Khreshchatyk and Kostyolna streets, no definite article
Use of definite article before phrases like Heathrow Airport, Hyde Park, Waterloo Station, Edgware Road and Parliament Square
I have an object x. I'd like to copy it as object y, such that changes to y do not modify x. I realized that copying objects derived from built-in JavaScript objects will result in extra, unwanted properties. This isn't a problem, since I'm copying one of my own literal-constructed objects.  How do I correctly clone a JavaScript object? How can I get a list of all packages in a repository section from command line? Can Ubuntu use all my 4GB of RAM? I'm trying to execute a string into my bash script. String contains variables (so I could substitute some CLI arguments depending on circumstances).  The problem is when I use variable containing --argument=value, everything breaks up, giving error:  Missing trailing-' in remote-shell command.   Example code:  #!/bin/bash  rsync_path="/usr/bin/rsync -azhrP" rsync_ssh_cmd="--rsh='ssh -o Compression=no'"  `$rsync_path /path/to/file $rsync_ssh_cmd username@localhost:/tmp`   If I just echo the last string from this code, it looks fine. But if i try to execute this string from script, it doesn't executes as expected.  I found a workaround - everything became OK if I try  eval "my-command-string"   instead of  `my-command-string`   or  (my-command-string)   Why does it so? How could I (should I really?) avoid to use eval?  I use bash 4.3.11(1)-release (x86_64-pc-linux-gnu) (Kubuntu 14.04.3). Using Newton's Law of Universal Gravitation to find distance, with the question not giving sufficient information to substitute into the equation. Problem:  $F = \frac{(G m_1 m_2)}{r^2}$  An object of unknown mass is placed directly between the Earth and the Moon such that the forces of gravity acting on the object are equal from both the Earth and the Moon. The distance from the Moon to the object is exactly one-tenth of the distance from the Moon to Earth. Using the above formula, determine the distance from the Moon to the Earth.  Given is:  The factor $G≈6.67∙10−11\mathbf{N(\frac{m^2}{kg^2})}$ is a universal constant.  Mass of Earth $≈5.972∙10^{24}\mathbf{kg}$   Mass of the Moon as $≈7.348∙10^{22}\mathbf{kg}$  Mass of unknown object = $m$  My solution:  $F = \frac{(6.67 *10^-11) m (7.348*10^{24})}{R^2}$  $F = \frac{(6.67 *10^-11) (5.92* 10^22) m}{10R^2}$  As gravitational force acting on the object is equal   $\frac{(5.92\cdot 10^22)}{100r^2} = \frac{(7.348*10^{24})}{r^2}$  $R = 1.24 \cdot 10^4 KM$  Is this a viable solution to the problem? Please provide feedback. Thank you! Plot Details/Summary I only watched an episode or two of this one, so I can't recall a whole lot about it.  The protagonist is a former astronaut of some sort, who makes it his mission to clean up the crime in his city.  He might have been a police officer in his &quot;new life&quot; or he might have decided to become a sort of quasi-superhero.  In either case, I distinctly recall his space suit being the gimmick that makes him an effective crime fighter in the show.  I seem to recall the protagonist being a young, dark-haired man, and I think he had a friendship or an alliance with a young woman (maybe a fellow cop, or someone from the space program?).  I don't think there were alien beings in the show.   The criminal threats were all quite terrestrial, IIRC. Timeframe and other Publication Details This was a syndicated tv show I saw on American television, probably around the late 90s to early 2000's.  I believe the show was filmed in Canada, though I'm not certain.  I don't think it lasted very long - it was pretty dreadful.  I can say for certain the show is not Space Cop or Gerry Anderson's Space Precinct. What’s the best way to reload / refresh an iframe? Sarrus Rule with LaTeX I couldn’t find any proof on the internet. I would appreciate an elementary proof , but any help would be appreciated!  Thank you. How to negate a specific symbol? I want to negate the symbol whose code is \models (this would be specific to Formal Logic). How can I do that? I tried a number of combination, but didn't find how this could be done. I tried \neqmodels, \nemodels, \notmodels, \nmodels  but all of them are wrong.  Is there a general way to negate symbols? The easiest way to explain this question is with a thought experiment:  Consider God, the ultimate of everything, who is wholly omnipotent (all-powerful) and omniscient (all-knowing). Let's just say, hypothetically, that he wanted  (this is a totally random example I just happened to be reading about; I could have just as easily said He wanted Bob to score a free-throw in basketball 3 times in a row tomorrow, or Sally to knit a blue sweater on Sunday, November 4th, 2012).  But anyways, one way He could do this (get X group of people to save a man from a burning car) is: At the beginning of time, God could instantly plan out the future and set in motion a massive chain of events, from the creation of light and stars, the creation of Earth and the creatures, mankind, then civilization with all the conflicts and progress and glory that comes with it, such that one day, a few people would come from out of nowhere—complete strangers to each other—and save this man (also a stranger) from under a burning car. God need not intervene at all this whole time, He merely "ignited" the chain of events from day 1 and watched it unfold exactly as He planned. Let's call this Universe A.  He could also, being all-powerful, just freeze time for a bit and skip a few steps, creating the world and universe instantly, with all the civilizations and animals and things in place, putting all the strangers there together next to a car which is already on fire and the man trapped under it. Then press play, and presto, you have the exact same scenario, without billions of years of buildup. Let's refer to this as Universe B.  God is obviously capable of doing both. My question thus is whether there is an  (really any difference at all) between Universe A and Universe B. Personally, I don't think this kind of power is outside of God's capability; he should, after all, have no problem with creating identical universes which match up exactly once they reach "biker under the car" moment where He unfroze time in Universe B. At that moment, Universe A and Universe B are exactly the same, right? Or is there somethinge special about Universe A, with all it's buildup, that separates it intrinsically from Universe B? In other words, is it outside of God's ability to make them exactly equivalent? Get the subdomain from a URL Getting the subdomain from a URL sounds easy at first.  http://www.domain.example   Scan for the first period then return whatever came after the "http://" ...  Then you remember  http://super.duper.domain.example   Oh. So then you think, okay, find the last period, go back a word and get everything before!   Then you remember  http://super.duper.domain.co.uk   And you're back to square one. Anyone have any great ideas besides storing a list of all TLDs? Blank lines in an equation and some other similar function Why blank lines between equation makes error? there are a lot of commands in latex and almost for all of them these blank lines are not important,  but why in this case is important and is there any similar function? There is a lemma that says if a group $G$ has no proper nontrivial subgroups, then $G$ is cyclic. And here is the proof of the lemma:     Suppose $G$ has no proper nontrivial subgroups. Take an element $a$ in $G$ for which $a$ is not  equal to $e$. Consider the cyclic subgroup $\langle a \rangle$. This subgroup contains at least $e$ and $a$, so it is not trivial. But $G$ has no proper subgroups, so it must be that $\langle a \rangle = G$. Thus $G$ is cyclic, by definition of a cyclic group.   But here i do not understand the following: Why must $\langle a \rangle$ be a subgroup of $G$? For every single element $a$ in $G$, if $\langle a \rangle$ is a subgroup of $G$, then every group should have at least as many subgroups as the number of its elements. I would appreciate any help. Thanks Prove $(a+b)^\frac{1}{n} \le a^\frac{1}{n} + b^\frac{1}{n}$ Prove: $$ (a+b)^\frac{1}{n} \le a^\frac{1}{n} + b^\frac{1}{n}, \qquad \forall n \in \mathbb{N} $$ I have have tried using the triangle inequlity $ |a + b| \le |a| + |b| $,  without any success. Dual boot => Triple boot A 256GB SSD has Windows-10 and 16.04 installed.  BIOS not UEFI.  A charity I work with requires me to use Quickbooks Desktop on Windows.  The plan is to ghost the existing system to a 512GB or larger SSD and create a third bootable Windows 7  partition for performing charity activities.   Is this possible to have a third partition? Is there a good example you have used as a guide? Is triple booting with two Windows partitions different from 2 Linux partitions?   If you have done this before ( with GRUB) please indicate this in your response: lessons-learned are appreciated.  Thank you Why don't we define division by zero as an arbritrary constant such as $j$? Why don't we define $\frac 10$ as $j$ , $\frac 20$ as $2j$ , and so on? I know that by following the rules of math this eventually leads to $1=2$ , but we could make an exception and say that $j$ is the only number such that $0*j \not= 0$ , and put other restrictions necesary so that we don't get contradictions. We do this for $i$ , so why can't we do it here? For example, $i^2$ , is defined as $-1$ , but you could also say $i^2=\sqrt {-1} *\sqrt {-1}=\sqrt {(-1)(-1)}=\sqrt{1}=1$ , but we make an exception for this. Proof conclusion to: Let m,n $\in$ $\mathbb{N}$ $\backslash$ $\{0\}$ . Prove that $s |\tau (m^{s}) - \tau(n^{s})$, where $\tau$ is a divisor function.   Hello, so I have a tiny question about the summarization of my proof.  I got to the point where I defined my $\tau$ divisor function and got them both $\tau(m^s)$= $\prod$ something +1 and $\tau(n^{s})$ = $\prod$ something +1.    I've noticed that the last terms of the polynomial are both one. Why is it with the +1 part, I can conclude with that:  s| $\tau(m^s)$ - $\tau(n^s)$.   The line for why that is, isn't quite clear. Using getline(cin, s) after cin I want to refresh the entire service console on clicking of the save button on the visual force page. The button is an inline visual force page. Any ideas?  &lt;apex:includeScript value="/soap/ajax/26.0/connection.js"/&gt; &lt;apex:includeScript value="/support/console/26.0/integration.js"/&gt; &lt;script type="text/javascript"&gt; function focusAndSave() {     document.getElementById('focusMe').click(); }     &lt;/script&gt;     &lt;apex:form &gt;     &lt;apex:pageBlock id="pb"&gt;         &lt;apex:pageMessages id="errMsgsId"&gt;&lt;/apex:pageMessages&gt;         &lt;input type="text" id="focusMe" style="display:none" /&gt;         &lt;apex:pageBlockTable id="table" value="{!candidateMap}" var="c"&gt;             &lt;apex:column value="{!candidateMap[c].Contact__r.Name}"/&gt;             &lt;apex:column value="{!candidateMap[c].Submitted_at__c}"/&gt;             &lt;apex:column value="{!candidateMap[c].Interview_Availability__c}"/&gt;             &lt;apex:column value="{!candidateMap[c].Notice_Available__c}"/&gt;             &lt;apex:column headervalue="Stage"&gt;                 &lt;apex:outputfield value="{!candidateMap[c].Stage__c}"&gt;                     &lt;apex:inlineEditSupport event="ondblclick"/&gt;                 &lt;/apex:outputfield&gt;             &lt;/apex:column&gt;             &lt;apex:column headervalue="Ideally looking for"&gt;                 &lt;apex:outputfield value="{!candidateMap[c].Ideally_looking_for__c}"&gt;                     &lt;apex:inlineEditSupport event="ondblclick"/&gt;                 &lt;/apex:outputfield&gt;             &lt;/apex:column&gt;             &lt;apex:column headervalue="Action"&gt;                 &lt;apex:commandLink value="Save" action="{!saveCandidate}" rerender="errMsgsId,table" onclick="focusAndSave()" oncomplete="testGetFocusedPrimaryTabId()"&gt;                     &lt;apex:param name="candidateId" value="{!candidateMap[c].Id}" assignTo="{!candidateId}"/&gt;                 &lt;/apex:commandLink&gt;             &lt;/apex:column&gt;         &lt;/apex:pageBlockTable&gt;         &lt;apex:panelGrid columns="7" style="margin: 0 auto;"&gt;             &lt;apex:outputLabel value="{!noOfRecords} records found"&gt;&lt;/apex:outputLabel&gt;             &lt;apex:commandButton status="fetchStatus" reRender="pb" value="|&lt;" action="{!first}" disabled="{!!hasPrevious}" title="First Page"/&gt;             &lt;apex:commandButton status="fetchStatus" reRender="pb" value="&lt;" action="{!previous}" disabled="{!!hasPrevious}" title="Previous Page"/&gt;             &lt;apex:commandButton status="fetchStatus" reRender="pb" value="&gt;" action="{!next}" disabled="{!!hasNext}" title="Next Page"/&gt;             &lt;apex:commandButton status="fetchStatus" reRender="pb" value="&gt;|" action="{!last}" disabled="{!!hasNext}" title="Last Page"/&gt;             &lt;apex:outputLabel value="Page {!pageNumber} of {!pagecount}"&gt;&lt;/apex:outputLabel&gt;         &lt;/apex:panelGrid&gt;     &lt;/apex:pageBlock&gt; &lt;/apex:form&gt;