Please help me solve this math problem and please break it down! Thanks!?
89158
r u crazy? i dont know maths
22859
Subract the two terms on the left giving:\n-2t < 16\n\nAdd 2t to both sides giving\n0 < 16 + 2t\n\nSubtract 16 from both sides\n\n-16 < 2t\n\nDivide both sides by 2\n\n-8 < t
290027
9 - 48m^2 or 9(1-4m^2)\nthe 1 before the second set can be dropped, it's implied. Read it like this:\n(3*3)-(3(4m*4m))\n(9) - (3*16m^2)\n9-48m^2\nThen divide it all by the common 9\n9(1-4m^2) : That's your answer
777951
Tackling the problem bit-by-bit:\n\nFirst, let x = the larger number\nlet y = the smaller number\n\nYou can write out an equation to show their relationship of "difference" by:\nx - y = 68\n\nNext, you write out the equation to show their quotient relationship by:\nx/y = 5\nwhich gives:\nx = 5y\n\nNow plug x = 5y into the "difference" equation:\n(5y) - y = 68\nwhich gives\n4y = 68\nwhich gives \ny = 17\n\nNow plug y = 17 into the "difference" equation:\nx - 17 = 68\nx = 85
641208
The best place to go for math help online that i found was \nhttp://www.math.com\nI hope its useful to you.  I know people on here can tell you the answers, but if you have a test to take, and want to really learn it, go there.
1169872
(7/(3x)) / (x/3)\n(7/(3x)) * (3/x)\n21/(3x^2)\n7/x^2\n\nBut if you meant\n\n((7/3)x)/(x/3)\n((7x)/3)*(3/x)\n(21x)/(3x)\nANS : 7\n\n-------------------------------\n\n2 1/3 - 3/4\n2 1/3 = (7/3)\n\n(7/3) - (3/4)\nMultiply everything by 12\n(28 - 9)/12\n(19/12) or 1 (7/12)
954300
ok\nso its factoring.this is hella easy.10x+40 is 10(x+4)\nso the answer is 10(x+4)there you go
897429
This is the third time that this question has been asked!?!?!\n\nIt's a tough one, too.\n\nI'm taking it to work with me and asking my colleges to help me out on it.\n\nThis is as far as I got:\n(2B+1)^(D-E) - F^(3G+G2) = (10J)/A\n\nBut someone "did" crack this CHALLENGE Question.\n\nSo here's the answer. . .\n\nhttp://answers.yahoo.com/question/index;_ylt=AvnsMpyNhtwrHV1JVMvXrE4jzKIX?qid=20061130045858AAB57A7\n\nANSWER:  ABCDEFGHJ = 25,693,148\n\nA=2\nB=5 \nC=6\nD=9\nE=7\nF=3\nG=1\nH=4\nJ=8
255329
Have patience :)  You got some answers the first time you asked this.  Here it is again:\n\nIt does not get eliminated, it gets split up into the 2 factors.\n\nOn this one, you can go ahead and divide by 2 to make things a little easier. You'll be left with\n\n3x^2 - 7x - 6 = 0\n\nNow to factor. You need 2 numbers whose product equals 3*-6, or -18 and whose sum equals -7. From this point on it's just sort of educated guessing. \n\n1*-18 = -18, but 1-18 = -17, so that won't work\n2*-9 = -18, and 1-9 = -7 -- THIS ONE WORKS!! yay!\n\nSo now you can rewrite your problem as\n\n3x^2 - 9x + 2x -6 = 0 and group the first 2 and last 2 terms\n\n(3x^2-9x) + (2x-6) = 0 -- you can factor a 3x out of the first group, and a 2 out of the second\n\n3x(x-3) + 2(x-3)=0 -- and now you can factor an (x-3) out\n\n(x-3)(3x+2)=0\n\n~~~~~~~~~~~~~~~~~~~\nOops, you're right. I was typing too fast.  Oh well, I still got the right final answer :)  Thanks
193851
to be able to solve this you'll need to see a pattern, because it is obvious that, that is the only way.\n\nnow look at this,\n\n2^1 / 11 , R = 2             \n2^2 / 11 , R = 4             \n2^3 / 11 , R = 8             \n2^4 / 11 , R = 5             \n2^5 / 11 , R = 10            \n2^6 / 11 , R = 9             \n2^7 / 11 , R = 7             \n2^8 / 11 , R = 3             \n2^9 / 11 , R = 6             \n2^10 / 11 , R = 1            \n\n2^11 / 11 , R = 2\n2^12 / 11 , R = 4\n2^13 / 11 , R = 8\n2^14 / 11 , R = 5\n2^15 / 11 , R = 10\n2^16 / 11 , R = 9\n2^17 / 11 , R = 7\n2^18 / 11 , R = 3\n2^19 / 11 , R = 6\n2^20 / 11 , R = 1\n\n\ndid you see a pattern? so if you follow this pattern you will see the the remainder of 2^1344452457 / 11 will be, \n\n7.
390719
so you have (1/2)a+a-(6/3)=4+(1/3)a\n\nadding like terms: (3/2)a-2=4+(1/3)a\n\nsubtract (1/3)a from (3/2)a and add two to both sides:\n(3/2-1/3)a=4+2\n(9/6-2/6)a=6\n(7/6)a=6\n\nnow solve and what do you get? :)
154380
I posted these sources earlier to someone else who was looking for math help.\n\nGood Luck!!
712544
ok so you know 15 can only be broken down to 5*3, -5*-3, 15*1 and -15*-1\ntherefore when you break it up\n(x+3)(x+5) using FOIL (I assume you know how to do that) k would equal 8. For (x-3)(x-5) k would be -8. Do the same for the set of (x+15)(x+1) and (x-15)(x-1)
311639
i don't understand the question...email me at too_cool2kissz_ne1@yahoo.com and break it down 4 me
756828
The objective of this problem is to "solve for t" which means to isolate it on one side of the equation, hoping that only a number appears on the other side.\n\nBegin by distributing the (-6) factor through the left-hand side's other group of terms:\n\n-24 + 6t = 12t\n\n... being careful to let the two minus signs "cancel each other out" and become a + sign.\n\nNow, we hope to "collect like terms" -- that is, terms containing 't' -- on the right side.  Do so by subtracting 6t from both sides:\n\n-24 = 6t\n\nNow, finally, divide by the "coefficient of t" which is 6:\n\n-4 = t\n\nAnd there is your solution!\n\nMany teachers instruct you to "check your work" by substituting the "answer" back into the original problem, to make sure it is correct.  Let's do that here:\n\n(-6)(4-(-4) = 12(-4)?\n\nSimplify the left-hand slightly:\n\n-6 * (8) = -48?\n-48 = -48\n\nYes!  This yielded a true mathematical statement, hence our solution of t=-4 was correct all along.\n\nHope this helps!
859897
***************\nQUESTION 1\n***************\nOn the first question, we first have to find the equation that we will be solving for.  \n\nAssume that x is one integer.\nWe know that x+1 is the other integer because they are consecutive.\n\nSo we now put the wording into an equation\n1/3(x + (x+1)) = x - 5\n\nNow we solve the equation\n1/3(2x + 1) = x - 5\n2/3x + 1/3 = x - 5\n16/3 = 1/3x\n16 = x\n17 = x + 1\n\nOur two integers are 16 and 17.\n\nNow we check our answer.\n1/3 of 33 = 11 & 16 - 5 = 11 We are good! :)\n\n\n***************\nQUESTION 2\n***************\nEvery hour, Amy and Randy together walked 3.6 + 4.2 km apart from each other.\n\n3.6 + 4.2 = 7.8\n\nSo, every hour they will be 7.8 more km apart from each other.  We only want 10 minutes though, and there are 60 minutes in an hour. To get how far apart they will be in 10 minutes, we take:\n7.8 * 10/60 = 1.3\n\nRandy and Amy will be 1.3 km apart after 10 minutes.\n\nWe are done! :)
517123
It's hard to show it clearly here but the solution is actually:\n\n[-b±√(b²-4ac)]/2a\n\nthere will usually be two solutions!\nThe site below has it laid out more clearly...\n\n("invited" to leave school early.. 1974)