Middle-Earth Holidays/Festivals/Celebrations
Are there any holidays in Middle Earth, except Yule, Lithe, New Year in Gondor and Durin's Day?
I want to enable gzip compression for acethehimalaya.com. Can anybody please tell me what is the best way of achieving compression in an Apache Webserver? Pokemon GO isn't working at all for me right now. I'm in one of the following circumstances and can't do anything:   My game is displaying a "Try Again" message I'm stuck on the Loading Screen When I sign in I get a message that the servers are experiencing problems. I see the map but nothing is loaded, and my team color is wrong The "loading" Pokeball just ends up spinning and I can't catch or interact with things When I try to catch a Pokemon, the Pokeball just sits on my screen doing nothing Gym opponents will drop to 1 HP and won't take any more damage or attack When I open a pokestop, the pokestop image and the name of the pokestop does not load.   What's causing this? Is there a way to fix it? Variance of product of dependent variables Code in beamer presentation Good day! So, I need to present my disertation code to my thesis advisors, but I'm quite unsure how to actually do it in a proper way. I found  showing some ideas.  Is there a way of making the slides 48-67 in beamer without using tikz? Any ideas to implement the whole ideas the author propose?  Thanks in advance. Permutation module of $S_n$ Let $G=S_n$ and let $V$ be the permutation module of $G$ with basis $\{x_1,\ldots,x_n\}.$  Let $\lambda, \mu \in \mathbb{C}$ to allow one to define a $\mathbb{C}G$-homomorphism $\rho:V \to V$ by $$\rho(x_j):=\lambda x_j+\mu\sum_{i \neq j}x_i.$$  By using the above fact or otherwise, how can we prove that $V$ is the direct sum of two non-isomorphic irreducible $\mathbb{C}G$ -submodules?  I tried to prove this by construction. A familiar irreducible submodule in this case is the $1$-dimensional space $U:=\operatorname{span}\{x_1+\cdots+x_n\}$. I intend to find another $(n-1)$-dimensional submodule $W$  which makes $V=U\oplus W$ hold, but it's hard to do so. Is there a way to use the fact instead of a random construction? How to install MySQL workbench? Installing MySQL workbench on 10.04 or 10.10 is not a problem, as the deb packages are available on MySQL's website.  But there is no 11.04 deb package available.  So, how do I install MySQL workbench on 11.04 and keep it updated automatically when updates become available to ubuntu via apt-get update. Generalized RBF Kernels There is the notion of Generalized RBF Kernels, for example in "Towards Optimal Bag-of-Features for Object Categorization and Semantic Video Retrieval" from Jiang (1) or in formula (2.72) in  (2).  They define: Gen. RBF Kernel: $e^{-pd(x,y)}$, where (1) says d can be any distance function and (2) requires it to be a metric.  I now have been wondering for a long time: Is a function defined by $e^{-pd(x,y)}$ where d is a metric always a Mercer's Kernel? I think in (2) it sounds like it, but if it were true, not many people know of it, since they are still looking to prove that $e^{-EMD(x,y)}$ is a kernel, where EMD = Earth Mover's Distance, which is a metric.  If its not a Mercer's Kernel - do you know of any counter example? Is there any web browser with NPAPI plugins support? As per  article, Mozilla has dropped the support of NPAPI plugins from Mozilla Firefox version 52. Is there any web browser with NPAPI plugin support? I have to use a website frequently, which uses Oracle Java plugin. I'm using Ubuntu 16.04 64 bit with Java JDK 8u121. Helps are much appreciated. Thanks. Edit1: After 3 years of asking this question, Java plugin still works fine in Palemoon v28.9.2-1 64 bit on Ubuntu 20.04 LTS. Java version is JRE 8u251 64 bit Edit2: As of 20th October 2020, Oracle completely removed Java Plugin from 8u271 JRE and JDK packages mentioned in  article. But 8u261 or prior versions works just fine. Who would get the longest road? Imagine the following setup. There are 3 (or more) players with an equally long road. What would happen if the longest road was broken? How is it decided who obtains the longest road from there on? When and where was “portfolio career“ first used? The expression  meaning:  the fact of having several part-time jobs at once, rather than one full-time job:    A portfolio career is suitable for people who want to have a variety in their work life.   (Cambridge Dictionary) Etymonline has no information about the origin of the above expression, can anyone tell me when and where it was first used? Power set of a finite set is finite proof, no cardinality of power set Prove that $\mathcal{P}(A)$ of a finite set $A$ is finite.      I need to prove this without using the cardinality of $\mathcal{P}(A)$.  This is my attempt, which is by induction: $\newcommand{\lbrac}[1]{\left(#1\right)}$ $\newcommand{\sett}[1]{\left\{#1\right\}}$ $\newcommand{\pset}[1]{\mathcal{P}\lbrac{#1}}$ Proof by induction over cardinality.  If $A = \varnothing$, then $\pset{A} = \sett{\varnothing}$, which is finite.  Suppose that for a set $A$ of cardinality $n$, $\pset{A}$ is finite.  Let $A$ be a set of cardinality $n+1$. $A$ is not empty, since it is of cardinality $n+1 &gt; 0$, and therefore pick some $x\in A$. It follows that $A = \lbrac{A-\sett{x}}\cup\sett{x}$. We claim that $$ \pset{A} = \pset{\lbrac{A - \sett{x}}\cup\sett{x}} = \pset{A - \sett{x}}\cup\sett{C | C\in\pset{A}\wedge x\in C} $$ Suppose $B\in\pset{A} = \pset{\lbrac{A-\sett{x}}\cup{x}}$. Then either $x\in B$ or $x\not\in B$. If $x\in B$, then $x\in B \wedge B\in\pset{A}\Rightarrow B\in C$. If $x\not\in B$ then $B\subseteq A - \sett{x}$.  \newline Either way, $B\in \pset{A - \sett{x}}\cup\sett{C | C\in\pset{A}\wedge x\in C}\Rightarrow \pset{A}\subseteq\pset{A - \sett{x}}\cup\sett{C | C\in\pset{A}\wedge x\in C}$.  Suppose $B\in\pset{A - \sett{x}}\cup\sett{C | C\in\pset{A}\wedge x\in C}$. Then either $B\in\pset{A-\sett{x}}$ or $B\in\sett{C | C\in\pset{A}\wedge x\in C}$ (or both).  If $B\in\pset{A-\sett{x}}$, then $B\subseteq(A-\sett{x})\cup\sett{x} = A$, and if $B\in\sett{C | C\in\pset{A}\wedge x\in C}$, then by definition, $B\subseteq A$. Either way, we get that $B\in\pset{A} \Rightarrow \pset{A - \sett{x}}\cup\sett{C | C\in\pset{A}\wedge x\in C} \subseteq \pset{A}$.  Since we have shown both sets are contained in each other, they are equal.  My goal is to now prove that $\sett{C|C\in\pset{A} \wedge x\in C}$ is finite. I didn't manage to do so without non rigorous claims that could also "prove" the main question.  If this set is finite, and by induction hypothesis $\pset{A - \sett{x}}$ is finite, I'll be done.  Any ideas on how to prove $\sett{C|C\in\pset{A} \wedge x\in C}$ is finite? "elements required by agent" is "required" here an adjective or verb? "elements required by agent" is "required" here an adjective or verb?  another example "elements expressed by person". How can I attach a file to a post? Shape of a string/chain/cable/rope/wire? The height of a string in a gravitational field in 2-dimensions is bounded by $h(x_0)=h(x_l)=0$ (nails in the wall)  and also $\int_0^l ds= l$. ($h(0)=h(l)=0$, if you take $h$ as a function of arc length) .  What shape does it take?  My try so far: minimise potential energy of the whole string,  $$J(x,h, \dot{h})=\int_0^l gh(x) \rho \frac{ds}{l}=\frac{g \rho }{l}\int_0^l h(x) \sqrt{1+\dot{h}^2} dx$$  With the constraint  $$\int_0^l \sqrt{1+\dot{h}^2} dx- l=0$$ If it helps, it's evident that $\dot{h}(\frac{l}{2})=0$.  Generally, this kind of equation is a case of a constrained variational problem, meaning that the integrand in  $$\int_0^l \frac{g \rho }{l}h(x) \sqrt{1+\dot{h}^2} +\lambda(\int_0^l \sqrt{1+\dot{h}^2} dx- l)dx$$  Must satisfy the Euler Lagrange equation. The constraint must also be satisfied.  But, in truth, by this point I am clueless. $\lambda$ is worked through $\nabla J  = \lambda \nabla(\int_0^l \sqrt{1+\dot{h}^2} dx- l)$. I have tried this , but get nonsensical answers.  Is this method the best? If so, in what ways am I going about it wrongly thusfar? How can I make Devanagari fonts render properly in Ubuntu 16.04? Devanagari fonts appear broken like this:     It should appear this way    I have the same problem in browsers and office applications.  Is there any way to fix it? Xubuntu or Lubuntu on a Mac mini? My Mac mini doesn't have sufficient hardware for Ubuntu 11.04 (specifically Unity I think), and so I have to use the classic environment, which is fine, but it seems to run slower on 11.04 (I'm upgrading now to 11.10).  However, I heard  that if it runs slow I should use Xubuntu or Lubuntu.   So my question is:    What is the best way to upgrade from Ubuntu 11.10 to Xubuntu or Lubuntu and which one would be better for a late 2005 model Mac Mini PPC? I have trouble on this question: "Characterize the groups G for which the map $$\iota: G \to G$$ sending $$x \mapsto x^{-1}$$ for all $x \in G$, is an automorphism of $G$." From  post I have seen that $G$ must be abelian. Can anyone propose another characteristic of $G$ that I can derive from the given conditions besides abelian? Thank you so much!! New messages flagged blue bubble does not go away When someone flags a message in chat all 10k+ users in chat get a little blue bubble to vote on. It shows up in the upper left hand corner of your gravatar (which is in the bottom left of the page).  When someone flags a message and it shows up, if I wait for a second to click on it, and then click on it, and it has already been handled, it shows the message  "There are no flags to display."  In the past, after showing this message, the blue (1) would disappear. However, lately it has not been going away and requires a page refresh in order to remove. Can this be fixed?  This issue is addressed here:  from September 12th 2012. But since it is still occurring 10 months later, I believe the cause is different. Limit of ${a_n}^{1/n}$ is equal to $\lim_{n\to\infty} a_{n+1}/a_n$ Today my lecturer put up on the board that:  If $\lim\limits_{n\to\infty}\frac{a_{n+1}}{a_n}$ exists and $a_n&gt;0$ then   $\displaystyle \limsup\limits_{n\to\infty}\left(a_n^{\frac{1}{n}}\right)=\lim_{n\to\infty}\frac{a_{n+1}}{a_n}$  however I am not sure why this is true, can somebody give me a hint or something as to how to go about proving this.  thanks for any help Let $f : \mathbb R^n \rightarrow \mathbb R$ be a measurable function.  We know that $f$ is not necessarily locally integrable - but how hard can a measurable $f$ fail to be so? For example, is it true that $f$ is locally integrable outside of a negligible set $N \subset \mathbb R^n$?   Edit: In consideration of the comment by zhs, let me correct the phrasing of the question. I was originally wondering whether the 'singular' behaviour of a measurable function can be localized to a 'small' set.   A motivational example is $f(x) = 1/x$ over the real line. It is locally integrable in the complement of the origin. Hence, a conceivable phenomenon, which I had in mind originally when asking the question, could be that a measurable $f$ is integrable over open sets that are compactly contained in the complement of some negligible sets.