How to solve this?????
85313
1.)The area of a carpet is 308sq.m. If its length is 2m less and its width 6m more, the carpetwill be square. Find the dimension of the carpet...\n\nSo we can see the length of the carpet is 8m longer than the width\n\nL B = Area\nL (L-8) = 308\nL^2 - 8L - 308 = 0\n(L-22)(L+14) = 0\n\ntherefore L=22m or L= -14m\n\nNow a carpet that was -14m long wouldn't be very useful, so we discard that result as not representing the real world.\n\nL = 22 ; B = 308/L = 14m\n\n2.) Gerry wants to fence a rectangular field whose area is 1200sq. m. He has only 100m of fencing so he decided to fence only the three sides of the rectangle letting the wall be the fourth side. How wide should the rectanglebe??? \n\nLet a and b  be the length of sides of the field\na.b = 1200       ------(1)\n2a+b = 100       ------(2)\nb = 100 - 2a     ------(2a)\n(100-2a)(a) = 1200     (substituting into eqn 1)\n2a^2-100a+1200 = 0     (expanding and collecting terms)\na^2-50a+600 = 0        (divide by 2)\n(a-20)(a-30) = 0\na = 20 or a =30\nb = 100-2a\nif a = 20, b = 60      (Check L=20+20+60,A=20*60 correct)\nif a = 30, b = 40      (Check L=30+30+40, A=30*40 correct)\n\nSo two feasible answers.
510279
Jimbo, you gave up too soon......\n\nV = L*W*H = L*W*x in this problem\n\nV = (6-2x)*(4-2x)*x\n\nV  oila!
1152551
i believe there is no solution.\na has to be positive if it is greater than 0.\nIf a = 1, than a^2+(2/a) = 3,  so a would have to be greater that 1 for a^2+(2/a) to be greater than 3, but it can not at the same time equal less than zero.
1135408
OH NOES THIS IS LIKE A MATH PROBLEM!!!! i can't handle any more variables :( sry.\n\n\nhahahaha.
614837
I already posted this solution (or how to get it).  Do a search of yahoo answers....
693274
HOW TO ANSWER THIS QUESTION?
549551
The way this is written, there is nothing to solve because it's not an equation.\n\nTo use the zero product property, you want to factor an expression that equals zero. Then you conclude that if a product equals zero, one of its factors must be zero. To factor the expression in your problem, combine any like terms to simplify, then factor the simplified expression.\n\nHope that helps.
607601
I think you set the equation to zero then you have to factor it.  Go to the link below if you wanna know how to do it. OR look your your math book.
402617
No solutions.\nFrom the first equation you have\ny=x^2+2x+9/2\n\nUsing the second:\nx^2+2x+3=x^2+2x+9/2\n3=9/2 , so there is no solution
856711
because this has 2 unknowns it cannot be solved.\n\nbut I can write  x in terms of b\n\n2x = 13-b\nor x =(13-b)/2
917052
16/24....it's really not that hard...you should be able to solve it on your own.\nps. you might want to simplify it down to 2/3.
962594
you sure you have this problem right ???????\n\nhere's what i came up with\n\nm + ( m + 3 ) = ( m - 2 ) - ( m - 1 ) \nthis is wrong \n\nm + ( m + 3 ) = 2m + 3\n\n( m - 2 ) - ( m - 1 ) \n\n= ( m - 2 ) ( m + 12 ) \n\n= m^2  + 1m - 2m  + 2 \n\n= m^2 - 1m + 2
636051
x=4\n\nplease solve...\n\n8-(1) :-) ;-(
974614
Simple. Get rid of the denominators on both sides by multiplying by the lowest common multiple (in this case, 8). So that would make the left side: 2(3x +7) and the right side: -x. Then just isolate and solve for x!
296877
It has a solution, indeed. It actually has two solutions, -3 and 7. To find it out, set each pair of nomials, (e.g. (x + 3)) to zero. So it would be (x+3)=0. Then solve for x. Do the same for the other nomial, and there you have it.
904672
let u = x^2 + 1, then you have du = 2xdx, => dx = 1/2x du,\n\nsubstitute back you are on the way  to solve it
832646
I'm sorry, but how could you not know this?\nThis is basic elementary math and if you don't know how to round you are in trouble.\nIt's 0.1 by the way