I need help with my question...(I am a true algebra student!)?
79472
x = (1/3)y + 2\n-2x - y = 1\n\nTake the first equation, and plug its value of x into the second eq.\n\n-2[(1/3)y+2] - y = 1\n\nSimplify\n\n(-2/3)y - 4 - y = 1\n\n(-2/3)y - y = 5\n\n(-5/3)y = 5\n\ny = -3\n\nUsing the value of y, solve for x.\n\nx = (1/3)(-3) + 2\nx = (-1) + 2\nx = 1\n\nSo, the ANSWER is x=1 & y=-3
390615
For #1, try fully factoring the numerator and the denominator. You will find that some of the terms cancel. Start by factoring x from each one. Your resulting term in the numerator is a difference of squares. Your resulting term in the denominator is a factorable quadratic.\n\nFor #2 the expression will be undefined for any value that makes the denominator equal to zero. Again factoring so you can solve for the zeroes is the way to go.\n\nI don't like to work out problems for people, so I hope this is helpful. Likely enough someone else will give you the answers, but I wanted to make sure you knew the process.
895063
Google the word algebra help.  Purple math is great, but there are other sites also.  I am sorry I do not have the names at the moment.
924405
Is it possible to have 2 equal signs in a problem?\nI am only in algebra but I haven't seen one like that before.\nSorry I couldn't help.
88080
there is one you can use for A LITTLE BIT of math/algebra. it's www.algebrasolutions.com
156840
Look up "Algebra Solved 2005" or "algebrator", these two programs not only solve problems, but they give step by step solutions for understanding. they have tutorials and practice test. I went from knowing none to fairly advanced in a few weeks.
904752
here's a link, page down and see if you can follow the steps. :\ngood luck.\n\nhttp://cstl.syr.edu/fipse/Algebra/Unit2/expo.htm
283992
Simple algebra question:\n\na^2 + (a+1)^2 + (a+2)^2 = (a+3)^2 + (a+4)^2\n\nMultiply everything out getting...\n\na^2 + (a^2+2a+1) + (a^2+4a+1) = (a^2+6a+9) + (a^2+8a+16)\n\nAdd like terms on each side...\n\n3a^2 + 6a + 5 = 2a^2 + 14a + 25\n\nAll terms to the left...\n\na^2 - 8a - 20 = 0\n\nFactor into...\n\n(a-10)(a+2) = 0\n\nSolutions are a=10, or a=-2.  Since a has to be a positive integer, a=10.\n\n10,11,12,13,14 are your answers.\n\n\nCHECK:  \n\n10^2 + 11^2 + 12^2 =? 13^2 + 14^2\n\n100 + 121 + 144 =? 169 + 196\n\n365 = 365.
151739
algebra is the solution of equations like the above.  Let the "what" be expressed as w.  Then the question becomes\n\n  w * 3 = 4/3\n\nNow how do we solve this for w.  The trick is to operate on both sides of the equation the same function.  The caveat is that the function applied must have an inverse.  In this case multiply both sides by (1/3).\n\n(1/3)*3*w = (1/3)*(4/3)\n\nNow since 1/3 is multiplicative inverse of 3, the result is 1, and since 1 is the multiplicative identity, the result of the left hand side is w.  For the right hand side just do the multiplication\n\nw = 4/9\n\nThus 4/9 multiplied by 3 equals 4/3.
414537
I was in your shoes once. My brain just doesn't work math the way I was taught it. Are you using the same teacher/tutor or do your teacher and tutor use the same style of teaching? Perhaps trying a new tutor, or getting someone else to work with you will help. I have noticed that not everyone's mind works in the same way. I struggled with math/algebra for years only to later in life have someone else explain it to me and it clicked right away. If someone can present it to you in a way your brain understands, perhaps it will make sense and you will start to do better.\n\nGood luck.
955298
The KEY to solving any algebra problem, as I tell my students, is to get your unknown variable all by itself on one side of the equal sign.\n\nYou do this by "undoing" everyingthing that's being done to it right now.  And you "undo" the easy stuff first, like addition and subtraction, and then the more complicated stuff like multiplication and division.\n\nSo if you're adding 3 to X, then you would subtract 3.  And remember, what you do to one side of the equal sign, you MUST do to the other, so you would need to subtract 3 from both sides in my example.
127894
I can probably help u with it....I am in grade 10, skipped grades 9...reasonably good at Algebra and Trig, Geomerticaly retarded though T,T"\ndamnedatheist@gmail.com can help u
931883
Ummm...\nThe equation of algebra, eh?\nWhat on earth are teachers teaching kids these days?!
87985
The expression was not set equal to anything.\n\nIf you're doing simple factoring in algebra class, the \nsimplest factors would be (b+4) (b+3).\n\nIf the expression was set to equal 0, solve for b, then your answer set would include -4 and -3.\n\nHope this helps!
330568
ask a question! I can help! maybe... yeah, pretty sure I can, I'm in Algebra 2!
405166
Try this:\nhttp://www.wtamu.edu/academic/anns/mps/math/mathlab/beg_algebra/beg_alg_tut9_bar.htm
202506
I can help, I've taken College Algebra, Calc. I, Calc. II and I've also taken many other math courses, and I'm also studying to be a computer programmer, so if you need help you can contact me at assassin7262002@yahoo.com