(OS X) How do I bind "enter" to a combination of keys at the left side of my keyboard? I would like to bind "enter" to a combination of keys at the left side of my keyboard. How do I go about doing this? (I would like the combination of keys to be Ctrl+Shift+Q, or maybe there is a better one out there?). It's sort of becoming tedious to reach around or let go of the mouse from my right hand whenever I enter something.
How can I set custom key bindings and key macros on Mac OS X? I recently upgraded to Snow Leopard, from Leopard and I was using an awesome app called  that let you remap your keys, set scripts/macros and even had repeat functionality.   However, this app doesn't seem to be in active development anymore, and 10.6 broke the ability to bind certain modifier keys (Shift) with other keys.   I totally miss things like Shift+Insert for paste (Linux/Windows), setting Ctrl+Shift+Esc for Activity Monitor, and Ctrl+Alt+Del for the login window.   So, how can I achieve this instead?
Using Windows DLL from Linux Custom first page with fancyhdr I'm using the package fancyhdr to format my footers and headers, with my name in the header and a n of m pages format for the footer. Like so:  \pagestyle{fancy} \fancyhf{} % clear all header and footer fields \fancyhead[C]{Name} \fancyfoot[C]{\footnotesize Page \thepage\ of \pageref{LastPage}}   By default, the fancy page style only affects the pages after the first page. I know I can set the first page to the fancy page style using \thispagestyle, but I only want the first page to use the footer, not the header. Is there a way to create a custom style that just the first page will use? Are the LIGO observations proof of a black hole merger, and what happened to the black holes? Math people:  The title is the question. I am convinced that uncountable sets exist, thanks to Cantor's diagonal proof.  It is not intuitively clear to me that uncountable ordinals or cardinals should exist.  What axioms of set theory are needed to accept their existence?  I think I have read here that the Axiom of Choice is not necessary.  I am reluctant to accept as "true" any theorems that rely on the Axiom of Choice.  EDIT: This question may be a duplicate: I just found  .  I apologize if this is so. How do you rotate a two dimensional array? Inspired by , say you have a 4x4 two dimensional array, write a function that rotates it 90 degrees. Raymond links to a solution in pseudo code, but I'd like to see some real world stuff.  [1][2][3][4] [5][6][7][8] [9][0][1][2] [3][4][5][6]   Becomes:  [3][9][5][1] [4][0][6][2] [5][1][7][3] [6][2][8][4]   Update: Nick's answer is the most straightforward, but is there a way to do it better than n^2? What if the matrix was 10000x10000? Launchers for installed snap applications (including Ubuntu Software) disappeared after installing GNOME Software I have some doubts regarding net run rate in the ongoing ICC world twenty 20 2014 event.It takes a while to read so please don't hesitate and give me a solution regarding this.    My doubt is that in match 12 of world twenty 20 2014(In Group Stage Last Match on march 21 2014) () Wesley Barresi of Netherlands hit a six when the team score was 187 while chasing Ireland score of 189, That take Netherlands score to 193.  If that is the case in match 17 between India and West Indies in match of super10 group (in ICC world twenty 20 2014 on march 23 2014) () while Suresh Raina (India) hit a four when the team score was 129 while chasing West Indies score of 129,That takes India Only To 130. why Only One run is added to the score in this match(match 17 on march 23 2014) while 6 runs are added to the score in match 12 on march 21 2014.  I don't understand the strategy behind this.Because if India's Score is taken as 133 then India's net run rate as of now(24 march 2014) will be 0.442(Runs Scored For 264 in 38.1 overs ) But Now it is only 0.383(Runs Scored For 261 in 38.1 overs ).As the net run rate plays an important role in the tournaments like this i am not very happy with this.  As being an Indian Fan now a days I look a lot in to net run rate as it has eliminated India in many tournaments including last ICC world twenty 20 2012.  Is There Any One who can clarify my doubts regarding the net run rate as i want to be sure of what was happening? Code coverage for wrapper class is 0% I understand there is a method for solving simultaneous modular equations. For example; $$x = 2 \mod{3}$$ $$x = 3 \mod{5}$$ $$x = 2 \mod{7}$$ We find numbers equal to the product of every given modulo except one of them - giving $5 \cdot 7$, $3 \cdot 7$ and $3 \cdot 5$. We then find the multiplicative inverses of these numbers with modulo equal to the number missing from the product. The numbers found are then 2, 1 and 1 in this case. The value of x is then given by: $$x = 2 \cdot (5 \cdot 7) \cdot 2 + 3 \cdot (3 \cdot 7) \cdot 1 + 2 \cdot (3 \cdot 5) \cdot 1 = 233 = 23 \mod{3\cdot5\cdot7}$$  But I do not understand how this method correctly gives the value of $x$. I understand that the Chinese remainder theorem proves that there is a unique value of $0\le x \lt 3\cdot5\cdot7 \mod{3\cdot5\cdot7}$ but can someone please explain why this method finds this value of x? Uniform Scattering with vector This is really two questions.   Is there a definition of the principal $n$th root of a complex number? I can't find it anywhere. Presumably, the usual definition is $[r\exp(i\theta)]^{1/n} = r^{1/n}\exp(i\theta/n)$ for $\theta \in [0,2\pi)$, but I have yet to see this anywhere. Is this because it has bad properties? For instance, according to this definition is it true that for all complex $z$ it holds that $(z^{1/a})^b = (z^b)^{1/a}$? Do you add Proficiency bonus AND the stat modifier to skill rolls? I know this basic knowledge, but I seemed to have missed this info in the player's manual.  Say someone makes an stealth check: do I add their Dexterity modifier and their proficiency bonus in Stealth to the roll? In other words, does the Dexterity modifier apply to all Dex-related skills, including ones with a proficiency? What to do if a referee plagiarises the result after rejecting a paper? Considering that sound can't travel through vacuum. How would one throw an unwilling creature? My bugbear barbarian, who can lift about double the weight of a wolf, wanted to throw the wolf at a second wolf. How would we go about doing that given existing rules options? How can I best describe "making a new discovery"? How to get class object's name as a string in Javascript? Inner border over images with CSS? How to draw Venn diagrams (especially: complements) in LaTeX With me going it alone in development I only have limited resources at my disposal i.e one pc with which I develop and test the game. so I only know for certain my game works with that setup.  What options have I got in testing the game on the many different hardware/operating system combinations? Its a windows desktop game.