If the point (-2,y) is on the line 4x- 3y=1 what is the value of y?
79630
replace x with -2 and solve for y and get y = -3.
744474
x=2y\n\n-2 -4\n0 0\n1 2\n3 6
293623
(y(1)-y(2))/(x(1)-x(2)) =\n(3-(-2))/(3-8) =\n(5)/(-5) =\n-1
399118
y-int= (0,-5)\nx-int= (-1.2,0)
743965
If you can find the slope, you use the formula\n\ny - y1 = m(x-x1) where y and x are in general and y1 and x1 are the x and y values from ONE point. Pick either, it doesn't matter. So...\n\nThe slope is -2.\n\ny - 8 = -2 (x - - 2)\n\ny-8 = -2x - 4\n\ny = -2x + 4
935919
Please calm down. Now do you want the line between (2,0) and (-2,-2) The way I do it is to get the point vector solution of the line and eliminate t. The point is (2,0). The vector is <-2 - 2, -2 -0>. Just subtract the first coordinate from the second. So the vector is <-4, -2> \nNow set up the point vector equation describing the postion of the graph at time t.\nJust point + vector*t in component form.\nThe x-components: x = 2 - 4t \nThe ys: y = 0 - 2t\n\nThere, that is it. But some nasty professors don't like this form, so we'll eliminate t. We plug y = -2t into first equation and get x = 2 + 2y.\n2y = x - 2. y = x/2 -1.
861275
x(y-1) = 2y + 3\n\nxy - x = 2y + 3\nxy - 2y = x + 3\n(x - 2) = (x + 3) / y\n y = (x + 3) / (x -2)
805693
#1\n4x+1+3=0\n4x+4=0\n4x=-4\nx=-1\n\n#2\n2y+7+4=y\n2y+11=y\ny=-11
852206
since the line is perpendicular to y - axis . that means the x value can change but y value remains the same.\nIt is given that ( 5, -3) is a point on the line. So, y = (-3)
1169467
y = x^2 + 5x - 3\n2y=3x - 2\n----------------\n2y = 2x^2 + 10x - 6\n2y = 3x - 2\n-----------------------\n    0 = 2x^2 + 7x - 4\n=>2x^2 + 7x - 4 =0\n=>2x^2 + 8x - x - 4 = 0\n=>2x(x + 4) -1(x+4) = 0\n=> (2x - 1)(x + 4) = 0\ntherefore 2x - 1 = 0 => x = 1/2 or \nx + 4 = 0 or x = -4\nx = - 4 or 1/2  \ngot it?
245933
(4x+3)(x-1)=0\n\nx= -3/4, x=1
311149
y=-1\nEDIT-OOPS-forgot about the negative part-more info:\nas in the point = (0,-1)\n\nthis is because the 1 part int he equation is the "B" in y=mx+b.  b is your y-intercept.  if b is negative, then your y-intercept is negative
384702
The first 3 are all straight lines, so you just need to get 2 points in each.\n1. y = |x| + 3 for x = 1 then y = 4, for x = 2 y = 5.\n\n2. y = 3/2x - 2 for x = 2 then y = 1, for x = 4 y = 4\n\n3. y = x - 5 for x = 5 y = 0 for x = 6 y = 1\n\nFor #4. This is a curve shaped like and upside down U that passes through 0,0, for all values of x, y will always be negaive.\n\nThe best way is to substitute values of x and get values of y and sketch.\n\nHope I was some help
70526
=((-4y)^2)/(10y-5)= (16y^2)/(10y-5)\nand if the equation is equal to zero then y=4i
917321
x+y=2\n2x-y=0\n\nx=2-y\n2(2-y)-y=0\n\nX=2-y     \n4-3y=0   \n\nx=2-4/3\ny=4/3
35268
slope = (-4-(-6))/(-2-0)\nslope = -1
549653
Subtract 2x from each side\n-y = 0 - 2x\nMultiply each side by -1\ny = 2x