Cynthia had 4 dollar bills, 3 quarters, 2 dimes ,and 1 nickel if she spent half of her money how much money do
90859
3 quarters = 75 cents\n2 dimes = 20 cents\n1 nickel = 5 cents\n\n75 + 20 + 5 = 100 cents, or 1 dollar\n\n1 dollar + 4 dollars = 5 dollars\n\n5/2 = 2.50\n\nSo she has two and a half dollars, or two dollars and 50 cents --- $2.50
801304
x = dimes\n2x = nickels\n2x-3 = quarters\n\nNow multiply in the values of the coins:\n\n.10(x) for dimes               .10x\n.05(2x) for nickels            .10x\n.25(2x-3) for quarters       .50x-.75\n\nall of which sums to 2.05.\n\nMultiply everything by 100 to get rid of the pesky decimals and you get to:\n\n10x + 10x + 50x - 75 = 205\n\n70x = 280\n\nx = 4\n\nSO.....\n\nThere are 4 dimes for 40 cents\nthere are 8 nickels for 40 cents\nand there are 5 quarters for 1.25\n\nFor a grand total of 2.05.\n\nHappy happy!!
588899
7 dimes and 16 nickles because set x as dimes y as nickels x+y=23 10x+5y=150 so y=-x=23 and 10x-5x+115=150 so 5x=35 so x=7 and 7+y=23 so y=23-7 so y=7 so there is 7 dimes and 16 nickles
876730
A quarter and a nickel.\n\nONE of them is not a nickel...its a quarter!
319912
you're indeed a filipino!\n\ntry this one...i know the problem is already wrong\nbut this is even better...you'll get the extra dollar!!!!\n\nyou borrow $50 from each of your friend\nbought item worth $97\nyou have $3 left\ngive them $0.50 each\nyou have $2\n\n50 - 0.50 = 49.5\n49.5 x 2 = $99\nyou have the $2 remaining\n\n$99 + $2 ====== $101   TADA!!!!\n\nhehehehe...isn't it genius!!!!
809176
first, you need to add up 1/2, 1/4 and 1/5...first by finding a common denomonator.\n\n10/20 + 5/20 + 4/20 = 19/20\n\nSo, the first three grandkids get 19/20ths of the collection.  Meaning that the 4th grandchild gets 1/20th\n\nSo, since we know the fourth gets 49, this means that 49 = 1/20\n\nnow, cross multiply to find out the total number of coins  1/20 = 49/x\n20 x 49 =  980 (in cross multiplication, you then divide it by the remaininng number, but in this case, it's a one, so the answer will still be 980)\n\nSo, you now know the total number of coins\n\nand just need to calculate the following (I'll leave you to do it)\n\n1/2 of 980\n1/4 of 980\n1/5 of 980\n\nGood luck.
57387
She said she would be here at quarter to six and it is now 6:15, how long have I been waiting?\nThe item cost $1.29 including tax, how much change do I get back from two one dollar bills?\nFive of us and a dozen donuts, can each of us have two?\nThe toll booth wants 75 cents, will two quarters, two dimes and a nickel do it?\nThe ring cost $35.00 and I can afford to save $7.00 each week, how long is it going to take to be able to buy it?\nRelevant?
405715
x+y=50\n.02x + .05y=1.87\n\nfrom the first equation, subtract y from both sides:\n\nx=50-y\n\nsubstitute this into x in the second equation:\n.02(50-y) + .05y = 1.87\n\nand solve for y\n1-.02y+.05y=1.87\n.03y=.87\ny=29\n\nso there are 29 5 cent coins and 21 2 cent coins.
1131661
That problem is the way you state the question.  They each paid $15 * 3 = $45.  Her returned $5, so the total paid to the store is $40.\n\nNow each got one dollar back, so they paid in $14*3 = $42, and the one boy has the extra $2 which needs to be split.  There is no extra dollar:  $42 - $2 = $40!!
371469
ok. there are 3 guys who go on a road trip. they go into the hotel and its $30.00 even for the room. so each guy pays 10.00. (10 x 3 =30)\nwhile they are in the room the checkin girl realizes its only $25.00 for the room. so she grabs 5 one dollar bills and goes up to the room. she realizes that 5 does not divide by 3 evenly. so she taked $2.00 and puts them in her pocket. as she knocks at the door she feels guilty and pulls the $2.00 out of her pocket. they ended up giving her 2 dollars and kept 3. if each guy gets 1 dollar back then instead of 10 they paid 9 each for the room. ( $9 x 3 = 27)\n27 + 2 (tip they gave lady) = $29.00\n\nWHERES THE LAST DOLLAR??????????????
877044
$1.19 - 3 quarters, 4 nickels, 4 pennies\n\nThe people above me who have changed there answers are cheats and should be reported as such !
833462
If he had NO quarters, then he would have 18 dimes and 22 nickels, worth $2.90.  Every time you replace 1 nickel and 1 dime with 2 quarters, it keeps the coin count right, and the extra nickels right, while the value goes up by (2 * 25 - 10 - 5) = 35 cents.  But to get from $2.90 to $4.05, the total value needs to go up by $1.15 which is NOT an even multiple of $0.35, so there is no solutuion in whole numbers.  One of the figures in the question must be wrong.
636056
one coin is not a nickel. the other one is. the answer is a quarter and a nickel
789045
Let\nd = number of dimes\nq = number of quarters\nn = number of nickels\np = number of pennies\n.10d = value of dimes\n.25q = value of quarters\n.05n = value of nickels\n.01p = value of pennies\n\n\n\n\nWe have the following equations:\n\nKeinv has $6.45 in coins in his cash box. \n.10d + .25q + .05n + .01p = 6.45\n\nThe number of quarters is one less than twice the number of dimes. \nq = 2d - 1\n\nThe number of nickels is one less than twice the number of \nquarters. \nn = 2q - 1\n\nThe value of the pennies is the same as the value of \nthe nickels. \n.01p = .05n\n\n\n\nIn summary,\n(1) .10d + .25q + .05n + .01p = 6.45\n(2) q = 2d - 1\n(3) n = 2q - 1\n(4) .01p = .05n\n\nWe simplify these:\n(1) 10d + 25q + 5n + p = 645\n(2) q = 2d - 1\n(3) n = 2q - 1\n(4) p = 5n\n\nSubstitute (2) into (3)\nn = 2(2d - 1) - 1\nn = 4d - 2 - 1\nn = 4d - 3\n\nSubstitute this into (4)\np = 5(4d - 3)\np = 20d - 15\n\nSubstitute n and p into (1)\n10d + 25(2d - 1) + 5(4d - 3) + (20d - 15) = 645\n\nWe distribute\n10d + 50d - 25 + 20d - 15 + 20d - 15 = 645\n\nWe add the d's and the constants\n100d - 55 = 645\n\nWe transpose the constant to the right, and simplify\n100d = 700\n\nThus,\nd = 7\nq = 2d - 1 = 13\nn = 4d - 3 = 25\np = 20d - 15 = 125\n\nTherefore, Keinv has 7 dimes, 13 quarters, 25 nickels, and 125 pennies (having a total value of $6.45).\n^_^
813640
Think of this as an algebra problem.  Let's say N represents the number of quarters.  Therefore, the number of pennies = N+1 and the number of nickels = N+5.  From this you can get the equation\n\nN(.25) + (N+1)(0.01) + (N+5)(0.05) = 3.08\n\nMultiplying it out you get\n\n.25N + .01N + .01 + .05N + .25 = 3.08\n\nCombining the common values gives you\n\n.31N + .29 = 3.08\n\nFrom there you find that N is equal to 9 and the rest is easy.
206421
There are:\n 100 pennies in a dollar\n  20 nickels in a dollar\n  10 dimes in a dollar\n   4 quarters in a dollar\n   2 half dollars in a dollar\n and even 1000 mils in a dollar\n But there are no "pesos".
865487
3 dimes\n30 pennies\n1 quarter and 5 pennies\n2 dimes and 10 pennies\n1 dime and 20 pennies