Concentration Problem?
95585
try this out it should help you!!!\n\nhttp://www.gjk2.com/test/test.swf
619595
Start playing a video game that you enjoy. It will help improve your concentration.
436191
Uh, the rest of the question isn't appearing. But it's an equilibrium solubility problem. Write a reaction:\n\nMgF2 --> Mg+2 + 2F-\n\nKsp = 5.52e-9\n\nFill in the values on the ICE table (I don't know them, the numbers are missing), and set an equation up.\n\nKsp = [F-]^2 * [Mg+2]\n\nSolve with the numbers from the ICE table. Remember that those concentrations in the above equation are the equilibrated concentrations, not the initial.\n\n\nHope this helped.
188200
I had trouble with the same thing. The best way, and it's worked till now in college, is to take the most complicated element used (i.e. CH3OOH + C2H3O9 ---> etc), figure out O's first since O is used the most. Then work backward using the 2nd most used element. You might get a non-reduced form of balancing, but you can check whats divisible (i.e.  4CH + 2 CH2H3O2 <---> 4 OH + 2 CH3; all divisible by 2 so it'd be 2, 1, 2, 1 respectively). See if this works, it's worked when I've helped other people in the past as well.
671225
we are concentrating,  we can't do 2 things at once
16164
The instruction is not correct because the total volume yielded when you mix 100ml of concentrated solution and 900ml water will be somewhat less than 1000ml. The concentration will be slightly higher than 1.0M\n\nThe correct procedure is to take a 1l volumetric flask  and add the concentrated solution to about 800ml water, then fill up to the mark.
85199
For one thing, focus on what you want to achieve or what you are supposed to be doing at the moment. Eliminate all distractions.  Concentration is a discipline of the mind so it does take practice especially since we have so many distractions these days.  Try meditation to improve your concentration.
885954
you can try yoga and meditation it will help u to increase your concentration  power.
787233
Are you interested?\n\nIf you can answer this question honestly, then you will get the answer to your question.  Concentration is directly related to interest, if you are interested in doing something you concentrate else you are distracted.\n\nEven then try doing these things if possible:\nWhenever you feel your concentration wavering, get up from your studies move away for approx. 5 mins and come back.  In between don't go and watch TV.\nFeel your eyes are drooping, splash cold water on them a few times but don't wipe immediately.\nDon't study at a stretch, never good, you will not be able to retain anything.\nAlways have a settled time and place if possible, coz "Practice Makes Perfect".  Your mind and body need to get used to routine, and then it will be almost automatic.  You won't need to get up to study, it will happen automatically.\n\nLast but not the least, don't try doing everything now at the last moment, prioritise your workload and then do it.\n\nFor your future do pranayam and dhyana, they will really help you. Trust me.
781038
I agree with birchardv here...........we need the rest of the problem, and you would learn a lot more if you did the homework yourself.  But do whatever floats your boat.  Add the rest of the problem and I'll get back to you.\n\nOkay Chemist, this problem is really long; if you want a good answer with plenty of steps, I'll need more room.  Email me and I'll send you the solution.
957569
When you do dilutions you need to use M1V1=M2V2 to figure out the concentration of each solution.  You know how much of the stock solution was put into each, and the volume of stock, and the total volume so use algebra and figure out the concentration of the diluted solution.\n\nYou haven't gotten to the phase where you use Beer's law.  that comes after you test your dilutions and test an unknown.
948225
to maintain the concentration level of the cell
245982
Sorry, can't help. You use different units than I do.\n but concentration(mol per dm3) = no. of moles(mol) divided by volume(dm3)
529894
Intensity refers to the number of photons.  Concentration is the number photons/unit area, so what the smarties who've answered this question mean is, no, you can't increase the number of photons, you're just making them bounce off something (like a ball would), they're not multiplying in number.  Instead, you're increasing the number of photons in the area, making it moer concentrated.  In fact, do a thought experiment with a number of balls bouncing off a semicircle of walls.  They'd all hit close to the same place, but there'd still be the same number.
696083
just concentrate more man!
235402
See comment above.\n\nYou do need to do several trials at various concentrations though. You can then determine it through a linear regression.\n\nI also suggest that you consult a book on Analytical chemistry, because Beer's law has limitations. For example, it loses linearity at higher concentrations.
851560
solution...Bicarbonate and sodium. :)