What is the relationship between traffic flow and linear equations?
89176
linear equatin is represented in the form of y=mx+c where m is the gradient of a graph and c is y intersection. traffic flow can be described as number of cars that use a road in a unit of time. if u plot the number of cars versus time, u will get a linear graph. find the gradient of the graph n find the y intersection, u will get a linear equation.
867942
assuming the rate of flow is constant, find the slope of the line by dividing rise over run...then find the equation of the line.  \n\nt = mx +b \n\nwhere t = time, m = slope, b = t intercept (point tank is empty) and x is number of quarts (make sure and check your units, 4 quarts equals a gallon)..\n\nthen put in zero for t and solve for x.
824196
conservation of linear moment:\nm1*v1 = m2*v2\nm1*v1/m2 = v2\n(100.0 kg)(3.0 m/s)/(175.0 kg) = v2 = 1.71 m/s
476794
This graph helps us to show what happens when a quantity y is inversely proportional to another quantity x.\n\nAgain, it shows us that a computer algorithm implementing y=(1/x) for the order of efficiency of the algorithm..
210231
1. by radar (traffic)\n2. distance over time
268125
just investigate for example ODE y"=-y and then add to the left part increasingly small non-linearity +c*y^2 and find solution of the first order of c - you will see how different modes interact with each other.
779994
If you are solving a system of linear equations (presumbale, two equations with two variables), then there are an infinite number of solutions if the graphs coincide, i.e. are the same.\n\nFor example, if I ask you to solve the system\n\n4x - 2y = 12\ny = 2x - 6\n\nby graphing, you should discover that ythe graphs are the same.  As such, this system has an infinite number of solutions.  Any ordered pair that makes the first equation true (and there are an infinite number of them) will also make the second equation true.\n\n\nI really have no idea what you are asking, but that seemed reasonable.
532639
I believe in a generalized fashion the equation for flow rate is:\n\nFlowrate = K*(cv)*((p)^.5)\n\nK = a variable to adjust for various fluids
865054
Let u=ln t, e^u=t, du=dt/t, dt=t du\nThen:\n∫ln² t dt = ∫t u² du = ∫u² e^u du\nIntegrating by parts:\nu² e^u - ∫2u e^u du\nu² e^u - 2u e^u + ∫2e^u du\nu² e^u - 2u e^u + 2e^u + C\nt ln² t - 2t ln t + 2t +C\nAnd we are done.
1063816
My thinking is...Cars flow through lights in highs and lows. Let's assume during high there are X Cars (each 25ft long) that pass at Y miles/hr. Then the duration for the Green would be:\n\nT = ( [ (25+BD) / 5280)*X] / Y ) * 3600\n\nT=Duration of Green light in secs\nBD=Break Distance in ft\nX= Number of Cars\nY=Speed of the Cars\n\nThere is something missing here...just work on it a little more...\n\nBye
581102
You use derivatives to compute how values are changing. A good example is to compute velocities.\n\nIntegration is used to compute areas and volumes.
996164
Assuming A, B, and C to be constants, this is an equation that defines a linear relation between variables x and y. There are a number of places where this would appear, but it would be easier to see it in the form y = -(A/B)x + (C/B), its equivalent.
447565
Try runnig ethereal.  It will show you the actual traffic and you can look at stuff by port.  There mays be clues in the content.
733825
The total KE is the sum of the linear and rotational KE.\nMat gave you the equation for rotational, and you seem to know the eqn for linear.  He didn't mention that ω, the angular velocity must be expressed in radians/sec, so at a given speed down the lane, ω is v/r.  So your final eq is:\n\nKEtot = mv²/2 + I(v/r)²/2
532726
CW= PW / (.5)(A)(Gr)(vcubed)\n\nCW=drag coefficient\nPW= aerodynamic power (kilowats)\n.5= constant\nA= total front area of the vehicle in meters squared.\nGr= gradient of the terrain.\nv3= velocity cubed.\n\nGr can be found with the equation:\nGR=(mass)(gravity)(velocity)(sin of the angle of the gradient)\n\nyour total answer should be  no more than 1
1074016
Detailed information as well as equations are available on the following page : \n\nhttp://www.jwave.vt.edu/crcd/kriz/modules/module06/formulation/edge_formulation.html
771447
It is an equation, the result of the equation is the function. The result may be plotted and it would be a linear function. The plot is a function of the form (equation). It is linear only if it works out to a stright line, which this does.\n\n"A linear function of x is a function of the form y = ax + b, where a and b are constants.  It's called a "linear" function because a plot of the x and y coordinates for which this equation is true takes the shape of a straight line"