how many possible combinations for 3 digit code?
47858
There are, you see, 3 x 2 x 1 = 6 possible ways of arranging the three digits. Therefore in that set of 720 possibilities, each unique combination of three digits is represented 6 times. So we just divide by 6.
212052
There are, you see, 3 x 2 x 1 = 6 possible ways of arranging the three digits. Therefore in that set of 720 possibilities, each unique combination of three digits is represented 6 times. So we just divide by 6. 720 / 6 = 120.
955838
There are 3 numbers. So the number of permutations (arrangements) of three items equals 1 x 2 x 3 = 6. Thus, there are six permutations per combination. The number of combinations therefore is 6480 / 6 = 1080.
551730
Berry analyzed passwords from previously released and exposed tables and security breaches, filtering the results to just those that were exactly four digits long [0-9]. There are 10,000 possible combinations that the digits 0-9 can be arranged into to form a four-digit code.
461583
Answer: There are 9,999 different combinations in a 4-digit lock. And now we have 1,000+9,000=10,000 combinations total.
350931
Clearly, from 1 to 100, there are ten numbers with 3 as the unit's digit- 3, 13, 23, 33, 43, 53, 63, 73, 83, 93; and ten numbers with 3 as the ten's digit - 30, 31, 32, 33, 34, 35, 36, 37, 38, 39.
1374971
If you allow repetitions of any digit, then there are 4 choices for each of the 3 positions in the 3-digit numbers, or 4 x 4 x 4 = 64 3-digit numbers, in total.
10234
There are 10,000 possible combinations that the digits 0-9 can be arranged into to form a four-digit code.
261118
Included with Your Order: All Possible 5/30 Number Combinations. Total Combinations - 142,506. 50K-1M number combinations per file.
130300
The number of 5-digit combinations is 10 5=100,000. So, one more than 99,999. You can generalize that: the number of N-digit combinations is 10 N.
1372280
Each three-digit area code may contain up to 7,919,900 unique phone numbers: NXX may begin only with the digits [2–9], providing a base of 8 million numbers: ( 8 x 100 x 10000 ) . However, the last two digits of NXX cannot both be 1, to avoid confusion with the N11 codes (subtract 80,000).
1116347
Dana F Anderson, Just interested in math is all. Kinda a hobby. Assuming the digits 0 through 9 can be used, and a number can be repeated in the combination, then there are 10^3 possible combinations (1000 - from 000 to 999). If three different numbers have to be used, then 10 x 9 x 8 = 720 possible combinations.
1092906
The number of possible combinations that are possible with 26 letters, with no repetition, is 67,108,863.
741636
Included with Your Order: All Possible 6/40 Number Combinations. Total Combinations - 3,838,380.
184905
Included with Your Order: All Possible 6/49 Number Combinations. Total Combinations - 13,983,816. 50K-1M number combinations per file.
589379
There are 1 billion 9 digit numbers (000,000,000 through 999,999,999). There are 45 different combinations of two different numerals (10 x 9 divided by 2). There are 512 (2 to the 9th power) different permutations for any two numbers to be used in a 9 digit number. 45 x 512 = 23,040 - 10 = 23,030.
84525
Hence there are 2 choices for the fourth digit and only 1 choice for the fifth digit. Thus you have made 5 × 4 × 3 × 2 1 = 120 choices and there are 120 possible 5 digit numbers made from 1, 2, 3, 4 and 5 if you don't allow any digit to be repeated.