Factor completely. 5a^2 – 125?
81890
it's not factored completely if you leave it as a^2-25 so the proper answer is 5(a-5)(a+5)
734679
5a^2 + 3a - 2 = 0\n\ncan be factored as (5a - 2) (a + 1) = 0\nThus a = 2/5 and a = -1
706038
125 = log(x^2/1.5) \n125 = 2/1.5 logx  [using logx^m = m logx]\n(125*1.5)/2 = logx\n93.75 = logx\nx = antilog (93.75) OR x = e^93.75
533127
2*2*2*5*5 or 2to the third power times 5 to the second power
798535
x^3 - x^2 + 5x + 5\n\n(x^3 - x^2) + (5x - 5)\n\nx^2(x - 1) + 5(x - 1)\n\nsince both x^2 and 5 have the same factor, you can factor it to\n\n(x^2 + 5)(x - 1)\n\nif you want, you can either leave it that way, or\n\n(x + sqrt(5i))(x - sqrt(5i))(x - 1)\n\nwhat you can probably just leave it as (x^2 + 5)(x - 1)\n\nyou can also try www.quickmath.com, click Factor under Algebra, then type in x^3 - x^2 + 5x - 5, then click enter. \n\nAnymore Questions Ask ME
943073
sqrt(5/12a)=sqrt(1/4)*sqrt(5/3a)=(1/2)*sqrt(5/3a)
677061
i think this formula works.\nfactorial of A-4A\nso.using this formula the correct answer is 5012
737484
5^-2 = (1/5)^2 = (1/5)*(1/5) = (1*1)/(5*5) = 1/25
920470
The answer is:  4.47, and that's all there is to it!\n\nOk Vanessa, all you have to do is pull up your calculator (Start>Accessories).\nI am not suggesting you don't work it out in your head first: it's just basic. Check the answer on the calc, or, if you get stuck....go back.... to POWERS OF HIGH HOLY ROOTISM   SQUARE YOU KNOW, 1x1+(2x2)+2+(10-5)/1=       Simple:\n1+4+2+5/1=12
771554
(x+5)(x-5)\n(x)^2-(5)^2\n=x^2-25
872016
Factor out the constants:\n2, 5, (3 X 5)\nYou can eliminate the extra 5, since that only needs to appear once, and then multiply the remaining numbers together:\n2 X 5 X 3 = 30\nThen multiply by the highest power of each variable present in any of the numbers to get your answer:\n30x^3y^2
831044
2x² - 10a\n\n2a(a - 5)\n\nThe answer is 2a(a - 5)\n\n- - - - - - - -s-
96233
+5,+12, -5, -12, +3.3
30589
2(5)-5(5)+2(5)=\n10-25+10\n20-25\n-5
254834
if you use quadratic formula you get the factors of \n\nx= ( ( 3 +/- square rt.(5) ) / -6 )
689918
use  power rule and product rule\nf'(x)=[1/5]*5*x^4 + 2x(x^2-x-9)+ \n(x^2+9)(2x-1) + 0=\n\nx^4 + 2x^3 - 2x^2 -18x + 2x^3 - x^2 +18x -9 =\n\nx^4 + 4x^3 - 3x^2 -9
792279
25a^2-20a+4\n= 25a^2-10a-10a+4\n=5a(5a-2)-2(5a-2)\n= (5a-2)(5a-2)Ans.