NodeJS write or delete cookies on a specific route
Cookie path and its accessibility to subfolder pages
Let $(a_n)$ be a sequence of positive terms and suppose that $\sum_\limits{n=0}^{\infty} a_n$ converges. Show that $\sum_\limits{n=0}^{\infty} a_n^2$ converges.   This is in the section on the Comparison Test so that must be what I'm supposed to use.  But I don't see how.  $(a_n)^2$ might be smaller or larger than $a_n$ depending on $a_n$.  And I can't use the Comparison Test with some other series because there's no info here about how fast $\sum a_n$ converges.  Hmm.  Any hints? .       The  has no sign of the user sharth The  also does not have any sign of related activity   I would like to know why the user's name is associated with the question. At least why their display name shows up as having modified the question timeline activity.  Possible reason that I can think of is that, .  Is this the reason?  Is there a way (for normal users), to look for such details, other than looking at the user activity and the question's revision history. What is the correct name for a "product function" on a monoid? SQL Server: Examples of PIVOTing String data I am a newbie in linux. I wanted to install ubuntu to my desktop. I currently have two partitions, Windows 8 in installed on one, and i have some important files in another partition. While installing ubuntu, if I chose "Replace Windows 8 with Ubuntu", do I lose the other partition too?   And are there other ways to leave the other partition as it is, and install ubuntu in the partition  where windows was installed. Bad Character code (256)/ \select@language{greek} I want to have a  video background that will loop on some frames of my presentation. Can anyone help me to do that? Derivation of binomial coefficient in binomial theorem. How was the binomial coefficient of the binomial theorem derived?  $$\frac{n!}{k!(n-k)!}$$ Extension “RANDR” missing on xvfb My system:  $lsb_release -a No LSB modules are available. Distributor ID: Ubuntu Description:    Ubuntu 14.04.3 LTS Release:        14.04 Codename:       trusty   Xvfb:  $ dpkg -s xvfb Package: xvfb Status: install ok installed Priority: optional Section: x11 Installed-Size: 2140 Maintainer: Ubuntu X-SWAT &lt;ubuntu-x@lists.ubuntu.com&gt; Architecture: amd64 Multi-Arch: foreign Source: xorg-server Version: 2:1.15.1-0ubuntu2.7 Provides: xserver   Current problem:  Xvfb do not support RANDR extension, even if I add the flag:  +extension RANDR   If I run xdpyinfo, RANDR is not on the list. It's a missing feature or a bug. I found a reference here with a patch:   And looks like that in other distros like debian, there is already a testing build of Xvfb with support:   I am trying to run a program throught Xvfb, and it returns the following error:  Xlib:  extension "RANDR" missing on display ":99".   The program works if I run it via ssh/command line. The problem appears to be the the lack of support for "RANDR" in xvfb.  My question is: what is the easiest way to get xvfb with "RANDR" support in my system? Finding $\int^{\infty}_{0}\frac{\ln^2(x)}{(1-x^2)^2} dx$ I'm setting up an online ordering system but I'm in Australia and for international customers I'd like to show prices in US dollars or Euros so they don't have to make the mental effort to convert from Australian dollars.  Does anyone know if I can pull up to date exchange rates off the net somewhere in an easy-to-parse format I can access from my PHP script ?    UPDATE: I have now written a PHP class which implements this. . Usage and origin of "sister" in expressions like "sister company, sister ship, sister site" etc The term  is often  used figuratively  to refer, for instance,  to a “sister company” for a company  within the same group, or to a “sister  site” for  sites that belong to the same family. This connotation as explained by the   means:         belonging to a pair or group of similar and related things, such as businesses, usually owned or operated by the same person or organization:         our sister company in Australia.          also, from :        You can use sister to describe something that is of the same type or is connected in some way to another thing you have mentioned.    ⇒ ...the International Monetary Fund and its sister organisation, the World Bank.   ⇒ ...Voyager 2 and its sister ship, Voyager 1.       This usage appears to be common with things that are  regarded as feminine and are associated, as if by kinship,  with other similar things that belong to the same group. An early  usage example of this is the "sister" referred to  ships:         the US battleship Missouri and her sister ship, the Wisconsin.      In other instances,  the "feminine" issue is less explicit as in the case of internet sites, so I guess this usage has to do with the fact that English is less gender specific when it comes to things or abstract entities.   Questions:    Does “sister” apply to whatever entity that belongs to the same group irrespective of its real or perceived gender? or could "brother" be used instead?  Where does this usage come from? I want to determine the set of natural numbers that can be expressed as the sum of some non-negative number of 3s and 5s.  $$S=\{3k+5j∣k,j∈\mathbb{N}∪\{0\}\}$$  I want to check whether that would be: 0,3, 5, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, and so on.  Meaning that it would include 0, 3, 5, 8. Then from 9 and on, every Natural Number. But how would I explain it as a set? or prove that these are the numbers in the set? Breitbart today:   What is the source for the term nothing-burger? Well, luckily I got this error on my test environment. I'm so scared about this error that I disabled all logon triggers I was using on production environment.   I created the famous logon trigger, and I put a database in offline mode just to mess with something else. Then I discover that because the trigger can't find the table, I can't access the instance anymore. There are plenty of questions related to this, but even doing everything I could find, I still can't acces the instance, not even with SQLCMD.  I'm doing this:  sqlcmd -S server\instance -U sa -P &lt;pass&gt;  -A   If I don't use -A I receive the famous error:  logon failed for sa due trigger execution.   If I use -A:     Sqlcmd: Error: Microsoft ODBC Driver 11 for SQL Server : SQL Server   Network Interfaces: An error occurred while obtaining the dedicated   administrator connection (DAC) port. Make sure that SQL Browser is   running, or check the error log for the port number [xFFFFFFFF]. .   Sqlcmd: Error: Microsoft ODBC Driver 11 for SQL Server : Login timeout   expired. Sqlcmd: Error: Microsoft ODBC Driver 11 for SQL Server : A   network-related or instance-specific error has occurred while   establishing a connection to SQL Server. Server is not found or not   accessible. Check if instance name is correct and if SQL Server is   configured to allow remote connections. For more information see SQL   Server Books Online..   Why i'm not able to connect to the sql server    sql server express here.  I could enable SQL Browser, but I still can't access it.  I don't think this question is duplicated because is not about the trigger, is about Why I can't access the server with SQLCMD. I pretty much know how to fix this. I just don't know how can I acces sql server without triggering the trigger. I am afraid that listing doesn't support javascript.  \begin{lstlisting}[language=javascript] ... \end{lstlisting}   What am I doing wrong? How to programmatically remove a field from a node? Uniform convergence of $\sum (-1)^nf_n(x)$ on $[0,1]$ where $f_n(x)=x^n(1-x)$. Let $f_n(x) = x^n(1-x)$ and $\sum (-1)^nf_n(x)$.  I showed that this series point wise.  Case1) $x=1$ $$ f_n(1)=0 \, , \sum{(-1)^nf_n(1)} = 0 $$ Case2) $x\neq 1$ $$|f_n(x)| \leq |x|^n$$ since $$\sum |x|^n$$ converges, By abosultely convergese test $\sum (-1)f_n(x)$ converges.  I want to show that this series uniformly converges on $[0,1]$. mysql database no space available Could it be that Goldbach conjecture is undecidable? The result closest to Goldbach conjecture is Chen's theorem [Sci. Sinica 16 157–176], the proposition ``1+2''. It is natural to ask if it is likely that under our arithmetic axioms the Goldbach conjecture is an undecidable proposition.