Rapid acceleration increases the weight of an object. How much is this increase in airplanes and in rockets?
96093
I assume that rapid means a large change of acceleration with time.\nThat is described as an Impulse.\nUsually an impulse chalenges the structure of the mass and would tend to break the mass into smaller components.\n\nWhat is called weigth is gravitation forces between two interacting masses.\n\nTo prevent the rocket or airplane to breack appart ,the power that is Invested in these vehicules must be in equilibrium with the power of Gravity at all times.
1151411
Objects of different mass do fall at the same speed, but air resistance hinders this fact.  For example, if you drop a bowling ball and a feather at the same time on the Earth, obviously the bowling ball falls faster. \n\nHowever, on the moon, when the astronauts dropped a feather and a bowling ball, they hit the ground at the same time. \n\nIt would seem that the bowling ball should fall faster since gravity is pulling on it with more force. But, with the more mass, comes more inertia, which meas it resists being pulled more than the feather. So, the feather is pulled less, but it resists less as well, so because of that, they will fall at the same time. The relationship between the force of pull and the object's inertial compensates exactly so that all objects fall at the same rate.
612059
Consider two objects having masses 1kg and 5 kg are in a horizontal plane.\n\nWe apply a force of 10 newton to the 1 kg mass and 50 newton to the 5kg mass. \n\nThat is, we apply less force for less mass and greater force for greater mass.\n\nNow we find the acceleration of the two bodies.\n\nThe1 kg mass will have an acceleration of 10/1 = 10 m/ s^2. That is its speed will be going on increasing by 10meter / second in every second. \n\nSimilarly the 5 kg mass will have an acceleration of 50/5 = 10 m/s^2. That is its speed will be going on increasing by 10meter / second in every second. \n\nBoth have the same acceleration and both have the same speed at any time after start.\n\nNow returning to gravitational pull, let us place the 1kg mass in one pan of the balance and the 5kg mass in another pan. \n\nThe pan having 5kg mass will come down and the pan having 1kg mass will go up.\n\nThis is because the earth is pulling the 5 kg mass with a force of 50 newton and 1kg mass with a force of 10 newton.\n\nIf  we drop the two objects from the same place, as we have seen already the 1 kg mass will fall down with an acceleration of 10 m/ s^2 and the 5kg mass will also fall down with 10 m/ s^2. But the forces acting on them are different.\n\nThe Earth’s pull is such that it gives less force for less mass and greater force for greater mass.\n\nTo be more specific it gives a force of 10 newton for every kilogram of mass and hence the acceleration is for any mass is the same as approximately 10m/s^2.
709931
kaksi_guy: I think charlesellis753 is correct.  If we interpret the question as a fill in the blank, mass appears to be the best answer.\n\nIf the ______ of an object doubles, then the force required to accelerate it at the same rate will double.\n\nThat sentence is true is the blank is filled with 'mass'.
845137
I don't belive mass equals acceleration. Mass is suppost to increase the faster you go but speed is also relative to the position and speed of the observer. I would try to think of it as speed affects the mass of an object. The mass of an object at rest is less than the same mass at speed.
585763
When the lift descending,the acceleration is increasing.Relatively,body and the lift is moving down with a gradually increase speed.The acceleration will increase until its value is the same as the value of the acceleration due to gravity.\n\nLet R = normal reaction of the floor of the lift on the body, \n   mg = the weight of the body inside the lift\n    g = acceleration due to gravity\n      = 9.81 meter per second square (unit SI)\n    F = resultant force of the whole system\nusing this equation:\n\n     F = ma     \n     F = mg - R  (because the lift is moving downwards,\n                  resultant force is moving downwards too.)\nmg - R = m(a)    (a = g,because the acceleration of the lift\n                 is equals to the acceleration due to the\n                 gravity)\nmg - R = mg\n     R = 0\n\nAs R = 0,the body will not experience any force exerted by the floor of the lift,the body experiences weightlessness.\n\nIn short, weightlessness happens only when a body is in free fall motion, or fall freely under the gravity, or a more accurate explaination, weightlessness happens when a body falls freely with an acceleration which is equals to the acceleration due to gravity.\n\nHope my answer helps you.
404829
the only thing that leads to the misconception that heavier things fall faster is most likely due to air resistance. In a vacuum, all objects fall under the same acceleration/gravity.
59053
actually... although the first answerer did the correct calculation, he left out a step. that is the acceleration produced by the rocket, however you must take gravity into account. \nF=ma, a=F/m= 23.3 is the acceleration produced by the thrust of the rocket, but the rocket is not actually going to accelerate that much because an acceleration of 9.8(due to gravity) is pulling it down in the opposite direction. so 23.3-9.8= 13.53\nso the initial acceleration of the rocket is:\n13.53m/s^2
396138
a=F/m, lim x->inf x/x = 1. The object will accelerate.
939350
The height of the plane does not affect the acceleration, only the angle.\n\nAcceleration will be constant as long as the force acting on it is constant. The force contributing to acceleration (gravity) is constant.
124905
There is no absolute reference frame, that is, there is no universal "stationary point" that we can use to say whether an object is moving.  Thus, every object is "at rest" in the frame of reference centered on itself.  In that frame of reference, an object's mass is always the same, its so-called rest mass.  That is the mass that you are likely thinking of when you say it doesn't increase.\n\nHowever, if the object is moving at a high speed relative to an observer, its mass is increased in the reference frame of that observer.  It will require more force to accelerate it a given amount, etc.
487670
None. It takes no power to maintain that speed (on level ground, no friction). The object has kinetic energy (0.5 * m * v^2). Power was required to put it in motion and power can be recovered by decelerating it. If you do the math, the energy is 3551.86 ft-lb, equivalent to 1 horsepower for 6.458 seconds. Answer 1 neglected the fact that weight must be converted to mass by dividing by g, and energy is proportional to v^2.
964035
You need to consider vectors ....\n\nAcceleration has a direction. In the case of gravity its down towards the ground. \n\nNow what accelerationis doing is changing the instantaneous velocity of the particle or object or whatever.\n\nVelocity is also a vector.\n\nSo if the velocity is in the opposite direction to the acceleration then the object will motion will slow down and eventually increase in the same direction as the acceleration.\n\nIf the velocity is in the same direction then it will increase in that direction.\n\n So if UP is defined as positive then down is defined as negative. This goes for:\n- position (above (+) and below (-) ground if ground level is defined as zero);\n- velocity is positive if the object is moving up and negaitve oif it is moving downward; and\n- acceleration is positive if applied upward or negative if applied downward.\n\nNote acceleration is in the same direction as an applied force as by Newton's Second Law, F = ma and mass is a scalar quantity .. it has no directionality. It is the same wherever the object is. (Not to be confused with weight which is a force attracting us to the ground and is dependent on the strength of gravity. So for example we weigh on earth and are weightless in space and are 1/6 of our weight on the moon etc ... In all locations our mass is the same but the forces acting on us are different)
718152
weight equals mass times acceleration due to gravity
516868
for gaining speed acceleration is required.acceleration is provided by a force.the force which provides acceleration to falling bodies is the force of gravity or the gravitational pull.\n\nthe speed of any falling object is given by the formula\nv=u+gt where u is the initial velocity which is zero for an object falling from rest,v is the velocity after a lapse of time t and g is the acceleration due to gravity which is approximately 10 metre/sec/sec.you will find that the mass of the object or the weight which is nothing but the force with which the earth is pulling it (w=mg) doesn't figure in this formula at all.The momentum of the heavier object will be more as momentum is the product of the mas and the velocity\n\nif at all there is any marginal difference in the speeds it could be attributed to the resistance provided by the atmosphere
905311
Air resistance is a force operating in opposition to thrust.  With a given thrust the object increases speed, which increases drag due to air resistance, until thrust and drag are equal at which point the object no longer accelerates.  This also applies if the "thrust" is gravity acting on a falling object -- it will reach "terminal velocity" when gravity has accelerated it to a speed at which the air resistance is equal to the weight of the falling object, at which point the forces are in equilibrium and the object neither increases nor decreases in speed.\n\nThe shape of an object affects air resistance -- generally speaking the greater the cross section and the flatter the leading and trailing edges are perpendicular to the direction of travel, the greater the air resistance and the lower the maximum velocity or terminal velocity that can be achieved.\n\nBy adjusting the shape of an object so that air flows around that object with the minimum of resistance, you decrease the drag and this in turn increases the maximum acceleration and speed.  It can alternately be used to increase efficiency as less thrust is needed to achieve the same accelerations and speeds.
767968
This question can actually get rather complex (a larger parachute weights more, and its shape can be different) but we'll assume for a minute that all parachutes weigh the same, and have the same aerodynamic properties (namely coefficient of drag - Cd).  The parachute acts as a source of drag on the falling body.  When you're falling to earth the force of gravity (as long as your decently close - airplanes are more then close enough) = F = m*9.81m/s^2.  The force of drag is a little more complex \nDrag = 1/2 * Density of Air * Speed Falling ^2 *Surface Area * Cd\n\nThe larger the object the more drag it will exert (its linear).  There are also other effects such as lift from the parachute, etc, but we wont worry about any of that now.