 sq in.\n\nA 15 inch 4:3 monitor would have dimensions of 12 x 9 inches or 108 sq in. So two of them would be 216 sq in. The combined viewing surface would be 24 x 9 inches if you arrange them horizontally, or 12 x 18 inches if arranged vertically. Depends what you want to do with them.\n\nNot much difference in area. But consider that you'll have a single uninterrupted display surface with the 22 incher. I'd go for the 22 inch monitor.\n\nYou'll want to be sure you can supply a high enough resolution to the 22 inch monitor, preferably at least 1600 pixels horizontally
1127073
Finding an image that large to use is going to be difficult.  But it's possible, here's one of the space station, http://antwrp.gsfc.nasa.gov/apod/image/0605/iss2_sts114_big.jpg note you'll have to use an image editor to cut the file information off the bottom of it and use image resizer to cut it down to the size you want, http://www.microsoft.com/windowsxp/downloads/powertoys/xppowertoys.mspx\n\nIn all honesty that's the only image I know of meeting your requirment, most wallpaper sites top out at 1600 x 1200 and why not most LCD monitors are between 17" and 20" in size.
688001
NTSC Pixel ratio is 720 x 480 or 720 x 486 Either one works fine. (Trust me, I'm having to do the same thing for a school project right now!) Good luck!
1045144
buy a small portable TV!
130661
I have a 42" Panasonic Plasma.  At the time, I was really underwelmed by the color and picture quality of LCDs.  The colors always felt a little washed out, the blacks weren't very black, there were "lags" in the picture update, and the price was more than a plasma.\n\nThen, this past weekend, I saw a Sony Bravia 42" LCD next to the Panasonic, and I gotta say, I was impressed.  Many of my reasons for picking the plasma were now being given a run for their money.\n\nStill, every night, my wife and I sit in front of the Plasma watching a DVD or Comcast HD and just marvel at how good the picture is.  This is 10 months later.
73177
Well if I've worked this out correctly and assuming that you'll be watching HDTV on this screen then you should be looking at approx 42".\nFormula is:\n\nFor Cable Antenna or Video tape Multiply the number of feet between you and the screen by 4 inches. \n\nFor DVD or Satellite Multiply the number of feet between you and the screen by 6 inches. \n\nFor HDTV Multiply the number of feet between you and the screen by 7 inches.\n\nHope this helps
810960
Easy. 40 divided by 2 is 20. Take half of 40.  OR 40x0.5