Error in retrieving data using JPA : No Dialect mapping for JDBC type: -9
No Dialect mapping for JDBC type: -9
Bridged interfaces and VLAN tags I am downloading macOS Sierra from Mac App Store. But I have electricity problem here. Due to which my iMac will lose power after 2 hours. Now I want to pause the downloading so that I can resume the download later on. How can I do that?  Here is a screenshot. Lost/Deleted dpkg (package manager for Debian). How do I get it back? OS: Ubuntu 12.04  Accidentally deleted dpkg. Now, packages can't be installed. So, needs an dpkg installer which installs packages. I know there are some similar posts on adding review queues to the mobile web page. However, this is regarding the Stack Exchange Android app. I really would like to review posts and edits from the Android app, however this isn't included in the app yet. I'm not sure how it would be implemented; maybe there could be a button or something for review. Could we please see this? Let $X$ be a smooth projective variety over $\mathbb{C}$, then the Neron-Severi group $NS(X)$ of $X$ is defined to be the Picard group of $X$ modulo algebraically equivalent relations.   On the other hand, by the exponential sequence, there is a first Chern class map  $$c_1: {\rm Pic}(X) \to H^2(X, \mathbb{Z}).$$ It is claimed that the image of $c_1$ coincides with $NS(X)$.   I want to know why this is true. Any suggestion or reference is greatly welcome! It used to be in settings under the friends tab. The friends tab no longer exists! Where do I find that infuriatingly missing setting now? If I create a custom environment based on the equation environment, I get a spacing issue: the next line of text after my environment closes doesn't start on the left margin.  Example code:  \documentclass{article} \begin{document} \newenvironment{myenv}{\begin{equation}}{\end{equation}} \noindent $| \leftarrow$ this is the left margin. \begin{myenv} e ^{i \pi} + 1 = 0 \end{myenv} $| \leftarrow$ this isn't the left margin. \end{document}   Output:    Removing the newline after \end{myenv} solves the spacing problem, but the resulting code is not readable.  Of course, in this example I could just use the equation environment itself. My real issue involves a more complex custom environment that suffers from the same problem, and which also includes an equation environment within it. How do I open a terminal? Possible Duplicate:             I just got ubuntu running on my computer and now I am ready to write a program...but I can't figure out how to open a command terminal. I guess I don't know where to find which version I am running either. Any help would be appreciated. Thank you. I needed some simple string encryption, so I wrote the following code (with a great deal of "inspiration" from ):      // create and initialize a crypto algorithm     private static SymmetricAlgorithm getAlgorithm(string password) {         SymmetricAlgorithm algorithm = Rijndael.Create();         Rfc2898DeriveBytes rdb = new Rfc2898DeriveBytes(             password, new byte[] {             0x53,0x6f,0x64,0x69,0x75,0x6d,0x20,             // salty goodness             0x43,0x68,0x6c,0x6f,0x72,0x69,0x64,0x65         }         );         algorithm.Padding = PaddingMode.ISO10126;         algorithm.Key = rdb.GetBytes(32);         algorithm.IV = rdb.GetBytes(16);         return algorithm;     }      /*       * encryptString      * provides simple encryption of a string, with a given password      */     public static string encryptString(string clearText, string password) {         SymmetricAlgorithm algorithm = getAlgorithm(password);         byte[] clearBytes = System.Text.Encoding.Unicode.GetBytes(clearText);         MemoryStream ms = new MemoryStream();         CryptoStream cs = new CryptoStream(ms, algorithm.CreateEncryptor(), CryptoStreamMode.Write);         cs.Write(clearBytes, 0, clearBytes.Length);         cs.Close();         return Convert.ToBase64String(ms.ToArray());     }      /*      * decryptString      * provides simple decryption of a string, with a given password      */     public static string decryptString(string cipherText, string password) {         SymmetricAlgorithm algorithm = getAlgorithm(password);         byte[] cipherBytes = Convert.FromBase64String(cipherText);         MemoryStream ms = new MemoryStream();         CryptoStream cs = new CryptoStream(ms, algorithm.CreateDecryptor(), CryptoStreamMode.Write);         cs.Write(cipherBytes, 0, cipherBytes.Length);         cs.Close();                     return System.Text.Encoding.Unicode.GetString(ms.ToArray());     }   The code appears to work fine, except that when decrypting data with an incorrect key, I get a CryptographicException - "Padding is invalid and cannot be removed" - on the cs.Close() line in decryptString.   example code:      string password1 = "password";     string password2 = "letmein";     string startClearText = "The quick brown fox jumps over the lazy dog";     string cipherText = encryptString(startClearText, password1);     string endClearText = decryptString(cipherText, password2);     // exception thrown   My question is, is this to be expected? I would have thought that decrypting with the wrong password would just result in nonsense output, rather than an exception. How can one differentiate between Dr. (PhD) and Dr. (MD or DO)? Euler-Lagrange equation in curved spacetime: how to calculate $\partial \mathcal{L}/\partial(\nabla_\nu A_\mu)$? My problem is mostly with notation. When we apply the Euler-Lagrange equation to the Lagrangian scalar $$\mathcal{L}= -\frac{1}{4}F^{\mu\nu}F_{\mu\nu}$$ Where $$F_{\mu\nu} = \partial_\mu A_\nu -\partial_\nu A_\mu= \nabla_\mu A_\nu -\nabla_\nu A_\mu$$ and I start with $$\frac{\partial\mathcal{L}}{\partial A_\mu}=\nabla_\nu\left(\frac{\partial \mathcal{L}}{\partial(\nabla_\nu A_\mu)}\right).$$   Now I rewrite the lagrangian as $\mathcal{L} = -\frac{1}{4}g^{\mu\alpha}g^{ \nu\beta}(\nabla_\mu A_\nu-\nabla_\nu A_\mu)(\nabla_\alpha A_\beta-\nabla_\beta A_\alpha)$ $$\mathcal{L}= -\frac{1}{4}g^{\mu\alpha}g^{\nu\beta}\left[(\nabla_\mu A_\nu)(\nabla_\alpha A_\beta)-(\nabla_\mu A_\nu)(\nabla_\beta A_\alpha)-(\nabla_\nu A_\mu)(\nabla_\alpha A_\beta)+(\nabla_\nu A_\mu)(\nabla_\beta A_\alpha) \right]$$ My problem is calculating $\frac{\partial \mathcal{L}}{\partial(\nabla_\nu A_\mu)}$, how are the rules of partial derivatives generalised to covariant ones? Also, is $\frac{\partial\mathcal{L}}{\partial A_\mu}=0$, is that correct ? How much money does Stack Exchange make? Accidental chown under / as root How does java do modulus calculations with negative numbers? Class not found loading JDBC org.postgresql.Driver Why isn't the center of the galaxy "younger" than the outer parts? I understand that time is relative for all but as I understand it, time flows at a slower rate for objects that are either moving faster or objects that are near larger masses than for those that are slower or further from mass.  So, the illustrative example I always see is that if I were to leave earth and fly around at near light speed for a while or go into orbit around a black hole the time I experience would be substantially shorter than for those I left behind at home on earth and I'd come back to find that I've only aged however long I felt I was gone by my own clock but that on Earth substantially more time would have elapsed.  Following through on this model, the stars in orbit around the black hole at the center of the Milky Way are aging much much slower (relative to us), right?  So does it not follow that the center of the galaxy is some appreciable (I have no idea how to go about putting this in an equation so will avoid guessing at the difference) amount "younger" than the stuff further away from the center?   If this is not true, could someone please explain why not, and if it is true, can someone please point me to where I can calculate the age of the center of the galaxy :-)  And to be clear... what I'm asking is... if there was an atomic clock that appeared at the center of the galaxy when the center was first formed, and we brought it through a worm hole to earth today - how much time would have elapsed on that clock vs. the age we recon the galaxy currently is? (13.2 billion years) Does the following limit exist? $$\lim_{x \to 0} x\sin\left(\frac{1}{x}\right)$$  If yes, then I have to find it; if no, then I need to give reason why. I couldn’t figure out how to prove this formally, can someone please help me out. How to type an inline chi in Latex \( \chi \) produces a letter that is slightly below the row, but I've seen in many papers a chi that is in the same line as the rest of the row) Leave newlines intact in bounty messages "I want you succeeding" vs. "I want your succeeding"