Apply depth of field blur effect from a grayscale video using ffmpeg
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How do I bake multiple texture maps into 1 UV, In Blender Cycles? What is "it" in the following sentence: It is clear that Bob likes doughnuts The situation is somewhat like-  var someVar = some_other_function(); someObj.addEventListener("click", function(){     some_function(someVar); }, false);   The problem is that the value of someVar is not visible inside the listener function of the addEventListener, where it is probably being treated as a new variable. Training N classifiers for N labels vs one classifier with N labels I have a classification problem which is multi-label with N labels. I would like to know which method would be the better choice? Training N classifiers (1 for each label) or a single classifier which use K-hot encoding. I'm using a neural network for this with a softmax at the last layer. (Is there any chance that the softmax would cause a problem?) I'm using tensorflow for the model. find a $\int_{x}^{g(x)} f(t)\,dt = 1$ Why can't the indefinite integral $\int\frac{\sin(x)}{x}\mathrm dx$ be found? I came across a list of functions in my calculus textbook whose indefinite integral cannot be found. It was written that the integral $$\int \frac{\sin(x)}{x} dx$$ cannot be evaluated without any explanation as to why.  I did some research over the internet and found out that the definite integral $$\int_{0}^{\infty} \frac{\sin(x)}{x} dx$$ can be evaluated using Laplace transformation and is equal to $\pi /2$. But I still couldn't find answer to my original question. I read somewhere that the integral cannot be expressed using 'elementary functions'. A little help is appreciated, I'm in Calc 1 going advanced than my course but I am sorry if my post shows lack of research. Thank you! TSQL Script Execution Through Power shell, Special Characters Rendering Problem We have a simple T-SQL script file (.sql), which we execute through Powershell. Everything works fine, except the script portion, where we are using some special characters as string (example: 'ô' ).   The same script works fine, if I just execute it through SQL Server Management Studio, but through Powershell it's not rendering these special characters properly.  Here how we access the script file to execute on all databases on instance  Add-PSSnapin SqlServerCmdletSnapin100 Add-PSSnapin SqlServerProviderSnapin100 invoke-Sqlcmd -InputFile "C:\DailyPatch\run.sql" | Out-File -filePath "C:\DailyPatch\dbname.txt"  $text=Get-Content C:\DailyPatch\dbname.txt $a = $text.length $a=$a-3  $logFile = 'C:\DailyPatch\dblog.txt'  for ($i=3 ; $i -le $a ;$i++) {        write-host $text[$i]     $error.clear()      Invoke-sqlcmd -inputfile "C:\DailyPatch\Script4AllDBs.sql"-database $text[$i]-OutputSqlErrors $true|Out-File -filePath "C:\DailyPatch\dbname.txt"      foreach ($rr in $error) {         $text[$i] &gt;&gt; $logFile         $rr &gt;&gt; $logFile     } }   How to set collation in Powershell to avoid such kind of issues?  ps. Unicode thing is already handled on script side  Added: Special characters are being changed to � (Replacement Character) Duplicate objects transformation applies to both objects I'm facing this frustrating "feature" that I can't seem to remedy; when I duplicate an object (and now, even when I create two completely new objects), their transformations/scaling is synchronized. This is extremely annoying when trying to use any sort of transformation keyboard shortcut.  It should be noted by going to the properties menu (N) and manually setting the properties works just fine.  For instance, here is just the camera selected (trust me, I made sure):   And when I try to transform by clicking+dragging on the X axis OR by hitting G->X, this happens:   They are not grouped (verified by going to the Groups list up in the Scene panel) and they do not have parents (verified by going to Object->Relations).  I have tried the unlink command as well, to no avail.  I have seriously run out of options; what did I change to have my G->X shortcuts transform multiple objects? It seems completely at random, too; certain objects seemed to be "linked" to other random objects, and this "linking" is guaranteed when duplicating even when I do a non-linking duplicate (Shift+D).  What gives? Compute $E(X\mid X+Y)$ for independent random variables $X$ and $Y$ with standard exponential distributions Being $X$ and $Y$ independent random variables distributed as $\mathrm{Exponential}(1)$ and let $T=X+Y$ Calculate $E(X|T)$.  This is my attempt at solving this:  Being $Z=\sum_{i=1}^{n}P_{i}$ where $P_{i}$~$\mathrm{Exp}(\lambda)$ then using it's MFG you have that $$M_{P_i}(t)=\frac{\lambda}{\lambda-t}$$ then $$M_{Z}(t)=M_{\sum{P_{i}}}(t)=(M_{P_{1}})...(M_{P_{n}})=(\frac{\lambda}{\lambda-t})^n$$ with this being the MFG of a $\mathrm{Gamma}$ distribution with parameters $(n,\lambda)$  With this result is easy to see that $T$~$\mathrm{Gamma}(2,1)$  Now $E[X|T]=\int xf_{X|T}(x|t)dx$  Then using Bayes' theorem we can make $$f_{X|T}(x|t)=\frac{f_{T|X}(t|x)f_{X}(x)}{f_{T}(t)}$$ then $$f_{T|X}(t|x)=Pr(T=t|X=x)$$ $$=Pr(X+Y=t|X=x)$$ $$=Pr(x+Y=t|X=x)$$ $$=Pr(Y=t-x)=f_{Y}(t-x)$$  Using this result we can now rearrenge $$f_{X|T}(x|t)=\frac{f_{Y}(t-x)f_{X}(x)}{f_{T}(t)}$$ $$=\frac{e^{-(t-x)}.e^{-x}}{\frac{te^{-t}}{\Gamma(2)}}$$ $$=\frac{1}{t}$$ then $$E[X|T]=\int (x)(\frac{1}{t})dx$$  And this where I got stuck because $1_{x\epsilon(0,\infty})$, I made this explanation step-by-step hoping that someone can se easily check where I went wrong. I would aprecciate a step-by-step answer, thanks. How to set Oracle's Java as the default Java in Ubuntu? Javascript get date in format I think this was more of a fantasy series, though it was more subtle than The Lord of the Rings IIRC. Set in modern times - though there was some alternate realm thing that was less modern I think.   I read it about ten years ago, I think, and there were a number of books at that time. My brother and I stopped reading it shortly after the main character summoned a small demon somehow who was a bad influence... I think.  It involved a boy who somehow was at some kind of training school/academy. Unsure where it was located, but it needed a classic portal to get to it I think. I clearly remember some scene involving a car driving at specific speeds to get past some barriers. There may have been something about how the school was (slowly) moving or the wards were shrinking... unsure. I don't think it was only magic based, but that was some element of it. The boy had some kind of strange power that made him an incredible fighter, but he wasn't sure how (at least from what I remember). The recordings of him training just showed a white flash I think. I remember some scene in an elevator going down to the training floor where he went to a level below some adult with him.  There was something else about him joining a group that had twelve members, one for each month, whose powers grew and lessened based on how close the date was to "their" month.  Oh, and there was something about him looking for his mother I think? Perhaps in another "realm"?   Any help is appreciated! Add the option to do a case-sensitive search I noticed that the search engine does not consider capital letters (just like most regular search engines). However, I have the feeling that in a "coding" context, this could be useful.  For example, searching pages about the standard C library "FILE" struct returns a lot of pages containing the "file" word, that are not (always) relevant.  Is there a way to force keeping capitals? If not, maybe it could be a nice feature to add? I'm having trouble understanding what I'm doing wrong here: I'm trying to set up two network Locations, one for my home network via my cable modem and a second for Wi-Fi tethering via my mobile phone. What I'd like to be able to do is change the Location (under the Apple menu &gt; Location) and have my Mac automatically connect to the proper Wi-Fi network: either my home network SSID or my WiFi tethering SSID. I defined two locations, switched between them, and set the preferred network list for each location. But when I change the preferred network list for one Location, it changes the list for the other Location as well! Am I doing something wrong or is it really not possible to maintain a separate list of Preferred Networks for each network Location? It seems doubtful it's not possible since just about every other netrok setting depends on the location... I am using OS X 10.7.2. How useful is that rule and how many times we can use that in one game?  Under what conditions can the en passant rule be used?  How often does it come up and is it a good idea to use it? Use of Predictable Network Interface Names with alternate kernels Almost constantly, I use kernels from the , or kernels I have compiled myself, using the Ubuntu kernel configuration.  The problem is when I am using the stock kernel it seems to default to using predictable network interface names (i.e. "p4p1"), but when I use any alternate kernel it seems to default to using the old method (i.e. "eth0").  While not really relevant to this question, I had a hard disk failure on my test computer and am doing a new install of Ubuntu Server 14.04.2.  I have not been able to determine what is the difference between the kernels. I suspect a kernel configuration parameter, but have been unable to identify which one.  My question: How can I make predictable network interface names work consistently across all kernels?  Additional notes: Somewhere I saw to disable predictable network interface names to add this to grub:  GRUB_CMDLINE_LINUX_DEFAULT="net.ifnames=0 biosdevname=0"   so, I thought the opposite might help:  GRUB_CMDLINE_LINUX_DEFAULT="net.ifnames=1 biosdevname=1"   but it made no difference. Actually, I can never get the non-stock kernel to use biosdevname, no matter the setting. And I can never get the stock kernel to generate a /etc/udev/rules.d/70-persistent-net.rules file (even though, that is not what I want), no matter the setting of net.ifnames. If I have net.ifnames=1, then at least the non-stock kernel doesn't generate an incorrect /etc/udev/rules.d/70-persistent-net.rules file.  Excerpts from /var/log/udev: stock kernel:  KERNEL[9.216730] add      /devices/pci0000:00/0000:00:1c.4/0000:03:00.0/net/p4p1 (net) ACTION=add DEVPATH=/devices/pci0000:00/0000:00:1c.4/0000:03:00.0/net/p4p1 IFINDEX=2 INTERFACE=p4p1 SEQNUM=1945 SUBSYSTEM=net ... UDEV  [9.241073] add      /devices/pci0000:00/0000:00:1c.4/0000:03:00.0/net/p4p1 (net) ACTION=add DEVPATH=/devices/pci0000:00/0000:00:1c.4/0000:03:00.0/net/p4p1 ID_BUS=pci ID_MODEL_FROM_DATABASE=P8P67 and other motherboards ID_MODEL_ID=0x8168 ID_NET_NAME_MAC=enxf46d04652d8e ID_NET_NAME_PATH=enp3s0 ID_OUI_FROM_DATABASE=ASUSTek COMPUTER INC. ID_PCI_CLASS_FROM_DATABASE=Network controller ID_PCI_SUBCLASS_FROM_DATABASE=Ethernet controller ID_VENDOR_FROM_DATABASE=Realtek Semiconductor Co., Ltd. ID_VENDOR_ID=0x10ec IFINDEX=2 INTERFACE=p4p1   From Ubuntu PPA kernel 4.1RC5:  KERNEL[10.772566] add      /devices/pci0000:00/0000:00:1c.4/0000:03:00.0/net/eth0 (net) ACTION=add DEVPATH=/devices/pci0000:00/0000:00:1c.4/0000:03:00.0/net/eth0 IFINDEX=2 INTERFACE=eth0 SEQNUM=1962 SUBSYSTEM=net ... UDEV  [11.185866] add      /devices/pci0000:00/0000:00:1c.4/0000:03:00.0/net/eth0 (net) ACTION=add DEVPATH=/devices/pci0000:00/0000:00:1c.4/0000:03:00.0/net/eth0 ID_BUS=pci ID_MODEL_FROM_DATABASE=P8P67 and other motherboards ID_MODEL_ID=0x8168 ID_NET_NAME_MAC=enxf46d04652d8e ID_NET_NAME_PATH=enp3s0 ID_OUI_FROM_DATABASE=ASUSTek COMPUTER INC. ID_PCI_CLASS_FROM_DATABASE=Network controller ID_PCI_SUBCLASS_FROM_DATABASE=Ethernet controller ID_VENDOR_FROM_DATABASE=Realtek Semiconductor Co., Ltd. ID_VENDOR_ID=0x10ec IFINDEX=2 INTERFACE=eth0 SEQNUM=1962 SUBSYSTEM=net USEC_INITIALIZED=3227   Note: I have temporarily moved past this issue by allowing a /etc/udev/rules.d/70-persistent-net.rules file to be created, and then editing it for proper device names. Ultimately, I would like to get rid of the file. Why $\gcd(qb+r,b)=\gcd(b,r)$? Given: $a = qb + r$. Then it holds that $\gcd(a,b)=\gcd(b,r)$. That doesn't sound logical to me. Why is this so?    Addendum by LePressentiment on 11/29/2013: (in the interest of  and averting a duplicate)  What's the intuition behind this result? I only recognise the proof and examples solely due to algebraic properties and formal definitions; I'd like to apprehend the result naturally. What is a token? Please forgive such a basic question, but I did some Google searching and looked around on this site,  and while there are many threads and online resources that involve tokens, I can't seem to find a direct explanation of what a token is, specifically in the context of TeX, LaTeX, etc. Perhaps there is a good explanation of tokens in the TeXbook, but I don't have a copy of it.   gives me some idea:     A token is a string of characters, categorized according to the rules as a symbol (e.g., IDENTIFIER, NUMBER, COMMA).   but this is a bit too general for me to understand. Taking a guess based on the Wikipedia definition and , is it correct to say that a token is "a thing that has a catcode"? (which, even if true, does not seem entirely satisfactory as an answer: what characterizes the things that are given catcodes?)  Some illustrative examples, and non-examples, of tokens in the realm of TeX, LaTeX, etc. would be much appreciated. I frequently find myself needing a word to express happiness that acknowledges a tragic or unfortunate circumstance underpinning that happiness. Preferably the word could have both adjective and verb forms. For example, "Gregory [verb-ed | felt adjective about] the balmy February day, suspecting it was yet another consequence of catastrophic and irreversible climate change."  "Bittersweet" is close, but not precisely right. It implies ambivalence rather than genuine gladness. "Schadenfreude" is also in the neighborhood, but I don't want to imply that the tragic part of the situation is what causes the pleasure. (Also, I recognize that the word may not quite exist in English, and I don't know if this is forbidden for this forum, but I'd welcome a loan word or phrase if there's a better one.) Consider the following:   $1 = 1^2$ $2 + 2 = 2^2$ $3 + 3 + 3 = 3^2$   Therefore,   $\underbrace{x + x + x + \ldots + x}_{x \textrm{ times}}= x^2$   Take the derivative of lhs and rhs and we get:   $\underbrace{1 + 1 + 1 + \ldots + 1}_{x \textrm{ times}} = 2x$   Which simplifies to:   $x = 2x$   and hence    $1 = 2$.     Clearly something is wrong but I am unable pinpoint my mistake.