Was "bicycle" ever pronounced "bi-cycle" and if so where and when?
Why is "bicycle" pronounced differently from other obviously related words?
I have a quick question about buttons that toggle between two states. (Think Play/Pause, or Shuffle/Regular Play.) As the title says, should the toggle show it's current state or the state to which it will transition?  I think people are used to the Play/Pause convention. But the Shuffle/Regular play might be more confusing if you show the transition state instead of current. For example, the built-in music player on the Xbox 360 does it this way: when it's in shuffle mode, it shows the icon for direct play and vice versa and it always confuses me (am I in shuffle mode or straight play).  I see it this way: Play/Pause is more like action as in begin playing or pause playing. Yes behind the scenes it is a state transition but to the user, there is an action. Whereas Shuffle/Straight Play is an option and it's best to show the current state (and possibly have only one icon and change button to show that the option is enabled/disabled). Thoughts? How to get the spaces properly on the x axis, how to place the y values on the corresponding bars? I am using the following commands to draw a barchart.  \begin{tikzpicture}         \pgfplotstableread{ % Read the data into a table macro             Label       Female   Male               2006-2008    3     1              2007-2009    2     0             2008-2010    9     2             2019-2011    3     3             2010-2012    11    1              2011-2013    6     0             2012-2014    12    7             2013-2015    10    7             2014-2016    10    3         }\datatable          \begin{axis}[         compat=newest, %Better label placement %        axis on top,         ybar stacked,   % Stacked horizontal bars         xmin=0,              % Start x axis at 0         ymax=25,         ymin=0, ylabel={Number of students}, xlabel={Batches},bar width=10pt,         y axis line style={opacity=0},         yticklabels={\empty},         ytick style={draw=none},enlarge y limits={upper, value=0.2},         xtick=data,     % Use as many tick labels as x coordinates         enlarge x limits = .2,         xticklabels from table={\datatable}{Label}  % Get the labels from the Label column of the \datatable         ]         \addplot [fill=yellow] table [y=Male, x expr=\coordindex] {\datatable};    % Plot the "First" column against the data index         \addplot [fill=green!70!blue]table [y=Female, x expr=\coordindex] {\datatable}; %        \addplot [fill=red!80!yellow] table [y=Third, x expr=\coordindex] {\datatable}; \legend{Male,Female}         \end{axis}         \end{tikzpicture}   I got the picture as,     How to get the spaces properly on the x axis? How to place the y values on the corresponding bars? How to rotate the label 90 degree? How to take out the ticks on the top? Is there any other way of representing this data(two dim only)? (optional)   I hope all the questions can be answered in a single answer? Group of order $p^2$ is abelian. Yes, I know that there are tons of solutions of this up here, but I, essentially, wanted to try it a different way and ah, well.  Let $|G| = p^2$ for some prime $p$.  Consider $x \in G$. So, $|x| = p, $ or $ p^2$. If it is the latter, then, we are done.  So, if $|x|= p$, then, let, $H = [h|  h=x^i, i \in Z] \Rightarrow |H|= p$.  As $p$ is the smallest prime dividing $|G|$, $H$ is a normal subgroup.  Now, consider some $y \in G$, but not in $H \Rightarrow y^p= e$. Then, its easy to show that $G = \langle x,y \rangle$.  Now, consider a homomorphism $f:G \rightarrow \operatorname{Aut}(H), g \to c_g $, wherein $c_g$ represents conjugacy by $g$. So, for example, $c_g(x) = gx g^{-1}$.  Then, it is clear that, $H \subset \operatorname{Ker}(f) $, as it is cyclic and therefore abelian. So, we need only look at $G/H$.  Basically, I am asking for a hint as to why $c_y(x) = yxy^{-1} = x = c_e(x)$, where $x$ and $y$ are the generators of $H$ and $G/H$, respectively?  Because, if I establish it for the generators, then it follows that it applies for for all elements, i.e, that $\operatorname{Im}(f)$ is trivial and therefore that $G$ is abelian.  Thank You! A switch that is only ON if the reference voltage is matched -+ 0.1 volts Im a beginnerish will electronic and im looking for a switch that is only ON if the reference voltage is matched -+ 0.25 volts. So if i have a reference of 2.7v to match and i feed the switch a 2.75v the switch would be ON. But if i feed it  2.5v or 2.85v the switch would is OFF.   This might be a simple google search, but i am lacking the correct terminology. block all but a few ips with firewalld On a linux  networked machine,  i would like to restrict the set of addresses on the "public" zone  (firewalld concept), that are allowed to reach it. So the end result would be no other machine can access  any port or protocol, except those explicitly allowed, sort of a mix of     --add-rich-rule='rule family="ipv4" source not  address="192.168.56.120" drop'    --add-rich-rule='rule family="ipv4" source not  address="192.168.56.105" drop'   The problem above is that  this is not a real list, it will block everything since if its one address its blocked by not being the same as the other, generating an accidental "drop all" effect,  how would i  "unblock" a specific non contiguous set? does source accept a list of addresses? i have not see anything in my look at the docs or google result so far.     EDIT: I  just  created this:  # firewall-cmd  --zone=encrypt --list-all encrypt (active)   interfaces: eth1   sources: 192.168.56.120   services: ssh   ports: 6000/tcp   masquerade: no   forward-ports:    icmp-blocks:    rich rules:    But i can still reach port 6000 from  .123   my intention was that   if a source is not listed, it should not be able to reach any service or port Consider equations defined in $D_x = (0,\infty) \times (0,\infty)$  1) Find the maximal solution to  $$ \dot y = \frac{3t^2}{5y^4} $$ satisfying the initial value problem $y(1) = 2^{\frac{1}{5}}$  I have found the maximum solution to be $((0,\infty), (t^3+1)^\frac{1}{5})$  2) Find the maximal solution to   $$ \dot y = -\frac{2y}{5t}+\frac{3}{5y^4}$$  satisfying the IVP $y(1) = 2^{\frac{1}{5}}$.  (HINT: Use a transformation of the form $t^{\alpha}y(t)$.   I hope someone can explain how to use the transformation to find the maximal solution. One single command to update everything in Ubuntu? Ubuntu 14.04 System Logging I've set up an Ubuntu 14.04 Server (from an Ubuntu 12.04 Server) but today I wanted to look in the auth.log but this file is not used. It seems that ´syslog´ was deleted.  How does Ubuntu 14.04 log? I need this for a server.  Thank you. Dual-boot boot menu does not show up after installing Ubuntu 15.10 alongside Windows 10 Extrude and bevel an imported svg curve When I turn 13 years old, will some of my Roblox account restrictions unlock automatically? How do I restore an accidentally deleted initrd image? Is there a way to find out if I need a transit visa for Canada? Drawing on an image with TikZ Gravatar profile image not showing sometimes It seems that with some profiles the Gravatar image is broken. I am not sure if this is an issue with SE or Gravatar, or both, so posting here.  As an example,  shows an error on , which shows a HTTP 500 on Gravatar.  Profile image on SO:        Image on Gravatar:        Switching to the MSE profile of the user, the image is working (but has a different hash).  Is this a bug on the SE side? Can anything be done to make Gravatar fix this?    Update 2016-10-04:  It happened to me again two times today. The last user profile was . Calling the service two or three times fixes the issue. MSO Review Queue Privileges are Misleading When I visit Stack Overflow, I see the review option in the bar at the top of the screen.    However when on MSO, I don't see it. I assumed this was because I didn't have enough reputation to access the queue. I was curious what the requirement was on meta, so I moseyed on over to the privileges page. To my surprise, I saw that the privilege is listed as only requiring 500 rep and informs me I already have it:    Confused, I manually typed in meta.stackoverflow.com/review to see what would happen. The page did in fact load, but as you can see meta has no "First Posts" or "Late Answers" queue.    Seeing on that page that a minimum of 2k reputation is required to access any queues on MSO, I report the following bug:  1) On the privileges list on MSO, the 500 rep privilege of "Access first posts and late answers review queues" should not appear.  I also have the following feature request:  2) On the privileges list on MSO, it would be useful if instead there was a 2k privilege that informed you that you have access to the "Suggested Edits" and "Low Quality Posts" queues. What is the optimal distance function for individuals when attributes are nominal? I do not know which distance function between individuals to use in case of nominal (unordered categorical) attributes. I was reading some textbook and they suggest Simple Matching function but some books suggest that I should change the nominal to binary attributes and use Jaccard Coefficient. However, what if the values of the nominal attribute is not 2? what if there are three or four values in that attribute?  Which distance function should I use for nominal attributes? Can someone please explain how I can install  in the following ways?   By using the package manager? By downloading and installing a pre-built package? Cannot see pictures on Stack Overflow How to avoid the 'not properly formatted as code' alert