I have Ubuntu precise running on a VPS (server). I am connected with SSH and would like to upgrade to Ubuntu trusty.  I do not want the newest release. Changing /etc/update-manager/release-upgrades to "normal" causes the do-release-upgrade shell script to select the next release (12.10), not 13.x. Selecting LTS goes straight to 14.x. How do I specify 13.x release?  Would I have to manually change the /apt/sources.list to point to trusty and then do a dist-upgrade? I prefer to do it with the do-release-upgrade script, but can't figure out how.
I am currently using Ubuntu 10.04. I know there is a 10.10 release, but can I upgrade directly to 11.04? Could you walk me through the steps please?
Western Digital drive making beeping noise Limit of $L^p$ norm when $p\to0$ Let ($\Omega$, $\cal{F}$, $\mu$) be a probability space and $f\in L^1(\Omega)$. Prove that  $$\displaystyle\lim_{p\to 0} \left[ \int_{\Omega}|f|^pd\mu \right]^{\frac{1}{p}}=\exp \left[ \int_{\Omega}\log|f| d\mu  \right],$$  where $\exp[-\infty]=0$. To simplify the problem, we may assume $\log|f|\in L^1(\Omega).$ Identify story: Overpopulation problem causes people to live one day a week This story is about a man that is able to live every day of the week, while everybody else has a single day of wakefulness assigned to them. Due to overpopulation, each human spends 6 out of 7 days of the week in stasis, and has jobs assigned to them in daily shifts. 1/7 of the population works on Monday. 1/7 works on Tuesday, &amp; so on. The main character has found away to circumvent the process and illegally live out his days consecutively by skipping the stasis program that is imposed on the general population and by working a different job everyday. Can somebody name this scifi story? I was having a discussion with a friend of mine about some normal group properties and then came up with the question "if G is not commutative, then is there always a subgroup that is not a normal subgroup?" It's probably more easy to solve this in the following form:$$\forall H \leq G : H  \lhd G \Rightarrow \forall a,b \in G : ab=ba$$ My question is, can anybody give a proof, or a counter-example (because I don't think it holds) of this theorem? Thanks! Question regarding use of low voltage high current outputs I see every day high voltage, high current; high voltage, low current. I rarely see low voltage, high current; why?  I know that I can take a high voltage, high current signal, send it through a step-down transformer and theoretically get a low voltage high current (with the same power output, of course), but I never see this done.  Can someone give me a reason as to why I wouldn't want a low-voltage high-current scenario? Does anyone know of a good way to set up some sort of parental controls so that one user account is subject to them, but not another?  A couple of friends of mine use Ubuntu and have kids (7 to 10 years old) who use the family computer. They'd like to have some blocking of adult sites. They're not going to supervise all the time, which I know might be ideal, but there we go. And they're not particularly technical, so they don't want to have to run scripts to turn the parental controls on and off regularly, but they can cope with having different accounts for different people. I haven't found a great way of doing this. I am pretty technical, so I'm happy to spend some time at the command line to set it up, but then it needs to just work.  Please don't just link to DansGuardian. If your answer doesn't address the different user account aspect, I will vote it down. If you want to talk about general parental controls that apply to all users then please start a new question - I'm sure that plenty of people would be interested in it, and I'll link to it from this question. In  it says that flagged comments can be handled automatically if flagged repeatedly (3 + (score / 3) flags = deletion). Which is great; mods are busy people.  In , the venerable Bill the Lizard says that if all comments on a post are obsolete, you can flag the post (or one of the comments) with a custom flag saying that they're all obsolete, and the mod can remove them with one fell swoop. Problem is, that requires a mod.  What should I do when some of the obsolete comments are mine? I can't flag my own comments, and I don't like raising custom flags if I can avoid it.  You're wondering why I don't just delete them. There are two scenarios where I don't, at least not immediately:   Someone has commented with incorrect information. In that situation, I reply to the comment telling them how they've got it wrong. (Sometimes, of course, they quite correctly reply telling me how I got it wrong, which is neither here nor there&nbsp;&mdash; we still end up with obsolete comments. :-) ) Frequently, they reply saying "you're right" but (near universally) leave the comment lying around. I can (and do) then comment again saying "Let's clean these up" and flag their comments as obsolete. But I can't flag mine. Nor do I want to remove mine while the incorrect comment is still there; it leaves a confusing situation for anyone coming to the post later. Someone has commented with correct information. In that situation, if appropriate (e.g., the post author isn't busily editing at the same time and I know enough to do it properly), I'll edit the comment into the post and reply with "You're right, edited that in." and flag their comment as obsolete. These are rarely removed by the commenter. And again I can't flag mine.   The first scenario is the more problematic, since I can go back 10-20 minutes later and remove my "edited that in" comment and there's no harm if their comment is still there.  I currently bookmark and check back periodically, but that's labor-intensive and I'd like a better way.  Ideally, I'd want to tie my comment to one I've flagged so that it's deleted automatically if the other one is (by flagging, or by the commenter). That's a fair bit of development, though, I'm guessing.  What should I do? Go with a custom flag saying "The conversation between X and me is now obsolete," even though that means dumping it on a mod? Ubuntu 17.10 Keyboard not working after login following upgrade from 17.04 (Gnome version) Excel automatic hyperlinks I want to detect when someone is building a lever, then replace it with another lever that has the canplaceon tag so it can be placed on a redstone_lamp  How can I clear the crafting item and replace it with one that has a canplaceon tag? Generalized Euler sum $\sum_{n=1}^\infty \frac{H_n}{n^q}$ I found the following formula   $$\sum_{n=1}^\infty \frac{H_n}{n^q}= \left(1+\frac{q}{2} \right)\zeta(q+1)-\frac{1}{2}\sum_{k=1}^{q-2}\zeta(k+1)\zeta(q-k)$$  and it is cited that Euler proved the formula above , but how ?  Do there exist other proofs ?  Can we have a general formula for the alternating form   $$\sum_{n=1}^\infty (-1)^{n+1}\frac{H_n}{n^q}$$ $\LaTeX$ and Mathematica Do images uploaded to imgur.com have any backup? Binary Bomb Phase 5 - lookup table translation -> string compare Draft mode for pgfplots I'm working on a fairly big document that has a lot of graphs of functions- so far it has around 200, by the end it will have around 1500. I use pgfplots for each graphic, and the functions are pretty basic: exponential, rational, polynomial, and trigonometric.  Once I am happy with each graph, I don't necessarily need to see it every time I compile, and would like to minimize compilation time for future drafts. Naturally, the document is already chopped up into chapter files, but each chapter contains around 100 figures.  Having studied the pgfplots documentation, I haven't found a draft mode, but I'm interested in knowing if one could be created.    I'm envisaging something similar to the draft mode of the graphicx package, in which graphics are not included, and blank boxes are put in their place.  Some things I've considered:   the  documentclass; but with about 1500 figures, wouldn't this mean over-modulization?  tikzexternalize, but this still requires an initial 'monster' compilation to get the images externalized before the draft option could be invoked   Here's a MWE to play with  \documentclass{article} \usepackage{pgfplots}  \begin{document}  \begin{tikzpicture}     \begin{axis}         \addplot {x^2};     \end{axis} \end{tikzpicture}  \end{document} Is the empty set a subset of itself? Let $f$ be a continuous function on a set $E$.  Is it always true that $f^{-1}(A)$ is always measurable if $A$ is measurable?  I say no.  We know that $\bar{\psi(x)}:=\frac{\phi(x)+x}{2}$ where $\phi$ is the Cantor (or Cantor-Lebesgue) function and $\bar{\psi}:[0,1] \rightarrow [0,1]$.  We know this function maps a measurable subset of $C$ (the Cantor set) into a non-measurable set $W$.  A few observations about $\bar{\psi(x)}$.  It is strictly increasing and continuous, so it has a continuous inverse $\bar{\psi(x)}^{-1}$.  Thus $\bar{\psi(x)}^{-1}(W)=c \subset C$; that is, $\bar{\psi(x)}^{-1}(W)$ is non-measurable, but c is.  Is this correct? So, I was just assaulted by a trio of fairly well armed thugs while walking out of Riften. Before attacking me, they informed me that they were 'here to teach me a lesson.'  After dispatching them in due course, I found this on the body of what I can only assume to be the leader, given his vastly superior armaments:   Orgnar is the innkeeper in Riverwood. Now, I admit, I've stolen a fair amount, but I pride myself on having never been caught. My total bounty to date is at zero. So, how did he figure out that I stole something, why is he taking the law into his own hands, and if I go back to Riverwood, am I going to get shanked? I'm trying to find a good way to print leading 0, such as 01001 for a . While the number would be stored as 1001, what is a good way to do it? I thought of using either case statements or if to figure out how many digits the number is and then convert it to an char array with extra 0's for printing, but I can't help but think there may be a way to do this with the printf format syntax that is eluding me. Let $U = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12\}$, and $f$ be a function from $U$ into $U$.   Finally, let $F : P(U) \to P(U)$ be the function defined by  $$F(X) = \{f(x) | x \in X\}$$  For instance, if $f(x) = 13 − x$, and $X = ${1, 3, 4, 7}, then $$F(X) = \{f(1), f(3), f(4), f(7)\} = \{12, 10, 9, 6\}$$  Show that $F(A−B)$ is not necessarily a subset of $F(A)−F(B)$.    I am having trouble showing an example. Let's say:  $A = \{1,3\} , B = \{2,3\}$  $F(A) = \{f(1),f(2)\} = \{12,11\}$  $F(B) =\{f(2),f(3)\} = \{11,10\}$  Now, $F(A-B) = \{12,10\}$  $F(A)-F(B) = \{12\}$.  Hence, $\{12,10\} \nsubseteq \{12\}$ &lt;-- hmm..  By definition if $A \nsubseteq B$, there exist an $x \in A$ such that $x \notin B$. From my example, we have $x=10 \in A $ but $\notin B$. Is that sufficient?     I'm confused between the difference of $F(A-B)$ and $F(A)-F(B)$.