link2sd doesnot work please help
Link2SD not working completely
For an affine connection $\nabla$, prove the curvature R  $R(X,Y,Z,\alpha)=\alpha(\nabla_X \nabla_Y Z - \nabla_Y \nabla_X Z -\nabla_{[X,Y]}Z)$  with $X,Y,Z$ vector fields and $\alpha$ a co-vector, is a tensor.  So I realise the aim is probably to show that each of the three terms in the expression for $R$ are tensors themselves as then the result will obviously follow. However, I'm not too sure how to show each of these terms are tensors. Do I need to expand out each covariant derivate to get a bunch of connection coefficients and then see some cancellations? Still though, I'm not too sure what I'll want to see after all of this so that I can say "…therefore $R$ is a tensor".  Also, very much related to the question, I'm a bit confused with the difference between  $\nabla_Y Z$ $\space \space $ and $\space \space $  $\nabla_{\mu}\omega$.  The second one I know as the covariant derivative of a 1-form, but what is meant by the covariant derivate of a vector $\textit{field}$? As in, what's the difference between the $\nabla_Y$ and $\nabla_{\mu}$?  Edit: In answering this last question, I have realised that $\nabla_YZ=Y^{\mu}\nabla_{\mu}Z^{\nu}$ and $\nabla_{\mu}\omega=\nabla_{\mu}\omega_{\nu}$. I get Chrome notifications from several websites and they work when I don't even have any tabs open for those sites.  But sometimes I get these Chrome notifications when I am not at my desk or looking at my laptop.  As some of these notifications are useful to me, I would like to be able to access any that I have missed.  Is there a way to view the notification history? Do strong and weak interactions have classical force fields as their limits? Electromagnetic interaction has classical electromagnetism as its classical limit. Is it possible to similarly describe strong and weak interactions classically? Mobile notifications unread status independent from full site inbox and achievements It is suggested as an exercise in Serge Lang's book "Algebra" to show that the commutator subgroup $G^c$ of a group $G$ is a normal subgroup.   I'd like to do that but I am afraid I need help,   I think the first thing I need to figure out is how a general element in the commutator subgroup looks like, so that I can check that the defining condition for normality is satisfied.  That is, supposing for a moment that a general element in $G^c$ is denoted by $g$, I need to show that $aga^{-1} \in G^c,$ for all $a \in G$.  But here I get stuck, first because I am unsure how to write a general element in $G^c$ - a simple product in $G^c$ is of the form $xyx^{-1}y^{-1}aba^{-1}b^{-1}$ where $a,b \in G$. I cannot see a way to simplify this - I am sure there is one, but somehow I am blind today.  The second thing then is, even if one tries out the conjugation of a simple element like $xyx^{-1}y^{-1}$ in $G^c$, again not simplification offers itself easily I think .. what am I missing ?  An alternative would be to find a homomorphism of $G$ whose kernel is precisely $G^c$ - here I tried to think of this as a map $G \times G \to G$ but whatever I cook up is not a homomorphism.  Thanks for your hints !! Continuous function on closed unit ball Take a continuous mapping $f: \bar{B^{n}} \rightarrow \bar{B^{n}}$, where $\bar{B^{n}}$ is a closed unit ball in $\mathbb{R}^{n}$. Assume that $f(x) \neq x$ for every $x \in \bar{B^{n}}$. Define another function $r$ by following the directed line segment from $f(x)$ through $x$ to its intersection with $\partial B^{n}$, and let the intersection point be $r(x)$. Is it immediately evident that $r$ is a continuous function? Is so how does it follow? Thanks. Why do rainbows have distinct colors? When I searched on the Internet for the reason of formation of , I got many explanations like  one &amp; . All the explanations consider only one spherical water droplet (like ).  Why don't the refracted waves coming from the adjacent droplets interfere with each other? For example, why doesn't a red ray coincide with a violet ray coming from another droplet at a suitable position?   How are we able to see rainbows with distinct colors? Since there are thousands of raindrops in the sky when it is raining, shouldn't it be a mess due to overlapping of different wavelengths?  Please explain. Is Cesaro convergence still weaker in measure? How to develop intuition for conditional probability? Got a working screen via HDMI, but the DVI won't go past 1360x768 (a PackardBell Maestro monitor). Had no issues in Windows 7.  I've tried all the xrandr tricks, see the output below:   xrandr  Screen 0: minimum 8 x 8, current 3280 x 1080, maximum 16384 x 16384 VGA-0 disconnected (normal left inverted right x axis y axis) DVI-D-0 disconnected (normal left inverted right x axis y axis) HDMI-0 connected primary 1920x1080+1360+0 (normal left inverted right x axis y axis) 510mm x 287mm    1920x1080      60.0*+   59.9     50.0      1680x1050      60.0      1600x900       60.0      1440x900       59.9      1280x1024      75.0     60.0      1280x800       59.8      1280x720       60.0     59.9     50.0      1152x864       75.0      1024x768       75.0     70.1     60.0      800x600        75.0     72.2     60.3     56.2      720x576        50.0      720x480        59.9      640x480        75.0     72.8     59.9   DVI-D-1 connected 1360x768+0+0 (normal left inverted right x axis y axis) 0mm x 0mm    1024x768       60.0 +    1360x768       60.0*    59.8      1152x864       60.0      800x600        72.2     60.3     56.2      680x384        60.0     59.8      640x480        59.9      512x384        60.0      400x300        72.2      320x240        60.1     cvt 1920 1080 # 1920x1080 59.96 Hz (CVT 2.07M9) hsync: 67.16 kHz; pclk: 173.00 MHz Modeline "1920x1080_60.00"  173.00  1920 2048 2248 2576  1080 1083 1088 1120 -hsync +vsync  xrandr --newmode "test" 173.00  1920 2048 2248 2576  1080 1083 1088 1120 -hsync +vsync  xrandr --addmode DVI-D-1 test X Error of failed request:  BadMatch (invalid parameter attributes)   Major opcode of failed request:  140 (RANDR)   Minor opcode of failed request:  18 (RRAddOutputMode)   Serial number of failed request:  37   Current serial number in output stream:  38    I'm using the latest driver from Nvidia (binary, 352.63) because Nouveau would show a black screen on my second monitor.  I got stuck on manually finding/creating a xorg.conf file and adding some monitor hacks, can anyone help me? So, say you are a wizard 15/warlock 2. You have the Lance of Lethargy invocation, which pushes an enemy you target with eldritch blast and hit back 10 feet. Say you put a demiplane entrance ~5 feet behind the enemy you target with it. When you hit, you throw the enemy in. Before all this, you had put a Glyph of Warding in there on one of the surfaces. What would be the limit to the trigger for this? Would it be forced to be touch or proximity, or could you base it off something like hostility towards the caster?      ... When you cast this spell, you inscribe a glyph that later unleashes a magical effect ... You decide what triggers the glyph when you cast the spell. For glyphs inscribed on a surface, the most typical triggers include touching or standing on the glyph, ... (PHB 245)   The key word here is "typical". Based on Google's definition, the informal definition of "typical" is     showing the characteristics expected of or popularly associated with a particular person, situation, or thing.   This means, if my assumption is true, that the triggers in the PHB are only the most common ones. Other than the one about being forcibly at maximum 10 feet in diameter in the PHB, I cannot see a limit. Though I probably should assume this would all be DM discretion, (and I know that I sound like a broken record here) but could the trigger be hostility toward the caster, or something else, like being a specific race, gender, from a specific place, etc., or would it be forced to being something from the PHB? I have two limit problems which are quite similar, so I've put them both into this post.   $((4^{10}+2^{n})^{\frac{1}{n}})$ $((3n^{2}+n)^{\frac{1}{n}})$   Attempt:  For 1, I'm not sure if this is permissible. I know that $\lim_{n \to \infty}(x^{n}+y^{n})^{\frac{1}{n}} = \max\{x,y\}$. Obviously $4^{10}$ is a constant so it's not quite in the same form, but I believe it is still okay to use this result, and so the limit is $2$.  For 2, I've got $((3n^{2}+n)^{\frac{1}{n}}) = (n(3n+1)^{\frac{1}{n}})$, but then I'm not too sure how to proceed.   I also thought of taking the log and proceeding that way, however in the notes I'm learning from they haven't covered l'hopital yet, so I'm trying to not use it.  Thanks. How many $4$ digit even numbers have all $4$ digits distinct ?   This question has been asked if we replace even with positive.   I was solving this Problem like: For first position $1-9$ (No $0$) for next $0-9$ (leaving out the digit which has been choose) for next $0-9$ (leaving out $2$ digits), but on last digit I get stuck. From what I should choose. Will it be $0, 2, 4, 6, 8$, because number needs to be even? How should I solve it? I have added a background image to the world settings. However, it has disappeared from my 3D view and only shows when I view the scene from the camera. Does anyone know if there is something I can do to make it reappear? How to convert an instance of std::string to lower case Find $x,y$ given $\gcd(x,y)$ and ${\rm lcm}(x,y)$ These two exercises I encountered recently seem to develop some type of connection between GCD and LCM I can't quite figure out. Exercise 1:  Find all the numbers $x$ and $y$ such that: $a) \ GCD(x,y)=15, \ LCM(x,y)=150$ $b) \ GCD(x,y)=120 \ LCM(x,y)=1320$ $c) \ GCD(x,y)=100 \ LCM(x,y)=990$  Exercise 2:   Find all the numbers $m,n$ such that $GCD(m,n)=pq , \ LCM(m,n)=p^2qs$  where $p,q,s$ are prime  The first thing that is known to me is that $GCD(x,y) \cdot LCM(x,y)= x \cdot y$ Also $LCM(x,y)$ is at most $x \cdot y$ while $GCD(x,y)$ is at most $\max \{x,y\}$. Last thing is that $GCD(x,y)|LCM(x,y)$. Using all this I tried to solve the first exercise: $a)$ First two obvious pairs are $x=15, y=150$ and $y=15, x=150$. Now neither of the numbers can be bigger than $150$ or smaller than $15$. So we are looking for numbers in the range $15-150$ that satisfy $x \cdot y = 15 \cdot 150$ Another such pair is $(x,y)=(30,75), \ (x,y)=(75,30)$. Similarly for $b)$ we find that the only possible values are permutations of the set {$120,1320$} and in $c)$ since $100$ does not divide $990$ no such numbers exist. Now exercise 2 is what made me think there is actually another connection I'm not quite aware of since now it's about arbitrary prime numbers and the previous method doesn't work anymore. My intuition is that it has something to do with $GCD$ or $LCM$ of the $GCD(x,y), \ LCM(x,y)$ Fell for fake sugar daddy. How do I get out? I fell on hard times and for the first time I attempted to get a sugar daddy. He asked for my bank account login info and reluctantly I gave it to him even though I knew I shouldn't have. Short story, I figured out he's fake and called him out on it after he made a couple of mobile deposits. Every time he made a mobile deposit he would go in there and take a third of the money he deposited. I also noticed he somehow used an old check I deposited and changed it and used it again. I got him to admit he wasn't who he claimed to be and I changed my login info. He claimed he could still see how much money was in my account and sent me a screenshot of how much money was in the account with the amount and &quot;Chase checking&quot; before it. That was the only information in the screenshot. He also threatened to get me in trouble with the law if I didn't send him more money. I changed my login info again just in case but I could really use some advice on what should I do next. I know Wonder Woman has died in canon before, but in which issue did this happen? Linear functional and a bounded norm I'm trying to work through some example questions for my class but there is no mention of "Piecewise affine functions" anywhere and I'm completely stumped on how to do this.  Any help would be appreciated please. 1.I will study hard until I get a high score on this exam. 2.I will study hard until I've gotten a high score on this exam.  I think these sentences are grammatically correct. but if I add a specific time, I think these sentences have to be only this one:  3.I will study hard until I get a high score on this exam on July 25th.  And how about these?  a. I'd like to watch all of the holocaust movies present in the world until I've become an expert on it. b. I'd like to watch all of the holocaust movies present in the world until I become an expert on it.  Since there's no a word representing a specific time, both of them are okay, right? And what I'd like to know is the difference between &quot;have gotten&quot; and &quot;get&quot;. What I know about them is we can use &quot;future perfect&quot; to refer to unspecific future event that might happen before some accident. but &quot;get&quot; refers to future event that could be either a specific scheduled event or unspecific future event. that's why if I add a specific time mentioning, I have to use &quot;get&quot;.