Enable Access-Control-Allow-Origin for multiple domains in Node.js
Access-Control-Allow-Origin Multiple Origin Domains?
Well, this might be a really simple one. But still... What will be the soln. to --- \begin{aligned} \int\frac{1}{1+x^n} dx \end{aligned}  Is substituting \begin{aligned} 1+x^n \end{aligned} by tan z the correct step?  Thanks for the Help. How to avoid duplicating assigned materials when duplicating a mesh? how can I prevent Blender 2.8 from duplicating materials every time (?) I duplicate a mesh. I was reading  when I came across  saying something about a particular type of programmer knowing the difference between an int and an Integer in Java/C# (Object-Oriented Programming Languages).  So, what is the difference? Does untapping an attacker stop its attack? If someone declares an attacker and that creature does not have vigilance, if I untap that creature, for example with , does it stop the creature from attacking? Is being a right triangle both necessary and sufficient for the Pythagorean Theorem to hold? I recently encountered a Stack Overflow question (since closed) in which the OP was testing for whether a triangle was right by whether or not it "met" the criteria of the Pythagorean Theorem (i.e. whether or not the square of the hypotenuse is equal to the square of the two sides). The code was to this effect:  public void Test(int a, int b, int c) {    if ((c * c) == ((a * a) + (b * b)) {      System.out.println("This is a right triangle");    }    else {      System.out.println("This is not a right triangle");    } }   (There are obviously some other problems with this code, like the fact that it doesn't validate the input to make sure that the inputs are positive and the fact that it only accepts integers).  The question was asking about something completely different in the code and never directly addressed the test, but I got to thinking: is this a valid test for whether a triangle is a right triangle?  Obviously, the Pythagorean Theorem states that, for all right triangles, $a^2 + b^2 = c^2$ (where $a$ and $b$ are sides and $c$ is the hypotenuse). This will hold for all right triangles, so being a right triangle is a sufficient condition for the Pythagorean Theorem to hold.  Is it also a necessary condition? I.e. if $c^2 = a^2 + b^2$ for some arbitrary triangle, is the triangle necessarily a right triangle? Or are there counterexamples? How does Router know where to forward packet Is redirecting homepage to a page with keyword it's targeting helps in SEO? Why is the mean function in Gaussian Process uninteresting? Do Israeli security agents interview all those flying to Israel or is it restricted to El Al flights? The one thing I hate about flying to Israel are the security checks at the origin airports. I don't mind X-rays and deep luggage searches, but there's also an annoying interview you have to "pass". The security folks can't really turn you down (especially since I'm a citizen), but they always make it a pain in the butt, because for some reason I fit their profile of a suspicious person.  Can I avoid the personal interviews if I book on a non-Israeli airline? Or perhaps a low-cost airline? Interpreting plot.lm() How can I test for POSIX compliance of shell scripts? Considering that POSIX is the closest thing to a common standard among all unices, I'm interested in knowing if there's a shell that supports it exclusively. While most modern shells provide support for POSIX (and will run POSIX compliant scripts without any problem), they don't do a good job at pointing out non compliant features.  Is there any shell that implements POSIX and POSIX only, in such a way that it'd throw an error for any non compliant feature?  EDIT I want to clarify that I'm not asking for general tips for writing portable shell scripts. The related question mentionned in the comments already covered this. I thought of this question when I found out that bash has a --posix option but only to discover that it only affects some intialization behaviors which is not exactly what I'm looking for. Non-empty intersection. Let $A_1,A_2,...,A_{2019}$ be sets s.t. $|A_i|$=45 for each $i=\overline{1,2019}$ and $|A_i\cap A_j|=1$ for every $i\neq j$. Is it true that $$\Big|\bigcap _{i=1}^{2019} A_i\Big|=1?$$ What I thought of doing is proving by induction by i, the base is obvious. However I'm stuck on the next step. Why do I sometimes see a downloading 'pie' icon when viewing photostream photos? it normally shows in the bottom corner as a sort of 'pie' that fills up as the picture is downloaded, similar to the 'app downloading' pie when viewing a downloading app on the home page/s  prior to this the picture resolution is terrible How do you check the windows version in Win32 at runtime? How do you check the windows version in Win32 at runtime? $\ker \phi = (x_1-a_1, ..., x_n-a_n)$ for a ring homomorphism $\phi: R[x_1, ..., x_n] \to R$ Let $R$ be a commutative ring, $a_1, ..., a_n$ its elements and  $\phi: R[x_1, ..., x_n] \to R$  defined by  $ \phi(f(x_1, ..., x_n)) = f(a_1, ... ,a_n)$  a ring homomorphism.  Prove: $\ker \phi = (x_1-a_1, ..., x_n-a_n)$  It is obvious that $(x_1 - a_1, ..., x_n -a_n) \subseteq \ker \phi$. I'm not sure how to prove the converse.  At this point I don't know any division algorithms for multivariable polynomials, only for the ones in $R[x]$(and the book from where I taken the exercise doesn't assume the reader to know something beyond basics of rings and ideals, and the division algorithm for $R[x]$). Though I know this could be solved for $i = 1$ by dividing by $x-a$:   Let $f(x) \in \ker \phi$, divide by $x-a: f(x) = q(x)(x-a) + r, f(a) = r = 0$, so $f(x) = q(x)(x-a) \in (x-a)$. How to sort a list of objects based on an attribute of the objects? I've got a list of Python objects that I'd like to sort by an attribute of the objects themselves.  The list looks like:  &gt;&gt;&gt; ut [&lt;Tag: 128&gt;, &lt;Tag: 2008&gt;, &lt;Tag: &lt;&gt;, &lt;Tag: actionscript&gt;, &lt;Tag: addresses&gt;,  &lt;Tag: aes&gt;, &lt;Tag: ajax&gt; ...]   Each object has a count:  &gt;&gt;&gt; ut[1].count 1L   I need to sort the list by number of counts descending.  I've seen several methods for this, but I'm looking for best practice in Python. I have the following code: info = new System.Diagnostics.ProcessStartInfo(&quot;TheProgram.exe&quot;, String.Join(&quot; &quot;, args)); info.CreateNoWindow = true; info.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden; info.RedirectStandardOutput = true; info.UseShellExecute = false; System.Diagnostics.Process p = System.Diagnostics.Process.Start(info); p.WaitForExit(); Console.WriteLine(p.StandardOutput.ReadToEnd()); //need the StandardOutput contents  I know that the output from the process I am starting is around 7MB long. Running it in the Windows console works fine. Unfortunately programmatically this hangs indefinitely at WaitForExit. Note also this code does NOT hang for smaller outputs (like 3KB). Is it possible that the internal StandardOutput in ProcessStartInfo can't buffer 7MB? If so, what should I do instead? If not, what am I doing wrong? I have a parent theme that uses correctly load_theme_textdomain() to load all the translated strings in many languages.  Then I created a child theme that uses load_child_theme_textdomain() to achieve the same thing for its strings.  There are certain translated strings for a particular language on the parent theme that I'd like to replace/override in the child theme.  I know if they were on a template file I could replace the file and simply change the textdomain for those strings, but unfortunately the ones I'm talking about are used in many places and also in the dashboard (so inside some filter/action functions).  So my question is: is there a way to replace those translated strings inside the child theme without having to replace parent template files or functions?  I don't know, maybe adding a parent-theme.mo file inside the languages folder of the child theme with only those strings translated, or something like that. "Closed" (square) root symbol I found a cool trick in the  which allows the square root sign to be altered such that it &quot;closes&quot; over its contents. Here's an example:  (&quot;closed&quot; root on the left, normal one on the right) The way they do this is as follows: % New definition of square root: % it renames \sqrt as \oldsqrt \let\oldsqrt\sqrt % it defines the new \sqrt in terms of the old one \def\sqrt{\mathpalette\DHLhksqrt} \def\DHLhksqrt#1#2{% \setbox0=\hbox{$#1\oldsqrt{#2\,}$}\dimen0=\ht0 \advance\dimen0-0.2\ht0 \setbox2=\hbox{\vrule height\ht0 depth -\dimen0}% {\box0\lower0.4pt\box2}} The cool thing is that (as far as I've tested it) this works regardless of the math font and with pdftex as well as xetex. However what is not possible is mulitple roots, such as \sqrt[3]{a}. Those produce incorrect output when this &quot;trick&quot; is being used. So my question is, is somebody able to tweak this code so that it works for multiple roots as well? Can I run CAT5/6 cables parallel to electrical cables? I am building a new house and am planning to hardwire network cables into each room.   Can I run CAT5/6 cables parallel to electrical wires without introducing any general safety issues or losing much in connection quality?  Wiring runs for up to 25 metres from patch panel and distribution board in garage to rooms.   My research indicates that is should be fine if they are in separate conduits or if the CAT cables are shielded.