apt-get remove messages (triggers for shared-mime-info): Unknown media type in type '...'
How to remove warnings like `Unknown media type ...`
Photoshop CS6 Resize Rectangle with Rounded Corners This question is about Photoshop CS6. Hopefully the feature was added in this version. Before posting I looked up Google and  and  but didn't find an answer for CS6.  So the question is: Is there a feature within CS6 or a script that allows to resize a vector element with rounded corners without using the Direct Selection Tool (white arrow tool) and not changing the border radius? What would be great would be something like simply using the transform tool or something like a grid resize tool. I converted a raster image to vector in Illustrator CS6 using Image Trace then the Expand option, though when I save as an svg the image looks embossed. I suspect it's due to the layer background being white and the paths not lining up, but I'm unsure how to fix it or prove that theory without manually having to adjust every path.   This is how it looks in Illustrator before I export it:    The image looks like this when saved/exported with art optimized option: Why does the wire-frame material fades across the object? Why does the wire-frame material fades across the object?  Here is what I did - I created a new material and I selected on "Wire" and I made it shadeless. Then, I created a new material and assigned the new material on the on the object. However, doing it that way, it allows me to render both materials - "Wire" and "Surface". Then I get a fading result like this -    But I want all of the edges to be shown, not a fading result. How can I make that?  Here is the blend file if anybody wants to check it out - What do you call snow that has collected between a car body and the tire? Is there a way that I can configure Visual Studio 2008 to understand CamelCase?  Specifically, I'd like to be able to get Ctrl + right or left cursor to take me to a subsection of a variable or type name. i.e., if my cursor was at the start of this line: LongNamedExampleClass longNamed = new LongNamedExampleClass();  and I hit Ctrl + right, I'd like to jump to &quot;Named&quot; in the class name, rather than the start of the variable name.  If I hit it again, I'd like to go to &quot;Example&quot;.  I hope that makes sense. I used this navigational feature in Eclipse quite a lot, and find it difficult to unlearn something so ingrained. I'm having a heck of a time trying to disable the option  "Check for updates Automatically"  I ran composer to see what plist was being modified and it looks like ~/Library/Preferences/com.oracle.javadeployment.plist  &lt;?xml version="1.0" encoding="UTF-8"?&gt; &lt;!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN"    "http://www.apple.com/DTDs/PropertyList-1.0.dtd"&gt; &lt;plist version="1.0"&gt; &lt;dict&gt;     &lt;key&gt;/com/oracle/javadeployment/&lt;/key&gt;     &lt;dict&gt;         &lt;key&gt;deployment.macosx.check.update&lt;/key&gt;         &lt;string&gt;false&lt;/string&gt; &lt;/dict&gt; &lt;/dict&gt; &lt;/plist&gt;   So I experimented with changing that value to true or false and it would not effect the checkbox under the Java Control Panel > Update > Check for Updates Automatically  Your assistance would be much appreciated.  Initially I was looking @ /Library/Internet\ Plug-Ins/JavaAppletPlugin.plugin Show a connected metric space (X,d) is $\epsilon$-chainable for $\epsilon &gt;0$       $\epsilon$-chainable Definition      (X,d) is $\epsilon$-chainable if given any two points $a,b \in X$, $\exists$ a finite set $\{ x_0,x_1,...,x_n\}$ of points in X with $x_0 = a$, $x_n=b$ and $d(x_{n-1},x_n)&lt;\epsilon$, $\forall$ n      Clopen Definition      A set is clopen $iff$ its boundary is empty      Connected Metric Definition      Let $(X,d)$ be a metric space. It is connected $iff$ it has no proper subsets which are clopen      The following are equivalent:         $X$ is connected   The only subsets of $X$ that are clopen are $\emptyset$ and $X$   $\nexists$ non-empty, disjoint, open sets $A$ and $B$ such that $X=A\bigcup B$   $\nexists$ non-empty, disjoint, closed sets $A$ and $B$ such that $X=A\bigcup B$         Theorem      Let $(X,d)$ be a metric space, and let $S$ be any subset of $X$. Then $S$ is closed $iff$ $S^c$ is open.     So how would someone show this exactly?  Let the set $A$ be the set of all elements in $(X,d)$ that can be reached from $a\in X$ in a finite number of steps with length less than $\epsilon$.  Does this mean that there should be no isolated points? (an isolated point would be at distance infinity from any other point, or distance zero from itself, since $\epsilon &gt;0$ we don't want this?)  Knowing that $X$ is connected $\implies$the only subsets of X that are clopen are $\emptyset$ and $X$  Also, by construction of A;   A is the set of all $\epsilon$-chains between any element and $a$  And, so $A^c = \emptyset$ if $A$ was $\epsilon$-chainable (because A has to have a path from all elements to a, for this to be true, the complement wouldn't have anything in it)  Leaving only $A$ as the remaining clopen set  Does this make any sense? Or should an alternative be used, and how to formalize it.  Thanks. How do I get evolution items like King's Rock? What are the big differences among the D&D editions? I've been out of the loop for a while, and I used to play AD&amp;D 2nd ed, but today I find there are a lot of different versions that have fairly different gameplay.   Can anyone summarize the really big differences, the ones (maybe top three?) that are the 'killer features' of the different editions? What makes each edition play differently than the others? Can I publish parts of the Ph.D thesis as a paper in a journal? Importing only certain rows between spreadsheet documents Document 1 has many rows of data.  How do I import into document 2 only those rows that have a certain value in column C? Minor grid in pgfplot not showing when specifying ticks manualy Firstly I would like a minor tick between every major tick in my pgfplots graph (and minor grids). I wrote minor tick num=1 but it doesn't work. I am not using a logarithmic axis so it is unrelated to other questions.  Secondly, why is the tick label "1" missing for each axis? How do I get that to display?     \documentclass{standalone} \usepackage{pgfplots} \begin{document} \begin{tikzpicture}  \begin{axis}[% footnotesize, width=4in, height=4in, axis equal, scale only axis, separate axis lines, grid=both, every outer x axis line/.append style={black}, every x tick label/.append style={font=\color{black}}, xmin=0, xmax=1, xlabel={X}, every outer y axis line/.append style={black}, every y tick label/.append style={font=\color{black}}, ymin=0, ymax=1, ylabel={Y}, minor tick num=1, xtick={0,0.1,...,1}, ytick={0,0.1,...,1}, axis background/.style={fill=white}, legend style={at={(0.97,0.03)},anchor=south east,legend cell align=left,align=left,fill=white} ]  \end{axis}  \end{tikzpicture}% \end{document} Show *realtime* mouse cursor coordinates? (Cursor mod / overlay) Also, copy to clipboard? I'm looking for a solution that would display the current mouse cursor coordinates in realtime (i.e. NOT xdotool and NOT xev).  I need to move the mouse to a certain position, then press Alt-Tab to flip to another window and record the coordinates there. (This would not move the mouse, so the coordinate display would stay the same).  There's a Windows program that works BEAUTIFULLY for this purpose -   ...but it doesn't even start up in Wine.  Alternately, instead of displaying the coordinates, if this solution could copy the coordinates (in XXX,YYY format) to the clipboard, upon pressing a hotkey, that would be even better.  Any suggestions would be much appreciated!  P.S. I'm running Ubuntu 12.04 LTS. How to Deserialize XML document ꕺ (U+A57A Vai Syllable Kpoo) is allowed in character names as the last character I believe this should be changed so ꕺ can not be the last character of a name at minimum. This could be a bug in my opinion because it provides confusion with diamond mods.  Although other symbols are blocked from what I understand but this does technically look different.  I have changed my name to such to demonstrate the confusion at least temporarily.  They say imitation is the greatest form of flattery so maybe this should be accepted because to anyone who is familiar with SO I doubt this would cause an issue. novel with psi slavery Name the novel, 197x.  Setting is a world of human(oid)s most of whom have the psi ability to enslave weaker others.  (Maybe the word slave and its derivatives are not used.)  Masters and slaves form a tree rather than a dichotomy; everyone delegates as much as they can. The protagonist is an outworlder on a mission, maybe simply doing a survey.  He wears the green robe of a native subculture who lack the power (or maybe they renounce it?) and are immune to it – by law or custom, I think, rather than by nature. His host or primary contact is Jael Forty of Lant, the number being how many slaves he can control; it can fluctuate. Is there a way to make IE8 honour opacity on an `:before` pseudo element? Let's say we have $x^2=25$ So we have two real roots ie $+5$ and $-5$.  But if we were to differentiate on both sides with respect to $x$ we'll have the equation $2x=0$ which gives us the only root as $x=0$.  So does differentiating on both sides of an equation alter it? If it does, then how do we conveniently do it in Integration by substitutions? If not then what exactly is going on here ? Block of equations with only some being subequations I'm trying to make a block of equations where the first two are standalone equations, and the second two are subequations, ie  X=XXXX (1)  X=XXXX (2)  X=XXXX (3a)  =XXXX (3b)  I'm using the amsmath package, with align and subequation, but I can't figure out how to do this without making a separate block for Eqs 1-2 and one for Eqs 3a-3b. That solution is unsatisfactory, because then there is a big vertical gap between the two blocks, and I want them to appear all as one.  Here's the code I have so far, in case it's unclear.  \begin{align} T(x) &amp;= \frac{m}{2{k_{B}}} \left\langle \mathbf{\tilde{v}}{(\mathbf{x}_{i},t)}^{2} \right\rangle\\  \mathbf{u}(x) &amp;= \left\langle \mathbf{v}_{i}(\mathbf{x}_{i},t) \right\rangle \end{align} \begin{subequations}  \begin{align} P_{xy}(x) &amp;= \frac{1}{A} \left\langle \sum\limits_{i} {m \tilde{v}_{i,x} \tilde{v}_{i,y}} + \frac{1}{2} \sum\limits_{i} {\sum\limits_{j\ne i} {r_{ij,y} F_{ij,x}}} \right\rangle \\ \begin{split}  &amp;=\frac{m}{A} \Bigg\langle \sum\limits_{i}{{{{\tilde{v}}}_{i,x}}{{{\tilde{v}}}_{i,y}}} + \frac{a^3\omega _{pd}^2}{4} \\  &amp;\quad \times \sum\limits_{i}{\sum\limits_{j\ne i}{r_{ij,y}{\left\{ \frac{e^{(-{{r}_{ij}}/\lambda )}}{{{r}_{ij}}}\left( \frac{1}{r_{ij}}+\frac{1}{\lambda} \right) \right\}_{x}}}} \Bigg\rangle \end{split} \end{align} \end{subequations}   Any suggestions would be greatly appreciated! There a  who has no valid parent user. It is indicated that his chat account is associated to a Maths.SE account, which does not appear to exist. The user was still able to chat. Is it normal? If it's a bug, could someone look into it?  Edit: if you browse the Google cache for users named Skullpatrol, it turns out a single series of associated accounts. The user is now named . I don't know what went wrong, maybe an account merge or something like that, but it needs someone from staff looking into it with some superpowers. I also tried to update the parent user of the chat account to this &quot;Rob&quot; profile, but the interface goes all buggy on me (works for other users, fails only for this one):