What is the relationship between voltage, current and resistance in an electric circuit?
80597
V = IR\nV---Voltage\nI--current\nR--- resistance\nIts also called ohm's law
757379
Resistance is connected to conductance as resistivity is related to conductivity.\n  By ohm's law\n   J= E * condutivity\nor \n  J= E/resistivity\n Resistance=( resistivity X length) /  Cross Sectional Area
36781
In light, resistance of a solar cell goes down.  When resistance goes down, voltage and current go up.
813641
using KCL (current law), A is corrent.\nusing KVL (voltage law), B is correct\nC doesn't make any sense, and you can support that with the definition of the KCL.
244228
Hi! You haven't mentioned which of the resistances are in series or parallel. Too bad we can't provide images in Yahoo! Answers.\n:(\n\nDo this: Remove V2 and V3 from the circuit, and replace them by a simple wire. Then find the equivalent resistance of the circuit taking V1 as the battery source. Then find the voltage drops across each of the resistances R1, R2, R3, R4 (you can do this by finding current through them using simple Ohm's Law and then multiplying by the R value).\n\nTAKE CARE that you note the DIRECTIONS of the voltage drops. The direction of voltage drop across R is the direction of current through R. So you must see if its positive or negative.\n\nOnce you have done this, repeat the procedure by removing V1, V3 and taking only V2 in circuit. This time, again specifically note the direction (+ or -). Then do it with V3.\n\nFinally, add the drops across each R, and this is when you use the signs (directions) of the voltage drops. For instance (just an EXAMPLE. You will get diff. values), if you get VR1 with V1 battery as -6V, with V2 as 4V, and with V3 as -2V, then VR1 will be:\n\nVR1 = (-6)+(4)+(-2) volts = -4 volts\n\nYou can use the same procedure to compute IR1: find current each time with V1, V2, V3 resp.\n\nHope this helps!
238179
Resistance=Voltage/Amperes
627574
if you have a series circuit with 2 resistors, then the current through the resistors will be the same as the total current. if you have a parallel circuit, then the current through the resistors will be lesser than the total current, but may or may not be higher than the current in the series circuit. follow the definition of electricity, and figure it out.
1046550
Remember the equation v/i=r, Keep the voltage constant over all the areas. If the resistance goes up, then the current goes down.\nIf you have zero ohms, you have a short. IF you have infinite resistance, you have a break.  This seems general, but this is a great help for most of the electronics applications you will need. \nIf you want more you will need to give us more info.
941082
If you consider 2 nodes in a circuit, node A and node B, and you consider that node A has a higher potential than node B, then the current between A and B is 0.30 A, but the current between Node B and Node A is -0.30 A. See Kirchoff's laws.
709414
Your question is very confusing.  Among other things, resistors are used to limit or control the amount of current through a circuit.  If you know the required voltage drop across the resistor and the current through the resistor, Ohm's Law tells you to divide the voltage by the current to obtain the resistance in ohms.\n\nSay you have a light emitting diode (LED) that you want to power from a 5 volt power supply.  You put a resistor in series with the LED to control the current.  The voltage drop across the LED is about 0.7 volts, so the voltage across the resistor will be about 4.3 volts.  If you want 20 milliamperes to flow through the LED (and resistor), the required resistance is 4.3 volts divided by 0.020 amperes, or 215 ohms.  The nearest standard resistance value is 220 ohms, which is close enough.
655128
Assuming that we have 2 series resistors R1 and R2. And the voltage applied on them is V.\n\nTo get voltage applied on R1 (V1)= V * R1/(R1+R2)\nand so V2= V * R2/(R1+R2)
1023349
Electron flow in the circuit (outside the battery) is from - to +\nHole flow in the circuit (outside the battery) is from + to -\n\nPower in an electric circuit is defined as:\n Watts = Amps x Volts\n\nis equivalent to:\n <power> = <current> x <potential, voltage>\n\nis equivalent to:\n P = I x E\n\nSince one cannot have a non-zero value for power without flow(current), then you could say it comes from both - and + being applied to a load.
301222
Voltage is the parameter of electricity which causes current to flow when a circuit is completed. Voltage is always presented in an energized line, whether or not the circuit is complete. When the circit is complete, we say that electricity is flowing.\n\nHence, it is said that a cell is an electrictiy generating device.
1115026
Voltage is simply the potential electrical "pressure" of a circuit.  Current is the actual flow of electrons, so that's what's felt.  Think of it in terms of water & pipes.  You feel the water flow, not the potential pressure behind it.  If there is more resistance (smaller pipes, more valves), the potential pressure of the water doesn't change, but the flow is reduced.
855540
The circuit has a time constant which is calculated as\nT=L/R\n\nThe circuit will have the equation\nfor current of:\n\ni(t)=(Vs/R)*e^(-t/T)\nWhere\nVs is the supply voltage\ne is Euler's constant\n\nj
291589
Use the node voltage method. Label each node with a voltage, then apply Kirchoff's current law at as many nodes as you need to generate enough equations to solve for any unknowns you have introduced.\n\nLet the node at the bottom of the circuit be ground, and then try to figure out the voltages at the other nodes relative to ground. Clearly the voltage at the node on the top will be 14V (I'll just call this V1) but no other voltages are apparent. So call the voltage at the node between R1, R3, and R4 Vx and the voltage at the node between R2, R3, and R5 Vy.\n\nNow that we have labeled all the node voltages, you can figure out every single current in the circuit in terms of V1, Vx, and Vy (using Ohms Law, the voltage drop across a resistor is equal to the resistance times the current in the direction of the voltage drop). For example, we know the current going down through R1 is (V1-Vx)/R1, the current going right through R3 is (Vx-Vy)/R3, etc. Now we just have to solve for the unknowns Vx and Vy.\n\nKirchoff's current law (KCL) says that the sum of the currents leaving a node is equal to zero. If we apply this law to the node with voltage Vx and the node with voltage Vy, we'll get a pair of equations that we can use to solve for Vx and Vy.\n\nApplying KCL at the node with voltage Vx should give you the following equation:\n\n(Vx-V1)/R1 + (Vx-Vy)/R3 + Vx/R4 = 0\n\nThe first term is the current going up through R1 (we already figured out the current going down through R1, but we want currents that are leaving node Vx so we had to flip the sign), the second term is the current going right through R3, and the final term is the current going down through R4.\n\nI'll leave it to you to figure out the equation for node Vy. Once you have that you'll have two equations and two unknowns and you can solve for everything. Once you have Vx and Vy, you can easily figure out a numerical value for any current in the circuit.\n\nBTW, the node-voltage method is pretty powerful and can solve most linear circuits. Check out the link below, it was written by an old EE prof of mine who is very thorough.
151570
ohm's law states that current throught a conductor is directly proportional to the voltage applied to it.\n\nso,  i oc V\n=> i = R*V where R is proportionality constant called resistance of the conductor. \n\nResistance of a material is the electrical property which opposes the flow of electrons or current.