Solve this math problem, using order of operations:?
79707
16 - 3(8-3)squared / 2\n\n1. 16-3x(8-3)²÷2\n2. 16-3x(5)²÷2\n3. 16-3x25÷2\n4. 16-37.5\n5. -21.5
137681
Ok...\nI see what you are doing...\nYou merely substitute the number in for x...\nso the problem becomes 6-2*(-1)\n6+2\n8
215091
2.  \nOrder of operations says, since there are no brackets, you do multiplication and division first in the order they appear, 2*2 = 4, 4/2 = 2, then addition/subtraction in the order they appear, so 2+2-2 = 2.
627342
ok, this is found in the 4th quadrant, the order is as follows\n\n(x,y) 1st\n(-x,y) 2nd\n(-x,-y) 3rd\n(x,-y) 4th\n\nhope this helps\n\nmatttlocke
934652
So let's say the problem looks like this\n\n   11\nx 12\n--------\n        <-----the answer from 11*2\n       <------answer from 11*1\n\nfirst hide the 1 from the 12 and work out the problem as 11*2\nthen work on multiplying the 1 with 11 but make sure you start putting your answer down below your first answer and the answer starts in the column that is below the 1 from the 12.\n\nfinally when the two answers are found, you can add them and get your final answer. SOOO here's what it looks like\n\n      11\n   x  12\n--------------\n           22    (this is from 11x2)\n +  11       (this is from 11 x1)\n------------\n     132 = final answer!
40850
-3 <4x\n x < -3/4\n solution set : {- infinity ,.............,-3/4}
928231
8x-10x > -11-1\n\n-2x > -12\n\nx < 6
238182
p1    p2\n--- = ---\nq1    q2\n\n 5     2\n--- = ---\n 2    q2\n\nCross multiply,\n\n4/5
712412
the first one is\ny= -3/2+3
511948
There are an infinite number of ordered pairs that would satisfy this equation. If you want to find a few of them, assign a value to x and then solve for y.
665576
x^2<4x\n\ncase 1: x<=0\nno solution\n\ncase 2: x>0\ndivide by x\nx<4\n\ntherfore the solutions are 0<x<4
830946
c)\n\n= x^3 + x^2 + x - x^2 - x -1\n= x^3 -1
730496
iteration1: a = 3, b = 2\niteration2: a = 13, b = 8\niteration3: a = 51, b = 30\nloop exit:  a = 81, b = 30 // condition a = a + b executed before exit
200519
+/- 1\n\nThe answer is not 1, because -1 * -1 = 1 also.
191567
Please use parentheses to explain the problem more effectively. Assuming the problem as,\n\n(x-1)/2x + x/(x+3)\n\nThe solution can be,\n\n(3x^2+2x-3)/(2x^2+6)
795656
The first thing you should remember is the phrase PEMDAS.  This is shorthand for parenthesis, exponents, multiplication/division, and addition/subtraction.  This is the order of operations in math.  You should solve all equations in this order.  So for the first one, you should first distribute (multiply) -7 with (3-3x).  After that combine like terms, i got 25x -30; you can also factor that to be 5(5x-6).  The same steps apply for the rest of the problems.  I hope it helps.
889891
~..-8,-6,-4,-2,0,2,4,6,8