How do I accurately read a dial caliper or vernier when measuring the outside dimensions of an object?
96567
got a dandy.....even though  it  seems  difficult   youll  break through  and  find  out  you can  almost  measure  anything....try  this  because  i dont  know  what  type  of  equipment  you have....in  search  bar  go.....vernier  read .. hit search..the  NTNU site java  is  excellentyou you can  even  practice  measuring  on  line.....reading  a  vernier  is  good too.....check  them  all
618692
the correct option is e \n the value of i radian is 180/pi = 57.3248 ( if pi is 3.14)
1116867
try the conversion table. europe uses metrics
76603
A vernier caliper allows size measurement to a greater precision than that available from a single calibrated scale.  From the referenced web page, referring to a specific vernier caliper: "The vernier consists of a main scale engraved on a fixed ruler and an auxiliary vernier scale engraved on a movable jaw [...]. The movable auxiliary scale is free to slide along the length of the fixed ruler. This vernier's main scale is calibrated in centimeters with the smallest division in millimeters. The auxiliary scale has 10 divisions that cover the same distance as 9 divisions on the main scale."\n\nThus the length of each division on the aux scale is 0.9 mm.  The user closes the caliper on the object to be measured.  If the left end of the aux scale aligns with a millimeter mark on the main scale, the size is that indicated by the mark.  Otherwise the user finds the aux-scale mark (call it X) that most closely aligns with a main-scale mark, and adds 0.1 mm for each aux-scale division of distance X is from the left end.  This gives 0.1 mm resolution.  A sharp-eyed user can improve on that by noting how well-aligned X is compared to adjacent aux-scale marks.  If this is unclear, visit the web site to see the article which includes pictures.
720092
While the answers above are correct, I will go a bit further.\n\nEstes rockets sells a nice tool for just this very job that will make your measurement fairly easy and accurate. It is called AltiTrak (TM).\n\nhttp://www.estesrockets.com/cgi-bin/products.cgi?view,296
191332
Find the dementions and multiply.
449028
check out the internet\n\ngo onto yahoo.com and type in metric conversion calculator and you should get a website that will let you convert pretty much anything into just about anything
720465
ANSWER: 643.241 sq mm\n\nEXPLANATION:\nLet the radius of the inner circle (black portion) = r\nand that of the outer circle = R.\nAlso let the eccentricity = e.\n\nOn y-axis of the crosshair\nR - 5 = sqrt(r^2 - e^2)\nSquaring both sides\n(R-5)^2 = (r^2-e^2)___________(1)\n\nNow consider the x-axis of the crosshair,\n2R - 2r = 9\nor R - r = 9/2\nor R = 9/2 + r ___________(2)\n\nBut e = (difference of radii) \nSo e = R-r = 9/2 _________(3)\n\nSubstituting R from eqn(2) and e from eqn(3) in eqn(1)\n(r+9/2-5)^2 = r^2-(9/2)^2\nor (r-1/2)^2 = r^2-81/4\nor r^2-r+1/4 = r^2-81/4\nor r = 81/4 + 1/4 = 41/2\n\nThen R = r+9/2 = 41/2+9/2 = 50/2 = 25\n\nNow, area of the white region \n= (Area of outer circle) - (Area of inner circle)\n= (pi*R^2) - (pi*r^2)\n= pi*(R^2 - r^2)\n= pi*{25^2 - (41/2)^2}\n= 643.24 sq mm
908965
the answer is pi 3.14. use the pythagoran therom with x= pi(r2) then compensate for the remainder and it'll work itself out. If that doesn't work, try FOIL. first, outside, inside, last.
136243
measuring device of some sort (scale, ruler, thermometer)
50418
"Reading  the  vernier  micrometer  is  the  same  as  reading the standard micrometer. An additional step must be taken,  to  add  the  vernier  reading  to  the  dimensions.  This allows  for  precise  measurements  which  are  accurate  to ten-thousandths (0.0001) of an inch. This scale furnishes  the  fine  readings  between  the  lines  on  the  thimble rather than making an estimate as you would on a standard micrometer."\n\nThe site below has illustrations that make it very clear how to read it:
691057
Imagine cutting the tube down its length and opening it up into a long, narrow rectangle.  The outside area would be the length times the width.  The width of the rectangle is really the circumference of the circular cross section of the tube.  Thus, since you know the diameter, you have this:\n\nsurface area = length * pi * diameter\n\nwhere pi is approximately 3.14159265358979.\n\nNote, if the tube is not flexible, you have to be careful measuring the length of the bent tube.  it is the length of an imaginary line through the center of the tube, but as the other answerer pointed out, you can get this by taking the average of the "inside the curve" length and the "outside the curve" length.  Of course, if the tube is flexible, just straighten it out and measure it.\n\n\nNote--straightening, cutting and opening up, etc., will change the area slightly as it stretches part of the tube and compresses another part--this is a very small effect (unless you tie the tube into a tight knot or something) and probably can't easily be measured well anyway--should be too small to matter in most applications.
238652
Assuming you have a rectangular object, then L x H x W will work. For other shapes you need something else. See sources.
728902
This can be done easily using a scientific calculator or there are many angular / decimal tables in Trig text books or many machinists handbooks or machinists guides.\n\nwww.industrialpress.com/en/tabid/63/Default.aspx
151657
There is no answer to that question.\n\nMillimeters is a measure of length and arc seconds are a measure of angle. It's like asking how many mm in 30 degrees.\n\nYou need to know the distance to the object or thing that you are measuring to be 0.2 arc seconds across. Then you can use the pythogorean theorem to calculate the length in mm. (As long as the object is reasonably far away, if it is very close then you can't make the approximation of a right triangle.)\n\nadded:\nkirchwey is absolutey correct!\n\nach! its been too many years since I did this stuff!
1022457
Type O or Offset <enter>\nClick on Object to be offset <enter>\nType in distance to offset <enter>\nClick on side to offset \nGame over!!!!
1098468
If you are measuring something with a round cross section, make sure that the axis of the object is perpendicular to the caliper. This is necessary to ensure that you are measuring the full diameter and not merely a chord.