Which of the following binary numbers could be a binary coded decimail?
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(A) 1000 (B) 1011 (C) 11011011 (D)11001110 \n\nA \n\nIf you translate each group of 4 from binary to decimal you get\n1000 = 8\n1011 = 11\n1100 = 12\n1110 = 14\n\nSince binary coded decimals represent the decimal digits 0-9 the only one that can be correct is (A) 1000
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There are 4 steps of excuting every command in computer. Fetch , Decode , Excute , Store . In first step binary codes come to CPU from Ram.It's just one of them.If you want to know more it's my Id: amirhesam_kh@yahoo.com i can help you more.
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100,000,000,000,001 or one could give it to you in scientifi notation with a rounding error 10.0 E13
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Are you looking at computer code?  B indicates binary base and D indicates decimal.\nB100 = 1*2^2 + 0*2^1 + 0*2^0.\nD1000 is one-thousand.
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76063 in decimal\n0x1291F in Hexadecimal\n1001 0100 1000 11111 in binary
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Binary system uses only 0 and 1 to represent numbers.\n\nThe ternary system uses 0, 1 and 2 or 0, -1 and +1 to do so.
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9804781928\nor\n3851297493
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Whether you are looking for general information about binary numbers or looking to perform mathematical operations on them I would suggest you take a look at this article at Wikipedia, http://en.wikipedia.org/wiki/Binary_numbers I think it has all the information you are looking for.
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hello!!!!!!!!!! \n1+1 in binary is 10! it's not ten but one zero!!!
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keep a table of binary 4 bit equivalents 0 1 2 ... F of hexadecimal degits.\nconvert each 4 bits of your binary no. to equivalent hex. no looking the table.\n\nyou got the answer
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This is possible only if at least half of those 256 values will not be used at all, and that you know which ones won't be used beforehand. If that's the case, you can map the remaining values that will be used with 7 bits.\n\nSee Shannon's entropy equation...
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rgb is represented decimally like this:\n###,###,###\neach three # represent a value between '0 & 255' representing how much Red, Green & Blue are in the color, respectively,\nthis needs one byte to represent binary, so, say red is:\n'255,0,0'\nso in binary this is '111111110000000000000000'\nin hexa is FF0000\ngot the picture?
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Vigintillion\n10 to the 63rd power\nor 9with 63 zeros and that is a real #
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in decimal its 2\nin binary its  0\nin other like octal hexa etc its 2\nin logical or its 1\nnow wat do u want????
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If you are thinking of f : ? -> { 0, 1, 2, 3, ... } (i.e., the domain is mapped into the set of non-negative integers) then clearly the domain "?" contains [at least] all finite bit strings.  If you keep the same restriction on the range, you can even extend the domain to include those infinite bit strings (however you wish to define that) which contain only finitely many ones.  If you extend the range to also include infinite cardinals and/or ordinals then you can include even more infinite bit strings into the domain.
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0.\n...and the counting stops, because we are counting in binary....lol.
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Binary numbers use only one (1) and zero (0). \n\n10 in binary is 2 in decimal.\n11 in binary is 3 in decimal.\n110 in binary is 6 in decimal.\n\n(Decimal numbers are normal numbers.)