What could be an equation for the points (2, -4 ): ( 11, -4 ) in slope-intercept form?
97021
Using the points you can work out the slope. That is 0.\nThen use one set of points and the slope to work out the equation of a line formula which is:   \n         y-y1=m(x-x1)\nm is the slope \n       y+4=0(x-11)\n       y+4=0\n       y=-4
907088
The slope is 1/3 and the point is (-2, -4).
892026
The slope intercept form is y=mx+b\n\nSo we rewrite the equation of the line as so:\n\nx - 2y = 5  , subtract x from both sides\nx - x -2y = 5 - x\n-2y = 5 - x  , now divide both sides by -2\n-2y/-2 = (5 -x)/-2\ny = -5/2 + x/2  , rearrange the left side\ny = x/2 - 5/2\n\nSo the slope (m) is 1/2.  Now we use the point given and the general equation.  From the point we know that x=2 and y=-4.  Sustitute these into the general equation.\n\ny = mx +b\n-4 = (1/2)2 + b  , do the math\n-4 = 2 + b ,subtract 2 from both sides\n-4 - 2 = 2 - 2 +b\n-6 = b\n\nSo the equation of the required line is:\n\ny = x/2 - 6
875002
slope is a fraction found by subtracting the two y-coordinates and putting this on top, then subtracting the two x-coordinates (in the same order as you did for y) and putting this on bottom.  So, either\n\n(4-2)/(1- -6) = 2/7\n\nor\n\n(2-4)/(-6 - 1) = -2/-7 which is also 2/7 since a negative divided by a negative is positive
806897
First equation:\n4x + 2y = 10\n\nRearrange to get the y-term alone:\n2y = 10 - 4x\n\nDivide both sides by 2 to get it in slope-intercept form (y = mx + b):\ny = -2x + 5\n\nNow you can graph it by drawing a line through (0,5) as the y-intercept and have it go down at a slope of -2 through points (1,3), (2,1), (3,-1), etc.\n\nFor the second equation, draw a horizontal line for y = 4\n\nYou'll see they intersect at the point (½, 4).  I've attached a graph of the two lines...\n\nSo your solution is:\nx = 0.5 (or ½)\ny = 4
1163751
If you are given the slope(m) and a point on the line(x1, y1) you can write the equation of the line.\n\nYou take the y-intercept equation\ny =m*x + b and substitute x1 and y1 for x and y and get\ny1 = m*x1 + b    \nnow solve for b\nb = (y1-m*x1)\nsubstite b = (y1-m*x1) into the y-intercept equation\ny =m*x +(y1-m*x1)\nsubtract y1 from both sides of the equation\ny -y1 = m*x -m*x1\nbecomes the point-slope formula\ny -y1 =m*(x-x1)
910261
Slope = m\n= y2-y1&#92;x2-x1 \n= -4-6/-3-2\n = -10&#92;-5\n=2\n\nnote: / means divided by\n\nthe slope of y= 2&#92;3x-4 is 2&#92;3
124756
slope intercept formula is y=mx +b to find b subsitute in for y,m, and x.  so 1 = -2(0) + b.   1 = 0 + b so b = 1 then your equation would be y=-2x + 1.
359675
y-intercept occurs when x=0\n\nSo, set x=0, and your equation becomes:\n    2(0) - y = 4\n\nor, because 2*0 = 0,\n    \n    y = -4 is your y-intercept.\n\nThe slope can be found by writing the equation in standard "y = mx + b" form, where "m" is the slope. In your example, that would be:\n\n    y = 2x - 4\n\nSo, the slope ("m") is 2.\n\nDone and done.
101123
(3, -3)\n\n-3 ?>= -2(3) + 5\n-3 ?>= -6 + 5\n-3 ?>= -1 (not true)\n\nIf you don't want to "plug and chug" all the points individually into the equation, you could draw up a graph and plot each point, and then draw the line for the equation. The solution set for the equation will be the shaded area to the right of the line, including the line itself.
1088418
Equation/Formula for Point slope equation is y = mx + b wherein b is the y intercept and m is the slope.\n\n1. y intercept = -3\n    slope = 4\n\n2. y intercept = 4\n    slope = -3\n\n3. y intercept = 0\n    slope = 3\n\n4. you must simplify this one. The solution is:\n\n(step by step)\n\nIsolate the y     4/5y = -1/2x + 1\ncancel the fraction beside y  (5/4)4/5y = -1/2x(5/4) + 1 (5/4)\nand then it becomes    y = -5/8x + 1 1/4\n\nso then the y intercept is = 1 1/4 (--one and one over four)\nand the slope is = -5/8\n\n*when looking for the slope, do not inclued the variable "x" in your answer :)\n\nI hope this helped :)
737993
equation of line through (4,3) and (2,4) is 2y=-x+10
389930
Write the equation in the point-slope form, then substitute 0 for x and solve for y.  That is the y-intercept.
746991
the slope is 4\nwhen an equation is in standard form:\ny=mx+b\nm (which is the coefficient of x) is the slope
533058
Point slope form:\n\ny-(-3)=(1/2)(x-5)
829794
The standard equation for slope-intercept form is y=mx+b. m is the slope and b is the y-coordinate of the vertical (y) intercept\n\n-2x=y+3       Original equation\n\ny=-2x-3        Rewritten in S-I form\n\nm= -2, b= -3\n\nThis means that the graph of the funtion is a line through the y-axis at the point (0, -3) with a slope of (-2)
730934
First you have to find the equation of the line that contains these two points (9,1) and (5,5)\nI believe the easiest way to do that is to use slope and y-intercept form (y=mx+b) m= slope and b= y-intercept\n\nto find slope, m = rise/run\nrise = -4\nrun = 4\nrise / run = -1\n\nTo find y-intercept plug in a coordinate pair and use are found slope.( i used 5,5)\ny=mx+b  x= 5 y=5 m=-1 b =?\n5=(-1)(5) +b\n10 = b\n\nSo this is our equation of the two points\ny=-x +10 \n\nNow we can use this equation to find whether  (10,0) is on  the line: Substitute (10,0) and see if the equation is still valid\n\n 0 = (-1)(10) + 10\n 0 = 0 Yes (10,0) is on the same line as the other points