Is weight the same out of water as when it's in?
87856
It all depends on the definition of what we call as weight.  Generally weight is defined as the force equal to the product of mass and acceleration due to gravity. By this definition the weight of an object is the same irrespective of its surrounding medium.\n\nBut often we deal with problems when an object is surrounded by some medium say air or water.\n\nIn that case we have to say that the weight in air or weight in water.\n\nBy ‘weight in air’ we mean the net force (weight in vacuum minus the upward force due to air)\n\nBy ‘weight in water’ we mean the net force (weight in vacuum minus the upward force due to water)\n\nTherefore,\n The weight in vacuum will be greater than the weight in air. \nThe weight in air will be greater than the weight in water.\n\nIf nothing is added (surrounded) to the term weight, \nWeight means weight in vacuum\n\nAnd is the same whether it is in air or water.
449872
The both weigh the same
695350
Yes.\n\nIn fact there is a very nice relationship that when you are below the surface of the Earth (assuming the Earth is a perfect sphere), your weight is proportional to your radius from the center. E.g. if you were 1/3 of the way to the center (2/3 from the center), you'd weigh 2/3 as much as you do on the surface.\n\nThe proof uses a variant of Gauss's law from electromagnetics (because Newton's equation for gravity and Coulomb's equation for charge have the same form). Without delving into advanced calculus, the gravity that affects you depends only on the earth in the sphere below you - everything at your altitude and above cancels out. Since the volume of a sphere is proportional to r^3, but the gravitational force is proportional to 1/r^2, the remaining term is simply r - so your weight is proportional to the radius, if you're inside a sphere.\n\nOf course this assumes that the Earth's weight is distributed evenly. However, it's close enough to even for most purposes.
923764
a) F = ma\n    F = 0.0412 kg * 9.8m/s^2\n    F = 0.404 N\n\nb) F = 0.0370 kg * 9.8 m/s^2\n    F = 0.363 N\n\nc) The difference in "weight" is equivalent the weight of the displaced volume of water...  So...\n   0.404N - 0.363N = V * 1000 kg/m^3 * 9.8 m/s^2\n   0.041N = V * 9800N/m^3\n   V = 4.18 * 10^-6 m^3   or  4.18 cm^3\n\nd) Oh Juliet you are my density.... (bad joke!)\n     Density = m/V\n     D = 0.0412 kg / 4.18  * 10^-6 m^3\n     D = 9848 kg/m^3
1163141
yes .. in vacuum, all items will fall at same rate... it is the rate at which the gravity acceleration attacts everything to the center of teh Earth. But you might have a queation, that if the acceleration  is same then why different things weigh different... \n\nweight =mass X acceleration of gravity (9.8meter/second^2) and mass is the one which is a measure of matter in a body makes the difference... so if you let a 5kg weight and a 5,000kg weight fall in a vaccum, they will fall at the same rate and will reach the ground at the same time.
291004
if an object is floating, the buoyant force on it equals its weight -- the vertical forces have to sum to zero.  try drawing a free body diagram to convince yourself of this.
810641
Use Archimedes's buoyancy principal.  The weight outside represents the response of mass to the Earth's gravity.  The weight in water represents the displaced water's weight.  Use the ratio to get the answer.  HINT: if you convert to mass, the answer almost gives itself away.\nThe displaced water has a well known density.  That density will give the volume of the both the displaced water and the object displacing it.
903913
The frozen one feels heavier because of the more solid (for lack of a better word) weight distribution. Did you try comparing weight by holding the bottle upright in the palm of your hand? That should give you a better relative idea. The weight is the same, in theory (assuming each bottle had exactly the same amount of water to begin with, the same amount of trapped air, and were both completely air-tight (all of which are unlikely)).
1044964
The weight of water equals the weight of the cloud, since the cloud is nothing but water. If it loses water by raining, the cloud loses that amount of weight.
160578
No, the same molecules and atoms are on (in) the screens regardless of what the image is.  Their appearance changes, but there is no change in weight.
1165265
its all to do with weight displacement and the volume of water
1043479
...because their density is less than water density (1000 Kg/m^3).\n\nIf the density of an object is less than the density of the water, it floats on the surface of the water. If the density of the object is equal to the density of the water, the object floats anywhere inside the water. If the density of the object is more than the density of the water, the object sinks to the bottom.
566264
It has all to do with the law of floatation.\n\nA piece of metal will sink to the bottom of a tank of water because its weight is GREATER than the weight of an equal volume of water. \n\nLikewise, a piece of wood or plastic will float because its weight is LESS than the weight of an equal volume of water.\n\nA ship may weight tonnes. However, its overall weight IS LESS THAN the weight of an equal volume of water.\n\nIf you are able to measure the total volume of the ship, you will find that the WEIGHT INSIDE this volume IS LESS than the weight of an equal volume of water.\n\nSo the ship can float.
1054074
You float without weight there.
578701
Both are Same Weight , 1 Kg\nbut Volume is different
49373
When you put an object in water--or any other fluid that is minimally compressable, like milk or oil or alcohol--the object takes up space.  Especially for fluids that are very runny--like water, in contrast to, say, old crank-case oil--the fluid will fill every nook and cranny available.  Since the water, or other non-compressable fluid, has to move out of the way for the object put in it, the apparent rise in the total volume of water-plus-object is due to the volume of the object.\n\nOf course, if the object FLOATS in water, you're in a whole new situation: the object will displace (move aside) exactly the amount of water that weighs what the object does.  That's a whole different discussion!
508636
same mass, same weight