how to make AutoExpand UITextView Dynamically in ios
Autoexpand UITextView height dynamically in ios
How can i limit the character length in excerpt? Possible Duplicate:          I have a question after reading this post (). I like this function(Search Term Without Plugin) very much but the character length is too long. What php code should i add to make the excerpt shorter? Would appreciate if someone can suggest it. Thank you! How do I create a villager with custom trade offers? I remember very little but enough... I know that there were 3 worlds, a real one, a mid-world kind of with a teleporter, and the world with all the creatures. The first episode was in the desert and there was a good monster that saved the main guys from a bad one. Before he saved them he said every end is a beginning and every beginning is an end.   Please help me; I've tried everything. I saw it on , I think it was not Japanese. I live in Croatia, so I saw it there. It was aimed at kids, but not younger kids. The main characters were human, around 15 years old. The teleporter was in the middle of a big structure. It was a 6 piece tp, so every circle was one, and it was shaped like a star. There were robots working there; they carried food and other things.  I remember that all the creatures thought that the humans are evil, all but the one, the "lord" of all of them. And yes, the main character got to the world by some sort of a device that he found and it belonged to another kid who lost it and they were able to transform in the creatures from the world by it. When they are in the "other world", their body stays in the real world and acts normally but their soul gets transported to the mid-world Can we have a way to edit bounty custom message? Some vertices don't move along with the rig Solving $\sqrt{x+5} = x - 1$ I'm currently learning about radicals and simplifying them, and I came across this problem on the internet and tried to solve it:  $$\sqrt{x+5} = x - 1$$  So I used this logic:  $$ \begin{align} \sqrt{x+5} &amp;= x - 1 \\ x + 5 &amp;= (x-1)^2 \\ x + 5 &amp;= (x-1)(x-1) \\ x + 5 &amp;= x^2 - 2x + 1 \\ 0 &amp;= x^2 - 3x - 4 \\ 0 &amp;= (x-4)(x+1) \\ \end{align} $$  Therefore, $x = -1$ and $x = 4$ satisfy the equation $0 = (x-4)(x+1)$.  But then I tried to plug them in the original problem $\sqrt{x+5}=x-1$:  $$ \begin{align} \sqrt{4 + 5} &amp;= 4 - 1 \\ \sqrt{9} &amp;= 3 \\ 3 &amp;= 3 \end{align} $$  So using 4 works as expected, but when using $-1$:  $$ \begin{align} \sqrt{-1 + 5} &amp;= -1 - 1 \\ \sqrt{4} &amp;= -2 \\ 2 &amp;\ne -2 \end{align} $$  At what stage am I going wrong?  And according the , the solution is $x = 4$. I understand that the Bernoulli effect is a flawed explanation for the cause of lift, and does not cause much at all, but how much?   Is there any experimental data on the force caused by the Bernoulli effect? Maybe implicitly through data of the pressure difference between the top and underside of an aeroplane's wings. After that, I assume I could (crudely approximating the pressure to be acting perpendicularly to the flight direction) use $\Delta P A$ to work out the net force on the plane.    Perhaps there is another way to quantitatively analyse the extent to which the Bernoulli effect causes lift.  Edit: see  short cartoon (content similar to Mike Dunlavey's answer). I am building a drupal site using Views, search API module and user-points module.  I created the "database server", and indexed many fields of nodes.  I created a search page using views and the search API, that present content (image, title etc.) In addition, I want to add to every content in this search view the name of the author that wrote it, his author picture.  I add the Indexed Content: Author relationship. Unfortunately, I can't find a way to add the author picture and the current total point to my view.  Can somebody advice how to do that? Prove $\sin^2\theta + \cos^2\theta = 1$ How do you prove the following trigonometric identity: $$ \sin^2\theta+\cos^2\theta=1$$  I'm curious to know of the different ways of proving this depending on different characterizations of sine and cosine. How do I go about backing up/saving installed device drivers in Windows? I want to reinstall Windows on a machine which has some very obscure drivers. I don't much fancy having to hunt round for them (that's if I'm able to locate them at all). Is it possible to save or backup already installed drivers? If so, how do I do this? How do I then go about installing these 'saved' drivers? The range of $T^*$ is the orthogonal complement of $\ker(T)$ How can I prove that, if $V$ is a finite-dimensional vector space with inner product and $T$ a linear operator in $V$, then the range of $T^*$ is the orthogonal complement of the null space of $T$?  I know what I must do (for a $v$ in the range of $T^*$, I have to show that $v\perp w$ for every $w$ in $\ker(T)$ and then do the opposite), but I don't know how to show that this inner product is zero. Earning a PhD help you learn tools and techniques in your field, and lets you become an expert in a very specific field of science. However, once you get your degree and try to enter the labor market, you're competing against people who are younger than you (i.e. recently graduated non-phd engineers) and may have actual work experience (i.e. non-phd engineers with a few years in the market).  There are, of course, some positions in which they cannot compete, including research and teaching position. Those are the minority, though... in most other fields it seems that holding a PhD is not as important as (for example) work experience.  So, I would like to know:   Is work experience more important than having a PhD in the many work environments? What skills can I acquire/demonstrate during my PhD to become more "valuable" than a non-PhD candidate for the same job? Where are executables for programs stored in Ubuntu?  An application (Komodo Edit) is asking me to identify an application to be used as a web browser. I've become used to just entering the application name as a command for situations such as these, but this scenario got me thinking.   I know in Windows it would just be the relevant application folder in the 'program files' folder, but I'm assuming things are a bit different on Linux?  I thought somewhere like bin would be logical but this appears to standard Linux/Unix applications. Where would I find the binary executable for applications stored on my system? What methods of suicide cause the least amounts of collateral damage? CK2 is a big game with lots of variables, so I'll stick to adding them upon being requested to minimize the hassle.  Anyway, let's say that you have a lot of children and the oldest one claims all the land according to laws of succession. After the father dies, the circumstances will obviously piss off a lot of people (in my case that would be 6 out of 8 vassals and 4 siblings with an opinion of -50 and below one of which is a sister married to the Basileus of the Byzantine friggin' Empire, a case of excommunication, 4 failed assassination attempts under 3 years... and lots and lots of vikings). Let's also say that the current playable character is completely incompetent compare to the next sibling in line.  So, what would be the most optimal methods to off myself without further screwing over the countryside so the next heir in line has to fix it (if we assume that said heir is actually capable of doing so)?  This is my list of DLCs (not including music and unit packs):   Charlemange Legacy of Rome Sword of Islam The Republic Way of Life Export tikz as image file Why does QgsSpatialIndex.nearestNeighbor(point, 1) sometimes return 2 lines? I'm trying to get the closest line to a point using PyQGIS in a plugin. The active code file is this:   When I request the closest line (only 1)  nearestIds = self.spIndex.nearestNeighbor(self.feat2.geometry().centroid().asPoint(),1)   I sometimes get a list with two lines and the first one is not the closest but as far as I can see the second one is. Why is this?   Does QgsSpatialIndex use only boundingboxes for lines? How do I get the real closest line always, not only most of the time? Project Euler - 34 / Find a mathematical approach for upper bound 145 is a curious number, as 1! + 4! + 5! = 1 + 24 + 120 = 145. Find   the sum of all numbers which are equal to the sum of the factorial of   their digits. Note: as 1! = 1 and 2! = 2 are not sums they are not   included.   So I tried a random enough large upper bound (100000) in my program and it worked.  I deleted this part to not spoil the answer  My question is : How to find the closest upper bound using a mathematical approach ? Comment font sizes are inconsistent on Android An issue similar to that described in  and likely to be related.  The comments for a question may vary in size:         Chrome for Android on Nexus 7 running 4.2.2 Jelly Bean. This also occurs on Firefox for Android: A question about a primitive root mod $p=2^{2^k}+1$, where $p$ is prime. wp_get_nav_menu_items order doesn't work