Why can't Sasuke use Tsukuyomi even after implanting Itachi's eyes?
Can Sasuke use Tsukuyomi?
Can the Earth's magnetic field be used to generate electricity? I am trying to import an Excel table with around 10,000 XY points into ArcMap 10.2. I am using State Plane NAD 1983 Alabama West (US Feet) as the Coordinate System in my map data frame. I then add the excel table to my Table of Contents in the map then select Display XY Data. Next, I choose the same coordinate system as my data frame then select OK. Once it creates the Events layer for my points they are not in the correct location.   Should I switch everything in my map to WGS84 or is there a solution for my points to be added onto my current map with the state plane coordinate system? I was watching the film A Game of Shadows starring Robert Downey Junior and Jude Law when this line came up, "...neither you nor I is in control..." (I can’t remember the exact words that ended the phrase; if anyone can supply them, it would be much appreciated.)   It immediately struck me as being odd. When I mentioned this to my boyfriend; an English native speaker, with a PhD in something sciency, he told me it was correct. When I asked why, he couldn't explain but put forward the following sentence as an example. "Neither of us is in control..." However, I disagreed with the wording and said the sentence should have been: "Neither one of us is in control..." The genderless third person, one, is singular, and hence, so too the verb that follows. And we say, "one is" NOT "one are".      "Neither you nor I are in control over ..."    I believe the above sounds better, but it is more logical to say:     "Neither you nor I am in control..."    because the verb agrees with the subject closest to it; however, I'm not sure if I have ever read or heard this solution. So, I tried inverting the subject and auxiliary verb order and the resulting phrase was:    "Neither you nor am I in control..."    which sounds very formal, pompous, and ... odd. Am I imagining things?  The two subjects you and I are two separate individuals who are not joined together, I agree the verb should be in the singular; but why should we use "is"? We don't say, "you is" or "I is". Before anyone rushes off to claim my question is a duplicate of a previous Stackexchange one:  I want to explain why the answer to that question fails to explain why my boyfriend and the film makers consider the  sentence below correct:     Neither you nor I is in control...   As I see it, Michael and Albert are two separate individuals, it therefore stands to reason that the verb should be singular, and "is" agrees with the subject. If I rephrase the neither and nor construction, I would get:          Michael is not correct but neither is Albert   OR          Michael is not correct and Albert isn't either.      Which have the same meaning, (either being the negative equivalent of neither) the sentences are grammatical which leads me to conclude that the verb must be singular and hence         Neither Michael nor Albert is correct      However, when I rephrase the "neither you nor I" sentence following the same procedure I have to say this:        You are not in control but neither am I (‘I am’ is ungrammatical)   OR              You are not in control and I’m not either.      which leads me to surmise that the sentence below must be grammatically correct        Neither you nor I am in control"      So, why does my boyfriend insist that the sentence ought to be:     Neither you nor I is in control   Which one of us is right and why? When NASA sends astronauts to space, they have to wear uncomfortable suits. Why aren't the humans in Star Wars spacecraft doing the same thing? What technology do they have on board that remove this need? Why is logistic regression a linear classifier? Since we are using the logistic function to transform a linear combination of the input into a non-linear output, how can logistic regression be considered a linear classifier?  Linear regression is just like a neural network without the hidden layer, so why are neural networks considered non-linear classifiers and logistic regression is linear? Comma as decimal marker with siunitx (Spanish usage) Do Thorncaster Sliver's triggered abilities go on the stack? I was guessing, since you actually target things instead of just dealing damage (similar to ), 's triggered abilities would actually go on the stack.  This came up in a separate game this past Friday when the Sliver deck attacked with two s, one , and two s while his opponent had a  as well as some 2/2.  The reason this even came up was because, if the triggers went on the stack, you could target things so they resolve in the following order:   Predatory Sliver targets Blood Artist, killing it. Predatory Sliver targets the 2/2, dealing one damage to it. Thorncaster Sliver targets the 2/2, killing it. and 5. Both Manaweft Slivers target the player, dealing one damage each to him. Proof Verification : Prove -(-a)=a using only ordered field axioms I need to prove for all real numbers $a$, $-(-a) = a$ using only the following axioms:     Thanks to many members of the Mathematics Stackexchange Community, I have the following proof worked out:  Theorem: The Additive Inverse Identity is Unique  $ ( \forall a,b,c \in \mathbb{R} )(a+b=0) \land (a+c=0) \\ ( \forall a,b,c \in \mathbb{R} )(a+b=a+c) \\ ( \forall a,b,c \in \mathbb{R} )(b=c) \\ \text{QED} \\ $  Theorem $\textbf{a} \cdot \textbf{0 = 0}$  $ \begin{align} a \cdot 0 &amp;= a \cdot 0 \\ a \cdot (0 + 0) &amp;= a \cdot 0 \\ a \cdot 0 + a \cdot 0 &amp;= a \cdot 0 \\ a \cdot 0 + a \cdot 0 + (-a) \cdot 0 &amp;= a \cdot 0 + (-a) \cdot 0 \\ a \cdot 0 &amp;= 0 \\ &amp;\text{QED} \\ \end{align} $  Theorem: $-\textbf{1} \cdot \textbf{(a) = (}-\textbf{a)}$  $ \begin{align} a \cdot 0 &amp;= 0 \\ a \cdot \left[ 1 + (-1) \right] &amp;= a + (-a) \\ 1 \cdot a + (-1) \cdot a &amp;= a + (-a) \\ -1 \cdot (a) &amp;= (-a) \\ &amp;\text{QED} \\ \end{align} $  Theorem: $-\textbf{(}-\textbf{a) = a}$  $ \begin{align} 0 &amp;= 0 \\ -a \cdot 0 &amp;= 0 \\ -a \cdot \left[ 1 + (-1) \right] &amp;= 0 \\ -a \cdot 1 + -a \cdot (-1) &amp;= 0 \\ -a + \left[ -(-a) \right] &amp;= 0 \\ -(-a) &amp;= a \\ \text{QED} \\ \end{align} $  Does everything look alright? Have I missed anything?  Also--why is it necessary to show that the additive inverse is unique?  Many thanks in advance. Is it okay to publish my personal notes from a lecture? Block apps from accessing the Internet on Android device In Android, is it possible to block apps from accessing the Internet? Many apps will often connect to remote servers in the background, including Google's own apps or system services. Over time this can eat away at a user's data limit set by a mobile carrier. Does Android allow an app to act as a firewall whereby the user can select which apps have access to the Internet? Or does the device have to be rooted to have that ability? How do you copy a record in a SQL table but swap out the unique id of the new row? Is there any way to recover unsaved notepad++ docs? I recently put a bounty on a question regarding the . I did this as the only two answers on that page are not satisfactory and I wish to encourage a tractable answer.  I am concerned that when the bounty period expires, if I do not select an answer for the bounty that it may be awarded automatically to one of these speculative and unsatisfactory answers. How might I prevent that? I could put an answer of my own stating "no satisfactory sources are available" and award the bounty to that, however I feel that there should be a better way.  I stress that I put the bounty on the question specifically because the current answers are not satisfactory and I do not want to award them. Number of ways a natural number can be written as sum of smaller natural number It is easy to realize that given a natural number N the number of doublets that sum N are $\frac{N+(-1)(N \pmod 2)}{2}$ , so I thought I could reach some recursive formula in the sense that found the number of doublets I could find the number of triplets and so on ...,  example: N=3 the only doublet is 2+1=3 -not said yet but 2+1, and 1+2 count as one- then I could count the number of way the number 2 can be expressed as the indicated sum and got the total number of ways 3 can be written as a sum. But this seems not so efficient, so I was wondering if there is other way to attack the problem and if there is some reference to this problem such as if it is well known its used, once I read that this have a chaotic behavior, and also read It was used in probability but don't remember where I got that information. So if you know something I would be grateful to be notice, thanks in advance. iPhone Passcode for Powering Off I am looking for an option to require a passcode to power off my iPhone. That way, if the phone is lost, the person who finds it cannot simply turn it off, rendering Find My iPhone useless. Is there a way to accomplish this? How to remove symbolic link I was trying to create this symbolic link:  sudo ln -s /usr/share/phpmyadmin /var/www/phpmyadmin   but I accidentally typed:  sudo ln -s /usr/share/php,yad,in /var/www/phpmyadmin   So now I want to correct it but it says symbolic link already exist. "did shoot" vs "shot" Sometimes a question I ask will get answers that don't help me, or maybe it doesn't receive any answers at all.  How about making a notification when somebody links to my question?   It could be something like this:     New information regarding your question might be available at {link}   It might help me getting an answer from related questions that weren't there when I first asked the question. Is there a built-in function to print all the current properties and values of an object? So what I'm looking for here is something like PHP's  function.  This is so I can debug my scripts by seeing what's the state of the object in question. Solving infinite sums with primes. Let $p_n$ denote the $n$'th prime number.  How would one go about proving that infinite products like: $$\prod_{k=1}^\infty1 - \frac{1}{(p_k)^2} = \frac{6}{\pi^2}$$  or  $$\prod_{k=1}^\infty\frac{{p_k}^2}{{p_k}^2 - 1} = \frac{\pi^2}{6}$$ are correct?  Is there any way to prove it except by exhaustion?