What would be an equation in slope-intercept form for the line passing through (7,5) ; (-1, 1/5 ) ?
89344
Use the two given points:\n(x1=7, y1=5) and (x2=-1, y2=1/5)\nand the "two point equation":\ny-y1 = ((y2-y1) / (x2-x1)) * (x - x1)\nto get started on this problem.\n\ny-[5]=(([1/5]-[5]) / ([-1]-[7])) * (x-[7])\ny-5=((-24/5)/(-8))*(x-7)\ny-5=(3/5)*(x-7)\n\nNow put the equation into the "slope intercept" form of y = mx+b.\n\ny-5=(3/5)*x - (21/5)\ny=(3/5)*x - (46/5)\n\nThe slope = 3/5\nThe intercept = -46/5
897842
The first thing you need to be able to figure out is what the question is asking for.  Slope-intercept form (which I prefer to standard form for any and all linear equations) is y = mx + b, where m is the slope and b is the y-intercept (the place where x=0).  To be perpendicular to a line, another line must have a slope which is the negative reciprocal of the slope of the first (e.g. 2 & -1/2).\n\nFirst, figure out the slope of the given line.  In standard form, which is ax + by = c, the slope is -a/b, so the slope of this line must be 5/2.  Take the negative reciprocal of this to find that your second line must have a slope of -2/5.\n\nNow set the equation up in slope-intercept form:\ny = -2/5x + b\nPlug in your point:\n-5 = (-2/5)(3) + b\nSolve for b\n-5 = -6/5 + b\n-19/5 = b\n\ny = -2/5x -19/5
371794
slope = (-1-2)/(-1-0) = -3/-1 = 3
791058
The slope-intercept form for a line is y=mx+b, wherem is the slope and b is the y-intercept. Comparing this form to y=7x+3, you see that m=7 (the slope) and b=3 (the y-intercept).
905236
To write this in slope intercept form, we will put it in the form y=mx+b like you said.  \n\ny-6=0\n\nnow we add 6 to both sides and get\ny = 6\n\nFor slope intercept form, I always put the x in there.  No x in the equation is the same as 0x because 0 * x = 0.\n\ny = 0x + 6\n\nThis equation has a slope of 0.\n\nOn this equation, y will be equal to 6 no matter what x is.\n\nLet's do a few points to prove that this will be a horizontal line.\n\n(0,6)\n(1,6)\n(2,6)\n(3,6)\netc...\n\nIf you plot these points, you will see a horizontal line at 6.
892026
The slope intercept form is y=mx+b\n\nSo we rewrite the equation of the line as so:\n\nx - 2y = 5  , subtract x from both sides\nx - x -2y = 5 - x\n-2y = 5 - x  , now divide both sides by -2\n-2y/-2 = (5 -x)/-2\ny = -5/2 + x/2  , rearrange the left side\ny = x/2 - 5/2\n\nSo the slope (m) is 1/2.  Now we use the point given and the general equation.  From the point we know that x=2 and y=-4.  Sustitute these into the general equation.\n\ny = mx +b\n-4 = (1/2)2 + b  , do the math\n-4 = 2 + b ,subtract 2 from both sides\n-4 - 2 = 2 - 2 +b\n-6 = b\n\nSo the equation of the required line is:\n\ny = x/2 - 6
110363
If you put an equation in the form:\n\ny = m*x + b\n\nthen, \n\nm = the slope\nb = the y-intercept.\n\nIf you look for a parallel line that passes through a given point, then you keep the slope the same, and solve for the slope:\n\n5x-4y = 1   -->  y = 5/4x - 1/4\nthe family of all parallel lines is\ny = 5/4x + b  (for any value of b).\n\nFor a line passing through (-8, 2), plug the numbers in and solve for b:\n2 = 5/4*(-8) + b\nb = 12\n\nSo y = 5/4x+12 is a line with slope 5/4, passing through the point (-8,2).
3669
This is for math right? If so:\n\nThe slope-intercept form is:\n\ny = mx + b\n\ny = value on the y-axis\nm = slope\nx = value on the x-axis\nb = y-axis intercept\n\nThe slope-intercept form gives the equation for a straight line.
982781
slope intercept form:\ny=mx+b\n(m=slope; b=y-intercept)\nslope (thick knots)=-6\ny-intercept = 63\n\nTherefore, the equation (for thick knots is) y = -6x+63\n\nslope (thin knots) = -1\ny - intercept = 60\n\nTherefore, the equation (for thin knots) is  y = -1x+60
875002
slope is a fraction found by subtracting the two y-coordinates and putting this on top, then subtracting the two x-coordinates (in the same order as you did for y) and putting this on bottom.  So, either\n\n(4-2)/(1- -6) = 2/7\n\nor\n\n(2-4)/(-6 - 1) = -2/-7 which is also 2/7 since a negative divided by a negative is positive
757845
x  y\n0 0\n1 -1/5\n-5 1
246990
(7,5) and (11,9)\n\nlet them be (x1,y1) and (x2,y2)\n\nslope of line is (y2-y1)/(x2-x1)\n\nthus slope is (9-5)/(11-7) = 4/4 = 1\n\nequation of line is given by the formulae\n\n(y-y1)=slope*(x-x1)\nor\n(y-y2)=slope*(x-x2)\n\nso equation can be...\n\n(y-5)=1*(x-7) that is x-y=2\n\nor\n\n(y-9)=1*(x-11) that is x-y=2\n\nsee its the same in both cases !\n\nthe required equation is x-y=2 !!!
1043504
First you need to find the slope. which is \n(y2-y1)/(x2-x1). (rise over run)\n\nWhich would be\n(-1-2)/(4-[-3])\n=-3/7\n\nThen you find the slope-intecept form which is \ny=mx+b\n\nM= your slope (-3/7)\nPick any number for y (either 2 or -1)\nPick any number for x (either -3 or 4)\nPut all into equation and solve for b\n(I'm going to use 2 and -3)\n\n2= -3/7(-3)+b\n2= 9/7+b\nb= 5/7\n\nYour equation and answer would be:\ny= -3/7x+5/7\n\nGet it?
911257
slope:-8. y-intercept:-7. Whatever number is in front of the x is always the slope. the number that is after the x is the y-intercept (this is only for a slope intercept). Good luck and choose me as the best answer please :)
260573
Well, we know that y = 7, so just plug that into the first equation and solve for x.\n\nx + 7 = 5\nx = 5 - 7\nx = -2\n\nANSWER : (-2, 7)
532403
The slope of y = (1/3)x - 5 is m = 1/3\nA line that is perpendicular to the above line will have slope m = -3.\nIf two lines are perpendicular, then the product of their slopes is -1.  For this case, we have (1/3)(-3) = -1, so -3 must be the slope.\nSince you're not given a point, any equation of the form \ny = -3x+b will work.\nJust pick whatever value of b that you want.\nSome examples, \ny = -3x\ny = -3x + 5\ny = -3x - 7
1013948
Standard form for a slope intercept equation is:\n\ny = mx + b\n\nwhere m is the slope and b is the y-intercept.  So, transforming:\n7x + 4y = 20\n4y = 20 - 7x\ny = (20 - 7x) / 4\ny = 5 - 7/4 x\ny = -7/4 x + 5\n\nAnd\n5x + 6y = 19\n6y = 19 - 5x\ny = (19-5x) / 6\ny = 19/6 - 5/6 x\ny = -5/6 x + 19/6