can you solve: sqrt2x^2y^3 times sqrt5xy?
84518
If the directions are to simplify, then what you have to do when multiplying square roots is to multiply the coefficients (numbers in front of the variables) and add the exponents of each variable.  Then if possible simplify the new coefficient (here, that won't be possible). Finally, if any exponent is 2 or higher, put one of that variable outside the square root for every 2 that the exponent has.  So if it is x^7 under the square root, x^3 goes outside and x is left inside.  For y^4, y^2 goes outside and no y is left inside.  I hope that makes sense and you can figure it out from here.
18182
2x^2 + 5x + 20x + 50\n2x^2 + 25x + 50
617827
3x^3y^2z^4\n\nbecause you divide the exponents by 4, but do the fourth root of the coefficient 81
901403
Do you mean\n\n3^(x+5) = 9^x → 3^(x+5) = 3^(2x)  → x = 5\n\nOr\n\n3^x+5 = 9^x\nie 3^(2x) = 3^x + 5\nSo [3^(x)]² - 3^x - 5 = 0\nLet v = 3^x\nThus v² - v - 5 = 0\nSo v = ½{1 ± √[(-1)² - 4.(1)*(-5)]}\n= ½ (1 ± √21)\nSince v = 3^x and we seek real solutions\nv = ½ (1 + √21)\nSo 3^x = ½ (1 + √21)\nx = log [½ (1 + √21)] / log3\n≈ 0.9344\n\nCheck\nLHS = 3^x + 5 ≈ 3^(0.9344) + 5 ≈ 7.791\nRHS = 9^x ≈ 9^(0.9344) ≈ 7.792 (Differences are from truncation errors)
233924
48x^2y+20xz+20xy+5z\nI switched the position of the two middle terms.\n48x^2y+20xy+20xz+5z\n4xy(12x+5)+5z(4x+1)
814548
no the correct answer will be\n(1/2)y^-5v^-12
636732
8x^2y^3+5y^2 when "FACTORED COMPLETELY"=\n\ny^2 (8yx^2+5). \n\nThis should be right. My dad is a complete genius and he did this in like 2 seconds. I double checked it on my calculator too by plugging in numbers, so I can assure you he's right.\n\nHope this helps! Have a nice day :)
250701
first put the division under the sqrt, then do the division:\nsqrt(63xy^5/7xy)=sqrt(9y^4)\n\nthen do the sqrt:  sqrt(9y^4)=3y^2\n\nwatch out: sqrt(y^2) isn't y, it's absolute value of y.\nas a rule, sqrt of variable with even exponent is half the exponent, and if the result is an odd exponent, you have to use absolute value, right up until the book tells you not to worry about it.
971390
{3XY^2M/1}-{2M/[X^-1Y^-1]^2\n+{[4X^2Y^2]/M^-1}-\n(3X^(3Y)^(3M)^-1/(XYM)^-2
840475
x^9- y^3z^3=(x³-yz)³ \n                  =x^9-3*x^6*yz+3x³y²z²-y³z³
699778
first get all the y's on one side and the x and y's seperated by rewriting the equation like this: x^3 = (3x-y^2)y. Then you can plug in your x so that you get 2 = (3*2^(1/3)-y^2)y it gets sticky from here. The equation can be writen 2 = ((sqrt(3*2^(1/3)-y)(sqrt(3*2^(1/3 ) + y) ) y which gives you y = 1.5874, .5810, -2.1684. So there you go, I got those values using the solve function on my 89. However the derivative of x^3+y^3=3xy is\n\n(x^2-y)/(x-y^2)=dy/dx\n\nso dy/dx equals 0 whenever y = x^2 and that my friend is your answer.
801272
x³y - 3x²y - 10xy --- Take x and y out of each term...\nxy(x² -3x - 10) --- Factor the x² - 3x - 10\nxy(x - 5)(x + 2)\n\n*Note: To show exponents, such as x², use the ^ key (such as x^2). This expression looks like you basiclly wrote:\n3xy - 6xy - 10xy
1123203
You can multiply and divide them easier.\n\nfifth root of 2x times 2x^20\n           -or-\n2x^(1/5) times 2x^20
811519
sqrt(250y^6)\n=sqrt[25X10(y^6)]\n=5y^3 (sqrt)10
669578
I have corrected the expression. Well here I redo the factorization\n\nThe given expresion \n= 12x^3+60x^2y+75xy^2\n= 3x(4x^2+20xy+25y^2)\n= 3x[(2x)^2+2(2x)(5y)+(5y)^2]\n= 3x(2x+5y)^2
759871
These are really hard to solve; you have to square both sides twice.\n\n(sqrt [19y - 20] + 3)^2 = (5sqrt[y-2])^2\n\n19y - 20 + 6 sqrt (19y - 20) + 9 = 25 (y-2)\n\n19y - 11 + 6 sqrt (19y-20) = 25y - 50\n\n(subtract 19y; add 11 to both sides)\n\n6 sqrt(19y - 20) = 6y - 39\n\ndiv both =sides by 3:\n\n2 sqrt(19y-20) = 2y - 13\n\nsquare both sides again:\n\n4 (19y - 20) = (2y - 13)^2 \n\n78y - 80 = 4y^2 - 52y + 169\n\nsubtract 78y; add 80 to both sides\n\n4y^2 - 140y + 249 = 0\n\n\nA huge quadratic to solve, you are on your own from here.  Are you sure you typed in the problem right?
934867
(√3x²z³) * (√15x²z )\n\n(√3x²z) (√z²)  * (√3x²z) (√5z)\n\n3x²z (√5z³ )\n   \n3(√5) x²z²  <--answer\n\nor\n\n√3x²z³ * √15x²z \n\n(√45x^4z^4)\n\n(√[9*5]x^4z^4)\n\n3(√5)x²z²  <--answer