Two workers push horizontally on a refrigerator. One pushes due north with a force of 112 N and the other push
89777
nearest Newton?...haha...moron\nI don't have a neighbor by that name.\nYou should have said 'the nearest unit'.\nAnyway, 183 is what you need.\nI mean this is the magnitude.\nAnd the guy who has spoken a lot on this subject should have noticed that a rounded answer is needed and not a nutty professor lecture.
449872
The both weigh the same
152263
A is on the x-axis (horizontally), while B is on y-axis (vertically).
701968
it is ups they are hotter
904985
They wear Ziploc freezer bags on their feet. You should put one over your head and slowly count backwards from 10.
777818
Magnitude of net force would be sqrt(2) times magnitude of F  and it will act along a line bisecting the angle between AB and CB produced. [ By Parallelogram law of forces]
690572
against the direction of travel.
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The maximum possible net force is 125N, if the two forces are pushing in the exact same direction.\n\nForce is a vector quantity, which means that any measurement of force includes both a magnitude (size, the number) and a direction (the way that the force is pushing).  The simplest way to indicate direction is with a positive or negative sign, which only gives us two options: left/right, forward/backward, up/down, etc.\n\nIn your question, no direction is specified for either of the forces, but we can figure out the minimum and maximum possible net force rather easily.  The minimum net force would result when the two forces are pushing directly against one another:  100 -25 = 75N (toward the direction that the 100N was pushing).  Similarly, the maximum net force would result when the two forces are pushing together in the same direction:  100 +25 = 125N.\n\nIn general, then, the maximum possible net force (in cases where you are not given directions with the forces) can be found by adding the magnitudes of the forces together, as if they were all pushing in the same direction.
112424
the person to the left has the right a way
898114
there are two...lb  & pd
1093836
Centrifugal force and gravity.
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the particles move faster.
894578
Don't add the two. Only the vertical distance counts in determining work because only in lifting the block did you move it against the force of gravity.
948754
we juss need to take vector sum of the two forces. assuming the wind is directly in horizontal direction....... sqrt(9.25sq+1.05sq)=9.3N
760426
Figure out the centripetal force.  After that, this becomes a sliding problem turned on its side.
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a. Calculate the horizontal component of the 485 N.\nFh = 485 N*cos35\nCalculate the force of friction.\nFf = 0.57*319 N\nCalculate the net force.\nFn = Fh-Ff\nCalculate the mass of the box.\nW = m*g\nCalculate the acceleration.\nFn = m*a\nCalculate time to move s = 4.00 meters\ns = (1/2)*a*t^2\n\nb. Repeat with uk = 0.75
935603
The net force is F2 - F1 = 25 - 19 = 6N.\n\nFrom F = ma, a = F/m = 6/5 = 1.2 m/s^2, toward the west because F2 > F1.  Also, we're ignoring friction.