What types of systems are easiest to do using the process of substitution?  What types of systems are easiest?
91756
Ok if you have like 5x+6=y,and x=2,then obviously use substitution. Substitute the x for the 2 and solve. Y would equal 16. If you have any system that has variable=whatever then that would be easier because in the second equation you would just have to substitute the variable for whatever it equals. Hope this helps.
808897
easy!\n\nwww.wikipedia.com
604097
actually there are more than 2 types....\n and I'm not kidding..\n but if you want 2....\n i would go with compound and simple...there are some how intersting to read about.
826575
Use one equation to substitute into the other,then solve for a one variable problem.  Use your new information (the solved variable) to solve for the second variable.\n\nFor the first set:\n\n-3x - y = 2 rearranged becomes:\ny = -3x -2\n\nUsing this "definition" of y, substitute it into the second equation as such:\n\n-6x + 2(-3x -2) = -2\n-6x - 6x - 4 = -2\n-12x = 2\nx = -1/6\n\nSubstitute -(1/6) for x in either equation to solve for y:\n\n-3(-1/6) - y = 2\ny = -3/2\n\nDo the same for the second pair of equations to make sure you got it (the answers for x and y are x=9/7, y = 1/7).
49208
The types of reactions are endothermic and exothermic.Also there are the types like reversible and irreversible.And according to me there are four types of reactions:-\n1) Displacement Reactions\n2) Combination Reactions\n3) Decomposition Reactions  &\n4) Double Decomposition Reactions.
130202
regular, reverse and atomic
69889
Java or C.\nChoose Java, because it's similar to C, and easier to learn, due to Java's consistent handling of storage locations by reference, and automatic handling of memory management.  As a bonus, you can run your program on any system that supports Java, and embed your program as an applet accessible from anywhere with Internet access. Should you require more efficiency, you can relatively easily translate your program in Java, to a program in C, after you learn and know C.\n\nI'm limiting my answer based on the assumption that you personally want to *learn* a programming language.  You would likely expend fewer resources by simply giving your problem data to a programmer for hire.  If your script conversion doesn't require capabilities like grammar recognition, any programmer with a clue can code a basic utility in minutes.\n\nNote to programmers: I base this learning approach on a graduated, learn as you need to know, rationale, that leaves open a transition path to maximum product efficiency (C or C/assembly), or to high efficiency with a graphical interface (C or C++).  I acknowledge that less ubiquitous higher level languages exist that are better suited for specific types of text processing.
428665
This one is fairly clear.  Hope it helps.\n\nhttp://www.math.hmc.edu/calculus/tutorials/substitution/
934633
By substitution, the first equation when substituting in y=2+x becomes:\n4x - 4(2+x) = -8 ==> -8 = -8 which is always true.  This means that what you have are two equations with an infinite number of solutions, as the two lines are the same line.  So any pair of the form (x,x+2) such as (0,2) or (1000,1002) will work.
52711
shift or change\nfixed or immobile\nvector
865842
Energy\n\nA chemical reaction simply supplies energy to the system
965420
You have to use trigonmetric substitution, which is by far, the hardest type of integration.  It also involves making diagrams of triangles, which I hope you will bear with me with this limited interface.\n\nSo we want to solve for Integral (1/(1+y^2))dy.  You have to use trigonometric substitution, and \n\nlet y = tan(x).  Then dy = (sec(x))^2, or "secant squared x", and we just directly substitute that.\n\nIntegral (1/(1+y^2))dy = \nIntegral (1/(1 + (tan(x))^2) (sec(x))^2 dx =\n\nNote:  In trigonometric substitution, unlike the regular type, you're also replacing dy for what you solved for.\n\nUsing the trig identity (sec(x))^2 = (tan(x))^2 + 1, we get\n\nIntegral (1/(sec(x))^2 * (sec(x))^2) dx = (the two values will cancel each other out into 1)\nIntegral (1)dx =\n\nx + C\n\nRemember that above, we let y = tan(x), so we have to solve for x, and we get x = tan(inverse)y, or tan(x) with a -1 value between the "tan" and the "x".  The reason for this step is we require an answer __in terms of y__.\n\nSo, our actual answer is tan(inverse)(y) + C
917224
Simply use correct order of operations\n\nparentheses\nexponents\nmult/division (from left to right)\naddition/subtraction (from left to right)
981128
1. synthesis\n2. single replacement\n3. decomposition\n4. single replacement
396820
i think a transposition cipher cuz if u figure out one letter, you have figured out the rest. in a substitution cipher, a letter could be any letter and if you found one, you still would not know the others.
954291
the most important factor would be TIME. for example think about all the softwares that are daily used in businesses, what if they did not exist? how long and tiring would the procedure be to complete a simple process...
382957
I you can express the problems in mathematical relations, yuo can use calculus  everywhere. For businesses you can use differentiation to find sensitivity of for example of profit to  a unit change in cost or sales or production.  you can use integration to find out over all profit or production, etc.