how do you rotate t-shapes?
96716
Turn it any number of degrees!\nMaybe you mean only 0 or 360 degrees, because the 'T' or 't' has no rotation symmetry.
636329
I like to use GraphCalc, as it also includes live rotation of 3-D graphs. See http://www.graphcalc.com/ .
655065
In photoshop, EDIT > TRANSFORM > FLIP HORIZONTAL\n\nIn Illustrator, OBJECT > TRANSFORM > REFLECT
1164324
To rotate a two dimension image, you need to put you camera in third dimension. \n\nPut a perpendicular on both of rectangles (centers of rectangles) and project them to intersect. Intersection point would be Camera Point A.
900433
Discounting rotations and mirror images, there is only one way to make a magic square using the digits 1 through 9.  \n\nFirst, we can prove the 5 has to go in the middle:\n\nLet the numbers in the top row from left to right be a, b, and c.  Let the numbers in the middle row from left to right be d, e, and f.  (Note e is the middle box.)  Let the numbers in the bottom row from left to right be g, h, and i.     \n\nWe know a + b + c = 15 and g + h + i = 15\n\nWe also know a + e + i = 15, b + e + h = 15, and c + e + g =15.  Therefore, (a + e + i) + (b + e + h) + (c + e + g) = 15 * 3 = 45.  We can rearrange this to (a + b + c) + (g + h + i) + 3e = 45.  Since a + b + c = 15 and g + h + i = 15, that reduces to 15 + 15 + 3e = 45, or 3e = 15.  Therefore e (the middle box) must equal 5.   \n\nKnowing the middle box is 5, try 9 in a corner and you'll notice a problem - the 6, 7 and 8 can't all be placed in the square without the row or column with the 9 exceeding 15.  So, the 9 has to occupy a side box.  Since we are discounting rotations and mirror images, we can arbitrarily select box b for the 9.  This forces the placement of the 1 in box h.   \n\nWith the 9 and 1 now placed, the 8 and 6 have to go in the row with the 1.  So, we'll put the 8 in box g and the 6 in box i.  (We still haven't done anything to create a second square if rotations and mirror images are discounted.)  That forces the placement of the final four numbers.
504335
Draw two lines from any tow angles to two opposite base
42319
go to control panel\nclick on printers \nclick show installed printers\nRIGHT CLICK on the printer\nLeft click propertys\nclick on printing prefferences\nuncheck rotated\nclick apply
1035212
I know of two:\n\nTranslation and rotation: \n\n1) translation :\n\n Take a rectangle and cut a diagonal and extended the lines  from all three side of the triangle at right angle to it  from the side that is made from cutting the rectangle until those lines equal the lenght of the side of the triangle drawn from  and it  form three boxes  around all three sides of the triangle. Now let take the big side an calulate the square  of it ,then calulate the squares of the other two sides and add themup,  it should equal the square of the big side and that proves the pythagorean theorem. \n\nRotation: \n\nSee the show : Project Mathematics by Cal tech : Entitled "The Pythagorean Theorem" it explain better  than I can, It worth watching. Very good show on Math & Geometry
792270
Hi I assume you mean an unsymmetrical item. I also assume you want a best fit. I have done similar things on a computer but not by hand. The computer finds three point most distant from the centroid and uses these points as pivots for three orthogonal planes. Not sure of the rest.
291300
Try this:\nhttp://flash.lakeheadu.ca/~yzhang/myText/dspGuide/CH32.PDF#search='laplace%20transform'
1075484
Make a fist with your right hand.\nUncurl your right index finger and point it at this text.\nExtend your right thumb so it points straight up.\nUncurl your right middle finger so that it points to your left.\n\nVector I in the direction of your index finger\nVector M in the direction of your middle finger\nVector T in the direction of your thumb.\n\nI X M = T, that is if you take the vector cross product of I and M the direction of the cross product will be in the direction of T.\n\nIn 3-space,   (1,0,0) X (0,1,0) = (0,0,1)  \nSimplely stated:  (i X j = k).
775545
If you mean rotate vertically like the square is doing backflips, I recommend effect->3d->rotate, and then select "front" from position, then pick a few degrees to rotate around the x-axis by, then rotate, save, rotate, save, etc. \n\nIf you mean rotate like the square is "rolling" like a wheel, I do the same thing, but manipulate the z-axis instead.\n\nGood luck.
786997
Use the picture thing to copy it then paste and rotate it.  Make sure you cut it right.
215568
It's called morphing.  There is a software out there called Morpheus that will do it. It should be really easy to find
409096
Use the line tool.  You can also use the rectangle tool and then transform the rectangle by hitting CTRL-T.  Move your cursor just outside the corner bounding box handle until it turns into the rotate cursor.  Rotate at will to create diagonals.
471695
They are a set of Matricies that map one set of {x,y,z} to another set of {x',y',z'} through a rotation angle.  In oder to use them you need to know your starting set of coordiantes and the three angles through which you want to rotate.\n\nOne such set of angles that forms a perfectly good rotation basis are the Euler angles.\n\nIf you know the rotations, you can actually write the whole transformation as one matrix (usefull if you have to apply it over and over again.
363795
Well, if you think about it, you shouldn't have to copy. To make any shape 3D from 2D, just give it DEPTH. Draw lines slightly up and tilted from each corner, then connect them accordingly. It's super easy once you get the concept.\n\nFor pictures, go to www.mathworld.com and search for cubes, prisms, etc.