Define Mw generated Per Hour?
90631
energy because power wich is in mw multipiled by time wich is actualy in seconds or hour equals energy wicj is in joules
896349
RPM=120*FREQUENCY/P\nRPM=120*50/4\nRPM=1500 RPM.\nnow you want to run motor on 60 hz supply and others parameters same,then\nRpm=120*60/4\nRpm=120*15\nRpm=1800.\nRpm will be increased by 20 %.\nIf the 60 hz is permitted , then you will get 20 % more production.\nWe have lost production what we have expected as we are using 50 hz supply system and machine which we have procured having capacity based on 60 hz capacity!
143077
how much radiation you absorb in an hour\n\ni assume you mean mR/hr
781911
None.\n\nCalories are a measure of the heat content of objects.  If you are referring to the amount of heat radiated by the earth, it would be stated in some unit appropriate to the measure of radiant energy, such as watts or newtons per second.\n\nYou may be able to find an answer by visiting the library or using the internet.
327062
kWh is NOT Kilowatts per hour. It is Kilowatt Hours and is the measure of the amount of energy drawn in one hour hour if it is drawn at a rate of one Kilowatt.\n\nKilowatts are a measure of Energy per unit time ie. Joules/s so kWh are J/s x 3600 s ie. measured in Joules.\n\nThe peak is just the highest energy usage rate in a given time period
588292
22) 75 Watts X 6 hours X 30 days = 13,500 Watt-hours\n\n  Divide this by 1,000 to get kWh, which is 13.5 kWh.\n\n23) 60 Watts X 6 hours X 30 days = 10,800 Watt-hours\n\n  this equals 10.8 kWh.\n\n  13.5 kWh - 10.8 kWh = 2.7 kWh saved\n\n24) 12,000 Watts equals 12 kW.\n\n  12 kW X 2 hours = 24 kWh
511371
8,639,930 Joules\n\nEnergy is represented by units of Joules.\n\n1 Joule = 2.7778×10−4 watt-hour\n\nassume your battery can deliver 100 AMPS for 1 hour at 24 volts\n\n(24V x 100A) x 1 hour = 2400 Watt-Hour\n\n2400 W-H / 2.7778 x 10^(-4) = 8,639,930 Joules
496124
Calculate the electricity.
765230
EER = Q in (BTU/hr) divided by W in (watts)\n\n600/500= 1.2
349215
mechanical power, P = Work done per unit time = W/t\n\nElectical Power P = current times potential difference = IV\n\nfor ohmic devices we can also use the substition from Ohm's law V = IR in the power formula above.
340440
power is the amount of work done in unit time \nit is measured in Joules per second , dude
215059
classes are defined by power usage and range:\nClass 1 = 100 MW, range up to 100 meters\nClass 2 = 1-2.5 MW, range up to 10 meters\nClass 3 = 1 MW, range of 0.1-10 meters
162775
One kilowatt used over a one hour period is one kilowatt-hour.  To find out how many kilowatt hours an electrical appliance uses, look on the label (wattage - say 300 watts).  Divide that by 1000 to get kilowatts (0.3 kilowatts).  Now multiply it by the time you are going to use it for (say 20 minutes [6 kilowatt-minutes] - divided by 60 minutes in an hour [0.1 kilowatt-hours]).  The result should be the number of kilowatt-hours used.
621263
Now See\nA typical monitor has  about 60 watts to consume to show the display.\nAnd a CPU Adapter takes 10-12 watts.\nThe normal speakers with woofer if you add take 5 watts.\nAdd these quantities Total Watts = 60+12+5=77\n\nConvert above value In KWh (Kilo Watt Hour) electrical units\nBecause we have to calculate the unit consumption hourly.\nKWh= 77/1000 = 0.077 unit\nThis figure is for the whole hours comsumption in kwh unit, because utility companies multiply the unit consumed into price/unit.\nsimply price = units * (price/unit)\n             = 0.077 * ? your price\ne.g.         = 0.077 * (20 cents/unit)\nprice for 1 hour = 0.0154 dollar\nprice for 24 hours = 0.0154 * 24\ntotal price a day  = 0.3696 cent\nHow much power you consumed in 24 hours\n= .077*24 = 1.848 Kilo Watts\nnearly 2 units per day 24hours.\n\n\nhttp://360.yahoo.com/jcbroogley
611115
Do you mean ML/hr (mega litres per hour) OR nL/hr (nano litres per hour)?\n\n1 litre  = 0.035315 cubic feet and of course 60 min = 1 hour\n\nSo 1 ML/hr = 0.035315 x 10^6 / 60 = 588.6 cubic feet per min
612298
up to 10 trillion watts
88686
You are usually billed by the electric company in terms of how much energy you use per month.  The unit for measuring this is given in kiloWatt-hours (kWh).\n1 kWh is defined as the amount of energy consumed by something drawing one kiloWatt of power consistantly for 1 hour, or something drawing 1 watt for 1000 hours (or any combination there of).\n\nSo, for example, say your computer opperated at a constant 200 watts for 12 hours a day for 30 days straight.\nDaily energy consumption = 200 watts * 12 hours = 2400 katt-hours.  For 30 days, that would equal 72000 Wh or 72 kWh.\nI dont know how much energy costs where you live, but for me it is roughtly 12 cents / kWh, so that would come to $8.64 per month.