At what speed of rotation of earth would we be thrown out of earth?
93072
As we are not, the Earth is spinning at a pretty constant speed (1 rotation / day).  Based on the position we are on the Earth, we are traveling around at different speeds, the closer one is to the equater, the faster one is traveling.\nAt the same time, the force of gavity is pulling us toward the center of the Earth, this force acts as the centripetal force (NOT to be confused with the ficticious centrifugal force) that keeps us in circular motion.\n\nIf the Earth's rotation we to increase, the force needed to keep up down on the ground would need to increase too.  However, the force (gravity) is only so strong, it can only pull up down by some much.  So it one were to increase the spin of the Earth enough, it is possible for the centripetal acceleration to equal the gravitational acceleration....therefore we would be weightless.\n\nBut now the question is, what happens is we further increase the Earth's rotation past this point of weightlessness?\nIf you spin the Earth faster, our weight would not be enough to keep us in the circular motion we are currently in, so it would have the effect of seeminly lifting up off the ground.  HOWEVER, we would not fly up into space.  The moment we leave the ground, the centripetal acceleration needed is reduced (a = v^2 / r, when r increases, a decreases).  If we could maintain a constant speed once we leave the ground, we would eventually lift up enough to that we get to a height so that the centripetal acceleration equals the gravitational acceleration again and we would hover at that height.
673492
No. If the Earth suddenly came to a stop and started orbiting the sun in the opposite direction it would probably kill us all. Inertia is not your friend.
1061210
If you're not taking earth rotation into account, the value of GMe is 9.8 * (6.38E6)^2, so the square of the radius required is that value divided by .660, the root of which is 2.4584521E7.  Subtracting the earth radius from that gives\n\n1.8204521E7, or about 18 million km.\n\nIf you're considering a point that stays directly above the earth as it rotates, the nswer depends on the latitude and is the solution of a cubic equation.   I'm not going there for you!
1018691
about 1000 mph.\n\napprox #'s here--earth is 25,000 miles in circuvfrence, 24 hours per day.   this is at equator.\n\ni am thinking, the farther away from equator, the speed can be progressivly slower.
448267
the average orbital velocity of earth is 29.783 km/s.\n\nhttp://en.wikipedia.org/wiki/Earth
834910
You would need to travel at the same speed as the Earth rotates, but also take into consideration the distance you have to travel due to the circumference of the Earth. I.E. If you were on the equater you could work it out easy...take circumference of the earth at the equator (40,000Km) and you know you want to stay in the same spot so for one rotation its 24 hours,  speed = distance over time so at the equator your speed would need to be 1666 Km/h. However because the circumference is smaller at Latitude 51 32N (London) The speed would need to be reduced. But by how much im not certain as I dont not know the relationship between the two circumferences\nHope that helps
324486
Add v2/R.\nv=speed of rotation at the suface of the earth.\n(it depends on the geographic altitude fi)\nR = radius of the earth.
925006
Since the magnitude of the acceleration is v^2/r, and the radius of the Earth is approximately 4000 miles (21120000 ft), you would have to solve the following equation: v^2/21120000=32\nv^2=675840000\nv=25997feet per second  or\nv=4.92 miles per second
53782
The Earth rotates on its axis at 1000 miles per hour (1600 kph). It orbits around the Sun at an average speed of around 67,250 miles per hour (107,600 kph). The Sun, in turn, is orbiting around the centre of the galaxy at a speed of 540,000 miles per hour. So the combined speed through space of the Earth and the Sun is 607,250 miles per hour. But there´s more - our Galaxy is also hurtling through space at a speed of 360,000 miles per hour. The combined motion of the Earth, Sun and Galaxy means that we are about twenty three and a quarter million miles away from where we were in space this time yesterday.\n\n  The Solar Sytem is believed to be about 4.5 billion years old but it's constituent parts were undoubtedly moving even before that. It is predicted\nthat our Milky Way galaxy will collide with the Andromeda galaxy in, roughly, 5 billion years.
855234
Earth rotates 360 degrees in 24 hours or 15 degrees per hour that it goes through 0,5 degrees of rotation in two Minutes\n\nClick on the URL below for addition information concening the earth rotation. See Item 17\n\nhelios.gsfc.nasa.gov/qa_earth.html \n\n. - - - - - - - - - - - - - - - - - - - - - - - - - -\n\nThe diameter is 7926 Miles\n\nCircumference\n\nc = d π\n\nc = 7916(3.141592654)\n\nc = 24900.26337 miles\n\nClick on the URL below for additional informatio concerning the circumference of the earth\n\nwww.lyberty.com/encyc/articles/earth.html \n\n- - - - - - - - - - - - - - - - - - - - - - - - \n\nSolving for earth rotation per degree in miles\n\n24900 ÷ 360 = 69.16666667\n\nThe earth  rotates 69.2 Miles for each degree of rotation. Rounded to one decimal point.\n\n- - - - - -s-
1029696
0,000694rpm -> considering that the Earth rotates in 24 hours\n0,000696rpm -> considering that the Earth rotates in 23h and 56 minutes (which is the real time in which the Earth makes 1 revolution)
151979
I tried to figure this out and it's incredibly complex, as it turns out.\n\nThe earth rotates at a little over 1037 miles an hour, so you've got that.\n\nThe earth revolves around the sun at about 66486 miles an hour, so you add that.\n\nThen you consider that the sun is moving toward other stars at 45,000 miles per hour.  (and taking us along with it.)  So if you were outside our solar system, you'd see that too, I guess.\n\nThen you add that the sun moves up and down (if you consider the disk of the solar system to be the horizon) at about 261 mph.\n\nThen you add in the sun revolving around the galaxy, which is a difficult thing to calculate, but it can be figured that the sun revolves around at about a blistering 447,386.4 miles per hour.\n\nAdd that all up and you see that, relative to a person standing OUTSIDE the galaxy, we're moving at ABOUT....\n\n\n493,684 miles per hour!  That's awfully fast!\n\nNow, I have no idea how to calculate this, but the whole galaxy is moving as the universe expands...\n\nBut, hope that gives you somewhat of an answer.
1044221
I would think that you would spiral toward Australia and then back toward us with the mid point at the center of earth's mass, each time not going as far as before .  \n\nThe reason that you would basically oscillate like that, is that the force of gravity increases the closer the centers of mass are to each other (the closer you got to the center of the earth) and so you would be accelerating the entire way till you got there and you would continue going because there would be no force acting on you to decelerate you.  As you start going away from the center toward the land down under, the force of gravity would act against your current velocity, till they cancel each other out and you start to fall toward the center of the earth this time the other way.  The reason that you would not quite make it out the other side of the hole is wind resistance and other very small forces would be affecting you. \n\nAssuming I'm right, you would eventually end up rotating in 3-dimensions around your stomach (or where ever your center of mass is) at the center of the earth.
842146
Well the earth orbit's the sun \n2AU * PI / year\n\nAn AU is the average distance of the Earth from the sun in it's orbit.  Although all orbit's are ellipses, the equation of a circle should approximate close enough.\n\n1AU =149.598×10^6 km.\n2AU = 299196000 km \n\nThe earth moves really fast so we should convert years into seconds.  The earth orbits the sun once about every 365.25 days (the .25 is why we have leap years).\n\n365.25 * 24 * 60 * 60 = 31557600 seconds.\n\nSo now all we must figure out to get the speed in km/sec we calculate \n(299196000 * PI) / 31557600\n=29.785280109497\n\nSo the Earth orbits the sun at a speed of 29.785280109497 km/sec.  That's pretty fast!\n\nWikipedia gives a max orbital speed of 29.783 km/sec and a min orbital speed of 29.291 km/sec, so my estimate was pretty darn close.
559917
First, the speed of the rotation of the earth relative to where you are on the earth.  At the equator, the circumference of the Earth is roughly 24000 miles.  This is convenient, because the Earth rotates about its axis once every 24 hours.  Therefore an hour = 1000 miles of equatorial rotation.  Understand the fastest moving part of the Earth is the equator, since an object on the equator travels 24000 around the earth's Axis every day.  If you are closer to the poles, you are on a "thinner" slice of the earth, where the circumferene may only be 20000miles.  In that case you are moving at 833 miles per hour.  The fact that the Earth moves faster at the Equator than at the poles is responsible for the Coriolus Effect which is really important to people who study meteorology, or who wonder why their toilets get all swirly when flushed.  Why we don't "feel" the rotation is, simply put, because we are rotating exactly the same way as the earth.  In physics, this is called a "frame of reference".  For most intents and purposes, the earth is at "rest" relative to us.  As a human, you make up part of the mass of the earth, and you spin with it in a constant rotation.  It's only when we look to things that are not directly connected to the earth that we really see the effects of it's rotation (ie Tides of water, moments of clouds and weather, etc. . .)  Hope that helps.
230260
First, the Earth is rotating at about 1,600 km an hour. Second, a full Earth orbit takes 365.242 Earth days, or about 8,766 hours. We can find the "circumference" of Earth's orbit by taking the radius (about 150,000,000 km) and multiply by 2pi, giving us about 940,000,000 km. Rate equals distance over time, so (940,000,000 km)/(8,766 hours) equals about 107,300 km per hour. \n \nSo far: In only the solar system, Earth's maximum speed is about 109,000 kmph and minimum speed is about 105,500 kmph.\n\nHowever, the solar system is orbiting around the center of the Milky Way galaxy. We are about 2/3 of the way out on the 100,000 light-year disc, or about 624,394,875,000,000,000 km. It takes us 200 million years to orbit. I'll shorten this and not completely lay out the math..................\n\nroughly 2,240,000 kmph.\n\nAdd this with our previous number to get:\n-Earth's maximum speed: roughly 2,357,000 kmph\n-Earth's minimum speed: roughly 2,130,000 kmph\n\nBut wait: we're not done yet. The Milky Way is speeding through space towards the (relatively) near-by Andromeda Galaxy at 600km every second, or 2,160,000 kmph. Factor this in to get our final result:\n\n-Earth's maximum speed: roughly 4,500,000 kmph\n-Earth's minimum speed: roughly 197,000 kmph\n\n\nSo how does all of this confusing math relate to your question? Look at this set of data. Regardless of the Earth, the Milky Way is cruising along at roughly 2,160,000 kmph. The Earth, however, relative to the Milky Way, is moving as much as about 2,357,000 kmph and as little as about 2,130,000 kmph.\n\nSorry this is so long winded.
90857
It depends on where you dig the hole !\nIf you dig it on the north Pole (or south Pole) you would accelerate until wind drag compensates for gravitational forces (around 200 km per hour, approximately 120 miles per hour)\nThe gravitational forces become weaker the more you enter the center of the earth (and vanish at the center) so your speed will decrease to a minimum(some speed might remain, because wind drag increased with speed).\n\nI think that you would get stuck near the center of the earth.\n\nIf you dig a hole on the equater, you will probably notice after an hour or so that the wall of the hole seems to get closer to you.\nThe reason is the rotation of the earth: on the equator, you have a speed of some 40,000 km per day (24,000 miles per day - 1000 miles per hour).\nAt lower heights, the earth will still turn in 24 hours - but the circle is smaller, whence the speed.\nAs a consequence, you are likely to scrape against the wall.\n(and remain stuck in the center of the earth as well).