Is it possible to configure Keychain to share passwords in Chrome on OS X Catalina? The problem I face is that some websites function better in Chrome than Safari and I would like to be able to switch between the two browsers and use auto-logins in each. Currently I can do this in Safari if use Keychain and Password autocomplete. I would like to be able to do same or similar in Chrome.
Background:   Story: A colleague of mine told me about  and it seems good to me. I am always trying to use tools which Mac OS X itself gives me, so I've given the Keychain a try. It seems satisfying, but I don't know how to tell Google Chrome to use my specific keychain. I need it to separate saved stuff for work and for private (syncing private to work, but separated from work data).  Stuff:   Google Chrome 21.0.1180.57 (Fully updated) Mac OS X Lion (Fully updated) OS X Mountain Lion (Fully updated)   Question:  How do I tell to Chrome to use a specific keychain and to save data from/to this keychain?
Are there any disadvantages to always using nvarchar(MAX)? What is a Generic Handler in asp.net and its use? Get lists of dependent picklist options in Apex Google's CDN is nice, but it's not 100% reliable for all users. It occasionally fails to load for me. Other users , and some .  It's one more possible point of failure. It would be preferable if Stack Exchange didn't depend on it.  If you don't want to stop using it, consider adding a fallback if it fails to load. Something like this:  &lt;script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"&gt;&lt;/script&gt; &lt;script&gt;   if (!window.jQuery) {     document.write('&lt;script src="https://cdn.sstatic.net/stackoverflow/content/js/jquery-1.7.1.min.js"&gt;&lt;\/script&gt;');   } &lt;/script&gt; Somebody asked me this question in a job interview and I replied that their joint distribution is always Gaussian. I thought that I can always write a bivariate Gaussian with their means and variance and covariances. I am wondering if there can be a case for which the joint probability of two Gaussians is not Gaussian? Compute approximately the probability that more than 50 of the observations of the random sample are less than 3. Let $X_1,X_2,...,X_n$ be a random sample of size $n = 72$ from a distribution with probability density function $f(x) =\begin{cases} 1/x^2,&amp; 1 &lt; x &lt; infinity\\0,&amp;\text{otherwise}\end{cases}$ Compute approximately the probability that more than $50$ of the ob- servations of the random sample are less than $3$. Firstly, I apologise if my thinking is completely incorrect - I am by no means a physicist (yet!), I have included layman illustrations to hopefully assist in explaining my thinking.  I am imagining the big bang to be, for lack of a better word, an explosion, thus the universe to be progressively expanding:    Therefore, to me it seems logical to suggest that there is an edge.  If this is the case, then is it reasonable to suggest that explosion + edge = 'bright edge'? Where light projects in all directions at the edge, not just outwards into the 'nothingness'.     So, this brings me to my question: why, when someone looks deeply enough 'at the edge' do they see an absence of light?   Again, apologies if I'm jumping to irrational conclusions &amp; am way off. How would I implement a binary search using just an array? Empty vector menu in QGIS on PC with French as default language verifying an incorrect integrating factor I was doing some practice problems that my professor had sent us and I have not been able to figure out one of them. The given equation is:  $-y^2dx +x^2dy = 0$  He then asks us to verify that:  $ u(x, y) = \frac{1}{(x-y)^2}$  is an integrating factor.   I multiplied through to get:  $\frac{-y^2}{(x-y)^2}dx + \frac{x^2}{(x-y)^2}dy = 0$   However, the partial derivatives of these do not equal each other so I am a bit confused... Outlook, POP and PST handling Essentially I have a client who is on hosted exchange and have decided to use POP3 to download the mail (I don't know why they don't use .OST's but anyway), they rebuilt the machine and backed up their .PST file. Now their Outlook was configured to keep mail downloaded on the server for 14days.  Essentially their current PST is fairly complex, many folders and sub folders and so on. So what is the best way to handle it really - create a new Outlook profile on the rebuilt machine and download the mail via POP into a new .PST then just recreate the folders in the new pst and drag and drop the mail via attaching the backed up .pst, recreating the folders etc?  But is their an easier way to do this, maybe pointing the new account to use the original PST, but then that would download all the mail again from the server to that .PST file.  Any ideas on the best way to handle POP3 account rebuilds from scratch when you have a backed up PST? MariaDB won't start on Ubuntu: Can't lock aria control file Today i was at a arena. A player from the red team put a Grimer there, which causes my game to crash every time I select the arena (Samsung Galaxy S4 mini). All other pokemons i saw so far did not make any problems  I searched a bit, and found out that this is a known bug, e.G.:   Now my question, is there a way to battle in the arena or even select it without crashing my app? Some option like "hide model in arena",changing some smartphone-settings or another trick? Or do i have to wait till a bugifx from niantec comes or somebody else which has a handy which dont crashes with grimer clears the arena, before selecting the arena?  Because somebody could place him there i guess this is only a bug for specific smartphones, but this could be used to exclude a lot of players from arenafighting by only placing grimers in arenas to let the game crash for them, are there some official notes about this from niantec or how to avoid the crash? How do I find this conditional expectation? Best way to store currency values in C++ As small as it may be, does every 'thing' have a gravitational pull?  That is, something with mass or energy. No matter how obsolete or negligible it may be, is it there? If so, how is it calculated? What does 'it' affect? Contradicting Fubini's theorem I have a function defined as follows: $f(x,y)= \dfrac{x^2-y^2}{\left(x^2+y^2\right)^2}$, if $(x,y)\neq (0, 0)$ and $f(x,y)=0$ if $(x,y)=(0,0)$.  Now, $$\int_0^1\int_0^1 f(x,y)\,\text{d}x~\text{d}y=-\frac{\pi}{4}$$ and $$\int_0^1\int_0^1 f(x,y)\,\text{d}y~\text{d}x=\frac{\pi}{4}.$$   The question I have is this: why does this not contradict Fubini's theorem?    thanks. dimension of a subspace spanned by two subspaces If $M$ and $ N$ be the subspaces of a vector space $V$ then prove that  $(\dim M) + (\dim N) = (\dim M+N) + (\dim M \cap N)$. Can 'home' be an adjective as well as an adverb or a noun? All the dictionaries I've consulted say that 'home' is an adverb and a noun, depending on context. For example:  (1) He went home. [adverb] (2) He is at home. [noun]  Also, there's  that seemingly resolves the issue of why 'home' sometimes should be analyzed as an adverb. But what about this example?  (3) I can find my way home.  Can you also say that home in (3) is an adverb? It seems to me that home in (3) cannot be an adverb, because I think it functions as a complement of the noun way and that my way home as a whole is a noun phrase. Even if we accept John Lawler's analysis in the above quoted answer of considering home &quot;one of those idiomatic locative nouns that are allowed to drop determiners and occasionally even prepositions,&quot; we cannot say home in (3) is an example of &quot;how a noun can be used as an adverb&quot;, because (3) can be analyzed as John Lawler suggests:  (3') I can find my way (to my) home.  Here, to my home is not an adverbial prepositional phrase but an adjectival prepositional phrase that acts as a complement of the noun way. So, to take what John Lawler said and adapt it to (3), &quot;what it is is an [adjectival] prepositional phrase that has been stripped of its prepositions and determiners, leaving only a naked noun to stand for the whole phrase. That's how a noun can be used as an [adjective].&quot; Now, does this mean we should call home a noun, an adverb, or an adjective, depending on context? Javascript mechanism to autoscroll to the bottom of a growing page?