How do I make higher enchants on my weapons, tools, and armor?
How do I give players already enchanted Tools/Armour/Weapons
Consider the following:   $1 = 1^2$ $2 + 2 = 2^2$ $3 + 3 + 3 = 3^2$   Therefore,   $\underbrace{x + x + x + \ldots + x}_{x \textrm{ times}}= x^2$   Take the derivative of lhs and rhs and we get:   $\underbrace{1 + 1 + 1 + \ldots + 1}_{x \textrm{ times}} = 2x$   Which simplifies to:   $x = 2x$   and hence    $1 = 2$.     Clearly something is wrong but I am unable pinpoint my mistake. I am looking for either an online tool or one that I can download to convert DD to DMS.  For example, I want to convert from:  41.590833, -93.620833 to 41° 35′ 27″ N, 93° 37′ 15″ W ...  Those are the coordinates, according to , for Des Moines. SR Flip-Flop: NOR or NAND? How to query Sharepoint 2010 lists with sql? I think it has to be a common task. We have some applications on sharepoint and we need to prepare reports with data from these applications. It would be great if we could use Reporting Services. We need to query this data with sql because we need to join with some other sources. How can I do this? Are there any 3rd party tools or any built-it mechanisms in sharepoint to use Sharepoint lists data like ms sql tables? A comparison between the verbs (come in / by), (drop in / by), (check in / by) (step in / by) and come over I need a CD or USB stick, that will install Ubuntu on a completely headless machine. Stick CD in and restart, no keyboard or screen should be involved.  There are a few obstacles:   The language selection menu when you first boot the CD. The fact that the CD menu waits. The installer's asking questions during installation. Suppose $f:\mathbb{R}\to\mathbb{R}$ is Borel measurable. I want to show that $\displaystyle \int_a^b f(x)\mathrm dx=0$ for all $-\infty&lt;a&lt;b&lt;\infty$ with $a$ and $b$ rational implies that $f=0$ a.e. I'm really not sure how to approach this problem; any help would be welcome. Is it really possible to break the speed of light by flicking your wrist with a laser pointer? Minutephysics has a popular  called "How to break the speed of light". In the video it states that if you flick your wrist while pointing a laser that reaches the moon, that the spot of light on the moon will travel 20 times the speed of light. Now don't get me wrong, I do like their videos, just this one seemed a bit fishy to me. At first I thought it all practically made sense, then I realised something...  In my mind, I would think that light particles (photons) travel from the laser to the moon and bounces off the moon and back to your eye (it doesn't just stay there, in place, so you can't move it around). Now, what he is stating is that if you flick your wrist these photons that have travelled to the moon will move along with your wrist. Wouldn't these photons be bouncing off of other objects or still travelling to the moon by the time you flick your wrist? i.e. dissipating, therefore new photons will be travelling to the moon (from the laser directly).  For example: let's say you point the laser at the moon, and once it reaches the moon, you wait a couple of seconds and then flick your wrist. The laser that you have flicked will emit photons in every direction that your wrist was in, correct? i.e. The photons would shoot out in a straight line (unless disrupted) continuously, with your wrist taking no affect on the speed of the photons.  So back to the question, is this video wrong? How were hobbits created? How were hobbits created? I can't find any reference in The Silmarillion about this. Are they just men who have shrunken over generations or what? Proving the geometric sum formula by induction Packet Tracer 7 on Ubuntu 18.04 cannot launch I am having some issues with Packet Tracer 7 on Ubuntu 18.04: when I launch it with ./PacketTracer7 within the /opt/pt/bin directory, it opens but close immediately with a lot of:     "Warning: libpng warning: iCCP: known incorrect sRGB profile"   error msgs on the console.  The thing is, I installed PacketTracer7 on Ubuntu 16.04 and I remember that I had that issue with the libqt5multimedia.so.5 dependency, but I was able to find the solution (thanks to askubuntu and google) by installing the dependencies. So, everything perfect with 16.04.  But I'm a bit lost now. I can't realize where the issue come from, because I know the qt5 libs are installed on the system.  This is what I see when I run dpkg --get-selections:  libqt4-xmlpatterns:amd64            install libqt5concurrent5:amd64             install libqt5core5a:amd64              install libqt5dbus5:amd64               install libqt5gui5:amd64                install libqt5multimedia5:amd64             install libqt5multimediaquick-p5:amd64          install libqt5multimediawidgets5:amd64          install libqt5network5:amd64                install libqt5opengl5:amd64             install libqt5opengl5-dev:amd64             install libqt5positioning5:amd64            install libqt5printsupport5:amd64           install libqt5qml5:amd64                install libqt5quick5:amd64              install libqt5quickparticles5:amd64         install libqt5quicktest5:amd64              install libqt5quickwidgets5:amd64           install libqt5script5:amd64             install libqt5scripttools5:amd64            install libqt5sensors5:amd64                install libqt5sql5:amd64                install libqt5sql5-sqlite:amd64             install libqt5svg5:amd64                install libqt5test5:amd64               install libqt5webchannel5:amd64             install libqt5webkit5:amd64             install libqt5webkit5-dev:amd64             install libqt5widgets5:amd64                install libqt5x11extras5:amd64              install libqt5xml5:amd64       I've tried to uninstall pt and the qt5 libs and install everything again, but nothing... the same issue.  Did anybody install PacketTracer7 on Ubuntu 18.04?  I would be very happy to have your help for doing it!  Thanks and forgive me for my poor english :) $f$ bounded but $f'$ isn't Drawing Day and Night on a Google Map I'm looking to plot day/night on a Google map, for an arbitrary point in time. I'm familiar with generating map tiles; I'm just looking for an algorithm to tell me whether a particular point on the globe is currently in daylight or darkness, or to otherwise plot the curve of the day/night interface onto the map.  I've done some searching, but it's possible I don't even know enough about the problem domain here to know what terms to search for!  Any ideas? Doesn't have to be perfect -- basically, I'm comparing Flickr geolocation data of sunrise and sunset photos (and their "date taken" timestamps) with reality, and this is to help me visualise it. Text not very readable on different image backgrounds I've come here seeking for a bit of design help or advice on how I could possibly improve the following:  Like the title says, I'm having a website banner with multiple text displayed on different images as backgrounds. Now, since most of the images are dark, I've set the font color as white. But even then, some of the text is not very readable on a couple of images like:    Since I'm working with CSS, I've tried different options such as:  Adding Text Shadows:    CSS:  text-shadow: 3px 3px 0px #000;  Also tried, creating a semi-transparent box around the text:      I feel the box one looks out of place.  I've created a  for anyone who knows CSS. If not, please feel free to advice me based on your imagination alone.  PS: You could also advice on using a different font if that would help it stand out better. Why is the word 'number' abbreviated to 'No.' in UK English and '#' in American English? Why the disparity? And why use 'No.'? Is it from the French?  And the hash or pound sign seems a weird choice too, is there a history or any reason involved? Let f(x) be a  polynomial satisfying $\lim_{x \to\infty} \frac{x^4f(x)}{x^8+1}=3,$  $f(2)=5 $ and $f(3)=10$, $f(-1)=2$ and $f(-6)=37$ . And then there are some question related to this. In the solution it is given that according to the given information, $f(x)$ is a polynomial of degree 4 with leading coefficient 3. $f(x)=3(x-2)(x-3)(x+1)(x+6)+(x^2+1)$ Now what i think is that he got the coefficient 3 using the limits and the rest of the terms$[(x-2)(x-3)(x+1)(x+6)]$ from the respective $f(x)$ values from what was given and also the $(x^2+1)$ was added for the remainders, as they satisfy all the values that have been given to us in the question. I just wanted to know if my approach is right? or is there another elegant way to do it?. Show that a number has a terminating decimal expansion if and only if, it is rational and when in lowest terms, its denominator is coprime to all primes other than $2$ and $5$.   This is an unsolved question in my lecture notes. I can only seem to prove the converse direction for this. Would appreciate a solution for the other direction.     For converse direction:   Let the number, in lowest terms, be given by $\frac{l}{m}$ where $m = 2^ \alpha 5^\beta$, for some positive integers, $\alpha$ and $\beta$.    If $\alpha &gt; \beta$, let $k = 5^{(\alpha-\beta)}$. If $\alpha &lt; \beta$, let $k = 2^{(\beta-\alpha)}$.   Then $\frac{l}{m} = \frac{kl}{k2^\alpha5^\beta}=\frac{kl}{10^q}$ where $q = \max(\alpha,\beta)$.   Hence $\frac{l}{m}$ is a terminating decimal. Can you fly over a Medium enemy creature in a 10ft tall corridor? Let $A$ and $B$ be two matrices which can be multiplied. Then $$\operatorname{rank}(AB) \leq \operatorname{min}(\operatorname{rank}(A), \operatorname{rank}(B)).$$   I proved $\operatorname{rank}(AB) \leq \operatorname{rank}(B)$ by interpreting $AB$ as a composition of linear maps, observing that $\operatorname{ker}(B) \subseteq \operatorname{ker}(AB)$ and using the kernel-image dimension formula. This also provides, in my opinion, a nice interpretation: if non-stable, under subsequent compositions the kernel can only get bigger, and the image can only get smaller, in a sort of loss of information.  How do you manage $\operatorname{rank}(AB) \leq \operatorname{rank}(A)$? Is there a nice interpretation like the previous one? Find a plane that passes through a point and is perpendicular to 2 planes