How to convert price format string into number in jquery
How to convert a currency string to a double with jQuery or Javascript?
Is $\mathbb{Z} \left[ \frac{1+i \sqrt{7}}{2} \right]$ euclidean? NOTE: this question is sorta like a follow-on question to  I asked. In that question, the main suggestion was that I was trying to show two polys. Now, I'm asking about a SINGLE poly.  I have the following GEOGRPAHY of Los Angeles in my Sql Server 2008 :-     (or in )  It's bascially ..  -- Shape of Los Angeles.  DECLARE @WKT VARCHAR(MAX) = 'POLYGON ((-118.66815700000011 34.181235000000029, ... )) SELECT GEOGRAPHY::STGeomFromText(@WKT, 4326)   Now when I just try and render this out, It now looks like this (NOTE: this is different, but still not correct .. compared to my previous GIS Question).    Now, in the previous question people were suggesting that the previous data was a MULTIPOLYGON so there was some bad stuff I must have been doing, trying to render out holes in polys.  This time, this is a single polygon. So i'm assuming the hole theory still doesn't work. Now, I understand that by looking at this image, there's a number of holes ... but the Well Known Text data which Sql Server gives me is a POLYGON which to me means .. one single shape. So i'm not sure how I can fix this :(  This is why i'm asking the a similar question to my previous one.  Can anyone help? Can they see the data I've posted and see what happens in other systems? (I don't have any other software besides Sql Server 2008).  Maybe I need to extract all my data from Sql Server 2008 .. and clean it up (whatever that means) through another system. For example. If Sql Server is saying that the shape of Los Angeles is a single Polygon .. but when cleaned up .. it's actually 7 Polygons .. and then those shapes then get rendered correctly .. then we have a solution!   Any suggestions?  Can -anyone- render this shape onto a Google map? How can I tell what year my bike was made? How to add a guest account without a password? This question was prompted by . Notoriously, if you calculate the Schwarzschild coordinate time for anything, matter or light, to reach the event horizon the result is infinite. This implies that the universe ages by an infinite time before someone falling into the black hole reaches the event horizon, so could that person see the universe age by an infinite time?  To be more precise, suppose the observer starts falling from rest at time $t = 0$ and some initial distance $r &gt; r_s$. If we wait for some time $T$ then shine a light ray at the falling observer. Will the light ray always reach the falling observer before they cross the event horizon? If not, what is the formula for the longest time $T$ that we can wait and still be sure the ray will catch the observer? If $T$ is not bounded it implies that observer could indeed see the end of the universe.  I can think of a qualitative argument for an upper limit on $T$, but I'm not sure how sound my argument is. The proper time for the observer to fall to the event horizon is finite - call this $\tau$. The proper time for the light ray to reach the horizon is zero, therefore the light ray will reach the observer before they cross the event horizon only if $T &lt; \tau$. Hence $T$ is bounded and the observer won't see the end of the universe.  I think a more rigorous approach would be to determine the equations of motion (in the Schwarzschild coordinates) for the falling observer and the light ray, and then find the condition for the light to reach the falling observer at some distance $\epsilon$ from the event horizon. Then take the limit as $\epsilon \rightarrow 0$. In principle this seems straightforward, but in practice the algebra rapidly defeated me. Even for a light ray the radial distance:time equation isn't closed form (Wolfram claims it needs the $W$ function) and for the falling observer the calculation is even harder. Quaternion for beginner I have 2 points in 3d space ,point A= &lt;5,3,6> and B=&lt;8,2,3>  I want to rotate "point B" by 30 degree from point A.  how do I solve this question using quaternion.  Plz, explain the steps.... mailto link with HTML body I have a 1-year residence permit from one Schengen country that is now expiring. Upon its expiration, I would like to get my 90/180 days validity as a tourist to stay, or return here as soon as possible.  I understand that the tourist short-stay scheme is based on the 90/180 days "counter". But what happens if my previous stay was not tourism but residence (as searching year). Wouldn't that mean that I can quickly exit and re-enter the Schengen area to activate my tourist stay?   Also, is there a way to change this purpose of stay without exiting the Schengen area? Area 51 Site is quite different from other SE sites and needs an SE footer Honestly, navigation through Area 51 is a bit confusing and seems to be much different from the other SE sites.    The feature that is very lacking is the footer with all the sites you are subscribed to so that a user can easily return to a different SE site. This one really bugs me.  Can this be easily fixed?  Also, unlike all the other sites there is no "meta" site to add comments specifically about that site.    Again Area 51 seems out of sync with the other SE sites. Why do first years cross the lake to get to the castle? It makes sense to keep them together, and to have them arrive in the Great Hall separately from the rest of the school for the Sorting. But why the boats? The lake crossing is dramatic, but inefficient - as we see in book 4 when Dennis Creevey falls in the lake during the storm.   Is there a canon (books/movies or JKR) explanation for why the first years come up from the train in boats instead of carriages? Extra }, or forgotten \right My MWE:  \documentclass{report}  \usepackage{amsmath}  \begin{document}  \begin{align} y &amp;= a \\ =&amp; -2c_1\bar{z}_1^2 + 2\bar{z}_1\bar{z}_2 + 2\bar{z}_2 \left ( -\bar{z}_1 -c_2z_2 - \frac{3\epsilon}{2}\bar{z}_2 -\sigma_{2,1}\cos(x_1)\Delta x_1 \notag \right. \\ \left. &amp;- \sigma_{2,2}\Delta x_2 -\sigma_{2,3} \Delta u +c_2 \chi_2 \vphantom{\frac{1}{1}} \right ) - 2\gamma \sigma_{2,1}^2\cos^2(x_1) \Delta x_1^2 - \gamma \sigma_{2,2}^2 \Delta x_2^2   - 2\gamma \sigma_{2,3}^2 \Delta u^2 \end{align}  \end{document}   The error I get:  Extra }, or forgotten \right.   The expected result: How can I circumvent regional restrictions in Google's Play Store? I'm travelling to country X. I want to install an application which isn't available in my country, but is available in country X; but I prefer to download and install it in advance, while the data connection is still cheap.  Unfortunately, the Play Stores does not allow me to install this app. Is there any way to circumvent this limitation? What does $$ mean in the shell? How to pad zeroes to a string? What is a Pythonic way to pad a numeric string with zeroes to the left, i.e. so the numeric string has a specific length? I already searched the internet but could not find a solution to this. Maybe it is the same question as  but there was no answer.  I want to render a video with tracking, but the output "loses" color information and gets kind of greyish. I first thought that it is related to the renderer, but it happens in Cycles and Eevee. Therefore i made a sample image, added it to the image sequence editor and rendered it as 1 frame. Resulting in the same problem.  I placed the original image beside blenders output so that you can see the difference. The only idea I came up with is that something with the lighting is not correct but I can't find a setting for that.  I am using Blender 2.80 with the default settings. Only set the output resolution to match the input resolution. Does the artificer's Enhanced Weapon stack on top of hexblade's Improved Pact Blade? I play a hexblade warlock with an Improved Pact Blade longsword. I like the idea of the eldritch tinkerer, who builds his patron's gifts into his gadgets, which fits in a warlock/artificer multiclass. The artificer's Enhanced Weapon infusion would be very nice with the warlock if it stacks with the Improved Pact Blade bonuses, but I can't tell if it does from the class descriptions. Do these features stack, or do I need to rethink this build? I was running an upgrade with the apt-get command, and it was taking an exceptionally long time because half way through my ISP hit me in the face with their fair usage policy.   After sitting outside &amp; watching the rain for awhile my electronics regained consciousness, so I went back to complete the upgrade and my terminal scolds me with   "E: dpkg was interrupted, you must manually run 'sudo dpkg --configure -a' to correct the problem."   The last bit of legible info was all this:  Installing (ri/RDoc) documention for (stuff and such) ERROR:  Could not find a valid gem 'watobo-0.9.8.724.gem' (&gt;= 0) in any repository rm: cannot remove `watobo-0.9.8.724.gem': No such file or directory  Setting up metasploit (4.3.0-bt1) ... Upgrading Pre-Existing Installation... /opt/metasploit/postgresql/scripts/ctl.sh : postgresql  (pid 1191) already running prosvc is running metasploit is running [*] [*] Attempting to update the Metasploit Framework... [*]   So on it goes for miles, talking about gem caches, rubies, &amp; stuff I wish I had. All up until:  A    lib/gemcache/ruby/1.9.1/gems/state_machine-1.1.2/gemfiles/active_record-2.1.2.gemfile.lock   ...and there it has sat, all night.    If I stop it, will I still get the dpkg error (on the off chance that I won't), or if so what do I need to to resume using apt-get commands and its Super Cow Powers? Given three matrices $A$, $B$ and $C$ such that $ABA^T C$ is a square matrix, the derivative of the trace with respect to $A$ is:  $$ \nabla_A \operatorname{trace}( ABA^{T}C )  = CAB + C^T AB^T $$  There is a proof . However, I was not able to understand the second line of the proof. it says something like this:  $$ \nabla_A \operatorname{trace}( ABA^T C )= \nabla_\bullet \operatorname{trace}(f(\bullet)A^{T}C) + \nabla_\bullet \operatorname{trace}(f(A) \bullet^T C) $$  Where  $f(A) = AB$  I tried searching the proof or any hint using google, but I couldn't fine anything. Could anyone please help me with this second line. I cannot sleep. I am obsessed with this proof. How can I control where smoke and fire are emitted from? How to install Ubuntu on a laptop with Windows 10 I want to install Ubuntu and remove Windows 10 , but when you restart the PC does not read the Ubuntu installer that is on a bootable USB.