Blender subdividing faces and creating edges where shouldn't be any
Flat quads (or, why is my mesh so funky?)
I know that its is the possessive and it's is the contraction, and know when to use them.  But why doesn't the possessive have an apostrophe?   "The bear's eating a fish." [contraction] "The bear's coat is brown." [possessive] "It's eating a fish." [contraction] "Its coat is brown." [possessive] "One's eating a fish." [contraction] "One's coat is brown." [possessive]    lists the etymology as "From  +‎ ", and  says that this is actually the original form:     Originally written it's, and still deliberately spelled thus by some writers until early 1800s.   So what happened to the apostrophe?  When did people stop using it, and why did they?  It seems that it's as the possessive is more natural, as most people do this until they're taught that it is wrong (or even after).  Update: Online Etymology Dictionary has been updated to include two potential explanations:     The apostrophe came to be omitted, perhaps because it's already was established as a contraction of it is, or by general habit of omitting apostrophes in personal pronouns (hers, yours, theirs, etc.).   Can anyone back up either of these arguments?  The possessive one's still has the apostrophe, despite these. How to solve $y^2=3x^4+3x^2+1$ for integers. If $x,y \in \mathbb Z$ , then find all the solutions of   $$y^2=3x^4+3x^2+1$$       I was asked this question by my friend who said that he encountered this while solving another problem. I have tried several things but am unable to solve this question. Moreover, this has to be done using elementary methods only. So far, I have tried to factorize and use Pell's equation. At the end, I'm getting $$2y_{n} + (2x^2_{n}+1)\sqrt{3}=(2+\sqrt{3})^{n}$$   where $n \in \mathbb Z^{+}$    But I'm not able to figure out how to show a contradiction from here. Can anyone please help me out? Thanks. Show that $\sum_{n = 1}^\infty n^qx^n$ is absolutely convergent, and that $\lim_{n \rightarrow \infty}$ $n^qx^n = 0$ I'm having trouble with proving the following for my math study:  Let $x$ be a real number with $|x| &lt; 1$, and $q$ be a real number. Show that the series $\sum_{n = 1}^\infty n^qx^n$ is absolutely convergent, and that $\lim_{n \rightarrow \infty}$ $n^qx^n = 0$  I tried this:  $\sum_{n = 1}^\infty n^qx^n$ = $x + 2^q + 3^qx^3 + ...$ $= x(1 + 2^qx + 3^qx^2 + ...)$  So far, I don't know how I have to do this, I tried to apply the root test on this, but for that I would need to compute the lim sup of the series, so I thought that was not correct. Could you explain me how to prove this?  Thanks in advance! I noticed that the these two commands to list files below 5 GiB produce different results:  find . -type f -size -5368709120c find . -type f -size -5G   Specifically the one that uses kilobyte unit (5368709120c) returns additional files that are larger than the maximum file size returned by the one that uses the GiB unit (5G).  From the find manual page I read the following:  -size n[cwbkMG]           File uses n units of space.  The following suffixes can be used:           `b'    for 512-byte blocks (this is the default if no suffix is used)           `c'    for bytes           `w'    for two-byte words           `k'    for Kilobytes (units of 1024 bytes)           `M'    for Megabytes (units of 1048576 bytes)           `G'    for Gigabytes (units of 1073741824 bytes)  The size does not count indirect blocks, but it does count blocks  in sparse files that are not actually allocated.  Bear in mind that the `%k' and `%b' format specifiers of -printf handle sparse files differently.   The  `b'  suffix always denotes 512-byte blocks and never 1 Kilobyte blocks,  which is different to the behaviour of -ls.   So, given that the unit of G is 1073741824, 5G should be 5368709120c. Is the issue due to how sparse or indirect blocks are counted?  Thanks in advance for the help. Calculate text width with JavaScript let q be an odd prime and p a prime dividing $1+n+\dots+n^{q-1}$. Prove that $p = 1 \mod q$ or $p = q$.  I don't actually know how to start, i thought of using fermat's little theorem or an application of eulers formula, but it didn't really give me any insights.   Any hints? Block network access of a process? Is it possible to block the (outgoing) network access of a single process? I  to the question "" which was specific to the question asked.  Another user engaged positively with my answer, as there was a small conversation thread.  That person then  and made what I would say are minor modifications (the comments I left in my original code that pertained to the specific case are still in the places where he made edits to be more specific).  The answer does acknowledge that it is a general case of my specific code.  Ignoring the fact that I'm involved in it, what should one do when seeing this situation?  The only thing I can think of, and I'm not sure that it's necessarily the right solution, is to flag the answer for moderator attention.  Other possible actions, which I believe are wrong, are:   Editing the answer; that would change its intent Voting the answer down; it's a technically correct answer   One could leave a comment, but that can lead to confrontation and escalation (depending on the parties involved) which would be counterproductive.  The only thing I've done, which is not really related, is edit the answer to hyperlink the already existing attribution (but I do this as a regular edit for any answer which explicitly references another).  What's the best approach here, if any? Isomorphism between quotient modules Is it true for a commutative ring $R$ and its ideals $I$ and $J$ that if the quotient $R$-modules $R/I$ and $R/J$ are isomorphic then $I=J$? How to bake to vertex colors in blender cycles? Is $f(x)=10$ a periodic function? I've been writing in English for many years, but there are certain recurring issues that come up in my writing, which I can't seem to resolve permanently. Primarily I have a problem with punctuation. In my native language, commas are very commonly used. One would place a comma to separate any portion of the sentence that serves a specific grammatical role. At least, this is the case according to the rules I was taught in school. I can see when I write in English that there are extraneous commas, but I can't always figure out which ones, and why. When dependent clauses require commas, when do they allow them, and when are they definitely incorrect? How to make \left, \right pairs of delimiter work over multiple lines? I have a very long equation that must be separated into two lines, and it has several pairs of nesting \left \right delimiters. Unfortunately, it seems that they need to be on the same line in order for them to work.  Also I'm using the align environment because I need the aligning functionality. Is there a way to have the size of delimiters automatically adjusted over multiple lines? Here is my script:  #!/bin/bash  echo "Digite o local em que deseja instalar o IGRAFU(pressione enter para  instalar em  ${HOME}/IGRAFO):" read caminho if test -z $caminho then caminho="${HOME}/IGRAFO" fi echo "O IGRAFU será instalado no diretório: $caminho" mkdir -pv $caminho  mv -v ./* $caminho echo "Pronto!"   At 'read caminho' I may receive from the user a path like ~/somefolder. When the script receives that kind of path both mv and mkdir won't make tilde expansion, so it will try to create a ~/somefolder and not /home/username/somefolder and therefore fail.  How do I ensure that the tilde will be converted into the HOME variable? I left myself signed in to my work Gmail account on my personal computer. I am not using Chrome. I had an internet session that was not suitable for work. At all. This included Google searches and YouTube searches.  Will my employer be able to identify what I have been searching? Continuity of a convex function I'm trying to solve the following problem:  Let $f:K\rightarrow \mathbb{R} $, $f$ convex and $K \subseteq \mathbb{R}^n$ convex. Then $f$ is continuous on $K$.   I have proved the only case $n=1$, but for an arbitrary $n$?? How to create a Wi-Fi Hotspot (in Access Point mode)? How to setup an Access Point (AP) mode Wi-Fi Hotspot?  Point to be noted: Wireless access points aren't the same as ad hoc networks. They differ significantly. In short, ad hoc networks aren't supported on newer devices and most Android, Windows Phone and Blackberry devices (and maybe iOS devices too), whereas AP mode Wi-Fi hotspots are. To get an idea about AP mode hotspots, ad hoc networks and their difference, refer to . cvc-complex-type.2.4.a: Invalid content was found starting with element 'init-param' Proof of $a^n+b^n$ divisible by $a+b$ when $n$ is odd I'm playing on a Survival world with cheats on, "easy" difficulty, and at night in-game. I didn't have a sword or anything to make a sword with, and I was starving, so I switched to Creative to give myself a stack of food and a bed to set my spawn point. When I switched back to Survival, I couldn't destroy or place blocks. I'm on single player, and my Internet is fine, and I can destroy blocks still if I switch to creative. I've tried resetting the button one, and reloading the map, and it still doesn't work. I've even tried deleting everything I gave myself in Creative. This happened before on a different world and I ended up deleting it.  This only happens on this world. How do I fix it?  If I know I'm in the correct game mode, what else can cause this?  Are there different causes in multiplayer?