So I want to store full Ubuntu on a flash drive so when I plug in the flash drive in a computer with the BIOS edited full Ubuntu starts up. I already have a bootable USB 32GB with and i know how to start it. I don't want the live version. I don't have too much experience with Linux.
Every issue of Ubuntu LTS since 8.04, I have made a Full install of Ubuntu to USB flash drive, and recorded each step..  This has been intended to make a guide/check list for users wishing to create Full install bootable flash drives.  Previously the procedure worked for BIOS boot if created in BIOS and for UEFI boot if created in UEFI.  This year for 20.04 the instructions should work for both creating and running the drive booted from either BIOS or UEFI.  The question is:  How to Create a Full Install of Ubuntu to USB device with Step by Step instructions that work in either BIOS or UEFI.
Split Data Based on Year in a Visual force Page PDF "Reality" of length contraction in SR Showing that if a subset of a complete metric space is closed, it is also complete Let $(X, d(x,y))$ be a complete metric space. Prove that if $A\subseteq X$ is a closed set, then $A$ is also complete.  My attempt: I tried to prove that every Cauchy sequence $(b_n)$ of points of $A$ converges to a point $b\in A$. However could not figure out the exit way. Maybe I am on the wrong track. Could you please help me?  edit: More from my attempt:  Suppose $A$ is a closed set and let $(x_n)$ be a sequence of points $A$ such that $\lim_n x_n\to b$.  Suppose now that $A$ has the property that $b\in A$, whenever $x_n$ converges to $b$. We know that every element of $x_n$ which is convergent in $X$ also converges to a point in $A$. Since $x_n$ is a Cauchy sequence in $A$, it must converge to a point $y\in A$. But the limit of a convergent sequence is unique.   Take $x\in A$ and select an appropriate $n$, which enables $x_n$ to converge to a point $x$ in $X$. Since the limit is unique, it must follow that $x=y$. Thus $x\in A$ and $A$ is closed.   If $A$ is a closed subset of $X$, then any Cauchy sequence of a point in $A$ is convergent in $X$ and hence converges to a point in $A$. Thus $A$ is complete. I am installing an overhead automatic garage door opener. My only power source close to where I will be hanging the motor is an overhead light socket that is operated by a switch on the wall next to the house entry door.   I wanted to know if it is possible to rewire the light socket with a standard electrical plug outlet AND to remove the switch &amp; wire it to provide constant power to the new outlet. The overhead light is on my 15A garage GFI circuit &amp; the opener lists 120V/6A as its power requirements.  I live in the US. Overloading getter and setter causes a stack overflow in C# This is Spivak's Calculus on Manifolds ex. 2-25, he says     Define $f:\mathbb{R}\to \mathbb{R}$ by $f(x) =  \left\lbrace   \begin{array}{l}      e^{-x^{-2}} &amp;\text{ if } x \neq 0\\      0 &amp;\text{ otherwise } \\   \end{array}   \right.$. Show that $f$ is $C^{\infty}$ anf $f^{(i)}(0)=0\; \forall i$.   I haven't found a way to get a general solution. I only managed to prove:  $(1)$ $f$ is continuous at $0$.  This follows from $f(0)=0$ and $\lim_{x\to0} f(x)=\lim_{x\to 0}e^{-x^{-2}}=\lim_{x\to 0}\displaystyle\frac{1}{e^{1/x^2}}=0$ since $\displaystyle\frac{1}{x^2}\to+\infty$ if $x\to 0$ then $e^{1/x^2}\to+\infty$ if $x\to 0$, which means that $\displaystyle\frac{1}{e^{1/x^2}}\to 0$ if $x\to 0$ .  $(2)$$f'(0)=0$.  I got this by calculating the limit $f'(0)=\lim_{h\to 0}\displaystyle\frac{f(0+h)-f(0)}{h}=\lim_{h\to 0}\displaystyle\frac{f(h)}{h}=\lim_{h\to 0}\displaystyle\frac{e^{-h^{-2}}}{h}=\lim_{h\to 0}\displaystyle\frac{1/h}{e^{h^{-2}}}$.  The last one follows from L'Hôpital: $\lim_{h\to 0}\displaystyle\frac{\frac{d}{dh}(1/h)}{\frac{d}{dh}(e^{h^{-2}})}=\lim_{h\to 0}\displaystyle\frac{(-1/h^2)}{(e^{h^{-2}})(-2h^{-3})}=\lim_{h\to 0}\displaystyle\frac{h}{2e^{h^{-2}}}=\displaystyle\frac{1}{2}\left(\lim_{h\to 0}\displaystyle\frac{1}{e^{h^{-2}}}\right)\left(\lim_{h\to 0} h\right) = 0$.  $(3)$ $f''(0)=0$  I found that $\displaystyle\frac{df}{dx} =  \left\lbrace   \begin{array}{l}      2x^{-3}e^{-x^{-2}} &amp;\text{ if } x \neq 0\\      0 &amp;\text{ otherwise } \\   \end{array}   \right.$, then  I can get $f''(0)$ computing the limit $\lim_{h\to 0}\displaystyle\frac{f'(0+h)-f'(0)}{h} = \lim_{h\to 0}\displaystyle\frac{f'(h)}{h} = \lim_{h\to 0}\displaystyle\frac{2e^{-h^{-2}}}{h^4}= 2\lim_{h\to 0}\displaystyle\frac{1/h^4}{e^{h^{-2}}}=-2\lim_{h\to 0}\displaystyle\frac{-4h^{-5}}{-2h^{-3}e^{h^{-2}}}\\=4\lim_{h\to 0}\displaystyle\frac{1}{h^2e^{h^{-2}}}=4\lim_{h\to 0}\displaystyle\frac{h^{-2}}{e^{h^{-2}}})=-4\lim_{h\to 0}\displaystyle\frac{-2h^{-3}}{e^{h^{-2}}(-2h^{-3})}=-4\lim_{h\to 0}\displaystyle\frac{1}{e^{h^{-2}}}=0$, after using L'Hôpital twice.  But still I don't have a clue to prove that $f^{(i)}(0)=0$ for every $i$. One of the ideas I managed was to find a general form for $f^{(i)}$ but after I got $f'$ doesn't seem possible to do so considering that I would have to apply the product rule each time. Show intersection of two algebras are not a $\sigma$-algebra I have the following question:    $\textbf{Question}:$ Let $\mathcal{F}_1$ and $\mathcal{F}_2$ be two algebras. Is $\mathcal{F}_1 \cap \mathcal{F}_2$ a $\sigma$-algebra?  I believe the answer is no. I know the definition of an algebra and the definition of $\sigma$-algebra.    I'm assuming I need to show that the intersection of the finite unions of each algebra is finite, but then I get stuck trying to work out how to show it is not a $\sigma$-algebra.  All help is appreciated.  Many thanks, John Unable to play MP3 or MP4 files in Rhythmbox or Movie Player I am unable to play any MP3 or MP4 files. When I try to open any MP3 or MP4 file, both show an error, a Python 2.7 plug-in is required. Potential difference across a zero resistance wire I am running Ubuntu 20.04 an  with an NVIDIA GeForce GTX 1660TI GPU. According to , the driver version for this GPU is 430. When I first installed Ubuntu, I installed 440. I'm now trying to correct that and install 430. I ran sudo apt-get install nvidia-driver-430, and then did a reboot. When I examined nvidia-smi, though, it still showed the 440: +-----------------------------------------------------------------------------+ | NVIDIA-SMI 440.100      Driver Version: 440.100      CUDA Version: 10.2     | |-------------------------------+----------------------+----------------------+ | GPU  Name        Persistence-M| Bus-Id        Disp.A | Volatile Uncorr. ECC | | Fan  Temp  Perf  Pwr:Usage/Cap|         Memory-Usage | GPU-Util  Compute M. | |===============================+======================+======================| |   0  GeForce GTX 166...  Off  | 00000000:01:00.0 Off |                  N/A | | N/A   55C    P0     9W /  N/A |      0MiB /  5944MiB |      0%      Default | +-------------------------------+----------------------+----------------------+  What is the appropriate way of updating this driver? There is (there's) vs.There are What are the roots of the creeping usage of "there's" for both singular and plural predicates? (This seems to be more common in spoken English.) I have 2 theories.  Perhaps it is because spoken communication our society is becoming less formal by the day. Or perhaps it is a reflection of speakers of other languages having increasing contact with native English speakers.  I am aware of German  "es gibt" and Spanish  "hay" constructions. Please comment.  3/06/14 I ran a couple of Google Ngrams and was surprised to find a greater rise in the use of "there's" in English fiction than in general English language books, since the turn of the century.  This would seem to support my contention that informality is behind the shift. JDBC-ODBC Bridge queries to Access fail when they have accented characters Negative integer division surprising result Is a passport needed when flying within Mexico as a U.S permanent resident? I have an ASUS E402S laptop with Ubuntu 64-bit 16.04 LTS installed. The main problem is that the OS does recognize the touchpad with basic functions, but additional options such as scrolling through pages or between open applications are non-existent.  This is what my xinput result is showing:  ⎡ Virtual core pointer                      id=2    [master pointer  (3)] ⎜   ↳ Virtual core XTEST pointer                id=4    [slave  pointer  (2)] ⎜   ↳ Logitech USB Receiver                     id=9    [slave  pointer  (2)] ⎜   ↳ Logitech USB Receiver                     id=10   [slave  pointer  (2)] ⎜   ↳ FTE1000:00 0B05:0101                      id=12   [slave  pointer  (2)] ⎣ Virtual core keyboard                     id=3    [master keyboard (2)]     ↳ Virtual core XTEST keyboard               id=5    [slave  keyboard (3)]     ↳ Power Button                              id=6    [slave  keyboard (3)]     ↳ Video Bus                                 id=7    [slave  keyboard (3)]     ↳ Sleep Button                              id=8    [slave  keyboard (3)]     ↳ USB2.0 VGA UVC WebCam                     id=11   [slave  keyboard (3)]     ↳ Asus WMI hotkeys                          id=13   [slave  keyboard (3)]     ↳ AT Translated Set 2 keyboard              id=14   [slave  keyboard (3)]   Apparently my touchpad's type is not shown in the list. What are the possible solutions to fix this issue? What's an intuitive way to think about the determinant? In my linear algebra class, we just talked about determinants. So far I’ve been understanding the material okay, but now I’m very confused. I get that when the determinant is zero, the matrix doesn’t have an inverse. I can find the determinant of a $2\times 2$ matrix by the formula. Our teacher showed us how to compute the determinant of an $n \times n$ matrix by breaking it up into the determinants of smaller matrices. Apparently there is a way by summing over a bunch of permutations. But the notation is really hard for me and I don’t really know what’s going on with them anymore. Can someone help me figure out what a determinant is, intuitively, and how all those definitions of it are related? I'm interested in quantum mechanics book that uses high level mathematics (not only the usual functional analysis and the theory of generalised functions but the theory of pseudodifferential operators etc, certainly the modern mathematics). If there isn't something similar please give me a reference to the book that is strictly supported by mathematics (given a set of mathematically descripted axioms author develops the theory using mathematics as a main tool). Given Newton's third law, why are things capable of moving? Let $S$ and $T$ be finite non-empty sets such that $|S| = |T|$. Show that the function $f : S\to T$ is onto if and only if it is one-to-one. This is a recent homework bonus question assigned in my Proofs and Conjectures class. It (evidently) includes and evaluates our understanding of elementary-set theory and how to determine and prove that the function f is onto and one-to-one. I haven't been able to really grasp firmly how it is we do this. Help would be much appreciate, thank you. My son has been playing Minecraft on our home computer for a couple of years now.  He just got an iPad Mini 2 for his birthday. Is it possible to transfer his game and his saves onto his iPad Mini 2?