Is there a class for typesetting novels?
LaTeX template for typesetting a novel
pgfplots external with large dataset (lualatex?) I have fairly large datasets with densely strucutred data that i cant downsampe much without loosing structure. I use TexMaker on Ubuntu 14.04LTS. I use   \usepackage{tikz,pgfplots,pgfplotstable} \pgfplotsset{compat=1.9} \usepgfplotslibrary{external} \tikzexternalize   and   \tikzsetnextfilename{figs/test1}   to externalize the figures. This works good compiling with pdflatex -shell-escape. But as the data becomes to large I am out of memory. I am trying to compile using LuaLaTeX -shell-escape instead of pdfLatex but get the following error message:   ! Package tikz Error: Sorry, the system call 'pdflatex -halt-on-error -interact ion=batchmode -jobname "figs/test1" "\def\tikzexternalrealjob{article}\input{ar ticle}"' did NOT result in a usable output file 'figs/test1' (expected one of . pdf:.jpg:.jpeg:.png:). Please verify that you have enabled system calls. For pd flatex, this is 'pdflatex -shell-escape'. Sometimes it is also named 'write 18' or something like that. Or maybe the command simply failed?   so pgfPlots seem to call pdfLatex without the appropriate -shell-escape flag and without me specifying it. How can i get this to compile in LuaLatex? or can i compile only the figures in LuaLatex and the rest in pdfLatex (the opposite of what is happening now)? I found  and  example but neither helped me...  Thankfull for help and i am also thankful for any general advice that can help me resolve the problem of ploting larger data sets in pgfplots.   Cheers /J What is the electric charge of the Sun and its corona? Alt-Tab shows two application switchers on Unity I started to have problems with my Ubuntu application switcher (Alt +  Tab) this morning. When I press Alt +  Tab, not only one, but two application switchers show up. Last night I customized some stuff using the Unity Tweak Tool. I thought I didn't touch the application switcher. So now it looks like this: How do I share an ethernet connection via wifi on Windows 8? I have a Windows 8 laptop that is connected to a router via Ethernet. I want to make the laptop act like a wireless router via wifi so that other devices could connect to the computer using wifi and gain access to its Ethernet internet connection.  How do I do something like this? I would like to travel in the USA for a period of 3 - 6 months. But I want to spend some time working for my employer (remote work) and getting paid by the employer. Is this possible under a tourist visa (B1/B2)?  I hope this is OK since I will not be getting paid by a US employer. I am in the IT trade so all that I will be needing is my own laptop and a connection to the internet. The money I earn would actually help me pay for the expenses I get during the holiday. A mysterious app named &quot;10102&quot; shows up in my data usage. It bears only the standard Android app icon (the Bugdroid logo with a cube on its torso). From what the graph tells me, it has used 36 megabytes of data in the background and zero on the foreground. I think I haven't uninstalled anything for months. Is it malware? I haven't sideloaded anything and only authorized my laptop as a USB debugger. If it's malware, how do I remove it? I have no idea how to find its package name and 10102 isn't in the list of downloaded apps in settings. I'm running stock &amp; never-been-rooted Android 4.4.4 on Nexus 4. I've taken some stock photography of lots of clear bottles, and now want to remove the background (which is white-ish, because at a pinch I could leave it...) so that the bottle becomes transparent with highlighting.  My bottles are clear with different colored liquids with multiple refraction and reflection surfaces.  I am looking for a background color subtraction effect that will allow me to get to transparent (hopefully with some sort of effect/opacity slider).  Ideas that I can't pull off yet:   Combine layer with a color fill layer (keyed off the "transparent color") in some manner to produce some output that could be used as the starting point of a layer mask Same layer combination as above, but somehow translating "pure white" to transparency.   Notes for what doesn't work (Photoshop terminology):   "Color Range" and delete (fuzzy select, but not graded/alpha) - results in harsh lines and only leaves the pure white and dark highlights and shadow refractions/reflections Magic wand selections for the same reason "Background Eraser" because although it is able to only subtract a certain color and leave "the rest", it (like all tolerance based tools) eventually hits a colour slightly outside of the range that it just won't touch.   I'll add more if I can remember what I've found Prove if $|a_{n+1}|/|a_n| \leq |b_{n+1}|/|{b_n}|$ and $\sum |b_n|$ is convergent, then $\sum |a_n|$ is convergent How discontinuous can a derivative be? There is a well-known result in elementary analysis due to Darboux which says if $f$ is a differentiable function then $f'$ satisfies the intermediate value property.  To my knowledge, not many "highly" discontinuous Darboux functions are known--the only one I am aware of being the Conway base 13 function--and few (none?) of these are derivatives of differentiable functions.  In fact they generally cannot be since an application of Baire's theorem gives that the set of continuity points of the derivative is dense $G_\delta$.  Is it known how sharp that last result is?  Are there known Darboux functions which are derivatives and are discontinuous on "large" sets in some appropriate sense? Finding $\tan t$ if $t=\sum\tan^{-1}(1/2t^2)$ I am solving this problem. If $$\sum\limits_{i=1}^{\infty} \tan^{-1}\biggl(\frac{1}{2i^{2}}\biggr)= t$$ then find the value of $\tan{t}$.   My solution is like the following: I can rewrite: \begin{align*} \tan^{-1}\biggl(\frac{1}{2i^{2}}\biggr) &amp; = \tan^{-1}\biggl[\frac{(2i+1) - (2i-1)}{1+(2i+1)\cdot (2i-1)}\biggr] \\\ &amp;= \tan^{-1}(2i+1) - \tan^{-1}(2i-1) \end{align*}  and when I take the summation the only term which remains is $-\tan^{-1}(1)$, from which I get the value of $\tan{t}$ as $-1$. But the answer appears to be $1$. Can anyone help me on this. Show that $3p^2=q^2$ implies $3|p$ and $3|q$ This is a problem from "" (specifically, exercise set 2 #9), which is one of my math texts. Please note that this isn't homework, but I would still appreciate hints rather than a complete answer.  The problem reads as follows:     If 3p2 = q2, where $p,q \in \mathbb{Z}$, show that 3 is a common divisor of p and q.   I am able to show that 3 divides q, simply by rearranging for p2 and showing that  $$p^2 \in \mathbb{Z} \Rightarrow q^2/3 \in \mathbb{Z} \Rightarrow 3|q$$  However, I'm not sure how to show that 3 divides p.    Edit:  Moron left a comment below in which I was prompted to apply the solution to this question as a proof of $\sqrt{3}$'s irrationality. Here's what I came up with...  [incorrect solution...]  ...is this correct?  Edit:  The correct solution is provided in the comments below by Bill Dubuque. Do I need to activate the firewall? I only use Ubuntu for a home desktop use? Probability distribution in the coupon collector's problem Why does friction play the role of centripetal force during the turning of a car? How do I handle partially correct edits in the Suggested Edits review queue? Contradicting Instructions While going through the suggested edits review queue, one sometimes stumbles upon partially useful edits like . Trying to follow the instructions listed in the descriptions doesn't lead to a conclusive answer. Considering our example:   Approve edits that clearly improve the post ↳ No, not *clearly* Improve Edit when you can make additional improvements to the post ↳ I most definitively can Reject and Edit to replace an ineffective edit with your own substantive changes ↳ It is ineffective in the sense that it made the post worse overall (imho) Reject edits that fail to improve the post or that make it worse ↳ Like the last option: yes Skip if you are not sure and want to go to the next suggested edit ↳ Well, yes. But that is really why I am here, asking this question   Reasoning about the remaining Choices This leaves us with three choices: Improve Edit, Reject and Edit and Reject (the last one slightly modified):  Improve Edit  + Acknowledges that some things in the edit where correct - Learning effect for author might vanish, as the improvement might get overlooked - Can't leave a custom message for edit author (except in comments, which pollutes the thread) - Doesn't trigger the system which &quot;punishes&quot; users who repeatedly have their edits rejected - Rewards the edit author with reputation for a poor edit   Reject and Edit  + Clearly shows the author that there were problems with the edit - Still can't leave a custom message explaining the problems of the original post. - One has to partially redo parts of the edit that have just been rejected, which might feel unjust to the original editor   Reject with a custom note and come back immediately to make a good Edit  + Clearly shows the author that there were problems with the edit + Possibility to leave an explanation as to what was wrong with the edit - One still has to redo parts of the edit that has just been rejected - Seems to be a weird workaround for Reject and Edit   Something else?   Each of the three options come with their distinct advantages/disadvantages making it non trivial to decide which one to pick.  Or does the answer simply depend on the quality of the edit? Like:  Improve Edit for subjectively slightly positive edits Reject and Edit (Or Reject and Edit) for subjectively slightly negative edits I heard about nautilus-gksu and would like to install it. Unfortunately, when I try, I get this:  glemi@XPS:~$ sudo apt-get install nautilus-gksu Reading package lists... Done Building dependency tree        Reading state information... Done E: Unable to locate package nautilus-gksu   How and where can I get this package? I am trying to hide Authoring information, Revision information, Publishing options tabs in create/edit node for any content type. I tried different modules with no luck. Please give me suggestions how to achieve this. Thanks a lot Difference between "did + verb" and just "verb+ed" This is something I always get confuse with (native language German). As far as I know "did + verb" is something done and finished in the past. But isn't it the same with "verb + ed"? how to get the selected date in jquery Should I use UUID as well as ID