I want to only use alt+tab to switch tabs, I consider the desktop a tab.  How would I enable switching to the desktop? I saw in this  that you need to change the option below, however it's nowhere to be seen in my settings menu.  Also there is this 5 year old . Windows version: 2004
In Windows 8, when Alt+Tab, the desktop would appear as an option to switch to at the end of the list of open programs (thus Alt-Shift-Tab helpfully took you right to the desktop).  In Windows 10 that desktop option is gone. Is there any way to get it back?  I know about Windows+D but Alt+Tab is just more convenient in my opinion. And  also has no desktop and is uglier.
What is the distribution of the sum of non i.i.d. gaussian variates? Is there a way to absolutely force a Log Out, Shut Down, or Restart with open tabs and unsaved documents? I could not find any relatively simple way to log out of a public use Mac quickly with many tabs open and unsaved document in the background without resorting to sudo shutdown -h now.  The reason I ask is that sometimes a user will have his/her account logged into the iMacs here at school and they would try to log off and then leave, thinking it has completed but the process is interrupted by Safari and Office apps, leaving their account, mounts, and websites still accessible to the next person who sits down.  Obviously a shortcut string would be nice instead of posting a note telling the person to type arcane things in a terminal. For example, just having them try to find Terminal.app is going to be a chore.  This doesn't seem to make sense because the user can just quit each app and click a few dialog boxes but unlike you and I to whom repeatedly pounding Command-Q while hitting the spacebar and D keys are probably second nature. The search parameter isanswered ignores acceptances The SE definition of "answered" question is: has an answer that is either accepted or has positive score. But the search parameter isanswered appears to ignore the "accepted" clause: when set to "no" it still returns questions with an accepted answer, as long as it has 0 score.    to reproduce the bug (unless meta effect kicks in and the answers get upvotes).     By the way, it seems that isanswered works only when is:question is present, but I'm not complaining about that... yet.   Also, this parameter is not listed on the , but I'm not complaining about that either... yet. Possible Duplicate:          I am always confused with the prepositions to use when indicating an event happening at a place. Should I use "at" or "in" or "on"?  For example:     We had our dinner at the McDonalds at/in the shopping centre at/on Sixth   Avenue.   The McDonalds restaurant is in the shopping centre. The shopping centre is located at Sixth Avenue. So am I right to say "the McDonalds in the shopping centre at Sixth Avenue"?  Now, what if it was a street instead of an avenue? Say for example:     We had our dinner at the McDonalds at/in the shopping centre at/on Coral Street.   Here, somehow, I find it natural to say "the McDonalds at the shopping centre on Coral Street".  How do I determine the right prepositions to use? And how would the different prepositions give different meanings to the sentence? How to check for empty xml files when parsing through multiple xml files Is there a performance difference between i++ and ++i in C++? We have the question   What's the answer for C++? (I'm going to link to this Stackexchange post concerning Nullary Operations: )  In general an  is a function $f:S^n \to S$, where $n$ denotes the arity of the operation, and a  is a function $f:S^0 \to S$.  It is clear that $S^n=S \times S \times \cdots \times S$ denotes the Cartesian product of a set with itself ($n$ times), however $S^0$ makes little sense to me.  One might define $S^0=\emptyset$. At first glance, that seems like a good choice. However then a nullary operation makes no sense, since it must be a function $f: A \to B$ where $A$ and $B$ are two sets representing the domain and codomain of the function. And note a function is defined in terms of relation, where a relation is a subset of the Cartesian product $A \times B$. So when we think of $A=S^0=\emptyset$ and $B=S$, so that we have a nullary operation $f:\emptyset \to S$, what is a a subset of $\emptyset \times S$? What even is $\emptyset \times S$? By definition of the Cartesian product, \begin{equation} \emptyset \times S = \{(a,b):a \in \emptyset\textrm{ and }b \in S\}. \end{equation} But there exists no $a \in \emptyset$! Therefore there exist no ordered pairs in our Cartesian product! Therefore $\emptyset \times S = \emptyset !$. Remember a function is a relation which is a subset of the Cartesian product. Therefore our relation is the empty set, and therefore also $f=\emptyset$.    Edit: We got the definition sorted out in the comments. Thanks especially to Hayden and Christoff for their great help. In summary, we figured out that $S^0=\{()\}$, the set containing only one element, the "empty $n$-tuple". Then if taking $S=\{1,2,...,k\}$, then a nullary operation $f:S^0 \to S$ is a function, i.e. some subset of $S^0 \times S = \{()\} \times S$. Looking at $\{()\} \times S$, this equals $\{((),1),((),2),...,((),k)\}$. Then a function is a special subset of this, so that each element of the domain (and there is only one element, namely $()$) is paired with exactly one element of the codomain. Therefore a function would have the form $f=\{((),a)\}$ where $a$ is one of $1,2,...,k$. Thank you for your help. How can I mount the /system directory rewritable or read-only on my Android phone? Should one downvote answers to off-topic questions? It annoys me when people post answers to obviously off-topic questions like , especially after those questions have already received several close votes. Migrations seem to happen rather infrequently these days, so there's probably no reputation to gain for questions that are likely to be closed. And although sure, the answer may help the OP, it also encourages bad behavior (posting off-topic questions.)  Is it appropriate to downvote these answers?   Personally, I think I could make a case for both sides. I am looking for a word that would describe someone who always goes out of their way to take their time and do a good job. Sort of the opposite of half-assing something.  I am looking for something that is more about a work ethic than a technically proper way of doing things. Something like canonical or protocol would not be a good fit. How do I make my textures show in cycles? I am admittedly new to Blender, and of course cycles. I am working on a scene and I have textures set to my objects that render with internal engine just fine. However, when I go into cycles, everything is greyish. I have two light sources that should be sufficient (I think), I just don't know what I'm doing wrong. This is a screenshot of the cycles result. Prove continuous functions $f$ and $g$ are equal Order of a product of elements in a generic group I'm dealing with the following question: having a group $G$ (of which nothing else is specified, doesn't have to be abelian), prove that $|ab|=|ba|$ for any $a$, $b$. Since $G$ is not abelian I'm not sure what to use here. I was thinking that except the case where $b=a^{-1}$, the order of those would be $lcm(m,n)$ where $m$ and $n$ are the orders of a and b. But looking it up it seems not to be so simple, even if all the info I could find was for abelian groups, so I would like some help with this specific case. How would I remove the border from an iframe embedded in my web app? An example of the iframe is:  &lt;iframe src="myURL" width="300" height="300"&gt;Browser not compatible.&lt;/iframe&gt;   I would like the transition from the content on my page to the contents of the iframe to be seamless, assuming the background colors are consistent. The target browser is IE6 only and unfortunately solutions for others will not help. OSVR has a right-handed system: x is right, y is up, z is near.  I need to convert orientation data from a sensor in OSVR to a different right-handed system in which x is forward, y is left, and z is up.  I need to calculate the transformation that will convert a quaternion from one system to the other.  I naively tried:  void osvrPoseCallback(const geometry_msgs::PoseStampedConstPtr &amp;msg) { // osvr to ros     geometry_msgs::PoseStamped outputMsg;      outputMsg.header = msg-&gt;header;     outputMsg.pose.orientation.x = msg-&gt;pose.orientation.y;     outputMsg.pose.orientation.y = msg-&gt;pose.orientation.z;     outputMsg.pose.orientation.z = msg-&gt;pose.orientation.x;     outputMsg.pose.orientation.w = msg-&gt;pose.orientation.w;      osvrPosePub.publish(outputMsg);     ros::spinOnce(); }   But that made things really weird. Facing north pitch is pitch, facing west, pitch is yaw, facing south, pitch is negative pitch...  How can I convert my OSVR quaternion to the a corresponding quaternion in the new coordinate system? I have two lightning component placed on one page lightning app. First Component have refresh icon and I set onclick action to refresh Component $A.get('e.force:refreshView').fire(); but this event refresh the whole page instead of First component.  how can refresh only one component on page not all the page ? I have designed a VF page to create a new record in which I am trying to display the value of a pick-list field. I have set a default value for this pick-list field. When trying to create the record using the salesforce native page, the value with which pick-list loads is the one I set as default but when creating the same record using VF page, the pick-list loads with "--None--" as default value.  Can anyone suggest If this is salesforce related bug or Am I doing anything wrong ? ZFC + $\exists$ Standard model $\rightarrow$ Con(ZFC + $\exists \omega$-model) $ZFC + \exists V_\alpha$ model of $ZFC \vdash Con(ZFC + \exists$ transitive standard model of $ZFC)$  and then  $ZFC + \exists$ transitive standard model of $ZFC \vdash Con(ZFC + \exists \omega-model$ of $ZFC)$  For the first one :   We can always find a countable extentional $M \subset V_\alpha$ elementary equivalent to $V_\alpha$. Let $M&#39;$ be the mostowski collapse of $M$. $M&#39; \approx M$ so $M&#39;$ is model of ZFC. And because $M&#39;$ is countable and transitive then $M&#39; \in V_\alpha$ (since $H_{\omega_1} \subset V_{\omega_1}$ and $\alpha$ is surely far larger than $\omega_1$).   So $V_\alpha$ is the model of '$\exists$ a standard transitive model of ZFC'.  For the second one :   I don't really know how to do it... Does anyone have an idea ? In Windows I used command-line clipboard copy-and-paste utilities...      pclip.exe and gclip.exe     These were UnixUtils ports for Windows (but they only handled plain text). There were a couple of other native Windows utilities which could write/extract any format.    I've looked for something similar in Synaptic Package Manager, but I can't find anything.    Is there something there, that I've missed? ... or maybe this is available in Bash scripting?    The type of utility I'd like will be able to read/write via std-in/std-out or file-in/file-out, and handle Unicode, Rich Text Format, picture, etc. clipboard formats...    NB: I'm not after a clipboard manager. Changing affiliation on publication