Can you give me a clue how to solve addition of magic square and multiplication?
84611
Check this website:\nhttp://mathworld.wolfram.com/Addition-MultiplicationMagicSquare.html
695328
(1) add row#1*6 from row#2, then from row#3\nthat is [–6+1*6, –47+6*6, -2+1*6] for row#2\nthat is [-6+1*6, -41+6*6, 2+1*6] for row#3\nthus:\n1……6……1       \n0…..-11…..4\n0……-5…..8\n(2) add row#2*(-5/11) from row#3\nthat is [0, -5+(-5)*(-5/11), 8+4*(-5/11)] for row#3 \nthus:\n1……6……1       \n0…...-11…..4\n0……0….68/11\nto check the result multiply main diagonal: 1*(-11)*(68/11)=-68
708943
You have to complete the square.\n\ny = a(x^2 + b/a x) + c\ny = a(x^2 +b/a x + b^2/4a^2) + c - b^2/4a\ny = a(x + b/2a)^2 + (4ac - b^2)/4a\n\n[4ay - (4ac - b^2)]/4a = a(x + b/2a)^2\n[4ay - 4ac + b^2]/(4a^2) = (x + b/2a)^2\n\n+/- sqrt(4ay - 4ac + b^2)/2a = x + b/2a\n\nx = (-b +/- sqrt(4ay - 4ac + b^2))/2a
960799
BIMDAS BIMDAS BIMDAS!\nbrackets, indices, multiplication, division, addition, and then subtraction\n\nHence, do your 6.4 divided by 0.032 first.\nThen, do 3.34 add the answer from above.\n\nShould be 203.34
437832
Homework.\n\nSuppose a1*x+a2*Tx+..+am*T^(m-1)x=0.\n\nApply T^(m-1) to get a1=0.\nApply T^(m-2) to get a2=0, etc.
674087
The question is how to describe the steps of the multiplication. The asker is not a native English speaker and wants the words that describe the multiplication procedure.\n\nFirst, you multiply 123 by 8 and write the product.\nThen, you multiply 123 by 6 and write the product under the previous product and one place to the left.\nThen, you multiply 123 by 7 and write that product under the previous product and one place to the left.\n\nThen you add the products to get your final answer.
903769
You can cross-cancel, and then multiply ... at least I think that's what it's called. \n\nLet's say you have the problem 27/4 x 16/9. Looks somewhat large at first, but you can make it really simple. The 9 and 27 can be reduced, because 9 is a factor of both of those numbers. Take 9 out of each and you get 3/4 x 16/1. Then you can take 4 out of the 16 and the 4. You're left with the problem 3/1 x 4/1, which equals 12/1. That reduces to 12.\n\nA long-looking problem that can be easily simplified. Hope that helps.
1187142
maybe something like 7^(1/3) over 7^(1/2)\n\nthat's the same as the cube root of 7 over the square root of 7.\nTo solve it, you would just subtract the exponents and you'd get 1 over 7^(1/6)\n\nI hope that is what you are looking for.
956128
Simply multiply\n9 * 8 * 7 * 6\nBecause the first number can be 1-9 but not zero and the second number can be 1-9 but one number has already been used and so on and so forth.\nHope it helps.
294579
First multiply p times the second polynomial.\np(p^4 - 2p^3 + 3) = p^5 - 2p^4 + 3p\nthen multiply 2 times the second polynomial.\n2(p^4 - 2p^3 + 3) = 2p^4 - 4p^3 + 6\nNow add these two together.\n\n(p^5 - 2p^4 + 3p) + (2p^4 - 4p^3 + 6)\n= p^5 - 4p^3 + 3p + 6
1160760
what you have is something like\na(b+c)\n\nthe solution is \nab+ac\n\n(x^3)(2x^-2)+(x^3)(4x)\nnow to multiply x^a * x^b you get x^(a+b)\n\n2x^((3+(-2))+4x^(3+1)\n\n2x+4x^4
342699
Completing the square involves creating a perfect square trinomial.  Consider\n\nx^2 + 4x - 1 = 0\n\nCompleting the square would involve trying to make one side a perfect square: (x + 2)^2 in this case.  Step by step:\n\n1.  Get all your x terms on one side, and constants on the other.\n\nx^2 + 4x = 1\n\n2.  Take half of the coefficient of the x term and square it.  Half of 4 is 2, and 2 squared is 4.\n\n3.  Add this to both sides of the equation.\n\nx^2 + 4x +4 = 1 + 4\n\n4.  Now factor the left side.  It works out to be a perfect square.\n\n(x + 2)^2 = 5\n\n5.  Take the square root of both sides and solve for x.\n\nx + 2 = +/- sqrt(5)\n\nx = +/- sqrt(5) - 2\n\nThe quadratic equation is pretty easy:\n\nx = [-b +/- sqrt (b^2 - 4ac)] / 2a\n\nIn the above example, a = 1, b = 4, and c = -1 (coefficients of the x^2 and x terms are a and b, and the constant is c).  So plugging in to the quadratic formula gives you\n\nx = [-4 +/- sqrt(4^2 - 4x1x(-1))] / 2x1\n  = [-4 +/- sqrt(16 - (-4))] / 2\n  = [-4 +/- sqrt(20)] / 2\n  = [-4 +/- 2sqrt(5)] / 2\n  = -2 +/- sqrt(5)\n\nwhich is the same as we got via completing the square.
263286
the problem you presented above can be represented as,\n\n(8x^8/2x^2) + (16x^6/2x^2) - (12x^3/2x^2)\n\nthen you can simply divide each of the term\nyou'll get\n\n4x^6 + 8x^4 - 6x
903533
ignore the decimals when u originally do the problem, then however many deciams there are in both of the decimals you're multiplying is how many there will b in the answer. i.e. if you multiply 6.78x4.234 together the answer will have 5 numbers behidnthe dceimal point
208112
use the order of operations, so first the multiplcation. so\n\n2 + 2 - 3 + 96/2\n\nThen divide by two\n\n2 + 2 - 3 + 48\n\nAdd the twos\n\n4 - 3 + 48\n\nSubtract\n\n1 + 48\n\nAdd and get\n\n49
11064
I believe you mean Magic Square. Look it up on the web.
221530
Add them together and divide by 5.\n\nWow. I could seriously have you people do my homework for me. Every night. I'll type out the problems and see how you all do. :P JP