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Generics and inheritance: need a complex Map instance Whence came the different varieties of the "long i" diphthong? What is the origin of “long long i” before voiced consonants (the [ai] of wide, while, &amp; tribe) versus “short long i” before unvoiced consonants (the [ʌi] of white, wife, &amp; wipe)? When did this difference appear? Is it just a secondary distinction, or are there minimal pairs for these two diphthongs?  Obviously the distinction is not present in all accents—though its presence in most leads me to believe it's not a late arrival—and yet I've never found a dictionary that distinguishes them. Are there substitutes for chain lubricant? With long journeys and particularly during winter I have noticed that the salt erodes the chain very quickly, even when I have lubricated the chain beforehand. When you are missing proper chain lubricants, what would you use as a substitute? Could you use cooking oil if you are missing the right stuff, or should I keep a small bottle of oil with me on my rides?  Related String answer1 = "yes"; if (answer1 == "yes") gives false. Why? Why is the (free) neutron lifetime so long? A neutron outside the nucleus lives for about 15 minutes and decays mainly through weak decays (beta decay). Many other weakly decaying particles decay with lifetimes between $10^{-10}$ and $10^{-12}$ seconds, which is consistent with $\alpha_W \simeq 10^{-6}$.  Why does the neutron lives so much longer than the others? Find objects between two dates MongoDB Deleted posts should not influence reputation How can I solve this quantum mechanical "paradox"? Let a (free) particle move in $[0,a]$ with cyclic boundary condition $\psi(0)=\psi(a)$. The solution of the Schrödinger-equation can be put in the form of a plane wave. In this state the standard deviation of momentum is $0$, but $\sigma_x$ must be finite. So we find that $\sigma_x\sigma_p=0$. Is something wrong with the uncertainty principle? In my preamble, you'll find:  \renewcommand{\baselinestretch}{1} \renewcommand{\familydefault}{\sfdefault} \usepackage[sfmath]{kpfonts} \usepackage[mathrmOrig]{sfmath} \usepackage{amsmath} \usepackage{amssymb} \usepackage{amsfonts} \usepackage{animate} \usepackage{anysize} \usepackage{arcs} \usepackage{array} \usepackage[scale=0]{background} \usepackage{blindtext} \usepackage{calc} \usepackage{cancel} \usepackage{chngcntr} \usepackage{CJK} \usepackage{CJKspace} \usepackage{CJKpunct} \usepackage{colortbl} \usepackage{enumitem} \usepackage{epstopdf} \usepackage{etoolbox} \usepackage{fancybox} \usepackage{fancyhdr} \usepackage{float} \usepackage{framed} \usepackage{graphicx} \usepackage{hyphenat} \usepackage{ifthen} \usepackage{latexsym} \usepackage{lmodern} \usepackage{multicol} \usepackage{multirow} \usepackage{mwe} \usepackage{pgffor} \usepackage{rotating} \usepackage{tabularx} \usepackage{textcomp} \usepackage{tgheros,tgtermes,tgcursor} \usepackage{tikz} \usepackage{times} \usepackage{tipa} \usepackage{varwidth} \usepackage{wasysym} \usepackage{wboiboites} \usepackage[abs]{overpic} \usepackage[breaklinks,colorlinks=true,linkcolor=red,citecolor=red, urlcolor=blue]{hyperref} \usepackage[framemethod=TikZ]{mdframed} \usepackage[breakable, theorems, skins]{tcolorbox,empheq} \usepackage[default]{gillius} \usepackage[document]{ragged2e} \usepackage[latin1]{inputenc} \usepackage[spanish]{babel} \usepackage[T1]{fontenc} \usepackage[total={18.59cm,26.5cm},left=1.5cm,top=2.5cm]{geometry} \usetikzlibrary{matrix,arrows, positioning,shadows,shadings,backgrounds,calc, shapes, tikzmark} \usetikzlibrary{shadows.blur} \usetikzlibrary{shapes.symbols} \usetikzlibrary{patterns,fadings} \tcbuselibrary{skins,breakable,listings,theorems}    I'm trying to draw an arrow for X axis and Y axis.   \begin{tikzpicture} \draw[yellow!10, fill=blue!5](-1, -1) rectangle (7, 5); \draw[dotted] (-0.75,-0.75) grid (6.75,4.75); \node[below] at (-0.25,0){$O$}; \draw[-&gt;,black, thick] (-0.75,0)--(6.75,0); \end{tikzpicture}   But I get this error:    Additionally, if I remove -> from the options of \draw the tikz picture compiles normally. Is there a limit to the number of Power Armor sets you can keep? I've seen videos of some folks having several armor sets (4 is the most I've seen so far) standing about on their settlement. I'm wondering if having too many would cause some sets to disappear. They're not like guns/items that you can safely store in settlement crates, the suits kind of just... stand around. (I know there's the extra step of taking out the fusion cores, so that NPC's don't use them.)  Is there a limit to the number of Power Armor sets you can keep? Can bug reports and feature requests requiring SE Dev attention be reported on per-site metas, or do they need to all go here? As we all know, air consists of many gases including oxygen and carbon dioxide. I found that carbon dioxide is heavier than O2. Does the volume difference neglect the mass difference? Is it same for all other gases in air or is there another force that keeps all of these gases together?  If I take a breath of a fresh air, will the exhaled air be heavier because of its higher CO2 content? Will it fall on the floor? Does there currently exist a free online service that accepts a file, hashes it, takes an authoritatively chosen timestamp (from one or more time services), signs these and sends this signed message back? E.g. a digital notary, but only with regards to the timestamp and not the validity of the content as legal notaries might be obligated to guarantee.  Such a service might have an extremely simple API: Simply wget http://service/&lt;checksum&gt; and receive a signed message containing one or more timestamps and the checksum. The emphasis would be on the type of authority who might make such a service.  Edit: Although the original question did not emphasise the following, the Bitcoin-based timestamping services provided below do not rely on one authority, but rather the entire Bitcoin network. They can be seen as tamper-proof and verifiable without the help of the service that helped you sign it! If $a^2+b^2+c^2=1$ then prove the following. shorter proof of generalized mediant inequality? How can I do case insensitive string comparison in Python?  I would like to encapsulate comparison of a regular strings to a repository string using in a very simple and Pythonic way. I also would like to have ability to look up values in a dict hashed by strings using regular python strings. I'm using using algorithm2e package with the following settings:  \usepackage[ruled,vlined,linesnumbered,noresetcount]{algorithm2e}   But for some subset of algorithms in the same document, I want to use this setting:  \usepackage[boxed]{algorithm2e}   Is there a way to override the default setting just for a subset?  I found a similar question:  Here newenvironment is used to override the default setting of an option. But I want to override the option itself.  I wish there was a way to load a package several times with different options for each instance. Executing Java programs through Python How do I do this? How do I get started working with JSON in Apex? Explanation of unpredictable behaviour of tee I encountered a behaviour that I don't understand while testing a script that sums the outputs from repeated executions of a program. To reproduce it create the text files out, which represents the output of my program, and sum, the file that holds the sum of the values returned on previous executions and which starts out as a copy of out,  cat &gt; out &lt;&lt; EOF 2 20 5 50 EOF cp out sum   The strange thing happens on running  paste out sum | awk '{$1 += $3; $2 += $4; NF = 2; print}' | tee sum   several times (15-20 times might be needed). Each time it runs, this command should add to the values in sum the corresponding values in out and write the results back to sum. What I get is that it works an unpredictable number of times, then sum reverts back to  2 20 5 50   I have later learned that  and solved the issue using a temporary file, still, this behaviour baffles me:   why does … | tee sum work at all (even if only for a limited number of iterations), while … &gt; sum never overwrites sum? why doesn't it work a predictable number of times?