how do I do linear regression on a TI-84 plus? I can't get the r?
79585
If it is anything like the TI-83 plus, you need to turn on DiagnosticOn. For the 83 hit [2nd][0] which is the catalog of all commands and scroll down to DiagnosticOn hit enter twice and then run the linear regression. I assuming they didn't change the calculator that much and that this wont work for the TI-84 plus.
509283
In statistics we talked about residuals. a Residual is anestimate on how well your regression line fits your data. The residual is often notes as r^2. I'm not sure on exactly how to find it, but on the TI 83 plus, the residual is a flat line and the data is scattered around it. The data should be spread equally on both sides of the line. the more equal the data is spread, the better your residual line. When you find the "VarsStat1" on the TI 83, the residual value will be there noted as r^2.
300929
r is probably 27 and t is 8. Here's my reasoning:\n\n18 * 18 * 18 = r * r * t\n5832/r = r * t\nLets factorize 5832\n5832 = 27 * 27 * 8\nAnd Since 27 > 8, it can be accepted as the solution.\n\nI don't know if this is the correct way of doing it. Anyway, in my opinion worth a shot.
520825
Sorry but the model TI-83 is an outdated tool, that was used by the Aertms generation, six centuries ago.  This model could only perform 2,000 logic calculations per second.  In this age that is pathetic.  I am sorry all knowledge that is more then 2 centuries old has been deleted from my memory banks.
613944
the ti83 does have the solver program. it's under MATH and is the nhumber zero
997106
It is possible to numerically calculate integrals on an 83, but it takes the calculater some time because it literally adds up the area under the curve. You have to plot the function in the y =. Then press CALC (2nd TRACE), choose option 7, enter the lower limit, enter the upper limit. The TI-83 only does definate integrals.
955875
You need the software: TI-Connect. I think it is a free download from education.ti.com.
960662
ry +s = tx - m\nYou must leave y alone for indicate its value in terms of other variables.\n\nFirst of all you move the s to the other side or the = as shown: ry =tx- m - s (you change the sign of s)\n\nThen you move the r as follows: y=(tx-m-s)/r\n\nAnd thats it \n\nYou have a restriction because the r has to be different than 0 to avoid a division by zero.  So restriction is r different from zero.
986574
if you are using a TI-83, use the Z-Interval test funcition.\n\nManual working:\n\nSampling error = 2.06(SD/sqrt n)\n\n\nlower boundary =  20 - 2.06(3/sqrt 25) = 18.764\nupper boundary =  20 + 2.06(3/sqrt 25) = 21.236\n\n96% confidence limits is\n18.764 < mean < 21.236
1109299
I do a lot of graphics calculator programming so could give you tips if you want. In any case you could write a program on the ti-83 + or 84+ by pressing prgm right right enter typing in a name then writing the equation which can be viewed from edit. You can also store them in the GDB I think it's called by going second prgm and across to store GDB. or You can write a program\n:Clrhome\n:Output(1,1,"Your info"\n:Pause\n:Clrhome\n:Output(1,1,"More info"
816484
You need to do two things:\n1. set your window\n2. program the equations.\n\n1. At the top there's a 'Window' button.  You can set window parameters there.  However, I'd recommend using the 'Zoon' button and chosing option 6: ZStandard.  This will give you a good window.   You can change it later.\n\n2. The top left button says 'Y='.  Press this and program equation 1 then 'enter'.  This put you down one line so that you can program equation 2.\n\nTo run press the upper right hand button 'Graph'.\n\nAlso, go to the Texas Instruments website for help and to download an users manual.
744496
A row of AB is of the form RB where R is a row of A. Now, if\nR1, R2, ...Rk are linearly dependent, there are constants c1,..ck\nwhere\nc1*R1+c2*R2+..ck*Rk=0.\nNow apply B on the right to get your result.
450656
The statement is true.  The formula for the slope of the regression line is\n\nr(SDy)/SDx\n\nSince SDy and SDx are always positive, then the only thing that determines the sign of the slope is r, the correlation coefficient.  So if r is positive, then the slope is positive; if r is negative, then the slope is negative.
535506
If on a TI-83:\n1) Put the equation into Y=\n2) Click 2nd+Window (Tblset) to select the start of the table and the intervals\n3) Click 2nd+Graph (Table)
415862
R is the gas constant (= 8.31 J/mol*K).  The value should be with the list of constants in your book.\n\nOk Nic, you seem to be a bit confused on this issue so lets go back and start from scratch.\n\nFirst you obtained you values for T and K (experimentally or otherwise).  MAKE SURE YOU CONVERT YOUR TEMP VALUES TO KELVIN.  It's important for the units of the constant (R) are in Kelvin.  So then you calculate 1/T and lnK and plot the values for each set to generate your graph.\n\nYou calculate slope by taking two of your points (x1,y1) and (x2,y2).  From the data you added, let's say we'll use your first (0.002976, -3.079) and last points (0.003165, -4.225).\n\nslope= [-4.225- (-3.079)]/[0.003165-0.002976]= -6063.49 kelvin\n\nSince slope = -delta H/R\nThen -delta H = slope * R\nSo -delta H = -6063.49kelvin * 8.31 J/molkelvin\nAnd -delta H= -50387.62 J/mol\nRemoving the negatives from both sides\nDelta H= 50387.62 J/mol\n\nFor the second part of the question, use one (x,y) experimental point to find the y-intercept.  They don't want you to determine it from your plot, they want you to calculate the exact value.\n\nThe equation of a line is y=mx+b where "m" is the slope and "b" is the intercept.  So take another experimental point from readings (ie 0.003012, -3.751) and calculate the intercept by using the slope value calculated above.\n\nIf y=mx+b, then b= y-mx\nPlugging in the values\nb= -3.751 - (-6063.49kelvin * 0.003012/kelvin)\nb= -3.751 - (-18.26)\nb= 14.51\n\nTo calculate delta S for that same point (for that's what is requested), first you have to calculate delta G for that point.  Use the  following equation;\n\ndelta G = -RTlnK\n\nYou know the value for R (8.31 J/molkelvin), and you have the temp value and lnK value for that point for it was expermientally determined\n\n1/T= 0.003012/kelvin so T=332.01 kelvin\nlnK= -3.751\n\nSo delta G= -8.31 J/molkelvin * 332.01 kelvin * -3.751\nand delta G = 10349.02 J/mol\n\nYou can then calculate delta S for\nintercept = delta S/ delta G (given in your original data)\n\nTherefore delta S = intercept * delta G\nSo delta S = 14.51 * 10349.02 J/mol = 150164.28 J/mol\n\nHope this clarifies things.
168156
get a TI 82 or above graphing calculator.  MUCH easier. program already installed, just build the type of matrix,, and plug in the numbers
705232
Regression is basically trying to draw a line of best fit through a set of data to see if a (typically linear) relationship exists between the 2 variables.  A regression equation is expressed as y = mx + c where y is the independent variable, x is the dependent variable and m is the slope of the line.\n\nTo use regression in excel, highlight the data you want to use and go to Tools > Data Analysis > Regression. Try the excel help function an read up about regression analysis on wikipedia.