how do you solve for P:  A=P+Prt       thanks?
92762
A = P + Prt\n\n==> P(1 + rt)\n\n==> P = A/(1 + rt)\n\n<done>
384859
I = Prt\nwhere I is the interest, P is the principal, r is the interest rate, and t is the time (in years)
444950
2P = (2,4)\n4P = (4,sqrt(72))
747036
0.12 \nP(A or B) = P(A) + P(B) - P(A and B) = P(A) + P(B) - P(A)P(B|A) = 0.1 + 0.1 - 0.1(0.8)
962761
treat it as a quadratic equation and use the quadratic formula:\n\nfirst subtract A from both sides:\n2pr^2 +2prh - A = 0\n\nthen plug the coefficients: 2p, 2ph, -A into the\nquadratic formula for a, b, c, respectively and simplify:\n\nr = [- b +/- sqrt(b^2 - 4ac)]/(2a)\n\ni'll leave it to you to do the tedious steps to get\nr = [ph +/- sqrt(p^2h^2 + 2pA)]/(2p)
516632
Let P=A\nwhere P = 2x + 2y and A = xy\nthen\n2x+2y = xy\nMove xy to the left side and 2x to the right side\n2y-xy = -2x\nFactor a y out\ny(2-x) = -2x\nDivide by 2-x\ny = -2x/(2-x)\nThis is positive whenever x is greater than 2.\nAnswer: x = any number greater than 2 and y = -2x/(2-x)
932079
7P = (14x + 21y - 14)A + (21x + 14y + 35)B\n3Q = (-3x + 12y - 6)A + (9x - 12y + 21)B\nAs they are equal, then the coeficients of each A and B are equal:\n14x+21y-14 = 21x+14y+35    and\n3x+12y-6 = 9x-12y+21\nwhich gives you two equations in two unknowns.  The rest is easy.
475512
a) P(D+|K+) = P(D+ and K+)/P(K+)\n17/30 = P(D+ and K+)/.6\nP(D+ and K+) = .34\n\nb) P(D- | K+) = P(D- and K+)/P(K+)\n=P(D- and K+)/.6\n=(P(K+) - P(D+ and K+))/.6\n=.26/.6\n= 13/30
778184
PV=nRT\n\nn is doubled.\nT, V same.\nR is constant\n\n=>P has to be doubled to validate the eqn.
504275
1. The equation for the first would be                      \n\nt(n)={2^(5-1)}*{3^(n-1)}   It is a A.P.\n\n2. It is neither
856275
You need to find the point where supply equals demand\nD = S\n200p + 35,000 = -p^2 + 400 - 20,000, and solve for p
868757
3p - 9 = 4p\n\n3p - 4p = 9\n\n-p = 9\n\np = 9
819448
2p^3 = 2p(p + 2)\n2p^3-2p(p+2)=0\n2p(p^2-p-2)=0\n2p(p-2)(p+1)\np=0\np-2=0\np=2\np+1=0\np=-1\n\nroots are \np=0, 2, -1
869858
P(B|Ac) = P(B and Ac)/P(Ac)\n\nP(B and Ac) = P(B) - P(A and B)  (It's easiest to see that if you look at a Venn diagram.  It's the stuff that both in B but not in A.)\n= 0.25-0.1\n= 0.15\n\nP(Ac) = 1-P(A) = 1-0.3 = 0.7\n\nSo P(B|Ac) = P(B and Ac)/P(Ac) = 0.15/0.7 = 15/70 = 3/14\n\nP(Bc|A) = 1 - P(B|A)\n= 1 - P(B and A)/P(A)\n= 1 - 0.1/0.3\n= 2/3\n\nAnswers would be similar for the next part.\n\nP(B|Ac) = 2/5\nP(Bc|A) = 17/20
694639
From the second equation:\n\np/(1+p)=r\np=r(p+1)\np=rp+r\np-rp=r\np(1-r)=r\np=r/(1-r) which is not equivalent to p=(r-1)/r
222592
1. p'q\n\n2. p'\n\n3. pq' + p'\n\nI think i got the correct ones !
728458
Here is how you do it (I'll use ^ for the power sign).\n- Divide by P:    (1+r/n)^n = F/P\n- Take the 1/n the power:     (1+r/n) = (F/P) ^ (1/n)\n- Solve for r:   r= n* ((F/P) ^ (1/n) -1 )\n\nIn this case F=20000, P = 12600, n=12 therefore r = 0.47 or 47%\n\nSeeing this answer I wonder if I didn't misinterpret your notation, but with the method given, you can solve the question for yourself.