if a and b are both equal and a is 34 what is b?
92305
a= 34\n\na=b\n\ntherefore, b=34.\n\nunless this is a trick question.
38366
I think this is the answer\n\na^2-2ab-b^2\n-a^2(b-b^2)\n= -a^2
895454
There is no ordered pair {a,b} which solves both equations\n\nif a+b = a-b , then 2b = 0 or b = 0 and a is anything\n\nBut the second equation is not defined for b=0, no matter what a is (specifically, a/b is not defined for b=0)
988850
In this case A, B, and C are all equal.  And yes, A will always equal C.
150867
Your question makes no sense. There is no equal sign. What do you want to solve for? Why so many powers (a^b means a to the power of b)?
435670
lets assume b = a/2\ntherefore 2b = a\n\nnow sin 2b = 12/13\n\nsin 2b is also equal to 2sinbcosb\n\nso 2sinbcosb = 12/13\n\nsinb * cosb = 6/13\n\nnow u know that cosb = sqrt ( 1 - sin^2 b)\n\nso sinb * sqrt(1-sin^2 b) = 6/13\n\nor sin^2 b * (1 - sin^2 b) = 36/169\n\nsubstituting sin ^ b = x\n\nyou get x - x^2 - 36/169 = 0\n\nThis is a simple quadratic equation\n\nsolving for x you get\n\nx = 234/338 or x = 104/338\n\nso you get sin b is sqrt (234/338) or sin b is sqrt(104/338)\n\nsince a is in the first quadrant, the value of sin a/2 will be less than that of cos a/2 since a/2 is less than 45 degrees.\n\nSo, sin a/2 = sqrt of (104/338)= 0.554\n\ncos a/2 = sqrt of (234/338) = 0.832
831094
36. >\n38. =\n40. >\n42. <\n44. <
451313
$107 = x - 34  \n107 + 34 = x  \n$141 = x
771168
1= B\n2= A\n3= D\n4= D\n5= D\n6= C
961456
assume b=boys ; g=gals\n\ng = (2/5)b\n \nb+(2/5)b =35\n(7/5)b=35\nb=25\n\nso , g=10 ; b=25
728108
A plus B equals C. That's the only algebraic phrase I remember.
722973
K=positive then U=negative K=U=A and B=equal.
970698
(a + b)(c + d + e)\n= a(c + d + e) + b(c + d + e)\n= ac + ad + ae + bc + bd + be\n\nOR\n\n(c + d + e)(a + b)\n= c(a + b) + d(a + b) + e(a + b)\n= etc.
833820
No one has answered it correctly \n\nlet a = x^2\nb = y^2\n\nx+y^2 = 31 ..1\nx^2+y = 41... 2\n\nfrom 1 \n\nx= 31-y^2\nso (31-y^2)^2 + y = 41\nor 961-62y^2+y^4+y = 41\n\nor y^4-62y^2+y+920 = 0\n\ny if real is a factro or 920\n\n1,2,4,5 \n\nby trial and error y =5 makes it zero\n\ny(1) and Y(2) are too high try 4 and 5\n\nso b = 25 and a = 36\n\nthis is answer
36273
(A^3 + B^3)=(A+B)(A^2 - AB + B^2)
556722
look at my question\n\nBidDogARRRRR...\n1 minute ago\nDoes anyone know 0=1 and anything = anything else?\na = 1; b = 0\n1. a = b + 1 \n2. (a-b)a = (a-b)(b+1)\n3. a2 - ab = ab + a - b2 - b \n4. a2 - ab -a = ab + a -a - b2 - b\n5. a(a - b - 1) = b(a - b - 1) \n6. a = b\n7. b + 1 = b \n8. Therefore, 1 = 0
678730
If a is greater than or equal to 0, then a=|a|.  And if you add two positive numbers together, their answer will also be positive, so a+b=|a+b|.  Substitute these equalities in, and you will get the simple equation, a+b=a+b.  It's fairly obvious that that's true, so you've solved the problem.