i say -3x+y=-15 i say the answer is (0,5) am i on the right track.?
96194
Yes you are on the right track...Sort of.  \n\nSay you plug in any number for x.  We'll use 5\n\n-3(5)+y=-15\n-15+y=-15\n\nNow add 15 from the left to cancel the negative 15.  Then add 15 to the right to make the equation:\n\ny=0\n\nSo if x=5 and y=0 then your points will be (5,0)\n\nSay you have your original equation again\n-3x+y=-15\n\nNow plugin for x any number.  We'll use 1.\n\n-3(1)+y=-15\n-3+y=-15\n\nNow add 3 to the left to cancel out the negative 3 and add 3 to the right to make:\n\ny=-12\n\nSo x=1 and y=-12   (1,-12)\n\nHope that helps
802801
i think -1; y=mx+b, "b" is the 3 and "m"(slope) is negative one.
949123
2x + 5y = 15\n\nSo 5y = 15 - 2x\n\nSo y = 3 - 0.4x\n\n3 is the intercept. -0.4 is the slope
490279
5x + 3y = 16    \n(-)  2x + 3y = 1\n------------------------\n     3x      = 15\n\nx = 5\ny = -3\n\nSolution Set = { (5, -3) }\n\n\nx + 5y = 10  &  -2x - 10y = -20   is one and the same.\ni.e., they have to be cnsistent.
939650
x+y=-3\nx=-y-3\nx -3  -2  -1  0  1  2  3 \ny  0  -1  -2 -3-4-5 -6\n\nx^2+2y^2-12y-18=0\nwhen y=-1\nx^2+2+12-18=0\nx^2-4=0\nx^2=4\nx=+/-2\nso (-2,-1),(2,-1)\nwhen y=3\nx^2+18-36-18=0\nx^2-36=0\nx=+/-6\nso(-6,3),(6,3)\n\npoints of intersection\n(-2,-1) and (-6,3)
123571
add the two equations on left hand side and right hand side\n\n3x - y + 5x + y = 4 + 4\n\n8x = 8\n\nx = 1\n\nput this into the first equation\n3(1) - y = 4\n-y = 4 - 3 = 1\ny = -1\n\nHence x= 1 y = -1\nconfirm it by checking the 2nd equation \n5(1) + (-1) = 4 \nCORRECT!
407918
(3,-7)(6,15)\nm = (y2 - y1)/(x2 - x1)\n\nm = (15 - (-7))/(6 - 3)\nm = (15 + 7)/3\nm = (22/3)\n\nANS : (22/3)
860585
Very ingenious to have a "That's Me" account. You can give yourself ten points over and over.\n\nfor x = -3, x^2 = 9 and 3x = -9. Result = 0\nfor x = -2, x^2 = 4 and 3x = -6. Result = -2\nfor x = -1, x^2 = 1 and 3x = -3. Result = -2\nfor x = 0, x^2 = 0 and 3x = 0. Result = 0\nfor x = 1, x^2 = 1 and 3x = 3. Result = 3\n\nOnly your zero value is correct.\n\nThis is an upward-opening parabola with its minimum point at \n\nx = -1.5\n\nIt crosses the x-axis at (-3, 0) and (0, 0). Obviously, it crosses the y-axis at (0, 0) also.
1169467
y = x^2 + 5x - 3\n2y=3x - 2\n----------------\n2y = 2x^2 + 10x - 6\n2y = 3x - 2\n-----------------------\n    0 = 2x^2 + 7x - 4\n=>2x^2 + 7x - 4 =0\n=>2x^2 + 8x - x - 4 = 0\n=>2x(x + 4) -1(x+4) = 0\n=> (2x - 1)(x + 4) = 0\ntherefore 2x - 1 = 0 => x = 1/2 or \nx + 4 = 0 or x = -4\nx = - 4 or 1/2  \ngot it?
986058
Wow I'm not even sure how to do this, but I would think Y would = -15
655321
set the lines equal to each other\n3x+4 = -2x-11\n5x+4 = -11\n5x = -15\nx = -3\nthen plug into either equation to find y\n\ny = -2(-3)-11\ny = 6-11\ny = -5\ntherefore the point of intersection is (-3,-5)\n\ntosmith
908426
Plug in each of the four answers.  The only one that works is (2), because you get\n\n | 3 (-2/3) - 3 | = 5\n | -2 - 3 | = 5\n | -5 | = 5\n 5 = 5
922439
x = 15\n\n10 - 15 = -5
966998
3(-5x - 7y =28)  Multiply the first equation by 3.\n  -5(-3x - 3y = 12) Multiply the second equation by -5.\n\nYour new equations are:\n-15x - 21y = 84\n15x +15y = -60\n\nAdd them together, and you get\n-6y = 24\n\nSolve for y\n-6y = 24\n---      ----\n-6       -6\ny= -4\n\nInput that value into any equation:\n-3x - 3y = 12\n-3x - 3(-4) = 12\n\nSolve for x:\n-3x + 12 = 12\n-3x = 0\n---     ---\n-3      -3\nx = 0\n\nAnswers: (0, -4) or x=0 y=-4
742600
No that is wrong. You have to isolate the (y) that would be \ny=3x+9\nb=9\nand slope =  -3\nWhatever is together to the x after isolating the (y) is your (m)\nand the other number will be your (b)
152532
y = 4x - 3 and y = 5x - 1, so\n4x - 3 = 5x - 1 (I substituted the value of y in the first eq'n to the second eq'n)\n-x = 2\nx = -2\ny = 4(-2) - 3\ny = -8 - 3\ny = -11\n;-)
1061869
5y+2x=-4--------(1)\ny=3x-7-----------(2)\nSubstitute the value of y from (2) into (1), we get\n5(3x-7)+2x=4\n15x-35+2x=4\n17x-35=4\n17x=39\nx=39/17\nnow, y=3(39/17)-7=-2/17