what is the resonant frequency of silver? Gold?
96897
use this link...\nhttp://www.sonic.net/~emgman/specs.html\n\nIf u are able to understand.....reply me....
579685
Silver just close around $12.65/oz , \na lb would be about $202 .
1161613
Angular frequency = Sqrt(k/m)\n\nk===spring constant ; m= mass\n\n2* pi*Frequency=Angular frquency\n\n===>Frequency =(1/(2*3.14) *sqrt(k/m)\n\n5.5=0.1592*sqrt(130/m)\n130/m=(5.5/0.1592).^2\n\nm=0.0109 Kg\n\nAngular frequency = 2*3.14*5.5=34.5400\n\n\nT=1/frequency\n\nT=1/5.5 s=  0.1818 sec
937514
wavelength = speed of light / frequency\nfrequency = speed of light / wavelength\nf = (3*10^8 m/s) / (615*10^-9 m)\nf = 4.878*10^14 Hz\n\nwavelength = planck's constant * speed of light / energy\nenergy = planck's constant * speed of light / wavelength\nE = (6.626*10^-34 J*s) * (3*10^8 m/s) / (615*10^-9 m)\nE = 3.232*10^-19 J
388869
resonance is the tendency of a system to absorb more energy when the frequency of its oscillations matches the system's natural frequency of vibration (its resonant frequency) than it does at other frequencies. Examples are the acoustic resonances of musical instruments, the tidal resonance of the Bay of Fundy, orbital resonance as exemplified by some moons of the solar system's gas giants, the resonance of the basilar membrane in the biological transduction of auditory input, and resonance in electrical circuits.\nA resonant object, whether mechanical, acoustic, or electrical, will probably have more than one resonant frequency (especially harmonics of the strongest resonance). It will be easy to vibrate at those frequencies, and more difficult to vibrate at other frequencies. It will "pick out" its resonant frequency from a complex excitation, such as an impulse or a wideband noise excitation. In effect, it is filtering out all frequencies other than its resonance.\n\n\nFor a linear oscillator with a resonant frequency Ω, the intensity of oscillations I when the system is driven with a driving frequency ω is given by:\n . \nThe intensity is defined as the square of the amplitude of the oscillations. This is a Lorentzian function, and this response is found in many physical situations involving resonant systems. Γ is a parameter dependent on the damping of the oscillator, and is known as the linewidth of the resonance. Heavily damped oscillators tend to have broad linewidths, and respond to a wider range of driving frequencies around the resonant frequency. The linewidth is inversely proportional to the Q factor, which is a measure of the sharpness of the resonance\n\nThe Cauchy-Lorentz distribution, named after Augustin Cauchy and Hendrik Lorentz, is a continuous probability distribution with probability density function\n \nWhere x0 is the location parameter, specifying the location of the peak of the distribution, and γ is the scale parameter which specifies the half-width at half-maximum (HWHM). As a probability distribution, it is known as the Cauchy distribution while among physicists it is known as the Lorentz distribution or the Breit-Wigner distribution. Its importance in physics is largely due to the fact that it is the solution to the differential equation describing forced resonance. In spectroscopy it is the description of the line shape of spectral lines which are broadened by many mechanisms including resonance broadening.
644355
"In physics, resonance is the tendency of a system to absorb more energy when the frequency of its oscillations matches the system's natural frequency of vibration (its resonant frequency) than it does at other frequencies. Examples are the acoustic resonances of musical instruments, the tidal resonance of the Bay of Fundy, orbital resonance as exemplified by some moons of the solar system's gas giants, the resonance of the basilar membrane in the biological transduction of auditory input, and resonance in electrical circuits.\n\nA resonant object, whether mechanical, acoustic, or electrical, will probably have more than one resonant frequency (especially harmonics of the strongest resonance). It will be easy to vibrate at those frequencies, and more difficult to vibrate at other frequencies. It will "pick out" its resonant frequency from a complex excitation, such as an impulse or a wideband noise excitation. In effect, it is filtering out all frequencies other than its resonance."\n\nThe above is lifted from Wikipedia, the online encyclopedia.\nIn electronic circuits, resonance is produced by a tuned combination of Capacitors and Inductors.\n\nThe following link allows you to input capacitance and inductance, and will calculate the resulting resonant frequency for you:\n\nhttp://www.deephaven.co.uk/lc.html
852104
The frequency in the number of times the wave vibrates in one second. \nIn your question, you probably have light.  The speed of light is 300,000km/s.  If you multiply the frequency and the wavelength, you get the speed.  That is v=lf\nThat 595nm is actually 595x10e-9m or 0,000000595m\nThe speed of light is 3x10e8m/s\nSo the frequency is\nf=v/l\nf=300000000/0.000000595\nf=504201680672268.91\nf=5.1e14 hertz
736832
You have stated that the tuning fork B is loaded and has a lesser frequency than that of A.\n\nLet the frequency of B be N and you know that N is lesser than 256 Hz.\n\nBeat frequency is the difference between the two frequencies.\n\nTherefore 256 - N = 10 ( given).\n\nOr N = 246 hz.\n\nFor your second  question:\n\nVelocity = frequency X wavelength.\n\nIn a closed tube the first resonant length is obtained when the length is one fourth of the wavelength.\n\n Therefore L = 4 x l.\n\nOr V = 4 N l where N is the frequency and l is first resonating length.\n\n\n344 =  4 x 440 x l.\n\nl = 344 / 1760 = 0.195 m  = 19.5 centimeter.
237020
Gold AU\nSilver AG\nLead PB\nCarbon C\nNickle NI\nIridium IR\nZR Zirconium\nCU copper\nLi Lithium
88694
It is a very pure conductive metal. More pure than gold. Indeed.
326804
There's an even easier method than calculating the density. Jewelers use it all the time. Gold is about the least reactive element in the periodic table, so simply bringing the gold in contact with acid will tell you.\n\nIf there is a reaction, if the metal is etched, then it is not gold, or it doesn't contain a high concentration. If nothing happens, then it's gold. I wouldn't recommend doing this yourself, however. A very strong acid is generally used. Also, if the object is something you don't want damaged, even if it isn't gold, I'd urge caution or another method. Or just go see a jeweler.\n\nThe density method works too, just be sure that if it is a necklace or something like that, shake out all the air bubbles in the links. A friend of mine thought a necklace that he bought for his wife was fake because he did a density analysis and determined it wasn't gold. The jeweler did an acid test and said it was gold. My friend repeated the experiment and realized he did not shake the air bubbles out of the necklace.
782952
20Hz- 20kHz (audible frequencies)\n< 20Hz (infrasonic)\n> 20kHz (ultrasonic)\n\nlongitudinal wave - sound wave\nthe rest are transverse waves
752428
Generally from 20 - 20,000 HZ depending on the individual. We lose some high end range as we age
834583
You can use the Rydberg formula, which relates the reciprocal of the wavelength of the photon absorbed or emitted to the squares of the reciprocals of the principal quantum numbers.\n\n1/wavelength = R(1/n_l^2 - 1/n_u^2)\n\nSo, for the listed values of n, \n\nA.  1/w = R(1/ 2^2 - 1/4^2) = 0.1875R\nB.  1/w = -0.75R\nC.  1/w = 0.21R\nD.  1/w = -0.04861R\n\nSince energy and frequency are proportional to 1/wavelength,\nlooks like the order is D, A, C, B.
480516
Silver is an element.  It is found in rocks that are called ore.  It usually occurs as a sulfide mineral, such as AgS2, or in small amounts in a sulfide mineral based on another metal, such as PbS2.\n\nGold is Au.  Silver is Ag.
1160585
4 Hertz = 4 times per second
486866
If one wave equals one cycle, then the answer is:\n\nA. 6 Hz