what is energy that is calculating in both joules and mev?. what is the name given to an hormone that is contr
89877
joules are an amount of power with an equivalent in calories btus and kilowatt-hours
1136309
HEAT ENERGY=mQ(t2-t1)\n\nM-MASS OF SUBSTANCE\nQ-SPECIFIC HEAT CAPACITY\n(t2-t1)-CHANGE IN TEMP.
475093
see dear ,\nwhile calculating the energy changes we need to know the hidden heat { latent heat } that is absorbed during the change in state . for eg when we are calculating the heat absorbed or given out during a change in state , like ice to water , just first calculate the latent heat ie \nq=mL{ heat=mass *latent heat } now add this value to \nq=mct{heat=mass*specific heat*change in temp} keep in mind that specific heat is a constant value \nwater's specific heat is 4180j/kg/degree Celsius.
226084
They are both measures of energy. However, joule has mostly replaced calorie except for food where calorie is still the most common measurement. There are two main measurements of the calorie:\n\n* The small calorie or gram calorie is exactly equal to the energy needed to increase the temperature of 1 g of water from 14 °C to 15 °C. This is about 4.185 J. \n* The large calorie or kilogram calorie is exactly to the energy needed to increase the temperature of 1 kg of water from 14 °C to 15 °C. This is about 4.185 kJ, and exactly 1000 small calories. It is named after British scientist James Prescott Joule.\n\nThe joule is the SI unit for energy. The joule is a derived unit defined as the work done or energy required, to exert a force of one newton for a distance of one metre, so the same quantity may be referred to as a newton metre or newton-metre (also with meter spelling), with the symbol N·m or N m. It can also be written as kg·m2/s2. However, the newton metre is usually used as a measure of torque, not energy.\n\nAs a rough guide, 1 joule is the absolute minimum amount of energy required (on the surface of Earth) to lift a one kilogram object up by a height of 10 centimetres. To convert calories to joules, multiply by 4.1868.
48326
kg m s^-1  is in base S.I units as technically all units are made up of seven base units... howerever the kg m s^-2 is known as the joule and 1joule per second is known as the watt
736683
.065kg * 35 * specific heat of Aluminum\n\njust make sure your units check out; you may need to convert this equation into calories as specific heat is normally defined in joules I think.
791910
The work done on an object by a force is the product of the component of the force in the direction of motion and the distance the object moves. The component of the force in the x direction is simply the magnitude of the force times the cosine of the angle. Thus:\n\nW = 100 N * cos 40° * 20.0 m ≈ 1530 J (to 3 significant digits)\n\nEdit: I don't know whether your teacher is complaining about the units or the numbers. A joule IS a newton·meter, so both units are correct. As for the number, I'd say someone made a typo when compiling the answer key. It happens a lot. Ask her to recompute it herself.
358448
specific heat? that would be represented by Cp.\nHowever if you are using delta H then it would either be: delta H (fus) which is the enthalpy of fusion, used in problems concerning melting point (indicating a state change from solid to liquid)\nOr it could be delta H (vap) which is the enthalpy of vaporization, used in problems concerning a boiling point (indicating a state change from liquid to gas)\n\nHeat calculations are done using the formulas:\nq=m x (delta T) Cp <-- Used when there is a temperature change, but no state change\ng= m x (delta H fus) <-- Used for state changes from solid to liquid\nq= m x (delta h vap) <-- Used for state changes from liquid to gas
710717
GPE is the gravitional potential energy.\nM is the mass.\nG is the gravitational constant.\nH is the height.\nJ stands for joules.\n\nGPE=(500 + 85 kg)(9.8 s^2)(1000)\nGPE=5733000 J
281104
It appears to be in relation to energy production.  I have referenced a hyperlink to a PDF file that refers to this term with in its context...the file does have some English translation.
1030224
The answer in SI units is 1200 joules or 1.2 kilojoules. the definition of a joule is one watt second. in Calories, or English units, which shouldn't really be used with watts as it mixes systems of measurements, is 286.806883 calories or 0.286806883 kilo calories.
238597
Joules. But Kilojoules are used often for practical purposes.
993443
29.5kg x (0.01 m)^2 / (3600 s)^2 = 2.28 x 10^-10 joule = \n0.228 nanojoule (nJ)
310103
Kinetic Energy:\n\nKinetic energy (SI unit: the joule) is energy that a body possesses as a result of its motion. It is formally defined as the work needed to accelerate a body from rest to its current velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. Negative work of the same magnitude would be required to return the body to a state of rest from that speed.\n\nIn simple cases, this work (and thus the kinetic enrgy) is equal to:\n\n    Ek =.5(M*(V^2))\nwhere m is the object's mass and v is the object's velocity.
85930
The specific heat of a substance is the radiation heat contained  by each atom or molecule per unit volume and temperature for a specific material.\nIt is calculated as follows; K(Bolzman's constant) multiplied by one kilogram mass of the material and divided by the atomic mass of the specific material.\n\nIts Unit is Joule(energy)per kilogram for each degree of absolute temperature.\n\nThis means that different materials dont have the same heat energy content for the same volume and atomic energy level.\n\nI hope if you find this explanation helpfull.
1175772
KE= 1/2 * m * v^2\n250,000 joules= 400* v^2\nV^2= 625 so v= 25 m/s or 0.025 km/s or 90 km/hr
64647
2x (G2 + M2 ---> 2GM)      DH=-280.0*2= -560.0 kJ\n2x (L + 2M2 ---> LM4)      DH=-350.0*2= -700.0 kJ\n   (L2G4 ---> 2L + 2 G2)   DH=122.0*(-1)=-122.0 kJ (change sign when flip over)\n\nAdd them together, we'll have:\n2G2 + 2L + 6M2 + L2G4 ---> 4GM + 2LM4 + 2L + 2G2\nthen cancel 2G2 and 2L on both side, we end up with:\nL2G4 + 6M2 ---> 2LM4 + 4GM\nthe enthalpy of this reaction is, therefore the sum of each enthalpies calculated above.\nDH=(-560.0) + (-700.0) + (-122.0)= -1382.0 kJ (exothermic process)\nhope that'll help!