How does Lecturer in UK compare to other systems?
Academic rank equivalence between the UK and the US systems
I am little confused with the applicability of reinterpret_cast vs static_cast. From what I have read the general rules are to use static cast when the types can be interpreted at compile time hence the word static. This is the cast the C++ compiler uses internally for implicit casts also.  reinterpret_casts are applicable in two scenarios:   convert integer types to pointer types and vice versa  convert one pointer type to another. The general idea I get is this is unportable and should be avoided.     Where I am a little confused is one usage which I need, I am calling C++ from C and the C code needs to hold on to the C++ object so basically it holds a void*. What cast should be used to convert between the void * and the Class type?  I have seen usage of both static_cast and reinterpret_cast? Though from what I have been reading it appears static is better as the cast can happen at compile time? Though it says to use reinterpret_cast to convert from one pointer type to another? A formula for Perspective measurement If I have a photograph of a rectangular object whose image recedes with perspective, is it possible to work out the scale of measurements along that object?  For example: I have a photograph of a (metric) ruler.  The ruler is graduated in centimetres as shown, 30 cms.  Is it possible to work out the distance between each centimetre?  The screenshot shows the photograph.  The representation on the Picture Plane shows the nearest edge of the ruler to be 50mm and the farthest edge to be 15mm. By measuring the photo, I see that the distance between 0 and 1 is 7.5mm and the distance between 27 and 28 is 0.9mm.  Is there a way to get these results from a formula?  It doesn't need to be 100% accurate: it's for photometric software I'm writing, so it's only going to be used as a rough guide. Is a general GRE score of X sufficient for entry to postgraduate degree Y? Question: I got general GRE scores of VR (verbal reasoning), QR (quantitative reasoning), and AW (analytical writing).  Is this a good score to apply for entry to postgraduate degree in field X?  How will this score look to the selection committee?    Note: This is an intentionally generic GRE question (with unspecified scores and field of study) which is intended as a template for a large number of questions asked on this forum regarding evaluating the scores on the general GRE test (e.g., , , , , , , , and ).  This question seeks answers that are applicable for an applicant for graduate-level programs in any field, based on any scores in the GRE general test.  The goal of this question is to provide a general reference to avoid the need for specific questions with particular scores/field of study. Can a class overload methods that also exist in the publicly inherited interface? It seems like this is unambiguous and useful, but compilers (VC, Intel, GCC) all complain, at least by my construction. Below is a toy example. The inherited rebound() function has two clear overloads, yet this will not compile.  If you rename the rebound() method in either class, it works fine, but if they share the same member function name (even though they're overloaded with different argument types!) you get a fatal error of "too few arguments to function call."  The workaround is trivial (I'll just rename the methods) but I'm just trying to understand if this is a C++ restriction (and why it would be).   #include  class Bound { public:   Bound() : x0(0.0), x1(0.0) {};   Bound(double x) : x0(x), x1(x) {};   double width() const {return x1-x0;}   void rebound(const Bound *a, const Bound *b); private:   double x0, x1; };  void Bound::rebound(const Bound *a, const Bound *b) {   if (a && b) {     x0=std::min(a->x0, b->x0);     x1=std::max(a->x1, b->x1);   } }  class Node : public Bound { public:   Node(double x) : Bound(x), left(0), right(0) {};   Node(Node *a, Node *b) : left(a), right(b) {rebound();}   void rebound() { rebound(left, right); } private:   Node *left;   Node *right; };   int main() {   Node A(1.0);   Node B(2.0);   Node C(&A, &B); } Buying from AliExpress I've notice that the business to business site AliBaba and it's more consumer friendly AliExpress website have a number of bike components for sale. They tend to be complete component groupsets and the like but are some quite reasonable deals, especially if you are building a bike from scratch.  I've used AliExpress before to purchase electronic components, which have been good quality and are what they say on the tin.   Has anyone used AliExpress to buy bike components and have they had any trouble? (quality, counterfeit etc.)  One benefit is that your money is held in escrow until you receive the item and aprove the payment so some safety. Suppose that $f(z)$ is analytic function in the disk $|z|\le R$ and $A(r)=\max_{|z|=r}Re(z)$ then prove that $r&lt;R$  $$\max_{|z|=r}\left|\frac{f^n(z)}{n!}\right|\le \frac{2^{n+2}R}{(R-r)^{n+1}}\{A(r)+|f(0)|\}$$  MY attempt   Using Cauchy generalized integral formula   $f^{(n)}(z_0)=\frac{n!}{2\pi i}\int _c\frac{f(z)dz}{(z-z_0)^{n+1}}$  then $\max_{|z|=r}\left|\frac{f^n(z)}{n!}\right|=\left|\max_{|z|=r} \frac{1}{2\pi i}\int _c\frac{f(z)dz}{(z-z_0)^{n+1}}\right|$  and i think we can solve by using Borel caratheodory theorem  Let $f(z)$ be holomorphic function on $|z|\le R$ and let $M(r)=\max_{|z|=r}|f(z)|$ and $A(r)=\max_{|z|=r}Re f(z)$ then  for $0&lt;r&lt;R$  $$ M(r)\le \frac{2r}{R-r}A(R)+\frac{R+r}{R-r}|f(0)|$$  from here how to processed ? For my MAC laptop, I only have 250GB and out of this 250GB MAC is taking up 129GB in the other section. I looked everywhere to the best of my knowledge. Please note my home directories is only 45GB. Can you somehow please help me? Getting ssh to execute a command in the background on target machine Show that antipodal points remain antipodal under any isometry of $S^2$ "The antipodal map of $S^2$ is the isometry $\bar m$ sending each point $P$ to its opposite point $-P$" (from textbook)  Show that antipodal points remain antipodal under any isometry of $S^2$. In other words, for each isometry f of $S^2$, if $P$ and $P'$ are antipodal, then so are $f(P)$ and $f(P')$  I am unsure how I can define the $P$ and $P'$ so that they are opposites of each other in the antipodal map, and am I supposed to apply the traditional isometries (translation, reflection and rotation) to the points? I don't understand this problem. How do I scan for Wireless Access Points? I would like to update VirtualBox on my 32 bit Ubuntu 15.04 machine from 4.3.26 to 4.3.28, using a Debian package I manually downloaded from . But simply double-clicking the package opens up the Software Centre which gives an error that installing it would break an existing package (the exact message was:   Breaks existing package 'virtualbox' conflict: virtualbox-4.3 ()   and it does not appear to have an option to ignore this and proceed with the installation anyway. Is there a command-line work-around this problem, perhaps? The Borel-Cantelli Lemma in  seems to be a sort of "corollary" of the .  It says:  "Let $(E_k)_{k=1}^{\infty}$ be a countable collection of measurable sets for which $\sum_{k=1}^{\infty} m(E_k) &lt; \infty$. Then almost all x $\epsilon \ \mathbb{R}$ belong to at most finitely many of the $E_k$'s"  I don't get three things:   "Then almost all x $\in \ \mathbb{R}$ belong to at most finitely many of the $E_k$'s"   What does that mean? Since the Borel-Cantelli Lemma comes after the "almost everywhere" definition, I guess: $\exists \ Z \ \subset \mathbb{R}$ s.t. $m(Z) = 0$ and $\forall x \ \in \ \mathbb{R} \setminus Z$, x belongs to $(E_{j}, E_{j+1}, E_{l}, ..., E_{m})$.   In the proof, one can see the $m(\limsup \ E_k) = 0$ part, stated as $m(\cap_{n=1}^{\infty} [\cup_{k=n}^{\infty} E_k]) = 0$. For some reason, $m(\cap_{n=1}^{\infty} [\cup_{k=n}^{\infty} E_k]) = 0$ implies that "Therefore almost all x $\in \ \mathbb{R}$ fail to belong to $\cap_{n=1}^{\infty} [\cup_{k=n}^{\infty} E_k]$ and therefore belong to at most finitely many $E_k$'s"   Okay, why? What is the contradiction if almost all $x \epsilon \ \mathbb{R}$ belong to all the $E_k$'s? Or a countably infinite subcollection?   What is the significance of this? Why not just state the Borel-Cantelli Lemma as "Let $(E_k)_{k=1}^{\infty}$ be a countable collection of measurable sets for which $\sum_{k=1}^{\infty} m(E_k) &lt; \infty$. $m(\cap_{n=1}^{\infty} [\cup_{k=n}^{\infty} E_k]) = 0$"? How to get client date and time in ASP.NET? Is "logicalising" a valid word? Is logicalising a valid word, if the meaning was to make something supposedly 'illogical', logical? Keep the same field headers after joining a table to a shapefile in QGIS I noticed that after joining a table to a shapefile the headers of each fields in the table used for the join are changed by QGIS and they are attributed to a different name.  For instance, I had a shapefile with vegetation_codes and a table with vegetation_codes and veg_definition (these were the headers). After joining the table to the shapefile and also saving the shapefile and creating a new one, the vegetation_classes header was changed into vegetati_1.  Is there a way to keep the original headers?  I am using QGIS Dufour on Windows 7 and the table that I join to the shapefile is CSV (tried with dbf as well and the problem is the same). Product of Consecutive Integers is Not a Power Prove that if $A$ is regular then $\operatorname{adj}(\operatorname{adj}(A)) = (\det A)^{n-2} A$ Overview of basic facts about Cauchy functional equation Volume of the torus with an integral How to find hydrogen wave-functions? I have found the hydrogen wave functions and would now like to calculate the function that describes the orbitals so that I can plot this function and see how they look.  I don't know how I can do that and it is crazy how I cannot find anything on the subject on the internet as if there was no relation between the wave functions and the orbitals.  Could you please tell me what I need to do to get a function $r(\theta,\phi)$ out of my wave functions $\psi(r,\theta,\phi)$.