what  is the probability of a leap year?
79668
It's not true that it's exactly 1 in 4. If you look at it on a daily basis, there are 366 days in a leap year, so in a 4 year period, the probability that any given day is within a leap year is 366/1461.
43237
For a year to be leap year it should satisfy the following:\n\n1. If it is divisible by 100..it should also be divisible by 400 ( to get a centurian leap year). Eg. 2000 was a leap year and 2100 ( if we live till then) would not be. \n2. If it is NOT divisible by 100 then it should be divisible by 4. e.g. 2004 was a leap year but 2006 is not.
911861
No, there is  24 hours over the period of 4 years which we dont account for on a daily basis but it gets added to our calender every 4 years & that year would be called a leap year. The day it falls on would be 29th February which will not be present for the other 3 years.
60849
There are 365 days in 2006 as there are in every year but leap year. The next leap year is 2008 and then every four years after that.\n\nThis year is one second longer though, as we had a leap second right at midnight on Jan. 1, 2006.
1064615
Every 4 years is a leap year.  2008, 2012, 2016 etc.
67005
Depends on if it is a leap year or not.
994954
Theres an extra day on the last week. Think how your birthday moves forward a day each year. Ther are actually 365 1/4 days in a year. The leap year every 4 years means this doesnt ever go out of synch too far
51580
Not quite. Years divisible by 100 are not leap years unless they are also divisible by 400. 2000 was a leap year, 2100 won't be a leap year.\n\nSo every 400 years you get 97 leap years, slightly less that 1/4.
249369
Is the term you are looking for "probability"?\n\nI hope this helps.
771065
Yes there is a better way than counting.\nBecause you have a leap year every four years, you can say that there are 365.25 days per year, as long as you deal in years that are multiples of four (which I will be doing). \n\nSo,  that means there are 52 + (1.25/7) weeks per year. \nThis is the same as 52 + (5/28) weeks per year. \nAs a top heavy fraction, this is 1461/28 weeks per year, and therefore there are 1461 weeks in 28 years. This is relevant because it is an exact number of weeks, the actual number 1461 doesn’t matter. This means that exactly 28 years ago, on 6 November, it was a Monday like it is today.\nSo, 6 November 1978 was a Monday.\n6 November 1950 was a Monday.\n6 November 1922 was a Monday.\n6 November 1894 was a Monday.\n\nWe have slightly overshot now, so we need to add on years. (I did this because it is easier to add than subtract, plus 1894 is closer to 1907 than 1922.)\nIn 4 years there are 208 weeks and 5 days (I found this by multiplying 52 + (1.25/7) by 4 to get 208 + (5/7) which is equivalent to 208 weeks and 5 days.)\n\nSo, 208 weeks after 6 November 1894, the date is 1 November 1898, also a Monday (because it’s an exact number of weeks later). 5 days later, it is a Saturday, on 6 November 1898.\nYou use the same process to find that it is a Thursday on 6 November 1902, and that it was a Tuesday on 6 November 1906.\n\nSince neither 1907 nor 1907 was a leap year (1904 and 1908 were), 365 days later it will be 6 November 1907.\n365 days is 52 weeks and 1 day. So, 52 weeks later, it is a Tuesday and the date is 5 November 1907, and the next day is 6 November 1907, and it’s a Wednesday.\n\nSo on 6 November 1907, it was a Wednesday.\n\nActually there is a slight problem with this method, because 1900 was not actually a leap year, but in this case it did not matter because the date is after 1900. You would have to adjust it very slightly for dates before 1900.
668819
It doesn't.  It actually takes 365.2422 days, which is why every 100 years the leap year doesn't have an extra day.  Except for years than are evenly divisible by 400, they do.  (To make up for the 0.0022 extra.)  This most recently happened in 2000 and won't happen again until 2400.
696135
If the year is divisible by 4 with no remainder, it is a leap year.
25917
If you take leap years into consideration, the average year contains 525,948.766 minutes.  A year with just 365 days contains 525,600 minutes.
53059
The number of days in a year is about 365.25, but is closer to 265.242..., so leap years are less often than every four years.
220111
Greetings:\n\nHaving selected one of the four, the probability that person #2 will have a different date of birth is 364/365 (if we seek no repeats, #2 can have any 364 of 365 possible b.days).  Similarly, having selected two, the probability that #3 will have a unique d.o.b. is 363/365 (any 363 of 365 possible dates okay).  Finally, for #4, the probability is 362/365.  Hence by the multiplication property, the probability that all four will have different b.days is given by, (364/365)(363/365)(362/365) = (364)(363)(362)/(365)^3 = 0.984 to three places.\n\nRegards,\n\nNikkor180
435037
try this site for help on probabiliity\n\nhttp://www.futureaccountant.com/probability/
1085792
It has occurred on \n\nAugust 1st, 2000, \nAugust 1st, 1995,\nAugust 1st, 1989,\nAugust 1st, 1978\n\nIt will always happen every 28 years. 28 years represents 7 days of the week X 4 years between leap years.