How to initialize a variable in a given memory chunk?
What uses are there for "placement new"?
is it possible to combine two fields in one and use that field to group by in reports? for example, i would like to combine ee id and ee name fields in 1 and show as 1 field in the "group by" section on reports. How do I reset a lost password (using recovery mode requires me to type the password)? What price is a limit buy and a limit sell order settled at? A market has an existing limit buy order at $1.00.  The market then receives a limit sell order at $0.95, what price is the transaction settled at? How to zero out a drive? I'm currently running Ubuntu 12.04 and want to completely format my laptop so I can install Windows 7 (replace Ubuntu).   When I put in my bootable USB with the OS it just shows a black screen with a white blinking cursor on the top left corner. I wait for hours (to be specific 5 whole hours) waiting for something to happen but I get nothing, so I pull out the USB and my Ubuntu 12.04 loads up.  Repeated this several times with putting different boot priority options on top-est that relate to USB but the results are same. I go and visit some sites on the net like this  that say I have to zero out my hard drive.   My question is how?  Note: Erasing out all my data is no problem cause I have nothing important to backup.  If I have to lose my primary OS (Ubuntu 12.04) in the process I am ready to as my aim is just to install Windows 7 successfully. Please don't answer that there is something wrong with my USB or my USB reader/port/hardware or the content inside the USB cause they all works fine on my brothers PC as it boots up flawlessly. Does separability imply the Lindelöf property? Does separability imply a sort of Lindelöf property?  Since I can't prove this fact I'm beginning to think that my conjecture is false.  Intuitively, $\mathbb{R}$ has a countable subset $\mathbb{Q}$ which is used to form a countable basis for $\mathbb{R}$ with the usual topology and prove the Lindeöf property. Proving $\int_0^1 \frac{(\ln(x))^5}{1+x} \mathrm{d}x = -\frac{31\pi^6}{252}$ I would like to show the following identity:     $$\boxed{ I :=  \int_0^1 \dfrac{(\ln(x))^5}{1+x} \mathrm{d}x = -\dfrac{31\pi^6}{252} }$$     Here is what I tried. The change of variables $u=1/x$ yields $$I= \int_1^{\infty} \dfrac{(\ln(x))^5}{1+1/u} \dfrac{1}{u^2} \mathrm{d}u = \int_1^{\infty} \dfrac{(\ln(x))^5}{u^2+u} \mathrm{d}u$$ Then $z=u-1$ gives $$I = \int_{0}^{\infty} \dfrac{(\ln(z+1))^5}{z^2+3z+2} \mathrm{d}z $$ with $z^2+3z+2=(z+1)(z+2)$. I wanted to use contour integration like , but I was not sure how to proceed in this case. Anyway, the computations of the residues (of which "well-chosen" function? Maybe something like ?) seem to be difficult.  I believe that we can generalize to $\frac{(\ln(x))^n}{1+x}$, or maybe even more (e.g. $\frac{(\ln(x))^n}{ax^2+bx+c}$). Related computations are: , , , .  Thank you for your detailed help. Using wilcox.test() and t.test() in R yielding different p-values Contraction mapping in the context of $f(x_n)=x_{n+1}$. Given $a + b = 1$, Prove that $a^ab^b + a^bb^a \le 1$; $a$ and $b$ are positive real numbers. Should we have a tag for significant points in time? There are many discussions about the current incidence. For example:          Should we have a whole tag for this incidence? In general, if in the future there are more crises and incidences like this, should they have their own tags too? I feel it's fine, as we have specific tags for individual events like . And, should we have a  tag?    Related:        Note that these questions are specifically about the conflict 2019, while this question is simply about creating meta tags for significant events. Embedding C++ Objects into QML with Context Properties According to Qt5 documentation:  all public slots of C++ classes that inherit from QObject, are accessible from QML Here what I did:  C++  class MyClass : public QObject {     Q_OBJECT  public slots:     void doStuffFromQmlSlot()     {         qDebug() &lt;&lt; Q_FUNC_INFO;     }  public:     MyClass()     {         qDebug() &lt;&lt; Q_FUNC_INFO;     } };   my main.cpp contains:  MyClass myClass; QQmlEngine engine; engine.rootContext()-&gt;setContextProperty( "myclass", &amp;myClass ); QQmlComponent component( &amp;engine, QUrl::fromLocalFile("qml/qtquick-01/main.qml") ); component.create();   QML  import QtQuick 2.0  Rectangle {     width: 360     height: 360     Text {         text: qsTr("Hello World")         anchors.centerIn: parent     }     MouseArea {         anchors.fill: parent         onClicked: {             myclass.doStuffFromQmlSlot();              Qt.quit();         }     } }   Actually the QtCreator seems to recognixe the exposed myclass object into the QML as it enables auto-completion of both class name (myclass) and the public slot doStuffFromQmlSlot(). When I run the application I unfortunately got the following error:  ReferenceError: myclass is not defined  Any clue on what I'm doing wrong? Number of ways to write n as a sum of k nonnegative integers How many ways can I write a positive integer $n$ as a sum of $k$ nonnegative integers up to commutativity?  For example, I can write $4$ as $0+0+4$, $0+1+3$, $0+2+2$, and $1+1+2$.    I know how to find the number of noncommutative ways to form the sum: Imagine a line of $n+k-1$ positions, where each position can contain either a cat or a divider. If you have $n$ (nameless) cats and $k-1$ dividers, you can split the cats in to $k$ groups by choosing positions for the dividers: $\binom{n+k-1}{k-1}$. The size of each group of cats corresponds to one of the nonnegative integers in the sum. I want to appropriate line segments that share the same geometry with a particular line width and labels based on the aggregated values of one field "GIS@BUS_5_Min".  My attribute table and polyline objects look as following, see image below   "BUSLINIE" means a bus line, "Overlap" means if the line has overlaps, i.e. it's geometry repeats.  Values of the field "GIS@BUS_5_Min" for these three objects has to be aggregated as one value and represented as a label sum("GIS@BUS_5_Min").  And the width of this line (selected in yellow) will be sum("GIS@BUS_5_Min")/100 = 19.10/100 = 0.1910  How can I achieve such output?  I assume it is possible with Layer Properties &gt; Width &gt; Data defined override &gt; Edit..., but I do not know how to check the same geometry and how to sum the values of certain features with CASE WHEN condition THEN result END conditional function?  Dissolve function does not work in my case because I do not have any key-fields.    References: In  Deathly Hallows, when Harry, Ron, and Hermione are at No. 12, Grimmauld Place, Harry summons Kreacher from the kitchens at Hogwarts where the elf has been working on Harry’s orders given a year previously.  When the trio’s heist in the Ministry of Magic ends with Hermione inadvertently bringing Yaxley inside the perimeter of the Fidelius charm that protects Grimmauld Place, the trio leg it and dare not return there for fear that it’s now crawling with Death Eaters.  Before they leave for the Ministry in the morning, Kreacher is talking about making a stew or pot roast or something for dinner. After the trio go on the run and camp out in the tent, Harry thinks of poor Kreacher preparing a dinner they’ll never return to eat, but they dare not summon him lest a Death Eater tag along (like how Dobby ‘tagged along’ with Kreacher when Harry called him to have him follow Draco in Half-Blood Prince).  The next time we see Kreacher is during the Battle of Hogwarts where he leads the house-elves from the kitchen with battle-cries of “For Master! For Harry Potter!” (or something like that), so he’s clearly lost none of his new-found loyalty to Harry.  Harry is still Kreacher’s master throughout the book, and since he does not communicate at all with Kreacher after their escape from the doorstep, he cannot have ordered Kreacher to return to Hogwarts to work there again.  We know that house-elves can go against their masters’ wishes, but this usually entails them punishing themselves rather brutally, and Kreacher does not seem to have been constantly injuring himself for the better part of a year at Hogwarts.  So when and how does Kreacher leave his master’s house without orders and return to Hogwarts? In this sentence:  "We would also accept an international transfer, but in that case we would ask you to pay your bank's charges at the time of the instruction to ensure that we received the full amount"  is it correct to use "received" or should it be in present tense? Can two PS4s log in to the same PSN account? Both myself and my boyfriend have PS4s.  Can I just get a single PSN account and sign both consoles into the same account, or do I need to get two separate accounts? Prove that if b is coprime to 6 then $b^2 \equiv 1 $ (mod 24) Let $\gcd(b,6) = 1$. Prove that $b^2 \equiv 1 $ (mod 24).  Now I have that as $\gcd(b,6) = 1$, we know that  $3\nmid b $ and $2\nmid b$ (else the GCD would be 3 or 2 resp.)  So as $2\nmid b$, $b$ must be odd. Hence $b^2$ is also odd.  Then I'm not sure where to take it from here? Maybe I've gone down the wrong path to start with, and should be looking more along the lines of the Chinese Remainder Theorem? I'm not sure. Unfortunately, I need to do this.  I'm using ELMAH for my error log.  Before I route to my error.aspx view, I have to grab the default ELMAH error log so I can log the exception.  You used to be able to use   Elmah.ErrorLog.Default   However, this is now marked as obsolete.  The compiler directs me to use the method  Elmah.ErrorLog.GetDefault(HttpContext context)   MVC's context is of type HttpContextBase, which enables us to mock it (YAY!).  How can we deal with MVC-unaware libraries that require the old style HttpContext? How does quantization solve the ultraviolet catastrophe? Intuituive reason why Fermats last theorem holds I am unsure of whether it is normal, but to me, intuitively Fermats last theorem should not hold.  If anyone intuitively believed it to be correct, why?     Can someone explain so I understand somewhat why FLT holds without reading a massive and complex proof?