Number of other close votes don't match when for the off-topic detailed list Just now, when reviewing close votes I voted to close a question and saw that there were four other votes cast for off-topic     but clicked off-topic I could only see one other vote, the other 3 was missing.    I have been seeing this issue many times today.
The close dialog says there are two off-topic votes, but none of the off-topic reasons have votes next to them I've found strange behavior when closing this  - I definitely see that there are 3 closing votes and 2 of them are at "Off-topic" section:   -but there are no explanations on section itself:   -while, normally, it's expected that it will appear. In custom comments section there are also no closing-votes displayed.   Perhaps it's just my browser (which is FF 26 x64 under Win) - so marking this as a "possible bug". Thank you for your attention.
bash dynamic (variable) variable names Is there a package to secure rendered pdf with a password? Given $y_n=(1+\frac{1}{n})^{n+1}$ show that $\lbrace y_n \rbrace$ is a decreasing sequence Given  $$ y_n=\left(1+\frac{1}{n}\right)^{n+1}\hspace{-6mm},\qquad n \in \mathbb{N}, \quad n \geq 1. $$ Show that $\lbrace y_n \rbrace$ is a decreasing sequence. Anyone can help ?  I consider the ratio $\frac{y_{n+1}}{y_n}$ but I got stuck. How to get scroll position from GridView? Disable COPY drag and drop in Windows Explorer in Windows 7 Learning special relativity and working with Minkowski diagrams for a while now i am still trying to get my head around some oddity.   From my understanding time can often be seen as the dependent variable in those diagrams, so why put it to the vertical axis? What confuses me even more is the apparent convention to denote a point in space time $(t,x)$ even though $x$ is on the horizontal and $t$ is on the vertical axis, so the usual notation would be to refer to that vector as $(x, t)$.  Are there mostly historical reasons or why is it beneficial to use this notation and to violate usual conventions? Unicoin Bug: Automining Returns Diminishing I'm using the auto-mining script from one of the meta posts here and it doesn't works!  At first I got steady returns but the returns seem to diminish over time. Using Fiddler I confirmed that the server seems to release less and less coins.  This is unacceptable! I am a loyal customer paying nothing and I demand that my auto-mining script continues to yield returns forever!  If you cannot deliver on that please refund what I have payed for using this site.  Plz advise!    In case you didn't notice: This is a parody of over-demanding, leeching askers on Stack Overflow. I have an iMac, connected to the Internet via Ethernet, and an iPhone 4. I would like to share the iMac's Internet connection to my iPhone via the USB Cable (because my wife dreams of a wifi-less household).  I've set up Internet Sharing, specifying "sharing from: Ethernet  via: USB IPhone", but when I test, the iPhone cannot connect to the Internet. Is there something I need to activate on the iPhone?   iMac, mac os x version: Mountain Lion, 10.8.4 iPhone 4, IOS Version: 6.1 Predict probabilities from Firth logistic regression in R I'm using the logistf package in R to perform Firth logistic regression on an unbalanced dataset. I have a logistf object:  fit = logistf(a~b)   Is there a predict() function like on that's used in the lm class to predict probabilities for future data points? Or do I have to manually input the estimated parameters from the Firth regression. $X^n-Y^m$ is irreducible in $\Bbb{C}[X,Y]$ iff $\gcd(n,m)=1$ I am trying to show that $X^n-Y^m$ is irreducible in $\Bbb{C}[X,Y]$ iff $\gcd(n,m)=1$ where $n,m$ are positive integers.    I showed that if $\gcd(n,m)$ is not $1$, then $X^n-Y^m$ is reducible. How to show the other direction. Please help. Permanent background ssh connection to create reverse tunnel: what is correct way? creating variable using variable value as part of new variable name I'm trying to create a new variable using the value of an existing variable as part of the variable name.  filemsg"$word1"=" "   I've also tried   filemsg$word1=" "  filemsg${word1}=" "   on all attempts I get the following when that line executes,  cicserrors.sh[45]: filemsgCICS= : not found [No such file or directory] A few days ago I was recalling some facts about the $p$-adic numbers, for example the fact that the $p$-adic metric is an ultrametric implies very strongly that there is no order on $\mathbb{Q}_p$, as any number in the interior of an open ball is in fact its center.  I know that if you take the completion of the algebraic closure of the $p$-adic completion you get something which is isomorphic to $\mathbb{C}$ (this result was very surprising until I studied model theory, then it became obvious).  Furthermore, if the algebraic closure is of an extension of dimension $2$ then the field is orderable, or even real closed. Either way, it implies that the $p$-adic numbers don't have this property.  So I was thinking, is there a $p$-adic number whose square equals $2$? $3$? $2011$? For which prime numbers $p$? How far down the rabbit hole of algebraic numbers can you go inside the $p$-adic numbers? Are there general results connecting the choice (or rather properties) of $p$ to the "amount" of algebraic closure it gives? Why we won't extract heat from air temperature? listings package in XeLaTeX: every tab in lstlisting compiles to "^^I" in the pdf In beamer class, when i compile using LaTeX, the output pdf results perfectly the way i expect it to. But when i change it to XeLaTeX, in the lstlisting environment, every tab in the code results in a "^^I"-Placeholder (See output-pdf below). How do I fix this?   if( Bedingung ) {  ^^I//Code, der nur ausgefuehrt wird, wenn die Bedingung wahr ist   }  ^^I^^I   LaTeX-Code (Reduced to the minimum, one frame as an example):  \begin{document}     \begin{frame}[fragile]{if-Statements}         \begin{block}{Syntax}                \begin{lstlisting} if( Bedingung ) {     //Code, der nur ausgefuehrt wird, wenn die Bedingung wahr ist }                    \end{lstlisting}         \end{block}         \begin{block}{Logik}                 \begin{itemize}                  \item Alles innerhalb eines if-Blocks wird nur ausgeführt, wenn die Bedingung (in Klammern) wahr ist.             \end{itemize}         \end{block}     \end{frame} \end{document} How to get ObjectContext to compile? Add/Show comments focuses text box by default If I open a post using the mobile theme, which has many comments, there is a link at the footer "add/show n more comments". If this link is clicked, the comments are loaded and displayed.   At the moment the text area is automatically focused which is not a great experience (in my opinion), as you have to close the editor and scroll back to the top if you just wanted to read the comments, without adding a new one.  Would it be possible to either   not focus the text area by default and to load only the comments add a new link for adding a comment Nested sequence of non-empty compact subsets - intersection differs from empty set I have the following proposition:  "If $(S_n)$ is a sequence of compact subsets of a metric space such that  $S_1 \supseteq S_2 \supseteq ... \supseteq S_n$  Then $\bigcap^\infty_{i=1} S_i$ $\neq$ $\emptyset$"  My lecture notes provide the following proof, whose last step I don't understand:    Proof: Assume by way of contradiction that $\bigcap^\infty_{i=1} S_i$ = $\emptyset$. Let $V_n := (S_n)^c$ for each $n$. The class $\mathbb{C} :=\{V_n: n \in \mathbb{N} \}$ is an open covering of $S_1$. Since $S_1$ is compact, $\exists I$ finite, $I \subset \mathbb{N}$, s.t $\{V_i: i \in I \}$ covers $S_1$. Let $n:=max(I)$. The class $\{V_1, ..., V_n \}$ also covers $S_1$ and we get the following contradiction   $\emptyset = \bigcap^n_{i=1} S_i = S_n$    So, I don't get the part from "Let $n:=max(I)$..." onwards, especially the contradiction. I have tried applying DeMorgan's Law and the only way the last equalities makes sense is if the union of $\{V_1, ..., V_n \}$ equals the whole metric space, a property I haven't been able to understand from the steps of the proof. This is a corollary to the finite intersection property, so it must have a connection but again I can't quite get it.  Thanks in advance Basically this suggestion for the Android app:   Many times I'll see that a post has been edited on the Android app. I'll want to see exactly what was edited, and the Android app doesn't show this. Can the revision history be added to the Android app? if $a,b$ are nilpotent elements of a commutative ring $R$, show that $a+b$ is also nilpotent