i am finding two different answers equation of the line passing through (-3,-3) and (-3,1)?
91103
x=-3 is the equation for the line.\n\ny=mx+b where m is slope and b is y-intercept.\n\nm=change in y/change in x= [(-3)-1]/[(-3)-(-3)]\nm=-4/0\nWhen you divide by zero the answer is undefined, so slope is undefined.\n\nOnly vertical lines have undefined slopes, so the equation for the line is x=-3. This means that no matter what value you pick for y, x will be equal to -3.
940096
You have z=2, and y-z=-3, so if you put the value of z in there you should have \ny - 2 = -3\nso y is -1\nNow, with the value of y, you can replace it in the x-y=4 equation\nx-(-1)=4\nso x=3\n\nYou were on the right track, you just stopped a bit short of the finish line.
599219
you have to solve the ones in the brackets first. so in this instance, 4(-1) = -4.\n\nand then, you solve -4 - 3 = -7
1073694
If you're given that:\n\nP1 is at (x1,y1) \nP2 is at (x2,y2)\n\nand you're looking for: \n\nP3 at (x3,y3)\n\nIf the length of the line from P1 to P3 is L1\nand the length of the line from P2 to P3 is L2\n\nThen you can solve for the single point which\nsatisfies both of:\n\nL1 = SQRT( (X3-X1)**2 + (Y3-Y1)**2 )\nL2 = SQRT( (X3-X2)**2 + (Y3-Y2)**2 )\n\nTo simplify the math, square both sides of each eq:\n\nL1**2 = (X3-X1)**2 + (Y3-Y1)**2 \nL2**2 = (X3-X2)**2 + (Y3-Y2)**2\n\nSince you're given the first two points and\nthe lengths to the last point, the terms\nX1, Y1, X2, Y2, and L1, L2 are all constants. \nOnce you plug in the constant values, you're\nleft with two equations and just two unknowns \n(X3 and Y3).\n\nSolve for X3 and Y3 using a little algebra.
1151668
The x-coordinate decreased by 4 - (-2) = 6 and the y-coordinate decreased by 2 - 0 = 2\n-3 - 6 = -9\n5 - 2 = 3\nAnswer: Q'(-9,3)
371794
slope = (-1-2)/(-1-0) = -3/-1 = 3
619339
It is symmetric about the line x = -3\nThis means that if you plug in -4, then you will get the same value when you plug in -2.\nSo you only have to plug in one of them.\nDo not foil it out.  It is easier the way it is written.\ny(-4) = (-4+3)^2 + 1\ny(-4) = 2\nThus, by symmetry y(-2) = 2\ny(-5) = (-5+3)^2 + 1\ny(-5) = 5\nThus, y(-1) = 5 by symmetry
523276
(3,10) and (7,-1)\n\nm = (-1 - 10)/(7 - 3)\nm = (-1 + (-10))/4\nm = (-11/4)\n\n(3,10), m = (-11/4)\n10 = (-11/4)(3) + b\n10 = (-33/4) + b\n40 = -33 + 4b\n73 = 4b\nb = (73/4)\n\nANS : y = (-11/4)x + (73/4)
655260
2=-1=x\n2+1=x\nthere fore x =3
846663
(x+3)(x-1)\n\n x= -3\nx=1
939650
x+y=-3\nx=-y-3\nx -3  -2  -1  0  1  2  3 \ny  0  -1  -2 -3-4-5 -6\n\nx^2+2y^2-12y-18=0\nwhen y=-1\nx^2+2+12-18=0\nx^2-4=0\nx^2=4\nx=+/-2\nso (-2,-1),(2,-1)\nwhen y=3\nx^2+18-36-18=0\nx^2-36=0\nx=+/-6\nso(-6,3),(6,3)\n\npoints of intersection\n(-2,-1) and (-6,3)
250429
the answer for the line eqwuation  is \n\nY= m(x)+c;\ny=(y2-y1)/(x2-x1)(x)+c;\n\nx1,y1 be the first coordinate and \nx2,y2 be the second coordinate.\n\nm is slope of the Equation.\nc is the Constant \n\nx,y  is  first cordinate value s or seconde cordinate values..\n\n\n\nBaalu..?
898860
First one: d= - 1\n\nEDIT: the rest I'm too lazy to do. Do your own homework! =D
469518
There is an obvious 1-dimensional continuum of solutions to this equation: the line y=x.\nHowever, there are a continuum of more solutions, most of which are nontrivial:\nNote that log(x^y) = y*log(x). Thus log(x)/log(y) = x/y. This implies that y = x^(y/x) and similarly x = y^(x/y). This is the general form of the solution where the obvious solution is the restriction x/y = 1. \nIf we let x/y = 2, we get 2y = y^2, or y(y - 2) = 0 which gives nondegenerate solution point (4, 2) as mentioned previously. Setting x/y = 3 gives us 3y = y^3 or y^2 - 3 = 0, which gives the nontrivial solution point (3*Sqrt[3], Sqrt[3]) and so on.
838330
Both equations are in slope-intercept form (y = mx + b).\n\nIn your case, both lines have the same slope (-2/3) but different y-intercepts (+1 for the first, -4 for the second).  Lines with the same slope but different y-intercepts are PARALLEL.\n\n(Note: if you got slopes that were the same and the intercepts were the same, the lines would be coincident -- the same line.  If the slopes were negative inverses, e.g. 2/3 and -3/2, then they would be perpendicular.  And if the slopes were completely different the lines would be skew.)
1174364
2(x -1) + 3 = X – 3(x + 1)\n2x-2 +3 = x - 3x-3\n2x + 1 = -2x -3 \n2x + 2x = -3 - 1\n4x = -4 \n4x/4 = -4/4 \nx = -1 \n\nTo check your answer plug -1 in the place of x in the main equation:\n2(-1-1) + 3 = -1-3(-1+1)\n-4 + 3 = -1 \n-1 = -1\nThus x = -1 is the correct answer.
579155
The first one isn't, because it's undefined when x=4 (assuming the (x-4) is the denominator, not just the x)\n\nThe second one is; it's a horizontal line with no breaks or holes.