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I'm running a VPS of a german provider and want to switch from Ubuntu to CentOS. There I tried to install firewalld (was not preinstalled), but it always fails with the error  ERROR: Failed to load nf_conntrack module: modprobe: ERROR: could not find module by name='nf_conntrack' modprobe: ERROR: could not insert 'nf_conntrack': Function not implemented modprobe: ERROR: Error running install command for nf_conntrack modprobe: ERROR: could not insert 'nf_conntrack': Operation not permitted   Obviously the nf_conntrack kernel module was not found. Since this is a VPS, I cannot tinker with the kernel modules. On the support site of my provider I found a list of available kernel modules, for example:  ip_conntrack_netbios_ns ipt_conntrack    ip_conntrack    ip_conntrack_ftp    ip_conntrack_irc   Since nf_conntrack is not listed here, does that mean, that I cannot use firewalld? Is it possible to run it without this module?  I guess I could use iptables, if I wanted to (it seems to run correctly). But as I have more experience with firewalld, I would like to stick with it.    CentOS Linux release 7.7.1908 (Core)  uname -a: Linux xxxxxx.xxxxxxxx.xxx 3.10.0-042stab140.1 #1 SMP Thu Aug 15 13:32:22 MSK 2019 x86_64 x86_64 x86_64 GNU/Linux I don't know which buttons I have to click or what key combination to type to calculate a cube root. How to prevent Windows from entering idle state? If the matrix $A^3 = 0$, is $A$ singular? Are these plural or singular? Does $\langle\Omega|\mathrm{e}^{\mathrm{i}Px}=\langle\Omega|\mathrm{e}^{\mathrm{i}0x}$? $(\langle\Omega| =$ ground state of the interacting theory) Let $\langle\Omega|$ be the ground state of an interacting theory, just as Peskin &amp; Schroeder(PS) describes on page 82 and page 213. On page 213 PS do the following   $$\tag{1}\langle\Omega|\phi(x)|\lambda_{\vec{p}}\rangle = \langle\Omega|\exp(+\mathrm{i}Px)\phi(0)\exp(-\mathrm{i}Px)|\lambda_{\vec{p}}\rangle \\ =\langle\Omega|\phi(0)|\lambda_{0}\rangle\exp(-\mathrm{i}px)\bigg|_{p^0=E_{\vec{p}}} $$  In the above $|\lambda_0\rangle$ is an eigenstate of the full interacting hamiltonian $H$. The ket $|\lambda_{\vec{p}}\rangle$ is the boost of $|\lambda_0\rangle$ with momentum $\vec{p}.$ Furthermore $E_{\vec{p}} = \sqrt{p^2+m_\lambda^2}$ and $\vec{P}|\lambda_0\rangle = 0.$  I assume PS used $$\tag{2}\langle\Omega|\mathrm{e}^{\mathrm{i}Px}=\langle\Omega|\mathrm{e}^{\mathrm{i}0x}$$ in $(1)$.   Is $(2)$ true?   I thought $\langle0|\mathrm{e}^{\mathrm{i}Px}=\langle0|\mathrm{e}^{\mathrm{i}0x}$ where $\langle0|$ is the ground state of the free theory.   I hope I have provided enough info for the question to make sense. How to check if a point is inside a rectangle? I need to somehow retrieve the client's IP address using JavaScript; no server side code, not even SSI.  However, I'm not against using a free 3rd party script/service. I downloaded Heroku from Heroku toolbelt using  wget -qO- https://toolbelt.heroku.com/install-ubuntu.sh | sh   in the terminal, which they recommended on their site.   My Ubuntu (14.04.1) didn't recognize the -q0-, so I took it out.  It then seemed to download fine - I see the  in the directory I was in when i downloaded it.   Now, however, it still doesn't recognize heroku as a command.  It also won't show me where it is with the 'whereis' command.  But when I look in the current directory with ls -a, it shows up.  It seems to be there.   How do I install it? Attending an academic conference is what type of travel? I am planning to travel to Portugal to attend an academic conference and in that regard needed a short-stay Schengen visa. The visa application has a field "Purpose of Travel" with the following options:   - Business - Sports - Cultural - Other - Study - Visiting family or friends - Medical reasons - Official visit - Transit - Airport transit - Tourism   I am attending the conference to present the research I am conducting as a part of my PhD. So "Study" is the closest in my opinion. But I don't want the Embassy to misconstrue that it is for studying at a university in Portugal. In that case, would "Business" be the right option to choose? Are ideal hashes possible to create? Do spice containers need to be hermetic? Spice containers purchase  I'm planning on upgrading my spice storage. Reading some advice online (e.g. , and ) I came to the conclusion that spice containers should:   Not be exposed to direct sunlight and high temperatures Be airtight   Which means that either you store it inside of some closed cupboard/wardrobe/room or you have containers which do block light and are in a relatively shady place. And the containers need to be airtight.  Available solutions  I've been browsing for some containers available online in my country and the 2 most sensible options I've seen are these:       The problem  The first one is hermetic (it has some rubber around the lid) but it's clear glass. The other one does not have the rubber, just a regular twist-off lid, but it's amber glass.  It'll be hard for me to find any space inside of cupboards to store all of my spices (I need at least 30), so I'd rather buy amber glass container, which I believe will effectively block the sunlight, even when kept on the counter. But I can't find any hermetic amber-glass containers, only ones with regular lid.  The question  Is that regular twist-off lid enough to keep spices airtight and fresh? Or should I focus on buying a hermetic container (like the one in clear glass). I could then for example paint them black to block the sunlight. Which piece of equipment is holding me back? I am primarily an amateur photographer but I do take small jobs from time to time.  I'm looking to upgrade my equipment but I'm not sure if I should be spending money on my body, glass, or both.  I have two common issues that I'd like to improve.   I shoot a lot at ice rinks and find that even in servo mode I get a lot of shots that are slightly out of focus.  I try to keep the AF target on face masks but many shots will come out focused an inch or two off (ears, hands, etc).  I'm shooting F/1.8-F/2.8 to get action stopping shutter speeds so you can really tell when the focus is even a hair off.  I don't know if this is a limitation of my camera, lens, or the human operator. Most of my paid work is indoors shooting candids where a flash is inappropriate.  I feel like I need to use a higher F-number to get more subject in focus but I usually can't do it without upping to ISO 3200 unless I'm using a flash.  By the time I clean up the high ISO noise in Camera Raw I end up with an image lacking detail.  So far this hasn't been a big problem because the photos are typically used in magazine prints only an inch or two wide but it's still driving me nuts.   Here is the equipment currently in my bag:   Canon Rebel T2i Canon EF-S 18-55mm f/3.5-5.6 II (no IS)   Collecting dust, came with my old Rebel XTi.  Canon EF-S 18-135mm f/3.5-5.6 IS   Purchased with my T2i.  This is my workhorse lens but I'm disappointed with the soft images it produces at higher focal lengths.  Stopping down makes the images acceptable but that's not always an option.  My eyes want more contrast and color but considering how inexpensive this lens is I can't really complain.  Canon EF 70-300mm f/4-5.6 IS USM   This was purchased with an older camera and doesn't get used much anymore.  The images are too soft beyond 200mm and the AF seems sluggish.  Canon EF 50mm f/1.4 USM   I am extremely happy with the images I get from this lens.  I use it indoors all the time and also paired with extension tubes for some macro work.  Some of my best ice hockey images have been from this lens even though I didn't have sports in mind for this lens.    My initial plan was to upgrade to a 60D or 7D body but after doing some reading it occurred to me that I might invest in better glass first.  I'm unsure of what will help improve focusing, image quality, high ISO shooting, etc.  Maybe it's a new camera, new glass, photography lessons, or a little of everything?  I'm looking to keep my next round of purchases under $3,000 and am willing to trade in some of my used equipment to offset costs.  Would anyone care to make a recommendation?  I'm looking at the EOS 60D and 7D bodies.  Not sure if the 7D is overkill for my needs.  I'm also looking at the EF 24-70mm f/2.8L USM lens to be my new workhorse but I'm concerned that it may not be wide enough on an APS-C body and the lack of IS might be an issue.  There's also the EF 70-200mm f/2.8L IS II USM but I'm thinking it wouldn't be wise to spend all my budget on that lens right now (or maybe not?). Does someone falling into a black hole see the end of the universe? This question was prompted by . Notoriously, if you calculate the Schwarzschild coordinate time for anything, matter or light, to reach the event horizon the result is infinite. This implies that the universe ages by an infinite time before someone falling into the black hole reaches the event horizon, so could that person see the universe age by an infinite time?  To be more precise, suppose the observer starts falling from rest at time $t = 0$ and some initial distance $r &gt; r_s$. If we wait for some time $T$ then shine a light ray at the falling observer. Will the light ray always reach the falling observer before they cross the event horizon? If not, what is the formula for the longest time $T$ that we can wait and still be sure the ray will catch the observer? If $T$ is not bounded it implies that observer could indeed see the end of the universe.  I can think of a qualitative argument for an upper limit on $T$, but I'm not sure how sound my argument is. The proper time for the observer to fall to the event horizon is finite - call this $\tau$. The proper time for the light ray to reach the horizon is zero, therefore the light ray will reach the observer before they cross the event horizon only if $T &lt; \tau$. Hence $T$ is bounded and the observer won't see the end of the universe.  I think a more rigorous approach would be to determine the equations of motion (in the Schwarzschild coordinates) for the falling observer and the light ray, and then find the condition for the light to reach the falling observer at some distance $\epsilon$ from the event horizon. Then take the limit as $\epsilon \rightarrow 0$. In principle this seems straightforward, but in practice the algebra rapidly defeated me. Even for a light ray the radial distance:time equation isn't closed form (Wolfram claims it needs the $W$ function) and for the falling observer the calculation is even harder. How to determine the size of a package while using apt prior to downloading? When using apt-get install &lt;package_name&gt;, and there are dependencies that need to be downloaded, the terminal outputs names of additional packages and total size, and asks for confirmation before downloading.   But, when dependencies are satisfied and nothing but the named package needs to be downloaded there is no size output and no confirmation.  When using Synaptic, I can see the total size that new packages that will use after installation but no way to see the size that needs to be downloaded, except to go from package to package and use properties to see the compressed size.  I would like to know if there is a way to see the size of a package(s) in terminal and Synaptic prior to downloading and installing it/them? Good review audit has "possible spam" warning? I was looking through someone's edit history and I was looking at :    Why does it give this notice, while at the same time saying that it's a high-quality post? I am running a fresh install of Linux Mint Nadia (14). I am following the instructions on Vagrant  but have gotten stuck on the . It seems the Vagrant box cannot connect outside and so I can't install anything using either Chef or Puppet.  In the basic Vagrant resolve.conf contains nameserver 10.0.2.3. But with that set I can't ping us.archive.ubuntu.com.  If I change it to 8.8.8.8 then I can ping us.archive.ubuntu.com but it does not stay set, and after a reboot it changes back to 10.0.2.3 - so provisioning fails again.  Ideally I would like for 10.0.2.3 to work on my setup. Failing that I would like a way to permanently change resolv.conf so that I can do provisioning. Why, microscopically, is the voltage drop across a resistor affected by the current through it? If voltage is a potential difference, describing how much energy will be lost per unit charge as charge carriers pass through the resistor, why would the rate at which charge flows (i.e. current, $=dq/dt$) affect the amount of energy lost per unit charge?  I suppose I am asking why a quasi-"extensive" property of the system (current) would affect a quasi-"intensive" property of the system (voltage drop across the resistor).  Apologies if the answer is obvious; I was having trouble understanding why the rate of charge flow would factor into voltage drop whilst trying to rationalize Ohm's law for myself. Google results for sponsee have scattered definitions in unreliable sources, so it does not appear that is a real word. I'm looking for something similar, a single word.  The specific context is a social group membership application where new members must be sponsored (as in definition 2, here - "one who assumes responsibility for some other person or thing") by existing members. I am looking for a single word to describe the target of such a sponsorship. I am about to sponsor a fraternity, but I would like to have a more general word for what I'm sponsoring. Next time, the fraternity could well be a study club, or something else.  Therefore, what is the sponsored party also called? E.g. if I sponsor somebody, that person is my __? I've been studying the Cox Proportional Hazards model, and  this question is glossed over in most texts.    Cox proposed fitting the coefficients of the Hazard function using a partial likelihood method, but why not just fit the coefficients of a parametric Survival function using the maximum likelihood method and a linear model?    In any cases where you have censored data, you could just find the area under the curve.  For example, if your estimate is 380 with standard deviation of 80, and a sample is censored >300, then there is an 84% probability for that sample in the likelihood calculation assuming normal error.