When an article for a long time is under review ,how can we send a letter to editor for status manuscript
What should I do, as my submitted paper is still under review after 1 year?
In MTG, what happens when a player loses in multiplayer? In Magic: The Gathering, the rules for a player losing in a multiplayer game are quite complex, so I'd like to try to understand them by example. I would be happy to ask each of these situations as a separate question if that is preferred, but they all seem related, and I would love to have one place to look up all of these answers.  Let's say I'm playing with two friends, Bob and Chloe, in a simple free for all. Unfortunately, I lose. When I lose, suppose the following:   I controlled an  which has exiled Bob's , does he get his bear back? I have a  on the stack targeting Chloe, does Chloe take the 2 damage still? Earlier in the turn I cast  to prevent damage to one of Bob's . If it later takes 3 damage, will that damage be prevented? Something I controlled gave Bob a 1/1 soldier token. What happens to the token? Something Chloe controlled gave me a 1/1 soldier token. What happens to the token? I had a  enchanting one of Bob's army of . What happens to the bear? I had also played  on Bob's final . What happens to the last bear? Chloe had  my . What happens to the Clone? Are there any other situations specifically addressed by the rules? How long does it take for a black hole to form for an external observer? The well-known fable of an astronaut sending signals out to an external observer while falling toward an event horizon states that the time lapse between such signals becomes greater even if in the astronaut sends them out periodically (as judged in his inertial frame). When viewed from earth and weighing time-dilation due to the gravitational field of the collapsing star, how is it possible that a black hole can form in finite time (for any external observer) if it takes an infinite amount of time to "see" events occurring at the event horizon? Calling sleep(5); and updating text field not working Should we pass a shared_ptr by reference or by value? Marginal probability derived from joint probability distribution of a poisson process and binomial process I thought I figured out this problem, but my answer is different than the solutions manual. Hoping someone here can stear me in the correct direction:     Assume the number of automobile collisions that occur on a given stretch of highway per year is a Poisson random variable $X$ with $\mu = 20$. The probability is $p=0.05$ that there will be one or more fatalities in each accident; occurrences of fatalities are independent from one collision to the next. If $Y$ is the number of collisions with one or more fatalities on this stretch of road in one year, find the probability law for $Y$.   So as said, X is poisson, so:  $$p_X(x) = \frac{20^x}{x!}e^{-20}$$  The conditional probability of $Y$ given $X=x$ is a Binomial random variable:  $$p_{Y\mid X}(y\mid x) = \binom{x}{y}p^yq^{x-y}$$  where $Y =$ number of fatal traffic accidents and $x =$ given number of accidents (from poisson distribution)  Therefore the joint probability for $X$ and $Y$ is:  $$p_{X,Y}(x,y)= p_{Y\mid X}\cdot p_X(x) = \binom{x}{y}p^yq^{x-y}\frac{20^x}{x!} e^{-20}$$  to find the marginal probability of $Y$, I sum over $P_{X,Y}$ for all $x$:  \begin{align} p_Y(y) &amp; = \sum_{x=y}^\infty{\binom{x}{y}p^yq^{x-y}\frac{20^x}{x!}e^{-20}} = \frac{(20p)^ye^{-20}}{y!} \sum_{x=y}^\infty {20^{x-y}\frac{q^{x-y}}{(x-y)!}} \\[10pt] &amp; = \frac{(20p)^ye^{-20}}{y!} \sum_{x-y=0}^\infty {20^{x-y}\frac{q^{x-y}}{(x-y)!}} = \frac{(20p)^ye^{-20}}{y!}e^{20q} \end{align}  So:   $$p_Y(y) = \frac{(20p)^ye^{-20p}}{y!}$$  however, the correct answer is apparently $p_Y(y)=\dfrac{e^{-1}}{y!}$ pgfplots: Clipping Everything Outside a Specific Area I want to add information to each column of a histogram. every node near coord is probably the best approach. It works well with bar plots but not with the histogram:  \documentclass{article}  \usepackage{pgfplots} \pgfplotsset{compat=newest} \usetikzlibrary{pgfplots.statistics}  \begin{document}  \begin{tikzpicture} \begin{axis}[ ybar interval, xticklabel=\pgfmathprintnumber\tick--\pgfmathprintnumber\nexttick, % Code to generate labels nodes near coords={ \pgfmathprintnumber{\pgfkeysvalueof{/data point/y}} }, every node near coord/.style={ anchor=south,xshift=9mm, }, % ] \addplot+[hist={bins=3}] table[row sep=\\,y index=0] { data\\ 1\\ 2\\ 1\\ 5\\ 4\\ 10\\ 7\\ 10\\ 9\\ 8\\ 9\\ 9\\ }; \end{axis} \end{tikzpicture}  \end{document}   I used every node near coord/.style to shift the labels.  The problem is that I have four labels for three columns/bars:    I addition I would like to center the labels. A workaround will be a manual adjustment (every node near coord/.style) just like in the shown example.  Update  Maybe clipping is a possibility. Is there a way to clip the labels (in this case the 7 in the right) away?  Like this: I've created a Lightning component to view key details for the Account and Contact lookups from a Case, like so:    The problem is, I have been unable to get field content to render when  using the &lt;force:inputField/&gt; or &lt;force:outputField/&gt; components when I place them inside the markup to style them as cards. I've used &lt;ui:outputText/&gt; as a workaround, but that means I don't get any of the built-in behaviors I would get with the &lt;force:*Field/&gt; components -- like Lightning styling, which means I have to manually do it using SLDS.  This displays the contact name as expected:  &lt;aura:component implements="flexipage:availableForRecordHome,force:hasRecordId" access="global" controller="LightningCaseTestController"&gt;   &lt;aura:handler name="init" value="{!this}" action="{!c.doInit}" /&gt;   &lt;aura:attribute name="recordId" type="Id" /&gt;   &lt;aura:attribute name="contact" type="Contact" default="{sobjectType: 'Contact'}"/&gt;    &lt;force:outputField value="{!v.contact.Name}"/&gt;   &lt;force:inputField value="{!v.contact.Name}"/&gt;  &lt;/aura:component&gt;   This does not:  &lt;aura:component implements="flexipage:availableForRecordHome,force:hasRecordId" access="global" controller="LightningCaseTestController"&gt;   &lt;aura:handler name="init" value="{!this}" action="{!c.doInit}" /&gt;   &lt;aura:attribute name="recordId" type="Id" /&gt;   &lt;aura:attribute name="contact" type="Contact" default="{sobjectType: 'Contact'}"/&gt;    &lt;article&gt;     &lt;force:outputField value="{!v.contact.Name}"/&gt;     &lt;force:inputField value="{!v.contact.Name}"/&gt;   &lt;/article&gt;  &lt;/aura:component&gt;   Basically, it appears that as soon as any markup is placed around the &lt;force:*Field/&gt; tags -- even just a &lt;div&gt; -- they no longer render. Examples in Trailhead and other places all seem to use &lt;ui:outputText/&gt; or &lt;ui:input*/&gt;.  This seems like a lot of extra manual work. Am I missing something?  Update: it only fails when the component is included in a Lightning page -- such as the record detail page -- from Lightning App Builder. If I add it to a simple Lightning app, it works:  &lt;aura:application &gt;     &lt;c:LightningCaseTest recordId="SOMECASEID" /&gt; &lt;/aura:application&gt;   So it appears to be a bug? What packages will let me use Cyrillic characters in math mode? Note I'm not actually planning on writing any, for instance, Russian prose or even any Russian words. It's just that, on paper, I've always had the habit of denoting sets by uppercase roman letters, sets of sets by script letters and, when the need arises, sets of sets of sets by uppercase Cyrillic letters. Is there some package I can load which will allow me to typeset (in LaTeX math mode) Cyrillic letters much as I would typeset Greek letters? ie. $\Zhe$ to produce an uppercase zhe. Thanks! If the magnetic field doesn't polarize does it follow the electric field path of propagation? or does it vanish? Laptop (Asus x555u) screen turns off as soon as you remove the power cord Multi-partition multi OS bootable USB I want to create a recovery flash drive. I have my 8 gb flash drive[Kingston data traveller] with me. I also have the required .iso files for a>Ubuntu 13.10 b>Boot-repair disk c>AVG Rescue CD  I Wish to create 4 partitions(3 for each bootable .iso and one for data storage. Also, I want a way in which I can select which OS to boot each time I boot from USB.   So, is there a way to install GRUB on USB as well as the three other live distros? And how to create such a setup? nodejs vs node on ubuntu 12.04 Taylor's polynomial uniqueness proof - why are these limits inferable? So I'm viewing a short proof on the uniqueness of Taylor polynomials.     Uniqueness of Taylor polynomial:   Let $f:]a,b,[ \rightarrow \mathbb{R}$ $n$ times continuously   differentiable and $x_0 \in ]a,b,[$. If $p$ is $n$th degree polynomial   function for which       $$f(x)-p(x)=o(|x-x_0|^n), \space \text{when} \space x \rightarrow x_0$$  then      $$p(x)=T_{n, x_0} f(x)$$   Proof starts like:  $$\frac{p(x)-T_{n, x_0}f(x)}{(x-x_0)^n} = \frac{p(x)-f(x)}{(x-x_0)^n}+\frac{f(x)-T_{n, x_0}f(x)}{(x-x_0)^n}$$  then   $$\frac{p(x)-f(x)}{(x-x_0)^n} \rightarrow 0 \space, when \space x-x_0 \rightarrow 0$$  $$\frac{f(x)-T_{n, x_0}f(x)}{(x-x_0)^n} \rightarrow 0 \space, when \space x-x_0 \rightarrow 0$$  Now my problem is, how can one actually say that the above approach $0$ if the denominator approaches $0$? Saving Mathematica kernel state? How to use an item in my off-hand? I'm looking to download and install the latest version of Ubuntu to replace the current version of Windows I had pre-installed on my machine when bought it.   I have some really neat features on the machine that I really am hoping will still work when I move over to Ubuntu.  Can someone please confirm if the below will still work and, if not, how I can get them to work:   The USB ports on my machine The ethernet or Network work port on the machine The HDMI output on the machine and finally, the built in webcam   Thanks Sam If my data is overdispersed when binomial but not when Poisson does that alone mean I should use Poisson GLM? Top is Poisson, bottom is Binomial Source of variation is different people observed over a week long period. 118 people to be exact.  want to make predictions about the proportion of days/week one exercises if they wake up at a given time.  &gt; summary(FMR7)  Call: glm(formula = No.Days.Ex ~ WaketimeStand, family = poisson, data = PSD)  Deviance Residuals:       Min        1Q    Median        3Q       Max   -2.99043  -0.64677  -0.03492   0.67393   1.51943    Coefficients:               Estimate Std. Error z value Pr(&gt;|z|)     (Intercept)    1.36991    0.04689  29.218   &lt;2e-16 *** WaketimeStand -0.08309    0.04806  -1.729   0.0839 .   --- Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1  (Dispersion parameter for poisson family taken to be 1)      Null deviance: 124.55  on 115  degrees of freedom Residual deviance: 121.51  on 114  degrees of freedom AIC: 479.71  Number of Fisher Scoring iterations: 4  &gt; summary(FMR6)  Call: glm(formula = cbind(No.Days.Ex, No.Days.NotEx) ~ WaketimeStand,      family = quasibinomial(link = logit), data = PSD)  Deviance Residuals:      Min       1Q   Median       3Q      Max   -3.7483  -0.9585  -0.0625   1.0428   2.9739    Coefficients:               Estimate Std. Error t value Pr(&gt;|t|)   (Intercept)     0.2595     0.1009   2.571   0.0114 * WaketimeStand  -0.1869     0.1020  -1.832   0.0695 . --- Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1  (Dispersion parameter for quasibinomial family taken to be 2.015388)      Null deviance: 288.42  on 115  degrees of freedom Residual deviance: 281.57  on 114  degrees of freedom AIC: NA  Number of Fisher Scoring iterations: 4  Quite clear that there is much more overdispersion on the quasibinomial than the poisson. The response variable is no.days exercise per week and so my original thought was to analyse with binomial GLM as it is the proportion of days in a week someone exercises. However, when modelled with a Poisson GLM it is much less overdispersed. Is this a sign I am using the wrong distribution. Show the Euclidean metric and maximum metric are strongly equivalent. I need to show that the Euclidean metric and maximum metric (or square metric??) are strongly equivalent. I have no idea how to start this proof. Any help?  $d_1, d_2$ are called strongly equivalent if there exist positive constants $K, M$ such that for all $x, y\in X$: $Md_1(x,y)\leq d_2(x,y)\leq Kd_1(x,y)$ Strange problem with BibTeX sorting How to delete a Test Class WITHOUT using eclipse I cannot install Eclipse, even if I wanted to.  It is not approved software for my org.  How can test classes be deleted from production, using deployments? There no 'active' checkbox when I am editing the classes in sandbox mode, so I can't just deactivate the test class, and i cant deploy a deleted class to prod...  how the heck is this done?  I dont want to use ANT or special software.  SF must have a native way to achieve this.  And if not...  then I am very disappointed in humanity.