Creation of Anaconda launcher
How can I create launchers on my desktop?
$a_{n+1}=\log(1+a_n),~a_1>0$. Then find $\lim_{n \rightarrow \infty} n \cdot a_n$ In other words, why do we need to connect the battery positive to the negative to get electron flow? As far as I know, voltage difference is what drives current flow.  From what I understand, there's a surplus of negative charge (electrons) in the positive end of a battery (weird I know, but I guess they do it for mathematical reasons). Between the positive and negative ends of the battery is some kind of wall that prevents the electrons from diffusing, so they have to go the long way (through a wire to the other end of the battery) to diffuse and reach the receiver atoms/molecules.  So why not just have the surplus of electrons on one end go to ground to equalize (e.g. 5 volts to 0 volts should produce current)? Why does it have to be the other end of the battery? I'm sure there's atoms/molecules in the ground that could accept the extra electrons (receivers atoms/molecules for the donors in the battery). I'm trying to prove that if there are to numbers $n,m$ (natural numbers), and their smallest common multiple is $k$, so that $k = n·i$ and $k = m·j$ for some $i,j$ natural numbers, any common multiple $q$ of $n,m$ is a multiple of $k$, so that there exists a $g$ so that $q=k·g$.  Logically it seems correct, but I can't seem to prove it... Any help? An elementary question regarding a multiplicative character over finite fields Reading Chapter 2 of Koblitz's Introduction to Elliptic Curves and Modular Forms, I got stuck on the following question. I would like to proceed my reading, so I would appreciate any hint to this. I have no background in Algebraic Number Theory, but if someone explains in that language, I would like to see it and learn it as much as I can at this moment. References will also be appreciated!  Let $q$ be a power of prime $p$ such that $q \equiv 1 \mod 4$ and $p \nmid 2n$.  Question. Let $\chi_{4} : \mathbb{F}_{q}^{*} \rightarrow S^{1}$ be the character of order $4$, show that $\chi_{4}(-4) = 1$.  The hint in the book says we may show that $\chi_{4}(4) = \chi_{4}(-1) = 1$ for $q \equiv 1 \mod 8$ and $\chi_{4}(4) = \chi_{4}(-1) = -1$ for $q \equiv 5 \mod 8$.  If $q \equiv 1 \mod 8$, then $\chi_{4}(4) = \chi_{4}(2)^{2} = \chi_{2}(2) = \pm 1$, where $\chi_{j}$ denotes the character of order $j$. So I think $2$ must be quadratic residue in this case, but I cannot figure out why. Can't save my render as an image I seem to be having issues when I try and save the output file as a .png, or .jpeg for that matter. I've set up my user preferences, File, Render Output to my desktop as well as render output in the editor window. What am I missing here? I'm obviously very new to this program and your help would be appreciated. Thanks for your time Recover Data from Card that cannnot be read I am trying to help a friend who is very concerned that she has just lost all of the data on her 32GB SanDisk microSD card.  I told her I would post this and see if anyone could offer help.  Here are the details:   The SanDisk microSD card is less than two years old.  Probably only about a year old.  The store will take it back, but that doesn't really help.  She wants her data. She used the card in her Samsung Galaxy S4 smartphone for over a month.  The phone was never exposed to water or temperature extremes. Today, her phone suddenly said something like "Your SD card is blank or an unsupported format". Her phone was then unable to read the SanDisk microSD card at all.   Here's what she has tried:   Rebooting her phone.  Had no effect. Taking out the SanDisk microSD card and putting it inside a full-size SD card adapter, and inserting it into a Windows 7 SP1 computer.  The computer did not recognize its presence at all. Putting the SanDisk microSD card into a USB 2.0 external card reader and inserting the card reader into a USB port on a Windows 7 SP1 computer.  The computer recognized the card reader and installed drivers for it.  The card reader shows up as 'Removable Disk' in Windows Explorer.  Clicking on 'Removable Disk' in Windows Explorer results in the error "Insert disk: Please insert a disk into the Removable Disk". After trying #3, tried opening the 'Removable Disk' in FreeCommander.  Doing so results in the error "The device is not ready".   She does not have access to a linux box, but does have access to her Android phone.  What can she do to recover the data on her 32GB SanDisk microSD card? Why is \[ ... \] preferable to $$ ... $$? Best way to add KeyEvents and faster Quit Remove Windows entry in GRUB menu Nvidia graphics card no longer works in Windows 10 (error: Code 43) but works in Ubuntu Why disable Fast Boot on Windows 8 when having dual booting? Why is everybody keep mentioning to disable Fast Boot on Windows 8 if you have installed alongside Ubuntu? Is it something that is recommended only for UEFI machines or is it a suggestion for Legacy BIOS machines as well? Is it because it makes the Windows partition inaccessible from Linux or there is another more serious reason to disable it? The nose of Tom Riddle (as a student) was fine, as I have seen in the movies. But, Voldemort's nose doesn't look like a normal human nose. What really happened? What is the smallest convex set includes all smooth unit curves? I try to understand: is there a smallest in area convex set that every smooth curve with length 1 can be placed inside it by translation and rotation?  I only have a upper bound $S \leq \frac14+\frac{\pi}{16}$ because of convex hull of two circles radius $\frac14$ and simple lower bound $S\geq\frac1{4\pi}$.  Does this set exist and what is its length? Postfix Connection Timed out Can I use set instead of List to resolve the duplicate id issue If you take a look into this issue     I have provide an answer of using set&lt;Sobject&gt; instead using list&lt;Sobject&gt;  i.e.  if( !contacts.values().isEmpty() ){   set&lt;Contact&gt; setContacts = new set&lt;Contact&gt;();   for( Contact objCon : contacts.values() ){     if(!setContacts.contains(objCon)){         setContacts.add( objCon );     }   }  update new list&lt;Contact&gt;(setContacts); }   even if(!setContacts.contains(objCon)) is not needed  if( !contacts.values().isEmpty() ){   set&lt;Contact&gt; setContacts = new set&lt;Contact&gt;();   for( Contact objCon : contacts.values() ){         setContacts.add( objCon );   }  update new list&lt;Contact&gt;(setContacts); }   So is there any condition/use case where this answer might fail? How did the writers not notice that the mailbox of Leela's parents says "Turanga," and not "Leela"?  Turanga Leela is Leela's proper name, with Leela being her surname, so shouldn't it follow that her folks would be the same? Covariance between sum of iid random variables and sum of indicator functions The question is-     Let $X_1,X_2,..,X_n$ be iid random variables from a continuous distribution whose density is symmetric about $0$. Suppose $\mathbb{E}(|X_1|)=2$ and define $Y=\sum_{i=1}^{n}X_i$ and $Z=\sum_{i=1}^{n}I(X_i&gt;0)$. Then calculate covariance between $Y$ and $Z$.   My attempt:  $E(X_i)=0$ for all $i=1(1)n$ because $X$ is symmetric about $0$ and $E(|X|) $ exists.   Now,  $Cov (Y,Z)=E(YZ)-E(Y)E(Z)$ $=E(YZ)-0$ $=E[(\sum_{i=1}^{n}X_i)(\sum_{i=1}^{n}I(X_i&gt;0)]$  $=(\sum_{i=1}^{n}E[(X_i.I(X_i&gt;0))]$ $+\sum\sum_{i \neq j}E(X_i)E(I(X_j&gt;0)$ as $X_i,X_j$ are independent.   $=\sum_{i=1}^{n}E[(X_i.I(X_i&gt;0)] +0 $ as $E(X_i)=0$  $ =\sum_{i=1}^{n}\{E[X_i.I(X_i&gt;0)|I(X_i&gt;0)=1]×1/2] + E[X_i.I(X_i&gt;0)|I(X_i&gt;0)=0]×1/2]\}$  $=\sum_{i=1}^{n}E[X_i.I(X_i&gt;0)|I(X_i&gt;0)=1]×1/2] +0$  $=\sum_{i=1}^{n}E[X_i|X_i&gt;0]×1/2]$  $=2n×(1/2)$ $=n$  Is my reasoning correct ? Thanks in advance! Localization of a UFD that is a PID Calculate the radius of a circle given the chord length and height of a segment I have a (circular) segment of known height and known chord length. Is is possible to determine the radius of the circle?  Any help much appreciated. Catching access violation exceptions? Example  int *ptr; *ptr = 1000;   can I catch memory access violation exception using standard C++ without using any microsoft specific.