Hey Im working on something for school called Equation Ananlysis tests - anyone know answers to these??
97769
4 s on a v\n4 strings on a violin
753451
A bit vague but a you could work out the rate from a titration, also the molar value from the same experiment.
740779
use pv=nrt and you can get the answers
412953
An equation that is incorrect.
771697
Try Google or Yahoo.  You'll find worked examples there.  I think it needs diagrams to understand; they and the accompanying explanations are too complex to attempt to reproduce here.
701654
Instead of memorizing all the equations,understand how they are derived.Try to do it yourself.If you can't go to someone who knows for help.
129663
Please do your own home work.\n\nI suspect you are missing a symbol, it probably should be,\nN2O4  <==>  2NO2\n\nThink about how each of the changes will effect the equilibrium of the reaction.
195201
i think u typed the question wrong, can u please correct it and if u have 2 unknowns, please give 2 equations, else u cant get a definite solution
388135
since it is difficult to use the equation writer on Yaho answers, I am giving you a link, that has the answer.\nhttp://homepage.mac.com/nshoffner/nsh/CalcBookAll/Chapter%206/Ch6DefInt.htm\nScroll down a little.
846447
http://www.bbc.co.uk/schools/gcsebitesize/chemistry/classifyingmaterials/formulae_and_equationsrev4.shtml
917250
I'm going off memory here so be sure to check this.  I think the formula is the same, but the structure may be different.  Just trying to point you in the right direction.
665576
x^2<4x\n\ncase 1: x<=0\nno solution\n\ncase 2: x>0\ndivide by x\nx<4\n\ntherfore the solutions are 0<x<4
908083
Tried to do it algebraically, that was a booger.\n\nI plugged that into mathematica and it gave me an error normally generated when the inverse of a function is needed to represent a solution and the solution variable occurs in more than one argument of that function.\n\nThat one might not have a solution?
644818
It's a polynomial. You've added no NaOH so far, so it's:\n\nDraw an ICE chart, where ICE is initial, change, equilibrium. Let x be the amount of BA\n\nBAH  <---> H+ + BA-\nI 1.0 M    0     0\nC  -x      +X    +X \nE 1.0-X    X      X\n\nI don't expect the formating to surivive, so the equation becomes, based on the law of mass action:\n\nX^2/1-x = 6.3*10^-5\n\nThere are two ways to proceed at this point. We can assume that the amount of benzoic acid that has diassociated is much larger than the amount that has not. If we assume this, we disregard the -x and figure out:\n\nx^2 = 6.3*10^-5  so x = 0.007937.\n\n-LOG (0.007937) = 2.1\n\nSay we don't make that assumption, then we have to solve the equation: \n\n\nX^2/1-x = 6.3*10^-5
33119
Is this your homework?cheater...look it up on Google
4935
ur second equation is wrong. \n2a is not equal to a-squared (which u symbolized by ab, since a=b).
1017997
The equations are wrongor insufficient. Post the correct data if you want me to help/ Alternately, you could also message me.