need to know the dimensions for a bar top. HxWxD? overhang?
82961
I built a brick bar with a tile top its 42 inches high x27 inches deep my width is 6 feet with an octagonal end. Stools are 30 inches, a 6 inch overhang works good for me.
1009332
Convert everything to inches, then multiply.  LxHxW.  They need to be the same units, though.
487976
You are better off with no tools bars.  I never use any.  Get rid of them all.
185422
First go to the instruction sheet that came with your rack. Get the correct measurements(important!), take a tape measure and mark those points, 2nd measure your load bars length, 3rd measure the points mark M1,M2,M3 this give you the correct fitting to the roof. Last place the mounts up and turn the screws for tightness. And don't forget to install the lock units because YOU NEED LOCKS on the rack for safety and security. As a owner of a Q Tower System one last thing after it's up and on pull on the clips with the doors closed. If they move, retighten the screws. \nP.S. What are you carrying on the roof because some roofs have a load limit.
308904
I would say that if you got some 2x4's ... measured it a bit bigger then the tub .. double them up ..... tack down a leather piece over it and that might work lol .. good luck :)
689785
Have you tried this database. It's certified by ebay\n\nhttp://www.getyourebook.com/wwbstartright
311553
contact a supplier, they will give you all the specs you need.\nno one is going to type out 4 pages of stuff here for you.\nFittings is not a very specific question.
105685
1 bar =  1x10^5 Pa and 1 atm = 101325 Pa\ntherefore 1 bar = 0.987 atm\n\n_______\nOK, got it.  Just for future reference, you can clarify a question using the "add details" button in the stick note in the top right rather than posting it as the answer to a different question :)\n\nWith a signficant increase in height, water pressure will change signficantly.  Basically, that extra 33-foot column of water weighs quite a bit and is pushing down on things under it.\n\nThe density of water is 1 g/cm^3 = 0.001 kg/cm^3.  33 feet = approx. 1,000 cm.  A 1,000 cm high column of water with one cm^2 cross-secional area would weigh about 1kg, adding 1kg/cm^2.  1kg/cm^2 = 1.097 bar.  So being three stories up would add just about 1 bar of water pressure.\n\nI'm not sure how these water tank assemblies work, but it seems to me that if you put the tank three stories up and didn't pressurize it you would have about 1 bar of water pressure at the bottom.  If you pressurized the tank so you had 1 bar of water pressure at the top, you'd have 2 bars down where your dishwasher is.
162809
Support.dell.com has diagrams of the components, but they will not give you the design plans (which is what I think you are looking for)
474599
5.5 inches. Measure along the top.
1020997
Hahahahaha, thats a good question.  Stick them all together so that you have another full bar.
1046488
length x width (in inches)\n\ndivide by 12 ( feet)
191692
i dont know if this will help u :- http://www.jacketshop.com/jackethome2.html
205825
Try this database\nhttp://www.getyourebook.com/wwbstartright
211197
ofcourse there is!!\ncheck the toolbox and the system.windows.dll packages for it.I think you can find it easily in the toolbox itself.\n\nIf you find horizontal bar then see its properties too.\n\nHope this will work :)
404909
http://www.x-tremegeek.com/templates/searchproducts.asp?categoryID=148
714452
This trick should work.\n\nTurn off your Taskbar's Auto-hide feature, if enabled, and then maximise the problem window. While the window is maximised, increase the height of the Taskbar from one row to two. Allow the maximised window to reset itself to fit into the new area allowed by the taller Taskbar. Now return the Taskbar to its normal single row. This is to try to make Windows re-calculate the window size and boundaries.\n\nIf no joy, run regedit and remove these registry key values which are most likely corrupted:\n\nHKCU&#92;Software&#92;Microsoft&#92;Internet Explorer&#92;Main&#92;\nwindow_placement\n\nHKCU&#92;Software&#92;Microsoft&#92;Internet Explorer&#92;Desktop&#92;\nOldWorkAreas&#92;OldWorkAreaRects\n\nThen reboot.\n\nNote - there is a known bug that causes off-centre windows - check out the following KB article:\n\nhttp://support.microsoft.com?scid=kb;EN-US;Q321268