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Is it possible to adjust desktop monitor brightness like on laptops? Yes all desktop monitors have separate menu for it. But is it possible to change this to something like Winkey+(F1..F12)?    Monitor is connected via VGA or DVI cable.   OS: Ubuntu 14.04 Desktop monitors I've read through the elementary proof of why there exists a solution $x$ to $x^2\equiv -1\pmod p$ iff $p\equiv 1 \pmod 4$ for $p$ an odd prime. Is there a group theory generalization for this fact as well? From this paper:     Shouldn't $du$ be $dt$? And also how do you get from that line to the final result if $du$ is not $dt$? Quick directory navigation in the bash shell Number of $(0,1)$ $m\times n$ matrices with no empty rows or columns How do I fix these M4 macro errors? I am trying to compile  but when I run ./autogen.sh the script terminates with these errors  Checking for required M4 macros...   libtool.m4 not found   glib-gettext.m4 not found   intltool.m4 not found   pkg.m4 not found   gtk-doc.m4 not found   yelp.m4 not found ***Error***: some autoconf macros required to build mate-desktop   were not found in your aclocal path, or some forbidden   macros were found.  Perhaps you need to adjust your   ACLOCAL_FLAGS?   What do I need to do to get rid of these errors? I tired installing the latest versions of inittool, glib, gtk, yelp, etc... but I still get the macros errors. I want to do the not independent sign in latex without having to install or define new commands (since I am using latexIT and I cannot load new packages).  Currently I use the following sign for independent:  X{\perp\!\!\!\perp}Y   What can I use for X not independent of Y?  I.e., something like this: ? I'm trying to display models that have shading drawn or baked directly on the textures, but I can't figure out how to disable Blender's default scene lighting. If there are no lights in the scene, everything is black, but I want to see the textured objects fully bright. How do I disable the lighting?  NOTE: Just before posting this, I found the "Shadeless" material property, which does more or less what I want. However, is there a way to globally toggle the default lighting? Show that a positive operator on a complex Hilbert space is self-adjoint Let $(\mathcal{H}, (\cdot, \cdot))$ be a complex Hilbert space, and $A :  \mathcal{H} \to \mathcal{H}$ a positive, bounded operator ($A$ being positive means $(Ax,x) \ge 0$ for all $x \in \mathcal{H}$). Prove that $A$ is self-adjoint. That is, prove that $(Ax,y) = (x, Ay)$ for all $x,y \in \mathcal{H}$. Here's what I have so far. Because $A$ is positive we have $\mathbb{R} \ni (Ax,x) = \overline{(x,Ax)} = (x,Ax)$, all $x \in \mathcal{H}$. Next, I have seen some hints that tell me to apply the polarization identity: $$(x,y) = \frac{1}{4}((\lVert x+y \rVert^2 + \lVert x-y \rVert^2) - i(\lVert x + iy \rVert^2 - \lVert x - iy \rVert^2)),$$ where of course the norm is defined by $\lVert \cdot \rVert^2 = (\cdot, \cdot)$. So my guess is that I need to start with the expressions: $$(Ax,y) = \frac{1}{4}((\lVert Ax+y \rVert^2 + \lVert Ax-y \rVert^2) - i(\lVert Ax + iy \rVert^2 - \lVert Ax - iy \rVert^2)),$$ $$(x,Ay) = \frac{1}{4}((\lVert x+Ay \rVert^2 + \lVert x-Ay \rVert^2) - i(\lVert x + iAy \rVert^2 - \lVert x - iAy \rVert^2)),$$ and somehow show they are equal. But here is where I have gotten stuck. Hints or solutions are greatly appreciated. "Can’t help but" vs. "can help but" Is "can’t help but" considered to be a confused mix of the expressions "can but" and "can’t help"? If not, what is the difference between "can help but" and "can’t help but"? I have ubuntu mate. I have recently changed my password using the passwd command. I know now that I have made a mistake because I also have my home directory encrypted with the previous password.  Consequently after enter my new password at login screen it return me back to the login screen.  Can someone please help me?  I am able to enter to grub boot menu and shell, i am also able to log into guest user. Sorry if the topic is duplicate but I haven't found the same question  Thanks in advance. Prove that $\frac{1}{f'(a)} = \frac{1}{2\pi i} \int_C \frac{1}{f(z)-f(a)} dz$ Let $f$ be analytic on an open set $U$, let $a \in U$, and $f'(a)\neq 0$.  Show that  \begin{align*} \frac{1}{f'(a)} = \frac{1}{2\pi i} \int_C \frac{1}{f(z)-f(a)} dz \end{align*} where $C$ is a small circle centered at a.  I thought that this is very similar with Cauchy's integral formula. But, I can't apply the Cauchy's integral formula. How to apply that?   Any help is appreciated..   Thank you! Why don't planets have Circular orbits? $\int_0^{\infty} f(x)dx$ converges and $\lim_{x\rightarrow \infty} f(x)$ exists, then $\lim_{x\rightarrow \infty} f(x)=0$? How can I know what speed card to get for my camera? why is there no non-degenerate 2-forms on 4-sphere? Many LaTeX “hacks” begin with \makeatletter and end with \makeatother. What do these commands do? Why does the set of all singleton sets not exist? How do I calculate a time delta in my Google Spreadsheets? I've got a Google Spreadsheet that looks roughly like this:   Date        | Start time  | End time    | Minutes  ------------+-------------+-------------+-----------  1/11/2012   | 11:39       | 12:41       | ?!  ------------+-------------+-------------+-----------              |             |             |    Right now if I fill in the number of minutes between the two times of day by hand. Is there a straight-forward way to calculate a time delta and have the spreadsheet do it for me? Reference request: Standard textbook for first-order predicate logic in english I am writing my bachelor thesis in english, but I have studied logic in my different native language. Since a rely on elementary results from first-order predicate logic (especially satisfaction in structures), I should reference the reader to a textbook for details.   Is there a standard textbook that starts with elementary propositional logic and goes to Incompleteness theorems?