what is the value of the stiffness of steel?
93591
The rather loose grammar in use on Yahooanswers makes your question ambiguous.  Do you want to know what of what value stiff steel is? If so, the answer is obvious; the uses of steel in construction, consumer products, automobiles, etc. are myriad.\n\nIf you mean instead, what numerical value of "stiffness" does steel posses, there are several possible answers.  One would be the shear modulus of steel, which is a measure of how much a substance deforms when a shearing force is applied.  It is define as S= Shear stress/shear strain= F/A)/ (DEL X/h) where F is the force applied parallel to an object's fixed end, A is the area over which the force is applied, DEL x is the distance the object deforms, and h is the height of the object.  For steel, this is 8.4 x 10^10 Pascals.  Compare this to 2.5 x 10^10 Pascals for aluminum, and 14 x 10^10 Pa for tungsten.
895890
Cast iron is not elastic, Increase the carbon content and it becomes brittle. No elasticity.
724807
Yong's modulus is a measure of stiffnes = tensile stress / tensile strain\n\n"Poisson's ratio is the ratio of the relative contraction strain, or transverse strain (normal to the applied load), divided by the relative extension strain (in the direction of the applied load)." (wiki)\n\n"Datum geometry is geometry that exists only for reference purposes and has no mass, no color, no material properties"\n( http://216.118.118.21/dbbp/cadbikes/howto_1.htm )
1051673
Riffle iron shaft has different flex as well although people often say they are stiffer than dynamic gold. I would think normal or regular for Riffle is 5.0, 5.5 would be strong, and 6.0 would be stiff.\n\nSay you generally have a driver swing speed of a 100-110 miles per hour, you could go for 6.0. 90 miles for 5.5, 85 miles for 5.0 and so on.
899334
see first u must understand that aisi,astm,en,jis,din all the standards are distinguish as per composition of a steel.\n\nso as per the customer requirement we are developig a standard of a steel.If it answers to a already available standard such as jis,bin,is,etc etc we are following that..\n\nso we must follow the P - no of the steel specified by ASME sec IX..that is the major classification which is globally followed
784818
no way to say.  it could be ANY grade of carbon steel (A36, 1018, 1010, 1008, ETC.), and even then, all grades have a range of carbon.\n\nfor example, 1144 has a carbon range of .40 - .48, and 1018 has a carbon range of .15- .20.  the only way to know for sure on a physical piece is to have it tested by a lab, such as Stork, Durkee, or Bodycote.
1171262
Iron is the primary element in steel. Carbon is added in an amount generally around to 0.2% (by weight). Structural steel is often made of steel identified as "A36" with the following composition (by weight):\n\nC: 0.26%\nCu: 0.20%\nMn: 0.75%\nP: Max 0.04%\nS: Max 0.05%\nThe remaining ~99% is iron (Fe).\n\nAs you can see, carbon is actually a closer third in amount (by weight) after Fe and Mn. However, the amount of carbon has large effects on the steel properties and is therefore the amount of carbon is a common way of classifying different steels.\n\nSteel actually has a number of different structures, and the amount of carbon is the important element in determing which structure, along with the way it was formed (or heat treated after first being formed from a liquid).\n\nThere are a wide range of elements added to steel and different process and treatments used to achieve the desired properties.
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tensile strength = (2*P)/(pi*t*d)\nwhere; P =maximum load you get from the machine(kPa); pi = 3.14; t = thickness/height of specimen (m) and d = diameter of specimen(m)
470540
http://en.wikipedia.org/wiki/Strength_of_materials
1137202
Cosidering that the load (2P) has been applied to the midpoint of the bar, the load which will be carried by each cantilever beam will be 'P'.\nIn that case, the maximum deflection at the free edge of the system will be  \n\n(P*L*L*L )/ (3EI)\nwhere L is the span of each beam \nEI is the flexural rigidity
94774
the absolite roughness for galvanized steel is 0.15 ks/mm and for cooper not sure , but i think its 0.0015 ks/mm
1140224
There are literally thousands of grades of steel out there. Each one having different properties including tensile strength, carbon content, etc.  If you are wanting to know about a certain application, its best to consult an engineer. If you are just wanting to learn a little about it, just get a book about engineering materials.
182647
The ref. lists many different steels and their physical properties. Go there and search "high carbon steel" and "high chromium steel".\nI checked the first item listed for these two searches and got:\n(for high carbon steel:)\nAISI 1055 Steel, cold drawn, annealed, 19-32 mm (0.75-1.25 in) round\nComponent    Wt. %  \nC 0.5 - 0.6   \nFe 98.41 - 98.9   \nMn 0.6 - 0.9   \nP Max 0.04   \nS Max 0.05   \nDensity 7.85 g/cc 0.284 lb/in³ \n\n(for high chromium steel:)\nCrucible AIRKOOL® (AISI A2) Tool Steel\nComponent    Wt. %  \nC 1   \nCr 5.25   \nFe 91.55   \nMn 0.85   \nMo 1.1   \nV 0.25   \nDensity 7.86 g/cc 0.284 lb/in³
401262
The answer to that depends on your application, you need to decide whether you want hardness, ductility, hardness, hardenability, or any of a number of other characteristics
282242
that's a real vague question, try to be more specific or at least say what king of structure do u want? (steel, conc, ..?)\nanyways this is an exremely simple example.\n\nlets' say u want to design a tension member -carrying tension force = 100 tons, -between 2 supports and this member is a steel member of yield stress= 1.4\nso to get the area u need :\n100/1.4= 71.43 cm square let's say again u want it to be I-shaped steel then u'll need  I number 400 i.e IPE 400
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For (a), with a nat. freq. of 100 rad/s or about 16 Hz, the measurement error is bound to be greater than 5% at the upper range of the excitation, 40 Hz.\nFor (b), the necessary equations are found in the reference. First solve for the natural frequency of the mass-stiffness w0 using eq. 5. Then iterate eq. 7 to find the maximum Q needed for a TR = 0.3 at w = 30 Hz. Finally use eqs. 6 to get the needed damping ratio zeta.
33498
Are you talking about steel? If so, each one has his own set of possible problems. Most of it depends on chemistry and what the end use is going to be. Take a look at ASTM and API specifications. You might find your answer there. A metallurgist can answer your question.