Methode specialization with two arguments in
C++ single template specialisation with multiple template parameters
Make Chrome always execute with flags, for eg., directly opening an HTML file I want to run Chrome with a given set of flags, always  I created a shortcut and added the flag to it in the following way, so my target of the shortcut says:  C:\&lt;application-path&gt;\chrome.exe --user-data-dir=D:\Chrome   But when I double click an HTML file, or if any other application triggers Chrome, it looses the flag value. The result - A new chrome window opens with Default profile directory.  I want to make the flag permanent, so that its active irrespective of however Chrome executes.  I tried changing the following registry key:  HKEY_CLASSES_ROOT\ChromeHTML\shell\open\command   It was this earlier:  "C:\&lt;application-path&gt;\chrome.exe" -- "%1"    I changed to following attempts which did not work:  1. "C:\&lt;application-path&gt;\chrome.exe" -- "%1" --user-data-dir=D:\Chrome 2. "C:\&lt;application-path&gt;\chrome.exe" -- "%1" -- "user-data-dir=D:\Chrome" 3. "C:\&lt;application-path&gt;\chrome.exe" -- "%1 user-data-dir=D:\Chrome"   Conclusively, when I try to open a link from any application, it doesn't open in my current Chrome as a new tab, rather opens a new Chrome window with no plugins and extensions since its from other directory.  Why I have changed my default directory? - because the OS drive was getting low on memory due to heave Chrome caches and apps. Since when did kidnapping come to include adults too? As per , the word 'kidnap' originated to denote nabbing away of a child. When and how did kidnap come to denote nabbing of adults?  Update: Just found a link to a  that mentions kidnapping of souls. Now not sure how correct the above link is. SQLiteException while inserting values in the database in Android This question exists because it has historical significance, but it is not considered a good, on-topic question for this site, so please do not use it as evidence that you can ask similar questions here. See  for more information.   This is a community wiki for IDEs available on Ubuntu. Please post one IDE per answer (including more than just a screenshot or a link, please at least put a short description).  In your answer, tell us what the IDE is for (which language(s) or if it is RAD capable). Prove that $\left| f'(x)\right| \leq \sqrt{2AC}$ using integration Suppose that $f(x)$ is a $C^2$ function on $\mathbb{R}$ such that $\left| f(x) \right| \leq A$ and $\left| f''(x) \right| \leq C $ for $x \in \mathbb{R}$. Prove that $\left| f'(x)\right| \leq \sqrt{2AC}$. Determining the name of the VMware host of a VM guest - from the guest Is it possible to determine the name of the VMware host (ESX or ESXi) that my guest resides in, from within the guest itself?  I would expect this to be possible via VMware Tools, but am not sure where to look. Is there a noun for something that is "out of place" in space, like an anachronism is "out of place" in time? E.g., an old-timey barber shop in a chic neighborhood. How can I find all files that do NOT contain a text string? What concise command can I use to find all files that do NOT contain a text string?  I tried this (using -v to invert grep's parameters) with no luck:  find . -exec grep -v -l shared.php {} \;   Someone said this would work:  find . ! -exec grep -l shared.php {} \;   But it does not seem to work for me.   has this example:  find ./logs -size +1c  &gt; t._tmp while read filename do      grep -q "Process Complete" $filename      if [ $? -ne 0 ] ; then              echo $filename      fi done &lt; t._tmp rm -f t_tmp   But that's cumbersome and not at all concise.  ps: I know that grep -L * will do this, but how can I use the find command in combination with grep to excluded files is what I really want to know.  pss: Also I'm not sure how to have grep include subdirectories with the grep -L * syntax, but I still want to know how to use it with find :) I've been asked the following question:  What five odd integers from the set  $\{1, 3, 5, 7, 9, 11, 13, 15\}$ that when summed together equals to $30$? Note that any integer can be used more than once.   If my limited knowledge of maths is correct, there should be no answer, as no odd number of odd integers summed together can give an even number. What is a simple way to create a binary relation symbol on top of another? What is a simple way to have \ll on top of \gg with equal size and vertically center aligned and have them work as a binary relation symbol like \lessgtr? The commands \underset and \overset cannot be used because they do not treat the two symbols equally, and they do not vertically center. Bash is not finding a program even though it's on my path Rendering of Favorite/Ignored Tags in Firefox Sort lines based on a variable-width number at a fixed position Disable Mac startup sound Anyone know how to disable that cheesy startup sound when I power on my Mac?  If it makes a difference, I'm running Mac OS X 10.6. Why don't virtual particles violate conservation of mass/energy? Ubuntu 14.04 LTS live USB boot error (gfxboot.c32:not a valid COM32R image) How can I invest in country A to take advantage of their great interest rate while I live in country B? If I live in the US, for example, where current interest rates are practically nil, how can I take advantage of the fact that ? Equivalent conditions for a preabelian category to be abelian Let's fix some terminology first. A category $\mathcal{C}$ is preabelian if:  1) $Hom_{\mathcal{C}}(A,B)$ is an abelian group for every $A,B$ such that composition is biadditive,  2) $\mathcal{C}$ has a zero object,  3) $\mathcal{C}$ has binary products,  4) $\mathcal{C}$ has kernels and cokernels.  A category $\mathcal{C}$ is abelian if it is preabelian and satisfies:  5) every monomorphism is a kernel and every epimorphism is a cokernel.  Define the coimage of a map to be the cokernel of its kernel, and the image to be the kernel of its cokernel. We have the following commutative diagram:    where $\overline{f}$ is the only existing map (because of universality of kernel and cokernel).  I'm having trouble proving the following:     A preabelian category $\mathcal{C}$ is abelian iff $\overline{f}$ is an isomorphism.   The converse is easily shown, I'm having trouble proving $\Rightarrow$... How can I find out where an email really came from? Characterizing units in polynomial rings I am trying to prove a result, for which I have got one part, but I am not able to get the converse part.  Theorem. Let $R$ be a commutative ring with $1$. Then $f(X)=a_{0}+a_{1}X+a_{2}X^{2} + \cdots + a_{n}X^{n}$ is a unit in $R[X]$ if and only if $a_{0}$ is a unit in $R$ and $a_{1},a_{2},\dots,a_{n}$ are all nilpotent in $R$.  Proof. Suppose $f(X)=a_{0}+a_{1}X+\cdots +a_{n}X^{n}$ is such that $a_{0}$ is a unit in $R$ and $a_{1},a_{2}, \dots,a_{r}$ are all nilpotent in $R$. Since $R$ is commutative, we get that $a_{1}X,a_{2}X^{2},\cdots,a_{n}X^{n}$ are all nilpotent and hence also their sum is nilpotent. Let $z = \sum a_{i}X^{i}$ then $a_{0}^{-1}z$ is nilpotent and so $1+a_{0}^{-1}z$ is a unit. Thus $f(X)=a_{0}+z=a_{0} \cdot (1+a_{0}^{-1}z)$ is a unit since product of two units in $R[X]$ is a unit.   I have not been able to get the converse part and would like to see the proof for the converse part.