How e number(alomost=2.7) is calculated?
79257
e = 1 + 1 + 1/2! + 1/3! +1/4! +1/5!+....\n\n\nThat's the MacLauren Series for f(x) = e^x evaluated at x=1.
239849
.7M x 20mL = .25M x (Volume of new IA solution)\nVol = (.7 x 20) / .25\nVol= 56mL
951454
it is 178 * 177 !\n\nthis can always be computed.
639100
A = Pe^(rt)\nP = 25000, r = .08 and A = 50000 (since you are doubling and 25000*2 = 50000)\n50000 = 25000e^(.08t)\nDivide both sides by 25000\n2 = e^(.08t)\nTake the ln of each side\nln(2) = .08t\nDivide each side by .08\nln(2)/.08 = t\nt = 8.664339757
386376
My computer gives me this 4 real results, there are two more Imaginary results.\n\n1) -1\n2) 1.8698\n3) -0.260\n4) -2.688\n\nImaginary roots are\n\n5) 1.039 + j1.40\n6) 1.039 - j1.40
821366
2.7*10^-5\n7.041*10^5
534027
function f1(){\nvar e = 12.88;\n\nvar e1 = e + "";\n\nif(e1.indexOf(".") != -1){\nif(e1.substring(e1.indexOf(".")+1,e1.length).length >  2)\nalert (" Invalid");\nelse\nalert ("Valid  "+e1);\n}\n}\n\nTest with changing the Value of e to different numbers
981364
Gopal has the correct answer! \n\nSo... becareful with some other results... and... never use:\n0.833 instead of 5/6... it's a mistake!\n\nFinished Algebra with 19!
389904
Multiply 12.75 by a conversion factor of 2.54 for an approximation.  It's a little over 32
559931
the book would not be wrong if that number is [OH-]\n\n[OH][H+]=1e-14\n\npH = - log({1e-14}/(7.2e-11))\npH = 3.86
400127
C  H   O\n.6  12   6\n\nWITHOUT DECIMAL POINT
798483
Here it is:\n\n(98,42)Mo + (1,0)n ---> (99,42)Mo
298505
7.7460824293385895341052207744781\n\nFollowing Correct order of operations:\n\n2 + (2x24.546/8.54356)+10*0\n\n2 + (5.7460824293385895341052207744781) + 0\n\n7.7460824293385895341052207744781
869649
For (1.23e11)*25,  multiply the mantissa (1.23) times the regular number (25), and leave the exponent alone:\n30.75e25.\nNow, move the decimal point of the mantissa to the left one space, and increase the exponent by 1, to keep the value the same:\n3.075e26.\nHere's another example:\n(8.74e12)*498000 = 4352520e12 = 4.352520e18.  You'd probably want to round that off to 4.35e18.
470294
Press Alt and the numbers 164 = ñ\n\nPress Alt and the numbers 165 = Ñ
352749
By the chain rule:\n[e^(3x^(2)-7x)]*(6x-7)
129253
.5024\n\nYou could just use a calculator.