Changing “index.php” Within The Address
Changing "index.php" Within The Address
how to get rid of arm64 in apt W: Invalid 'Date' entry in Release file /var/lib/apt/lists/_var_cuda-repo-8-0-local_Release N: Skipping acquire of configured file 'non-free/binary-arm64/Packages' as repository 'http://repository.spotify.com stable InRelease' doesn't support architecture 'arm64' E: Failed to fetch http://archive.ubuntu.com/ubuntu/dists/xenial/main/binary-arm64/Packages  404  Not Found [IP: 91.189.88.161 80] E: Failed to fetch http://archive.ubuntu.com/ubuntu/dists/xenial-updates/main/binary-arm64/Packages  404  Not Found [IP: 91.189.88.161 80] E: Failed to fetch http://archive.ubuntu.com/ubuntu/dists/xenial-backports/main/binary-arm64/Packages  404  Not Found [IP: 91.189.88.161 80] E: Failed to fetch http://archive.ubuntu.com/ubuntu/dists/xenial-security/main/binary-arm64/Packages  404  Not Found [IP: 91.189.88.161 80] E: Some index files failed to download. They have been ignored, or old ones used instead.   After I installed Jetpack for Jetson tx1, my ubuntu constantly tries to fetch arm updates. Is there a way to disable this?  EDIT:   $dpkg --print-architecture amd64  $dpkg --print-foreign-architectures i386 arm64   I see that arm64 is included in foreign architectures. How do I remove it? How to set shell to wrap words for long commands? I am using Ubuntu 11.10 and my screensaver keeps coming on while I'm watching a movie.  I don't remember this happening in 11.04 and can't remember how to stop it? Does anyone know what song plays at about ? I often need to select a number of rows from each group in a result set.  For example, I might want to list the 'n' highest or lowest recent order values per customer.  In more complex cases, the number of rows to list might vary per group (defined by an attribute of the grouping/parent record). This part is definitely optional/for extra credit and not intended to dissuade people from answering.  What are the main options for solving these types of problems in SQL Server 2005 and later? What are the main advantages and disadvantages of each method?  AdventureWorks examples (for clarity, optional)   List the five most recent recent transaction dates and IDs from the TransactionHistory table, for each product that starts with a letter from M to R inclusive. Same again, but with n history lines per product, where n is five times the DaysToManufacture Product attribute. Same, for the special case where exactly one history line per product is required (the single most recent entry by TransactionDate, tie-break on TransactionID. I am trying to install  under Wine. The program setup continually requests proxy settings. My broker tells me this shouldn't happen, and is a problem on my end. Here is what I have tried to attempt to solve this error:   I have gone into Network settings and proxy is set to none. I have looked in Wine Regedit and proxy_enable is set to 0. I have checked the firewall settings on my modem. I have tried reinstalling wine. I have installed lib32nss-mdns I can log on to my modem in iexplore using the gateway ip but thats it I've set my DNS to 10.0.0.138 to reflect the gateway I've set up a 32 bit Wine prefix   How should I proceed in solving this? Hint proving this $\sum_{k=0}^{n}\binom{2n}{k}k=n2^{2n-1}$ I need hint proving this $$\sum_{k=0}^{n}\binom{2n}{k}k=n2^{2n-1}$$ List or IList Can anyone explain to me why I would want to use IList over List in C#?  Related question: $f$ is entire and maps a rectangle to a rectangle, then $f$ is linear The problem is in the subject line, I have it for homework. $f$ is a complex valued function. For completeness:     Prove that if $f$ is an entire function and for some rectangle $R$, the image $f(R)$ is also a rectangle, then $f$ is linear.    The composition of linear maps is linear, so we can choose the two rectangles to have two edges coinciding with the real and imaginary axes, and their common vertex at the origin. So as a portion of the real line gets mapped to itself, we can take $f$ to be the analytic continuation of a real function. Then I'm stuck.  This question is confusing me. It's well known from the Riemann mapping theorem that there exists many holomorphic functions taking any rectangle to any other given rectangle. But if $f$ is linear, then the two rectangles must be similar. So the added restraint of $f$ being entire seems to be causing this hassle. Thoughts? Duality discrete math problem This is the only answer I got wrong on my HW and the prof does not want to give us the correct answers before our midterm     The dual of a compound proposition that contains only the logical operators $\lor$ , $\land$ , and   $\neg$ is the compound proposition obtained by replacing each $\lor$ by $\land$ , each $\land$ by $\lor$ , each $\def\T{{\rm T}}\def\F{{\rm F}}$   $\T$ by $\F$ , and each $\F$ by $\T$ . The dual of $s$ is denoted by $s^*$. Find the dual of these compound propositions.      a) $p \lor\neg q$     I got $\neg p \land q$       b) $p \land (q \lor (r \land \T))$     My answer was $\neg p \lor (\neg q \land r)$       c) $(p \land \neg q) \lor (q \land \F)$     My answer was $(\neg p \lor q) \land  \neg q$  I have tried googling the problem and cannot come up with anything on duals and our lectures are online and upon reviewing do not see anything. I am just confused and looking for a little guidance on what was incorrect with my answers. Large snap packages because of dependencies There exists an injection from $X$ to $Y$ if and only if there exists a surjection from $Y$ to $X$. Theorem. Let $X$ and $Y$ be sets with $X$ nonempty. Then (P) there exists an injection $f:X\rightarrow Y$ if and only if (Q) there exists a surjection $g:Y\rightarrow X$.  For the P $\implies$ Q part, I know you can get a surjection $Y\to X$ by mapping $y$ to $x$ if $y=f(x)$ for some $x\in X$ and mapping $y$ to some arbitrary $\alpha\in X$ if $y\in Y\setminus f(X)$. But I don't know about the Q $\implies$ P part.  Could someone give an elementary proof of the theorem? I've got bunch of files with ill-formed numbering:  prefix-#.ext       | for files with number 1-9 prefix-##.ext      | for files with number 10-99 prefix-###.ext     | for files with number 100-999   Due to further processing I need all of their names to be in format: prefix-###.ext. Is there any easy way to do that? I have secured a visa for the US, be it an ESTA or another visa requiring me to go for an interview. My understanding is that obtaining a visa for the US does not guarantee me entry into the country. Rather, :  Entering the United States A visa allows a foreign citizen to travel to a U.S. port-of-entry (generally an airport) and request permission to enter the United States. A visa does not guarantee entry into the United States. The Department of Homeland Security (DHS), U.S. Customs and Border Protection (CBP) officials at the port-of-entry have authority to permit or deny admission to the United States. If you are allowed to enter the United States, the CBP official will provide an admission stamp or a paper Form I-94, Arrival/Departure Record.  What happens once I arrive in one such port-of-entry? Will I have to go through customs checks? Will I have to talk to an immigration officer explaining my reasons for visiting the US? What documentation, if any, should I bring? Is the documentation I brought for the interview enough? What if I did not attend an interview since it was not required (for example if I obtained an ESTA online)? Disable chat migration notification if one of the users has insufficient rep? Simple request, really.  Can we add a detection for the     Please avoid extended discussions in   comments. Would you like to   automatically move this discussion to   chat?   prompt, so that if one of the users in the "extended discussion" has under 20 rep it doesn't appear?  I think a lot of the users this apply to will have low rep and it may take some back and forth to get good info out of them.  New suggestion: how about if a sufficiently high-rep user is clicking on the link, the low-rep user gets a field promotion sufficient to chat? Low-rep users are particularly prone to post questions to lead in this direction of needing to move to chat. How to enable or disable a user? I'm uing ubuntu 12.04 desktop. I have 3 users: user1(administrator), user2(standard) and guest. I wanted to disable user1 and enable user2 which auto logs on with no password but after I did that I can't login to user1 and user2 accounts except the guest session user. I'm striped off every administrative privileges. I don't know which options are available to me and how do I enable root or user which is an administrator? Which expressions can be used to close an email? At the end of written communication like emails and letters, it is customary to use a closing . Which formal and informal expressions can be used to end emails? Prove by induction that for all $n \geq 3$: $n^{n+1} > (n+1)^n$ I am currently helping a friend of mine with his preperations for his next exam. A big topic of the exam will be induction, thus I told him he should practice this a lot. As at the beginning he had no idea how induction worked, I showed him some typical examples.  Now he showed me an exercise he was having trouble with, which states that one should prove $$n^{n+1} &gt; (n+1)^n$$  for all $n \geq 3$. I have to admit that I too have trouble showing this inequality, as in all of my attempts, my lower bound is too low. Also, I have not yet figured out, how one gets the $(n+2)^{n+1}$, primarely the number $2$ is a problem. I think this might be solved using the binomial theorem, however, I don't think they have already seen the binomial theorem in school.  Is there an easy method to show this inequality by induction not using the binomial theorem? If no: How can one show it using the binomial theorem?  Thanks for answers in advance. How do I create an .exe for a Java program? Do virtual particles actually physically exist?