how many combinations of two letters are there?
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Answer and Explanation: There are 325 possible combinations with two letters. To determine this number of combinations, we use the fact that the alphabet has 26 letters....
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Given 100, choose 98, there are 161,700 combinations. The number of combinations gets bigger fast. 100, choose 95, is over 7 million combinations. The largest number of combinations given a set of 100 elements, will be 100, choose 50.
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Hence there are 26 × 26 possible two letter words. You can extend each of these possible two letter words into a three letter word by adding one of 26 possible letters and hence there are 26 × 26 × 26 possible three letter words.
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If we assume your letters range from A to Z and your digits from 0 to 9, you have 26 possibilities per letter and 10 per digit. This gives you 26^4*10^4 which is roughly 4 billion and a half.
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With 1 item there are 6 possibilities with 2 you only have 5 choices after the first if you don't repeat the same item. So for 6 items the equation is as follows 6*5*4*3*2= 720 possible combinations of 6 items.
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There are 10,000 possible combinations. Start at 0001, then 0002, then 0003...and work your way to 9999. Don't forget to try 0000 as well. You can also start at 9999 and work your way down to 0000 if you'd rather.
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We conclude that there are 35−3×25+3=150 combinations. If there were no restrictions, the number of five digit codes that could be formed with the digits 1, 2, 3 would be 35 since there are three ways to choose each of the five digits.
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There are 60 of them. Using the same argument as above there are 60 60 = 3600 two "digit" combinations and 60 60 60 = 216000 three "digit" combinations.
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2! See for 11 numbers there can be 9 ways for each number for 1st nine places since 0 can't be the fist number and next two are repeated from 10 numbers hence 10!/2! So 99 combinations have 10!/2! Permutations hence total ways are 99*10!/2!
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For any group of 6 numbers and letters, there are a possible 720 different permutations or combinations that can be made.
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Since there are only 12 notes to our Western musical vocabulary, there is a finite number that my feeble brain can't comprehend. With about ten notes there are at least 82,500,000,000,000,000,000 combinations. Anyone who has a simple college level understanding of algebra can figure it out to a finite number.
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This brings us to the final bracket. With 63 games and 2 possible selections for each one, that's 9,223,372,036,854,775,808 possible combinations.
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17,576 POSSIBLE COMBINATIONS. How can we solve this type of problems in the English alphabet series, which letter is the 7th to the right of the 13th letter from left?
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results? just 50,063,860. order not required. Strange enough but I do, there are 50063860 combinations.
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Answer: There are 9,999 different combinations in a 4-digit lock. And now we have 1,000+9,000=10,000 combinations total.
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List all combinations of the letters ABCD in groups of 3. There are only four combinations (ABC, ABD, ACD, and BCD). Listed below each of those combinations are the six permutations that are equivalent as combinations.
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With three columns, each with ten possibilities, the number of total combinations is 10 × 10 × 10, or 1000. With three switches, each with two possibilities, the number of total combinations is 2 × 2 × 2, or 8.