Update /bin/usr/php in CentOS 6
PHP 5.5.13 on CentOS 6.5 with yum
Initializing Manipulator value within DialogInput (version 10.1 only) mathpazo + siunitx: π turns into ß When I use mathpazo and siunitx (version 2.3h) together, if I use \pi inside the numerical argument to \SI, it will show up in the output as "ß".  \documentclass{article} \usepackage{mathpazo, siunitx} \begin{document}     $\pi + \SI{\pi}{\ohm}$ \end{document}   Produces:    But when I don't use mathpazo:    Why does this happen and how can I fix it? Title of 80's movie: future-era timetraveling humans go extinct and rescue/kidnap todays air crash victims What is the title of a 80's (i believe?) movie where humans in the far future are going extinct, and are aquiring new humans by going back in time to todays world, kidnapping air travelers that are known to have died that day, from the flying passenger aircraft just before its crashing.  A key visual:    Inside a hangar, a time portal opened, and a tail of a (flying) passenger aircraft extruded into the hangar where a stairs provided access to the back door of the aircraft.  The kidnappers made sure the surviving passengers remain seated and would forget about the whole ordeal. Kidnapped humans got replaced by lookalike dummies, including things they had on them. They tried hard not to alter the timeline. Length of generator output Python provides a nice method for getting length of an eager iterable, len(x) that is. But I couldn't find anything similar for lazy iterables represented by generator comprehensions and functions. Of course, it is not hard to write something like:  def iterlen(x):   n = 0   try:     while True:       next(x)       n += 1   except StopIteration: pass   return n   But I can't get rid of a feeling that I'm reimplementing a bicycle.  (While I was typing the function, a thought struck my mind: maybe there really is no such function, because it "destroys" its argument. Not an issue for my case, though).  P.S.: concerning the first answers - yes, something like len(list(x)) would work too, but that drastically increases the usage of memory.  P.P.S.: re-checked... Disregard the P.S., seems I made a mistake while trying that, it works fine. Sorry for the trouble. Often confusion arises when the  spell is used, an  is worn, or the 's anti-magic ray is employed, whether a given character's ability will still function.   The spell does give you some guidelines on how to adjudicate the effects of the loss of magic but says very little about how to determine what is affected.  In short, how do I tell if an ability is magical? What is the difference between 'sudo' and 'su -c' UIToolbar tint on iOS 4 Repost it with a minimal working example for the amsmath must be loaded earlier than mathspec problem Eclipse Scala IDE - class file needed by X is missing TikZ: turning edges into arrows using "child" notation I'm using TikZ for the first time to draw a simple Kripke model, and I'm using the child notation to produce new nodes. How can I turn my edges into arrows?  \begin{tikzpicture}   \node [circle,draw] (q0) {}   child {node [circle,draw] (q1) {$p$}     child {node [circle,draw] (q4) {$p$}       child {node [circle,draw] (q7) {$p\land q$}}       child {node [circle,draw] (q8) {$p\land q$}}       child {node (q9) {} edge from parent[-&gt;, dashed]}}     child {node [circle,draw] (q5) {$q$}}     child {node (q6) {} edge from parent[dashed]}}   child {node [circle,draw] (q2) {$p$}}   child {node (q3) {} edge from parent[dashed]}; \end{tikzpicture}   I know how to change the color or thickness of all edges by passing an option at the beginning of \begin{tikzpicture}, but I can't turn them into arrows.   Also, while we're at it, is there a way to label these edges? Or am I left with simply using node notation for all my nodes?  Thanks for all your help, Piotr How many solutions are there to $x_1 + x_2 + ... + x_5 = 21$? How many solutions are there to the equation      $x_1 + x_2 + x_3 + x_4 + x_5 = 21$    where $x_1, i = 1,2,3,4,5$ is a nonnegative integer such that $0 ≤ x_1 ≤ 3, 1 ≤ x_2 &lt; 4$, and $x_3 ≥ 15$?  I have correctly completed the previous parts of the question but am having trouble with this particular restriction.  The total number of solutions to the equation is $C(25,21) = 12650$.  I have tried to do each restriction individually:  For $0 ≤ x_1 ≤ 3$, I solved this by subtracting the number of solutions when $x_1 ≥ 4$ from the total number of solutions. This is $C(25,21) - C(21,17) = 5985$.  For $1 ≤ x_2 &lt; 4$, I have $C(24,20) - C(21,17) = 5985$.  For $x_3 ≥ 15$, I have $C(10,6) = 210$.  However, the restriction is when these are all together. I am not sure how to proceed. The answer is $106$. I am unable to cover the following class get set method. Need help in creating test class  public class Aresult{      public class Parent {         public String type {get; set;}         public String id {get; set;}         public String sequence_id {get; set;}         public String etag {get; set;}         public String name {get; set;}     } }   Please suggest  @isTest  public class CirriusGetItemsResultTest {     public static void myUnitTest(){         Aresult.parent a = new Aresult.parent();         a.type='hello';         a.id='hello';         a.sequence_id ='hello';         a.etag ='hello';         a.name ='hello';     } } How do I select an object in the 3D viewport? Consider two different shaped containers having same area: one is cylinder, the other is like an inverted pyramid (roughly). Both have the same level of water, the weight of the inverted pyramidal container will therefore be greater than that of the cylinder. But I know from Pascal's law that the pressure should be same in both containers. If the base areas are the same then the force (weight as measured by a scale) should also be the same. Why are the weights different? REST Service API executor.executeAsync Call Ends in Failure Function in Sharepoint Hosted App Any Answers Will Help me to Forward and Gain Knowledge in SharePoint Development  While i am Trying to get the list Items Using Rest API Calls in SharePoint Hosted App Using Below Function  function loadingSamples()  {     var JobListName = "RRR Jobs #";     var executor;     // Initialize the RequestExecutor with the app web URL.     executor = new SP.RequestExecutor("/");      //Fetching the choice values from the Job Status Field, to show in the Dropdown field     executor.executeAsync     ({         url: "/_api/web/lists/getbytitle('" + encodeURIComponent(JobListName) + "')/fields/getbytitle('Job Status')?$select=Choices",         method: "GET",         headers: { "Accept": "application/json; odata=verbose" },         success: successHandlerStatus,         error: errorHandler     }); } function successHandlerStatus(data)  {     alert("sucesss") }  function errorHandler(data, errorCode, errorMessage)  {     alert("errorMessage") }   It's always going to error function named errorHandler With  Error Code as -1002 and Error Message as Bad Request and Inside Data -> Body , the Error message is  {     "error":{            "code":"-1,Microsoft.SharePoint.Client.InvalidClientQueryException",         "message":{             "lang":"en-US",             "value":"The expression \"web/lists/getbytitle('DWR Jobs \" is not valid."         }     } }   Note :    This is working code in Sharepoint Hosted App that previously hosted in another Windows server. Now i hosted this App in New windows server,it's successfully hosted but it gives above mentioned Error in Rest Service Call. Viewing all my questions from Android app Why are there so few robots in Star Trek? Okay, obviously beyond Data and the Soong-type androids. But seriously, we have more robots in our daily life now than there apparently are on Trek. Is there a canon answer why not? It seems like Star Wars is more on the nose in this regard - it’s unclear why all dirty/dangerous/boring work wouldn’t be done by robots (anthropomorphic or not). What's the simplest way to print a Java array? YA novel about dystopian future with non-human overlords and teenage heroes Proof of an elementary property of Projection Operators I'm asked to show the following:  Let $X$ be a linear space, and let $P : X \rightarrow X$ be a projection operator. Restricted to the linear space $range(P)$, the projection $P$ is the identity operator, that is, $Px = x$ for all $x \in range(P)$.  If anyone could offer a hint for how to show this. I'm rusty with linear algebra so don't really know what I'm supposed to bring in outside of what's specified in the lemma/definition of projection. What is so special about the range of P that would make this so?