Could anyone tell me how far up you would have to reach to touch the sky?
83796
The sky is anything above the ground, it is only air. \n\nGod has always been there he was not created, he was the creator.
880249
Surprisingly for an average height person standing at sea level, the horizon is only about six miles away.  You could see disturbances at that distance.
116040
Im afraid my eyes arent good enuf to see that far... Its an unaswerable question
984017
try the tv guide\ntry the sky planner
128576
depends how high off the ground it is.
1147123
Depends on your definition of the sky. The "sky" or portion of the atmosphere that deflect the blue wavelength of light is in a sphere around the earth about 350km high. So if you look North, South, East or West the sky never ends, but if you look straight up it ends and space begins at about 234 miles up.
643214
Elevation: 138 feet      \nLatitude: 78 11S   \nLongitude: 162 12W
771141
In its entirety or only the top?\n\nA 6ft person will see the Earth horizon at out 3 mi.\nLikewise, the top (http://en.wikipedia.org/wiki/Empire_state_building) of the Empire State Building is 1454 ft, so its horizon is ~47 miles.  \n\nTherefore, maximum distance that a 6 ft person can see the top of the Empire State Building is ~50 miles on a round Earth with radius 6378.14  km (http://en.wikipedia.org/wiki/Earth).\n\nIf you're asking far can someone see an object that big, visual acuity is about 1 minute of arc, so the building will appear as a visible dot at about 946 miles.
767544
Let r=the earth's radius and h=your height.\n\nDraw a right triangle ABC, where AC = length r, BC = length r+h, and <A is the right angle and angle C is very small.  C is the center of the earth, and BA is tangent to the earth.  BA is the distance from your head to the horizon.  By Pythagoreas' theorem, \n\nlength(BA) = sqrt((r+h)^2 - r^2)\n= sqrt(2rh + h^2).
908785
very close to 2 meters.
871085
let me go check it, 924,375,700 km\n\n:> peace\n.
513176
Try http://googleearth.com\nMaster.
555817
Approximately 600 kilometers (372 miles)above the surface of the Earth
365555
I assume you mean how far away is the horizon, which isn't quite what the wording of your question really asks.\n\nAnyway, it is a simple geometry question. Construct a triangle. One point is the center of the Earth, one point is at your eye and one point is at your horizon. The horizon is that place where your line of sight is tangent to the curved surface of the earth, which means that the angle between the line from your eye to the horizon and the line from the center of the Earth to the same point on the horizon is 90 degrees. So you have a right triangle. The hypotenuse is the line from your eye to the center of the Earth and it's length is the radius of the Earth plus your height. That length, squared, is the sum of the squares of the other two sides. One of those sides is the radius of the Earth and the other is the unknown distance to the horizon you are trying to find. Just do the algebra to solve for the third side, which is the distance to the horizon. I think it is about 20 kilometers for the average person.
501508
3853 feet (1175 meters)?
1135263
The height of the trajectory is 1 m (3.05-2.05)\n\nThe horizontal distance is 6.02 m\n\nNow you have ucos(25)t = 6.02\n\nand usin(25)t-0.5*9.8*t^2 = 1\n\nSubstitute t = 6.02/ucos(25) in the 2nd eqn and solv.
722020
Heights!..How bout that?