How much would a sheet of Lexan 3' x 5' x 1/2 " thick expand from -20ºF to 130ºF  50% Humidity, 6000 Ft' Alt?
92881
Maybe this will help (Lexan LS2)\n\nCoefficient of linear thermal expansion (parallel) \n0.7 E-4/°C
580938
All you have to do is find one that is either\na) larger than .5 or\nb) smaller than .45\n.501 > .500\nHence, your answer is .501
157585
[D]esiccant's adsorption capacity decreases as temperature increases....
687306
Check the Michaelis-Menten equation.It's too long to write it all down for you ;)
331051
I listed some expansion coefficients\n\n\nMetal Temperature Range \n(oF) Thermal Expansion \n(microinch/(in oF)) \nAdmiralty Brass 68 - 572 11.2 \nAluminum  68 - 212 13.1 \nAluminum Bronze 68 - 572 9.0 \nBeryllium Copper 68 - 212 9.3 \nCast Iron, gray 32 - 212 5.8 \nCopper 68 - 572 9.8 \nCupronickel 68 - 572 9.0 \nHastelloy C 70 - 200 5.3 \nInconel 68 - 212 6.4 \nIncoloy 32 - 212 8.0 \nIron, nodular pearlitic 68 - 212 6.5 \nIron, pure 68 - 212 6.8 \nManganese Bronze 68 - 572 11.8 \nMonel 32 - 212 7.8 \nNickel Wrought 77 - 212 7.4 \nRed Brass 68 - 572 10.4 \nTin  32 - 212 12.8 \nTitanium 68 - 200 4.8 \nWrought Carbon Steel 70 - 800 7.8 \nYellow Brass 68 - 572 11.3
142989
I am having a hard time picturing the gaps you are trying to fill, so I'm not sure if my ideas will be helpful.  Perhaps you could try ceramic as an insulator.  It also depends on how long the surface will be exposed to the high temperatures.  If its not too long, perhaps you could use wood that has been soaked overnight in water.\nThe aluminum isn't a bad idea, but perhaps you need thicker aluminum.  Like maybe cut open a few soda cans and flaten the result into a crude sheet of aluminum.  Maybe two or three layers worth would do the trick.\nMaybe some gravel or stones?\nWell, those are just some ideas.  Not sure if any of them will work, but maybe that gives you some things to explore.
155820
Each time you fold it, it doubles in thickness and halves it surface area.\n\n0.1mm x 2 ^ 40 = 109,951.1627776 km\n\n(68,320 miles)\n\nThat means that the piece of paper would be so thick that it would reach to the Ionosphere (well past the ozone layer!)\n\nAlthough the thickness of the paper would be huge, the surface would be tiny. Say you had a large sheet of paper\n1m x 1m (3'4" x 3'4")\n\n1(m^2) / 2 ^ 40 = (m^2) = 0.90949 (μm)^2\n\n(0.0000000014097 square inch)\n\nSo basically your talking about a large piece of paper that now has such a small surface as to become invisible and so thick that it may get hit by international aircraft!\n\nThat is ridiculous and impossible! Incidentally, no paper can be folded more than 8 times.
591001
The general rule of thumb in the Deep South of the USA is 1 ton of AC for every 600 square feet of space with an 8-10ft ceiling.\n\nYour room has a volume of 86.8 cubic meters.\n\n1 cubic meters = 35.3146667 cubic feet\n\nso your volume is 3065.25 cubic feet.\n\n1 ton is recommended for 600 sq.ft X 10ft = 6000 cubic feet.\n\nSince you have about half of that then 1/2 ton would probably do the trick.  A ton = 12,000 BTUH so 1/2 ton = 6000ft.\n\nI would recommend you get 9000BTUH to help handle the extra load from no insulation and the excessive temperature rise.  Since you don't have to worry about humidity in the desert, then oversizing the A/C shouldn't be a problem as it would be in a place with high humidity.\n\nGood luck!
950995
208 feet by 208 feet.
317109
Take table for R134a refrigerant:\n\na) delta s = entropy change\n--inlet for evaporator assuming 50%moisture= interpolate to get S \n@200kpa for R134a\n0       Sg   \n0.5     S\n1       Sf\nget Sg and Sf from table at 200kpa for R134a. \n \n--out for evaporator = Sg at 200Kpa (get from table) since it is sat vap.\n\nthe difference of both Sfg and Sg is the answer.\n\nb)  delta S = Q / T  where Q = 120 KJ and T = -5+273 = 268K\n\nc) add both a) and b) is the total entropy
968613
If you want to make 1 Liter of this final solution, you would need to take 721 mL of your 52% formaldehyde solution, add 120 mL of methanol to it and bring the final volume up to 1 Liter with water.  You should be able to scale this up or down to make any particular volume you need.\n\nWhat isn't coming out right in your calculations?
651326
approx:200 per sqr.inch.
175159
Solid\nCopper melts at 1083ºC
693858
Difficult without paper, but the principle is to work out a formula for the total area of aluminium sheet which still maintaining 1000cm3 volume.\n\nIn the following, r = radius of cylinder and h = height of can.\n\nArea of aluminium = 2*pi*r^2 [the top and bottom] + 2*pi*r*h [because 2*pi*r is the circumference of the can]\n\nBecause pi*r^2*h = 1000, you can substitute h = 1000/pi*r^2 into the Area equation.\n\nThen differentiate with respect to r, and when dA/dr = 0, that's the most economical way to make the can.\n\nIt should turn out at close to r = 5.4; h = 10.9
969868
What parameters do you already have?  I guess you have an a/c weight? The CL equation is a standard with CL= L/(1/2 density*V^2*S)  where S is the Area.
315401
Use PV=nRT ideal gas equation.\nP=0.400 atm\nV=?\nn=3 mol\nR=0.0821 L atm /K/Mol\nT=300K\n\nDo yourself now...
329557
Try this....\n\nhttp://www.efunda.com/formulae/solid_mechanics/mat_mechanics/pressure_vessel.cfm