how do you do Algebra 2 work?
85187
I don't really know what you need help on....\n\nCheck out some of the sites below in the source section, or you could just post what in particular is troubling you...\n\n(I can sympathize if you're having trouble with Matrices though... those always have so many places to go wrong.. ugh.)\n\n(PPS: Wikipedia can be very useful for finding out more information, as you can tell from the number of links below.)
16153
this is a mathematical trick that is done as a teaching method on commonf fallacies of math.\n\nLet a=b\n\na^2=a*a\n\nsince a=b, a^2=ab\n\na^2+a^2=a^2+a^2\n\nsince a^2=ab, a^2+a^2=a^2+ab or 2a^2=a^2+ab\n\nsubtract 2ab from each side to get 2a^2-2ab=a^2+ab-2ab or 2a^2-2ab=a^2-ab\n\nthis can be rewritten as 2(a^2-ab)=1(a^2-ab)\n\ndivide both sides by a^2-ab to get 2=1\n\n\ncheck it over, mathematically its sound.. except for one thing... from what we already described, a^2=ab! therefore a^2-ab=0!  and if you all remember, you can not divide a number by 0!  \n\n2(a^2-ab)=1(a^2-ab) is actually saying that 2*0=1*0 which is a correct statement!\n\nthus no issues
885189
You should "cancel out". If you are saying what I think you're saying, then that's what you should do. Narrow it down until you have the answer. For example:\n\nx -10=2 + 2x   : This is your algebraic equation.\n\nYou should subtract 2 from each side, to get rid, or "cancel out" the 2. You get this:\n\nx-8= 2x\n\nNow you want to narrow down the x value so it just equals x. Subtract x from both sides.\n\n-8 = x\n\nTa da! There's a simple algabraic equation. If you have any questions, or if I was unclear, feel free to send me a message.
890645
Wow, there is a lot here!  I'll start with some tips for solving algebra problems.  The first thing you should always remember is to play the equal game.  Whenever you add, subtract, multiply, or divide, you should do the same to the other side.  The other tip is to use the order of operations when simplifying.  Remember the sentence: Please excuse my dear Aunt Sally.  The initial letters of each word stands for the order of operations.  Do the Parenthesis first, followed by the Exponents, then Multiplication or Division, and Addition and/or subtraction next.  Finally, you should always simplify first using the order of operations before you start shifting numbers from one side of the = to the other.  \n\nI'm not going to work all of these problems, but I'll show you a few to get you started.\n\n1)\n3x-7 = 2   Add 7 to both sides\n3x = 9   Divide by 3\nx = 3\n\n4)\n6x - 3 = 2x - (4-3)/3   Simplify the stuff inside the parenthesis first\n6x - 3 = 2x - 1/3  Add 3 to both sides\n6x = 2x - 5/3  Subtract 2x from both sides\n4x = -5/3  Multiply both sides by 3\n12x = -5  Divide both sides by 12\nx = -12/5\n\nI hope this helps.  Good luck!
735754
just plug the numbers in.  if y=8, and x=2, \nits 8=a(2^2)\nso 8=a(4)\nso a=2.\nhope that helps!
869887
If you have 2 equations, just solve for one variable for one of the equations. Take that equation and plug it into the same variable for the other equation. You will solve for that variable, and plug in that number to any of the 2 equations to solve for the other variable.
1148067
You elevate the number to the power 2 like this:\n\n                                    x^2\n\nYou should still do the normal product but it is easier to thing you et the square of a certain number and most calculators already have the elevate to the second power function integrated\n\nCynthia
102673
If you can't get an answer here, try asking your Algebra teacher for extra help after school tomorrow.  It's sure to add to your grade that you asked for the help.
686655
No prob dude... take a deep breath, grab a cold drink, and concentrate on this... ready? ok....\n\nOften, the simplest way to solve "ax2 + bx + c = 0" for the value of x is to factor the quadratic, set each factor equal to zero, and then solve each factor. But sometimes the quadratic is too messy, or it doesn't factor at all, or you just don't feel like factoring. So, while factoring may not always be successful, the Quadratic Formula can always find the solution. \nThe Quadratic Formula uses the "a", "b", and "c" from "ax2 + bx + c", where "a", "b", and "c" are just numbers. The Formula is derived from the process of completing the square, and is formally stated as:\n\n For ax2 + bx + c = 0, the value of x is given by:\n   \nNote that, for the Formula to work, you must have "(quadratic) = 0". Note also that the "2a" at the bottom of the Formula is underneath everything above, not just the square root. And don't forget that it's a "2a" under there, not just a "2"! And make sure that you are careful not to drop the square root or the "plus/minus" in the middle of your calculations, or I can guarantee that you will forget to "put them back" on your test, and you'll mess yourself up. And remember that "b2" means "the square of ALL of b, including the sign", so don't leave b2 being negative, even if b is negative, because the square of a negative is a positive. In other words, don't be sloppy and don't try to take shortcuts, because it will only hurt you in the long run. Trust me on this!
414537
I was in your shoes once. My brain just doesn't work math the way I was taught it. Are you using the same teacher/tutor or do your teacher and tutor use the same style of teaching? Perhaps trying a new tutor, or getting someone else to work with you will help. I have noticed that not everyone's mind works in the same way. I struggled with math/algebra for years only to later in life have someone else explain it to me and it clicked right away. If someone can present it to you in a way your brain understands, perhaps it will make sense and you will start to do better.\n\nGood luck.
732232
3x - 2 = 2x - 1\n\n3x - 2 - 2x = 2x - 1 - 2x\n\nx - 2 = - 1\n\nx - 2 + 2 = - 1 + 2\n\nx = 1\n\nThe answer is x = 1\n\nInsert the x value into the equation\n\n- - - - - - - - - - - - - - - - -\n\nCheck\n\n3x - 2 = 2x - 1\n\n3(1) - 2 = 2(1) - 1\n\n3 - 2 = 2 - 1\n\n1 = 1
571127
Try going to this website. The will explain it step by step and you can ask all the math questions you want. www.algebra.com
516830
http://www.gateways2learning.com/Algebra/Algebra.htm\n\nAlso try here.......\n\nYou may want to reconsider having it solve the answer for you, always know how to do the breakdown, it will help you to know "how" to go about it when you take a test.\n\nGood luck.....................
738509
Well, the idea of the answer being a product of numbers when multiplied does suffice. In advance math, the process is far more complicated. But the prinicple is the same. Example:\n2x(-2) = a -4x\nWhere 2x(2x) =4x squared. \nOr 2x(2) = 4x.\nOnce these little ideas are mastered, the rest begins to fall together. \nThe main thing for me is to have fun with maths, and not think the learning a chore!
152888
I'm in Algebra 1 (I go to an online high school). I would be glad to help you if I can.
888151
Basic math/algebra. You are taking two known numbers and finding the unknown number. \nE=P/I  solve for I    Think like simple Algebra I is X. So you want to work the problem and get a final answer x=?  or   I=?\nHope this helps.
794610
You have to do the equations in the [ ] first.\nThen you have to do multiplication before addition.\nHere's the order of how you should do math like this:\nP - Parenthesis\nE - Exponents (a number to the something power)\nM - Multiplication\nD - Division\nA - Addition\nS - Subtraction\n\nSo you do [2+6(-3)] first\n[2-18]\n[-16]\nNow it's 15-3[-16]\n15+48\nAnswer: 63