HOCUS + POCUS = PRESTO in unique digits?
84848
HOCUS + POCUS = PRESTO\n92836 + 12836 = 105672
663163
go to run-regedit\nand then open HKEY_CLASSES_ROOT&#92;CLSID&#92;{450D8... key\nthen see the SortOrderIndex and make its value 54.\n\n:-)
222426
For one, it contain all digits 0 - 9 which appears only once. They are in alphabetical order when spelt out. And it gives me two points to Yahoo! Answers.
400127
C  H   O\n.6  12   6\n\nWITHOUT DECIMAL POINT
635970
You mean Roman numerals? Here's an easy way to remember them:\n\nIt's Very eXciting, Linda Cried During Math (I V X L C D M).\n\nThen the values are 1 and 5 over and over again:\n1, 5, 10, 50, 100, 500, 1000\n\nSo you get I=1, V=5, X=10, L=50, C=100, D=500, M=1000\n\nIf a smaller number comes before a larger one, you subtract. (Example: IV=4)\n\nIf a smaller number comes AFTER a larger one, you add. (Example: VI=6)
238247
On the bottom - usually the left side.  It is the 9 digits between the semicolons.\n\nLooks like this: |:123456789|:
461750
A word or number that is the same forwards and backwards is called a palindrome
732158
I feel your pain. This is busy work, to say the least. Renaming in this context refers to whether or not the various place-holders are changed (or "renamed") when you add the numbers together. In this example, when you add the digits in the "ones" column together, you get 13, so you "rename" that as 3 ones and 1 ten and add the 1 ten to the tens column. \n\nTo me, fussing with this concept, rather than just concentrating on the HOW, is busy work and just makes it more confusing. (That's a vent to our public education system -- not to you.)\n\nAnyway, I hope that helped shed some light. Please feel free to email me additional items and I'll help work them out and explain whether or not "renaming" was involved.
651114
it would be X<12, with extra line
457026
Create a method called numDigits(long). Then you can use code something like this:\n\nint num;\ncin >> num;\n\nint numDigs = numDigits( num );\nint digits[ numDigs ];\nint temp = num;\nfor ( int i = numDigs - 1; i >= 0; i-- )\n{\n digits[ i ] = temp % 10;\n temp = (int)( temp / 10 );\n}\n\nThe digits array holds each of the digits in the number.\nThis is the code I used for numDigits():\n\nint numDigits( long num )\n{\nint digits;\nfor ( digits = 0; num > 0; digits++ )\n{\nnum /= 10;\n}\n\nreturn digits;\n}
751189
If you are under Windows you can turn on NumLock, and use Alt plus codes on the number pad to do some of them (Alt-253 = ², Alt-171 = ½, Alt-251 = √, etc.) \n\nAlternatively, you can use Character Map utility under Start > All Programs > Accessories > System Tools.  Then you can get lots of others:\n°±²³ΦΘΠⁿ⅓⅔⅛⅜⅝⅞∆∏∑√∞∫≈≠≤≥\n\nFeel free to copy these from here too...
1116625
In the UK we tend to say Nought rather than Zero so 8 5 4 9 0 1 7 6 3 2 would be in alphabetical order this side of the pond.\n\nIn France it would be cinq deux huit neuf quatre sept six trois un 5 2 8 9 4 7 6 3 1\n\nIn German it would be acht drei eins funf neun sechs sieben vier zwei 8 2 1 5 9 6 7 4 2\n\nRe the last-but-one contributor\n\nV100 = 10 and 10 + 0 = 10 \nV9801 = 99 and 98 + 01 = 99\nV998001 = 999 and 998 + 001 = 999\nV99980001 = 9999 and 9998 + 0001 = 9999\nV9999800001 = 99999 and 99998 + 00001 = 99999 etc\n\nso not unique but one member of an infinite set of numbers with this property.
754112
9804781928\nor\n3851297493
150167
(a) 111100111101\n(b) 110001011
130921
Ah, love these kinds of problems.\n\nOK, there is a very efficient solution if you restrict yourself to integer types. Try this code:\n\nint Answer = 0;\nint i;\nfor (i=0; i < 2*n + 1; i++)\n{\n   Answer ^= Array[i];\n}\nprintf ("Single entry is %d&#92;n", Answer);\n\nThe clincher here is that every integer when exclusive ORed with itself yields zero, so all of the duplicates simply disappear - you will only be left with the unpaired entry.
785224
An algorithm for solving this would be to divide up the digits and shuffle or switch them in the direction that makes them closer to correct (the "greedy algorithm").  That should work without too much trial and error.
712479
You have to digit:\n011 + 39 (Italy country code) + 10 digit number\n\nYou don't have to include city code because this is a cell phone.\nIn Italy cell phone numbers don't have 0 in front.