If you're good at calc,could you help make a very involved word problem involving derivatives and sports.Thank
84224
How involved? \n1. Compute the effect of the dimples on a golfball on the trajectory of a golfball.\n2. Compute the effect of the seams on a baseball on baseball tranjectory. \n3. what are the normal modes of oscillation of a hockey stick, held by a hockey player?
625162
Try dictionary.com, m-w.com, or one of the thousand other good dictionary websites on the web, as for problems, try search on http://mathforum.org/
629091
Sorry, but the formulas do not present well here.  Cannot discern operations.
921398
I just taught this section today to my calc students.  You start by finding the first and second derivative.  I recommend looking in your book for an example.  Your book probably has something like this towards the front of the section.  It would be too long winded to write everything down here.  If you don't have your book on you, the web page below has problems that you can do and then check your answer.\n\nhttp://www.math.ucdavis.edu/~kouba/CalcOneDIRECTORY/graphingdirectory/Graphing.html
408554
yes. take out an x \nyou answer should be x(x+3)
3246
So for the first derivative:\n\n4(x-1)\n-----------\n3x^(2/3)\n\nThe second derivative:\n\n4(x+2)\n-----------\n9x^(5/3)
244823
The amount (A) will be doubling, so substitute "2P" in for A. Then you can drop the "P" from each side by division and solve for t.\n\nA = Pe^(rt)\n2P = Pe^(rt)\n2 = e^(rt)\nln 2 = (rt) ln e\nln 2 = .054t (ln e = 1)\n(ln 2)/.054 = t\n(approx.) 12.836 = t\n\nDoes that sound correct? (It's been awhile since I've done these kinds of problems.)
931778
Since you have conflicting answers, I'm just chiming in to say go with ManiacalAce -- he got the correct answer.\n\nCorrect second derivative is as follows:\n\n(-9/4)x^(-3/2) - (3/4)x^(-1/2)\n\n~ ♥ ~
221721
Product rule:\n\n(fg)' = (f ')g + f(g ')\n\nSo,\n\n(-2x^2 * ln(x))' = (-4x * ln(x)) + (-2x^2 * 1/x)\n\nMultiply and clean up:\n\n-4xln(x) - 2x
117843
Sure.  The derivative of x^3 is 3x^2.  That should get you started.
846527
You'll have to do this in more than one step.  Basically it will sort of have to be a program.  I would start with the restart; command and then  define the function (I would look this up in the help menu since it is dependent on 2 variables).  Then use a command to find the derivative.  Then a command to solve for the pairs (x,y) when the derivative is 0.  That will give you 1.  For 2 and 3 you will also have to do a series of commands.  Use your calc book to refresh your memory on the procedure of finding these, it should be a similar procedure in maple.
915953
Please, learn arithmetic.\n\n12
816542
Find derivatives with respect to each variable.
986880
Do you want how to derive them or what the derivatives are?\n\nF(x)=a^x  ---> f'(x) = a^x (ln a)\n\nf(x) = sin x ---> f'(x) = cos x\n         cos x      --->           -sin x\n         tan x       ---->           sec^2 (x)\n         sec x      ---->           sec x tan x\n         csc x      ---->           - csc x cot x\n         cot x       ---->            - csc^2 (x)
711470
Try here:/\n\nhttp://archives.math.utk.edu/visual.calculus/
550682
Oy that is a great question.  I take it you taking a risk managment or a derivative course! ;)  Basically you would have to put in functions (functions of interest and volatility variations) for both and then evaluate it accordingly.  It is nearly impossible to do by hand but computer can provide you with some good insight :).  That's when 3D probability that engineers love so much kicks in.  \n\nRival
741552
You have got it right.\nthe answer is\n\nf(x) = 3x