Using Private Styles in Android
Android: Using default styles
Does changing your Compute Device, change all computes of Blender? So, I have recently moved from using Blender, on my family's Nettop PC, to my personal, gaming PC. And with this move, came to option to use CUDA instead of CPU.  Which leaves the question, if I move to CUDA, does that change all computing, for like physics baking, or only for rendering?  Just a nooby question that I wanted to know, and yes, I know you can specify GPU rendering separately. Another question I am struggling with:  Let $f:\mathbb{R} \rightarrow \mathbb{R}$ be defined in a neighborhood of $a$ (except maybe $a$ itself) and suppose that, $\lim_{x \rightarrow a}\left(f(x)+\dfrac{1}{\left|f(x)\right|}\right)=0$. Find $\lim_{x \rightarrow a}f(x)$, and prove by definition, that this is indeed the limit.    Thank you all for your answers!!  But.. How can I prove by definition that this is indeed the limit? take $\epsilon&gt;0$, I have to show that there exists a $\delta&gt;0$ such that, $|x-a| \leq \delta$ implies $|f(x)+1| \leq \epsilon$. now, I do know that there exists an $\delta_1&gt;0$, such that $|f(x)+\frac{1}{|f(x)|}|&lt; \epsilon$.Or, $\frac{\epsilon}{k}$ for some constant $k$ But, how can I continue from there? Kernel requires an x86-64 CPU, but only detected an i686 CPU. How can I install Lubuntu/Ubuntu? I'm trying to install Lubuntu on my laptop (sorta old 2005). [Laptop stats: Intel® Celeron® CPU 410 @ 1.46 GHz 1.47GHz, 448 MB of RAM]  I press Install and this message appears:   This kernel requires an x86-64 CPU, but only detected an i686 CPU.  Unable to boot - please use a kernel appropriate for your CPU.   What can I do to install Lubuntu on my computer? Schengen visa permit I am a student with a Singapore passport currently studying in the Czech Republic for a semester. My permit is valid until 2nd of February, I plan to fly to the UK to travel for 3 days before heading back to Singapore from there.  Would there be any problems, such as exit immigration from the Czech Republic to the UK? I searched online that the UK is not part of Schengen Area Agreement states, and my passport has a visa free entry to the UK. Prove that $\lim_{n\to\infty}a_n\le \lim_{n\to\infty}b_n$ Theorem  Let $\{a_n\}$ and $\{b_n\}$ be convergent real sequences. Assume that there exists a $N\in\mathbb{N}$ so  $a_n\le b_n$ (eq. 1)  for all $n\ge N$. Then  $\lim_{n\to\infty}a_n\le \lim_{n\to\infty}b_n$.  My attempt at proving  Let $a=\lim_{n\to\infty}a_n$ and $b=\lim_{n\to\infty}b_n$. $a$ and $b$ are real numbers because the limit of a sequence of real numbers is a real number (which is a corollary in my textbook). For proof by contradiction, assume  $b&lt;a$.  Let $\epsilon=\frac{a-b}{2}$. Then we can find $N_a,N_b\in\mathbb{N}$ so  $|a-a_n|\le\frac{\epsilon}{2}$ when $n\ge N_a$, (eq. 2)  $|b-b_n|\le\frac{\epsilon}{2}$ when $n\ge N_b$. (eq. 3)  In a textbook I found that I should do the following:  Choose a $n$ so $n\ge\max(N,N_a,N_b$), then eqs. (1-3) are satisfied. Then  $a-\epsilon\le a_n+\frac{\epsilon}{2}-\epsilon$  How do I get that last thing? Is it necessary to do a proof by contradiction or can one do a direct proof? Does assumption of normality of each mixture components implies that each margins is normal I just would like to understand some information about the joint normality and the margins. I read that the normal joint distribution almost always implies that the univariate margins are all normal.   My question is:  1- Is this apply for Gaussian mixture models? For example, in the Gaussian mixture model, each mixture component follows a Gaussian distribution. Hence, does it imply that each margin will be a Gaussian distribution as well? "I understand that mixture components are used to describe the dependency structures, and they are the joint distribution. is that correct?  2- I read this from one answer to a question in this site . "So yes, the assumption of joint normality is a sufficient condition for all marginal distributions to be normal, irrespective of the dependence structure. Hence, the theory of Copulas does not affect this result in any way."  However, I really do not understand this: irrespective of the dependence structure. As I understand if the joint distribution in normal then the dependence structure is normal.   Could someone help me with my questions, please? I have the following content in in /etc/udev/rules.d/81-external-disk.rules:  ENV{ID_FS_UUID}=="6826692e-79f4-4423-8467-cef4d5e840c5", RUN{program}+="/bin/mount -o nofail,x-systemd.device-timeout=1 -t ext4 -U 6826692e-79f4-4423-8467-cef4d5e840c5 /backup/external"   After running:  udevadm control --reload ; udevadm trigger /dev/sdb1   It does nothing at all. However if II change the mount command for something such as /bin/touch /tmp/xyz it works.  Versions:  [root@helsinki rules.d]# rpm -qa | grep udev libgudev1-219-19.el7_2.12.x86_64 python-pyudev-0.15-7.el7_2.1.noarch [root@helsinki rules.d]# rpm -qa | grep systemd systemd-libs-219-19.el7_2.12.x86_64 systemd-219-19.el7_2.12.x86_64 systemd-sysv-219-19.el7_2.12.x86_64 [root@helsinki rules.d]# cat /etc/redhat-release  CentOS Linux release 7.2.1511 (Core) Solving the recurrence $T(n) = \sqrt n T(\sqrt{n}) + \sqrt{n}$ A former student of mine was TA-ing an algorithms class last quarter and asked students to solve this famous recurrence relation:  $$T(n) = \sqrt n T(\sqrt{n}) + n$$  There are  and this question has already been asked here.  I was talking to my student about this problem and mentioned that it's quite hard to solve and is pretty dependent on the particular choices being made. As an example, I suggested this variant of a recurrence relation that was less simple to solve:  $$T(n) = \sqrt n T(\sqrt{n}) + \sqrt{n}$$  The TA and I tried solving this recurrence for about an hour and a half without making any progress. Here are a few things we tried:   My approach to solving the initial recurrence relation was to draw out a recursion tree and notice that each level of the tree contributes $n$ to the total and that there are $O(\log \log n)$ layers, so the recurrence solves to $O(n \log \log n)$. When I tried doing this here, I noticed that the work per layer was no longer constant; instead, the top layer sums to $\sqrt{n}$, the second layer to $n^{3/4}$, the third to $n^{7/8}$, etc. We got stuck working with the summation $n^{1/2} + n^{3/4} + n^{7/8} + ...$. We tried using the iteration method to unroll the recurrence. With the original recurrence relation, this works out nicely; here, we got stuck at the same summation given above.   I'm completely stuck trying to figure out how to solve this recurrence relation. There's nothing riding on it per se - I don't need to solve it for any particular reason - but the fact that we arrived at it by a straightforward modification of a common algorithms problem set question makes it all the more enticing.  Any idea how to solve this recurrence?  Thanks! I'm thinking that one way Jeff and the Stack Overflow team could squeeze some extra money out of this site would be to automatically convert all Amazon links posted here into affiliate links, e.g. Stick "tag=codinghorror-20" (or more likely a new site-specific tag) onto every Amazon link. This would bring in some additional revenue every time someone purchased a book via a link on this site.   They could do similar things with other links as well. Amazon's simply the most obvious choice.  So my question is, would anyone have a problem with this?  I know I wouldn't mind, but I don't know how other people would react.  What does everyone think? Is this a horrible idea, a great idea, a waste of time? How do I get permissions to edit system configuration files? Story about criminal being "adjusted" which stops a man's commute I'm trying to remember the name of a story, I think the author was Larry Niven, but it might possibly be from Heinlein's "Future History" series (but a check of the stories included in the Future History indicates it's not in there), about a man whose commute is stopped because a criminal has to be 'adjusted'.  In this case, the criminal was a hit-and-run driver who left his victim untreated on the roadside, and was sentenced to suffer in the same manner. So his leg was carefully broken and he was left, untreated and in pain, on the side of the road in the same place for an hour. All the time ambulances were standing by, and every effort was made to ensure that the criminal did not suffer unduly - but that he did suffer, in a manner as close to the suffering he inflicted on his victim. Why do people have darker skin in sunnier climates? I already have cast iron skillet but I can't find a decent "normal" pan, for eggs and stuff, sometimes steaks, more or less general purpose.   Here are some more features: high quality, durable, non stick, oven safe, dish washer safe, extremely flat surface - not to be higher in the middle, this is very important.  Of course pricier usually means better quality, but is it worth it based on the criteria I'm after? Is it likely to be worth going from pans below $60, to pans from $60 to $130, or to pans over $130? I am trying to make a top down shooter that could potentially have hundreds of objects at once at one point. I need to check collision with projectiles, walls, and enemies. I am currently using ArrayLists which probably won't suffice later on and was wondering if someone had a good method or knows a good method for checking all of those objects at once. This is going to be a game for smartphones and is built in java. Any ideas would be great or if you could point me in some direction that would be fantastic.  Thanks in advance! What is a reasonable depth and diameter for postholes dug in clay soil to support an 8' fence? What is a reasonable depth and diameter for postholes dug in clay soil where the frost line is no more than 12” and that will support an 8 foot tall solid wood fence that uses PostMaster metal posts?  I hope to have someone else install an 8 foot high PT wood fence.  There will be no light or air passing through or under the fence and it will be heavier than average, given the additional height and board weight.  One side will run for 135’.  The attached diagram provides more detail.  The PostMaster Installation Instructions describe a 30” deep, sloped, 10” diameter hole, filled with 6” of gravel plus 24” of concrete for a 6 foot high fence.  They caveat that the “exact diameter and depth will be determined by local weather and soil conditions.”  Got it.  Huntsville, AL; very clay soil.  Maximum wind gusts of 65 mph.  (This is not in the normal tornado path and is not intended to withstand a tornado.)  In reviewing the StackExchange posts on fencing and post holes I came across the concept that the diameter of the pier may be increased to compensate for a shallower post hole.  I would like to know the recommended depth and diameter without relying on the 2 buttress posts, which are my small overbuild idea.  We will be able to walk under them.  26 APR 18 update: I just found a Master Halco youtube video specifying 6-8" diameter holes dug 36" deep for an 8' board-on-board fence, such as I would like to have.   - I also spoke to a fence builder experienced using PostMaster posts who opined that the 10" diameter and 30 deep holes were more than adequate, but that the gravel was of no value in our climate.  So, 30" x 10" dia inches of concrete vs. 36" x 8" dia of concrete. How do I ignore ampersands in a SQL script running from SQL Plus? I have a SQL script that creates a package with a comment containing an ampersand (&amp;). When I run the script from SQL Plus, I am prompted to enter a substitute value for the string starting with &amp;. How do I disable this feature so that SQL Plus ignores the ampersand? The beamer command \alt&lt;*overlay specification*&gt;{foo}{bar} will insert foo if the current slide is within the given overlay specification, and bar otherwise.  It's equivalent to   \only&lt;*overlay specification*&gt;{foo}\only&lt;*complementary overlay specification*&gt;{bar}   Here is a sample document using it:  \documentclass{beamer} \begin{document} \begin{frame} \begin{align*} y &amp;= \frac{(x^2+1)\sqrt{x+3}}{x-1} \\ \ln y &amp;= \ln (x^2+1) + \frac{1}{2} \ln(x+3) - \ln(x-1) \\ \frac{1}{y} \frac{dy}{dx}       &amp;= \frac{2x}{x^2+1} + \frac{1}{2(x+3)} - \frac{1}{x-1} \end{align*} So \[ \begin{split} \frac{dy}{dx} &amp;= \left(\frac{2x}{x^2+1} + \frac{1}{2(x+3)} - \frac{1}{x-1} \right) \alt&lt;2&gt;{\frac{(x^2+1)\sqrt{x+3}}{x-1}}{y} \end{split} \] \end{frame} \end{document}   This is very useful and saves typing.  But if one of the alternatives is larger than the other, it leads to jiggling slides.    What I would like is a overlay-specification-aware command \altvisible that would take the same amount of space on each slide.  So it would have to insert a box as big as the bigger of the two, and then set the correct material.  So the above document with \altvisible instead of \alt would not jiggle.  Any takers? Mathematical notation around the world "All our X" vs. "all of our X" Is the word "of" optional in this instance? Is either of these considered preferable to the other?        Taste all our delicious treats.   Taste all of our delicious treats. Create WiFi hotspot with web access point I want to setup a WiFi network with access through a web interface. Essentially people would be asked to enter a username/password and their session would be valid for X minutes after which they'd be logged out.  I am capable of quite a few programming/scripting languages, but browsing through router settings I don't see how to/where hosted/etc. the web interface/session handling comes in.  Please push me the right direction.