create a team rails 3
Teams of users rails app
What are the differences between "lay" and "lie"? How can swapoff be that slow? Somehow I happened to swap out 14 GB of memory. After having killed the culprit, I have tons of free memory again, so I thought I could  again. So with 5 GB out of 32 GB used and 14 GB of swap space used, I ran swapoff -a.... and 4 hours later about half of the work was finished.  This means less that 1 MB/s, while I can easily copy 200 MB/s. My swap is encrypted but so are all normal partitions and with  it leads to no noticeable CPU load (and filling the swap space took only a few minutes). I see that there's no special reason to optimize swapoff, however I wonder how it could get that slow?    Just adding some more data: My main memory is 32 GB and I have 32 GB swap space on each of 4 harddisks (surely an overkill, but who cares?). The whole swap space can be  (decrypted and) read in less than 5 minutes:  time -p sudo sh -c 'for i in /dev/mapper/cryptswap?; do md5sum $i &amp; done; wait' 014a2b7ef300e11094134785e1d882af  /dev/mapper/cryptswap1 a6d8ef09203c1d8d459109ff93b6627c  /dev/mapper/cryptswap4 05aff81f8d276ddf07cf26619726a405  /dev/mapper/cryptswap3 e7f606449327b9a016e88d46049c0c9a  /dev/mapper/cryptswap2 real 264.27   Reading a part of a partition can't be slower than reading it all. Yet reading about 1/10th of it takes about 100 times longer.  I observed that during swapoff both the CPU was mostly idle (maybe 10% of one core) and so were the disks ("measured" by the LEDs). I also saw that the swap spaces were turned off one after the other. Faithful group actions for singleton group or for empty set Let $G$ be a group, possibly a singleton. Let $M$ be a set, possibly empty. Let $\mu: M \times G \to M$ be a right group action. Let $1_G$ be the identity of $G$.  I understand 's second definition of faithful as follows:     $\mu$ is faithful if for each $g \in G$ such that $g \ne 1_G$, there exists $x \in M$ such that $\mu(x,g) \ne x$. $\tag{1}$   Later  says if $\mu$ is free and $M$ is a non-empty set, then $\mu$ is faithful.  Question: Given the idea that we can have $M$ as an empty set, I would like to clarify: Are these correct?   If $G$ is a singleton, then every action $\mu$ is faithful, whether or not $M$ is empty. If $G$ is not a singleton, but $M$ is empty, then every action $\mu$ is not faithful. If $R$ is a local ring and $M$ and $N$ are finitely generated $R$-modules such that $M\otimes N=0$ then how does it follow from Nakayama's lemma that either $M=0$ or $N=0$?    This is an exercise in Atiyah and Macdonald. The part I could not show in the hints is $({M{\otimes}_R N)}_{k}=0$ implies $M_{k}{\otimes }_{k} N_{k}=0$, where $k=R/\mathfrak m$ and $\mathfrak m$ is the maximal ideal of $R$. Link broken on desktop but work on nautilus file manger I created a shortcut to a text file called &quot;imp&quot; on right-clicking it from the default file manager everything works well. But on clicking it on the desktop I get this  Any Idea why? How do I rip audio from a DVD? How to copy a file to multiple directories using the gnu cp command What are 'user' and 'system' times measuring in R system.time(exp) output? Using InDesign CS6, how can I simultaneously edit A4 and A5 versions of a poster? I'm on Adobe Creative Cloud, so I have the latest InDesign, and I'm attempting to design a poster for my choir's next concert. Traditionally, I've done this in Photoshop, in two separate files, however I've recently started using InDesign after converting to it to create wedding albums through Blurb.  I've created an A4 document, and created an alternate-layout for it in A5. I've then lined them up side-by-side, and I've added a black frame to the A4 page, to act as the black background for my page (by the way, feel free to advise on better ways to do this).  My assumption is that I've failed to understand how this works, as I was hoping that I'd magically get a black frame on the A5 version, and that I could use liquid layout to get this to automatically scale (along with all other elements), in order to create the two versions simultaneously.  All help/advice would be greatly appreciated! Proof that Epicycloids are Algebraic Curves? Epicycloids are most commonly described by the parametric equations,   $x(t) = (R + a)\cos(t) – a \cos \left(\frac{R + a}{a} t \right),$  $y(t) = (R + a)\sin(t) – a \sin \left(\frac{R + a}{a} t \right).$  Where $R$ is the radius of the fixed circle and $a$ is the radius of the rolling circle.   With $R = ka$ we also have,   $x(t) = a[(k + 1)\cos(t) - \cos((k + 1)t)],$  $y(t) = a[(k + 1)\sin(t) - \sin((k + 1)t)].$  Several books discussing epicycloids mention that if the ratio of the radii of the circles $\left( \frac{R}{a} = k \right)$ is rational, then they are algebraic curves. However, I’ve only been able to find the Cartesian equations for the cardioid, nephroid and ranunculoid. With the cardioid being,   $(ax + x^2 + y^2)^2 = a^2(x^2 + y^2).$   The nephroid,   $(-4a^2 + x^2 + y^2)^3 = 108a^4y^2.$  And the ranunculoid,   $-52521875a^{12} – 1286250a^{10} (x^2 + y^2) – 32025a^8 (x^2 + y^2)^2 + 93312a^7 (x^5 – 10x^3y^2 + 5xy^4) – 812a^6 (x^2 + y^2)^3 – 21a^4 (x^2 + y^2)^4 – 42a^2(x^2 + y^2)^5 + (x^2 + y^2)^6 = 0.$  Clearly this doesn’t cover all epicycloids where $\frac{R}{a}$ is rational.   What is the proof that shows that epicycloids, where the ratio of the radii are rational, are algebraic curves? Sometimes I found that writing just "J. Doe" may lead, in a justified line with few words, to a big space between the initial and the surname. Using J.\,Doe looks ok but I would like to know if there is a general rule for spacing between initials and surnames. Basically, I acidentally spawned too many ArmorStands due to a wrong code writing , resulting in the game crashing, and wanted to know how to delete those armorstands from the World save folder. They hava names and I belive they also have a scoreboard set, if that helps.   I have already tried to open the world but it crashes, I tried to open a server (Since it worked the last time I tried it) and killing it all from the console but, different from the last time, it crashed before killing them and now I just tried MCedit but it crashes as well. Ignore Pulses Less than a Given Width in a Pulse Train Let's say I have a 5V pulse train that varies between 0 and 75000 pulses per second. Pulse width, let's say, is 5 microseconds. How could I calculate or determine the best way to filter out all pulses less than 4 microseconds in width? Change Windows 7/8/10 system language - welcome screen, login, etc "None is" or "none are" I know this subject was discussed for many times, but I still don't get it..  I've read in a book that we can use "I've got" instead of "I have" for possesion and it gave some examples,      I've got an English book.   I've got a red car.   So I understand that it can be used only for possession of physical objects, but I saw it used in sentences like "I've got something to say", is it correct? I hope it's not a stupid question..Thank you very much! Levels or First Differences, VECM or VAR for Ultimate Impulse Response Functions? How do I get the current date and time in PHP? Which PHP function can return the current date/time? If the series $\sum_0^\infty a_n$ converges, then so does $\sum_1^\infty \frac{\sqrt{a_n}}{n} $ Problem:      Suppose that for every $n\in\mathbb{N}$, $a_n\in\mathbb{R}$ and $a_n\ge 0$. Given that   $$\sum_0^\infty a_n$$   converges, show that    $$\sum_1^\infty \frac{\sqrt{a_n}}{n} $$   converges.   Source: Rudin, Principles of Mathematical Analysis, Chapter 3, Exercise 7. Why am I getting "size mismatch" errors from the Iceland mirror? After installing Ubuntu 12.04 (clean install) I fetch a bunch of program via synaptic (installed specially), all programs worked except Gimp 2.8. So I tried purging Gimp, install again (no luck). Checked broken packages and reinstalled them. When using the Software center I get this MSG:  Failed to fetch http://is.archive.ubuntu.com/ubuntu/pool/main/o/openexr/libopenexr6_1.6.1-4.1_amd64.deb Size mismatch   Tried also this:  sudo apt-get purge gimp* sudo add-apt-repository ppa:otto-kesselgulasch/gimp sudo apt-get update sudo apt-get install gimp   And get this MSG:  Failed to fetch http://is.archive.ubuntu.com/ubuntu/pool/main/o/openexr/libopenexr6_1.6.1-4.1_amd64.deb  Size mismatch E: Unable to fetch some archives, maybe run apt-get update or try with --fix-missing?   I am wondering if the Icelandic Archive has an outdated version or something?   would really like to install Gimp 2.8 but Gimp 2.6 is OK to.   I am also wondering if I am doing something wrong?