oneleg of a right triangle 1 inch more than the other leg the measure of hypotenuse is 5 cm find lengh of 2 le
80712
If you mean 1 cm and 5 cm, then the answer would be\n\n3 cm\n4 cm\nand a 5 cm hypotenuse.
1126945
Thales understood similar triangles and right triangles, and what is more, used that knowledge in practical ways. The story is told in DL (loc. cit.) that he measured the height of the pyramids by their shadows at the moment when his own shadow was equal to his height. A right triangle with two equal legs is a 45-degree right triangle, all of which are similar. The length of the pyramid’s shadow measured from the center of the pyramid at that moment must have been equal to its height.
421239
since this starts as a square.  when we place the diagonal line from the bottom right corner to the upper left corner we end up with two right triangles.  This is the perfect set up to use the Pythagorean theorem, which states "the square of the hypotenuese is qual to the sum of the squares of the base and height. you may have seen it as \n       h^2 = x^2 + y^2\nwe started with a square so we know the base (x) and height (y) are each 7 sq rt 2.\nsquare the values then add them together.  this will give you that diagonal's square. ****remember to take the sqrt of the answer to find the length of the diagonal.
616025
Pretend that:\nx= length of base\n\nUsing the information given:\n4x-8= length of one of the legs\n\n\nProcedure:\n2(4x-8) + x = 29 ---> (there are 2 legs- so you x2)\n8x-16 + x= 29\n9x-16= 29\n9x= 29+16\n9x= 45\nx=5\n\nResult:\nSince x=5 and 4x-8 is one of legs of the triangle, by simplying applying the x=5 into 4x-8, you can get your length of one of the equal legs.\n\n4x-8= 4(5)-8= 20-8= 12\n\nANSWER: D) 12 cm
956162
It depends on which leg you know the length of.  If it's the "adjacent"leg--the one that, along with the hypotenuse, forms the angle--then remember that the cosine of an angle is defined as the length of the adjacent angle divided by the length of the hypotenuse.\n\nIf it's the "opposite" leg--the one that isn't part of the angle--then you use the fact that the sine is defined as the length of the opposite leg divided by the length of the hypotenuse.\n\nEither way, you use the inverse trig functions on your calculator to find the angle.
882750
Listen to the first guy.\nThe distance on the y axis is 1 ((-5)-(-4)) and on the x axis it is 3 ((-3)-0).\nThis gives you a right angles triangle with sides of 3 & 1. \nUnder Pythagoras theoem the sum of the squares is equal to the square of the hypoteneuse so\n1^2 + 3^2 = 10.\nTherefore the distance is the square root of 10.
959978
use pythagorean thereom a^2 + b^2 = c^2. (c being teh longest side or the hypotenuse) the two legs are a and b. so you have the sq rt of 169. (sqrt of 12^2 + 5^2) which is 13
1139471
Yeah where's angle 1 and 2.\nBut remember the angle opposite the longest side has the greastest measurement.
894026
Let the shorter leg have length x.\n\nThe longer leg has length x + 2.\n\nThe hypotenuse has length x + 4.\n\nUse the Pythagorean Theorem:\n\nx^2 + (x + 2)^2 = (x + 4)^2\n\nx^2 + x^2 + 4x + 4 = x^2 + 8x + 16\n\n2x^2 + 4x + 4 = x^2 + 8x + 16\n\nx^2 - 4x - 12 = 0\n\n(x - 6)(x + 2) = 0\n\nx = 6 or x = -2\n\nA length cannot be negative, so the shorter leg has length 6 cm.\n\nThe longer leg has length 8 cm.\n\nThe hypotenuse has length 10 cm.\n\n(This is a common Pythagorean triple, by the way, so you could have found the answer like that. :D )
903414
Because the diagonal creates two right triangles you can use the Pythagorean theorem to find the length of the other side:\n\n5^2 +x^2 = 9^2\n25 + x^2 = 81\nx^2 = 56\nsqrt of 56 = 7.48\n\nNow that you have the length of the other side you can use the formula    area = length x width:\n\n5 x 7.48 = 37.4 feet
331507
sorry hunny you need at least 2 side lengths in order for us to help you figure it out... plus once you have that the formula for figuring it out is using the pathagorean theorem! a2+b2=c2 (s = squared) say for instance... the 2 sides of your triangle are 7 and 3inches. 3>2+7>2=c>2\nwhich would turn into 9+49=c>2~~~~~~~ then 58=c>2 then to get c by itself(which is needed) you would take the square root of 58! your hypotenuse would equal 7.6 or rounded, 8!\nnow if you use my steps you should be able to do your problem! I'm a 10th grader in geometry and it's the most lovely subject!
837883
Draw a picture of the triangle formed to see that the side opposite the angle is 24 and the side adjacent is k, with 25 being the hypotenuse.  Sine = opp. leg/hyp. which is 24/25\nCosine = adj. leg. / hyp. = k/25\n\nIf you need to, you can find k using the Pyhhagorean Theorem\n(k squared = 25 squared - 24 squared), keeping in mind it can be positive or negative.
797707
See the picture:\n\nhttp://mudandmuck.com/str2/sin&cos.jpg\n\nThe two triangles in the picture are equivalent.  (Same angles, and one side of each we know to be the same (hypotenuse=1), so all the sides have the same absolute length, only their signs are different.)
555699
I think I can help you with this one... I learned how to do it in Kindergarten.\n\nPull your head out of your ass and measure.\n\nGood Luck!
764383
I get 5:\n\nThe difference in the y coordinates is:\n-5 - (-1)\n= -5 + 1\n= -4\nBut for a length we take the absolute value --> 4\n\nThe difference in the x coordinates is:\n0 - (-3)\n= 0 + 3\n= 3\n\nSo you have two sides of 3 and 4.  The hypotenuse can be found by remembering the special 3-4-5 triangle, or using the Pythagorean theorem.\n\na² + b² = c²\n3² + 4² = c²\n9 + 16 = c²\n25 = c²\nc = sqrt(25)\nc = 5\n\nIn general, the distance is sqrt((Δx)² + (Δy)²) where Δx is the change in x coordinates and Δy is the change in y coordinates.  I think you made a mistake and accidentally got sides of 3 and 2, rather than 3 and 4.
93089
This seems like a homework problem, so I'll give a few hints.\n\nThe arclength is radius times the angle subtended.\n\nTo find the angle subtended, consider the isosceles triangle created inside the circle where the chord is the hypotenuse and the radius of the circle is the two other legs. \n\nSince the isosceles triangle created is not a right triangle you need to use a specific formula to find the angle "C" subtended by the chord.
155406
By definition,hypotenuse is the side opposite the right angle. So it has to be a right angled triangle.