what is x times the square root of 8+3x times the square root of 50 - 4 times the sq root of 2x squared?
91424
x*SQRT(8+3x)*SQRT(50-4)*2x^2?????\n\nYour statement can be expressed as different algebraic expressions.\n\nExample: The last statement, "2x squared" can be 2x^2 or (2x)^2.\n\nTry to write it in algebraic form with, paranthesis if needed.
1137313
=> 14x -8+5-9x=1-3x\n=> 14x-9x+3x=1+8-5\n=> 8x=4\n=> x=4/8=1/2=0.5\n\nCHEERS!
765445
(1) sqrt(7a)Xsqrt3=sqrt(7aX3)=sqrt(21a)\n(2)sqrt(5a)Xsqrt(15a)\n=sqrt(5aX15a)\n=sqrt(75a^2)\n=sqrt(25X3Xa^2)\n=5a)sqrt)3\n(3)sqrt3(sqrt5-sqrt3)\n=sqrt(15)-3\n(4)(sqrt2+3)(sqrt2-7)\n=2+3(sqrt)2-7(sqrt)2-21\n=-19-4(sqrt)2
713553
you mean simplify squared root of 8?\n8= squared root of 2x2x2\n8= 2 radical 2
896553
4x^2+8x-x-2\n(4x-1)(x+2)
733063
5x^2-35x+3x-21\n5x^2-32x-21
342699
Completing the square involves creating a perfect square trinomial.  Consider\n\nx^2 + 4x - 1 = 0\n\nCompleting the square would involve trying to make one side a perfect square: (x + 2)^2 in this case.  Step by step:\n\n1.  Get all your x terms on one side, and constants on the other.\n\nx^2 + 4x = 1\n\n2.  Take half of the coefficient of the x term and square it.  Half of 4 is 2, and 2 squared is 4.\n\n3.  Add this to both sides of the equation.\n\nx^2 + 4x +4 = 1 + 4\n\n4.  Now factor the left side.  It works out to be a perfect square.\n\n(x + 2)^2 = 5\n\n5.  Take the square root of both sides and solve for x.\n\nx + 2 = +/- sqrt(5)\n\nx = +/- sqrt(5) - 2\n\nThe quadratic equation is pretty easy:\n\nx = [-b +/- sqrt (b^2 - 4ac)] / 2a\n\nIn the above example, a = 1, b = 4, and c = -1 (coefficients of the x^2 and x terms are a and b, and the constant is c).  So plugging in to the quadratic formula gives you\n\nx = [-4 +/- sqrt(4^2 - 4x1x(-1))] / 2x1\n  = [-4 +/- sqrt(16 - (-4))] / 2\n  = [-4 +/- sqrt(20)] / 2\n  = [-4 +/- 2sqrt(5)] / 2\n  = -2 +/- sqrt(5)\n\nwhich is the same as we got via completing the square.
522997
ok, lets say that Sqrt() means square root \n\nSqrt(2x-5)=13   , elevate both sides of the equation to square\n (Sqrt(2x-5))^2 = 13^2  , the square root and the square power cancell each other, so\n\n(2x-5) = 169\n2x = 164, x = 82\n\nThe second one is the same, only that you have to leave the square root alone in the left side of the equation\n\nsqrt(3x-5)+7 = 3 , \nsqrt(3x-5) = -4\n\nand do the same as the first one\n\n3x-5 = 16\nx = 7\n\nthe last one is a bit harder cause there's an 'x' outside of the square root, and you do it like this\n\nsqrt(x+2) = x - 4    , elevate both sides to the square\n\n(x+2) = (x-4)^2    , and do the special product \n(x-4)^2 = x^2 -8x + 16 , then you get\n\n(x+2) = x^2 - 8x + 16 ,  this is a quadratic equation, take it to the general form\n\nx^2 -9x + 14 = 0    and factorize\n\n(x-7)(x-2) = 0  then you get\n\nx1 = 7 and x2 = 2 \n\nthat's it, if you have doubts contact me
18182
2x^2 + 5x + 20x + 50\n2x^2 + 25x + 50
714160
x^2+6x+8/x^2-4-21 / x^2-4/x^2-7x\n=x^2 + 6x +(8/x^2) - 4 - (21/x^2) - (4/x^2) - 7x\n=x^2 + 6x -4 -7x +(8/x^2) - (21/x^2) - (4/x^2) \n=x^2 + 6x -4 -7x +[8-21-4]/x^2\n=x^2 + 6x -4 -7x -17/x^2\n=(x^2)*[x^2 - x -4  -17]/x^2\n=(x^2)*(x^2) - (x^2)*(x) -4*(x^2)  -17]/x^2\n=(x^4) - (x^3) - 4(x^2)x -17]/x^2
839343
x^2 + 4x + 4 = 7 (subtrat 7 from both sides)\n\nx^2 + 4x -3 = 0 (use the quadratic equation formula)\n\n-b + or - the square root of (b^2 - 4ac) / a^2\n\n-4 + or - the square root of 16 - (4) (1) (-3) / 2\n\n-4 + or - the square root of 28 / 2\n\n-4 + or - (the square root of 4) (the square root of 7) / 2\n\n-4 + or - 2 (the square root of 7) / 2 (simplify by dividing 2 into  the -4 and 2 on the top to get rid of the 2 on the bottom)\n\nthat gives you x = - 2 + or - the square root of 7.
758567
2(2x-4)= x+4\n4x-8 = x+4\n4x-x = 8+4\n3x = 12\nx=4\n\n&\n\n4(x+3)+3= 5(x-4) + 5\n4x+12+3 = 5x-20+5\n4x+15 = 5x-15\n4x-5x = -15-15\n-x= -30\nx = 30\n\n&\n\nx+2= 4(5x-2)\nx+2 = 20x-8\n2+8=20x-x\n10 = 19x\n19x= 10\nx=10/19\n\n&\n\n21-3x = 4x+7\n21-7 = 4x+3x\n14=7x\n7x = 14\nx=14/7\nx=2
795657
1. Move the constant to the right side of the equation:\n3x^2 - 8x = 6\n\n2. Divide out the x^2 coefficient:\nx^2 - 8/3x = 2\n\n3. Divide the coefficient of x (in this case, -8/3) by 2 and square it, then add it to both sides:\nx^2 - 8/3x + 16/9 = 34/9\n\n4. Factor the left side of the equation to (x + a)^2, where a is the number you just squared:\n(x - 4/3)^2 = 34/9\n\n5. Take the square root of both sides, remembering that this will produce both a positive and a negative root:\nx - 4/3 = +/-sqrt(34/9)\n\n6. Move the constant on the left to the right and simplify:\nx = 4/3 +/-sqrt(34/9) = 4/3 +/-(sqrt 34)/3 = (4 +/- sqrt 34)/3
879176
= x(x+3) + 4(x+3)\n= x^2 + 3x +4x + 12\n= x^2 +7x + 12
897641
8-3x=4x-12+6\n-7x=-14\nx=2
763039
x(sqrt)3+4=7+(sqrt)3\n=>x(sqrt)3-(sqrt)3=7-4=3\n(sqrt)3} (x-1)=3\n3(x-1)=3(sqrt)3    [multiplying both sides by (sqrt)3]\nx-1=(sqrt)3      [cancelling or dividing both sides by 3]\nx=1+(sqrt)3  ans
164954
x^3 – 3x^2 + 4x – 12\n= x^2(x – 3) + 4(x – 3)\n= (x-3)(x^2 +4)