If you were gripping a bar and it unexpectedly yanked away at 100 mph, would you lose your arm, or your grip?
91176
I think it all depends on how good a grip you've got. I can see that happening, under the right circumstances...\n\nHEY! Mythbusters...
701082
If you are travelling fast I would think the signal would be completely disrupted...:D
487674
Arm bar, because it is so effective!!
1072001
I guess not, if he broke his arm. Otherwise his elbow would have touched too and the elbow is considered down (try it).  That, and  if the someone he spun off of was the opponent anyway unless you're talking college rules.\n\nPS who are those other donuts.  Both knees?  Shoulders?  Ball and knee?
990799
the most logical answer:\n10 minus the number of finger you're not holding up!
1044401
He will continue to fall.  This boils down to the idea of a net external force - in this case only gravity and drag play big roles.\n\nIf if pulls on his collar, his collar exerts an equal and opposite force on his hands.  His hands and arms transmit this force to the rest of his mass.  So...the net force he applies to his body is zero.
345146
i broke my right arm twice. once falling off the banister. the second time i was jumping off the couch playing superman..LOL thats true.
897343
are you for real??? I'm just curious how old are you???? want to test your biceps try doing a 1-armed chin up....and yes it can be done.....oh and by 1-arm i mean only one hand is pulling...not one hand on the bar and one around the other ones wrist
320925
I was driving in a car with my friend who was drunk and I knew he was driving to fast and that we would not have time to stop at a stop sign. He went right through the stop sign and we hit a tree straight on at about 50 mph. What was scary is that I saw this coming for at least 5 seconds.\nWe fortunately came out of this with only bruises and cuts.
819706
Depends entirely on how they got the wind knocked out of them. A fall onto the back or other impact of that sort, yes it would since the air was simply blasted from the lungs by impact pressures. If the person was punched in the pit of the stomach, no it really wouldn't do much since the person stops breathing due to temporary paralysis of the diaphragm from impact on the solar nerve plexus. If the loss of breath is from a punch in the stomach, mouth to mouth may be necessary if the persons body takes too long to regain control of the diaphragm, to prevent damage from oxygen deprivation. Normally though, the diaphragm regains controlled mobility within seconds. I hope this answer helped you.
517093
No, as the force (100 mph) would make your eyes pop out, also you should let your sneeze out and not keep it quiet as the pressure can do damage, burst blood vessels etc
909593
Yes.\n\nTo obtain my taser certification so I could carry one for my department.\n\nIt hurt like hell for five seconds, then it was gone. I was immediately able to move and function again, but the memory doesn't fade quite as fast.
697168
The faster an object (in this case your arm) is moving, the more mass in the direction it's travelling it has.\n\nYou have to overcome the inertia (tendancy to stay in place in this case) holding the paper sheets to each other.  If you pull the roll slowly the paper doesn't tear and instead pulls out more paper; however, if you snap it quick the paper'll break off for you.  In other words: you produce more inertia in another direction than the paper can resist.\n\nA martial artist puts lots of power behind the motion, therefore building up enough inertia to break the board.  Olympic weightlifters do it too: rather than moving slowly to lift the weight and therefore wasting energy, they instead lift it as quickly as possible, putting all the energy they can into the lift.
803571
For the first question: momentum is equal to mass times velocity, therefore; if the motorcycle has a higher velocity then its momentum would be equal. Keep in mind the momentum could only be the same if the velocity of the motorcycle is greater than the velocity of the car by the same factor that the mass of the car is greater than the mass of the motorcycle. \n\nex.  car: \nm=1200 kg\nv= 20 m/s\n\nmotorcycle: \nm= 400 kg                             \nv= 60 m/s\n\np= momentum\np(car)= 24000 kg x m/s\np(motorcycle)= 24000 kg x m/s\n\nFor your second question I would have to guess that if you spin the sack in a centripetal motion and stopped it at a certain point, the tangential velocity would propel you in the desired direction. Think about a fast pitch softball throw using the sack without letting go. In this case the radial acceleration would be conserved as linear acceleration which would propel you in whichever way you want to go.
250759
Remember, momentum is affected by mass.  The fly's mass makes it easier to dissipate the inertia.  So it seems that the fly could crash into the front, but not likely. Of course, most people are worrying about other things at the time, so no specific measurements have been taken!  The air inside has mass also, so in effect the car and the air mass have become one unit, in which the fly is also a small part.  When it stops, it helps everything else stop.
312216
How about pretty much all of the bones in my right hand?   \n\nYears ago I was changing a flat tire on my International Truck out in the parking lot where I worked.  A buncha guys were talking to me as I was doing it.  When I was putting the new tire on, my right hand was on the top of the tire, right below the wheel well...and then the jack slipped and the truck came down crushing my hand between the tire and the truck.\n\nI don't think I've ever cursed as much in my whole life, and thank god those guys were there because they were able to lift the truck up enough to get my hand out and take me to the hospital.
904552
Both balls would hit the rocks at the same speed.\nBall #1 would leave your hand travelling straight up at speed 'u'. It travels up, stops, and starts plummeting back to earth. When it reaches the height at which it left your hand, it is travelling at speed 'u' straight down. The speed that it hits the rocks at is u+(time x 10m/s/s).\n\nBall #2 would leave your hand travelling straight down at speed 'u'. The speed that it hits the rocks at is u+(time x 10m/s/s). It is the same speed.