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How do I make Units efficiently? I just blew almost all my money on a really cool lookin' ship. How do I regain solvency without spending a lot of time fiddling around in my inventory?  At the moment I've found a sequence of steps that'll turn 50 carbon and 100 Plutonium into ~5000 Units (by creating Suspension Fluid and then turning it into Electron Vapor). Are there better recipes or sequences of recipes I should look for? Or should I just drop the whole thing and go mine a particular mineral? I'd like to get a list of packages installed manually by apt or aptitude and be able to find out whether a foobar package was installed manually or automatically. Is there any neat way of doing that from the command line? The equals() method in Java works unexpectedly on Long data type Is there a saying or idiom for "trying to get the truth from someone by lying"? context   Mary-Ann got home late from school.  Asked where she had been, she said she had spent the afternoon at the library.  Her father thinks she is lying and says: "I know you haven’t been there because I was there myself".  He is lying because he thinks she will tell the truth if she realizes she has been caught. boyfriend – “your sister told me everything” (sister did nothing) -  girlfriend – “Oh, did she? I’m gonna kill her.    The rationale for doing this is to catch someone by surprise so he will admit having lied.  Soemtimes, however, the person isn’t lying and the real liar will have to reap the consequences of his reproachable action, having to admit he was just/it was just ...........(saying or idiom)..... Show that $\sum_{n = 1}^\infty n^qx^n$ is absolutely convergent, and that $\lim_{n \rightarrow \infty}$ $n^qx^n = 0$ I'm having trouble with proving the following for my math study:  Let $x$ be a real number with $|x| &lt; 1$, and $q$ be a real number. Show that the series $\sum_{n = 1}^\infty n^qx^n$ is absolutely convergent, and that $\lim_{n \rightarrow \infty}$ $n^qx^n = 0$  I tried this:  $\sum_{n = 1}^\infty n^qx^n$ = $x + 2^q + 3^qx^3 + ...$ $= x(1 + 2^qx + 3^qx^2 + ...)$  So far, I don't know how I have to do this, I tried to apply the root test on this, but for that I would need to compute the lim sup of the series, so I thought that was not correct. Could you explain me how to prove this?  Thanks in advance! Batch renaming files I have a directory full of images:  image0001.png image0002.png image0003.png ...   And I would like a one-liner to rename them to (say).  0001.png 0002.png 0003.png ...   How do I do this? Could humans choose to establish fibre digesting colonies in our guts? Humans don't digest fibre, and nor do any animals, but some creatures have micro-organisms (bacteria, I'm guessing) in their gut which digest fibre for them.  My question is, could humans take some sort of pill and establish our own fibre-digesting colonies in our intestines?  Has this been tried?  Supposing it could be done, would you suppose it would have any negative effects on our health?  (i.e.. would those whose gut digested fibre for them be stuck on a low-fibre diet?).    Purpose of question: just wondering.  It would be cool to be able to eat bark. Let $X$ be a space that satisfies the hypotheses used to construct a universal cover $\overline{X}$. Let $\pi = \pi_1(X)$ and consider the action of the group $\pi$ on the space $\overline{X}$ given by the isomorphism of $\pi$ with $\text{Aut}(\overline{X})$. Let $A$ be an abelian group and let $\mathbb{Z}[\pi]$ act trivially on $A$, $a \cdot \sigma = a$ for $\sigma \in \pi$ and $a \in A$.  Now, assume that $X$ is a CW complex. How do I see that $\overline{X}$ is a CW complex such that the action of $\pi$ on $\overline{X}$ induces an action of the group ring $\mathbb{Z}[\pi]$ on the cellular chain complex $C_*(\overline{X})$ such that each $C_q(\overline{X})$ is a free $\mathbb{Z}[\pi]$-module and$$C_*(X; A) \cong A \otimes_{\mathbb{Z}[\pi]} C_*(\overline{X})?$$ Show that $\sum_{n=1}^{\infty}(n^{3}\sin\left(\frac{1}{n}\right)-n^{2}+\frac{1}{6})$ converges Let $t\in \mathbb R$. Prove that $\displaystyle{\sum_{n=1}^{\infty}n^{3}\sin\left(\frac{1}{n}\right)-n^{2}+t}$ converges iff $t=\frac{1}{6}$.  While the $(\Rightarrow)$ direction was fairly easy (as $a_n$ should converge to $0$, forcing $t=\frac{1}{6}$), i'm facing some hard time trying to prove the second direction, that is $\displaystyle{\sum_{n=1}^{\infty}(n^{3}\sin\left(\frac{1}{n}\right)-n^{2}+\frac{1}{6})}$ converges. I did notice that $a_n=a_{-n}$ and tried to write this series as a Leibnitz series, but had no luck since the sequence doesn't decrease. I also tried to prove absolute convergence but then again, no luck. Thanks. How can I make focus follow the mouse cursor? Alright, I have been doing the following (variable names have been changed):   FileInputStream fis = null; try {     fis = new FileInputStream(file);      ... process ...  } catch (IOException e) {     ... handle error ... } finally {     if (fis != null)         fis.close(); }    Recently, I started using FindBugs, which suggests that I am not properly closing streams.  I decide to see if there's anything that can be done with a finally{} block, and then I see, oh yeah, close() can throw IOException.  What are people supposed to do here?  The Java libraries throw too many checked exceptions. Let $m$ be a natural number. Define $f(m) = m + \lfloor\sqrt{m}\rfloor$. Prove that at least one of the number among $m, f(m), f^2(m), \ldots$ is a perfect square. Here $f^k(m)$ denotes the composition of $f$ over itself $k$ times.  I tried the question, but the greatest integer along with square root is creating trouble. How do I show that all continuous periodic functions are bounded and uniform continuous? A function $f:\mathbb{R}\to \mathbb{R}$ is periodic if there exits $p&gt;0$ such that $f(x+P)=f(x)$ for all $x\in \mathbb{R}$. Show that every continuous periodic function is bounded and uniformly continuous.   For boundedness, I first tried to show that since the a periodic function is continuous, it is continuous for the closed interval $[x_0,x_0+P]$. I know that there is a theorem saying that if it is continuous on a closed interval, then it is bounded. However, I'm not allowed to state that theorem directly. Should I just aim for a contradiction by supposing f is not bounded on the interval stated above? Check differentiability of multivariable functions I am trying to determine if the following functions are (totally)   differentiable at $(x,y)=(0,0)$.      $$f(x,y)=\sqrt{\vert xy \vert}$$      $$g(x,y)=e^{{{\vert x \vert}^3}y}$$   However I am not particularly sure where to start. The concept of the total derivative being the Jacobian matrix makes sense but I don't really understand how to work with functions that may not have a Jacobian matrix. Any help would be greatly appreciated! Real numbers equipped with the metric $ d (x,y) = | \arctan(x) - \arctan(y)| $ is an incomplete metric space I have to show that the real numbers equipped with the metric $ d (x,y) = | \arctan(x) - \arctan(y)| $ is an incomplete metric space.  Certainly, I have to search for a Cauchy sequence of real numbers with respect to given metric that must not be convergent. But I am unable to figure out that.  Can anybody help me with this.   Thanks for helping me. Dual Canadian and British citizen - healthcare coverage in the UK? I want to know if I am entitled to medical assistance in the UK while visiting for 3 weeks in June. I am travelling on my Canadian passport since my UK one is outdated. After deleting all nodes, how do I reset the node ID to start from 1 again? I generated tons of dummy content for testing, and then deleted them all.  As nid is auto-increment, newly created node will have a nid of last created nid +1.  How can I make nid start from 1 again? Stopping users voting multiple times on a website I'm planning to add some vote up/vote down buttons to a website I run. This seems easy enough but I want to stop people voting multiple times. One solution would be to make them register before allowing them to vote but I'd prefer not to have to force them to register.   Is there are a reasonably straightforward way of doing this? Checking the IP address doesn't seem like a good solution, since it's possible that multiple users may come from the same IP address.   Cookies might be the answer, but a savvy user could delete the cookie. Any better ideas? Terminal only shows up as a black window I am travelling to Budapest and therefore have a Schengen Visa. I hold an Indian passport and a valid US visa. I'm travelling from Chicago-Heathrow-Budapest and returning by Budapest-Dublin-Chicago.  Would I need a transit visa for UK/Ireland?  UPDATE  Hoping this will help someone someday.   I was not allowed to board my return flight (BUD-DUB-ORD) because I do not hold an overnight Irish Transit Visa. They said I could have transited happily if the connecting flight was in the same day, but because I would have to originally land at 10 PM and catch the connecting flight next morning at 10 AM, I needed a transit visa. Well, I thought it was BS, but couldn't help comply with the rules. I booked another last minute ticket and flew via Warsaw via LOT.