I have never understood a word Alice "has said" or "said"
"I have never said" versus "I never said"
How to remove feeds from WordPress totally? I want to completely remove feeds from WordPress. I am using this little function from    /** * disable feed */ function fb_disable_feed() { wp_die( __('No feed available,please visit our &lt;a href="'. get_bloginfo('url') .'"&gt;homepage&lt;/a&gt;!') ); } add_action('do_feed', 'fb_disable_feed', 1); add_action('do_feed_rdf', 'fb_disable_feed', 1); add_action('do_feed_rss', 'fb_disable_feed', 1); add_action('do_feed_rss2', 'fb_disable_feed', 1); add_action('do_feed_atom', 'fb_disable_feed', 1);   Still there is tons of transient options.. like _transient_feed_mod or _transient_timeout_feed_mod  How can i completely remove feeds from WordPress? How can I control the name of generic WCF return types? I've got a WCF Web Service method whose prototype is:  [OperationContract] Response&lt;List&lt;Customer&gt;&gt; GetCustomers();   When I add the service reference to a client, Visual Studio (2005) creates a type called "ResponseOfArrayOfCustomerrleXg3IC" that is a wrapper for "Response&lt;List&lt;Customer>>".  Is there any way I can control the wrapper name?  ResponseOfArrayOfCustomerrleXg3IC doesn't sound very appealing... I was running a Python script that malfunctioned and used sudo to create a file named &gt;.  How can I get rid of this file?  Of course, when I try sudo rm &gt;, I get the error bash: syntax error near unexpected token 'newline', because it thinks I'm trying to redirect the output of rm.  Its permissions are -rw-r--r--. Extend x axis on graph? I'd like to extend my x axis a little longer. Is it possible to do that?  \centering     \begin{tikzpicture}[scale=1.5]      \begin{axis}[         xlabel=Reynolds Number,ylabel=Coefficient Discharge]     \addplot [color=blue,mark=*] coordinates {         (6485.41491,0.408143397)         (7927.942858,0.407370795)         (8663.115504,0.38550864)         (9219.462371,0.366953133)         (9537.374867,0.346531912)         (10491.11235,0.330115983)         (11087.19828,0.312041115)         (12219.76155,0.313951177)     };         \addlegendentry{1/4}     \addplot [color=red,mark=triangle] coordinates {         (6556.945221,   0.412644978)         (7868.334265,   0.404307857)         (8663.115504,   0.38550864)         (9187.671122,   0.365687778)         (9120.114717,   0.331371141)         (10443.42548,   0.328615455)         (11683.28421,   0.328817519)         (12875.45607,   0.330797337)     };         \addlegendentry{1/2 Lift}     \addplot [color=black,mark=*] coordinates {         (6843.066467,   0.430651305)         (8297.516134,   0.426361012)         (9203.566747,   0.40955872)         (8615.42863,    0.342911376)         (9298.940495,   0.337868614)         (10824.92047,   0.340619673)         (11683.28421,   0.328817519)         (12899.29951,   0.331409925)     };         \addlegendentry{3/4 Lift}     \addplot [color=yellow,mark=*] coordinates {         (6854.988186,   0.431401568)         (8398.850742,   0.431568008)         (9267.149246,   0.412388141)         (8567.741755,   0.341013343)         (9346.62737 ,   0.339601273)         (10753.39016,   0.338368882)         (11897.87515,   0.334857025)         (13030.43841,   0.334779157)     };         \addlegendentry{Full Lift}     \end{axis}% \end{tikzpicture}% Finding the limit of roots products $(\sqrt{2}-\sqrt[3]{2})(\sqrt{2}-\sqrt[4]{2})(\sqrt{2}-\sqrt[5]{2})\cdot \cdot \cdot (\sqrt{2}-\sqrt[n]{2})$ What are the options for managing multiple Ubuntu installations together and keeping them in same state Commenting out large sections Simple example of non-arithmetic ring (non-distributive ideal lattice) Can anyone provide a simple concrete example of a non-arithmetic commutative and unitary ring (i.e., a commutative and unitary ring in which the lattice of ideals is non-distributive)? So before I reformatted (to get rid of Windows), I simply used this command to open documents by putting it at the end of the ~/.bashrc file:  alias commandless= 'gnome-open ./Documents/the-linux-command-line.pdf; gnome-open ./Documents/linux.odt'   But now everytime I start the terminal, it says:  bash: alias: gnome-open ./Documents/the-linux-command-line.pdf; gnome-open ./Documents/linux.odt: not found   before even typing anything in, and when I run the command nothing happens, not even error messages. Academic dishonest: Possession of unauthorized materials during an exam that you didn't even know existed So unfortunately during an exam, I had the misfortune of using an eraser (with cover) that was not mine and had a small amount of words inside it unknown to me. I did not know this was the case, as I don't have a habit of unraveling erasers or looking at them closely?  However, now I face the problem in trying to defend myself against the accusation of me cheating.  I'm specifically concerned on my university's blank statement of "possession of unauthorized materials during an exam" is considered academic dishonesty. Seems like student conduct has all the power in trying to prove academic dishonesty, despite none of my test containing any of what to me is  unreadable, small notes. I have a Toshiba z830 with ubuntu 12.04. I could use without problems the DSL connection (I have no router, only a modem) at home until a couple of days ago:   It stopped to work when while connected with the DSL connection via CiscoVPN (to my workplace), I had to leave the laptop unattended for a while and I guess the laptop tried to go to suspend. When I came back there were many messages on a black screen (sorry, I cannot attach an image because of my low reputation) and the laptop was not responding. I had to reset the it.   After rebooting it, the internet connection didn't work as did before (no browsing, no ssh, no skype, etc) although it says it is connected. I only can browse, etc when I connect to CiscoVPN to the same place where I was connected when it crashed.  When I am physically where I connected via VPN (at work) I can use the wireless, which I am not able to use now anymore since the incident described above.  Some additional information:  martillu@ubuntu:~$ cat /etc/resolv.conf   domain km.icrr.u-tokyo.ac.jp   nameserver 10.240.12.134   nameserver 10.240.12.135    martillu@ubuntu:~$ route -n   Kernel IP routing table   Destination Gateway Genmask Flags Metric Ref Use Iface   0.0.0.0 61.127.116.199 0.0.0.0 UG 0 0 0 ppp0   61.127.116.199 0.0.0.0 255.255.255.255 UH 0 0 0 ppp0   169.254.0.0 0.0.0.0 255.255.0.0 U 1000 0 0 ppp0    martillu@ubuntu:~$ ifconfig   eth0 Link encap:Ethernet HWaddr e8:e0:b7:2f:bc:5a   inet6 addr: fe80::eae0:b7ff:fe2f:bc5a/64 Scope:Link   UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1   RX packets:17620 errors:0 dropped:1 overruns:0 frame:0   TX packets:13168 errors:0 dropped:0 overruns:0 carrier:0   collisions:0 txqueuelen:1000   RX bytes:19452232 (19.4 MB) TX bytes:2568218 (2.5 MB)   Interrupt:20 Memory:c0700000-c0720000    lo Link encap:Local Loopback   inet addr:127.0.0.1 Mask:255.0.0.0   inet6 addr: ::1/128 Scope:Host   UP LOOPBACK RUNNING MTU:16436 Metric:1   RX packets:134 errors:0 dropped:0 overruns:0 frame:0   TX packets:134 errors:0 dropped:0 overruns:0 carrier:0   collisions:0 txqueuelen:0   RX bytes:36316 (36.3 KB) TX bytes:36316 (36.3 KB)    ppp0 Link encapoint-to-Point Protocol   inet addr:219.167.252.226 P-t-P:61.127.116.199 Mask:255.255.255.255   UP POINTOPOINT RUNNING NOARP MULTICAST MTU:1454 Metric:1   RX packets:17608 errors:0 dropped:0 overruns:0 frame:0   TX packets:13129 errors:0 dropped:0 overruns:0 carrier:0   collisions:0 txqueuelen:3   RX bytes:18993590 (18.9 MB) TX bytes:2221195 (2.2 MB)    wlan0 Link encap:Ethernet HWaddr 9c:b7:0d:d9:21:f3   UP BROADCAST MULTICAST MTU:1500 Metric:1   RX packets:0 errors:0 dropped:0 overruns:0 frame:0   TX packets:0 errors:0 dropped:0 overruns:0 carrier:0   collisions:0 txqueuelen:1000   RX bytes:0 (0.0 B) TX bytes:0 (0.0 B)    I think that: domain km.icrr.u-tokyo.ac.jp in the resolv.conf may be suspicious, since if I am not connected via CiscoVPN I do not know why it should appear "km.icrr.u-tokyo.ac.jp" (this is where I connect via VPN). consider positive numbers $a_1,a_2,a_3,\ldots,a_n$ and $b_1,b_2,\ldots,b_n$. does the following in-equality holds and if it does then how to prove it  $\left[(a_1+b_1)(a_2+b_2)\cdots(a_n+b_n)\right]^{1/n}\ge \left(a_1a_2\cdots a_n\right)^{1/n}+\left(b_1b_2\cdots b_n\right)^{1/n}$ Should I disable swap file if I have lots of RAM or should I move it to a virtual RAM drive? Imagine I have tons of RAM. Let's say 64GB. That's a lot for even gaming PCs. Now the default location of a pagefile in Windows is on the main OS drive, be it HDD or SSD, which are faster in general, but still not as fast as RAM.  Something tells me that disabling the pagefile on the hard drive or creating a virtual RAM drive and letting the pagefile be there could make Windows move all its virtual memory to RAM, and so increase the system's performance, but I'm not very knowledgeable in that area, so that might not be true at all.  I tried both, but I couldn't analyze the results to reach a definite conclusion with my knowledge level in memory things.  Would this work? If not, why? I'd like to know if there is a way to run  program/shell script without typing full path:  /opt/idea/bin/idea.sh I don't know about you, but to me happens a lot: if I'm reading a question with a LOT of answers, (specially in a really specific question) I just read the most voted up: that's the way the system was made to be, and it's really good. The most relevant voted by the community are the first ones.  Since we have TOO many users, and a lot of them are reading the same questions and answering them almost at the same time, do you think the "urge" to be the first to answer a question and so gain reputation points makes people sometimes write things too fast and not try to really elaborate a really helpful answer? We may think: "people aren't going to read all answers, so I need to be really concerned about how fast I'm to answer". Are we incentivating "objective answers", or "not so good but objective and good to be voted up"?  I'm not trying to be unfair with all answers people here provide, we have really good ones here. But supose what I wrote above is a reality: what you think it would happen if it was a "time delay" between an "up-vote or down-vote" and it's sum in the answer? Summarizing: what if the sum wasn't almost "real time"? Determining if trees within forest gaps are clustered using R? The attached dataset shows approximately 6000 saplings in approximately 50 variable sized forest gaps.  I am interested in learning how these saplings are growing within their respective gaps (i.e. clustered, random, dispersed).  As you know, a traditional approach would be to run Global Moran's I.  However, aggregations of trees within aggregations of gaps seems to be an inappropriate use of Moran's I.  I ran some test statistics with Moran's I using a threshold distance of 50 meters, which produced nonsensical results (i.e. p-value = 0.0000000...).  The interaction among the gap aggregations are likely producing these results.  I have considered creating a script to loop through individual canopy gaps and determine the clustering within each gap, although displaying these results to the public would be problematic.    What is the best approach to quantify clustering within clusters? How to install apk in 2nd user of android 5.0 without playstore So, android 5.0.2 doesn't allow side loading of apks for 2nd user (irrespective of whether it is guest or standard user). "Unknown Sources" is disabled and is uncheckable. And I use a pure Cyanogen Mod 12 (android 5.0.2) without any Google apps. So, there is no Play Store app.  But I have root access.  As shown in the pics, Unknown Sources is Uncheckable and installation is blocked.  (Click image to enlarge)     With this situation, how can i install apks on to the 2nd user account??  EDIT:   It seems Google intentionally (in the name of security) blocked sideloading apks for 2nd user in android 5.0.2. There is a bug report . And sideloading was reenabled in android 5.1.   I will post how to sideload apks on lolipop 2nd user using adb. If this can be done without adb please post. $1+a$ and $1-a$ in a ring are invertible if $a$ is nilpotent Given fields $M/E/F$, why does $[M:F] = [M:E][E:F]$? Let $M$ be a finite extension of $E$ and let $E$ be a finite extension of $F$. Then $M$ is a finite extension of $F$ and $[M:F] = [M:E][E:F]$.   Is there an easy explanation and/or proof for this theorem? My instructor gave an incomplete proof in class but got stuck and I'm kind of confused of what's going on. If $a$ and $b$ are consecutive integers, prove that $a^2 + b^2 + a^2b^2$ is a perfect square. Problem is as stated in the title. Source is Larson's 'Problem Solving through Problems'. I've tried all kinds of factorizations with this trying to get it to the form $$k^2l^2$$ but nothing's clicking. I tried Bézout but the same expression can be written as $$a^2 + (a^2 + 1)(a+1)^2$$ which would imply that there is no real root.  Would really appreciate some help, thanks.