f(x)=x^2+3x-4 & g(x)=5x-2  find f(g(2))?
81877
g(2) = 8\nf(g(2)) = f(8) = 84
884668
f(x)=-4x^3+5x^2+8\nf(-3)=-4(-3)^3+5(-3)^2+8\n=108+45+8 is not equal to zero\nso x+3 is not a factor
449247
f(x)=(3x^2)-x+10\ng(x)=1-20x\n\n(f°g)=f[g(x)]\n\nSo we have:\n\nf[g(x)]={[3(1-20x)^2]-(1-20x)+10}\n={3[1-40x+(400x^2)]-1+20x+10}\n=3-120x+(1200x^2)-1+20x+10\n=(1200x^2)-100x+12\n\n(f°g)(5) means that we substitue 5 for x.\n\n[(1200x^2)-100x+12](5)\n={[1200(5)^2]-[100(5)]+12}\n=[1200(25)]-500+12\n=30000-488\n=29512
1019687
F(n)=F(n-1)+F(n-2), where F(0) = 0 and F(1) = 1\nn= 2 \nF(2) = F(2-1) + F(2-2)\nF(2) = F(1) + F(0) \nF(2) = 1 + 0 = 1\nn = 3\nF(3) = F(3-1) + F(3-2)\nF(3) = F(2) + F(1)\nF(3) = 1 + 1 \nF(3) = 2\nn = 4\nF(4) = F(4-1) + F(4-2)\nF(4) = F(3) + F(2)\nF(4) = 2 + 1\nF(4) = 3\nn = 5\nF(5) = F(4) + F(3)\nF(5) = 3 + 2\nF(5) = 5
838051
5(x – 2)^2 = 3\n(x – 2)^2 =3/5\nx -2 =+- sqrt(3/5)\nx=2+- sqrt(3/5)
236346
Here's what you have to do.  Each function has its own rule: f(x) and g(x).  The composition fog (read f of g of x) means you have to do g(x) FIRST, then take the ANSWER you get and find f of that answer.  It kind of works backward.  Here are a couple examples:\n\nIf f(x) = 3x and g(x) = x-5, find fog(4)\n\nDo g(4) which is 4-5 or -1.\nThen do f(-1) which is 3x-1 or -3.\nSo fog(4)=-3.\n\nNow try gof(4).\n\nNow you have to do f(4) first: 3x4 = 12\nThe do g(12) = 12-5 = 7\n\nSo gof(4) = 7.  So you can see the order makes a difference most of the time.\n\nIf a variable or expression is there instead of a number, do the same thing, just plug in the variable or expression.  Example:\n\nIf f(x) = x^2  [x squared]  and g(x) = x-5, find fog(x+2)\n\nDo g(x+2) which means replace the x with x+2: G(x+2)=(x+2) - 5, or x-3\n\nThen replace the x in f(x) with (x-3), the answer to the first part\n\nf(x-3) = (x-3)^2 = (x-3)(x-3)= x^2 - 6x + 9\n\nThe other way around, gof(x+2)\nNow do f first: f(x+2) = (x+2)^2 or (x+2)(x+2)=x^2 + 4x + 4\n\nThen do g(x^2 + 4x + 4)= (x^2 + 4x + 4) - 5, or x^2 + 4x - 1\n\nThat's how it works, hope that helps.\n\nPS Some books write f(g(x)) instead of fog(x).
768435
(fog)(x) and (gof)(x) are called composite functions of x.\nnow, in the first case, f(x)=2x-3, g(x)=x+7\nso, (fog)(x)=f(g(x)), ie., we have to substitute g(x) in place of x in  f(x).\nso, f(g(x))=2(g(x))-3\n                =2(x+7)-3\n                =2x-11\nsimilarly, gof(x)=g(f(x))\n                         =(2x-3)+7\n                         =2x+4\nin the second problem also, we hav to follow the same approach\nso, fog(x)=f(g(x))\n               =(3x+1)^2+(3x+1)-2\n               =9x^2+1+6x+3x-1\n               =9x^2+9x\nsimilarly, gof(x)=g(f(x))\n                        =3(x^2+x-2)+1\n                        =3x^2+3x-5
838016
This is basically just asking what is f(x)/g(x)\n\nso your answer would be \n\n(x+2) / (3x^2 - 5)
965701
f(x) = x(x+2)(x-2)(x-4)\n\nMultiply it out if you need it in general form.\n\nThere could also be a constant in front of the x.
188488
That question is asking you to put the g function inside the f function...\n\nSo, put x^(1/2) in for u in the f function like this:\n(x^(1/2))^5 +2\n\nYou can simplify: x to the (1/2) to the 5th power is x^(5/2).\n\nFinal answer: x^(5/2) +2
941498
1)2(x+5)=-3x\n2)-5 and 11
974938
I believe this is how you do it:\n\n(f o g)(x) = f[g(x)] = 3(-x^2) - 4 = -3x^2 -4\n\nNow that this formula is found, sub in 2;\n\n(f o g)(2) = -3(2)^2 - 4 = -3(4) - 4 = -12 - 4 = -16
876214
g(x)=-x^3+4x-2\ng'(x)=3x^2+4\ng"(x)=6x\ng"(x)=0=6x\nx=0 is the inflection point
972739
f(x)=-5(x)+7\nf0g=-5[-9x^2-4x+5]+7\n     =45x^2+20x-25+7\n     =45x^2+20x-18\nfog(-9)\n=45(-9)^2+20(-9)-18\n=3645-180-18\n=3447
945505
{(x^2+5x+4)/(x+3)^2}/(x+1/(x^2 -9))\nFactor everything that you can factor.\nx^2 + 5x + 4 = (x+1)(x+4)\nx^2 - 9 = (x+3)(x-3)\nYou have\n{(x+1)(x+4)/(x+3)^2} * {(x+3)(x-3)/(x+1)}\nYou can cancel the (x+3)'s and the (x+1)'s leaving you with\n(x+4)(x-3)/(x+3)
630233
(4/x+2)+3-4/x = (2/x-3)+3-4/x\n5 = 2/x-4/x\nx(5) = x(2/x-4/x)\n5x = 2-4 = -2\n(5x)/5 = (-2)/5 = -0.4\nx = -2/5 = -0.4
781968
I'm not sure if your question meant f(x)=2x(x-1)(x-4) or f(x)=x(x-1)(x-4)^2, so I will answer both.\n\n1) f(x)=2x(x-1)(x-4)\n(0, 1) U (4, ∞)\n\n2) f(x)=x(x-1)(x-4)^2\n(-∞, 0) U (1, 4) U (4, ∞)