how many combinations of 4 numbers and letters?
529550
If we assume your letters range from A to Z and your digits from 0 to 9, you have 26 possibilities per letter and 10 per digit. This gives you 26^4*10^4 which is roughly 4 billion and a half. 8! / (4!
475048
Originally Answered: How many different ways can you make combinations of 3 letters out of the five-letter word LEARN? So, 60 different combinations of 3 letters out of 5 given letters can be formed.
107557
There are 10,000 possible combinations that the digits 0-9 can be arranged into to form a four-digit code. Berry analyzed those to find which are the least and most predictable.
16468
There are, you see, 3 x 2 x 1 = 6 possible ways of arranging the three digits. Therefore in that set of 720 possibilities, each unique combination of three digits is represented 6 times.
332504
There are 325 possible combinations with two letters. To determine this number of combinations, we use the fact that the alphabet has 26 letters....
820814
So there are 4 x 3 x 2 x 1 = 24 possible ways of arranging 4 items. Therefore I divide 5040 / 24 = 210. So there are 210 different combinations of four digits chosen from 0-9 where the digits don't repeat.
84525
Hence there are 2 choices for the fourth digit and only 1 choice for the fifth digit. Thus you have made 5 × 4 × 3 × 2 1 = 120 choices and there are 120 possible 5 digit numbers made from 1, 2, 3, 4 and 5 if you don't allow any digit to be repeated.
1092073
By dividing a binary number up into groups of 4 bits, each group or set of 4 digits can now have a possible value of between “0000” (0) and “1111” ( 8+4+2+1 = 15 ) giving a total of 16 different number combinations from 0 to 15.
157883
For example, a lock with ten numbers would be 10^4 or 10 000 different four digit combinations. Considering the lock only uses number: 10 x 10 x 10 x 10. 10,000 combinations.
1271554
There are four possible combinations. All three in series. All three in parallel.
22327
There are 1 billion 9 digit numbers (000,000,000 through 999,999,999). There are 45 different combinations of two different numerals (10 x 9 divided by 2). There are 512 (2 to the 9th power) different permutations for any two numbers to be used in a 9 digit number.
1374971
If you allow repetitions of any digit, then there are 4 choices for each of the 3 positions in the 3-digit numbers, or 4 x 4 x 4 = 64 3-digit numbers, in total.
200142
You multiply these choices together to get your result: 4 x 3 x 2 (x 1) = 24. Combinations and permutations are often confused by students - they are related, but they mean different things and can lead to totally different interpretations of situations and questions.
934195
With 1 item there are 6 possibilities with 2 you only have 5 choices after the first if you don't repeat the same item. So for 6 items the equation is as follows 6*5*4*3*2= 720 possible combinations of 6 items.
1440137
There are about 1,000 combinations possible for a 3-digit number/code. There are 10,000 combinations possible for a 4-digit number/code. You are much better off choosing the 4-digit code lock because anyone can easily brute-force the combination in between 20 minutes and an hour.
903955
6 x 5 x 4 x 3 = 360 possible combinations. Given a 4 digit integer. each digit can be 1 through 6. No two digits the same.
600213
There are 10,000 possible combinations that the digits 0-9 can be arranged to form a 4-digit pin code.