What is the formula for finding the perimeter of a triangle?
87753
Just add up the lengths of the three sides. Works for any triangle - wether it's equilateral, isosceles or obtuse.
882048
Here's the answer you want:  With a compass set to the radius of the circle, start marking off radii around the circle, dividing it into 6 equal parts.  Connect any 3 alternate points and you'll have your triangle.\n\nNO MATH REQUIRED!
826433
perimeter=4 times the side\n=4*64=256 foot
609578
definitely 63 square inches. The formula to find the area of a triangle is A=(1/2) x base x height. That is 0.5 times base times height. So, if you plug in the numbers, you get\n0.5 x 14 x 9 square inches\n(0.5 x 14) x 9 square inches\n(7) x 9 square inches\n63 square inches\n\nMake sure that whenever you look for the area of the triangle, the problem tells you that the numbers are the height and base.\n\nYes, 24 is correct.
802049
The answer is (D).\n\nThe perimeter is 9x (just add up the 4 sides 2x+3x+3x+x to determine this) -- which eliminates (B) and (C) as a possible answer.\n\nThe area is 6x^2 -- which eliminates (A) as a possible answer, leaving only (D).\n\nLooks like you have a trapezoid, where the base is 2x, the sides are 3x each, and the top is x.  Draw straight lines down from your top to your base, so that your trapezoid is in 3 pieces:  a right triangle with base = x/2 and hypotenuse 3x, a rectangle x by 2x, and another right triangle with base = x/2 and hypotenuse 3x.  The area of the inner rectangle is 3x^2, and you can put the two triangles together to get another x by 2x rectangle for another 3x^2 area, or a total area of 6x^2.\n\nI hope that helped.\n\n~ ♥ ~
411731
The perimeter might be 14.0625. \n3+4+5+6+7 = 25 and the pentagons are similar. It is just a matter of proportions. \n(the perimeter of given)/ (perimeter you r tryin to find) = (area of given)/ (area given for the second pentagon)\n\nso in numbers it is (25/x)=(48/27) and you just solve for x because the pentagons are similiar.
89513
There are so many way to find the area of the triangle, depends on what you know about that triangle.\n1, If you know the height and the base: the area is\nA=base*height*(1/2)\n\n2, If you know 2 sides of the triangle, and the angle in between that 2 sides.\nLet the 2 sides be (a) and (b), the angle be C.\nArea would be equal to\nA= a*b*sinC/2\n\n3, If you dont know any angle, but you know all 3 sides.\nLet 3 sides be equal to a, b, and c. Let s= (a+b+c)/2\nThe area can be calculated using:\nA= square root of [s*(s-a)*(s-b)*(s-c)]\n\n4, If you know all 3 angles, and 1 side of the triangle.\nLet the 3 angles be A, B and C, and the side be a which is opposite of angle A.\n\nA= (a^2*sinB*sinC) / (2*sinA)
303035
If the triangle is a right triangle, you can find the other side by Py's Th and then by the formula,(A=1/2bh).\nIf it is not, you should know the angle they make each other or an adjacent angle. Only if, you can find the area by sine laws or cosine laws.
975962
Let n be the length of one of the equal sides.\nLet n + 3 be the length of the third side.\n\nThe sides are n, n and n + 3 respectively.\n\nn + n + (n + 3) = 27\n3n + 3 = 27\n3n = 24\nn = 8\n\nSo the sides are 8 cm, 8 cm and 11 cm respectively, for a total perimeter of 27 cm.
1068661
Perimeter of the triangle multiplied by the height of the prism.
897796
Let L be the length\nLet W be the width\nWe know the perimeter is:\n2(L + W) = 300\nSolving for L:\nL + W = 150\nL = 150 - W\n\nNow write a formula for the area:\nArea = L * W\nArea = (150 - W) * W\nArea = -W² + 150W\n\nYou can see this is the formula for a parabola.  I'll simplify things by expressing it in terms of x:\nf(x) = -x² + 150x\n\nBut it isn't in vertex form:\nf(x) = a(x - h) + k\n\nTo get it in that form, first pull out the -1 to get x²:\nf(x) = -1(x² - 150x)\n\nNow take the coefficient on the x term (-150), take half of it (-75) and square it (5625). Add and subtract this:\nf(x) = -1(x² - 150x + 5625 - 5625)\nNow you can write this as a square:\nf(x) = -1[ (x - 75)(x - 75) - 5625)\nSimplify:\nf(x) = -1(x - 75)² + 5625\n\nYou have a downward facing parabola, with a maximum vertex at the point (h, k) or (75, 5625)\n\nSo the maximum is when the width is 75. When you solve for length you get that the length is also 75. So the maximum area for the patio is a square with sides of length 75 feet.  The total area will be 5,625 sq. feet, a maximum.
343312
perimeter = 2 (side1 + side2)\narea = side1 * side2
969755
Relax\n\n1)) (5x + 7) + (x - 2) = 5x + 7 + x - 2 = 5x + x + 7 - 2 = 6x + 5\n\n2)) 2 X length + 2 X height = perimeter\n\n  (2 X x) + (2 X (x - 3)) = per = 2x + (2x - 6) = cir = 2x + 2x - 6\n\n  perimeter = 4x - 6,   or 2 ( 2x - 3)\n\n3)) same as # 2;\n\n  2 X (t + 5) + 2 X 2t = 2t + 10 + 4t = 2t + 4t + 10 = 6t + 10 = per\n\n4)) (t - 5) - (3t - 1) = t - 5 - 3t + 1 = t - 3t - 5 + 1 = -2t -4\n\n  or -2 (t + 2)
972787
Heron's formula can only be used when the sides are given. The formula is:\nArea = square root of[(s)(s - a)(s - b)(s - c)]\n\ns = (a + b + c)/2\nwhere a,b and c are the sides of the triangle.\n\nSorry, but there really isn't enough information to work with.
979599
L = length\nW = width\n\nLW = Area\n1) LW = 35\n\n2L + 2W = Perimeter\n2) 2L + 2W = 27\n\nSolve equation 1 for L and substitute into equation 2\n\nLW = 35\nL = 35/W\n\n2L + 2W = 27\n2(35/W) + 2W = 27\n70/W + 2W = 27\n70 + 2W^2 = 27W\n2W^2 - 27W + 70 = 0\n(2W - 7)(W - 10) = 0\nW = 7/2, 10\n\nL = 35/W\n\nIf W = 3.5, L = 10 and if W = 10, L = 3.5\n\nAssume L is longer than W: L = 10, W = 3.5
764538
For any given triangle ABC with sides a, b and c.\n\nCos C = (a^2 + b^2 - c^2)/2ab  This is the cosine rule.\n\nSin C =sqrt(1 - Cos^2 C). You may need to adjust the sign of the sign to match the triangle.
503124
first split the triangle in half. \nfind the height of the triangle (with the 12cm side as base)\n\n7^2 - 6^2 = (height)^2\nheight = 3.61\n\nUse formula\n\nArea = (0.5) (height)(base)\n     = (0.5) (3.61)(12)\n     = 21.66 cm squared