Where is the documentation for the KDE Desktop (Plasma?)
Is there a detailed user's documentation for KDE Plasma 5?
How to redirect stderr and stdout to different files and also display in terminal? Non-Metrizable Topological Spaces Difference between generalized linear models & generalized linear mixed models What happens when you plug two sides of a cable to a single networking device? What is likely to happen when you plug two ends of a network cable to a single switch/router? Will this create problems on the network, or just be ignored? Feature request - links underlined Moment generating function (MGF) of the ratio distribution $\displaystyle\frac{X}{Y}$ If we know the moment generating functions (MGFs) of the random variables $X$ and $Y$ to be $M_{X}(s)$ and $M_{Y}(s)$, respectively. The MGF of the sum $X+Y$ will $M_{X}(s) \cdot M_{Y}(s)$.  So what is the MGF of the ratio distribution $\displaystyle\frac{X}{Y}$? How to batch resize an image and create multiple sizes (with Photoshop)? I want to batch resize an image in multiple sizes with Photoshop.  The sizes are most of the time the same so I would like to have profiles for a set of fixed sizes. Ideally I just need to open my source image and click on "Batch Profile #1" and then Photoshop is creating/saving X different sizes of that image as an output in a specific folder.  This is what i want: due to versus as a result of Tabular with p type columns to fill page width I have a table:  table votes (     id,     user,     email,     address,     primary key(id), );   Now I want to make the columns user, email, address unique (together).  How do I do this in MySql?  Of course the example is just... an example. So please don't worry about the semantics. My family PC has Windows Vista and lately it has became unusable, having strange errors and taking hours to do anything at all, so I'm installing Ubuntu 11.10 alongside it.  I went into GParted to resize the Vista partition but found that it had an exclamation point in a red circle next to it:   I tried to resize it but the Resize/Move button was grayed out.  I thought that this might have to do with the exclamation point so I looked at the information and found a load of errors:   What does the exclamation point mean?  How can I resize my partition?  UPDATE 1  I booted into Safe Mode with Command Prompt in Vista as suggested by eug and ranchkdsk c: /F /R (/F Fixed errors on the disk, /R Locates bad sectors and recovers readable information) and got:  Chkdsk cannot run because the volume is in use by another process.  Would you like to schedule this volume to be checked the next time the system restarts? (Y/)   When I reboot it doesn't run chkdsk, I'm selecting Safe Mode with Command Prompt again because I can't boot normally.  How can I stop it being used?  UPDATE 2  I tried doing what Luis suggested.  Here is the terminal output:  ubuntu@ubuntu:~$ sudo ntfsfix /dev/sda3 Mounting volume... OK Processing of $MFT and $MFTMirr completed successfully. NTFS volume version is 3.1. NTFS partition /dev/sda3 was processed successfully. ubuntu@ubuntu:~$ sudo apt-get install ntfsprogs Reading package lists... Done Building dependency tree        Reading state information... Done Note, selecting 'ntfs-3g' instead of 'ntfsprogs' ntfs-3g is already the newest version. 0 upgraded, 0 newly installed, 0 to remove and 0 not upgraded.   I still cannot resize the partition.  Ntfsfix doesn't look like it did anything and ntfsprogs is already installed.  I can access the hard drive and do backups with the Ubuntu Live CD which I'm using now.  Any other suggestions?  UPDATE 3  I attempted to use the ntfsresize command but I got an error:  ERROR: Volume is scheduled for check. Run chkdsk /f and please try again, or see option -f.   This is because I ran chkdsk in Vista Safe Mode with Command Prompt and it couldn't do it because it was in use but offered to do it at the next reboot.  I reboot and I get to the menu to the menu to choose whether to Start Windows Normally, Safe Mode, etc instead of checking the disk.  Is there any way I can unschedule?  EDIT  I just found out that I could use the -f option to force it.  It failed and told me to run chkdsk /f in Windows and then reboot twice.  But the chkdsk program is in the partition I am trying to check so it says it is in use. read only access to all files in a specific sub-folder I have got a specific folder located in "/home/.../reboot/".  I have a series of users that require read-only access to the ever changing files within.  My problem is that the same users are not authorized to view any of the parent directory files.  Right now, the only thing I have in place is that their starting folder is at "/home/.../reboot/" by changing the etc/passwd file; and I need to block all access to other folders.  How could I only give them access to this directory? For $x$ and $\lambda$ complex, if $|x| \gt \frac{1}{2} + \sqrt{\frac{5}{4} + |\lambda|}$ then $|x^2+\lambda| \gt |x| +1$ Define $f(z) = z \ ^ 2 + \lambda$ and $V = \left\{x \in \Bbb C : |x| \gt \frac{1}{2} + \sqrt{\frac{5}{4} + |\lambda|} \right\}$, for some $\lambda \in \Bbb C$.   Then, if $x \in V$ then $|f(x)| \gt |x| +1$.   I tried the following :   Let $x\in V$ then $|f(x)| = |x \  ^ 2 +\lambda | \ge |x |  \ ^ 2 - | \lambda| \gt (\frac{1}{2} + \sqrt{\frac{5}{4} + |\lambda|}) \  ^ 2 - |\lambda| = 1.5 + \sqrt{\frac{5}{4} + |\lambda|} $.  But this doesn't get me anywhere. Inherited values between polygons in QGIS In this project, I have three polygons, see the image below  'Polygons_From', includes input attributes, i.g. &quot;Value_1&quot;, &quot;Value_2&quot;, &quot;Value_3&quot;, and $area for each quadrate (on the image there are two types of them). 'Polygons_To' polygons for which new values &quot;Value_1_new&quot;, &quot;Value_2_new&quot;, &quot;Value_3_new&quot; need to be defined 'Border' defines an area where the calculation should be done.   My task is to transfer values from 'Polygons_From' into 'Polygons_To' based on a certain aspect/ratio. Of course, I can simply achieve it with the 'Union' function as was suggested in . It uses $area-factor, but perhaps there are better approaches that will lead me to a much more efficient output? So, I am asking for a recommendation regarding the technique/workflow that can be applied in QGIS 2.18. Shall I consider only $area or there are some other criteria? Moreover, I looking forward to finding some papers that may improve my general understanding of the methodology.  References: Name an Armor Stand using the Standard Galactic Alphabet The Standard Galactic Alphabet is what appears in the Enchanting Table. Is there a way to give a name to an Armor Stand using these character.  I know there is a LingoJam Translator that give ASCII characters that look like the SGA, but that is not what I'm looking for. Can I use the same characters as the Enchanting Table? ok, ive a class and i pass an object as property.  the object that i pass is a List&lt;X&gt;  in my class im trying to access the Object index by reflection BUT I CAN'T!!!   Example:  this class works i just wrote down the part i want to show you and i need help.  class MyClass {     private object _recordSet;     public object RecordSet     {         get { return _recordSet; }         set { _recordSet = value; }     }      public string Draw()     {         system.reflection.Assembly asem = system.reflection.Assembly.getAssembly(_dataSource.GetType());          object instance;          instance = asem.CreateInstance(_dataSource.GetType().UnderlyingSystemType.FullName);          //to access de Count of my List         int recordcount = int.Parse(_dataSource.GetType().GetProperty("Count").GetValue(_dataSource,null));          //i need to do a          for(int cont = 0; cont &lt; recordCount; cont++)         {             _dataSource[cont].Name; // &lt;-- THIS PART IS NOT WORKING!!! because i cant access the Index Directly.... WHAT TO DO!! ???         }     } } Story whose final line is "Let there be light!" I read this series around 5-10 years ago. There were two parallel universes, ours and the universe of demons, and much of the series revolved around attacks in which demons created gateways to cross into our universe to kill people and wreak havoc, and had to be stopped by human magicians. Three youngsters (one guy from modern times, one from a few decades ago, and a girl from ancient Celtic times, all with funny names) end up being the key to the war when it's revealed that they are the three components of a mythical superweapon. These three are the only point-of-view characters in the series, each book being told from the PoV of just one of them. At the very end, they   destroy our entire universe so that, after killing all the demon masters, they can rebuild it and make sure everything happens as before up until the very last moment.  As they begin recreating the universe, the current PoV character (the one from modern times) says something like the following, the very last lines of the series. (sic on the quotation marks)  &quot;In the beginning, there was nothing but darkness. Then [name] said, 'Let there be light!'&quot; And there was light. Coolio! Open CSV File with Different Delimiter It's been said that .  It the corresponding statement true for typical cryptographic hashes, like MD5, SHA-1, SHA-2 or SHA-3?  For example, would SHA-512 be bijective when hashing a single 512 bit block? Evaluating indefinite integrals of the form $\int \frac{x^2 \,dx}{a x^5 + b}$ Evaluate the indefinite integral   $$\int \frac{x^2 \,dx}{a x^5 + b},$$   for real parameters $a, b \neq 0$.   No apparent substitutions simplify the expression (if the exponent of $x$ were an integral multiple of $3$, this would suggest the substitution $u = x^3$, $du = 3 x^2 \,dx$, but the exponent is not). Applying integration by parts with $u = a x^5 + b$, $dv = x^2 dx$ is straightforward, but it produces an integrand with a much larger degree in the denominator and so appears only to make the situation worse. Applying integration by parts instead with $dw = \frac{x^k dx}{a x^5 + b}$ results in integrating $\frac{x^k dx}{a x^5 + b}$, which except when $k \equiv 4 \pmod 5$ (which doesn't appear immediately fruitful), doesn't appear much easier than the given integral.