Can I use z-score for data that doesn't belong to a normal distribution but passes some normality tests?
z-score and Normal Distribution
"Coming soon" pages & SEO What is the scientific name of this evergreen plant? This plant is found in India. It is an evergreen plant. Would love to know the scientific name. I am trying to change the page size in the QGIS 3.0 Composer but I am not able to see the Composition tab.  I have right clicked an empty space in the toolbar but did not see anything about composition.  I am using Windows 7.  I tried looking at the QGIS docs but they are still in testing. Entity Framework and SQL Server View Show that the series $\sum(\exp(\frac{(-1)^n}{n})-1)$converges, but not absolutely. Show that the series converges, but not absolutely. $\sum_{n=1}^{\infty}( $exp$(\frac{(-1)^n}{n})-1)$.   My Try:  Let $a_n=$exp$(\frac{(-1)^n}{n})-1$. I was going to use alternating series test because the sequence $\{a_n\}$ is alternating. But $\{|a_n|\}$ is not decreasing to $0$. So, I am stuck now. Can anybody please give me a hint? How do you subtract Dates in Java? Why is it true that $\mathrm{adj}(A)A = \det(A) \cdot I$? Let $A, B$ be subsets of a metric space $X$. If $A$ is compact and $B$ is closed, show that the distance between $A$ and $B$ is achieved.   Attempt at a proof:    Let $A$ be compact and $B$ be closed. Let $m=d(A,B)=\inf_{b\in B} d(A,B)$. Then, there are two possibilities: (a) $\exists b\in B$, $d(a,b)=m$. If this is the case, we're done. (b) $\forall b\in B$, $d(a,b)&gt;m$. In this case,     there exists a sequence $\{b_n\}\subseteq B:$ $d(a,b_n)\rightarrow m$ as $n\rightarrow\infty$ by definition of infinum. Then there exists a subsequence $\{b_{n_k}\}$: $d(b_{n_1},a)&gt;d(b_{n_2},a)&gt;...$ which is monotonic decreasing. Then note that $d(b_{n_k},a)&lt;d(b_{n_1},a)&lt;\infty$. So it's a bounded sequence. Now I want to show that it has a convergent subsequence that converges to $b\in B$ and then I want to do the same for $A$. And then finally to show that $d(a,b)=m$ in fact. Any clues to how to get there? I have the following diagram:  \documentclass{article} \usepackage{amsmath,amsfonts,graphicx} \usepackage{algpseudocode} \usepackage{tikz, nth} \usetikzlibrary{arrows.meta,decorations,decorations.pathreplacing,calc,bending,positioning, chains}  \begin{document} \begin{tikzpicture}[scale=0.6]         \draw[thick,]  (0,8) -- (0,0) node[left] {0};         \draw[thick,]  (0,0) -- (8,0) node[right] {8};         \draw[thick,]  (8,8) -- (8,0) node[left] {};         \draw[thick,]  (8,8) -- (0,8) node[left] {8};          \draw[thick,]  (4,0) -- (4,8) node[left] {};          \fill (1, 4) circle[radius=2.5pt] node[below]{$A$};         \fill (2, 6) circle[radius=2.5pt] node[below]{$B$};         \fill (3, 2) circle[radius=2.5pt] node[below]{$C$};         \fill (4, 8) circle[radius=2.5pt] node[below]{$D$};         \fill (7, 3) circle[radius=2.5pt] node[below]{$E$};         \fill (6, 1) circle[radius=2.5pt] node[below]{$F$};         \fill (5, 7) circle[radius=2.5pt] node[below]{$G$};         \fill (3, 8) circle[radius=2.5pt] node[below]{$H$}; \end{tikzpicture} \end{document}   How can I position the caption of the node $D$ both below and left, so that the line doesn't obscure the caption? How do I tell Maven to use the latest version of a dependency? In Maven, dependencies are usually set up like this:  &lt;dependency&gt;   &lt;groupId&gt;wonderful-inc&lt;/groupId&gt;   &lt;artifactId&gt;dream-library&lt;/artifactId&gt;   &lt;version&gt;1.2.3&lt;/version&gt; &lt;/dependency&gt;   Now, if you are working with libraries that have frequent releases, constantly updating the &lt;version&gt; tag can be somewhat annoying. Is there any way to tell Maven to always use the latest available version (from the repository)? Mac equivalent of Ctrl + Space to select an item on a list I want to select non-consecutive items on a list, without using a mouse/trackpad - there should be no clicks involved.  In Windows and Linux (at least Ubuntu) an item can be selected using Space/ button, which, in combination with arrows and Ctrl key allows me to select multiple items in any environment (file manager, IDE etc.) - e.g.  Enter a directory -> hold Ctrl -> down arrow twice -> press Space -> down arrow twice -> press Space.  Now I should have items 1, 3 and 5 selected. Is there a way to do the same thing in OS X?  PS. Sorry for such a verbose description, but so far every answer I encountered advices using Command + Click, and this is something I don't want to do. How to show the number of domains the disk is split into is $1+ C_n^2 + C_n^4$? Assuming there are n points on a circle, then there are $C_n^2$ chords. If any three chords don't intersect in circle. How to show the circle will be divided into $1+ C_n^2 + C_n^4$ domains?  Picture below is a example of 5 points on circle. Is particle superposition reflected in the particle's gravitational footprint? I constantly have problems working with dates in Excel, I must be doing something wrong but I don't understand what.  I have a spreadsheet, exported from our exchange server, that contains a column with dates on. They have come out in US format even though I'm in the UK.   The column in question looks like this  04/08/2012 04/09/2009 04/01/2010 04/21/2011 04/05/2012 08/30/2009 08/29/2010 08/28/2011   In Excel, I have highlighted the column and selected Format Cells.... In this dialog box, I have selected the Date, selected English (United States) as the locale and chosen the matching date format from the list. I hit OK and try to sort the data by this column.   In the sort dialogue I choose this column, select sort on Values but the order only gives me options for A to Z, not oldest to newest as I would expect.  This in turn sorts the date data by the first two digits.  I am aware I could re-format this data to ISO and then the A to Z sort would work but I shouldn't have too, I'm obviously missing something. What is it?  EDIT: I messed up the bounty but this should have gone to @r0berts answer, his first suggestion of Text to Columns with no delimiter and choosing 'MDY' as the type of data works. Additionally, if you have a time (i.e. 04/21/2015 18:34:22), you need to first get rid of the time data. However after that the method suggested by @r0berts works fine. How do I extract text that lies between parentheses (round brackets)? I have a string User name (sales) and I want to extract the text between the brackets, how would I do this?   I suspect sub-string but I can't work out how to read until the closing bracket, the length of text will vary. Is it possible to see a list of all my edits using a query? Prove that any finite group $G$ of even order contains an element of order $2.$ wildcard * in CSS for classes On the one hand, I'm aware that  in the US do not have a valid government ID. On the other hand, traveling within the US requires you to show a piece of ID wherever you go - even when taking a Greyhound.   So let's say you're an American who has a large number of cash in their pocket but no ID whatsoever. Would you be able to get from New York to San Francisco or from Seattle to Miami? If so, what are your options? Even though I do have plenty of identification documents, I find it enjoyable to be able to travel anonymously. A stranger told me that he will give me an allowance of $ weekly. I know the saying "If it sounds too good to be true, then it is".   He told me that he would  email me his check and I would be able to deposit it via mobile banking. The only information he needs is my email, name on bank account, and bank name.   Is this too much information? Do you think this is a scam? I would definitely know if it was a scam if he asked for my log in but that is not what he wants.  Thank you for your time and answers!