Indesign question regarding "placed" objects
Why are imported PDFs blurry in InDesign?
Error -504 on appliation installation Yes. I've read all other questions regarding this problem. Like this one:  It's the same problem as this one but with more background information and an other app:   The details: My device is an Ulefone Be Touch 2 running Android 5.0.  My connection is perfect. To be sure I tried different networks, among them are 3G, 4G and wifi on ADSL, VDSL, cable and fiber. I've also used Tor and 3 different VPN providers in 3 countries on 2 continents. Let's say I ruled the network out.   A single app does not install: OpenKeychain.  Currently I have 126 apps installed. It does not install via desktop browser > play store > install button.    I have enough free space (40GB). The app is 7MB.   Re-adding Google account and clearing caches did not work.    Even a complete device wipe and re-install didn't work.     Downloaded the apk and tried manual installation, same error.   I also own a Nexus 7 (2013 wifi) and the app installs fine on that device. How to troubleshoot unwanted white spaces smartly? Why is there a white space on the left side?  \documentclass{standalone} \usepackage{asymptote} \begin{document} \noindent \begin{asy} size(10cm,10cm); draw((0,0)--(100,100)); draw((0,100)--(100,0)); dot((50,50)); \end{asy} \end{document} Bluetooth is on but can't find or be found by any other devices.  Output of sudo service bluetooth status:  ● bluetooth.service - Bluetooth service    Loaded: loaded (/lib/systemd/system/bluetooth.service; enabled; vendor preset: enabled)    Active: active (running) since ხუთ 2015-06-04 22:33:18 GET; 13min ago  Main PID: 26678 (bluetoothd)    CGroup: /system.slice/bluetooth.service            └─26678 /usr/sbin/bluetoothd -n  ივნ 04 22:39:14 Rangoo bluetoothd[26678]: Endpoint registered: sender=:1.63 path=/MediaEndpoint/BlueZ4/HFPAG ივნ 04 22:39:14 Rangoo bluetoothd[26678]: Endpoint registered: sender=:1.63 path=/MediaEndpoint/BlueZ4/HFPHS ივნ 04 22:39:14 Rangoo bluetoothd[26678]: Endpoint registered: sender=:1.63 path=/MediaEndpoint/BlueZ4/A2DPSource ივნ 04 22:39:14 Rangoo bluetoothd[26678]: Endpoint registered: sender=:1.63 path=/MediaEndpoint/BlueZ4/A2DPSink ივნ 04 22:39:14 Rangoo bluetoothd[26678]: bluetoothd[26678]: Endpoint registered: sender=:1.63 path=/MediaEndpoint/BlueZ4/HFPAG ივნ 04 22:39:14 Rangoo bluetoothd[26678]: bluetoothd[26678]: Endpoint registered: sender=:1.63 path=/MediaEndpoint/BlueZ4/HFPHS ივნ 04 22:39:14 Rangoo bluetoothd[26678]: bluetoothd[26678]: Endpoint registered: sender=:1.63 path=/MediaEndpoint/BlueZ4/A2DPSource ივნ 04 22:39:14 Rangoo bluetoothd[26678]: bluetoothd[26678]: Endpoint registered: sender=:1.63 path=/MediaEndpoint/BlueZ4/A2DPSink ივნ 04 22:39:14 Rangoo bluetoothd[26678]: Adapter /org/bluez/26678/hci0 has been enabled ივნ 04 22:39:14 Rangoo bluetoothd[26678]: bluetoothd[26678]: Adapter /org/bluez/26678/hci0 has been enabled   Output of lsusb:  Bus 003 Device 005: ID 0a5c:21d7 Broadcom Corp. BCM43142 Bluetooth 4.0   How can I fix it? Installing PHP 5.6 on Xenial (16.04) I need to use php5 (5.6) because I'm working on a Drupal 7 project which doesn't support php7. The problem is I recently updated to ubuntu 16.04 Xenial which seems to .   I tried to install it from , however when It try to install it with apt I always get similar errors.  $ sudo apt-get install php5-cli Cependant les paquets suivants le remplacent :   php7.0-cli:i386 php7.0-cli`   Which means it's obsolete. How can I install PHP 5.6 on Xenial? Hitting arrow keys adds characters in vi editor When I tried to use arrow keys in insert mode in vi editor the following characters are being inserted in the editor:   for ↓ I get B, for ↑ I get A, for ← I get D, for → I get C.   Please help me in resolve this problem. Per the kernel documentation:  This control is used to define how aggressive the kernel will swap memory pages.  Higher values will increase aggressiveness, lower values decrease the amount of swap.   However this is kind of vague. I'm trying to figure out exactly what the parameter ultimately controls. I know it adjusts how aggressively the kernel tries to swap out pages, but what decision making process in the kernel code does it affect?  Does it adjust how long ago a page must have been accessed before the kernel swaps it out? If so what does the default value of 60 represent? And how much is changed by a increment/decrement of 1 (a formula would be nice)? Or does it swap out pages based on their access frequency? Or something else? I can ask any of:     Do you know a breakfast place nearby?   Do you know a nearby breakfast place?   Do you know a good breakfast place?   but I really can't ask:     Do you know a breakfast place good?   Is there a general rule for determining whether an adjective must come before the noun or may come, Spanish-style, after it? Remove Background in Inkscape Why are C character literals ints instead of chars? In C++, sizeof('a') == sizeof(char) == 1. This makes intuitive sense, since 'a' is a character literal, and sizeof(char) == 1 as defined by the standard.  In C however, sizeof('a') == sizeof(int). That is, it appears that C character literals are actually integers. Does anyone know why? I can find plenty of mentions of this C quirk but no explanation for why it exists. How to terminate a script? I am aware of the die() command in PHP which exits a script early.  How can I do this in Python? My primary router has trouble extending wifi coverage to some bedrooms in the house so I am planning to add a second router to extend the wifi network using the wired Ethernet ports in one of the areas of poor coverage. Basic layout -   The ISP's router is in my family room downstairs (fiber connection) and the internet connects to the fiber via a box in an upstairs closet.   I purchased and installed an unmanaged Ethernet switch/splitter. In the upstairs closet where all of the Ethernet wires meet, the family room Ethernet cable was plugged into the ISP's box. I disconnected this wire and replaced it with a CAT5 cable running from the ISP's box in the closet to the Ethernet switch's port 1.  I think connected the family room Ethernet cable to port 2 and did the same in order for all the remaining Ethernet cables to various bedrooms.   So far, the switch is working fine.  I have wifi working with internet coming off of the router in the living room so I believe the switch is installed correctly otherwise that wifi should not have internet coming off of the living room jack.   Here is where things go awry - I took my second wifi router and connected the WAN/Yellow port to the Ethernet wall jack in another bedroom.  I then connected a lap top to one of the Ethernet ports on this router and found "no internet" after connecting.  On a whim, I changed the connection so that the router was connected to the Ethernet wall jack in one of the white ports but with the same results.   I don't think this counts as cascading and I don't really need a new network since I do not share the connection with any non-family members.  The router has been reset to factory settings to clear out any old instructions - but I still can't get it to connect to the internet or access the router to change the settings even - it's a netgear and the routerlogin.net will not let me access the router even when I am on the working WIFI for internet and have a cable running from the laptop to the netgear router.   I could use some help - just trying to extend the wifi range and it seems like it should be much less complicated. Tried following instructions in several other posts and they did not work for me - because I cannot access the router to change any settings. How to replace the_post_thumbnail template tag and show the first inside the post image instead How to iterate over arguments in a Bash script I have a complex command that I'd like to make a shell/bash script of.  I can write it in terms of $1 easily:  foo $1 args -o $1.ext   I want to be able to pass multiple input names to the script. What's the right way to do it?    And, of course, I want to handle filenames with spaces in them. I'm trying to understand the /etc/rsyslog.conf file, but I'm missing something. For example, this is a part of the file:  auth,authpriv.*         /var/log/auth.log *.*;auth,authpriv.none      -/var/log/syslog cron.*              /var/log/cron.log daemon.*            -/var/log/daemon.log kern.*              -/var/log/kern.log lpr.*               -/var/log/lpr.log mail.*              -/var/log/mail.log user.*              -/var/log/user.log   According to  page:     The facility is one of the following keywords: auth, authpriv, cron,   daemon, kern, lpr, mail, mark, news, security (same as auth), syslog,   user, uucp and local0 through local7.      The priority is one of the following keywords, in ascending order:   debug,info, notice, warning, warn (same as warning), err, error (same   as err) crit, alert, emerg, panic (same as emerg). The keywords error,   warn and panic are deprecated and should not be used anymore. The   priority defines the severity of the message.      An asterisk ("*") stands for all facilities or all priorities,   depending on where it is used (before or after the period). The   keyword none stands for no priority of the given facility.      You can specify multiple facilities with the same priority pattern in   one statement using the comma (",") operator. You may specify as much   facilities as you want. Remember that only the facility part from such   a statement is taken, a priority part would be skipped.      Multiple selectors may be specified for a single action using the   semicolon (";") separator. Remember that each selector in the   selector field is capable to overwrite the preceding ones. Using this   behavior you can exclude some priorities from the pattern.   So, this is pretty understandable but what about the file path on the right. It can be just a path, or path with | or - before it (or maybe even something else). What is the difference between the three? Show $\lim \limits_{n \to \infty} \frac{a_{n+1}}{a_n} = \|f\|_{\infty}$ for $f \in L^{\infty}$ I have a question that I need help with getting started (possibly I would be back for more help).     I have a measure space $(X,A,\mu)$ that is finite, and $f \in L^{\infty}(\mu)$. Also, defined is $a_n = \int_X\,|f|^n\,d\mu$. I need to show that the limit is: $$\lim_{n\to\infty}\,\frac{a_{n+1}}{a_n} = \|f\|_{\infty} .$$   I am stuck on getting started, anybody have any suggestions?  thanks much bash command for each file in a folder I have a set of files on which I would like to apply the same command and the output should contain the same name as the processed file but with a different extension.  Currently I am doing rename /my/data/Andrew.doc to /my/data/Andrew.txt I would like to do this for all the .doc files from the /my/data/ folder and to preserve the name.  I tried several versions but I guess I have something wrong in the syntax as I an new to linux. Can I mix MySQL APIs in PHP? How to use maths symbols in text mode? I try to add a center dot with \circ but it fails to compile. How to use maths symbol in text mode? The error message is   ovak, slovenian, spanish, swedish, turkish, turkmen, ukrainian, uppersorbian,  welsh, loaded. (/usr/local/texlive/2012/texmf-dist/tex/latex/base/article.cls Document Class: article 2007/10/19 v1.4h Standard LaTeX document class (/usr/local/texlive/2012/texmf-dist/tex/latex/base/size10.clo)) (./untitled-1.aux) ! Missing $ inserted. &lt;inserted text&gt;              $ I'm new to inequalities in mathematical induction and don't know how to proceed further. So far I was able to do this:  $V(1): 1≤1 \text{  true}$  $V(n): n!≤((n+1)/2)^n$  $V(n+1): (n+1)!≤((n+2)/2)^{(n+1)}$  and I've got : $(((n+1)/2)^n)\cdot(n+1)≤((n+2)/2)^{(n+1)}$ $((n+1)^n)n(n+1)≤((n+2)^n)((n/2)+1)$ Unfortunately application has stopped android emulator genymotion