How does temperature effect spring constant?
93551
Length change and material stiffness change are both pretty small in metals.  Nonmetallic (e.g., elastomer) springs can have larger changes of both kinds and become noticeably weaker.
984213
http://en.wikipedia.org/wiki/Pressure_gradient_force\nhttp://en.wikipedia.org/wiki/Temperature_gradient\nHope this helps, good luck!
94789
Use Boyle's Law for that. Assuming the temperature is always constant, the product of pressure and volume is always constant.\n\nP * V = k\nor\nP1 * V1 = P2 * V2\n\nIf temperature is included in the equation, you could either use the combined gas law or the ideal gas law.\n\nNote: Elevation plays a significant role in Boyle's Law so it will have a difference in the gauge readings if you relocate it from sea level to the mountaintop.
421925
Mass isn't affected by temperature theoretically...but if you look at it realistically, heat causes accelerated evaporation, which therefore causes a loss in mass.  So it depends on how you look at it.
827729
it all depends on what Temperature is acting upon.  If your talking about a solid, no, not really, if it does, it is negligible.  However, Temp. does affect the density of liquids, most liquids become more dense as temp. get colder, and less dense if the temp gets higher.  If you are talking about gasses, then the temp will affect both volume and density. think of a balloon. If you put a balloon outside in the winter, it will become smaller.  This is because the density of the air inside goes up and the volume goes down.... \nThe formula to determine what happens with a gas is PV=nRT, whereby P=the atmospheric pressure, V=volume, n= the #of moles of a gas R=is the ideal gas constant and T=temp... hope that helps.
654039
its actually temperarure, pressure and polarity.\n\ntemperature increases then solubility increases\n\npressure increases then solubility decreases.\n\nand by the theory 'like dissolves like' polar is dissolved in polar solvents and vice versa.\n\n** though at room temperature, temp factor shall not have effect as temp remains constant
314230
yes...if you change the temperature....the density of water for example changes with its temperature....
775471
I think the cooling effect is the same as heating effect, but opposite of it. If so, then find out the coefficient per degree Celcius of that particular material.\n\nThe formula will be = difference in volume change / the original volume x difference in temperature change = coefficient per degree Celcius. Just reduce the minus (-) sign and treat it as positive even though we know it's reduced.\n\nThen find out if this material is one straight line/rod. If it's in square, then the volume change will be 2x. If cubic, 3x.\n\nDifferrent material have different coefficient. Liquids, solids, gases... Even different solids have different coefficient.\n\nAlso pay attention to...\nDensity = Mass/Volume\n\nI can't guarantee the accuracy but I hope this helps.
1070754
First, the spring constant (I suppose g=10m/sec^2):\nf=k.d\n0.3 x 10=k x 0.02  so  k = 150 N/m\nNow, the problem is like that we have a 2 Kg block hung from the spring and pull it down 2 cm then release it. The total force applied to block would be:\nf=Mg-kx=20-150x (x = distance of block from its final point, 2 cm above its first place) so the acceleration 'a' is:\na=10-75x   so applying the second law:\nx''=10-75x  so the movement equation is  x''+75x-10=0\nSolving this differential equation gives sin function for x as the general form x=a.Cos(w.t+c). By substitution we get:\nw^2=75 so w=5.sqrt(3)  rad/sec\n(divide it by 2*pi if you like to have the frequency in Hz)\nT=2*pi/w ~ 0.73 sec
451605
Anything warmer than the air temperature will be affected\n\nMeaning more heat will be lost from the warm object if there is  wind. The wind moves the lost heat away from the object.
569120
Isobars link locations with constant pressure, isotherms do the same for temperature
695376
The resistance of the filament of the lamp varies with temperature. When the filament is at room temperature the resistance is much lower than when it is white hot. \n\nCurrent = V/R. If the voltage is constant and the resistance increases, the current decreases.
245113
It is true that temperature will affect the distance of a golf ball. However, without knowing the exact composition or performing controlled experiments, it would be difficult to give an exact answer. \n\nBelow is a link to perform such an experiment. Measure the ball's rebound ability for 2 different temperature of balls, and you will get a good approximation of a percentage.\n\n**UPDATE**\n\nAs per your update, more information would be needed than just temperature to do this calculation, as humidity, atmospheric pressure, and type of clubs would have as much or more involvement than temperature.  I've included a couple new links that show some of the differences in ball flight vs. temperature, of particular note would be the last link, which has a calculator for your exact problem.
683535
No. \nHeat will flow from an object that has more temperature to another with less temperature. An object having less temperature can have more thermal energy than another witj more temperature. This will depend on the mass of the object. See it this way: 1 gram of iron at 1000ºC has less energy than 1 ton of iron at 100ºC. Heat will flow from the object with less energy to the object with more energy in this case. But it will always flow from the object with more temperature.
703096
Charles' law states that, under constant pressure, the ratio between a gas' volume and absolute temperature remains constant.  So if it heats up it expands and if it cools it contracts.  For example, you fill a balloon with helium at room temperature, and then put it in a refrigerator.  The helium will contract, and the balloon will shrink.
685907
Temperature speeds up reaction rate.  Until you had the high temperature (flame) the reaction (gas burning) couldn't happen.  The temperature is then more or less constant unti the gas runs out, and then the reaction stops but not due to temperature, just due to lack of reactant.
905049
First assume that we neglecting any losses from air resistance or internal friction.\n\nWith that simplification, imagine two states:\n1) you are on the bridge 100m above the water and at rest\n2) you are suspended by the spring at its point of maximum extension, and therefore with zero velocity\n\nSince we assumed that there were no losses, the energy of both of these states is equal. Where is that energy located?\n -->1: your gravitational potential energy (no kinetic energy, no stored elastic energy)\n--> 2: your remaining gravitational potential energy, and the stored elastic energy in the spring (by definition, no kinetic energy)\n\nSo what has happened is that the spring has stored elastic potential energy that is equal to your loss of gravitiational potential energy. That's the only way the energies of the two states are the same.\n\nNow you can set up some equations. Let's say that you start at height H0 and end up at height H1.\n\nchange in PEg= m * g * (H1-H0)\nchange in PEk = 1/2 * k * [(H1-H0)-30m]^2\nwhere we have accounted for the 30m long unstretched length of the spring.\n\nNow by observing that -PEg = PEk, and plugging in the given values for m and k and the known value for g, you can readily solve for the change in height (H1-H0) (it should be < 0) It's a quadratic, so you expect to find one answer that is not physically realizable - reject that one, and select the other one.\n\nDoes that help?