am trying to authenticate using an Active Directory User on a Apache with nested Groups.  Apache 2.4.7 Ubuntu 14.4  I have a Group with Name test in this Group i have a few nested Groups If i put the user in the test goup directly all fine. The user get authenticated. But if i put the user in a nested Group and put the nested Group in the Group test i get the errormessage.  didnt match with attr member [Comparison false (cached)] [5 - Compare false]  authoritation denied for user xyz  My Subgroupdepth is just one.  Anyone a idea ?  Best regards mobios  My Config:  &lt;AuthnProviderAlias ldap users&gt; AuthLDAPBindDN "CN=ldapbind,OU=Services,OU=Administration,DC=test,DC=tc" AuthLDAPBindPassword Password AuthLDAPURL "ldap://10.0.100.1:389/CN=Users,DC=test,DC=tc?sAMAccountName?sub" &lt;/AuthnProviderAlias&gt;   &lt;AuthnProviderAlias ldap project&gt; AuthLDAPBindDN "CN=ldapbind,OU=Services,OU=Administration,DC=test,DC=tc" AuthLDAPBindPassword Password AuthLDAPURL "ldap://10.0.100.1:389/OU=Projects,DC=test,DC=tc?sAMAccountName?sub" &lt;/AuthnProviderAlias&gt;  &lt;AuthzProviderAlias ldap-group test CN=test,CN=Users,,DC=test,DC=tc&gt; AuthLDAPBindDN "CN=ldapbind,OU=Services,OU=Administration,DC=test,DC=tc" AuthLDAPBindPassword Password AuthLDAPURL "ldap://10.0.100.1:389/CN=Users,DC=test,DC=tc?sAMAccountName?sub" &lt;/AuthzProviderAlias&gt;  Alias /production /srv/webdav/production  &lt;Location "/production"&gt; SSLRequireSSL  DAV On  Options None  AuthType Basic  AuthUserFile /dev/null  AuthName "Repository production"  AuthBasicProvider project users  AuthLDAPMAxSubGroupDepth 10 AuthLDAPSubGroupAttribute member AuthLDAPSubGroupClass Group AuthLDAPGroupAttribute member AuthLDAPGroupAttributeIsDN on Require test Options Indexes FollowSymLinks MultiViews  Order Deny,Allow  &lt;/Location&gt;   My active Directory Details are:  test.tc | |--(CN)Users--(CN)test | |--(OU)Projects--(OU)Group1--(CN)Group1    This are my Details in my active Directory. (CN)test is the main Group and (CN)Group1 are nested in (CN)test.  Additionally i tried: Require ldap-filter memberof:1.2.840.113556.1.4.1941:=CN=test,CN=Users,dc=test,dc=tc  unfortunately dont work :(
I've working LDAP authentication with the following setup   AuthName            "whatever"  AuthType            Basic  AuthBasicProvider   ldap  AuthLDAPUrl         "ldap://server/OU=SBSUsers,OU=Users,OU=MyBusiness,DC=company,DC=local?sAMAccountName?sub?(objectClass=*)"  Require ldap-group  CN=MySpecificGroup,OU=Security Groups,OU=MyBusiness,DC=company,DC=local   This works, however I've to put all users I want to authenticate into MySpecificGroup. But on LDAP server I've configured that MySpecificGroup also contains the group MyOtherGroup with another list of users.  But those users in MyOtherGroup are not authenticated, I've to manually add them all to MySpecificGroup and basically can't use the nested grouping. I'm using Windows SBS 2003.  Is there a way to configure Apache LDAP to do this? Or is there a problem with possible infinite recursion and thus not allowed?
Convert IEnumerable to DataTable Dihedral group - elements of order $2$ Conditional expectation of $\mathbb{E}(X - Y | (X, Y)\in\mathcal{A})$ Given two independent random variables $X \sim \mathcal{U}[-1,5]$ and $Y \sim \mathcal{U}[-5,5]$, what is $$\mathbb{E}\{Y - X | X \le 1, Y &gt; X, Y \in [-1,1] \}\,?$$  I managed to compute the respective probability   $$ \mathbb{P}\{ X \le 1, Y &gt; X, Y \in [-1,1] \} = \mathbb{P}(X \le 1) \mathbb{P}(Y &gt; X) \mathbb{P}(Y \in [-1,1]) = 1/3 * 1/2 * 1/5 = 1/30$$  How do I continue from there? I have recently purchased a hybrid bike with suspension (not sure if that is relevant to this question). It came with two pieces of plastic. Any ideas what they may be for? How do I clear command prompts in minecraft? $n$ balls are thrown randomly into $k$ bins - how many are empty? A large number of variants of this question were already asked here, including these - , , which are close, but none seem to answer my question. Assume that $n$ balls are thrown randomly and independently into $k$ bins.  What is the probability of finding $x$ empty bins? What is the expectation of the number of empty bins? Change the Ubuntu program that runs when a command can't be found Who is responsible for defining a site logo? I mean, there are moderators of the site that define it, or stackexchange defines it? Why can't I find any manpages? I'm working on a Power8 server running Ubuntu 16.04.2 LTS:  $ uname -a     Linux power 4.4.0-75-generic #96-Ubuntu SMP Thu Apr 20 09:55:30 UTC 2017 ppc64le ppc64le ppc64le GNU/Linux  $ cat /etc/lsb-release DISTRIB_ID=Ubuntu DISTRIB_RELEASE=16.04 DISTRIB_CODENAME=xenial DISTRIB_DESCRIPTION="Ubuntu 16.04.2 LTS"   None of the usual manpages appear to be installed. Even a simple command like:  man man   returns   No manual entry for man See 'man 7 undocumented' for help when manual pages are not available.   This goes for a variety of other tools, like ls, grep, etc. and library functions like usleep, printf, and so on.  I've checked that at least some manpages are actually installed:  $ dpkg -l | grep -i manpages ii  manpages                           4.04-2                                     all          Manual pages about using a GNU/Linux system ii  manpages-dev                       4.04-2                                     all          Manual pages about using GNU/Linux for development ii  manpages-posix                     2013a-1                                    all          Manual pages about using POSIX system ii  manpages-posix-dev                 2013a-1                                    all          Manual pages about using a POSIX system for development   Am I missing something? Is this specific to the ppc64le architecture? Or is there something else I can/should install to access these manpages?  Update: As requested, I ran sudo mandb. The result was:  0 man subdirectories contained newer manual pages. 0 manual pages were added. 0 stray cats were added. 2 old database entries were purged.   There were no changes to man man and other such commands.  Additionally, the output of manpath was:  $ manpath -g /usr/man:/usr/share/man:/usr/local/man:/usr/local/share/man:/usr/X11R6/man:/opt/man $ manpath -c /var/cache/man/oldlocal:/var/cache/man/local:/var/cache/man Note: This was posted when I was starting out C#. With 2014 knowledge, I can truly say that auto-properties are among the best things that ever happened to the C# language.  I am used to create my properties in C# using a private and a public field:  private string title; public string Title {     get { return title;  }     set { title = value;  } }   Now, with  3.0, we got auto-properties:  public string Title { get; set; }   I know this is more a philosophical/subjective questions, but is there any reason to use these auto-properties except from saving five lines of code for each field? My personal gripe is that those properties are hiding stuff from me, and I am not a big fan of black magic.  In fact, the hidden private field does not even show up in the debugger, which is OK given the fact that the get/set functions do nothing. But when I want to actually implement some getter/setter logic, I have to use the private/public pair anyway.  I see the benefit that I save a lot of code (one vs six lines) without losing the ability to change the getter/setter logic later, but then again I can already do that by simply declaring a public field "Public string Title" without the need of the { get; set; } block, thus even saving more code.  So, what am I missing here? Why would anyone actually want to use auto-properties? How to calculate last four digits of $2^{2017}$? can u suggest me any short trick of solving these kind of problems. How to find last four digits of any number raised to some power ? What are the differences between 32-bit and 64-bit, and which should I choose? What is the difference between 32-bit and 64-bit Ubuntu? I've heard the 64-bit platform performs better and can detect more than 4GB of RAM. Also, while some apps haven't ported to 64-bit yet, ia32-libs lets a 64-bit machine run them.  If so, why not promote 64-bit over 32-bit? Why does $(g^b \bmod m)^a \bmod m = (g^a \bmod m)^b \bmod m$? I have been trying to understand why the diffie hellman key exchange algorithm works, specifically why the two exponents can be swapped in it without the result changing.   So my specific question is why:  (g^b mod m)^a mod m  = (g^a mod m)^b mod m  I am interested in the reasoning/proof/explanation behind why it is true.    Thank you A known identity of binomial coefficients is that $$ \sum_i\binom{m}{i}\binom{n}{j-i}=\binom{m+n}{j}. $$ Is there a combinatorial proof/explanation of why it holds? Thanks. Why is the ##UserID## parameter not populated in Data Explorer anymore? Environment I'm logging in using the OpenID from  and using Chrome 31.0.1650.57 m if that matters. Steps to reproduce: Log in to  and , for example, like: DECLARE @MyUserID INT = ##UserID:int##  SELECT TOP 1     Id AS [Post Link],     Score AS [Score],     CreationDate AS [Creation Date] FROM     Posts WHERE     OwnerUserId = @MyUserID AND     PostTypeId IN (2, 3) ORDER BY     CreationDate DESC  Then press the Run Query button and see if the UserID field is filled with your own user ID like shown in the below screenshot:  Question: Did something changed on the ##UserID## parameter (for example, that it's not supported anymore)?  If so, then there is an outdated  paragraph about it (What's the point of logging in). If not, it is a bug which is there about three days (I've been waiting since I noticed that you were going to do some changes to Data Explorer, but it remains there, hence my question). I have a code that prints a table with 2 rows. I want to keep format of it and change 2 rows into 3.   \documentclass[conference]{IEEEtran}  \usepackage{pgfplots} \usepackage{siunitx} \usepackage{multirow} \begin{document}  \begin{table}[h] \caption{Family data set results} \label{tbl::Fam} \centering \begin{tabular}{|l|l|c|c|c!{\vrule width 2pt}l|l|c|c|c|} %\noalign{\hrule height 2pt} \hline \textbf{Column}&amp;\textbf{Algorithm}&amp;\textbf{min}&amp;\textbf{max}&amp;\textbf{std}l&amp;\textbf{Column}&amp;\textbf{Algorithm}&amp;\textbf{min}&amp;\textbf{max}&amp;\textbf{std}\\\hline \multirow{2}{*}{age}&amp;Original&amp;9&amp;2.8&amp;100&amp;\multirow{2}{*}{employer\_type}&amp;Original&amp;13&amp;2&amp;10\\ \cline{2-5} \cline{7-10}&amp;PrivBayes&amp;2&amp;95&amp;96&amp;&amp;PrivBayes&amp;2&amp;100&amp;100\\\hline \multirow{2}{*}{education\_level}&amp;Original&amp;7&amp;2&amp;98&amp;\multirow{2}{*}{marital\_status}&amp;Original&amp;10&amp;2&amp;100\\ \cline{2-5} \cline{7-10}&amp;PrivBayes&amp;2&amp;6&amp;96&amp;&amp;PrivBayes&amp;2&amp;6&amp;100\\\hline \hline %\noalign{\hrule height 2pt} \end{tabular} \end{table}  \end{document}   In this picture, I have 2 algorithms {Original, PrivBayes}. I want to change 2 algorithms into 3 algorithms with keeping the format of table. Can you please help me to do it? Which word to use when we ask for help?  Some conditions:     We know that the person asked is able to do it. We don't know if the person asked is able to do it. Terence Tao, Analysis I, Ex. 5.5.2: Entry point needed How to upgrade Ubuntu from an ISO image I'm using Ubuntu 10.04 now and want to Upgrade to Ubuntu 11.04. The problem is my net connection is very slow and I can not do a network upgrade from the "Updates Manager".  So, is there a way that I can download the Ubuntu upgrade as an bootable CD image and upgrade from it? Why not always present logistic regression estimates in the response scale (probablity)? There's a lot of discussion in epidemiology around the relative merits of odds ratios vs risk ratios. Proponents of the former cite the mathematical qualities of odds (not constrained to be between 0 and 1) and their suitability for examining common outcomes. Proponents of the latter believe that RR's are often more interpretable, and match how clinicians and the public tend to think. Some have suggested methods to model risk ratios directly (in multivariable models). For instance, the log binomial model and poisson regression with robust standard errors. What I don't understand is - why don't we just fit the model using standard logistic regression and perform the inverse logit transformation on the fitted estimates? For instance, lets say we are trying to predict coronary heart disease using BMI (exposure) and age (confounder). We could fit the model and estimate the odds of CHD across the range of values of BMI (adjusted for age), according to the model. We then take the inverse-logit of those fitted odds to transform them onto the probability scale. Seemingly this way we now have an idea of the risk of the outcome across all values of the exposure, which we can plot or otherwise describe. But i've never seen this method recommended. Which makes me think there must be a conceptual issue with it?? p.s. lets assume we are performing a cross-sectional or cohort study (not a case-control study).