Reduce vertical padding of itemize inside tabular
Preventing itemize environment to insert initial vertical space
Nignx - worker_connections are not enough I don't know what is going on. I double value for worker connections but it still return error.  server { server_name xxx.com;  root /var/www/web; index index.html index.htm index.php; error_log /var/log/nginx/error.log; location / { proxy_http_version 1.1; proxy_set_header   Host $http_host; proxy_set_header   X-Real-IP $remote_addr; proxy_set_header   Upgrade $http_upgrade; proxy_set_header   Connection "upgrade"; proxy_cache_bypass $http_upgrade; proxy_pass         http://127.0.0.1:7777; }        listen 443 ssl; # managed by Certbot     ssl_certificate /etc/letsencrypt/live/xxx.com/fullchain.pem; # managed by Certbot     ssl_certificate_key /etc/letsencrypt/live/xxx.com/privkey.pem; # managed by Certbot     include /etc/letsencrypt/options-ssl-nginx.conf; # managed by Certbot     ssl_dhparam /etc/letsencrypt/ssl-dhparams.pem; # managed by Certbot  } server {     listen 80;     server_name xxx.com;     return 301 https://$host$request_uri; # managed by Certbot  }   Everything is okej with this code?  ERROR:  Firstly was:  worker_connections are not enough worker_connections are not enough   Now is  27513#0: accept4() failed (24: Too many open files) 27513#0: accept4() failed (24: Too many open files) 27513#0: accept4() failed (24: Too many open files) 27513#0: accept4() failed (24: Too many open files) When I have a query that checks if a column of type uniqueidentifer does not exist in a table that has a null value then I get no results back. If the subquery does not return a null it works fine and it only happens when using not in.   I know I can just do a not null check in my subquery, but I am curious why this does not work.  Query Example:  select a.guid from tableA a where a.guid not in (select b.guid from tableB AS b)   Working Test:  select 1 where newid() not in (select newid())   Broken Test:  select 1 where newid() not in (select null) Let $K$ be a field and $f \in K[x]$ a polynomial of degree $n&gt;0$. Assume that $E$ is an extension of $K$ such that $f$ can be expressed as a product of linear factors over $E$:  $$f(x)=\gamma (x-\alpha_1)(x-\alpha_2)\dots(x-\alpha_n).$$  I want to show that $\lvert K(\alpha_1,\dots,\alpha_2) : K \rvert$ is a divisor of $n!$. I also want to show that if $\lvert K(\alpha_1,\dots,\alpha_n): K \geq (n-1)!$ then $f$ is irreducible over $K$ or $f$ already has a root in $K$.  The problem has a hint. It says: "Use induction on $n=\deg f$. If $f=gh$ in $K[x]$ with $\deg g =r$ and $\deg h=n-r$, then $r!(n-r)!$ is a divisor of $n!$.  Any idea for solving this problem would be appreciated. How to add a class to a given element? How do I install an individual package on a Linux system? Is there a detailed activity log on Mac OS X that lists my recent commands and actions? How can I see what I just did on my computer? For example, an activity log showing that I copied a file from here to there? When to use icons vs. icons with text vs. just text links? SELECT permission on view querying table from another database SQL Server 2008 R2 SP1  My company uses the Great Plains (GP) financial system with several customizations.  Our Value-Added-Reseller (VAR) for GP has setup most of these customizations in a separate database from the GP data called DYNCUSTOM.  In the DYNCUSTOM database is a View that is merely a SELECT * FROM a table in the GP company database (called PARTS).  I was approached by a user having problems trying to select on this view.  The error he was getting:  Msg 229, Level 14, State 5, Line 2 SELECT permission denied on object 'BM010415', database 'PARTS', schema 'dbo'   I looked at how his login was mapped and he had a database user in the DYNCUSTOM database belonging to a database role that was granted select on the view.  However, he did not have a database user in the PARTS database.    Usually the intent of a view is so that one can grant select permissions on the view without exposing access to the underlying table.  With SQL Server however, if the view crosses databases does it then change the security context being used?  Therefore, the user would also need a database user in the PARTS database as well as granted select access to the underlying table? Let $f\colon(0,\infty)\to\mathbb R$ be differentiable on $(0,\infty)$ and suppose that $\lim\limits_{x\to\infty} f'(x)=L$.         a. Show that for any $h&gt;0$, $\lim\limits_{x\to\infty} \frac{f(x+h)-f(x)}h=L$.      b. Show that $\lim\limits_{x\to\infty} \frac{f(x)} {x} =L$.   this is a differentiation question.  i don't know how to solve this question  Because it is Korean, it is difficult to deal with this cite. So for me, it is not easy to write.  thank you How do you use unlocked rewards after each mission in Splinter Cell: Double Agent? In the PC version of Splinter Cell: Double Agent, how can you use the rewards that you receive after each mission? For example, the shotgun attachment, or the colored night vision?  My list shows that the rewards are there, but I can not figure out how to use them. Proving $\gcd \left(\frac{a}{\gcd (a,b)},\frac{b}{\gcd (a,b)}\right)=1$ How would you go about proving that $$\gcd \left(\frac{a}{\gcd (a,b)},\frac{b}{\gcd (a,b)}\right)=1$$  for any two integers $a$ and $b$?  Intuitively it is true because when you divide $a$ and $b$ by $\gcd(a,b)$ you cancel out any common factors between them resulting in them becoming coprime. However, how would you prove this rigorously and mathematically? Tags in spoilers are always visible, even if you don't put your mouse on the spoiler (on  for example). See the screenshot:      Looks a bit strange on this site too:        that needs ! Area of intersection of two Annulus Given two separate annulus with centers $[C_1,C_2]$ and their corresponding radii being $[R_1,r_1]$ and $[R_2,r_2]$ respectively, larger radius being $R$. There are methods to look at whether they are overlapping or not. If they overlap how to find the overlapping area. Is there any close form expression for it?  equation of first annulus   $r_1^2&lt;(x-x_{c1})^2 + (y-y_{c1})^2 &lt;R_1^2$   equation of second annulus  $r_2^2&lt;(x-x_{c2})^2 + (y-y_{c2})^2 &lt;R_2^2$  If there are three circles overlapping, we get overlapping area as solution to set of 4 in-equations by least squares approach(Though we don't end up getting total area but, area within tangents of circles ). General way to determine $\mathbb{Q}(\gamma) = \mathbb{Q}(\alpha,\beta)$ given $\alpha$ and $\beta$ Best way to do multi-row insert in Oracle? EntityFieldQuery order by title Getting a better understanding of callback functions in JavaScript I understand passing in a function to another function as a callback and having it execute, but I'm not understanding the best implementation to do that. I'm looking for a very basic example, like this:  var myCallBackExample = {     myFirstFunction : function( param1, param2, callback ) {         // Do something with param1 and param2.         if ( arguments.length == 3 ) {             // Execute callback function.             // What is the "best" way to do this?         }     },     mySecondFunction : function() {         myFirstFunction( false, true, function() {             // When this anonymous function is called, execute it.         });     } };   In myFirstFunction, if I do return new callback(), then it works and executes the anonymous function, but that doesn't seem like the correct approach to me. Commuting: How to carry office clothing so it doesn't get crushed? I have the bike, I have the best route; but now I want to know, how do I transport my clothing in each day? I typically wear suit pants and a business shirt, but not a suit jacket.   Am I better off leaving my clothes at work, or is there a special bag that would let me carry in shirt/pants without them getting crushed? Suppose I know that I can find the $\gcd$ of two integers with the Euclidean algorithm. What is the 'extension' so I can use this method also for polynomials?  Edit: I found an easy answer with less rigor which is approachable without knowledge of matrices:    also the first 3 subchapters of How can I search for one label but not another? What search query will return conversations that have the label Reading but not the label Ignore?  I've tried using label:reading -label:ignore but Gmail still returns conversations that have the label Ignore:    The query label:(reading -ignore) gives me the same results.