does the size of a balloon affect the rate of how a balloon floats?
86606
The size affects the "floatability" of a ballon, because there is a larger percentage of "lighter than air" material inside the balloon pushing it up than the weight of the balloon's skin pulling it down.
466045
Picture two objects, one being a large beach ball, tightly filled with air, the other a fist sized stone.  These two objects will be dropped into a pond from the same height.  Which one makes the bigger splash?  Another way of looking at it would be to picture the same two objects sitting on the middle of a stretched out rubber sheet.  Looking at the indentation fromt he under side of the sheet, the stone will have a much larger one.  The cool thing is when the proportions of mass to density are unusual in that an object has an extremely large density and very small mass.  The resutls to the surrounding fabric of spacetime is noticibly more dramatic the further apart these two measurements become.  Another fun thing to think about is that as speed increases towards the speed of light an object increases in density and becomes extremely heavy.  This means that an object with any density while stationary has a variable potential for manipulation of spacetime dependant upon it's speed.  Read The Elegant Universe.  It's a cool book if you like this sort of stuff.  :)\n\nAnother thing to picture to help understand this concept:  Again go back to a stretched out rubber sheet, this time you are pressing objects into it with the same force.  One is a pencil (eraser side), the other is a basketball.  Remember that you are pressing just as heard on both objects (which represents gravity having the same pull on both) even though they are of different sizes.  This represents one small object with heigh density having the same pull as a larger mass object with lower density.  Now think about what the stretches on the sheet look like from each experiment.  Now take that idea and try to picture it in 3 dimensions (or 4 if you want to get technical :p)
400216
It depends on windspeed and direction, and the planes direction in relavence to that speed and direction. It depends on the speed of the plane. It depends on the density of the object, because of wind resistance. EX. feather would be close, lead ball would be further. Your question is like me saying, "I am in a car, how long will it take me to get to McDonalds?" Not enough info
408700
The following link is a pdf slide show that gives examples of buoyancy calculations and theory of floating objects.\n\nhttp://www.colorado.edu/physics/phys1010/phys1010_fa05/lectures/class12-09-29.pdf
965619
buoyancy forces are what cause a balloon to rise whether in water or air.  buoyant forces are proportional to the density of the media being displaced.  water, having a much higher density than air, when displaced produces a greater rising force on the balloon, ergo the balloon moves faster.  air, having a higher density than helium, when displaced also produces a greater rising force on the balloon, ergo the balloon still moves but slower than in water.
469382
depends on the time of day. During a hot day the air balloon would pop first because air heats up juch faster than water. at night the air balloon would actually shrink because the air in the balloon would contract because of the cold air.
713171
No the molecules still weigh the same. With water the volume will increase, that's why ice floats. Most other substances decrease as they freeze.
738177
density of helium balloon is less than density of air( with 1 atmosphere pressure) so it goes up(just like wood floating water).\nbut density of air decreases by decreasing pressure(i.e. increase altitude) so in a certain altitude, density of air becomes equal to density of balloon then balloon cease to go higher.\n\nto get more info you can search "archimedes principle"\n\nI'm afraid you can not explain that to your kid! better to buy him a new balloon !\n\nmy source : studies in university
182931
Lift under a liquid (or BOUYANCY FORCE) is defined as the weight of the volume of liquid displaced.  In other words, say a ball displaces 1 cubic meter of water.  The ball will be pushed back up with the same amount of force as the weight of that 1 cubic meter of water.\n\nSince water's density is 999 kg/cubic meter, we're looking at 999 kg of water (water is really heavy!).\n\nNow if we want the force of that water, we'd simply multiply it by the gravitational acceleration, 9.8 m/s/s:\n\n999 * 9.8m/s/s = 9790 Newtons (1 Newton = 1 (kg * m)/(s^2))\n\nSo the ball would be pushed back up with a force of 9790 Newtons.\n\nNow, the hard shell ball will (theoretically) not deform when subjected to the pressure of 10 feet of water.  So the *bouyance force* placed on the hard shell ball is easy to calculate, given the formula above.\n\nThe latex balloon, however, will shrink as it is exposed to increasing pressure, so the volume of water it displaces will be smaller. (I will not solve that problem here as it takes up quite a bit of space to show how much a balloon shrinks as it is subjected to increasing pressure.  Essentially it comes down to writing a spherical force balance and integrating over volume)\n\nConsequently, the bouyancy force exerted on the latex balloon will be smaller, and the ping pong ball would be forced back up through the water harder (and faster) than the balloon.\n\nAs an extreme, ever wondered what happens to helium filled balloons when they are released into the air and they float up until you can't see them anymore?  Since the atmospheric pressure is lower and lower the higher you go, the balloon expands until eventually it pops.  At that point, the popped balloon either falls back to earth or gets swept up into atmospheric currents, which can take it basically anywhere on earth.
203787
There are a couple of things you need to think about so you can work this out for yourself. \n\n1. Gases expand when they are heated. This is easily seen from the ideal gas law, PV=nRT, where P is pressure, V is volume, n is number of moles, R is a constant and T is temperature. Most gases roughly follow this law. As T increases, so does V, at constant P (of course, in the case of a balloon, P does not remain constant). \n\n2. When the volume of a gas increases, its density D=mass/V  decreases.\n\n3. By Archimedes principle, the buoyant force on an object is equal to the weight of the fluid displaced. The net buoyant force is the difference between the buoyant force on the object and the weight of the object. \n\nSo in the case of your balloon, if it displaces air of greater density (since it is colder), then there is going to be a net buoyant force upwards on the balloon. The weight of the air of density Da displaced by a balloon of volume V is V*Da*g, where g is the acceleration of gravity. \n\nI could go into more detail, but you might enjoy working this out for yourself. If you need more help, then ask.
66611
No the density would be the same. The sample size does not affect the density. The Volume and Mass grow at proportional rates, so it doesn't affect density.
300802
if the point is big the gravity don't effect it much but if it is small gravity will effect it i forgot the whole explanation though \n\nyou could try this link
94588
It depends on various factors but most important would be pressure. As the balloon ascends into the upper atmosphere pressure is slowly reduced as the air gets thinner farther up the balloon goes, Pressure within the balloon where the helium is held soon expands out as the air molecules in the atmosphere reduces and at one point it will burst as the helium expands past the stretchability limit of the balloon. So it depends on how strong the balloon fiber is, how much helium is stored within the balloon, how thin is the surrounding atmosphere compared to pressure within the balloon and also if the balloon meets any obstruction on its way up.
1163141
yes .. in vacuum, all items will fall at same rate... it is the rate at which the gravity acceleration attacts everything to the center of teh Earth. But you might have a queation, that if the acceleration  is same then why different things weigh different... \n\nweight =mass X acceleration of gravity (9.8meter/second^2) and mass is the one which is a measure of matter in a body makes the difference... so if you let a 5kg weight and a 5,000kg weight fall in a vaccum, they will fall at the same rate and will reach the ground at the same time.
286635
The magnitude of each force depends on a lot of factors. Gravititional force is constant as long as the mass of the object remains the same. Buoyant force depends on the the density of the fluid. If the fluid is plain old air, then the buoyant force is probably very small. But if the object were placed in water, it would have a significantly larger buoyant force. Fluid resistance depends on the surface area of the object, the speed of the object, the shape of the object, the mass of the object, and the density of the fluid. Fluid resistance may be large for a parachute but small for a penny. You could find all of these numbers and compare the forces to see which are larger.
1047922
It all depends on buoyancy and density. \n\nIf the weight of an object is less than the weight of the fluid the object would displace if it was fully submerged, then the object is less dense than the fluid and it floats at a level so it displaces the same weight of fluid as the weight of the object.\n\nIf the object has exactly the same density as the liquid, then it will stay still, neither sinking nor floating upwards, just as the liquid nearby stays still.\n\nUNLESS, \n\nAn object made of a material of higher density than the fluid, for example a metal object in water, can still float if it has a suitable shape (ex: hollow) that keeps a large enough volume of air below the surface level of the fluid. In that case, for the average density mentioned above, the air is included also, which may reduce this density to less than that of the fluid.
738510
The density will decrease.  This is because heating the gas will cause its pressure to increase.  The rubber (or whatever fabric the balloon is made of) will respond by moving outwards.  Therefore the volume will have increased and, since the mass of the gas will not have changed, it density will decrease.  The actual amount by which it decreases will depend on the elasticity of the fabric.\n\nIt's much easier to quantify the decrease if you are dealing with an open-necked balloon (such as a hot-air balloon), as the density of the gas is, to a fairly close approximation, inversely proportional to the absolute temperature.  So, if it is heated from 200°C (473K) to 300°C (573K), its density will decrease by a factor of 573 ÷ 473  =   1·211 (or, its density will become 0·825 (82·5%) of what it was before).