How many amperes flow through a 90 watt bulb when 120 volts are impressed across it?
87474
750 milliamps. (P=IxE)
734064
From How Stuff Works:\n\n"A three-way bulb has two filaments in it. The next time one burns out, carefully open it (for example, wrap it in a towel and hit it lightly with a hammer) and you will see the two separate filaments. \n\nFor the lowest setting, one filament comes on (it might be a 50-watt filament). For the next setting, the second filament comes on (it might be a 100-watt filament). For the third setting, both come on, for (in our example) a total of 150 watts. \n\nLook also at the end of the bulb's base -- you will be able to see how the lamp controls the two filaments. "\n\nAlso:\n\n"A three-way bulb has two filaments of different wattage -- typically a 50-watt filament and a 100-watt filament. The filaments are wired to separate circuits, which can be closed initially using a special three-way socket. \n\nThe switch in the three-way socket lets you choose from three different light levels. On the lowest level, the switch closes only the circuit for the 50-watt filament. For the medium light level, the switch closes the circuit for the 100-watt filament. For the brightest level, the switch closes the circuits for both filaments, so the bulb operates at 150 watts."\n\nHope this "brightens" your day!
261103
10 amps if the voltage difference is 120 volt as usual
413474
Electricity is charged by the kilowatt (1000 watts) hour.  A 60 watt bulb uses 60/1000 hr. That's .06 times price per KWH.
694434
By the electrician hand book the danger current flow is a small window of 100 to 200 Mil amps. any thing less than 100 u may hurt yourself,and above 200 ma. u will receive burns. In the window above it starts the heart to flutter.
561
8 amps 900(880) watts
897028
1/500th or less. You can check this out by looking at an auto supply catalog, finding out how much current is drawn by the fan under loaded conditions, determine the current draw (presumably at 12 volts), and find the wattage.\n\nThis can then be converted into horsepower by multiplying watts X 0.00134.
962559
120.... not more than that...
530475
It depends on the rating of the breaker.  Common values for the maximum current in houshold lighting circuits are 15 and 20 amps.\n\nCurrent = power/voltage, so each 60 W bulb running on 110V draws 60W/110V = 0.545 amps.  You could run 27 of these on a 15 amp circuit and not blow the breaker (15 * 0.545 = 14.73 amps).  The 28th light would exceed allowable current.\n\nFor a 20 amp circuit, you could run 36 60W lights. (36*0.545amp = 19.64 amps)
942921
Voltage is the amount of "potential difference" present - an analogy with water would be the pressure of the water\n\nCurrent - measured in Amps - (Coulombs per second) the flow of electrical charge - an analogy with water would be the thickness of the pipe.\n\nVolts x Current = Watts\n\nJust as\n\nWater pressure x pipe thickness = amount of water pumped\n\n\nSo a 12volt bulb taking 2 amps will be 24 Watts\nA mains bulb at 240Volts with 0.5 amp will be 120 Watts
313707
Assuming you are using US household electricity (120VAC)\nP=V^2/R   R=V^2/P = (120)^2/1875= 7.68 ohms which is really small.
165350
wattage of the bulb is important...prob not generating enough heat to make the 'lava' flow (wax).\n\nIt should show signs of flow within an hour...at least!
798595
The light-bulb has a tungsten filament, which has electrical resistance.  The voltage applied across the resistance causes a current to flow.  The value of the current is: I = V/R, where I is the current in amps, V is the voltage in volts, and R is the resistance in ohms.  The current flowing through the resistance causes it to heat up--it dissipates power.  The power is: P = I*V, or P = R*I^2, where the power is in watts.  MOST of that power produces heat; in an incandescent bulb only a little goes into light.  Power, incidentally, is energy per unit time.  Watts are Joules/sec, where the joule is the SI standard unit of energy.\n\nAs for the motors, connect them in parallel.  They will each receive the same voltage, and each will draw the amount of current it needs.
55433
120\n\nhttp://www.istec.com.uy/eng/calculations/HazenWilliamCoefficients.asp
1137293
Zero. They won't do it. Engineers are too busy to change light bulbs and it's beneath them. Just one and he/she will tell you.
767776
The Power, P = VI, hence\n\nThe current at 120V is I = P/V = 65000/120 = 541.667 A\nThe current at 1200V is = 54.1667 A\n\nHowever, here the power is carried by TWO parallel lines, each with 0.1 ohms of resistance. That means the effective resistance is given by:\n\n1/Reff = (1/R1) + (1/R2) = 20 or Reff = 0.05 ohms\n\nTherefore, the Power Loss at 120V is\n\nP = I^2R = (541.667)^2(0.05) = 14670.15 watts\n\nThe Power Loss at 1200V is = 146.7 watts\n\nHence the power saving by stepping up to 1200V is\n\n= 14670.15 - 146.7 = 14523.45 watts
151356
Converting Amps to Volts at fixed wattage\n\nThe conversion of Amps to Volts is governed by the equation Volts = Watts/Amps\n\nFor Example, 48 watts / 12 Amps = 4 Volts\n\nExplanation\n\nAmps are how many electrons flow past a certain point per second. Volts is a measure of how much force that each electron is under. Think of water in a hose. A gallon a minute (think amps) just dribbles out if it is under low pressure (think voltage). But if you restrict the end of the hose, letting the pressure build up, the water can have more power (like watts), even though it is still only one gallon a minute. In fact the power can grow enormous as the pressure builds, to the point that a water knife can cut a sheet of glass. In the same manner as the voltage is increased a small amount of current can turn into a lot of watts.