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Let $R$ be an integral domain. If $x \in R$ is prime, then $x$ is irreducible. I often read outputs in the terminal that get wrapped as they are too long. Since there is no way that I can modify the printed output, I need to let the Terminal allow for horizontal scrolling.  Is there a modification I can make to the default OS X Terminal to disable line wrapping and allow for horizontal scrolling?  Or do you know another alternative I can use? There's another question on physics.SE whose , if I have understood it correctly, explains that the farther the points are in space the faster they are moving away from each other.     Actually, the apparent speed with which two of the points on the   circle in a distance $D$ of each other would move relative to each   other will be $v = H_0 D$ where $H_0$ is the speed the balloon itself   is expanding.   This means that even the ruler sitting on my desk is expanding, just that the expansion is very very slow owing to the ruler's small size relative to the cosmic scales. However, if everything is scaling then everything should apparently be of the same size to an observer in such an expanding space. The  quote from the show "The Big Bang Theory" comes to mind.   To be able to counter that, there're some phenomena that we can observe which are scale invariant. Red-shift would be one such phenomenon. But is red-shift the only way we can tell that the space is expanding? Is there a logical flaw in my thinking? I know that red-shift is a result of the Doppler effect - there's bound to be a decrease in the frequency of a signal, as perceived by an observer, emitted by a source which is moving away relative to the observer. How do you programmatically set an attribute? Suppose I have a python object x and a string s, how do I set the attribute s on x? So:  &gt;&gt;&gt; x = SomeObject() &gt;&gt;&gt; attr = 'myAttr' &gt;&gt;&gt; # magic goes here &gt;&gt;&gt; x.myAttr 'magic'   What's the magic? The goal of this, incidentally, is to cache calls to x.__getattr__(). How to insert a very large number of records into a MySql database as fast as possible what are all the open subgroups of $(\mathbb{R},+)$ For every vector space $V$ does there exist a linear functional $f$ ( a linear map from $V$ to $F$ the underlying field ) such that for some $ \vec v \in V$ , $f(\vec v) \ne 0$ ? If it does exist , can we prove the existence without the "axiom of choice " ? Is the existence equivalent to axiom of choice ? If RSA is limited to 117-200 bytes or so, is that a very limited use case? Am I missing something, or is RSA very very limiting when it comes to ecrypting data when it comes to the actual message size?  I have read that you can only encrypt a message of around 117 to 200 bytes in size (depending on your key size: 1024 or 2048 bits). Is this correct?  If so, I think I have read people suggesting on using it for larger files. I guess they are just repeating the process many times over and over in blocks of 117 bytes? I've got two tables:  TableA ------ ID, Name  TableB ------ ID, SomeColumn, TableA_ID (FK for TableA)   The relationship is one row of TableA - many of TableB.  Now, I want to see a result like this:  ID     Name      SomeColumn  1.     ABC       X, Y, Z (these are three different rows) 2.     MNO       R, S   This won't work (multiple results in a subquery):  SELECT ID,        Name,         (SELECT SomeColumn FROM TableB WHERE F_ID=TableA.ID) FROM TableA   This is a trivial problem if I do the processing on the client side. But this will mean I will have to run X queries on every page, where X is the number of results of TableA.   Note that I can't simply do a GROUP BY or something similar, as it will return multiple results for rows of TableA.   I'm not sure if a UDF, utilizing COALESCE or something similar might work? Why is the application of probability in QM fundamentally different from application of probability in other areas? What is the fate of the Asgardians at the start of Avengers: Infinity War? Thor: Ragnarok ends with the remaining people of Asgard aboard a refugee ship that meets Thanos' ship. Avengers: Infinity War opens with      Thanos and his minions having commandeered the ship and several bodies can be seen on the floor.   This begs the question, what happened to these characters:   Korg Miek Asguardian extra #3 Valkyrie Confidence interval interpretation in linear regression when errors are not normally distributed If $m$ divides $n$, find a free resolution of $\mathbb{Z}/m$ as a $\mathbb{Z}/n$-module. If $m$ divides $n$, find a free resolution of $\mathbb{Z}/m$ as a $\mathbb{Z}/n$-module.   I have tried this one and got $0 \leftarrow \mathbb{Z}/m \leftarrow \mathbb{Z}/n \leftarrow \mathbb{Z}/n$.  The map $\mathbb{Z}/n \to \mathbb{Z}/n$ is multiplication by $m$, but I couldn't go further. Please help me. How does one type Chinese in LaTeX? At what time will the upcoming Ubuntu release be made available? Resizing Mac OS partition - macOS High Sierra Limit as $x\to 2$ of $\frac{\cos(\frac \pi x)}{x-2} $ given the 2 PDE  $$ \Delta u-au_{tt}+u_{t}=0$$  and $$ \Delta u + Du*Df=0 $$  here $ \Delta u $ is the Laplacian $ Du= grad(u) $ is the gradient and * means scalar product $u_{t} = \frac{\partial u}{\partial t}$  my doubt is what term should i include to get the linear part of the equations $ u_{t} $ and $Du*Df $ from the Euler Lagrange equations in $ R^{n} $ thanks How do I change the angle of the axis without changing the angle of the object? Hey guys I am currently working on a scene with multiple objects.  There is one object (a wheel) that I need to rotate the origin for without rotating the wheel itself.  I have the exact angle that I need so a manual solution would be the best.  Any help would be much appreciated. I am used to parametric modeling and Blender is a little out of my depth. Macbook pro Mid-2012 not booting on battery. Not responding to power button Macbook pro Mid-2012 - Keyboard not working (Space and Caps lock only works) - Doesn't switch on using battery, when I remove the battery connector from board and Plug on AC it boots. I had recently changed the HDD to SSD myself.