I'm using Ubuntu 13.04 , it can't read Arabic letters and words properly. that what I get when I open files contains Arabic, please notice that same files are showed correctly on windows:  ÇáÞÇäæä íÌÈÑ ÇáíåæÏ Úáì ÇáÚíÔ ÈãäØÞÉ ãÚÒæáÉ ãä ÇáãÏíäÉ ÊÏÚì ÇáÌíÊæ
I have some files that Ubuntu can't read it ( ANSI encoding ) but Windows can read it well.  When I open it in gedit or notepad++ it seems like this :     Êã ÇáÊÍæíá áÜÜ   How can I make Ubuntu read ANSI encoded files well?
TTY doesn't wait for password Can't delete files or folders on partition I have an NTFS partition. The idea is I can use this for data on either Ubuntu Mate or Windows 10 dual boot. It worked fine when I first installed Mate, but recently I no longer have the delete option when I right-click on a file or folder. The delete key does nothing. I also can't paste into the partition (Paste greyed out). It's as if the whole partition is read-only. In Gparted, the partition is marked with a key. Does this mean anything? I'm not aware of having changed anything, however, Windows recently did a big update - have they hijacked my drive?  I've read related posts, but people speak of returned errors - I have no errors, just nothing happens. Also, suggested solutions seem far too technical for what must surely be a simple tick-a-box fix!  Please note - for me the Terminal is where I get off a train and Sudo sounds like a Japanese noodle dish. ;) GUI's preferred if possible! Thanks for your patient help! Preface:  An axis plotted with  is usually using the current math font for its ticklabels. But if they are overwritten by e.g. xticklabels={-8,-6,...,8} then the current text font is used. Also an axis label ylabel={Y} would be in text font unless put explicitly in math mode ylabel={$Y$}. However it would be nice, if  one hadn't to do so.   Question:  I'm aiming to ensure that pgfplots always uses the current math font. But please assume that the classic font commands like \rmfamily are screwed up by the corporate design I'm supposed to use, e.g. assume: \renewcommand{\rmdefault}{\sfdefault}  It works if I explicitly define a font  \newcommand{\pgfmathfont}{\fontfamily{pxfonts}\selectfont}   and pass it to pgfplots together with assume math mode=true:  \begin{axis}[ font = \pgfmathfont,  tick label style={/pgf/number format/assume math mode=true} ]   But it requires that I insert the name of the current math font. How can I do that automatically? How to get the currently used math font to insert it into the macro?    MWE  \documentclass{beamer}  \usetheme{Warsaw} \usefonttheme{professionalfonts} \usepackage{pxfonts} \usepackage{pgfplots}  % screwed up by Corporate Design \renewcommand{\rmdefault}{\sfdefault}  % I'd like this line to be generic! \newcommand{\pgfmathfont}{\fontfamily{pxfonts}\selectfont} %           put current math font here   X  \begin{document}  \begin{frame}  This is a basic equation:    \[ x + y = 42\]  \begin{tikzpicture}     \begin{axis}[ %   font = \rmfamily, % makes no sense here     font = \pgfmathfont,      xlabel={$x$-label: I want to be in math font!},     ylabel={Y},     xtick={-4,-3,...,4},     xticklabels={-8,-6,...,8}, %   xticklabels={$-8$,$-6$,...,$8$}, % does not work     tick label style={/pgf/number format/assume math mode=true}     ]      \addplot {x^2};      \end{axis} \end{tikzpicture}  \end{frame}  \end{document}     Everything related to  is no option at all!  Thank you! Magic leaves "smudges" and a sorceress becomes a book I could use some help identifying a book I read some time in the last year or so. The book goes between two different stories:  1) A student of magic finds a book in a cave that turns out to be a person transformed into a book. The book talks to the student and they share thoughts. At some point, the student runs away, chase ensues, and at the very end of the book, he manages to travel to another plane.  2) A girl in a religious society where magic is forbidden. She is the daughter of painters. She discovers she can see magic. Falls in love with some random painter, risks performing magic to not be pregnant, does it again so she can, and is arrested and sent to some prison thing.  The common element between the stories is that magic use leaves behind a smudge of some kind that can be visible.  Any assistance is appreciated. Python dictionary: are keys() and values() always the same order? Why can't I press the Install button when installing applications from unknown sources? How do I kill the lockscreen after the Windows 10 anniversary update? My primary router has trouble extending wifi coverage to some bedrooms in the house so I am planning to add a second router to extend the wifi network using the wired Ethernet ports in one of the areas of poor coverage. Basic layout -   The ISP's router is in my family room downstairs (fiber connection) and the internet connects to the fiber via a box in an upstairs closet.   I purchased and installed an unmanaged Ethernet switch/splitter. In the upstairs closet where all of the Ethernet wires meet, the family room Ethernet cable was plugged into the ISP's box. I disconnected this wire and replaced it with a CAT5 cable running from the ISP's box in the closet to the Ethernet switch's port 1.  I think connected the family room Ethernet cable to port 2 and did the same in order for all the remaining Ethernet cables to various bedrooms.   So far, the switch is working fine.  I have wifi working with internet coming off of the router in the living room so I believe the switch is installed correctly otherwise that wifi should not have internet coming off of the living room jack.   Here is where things go awry - I took my second wifi router and connected the WAN/Yellow port to the Ethernet wall jack in another bedroom.  I then connected a lap top to one of the Ethernet ports on this router and found "no internet" after connecting.  On a whim, I changed the connection so that the router was connected to the Ethernet wall jack in one of the white ports but with the same results.   I don't think this counts as cascading and I don't really need a new network since I do not share the connection with any non-family members.  The router has been reset to factory settings to clear out any old instructions - but I still can't get it to connect to the internet or access the router to change the settings even - it's a netgear and the routerlogin.net will not let me access the router even when I am on the working WIFI for internet and have a cable running from the laptop to the netgear router.   I could use some help - just trying to extend the wifi range and it seems like it should be much less complicated. Tried following instructions in several other posts and they did not work for me - because I cannot access the router to change any settings. Does $A$ a UFD imply that  $A[T]$ is also a UFD? I'm trying to prove that $A$ a UFD implies that $A[T]$ is a UFD.   The only thing I am sure I could try to use is Gauss's lemma.  Also, how can we deduce that the polynomial rings $\mathbb{Z}[x_1,\ldots,x_n]$ and $k[x_1,\ldots,x_n]$ are UFDs? Conjugate Variables, Noether's Theorem and QM What would be the easiest way to UV map a complex object? I'm attempting to make a texture for a model i've been working on, so i've been trying to get a decent UV map, However whenever I do it usually ends up either very distorted or a lot of unrecognizable pieces or several different UV maps. What are some easier ways of unwrapping/UV Mapping? If $m,n\in N$ Prove that there is such a positive integer k, such that $(\sqrt{m}+\sqrt{m+1})^n=\sqrt{k}+\sqrt{k+1}$ If $m,n\in N$ Prove that there is such a positive integer k, such that $(\sqrt{m}+\sqrt{m+1})^n=\sqrt{k}+\sqrt{k+1}$ I attempted to solve this question using binomial coefficients, saying: $(\sqrt{m}+\sqrt{m+1})^n=\sqrt{k}+\sqrt{k+1}=\sum\limits_{a=0}^n {n\choose a}*\sqrt{m}^{n-a}*\sqrt{m+1}^a$ and from here I was thinking that I had to do something with $\sqrt{m}^{n-a}$ with $\sqrt{k}$ and do something else with $\sqrt{k+1}$ and $\sqrt{m+1}^a$. Unfortunately I couldn't think of what to do with this circumstance. I then thought of maybe taking $(\sqrt{k}+\sqrt{k+1})^2=(\sum\limits_{a=0}^n {n\choose a}*\sqrt{m}^{n-a}*\sqrt{m+1}^a)^2$, but this immediately over-complicated the question. Could you please explain to me how to solve this question and how to solve similar questions in the future? Is it possible to have test error lower than training error?  I have a classification problem with 2000 samples, 500 of which are positives, 1500 are negatives. I split my data into 70% training data, 30% test data.  Run random forest with 200 estimators and cv=10. I did this several times and compared the recall and precision score and notice the scores for my test set is significantly better. Is this possible? Most of the recipes I'm using (mainly Modernist; stocks, caramelized vegetables, confit) suggest cooking at 15psi. My pressure cooker has two settings 12psi and 7psi. I've always had success just using 12psi in recipes where it says 15psi. However recently the 12psi mode has broken on my PC. I can now only cook at 7psi. How can I convert my recipes to use this lower pressure?  For example I would cook a chicken stock at 12psi for 90mins, I presume at 7psi the cooking time would need to be longer but by how much? Unicode input retrieved via PrimeFaces input components become corrupted Looking for a basic PostGIS viewer to use as basis for own application I'm looking for a rather basic PostGIS viewer. It should be possible to pan, zoom and retrieve coordinate information on mouse click. No need to support coordinate transformations. It should introduce as little further dependencies as possible. Preferably written in C++. Number of solutions to the congruence $x^q \equiv 1 \mod p$. Let $p, q$ be distinct odd primes, I would like to compute the number of solution $\mod p$ to the congruence $x^q \equiv 1 \mod p$. (Show that it's $gcd(q, p - 1))$  If $x^q \equiv 1 \mod p$, since $q$ is prime, this must mean that $x$ is either $1$ or has order $q$.   Hence, the problem reduces to finding the number of elements of $U_p$ which is either $1$ or has order $q$.  If $ q \nmid  p - 1$, then there is only one element, namely $1$.  If $q \mid p - 1$, then the number of elements of order $q$ is $\phi(q) = q - 1$, and so the number of solutions to the congruence $\mod p$ is $q - 1 + 1 = q$, and in either case the number of solutions is $\gcd(q, p - 1)$.  Does this look fine? list transparency across non consecutive slides Alice has a secp256k1 key pair that she used some time ago when she communicated with Bob. Bob can no longer user secp256k1 but he only uses ed25519 instead.  Is there a secure algorithm that Bob can use to derive an ed25519 pubkey from original Alice's secp256k1 pub key and also Alice can derive the matching ed25519 private key from her original secp256k1 private key such that they can communicate securely via ed25519 encrypted messages?  Thanks! An item to break only SPECIFIED blocks? I know that I can make certain blocks only placeable on a specified block, but what is the command to give an item that can only BREAK certain blocks?