Is there a limit to how high you can go?  Well I got to something like 100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000 (I think) but I don't know as it went of the screen. Also it says 'Outside of world...' at the bottom left of the debugging menu. When you are this high when you fly up or down it does not change it! Please watch this video:                               .  Yes I did have to edit the photo but from the video you can see that the picture is still displaying the same number.
In Minecraft, you can only build up to a certain height limit (which is something around 256). However, if a player uses mods/hacks to go above the limit (Or simply goes into Creative Mode), then they can go above the height limit.  How high is the player height limit in Minecraft? Is there even a limit to it? I've tried testing this myself, but my thumb started hurting when I reached Y= 1000.
I just came onto a project with a pretty huge code base.   I'm mostly dealing with C++ and a lot of the code they write uses double negation for their boolean logic.    if (!!variable &amp;&amp; (!!api.lookup("some-string"))) {        do_some_stuff();  }                                      I know these guys are intelligent programmers, it's obvious they aren't doing this by accident.   I'm no seasoned C++ expert, my only guess at why they are doing this is that they want to make absolutely positive that the value being evaluated is the actual boolean representation. So they negate it, then negate that again to get it back to its actual boolean value.   Is this correct, or am I missing something? How can I transform the elliptic curve $E/\mathbb{C}$ of the form $$y^2=4(x-e_1)(x-e_2)(x-e_3)$$ with $e_1&gt;e_2&gt;e_3\in\mathbb{R}$ roots of $E$ into a Weierstrass-Form $y^2=x^3+ax+b$? Show that $\ker \hat{T} = \text{ann}(\text{range } T)$ Is there going to be a process around hellbanning? Given , I must say I think the idea (making that user's content visible to only them) is a good one.  However, the people in whose hands that power will be placed terrify me.  Jeff is saying that he doesn't like that bans can degenerate into meta-discussions about the fairness of banning, and in that respect I agree with him. But the meta-discussions do accomplish one thing -- they get more than one person to look at the ban and weigh in on what they think.  This isn't that I don't trust moderators (or, indeed, diamond moderators), but I don't trust any one single human being with an irrevocable and complete banhammer, where there's no potential to dispute things. (And if the user doesn't know they're banned, there's no potential for dispute)  Basically, I'd sleep a lot more soundly at night knowing that if one of these "enhanced bans" are put into place, that at least two people have looked at the "problem child", and only after more than one person has signed off on such a ban, does that go into effect. I don't care exactly what that process is, but I don't want to have to worry about pissing off a moderator and getting banned as a result.  We all get pissed off here -- it's part of any community. But "the nuclear option(s)" need(s) to be decided upon by someone with a cool head, not someone who's pissed off. Regex for splitting a string using space when not surrounded by single or double quotes I'm new to regular expressions and would appreciate your help.  I'm trying to put together an expression that will split the example string using all spaces that are not surrounded by single or double quotes. My last attempt looks like this: (?!") and isn't quite working. It's splitting on the space before the quote.  Example input:   This is a string that "will be" highlighted when your 'regular expression' matches something.   Desired output:  This is a string that will be highlighted when your regular expression matches something.   Note that "will be" and 'regular expression' retain the space between the words. I want to show that $$f: \mathbb{R}_{\geq0} \to \mathbb{R}_{\geq0}$$ $$x \mapsto x^s$$ is Holder continuous with Holder exponent $s \in \mathbb{R}$, where $0&lt;s \leq 1$. So what I want to show is that $\exists \hspace{2 mm} C \in \mathbb{R}_{\geq0}$ sucht that for all $ x,y \in \mathbb{R}_{\geq0},  $ $$|x^s -y^s| \leq C|x-y|^s$$ and therefore, assuming, wlog $\hspace{1mm} x&gt;y$ $$(x^s -y^s) \leq C(x-y)^s.$$  I thought about Bernoulli's inequality but couldn't make that work.I thought about the binomial theorem, but didn't know how to handle the fact that $s \in \mathbb{R}$. Prove that $\lim_{N\rightarrow\infty}(1/N)\sum_{n=1}^N f(nx)=\int_{0}^1f(t)dt$ Suppose $f$ is continuous and periodic on the reals with period 1. Prove that if $x\in[0,1]$ is an irrational number, then  $$\lim_{N\rightarrow\infty}\frac{1}{N}\sum_{n=1}^N f(nx)=\int_{0}^1f(t)dt$$   Suggestion: First consider $f(t) = e^{2\pi(ikt)}$ where k is an integer.   I can see that this is a limit of a weighted average, but the suggestion throws me off. I've seen the suggestion in fourier transforms but it's not clicking at the moment. Any help would be welcome. As a non-native speaker, I feel that it is ridiculous that can and can't could sound so similar in American accent.  Just now, I was just listening to a video in which the speaker with an American accent says     Fat cells can't reproduce themselves.   The speaker dragged the word "can't" longer for emphasis, but perhaps as a result, what I heard at first was     Fat cells can reproduce themselves.   Of course from the context I later figured out what he was really saying, but I felt extremely surprised by how these two words which literally mean the opposite could sound so similar in American accent. How is that not affecting American people's daily conversations? As a non-native speaker, is there a way for me to further clarify them when my listeners are confused? (Like when you say "one-eight" to clarify that you were trying to say "eighteen" as opposed to "eighty".) What changes with Kerberos authentication in IPv6 when everyone has a public IPv6 Address? How should Kerberos authentication be set up with IPv6?     What implications are there when client devices each use a public, globally routeable IPv6 IP address?  What changes when setup this way instead of using a NAT as was the norm with IPv4? Electron flow and electric potential In the physics tutorial topic on current electricity it defines the positive terminal as the high potential terminal and the negative as the low potential. When talking about positive test charges this analogy makes sense, the charge moves from the +ve to the -ve where it loses potential till it has to be "topped" up by the cell.   What confuses me when they begin talking electrons. Using this analogy would mean that the electrons move from the -ve to the +ve but this means it would work against the electric field so the potential energy increases till it reaches the +ve terminal.   My question is how does this analogy, if it does, change to accommodate electrons? Does the electric field reverse so the -ve terminal is the high potential and the +ve the low potential? Using Illustrator CS6 to create shape out of multiple paths Can I embed a custom font in an iPhone application? I would like to have an app include a custom font for rendering text, load it, and then use it with standard UIKit elements like UILabel. Is this possible? Custom attributes - Yea or nay? Related questions with over 99 score display incorrectly The score for the 4 questions are 111, 1218, 261 and 5 respectively, but they display 2 digits per line. This is an obvious bug in design. When we define the S-matrix, what are "in" and "out" states? I have seen the scattering matrix defined using initial ("in") and final ("out") eigenstates of the free hamiltonian, with  $$\left| \vec{p}_1 \cdots \vec{p}_n \; \text{out} \right\rangle = S^{-1} \left| \vec{p}_1 \cdots \vec{p}_n \; \text{in} \right\rangle$$  so that  $$\left\langle \vec{p}_1 \cdots \vec{p}_n \; \text{out} \mid \vec{q}_1 \cdots \vec{q}_m \; \text{in} \right\rangle = \left\langle \vec{p}_1 \cdots \vec{p}_n \; \text{in} \mid S \mid \vec{q}_1 \cdots \vec{q}_m \; \text{in} \right\rangle.$$  1) What are "in" and "out" states?   2) Are they Fock states?   3) In Schrödinger or Heisenberg or interaction representation?   4) How are they related? (I believe that I see what they handwavily represent physically, but not formally.)  My main issue is that, if "in" and "out" states are one-particle eigenstates of the free hamiltonian, i.e. if $\left| \vec{p}_1 \text{out} \right\rangle$ describes a free particle with momentum $\vec{p}_1$, and $\left| \vec{p}_1 \text{in} \right\rangle$ also describes a free particle with momentum $\vec{p}_1$, then $\left| \vec{p}_1 \text{out} \right\rangle = \left| \vec{p}_1 \text{in} \right\rangle$ ... which is false. Still, books (some at least) describe these "in" and "out" states like that.  Moreover, I have seen (e.g. in Wikipedia, but also ) that the scattering matrix is a map between two different Fock states, and I don't understand that.   5) Do states of the interacting system live in the same Fock space that asymptotic free states?   6) And if not, where do they live?  Understandable references would be appreciated. Applications of ultrafilters I'm looking for some interesting applications of ultrafilters and also everything of interest involving ultrafilters. Do you know some applications or interesting things involving ultrafilters?  I'm at the beginning, so I'd prefer some applications that also a beginner could read. How can I execute `date` inside of a cron tab job? \pdfendlink ended up in different nesting level than \pdfstartlink What does Fermi level in the band gap mean? What does it mean that the  for some semiconductors lie in the band gap?  Is Fermi level definition different from what is know as usual?  We define the Fermi level as the highest level of energy which is occupied by electrons.  Then what is missing here? can't create a jobs user profile I'm stuck on this page even after linking stackoverflow and github accounts.