how do i write an equation for a graph use y-intersect form(y=mx+b)?
92773
First get the slope (m):\n(-3-(-3))/(-6-3)=0\nNow the y-int (b):\n-3= 0(3)+b\nso b=-3\nso your equation is \ny=0x-3 or simply\ny=-3\nYou could also just note that the two numbers -6 and 3 map to -3 so the only linear equation satisfying this would be a constant function at -3.  If you don't understand this last comment just ignore it!
954269
it is natural to write the equation of st.line as y=ax+b (now common form is y=mx+c; this has its own story!)\n\nso if x=0, y=b
733627
Rewrite the equations as:\ny = -x + 2 and\ny = (x+10)/2 = 1/2*x +5\n\nNow, if you insert x=0 in each equation, you will get a y-value.\nIf you insert y=0 in each equation, you will get an x-value.\nFor each line, you can use those two intercepts to graph the line.
822663
What are you looking for?\nSlope?\ny=mx+b form?\nI will come back to read additional details.
791058
The slope-intercept form for a line is y=mx+b, wherem is the slope and b is the y-intercept. Comparing this form to y=7x+3, you see that m=7 (the slope) and b=3 (the y-intercept).
1164791
y=mx+b\n2=2(3)+b..... (in this you know the slope is 2 b/c the line is parallel.\n2=6+b\n-4=b...... (so now you will want to write your equation for your line)\n\ny=2x-4..... (DONE!)
184980
4x-2y-6=0\n+6      +6\n4x-2y=6\n\ny-2x=-5\n*2   *2\n -4x+2y=-10\n+ 4x-2y=6 (adding the previous equation)\n  0+0=-4\n0=-4\nNo solution\n\nTo graph:\ny-2x=-5\n+2x  +2x\ny=2x-5\nGraph that\n\n4x-2y-6=0\n+6      +6\n4x-2y=6\n-4x  -4x\n-2y=-4x+6\n/-2   /-2\ny=2x-3\nAnd graph that. As you can see, the lines do not intersect, confirming the answer of no solution.
218375
4x+2y=12\n2y=12-4x\ny=6-2x\n\ny=-2x+6\n\nfrom \ny=mx+b\n\nwhere M= slope\nb= intersept\ntherefore y intersept will be +6
916256
first express the equation in the form\ny=a(x-h)^2+k\nif the a is positive itwill open upwards\nif a is negativeit will open downwards\nfor finding the y intercept put x=0\nin this form y=ax^2+bx+c y intercept will bw (0,c)\nthe vertex will be given by(h,k)
316569
y = mx + c\n(0) = (2)(-1) + c\nc = 2\n\ntherefore y = 2x + 2
664092
A n B\n(A intersect B)
829794
The standard equation for slope-intercept form is y=mx+b. m is the slope and b is the y-coordinate of the vertical (y) intercept\n\n-2x=y+3       Original equation\n\ny=-2x-3        Rewritten in S-I form\n\nm= -2, b= -3\n\nThis means that the graph of the funtion is a line through the y-axis at the point (0, -3) with a slope of (-2)
431677
If you're dealing with a straight line (and a few other types of line I think), the equation will be of the form\ny=mx+c\nThe c part will give you the y-intercept i.e. where the line crosses the y-axis.
872809
If the equation is lineear, or a line like it sounds like, the equation is y=mx+b. m is the slope or ten. and b is the y-int. or -130, and you are done
838376
Does it have to be in any particular form?\n\nThe really easy form is point-slope form, which is\ny - y1 = m(x - x1)  where (x1, y1) is a point on the line and m is the slope.\n\nSo your first one would be y - 0 = 2/3 (x - 6)\n\nwhich simplifies to y = 2/3 x - 4\n\nDo the second just like that.
881416
Slope intercept form:  y=mx+b where m= the slope and b= the y-intercept.\n\ny=2x-4
927388
y=mx+b\n\njust rearrange it so you get b as your intercept..\n\nin this case y=-1/4x +3, so the slope is -1/4, and the intercept is 3