the density of ice is 920 and sea water is 1030 what fraction of total volume of ice is exposed?
89138
If they were tha same density, the ice would float at the surface of the water. As more dense water buoys a body floating in it, the amount below the surface is 920/1030 so the amount above the water is 10.6%
164912
The ice gives the dissolved gas (carbon dioxide) a surface upon which to gather.  Once the bubble is formed, it is no longer in direct equilibrium with the liquid and rises.
937218
ice is converted to water and water to gas.
243283
Ice is already frozen, if you mean what temperature does water freeze at, then 32°F or 0°C or 273 K.
912617
P=P(0)*exp(-1.1e-4*H)\n\nP(0) is the pressure at sea level. Note it's temperature dependent and it assumes a stable Boltzmann type distribution.
71291
Water has its highest density at 4 deg. C.\n\nYou might try a Yahoo! search next time.  That's how I found the info.\n\nTake care,\nDavid Roth\nwww.tutor-homework.com
379947
MY GOD!  Don't answer if you don't have a clue.\nA) False - water is exactly 1g/cm3\nB) False - ice floats, thus less dense\nC) False - Water is made of two elements (Hydrogen and Oxygen), thus it cannot be an element itself.\nD) True - The mass of water does not change when it is frozen, melted or heated into steam.  It is still H2O.  No atoms were split or made!\nE) False
787311
A. H2O. Molecular water is 2H2O
862439
The steam.  It would have to go through a phase change and give up a bunch of energy to turn back into water at 100.  Assuming you mean equal mass of water and steam. \n\nSame question for ice.  How much energy does it take to melt 1 Kg of ice at 0 to water at 0?
495414
125% the density of water.
10120
Well When you fill the plastic bottle the volume of water is 250 ml. So the mass of water is \n0.997 x 250 = 249.25 gm.\nNow it is frozen to -10°C. But the mass remains same.\nHence Volume occupied  by the frozen ice is\nd = m/v\nTherefore v=m/d\nHence v = 249.25/0.917 = 271.81.\nHence the ice expands. Hence the bottle will grow a bit in volume!!
1036867
Of course ice and water are chemically identical consisting of H2O.  The two hydrogen atoms attach to the oxygen atom other than in a straight line (not like beads on a string).  The electron field surrounding the water molecule is uneven providing it with a "polarity" that makes it much easier to pack many molecules together in a given (rather than arbitrary) arrangement.  When water is a vapor (or steam) there is so much vibrational energy that the molecules bounce off each other maintaining a "pressure" depending on their energy (temperature).  When the molecules are a liquid, they are very closely packed and are nearly incompressible (even seven miles below the surface of the ocean!).  The bulk water expands and contracts only a little with temperature changes.  When heat is removed from the water (in a freezer?) the molecules are attracted to each other in a preferred array due to polarity and form long chains of molecules that use up space far less efficiently.  The "ice" is less dense and floats on water because the space between chains is filled with a vacuum or gases that weigh very little.  When the water is allowed to freeze in open space (a cloud?) the polarity is free to align water molecules in the most preferred orientation; a six sided snow flake.  When hoar frost forms on a cold window pane the ice forms in dendrites, like growing Christmas trees.  Hope that helps a little.
470314
the specific gravity of water is 1.
143592
Heat required to rise the temperature of  ice from \n-10 degree centigrade to 0 degree centigrade \n= ms(t2-t1)\n=10 * 2.1 * 10  g* {joule/(g*degree)} (degree)\n=210 joule\n\nHeat required to convert ice to water  \n=mass x specific latent heat fusion of ice \n=10 * 336  g*joules per gram\n=3360 joule\n\nHeat required to rise the temperature of  water from \n0 degree centigrade to 100 degree centigrade\n=ms(t2-t1)\n=10 * 4.2 * 100\n=4200 joule\n\nHeat required to convert water to steam\nmass x specific latent heat of vaporisation of water\n10 * 2264\n22640 joule\n \nHeat required to rise the temperature of steam from \n100 degree centigrade to 110 degree centigrade \n= ms(t2-t1)\n=10 * 2 *  (110-100)\n=200 joule.\n\ntotal of all is  30610 joule.
781761
The answer is either 0% or 100%. If ice is 0 degrees C it will remain as ice. [in theory]
260885
water represent 2/3 from earth surface
252337
The figure I have from a university course was 45m (roughly 80ft).  You can discount any ice floating on the sea, such as the North Polar icecap,the large ice shelves around Antartica and the sea end of glaciers as they havealready displaced the equivilent amount of water already (imagine a glass fullof ice and water, as the ice melts the glass does not overflow).\n\nIf all the ice were to melt the rise would not actually be directly equal to the amount of water resulting due to differences in the densities of salt and freshwater.  Taking the temperature into account the molten ice would be denser than the warmer saltwater so reducing the overall rise.