Quiz question concerning a type of puzzle. How is this possible???
85821
doctor j long was doctor m longs mother
902207
I'm assuming you are referring to the disguised triangles in the attached link... (link 1).  I'm sure there are some rigorous mathematical proofs you could supply, or automated ways to count the triangles, but I basically decided to just use the "brute force" method of counting.  The hard part is recognizing all the different triangles while not double counting...\n\nWhat I finally did was to create several copies of the diagram and tried to color the triangles.  You can color the individual triangles (24), right off the bat.  Now if you try to pair up triangles, you can pair them one way (12) or another using the flipped image (12).  Grouping them further in groups of three or four triangles, I counted another set of (7) and the flip for another (7).  Then I noticed four other ways to group four triangles (3), (3), (3), (3).  Lastly, there are two large triangles composed of the inner sixteen triangles (1) and (1).\n\nAltogether I got seventy (76) triangles.  You can double check my work using the attached image (link 2).  I think I got them all and didn't double count...
831281
Alrighty! This one has been floating around for a very long time and this is the Third instance of the same riddle i've seen. I will cover it accordingly and supply the Answer so bare with me\n\nThe Riddle!\nCorrect Version....\nIn all instances of this riddle you notice that the title states "Find the Error" , Or "Find The Error For Me", or "Can you find The Error".  The Title is the KEY.. Notice how it just ask you to "Find The Error" it does NOT however state "What" kind of Error.. This is pretty much the meat and potatoes of the Trick Question..\n\nIncorrect Versions...\nNow there are some instances that actualy go as far as to say " Find the Error in The Alphabet". These titles are incorrect and defeat the purpose of the Riddle.. Fact of the matter is There IS NO ERROR in the Alphabet, or should NOT be.. But since the title was posted wrong, this confuses the Readers to the REAL problem and answer..\nSome have even "Intentionaly" distorted the alphabet by adding a "0" into the mix instead of the "O". Now this is tricky, yes, but once again. Incorrect, and defeats the purpose of "Misdirection"\n\nAlso another mistake people make is they "Repost" The riddle by hand INSTEAD of just copyiing and pasting it  the way they should. So it gets distorted as it moves on. This case is NO exception. The mistake made in this instance is with the sentence \n"find the error. it's impossible" <- this is the incorrect version\nit should be\n"find the error. its impossible"<-This is the Correct version \nNotice how in the "Correct Version" of the Riddle, I Intentionaly Neglected the Apostrophe between the "t" and "s" :) That is because THIS is the Error the reader is supposed to find. It's a grammatical Error NOT an Alphabetical.\n\nThe Answer!\nThe Error Is Not In The Alphabet\nNow since we know what the Real Version Is, let's cover the Answer.  As said.. the Title is a "Trick" Question.. when stated correctly, the Reader "Assumes" that the error WANTED is in the Alphabet , even though it was not Directly Stated, so you search the entire Alphabet for Anything that could be possibly seen as "Wrong" but this is intentional  Miss direction..\n\nThe Error SHOULD be in the actual question ABOVE the alphabet list .\n\n"find the error. its impossible" \n\nNotice how in "Its impossible", there is no apostrophe between the "t" and "s".. At least when this riddle is posted "Correctly", there should be "NO Apostrophe"..\nThe absences of the apostrophe is the "Error" of which the reader is supposed to find..\nConclusion..\nWhen you repost this riddle be sure you just have the title read "Find The Error" and try not to convert it in any way.\nAlso never try to retype the riddle by hand unless you KNOW exactly how it's stated. People already tend to make grammatical errors when typing as is and others tend to make NO mistakes whatsoever , either way , this this distorts the Riddle...
884867
is this a trick question ?
51168
actually,the first clue was turtle.  The second was balloon.  if you know the third  1/18, PLEASE share with me!!!  much appreciated!!  twister_51@yahoo.com
599437
It is a major puzzle, no one is quite sure. See the attached article for more details...
357332
Is this trick question?
732432
I'm assuming you mean *only* the four common operators; as this is a very well known puzzle (called the 24 game, or something similar).\nIn that case, its actually impossible (I have written a computer program to prove this for me). Of course, its possible if you allow various other things like ! or ^, but not with just +-/*.
1459
Just randomly enter numbers according to the rules of the puzzle, but using a blank grid. Start with one or two per 9-square block. To make the puzzle difficult, only enter a few numbers, and add more to make it easier.\n\nIt should be quite simple for a computer program to make a Sudoku puzzle, since there are basic rules to follow. I'm sure the "made by hand" claim is for marketing purposes (though I'm sure it's true).
900433
Discounting rotations and mirror images, there is only one way to make a magic square using the digits 1 through 9.  \n\nFirst, we can prove the 5 has to go in the middle:\n\nLet the numbers in the top row from left to right be a, b, and c.  Let the numbers in the middle row from left to right be d, e, and f.  (Note e is the middle box.)  Let the numbers in the bottom row from left to right be g, h, and i.     \n\nWe know a + b + c = 15 and g + h + i = 15\n\nWe also know a + e + i = 15, b + e + h = 15, and c + e + g =15.  Therefore, (a + e + i) + (b + e + h) + (c + e + g) = 15 * 3 = 45.  We can rearrange this to (a + b + c) + (g + h + i) + 3e = 45.  Since a + b + c = 15 and g + h + i = 15, that reduces to 15 + 15 + 3e = 45, or 3e = 15.  Therefore e (the middle box) must equal 5.   \n\nKnowing the middle box is 5, try 9 in a corner and you'll notice a problem - the 6, 7 and 8 can't all be placed in the square without the row or column with the 9 exceeding 15.  So, the 9 has to occupy a side box.  Since we are discounting rotations and mirror images, we can arbitrarily select box b for the 9.  This forces the placement of the 1 in box h.   \n\nWith the 9 and 1 now placed, the 8 and 6 have to go in the row with the 1.  So, we'll put the 8 in box g and the 6 in box i.  (We still haven't done anything to create a second square if rotations and mirror images are discounted.)  That forces the placement of the final four numbers.
924929
Nothing's hidden inside, but it's an ambigram.  Print it out and turn it 90 degrees and see what happens; then 90 more, then 90 more.  You will see something cool.
840342
What type of question is this?
942547
Can you please check you haven't made a mistake somewhere? I have just calculated (with 99% certainty) that there are no solutions to those equations with those restrictions.\n\nEdit - OK, I assumed you made exactly one mistake. By removing each possible word and trying to solve it, I discovered that removing 'SIGH' was the only option that gave an answer.\nt 1\nh 8\na 3\nn 7\nk 6\ns 5\ng 9\ni 4\nv 2\nwhere SIGH = 26, not 25. Then THANKSGIVING = 65.\n\nThat was actually a cooler puzzle that the original, assuming you made one mistake :)
225658
You may have miss-typed the riddle!\nThe question should be:\n8 _ 4 9 1 _ _ 10 3 2 0\nIf that is the case then the answer is:\n8 5 4 9 1 7 6 10 3 2 0\n\nReason: This list of numbers is in alphabetical order
780250
what type of question is this? and how is it equal to 34(why didnt adam explain this).
1112310
:o\nis this a tricky joke?lmao->
1095484
all alphabets -1 = congratstogettoroundthreeenterroundthree\ncongrats to get to round three enter round three??? juz thought of it makes some sense doesn't it?\nif u got this from some riddle site tell me about it too pls i really like this sort of stuff >.<