When is a curve broken or solid in graphing?
82793
I can think of two possible things you're asking:\n\n1. Are you asking about continuity?\nIf so, then the curve is broken when the denominator of a function equals zero. Also, the curve will be broken if it has a vertical asymtote. That is, when the graph of the curve gets closer and closer to an x-value without ever getting to it (thus, the y-value approaches infinity). An example of a graph with a vertical asymtote is y=sin(x).\n\n[edit: oops, I meant tan(x) instead of sin(x)]\n\n2. Are you refering to graphing a domain/range with inequalities?\nIf so, then use a solid line when the answer includes the graph of the function. That is, your function has an equal sign (=), greater than or equal sign, or less than or equal sign. If your answer does not include the function, use a dashed line (for >, <, or not equal to sign).\nFor example:\ny=x would have a solid line.\ny (is not equal to) x would have a dashed line with all the rest of the area of your plot shaded.\ny>x would have a dashed line with everything above shaded.\ny (greater than or equal to) x would have a solid line with everything above shaded.
608711
i think it's a parabola.. im not sure. u should try plotting it on a graph.. substitute  the x and y values and see what form comes out..
891649
(y-3x) cannot be graphed because there is no equality...\nyou could graph y=3x... that would be a line that passes through (0,0) with a slope of 3
911974
Go with a line graph, that way you can also find out (or estimate) temperatures at times when you didnt measure it.
145095
We can use graphs to create a more meaningful and visual representation of data.  For instance, pie charts represent the percentage of a data set (51% white, 49% black).  Line graphs can show trends (the rising sales of hybrid vehicles vs. the falling sales of gas-guzzling vehicles).
712712
[on] [y=] [(] [x,t,o,n] [+] [2] [)] [/] [x,t,o,n] [enter] [5] [-] [2] [x,t,o,n] [enter] [(-)] [2] [x,t,o,n] [-] [3] [enter] [window] [(-)] [5] [enter] [5] [enter] [1] [enter] [(-)] [5] [enter] [5] [enter] [graph]\n\nYou should have on screen a vertical asymptote at x=0, horizontal asymptote at y=1, a curve going to negative infinity towards 0 on the left, a curve going to positive infinity towards 0 on the right, on the left tangent line y=-2x-3 touches point(-1,-1), and on the right tangent line y=5-2x touches point(1,3).
298247
Select your data. You have already entered your data, right?\n\nPull down the "insert" menu to "chart". Choose "line", choose the particular line graph you like best. Hold down the sample bar to see if the graph looks the way you expect it to. If you aren't making any changes, you can pretty much click "next" until you get a chance to click "finish".
735957
Well. You can keep drawing tangents until one which you find is the steepest. From your info, i have the idea that the curve is in the shape of a bell. So perhaps you can try drawing tangents at the mid-range of the curve.\n\nHope this helps=)
502859
Okay, -2 is where your graph crosses the Y-axis. 1/3 represents the slope of the line (y/x or rise/run). So that means for every 1 step it goes up, it goes 3 to the right. Just chart it out and you should be able to get it from that. Since it is > and not =, that means Y (answer) is above the line.
818092
When Graphed\n\nEquations can be any line\nLinear Equations form only straight lines\nFunction is only a function if you don't have 2 identical x values.
358834
KNOW YOUR RELATED RATES FOR CALC!! thats one thing that killed me and know your 2-D rotation around a line intergrals.
919171
To answer this question, you need to know the shape that these points make.  Are they on a line? or are they some two-dimensional shape?
978117
The graph of f(x) is a line, which means it can't have an asymptote.\n\ng(x) = log5(2x) should have a vertical asymptote x = 0.
442406
Make a table of values.  Then plot the points.  Your graph should be a "V" shape (not a parabola which is U shaped)---whether upright, sideways, or downwards.
772313
You draw it under the curve\n\nThe tangent line will only touch the curve at one point for this type of smooth upward bending curve.(At least for the part of the graph shown).\n\nYour graph plots total displacement verses time. If the graph was a straight line then this would indicate a constant "velocity" but since the curve bends upwards you are dealing with a positive acceleration.\n\nPractically, from your graph, suppose you wanted to know the approximate slope of the tangent line at t=5. Use the two closest data points: t=4, d=8.4 and t=6, d=16.5. Then the slope is about (16.5-8.4)/(6-4) = 4.05 at t=5. it will be slightly greater than this. You can use a straight edge to make a visual adjustment and then you can find the slope by dividing the displacement value at t=5 by (5 minus the value of t where the straight edge crosses the time axis).\n\nThe other way is to use the data to deduce, a closely as possible, the formula of the function being graphed. For example if the displacement was directly proportional to the square of the time, d = k t^2 for a determined value of k, then the slope of the tangent line at any time, t, would simply be 2 k t which is the time derivatiive of the function.
926034
If by the whole you mean where the finction has a hole in the graph (a removeable discontinuity), then that is when the denominator equals 0.  so there is a hole at -3.  And, yes, I belive that the roots are both -3.
158569
Here is a tutorial...you can change any of the parameters that you mentioned and look at the graph as it is made and changed...really cool if you ask me.\nhttp://www.analyzemath.com/logfunction/logfunction.html