can anyone explain physics to me.?
90314
Check out these sites. Or just google your topic.\n\nhttp://www.physicsclassroom.com/Class/waves/U10L3b.html\nhttp://www.bbc.co.uk/schools/gcsebitesize/physics/waves/reflectionrefractionanddiffractionrev1.shtml\nhttp://physics.bu.edu/~duffy/PY106/Reflection.html
210676
Use free body diagram to balance the forces and u can derive the equation of motion \nIf u want i can give u full derivation.\n"::
659755
Physics= motion= speed, distance, displacement, velocity, time.\n\nSo you understand that the whole universe is made out of motion and motion = physics, think carefully and you will see that there is not one thing that does not apply to at least one of these things.\n\nLife is a recipe with many important ingredients and physics is one of them!
696750
try the following. they are really helpful.\n\nwww.tutor4physics.com\nwww.physicsclassroom.com
976575
Hi Mark, I will answer your question if you answer mine first.\nWhy are you asking this question, it seems like a lot of people in school are trying to take the easy way out of a physics or math problem.\nWill answer if you are not doing said above!\nCheers, Susie
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Try reading this, it should answer your question.\nhttp://phyun5.ucr.edu/~wudka/Physics7/Notes_www/node58.html
481524
Sports is a pretty easy way to explain physics of all sorts...  \n\nEnergy to heat (of exertion)...\n\nKinetic energy of the vaulter/gymnast being transferred into the spins, jump, landing...\n\nPotential energy meets kinteic energy: football (U.S.) linemen\n\nCircular forces (centrifugal/centrifical) / angular momentum: a speed skater around a corner\n\nEffect of friction/gravity/force on object with specific mass: skiing\n\nTransfer of kinetic energy: golf club to ball, kick to ball,\n\nKinetic meets kinetic: baseball meets bat - net sum of energy of bat in positive direction + energy if ball in negative direction = distance/height ball travels.  Same with volleyball\n\nAcceleration/deceleration of gravity: balls making arc \n\nHowever, you say you want to "analyze a problem with sports" - do you need quantitative examples or just be able to explain all the forces at work with one particular problem?
1014316
would you like to supply me with some formulas? im out of grade 12 physics and i forgot most of the formulas. trust me from experience, just plug numbers into a formula and things will work\n\nF=mg = ma\nFk=μkN\na= vf^2 - vi^2 / 2d
712396
Here's a nice explanation:\nhttp://www.4to40.com/QA/index.asp?counter=382&category=science
731157
Have you tried asking this question under the heading Science & Mathematics > Physics? You might have a better audience there.
494540
Haha whats with all these answers, if you know basic physics, One of Newtons laws of motion is that:\n\n"for an object that is stationary or travelling at constant velocity, no force acts."\n\nso you ask what is the force?\nthere is no resultant force, the driving force and resistance are equal and cancel each other out.\n\n\nAnd additionally the basic equation to find force is:\nF=ma (force = mass x accelleration), this is evidence that an accelleration needs to be taking place for a force to act.\n\nLets say you want the force for a 50kg object accellerating at 3ms-2. F=ma  ->  F=50x3 ->  F=150N.\n\nNow lets say you want the force for a 50kg object travelling at constant velocity, no accelleration.\nF=ma  ->  F=50x0  ->  F=0N\n\n\nThere you go, wasnt that easy
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first answer me this, WHY THE HELL IS THIS IN THE PHYSICS CATEGORY?
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i dont know much about physics but i did a search and this is what i got hope it has what you're looking for:\n\nhttp://science.electronicsinfoline.com/Physics/Electricity_and_Magnetism/
454258
can u explain further?
933787
plz ask in physics category
279554
I don't understand. Elaborate?
655249
I know the following two ways:\n\n1) Force on a body  is directly proportional  to the product of it's mass and acceleration, F=K*m * a(k=constant).The units are so chosen so that K=1.\n Your's is also correct but it is limited to free falling bodies, where a=g=9.8 m/s^2.\n2)Force is directly proportional to the rate of change of momentum.\nF=k*(change in momentum,p)/t=K*p/t. Again K=1 for same reason..\nBoth are related as p=m(v-u)/t=m*a.\nv=final velocity, u= initial velocity.\nhope it helps.