how to parse numbers in java?
83391
parseInt Method of Integer Wrapper class is used to parse integer from a string.\nsyntax:\nInteger.parseInt(string)\nit returns a integer value so an integer is used the store the return value at the left hand side of assignment statement.
946903
Numbers 1 - 9 are spelled out, once you get to10 and above, you can just use the numerals. Here's a web site to prove my point...\n\nhttp://www.grammarbook.com/numbers/numbers.asp
945798
Most people use a base 10 system. Whatever you use, the base is that "Unreachable" number. For example, in base 10, there is no digit for 10, you start a new column representing how many 10's you've amassed. You have a 1's column a 10's column a 100's column and so forth. To get the numerical value you multiply (most people are so used to it, they just do it in their head). If the number is 823 you can express it as 3X1 plus 2X10 plus 8X100\n3x1 = 1\n2x10 = 20\n8X100=800\n-----------------\n1+20+800= 821\n\nSo 3 plus 20 plus 800. Make sense?\n\nIn binary "2" is the unreachable number, so you go 1, 10, 11, 100, etc. You have a 1's, 2's, 4's, 8's column.\nThe number 11011 would be 1Xone, plus 1xtwo, plus 0Xfour, plus 1xeight, plus 1x16 or 27 in base 10.\n\n1x 1 = 1\n1x 2 = 2\n0x 4 = 0\n1x 8 = 8\n1x16 = 16\n---------------\n1+2+8+16=27\n\nLet's look at your specific numbers 1011, that's \n\n1  x  1  =  1\n1  x  2  =  2\n0  x  4  =  0\n1  x  8  =  8\n--------------------\n1+2+0+8= 11\n\nYour top number is 11 (in base 10)\nYour bottom number:\n\n1 x 1 = 1\n1 x 2 = 2\n----------------\n1+2=3\n\nSo the problem states 11/3, that's pretty easy. 3.666(repeating)\n\nWith practice, it becomes easier. You learn to recognize the column values and mulitply in your head. \n\nHope that helps,\nOdd
623394
IsNumeric will tell you if a value being passed into it can be converted into a number, were you to try to run Decimal.Parse on it. You might use it like this:\n\nFunction Translate(Foo as String) As Decimal\n    if IsNumeric(Foo) = True then\n      Return Decimal.Parse(Foo)\n    Else\n      Return 0\n    End if\nEnd Function
465084
string alpha="AAAABBBBAAAA"\n\nstring one=alpha.substring(0,4)\nstring b=alpha.substring(4,4)\nstring three=alpha.substring(8,4)\n\ni hav used substring which is valid in java,c,c++,visual basic,c#.
972788
Put a number in box A1\nPut a number in box A2\nClick in box A3\ntype "=A1-A2"\n(you don't type the question marks, just what is inside them)\nHit enter
978426
for example:\n\n-1 < 2\nthen\n1 > -2\n\nanother:\n x < -5\nthen\n-x > 5\n\n-2 x > 9\nx< -9/2\n\ns
74472
Use ToString() with a format, like ToString("#.00"), as in...\n\nDim test As Double\ntest = 0\nSystem.Console.WriteLine(test.ToString("#.00"))
902613
I just plugged this into my calculator.\n\n[1, 0, 2, 0, 2, 0 | 0\n0, 1, -3, 0, -2, 0 | 0\n0, 0, 0, 1, -1, 0 | 0\n0, 0, 0, 0, 0, 1 | 0\n0, 0, 0, 0, 0, 0 | 1 ]\n\nTake it however you want.
392646
You usually do this by using a programming language and comparing the input to a regular expression.\n\nLook up "regular expression tutorial" in Yahoo search and you'll find more information that you probably want  :)
1158354
This does not require hiring a professional, it's a rather simple & straightforward program. \n\nRaven put you on the right track, use the modulo (%) operator to break out the thousands from the hundreds, the hundreds from the tens, etc.  Define an array or map of strings with the words for each number up to twenty, then thirty, forty, fifty.. to ninety, then hundred, thousand.  Break the number apart, and get the appropriate words from the array & string them together.
38545
There is a split method in String Class. (See the source mentioned below). \n\nThere is also one more generalized Class called StringTokenizer, which is also used to split strings with various delimiters.
755691
U have to use JavaScript for calculations.\nThere is a function 'eval' in JavaScript that takes the operators and operands as input and returns the result.\n\nE.g:  eval(7*5), it will return 35.
1184383
put the number of the decimal over a 1 with the number of digits in the decimal number following it\n\nExamples\n0.1 = 1/10\n0.11 = 11/100\n.123 = 123/1000
513609
Well I can't tell u how to do it b/c that would be wrong. But yes. You have to use IndexOf, IsNumeric, substring, and focus. So yes u are the right track. Contact me at free_best_jack@yahoo.com if you have any more questions.
241489
Try any of this code\nDim i as integer=Convert.ToInt32("your number as string")\nor\nDim i as integer=Val("your number as string")\nor\nDim i as integer=CInt("your number as string")
376319
Are you able to use any other numbers and operators?  If so this would be fairly easy.  Using only Three 8's and a subtraction symbol it is not possibe\n\nClosest example (8+8)/8-1=1