how many moles of aluminum are in al2si4o10(oh)2?
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Expert Answer In 1 mole of pyrophyllite, Al2Si4O10(OH)2 there are 2 moles of aluminium (Al).
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A mole of a compound will have 6.02 x 10^23 molecules, so the number of atoms in a mole is 6.02 x 10^23 x number of atoms in a molecule. One Molecule of Ca(OH)2 has 5 atoms. Therefore, one mole of Ca(OH)2 has 6.022 x10^23 x 5 = 30.11 x 10^23 atoms.
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The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles aluminum chloride, or 133.340538 grams. Note that rounding errors may occur, so always check the results.
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So 1- mole of Al2(SO4)3 contains= 6- moles of oxygen.
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Now, you can figure out the mass of hydrogen present in 1 mole of aluminium hydroxide by first determining how many moles if hydrogen you get in 1 mole of aluminium hydroxide. The problem tells you that the molar mass of hydrogen is equal to 1.01 g mol−1 . This means that 1 mole of hydrogen has a mass of 1.01 g .
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You need to balance the equation and see the mole ratio between the reactants. For this equation, the mole ratio is 3 moles of O2 : 4 moles of Al. So, you would then multiply: 14.8 moles*(3/4) = 11.1 moles. 11.1 moles O2 are needed to react completely with 14.8 moles of Al.
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The subscript multiplies everything in ( ). the formula for aluminum sulfate is Al2(SO4)3. Then, in a formula unit of Al2(SO4)3 there are two aluminum ions and three sulfate ions; or two aluminum, three sulfur, and twelve oxygen atoms.
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In 1 formula unit of Al(NO3)3 , there are (clearly!) 9 atoms of oxygen, 3 nitrogen atoms, and 1 aluminum atom.
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Finally, to convert this to atoms of oxygen, use Avogadro's constant, which tells you that in order to have 1 mole of atoms of oxygen, you need to have 6.022⋅1023 atoms of oxygen. The answer is rounded to three sig figs, the number of sig figs you have for the mass of aluminium carbonate.
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3 mole of O2 reacts with 4 mole of aluminium to give =2 mole of Al2O3. Hence 0.78 mole of oygen react with Aluminium to give 0.52 mole of Al2O3.
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The answer is 0.037062379468509. We assume you are converting between moles Al and gram. You can view more details on each measurement unit: molecular weight of Al or grams The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Al, or 26.981538 grams.
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This shows that all of the oxygen is consumed before the aluminum and when the reaction ends the reactant aluminum is left. The number of moles of Al2O3 formed is approximately 4.25 moles.
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Assuming a sample weight of 100 g, there would be 53 g of Aℓ and 47 g of O. 3 , we need to multiply by 2. aluminum : oxygen = 1 : 1.5 = 2 : 3 So the empirical formula is Aℓ2O3.
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Al(NO3)3 -> Al(OH)3 (weak base) and HNO3 (strong acid) -> Al +3 (strong acid) and NO3 - (weak base) -> Al(NO3)3 is acidic.
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1 mole of HCl = 1 mole of H. 2 moles of HCl = 2 moles of H.
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Category - Chemistry How many grams of aluminum are needed to completely react with 192 g of oxygen gas? Answer: C - 216 g.
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How many moles of aluminum are needed to form 3.7 moles of Al2O3? 3.7 mol Al2O3 x 4 mol Al = 7.4 mol Al 2 mol Al2O3 Done using the mole ratio's as conversion factors with dimensional analysis.