Android Changing xml
What is a NullPointerException, and how do I fix it?
Finding the number of non-negative integral solutions of $x + y + z = 10$ We can solve the equation $x^x=c$ using the Lambert $W$ function, but how do we solve $x^{x^x}=c$ , Explanation of method for showing that $\frac{0}{0}$ is undefined (This was asked due to the comments and downvotes on this  answer. I am not that good at maths, so was wondering if I had made any basic mistakes)  Ignoring limits, I would like to know if this is a valid explanation for why $\frac00$ is undefined:     $x = \frac00$    $x \cdot 0 = 0$        Hence There are an infinite number of values for $x$ as anything multiplied by $0$ is $0$.   However, it seems to have got comments, with two general themes.  Once is that you lose the values of $x$ by multiplying by $0$.  The other is that the last line is:      $x \cdot 0 = \frac00 \cdot 0$   as it involves a division by $0$.  Is there any merit to either argument? More to the point, are there any major flaws in my explanation and is there a better way of showing why $\frac00$ is undefined? How to Sync OneDrive Business /Office 365 on Linux? Microsoft OneDrive Business/Office 365 Pro offers 1 TB of cloud storage but unfortunately there has never been a method to sync it on Linux. Where to ask "subjective and argumentative" questions on programming? My little brother is just getting into programming, and for his Science Fair project, he's doing a simulation of a flock of birds in the sky. He's gotten most of his code written, and it works nicely, but the birds need to move every moment.  Tkinter, however, hogs the time for its own event loop, and so his code won't run. Doing root.mainloop() runs, runs, and keeps running, and the only thing it runs is the event handlers.  Is there a way to have his code run alongside the mainloop (without multithreading, it's confusing and this should be kept simple), and if so, what is it?  Right now, he came up with an ugly hack, tying his move() function to &lt;b1-motion&gt;, so that as long as he holds the button down and wiggles the mouse, it works. But there's got to be a better way. Why is a finite integral domain always field? This is how I'm approaching it: let $R$ be a finite integral domain and I'm trying to show every element in $R$ has an inverse:   let $R-\{0\}=\{x_1,x_2,\ldots,x_k\}$,  then as $R$ is closed under multiplication $\prod_{n=1}^k\ x_i=x_j$,  therefore by canceling $x_j$ we get $x_1x_2\cdots x_{j-1}x_{j+1}\cdots x_k=1 $,  by commuting any of these elements to the front we find an inverse for first term, e.g. for $x_m$ we have $x_m(x_1\cdots x_{m-1}x_{m+1}\cdots x_{j-1}x_{j+1}\cdots x_k)=1$, where $(x_m)^{-1}=x_1\cdots x_{m-1}x_{m+1}\cdots x_{j-1}x_{j+1}\cdots x_k$.   As far as I can see this is correct, so we have found inverses for all $x_i\in R$ apart from $x_j$ if I am right so far. How would we find $(x_{j})^{-1}$? Per the 's Wild Magic Surge table (PHB, p. 104)     07-08: You cast fireball as a 3rd-level spell centered on yourself.   There's other questionable area spells in that list (grease is a 10 foot square, so your square and which three?), but I'll focus on spheres like  (PHB p. 241):     (...) Each creature in a 20-foot-radius sphere centered on the point must (...)   My problem is, the sources I found so far - including the   to similar questions here - talk about measuring spheres from grid square intersections, whereas this clearly talks about it being centered on the unlucky Wild Magic sorcerer. Plus, since it's a wild magic effect, it doesn't exactly have a caster that can pick a point of origin. Is there an accepted way to measure an effect like this? Notepad ignoring linebreaks Most documents I'm opening in notepad.exe under windows 7 lately, there are no linebreaks... everything just runs together.  The same documents in any other program, even previewed directly in Explorer, will show the linebreaks correctly.  this is happening with many .info files, .css, .js.. but not all of them.   I am guessing it's some kind of character encoding unix line endings something or other, but wondering if there's anything I can do or if anyone else has experienced similar and if I can make notepad work correctly. I prefer it to notepad++/other text editors for certain uses. Possible Duplicate:          In  the following claim was mentioned:  $R/I \otimes_R M \cong M / IM$  So I tried to prove it. Can you help me finish my proof? Thanks!    We recall that $M \otimes_R -$ is a covariant right-exact functor that it is exact if $M$ is flat and we observe that the following is an exact sequence: $$ 0 \to IM \xrightarrow{i} M \xrightarrow{\pi} M / IM \to 0$$  $R/I$ is an $R$ module since $R/I$ is a subring of $R$ closed with respect to multiplication from $R$ but it is not necessarily flat hence we only get exactness on one side:  $$  (R/I) \otimes_R IM \xrightarrow{id \otimes i} (R/I) \otimes_R M \xrightarrow{id \otimes \pi} (R/I) \otimes_R M / IM \to 0$$  Then $$ \mathrm{Im(id \otimes \pi)} = (R/I) \otimes_R M / IM  \cong (R/I) \otimes_R M / \mathrm{Ker} (id \otimes i) $$  so we want to show two things:   (i) that $\mathrm{Ker} (id \otimes i) = \{0\}$. To this end let $r + I \otimes im \in (R/I) \otimes_R  IM $ and assume $ id \otimes i(r + I \otimes im ) = r + I \otimes im = 0 + I \otimes 0$. I'm not sure how to proceed from here.   (ii) and that $M /IM \cong (R/I) \otimes_R M / IM $  Can you help me? Thanks. For which values of $x$, will $f (x) . f '(x) < 0$? For what real values of $a$ does $\sum_{n=1}^{\infty}{(\frac{an}{n +1})^n}$ converge? For what real values of $a$ does the series $$\sum_{n=1}^{\infty}\left(\frac{an}{n +1}\right)^n$$ converge?  At first, I wanted to do the root test, but the problem is that $a$ could be negative.  If I take it out of the fraction to get $$\left(\frac{a}{n+1}\right)^n$$ it doesn't meet the criteria of either the Dirichlet or the Abel tests. I have heard rumors that you can compile documents online, and more specifically that Google has a free online compiler, but I have never been able to find any. Is there a way to compile documents online, so that I can write and compile documents even if I don't have a TeX distribution installed on my computer? How do I withdraw all money from my HSA account as a non-resident? I have lived in US for 5 years, and I (still) have an HSA account with BoA. Now I am living in Europe, and there's a fat chance I'll ever go back to live in US, so I would like to withdraw the money from my HSA, pay the due taxes, of course, and just be able to use them. How exactly I go about that?  Thanks in advance. Why do soap operas have the soap opera effect? The soap opera effect occurs when frame interpolation is used. For example, if a movie is shot at 24 frames per second and then shown on a TV screen which is capable of displaying 60 frames per second then it is possible to use a computer to do motion interpolation. In other words the computer can average (interpolate) two frames and create a synthetic third frame and stick it between the two real frames.  This interpolation makes the picture look unnatural and plastic, somewhat like soap operas look on TV, hence the name.  My understanding of why soap operas have the soap opera effect has something to do with the fact that many of them are shot using camcorders instead of film, but I am not completely sure.  Why do soap operas have the soap opera effect? What does $\sum_{k=0}^\infty \frac{k}{2^k}$ converge to? This problem comes from another equation on another question (. I tried to split it in half but I found out that $$\sum_{k=0}^\infty \frac{k}{2^k}$$ can't be divided. Knowing that $$\sum_{k=0}^\infty x^k=\frac{1}{1-x}$$ I wrote that $$\sum_{k=0}^\infty \frac{k}{2^k}=\sum_{k=0}^\infty \left(\frac{\sqrt[k] k}{2}\right)^k=\frac{1}{1-\frac{\sqrt k}{2}}=\frac{2}{2-\sqrt[k] k}$$ But that's not what I wanted. Could anyone help me? Determining the name of the VMware host of a VM guest - from the guest Apply the latest Service Pack and Cumulative Update Execute sudo without Password? In the Futurama episode "" they save the world by rotating the Earth backwards saying it shouldn't matter (which direction Earth rotates). If Earth rotated clockwise and remained in it's current counter-clockwise orbit around the Sun, would it affect anything beyond the direction the constellations move across the sky?