How to get the Raw pixel data from CGImage
How to get pixel data from a UIImage (Cocoa Touch) or CGImage (Core Graphics)?
There is a way to add custom split normal use Python API? I can't find a way to achieve custom split normal effect. I want to use python (mesh normal/hard edge or soft edge) data collected from Maya then write to Blender mesh.    How to do it using the following Python API and how?  bpy.data.meshes[objName].normals_split_custom_set_from_vertices  bmesh module How to remove duplicate lines inside a text file? A huge (up to 2 GiB) text file of mine contains about 100 exact duplicates of every line in it (useless in my case, as the file is a CSV-like data table).  What I need is to remove all the repetitions while (preferably, but this can be sacrificed for a significant performance boost) maintaining the original sequence order. In the result each line is to be unique. If there were 100 equal lines (usually the duplicates are spread across the file and won't be neighbours) there is to be only one of the kind left.  I have written a program in Scala (consider it Java if you don't know about Scala) to implement this. But maybe there are faster C-written native tools able to do this faster?  UPDATE: the awk '!seen[$0]++' filename solution seemed working just fine for me as long as the files were near 2 GiB or smaller but now as I am to clean-up a 8 GiB file it doesn't work any more. It seems taking infinity on a Mac with 4 GiB RAM and a 64-bit Windows 7 PC with 4 GiB RAM and 6 GiB swap just runs out of memory. And I don't feel enthusiastic about trying it on Linux with 4 GiB RAM given this experience. Badge request: "Practically Perfect in Every Way" User suggested great corrective edit to my answer, but the edit was rejected. What can I do to approve it? A nice user suggested  to . The edit, though very good and desirable, was rejected. I do not understand the reasons, and I did not find a way to contact those people who rejected it. What can I do to re-approve the edit? Sum of derivatives of a polynomial I'm trying to delete some old flow which are inactive via workbench. DestructiveChanges.xml &lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt; &lt;Package xmlns=&quot;http://soap.sforce.com/2006/04/metadata&quot;&gt;     &lt;types&gt;         &lt;members&gt;Advanced_Round_Robin&lt;/members&gt;         &lt;name&gt;Flow&lt;/name&gt;     &lt;/types&gt;Ï &lt;/Package&gt;  package.xml &lt;?xml version=&quot;1.0&quot; encoding=&quot;UTF-8&quot;?&gt; &lt;Package xmlns=&quot;http://soap.sforce.com/2006/04/metadata&quot;&gt;       &lt;version&gt;48.0&lt;/version&gt; &lt;/Package&gt;  I've added both file in zip and in workbench when I deploy using this zip file I get below error.  insufficient access rights on cross-reference id   What permission I need to have to perform this action? Also is there way I can delete few version of same flow only? Like keep only last 3-4 version and delete all previous version of given flow? Thank you. Find the value of $\int_{-\infty}^{\infty} \frac{e^{-x^2}}{1+x^2} dx$ . Find the value of $\int_{-\infty}^{\infty} \frac{e^{-x^2}}{1+x^2} dx$     My attempt  First, I know the existence of this integral since $$ \mid \int_{-a}^{a} \frac{e^{-x^2}}{1+x^2} dx \mid \;\; \leq\;\;  \mid \int_{-a}^{a} \frac{1}{1+x^2} dx \mid$$  Next, let $R &gt;0 $ be an arbitrary and $\gamma_1(t) = -R(1-t) + Rt , \;\; 0 \leq t \leq1$ and $\gamma_2(t)= Re^{i\pi (t-1)}, \;\; 1 \leq t \leq 2 $.  So, take $f(z) = \frac{e^{-z^2}}{1+z^2}$.   I tried to find the value or upper bound of norm of $$\int_{\gamma_2} \frac{e^{-z^2}}{1+z^2} dz$$.  However, $$ \lvert\int_{\gamma_2} \frac{e^{-z^2}}{1+z^2} dz\rvert \leq  \frac{\text{max}\lvert e^{-z^2}\rvert}{R^2-1}\pi R = \frac{e^{R^2}}{R^2-1}\pi R $$ So, I can't proceed this.  May I ask you how to solve this? The following will cause infinite recursion on the == operator overload method      Foo foo1 = null;     Foo foo2 = new Foo();     Assert.IsFalse(foo1 == foo2);      public static bool operator ==(Foo foo1, Foo foo2) {         if (foo1 == null) return foo2 == null;         return foo1.Equals(foo2);     }   How do I check for nulls? How to specify password in ssh command From the terminal I type: ssh user@ip and then it prompts for a password.  Is there a way to specify the password in the ssh command itself? Prove $\frac{a+b+c}{abc} \leq \frac{1}{a^2} + \frac{1}{b^2} + \frac{1}{c^2}$. So I have to prove $$ \frac{a+b+c}{abc} \leq \frac{1}{a^2} + \frac{1}{b^2} + \frac{1}{c^2}.$$  I rearranged it   $$ a^2bc + ab^2c + abc^2 \leq b^2c^2 + a^2c^2 + a^2b^2 .$$  My idea from there is somehow using the AM-GM inequality. Not sure how though. Any ideas?  Thanks "a while" vs "awhile" Is there a difference between "awhile" and "a while"? If there is, what is it? I've been wondering this for awhile, but now I actually need the answer. Ampscript date range lookup I want to use LookupOrderedRows and return rows between a start and end date (last month range). What is the best way to handle using Ampscript?   I can add one date to the where using   "DateField", @varStartDate,   But if I add the below to add additional where filters  "DateField", @varStartDate,"DateField", @varEndDate,   I get this error:     "Duplicate Key Field Name: DateField"   EDIT: Also I tried the range as the var for the LookupOrderedRows using   set @strRange = StringToDate(Format(DateDiff(@strStartDate, @strEndDate, "M"),"MM/dd/yyyy"))  and then in the LookupOrderedRows just using  "DateField", @strRange  But that got an error as well. A method for the OP to accept comments? Question: What if the author of a question can accept a comment?   The problem:  Time and time again, answers are posted as a comment.  Usually, the person who commented has the best of intention (e.g. it was a trivial answer [to the answerer], and they weren't sure if the OP would immediately edit the question after the comment).  But this leaves the frustrating situation of an unanswered question with a perfectly good answer.  This problem accumulates over the years.     Candidate solution:  The OP can just "accept" the comment, after which a duplicate of the comment is made an accepted CW answer, with a preface indicating that it was originally a comment, e.g. This answer was originally a comment posted by [[blah]] that has been accepted by the author of the question.   Comments on this scheme:   The author of the comment has indicated they're not interested in gaining/losing reputation through their comment (thus CW answer). The original comment is still there. If desirable, the "author" of the accepted question could be a "bot", so the answer is not attributed to a genuine account.  (I suppose it would already be technically possible for Joe Blow to create a script for a bot that creates an answer from a comment in the proposed way.)     A similar question was asked before  (over 3 years ago), and in numerous other questions which have been deemed "duplicates" (,  and ; see also ), so there seems to be demand for such a feature.  The answers to these questions seem (to me, at least) quite weak:   "ask the commenter to add the comment as an answer"   The OP already did this by asking the question in the first place.  And what if the author of the comment doesn't respond (or takes a long time to respond)?  This also adds more chit-chat irrelevant to the question.   "add an answer of your own, referring to the comment, and accept it."   A hacky workaround.  How could this possibly be better than accepting a comment?  (Yet, this is the most up-voted response.)  Moreover, this adds to the user's list of "answers" (thus making the user's page harder to look through).   "When i leave a comment, i do so because i want to leave a comment."   Great; now what about everyone else?  In the immortal words of the FAQ: "Other people can edit my posts?!"  And it's not even an edit, it's copying the post from one box to another (a more hacky version of which is regarded as the "accepted" method). How to use HttpWebRequest (.NET) asynchronously? How can I use HttpWebRequest (.NET, C#) asynchronously? Integral $\int\csc^3{x} \ dx$ How to create a SQL Server function to "join" multiple rows from a subquery into a single delimited field? Rstudio is duplicating commands in the command line I am making a Minecraft Mini Game adventure map, and one of the levels has a /setblock command, I am using the command in a way to spawn an item in a chest (Wooden Button) I need the wooden button to have CanPlaceOn tag so it can be placed on a log. I have tried this command: setblock 294 5 -1251 minecraft:chest 0 replace {Items:[{Count:1,Slot:0,id:minecraft:wooden_button,CanPlaceOn:[log]}]}` Can the real and imaginary parts of $\dfrac{\sin z}z$ be simplified? I have calculated the real and imaginary parts of $\dfrac{\sin z}z.$ I've obtained  $$\begin{eqnarray} \frac{\sin z}z&amp;=&amp;\frac{\sin(x+iy)}{(x+iy)}\\ &amp;=&amp; \frac{\sin(x)\cosh(y)+i\cos(x)\sinh(y)}{x+iy}\\ &amp;=&amp; \frac{x\sin(x)\cosh(y)+y\cos(x)\sinh(y)}{x^2+y^2}+i\frac{x\cos(x)\sinh(y)-y\sin(x)\cosh(y)}{x^2+y^2}. \end{eqnarray}$$  Before calculating it, I hoped I could use this in a solution to a certain problem, but I would need to differentiate the real and imaginary parts of $\dfrac{\sin z}z$ with regard to $x$ and $y$. But what I'm getting is very complicated. I understand that it could be that that's just the way it is. But maybe there are some simplifications to be done either in the functions or in their derivatives? I've never really used hyperbolic functions before so I'm not sure I'm not missing something.  Added. The problem I'm working on is the following.     Prove that the solutions of the equation $$\tan z=z$$ are all real.   I will sketch the solution I know here.  It can be calculated that  $$\tan(x+iy)=\frac{\sin(2x)}{\cos(2x)+\cosh(2y)}+i\frac{\sinh(2y)}{\cos(2x)+\cosh(2y)}.$$  Plugging this to the equation, we get  $$\begin{eqnarray} x&amp;=&amp;\frac{\sin(2x)}{\cos(2x)+\cosh(2y)}\\ y&amp;=&amp;\frac{\sinh(2y)}{\cos(2x)+\cosh(2y)}. \end{eqnarray}$$  From this we can get   $$\sin(2x)\cdot2y=\sinh(2y)\cdot2x.$$  By plotting the functions $\sin,$ $\mathrm{id}$ and $\sinh$ (and proving the right inequalities we can see from the plots), we can see that this is only possible when $xy=0$. But when we plug $x=0$ to the second equation, we can show that the only solution is $y=0$, which ends the proof.  What strikes me in this solution is the fact that $\dfrac{\sin z}z$ is used. (Not explicitly in my statement.) This function has another connection to the problem:     The non-zero solutions of the equation $\tan z=z$ are exactly the zeros of the derivative of $\dfrac{\sin z}z.$   This is easy to prove. I wondered if there shouldn't be a solution to the problem which uses this fact, given that $\dfrac{\sin z}z$ appears in the solution I know. dropping ticklabel on pgfplot axis