how do you find the relative increase from data?
96543
A boy was 1.4 meter.\nLater his length was 1.5 meter.\nHis abolute grow was 0.1 meter\nHis relative grow was 0.1 m / 1.4 m = 0.071 = 7.1%.
1089687
Try this calculator, you can answer any question like that
663334
check out awstats or http://google.com/analytics
920955
You are on the right track.\n\ny(t) = y(0)*exp(k*t)\n\nWe need to find the growth constant, k and y(0).  There are a couple of ways to do this.  The most direct is to write down the equations for the two times you have data for.  This gives you two equations in two unknowns, which can then be solved for.\n\n1000 = y(0)*exp(k*40 min)\n700 = y(0)*exp(k*20 min)\n\nDivide the second equation by the first equation:\n\n700/1000 = exp(k*20 min)/exp(k*40 min)\n0.7 = exp(k*(20-40)) = exp(-k * 20 min)\n-ln(0.7)/20 min = k\nk = 1.78337*10^-2 min^-1\n\nPlug this value back into one of the equations we started with to find y(0):\n\n1000 = y(0)*exp(1.78337*10^-2 min^-1 * 40 min)\n1000 = y(0)*exp(0.71335)\n1000/exp(0.71335) = y(0)\ny(0)= 490\n\nAs a check, we can see if this gives the right result for t = 20 min:\n\ny(20 min) = 490*exp(1.78337*10^-2 min^-1 * 20 min)\n= 490*exp(0.356675)\n= 700 Check!
1011142
It's increased about 7%.\n\nThere's a calculator here: http://data.bls.gov/cgi-bin/cpicalc.pl\n\nThe actual raw data with all the historical numbers is here: http://www.bls.gov/cpi/home.htm
549479
The prior answer is exactly right, but as far as a general rule goes:\n\nDivide the current value by the present value - here, $200,000 divided by $100,000 = 2\n\nIf you want to figure out the average increase over x periods, simply take the xth root of the quotient you calculated above.\n\nHere, again, for example, you're looking for the 5th root of 2, because you're trying to figure out the average increase over 5 years (therefore, the 5th root) of 2 (the quotient)\n\nSo - using that formula here:\n\nThe 5th root of 2 (the same as 2 raised to the 0.2 power) equals 1.14869.\n\nIgnore the leading 1 - you're looking for the numbers after the decimal place. Therefore, the average rate of growth is 14.869 percent per year over 5 years.\n\nThis approach should work for any similar problem.\n\nGood luck!
52977
What I did was took the 2000 and added 500 for each month of the year and multiplied it by 1.035. then i added the 500 a month again and multiplied it by the 1.035 again. i did that until the end of the 10th year and I got 75673.15. Check this with others. this may not be exact!
517357
A 57% increase means that the 2002 figure has been multiplied by 1.57 to get the 2007 figure.  So, if we divide 2.2 million by 1.57, we will get the 2002 amount.  This works out to 1,401,274 (rounded to the nearest whole person).
1073261
% increase = 126000-120000/120000 *100\n\n= 6000*100/120000 = 5%
662293
You might be looking for Regression analysis.\nThis is the statistical technique used to look for correlations between variables.
1070468
Mutiply $28 by 0.30, then subrtact 28 again, and that should tell you how much it is. ($19.60. It will come up as -19.60 though, just ignore the negative)
323008
By calculationg it's mean. Add all the values of observations and then divide by the number of observations.\nThat's all!
191015
Since the first 3 answerers didn't really comment on where they got their answers from, I thought a more detailed answer was called for.\n\nThere's a general formula for these types of growth, which also applies to things like radioactive decay rates and interest rates:\n\nP(t) = P(0)*e^(r*t)\n\nP(t) is the population at time t\nP(0) is the population you're starting out with (the population at time 0)\ne is the "natural base" number\nr is the rate of change\nt is the time\n\nIn this case, r is .005 (.5 percent), t is 3 years (878-875), P(0) is 360, and P(t) is our only unknown.  So plug them in:\n\nP(3) = 360*e^(.005*3) = 365.440703...\nWhich rounds to 365.\n\nThe first answerer's method becomes inaccurate after a while; for example, 50 years should be 462, not 450.  The second answerer is better.  The third is just plain wrong, with no explanation of his methods.
163979
Try the Bureau of Labor Statistics :)
180050
try your national statistics office
1064501
This is how I would do it.\n\n 12......19\n-----  =  -----  ignore the periods in between 12/19 and 100/x\n100.....x\n\n12x = (19) (100)\n12x = 1900\n12x / 12_= 1900 / 12\nx =158.3\n\n158.3 - 100 = 58.3% increase
926663
the slope of the graph. the formula is rise/run. take 2 points X1,Y1 and X2,Y2  plug them in the formula X2-X1/Y2-Y1. youll get the rate of change! Best of Luck!