What is a temperature degree,and how do you measure temperature of a photon?
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Like many things in english, there are multiple means of the word "degree". The angle degree is not the same as the temperature degree. \n\nTo measure the temperature T of a photon of frequency f, use Planck's law:\n\nE=hf\n\nwhere E is energy and h is Planck's constant.\n\nThen E=kT\n\nwhere k is Boltzmann's constant, and\n\nT=E/k=hf/k
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Light consists of elementary particles called photons.  A photon can have both particle and wave like properties depending on the observer.  In fact, a photon will have both properties until it is observed.
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Absolute Zero or around 20 K.\n\nMelting point 14.01 K  (−259.14 °C, −434.45 °F) \nBoiling point 20.28 K  (−252.87 °C, −423.17 °F)
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The answer goes back to what temperature measures.  Heat is actually the motion (really kinetic energy) of atoms (since we're talking about an element).  Lower heat (and lower temperature) mean less motion.\n\n-273 C (or 0 degrees Kelvin) is known as "absolute zero".  It is the temperature at which that heat motion stops and kinetic energy goes to zero.  Since an atom cannot have negative motion or negative mass, its kinetic also cannot be zero and therefor its temperature cannot be less than absolute zero.
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i never really thought about it and so i was just going to say that temperature doesnt matter because its a vacuum and is dealing with the pressure... but when i thought about it... come to think of it, i do have an answer for you.  the temperature would be zero kelvin, absolute zero.\n\n in an absolute vacuum, the pressure would be 0 if there were no particles, because the more particles you cram into one place, the more pressure there is because p=F/A pressure equals the force of the particles divided by the area of the wall of the container, so with no force of particles(since there are no partiles), the pressure would be zero.  in an absolute vacuum, there are no particles.  Now, if the pressure is zero, then according to the formula PV=nRT (which is just the ideal gas law formula,) if P(pressure) equals 0, i think that means that T(temperature in Kelvin)would also be 0 which would mean that the temperature would be at absolute zero(which is defined as the temperature where all matter stops moving.. not that this would make a difference because there are no particles there because it's an absolute vacuum.  \n\nThis is what i suspect and to confirm my beliefs,  it is consistent with the fact that someone else said that outer space was 3K, and although it's very close to an absolute vacuum, there are a few particles and atoms of gas floating around there, and so it is not quite an absolute vacuum, and the temperature is 3K, meaning it's not quite at absolute zero.  so it stands to reason that since temperature decreases when pressure decreases, that in an absolute vacuum the temperature would be absolute zero, 0 kelvin.\n\ni hope this is a "good answer" and that i made sense while i took you through my reasoning :)
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a thermometer for temperature, but for tenperature i don't know.
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Temperature is a physical property of a system that underlies the common notions of hot and cold; something that is hotter has the greater temperature.\n\nThe degree Celsius is also a unit increment of temperature for use in indicating a temperature interval (a difference between two temperatures or an uncertainty). “Celsius” is named after the Swedish astronomer Anders Celsius (1701 – 1744), who first proposed a similar system two years before his death. \n\nFahrenheit is a temperature scale named after the German physicist Gabriel Fahrenheit (1686–1736), who proposed it in 1724.
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Absolute zero is the temperature at which sub-atomic particles cease to move.\n\nIn Celsius, that temperature is -273 degrees, or 0 Kelvin, which is the absolute scale in the SI system.\n\nIn Fahrenheit, it is -460 degrees, or 0 Rankine, the absolute scale in the English system.\n\nThe absolute scales are used when doing computations that include temperature, because it "provides a continuous definition of temperature, valid over all ranges of temperature. The normal temperature scales are based on the temperature at which water freezes, and the interval of measurement is determined by the distance to the temperature at which water boils.\n\nTherefore, since there is no temperature below absolute zero (since temperature is fundamentally the measurement of the movement of particles), it can be used as a standardized starting point for a scale of measurement.
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I'm not sure what you are asking.  Here are two possible answers:\n\nFirst:  E = h*nu\n\nIs the equation for the amount of quantized energy in light where h is Planck's constant, 6.626e-34 Joule seconds, and nu is the frequency in Hertz.\n\nThis determines the "raw" energy in the light.  As you know, going from electricity back to light varies in efficiency.  An electric light bulb requires much more electricity than a flourescent bulb to produce the same amount of light.\n\nSecond: hf = phi + Ek\n\nThis is the equation for the photoelectric effect, where electrons are ejected from a material being struck by light.  h is again Planck's constant and f is the frequency of the incident photon.  Phi is the amount of energy required to remove an electron from its binding and Ek is the kinetic energy observed.
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Measurement itself is an agreed upon science. Is the Temperature 0d or 32d.  Its bloody cold, that we can agree on, but one person would argue it is 0d and the other would say it is 32d. They are both correct, it is cold. They are both incorrect because they have never experienced an off Earth temperature. A measuring device on Earth would behave differently on Planet Zoltan. \nThat is the role of Scientific Measurement, so that two can agree on a given science therefore justifying the theory as true, relatively speaking. \nSomeone agreed that a certain lasar would emit a beam at Xcm per US second, this is how the mirrors on the Moon are gauged to reflect an emmitted ray back to Earth. Is it accurate? it is agreed to be accurate, by a majority. Therefore it is. relativley speaking. \nSee that Einstien fella was pretty smart, he noticed that Relativity is. He also noted that Relativity is an agreed upon Theory, what is Relative to one observer, may not be the same to another,but that is what makes it relative and irrationally perfect at the same moment.
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The temperature of a substance depends on the speed with which the molecules are vibrating.So,only matter which has some sort of energy can have temperature.A vacuum is just nothing.Due to this,temperature of vacuum cannot be measured.
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If it is for a science project, web sites may or nmay not have the answers....that is all part of a project, to figure it out for yourself, develop your own theories, hypothesis, etc.\n\nI will say it all depends on the temperature....beyond that you're on your own.
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By the spectrum of the light that it gives off.\nThink of a burner on a stove. As the temperature increases the light that it gives off changes (red to orange to bright orange). In exactly the same way we can look at the light of the sun (or distant stars) and by examining the peak wavelengths of light it gives off, we can determine what the actual temperature is.\n\ndo a google search for black body radiation or black body spectrum. or check out the wikipedia link\nhttp://en.wikipedia.org/wiki/Black_body
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One source that breaks down these classifications by temperature, or maybe it was only color photometry (I don't recall) is Kenneth Lang's Astrophysical formula:\n\nhttp://www.amazon.com/Astrophysical-Formulae-Radiation-Processes-Astrophysics/dp/3540296921/sr=1-1/qid=1163374728/ref=sr_1_1/102-7735916-8685767?ie=UTF8&s=books\n\nVolume I has some tables I think you will find helpful.  You might need to do a little interpolation...\n\nanother place to look would be the iau website http://www.iau.org . The IAU is the kind of group that would define a standard, though this might be too detail oriented for them to mess with.\n\nYou will be hard pressed to find an equation, however.  You are going to be stuck with a lookup table.
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The absorbed photon may be re-emitted as either reflected or refracted light. If it is absorbed, its energy is converted into heat. In some materials, a high-energy photon will stimulate the emission of a lower-energy photon. This is called fluorescence.
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You do not possibly have enough information to answer this question properly, you need to know, where it is at, how far from the sun, like the others said, is there a planet or any obstacle between it and the sun, what is it's current temp, so on and so on....here is something about tempature in space though\n\nEmpty space itself cannot have a temperature, unless you mean some abstruse question about quantum vacuums.\n\nHowever, if you put a physical object into space, it will reach a temperature that depends on how efficiently it absorbs and emits radiation and on what heating sources are nearby.  For example, an object that both absorbs and emits perfectly, put at the Earth's distance from the Sun, will reach a temperature of about 280 K or 7 C. If it is shielded from the Sun but exposed to interplanetary and interstellar radiation, it reaches about 5 K.  If it were far from all stars and galaxies, it would come into librium with the microwave background at about 2.7 K. Spacecraft (and spacewalking astronauts) often run a bit hotter than 280 K because they generate internal energy.
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Thermal energy is energy associated with temperature.  This corresponds to a measurement of how much the particles in a material 'wiggle'.  The more the wiggle the higher their temperature.  This wiggling causes the emmision of EM waves or light according to a blackbody curve.  Higher temps, with more wiggling, will emit more total energy and more photons at shorter wavelengths.  The hotter the object, the more infrared radiation it emits, however it will also emit more of every other wavelength too.  The peak wavelength shifts to shorter wavelengths ( higher energies) at higher temperatures.