Write  5xsquared y negative 6 exponent  using positive exponents?
97164
5 x squared would just be 5x^2\n\nx^-2  =  1/x^2\n\nSo, y negative 6 exponent  =  1/y^6
329438
log_5(X) + log_5(x-1)=log_5(6)\nlog_5(x(x-1)) = log_5(6)\nx(x-1) = 6\nx^2 - x - 6 = 0\n(x-3)(x+2) = 0\nx = 3 or x = -2\nYou cannot take the log of a negative number, so -2 cannot be a solution.\nAnswer: x=3\nFor the second part, find T(30) and T(75)\nT(30) = 70 + 100e^(-0.04(30))\n= 70 + 100(.3012)\n= 70 + 30.12\n= 100.12\n\nT(75) = 70 + 100e^(-.04(75))\n= 70 + 100(.0498)\n= 70 + 4.98\n= 74.98
765513
do u mean 6x^2(-9x^3) = -54x^5\nmultiply the constants and add the exponents
1155015
Original:\n13 + (-12) - (-5)\n\nSubtracting the negative (-5), reverse the signs and add\n13 + (-12) + 5\n\nNow just go left to right:\n13 - 12 + 5\n(13 - 12) + 5\n1 + 5\n6\n\nThe answer is 6
685997
u should write it like\n7.52*10^-4
1149797
The first one is (-5, 3). I don't remember how to do the others.
664485
nope \n5x+5y\n\nthe 4y and -4y cancel each other out
1099598
If you mean an exponent, the function in C is pow(x,y)
771896
expand x^2-6x+9 = 5\nor x^2-6x+4 =0
814830
HI!\nFor the first: 5 times six equals 30.\n\nSecond: x to the yth power.\n\nWhen in doubt...don't be afraid to ask! :) :)
204862
Write in descending order:\n2x^4 - 6x^3 + 4x - 1\nCount the number of sign changes\nThe signs go from plus to minus to plus to minus.  Thus, there are 3 sign changes, so there will be 3 or 1 positive zeros.\n(I got the 1 because you keep subtracting 2 until you get to 0 or 1.  Say there were 6 sign changes, then there could be 6, 4, 2, or 0 zeros)\n\nFor negative zeros, replace x with negative x and then count the sign changes.\n2(-x)^4 - 6(-x)^3 + 4(-x) - 1\n= 2x^4 + 6x^3 - 4x - 1\nThe signs go plus to plus to minus to minus.  Thus there will be 1 negative zero.
899014
an expression of the form x^-n can be written as \n    1\n_____\n \n   x^n\n\nwhere ^ implies raised to the power of\n\nSo first square the expression you have given. this gives\n\n  4 x^6 y^-6\n__________\n    \n    9 a^12\n\n\ntake reciprocal of this\n\n      9 a^12\n___________\n\n   4 x^6 y^-6\n\nThis is your answer
930900
(6x^) * (x^ +x -12) / (4x^y -12xy) * (3x^ +12x)\n\nif you mean ^ as   x^2 or    x squared\n\n(the number after ^ represents exponent ie. 2x^2 is= 2x squared\n\nthen the answer should be\n\n6x^4 +6x^3 -72x^2 / 12x^4y + 48 x^3y -36x^3y - 144x^2y\n\n2x^2  (3x^2 +3x -36)  /  12x^2y  (x^2 +x -12)\n\n2x^2  (3x  +12) (x -3)  /  12x^2y  (x +4) (x -3)\n\n2x^2  (3x  +12) / 12x^2y (x +4)\n\n(3x +12) / 6y (x+4)\n\n3 (x + 4) / 6y (x +4)\n\n3 / 6y\n\n1 / 2y\n\n0r\n\n0.5y
769323
6 - 12x\n-or-\n-12x + 6\n\n-or-\n\n6(1-2x)\n\n...although that depends on whether you want the simplest expanded form or the simplest factored form.
186095
Use the distributive property to eliminate the parentheses:\n\n2x - 6 + 5x = 10x + 30\n\nCombine 2x and 5x since they are on the same side of the equal sign\n\n7x - 6 = 10x + 30\n\nSubtract 10x from both sides and add 6 to both sides\n\n-3x = 36\n\nDivide both sides by -3\n\nx = -12
1128770
You want to exponentiate your logarathim. For example, a=log x is the equivalent of 10^a=x.\n\nIn your problem, first multiply both sides by negative one to move the negative sign to the other side. Then, -6.00=log[OH-] becomes 10^(-6)=[OH-]. Your concentration of OH- is 10^-6 M.
178588
Rearrange as (-7)(-11) m^(-6) m^(-4) u^(-4). Then combine the two coefficients into 77, and add exponents for the same base m, to get m^(-10). The final result is \n77 m^(-10) u^(-4). By the way, you should ask your teacher or consult the book to see if exponents should be made positive. In that case write the answer as 77 / [m^10 u^4].