| Alice and Bob are spending the day in the local library, learning about | |
| 2-player zero-sum games. One of the books they're reading, "Grundy Numbers For | |
| Fun And Profit" by Nim Nimberly, has an interactive insert with a bunch of | |
| graphs and instructions for a game where the players take turns colouring each | |
| graph's vertices. | |
| Each game starts with a directed graph that has 2***N** vertices, numbered | |
| from 1 to 2***N**, all of which are initially uncoloured, and **M** edges. The | |
| **i**th edge goes from vertex **Ai** to vertex **Bi**. No two edges connect | |
| the same pair of vertices in the same direction, and no edge connects a vertex | |
| to itself. | |
| Alice goes first and colours vertices 1 and 2. She must colour one of these | |
| two vertices black, and the other one white. Bob then takes his turn and | |
| similarly colours vertices 3 and 4, one of them black and the other one white. | |
| This continues with Alice colouring vertices 5 and 6, Bob colouring 7 and 8, | |
| and so on until every vertex is coloured. At the end of the game, Alice wins | |
| if there are no edges going from a black vertex to a white one. Bob wins if | |
| such an edge exists. | |
| Who will win if Alice and Bob play optimally? | |
| ### Input | |
| Input begins with an integer **T**, the number of graphs. For each graph, | |
| there is first a line containing the space-separated integers **N** and **M**. | |
| Then **M** lines follow, the **i**th of which contains the space-separated | |
| integers **Ai** and **Bi** . | |
| ### Output | |
| For the **i**th graph, print a line containing "Case #**i**: " followed by the | |
| winner of the game, either "Alice" or "Bob". | |
| ### Constraints | |
| 1 ≤ **T** ≤ 45 | |
| 1 ≤ **N** ≤ 500,000 | |
| 0 ≤ **M** ≤ 500,000 | |
| 1 ≤ **Ai**, **Bi**, ≤ 2***N** | |
| ### Explanation of Sample | |
| For the first graph, Alice can color vertex 1 white and vertex 2 black. Since | |
| all edges start at vertex 1, Alice will win. For the second graph, Alice can't | |
| control the color of vertex 3. If Bob makes it white, then one of the two | |
| edges must be from a black vertex to a white vertex, so Bob wins. | |