50 examples of balanced chemical equations?
81384
Just google it honey :) I am sure it's out there somewhere for you
164045
What do you want a step by step set of instructions or a balanced equation?\n\n2C6H5OH + NaOCL = 2C6H50 + NaCl + H2O
813421
Na2CO3(aq) + MgCl2(aq) --> 2NaCl(aq) + MgCO3(aq)
17774
It doesn't give me room to list them all and explain them on here so let me direct you to a website I found that does a pretty good job:\nhttp://vergil.chemistry.gatech.edu/notes/quantrev/node20.html
701763
First, notice you have two S atoms on right hand side.\nTo get two S atoms on left, you must have two H2SO4 molecules.\nYour equation is now Cu + 2H2SO4 ---> CuSO4 + SO2 + ??\nIf you subtract right from left, you are left with 4H + 2O atoms, for 2H2O\nSo final eq is Cu + 2H2SO4 ---> CuSO4 + SO2 + 2H2O\n\nHope this helps you to approach these equation-balancing problems methodically.
49101
Here is one for a software package which can be down loaded for a 30 day test:\n\nhttp://www.chembuddy.com/?left=EBAS&right=balancing-chemical-equations\n\nand another at:\n\nhttp://chemfinder.cambridgesoft.com/
691513
Check that both sides of equation match. Here is an example:\n\n3 CH3CH2OH + 2 Cr2O7 2- + 16 H+ --> 3 CH3COOH + 4 Cr3+ + 11 H2O\n\nThere should be an equal amount of H, C, O, Cr in both sides of the equation. \nIt is sometimes difficult to know where to start balancing an equation. In such case you should try to find an element/molecule that does not appear in every molecule on the other side of the equation. Eg. when balancing this equation above, I first balance the number of Cr because it is on its own on the right side. Sometimes you just need to try and play with numbers for a while to find the right answer. Hope this helped...
979796
2H3PO4+6NaOH-------->6H2O+2Na3PO4\n\nThere has to be two moles of phosphoric acid and six moles of sodium hydroxide for it to balance out
175025
many sites but\nI LIKE\n\nwww.iupac.org\nwwww.chemtutor.com\nhttp://funbasedlearning.com/chemistry/chembalancer/default.htm\nwww.wfu.edu/~ylwong/balanceeq/balanceq.html\nwww.webelements.com/ \ndir.yahoo.com/Science/Chemistry/\nwww.liv.ac.uk/Chemistry/Links/links.html\nwww.chemicool.com/
775066
You have the products, but now you have to balance the equation. The unbalanced equation is:\n\nLi2CO3 + Cr2(SO4)3 --> Li2SO4 + Cr2(CO3)3\n\nBalanced:\n\n3 Li2CO3 + Cr2(SO4)3 --> 3 Li2SO4 + Cr2(CO3)3
777428
well actually me and you are in the same situation. im trying to find out how to write wrod equations into a reaction. lol but neway i just learned how to balance equations its very simple.\nFe2O3+CO--Fe+CO2\n:draw a box around each set of elements:Fe2O3 would b in a box CO would be in a box and so forth.\n:then write out a diagram of how many atoms each element has:\nEx: Element/ Before/After\n      Fe          2         1\n      O            4         1\n      C            1          1\n:Then Write numbers in front of each of the boxes until the inventory for each element is the same both before and after the reaction. Now, what happens when we put a number in front of a formula? Basically, anything in that box is multiplied by that number, because we're saying that we have that many of that kind of molecule. \n:Now do this until the diagram is equal on both sides\nAND YOU HAVE YOUR BALANCED EQUATION
802803
The answer is:\n2Al(HCO3)3  -------> Al2(CO3)3  +  3CO2  +  3H20\n\nThe equation is now fully balanced as you have\n2 moles of Al on each side\n6 moles of H on each side\n6 moles of C on each side\n18 moles of O on each side\n\nHope that helps!
1097630
Na2CO3 + 2HCl-> NaCl + H2O + CO2
329382
c2h4+ 3o2 -> 2co2 + 2h2o is balanced\n\nBefore, there are 2 carbon, 2 hydrogen and 6 oxygen\nAfter is the exact same.   \n\nIs there something else you are asking?
40293
A balanced equation is one where the number of atoms of each element are the same on both sides of the equation. This means it will follow the Law of Conservation of Mass.
744922
HClO2 + Ba(OH)2 -> BaClO2 + H2O\n\n2(NH4)3PO4 + 3Ca(NO3)2 -> 6(NH4)(NO3) + Ca3(PO4)2\n\nFinished and balanced.
461580
C                    1s2 2s2 2p2\nSi                   1s2 2s2 2p6 3s2 3p2\nGe                   (Ar) 4s2 3d10 4p2\nSn                   (Kr) 5s2 4d10 5p2\nPb                   (Xe) 6s2 4f14 5d10 6p2\n\nConsult a good chemistry book.