What is the dot strucure for H2S?
98048
H:S:S with 2 dots on top and bottom of the S. S has 6 valence electrons and H has 1, a total of 8
59413
Hydrogen\n\nSODIUM BISULFATE\n\nSynonyms: Sodium hydrogen sulfate; sodium acid sulfate; sulfuric acid, monosodium salt, monohydrate \nCAS No.: 7681-38-1 (Anhydrous) \nMolecular Weight: 138.08 \nChemical Formula: NaHSO4 . H2O \nProduct Codes: \nJ.T. Baker: 3534 \nMallinckrodt: 7432
1158402
No. Think about connections. CH3-CH2-O-S-O3H. The ethyl must bind to an oxygen, not the hydrogen. [CH3CH2]- [HSO4]+ would seem to be the right "ionic" form, but these aren't ions.\n\nYou need to show that the hydrogen is on one side of the sulphur and the ethyl is on the other side, and each of them are connected through oxygens.
469352
(h+4)(h+8)\n\nglad i could help!
920228
CuSO4•5H20\nThe dot notation denotes the hydrate.
819123
You have to do this by analogy to other molecules.\nFor instance Se is in the same column as S and therefore SeO3 and SeO2 will look like SO3 and SO2.  Similarly SiF4 will have the structure of CF4. As comes two periods after N.\n\nFinally, the structure of simple molecules like SO2 can often be found on Wikipedia or here:\n http://www.3dchem.com/table.asp
761407
lewis dot structure shows the molecule's valence e-s and the bonding of the molecule \n\nit is very easy to draw \nhere are some hints for drawing lexis structure\nfirst you need to find out the valence e-s of that molecule i.e. h2O have 8 VALENCE e-s 2 from the hydrogens abd 6 from oxygen \nthere is is Carbon present in a molecule than carbon should be placed in the middle  if there is no carbon present than least electronegative atom should be in the middle \nput one or two or three pair(s) of electrons in the middle depending on the octet rule which states that all atoms want 8 valence e-s other than H, Be, and S. H bond to get 2 valence electron, Be bonds to get 6 valence e-s and S can get more than 8 valence electrons \nif you are confused or need help with any of the models just email me i will try my best to reply
283215
[Cu(NH3)4]SO4*H2O (s) + 2HCl(aq) --->\n\nCu(NH3)4 +2 (aq) + H2SO4(aq) + H2O(l) + 2Cl-(aq)
24810
Cu + 2H2SO4 --> 2H2O + SO2 + CuSO4\nDouble the H2SO4 and the H2O.
1151475
number of moles of hydrogen is 0.2\n\namount of water is 2.4
243712
H2S\n\nit's a chemical compound i had to smell in the lab\nit smells like the combination of Rotten Eggs and an old pile of garbage. beside it spreads in a very wide range\nthanks God i don't go to that lab anymore but sometimes i smell it from a distance\nrotten egg duhh
555626
The Lewis dot structure would be that N in the middle with branches off to oxygen and 2 Fs and then one single electron will be on nitrogen and it is a radical I think. It is very reactive because of this one electron. The electron geometry will be something with sp3 orbital, I am not sure since it only has one electron. I would check up on that. Hope that helps
956604
Try it out in the lewis-dot diagram\n      ..        ..\nH-O-Ca-O-H\n      ..        ..
127716
based on the given balances equation.\n\nthe volumes could be:\n  \nSTP = 22.4L per mole\n\n 14.2L SO2 ( 1 mol H2S / 2 mol SO2) = 7.01 L of H2S\n\n and\n \n14.2L SO2 (3 mol O2 / 2 mol SO2 )  =  21.3 L of O2
170129
CuSO4 (s)  --H2O-->  Cu+2 (aq) + SO4-2 (aq)
806618
The only difference I can see would be the molecular geometry, due to the number of H's bonded onto the anion. Also, when drawing the Lewis dot structures, NH3 (N) would have one lone pair of electrons, HF (F) and H2O (O) would have two. This would dictate their structures according to the VSEPR rules.
482177
SO2.\n\nS202 would be Disulfur dioxide.