Is y= 3/5x - 2 perpendicular, parallel, or neither to y = -5/3x + 3/5?
96323
2 lines are parallel if their slopes are equal. 2 lines are perpendicular if the product of their slopes is -1 (or if the slope of one line is the negative reciprocal of the other)\nFrom your given, the slope of the first equation is 3/5\nusing y = mx + b (m is the slope)\nThe slope of the second equation is -5/3. Notice that their product is -1, so the lines are perpendicular.
753792
You can find the slope of 2x - 3y = 12, call it m.  The line perpendicular to it will have slope -1/m.  Since you know the slope (-1/m) of your line and a point on it (2,8) you can solve to find the equation.\n\nSTEP 1 -- Find -1/m\n\n2x - 3y = 12\n-3y = -2x - 12\ny = 2/3 x - 4  << so m=2/3, and -1/m = -3/2\n\nSTEP 2 -- Use slope -3/2 and point (2,8) to find the equation\n\nRecall that (y-y0)=m(x-x0), so we get the following:\n\ny - 8 = -3/2 (x - 2)\ny - 8 = -3/2 x + 3\ny = -3/2 x + 11\n\nSo, the equation you are looking for is y = -3/2 x + 11\n\n~ ♥ ~
823070
Get the slopes of the two lines using the formula:\n(y2 - y1)/(x2-x1)\n\nIf the slopes are equal the lines are parallel\nIf the slopes multiply together to give -1 the lines are perpendicular\nIf the slopes do not meet these conditions they are neither\n\nHope this helps!
334248
The two intersect clearly at (-3,4). x=-3 is a vertical line parallel to the y-axis shifted 3 units to the left. y=4 is a horizontal line parallel to the x-axis shifted 4 units up.
823237
There is several way to solve the problem, but I think it is easies, to find the parametric representation, and then use, that the scalar-product of the orientations-vectors is zero, if the line are perpendicular, and the orientations-vectors is linear depended if parallel.\n\nL1:  y = -½x-3 => (x,y)= (1,-½)*t+(0,-3)\n4x-2y+5 = 0 <=> y=2x+5/2=>\nL2: (x,y) = (1,2)*t + (0+5/2)\n\nbecause (1,-½)*(1,2)=1-1=0 the lines are perpendicular
980603
I think the first is wrong because the Y point is not ZERO in the firsst equation and thats the point you need to find the perpendicular not (12.5, 0) because that point is not part of the first one...\n\nFirst, we get "m" of the first equation, which we can write this way\ny= -4/5x - 2\nand m= -4/5\nso, the m we need for the new equation would be 5/4\nFinding the intercept of the second equation\n2x=25\nx=12.5\nAnd finding y in the first one, y = -12\n\nNow we find the new equiation with m= 5/4 in (12.5, -12)\ny+12 = 5/4 (x-12.5)\n4y + 48 = 5x - 62.5\n4y - 5x + 110.5 = 0  (this is the equation you are looking for)
840251
parallel lines have same slope\nperpendicular lines have negative recipricol slopes\nthis is neither.....it is reciprical, but not negative.....\n\ny = mx+b..... in equation y = 3x-3, m = 3,  in equation y = 1/3x+2, m = 1/3......would have to be -1/3 for perpendicular....
1142461
1. x-y=5; y= x - 5\nAdd y to each side x - y + y = 5 + y, becomes x = 5 + y. Subtract 5 from each side, x - 5 = 5 - 5 + y, becomes x - 5 = y\n\nSolve the rest on your own
560706
You need to get the y alone on one side of the equation. Subtract 5x from both sides and you get:\n-3y=-5x-3\nDivide each variable by -3 to get:\ny=(5/3)x+1\nNow you can graph using this equation.\nThe y-intercept is 1 and the slope is 5/3.\nHope this helps.
759094
the perpendicular slope is the negative inverse of the origional, meaning, once you change your equation into y=mx+b form, you flip your slope, and make it negative.\n\n-3y=1212-2x\ny=-404-(2/3)x\ny=-(2/3)x-404\n\nso the slope is -2/3. the perpendicular is 3/2.\n\nplug it in with the point:\n\n3=(3/2)(4)+b\nb=-3\n\ny=(3/2)x-3
312440
yes, 2(3)+5(-5)=-19 .... 6+(-25) = -19 .... -19 = -19\n\nthe ordered pair 3 is the x variable and 5 is the y variable so just substitute to check the answer
104362
neither... the second eq boils down to y = 2/3 which is a horizontal line\n\nto tell:  if parallel the slopes will be equal\nif perpendicular slopes will be negative reciprocal
565940
Let the numbers be x and y where y is the larger number.\nx:y = 3:5 => 5x=3y => x=(3/5)y --(1)\ny = 36+((1/2)(y-x)) --(2)\n\nSubstitute (1) into (2),\ny = 36+((1/2)(y-(3/5)y))\ny = 36+((1/2)(2/5)y)\ny = 36+(1/5)y\ny-(1/5)y = 36\n(4/5)y = 36\ny = 36/(4/5)\ny = 36*(5/4)\ny = 45\n\nSo x=(3/5)(45)=27\n\nCheck:\n- 27:45 = 3:5 okay\n- 36+((1/2)(45-27)) = 45 okay
752053
Let say x is y, to avoid any confusion.\n3/y = (y + 5)/2\n\nMultiply by 2 at both side.\n3/y x 2 = (y + 5)/2 x 2\n6/y = y + 5\n\nMultiply by y at both side.\n6/y x y = y x (y + 5)\n6 = y(y + 5)\n6 = y^2 + 5y\n\nBring all the numbers to one side.\ny^2 + 5y - 6 = 0\n\nFactorize the equation.\n(y + 6)(y - 1) = 0\n\nTherefore,\ny + 6 = 0  or  y - 1 = 0\ny = -6  or  y = 1\n\nIn short,\ny = -6, 1\n\nAs I had mentioned earlier, x = y.  \nTherefore, x = -6, 1.
852206
since the line is perpendicular to y - axis . that means the x value can change but y value remains the same.\nIt is given that ( 5, -3) is a point on the line. So, y = (-3)
206028
exact correct steps:\n1. (y+5)(y+6)=0\neither y=-5 or y=-6 \n\n2. x(x+2)=0\neither x=0 or x=-2
920764
Perpendicular lines have slopes whose product is -1.\n\nIf the original line has slope 3, the line that is perpendicular has slope -(1/3)\n\nNow use the point slope form of the line.\n\ny - y1 = m(x - x1)\n\nIf (x1,y1) = (2,2) - your point, then:\n\ny - 2 = (-1/3)(x - 2)\n\nWe can convert this into slope-intercept form.\n\ny - 2 = (-1/3)x + (2/3)\ny = (-1/3)x +(8/3)\n\nBoth equations represent the same line.