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"Dummy Output" No sound in Ubuntu 16.04 None of the HDMI output are working, all saying "dummy output", it was working yesterday, but when I use the headphones it became soundless, with or without the headphones.  Thank you already! How to change material's color in blender game engine? Make it cost more to downvote without comment; make it hurt to leave a crap comment Possible Duplicate:    In the spirit of &quot;encouraging&quot; people to leave comments on downvoting, I would propose that if someone downvotes without a comment, I propose a heavy point tax, say 3x the current point cost for a downvote. If he or she downvotes and leaves a comment, then it costs the current amount. If someone leaves a crap comment (to avoid the &quot;charge&quot;) they get a painful spank (100 points gone or whatever the community decides) if and only if:  The comment is flagged Three (five? whatever) moderators agree it is crap  Common complaints Or, why my proposal is different.  &quot;  a &quot;   No it isn't. I specifically address the issue of leaving garbage comments to avoid the downvote tax, unlike the other proposals.   &quot;Some people want to leave anonymous (down)votes.&quot;  I understand that some might be fearful of retaliation. Is retaliation a real problem or a &quot;what if&quot; conjecture? (Where's the data?) What if we try it for 3-6 months and then circle back to see how well it works?  If a user starts retaliating against another user, they will be dealt with as are all other problem users. Nothing else is anonymous - asking questions, answering questions, editing questions, leaving comments, etc. and there is a clear benefit. What is the benefit to the community for having anonymous voting? I would argue &quot;none.&quot; Even though some people might want to leave anonymous questions, answer anonymously or anonymously edit a question, it is not allowed, because it is not good for the community.   &quot;But this will discourage downvoting&quot;  I agree, and I think that's a good thing, which goes to the philosophy of the site: promote good questions and answers. If a question or answer is poor, few will up-vote it. If is is really poor, it will get flagged and . If someone really wants to downvote, no one is stopping him or her. Just as we want quality questions and answers, we need quality voting.   It will require too much work to implement  Maybe. Let's ask if it is worth the effort. What benefit does anonymous, no-comment downvoting add to the site? It certainly doesn't allow the author to improve. What benefit would owned, commented downvoting add? It would hopefully allow authors to improve and discourage drive-by downvoting. Would me (or someone else) submitting a patch alleviate this complaint?   Jeff (or Joel) thinks this is a stupid feature, and you're stupid for suggesting it.  &quot;&quot; Is this a true statement?    Thanks for reading. In a photoelectric effect we remove electrons from a metal using high energy photons, the work function is the minimal energy required for this effect.  My question is why doesnt the work fucntion depended on time? The more electrons we take out from the metal, the more ionized it becomes (if we remove a lot of negative charge, it will turn positive), and as a result we would expect to need more energy for this effect (the possitive charge of the metal would make it harder to remove the remaining electrons).  Why does the work function remains constant no matter how much electrons we take out? How to get correlation between two categorical variable and a categorical variable and continuous variable? I am building a regression model and I need to calculate the below to check for correlations   Correlation between 2 Multi level categorical variables Correlation between a Multi level categorical variable and continuous variable  VIF(variance inflation factor) for a Multi level categorical variables   I believe its wrong to use Pearson correlation coefficient for the above scenarios because Pearson only works for 2 continuous variables.   Please answer the below questions   Which correlation coefficient works best for the above cases ?  VIF calculation only works for continuous data so what is the alternative?  What are the assumptions I need to check before I use the correlation coefficient you suggest?  How to implement them in SAS &amp; R? Create unmanaged c++ object in c# What are the various physical mechanisms for energy transfer to the photon during blackbody emission? In general, when can I omit that from a sentence?   Can I omit that (emphasized) in sentence (2) below?        We say that such algorithms handle concept drift and can learn from time-changing data streams.   When the statistical properties of the target variable change, we say that concept drift has occurred.   She told me that some of her classmates failed.      To me, sentences (1) and (3) sound better without that. If I omit that from (2), it just doesn't sound right when I read it out loud. (I should point out I'm not a native speaker.)  How do you decide when to omit it? Is it just a matter of taste? (I know that is sometimes mandatory.)  Can you think of sentences that "sound better" with that? Can you think of sentences that "sound better" without that? Can you think of a few sentences where it is wrong to omit that? How to get back Windows 10 [UEFI] after Legacy installation of Fedora 24? How to fill a mesh with solid color How long was Luke Skywalker's training with Yoda? Show $\inf_f\int_0^1|f'(x)-f(x)|dx=1/e$ for continuously differentiable functions with $f(0)=0$, $f(1)=1$. Run script as root at login (no sudoer user, shell session) Much like /etc/profile and ~/.profile but ran by root instead of the user is doing login. /etc/rc.local runs after boot but I need running the script before login. The user is not a sudoer one.   Thanks! Why is fundamental group insufficient to classify manifolds? I have heard that some issues in group theory prevent classifying all manifolds upto homotopy using the fundamental group invariant. Does anyone know what are those issues?  Thanks, K. Doing a search via regular Gmail frontend in the browser, shows strange results.  I want to search all mails from   *@ebay.*   My search:  from:@ebay   shows also emails sent from an ebay subdomain:   eBay@reply.ebay.com   It seems like Gmail ignores the "@", otherwise I can't see why those messages appear in the search results.  I also tried following searches with no success:  from:"@ebay" from:'@ebay' from:(@ebay) from:("@ebay") from:('@ebay') Can I use an "if" clause without "then"? I have the following sentence:     If T had still been alive, there is the great possibility that either T or C ...   My teacher says that the word "then" must appear after the comma, but I think that it's implied and unnecessary. Who is right? In the comment field on StackOverflow (and other StackExchange sites as well, I presume) you're required to write 15 characters for the server to accept your post. If a shorter post is submitted, an information message states that the comment is too short. That is all good.  However, below the comment field is a counter, which counts up to 15 and then down from however many characters you're allowed to type minus fifteen. This counter doesn't always act the same as the actual validation: if I pad my message with whitespace, the validation notices and still says the message is too short, but the counter does not notice, and counts as usual.  Suggested fix: make the character counter trim the message before it counts, so the two messages say the same thing. Question on operator: // N Class not found loading JDBC org.postgresql.Driver Find $\space\ \begin{align*} \lim_ {x \to+\infty} \left [ \frac{\log_{2}(x-1)}{x}\right]   \end{align*}$.   After some minutes around this limit I did it this way:  $\log_{2}(x-1)=y \Leftrightarrow 2^y=x-1$  So,$\space x=2^y+1$.  When $x \to +\infty$,$\space y \to +\infty$ also. By substitution:  $\begin{align*} \lim_ {y \to+\infty} \left [ \frac{\log_{2}(2^y+1-1)}{2^y+1}\right]=\lim_ {y \to+\infty} \left [ \frac{\log_{2}(2^y)}{2^y+1}\right]=\end{align*}$  $\begin{align*}\lim_ {y \to+\infty} \left [ \frac{y}{2^y+1}\right]=\lim_ {y \to+\infty} \left [ \frac{1}{\frac{2^y+1}{y}}  \right]=\lim_ {y \to+\infty} \left [ \frac{1}{\frac{2^y}{y}+\frac{1}{y}}\right]= \frac{1}{+\infty+0}=0  \end{align*}$  Is this correct?Are there any other easy way to find this limit?Thanks