is ultra sound -a)an electromagnetic wave ob)a transverse mechanical wave c)a longitudinal mechanical wave?
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The answer to this depends on the medium in which the ultrasound is travelling. Fluids will not in general support transverse mechanical waves, or at least they are damped out very rapidly. So if it is in a fluid like air or water, then ultrasound is a longitudinal mechanical wave. However, in a solid it can be both a transverse and a longitudinal wave.
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http://en.wikipedia.org/wiki/Sound_waves
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a supersonic wave is a wave that cannot be detected by human ears since it's frequency is higher than the range.\nwaves are electro-magnetic, mecanical, and optical. sound waves are believed to be mechanical waves, since they do not propagate in empty spaces (they need air, water, solids etc... as a supporting material)
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Both a radio and an ear respond logarithmically. A doubling of sound (3DB) will give a barely perceptable increase in the sound we hear,\nSame is true of am RF radio wave
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must be some kind of a transducer. it could also be a laser as i am not sure whether it is sound or light waves. i think it will use a laser and a sensor to detect the reflaction and hence how near it is to an object.
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When sound (or other waveform of similar shape, like an AC signal) travels through a medium, its intensity diminishes with distance. In idealized materials, signal amplitude is only reduced by the spreading of the wave. Natural materials, however, all produce an effect which further weakens the sound. This further weakening results from scattering and absorption. Scattering is the reflection of the sound in directions other than its original direction of propagation.  Absorption is the conversion of the sound energy to other forms of energy.  The combined effect of scattering and absorption is called attenuation.  Ultrasonic attenuation is the decay rate of the wave as it propagates through material.\n\nAttenuation of sound within a material itself is often not of intrinsic interest. However, natural properties and loading conditions can be related to attenuation. Attenuation often serves as a measurement tool that leads to the formation of theories to explain physical or chemical phenomenon that decreases the ultrasonic intensity. \n\nThe amplitude change of a decaying plane wave can be expressed as:\n\n A = A0*e^(-kz)\n\nIn this expression "A0" is the amplitude of the propagating wave at some location. The amplitude "A" is the reduced amplitude after the wave has traveled a distance "z" from that initial location. The quantity "k" is the attenuation coefficient of the wave traveling in the z-direction. The dimensions of are nepers/length, where a neper is a dimensionless quantity. The term "e" is Napier's constant which is equal to approximately 2.71828. \n\nAttenuation is generally proportional to the square of frequency. Quoted values of attenuation are often given for a single frequency, or an attenuation value averaged over many frequencies may be given. Also, the actual value of the attenuation coefficient for a given material is highly dependent on the way in which the material was manufactured. Thus, quoted values of attenuation only give a rough indication of the attenuation and should not be automatically trusted. Generally, a reliable value of attenuation can only be obtained by determining the attenuation experimentally for the particular material being used.\n\nThis is why higher-frequency signals tend to produce what is called "skin effect" ... basically, the energy isn't there for the wave to penetrate to any significant depth.
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Sound is a form of energy which is audible that is it can be registered by the ear. It travels in a medium and cannot travel in vaccuum. It is propagated in air as a series of compression and rarefaction (or expansion zones) these zones exist along the line joining the source and observer.\n\nIt is hard to localise sound unlike light because sound travels due to the disturbance of the material particles themselves.\n\nSound travels faster in a denser medium.
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A) isn't likely to be correct unless the person was deafened by the sound. For a person with undamaged hearing there is no "too large" an amplitude for hearing the sound. The sound could be too loud to make any sense of it, but that's another issue.\nB) is plausible. Most humans hear up to about 20 kHz when young, and this cutoff frequency becomes lower with age and/or cochlear damage.\nC) is the most interesting possibility. The sound would be inaudible if only transverse waves reached a sensing point of zero size, but such a point couldn't have a directional characteristic so it would also receive longitudinal (compression) waves. A finite-sized sensing area consisting of a flat flexible membrane with one-sided exposure to the air (like the eardrum) could be positioned parallel to the direction of propagation and compression. Then it would be swept by transverse waves, and pressure differences would travel across its outside surface and be transmitted into the inside space (middle ear) and heard. (Note this would not be true for a flat two-sided sensing area, which would have canceling pressure differences on the other side.) In addition, the external ear directs the sound toward the eardrum so longitudinal waves reach it. So C is ruled out.
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bats detect the presence of an obstacle by hearing the echo of the sound produced by them. this process is called sound ranging. as ultrasonic waves are used bcoz they have frquency above20000 hz and travel undeviated through long distances and can b confined to a narrow beam since they r not easily absorbed in an medium.light wave is a transverse wave.its a wave in which each particle of medium executes vibrations in the direction perpendicular to the direction of propagation of the wave. and sound wave is alongitudinal wave.its a wave in which each particle of the medium executes vibration about its mean position in direction of propagation of the wave.
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Cirric is always right.  Thought he was a robot did you?\n   On this site put sonic wave included in your question.\n  Or put the equivalence should equal gravity interactive with\n   magnesiums.
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Two traveling waves which exist in the same medium will interfere with each other. If their amplitudes add, the interference is said to be constructive interference, and destructive interference if they are "out of phase" and subtract. Patterns of destructive and constructive interference may lead to "dead spots" and "live spots" in auditorium acoustics.\n\nInterference of incident and reflected waves is essential to the production of resonant standing waves.\n\nInterference has far reaching consequences in sound because of the production of "beats" between two frequencies which interfere with each other. \n\nDiffraction: the bending of waves around small obstacles and the spreading out of waves beyond small openings.\n\nRefraction is the bending of waves when they enter a medium where their speed is different. Refraction is not so important a phenomena with sound as it is with light where it is responsible for image formation by lenses, the eye, cameras, etc. But bending of sound waves does occur and is an interesting phenomena in sound\n\nWhen a vehicle with a siren passes you, a noticeable drop in the pitch of the sound of the siren will be observed as the vehicle passes. This is an example of the Doppler effect. An approaching source moves closer during period of the sound wave so the effective wavelength is shortened, giving a higher pitch since the velocity of the wave is unchanged. Similarly the pitch of a receding sound source will be lowered.\n\nLight in the form of a plane wave in space is said to be linearly polarized. Light is a transverse electromagnetic wave, but natural light is generally unpolarized, all planes of propagation being equally probable. If light is composed of two plane waves of equal amplitude by differing in phase by 90°, then the light is said to be circularly polarized. If two plane waves of differing amplitude are related in phase by 90°, or if the relative phase is other than 90° then the light is said to be elliptically polarized.
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ohm, or om is correct. om is supposedly the sound vibration when the universe was created
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Probably ultrasonic....
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Velocity of sound  in air is relatively constant.\nAnd formula for the wavelength of sound is, lambda=v/f\n Whence, lambda, v, and f stand for wavelength, velocity of sound in air and frequency respectively.\nhere frequency is written in Hz\nIn view of the equation, as the frequency increases wave length decreases. Hence become short waves.\nOK, tymphanium membrane is a thin and delicate tissue. To cause vibration in the tissue wave should not be too long or short insted it should be within the specified range. \nWhen the wave becomes too short it passes through the membrane insted of causing vibration.\nThis is the cause for inaudibility of sound.
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Electromagnetic radiation is a propagating wave in space with electric and magnetic components. These components oscillate at right angles to each other and to the direction of propagation.\n\nThe term electromagnetic radiation is also used as a synonym for electromagnetic waves in general, even if they are not radiating or travelling in free space. This sense includes, for example, light travelling through an optical fiber, or electrical energy travelling within a coaxial cable.\n\nElectromagnetic (EM) radiation carries energy and momentum which may be imparted when it interacts with matter.
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A mechanical wave exists in a medium (which on deformation is capable of producing elastic restoring forces) through which they travel and can transfer energy from one place to another without any of the particles of the medium being displaced permanently; there is no associated mass transport.
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Both are waves, this is the similarity. Please visit:\nhttp://www.tpub.com/content/neets/14182/css/14182_44.htm,\n\nfor comparisions