How can I reset a 'ghost' table in MySQL?
Schrödingers MySQL table: exists, yet it does not
Return multiple values from a SQL Server function How would I return multiple values (say, a number and a string) from a user-defined function in SQL Server? Note: this is intended to be a canonical question about whether or not a spell or ability targets so there are multiple sub-questions.   Can Hexproof or Shroud save my creature from ? What about a  that was cast for it's Overload cost? Does shroud prevent me from using the Monstrosity ability of a creature, or from giving it more counters with Proliferate? Can I cast an Aura Enchantment on one of my creatures with Shroud, or an opponent's creature with Hexproof? Or can I use the Equip ability to attach an equipment to one of my creatures with Shroud? Will 's ability trigger when my opponent plays ? And will I have to sacrifice my  if my opponent casts ? Will Shroud or Hexproof prevent an opponent from choosing me with 's ability? Will Hexproof keep one of my creatures from being affected by ? If an Aura or Equipment is attached to a creature with Hexproof, does the Hexproof protect the attached permanent? Does convergence in $L^p$ imply convergence almost everywhere? If I know $\| f_n - f \|_{L^p(\mathbb{R})} \to 0$ as $n \to \infty$, do I know that $\lim_{n \to \infty}f_n(x) = f(x)$ for almost every $x$? using this command I changed root password   mysqladmin -u root password fg$pkh@567fghu   And now I cant access mysql. Is this because mysql parse the chars other than what I expect?  Also I completely removed and installed mysql and Problem is extant. How do I remove mysql so that I get rid of password? Why AUC =1 even classifier has misclassified half of the samples? When using the web interface, there is a favorite tags section where you can select a list of tags that you view most frequently.  This has become a cornerstone of my normal  on stack overflow, but it doesn't look like this is possible in the Android app.  There should be a mechanism by which you can add some favorite tags to the nav bar. Clicking these tags will take you to a list of similarly tagged questions.  Perhaps also the feed should include a section for each favorite tag.  These would be presented on their own, much like how "hot new questions" and "new unanswered questions" appear in the feed.  Perhaps something like this: How to render a 30K image with cycles? I have to render an image of 27000 x 7000 for a 150dpi print. The scene is quite big, but cycles preview and a render in 2700x7000 works as expected.  If I hit render my memory raises up to 20gb, but my cpu usage is at 5%. Why cycles does not using the full cpu power during the render process?  Here are my rendersettings:  Pathtracing Samples:3000 Tilesize: 64x64 Bounces: Max 12 | Min 3 Diffuse: 4 Glossy: 4 Transmission: 12 Volume: 1   Is there a way to optimize things? Can I levitate an object without using an electromagnet? Is my mobile AMD card being used? I have a new Sony E Series Vaio with an intel i5 and an AMD 7xxx mobile card. Despite making sure sure my app (game) is set to High Performance in switchable gfx and choosing high performance power plan I'm not entirely convinced the gfx card is being used over the CPU's HD4000 chipset. Is there anyway I can prove for sure the AMD card is being used?  thanks for reading  (OS is Win8 64bit) Proof Verification: Converse of Intermediate Value Theorem A function $f$ is increasing on $A$ if $f(x)\leq f(y)$ for all $x&lt;y$ in $A$. Show that the Intermediate Value Theorem does have a converse if we assume $f$ is increasing on $[a,b]$.  The converse of IVT along with the additional hypothesis would look like this: Lef $f:[a,b] \rightarrow \mathbb{R}$ be an increasing function on $[a,b]$ which satisfies: if $L$ is a real number such that $f(a)&lt;L&lt;f(b)$ (or $f(a)&gt;L&gt;f(b)$), then there exists a point $c\in (a,b)$ where $f(c)=L.$ If the preceding conditions are met, then $f$ is continuous on $[a,b]$.  The proof (if it's correct) I'm going to show is only for the $c \in (a,b)$, but I think for end points ($a$ or $b$), the method should be similar.  We want to show that given $c \in (a,b)$, for all $\epsilon&gt;0$, there exists a $\delta&gt;0$ such that $|x-c|&lt;\delta \implies |f(x)-f(c)|&lt;\epsilon$.  Since $f$ is increasing, we know that $f(a)\leq f(c)$. If $f(c)-\epsilon&lt;f(a)$, then set $x_1=a$, if $f(c)-\epsilon\geq f(a)$, then we know by hypothesis that a $x_1&lt;c$ exists such that $f(x_1)=f(c)-\epsilon.$ In either case, we have for $x \in (x_1,c]$ $$ f(c)-\epsilon \leq f(x_1) \leq f(x) \leq f(c) .$$  In a similar way, since we know that $f(c)\leq f(b)$, we can deduce that a $x_2&gt;c$ exists such that, for $x \in [c,x_2)$ $$f(c)\leq f(x)\leq f(x_2)\leq f(c)+\epsilon .$$  Pick $\delta = \min \{c-x_1,x_2-c \}$, we then have $$|x-c|&lt;\delta \implies |f(x)-f(c)|&lt;\epsilon .$$  Is this correct? In the proof that I saw, they originally used $\frac{\epsilon}{2}$, instead of just $\epsilon$, but I think this one works just as well, what do you guys think? I am trying to set multiple definition queries for one layer based on one field using python.  ie.  I have a City layer with a field that holds the city name.  I want a copy of the layer in an MXD with the Definition query set for each value in the City field.  So essentially, I have one source layer, with a copy of the layer as many times as there are values in the City field.  The query would look like this: CITY = 'Atlanta' In counting degrees of freedom of a linear molecule, why is rotation about the axis not counted? What happened to Yachiru? According to the , Yachiru disappeared leaving her belongings after the fight with Gremmy. She is said to be "gone" by Kenpachi in the penultimate chapter of the original series.  I use "original" because there might be extra chapters announced as the other big announcement.  So, what happened to her? Was she part of his Zanpakutou or something? Do USA States have reciprocal agreements for learner drivers' permits? How do I expire by type in .htaccess for remote loaded Google fonts? Is it possible to set expire by type for remote fonts or Google analytics? I'm getting this report from GTMetrix and everything I've tried isn't working. Suggestions?  There are 4 static components without a far-future expiration date. http://fonts.googleapis.com/css?family=Open+Sans:300 http://fonts.googleapis.com/css?family=Roboto&amp;subset=latin,latin-ext http://www.google-analytics.com/ga.js http://www.google-analytics.com/analytics.js   All of my other expires are working fine.  But apparently this type of thing isn't right?  ExpiresByType application/x-font-woff "access 1 year" ExpiresByType application/font-woff "access 1 year"   What should I do? Formula field is too big to execute (5,480 characters) I got an error when i am trying to add fomrula in formula field.  Error: Compiled formula is too big to execute (5,480 characters). Maximum size is 5,000 characters  My formula is   (ED__c+Service_Tax__c+Total_Site_Work_Price1__c+Total_Selling_Price_Based_on1__c )*WCTper__c   In this formula ED__c, Total_Site_Work_Price1__c, Total_Selling_Price_Based_on1__c are also Formula fields. And these formulas are also contain fomrula fields.  How can i calculate the formula..? Let $G$ a group with normal subgroups $M,N$ such that $M\cap N=\{e\}$.   i) Show that for every $m\in M$ and for every $n\in N$, $mn=nm$.   ii) If $G$ is generated by $M\cup N$ then $G\cong M \times N$.   This is an homework question for abstract algebra. I think I can prove $i)$. But I have no idea how to prove $ii)$. Can anybody give me a hint for this one ?    Here my proof for i): Let $n \in N$ and let $m\in M$. Let $x=mnm^{-1}n^{-1}$. As $N$ is normal subgroup, $mnm^{-1} \in N$. Therefore $x \in N$.  As $M$ is normal subgroup , $nmn^{-1} \in M$. Since $m\in M$, then $x=m(nm^{-1}n^{-1})\in M$. This implies that $c\in M \cap N$, then $c\in \{e\}$, then $c=e$, and we get $mn=nm$. Evaluate $\sum\limits_{k=1}^{n} \frac{k}{2^k}$ Evaluate $$\sum\limits_{k=1}^{n} \frac{k}{2^k}$$ How to get current CPU and RAM usage in Python? I was practicing with modeling a leaf using a image reference. Everything went fine and I finished modeling my leaf, but I wanted to make it more realistic (I'll add textures later), I saw lots of people using the Subdivision Surface modifier but it doesn't work for me.  My model:   My model when I add the Subdivision Surface modifier