I know there are tons of this question on here already but none of them seem to have solved my issue.  I've done a clean install of 14.04 Server and install Unity (I know, boss asked for it so he can do some things himself) with this;  sudo apt-get install --no-install-recommends ubuntu-desktop   He uses file.sh to execute a special program which works flawlessly from command line but it won't run from the GUI. Boss wants GUI so I need to figure this out.  I've set it executable from the properties window, set it executable from CLI with chmod +x, run  gconftool-2 --set /schemas/apps/nautilus/preferences/execute_text_activation --type=string ask   Tried creating a script.desktop file but get a generic execution error I haven't been able to resolve yet.  I don't have to use Unity so if XFCE or Gnome resolves the problem I'll do it. If anyone has any more ideas I would very grateful to hear them!
When I double-click on a script in Nautilus to run it, the script just opens in my text editor with no option to run it. Using Nautilus, how do I run executable text files and/or scripts?
What is the easiest way to handle huge numbers in C? I need to store values in the Area 1000^900, or in more human readable form 10^2700. Does anybody know of an easy way to do that? Any help would really be appreciated! Profitable strategy in coin tossing? Exponent and abelian groups Sum of (example: 0+1+2+3 = 6 , 0+1+2+3+4+5+6+7 = 28 and so on) What's the purpose (if any) of "javascript:" in event handler tags? I've been making a concerted effort to improve my javascript skills lately by reading as much javascript code as I can. In doing this I've sometimes seen the javascript: prefix appended to the front of event handler attributes in HTML element tags. What's the purpose of this prefix? Basically, is there any appreciable difference between:  onchange="javascript: myFunction(this)"   and  onchange="myFunction(this)"   ? Is it common for native speakers to put a question mark at the end of declarative sentence? 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Show that $(\mathbb{Q}^*,\cdot)$ and $(\mathbb{R}^*,\cdot)$ aren't cyclic I'm reading a book about abstract algebra, but I'm having trouble solving this excercise: "Show that $(\mathbb{Q}^*,\cdot)$ and $(\mathbb{R}^*,\cdot)$ aren't cyclic"  Where $(\mathbb{Q}^*,\cdot)$ is the group of nonzero rational numbers under multiplication and $(\mathbb{R}^*,\cdot)$ is the group of nonzero real numbers under multiplication.    Here is my attempt for the first.  Suppose $(\mathbb{Q}^*,\cdot)$ is cyclic, then $\mathbb{Q}^*=\langle\frac{p}{q}\rangle=\{(\frac{p}{q})^n,n\in\mathbb{Z}\}$, where $p$ and $q$ are coprime.  $\frac{2p}{q}$ is also in $\mathbb{Q}^*$ so it must be equal to $(\frac{p}{q})^n$ for some $n\in\mathbb{Z}$.  To solve $\frac{2p}{q}=(\frac{p}{q})^n$, I take a logarithm of both sides and end up with $1+\log_\frac{p}{q}(2)=n$, since $n$ is an integer $\log_\frac{p}{q}(2)$ must be an integer too, but it is possible only when $\frac{p}{q}=2^{\frac{1}{k}}, k\in\mathbb{N}$, (i.e. $\frac{p}{q}$ is a k-th root of $2$), but $k$ must be $1$ for $2^\frac{1}{k}$ to be rational so $\frac{p}{q}=2$ contradicting the hypothesis of $p$ and $q$ being coprime.    However I don't know whether this is a proper proof and the same reasoning cannot be applied to $\mathbb{R}^*$, I'd like you to just give me an hint towards a proof, without telling me the whole proof, if possible. 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Equivalent of "former" and "latter" for more than 2 items Former and latter are valid only when there are two choices.  If I have a list of more than two items, is there an elegant way to say the first one or the last one? How to show $(mn)!$ is divisible by $(m!)^n$? How to show $(mn)!$ divides $(m!)^n$, $m$ and $n$ is integers? find pair of numbers whose difference is an input value 'k' in an unsorted array When I render a page using the Django template renderer, I can pass in a dictionary variable containing various values to manipulate them in the page using {{ myVar }}.  Is there a way to access the same variable in Javascript (perhaps using the DOM, I don't know how Django makes the variables accessible)? I want to be able to lookup details using an AJAX lookup based on the values contained in the variables passed in. Duplicate flag lists "you have already raised this flag" after flagging as "Unclear what you're asking"