what is the value of zero over zero?
95725
Zero of zero is undefined because of the definition of division and some basic field axioms.  It's not zero and it's not infinity, it's UNDEFINED.  I can prove it.\n\nThe multiplicative inverse of n is defined as the number 1/n such that n*(1/n)=1.  It's a property of zero that anything times zero is zero.  Therefore for any 1/n, 0*(1/n)=0, and since zero cannot equal one, zero has no multiplicative inverse.\n\nDivision by n is defined as multiplication by the multiplicative inverse of n.  Since zero has no multiplicative inverse, you cannot divide by zero.\n\nAll you people who said that anything divide by zero is infinity are just flat out wrong.  If n is not equal to zero, the limit as x approaches zero for the positive side of n/x is infinity, but that does not mean that n/0 is infinity.  Also, note that if you come at it from the negative side the limit is negative infinity.  n/0 is undefined because zero has no mutiplicative inverse so the expression 1/0 is mathematically meaningless  Also, the limit of 0/x as x approaches zero would be zero, not infinity.\n\nWhoever it was who did the calculator thing, calculators are a far cry from a mathemtical proof.   There are plenty of arithmetic problems that make perfect sense but can't be done on a calculator.  In fact, there are infinetly many of them.  And there are some properties of multiplication and addition that can be proven mathematically but are not true on a calculator.  But you and the first poster get major props for being the only people to answer this question and demonstrate anything resembing an basic understand of elementary arithmetic.\n\n______\nH2++ cannot exist because it would have to have a covalent bond but would have no electrons.  Two hydrogen nuclei can't form a diatomic molecule.  O-- is not going to exist in water because the hyrogen atom would have to dissociate from the water molecule one at a time, and OH- is more stable than O-- and H+.  It could in theory exist as 2H+ and O--, but OH- is a much happier molecule than O--.\n\nNothing can go faster than the speed of light because as an object approaches the speed of light it's mass becomes infinite, and so the force required to cause it to accelerator more becomes infinite.  You can't apply infinite force to something.  Normally I'd do out the math to show that, but it's 3:30 in the morning so I doubt I can make it coherent.\n\nTensor calculus is too complicated to explain at 3:30 in the morning.  You can read about it here: http://en.wikipedia.org/wiki/Tensor_calculus
1137788
Nope, 0/0 could be 1 but it could also be anything else.   Division is the opposite of multiplication and 0 times anything at all, even infinity, is still zero.
228129
It's an expression (i.e. not an equation (no equal sign).\n\nIf it was an equation that equaled zero:\n\nt^0 equals 1 so that quantity equals 2.\n\n18t^2-3=0\n\nt = +or- 1/sqrt(6)
168972
Your question does not make sense. x cannot be less than or equal to 0 and less than or equal to 7 unless it is less than or equal to 0, which I do not think you mean. \n\nI think you mean 0<=x<=7\n\nThe rest of the question makes no sense. \n\nAnd it really smells like a homework problem. Try thinking for a change.
455800
if by o you mean zero then the answer is either \n\ntemperature is less than or equal to -7 degrees \nor greater than or equal to +7 degrees, \n\nif the o is actually an o then \ntemp is less than or equal to (o-7) degrees \nor greater than or equal to (o+7) degrees
535905
0 ( Zero )\n\nThe most importanat number which enables us to progress.
754976
It's true.\nThe answer is indeed y = 0.\nYou can find this by dividing each side by -4.\n-4y = 0\n-4y/-4 = 0/-4\ny = 0\nRemember that zero divided by any nonzero number is always zero.
68748
uhm, ZERO!  0x2=0  what, did you fail basic math?
579225
Division by zero is undefined, even if you divide zero into zero.\n\nhttp://en.wikipedia.org/wiki/Division_by_zero
706980
Zero is in the Hundreds position. \n\nTwo is in the Thousands, \nOne is in the Tens position,\nNine is in the Ones position.\n\nOnce you move to the right of the decimal, it is:\n\nFour in the Tenths position,\nSix  in the Hundredths position,\nand Three is in the Thousandths position.
914435
x > 5\n\n- - - - - -s-
846187
if you are using a "while" or "do while" loop\n\nwhile ((x1 - x0) > 0.001)\n{\n//your code here\n}\n\nor you can do this\n\ndo\n{\n//your code here\n}\nwhile ((x1 - x0) > 0.001);
621381
b) Replace y with 0\n(100+x)^0 = 2*100^0\n1 = 2*1\n1 = 2\nThis implies that y cannot be zero.\nc) Replace x with 0.\n(100+0)^y = 2*100^y\n100^y = 2*100^y\n0 = 2*100^y - 100^y\n0 = 100^y\nThis is never true.\nThis implies that x cannot be zero.\na) The graph looks similar to the graph of y = 1/x
90067
There's no answer actualy. O cannot be divided by 0. \nThe answer infinity is just an assumption when \nnumber really near to 0 divided by another number near to 0.\n\nSuch as 0.0000000000000000001 / 0.0000001\nAlthough the example doesn't really show number near to 0, but if you change to 0.00000000000000000....01, you will see the same result
843943
4, 0, -2, -2, 0\n\nFigure it out! Don't be lazy!
230430
The square root of -1 has no relation to zero.  It requires an imaginary number.  Division by zero is, unfortunately for our number system, impossible.  You cannot cut something into zero pieces, and in fact the very statement makes no sense.
596523
If you are approaching zero from the left, then -1 divided by 0 is positive infinity.\nIf you are approaching zero from the right, then -1 divided by 0 is negative infinity.\n-1 divided by 0 is undefined because you get different results when coming in from the right side of 0 and the left side of 0.\nI learned this in Calc 1 (possibly Calc 2).\nThere are different levels (degrees) of infinity.