How to search in an List and my List is look like : List myList = new ArrayList()
What is the best way to filter a Java Collection?
One form of Jensen's inequality is     If $X$ is a random variable and $g$ is a convex function, then   $\mathbb{E}(g(X))\geq g(\mathbb{E}(X))$.   Just out of curiosity, when do we have equality? If and only if $g$ is constant? What free/open source image design programs can you recommend? Are there any free/ open source image designing programs that you can recommend? Can a curve object modifier created geometry be used as boolean factor This question is related to .  Let me use an exemple to illustrate what I mean.  We've created a text object (made of curves). It can't be used in a boolean modifier as it won't appear in the list of usable objects in the modifier because it's a curve object.  But if we add a remesh modifier on the text, geometry is created from the shape.  The object could be used as boolean if we convert it to mesh. The remesh can't be applied on curve object.  My question is : Can we dynamicaly use the remesh modifier created geometry as real geometry or make the boolean modifier consider the text modified object as a real mesh?  The idea behind this is to be able to change the text (or any curve 3D shape) without having to make it a real mesh.  (don't hesitate to edit my poor english to make it understandable :) ) $R$ is commutative, $I$,$J$ are ideals, $I+J=R$, then $IJ=I\cap J$ If $R$ is a commutative ring and $I$ and $J$ are ideals s.t. $I+J=R$ then show that $IJ=I\cap J$.  I've already shown that $IJ \subset I\cap J$, now I need to show the reverse inclusion.   I'm a bit lost, so far i'm just figuring out what pieces I have to work with.  Such as:  $\forall r\in R$ $\exists i\in I ,j\in J$ s.t. $i+j=r$  $\forall ij\in IJ$, $ij=i_1$ and $ij=j_1$ for some $i_1\in I$, $j_1\in J$.  Also, if I let $x\in I\cap J$, then $x=i_2=j_2=i+j$ for some $i_2\in I$, $j_2\in J$  Anyone, having problem getting to the conclusion here, thanks in advance Countdowntimer in minutes and seconds I'm trying to make a systemd timer that runs every 15 minutes. Right now I have:     timer-fifteen.timer:  [Unit] Description=15min timer  [Timer] OnBootSec=0min OnCalendar=*:*:0,15,30,45 Unit=timer-fifteen.target  [Install] WantedBy=basic.target    timer-fifteen.target:  [Unit] Description=15min Timer Target StopWhenUnneeded=yes    This runs over and over again without stopping. Does it need to be *:0,15,30,45:* instead? How can I make this work? I am trying to auto-mount my NFS drives, but it doesn't work too well sadly.  What does work is mounting from CLI:  me@client:/$ sudo mount 192.168.178.4:/mountdir /mnt/mountdir me@client:/$ mount -t nfs 192.168.178.4:/mountdir on /mnt/mountdir type nfs (rw,addr=192.168.178.4)   when I try to add mountdir in the fstab, I cannot mount it due to "protocol not supported" (which seems strange as I can mount it)  $ sudo mount films_d3 mount.nfs: Protocol not supported   So there might be something wrong with my fstab entry. This is my current entry:  192.168.178.4:/mountdir /mnt/mountdir  nfs auto,_netdev,noatime,nolock,bg,nfsvers=4,intr,tcp,actimeo=1800 0 0   During startup I also get this error twice: I was trying to fix the mount-from-fstab first, then worry about that, but nevertheless this might be a different problem:  init: idmapd-mounting (/mnt/kazemat/films_d3) main process (445) killed by TERM signal   This seems to be before the eth0 is initialised, while I thought the "_netdev" option would make the entry wait for the network to be up?  can anywone see the mistake in my fstab entry? I have a scrbook document with an openright option, i.e. every once in a while a blank left page appears in the document. Not that I really want to do this, but how could I include the infamous "This page has been intentionally left blank" in those blank pages cleanly, i.e. without too many hacks?  Bonus points for including a different famous quote on each blank page instead of the dull default ;) Destroying a Planewalker before its ability is used Say my opponent plays a planeswalker during their first main phase.  I have a  or some other effect that will kill it after it is already in play, but before they use any of its abilities.  I could respond to them using a +1 ability, but I want to kill it before that effect goes on the stack.  In most casual situations, it would basically come down to whether I say "Hero's Downfall" first, or they say "+1" first.  But I can't imagine that's how it's supposed to work.  Is there a time between when the planeswalker hits the battlefield and when they activate its abilities that they must let me respond? It seems to me that situations like this arise frequently, and they are resolved simply by who speaks up first, which is horrible for such a rules-oriented game. How to render an ASP.NET MVC view as a string? I want to output two different views (one as a string that will be sent as an email), and the other the page displayed to a user.  Is this possible in ASP.NET MVC beta?  I've tried multiple examples:  1.      If I use this example, I receive the "Cannot redirect after HTTP   headers have been sent.".   2.      If I use this, I seem to be unable to do a redirectToAction, as it   tries to render a view that may not exist. If I do return the view, it   is completely messed up and doesn't look right at all.   Does anyone have any ideas/solutions to these issues i have, or have any suggestions for better ones?  Many thanks!  Below is an example. What I'm trying to do is create the GetViewForEmail method:  public ActionResult OrderResult(string ref) {     //Get the order     Order order = OrderService.GetOrder(ref);      //The email helper would do the meat and veg by getting the view as a string     //Pass the control name (OrderResultEmail) and the model (order)     string emailView = GetViewForEmail("OrderResultEmail", order);      //Email the order out     EmailHelper(order, emailView);     return View("OrderResult", order); }   Accepted answer from Tim Scott (changed and formatted a little by me):  public virtual string RenderViewToString(     ControllerContext controllerContext,     string viewPath,     string masterPath,     ViewDataDictionary viewData,     TempDataDictionary tempData) {     Stream filter = null;     ViewPage viewPage = new ViewPage();      //Right, create our view     viewPage.ViewContext = new ViewContext(controllerContext, new WebFormView(viewPath, masterPath), viewData, tempData);      //Get the response context, flush it and get the response filter.     var response = viewPage.ViewContext.HttpContext.Response;     response.Flush();     var oldFilter = response.Filter;      try     {         //Put a new filter into the response         filter = new MemoryStream();         response.Filter = filter;          //Now render the view into the memorystream and flush the response         viewPage.ViewContext.View.Render(viewPage.ViewContext, viewPage.ViewContext.HttpContext.Response.Output);         response.Flush();          //Now read the rendered view.         filter.Position = 0;         var reader = new StreamReader(filter, response.ContentEncoding);         return reader.ReadToEnd();     }     finally     {         //Clean up.         if (filter != null)         {             filter.Dispose();         }          //Now replace the response filter         response.Filter = oldFilter;     } }   Example usage  Assuming a call from the controller to get the order confirmation email, passing the Site.Master location.  string myString = RenderViewToString(this.ControllerContext, "~/Views/Order/OrderResultEmail.aspx", "~/Views/Shared/Site.Master", this.ViewData, this.TempData); Windows 10 internet speed capped at half the original speed on new PC Where can I get more favourable exchange rate, in general?changing baht to Canadian dollars in Thailand or Canada or make a bank transfer to my Canadian account If the original question is "What time is it?" and I want to communicate it to another person, are these Embedded Questions OK?        I don't know what time is it.       or        I didn't know what time was it. (if communicated later) Finding a pair of functions with properties I need to find a pair of functions $f$, $g$ such that    $f$ is not differentiable at  $x = 0$ $g$ is not differentiable at $f(0)$ $g \circ f$ is differentiable at $x = 0$   I've tried a lot of functions but just can't seem to find ones that work. Any help would be appreciated, thank you. In this kind of sentence the second half is an inversion of the first half. Is it a rhetorical artífice? What kind? "done" vs "have done" How do I obtain the ebony blade and how do I power it up? The ebony blade is a katana like two handed weapon in Skyrim.  Its apparently associated with one of the daedric quests, but which one, and how do I start it?  Also, once I obtain it, how do I power it up? How can I completely remove all traces of Java on my system?   I already know  in case I need it again. booting windows 10 spends too long Currently, when flagging an off-topic question, the following choices are offered.   Questions about general computing hardware and software are off-topic for Stack Overflow. Questions concerning problems with code you've written must describe the specific problem and include valid code to reproduce it. Questions must demonstrate a minimal understanding of the problem being solved. Questions on professional server, networking, or related infrastructure administration are off-topic for Stack Overflow unless they directly involve programming or programming tools. Questions asking us to recommend a tool, library or favorite off-site resource are off-topic for Stack Overflow as they tend to attract opinionated answers and spam. This question belongs on another site in the Stack Exchange network   However, there are some questions that fit in none of these categories.  For example, career advice questions are off-topic here (and on programmers.SE), questions like  are off-topic on pretty much any SE site.    Some questions might also be relevant on another SE site not listed when the "belongs on another site" option is selected.  How should those questions be flagged?  Why isn't there a "it's off-topic because it is" option?  EDIT: just to be clear, I don't have the "Other" option under Off-Topic.