How is the earths rotation effected by someone jumping?
90476
It is not effected to any significant degree.\n\nThe numbers used to do any calculations would absorb any effect which may occur.  For instance the mass of the Earth is about 5.9742 E24 kg.  But do you really think this is an exact number, no, it is just an estimate rounded off.  To try to use this value for the Earth's mass to try to calculate the effects of something so insignificant will not work too well.\n\nWhen you are standing on the Earth, you and the Earth together have a certain angular momentum.  When you jump, angular momentum must be conserved (its the law).  But now that your mass is rotating slightly farther out than it used to be, your angular momentum changes, there for the Earth's must change ever so slightly to compensate.\n\nIf you wanted "numbers and calculations", you did not specificy nearly enough information.
228929
Yes.  \n(1) The centripetal force due to rotation is greatest at the equator and vanishes near the poles.  Things literally weight more at the poles than the equator.  Rockets carrying satellites are typically launched from equatorial regions because it takes less fuel.\n\n(2) The coriolis (sp?) effect results from Earth's rotation.  Something moving in a straight line has the Earth turn out from underneath it.  This makes hurricaines spin in their respective directions in the northern or southern hemisphere.  Also, a "good" pendulum will seem to rotate it's swing over 24 hours.  It's going the same way - the Earth turns beneath it.
365770
i dont' know what causes the rotation of an orbiting planet, but the moon would definitely have gravity even if it didn't spin.  that dude was full of crap.  if anything, the spin would cause things to fly off.
25445
The earth is APPROXIMATELY round due to gravitational forces.
563712
Coriolis effect, the apparent acceleration of a moving body on or near the Earth as a result of the Earth's rotation. An object at the Earth's surface moves faster at the equator--because it is moving through a 25,000-mile (40,000-kilometer) circle in 24 hours--than it does away from the equator, where it travels in a smaller circle in the same 24-hour period. The Coriolis Effect alters the paths of projectiles on Earth. Everything from jets to ships to bowling balls are affected by it.
1037132
Well, you need to take more than one law into account.  There's also the law of inertia; that an object in motion tends to stay in motion along a straight line unless another force acts on it.  In the earth's case, that other force is the sun's gravity.  As a result of the earth's own intrinsic motion and the sun's gravitational pull, the earth continues to orbit around the sun (though the sun is winning out, veeeerrrry slowly).  To disturb that equilibrium, you'd need a very large mass and/or a very high speed to overcome earth's inertia enough to knock it out of orbit.  While the impact of asteroids do have *some* effect, because asteroids come from every direction their cumulative effect evens out.  \n\nAn analogy would be walking outside on a windy day.  Normally, if there's no wind or an occasional breeze, it doesn't affect you much.  But if there's a strong wind coming from one direction then you get pushed by it, and a really strong gust can knock you over.
373975
The Earth is not a perfect sphere so you are at different distances from the centre at different places.\nThe density of the Earth is not constant so above dense rocks you appear slightly heavier.\nThe Earth spins so at the equator you are lifted slightly by the Eotovos effect.
613764
I assume you are wondering if the Earth's rotation will come into play here.  \n\nThe answer is yes.  This is the same as asking if a ball thrown in an airplane will land back in the person's hand.  Why is that so?  Everything in the plane is moving at the same speed, even the air molecules inside the cabin.  So, when the ball is thrown up, since it had the plane's speed before it was thrown, it will have that speed while going in the air, and since the air molecules are trucking along with everything else, they won't hinder the ball's motion.  \n\nIf you were to be able to watch the ball be thrown from outside the cabin, you would see the ball follow a curved parabolic path, where everyone in the cabin would see it go straight up and straight down.  You would see that curved path, because of the ball's horizontal motion due to the plane's speed.  Everyone inside wouldn't not see that, because they too are traveling with that same horizontal motion.\n\nSame thing applies here.  You share the same tangential speed as the Earth's surface, and so do all of the air molecules.  If you were able to jump for that long of time, you and everyone else around you would see you go straight up and straight down.  However, if you were being watched from space, you would follow a parabolic curve because of your tangential motion.
404666
By the pull of earth's gravity
1141344
Because the plane moves along with the earth because of inertia, even after it leaves the ground. If it didn't, then when you jumped straight up, you would land about a hundred meters from where you started.
720326
Assuming the population of the earth is 6 billion, and the average person weighs 70kg, that equates to 420 million tonnes (if I've done my maths correctly). If everyone stood on one side and jumped simultaneously, then nothing will happen as no weight would be lost from the earth.\n\nIf everyone had such springy powerful feet that they were able to jump to escape velocity (25000 mph) which means they won't come back down again, then that would cause a displacement in weight which would affect the earth.
1178872
Not sure, but I have heard of an English prep school getting all the kids in one town to line up and jump at the exact same time thus changing the earth's axis. very slightly, i hope!
736239
rotation of earth causes days and nights and also effect in high tides and low tides across the seas.\n\nrevolution of earth result into years and centuries.\n\none rotation of earth take  24hrs=1day\none revolution takes 365 days
414593
Hi Keenan!  Im Matt, an astronomy wizz.  If you look at most astronomy questions where I am, my answers are usually always the best of the best thanks to my power source, Blue Moons to Black holes By Melton Knocke.\n\nAnyway your question:\n\nEarth is moving fast, despite what people think.  It spins at about 1000 miles per hour, and goes 67 miles per hour around the sun.  You'd think that you would feel the spinning right?  WRONG!!!!  Sorry, cant help it.  Its so fun.  ANyway, the reason: All of the motions are almost completely constant. \n\nDon't get it?  Ever ride a train?  If you haven't, you can surely picture it as a car if you wish.  Notice how you feel abolutly no motion pretty much unless you speed up, slow down, or hit a bump?  Thats the same reason the earth never can be felt.  Its always going at a constant speed, never slowing unless it actually is hit with something dangerous enough to wipe out the human race.  \n\nThere is also another way in which we could indirectly feel the Earth's spin. Above we said that the Earth spinning is an example of almost constant motion. The reason we said "almost" is that the Earth's spin carries us around in a circle, not in a straight line. It's a very big circle, and it takes a long time to go around, but qualitatively it is the same thing that happens on a spinning amusement park ride, where it feels like you're being flung outward as the ride spins around. The spinning Earth is flinging us away from its surface a tiny bit, so that we weigh a little less than we would otherwise, simply because we are not being held down to the surface as tightly. \n\nAnyway, my answer is yours truly.  Enjoy!  Have fun.
287697
The ball would execute simple harmonic motion in addition to being hugely affected by Coriolis "force" due to the spinning Earth. \nIf the tunnel were not spinning and the ball was dropped straight down the center, the equation governing the ball's motion would be ma = GM(r)m/r^2 where M(r) refers only to the mass of the solid sphere under the ball, since uniform spherical shells do not exert any force on objects inside them. Assuming uniform density p, we have M(r) = (4/3)*Pi*r^3*p, so a(r) = G*(4/3)*Pi*r*p. If we let k = G*(4/3)*Pi*p, which is a constant, we get the ubiquitous equation a(r) = k*r, or d^2r/dt^2 = k*r, which we all know the solution to as the simple harmonic oscillator r(t)=A*cos(Sqrt[k]*t + B) where in our case A is the radius of the Earth and B=0.\nTo complicate matters, due to the presence of some pretty dense air, it will be necessary to add dampening conditions to the differential equation, giving a damped oscillator.\nAlso, the Earth is spinning and since the ball is not rigidly connected to it, it experiences a Coriolis "force" towards the tunnel walls in addition to its oscillation, which will surely cause it to at least stop prematurely.\nIt is more likely the ball will be destroyed by hitting the sides of the tunnel at high velocity. ;)
830124
Nothin would happen.\nIf you consider two bodies the earth (name it E) and a large mass (m). \ninitially M rests on E. and you lift mass M. the force used to lift it will also act on E.\nAlso if you consider the mass M and E. as a system force exerted on dropping M would be internal and since internal forces do not cause acc. the Earth will not get unbalanced.\n\nThats good for us isn't it...
643446
If we assume the Earth is a perfect spehere, the gravitational accleration would, indeed, be equal at any point along the surface of the sphere.\nWhen you take the rotation of the Earth into account, yes, at the equator, an object's "weight" is less than it would be at the poles.\n\nThe gravitational acceleration acts as the centripetal acceleration which keeps us all on on the Earth instead of flying out into space in a straight line.\nAt the poles, no centripetal acceleration is needed (neglecting Earth's revolution around the sun), but at the equation, the objects inertia acts to lessen the appearent effects of gravity and reduce its weight.  This is NOT due to the fictitious centrifuga force.