What are the chances of having a baby boy if I came from a family of G while my hubby came from a family of B?
97444
I (a man) have one full sibling (a brother) and my wife has a sister. We had a boy for our first kid in November. So, it happens. Good luck.
217222
Their children will either be A or B.  One parent will give either an A or a B gene and the other can give only O.  Since O is a recessive gene it will take two of them to make an O child.\nGenotypes:\nParents:  \nAB\nOO\nChildren: \nAO\nBO\n\nIf they have only one child there is a 50% chance of A type and a 50% chance of B type.
1141540
None I want to wait a while before I have any.Congradulations on your child any way,how old they!?But I want either 2 identical twin boys or just 1 boy or 1 girl thats it!
943595
The statements \n "At least one of the woman’s children is a boy, and the man’s older child is a boy"    are equivalent from the statistical\nperspective. The probability of the other child being a boy in each\ncase is 50%.
748142
Hi\nOne problem I see is this:\nConsider all your relatives.  You have more cousins (first, second, third, etc.)  than anything else (direct descendants, siblings, etc.).\nIf your father married his third cousin, then your father and mother have great-great grandparents in common (first cousins have a set of grandparents in common, second cousins have a set of great-grandparents in common, third cousins have a set of great-great-grandparents in common, etc.). So, if your father and mother have a set of great-great-grandparents in common, you cannot count that you have a set of great-great-great-grandparents from each parent. You should be counting one less set of great-great-great-grandparents that you actually have.  This reduces the number of individual great-great-great-grandparents that you have from 16 g-g-g-grandparents to 14 g-g-g-grandparents.\nGoing on in this way, you can see that the number of anscestors you have is greatly reduced if the above scenario were repeated more than once by your anscestors.\n\nIt basically comes down to the fact that each position in your family tree is not populated by different people in each case, i.e. one individual person can be more than one kind of relative to you.\nSo, to figure it out mathematically, you would have to know your family's intermarriage history (marriage between distant cousins, etc.) and the intermarriage history of every other person on earth, also.  Then you can adjust the 2^80 number you calculated.\nGood luck.
526088
YES,  yes,  yes.\n\nThe father  CAN  be blood type "O" and the mother\ncan be blood type AB. The baby will be A or B.\nSince the father thought his type was O, something is amiss.
314497
All three of these answers above me are correct.  Your biological mother would have to be BO and your biological father would be AO and the O allele in each would be recessive, or not showing its trait because of the dominant a/b allele.  A Punnett Square would look something like this:  \nMOM    \n       ||||||||||  B |||  O  |\n       ------------\nD||     A| AB |  AO |\nA||     -------------\nD||     O| BO |  OO | <- That's you with type O blood.  If you had three siblings it would be likely that one would have AB blood, one type A blood, and one type B blood. \n       ------------
744603
This is WAY to complex for laymen to comment on on-line...would be just guesses anyway.  You need to speak to your family doctor about a consult with a genetecist.  There may be no test for Ausberger's, but, then you don't know that is what it is.  Before having more children, please ask to speak to a genetics counsellor for your peace of mind.  Most OB docs can do this referral.  Hope things go well for you.
877364
Well, let`s see. My mom is hispanic and has hazel eyes and very black hair with medium skin. My dad is anglo and has black hair and green eyes and medium skin. My sister has brown eyes and black hair with a little darker skin, my brother brown hair and green eyes with medium skin, and I have grey eyes and reddish brown hair with medium skin. My mom`s sister is darker than her and all her kids turned out darker than us with black hair and brown eyes. Her husband was anglo also with brown hair and blue eyes. So what you get is a luck of the draw.
764599
no more then straight couples. If this ideal was correct then straight couples would never have gay children. just for the record my parents were straight as arrows. in fact I would go as far as to bet 95% of the LGBT people on here had straight parents.
249918
You are giving me the impression that green eyes are due to a recessive gene since you have brown eyes and a recessive gene for green eyes, and also since your husband has green eyes and has a recessive for green eyes, he must have both recessive genes for green eyes. In that case, here is your probability, maintaining that brown is dominant over green and that B stands for a dominant brown eye and g stands for a recessive green eye.\n\nHere is you then: Bg and here is your husband gg\n\n\nBg X gg  After chromosome segregation:\n\nB g  g  g  And then crossing,\n\nBg, Bg, gg, gg are the possibilities. Now wherever the dominant gene B is, the eyes will definitely be brown. So there are two kids out of four with brown eyes and two out of four with green eyes. And that makes it a 50-50 % chance that you will have either kid.\n\nWhatever you are hoping for, you have a good chance I believe.
31990
No this combination is not possible. Blood type is a combo of one of each parent's alleles.  Therefore an O could produce an A with an AB or A mother or a B with an AB or B mother, but not an AB.  Please use the link to calculate.
555226
I've never heard of it, but it could happen. I mean, monocygote twins (identical twins) are exactly alike, their development is the same like any other baby, except for the company :) So I guess it could happen, I've never read a report case on it. The odds of an hermaphrodite are very very low combined with the chances of monocygote twins, the odds are almost impossible (just guessing).
168198
Actually, the odds are not 50:50.  The chances are 51.4 male to 48.6 female.  So the odds are slighly in favor of a boy.\n\nhttp://www.ourstolenfuture.org/NewScience/reproduction/sexratio/sexratio.htm\n\nAs people have said, the births are not connected so outcome of each event is independent.  So each birth event would seem to have the same likelihood as any other birth event.\n\nHowever, there may be individual factors which are not accounted for in this study.  We have several friends who have all girls.  3 girls in one family, 4 in another. While statistically plausible, and I haven't found any specific studies on this, I'm betting that there are heredity and environmental factors that are involved. Certainly their's some interest in why the birth rates of certain countries deviate significantly from the norm.\n\nHere's another website that talks about ways of modifying your behavior that might increase the odds of a boy or a girl.  It's not scientific but in the quote: "Dr. Moore also notes in his book that selecting a child's gender shouldn?t be taken too seriously, but he thinks using his methods make trying that much more fun."\n\nhttp://preconception.com/resources/articles/tochance.htm\n\nOf course, if you choose to adopt and make a proactive choice of gender (boy or girl), you have a much strongest choice of influencing the odds.
968185
First the probability that a family of 4 is all girls is:\n1/16 (and the chance that they are not is 15/16).\n\nRather than figuring the chance of at least one family having this arrangement, figure the probability that *none* of the families do.  Then subtract from 1.\n\nThe answer will be 1 - (15/16)^10\nor about 47.6%\n\nIt's not a simple multiplication by n... if it were, then with 16 families you should have a 100% chance.  And with 32 families you would have a 200% chance.  That logic would be correct if you couldn't repeat a combination, but you can.  Just because family A has four boys, for example, doesn't mean family B can't also have four boys.\n\nLabel the 10 families as A, B, C, D, ... , I, J.  The probability that A has four girls is 1/16.  The probability that B has four girls is 1/16, etc.\n\nThe chance that *none* of them have four girls is 15/16 x 15/16 x 15/16 x ... x 15/16.  This is (15/16)^10 or about 52.4%.  Therefore the chance that at least one of them has four girls is 100 - 52.4 or 47.6%
398876
it's 50 50 every time.  genetics states that you get one chromosome from your mom (always X) and one from the dad, X or Y.  XX means girl, XY means boy. (assuming dad has even amounts of both).\n\nHence you use condition probablity assuming each occurance is a 50% chance.\n\n50% x 50% x 50% = 12.5%
1185780
yes, it is technically possible.\n\nHowever, as you say, it is almost infinitely unlikely.  The chance of fraternal twins being identical would be the same as any two other siblings being identical.\n\nEach parent has a pair of each of the 23 different chromosomes.  you will get one of two chromosomes in each set from each of your parents.  \n\nIf you assume the odds of getting any one of the two chromosomes of each pair from each parent are 50/50 (assume that each chromosome in each pair is different-which should be true unless there was some incest in your family), the odds would be 2^46 to 1 that a sibling happened to get the same 46 chromosomes.  that comes to about 1 chance out of 70 trillion. (that is, of being genetically identical).\n\nanother way to calculate this is to figure the odds of having two genetically identical eggs from a woman, which is one in 8.4 million, and mulitplying the odds of having two identical sperm from a man, which is also one in 8.4 million, and multiplying these two numbers together-which gives you 1 chance in 70 trillion.\n\nthere are other possible factors, such as how each egg was treated (so were some genes turned on or off), astrology, mitochondrial DNA (which should be the same between any siblings so shouldnt be a factor), development in the womb, and others.  However, i assume what you were talking about was if they could be genetically identical, which they can, 1 out of 70 trillion times.\n\nthe odds of winning the powerball lottery are 70 million to one.  so if you played the lottery one time for each time someone had twins, you would win the powerball lottery one million times for each time someone had identical fraternal twins.\n\nthe chance of two random sets of parents having identical twins is theoretically possible, but the odds of that are so extremely low, it makes the odds of the lottery or identical fraternal twins look like a near certainty.