how many combinations can you make out of 4 letters?
114193
reto wrote: How many different 4 letter combinations can be created from the letters A,B,C, and D? This is a case of number of arrangements possible with repetition. Thus you have 4 options each for the 1st,2nd,3rd and 4th letter giving you a total of 4*4*4*4 = 256 number of possible combinations.
57864
But if you want to know how many different license plates you can make with six characters, assuming that you allow letters and numbers (that's 36 characters per digit), the formula for calculating the number of possible combinations is 36 6, which comes out to 2,176,782,336.
943591
First, we have six possible digits to use to form our number. Assuming we can reuse any of these, the answer is simply 6^4, or 1,296 possible combinations.
84525
Hence there are 2 choices for the fourth digit and only 1 choice for the fifth digit. Thus you have made 5 × 4 × 3 × 2 1 = 120 choices and there are 120 possible 5 digit numbers made from 1, 2, 3, 4 and 5 if you don't allow any digit to be repeated.
1092906
The number of possible combinations that are possible with 26 letters, with no repetition, is 67,108,863.
354349
To find the number of permutations it is all about choices. You know the 4 digits, but you don't know the order. So this is 4 × 3 × 2 × 1 = 24, if all 4 digits are different.
127783
With a four digit PIN, there are a possible 10,000 combinations. But with a six digit code, there are 1 million possible combos, making it a lot tougher for someone to crack your security code.
1382428
Welcome! Here you will find the answer to 4 Pics 1 Word Level 47 Answer! The answer for 4 Pics 1 Word Level 47 Answer contains 7 letters.
1427017
Answer: There are 9,999 different combinations in a 4-digit lock.
52844
Explanation: If we are looking at the number of numbers we can create using the numbers 1, 2, 3, and 4, we can calculate that the following way: for each digit (thousands, hundreds, tens, ones), we have 4 choices of numbers. And so we can create 4×4×4×4=44=256 numbers.
16574
Thus you have 10x10x10 = 1000 choices for the first three digits. Finally you have 10 choices for the fourth digit and thus there are 10x10x10x10 = 10 000 possible 4 digit combinations from 0-9.
921696
However, as we have 4 slots, which need to be all filled at the same time in order to form a 4-digit number, we have to multiply the number of possibilities for each slot together, ie. 2 x 2 x 2 x 2 = = 16. Thus, 16 permutations are made possible.
316456
There are about 1,000 combinations possible for a 3-digit number/code. There are 10,000 combinations possible for a 4-digit number/code.
820814
So there are 4 x 3 x 2 x 1 = 24 possible ways of arranging 4 items. Therefore I divide 5040 / 24 = 210. So there are 210 different combinations of four digits chosen from 0-9 where the digits don't repeat.
38270
Thus you have made 5 × 4 × 3 × 2 1 = 120 choices and there are 120 possible 5 digit numbers made from 1, 2, 3, 4 and 5 if you don't allow any digit to be repeated. Now consider the possibilities with 13 as the first two digits.
1440137
There are about 1,000 combinations possible for a 3-digit number/code. There are 10,000 combinations possible for a 4-digit number/code. You are much better off choosing the 4-digit code lock because anyone can easily brute-force the combination in between 20 minutes and an hour.
718196
Given 100, choose 98, there are 161,700 combinations. The number of combinations gets bigger fast. 100, choose 95, is over 7 million combinations. The largest number of combinations given a set of 100 elements, will be 100, choose 50.