how many atoms are in the compound tetraphosphorus decoxide?
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Obviously, Tetraphosphorus decoxide, (P4O10) is a non-metal oxide that gives acidic property when dissolved in water. The name phosphorus decoxide can be interpreted as 4 phosphorus (P) atoms ('Tetra'), bonds with 10 oxygen (O) atoms ('Dec') in a molecule. besides that, it is also known as phosphorus pentoxide.
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The empirical formula of a compound of phosphorus and oxygen was found to be P2O5. The molar mass of this compound is 283.89 g/mol.
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For each negative charge on an ion, we need to add 1 valence electron so this makes the total 29 + 3 = 32 valence electrons. This means we have 32 electrons to distribute into bonds to create phosphate ion. Step 2: Determine which atom will be central in the molecule.
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There are eight moles of oxygen atoms in one mole of Pb(SO4)2.
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A The empirical formula—Ca3(PO4)2—indicates that the simplest electrically neutral unit of calcium phosphate contains three Ca2+ ions and two PO43− ions. The formula mass of this molecular unit is calculated by adding together the atomic masses of three calcium atoms, two phosphorus atoms, and eight oxygen atoms.
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Phosphorus has a partially filled 3rd principal energy level with 2 electrons in the 3s and one in the 3p orbital. So the answer is 8.
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The coefficients represent the number of moles that react, not just molecules. We would speak of this equation as “one mole of molecular phosphorus reacts with five moles of elemental oxygen to make one mole of tetraphosphorus decoxide.”
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There is thus one lead atom and two oxygen atoms per compound of lead(IV) oxide.
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1 mole of Mg3(PO4)2 (molecule) contains 3 moles of Mg atoms, 2 moles of P atoms and 2X4 moles of O atoms. = 0.03125 moles.
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combine both the phosphorus and the oxygen in the compound, whereas PO4-P only considers the phosphorus in the compound. 3-. “heavier” than PO4-P. One molecule of orthophosphate weighs 95 atomic units.
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Answer. 1 mole of magnesium phosphate compound(Mg3(PO4)2) will contain 8 moles oxygen atom. So,moles of magnesium phosphate that contains 0.25 mole of oxygen atom= 0.25/8=0.03125 mol=3.1*10^-2 mol.
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This compound contains one magnesium atom, two nitrogen atoms and six oxygen atoms.
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For Ca(OH)2 there are a total of 5 atoms in the compound. To find the number of atoms in one mole of Ca(OH)2 we multiply the number of each atom (for example there are two oxygen atoms) by Avogadro's number, 6.02 x 10^23.
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For phosphorous or any chemical compound, a mole contains 6.022⋅1023 molecules in it. So if you have 1.20⋅1025 (that's what I assume you meant) atoms of phosphorous, then just divide by Avogadro's number to find the number of moles.
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Magnesium phosphate Mg3(PO4)2. ==> 1mole of Mg3(PO4)2 contains 8 moles of oxygen atom. ==>? moles of Mg3(PO4)2 contains 0.25 moles of oxygen atom.
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(i) 3 atoms because H2S molecule has two atoms of hydrogen and one atom of sulphur. (ii) 5 atoms because PO43- ion has one atom of phosphorus and four atoms of oxygen.
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moles of Mg3(PO4)2 contains 0.25 moles of oxygen atom.