im having problems determing which is the independent and which is the dependent variables?
92874
FOR THE MOST PART EQUATIONS WITH VARIABLES LOOK LIKE THIS F(IV)=DV FOR EXAMPLE Y=2X. X IS INDEPENDENT (OR IV IN MY EQ TO THE RIGHT) AND Y IS THE DEPENDENT OR DV THE INDEPENDENT VARIABLE IS THE ONE THAT YOU CONTROL
910993
This term is usually used for functions. Suppose a function f is defined in a domain D and has values in a set S. then, the elements of D are usually called independent variables. This name comes from the fact that yiu can change it's values independently.\n\nFor example, consider the function f defined in R by f(x) = x^2. We usually write y = x^2. Here x is the independent variable and y is the dependent one. Because you can choose values for x and y depends on x.
2775
They are not inconsistent. They have a solution (x,y)=(0,4). \n\nThey are not dependent, since one is not a multiple of the other. \n\nThey are independent.
874890
the degree of the variable is it's power like : A to the power 3\nthen A is a third degree variable....\n                                                                                         bye :)
741999
whats the equation or formula u need help with?
984829
basically, think of a function as a machine:\n\ntake this an an example: f(x) = 2x +3\nsee the x in brackets?\n\nif x = 1, then f(1) = 2(1) + 3 = 5\nif x = 2, then f(2) = 2(2) + 3 = 7\nif x = 3, then f(3) = 2(3) + 3 = 9\n\nsee whats happening? the answer DEPENDS on number inputted in the brackets.\n\nso therefore, the definition you quoted "a consistent, predictable, relationship between the independant and dependant variable" is true.
901923
The "variables" are the things in the experiment you are testing.  If you wanted to see if the rate of polar bear births increased when the sale of ice cream increased in Georgia (btw, it does), then the variables would be polar bear births and ice cream sales in Georgia.\n\nYou should note that just because the values of your variables change, does not mean that a cause and effect relationship exists.  As in the example above, just because more polar bears are born in years where ice cream sales in Georgia are high, does not mean that Georgia can make polar bears have more babies just by buying more ice cream.
509174
Yes.  x axis on graph is always independent.  y axis is dependent.  Independent variables are not changed by anything.  Like "time" secs, minutes, hours... does not vary due to any influence.  Dependent is influenced or changed by conditions that can control same.  Like the rate of sand falling out of a machine chute.  Close up the machine chute opening and the rate of sand falling decreases.
773699
You have said that they aren't independent; however, you have no mention of how they depend on each other. Therefore there is no way to calculate the answer.\nIf they *were* independent, then E[X*Y] = E[X]*E[Y]. Each one is an exponential distribution with lambda = 1, so the mean is just 1 (could also integrate e^(-x) from 0 to infinity, you also get 1.)
872957
Look at them carefully, find out the diff between each number and it should be obvious.\n\nEquations?
114095
the independant variable is the one that you can change/control, e.g. time\nThe dependant variable is the one that changes outside of your control. e.g. distance travelled. \nOn a graph you plot the independant variable on the x-axis and the dependant on the y-axis
1013660
Go to yahoo and it will help you do this homework  put in define \nstatistic and a parameter and it will tell you the difference.
846927
Sorry no one will be able to help you as we do not the data in #3.\n\nYou will need to figure this one out yourself...
2024
Case 1: f(x) := x-5*y; (y is parameter)\n\nL{f(x)} = int(exp(-s*x)*f(x),x=0..infinity);\nL{f(x)} = int(exp(-s*x)*(x-5*y),x=0..infinity);\nL{f(x)} = 1/s^2-5*y/s;\n\nCase 2: f(y) := x-5*y; (x is parameter)\n\nL{f(y)} = int(exp(-s*y)*f(y),y=0..infinity);\nL{f(y)} = int(exp(-s*y)*(x-5*y),y=0..infinity);\nL{f(y)} = x/s-5/s^2;
861788
There is no accurate way to do this because too many variables are involved. You can do like I do though and run a series of tests and then average them.\n\nhttp://www.toast.net/
129909
You might find the following informative:\nhttp://www2.mtroyal.ab.ca/~igilborn/admn1382/regression/theory/part_b.htm
1082511
I think your question have a typo.  There are three variables and I am not sure which one are you trying to solve for.