Zend GData Calendar: I can't use setUpdatedMin in the query
Gdata signed request error: "Unknown authorization header"
Show that if terms of a series have ratio less than the ratio of convergent series, then the series converges We have two infinite series $\sum a_n $ and $\sum b_n$, such that $a_n &gt; 0,\ b_n &gt; 0$ and $a_{n + 1}/a_n \leq b_{n + 1}/b_n$ for all $n$. Show that if $\sum b_n$ converges, then $\sum a_n$ also converges.   Any hints on how to prove this? I can sort of picture why this must be true, but I'm not sure how to prove this rigorously. I'm not sure using the ratio test would help here.. Was there any reason why Dr Soong chose for Data's eyes to be yellow?  I can understand that he wasn't going for a completely human-looking android based on his skin color, but why yellow eyes? How to SEO a Single-Page website The difference between "Older" and "Elder" What is the difference between "Older" and "Elder" ?  And are they interchangeable ? How to get all possible combinations of a list’s elements? I have a list with 15 numbers in, and I need to write some code that produces all 32,768 combinations of those numbers.   I've found  (by Googling) that apparently does what I'm looking for, but I found the code fairly opaque and am wary of using it. Plus I have a feeling there must be a more elegant solution.  The only thing that occurs to me would be to just loop through the decimal integers 1–32768 and convert those to binary, and use the binary representation as a filter to pick out the appropriate numbers.   Does anyone know of a better way? Using map(), maybe? The series $\sum_{n=2}^{\infty }\frac{1}{\log (n!)}$ I'm trying to find out whether this Series $\sum_{n=2}^{\infty } a_{n}$ converges or not when $$a_{n}=\frac{1}{\log (n!)}$$  I tried couple of methods, among them: d'Alembert $\frac{a_{n+1}}{a_{n}}$,   Cauchy condensation test $\sum_{n=2}^{\infty } 2^{n}a_{2^n}$, and they both didn't work for me.  Edit: I can't use stirling, and integral.  Thank you I don't know if it's the right place to ask but can somebody advise me for buying a ram memory for my computer.  I have a Dell Vostro 200 with 1GB of RAM and 667MHz. (2 x 512MB)  I want to buy raise the amount of RAM but I'm confused whether to buy 1 x 2GB or 2 x 1GB  I know it's the same for the available amount of memory but is ther a difference maybe in the clock speed so that 2 x 667MHz will be better than 1 x 667MHz. or maybe accessing one single memory slot will be faster and better than accessing two slots.  Please anyone helps. This is from  .      Let $\mathcal{A}$ be a locally small category, and let $A,A' \in \mathcal{A}$ with $\operatorname{Hom}(-,A) \cong \operatorname{Hom}(-,A')$. Prove directly that $A \cong A'$.     My thoughts:      Let $\eta$ denote the natural isomoprhism between the two functors.    We have    $$H(A,A) \xrightarrow{ \eta_A} H(A,A')$$   So $\eta_A(id_A): A \rightarrow A'$ is a candidate. Now I want to construct inverse.    $$ H(A',A') \xrightarrow{\eta_{A'}} H(A',A)$$   Then the map $\eta^{-1}_{A'} (id_{A'}):A' \rightarrow A$.    So I'd like to show that the composition is identity. By the naturality condition of $\eta$, from $H_A(A) \rightarrow H_{A'}(A')$ (and similarly on other direction)    $$ \eta_A(id_A) \circ \eta^{-1}_{A'}(id_{A'}) = \eta_{A'}(\eta_{A'}^{-1}(id_{A'}))= id_{A'} $$   We deduce these two maps are inverses. Hence $A' \cong A$.    Is this correct? Or is there a neat way to see this? How do I allow a non-default user to use serial device ttyUSB0? I have an Ubuntu 11.10 system with 2 users:   The first was created during the installation The second instead was created after. It belongs to the sudoers group.   Now the problem is that when the second tries to use a device ttyUSB0 the following error is returned:  "Could not open serial port /dev/ttyUSB0"   I was able to fix it by using:  sudo chown :second_user /dev/ttyUSB0   However when I disconnect the device and reconnect it the problem comes back.  Is there a way to allow different users to access the devices? I suppose I have to add the user to a specific group. Currently the owner is root and the group is dialout. However I'm not sure about the group and I don't know how to add the user.  Thanks! Clip for each feature I want to clip a polyline feature class by a polygon feature class (buffers created from points). Several polygons overlap, so I want to get each polygon feature clipped with each polyline feature.  Using the Clip_analysis tool, I get the orange lines:   whereas I want the following red lines:    In a python script, I tried the following code to clip every polyline with each polygon:          temp = arcpy.ValidateTableName("clip_temp")     bufferCursor = arcpy.SearchCursor(buffer)     n = 0     for pRow in bufferCursor:         arcpy.AddMessage(n)         feat = pRow.Shape         arcpy.Clip_analysis(inputPolylineLayer, feat, temp, "#")         if n == 0:             arcpy.Copy_management(temp, clip)         else:             arcpy.Append_management(temp, clip)         n=n+1   But the execution is very very slow and it crashes before finishing.  I also tried the Intersect_analysis tool but I didn't get the right geometries:   Do you have any idea of a better methods to do it? Why do we have an elementary charge $e$ in physics but no elementary mass? Is an elementary mass ruled out by experiment or is an elementary mass forbidden by some theoretical reason? In , it is established that Thieves' Cant is more of an encoding system built on top of a language than a language in its own right. According to the Basic Rules,  is:  ...a secret mix of dialect, jargon and code allows you to hide messages in seemingly normal conversation. Only another creature that knows thieves' cant understands such messages. It takes four times longer to convey such a message than it does to speak the same idea plainly. In addition, you understand a set of secret signs and symbols used to convey short, simple messages, such as whether an area is dangerous or the territory of a thieves' guild, whether loot is nearby, or whether the people in an area are easy marks or will provide a safe house for thieves on the run. (PBR, p. 27)  Can two creatures communicate using Thieves' Cant if they do not have a basic spoken language in common, or if they are speaking different basic languages? E.g. if one creature knows Orcish, Goblin, and Thieves' Cant, and another creature knows Elvish, Giant, Common, and Thieves' Cant, can they communicate with each other by embedding Thieves' Cant into their own languages? Hypothetically speaking, I can see how this could be possible in our own world, if we assume that Thieves' Cant depends on nuances of body language, emphasis, and tempo, e.g., one might say to a non-Spanish speaker:  Tenemos quEEEEEEE ir (wink) a la tieeeeenda de (shuffle left foot) armas para (twirl hair and giggle) comprar una espada (wink twice) para mi herMANO (wag right pinky and nod).  The literal message itself (&quot;We need to go to the weapon store to buy a sword for my brother.&quot;) would just be a carrier - the real message might be hidden within the gestures and the accented and extended syllables. Perhaps the drawn-out &quot;E&quot; vowel means &quot;robbery planned&quot;, the wink means &quot;bank&quot;, shuffling the left foot means &quot;be there at sunset&quot;, etc., and these are things that you wouldn't necessarily need to know Spanish to extract. Is this how Thieves' Cant actually works, or does it require actual comprehension of the literal message transmitted before the &quot;secret&quot; message can be extracted from it? Temporarily suspend bash_history on a given shell? Is there a way to temporarily suspend history tracking in bash, so as to enter a sort of "incognito" mode? I'm entering stuff into my terminal that I don't want recorded, sensitive financial info. How to easily map c++ enums to strings When can a noun be used attributively? Nouns can modify nouns: cat food, coffee cup, gold ring, laser surgery, flood insurance. It seems to me there are even cases where a noun sounds better than the corresponding adjective: sociology papers sounds a bit better than sociological papers.  Some noun-noun combinations don&rsquo;t work. You wouldn't say America gangsters or measurement spoons or greed crimes. If you spilled water on your keyboard you probably wouldn't call it a keyboard spill or even a water spill.  Are there rules that tell which combinations are acceptable? How to play DVDs in Ubuntu 16.04? Ruby -- capitalize first letter of every sentence in a paragraph I'm trying to typeset some python code, and I would like integer literals to be highlighted. I've come up, after about two hours of fighting with the documentation and various other questions here and on SO, with the following:  \lstset{ %     language=Python,     otherkeywords={1, 2, 3, 4, 5, 6, 7, 8, 9, 0},     morekeywords=[2]{1, 2, 3, 4, 5, 6, 7, 8, 9, 0},     keywordstyle=[2]{\color{orange}},     keywordstyle=\color{blue}\bfseries,     stringstyle=\color{red}, }   Unfortunately, that doesn't work. Numbers found in strings are also highlighted, which is rather annoying, and not only are they highlighted: they are highlighted in blue. Numerals in regular program text, on the other hand, are rightly highlighted in red.  Help?  EDIT: Thanks Peter Grill for your very nice solution. Is there a way to not break string colouring, though? When I use you code, the stringstyle=\color{red} doesn't seem to work anymore (strings are just plain black). Similarly, comments can be enclosed in triple quotes in python, and if I adapt your quote to detect """ blocks, then the corresponding  comments are not highlighted anymore. I know that we shouldn't being using the registry to store Application Data anymore, but in updating a Legacy application (and wanting to do the fewest changes), what Registry Hives are non-administrators allowed to use?    Can I access all of HKEY_CURRENT_USER (the application currently access HKEY_LOCAL_MACHINE) without Administrator privileges? remove isp-provided dns My isp provides a dns service; but unfortunately they do block certain sites. I would like to use opendns or google; but it seems like it doesn't work.    I have set up a wired connection; given a manual ip and entered opendns-ip's in the nameserver field (all through the gui). Still url's are being resolved through my ISP. I have tried to configure the same on my girlfriends laptop (win 7) and I also can't seem to do the setup. My previous computer also was a win 7 and had no problem. (so I believe the problem is 'me') If it were only one site, i could edit the hosts file; but I prefere to circumvent their whole dns server.  Is there something an isp can do to block the use of other dns-servers than theirs? Is it possible to re-route the ISP dns to the opendns?