Check for file on a remote server in Classic ASP
Access network share from within VBScript eg FileSystemObject
Viruses: Adaptation to a new host through repeated host jumps Strangely low reputation How is this possible that the user with  question only has that little reputation? I've checked his site and he doesn't have a lot of downvotes or bounties. Ahlfors "Prove the formula of Gauss" He says:     Prove the formula of Gauss:   $$ (2\pi)^\frac{n-1}{2} \Gamma(z) = n^{z - \frac{1}{2}}\Gamma(z/n)\Gamma(\frac{z+1}{n})\cdots\Gamma(\frac{z+n-1}{n}) $$   This is an exercise out of Ahlfors.  By taking the logarithmic derivative, it's easy to show the left &amp; right hand sides are the the same up to a multiplicative constant.  After that I'm lost. It's easy using another identity when $n$ is even to use induction. But when $n$ is odd I am lost.  It's obvious when $n$ is a power of 2. Allowing all/different file type uploads How to count number of bases and subspaces of a given dimension in a vector space over a finite field? Let $V_{n}(F)$ be a vector space over the field $F=\mathbb Z_{p}$ with $\dim V_{n} = n$, i.e., the cardinality of $V_{n}(\mathbb Z_{p}) = p^{n}$. What is a general criterion to find the number of bases in such a vector space? For example, find the number of bases in $ V_{2}(\mathbb Z_{3})$. Further, how can we find the number of subspaces of dimension, say, $r$?   I need a justification with proof. I have a formula, but I am unable to understand the basic idea behind that formula. MySQL Insert query doesn't work with WHERE clause In the Stack Exchange Android App v1.0.7 1.0.33 (with a HTC One running Android 4.4.2), the answer count for a question you're viewing is displayed in two places:   In the label of the answer tab:   At the bottom of the question tab:    I've noticed that these counts don't reliably update when new answers arrive.   If you refresh the question tab, neither count updates. If you refresh the answer tab, the second count will be updated, but the answer tab's count will not, leaving the two out of sync.   Refreshing either tab should probably update both counts!    Screenshots of the bug in action:    I waited for it to be answered. A while later, the question now has an answer.    The tab still says 0 answers though. Switching back to the question tab, , but the tab count still doesn't. old Designjet 430 with Windows 10 Excel How to make Text Qualifier editable or add a new entry in the existing list? Is there a keyboard command for 'show desktop'? Like Windows, I want to hit Super+D to jump to the desktop or minimize all windows. I don't see command like that in Keyboard Shortcuts. Any idea? This question is about an efficient way to compute principal components.   Many texts on linear PCA advocate using singular-value decomposition of the casewise data. That is, if we have data $\bf X$ and want to replace the variables (its columns) by principal components, we do SVD: $\bf X=USV'$, singular values (sq. roots of the eigenvalues) occupying the main diagonal of $\bf S$, right eigenvectors $\bf V$ are the orthogonal rotation matrix of axes-variables into axes-components, left eigenvectors $\bf U$ are like $\bf V$, only for cases. We can then compute component values as $ \bf C=XV=US$. Another way to do PCA of variables is via decomposition of $\bf R=X'X$ square matrix (i.e. $\bf R$  correlations or covariances etc., between the variables ). The decomposition may be eigen-decomposition or singular-value decomposition: with square symmetric positive semidefinite matrix, they will give the same result $\bf R=VLV'$ with eigenvalues as the diagonal of $\bf L$, and $\bf V$ as described earlier. Component values will be $\bf C=XV$.   Now, my question: if data $\bf X$ is a big matrix, and number of cases is (which is often a case) much greater than the number of variables, then way (1) is expected to be much slower than way (2), because way (1) applies a quite expensive algorithm (such as SVD) to a big matrix; it computes and stores huge matrix $\bf U$ which we really doesn't need in our case (the PCA of variables). If so, then why so many texbooks seem to advocate or just mention only way (1)? Maybe it is efficient and I'm missing something? Controversy over verb choice in "neither you nor I {is/am/are} in control" How does the wording "for each" work? Some cards in magic has something happen for each {something}. For instance:  makes you gain 2 life for each creature you control. Tapping  adds one green mana to your mana pool, and you gain 1 life for each non-land card revealed.  How is this life gained: all at once or "one bit" at a time? Say I tap Selvala and 1 land, and 2 non-lands are revealed: do I gain 2 life, or do I gain 1 life two times? Would  have one or two +1/+1 counters placed on it if I had it in play at that point? I know that $\operatorname{Spec} \mathbb{C}[x]$ can be identified with the set $\mathbb{C}\cup *$, where $*$ is a generic point via the correspondence  $$ \prod_{i}(x-a_i) \leftrightarrow \{a_i\}_i , \ \ \ \ (0)\leftrightarrow *. $$ This correspondence holds for any $\operatorname{Spec} k[x]$ with algebraic closed field $k$.   When $k$ is not algebraic closed, how should one understand $\operatorname{Spec} k[x]$? What happens if light/particles exceeded the speed of light for a particular medium? How to prove the convergence of $\sum_{n\geq 0}\frac{n!^d}{(dn)!}$ for $d\geq 2$? How can we find the general formula about the convergence of the serie $\sum_{n=0}^\infty \frac{(n!)^d}{(dn)!}$ for all $d\geq2$ ?  I tried using the d'Alembert Criteria but it doesn't simplify itself enough to prove the convergence. biblatex and autonum don't work together biblatex and autonum don't seem to work together in the newest version. Consider the following MWE:  \documentclass{article} \usepackage[utf8]{inputenc} \usepackage[backend=biber]{biblatex} \usepackage{autonum}  \begin{document}  \end{document}   I get the following error messages:  0 File ended while scanning use of \ettl@for@do1 0 pdflatex: \pdfmatch: repetition-operator operand invalid pdfTeX warning: pdflatex: \pdfmatch: repetition-operator operand invalid)Runaway argument?{{\blx@bibdata@i {\blx@tempb }}\blx@bibfiles \eappto \blx@tempa {\blx@xml@comme   After commenting out either biblatex or autonum, the errors disappear. How to read over 4k input without new lines on a terminal? So I have a lot of data WITHOUT NEW LINES on the clipboard (it's a large SVG file on one line). I went  $ cat &gt;file.svg   then tried to paste (in Gnome Terminal), but only the first 4kB characters were accepted.  I assume this is a readline feature/limitation.  Is there a way to read from STDIN that would avoid this problem?  EDIT  Test case: Create a demo file. This one will have ~4k "=" symbols followed by "foo bar".  { printf '=%.0s' {1..4095} ; echo "foo bar" ; } &gt; test.in   Copy that into your clipboard  xclip test.in   (if you want to middle-click to insert) or  xclip -selection clipboard test.in   (if you want to use Ctrl-Shift-Insert to past it in)  Then cat &gt;test.out, paste (whichever way). Press Ctrl-D to end the stream. cat test.out - do you see "foo bar"?  On my set-up (Ubuntu 12.04, Gnome Terminal, zsh) when I paste I only see the = and I don't see foo bar. Same when I inspect test.out. I'm using the Apache Commons EqualsBuilder to build the equals method for a non-static Java inner class. For example:  import org.apache.commons.lang.builder.EqualsBuilder;  public class Foo {     public class Bar {         private Bar() {}          public Foo getMyFoo() {             return Foo.this         }          private int myInt = 0;          public boolean equals(Object o) {             if (o == null || o.getClass() != getClass) return false;              Bar other = (Bar) o;             return new EqualsBuilder()                 .append(getMyFoo(), other.getMyFoo())                 .append(myInt, other.myInt)                 .isEquals();         }     }      public Bar createBar(...) {         //sensible implementation     }      public Bar createOtherBar(...) {         //another implementation     }      public boolean equals(Object o) {         //sensible equals implementation     } }   Is there syntax by which I can refer to other's Foo reference apart from declaring the getMyFoo() method? Something like other.Foo.this (which doesn't work)? How can I add a new user as sudoer using the command line? After I add a user using adduser, I can't see it via System > Administration > Users and Groups unless I log out and then log in again. Is that normal?  Also, can I set a newly added user as a sudoer or do I have to change that only after adding it? How can I do that via the shell?  Finally, can I delete the original user that was created upon initial installation of Ubuntu, or is this user somehow 'special'?