LaTeX does not render the picture?
I'm having trouble with \includegraphics I'm using MacTeX
How to fill a rectangular hole with an even amount of vertices on either side? I tried crating faces but it left missing edges. In the end I was left with all the right lines but there was no vertex in the center.    Here's a follow up image in case you're wondering what I mean. Notice how there's no vertex in the center. I apologize if this question is posted on the wrong portion of the website, but I knew no better place to ask.  I've come to see that some effects, such as super-conduction may happen at either extremely low temperatures, or at extreme temperatures (the recent discovery of superconducting iron in the bowels of the earth, for one), and this is fascinating.  My question is: can (does?) the same principle be applied to quantum effects? Would it be applicable to, for example, say that although quantum effects happen at nano scales and below they may happen on a grand scale of say, the entire Universe (as a solitary unit)?  Can said quantum effects happen at moments of say, picoseconds after the Big Bang due to the turbulence of forces involves in such an event? Or even within the core of a dying star?  Thank you for any answers or clarification of my misinformation. How do I set an environment variable on the command line and have it appear in commands? How to determine the point of intersection of two lines? I have two lines say P1( 0, -1, 0, -1 ) and P2( -1, 0, 0, -1 ). Since I'm working in 2D, there is no Z component. The x,y,z components are normals and the w component is the distance from origin. I am not given the origin or any points on the line.  What method should I use to programmatically determine the point of intersection for these two lines? NS list does not match list from parent zone I'm attempting to figure out an error message that I got from dnsstuff.com when examining my DNS records.  The error reads as follows.     NS list does not match list from parent zone. This should be addressed because queries for this domain may require an extra lookup (and more overhead) because there is no direct relationship between the NS records at the parent and the NS records at the authoritative servers. This can cause delays. The mismatched NS list is:      nameserver ns1.domain.co. | xxx.xx.xxx.xxx is missing NS2.domain.co. | yy.yyy.yy.yyy   There are a couple questions I have regarding this.   What is the difference between a parent and authoritative zone?  In other forum posts I've seen, the seem to be used interchangeably (although that could be my misperception). What does it mean for the NS list not to match the list from the parent zone?  What is "the list from the parent zone" to which they refer? How might you recommend that I resolve this?   In case this affects any answers, I'm running Virtualmin on Ubuntu 12.04.  Any help is appreciated.  Many thanks in advance! When is $2^n \pm 1$ a perfect power Is there an easy way of showing that $2^n \pm 1$ is never a perfect power, except for $2^3 + 1 = 3^2 $?  I know that   gives the result directly, but I'm hopefully for a more elementary method.    I can show that it is never a square, except for $2^3 + 1$.  Proof: Cases $n=1, 2, 3$ are easily dealt with. Henceforth, let $n\geq4$.  $2^n -1 \equiv 3 \pmod{4}$ hence is never a square.     If $2^n +1 =x^2$, then $2^n = (x-1)(x+1)$ and both of these are powers of 2. Thus we must have $(x-1) = 2, (x+1) = 4$. This gives the solution of $2^3 + 1 = 3^2$.    Let's now do an odd prime.  Say $2^n +1 = x^p$. Then $2^n = x^p - 1 = (x-1)(x^{p-1}+x^{p-2} + \ldots +1)$, so both terms are powers of 2. We have $ x = 2^m+1$ is odd. But the other term is the sum of $p$ odd numbers, hence is odd. Since this is clearly greater than 1, we get a contradiction.  Say $2^n -1 = x^p$. Then $2^n = x^p + 1 = (x+1)(x^{p-1} - x^{p-2} + \ldots -x +1 )$, so both terms are powers of 2. We have $x = 2^m -1$ is odd. But the other term is the sum of $p$ odd numbers, hence is odd. Since $x^p + 1 \neq x+1$ except for $p=1$, this means that the term is greater than 1. Hence we get a contradiction. limit of $\lim\limits_{x \to \infty}((x+1)^a - x^a)$ Hello everybody, i couldn't figure out how to demonstrate this equation without L'Hopital i wonder if its possible.   $a \in (0,1)$ $\lim\limits_{x \to \infty}((x+1)^a - x^a) = 0$ Virtualbox Windows 10 Guest installation is freezing up in 14.04 I've installed VirtualBox using the Software Centre and I'm running a system on Ubuntu 14.04 with 8gb RAM, 64-bit dual core processor.  I want to run Windows 10, I've tried both 64 and 32 bit versions, in virtualbox. However, every time I start up windows 10 it gets to the point where the dots go round in a circle, then it freezes up and crashes back to the virtualbox manager. The only information it gives me is that the virtual machine was aborted.  I've changed the settings around a lot and nothing is working.  Any help would be appreciated.  Oh, and I've run Windows 10 technical preview on this machine before, a while ago  Thanks for any help in advance. What does functools.wraps do? When and where does Attack on Titan take place? Is the setting of "Attack on Titan" (Shingeki no kyojin) supposed to be Earth in the distant future and Titans suddenly appeared out of nowhere and devolved society to medieval level of technology? Or is this just a completely fictional setting? I read on here of an exercise in interviews known as validating a binary search tree.  How exactly does this work? What would one be looking for in validating a binary search tree? I have written a basic search tree, but never heard of this concept. Does the Hunter's Mark spell chain to multiple creatures? I'm looking to play a ranger. The Hunter's Mark spell says:     If the target drops to 0 hit points before this spell ends. you can use a bonus action on a subsequent turn of yours to mark a new creature.   Does that mean I can keep marking a new enemy each time the last one dies until the hour's up? dotted line with appropriate length for answering a question? Kindly have a look at this code   \documentclass{article} \usepackage{fontspec} \defaultfontfeatures{Ligatures=TeX} \usepackage[small,sf,bf]{titlesec}  \setromanfont{Georgia} \usepackage{amssymb}  \newcommand{\checkbox}{$\square$} \begin{document}  If appropriate \checkbox  . Why appropriate, specify? ........... If inappropriate \checkbox . Why inappropriate, specify? .............. If appropriate \checkbox . Why appropriate, specify? ...........\\ If inappropriate \checkbox . Why inappropriate, specify? ...........  \end{document}   How can I make a dotted like, of appropriate length so that it is depressed, fainter, has consistent length so that it occupies the remaining white space in the  line or has specified length. How to search the internet for terms with special characters Disable Narrator shortcut key in Windows I've install Windows 8 on a BootCamp macbook air The problem is that the command key located differently from the winkey in a normal keyboard, therefor, I keep clicking Winkey+Enter which starts the narrator (which is really annoying!)  Is there a way to disable this shortcut? Leg bisectors in a trapezoid and angle equality Let $PQRS$ be a trapezoid. The bisectors of legs $PS$ and $QR$ intersect the opposite legs at $M$ and $N$ so that triangles $PMS$ and $QNR$ are formed.  Prove that $\measuredangle PMS= \measuredangle QNR$.  The question may seem easy but I fail to move on, playing with angles didn't help. I'd appreciate some hint from somebody with an eye for geometry and triangles. Series $\sum_{n=1}^\infty \frac{n^n}{(n!)^2}$ WIFI connection not working I ran these commands:  sudo rmmod iwlwif sudo modprobe iwlwifi 11n_disable=1 sudo su echo "options iwlwifi 11n_disable=1" &gt;&gt; /etc/modprobe.d/iwlwifi.conf   Now, my WiFi connection is lost and there is no WiFi option in the network manager. How can I restore it? I have a PC who wants to jump onto an enemy in a combat situation. The player wants him to land on the (humanoid) enemy, sword drawn, and use the enemy to break his fall while plunging shortswords into it. I thought of using a straight attack roll, because it was only a 12 foot drop from the ledge to the top of the enemy. But I would imagine a lot would depend on the distance, and also whether the enemy might suspect such an attack. Also, I would expect the PC would take damage on a miss, but how about on success? get list item by id using COM sharepoint 2013 I need to get item from list sharepoint by Id I use this code and it give me all the items of the list :  &lt;script&gt;  function parseURLParams(url) {         var queryStart = url.indexOf("?") + 1,             queryEnd = url.indexOf("#") + 1 || url.length + 1,             query = url.slice(queryStart, queryEnd - 1),             pairs = query.replace(/\+/g, " ").split("&amp;"),             parms = {}, i, n, v, nv;          if (query === url || query === "") {             return;         }          for (i = 0; i &lt; pairs.length; i++) {             nv = pairs[i].split("=");             n = decodeURIComponent(nv[0]);             v = decodeURIComponent(nv[1]);              if (!parms.hasOwnProperty(n)) {                 parms[n] = [];             }              parms[n].push(nv.length === 2 ? v : null);         }         return parms;     }  $( window ).load(function() {   var urlString = document.URL;  urlParams = parseURLParams(urlString);  ExecuteOrDelayUntilScriptLoaded(retrieveActualite, "sp.js");          var siteUrl = '/sites/securite';      function retrieveActualite() {              var clientContext = new SP.ClientContext(siteUrl);             var oList = clientContext.get_web().get_lists().getByTitle('Actualite');             var camlQuery = new SP.CamlQuery();              camlQuery.set_viewXml('&lt;Query&gt;&lt;Where&gt;&lt;Eq&gt;&lt;FieldRef Name=”ID” LookupId="TRUE"/&gt;&lt;Value Type="Text"&gt;' + urlParams.IdArt[0] + '&lt;/Value&gt;&lt;/Eq&gt;&lt;/Where&gt;&lt;/Query&gt;');             this.collListItem = oList.getItems(camlQuery);             clientContext.load(collListItem);             clientContext.executeQueryAsync(onQuerySucceededActualite, onQueryFailed);         }          function onQuerySucceededActualite(sender, args) {              var listItemInfo = '';              var listItemEnumerator = collListItem.getEnumerator();             while (listItemEnumerator.moveNext()) {                 var oListItem = listItemEnumerator.get_current();                   var desc=oListItem.get_item('Description');                 $('#idArticle').append('&lt;label class="titleArticle"&gt;'+oListItem.get_item('Title')+'&lt;/label&gt; &lt;br&gt;&lt;br&gt;&lt;p class="ContenuArticle" &gt;'+desc+'&lt;/p&gt;');                          }         }          function onQueryFailed(sender, args) {              alert('Request failed. ' + args.get_message() + '\n' + args.get_stackTrace());         }       });    &lt;/script&gt;   so how can I get only the considered item ?