what does w/v in 6% w/v potassium hydroxide means?
92910
weight/volume.\n\nIf you add 5 mL of water to 10 mL of water, you get 15 mL of water.  But if you add 5 mL of ethanol to 10 mL of water, you'll get a volume of fluid slightly less than 15 mL.  This is because the density of a fluid will change in odd ways when dissimilar liquids are mixed.  So if you say 5 w/v, you're distinguishing from the idea of volume of A per volume of B, or from a direct mass percentage.  If you added 60 grams of KOH to 940 grams of water, you'd have a 6% solution by weight.  But w/v means that you have 60 grams KOH added to a liter of water (1000 grams of water is a liter).  If you were to calculate that as a mass percentage, you'd divide 60 by (1000 + 60) and get a different answer for the percentage.
700313
NaOH + K+ = Na+ + KOH
919726
Sodium and Potassium are correct.  They are extremely reactive with water, forming Hydroxides and releasing Hydrogen gas, which is usually ignited from the exothermic heat of the reaction.\n\n2 Na + 2 H2O -> 2 NaOH + H2\n\n2 K + 2H2O -> 2 KOH + H2
893416
no you dont need the volume of acid because the value given is in moles. ie, that is already the M2 and V2 terms combined.\n\nthe MV expression goes like this\n\n(MValkali)/(MVacid)=1/2\n\n2 x 0.90 x Valkali = 0.0662\nValkali=0.0662/(2x0.9)\n=0.147L
49738
C*6+H*8+O*6=\n12.01*6+1.008*8+16.00*6=176.12 g/mol
504715
You need the formula:\ndelta Tf=iKfXmolality\nyour delta Tf is 1.96\nyour i is 1 (because it does not dissociate)\nyour Kf is 5.12\nmolality is moles of solute divided by kilogram solvent, which is .0250 kg\nYour final equation should read:\n1.96=(1)(5.12)(x/.0250)\nThen use algebra to find x.
573821
I think this question is incomplete because the Ka of HF hasn't been provided.  The amount of H+ that is formed from HF can only be calculated from its Ka value.
900470
kvar stands for "kilo-volt-amps-reactive", so...... what is the voltage?
767197
delta S = delta H vap in J / Temp in K\n\nPLEASE READ WAD WE HAVE WROTE IN YOUR EARLIER QNS
806205
d. 100% of the max number of hydroxide ions.\n\nIn chemistry, strong base or strong acid is not a degree of how much it would eat you alive if you got it on you, but the degree in which it disassociates in water.
146549
its not volts its volume. 1o volume is equal to 3% hydrogen peroxide.
283818
nihilistic is incorrect, kVA is actually a measure of power, not voltage.  high voltage or low voltage, the units are still volts.  \n\nhowever for high voltages, rather than saying 125,000 volts, people often say 125 kilovolts or 125 kV.
759238
just look at your units..that normally hleps\n\nhf ...kj / mole\n3.22 kJ / 6.02 Kj/mol =    x moles\nxmoles * 18 gram / mol.....  Thats your answer
342463
HCO3(-) <---> H(+) + CO3(2-) (Sodium ions are spectators.)\n\npH can be determined by either using the normal Ka expression:  Ka = 5.6 x 10^-11 = [H(+)][CO3(2-)]/[HCO3(-)]\n\nor by the Henderson-Hasselbach equation:\npH = pKa + log [CO3(2-)]/[HCO3(-)]
349946
Intracellular K+ should be about 140 mM (140 mEq/L)\nExtracellular K+ should be about 4 mM (4 mEq/L)\n\nTherefore, the ratio of intracellular to extracellular is about 35:1
822075
For any reaction between a strong base (potassium hydroxide) and a strong acid (nitric acid) the end result is the neutralization of the acid and base to produce water.  The net ionic reaction will always be the same and show the reaction of the acid (H+) with the base (OH-) to form water.  Therefore,\n\nH+  +  OH-  --->  H2O
276917
KE = (1/2)m*v^2 where m is the mass of the object in kilograms and v is the velocity of the object in meters/second. Plug and chug, answer will be in Netwon-meters or Joules.