how many moles of water are produced from 19.2 of b2h6?
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Note: 27.66 g B₂H₆ is from the molar mass of diborane; it is necessary for us to use this to cancel the units. I provided an image for the cancellation of the necessary units. Hence, there will be 1.39 moles of water produced from 19.2 grams of B₂H₆.
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1 mole of C6H12O produces 6 moles of CO2 . 4 moles of C6H12O produces 24 moles of CO2 .
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Water has a molar mass of 18.01528 g/mol≈18 g/mol . Since water has a chemical formula of H2O , there will be 2 moles of hydrogen in every mole of water. In one mole of water, there will exist approximately 6.02⋅1023 water molecules.
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3.50⋅mol×6.022×1023⋅mol−1≅21×1023 individual water molecules.
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The mole is the SI unit for amount of a substance. Just like the dozen and the gross, it is a name that stands for a number. There are therefore 6.02 × 10 23 water molecules in a mole of water molecules.
587666
A lot. 9.34g divided by 18g/mol (the molar mass of water) gets you about 0.52 moles, times Avogadro's number of 6.02x1023 = 3.13x1023 molecules.
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So, next we calculate how many molecules there are in a drop of water, which we determined contains 0.002775 moles: molecules in a drop of water = (6.022 x 1023 molecules/mole) x 0.002275 moles. molecules in a drop of water = 1.67 x 1021 water molecules.
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Using Avogrado's Number Avogadro's number tells us there are 6.022 x 1023 molecules of water per mole of water. So, next we calculate how many molecules there are in a drop of water, which we determined contains 0.002775 moles: molecules in a drop of water = (6.022 x 1023 molecules/mole) x 0.002275 moles.
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This means that 1 mole of water weighs 18 grams. Therefore x = (6.5x1)/18 = 0.361 moles. We have 0.361 moles, so: 0.361 x 6.022141 x 10 = 2.174 x 10 molecules.
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It is equal to Avogadro's number (NA), namely 6.022 x1023. If we have one mole of water, then we know that it will have a mass of 2 grams (for 2 moles of H atoms) + 16 grams (for one mole O atom) = 18 grams.
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Divide the mass of water by the molar mass of water to get moles of water. 2.60 g H2 O / (18.00 g/mol H2 O) = 0.144 moles H2 O. Divide the mass of anhydrate by the molar mass of anhydrate to get moles of anhydrate.
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We find moles of water. All you have to do is just divide 75 by 18 and you'll get 4.17 moles of H2O. That is the final answer.
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Answer : The number of moles of water produced are, 4.4 moles. By the stoichiometry we can say that, 2 moles of hydrogen gas react with 1 mole of oxygen gas to give 2 moles of water as a product.
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Notice how the "moles of C2H6" can cancel, giving you your answer: 12 moles of hydrogen.
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Therefore, 4 moles of water will have 4(6.022x10^23) number of water molecules.
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moles of water= 57.8g/ 18.01 g/mol = 3.21. The ratio between H2SO4 and H2O is 1:2. moles of H2SO4 required = 3.21/2 = 1.61.
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Water is H2O so 5 Moles of water contains; 2 x 5 x 6.022140857 × 10^23 atoms of Hydrogen ! There are two hydrogen atoms per water molecule. There are 6.022x10^23 water molecules per mole.