split() deprecated. How to convert?
Deprecated: Function split() is deprecated. How to rewrite this statement?
Why doesn't my systemd user unit start at boot? Control Cycles/Eevee material nodes and material properties using python? Defaults to true.  If set to true replaces all instances of known swear words with replacements (comical or * based). If false renders the content as originally presented.  Benefits:    Reduces moderation requirements necessary to ensure that people behind corporate firewalls are not blocked by an errent swear word.   Stops idiots like me complaining about it. Can 'AMD-only' RAM really be restricted to AMD chipsets, and if so, why? As I understand it Q&amp;A style questions are  but a self answered question should be judged independently of the answer. Often after I've solved a problem I would like to share the question and answer on stack overflow (and have on a couple of occasions) but how to show &quot;minimal understanding of the problem&quot; is always challenging. For example I have been looking into the following question  How can I plot a straight line in the JMonkey Engine library I'm trying to plot straight lines between vertices that I specify using the JMonkey Engine 3D graphics library. So for example if I was to try to plot between: (2,0,0) (-1,0,1) (0,1,1) (1,1,1) (1,4,0) Then I would get:   This is something I do (and forget how to do) relatively often and the answer is harder to find than you'd imagine ( provides everything needed to figure it out but its spread out over several posts and isn't a complete solution on its own). Therefore I want to provide a Q&amp;A for it but at present this question feels like it would fail the minimal understanding test  Questions must demonstrate a minimal understanding of the problem being solved. Tell us what you've tried to do, why it didn't work, and how it should work  Should I make up some imaginary problem? (Probably the final source code messed up a bit) Or mention in the question that I’m self answering to assuage some of the normal &quot;This is not a do your work for you site&quot; comments. Do natural weapons count for two weapon fighting? Do natural weapons such as those granted by being a Tabaxi or an Aarakocra count for the purposes of two weapon fighting? Would they have the light property to allow it and if not what about if you take the dual wielder feat that removes the restriction on them being light?  From a logical perspective I would think claws or talons would be light enough to count and with them being "natural weapons" this means they are definitely weapons so it would make sense for them to be considered light and one handed. I wonder about the Adjustments to Cost Basis after a wash sale occur. Considering this  ( from marketwatch.com) where someone: On 1 Dec, 2018 used an amount of money in his account to buy 100 shares of XYZ Co., for $2000 (to make it simple , let's say 1 Feb, 2019 to turn all the transactions into the same year) On 1 Apr, 2019 he sells the shares for $1200, and incurred a loss of 800$. On 10 Apr, 2019 he bought back 100 shares for $1300, and had a wash sale. The 800$ loss gets added to the cost basis of this transaction( and the basis becomes $2100) Now, If on 13 Apr 2019, he sold 100 shares for $1400; I'm pretty sure that the realized Gain/Loss record of this transaction would show something like this: &quot; XYZ Co. shares  100 , Proceeds $1400 , Cost basis  $2100(adjusted), Short-term Gain/Loss  -$700 &quot;. So, even though the Gain/Loss shows a negative number, he still got an actual profit of $100 from this sale, right? Is it always better to use the whole dataset to train the final model? A common technique after training, validating and testing the Machine Learning model of preference is to use the complete dataset, including the testing subset, to train a final model to deploy it on, e.g. a product.      My question is: Is it always for the best to do so? What if the   performance actually deteriorates?   For example, let us assume a case where the model scores around 65% in classifying the testing subset. This could mean that either the model is trained insufficiently OR that the testing subset consists of outliers. In the latter case, training the final model with them would decrease its performance and you find out only after deploying it.   Re-phrasing my initial question:     If you had a one-time demonstration of a model, such as deploying it   on embedded electronics on-board an expensive rocket experiment, would you trust a   model that has been re-trained with the test subset in the final step without being   re-tested on its new performance? SQL Server Agent Jobs and Availability Groups I'm looking for best practice in dealing with scheduled SQL Server Agent jobs in SQL Server 2012 availability groups. Maybe I missed something, however at the current state I feel that SQL Server Agent is not really integrated with this great SQL2012 feature.  How can I make a scheduled SQL agent job aware of a node switch?  For example I have a job running on the primary node which loads data each hour. Now if the primary goes down, how can I activate the job on the secondary which now becomes primary?   If I schedule the job always on the secondary it fails because then the secondary is read-only. I recently obtained a Seagate Expansion 3TB external harddrive. I'm trying to copy over all of my stuff to prepare for reformatting and installing a new OS. A handful of my mp3s did not transfer when I was doing my music folder. I checked them after the fact and the ORIGINAL files became corrupted somehow. I am certain of at least a few that were not corrupted in anyway before doing this. Every now and then during my transfer I got  There was an error copying the file into /media/***/Seagate Expansion Drive. Error splicing file: Input/output error   Each of these files that I check after are corrupted at some point in the duration and will not play. Why did this happen and what can I do to fix it? Most efficient method to break Ubuntu Efficiently finding two squares which sum to a prime "python" not recognized as a command What are the solutions to $z^4+1=0$? How can I calculate the following sum involving binomial terms:  $$\sum_{k=0}^{n} \binom{n}{k}\frac{(-1)^k}{(k+1)^2}$$  Where the value of n can get very big (thus calculating the binomial coefficients is not feasible).  Is there a closed form for this summation? Movie/TV series, which bullets carried DNA of the shooter Given some potential $V$, we have the eigenvalue problem   $$ -\frac{\hbar^2}{2m}\Delta \psi + V\psi = E\psi $$   with the boundary condition   $$ \lim_{|x|\rightarrow \infty} \psi(x) = 0 $$   If we wish to seek solutions for   $$ E &lt; \lim_{|x|\rightarrow \infty}V(x), $$   I find textbooks like Sakurai and others assert that (without proof) set of all such eigenvalues $E$ that admits nontivial solutions is discrete, which gives us liberty to index them with natural numbers (principal quantum numbers). Can anyone help me with a little elaboration of this mathematical fact ? As a student of mathematics, I know that compact operators have discrete spectrums, so for the operator $ T : L^2 \rightarrow L^2 $given as  $$ T(\psi) = -\frac{\hbar^2}{2m}\Delta \psi + V\psi. $$   Are there methods to show that $T$ is compact? Or possibly other ways to establish discreteness of its eigenspectrum? I don't think I've seen any answers to this question, but I'm curious as to why, when you have a 64-bit OS installed (ex: Vista x64), IE defaults to the 32-bit version? Are there drawbacks to using the x64 version of IE (IE8, specifically)? As far as I know, it's possible to create a radially polarised ring magnet, where one pole is on the inside, and the field lines cross the circumference at right angles.    So imagine if I made one which was shaped like a sector of a torus.    Then I forced a load of these magnets into a complete torus.     Clearly this magnet is impossible because there's no way for the field lines to get back into the middle. So what happens to the field in this case? Does it disappear completely? Do the magnets blow up? Cannot get grub menu to timeout (or go away)