Why didn't R2-D2 and/or C-3PO spill the beans?
Why doesn't C3PO recognize Leia in R2's recorded message?
When should we use "and" and/or "and/or"? What's the difference between "and" and "and/or"?  How do we decide whether to use one or the other?  Note: Also it would be great if someone could explain how do we actually pronounce "and/or" verbally in a sentence... For an odd prime $p$, prove that any primitive root $r$ of $p^n$ is also a primitive root of  $p$   So I have assumed $r$ have order $k$ modulo $p$ , So $k|p-1$.Then if I am able to show that $p-1|k$ then I am done .But I haven't been able to show that.Can anybody help me this method?Any other type of prove is also welcomed. Gendry was born in the Crownlands and should therefore be referred to as Gendry Waters. However, he refers to himself as Gendry Rivers.   Did showrunners forget or is Gendry ignorant of the customs? How do I record a screen cap video of the iPad? I'm looking for a method to record the video without actually filming the device. Does such a method exist? In comments, moderators have their diamonds in the OP rectangle:        And in the review (suggested edits), mods have their diamonds outside the blue OP background highlight rectangle:        Of course, it Doesn't Really Matter At All, but it is a small discrepancy (I am not saying that in the review, OP rectangles have a bigger padding). Give each NodeJs Process a name in Windows TaskList The units of $\mathbb Z[\sqrt{2}]$ Proving at least 99 pairwise sums of the reals are non-negative Suppose, one hundred real numbers are given and their sum is 0.Then how can I prove that at least 99 of the pairwise sums of these hundred numbers are non-negative?  I tried this: Let the real numbers be $a_i$,$1\leq i\leq100$. By the given condition, $a_1+a_2+\dots +a_{100}=0$.Suppose for the sake of contradiction, that at most 98 of the pairwise sums of these given reals are non-negative.I just tried to examine the case when exactly 98 of them are non-negative. I labelled the sums $S_1$,$S_2,\dots S_{4950}$,WLOG assume that sums $S_1,S_2,\dots S_{4852}$ are negative, the rest are non-negative. $$S_1+S_2+\dots +S_{4950}=99(\sum_{i=1}^na_i)=0$$ Case I: $S_{4853}+a_{4854}+\dots +a_{4950}=0$.That simply means that $S_1+S_2+\dots +S_{4852}=0$.But, by the given condition, $S_1+S_2+\dots +S_{4852}&lt;0$,a contradiction.After that, I am not able to make any progress.  Can anyone please suggest a more efficient method to solve this problem.I feel this approach will involve enormous case work. The volume "filesystem root" has only 0 bytes disk space remaining? How do I show that if $f : [0,1] \to [0,1]$ is continuous, then there is some $c$ such that $f(c) = c$? Theorem: Let $f:[0,1] \to [0,1]$. Assume $f$ is continuous. Then there exists   $c \in [0, 1]$ such that $f(c) = c$.         For any function $f$, let $g(x) = f(x) − x$. If the theorem is true, what does that say about $g(c)$?   Write a proof of the theorem. Do it by applying the Intermediate Value Theorem   in the appropriate way to the function $g(x) = f(x) − x$ with $a = 0$ and $b = 1$. Clearly state why the hypotheses of the IVT are satisfied here.        Well if the theorem is true, then there exists $c$ such that $f(c) = c$. Then $f(c) - c = 0$. Then $g(c) = 0$. Intermediate Value Theorem: Let $I$ be an interval and $f$ a function whose domain contains $I$. If $f$ is continuous, then for all $a, b \in I$ with $a &lt; b$ and all real numbers $k$, if $k$ is strictly between $f (a)$ and $f (b)$, then there exists $c$ such that $a &lt; c &lt; b$ and $f (c) = k$.   Proof Attempt: Take $a = 0$ and $b = 1$. Then $a,b \in[0,1]$ and $a &lt; b$. Since $f:[0,1] \to [0,1]$, it follows that for all real numbers $k$ such that $f(a) &lt; k &lt; f(b)$, then there exists $c$ such that $a &lt; c &lt; b$ so $0 &lt; c &lt; 1$ and $f(c) = k$. Then $f(c) - k = 0$. Thus, since $g(x)=f(x)-x$, it follows that $g(c) = 0$.   Looking to see if I did this correctly and/or if there is a more elegant way to prove problem 2. I am a little confused why the first theorem is true, but I went with it. Windows equivalent of the Linux command 'touch'? SSH connection problem with "Host key verification failed..." error I can connect to another Ubuntu machine in my LAN via SSH. On both of then PC's I installed   but from another Ubuntu computer I can not connect to my PC via SSH and I got this error:     Host key verification failed... Is it possible to assign the same value to multiple keys in a dict object at once? What is the difference between update-grub and update-grub2? I'm making some changes on my grub file under /etc/default/grub. In some tutorials I have seen sudo update-grub and others sudo update-grub2. What is the difference? Select organic group on the user registration form There's a post already on the post installation forum, but I'm not sure if this is a OG bug.   I am using Drupal 7 and OG 7.x-2.1 version. There is no "Group Audience" in the manage fields page and I think it is replaced with "Group membership", the field type is "Entity Reference" and the widget is "OG Reference". Also there is no input type in the field setting page and I can not find any field that has a "Always show other groups" option. I have checked the option "Show on registration form of that field, but the combo box on the registration form does not have any option. Any suggestion? What is covered by CDIC savings deposit insurance? Where should the apostrophe go on a possessive abbreviation? When expanding an abbreviation in parentheses, sometimes the thing that was abbreviate was used in a possessive context.  Consider the following example:     If the Giant Ostrich Bomb's (GOB) fuse is too short, you may be too close when it goes off and you may get kicked in the face.   Is the above correct, or should it be rewritten this way instead:     If the Giant Ostrich Bomb (GOB)'s fuse is too short, you may be too close when it goes off and you may get kicked in the face.   If this is a matter of style, do any of the popular style manuals have a recommendation? How do I show that if there are functions $f,g$ such that$$ f(g(x)+g(y))=bx+cy $$holds for all $b,c\in\mathbb{R}$, then we necessarily have $b=c$? Is this even true? It seems so, but I'm just not sure how to explain it in detail and using theory from functional equations. Any ideas?  Extra: In addition, I'd like to prove that there are no pair of functions $f,g$ such that$$ y^2+z^2=f(x,g(y-x)+g(z-x)). $$ Any ideas on how to prove this? Plus, does anyone know some literature regarding this type of problems? Package repository down, how to relocate? I would like to use the function of TeXnicCenter 1.0, where is automatically downloads missing packages used. The problem is, that the repository it wants to download from does not exist anymore (the one on piotrkosoft.net).  How do I get TeXnicCenter to try with another repository? After upgrading from Ubuntu 13.04 server, the www pages won't display themselves.     Error 403 Forbidden You don't have permission to access / on this server.   I've changed access control saves from apache2.2 to apache2.4, but that didn't work. What else could I do?