how to rduce the weight?
98243
eat a little and excercise everday jogging,work out. after a week you reduce your weight.
405919
http://en.wikipedia.org/wiki/Hundred_weight
916328
Up to 10 pounds.\n\nCoach
710992
Take the value of the height* and multiply the height to itself.\n \n(height times height) = height squared\n\n*Make sure that the heigh has been converted  all to inches,\n OR all to feet, first.\n\nREMINDER: 1 foot = 12 inches\n\nex.  5 ft. 2 in.  = ? inches  \n\n5 ft. x (12 in. / 1 ft.) + 2 in.  \n60 in. + 2 in. \n62 in.\n\n5 ft. 2 in.  =  62 inches\n\nAND,\n\n(inches times inches) = inches squared \n\n(62 in. X  62 in.) = 3,844 inches squared\n\nTherefore,  BMI=weight divided by ( inches times inches)\n\n\nGood Luck!
971560
well, first you have to calibrate it to make sure that the pointer thing is at the line. Turn the nob to calibrate it. Than put the object on the little plate thingy mobober. First, do the heaviest weight and figure out which weight would be the heaviest it can without going tooooooo heavy (if it is too heavy, the indicater/pointer will go below the line). Repeat for the second heaviest, than the lightest.
1099376
Start with a weight you are comfortable with and do ten reps,add five pounds and ten more,add five and ten more.Then move on to another part of the body.The important thing is to not make your self so sore the first few times or you will not feel like doing it the next time.Keep it light until you get used to it.
859844
The previous answerer has the right idea but the wrong details.\n\nThe four parts should weigh 1, 3, 9 and 27 pounds.  The logic is that the desired weight is written in "balanced ternary" notation, where the values of the digit positions are 1, 3, 9, 27, 81, . . . (that's "ternary"), but the allowed digit values instead of being 0, 1, 2 (that's regular ternary) are -1, 0, 1 (that's balanced ternary).  Then the digit values for any desired total weight written down in balanced ternary tell you whether the weight for that column is to go in one pan, go in the other pan, or stay on the floor.
53062
http://www.exploratorium.edu/ronh/weight/index.html
508636
same mass, same weight
508321
If you don't have the money to go buy weights to work out with, take 2 empty milk jugs, fill with water. They will weigh 8 ponds each. Start with those and just keep adding. You can also use an old broom stick to hang the milk jugs on. Just use tape.
1184492
The basic principle is to use leverage. Here's one way off the top of my head (I wish I could draw a diagram):\n(1) Hang the object from a rope/cable that runs up through a pulley. \n(2) Fix the other end of the rope so that it pulls up on a lever arm. \n(3) Make the other end of the lever arm (beyond the lever's pivot point) push down on the scale. \n(4) Since you want to effectively reduce the weight pushing on the scale, the length LR of the lever arm between the pivot and the rope will be shorter than the end LS between the pivot and the scale. \n(5) The relationship between the weight WO of the object and the weight WS you read on the scale will be: WO = (LS/LR)WS. \n(6) This ignores the effects of mechanical imperfections and friction in this apparatus. \n\nAlso, I can imagine several other mechanical configurations that would achieve the same thing.
659168
You should use density to check that out.\nDensity=Weight/Volume
881707
Determining the mass is trivial: just weigh the block.  For the density, you will need to know the volume, which will require some measuring with a ruler.  Then divide the mass by the volume for your answer.
332748
ok the simplest way is to hang a weight if some sort (key dog tag nail ect.) from a string held in your hand, now swing the weight in a circle eather way and think yes, now this direction of travel will be yes now go the oposit way and think no, this direction now will represent no, now for i don't know/ i will not answer, change direction to a back and forth motion so it swings tward you and away, \n\nnow all you have to do is think yes or no questions and remember the direction of travel\n\n\ngood luck
1059864
convert them to kilograms
833368
find the force of her weight. \nthat should be the answer
72845
use nasa's calculator:\nhttp://www.exploratorium.edu/ronh/weight/