If an electric motor runs 10,000 RPM on earth what is its speed when  in outerspace where there is no  gravity
87071
Probably pretty close to the same, the main factor that reduces a motor's speed is bearing friction, it would be slightly faster, because there would be no friction on the armature caused by air movement. If it is a D.C. motor (particularly a series field), the speed variations would be higher than for a fixed speed A.C. motor, and the speed of a syncroonous A.C. motor would be unnafected, however its current consumption would probably be slightly reduced. Also, the tourqe for almost any electric motor would be affected by the temperature change (lower temp. = more tourqe = higher current consumption), and possibly, this could affect speed.
332344
you already know that as the Earth orbits the Sun it is weightless. But it certainly is not massless.\n\nBecause the Earth has mass it exerts a force of gravity and the magnitude of this force of gravity is determined by the mass of the Earth and the distance away from the center of the Earth another object is. Now, you know that if you drop something it falls. But did you know that as it falls it accelerates? That means that as it falls it falls faster and faster and faster until it hits the ground. On earth at sea level objects that fall speed up at a rate of 9.8 m/s every second. So, for every second something falls it falls 9.8 m/s faster with each passing second. You can see that at this rate you are going pretty fast real soon. (9.8 m/s is a little more than 20 miles per hour, so in three seconds you are already going 60 mph!)\n\nIf you go way high up a mountain the acceleration due to gravity is a little less than 9.8 m/s. If you go higher still the accleleration is even less and so on. You can tell how high you are by how fast objects that fall accelerate.\n\nNow, here is the really neat part: all objects accelerate to the Earth at exactly the same rate given the same distance from the Earths center. In other words, even the Moon is accelerating towards the Earth at a rate that is appropriate for its distance from the Earth's center! If another object, say with the mass of this desktop computer, were to be placed in the moon's orbit it would circle the Earth at exactly the same speed as the moon. Why? Because both objects are accelerating towards the Earth and all objects, regardless of their mass, accelerate towards the Earth at exactly the same rate.\n\nSo here is where it all comes together: If you know how far an object is from the center of a planet or a sun and if you know the rate of acceleration that that object is accelerating towards that planet or that sun you can easily calculate the mass of that planet or sun because only an object of that planet's or sun's mass can accelerate an object towards it at that rate at that distance.\n\nIsn't that amazing? This procedure was actually used to calculate the mass of the earth and it is used to calculate, well, the mass of any orbited body. In fact, we did not know the mass of the planet Mercury until we put a satellite around it.\n\nWhat is that magic equation? Well, there are actually several. Here is one that can be used of you know the time it takes an object to orbit the object you want to find the mass of (T) and if you also know the distance between the centers of both objects (r): M=4 pi2*r3/T2G. 'M' is the mass of the orbited object in kilograms; 'r' is the distance between the centers of the two ogjects in meters; 'T' is the time it takes the orbiting object to orbit the planet or sun you want the mass of and 'G' is the Universal Gravitational Constant (6.672 x 10-11 Nm2/kg2) and pi is 3.14. Note that all this tells you is the mass of the orbited object. This will not tell you the mass of the orbiting object. There is no way to calculate that without finding something to orbit it!\n\ncheck this website \n\nhttp://www.physlink.com/Education/AskExperts/ae170.cfm
509966
Ummm that's not a real question.\n\nBut, if that happened, you'd end up with someone standing on the earth who observed that small particle moving in a direction opposite the earth's rotation at a speed that could be calculated by:\n\n(radius of the earth)*6.28*(1/30-1/24)
1113520
Earth is rotating at a speed of about 1100 miles per hour. If our planet suddenly stopped rotating, the atmosphere would still be in motion at that speed. The atmosphere would be moving so fast it would literally sweep the land masses clear of anything not anchored to bedrock, this would mean rocks, soil, trees, buildings, people and animals. All would be swept up into the atmosphere.
1164152
The earth rotates about its axis.  Obviously at the poles, there is no speed to the rotation at all.  At the equator, the circumference of the earth is about 25,000 miles and it rotates once per 24 hours, so the speed would have to be 25,000/24 = 1041.67 mph.  Depending on where you are between the equator and the pole, you'll get a speed of between 0 and 1041.67 mph.
867201
nothing can go faster than the speed of light (in theory) so the answer is 3*10^8
77860
hey, didnt i answer something very similar to this for you? you need to do F=ma so 43000000N/2100000kg then you get an acceleration, but then you have to subtract gravity from this because thats the acceleration produced by the rocket but there is still gravity pulling with 9.8 m/s^2 in the opposite direction. so just do (43000000/2100000) - 9.8, and that's your answer :)
757322
all you have to do is multiply the kg by 10 ( or the 9.81 which is the gravity constant)\n\nso you would have about 855 N
367853
F = m*a \n\nm = 2 kg (two masses; two strings)\na = gravitational constant which happens to be 9.81 m/s^2 on the surface of the earth (or 32.2 ft/s^2 in EE units)\n\nsum the forces in the y-direction:\n\nT = F = 2 * m * a = 2 N\n\n(assuming massless strings)
849468
gravity at the earth's surface = 9.80 m/s^2
1139189
The earth is surrounded by air approximately up to 200 km.\n\nThe space is surrounding the earth in all direction.\n\n Any object thrown or moving with a speed of 11.2km/s (25053.7 miles /hour) will escape from the gravitational pull of earth and will not return to earth.\n\nIf the speed is less than this value, the object will move in a circular path around the earth.\n\nOur planes are moving very slowly compared to that speed. Therefore, they cannot escape into space. If they have a constant speed they will be circulating the earth with a particular radius around the earth. \n\nIf a plane is flying (with a constant speed) at a height h from the ground of a city, after certain hour it may fly over the ground of another city. For the people in that city the plane will be flying at the same height h.  Since the earth is a globe, through out the globe, the plane will be flying at the same height. The height from the ground increases if the speed of the plane increases.
20798
The Earth spins from west to east at about 900 mph. Looking from above the Earth's North Pole, the Earth rotates counter-clockwise around the Sun.
981312
310 times faster\n\nif A is going 10mph, and B is going 5mph, the 10/5=2 or twice as fast. so 9.3X10^10 / 3.0X10^8 = 310 times faster.\n\nbut nothing can't go faster than 3X10^8m/s!!!! The normal speed of light means it's going though a vacum (nothing), so if it's going though a gas, it will slow down!! Not speed up! Since the energy will hit atoms and slow down. \n\nIf an object is going 3E8 (short way of 3X10^8m/s) releative to the ground and an object passes it at 3E8, then the object passing the first objects speed was 3E8 releative to the ground... so both were going the same speed, even if some was twice as fast as it!
526135
It's about 1/6 earth gravity. (But don't forget to add in 1/6 of the spacesuit you have to wear, too.)
225964
Depends where on Earth you are standing.  At the equator, it's just over 1000 miles per hour.  At either pole, it's virtually zero.
928544
KNOWN:\nf = 3.2 x 10^-2 Hz\nc (ie speed of light) = 3.00 * 10 ^8 m/s\n\nFIND L (AKA wavelength)\nL m = c m/s  /  f Hz\n= 3.00 * 10 ^8 m/s  /  3.2 x 10^-2 Hz\n= 9 375 000 kilometers\n\nAre you sure its 10^-2 Hz? That seems unlikely
419674
The Earth is approximately 25,000 miles in diameter at the equator, and it spins once in about 24 hours.  So, at the equator, the Earth is spinning about 1000 miles per hour.  However, if you live in the US, the Earth is moving much slower-about 70% the speed depending on your exact latitude-and slower as you go north or south from the equator.