Increasing each subplot's size and adjusting their width, matplotlib
How do you change the size of figures drawn with Matplotlib?
Calculator Program improvements I'm pretty new to programming and made a few programs so far. I recently made a Calculator program and I hope you guys could tell me what I could do to improve. int firstNumber; string sign; int secondNumber; int answer;  Console.WriteLine(&quot;Input Number:&quot;); firstNumber = Convert.ToInt32(Console.ReadLine()); Console.Clear();  Console.WriteLine(&quot;Input Sign:&quot;); sign = Console.ReadLine(); Console.Clear();  Console.WriteLine(&quot;Input Second Number:&quot;); secondNumber = Convert.ToInt32(Console.ReadLine()); Console.Clear();  switch (sign) {     case &quot;+&quot;:         answer = firstNumber + secondNumber;         Console.WriteLine(answer);         Console.ReadKey();     break;     case &quot;-&quot;:         answer = firstNumber - secondNumber;         Console.WriteLine(answer);         Console.ReadKey();     break;     case &quot;*&quot;:         answer = firstNumber * secondNumber;         Console.WriteLine(answer);         Console.ReadKey();     break;     case &quot;/&quot;:         answer = firstNumber / secondNumber;         Console.WriteLine(answer);         Console.ReadKey();     break;     default:         Console.WriteLine(&quot;Invalid Input&quot;);     break; } Calculate sums of inverses of binomial coefficients How to calculate the sum of sequence $$\frac{1}{\binom{n}{1}}+\frac{1}{\binom{n}{2}}+\frac{1}{\binom{n}{3}}+\cdots+\frac{1}{\binom{n}{n}}=？$$ How about its limit? Show $\lim_{n \to \infty} n^{-1} E \left( \frac{1}{X}1_{[X>n^{-1}]} \right) =0$ Suppose $X$ is a non-negative random variable satisfying  \begin{align*} P[0 \le X &lt; \infty ]=1. \end{align*} Show   a)  \begin{align*} \lim_{n \to \infty} n E \left( \frac{1}{X}1_{[X&gt;n]} \right) =0 \end{align*} b)  \begin{align*} \lim_{n \to \infty} n^{-1} E \left( \frac{1}{X}1_{[X&gt;n^{-1}]} \right) =0 \end{align*}  What I did  I showed part a) already here is the proof:  \begin{align*} n E \left( \frac{1}{X}1_{[X&gt;n]} \right) \le n E \left( \frac{1}{n}1_{[X&gt;n]} \right)=n\cdot\frac{1}{n}P[X&gt;n]=P[X&gt;n] \end{align*} So $\lim_{n \to \infty} n E \left( \frac{1}{X}1_{[X&gt;n]} \right) \le \lim_{n \to \infty} P[X&gt;n]=0$.  What about part b)? The same techniques no longer works.  I was thinking that  \begin{align*} \lim_{n \to \infty} n E \left( \frac{1}{X}1_{[X&gt;n]} \right) \le \lim_{n \to \infty} n E \left( \frac{1}{X} \right) \le 0 \end{align*} but I am not sure that $E \left( \frac{1}{X} \right) &lt; \infty$ Why don't the Ubuntu repositories have the latest versions of software? Why are packages in the official Ubuntu repositories older than the latest (upstream) versions from Debian Sid, PPAs, the authors, etc.? Can you end Beast Form early? Is there any way to end beast form early? I find myself using it to clear out a particularly hard portion of a dungeon at times, but then I have to sit around for 2-5 minutes so I can be my human character again (I have to feed to keep my health up, so I'm a werewolf longer than the 2.5 minutes).  Is there anyway to end it early? Google Maps API v3, jQuery UI Tabs, map not resizing Does IBIS reduce image resolution? How does it compare to lens based IS? Index with exercise numbers BasicTeX - how to identify packages that need to be added after an upgrade Unit Test - Creating Custom Metadata I have three questions that I'd like to be clarified.   Is their anyway we could create Custom Metadata in Test Classes? I tried to create on my Test Class but I got an error saying the fields of the metadata could not be writable.  If not, then does that mean we should declare real values in our Custom Metadata and use that instead in our test classes? If (2) is correct, then does this mean we have to create the Custom Metadata in the environment we'll be deploying our code before doing the actual deployment? How to read a windows registry file using java? What determines how much experience I get from a hearthstone match in play mode? Sometimes I win handily and get a little experience, sometimes I squeak out a victory and get a lot.  How is experience earned? Why didn't mastery of the Elder Wand move on from Harry? There's a lot of emphasis on Harry becoming the master of the Elder Wand after he defeats Draco. But what constitutes a “defeat”?  It seems that Harry wins a wrestling match with Draco, so now he’s the master of the Elder Wand.  But lots of other stuff happens to Harry: Nagini almost kills him, and he escapes just in time, but his wand breaks. The Snatchers chase him through the forest. He and his friends practically surrender (and Hermione even tries to disguise Harry). Voldemort almost kills Harry in the Forbidden Forest (or actually does, depending on how you look at it).  Why are none of these considered to be “defeats”? How can I automatically save screen shots by the press on the Prt Scr button? I want a screen shot to be saved automatically to a location I specify, as soon as I press the Prt Scr button on my keyboard, or the Alt+Prt Scr combo. I also want the date and time to be used as file name for each new screen shot. And I want the files to be saved as PNG images.  Is there a Windows program that would allow me to do just this? I don't want any other fancy features like editing and making notes, etc. just a plain simple program that will either automatically save the screen shots to a pre-set location or prompt me where I want to save it. I don't want to go through MS Paint to save the shots.  I guess what I'm after is a little bit of Linux behavior of Print Screen, but only for Windows. And I additionally want the files to be named by the date and time they were taken.  Update:  Meanwhile, I have found one called Greenshot. But I don't know how to get the file name pattern right.  This is the default pattern.  ${capturetime:d"yyyy-MM-dd HH_mm_ss"}-${title}   Can someone explain this? Why do they have the title capturetime and the quotation marks? It produces file names like this.  2013-01-26 15_24_28-Greenshot.png   And this is what it says about the file patterns in the program description.  ${YYYY} year, 4 digits ${MM} month, 2 digits ${DD} day, 2 digits ${hh} hour, 2 digits ${mm} minute, 2 digits ${ss} second, 2 digits ${NUM} incremental number, 6 digits ${title} Window title ${user} Windows user ${domain} Windows domain ${hostname} PC name   How do I get files that include year, month and day, separated by a dash, followed by hour, minute and second? I want to include a time for uniqueness of the file name. Edit - Original Title: Is there an alternative way to achieve border-collapse:collapse in CSS (in order to have a collapsed, rounded corner table)?  Since it turns out that simply getting the table's borders to collapse does not solve the root problem, I have updated the title to better reflect the discussion.  I am trying to make a table with rounded corners using the CSS3 border-radius property. The table styles I'm using look something like this:  table {     -moz-border-radius:10px;     -webkit-border-radius:10px;     border-radius:10px }   Here's the problem. I also want to set the border-collapse:collapse property, and when that is set border-radius no longer works. Is there a CSS-based way I can get the same effect as border-collapse:collapse without actually using it?  Edits:  I've made a simple page to demonstrate the problem  (Firefox/Safari only).  It seems that a large part of the problem is that setting the table to have rounded corners does not affect the corners of the corner td elements. If the table was all one color, this wouldn't be a problem since I could just make the top and bottom td corners rounded for the first and last row respectively. However, I am using different background colors for the table to differentiate the headings and for striping, so the inner td elements would show their rounded corners as well.  Summary of proposed solutions:  Surrounding the table with another element with round corners doesn't work because the table's square corners "bleed through."  Specifying border width to 0 doesn't collapse the table.  Bottom td corners still square after setting cellspacing to zero.  Using JavaScript instead- works by avoiding the problem.  Possible solutions:  The tables are generated in PHP, so I could just apply a different class to each of the outer th/tds and style each corner separately. I'd rather not do this, since it's not very elegant and a bit of a pain to apply to multiple tables, so please keep suggestions coming.  Possible solution 2 is to use JavaScript (jQuery, specifically) to style the corners. This solution also works, but still not quite what I'm looking for (I know I'm picky). I have two reservations:    this is a very lightweight site, and I'd like to keep JavaScript to the barest minimum  part of the appeal that using border-radius has for me is graceful degradation and progressive enhancement. By using border-radius for all rounded corners, I hope to have a consistently rounded site in CSS3-capable browsers and a consistently square site in others (I'm looking at you, IE).   I know that trying to do this with CSS3 today may seem needless, but I have my reasons. I would also like to point out that this problem is a result of the w3c specification, not poor CSS3 support, so any solution will still be relevant and useful when CSS3 has more widespread support. I have just started studying implication in mathematics. So, you'll probably have an idea of where my confusion lies right from the get go.  In the truth table, where $A \implies B$ we obtain this result:  A   B   T/F ___________ T | T | T T | F | F F | T | T F | F | T   Now, my confusion here is regarding why $A\implies B$ given A is false, and B true. The others I understand. The first and last one are obvious, the second one implies, to me anyway, that given A implies B, the truth of B rests upon the truth of A, B is false, A is True, which cannot be, thus not B given A is false.  Now... then, why is B true despite the fact that A is false? Or rather, why is the statement B given not A, True. The truth of B is implied from the truth of A, but A is a false statement. So it's very contradictory that this may be, and in fact, if you go through a real life example, you would find that the third statement seems to be false.  Say $A$ is the statement that it is dark outside, and $B$ the statement that the sun is not on our side of the earth. If it is not dark outside, than stating that the sun is on the other side of the planet must be wrong (in my example i'm going to claim that the sun is the only light source).  Side note:  I just had a thought, if A is false, does that mean you can conclude... mmm, whatever? I mean, B is implied via the truth of A, if A is false, B is NOT implied, but then B could be EITHER true or false, I suppose. Is this correct?  However, would that not mean that A does not imply anything when false. Would that not set the 3rd and 4th statement to be undefined? Conjugate class in the dihedral group List all the conjugate classes in the dihedral group of order $2n$ and verify the class equation.  The dihedral group is generated by two elements $r$ and $s$.   The order of $r$ is two since $r^2=e$ and $s$ is $n$ since $s^n = e$. And I know all elements can be produced as either $s^k$ or $rs^k$. How can I list all the conjugacy class? Prepend phone numbers with a calling card dial in number This is question 2.9 #9 from Topics in Algebra by Herstein:     If $o(G)$ is $pq$ where $p$ and $q$ are distinct prime numbers and if $G$ has a normal subgroup of order $p$ and a normal subgroup of order $q$, prove that $G$ is cyclic.   Let $N$ denote the normal subgroup of order $p$ and $M$ denote the normal subgroup of order $q$. Here are a couple things I noted while exploring the problem:   $N$ and $M$ are cyclic, since they have prime order. $G = NM$ [1].   Any hints where to look next?    [1] Since $N,M$ are normal, $NM \le G$. Then $o(NM) \mid o(G)$, so $o(NM)$ is either $1$, $p$, $q$, or $pq$. The first three don't work because they force one of $N$ or $M$ to be $(e)$, so we have $o(NM) = pq$. Therefore, $NM = G$. What is the default PATH environment variable setting on fresh install of Windows 7