How do you calculate the weight of the EARTH? (No Crap Anwsers Please!!)?
80825
The weight (or the mass) of a planet is determined by its gravitational effect on other bodies. Newton's Law of Gravitation states that every bit of matter in the universe attracts every other with a gravitational force that is proportional to its mass. For objects of the size we encounter in everyday life, this force is so minuscule that we don't notice it. However for objects the size of planets or stars, it is of great importance.\n\nIn order to use gravity to find the mass of a planet, we must somehow measure the strength of its "tug" on another object. If the planet in question has a moon (a natural satellite), then nature has already done the work for us. By observing the time it takes for the satellite to orbit its primary planet, we can utilize Newton's equations to infer what the mass of the planet must be.
578713
U can a measure the mass of an object accurately using a Physical Balance.\nUnit of mass is kg in SI unit ysstem.\nMore accurate ways of measuring mass is done now.\n\nU can calculate it's weight by a formulae:\nW=mg.\nW-Wieght\nm-mass\ng-aceleration due to gravity (9.8 ms^-2)
9301
ok, well the formula you need is:\n\nFg=Gm1m2/r^2\n\nwhere Fg is the force of gravitation, G is the universal gravitational constant(just a constant, you dont have to worry about it) m1 and m2 are the masses of the 2 objects, and r^2 is the distance between the two objects squared.\n(a) ok, so if r increases by 10 times, since r is squared, the denominator would actually increase by 100 times.  Since the denominator increases by 100 times, and the numerator stays the same, you're basically multiplying it by (1/100) so that means that you have to do the same thing to both sides, so you just multiply Fg by 1/100 so thats 500/100 so the answer is 5 newtons.  This makes sense because the farther objects get from each other, the less each other's gravity will affect them.\n\n(b) ok, now one of the m's, lets say m1 doubles.  The rest stays the same again, and this time its in the numerator, so you're just multipying the whole thing by 2, so the new force would be 1000 newtons.  This makes sense, because something with more mass would experience more gravitational force, for example, a person with more mass experiences a greater gravitational force with the earth, and therefore weighs more.
537931
The weight of the Earth is not increasing each year due to the population increase.\n\nFirstly, the net weight of the Earth is probably maintained as the weight increase in the population is offset by the loss in weight of food consumed.\n\nSecondly, if you compare the weight of the 6 billion people to the mass of the Earth, it is negligible. Something like 0.000000000006%.\n\nSome Calculations.\n\nMass of Earth = 5.9742 × 10^24 Kg\n\nThat's 5,974,200,000,000,000,000,000,000 Kg\n\nIf we take 6 billion people on Earth with an average of 60 Kg per person.\n\n6,000,000,000 x 60 kg = 360,000,000,000 Kg\n\nThe whole of 6 billion people will only contribute a miserable 0.000000000006% to the Earth's mass.
214139
Here is a calculator to find you weight on other planets/moons/stars,\nhttp://www.exploratorium.edu/ronh/weight/index.html
794978
saad, hi!\n\ni found this neat description for you... it's put in simple layman terms...\n\nQ. What's the difference between weight and mass?\n\nA. As long as you stay on Earth, the difference is more philosophical than practical.\n\nQ. Uh...what do you mean by that?\n\nA. Well, mass is a measurement of how much matter is in an object; weight is a measurement of how hard gravity is pulling on that object. Your mass is the same wherever you are--on Earth, on the moon, floating in space--because the amount of stuff you're made of doesn't change. But your weight depends on how much gravity is acting on you at the moment; you'd weigh less on the moon than on Earth, and in interstellar space you'd weigh almost nothing at all.\n\nQ. But if you stay on Earth, gravity is always the same, so it really doesn't matter whether you talk about weight or mass.\n\nA. That's right...but scientists still like to be careful about distinguishing between the two. If you talk about the mass of an atom--as I will do from now on--you're always talking about the same thing; if you talk about its weight, what you mean depends on where the atom is. \n____________________________________________\n\nhope this helped...!\n\nenjoy!
319592
The formula is to simply divide the mass of the sun by the mass of whatever planet you are interested in.\n\nThe sun's mass is: 1.989 x 10^30 kg\n\nThe mass of the planets:\nMercury: 0.33 x 10^24 kg\nVenus:   4.87 x 10^24 kg\nEarth:   5.98 x 10^24 kg\nMars:    0.65 x 10^24 kg\nJupiter: 1900 x 10^24 kg\nSaturn:   570 x 10^24 kg\nUranus     87 x 10^24 kg\nNeptune:  100 x 10^24 kg\nPluto:    0.7 x 10^24 kg\n\nSo, for instance, 332,609 earths would weigh the same as the sun.
69858
Weight is a force.  The National Institute of Science and Technologiy defines it here as such.\nhttp://physics.nist.gov/Pubs/SP811/sec08.html\n\nA force is acceleration times mass.  Weight is the accleration due to gravity times mass.  On the Earth's surface, this is approximately:\n\nWeight = Mass x 9.8 meters/second^2\n\nFor a accurate conversion, you would need to use the acceleration due gravity minus the accelration due to centrifugal force at your exact location.  \n\nThis is why physicists more commonly use mass than weight to describe an object.
823207
gravity is a special case  of gravitation.It is the force by which earth pulls a one kg object towards it.\n\nie g=GM/R^2\n M=mass of earth\nR=Radius of earth\n\nnow force acting on a object  of mass 1 kg at a height h(from earths surface) will be \nf=GM/(R+h)^2\nwe can take out R out of bracket so that (R+h)^2 can be R^2{1+h/R}^2\nNow\nGM/R^2=g\nSo we can easily WRITE it as \nf= g/{1+h/R}^2\n\nThis f is that something we usually write as g'\n\nNow g' can be written as g{1+h/R}^(-2)\n\nFOR NOT TOO SOPHISTICATED CALCULATION\nIT CAN BE REDUCED USING BINOMIAL THEORM TO \ng'=g{1-2h/R}
787952
The force of attraction is given by Newton's law, F = G* m1*m2/r^2, where G = universal gravitational constant, 6.67 * 10^-11 N*m^2/kg^2.  You have the two masses, and the radius of earth is the distance r.  Your weight is the same as the gravitational force.
490259
The mass of earth is found as follows.\n\nThe acceleration due to gravity at a place is g. \ng = G M/R^2, where, G is gravitational constant, which is determined experimentally with two known masses.\n\nR is the radius of earth which we know by surveying the circumference of earth.\n\n M = 9.8 x 6400,000 x 6400, 000x / 6.673x10^ (-11) = 6x10^24kg.\n\nThe mass of Sun is found as follows.  \n\nWe determine the distance of Sun observing their angular diameters measured from different heights from earth. \n\nWe observe its period of rotation about the earth.\n\nNow using the formula ‘M = 4pi^2 R^3/G T^2’, M is found\n\n39.48 x (1.496x10^11) ^ 3/6.673x10^ (-11){365.25x24x60x60}^2= 1.989x10^30 kg.\n\nSince we know the mass of Sun, we can use only the period of rotation to find the mass without knowing the distance.\n\nAbout the mass of stars, I don’t know whether there is some way to find their mass.
22095
Let's try to anser the question without looking it up and without using a calculator.\n\nWe know Newton's gravitation law: F = G*m*M/r^2\nAnd we know the gravity on earth: F = m*g\n==> m*g = G*m*M/r^2\n==> M = r^2*g/G\nNow, the acceleration on the earth surface is approximately 10 m/s^2\nThe earth's radius is approximately 6*10^6 m\nAnd I remember G to be approximately 7*10^-11 Nm^2/kg^2\n\nM = 6^2*10/7 * 10^12/10^-11 kg\n\nThe earth weights about 5*10^24 kg\n\nIf you look it up in Wikipedia, it says 5,9736*10^24 kg. \n\nSo we're close enough if you take into account that we used rough estimates for the constants.
981506
a. The force of the gravitational attraction between two objects is given by the formula\n\nF= G*(M1*M2/R^2)\n\nwhere G is the gravitational constant, M1,M2 are the two masses and R is the distance between their center of masses.\n\nSince the distance between your center of mass and the Earth's center of mass is such a large distance, you can approximate this distance as being the mean, average, radius of the Earth.\n\nG can be easily found in any physics book and you are given everything else. Just plug everything in to the equation and that will give you the gravitational force between you and the Earth.\n\nb. How much you weigh is directly related to the force you just calculated. In fact, they are the same thing. Your weight is a measure of how hard the Earth is pulling you towards its center.\n\nMy old physics professor used to joke that if you want to loose weight just walk up some stairs. Since you can't loose any mass, if you are able to decrease the distance between you and the center of the Earth you will lessen the pull of gravity and thus loose weight.
1041394
Actually, the term "weight of the earth" has no real meaning.  The mass of the earth can be calculated, but weight and mass are not the same thing.  Weight is usually used to express the apparent mass of an object in the Earth's gravitational field at the planet surface.  To speak of the Earth's weight is to try to speak of the Earth's apparent mass in relation to itself and its own gravitational field.  It's like asking how far a point is from itself.  It has no meaningful answer.  If your science teacher put this question to you in terms of weight instead of mass, they should go back to coaching PE or something.
215499
As explained above it will have different values at different places but standart value for the gravitational acceleration of Earth is g=9.81 m/s/s and 1 kg mass will weigh 9.81 Newtons on Earth if you calculate it with the standart value.
17651
I assume here you're asking about the Earth's mass (mass and weight are different concepts and often confused).  The earth's mass is 5.9736 x 10^24 kg.
254077
How is the mass of the Earth determined? Newton, Galileo, Henry Cavendish, and Eratosthenes contributed to this amazing calculation. \n\n\nThis calculation is done using Newton's Law of Gravity, which formulates the attractive force (gravitational force) that two masses exert on each other: \n\nF=GmM/r2 \n\nIn Newton's equation, F is the gravitational force, G is a constant of proportionality, M and m are the two masses exerting the forces, and r is the distance between the two objects. \nG was calculated by Henry Cavendish in 1798, and was determined to be 6.67 x 10-11 m3/(kg sec2). \nAlso needed is Newton's second law of motion, F=ma, where F is the force applied to an object, m is the mass of the object, and a is its acceleration due to the force. \nGalileo determined that the acceleration due to the force of gravity of Earth was a constant equal to 9.8 m/sec2 near the surface of the Earth. \nLastly, you need to know the radius of the Earth; this was first calculated by the Greek Eratosthenes thousands of years ago (by comparing shadows in wells during the summer solstice about 230 B.C.). \n\n\nCALCULATING THE MASS OF THE EARTH\n\n1. F = GmM/r2 = ma, where F is the gravitational force, G is the gravitational constant, M is the mass of the Earth, r is the radius of the Earth, and m is the mass of another object (near the surface of the Earth). \n\n2. GM/r2= a (The m's canceled out.) Now solve for M, the mass of the Earth. \n\n3. M = ar2/G, where a=9.8m/sec2, r=6.4 x 10 6m, and G=6.67 x 10-11m3/(kg sec2). \n\n4. M = 9.8 x (6.7 x 106)2/6.7 x 10-11 = 6.0 x 1024 kg