Installing SQL Server - HDD vs SSD?
SSD for production database
Is a visa to Poland required for a Russian spouse of a Polish citizen? I am a holder of a Russian passport and my husband is a Polish citizen. We both live and work in the UK. I have received my family member of EEA national card, good for 5 years. We would like to travel to Poland together. On the website of the Polish embassy it clearly states that if we are traveling together, I do not require a visa, however in the embassy they were sure that I do need a visa. Could anyone please clarify? Why does $x$ divided by zero not equal $x$? After all, $x$ is not being divided by anything. Sum of indepedent random variables and a constant What's wrong with this Wheatstone bridge? I was trying to solve this unbalanced Wheatstone bridge and found that the current $i$ in the mid wire is 9A .This result was achieved by using node voltage method.    Then I rearranged the same circuit to the form shown in the second image.  and at this point I flipped the right half of the circuit so as to obtain the equal resistors on the same side.    now I again rearranged the circuit as shown.    Here, the final circuit  is a balanced Wheatstone bridge and thus the current i must be 0.  So clearly something went wrong in there.  I saw a post  before this one just to make sure that there is no mistake in rearranging the circuit in the way I have done.   It was answered by the user PhillipWood as being correct and was unfortunately put on hold.  So can someone please point out what exactly went wrong with the above method. how to prove $\mathbb Z_n$ has divisors of zero if and only if $n$ is not prime A non-zero number $a \in \mathbb Z_n$ is called a divisor of zero if there is a non-zero number $b \in \mathbb Z_n$ such that $ab\equiv 0\pmod n.$  How can I prove $\mathbb Z_n$ has divisors of zero if and only if $n$ is not prime.  I filled out the addition and multiplication tables for modulo 6 and 7 and tried to find out the relation, and it's definitely true. I know I need to prove it in both directions since it is an 'iff' question. But I still don't get it. Eclipse doesn't start on Ubuntu 18.04 I installed eclipse via Ubuntu Software. When I start it, it take some seconds and then comes an error window showing the path of the error.  The following is the .log file:  !SESSION Wed May 02 12:53:28 BRT 2018 ------------------------------------------ !ENTRY org.eclipse.equinox.launcher 4 0 2018-05-02 12:53:28.587 !MESSAGE Exception launching the Eclipse Platform: !STACK java.lang.ClassNotFoundException: org.eclipse.core.runtime.adaptor.EclipseStarter     at java.base/java.net.URLClassLoader.findClass(URLClassLoader.java:466)     at java.base/java.lang.ClassLoader.loadClass(ClassLoader.java:566)     at java.base/java.lang.ClassLoader.loadClass(ClassLoader.java:499)     at org.eclipse.equinox.launcher.Main.invokeFramework(Main.java:626)     at org.eclipse.equinox.launcher.Main.basicRun(Main.java:584)     at org.eclipse.equinox.launcher.Main.run(Main.java:1438)     at org.eclipse.equinox.launcher.Main.main(Main.java:1414)   What is the problem and how can I fix it? Compute: $\lim_{x\to 0}\frac{\sqrt[m]{\cos(\alpha x)}-\sqrt[n]{\cos{(\beta x)}}}{x^2},\;m,n\in\mathbb N,\alpha,\beta\in\mathbb R$ Compute: $$\lim_{x\to 0}\frac{\sqrt[m]{\cos(\alpha  x)}-\sqrt[n]{\cos{(\beta x)}}}{x^2},\;m,n\in\mathbb N,\alpha,\beta\in\mathbb R$$   My attempt:  $$L=\lim_{x\to 0}\frac{\sqrt[m]{\cos(\alpha x)}-\sqrt[n]{\cos{(\beta x)}}}{x^2}=\lim_{x\to 0}\frac{\sqrt[m]{\cos(\alpha x)}-1+1-\sqrt[n]{\cos(\beta x)}}{x^2}\\\displaystyle=\lim_{x\to 0}\frac{\left(1+(\cos(\alpha x)-1)\right)^{\frac{1}{m}}-1-\left(\left(1+(\cos(\beta x)-1)\right)^{\frac{1}{n}}-1\right)}{x^2}$$  Transformed expression: $$-\frac{(1+(\cos(\alpha x)-1))^{\frac{1}{m}}-1}{\cos(\alpha x)-1}\cdot\frac{1-\cos(\alpha x)}{\alpha^2x^2}\alpha^2+\frac{(1+(\cos(\beta x)-1))^{\frac{1}{n}}-1}{\cos(\beta x)-1}\cdot\frac{1-\cos(\beta x)}{\beta^2x^2}\beta^2$$  I applied the standard limits from the table: $$\lim_{x\to 0}\frac{(1+x)^a-1}{x}=a\;\&amp;\;\lim_{x\to 0}\frac{1-\cos x}{x^2}=\frac{1}{2}$$ $$L=-\frac{1}{m}\cdot\frac{1}{2}\alpha^2+\frac{1}{n}\cdot\frac{1}{2}\beta^2=\frac{m\beta^2-n\alpha^2}{2mn}$$ Is this correct? Is there a difference between Therefor and Therefore? Do I have to code each case of this Grid full of plots separately? Referencing equation counter value in custom float caption I have used the float package to create an equation float, eqfloat, so I can add captions to equations. Within the eqfloat I used the equation environment to typeset the math.  I want to keep the right hand arabic numbering within parentheses that is added by the equation environment but I also would like the eqfloat caption below the equation to use the same number as the equation environment.  The following code achieves this by making the eqfloat use the same counter as the equation environment and then manually adjusting the equation numbering within each eqfloat.   Is there a better way to make the eqfloat caption reference the current value of the equation environment counter?  Is it possible to prevent the custom float environment from increasing the counter and only to reference the current value of the equation counter?  \documentclass[a4paper]{article}  \usepackage[margin=25pt, labelfont=bf]{caption} \usepackage{amsmath, amsfonts, pifont, float, color, url} \usepackage[pdftex, plainpages=false, pdfpagelabels, bookmarks=true]{hyperref}  \newfloat{eqfloat}{h}{eqflts} \floatname{eqfloat}{Equation} \makeatletter \let\c@eqfloat\c@equation \makeatother  \begin{document}     ...     \begin{eqfloat}         \begin{equation}             E = mc^2         \end{equation}         \addtocounter{equation}{-1}         \caption{Equation caption here.}         \label{eq:example}     \end{eqfloat}  \end{document} Is there a way to preserve a weapon in Magicka within a saved multiplayer game Turning vector grid into individual shapefiles using QGIS? I am using QGIS and I created a vector grid on a crop field in order to cut it into plots. I want to save each grid cell into individual polygon shapefiles automatically.  Here is an example of a vector grid I would like to split into 117 shapefiles:    Eventually, I did it manually with the selection tool and "Save as" but it is really time-consuming when there are more than 100 plots to save.    Is there any way to do it faster and more automatically?  Each plot as an attribute named "Plot" that can discriminate against them (basically being id + 1). It's the attribute used here to label them. Problems with # inside a verbatim that's inside a note I'm trying to use a # character inside a verbatim that's inside a note :   \begin{frame}[fragile]  \note{\begin{verbatim}  # \end{verbatim} }  \end{frame}   This produces the following errror :   >   ! Illegal parameter number in definition of \beamer@todo. >    to be read again>  >                     >   l.5 }   How can I write the # character in a way that doesn't break the latex compilation ?  Thanks in advanced,  PS : This is related to the following problem in pandoc : Validation Error less than training error? I found two questions  and  about this issue but there is no obvious answer or explanation yet.I enforce the same problem where the validation error is less than training error in my Convolution Neural Network. What does that mean? I want to prove  \begin{equation*} \tan A  + \tan B + \tan C = \tan A\tan B\tan C \quad\text{when } A+B+C = 180^\circ \end{equation*}  We know that   \begin{equation*} \tan(A+B) = \frac{\tan A+\tan B}{1-\tan A\tan B}~\text{and that}~A+B = 180^\circ-C. \end{equation*}  Therefore $\tan(A+B) = -\tan C.$ From here, I get stuck. Please help. Lagrange Multipler KKT condition I am looking at SVM, and reviewing Lagrange multiplier. Let's say with the constraint function $$g(x,y) = x^2 + y^2 -1 &gt; 0, $$ I am maximizing $$f(x,y) = x + y -1 .$$ Intuitively, since the constraint function does not provide a finite constrained region, there is no solution, and $f(x,y)$ can infinitely increase.  However, if I just plainly proceed with Lagrange multiplier calculation,  $$L(x,\lambda) = (x + y -1) +\lambda(x^2 + y^2 -1)$$ I get the solution: $$y,x = -\sqrt{2}/2, \lambda = 1/\sqrt{2}$$ And this still satisfies KKT conditions although the solution is wrong.  $$g(x) =&gt; 0 , \lambda =&gt;      0, \lambda g(x) = 0.$$  I expected that I would have some result that conflicted KKT conditions, but nothing was violated.   Does this mean that Lagrange multiplier under KKT conditions can produce a solution that cannot be solved, without giving any indication of intractability?  If functions are complicated, what's the systematic way to confirm that the optimization with inequality constraint functions is solvable using Lagrange multiplier? Yesterday I read Modern English:A Practical Reference Guide written by Marcella Frank, and she gives a paradigm about tenses on page 50. The page shows tenses in active voice and passive voice; she said these four tenses are exceedingly rare:   shall/will be being offered has/have been being offered had been being offered shall/will have been being offered   Why are these tense so rare? Are they normally replaced by other tenses? MAXDOP not working? I wanted to test out MAXDOP on my computer. So I set MAXDOP to 2 for a specific query. However, when I looked at my logical processors in Task Manager as I ran the query, it looked like they were all being used. I thought that it would only be using 2 logical processors if MAXDOP was set to 2? Does anyone know what is happening? Please see image below.  Another issue is, the DOP returned by the execution plan said 1. Now I know that setting MAXDOP does not mean SQL Server will actually use the number set. However, given that it seemed all my 4 logical processors were being used to process the query, it made it even more strange to see DOP 1.  This is the query I ran:   This was what happened as I ran it (i.e. it looks like all 4 logical processors are being used to run the query): Citing a range of papers using numeric keys as in \cite{a, b, c} -> [1-3] How can I cite a range of papers, the output is a range of numbers, instead of a list of numbers? In other words, when I type  ... some dummy text here is due to me \cite{me1, me2, me3, me4} ...   I want the output to be     ... some dummy text here is due to me [3-6] ...   instead of     ... some dummy text here is due to me [3.4.5.6] ...   (I use LaTeX, and am currently using the amsart class and whatever it includes. But I am open to other suggestions.) I typed up an assignment with a lot of numbers in LaTeX and turned it in to my adviser.  When he returned it to me with some corrections, one of which was a lot of $ around my numbers.  I understand that $ are necessary around some mathematical formulas, but I was just using numbers like -2 and 4.  I did not see any change in the font of the numbers when I added the $ either.  Since my adviser did not want to give me an explanation, what is the rationale?