i am trying to figure out a maths method so i can find out how long it will take a human to eat an elephant.?
87896
e=mc^2\ne=elephant\nm=mouth\nc=canines\nc=chew-speed
146112
This is a system of equations problem. With 20 heads, you know there were a grand total of 20 humans and goats, and with one head each, you can set humans to x and goats to y and get x+y=20. Then you know that there are 50 legs, and humans have two legs and goats have 4. So you can say 2x+4y=50. Then you must get one variable by itself. A way of doing this is to multiply each part of x+y=20 by 4 to get 4x+4y=80. With this new equation and the other one, you can subtract each term, therefore eliminating the y's from one equation, and you get 2x=30. You can then divide both sides by 2 to get x=15. Then to get y, substitute 15 for X back in the original x+y=20 to get 15+y=20. Then subtract 15 to get y=5. Therefore, there were 15 humans and 5 goats.
134187
Large elephants will surprisingly eat eggs sometimes.\n\nSometimes, elephants will eat surprisingly large eggs.
415302
You need to use Pythagorean theorem.\nMeasure the lenght of the lotus plant which is above the water.(X)\nBend the plant to any one side until it is just submerged under the surface of water.\nMeasure the Dist. between the initial and final positions of the plant(Y)(i.e. the initial position and final position where it is submerged)\n\nLet the actual lenght be L.\nThen (L x L) = (Y x Y) + (L - X)(L - X)
258248
One year and 10 months old.  \n\nYou take 1 million minutes, divide by 60 to get how many hours they have lived, divide by 24 to get how many days they have lived, divide by 365 to get how many years they have lived.  You arrive at 1.9 years, which is the same as 1 year 10 months.
974651
These are some nice websites that might help you out.\nhttp://www.dailymail.co.uk/pages/live/articles/news/news.html?in_article_id=400522&in_page_id=1770\nhttp://www.gan.ca/animals/elephants.en.html\nhttp://elephant.elehost.com/About_Elephants/Senses/senses.html\nhttp://news.softpedia.com/news/Elephants-Show-Compassion-and-Have-an-Awareness-about-Death-32660.shtml\nhttp://www.sussex.ac.uk/press_office/media/media513.shtml
181213
Kangaroos Hop Down Under drinking chocolate milk - this gives you the order\n\nK = kilo\nH = hecto\nD = deca\nU = unit (meter, liter, gram, etc)\nd = deci\nc = centi\nm = milli\n\nso start with what you are given, 10 meters would start on the U.  Move to the H for hecto - you had to move to the right 2.  So move your decimal point 2 to the right.  10 -> 1.0 -> .10.  There are .10 hetometers in 10 meters.
316406
Depends on how fast you're counting...\n\nhttp://hub1.worlded.org/docs/maththing/ny1p5.htm\nhttp://mathforum.org/library/drmath/view/58739.html
752431
Elephants dont generally chew anything - they just swallow their food hence it doesnot matter if it is peanuts or bananas :)
447208
OK. two things to do. Let's assume your 225 minutes are in cell A1\n\n\n=INT(A1/60) ;This gives you the hours\n\nNext\n\n=MOD(A1/60) ; This gives you the remaining minutes.
1062908
I did this problem with my calculus class. We used related rates to find the answer. I think that the average number each group of people got was like 304 licks. This was not an easy problem for us to solve, but we did.
624016
Take live caterpillars.  Isolate them in enclosures with their preferred food, being careful to weigh how much is in the enclosure with each caterpillar.  Let 'em eat for 24 hours.  Remove (and release, if you please!) the caterpillars, and weigh the remaining volume of food.  The difference between the starting weight and the remaining weight should be roughly what the caterpillar ate.  (There will be some weight loss due to evaporation of moisture from the food over 24 hours, but that should hopefully be small.  You could control for that by letting some of the preferred food be in an enclosure without a caterpillar, and find the difference in weight, but unless you need really high precision, I wouldn't bother.)\n\nTheoretically, you could weigh the caterpillars--but there is an additional variable: how much excrement is excreted, which may not be the same from caterpillar to caterpillar on any given day...  Easier to weigh the food.
448711
51,336\n\nNext time just type your math problem into at google search and it will do the math for you!\n\nLink below.
97110
Try\nhttp://www.math.buffalo.edu/mad/PEEPS/graham-carl.html
434589
almost exectly half  a metre, some times a litle bit less .sometimes a little bit more.depending on the age and the region\nthe elephant is fatter and longer(one metre) even though the girafe is taller\nso this goes to prove that the lenth of the neck does not determine the length of the penis.
107932
These are kind of fun if you apply dimensional analysis over and over again.  Lets assume that our years are 365, 365, 365, 366 days, and that we'll experience two leap years in the time span.  This is then 8*365 + 2*366 days, which is our starting point\n\n3652 days\n\nnow we know that there are 24 hours = 1 day, so take this formula and multiply both sides by (1/day) to get 24 hours/day = 1.  Since multiplying by 1, by this equation multiplying by 24 hours/day does not change value\n\n3652 days * 24 hours / day\n\nNow cancel the "day" term in the numerator and denomenator\n\n3652 * 24 hours\n\nNow do the same thing for minutes and then for seconds.  60minutes/hour = 1 so\n\n3652 * 24 * 60 hours * minutes / hour\n\ncancel hour and apply 60 seconds/minute = 1\n\n3652 * 24 * 60 * 60 minutes * seconds / minute\n\nand cancel the minute term and perform the multiplication:\n\n315,532,800 seconds
925143
This is an exponential increase function so it has the form\n\nN(t) = N0 e^(- λ * t)\n\nwhere N is the number of infected, N0 is the initial number of people infected, λ is the decay rate and t is the amount of time.\n\nIt is given that N(0) = 1 person and N(3) = 25 people\n\nUsing these values we can solve this for λ. These two equations are\n\n1 person = (1 person) e^(- λ * 0)   [a]\n\nand\n\n25 people= (1 person) e^(- λ * 3)  [b]\n\nSolving [a] will not let us determine λ so we must use [b] to find it. Taking the natural log of both sides gives us\n\nln[(25 people)/(1 person)] = ln(e^(- 3 days * λ))\nln25 = -3 days * λ\n(ln25)/-3 days = λ\nλ = -1.07/day\n\nSince we used days to determine the 'decay' rate we must now convert one week to days. So one week is 7 days. Now to find the number of infected we just plug in the values into the formula to find N(7)\n\nN(7) = (1 person) e^[-(-1.07/day) * (7 days)]\n\nnotice here that the units in the exponential cancel out, as they must, so that out units for out answer is people, as we would expect.\n\nEvaluating this expression gives \n\nN(7) = (1 person) e^(7.51)\n= 1826.21 people\n\nSince there are only 500 people everyone is infected. Because you referenced carbon decay that is why I used an exponential function. I'm not sure if this is correct, but it's what I came up with. This seems to be a particularly nasty virus.