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How to turn off Facebook notifications on Mac OS X?
What do you call a person who does/thinks the opposite of the crowd for just that reason? Such a person does not hold in high regard the decisions taken by a group (not a team) of people. She believes that groups tend to be anarchic and don't serve their purpose.  An example would be - for outings with friends, this person will not like planning it with the group since they will mess it up.  Therefore, this person has convinced herself that when more people are involved with something, it will be worse. She distrusts crowds instinctively basically. Given the key, the plain text and the cipher text can I calculate the IV used in CBC mode? If I have the plain text, the ciphertext and the key for an AES-128 CBC operation, can I determine the IV, even if I don't know the padding (assuming the padding follows one of the more common formats)?  I believe it should be possible since my understanding is that the IV is only used as an initial XOR of the plain text in encryption, and should, therefore, be able to be available like this:  AESDecrypt(key, ciphertext) =&gt; (PlainText XOR IV); IV = ((Plaintext XOR IV) XOR (Plaintext))   Is this correct? Disable Repeated System Alerts in iOS 7 On iOS 7, there is a feature under Cellular in Settings called: Use Cellular Data For:. This lists all of the apps I have on my iPhone 4 with individual On/Off Switches to disable or enable cellular data. So, I disable it on several of my apps, one of which being Music. When I open my Music app, it tells me…     Cellular Data is Turned Off for "Music"   You can turn on cellular data for this app in Settings.   This alert does not occur once, but every time I clear the Music app from my multitasking and re-open it. Is there a way to dismiss this alert once and forever?  The alert looks something like this, but for Music: Meaning of Simplify's tolerance parameter The standard parameters of Douglas-Peucker's simplify algorithm are geometry and tolerance (e.g  in PostGIS). What's the meaning of the tolerance parameter? I know that the bigger the value, the coarser the geometry will be. But does the number has any unit or it is just arbitrary? Code coverage for wrapper class is 0% I have written below Wrapper class.  global class BI_VA_AutomationWrapper {      global class BI_VA_AutomationRequest {      webservice String userName;     webservice String emailId;     webservice String buinessUnit;     webservice String orgName;     webservice String country;     webservice String environment;     webservice String myShopNumber;     webservice String BidsId;//for testing     webservice String Type; //for testing  }  global class BI_VA_AutomationResponse {      webservice String responseStatus;     webservice String myShopNumber;     //webservice list&lt;Error&gt; errorMessages;     webservice String  errorMessages;//for testing   } global class BI_VA_Error {      webservice String type;     webservice String message;    }}   And test class is,  @isTest public class BI_VA_AutomationWrapperTestClass  { public static testMethod void unitTest(){      BI_VA_AutomationWrapper.BI_VA_AutomationRequest wrap= new BI_VA_AutomationWrapper.BI_VA_AutomationRequest();        wrap.userName='Test@test.com';     wrap.emailId='Test@test11.com';     wrap.buinessUnit='AH';     wrap.orgName='ORD';     wrap.country='US';     wrap.environment='QA';     wrap.myShopNumber='123456789';     wrap.BidsId='123';     wrap.Type='ResetPassword';              BI_VA_AutomationWrapper.BI_VA_AutomationResponse res= new BI_VA_AutomationWrapper.BI_VA_AutomationResponse();     res.responseStatus = 'Success';     res.myShopNumber = '987654321';     res.errorMessages = 'Test error';      BI_VA_AutomationWrapper.BI_VA_Error error = new BI_VA_AutomationWrapper.BI_VA_Error();     error.type = 'Test';     error.message = 'Test';  }}   Code coverage is 0% only. Is there an international taxonomy of academic titles/ranks? Looking at the  on Wikipedia shows that the same academic rank/title can mean quite different things in different countries. For instant, a "research assistant" in the US can stand for an undergrad student doing an internship, while in the UK it can stand for a postdoc. Similarly, the term "lecturer" might stand for a permanent position (e.g. in the UK) or for a teaching assistant position, open to graduate students.   However, when thinking about it, there are not so many kind of possible positions (permanent or not, with teaching or not, with research or not, with PhD supervision or not, with team responsibility or not, etc), and having a clear title could help a lot (for instance, in my case, I've been working in four different countries, with a different job title each time!).    Is there some kind of official taxonomy that one could refer to?  If not, who could be in charge to create it? (the EU, if only for intra-Europe mobility?) Weil divisors on normal Noetherian schemes I'm looking at Section 7 of Liu's Algebraic Geometry and Arithmetic Curves.  In Section 7, Definition 2.4. defines a Weil divisor as a cycle of codimension 1 on a Noetherian integral scheme. But then Liu discusses Weil divisors on normal Noetherian schemes in Definition 2.7., 2.10., Proposition 2.11, etc., as well as the notion of function field $K(X)$ of a normal Noetherian scheme $X$.  I feel lost as the function field is defined over an integral scheme, and up to my understanding, the closest one to the function field of a normal Noetherian scheme is perhaps the direct sum of the function fields of the finite integral components.  What I'm more interested is whether Weil divisors are well-defined on normal Noetherian schemes and how close it is to be equivalent to invertible sheaves. Could someone provide an explanation on this?  Thank you. I've tried multiple times to  import a SVG file from illustrator CS5.5 to Blender 2.71 and 2.73. However, I do not see a mesh, curve, or anything pop up in my "Outliner" window. So I know its not so small I can't see it. I even made sure under user preferences that the "import and export of SVG 1.1 format" is "checked." I've tried even just importing text from illustrator and I'm still getting no where. What can I do to resolve this problem? If this is common error with this version of Blender, then what can I do to transform an image into a 3D object in Blender? Display solution/file path in the Visual Studio IDE I frequently work with multiple instances of Visual Studio, often working on different branches of the same solution.   used to display the full path of the current source file in its title bar, but Visual&nbsp;Studio 2005 doesn't appear to do this. This makes it slightly more awkward than it should be to work out which branch of the solution I'm currently looking at (the quickest way I know of is to hover over a tab so you get the source file's path as a tooltip).  Is there a way to get the full solution or file path into the title bar, or at least somewhere that's always visible, so I can quickly tell which branch is loaded into each instance? Is there any way to attract or repel neutrons? I know that neutrons are neutral and have no charge, but is there any other way to interact with them? Let $G$ be a group and $c\in G$. Define $*$ on $G$ by: $x*y=xdy$ for all $x,y\in G$, where $d$ is the inverse of $c$. Prove $(G,*)$ is a group. Let $G$ be a group and $c$ be a fixed element of $G$. Define a new operation $*$ on G by:   $$x*y=xdy$$   for all $x$ and $y$ in $G$, where $d$ is the inverse of $c$. Prove that $G$ is a group under the operation $*$.    If you want to check, this problem is in the book “A Course In Group Theory”, by John F. Humphreys (problem $3$, page $28$)   I know what are the axioms that $(G,*)$ must obey in order to be a group and I did show that all the axioms where obeyed except the inverse axiom.  My problem is that, whenever I try to verify what would the inverse be for some element $x$, I get an equation where the $x$ is cancelled in both sides.  Can please someone guide me?  Thank you!  (P.S.: This is NOT a homework assignment, I’m studying Group Theory by this book and got problems solving this question) MSO Review Queue Privileges are Misleading When I visit Stack Overflow, I see the review option in the bar at the top of the screen.    However when on MSO, I don't see it. I assumed this was because I didn't have enough reputation to access the queue. I was curious what the requirement was on meta, so I moseyed on over to the privileges page. To my surprise, I saw that the privilege is listed as only requiring 500 rep and informs me I already have it:    Confused, I manually typed in meta.stackoverflow.com/review to see what would happen. The page did in fact load, but as you can see meta has no "First Posts" or "Late Answers" queue.    Seeing on that page that a minimum of 2k reputation is required to access any queues on MSO, I report the following bug:  1) On the privileges list on MSO, the 500 rep privilege of "Access first posts and late answers review queues" should not appear.  I also have the following feature request:  2) On the privileges list on MSO, it would be useful if instead there was a 2k privilege that informed you that you have access to the "Suggested Edits" and "Low Quality Posts" queues. What are the readline word separators? Why not use a WAMP stack? This is a  about  the use of a *AMPP's stack.    I recently had a talk with some experienced people and they suggested to me not to use a WAMP stack, and instead install apache, mysql and php separately.  I don't understand why they have suggested this, though, so can anyone tell me?  Is there a particular disadvantage of WAMP, or a particular advantage to installing all of them separately?  Since a WAMP stack itself is composed of apache, mysql and php, then what's the difference between using the WAMP stack and installing them all separately? Compute $P(Y<3X)$ using joint PDF I'm given a joint pdf  $f_{X,Y}(x,y)=2e^{-x-y}, 0&lt;x&lt;y, 0&lt;y $  and asked to compute $P(Y&lt;3X)$. To do this, I let $Y=3X$ (the boundary) and found that the region of integration is under this line.  To find $P(Y&lt;3X)$, it seems to me that the integral for this region be written as   $P(Y&lt;3X)=\int_0^\infty \int_0^{3x} 2e^{-x-y} dy dx  $  However this isn't right, as the boundaries are actually   $P(Y&lt;3X)=\int_0^\infty \int_x^{3x} 2e^{-x-y} dy dx  $  Why is this? I'm having a hard time seeing how to construct these boundaries (especially the fact that the $y$ boundary goes from $x$ to $3x$ instead of $0$ to $3x$)  Thank you. ARMA lag selection for ARMA-GARCH models How do I mail merge from Google Spreadsheet to a Google Document? Group algebra ever a field? Let $G$ be a group. Let $K$ be any field and consider its group algebra $K[G]$. It is known that if $G$ is a finite group then $K[G]$ is never a field. Or even if $G$ is not finite: if $G$ has at least one non-trivial torsion element, then $K[G]$ is not a field.  Question: Do there exist infinite groups $G$ such that $K[G]$ is a field or a division ring? InDesign CS5 tables: Can I automatically fit rows or columns to the size of content? You know how Excel has the function "Autofit," where you select a whole row or a whole column and it resizes the entire thing to the height or depth of the largest content item? I want to do that in an InDesign table, but with one click. (I know I can drag the column out until the overflow box goes away, but I want to know if there's some automated function I'm overlooking.) Does this automatic function exist anywhere? Is there a program equivalent to lint for LaTeX? Is there a program equivalent to lint for LaTeX? (lint checks C code for syntax errors and possible mistakes.)