how to display date in fir mat like JANUARY 14,2021
Visualforce Date formatting
Alt-Tab shows two application switchers on Unity I started to have problems with my Ubuntu application switcher (Alt +  Tab) this morning. When I press Alt +  Tab, not only one, but two application switchers show up. Last night I customized some stuff using the Unity Tweak Tool. I thought I didn't touch the application switcher. So now it looks like this: A smooth vector field on $S^2$ vanishing at a single point I need to find a vector field as described in the title.  I was given a couple hints, and this is what I have so far. Let $\varphi:S^2\setminus\{N\}\to\mathbb{R}^2$ be stereographic projection ($N$ is the north pole). Let $Y$ be a smooth, non-zero vector field on $\mathbb{R}^2$ that dies off to $0$ "at infinity." Since $\varphi$ is a diffeomorphism, we can push $Y$ forward along $\varphi^{-1}$ to get a smooth vector field $(\varphi^{-1})_*Y_{\varphi(p)}$ on $S^2$. But this vector field is not zero at the north pole... it's undefined. So can I just define my vector field on $S^2$, call it Z, to be the pushforward of $Y$ (as above) away from $N$ but $0$ at $N$? And if so, do we still have smoothness? How to pronounce "Moderators's"? If I want to use the plural of &quot;moderator&quot; and also add the apostrophe plus S, how do I pronounce it? How do native speakers pronounce it?  Moderators = moderatorz Moderators's = moderatorziz or just moderatorz?  A sentence is:  &quot;I always thought that moderators's decisions seemed fairly arbitrary.&quot;   I guess moderatorziz is correct but it sounds weird to me. Do native speakers pronounce it as moderatorziz? How do I extract text that lies between parentheses (round brackets)? I have a string User name (sales) and I want to extract the text between the brackets, how would I do this?   I suspect sub-string but I can't work out how to read until the closing bracket, the length of text will vary. Prove that inequality $\sum _{cyc}\frac{a^2+b^2}{a+b}\le \frac{3\left(a^2+b^2+c^2\right)}{a+b+c}$ Let $a&gt;0$,$b&gt;0$ and $c&gt;0$. Prove that:    $$\dfrac{a^2+b^2}{a+b}+\dfrac{b^2+c^2}{b+c}+\dfrac{c^2+a^2}{c+a}\le \dfrac{3\left(a^2+b^2+c^2\right)}{a+b+c}.$$     $$\Leftrightarrow \frac{(a^2+b^2)(a+b+c)}{a+b}+\frac{(b^2+c^2)(a+b+c)}{b+c}+\frac{(c^2+a^2)(a+b+c)}{c+a}\leq 3(a^2+b^2+c^2)$$  $\Leftrightarrow 2(a^2+b^2+c^2)+\frac{c(a^2+b^2)}{a+b}+\frac{a(b^2+c^2)}{b+c}+\frac{b(a^2+c^2)}{a+c}\leq 3(a^2+b^2+c^2)$  $\Leftrightarrow \frac{c(a^2+b^2)}{a+b}+\frac{a(b^2+c^2)}{b+c}+\frac{b(a^2+c^2)}{a+c}\leq a^2+b^2+c^2$  $\Leftrightarrow \frac{c(a+b)^2-2abc}{a+b}+\frac{a(b+c)^2-2abc}{b+c}+\frac{b(a+c)^2-2abc}{a+c}\leq a^2+b^2+c^2$  $\Leftrightarrow 2(ab+bc+ac)\leq a^2+b^2+c^2+2abc\left(\frac{1}{a+b}+\frac{1}{b+c}+\frac{1}{a+c}\right)$  I can't continue. Help me It seems that most people who use the ignored tags feature end up with a fairly long list of those tags.  Although , it is sometimes necessary to add new ignored tags manually (typically when adding some-tag*).  It would be a lot easier if the add box was above the long list of ignored tags rather than below. I suppose the same would apply to the favorites tags for consistency's sake. Can I say: I have not gone to the cinema for a long time Are Variable Operators Possible? Prove that the number $19\cdot8^n+17$ is not prime, $n\in\mathbb{Z}^+$ On a Google search, I've notice that often the "trick" involves factoring the expression (and thus showing that the expression isn't prime), but I can't see it. Is this how you would go about it in this case, or would that be a dead end? Any hints? What are the most important things I need to do to encourage Google Sitelinks? My website used to have sitelinks and now it doesn't. It's very possible that it's due to changing the website to a sidebar design instead of having an "interstitial" type landing page which limited the number of choices, but I'm not sure.  Here is how sitelinks might look for a site:    What are some things that I can do to improve my chances of getting sitelinks? I am using Microsoft Visual C++ on Windows and Qt Creator on Ubuntu. I can't change permissions on my flash drive (FAT32), even as root.  How can I change permissions on a FAT32 flash-drive? Do I need to activate the firewall? I only use Ubuntu for a home desktop use? Tips to extend battery life for laptops and notebooks This question is present as a matter of historical interest.  While you are encouraged to help maintain its answers, please understand that "big list" questions are not generally allowed on Ask Ubuntu and will be closed per the .   It is possible to greatly extend the usage time of a laptop or netbook running on battery by disabling various services and installing various packages.   What tricks or tips do people have for getting an extra hour or two out of their batteries? What is currently the best way to get a favicon to display in all browsers that currently support it?  Please include:   Which image formats are supported by which browsers. Which lines are needed in what places for the various browsers. I am attempting to add a calendar to my Default.aspx in my sharepoint hosted add-in in visual studio. I used the default code-snippet for adding sharepoint lists. Here's what I added to my Default.aspx:    &lt;WebPartPages:WebPartZone runat="server" FrameType="Default" ID="full" Title="loc:full"&gt;     &lt;WebPartPages:XsltListViewWebPart runat="server"         ListUrl="Lists/Calendar"         IsIncluded="True"         JsLink="clientTemplate.js"         NoDefaultStyle="TRUE"         PageType="PAGE_NORMALVIEW"         Default="False"         ViewContentTypeId="0x"&gt;     &lt;/WebPartPages:XsltListViewWebPart&gt; &lt;/WebPartPages:WebPartZone&gt;     and this is the result...    Pretty dang ugly if you ask me. How can I get this looking like a normal share point calendar instead of an unusable mess?  Thank you! How do I activate Dauntless Cathar's ability? has the following ability:     {1}{W}, Exile Dauntless Cathar from your graveyard: Put a 1/1 white Spirit creature token with flying onto the battlefield. Activate this ability only any time you could cast a sorcery.   Please clarify. If the card is IN my hand, how can I exile if FROM the graveyard if it is not there? Did the writers mean SEND it to graveyard, or actually exile it? Confused, the writing does not make sense. I am having trouble understanding the estimation of an AR process. In some textbooks, the AR(1) process is defined as follows: $y_{t}=\theta y_{t-1}+ϵ_t$ (which does not contain a constant). So the OLS estimator is biased. I am confused about the cause of the bias. It is explained that $y_{t-1}$ is dependent on $ϵ_{t-1}$ although it is independent of $ϵ_t$. However in linear regression, if the equation does not contain a constant, we cannot make sure the expectation of disturbance is zero. So the OLS estimator is bias without a constant. Does it mean that the OLS estimator is unbiased if I add a constant in AR process? Plotting solutions to NDSolve If the imaginary part of an entire function is never zero, the function is constant Let $f : \mathbb{C} \to \{z\in\mathbb{C}:\Im(z)\neq0\} $ entire . Show that $f$ is constant.  I took $g(z)=\frac{1}{f(z)}$ and I think that g is bounded, therefore it is constant (due to Louville's theorem) but how do I prove it? Is $|g(z)|=\frac{1}{|f(z)|}=\frac{1}{u^2+v^2}\le M$ valid? How can I prove the IFF condition for this group of matrices? I'm tasked with showing that matrix $A$ commutes with every $2\times2$ matrix if and only if $A = \begin{bmatrix}a &amp; 0\\0 &amp; a\end{bmatrix}$ for some a.  I was able to prove in the first direction, assuming that $A = \begin{bmatrix}a &amp; 0\\0 &amp; a\end{bmatrix}$, by just multiplying the matrix by $\begin{bmatrix}a &amp; b\\c &amp; d\end{bmatrix}$ in AB = BA format, and showing how AB does equal BA.  $$ (=&gt;)$$  $$\begin{bmatrix}a &amp; 0\\0 &amp; a\end{bmatrix}\begin{bmatrix}a &amp; b\\c &amp; d\end{bmatrix} = \begin{bmatrix}a &amp; b\\c &amp; d\end{bmatrix}\begin{bmatrix}a &amp; 0\\0 &amp; a\end{bmatrix}$$  $$\begin{bmatrix}a^2 &amp; ab\\ac &amp; ad\end{bmatrix} = \begin{bmatrix}a^2 &amp; ab\\ac &amp; ad\end{bmatrix}$$  But now I have to prove in the other direction, assuming that A already does commute with every $2\times 2$ matrix, and I'm not particularly sure how I can do that. Somehow, I have to show that if A commutes with $\begin{bmatrix}a &amp; b\\c &amp; d\end{bmatrix}$, then A will be $\begin{bmatrix}a &amp; 0\\0 &amp; a\end{bmatrix}$, and I don't know how I can carry that out.   Where can I start? Ideas are appreciated.