how do you find the area of a trapizoid?
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It's easy\n\nYou can use the formula A=(b1+b2)h/2 wherein 1 and 2 are subscripts.\nA=area of trapezoid\nb1=1st base or top base\nb2=2nd base or bottom base\nh=height or altitude. Altitude is the line segment from b1 that is perpendicular to b2.
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to find areas of parallelograms use the formula: \n\nA = base×height.
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To calculate perimeter of trapezoid you need to know the dimension of each side of trapeziod..\nthen.. sum of sides give you perimeter.
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well you could split up the thing into triangles. you know what the base is (1m) and the height is unknown, so lets call it h for now. so for each side, the area of the triangle is h/2 (bh/2 and b=1 so h/2). so for every 2 sides, the area is h. so the total area is 18h. \n\nso to find h, you have to use some trig. the equation to find the internal angles is (n-2)*180/n. cuz the sum of the internal angles is (n-2)*180. and then to find each angle, you have to divide by number of angles (which is same as number of sides). so in this case 34*180/36 = 170 degrees each angle. so now for each side, if you make a triangle with the center of the polygon, u should notice that the triangle is isosceles and the base angle is half of the side angle. \nas in the bottom 2 angles are equal and they are equal to 170/2. which is um 85. you can try this with any polygon if you dont believe it. try a square, (n-2)*180 = 2*180 = 360 is the sum of the internal angles. so each angle is 360/4 = 90 degrees. so if u connect each vertex to the center of the circle, you get 4 isosceles triangles and the base angles are 45 degrees each. \nso you have 85 degrees as the angle. so now if you split the isosceles triangle into 2 right angle triangles, you have 3 sides in each right angle triangle: the h, 0.5m and the line from the vertex to center. so you have the angle 85 degrees and you need h and you have the adjacent side = 0.5m. so you can use tan 85 = h/0.5 and you get h. \nso the total area is 18h. \n\ni really hope you understand that. its kinda hard to explain without drawing it out and showing you. if you need more help, then message me or somethin. later
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This is a lot to ask here. Why dont you look it up? \n\nAnd a lot of these are easy to figure out. \n\nSphere surface area is A=4 *pi *R^2 where R is the radius\n\nbecause A={int 0 to 2 pi} {int 0 t0 pi} R^2 sin(a)dadb\n\n\nThe cube surface area is A=6*S^2, where S is the length of an edge because there are 6 sides, each of area A^2.\n\nThe cylinder surface area A=2*pi*(R^2)+2*pi*R*H, where R is radius and H is height, because it has two circular end caps of area pi*(R^2) and a side of dimensions 2*pi*R by H, when it is unrolled. \n\nCone surface areas can be found the same way. Just unroll the side, and you get a triangle with height sqrt(H^2+R^2) and base 2*pi*R. The area of a triangle is .5*base*height. Then add in the area of the round bottom. \n\nAnd so on. I am sure you can do this yourself.
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Reviewing the facts:\n\n1.  You're constructing a pentagon and two trapezoids by using the center of the square.  Since the sides are 1, the short parallel side of the trapezoid is 1/2.\n\n2.  Since the two trapezoids are congruent, the short parallel side is midway in the square.  So the height of each trapezoid is 1/2.\n\n3.  Since there are three areas now, and each area is equal, the area of the trapezoid is 1/3.\n\nThe area of a trapezoid is A = (1/2)h(b1 + b2).  We have everything we need now to solve for b2, the longer parallel side:\n\nA = (1/2)h(b1 + b2)\n1/3 = (1/2)(1/2)(1/2 + b2)\n1/3 = (1/4)(1/2 + b2)\n4/3 = (1/2 + b2)\nb2 = 5/6
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Cylinder: (pi)*(radius^2)*(height)\nPrism: (area of the base)*(height)
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Trapezoidal Rule : area occupied by given curve,y=f(x),\nbetween limits (a,b),divided into various values,x0,x1,x2,...xn,for which corresponding values are y0,y1,y2,y3....yn=f(xn).\n\nHence area =A=integration(y)=integration(f(x))\n\nA=Integration between a and b(f(x))\n\nA=(h/2)[(y0+yn)+2(y1+y2+....yn-1)]\nwhere h=(b-a)/n
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Area of a trapezoid = 1/2 Height (Base1 + Base 2)\n224 sqm = 1/2 (16)(20 + x)\nmultiply both sides of the equation by 2 to remove fractions\n448 = 16 (20 + x)\n448 = 320 + 16x\ncombine\n16x = 128\nx = 8 m
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Consider a regular n-gon in a circle of radius r with side length l\nDraw in all radii from vertices to centre.\nThis forms n isosceles triangles with the sides of the n-gon as their bases\n\nThen angle at centre = 360/n° and each angle at base = (90 - 180/n)°\n\nBy sine rule: sin(90 - 180/n)° /r = sin(360/n)° / l \nWhence l = r * sin(360/n)°/ sin(90 - 180/n)°\n= r * sin(2 * 180/n)°/ cos(180/n)°\n= r * 2 sin(180/n)°cos(180/n)°/cos(180/n)°\n=2rsin(180/n)°\n\nSo the perimeter of the polygon is 2nrsin(180/n)°\n\nNote: As n →∞ Perimeter  → circumference of circle\nie lim  n →∞ 2nrsin(180/n)° = 2πr\nSo lim  n →∞ nsin(180/n)° = π\nOr for large n, sin(180/n)° ≈ π/n; which makes sense given that for small x (in radians) sinx ≈ x\n\nGiven area of a triangle = ½absinC\nthen area of 1 isosceles triangle = ½r²sin(360/n)°\nSo the area of the polygon is ½nr²sin(360/n)°\n\nThus for n = 9 and r = 10;\nl = 2rsin(180/n)° \n= 20 sin 20°\n≈ 6.84 in
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Take the formula for the surface area(S) and solve for r\nS=4*pi*r^2\nr^2 = S/(4pi)\nr =squareroot(S/4pi) or (S/4pi)^(1/2)\n\nNow take the formula for the volume\n4/3*pi*r^3\nand substitute the formula for r into the equation\n4/3*pi*(squareroot(S/4pi))^3\n4/3*pi(S/4pi)^(3/2)
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volume of cyllinder = area of circle times height\n\n= Pi x radius x radius  x height\n\nremember its just the same as finding the volume of any prism.\nfind the area of the shape of the end then multiply by its length!!
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area = r^2 * pi\narea = 9.8^2 * 3.1415\narea = 96.04 * 3.1415\narea is about 301.71
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Area can be calculated by using the formula Area = 4 Pir^2 .  You didn't mention radius of the tank, thus a numerical answer is impossible.
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The surface area of any prism equals the sum of the areas of its faces, which include the floor, roof and walls. Because the floor and the roof of a prism have the same shape, the surface area can always be found as follows:\ncall the 'floor' the 'base'. The height of the prism = 'H'.\nThe surface area of a prism = 2 × area of base  +  perimeter of base × H\n\nexamples:\n\nRectangular based prism:\nBase shape: Rectangle, length 'L' and width 'W'\nArea of base: L  × W\nPerimeter of base: 2(L+W)\nSurface area = 2LW + 2(L+W)H\n \nCircular based prism\nBase shape: Circle, radius 'R'\nArea of base: pR²\nPerimeter of base: 2pR\nSurface area = 2pR² + 2pRH\n\nTriangular based prism\nBase shape: Triangle: base 'b', height 'h', and sides S1, S2 and S3 \nArea of base: ½b×h\nPerimeter of base: S1+ S2 + S3\nSurface area = bh + (S1+ S2 + S3)H\n\nAs for lateral area of a cone , If r is the radius of the base, h is the altitude, and l is the length between the vertex and a point on the base circle \nlateral area pi rl=pi r x sq.root of r to the power 2 + sq.root of h to the power of 2\n or try this site- http://www.mathepower.com\n\nThe lateral area of a prism is the sum of the areas of the lateral faces (all the ... How many lateral faces does this prism have?\nWhat is the area of each \n\nelse there are many sites to giv better details matching ur specific figure ...try google for search..all luck..
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the volume of a trapezoid-shaped box is the height of the box times the area of the trapezoid.\nwhere H is the height of the box, and h is the height of the trapezoid with bases b and B,\nV=1/2*(b+B)*h*H
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Area = Pi times the radius squared (A=pr2)\nIf you need to know how to find the radius, go here:\n\nhttp://math.about.com/library/blcircle.htm