whati is 9600 baud, no parity, 1 stop bit in Hyperterminal?
84988
It's a synchronization standards that Hyperterminal uses to link into equipment attached to the computer via LAN cable (CAT 5).  9600 or 9.6K is the rate (or clock speed) that the computer will talk to the piece of equipment it's attached to.  No parity refers to a control singal need for a data transmit  link, and one stop bit refers to a special bit sent to/from the computer to determine  when transmission has begun and when it has stopped.
407435
Nod32 very good.\n\nHope this helps.\n\nGood Luck.
14463
You are going to need to provide more information about your question.  I don't believe anyone is going to have enough context to answer it.  Where are you seeing "PROCESSOR_LEVEL=15"?  What type of mapping is going on?  \n\nSorry I can't answer your question, but at least I can let you know that you're not being ignored.
227540
001100100001\n\nSorry braxton_paul, you're second answer is incorrect, as it is binary, BCD, or BINARY CODED DECIMAL, is different. as stated by wd5gnr, BCD wastes space, this is why the BCD number is 12 digits, and your binary is only 9. This is due to the fact that BCD has no base (at least in the normal sense), wheras binary is base two. Just because BCD uses only two characters, doesn't mean its base is two. This is due to the fact that BCD has no "place weight", for example, if you have 95473 (for a random example), in a base 10 (decimal) system, the 4 would have a value of 400. Say you have a binary system, and lets just use the BINARY of 321, or 101000001, (from RIGHT to LEFT) the ones place has a "weight of 1, the two's has a weight of 2, the three's has a wieght of 4, position 4 is 8, 5 = 16, so forth (each time you multiply the previous space by two)... So to convert BIN to DEC, just multiply the digit ocupying the space by the spaces value, so from right to lef, you would get 1x1=1, (the zeros do not matter since anything times zero is zero) 1x64=64, and 1x256=256... then simply add the values together, and you get the DEC equiv. of your BIN, so 1+64+256=321... Just try that with BCD... and you do indeed get 801... that is why it is called binary CODED DECIMAL. the lack of a base is why BCD can only easily be converted to and from Decimal and Binary, just try converting it to octal, or hex... it is a pain in the a$$ unless you first convert it to DEC...\n\nso (as if anybody cares):\n\n321 (DEC, or base ten) = 141 (HEX, or base sixteen) = 501 (OCT, or base eight) = 101000001 (BIN, or base two) = 001100100001 (BCD, or base ten incoded in base two)\n\nwheras:\n\n801 (DEC) = 321 (HEX [coinciednce]) = 1441 (OCT) = 1100100001 (BIN) = 100000000001 (BCD)\n\nBinary, and (B)inary (C)oded (D)ecimal are not the same!\n(and wd5gnr's BCD to DEC conversion table is correct)\n\nUsualy a dead give away when it comes to BCD vs. BIN, is that BCD usaly has preceeding zeros listed, but BIN does not (though preceeding 0's could also mean ASCII, BCH, or BCO, or prettymuch binary coded anything)
361852
In computing and telecommunication, a parity bit is a binary digit that indicates whether the number of 1 bits in the preceding data was even or odd. If a single bit is changed in transmission, the message will change parity and the error can be detected at this point. (Note that the bit that changed may have been the parity bit itself!) The most common convention, or parity scheme, is that a parity bit of 1 indicates that there is an odd number of ones in the data, and a parity bit of 0 indicates that there is an even number of ones in the data.
752840
i am a hardware tech ..use this simple step\n[Start] \n[Run] \n[Regedit]\nRegistry Key: HKEY_LOCAL_MACHINE&#92;System&#92;CurrentControlSet&#92;Services&#92;LanmanServer&#92;Parameters\nModify/Create the Value Data Type(s) and Value Name(s) as detailed below.\nData Type: REG_DWORD [Dword Value] // Value Name: Autodisconnect\nValue Data: [Enter a new disconnect time. Use Hexadecimal if you are unfamiliar with Binary]\nExit Registry and Reboot
966120
try this stuff... pls understand the logic...\n\n#include<stdio.h>\n\nint main()\n{\nint no,rem;\nscanf("%d",&no);\nwhile (no)\n{\nrem = no % 10;\nprintf("%d",rem);\nno = no / 10;\n}\n}
49715
use bitwise operators. something like:\n\nnum_bits = 0;\nfor(i = 0; i < 32; i++) {\nif number & (1<<i) num_bits++;\n}\n\nnow num_bits holds the number of bits that were set in number. The "<<" operator does bit shifting. So "1<<i" equals a number that's all 0's except for a 1 at position i. If you bitwise and that with something, that tells you if that bit is set in the number. So we do this for each of the bits and add up the results.\n\nThis is assuming 32-bit integers. Adjust accordingly for 64-bit integers.
479514
It printed this for me 0♦8\n\nHope this Helps.\nGood Luck!!!
565668
next to the 0(zero key)is the hyphen-   push the hyphen key and shift at the same time.\n\nso instead of -, you will get _.\n\nYAY!
706983
We want to figure out what BER is, just knowing the chance that a symbol (two bits in a row) gets an error.\n\nThe chance that a single bit stays the same is 1-BER.\nAssuming errors are independent, then the chance that two bits in a row are unchanged is (1-BER)^2.  So, set this equal to 0.8 (the chance that an entire symbol is unchanged), and solve for BER.\n\n(I answer this w/o knowing, off-hand, what Amplitude Shift Keying is; this answer just relies on the fact that bit errors will be independent.)
964234
Take a closer look at the ASCII set in Hexadecimal.  A is 41H and a is 61H.   It makes perfect sense to a GEEK.\n\nGood luck and Happy Computing!
152443
It may mean the computer is trying to divide by 0
761907
560 = N / (1- u/ 340) --------------- [1]\n\n480 = N *(1+ u/ 340) --------------- [2]\n\n[2] Divided by [1] gives \n\n480 / 560 = (1 + u/ 340) *(1 - u/ 340)\n\n 0.8571 = 1- (u/ 340) ^2.\n\n(u/ 340) ^2 = 0.1429\n\nu = 128.5 m/s.
248038
I will give your in binary :\n0000\n0001\n0010\n0011\n0100\n0101\n0110\n0111\n1000\n1001\n1010\n1011\n1100\n1101\n1110\n1111
644438
you can find it in a byte\nASCII - it is a 7-bit code \n\nEBCDIC - 8-bit (the usual byte)
365175
It actually refers to a memory location whose address\nin hex is 800H or in decimal it is 2048D.