Pascal's principle states that any change in pressure exerted in an enclosed fluid is transmitted to...?
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Pascal's principle : Pressure applied to an enclosed fluid is transmitted undiminished to every part of the fluid, as well as to the walls of the container.  \nAn example: hydraulic lift.
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Weight of the body is always less than the weight of the liquid it displaces which is the buoyant force , if it has to float \n\nIt is the law of bouyancy ,\n\nIt states that:\n " any body completely or partially submerged in a fluid (gas or liquid) at rest is acted upon by an upward, or buoyant, force the magnitude of which is equal to the weight of the fluid displaced by the body."\n\nThe buoyant force is equal to the weight of the displaced fluid
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The well-known Bernoulli equation is obtained from conservation of momentum and energy applied to an inviscied flow. \nIts simplest form is:\n\np1/ρ + (u1)^2/2= p2/ρ + (u2)^2/2\n\nwhere,\n p1 : initial pressure\n p2 : final pressure\n u1 : initial velocity\n u2 : final velocity.\n\nAnd it implies that total energy of the flow through an stream line is constant and is exchanged between kinemaical and statical pressure.
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p1v1t1=p2v2t2\n\nSee Bernoulli's theorem and Pascals Law
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Darcy's Formula is the general equation for flow of fluids. I was going to list it here, but the notation would be too difficult to express in this format.\n\nFind a copy of the book Flow of Fluids Through Valves, Fittings, and Pipe, Technical paper No. 410 by Crane Valves North America
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In non viscous fluid mechanics, there are essetially two principle in play : 1. the Principle of Continuity 2. The Bernoulli's Principle\n\n The former states that the rate of flow of liquid is same throughout the length of a pipe etc. i.e A1 * V1 = A2 * V2 ( where A and V are the Area of Cross section and Velocity of liquid at different stages)\nThus, when u squeeze the hose the A decreases and to maintain the equation the V has to increase.\n\nThe Bernoulli's Principle relates the Energies of two different stages :\n P1 + 1/2 p*V1*V1 + p*g*H1 = P2 + 1/2 p*V2*V2 + p*g*H2\n\nWhere P,p,H are the Pressure, density and Height.\n\nSURPRISINGLY, using the above eqn, we find that when we squeeze the hose, the PRESSURE actually decreases rather than what we think logically.
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The density of the fluid and the density of the object.
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Check out the Bernoulli principle (try wikipedia).  That will explain all.
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Boyles Law PV/T I think. Anyway it has to do with the relationship of Pressure to Volume. If one increases the other decreases. Its useful in industry in making liquid Nitrogen and has endless applications in dealing with gasses in Chemisrty and Physics.
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There are many ways to do this problem.  The best way to probably handle density, and perhaps mass even, is using Archimedes principle of buoyancy.  You can find a detailed discussion on www.wikipedia.com and search for Archimedes or buoyancy.  The main idea is that "the weight of the displaced fluid is directly proportional to the volume of the displaced fluid".  \n\ngood luck!
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You better read something on this:\nhttp://en.wikipedia.org/wiki/Pressure
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Nothing. From the equation T=2pie x root(l/g). g= acceleration due to gravity. It does not have anything to do with the mass of the bob. Frequency=1/T. So nothing will change, if the water leaks out or stays in, the pendulum's frequency would be normal.\n\nT=time period
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This is true iff the pressure P1 = P2 = const.
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it is the normal force per area...\nyou can visit this site:\nhttp://en.wikipedia.org/wiki/Pressure
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Bernoulli's equation relates pressure to the speed of a moving fluid.  That's entirely different to what the question here is.\n\nThe reason things move from high pressure to low pressure is because such a pressure gradient is statistically unstable.  The principle is so simple it's studid.  Think of a fluid as being a bunch of tiny particles, flying around and banging into one another.  At high pressure, the particles are packed closely together, and they will hit eachother more frequently than they will at low pressure.  Every time two particles collide, they are driven away from one another.  So if a particle hits a particle and bounces toward a place of greater pressure, it will be statistically very likely to hit another particle again in a big hurry.  If it bounces to a place of lower pressure, it will be statistically less likely to hit another particle in a hurry.  If you sum up all of the collisions, the result is that movement up a pressure gradient is less stable--that is, it lasts a short time--than movement down a pressure gradient.  The effect of this is that on average, you end up with a net flux of particles in the direction down the pressure gradient.\n\nThis sounds absurd, but it ultimately makes the flow occur.  You have to realize that particles move very, very fast, and collisions happen with a frequency we can barely imagine.  So imagine you're an air molecule in a soda can that's been shaken.  There's so much pressure, that any way you go, you hit another molecule almost instantly.  Suddenly the top is opened.  Those molecule that are closest to the opnening are at an extreme point in the pressure gradient: below them are crowded molecules, and above them are the more rarified atmospheric air molecules.  They bump about at random.  But if they're bumped down into the can, they go little distance before being bounced back.  If they're bumped up, they go much further before hitting another molecule.  This means that in the vacinity of the opening, the pressure is reduced, and there are less molecules in that area.  Now the pressure gradient has propagated into the can.  Those areas adjacent to that area near the opnening now experience the same effect--being bumped away from the openeing meets it with a quick collision, while being bumped toward the opening makes it able to travel further before hitting another molecule, because so many have left the can that the area near the opening is much less crowded.  This keeps happeneing until the pressure inside and outside the can is the same, due to a net flux of molecules out of the can, and it happens really, really fast.\n\n\nConservation of momentum also makes it so that in an elastic collision, the net momentum of the collision before and after a collision is unchanged.  So for fluid in a pipe, that means most collisions will keep everything going down the pressure gradient.
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Boyle's Law states that the product of the volume and pressure of a fixed quantity of an ideal gas is constant, given constant temperature.  Mathematically, PV = K, where K is a constant.  So, if the volume or the pressure is changed, the other changes accrodingly.  For example, let's assume the volume of gas is V1 and the pressure is P1.  If we change the pressure to P2, the volume will change to a new volume (V2) such that P1V1 = P2V2
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P/T=P/T\n1/(20+273)=P/(600+273)\nP=30 atm\n\nThe new pressure would be 30 atms, but this is considering that the volume remains constant.