I know that Exchange Information Store (store.exe) is indeed a memory hog. So much so that it doesn't always seem to respectively release memory when other applications need it - causing the machine to be sluggish.  This is SBS 2011 Standard SP1 with Exchange 2010. There are about 30 computers on our network, most of which use Outlook to connect to Exchange. We also utilize SharePoint. There are 3 SQL Server instances, and I know SQL Server can also use up a lot of RAM - but they're already capped at 2GB, and don't even reach that limit. All 3 SQL Server instances combined use about 2.5GB.  What is very strange though is our SharePoint site gets extremely sluggish, and when I check it out, there's only a sliver of memory available (like under 1GB). This was with 12GB of RAM. So we just upgraded it to 32GB of RAM - but now Exchange uses about 20GB of it. We still have the issue where everything gets sluggish after it's been running for a while.  What I understand is that there's no option to put any cap on what memory Exchange uses. But with 32GB of RAM available to the machine, surely it shouldn't really need 20 of it. It's still leaving under 1GB available. Is there another way I can prevent Exchange from basically taking over the memory?  PS - this is a virtual machine on HyperV via Server 2012.
We have a SBS 2011 server with 16GB memory that runs Exchange, WSUS and File Sharing for approx 20 users. The server also gives 2GB memory to a virtual machine running in Hyper-V so 14GB left for the rest.  When the server first boots Store.exe consumes about 500MB memory, WSUS and IIS consume some as well, but we generally are only at 60% capacity. During the course of the working day Store.exe consumes 8GB memory and the server sits at approx 97% capacity.  This makes using the server very slow, logging on via RDP is slow, general server admin is slowed down.  Is this normal? I have read that Exchange will consume lots of memory that it does not neccessarily need and then releases it back to other applications that need it. I have also checked that all mailboxes are opened in cached mode. We do have some external uses who connect via Outlook Anywhere or OWA.  If it's deemed to be "normal" is there some way I can restrict it using ALL available memory and leave a little bit for SBS to use for server admin? I have seen some articles regarding setting a high and low memory flag but rumours that this does not work with update rollup 5 which we have installed.  Am I expecting a single server to do to much with only 14GB memory?  Thanks
The problem is to prove that every Hilbert space has a orthonormal basis. We are given Zorn's Lemma, which is taken as an axiom of set theory:  Lemma If X is a nonempty  with the property that every  of X has an upper bound in X, then X has a maximal element.   Given a orthonormal set $E$ in a Hilbert space $H$, it is apparently possible to show that $H$ has an orthonormal basis containing $E$.   I tried to reason as follows: Suppose $E$ is a finite set of $n$ elements. Then one can number the elements of $E$ to create a totally ordered set of orthonormal elements. Then the span $&lt;E&gt;$ can be identified with $R^n$, where each element $v = v_1 e_1 + v_2 e_2 + ... + v_n e_n$ is identified with the vector $(v_1, v_2, ..., v_n)$. On $R^n$ we have a total order, namely the "lexigraphical order" $(x_1,x_2,...,x_n) \leq (y_1,y_2,...,y_n)$ if $x_1 &lt; y_1$ or if $x_1 = y_1$ and $x_2 &lt; y_2$ or if $x_1 = y_1$, $x_2 = y_2$ and $x_3 &lt; y_3$ and so on. Hence $E$ is a totally ordered subset of $H$ and $H$ is a partially ordered set. However, this set doesn't seem to have an upper bound. The set $E$ does have an upper bound. If we define a total order on $E$ only, then X is a partially ordered set satisfying the criteria so X has a maximal element?   This is as far as I got, and I am not sure the entire argument is correct. I don't see how what kind of maximal element I am seeking, since the orthonormal basis of a Hilbert space can have countably infinity number of elements. install other packages when creating new package in R I've already taken my calculus sequence and I'm interested in brushing up and staying sharp on the basics. So far, my calculus background is limited to single-variable calculus, which I applied in my physics sequence and engineering statistics. I learned a little bit of vector math in physics as well, but I'm not strong in it. My mathematical strengths lie in the discrete mathematics.  I'm particularly interested in studying for my IEEE Certified Software Development Associate exam - 10% of the exam is mathematics (calculus, differential equations, and statistics). Calculus is one of the mathematics knowledge areas that a software engineer should be competent in, so I'm looking for not only solidifying the courses that I've already taken, but moving forward with slightly more advanced topics, at an undergraduate mathematics level.  I'm currently using the textbook from my calculus sequence, but I'm interested to know what books other people used to learn calculus and if the book is potentially worth checking out.  What books are available to help me? "Goose"–"geese" vs. "moose"–"moose" Why is it that the plural of goose is geese but the plural of moose is moose? The same goes for mouse and house. Mouse becomes mice, yet house becomes houses. I am a novice user and I am trying to install Oracle Java. The process calls for me to access /usr/local/java, but here is the problem. I get as far as /usr/local, then this is the message I get:  leonard@leonard-MT6452:/usr/local$ dir bin  etc  games  include  java  lib  man  sbin  share  src  leonard@leonard-MT6452:/usr/local$ cd /java/ bash: cd: /java/: No such file or directory  leonard@leonard-MT6452:/usr/local$ rm -r ~/java rm: cannot remove ‘/home/leonard/java’: No such file or directory   Help? Say I had a Core i7 Laptop with 16GB of RAM and a 750gb drive.  Is there a mechanism where I can partition the HD into a Linux, Windows, OS X, Shared Data, Hypervisor setup where I boot a small hypervisor. I can start/stop a linux, Windows and OS X virtual machine and interact with them all from the hypervisor?   Code, Test, etc?  is this a type 1 Hypervisor?  I suppose I could run a small linux install and VmWare but could VmWare read the virtual machines from a physical hard disk partition versus a file based setup (.vmdk files)? "I don't know nothing" vs "I don't know anything" Possible Duplicate:             I'm not a native English speaker, and this question may be very basic, but I want to learn English better, so don't hurt me with downvotes.  What is the difference between "I don't know nothing" and "I don't know anything"?  Do they have the same meaning or opposite ones? Android: View.setID(int id) programmatically - how to avoid ID conflicts? Is there a term for someone who "can see multiple perspectives"? A colleague of mine is trying to describe herself as "capable of seeing a situation from multiple perspectives" or "able to look at the big picture from various viewpoints". I feel like there must be a better way to get this point across.  Is there a more concise way to describe this characteristic? Merge pdfs sequentially I would like to merge 4 pdfs, pdf1.pdf, pdf2.pdf, pdf3.pdf pdf4.pdf together so that the pdfs are spliced, i.e. the first page will be the first page of pdf1, the second the first of pdf2, the third the first of pdf3, etc.  The pdf files are with plain images, no table of contents.  How would I accomplish this? It would be nice to do it from Terminal as well. Show the number of up-votes and down-votes on the mobile site theme This bug was found on a couch in . The couch, and the two beds in the room show no signs of other bugs. Is this a bed bug that I should worry about or something harmless? It was slightly larger than a common tick. Why did the slaver in Astapor think Daenerys wouldn't do exactly what she did? Spoilers! (do I have to even say that here?)  I recently rewatched the episode of Game of Thrones where Daenerys is in Astapor. She makes the deal with the master slaver guy, where she trades him one of her dragons for 8,000 of his very tough slaves. I immediately thought this was stupid for two reasons:   Why would he think the dragon would immediately obey him rather than her? Maybe he doesn't quite believe the 'Mother of Dragons' lore, but it's still basically a pet at the very least. This one isn't as bad though, as... Why would he possibly think she wouldn't betray him and use her freshly bought slaves to take back her dragon? He just traded her literally all his slaves and he has not been kind to her so far. He has motivation to not go back on the deal -- he's running a business, basically... but she has no reason not to.   I guess you could argue that he was blinded by greed, but I think that would be poor writing -- he's in a vicious trade, I can't imagine he would've survived long thinking so naively.  Does anyone have a good explanation? I'm looking for a word which describes a task which I think is poorly designed and will lead to either mediocre results or failure, but which I have to do anyway, especially in a work setting.   The word "Dilbertian" comes to mind, however this word is obviously made up and is only meaningful to someone who is familiar with the Dilbert comic strip, so I'm looking for something which captures both the futility and compulsory nature of the task in a way which is meaningful to a broader audience. Android - Read Only File System IOException Evaluating the sum after reordering an infinite series $1-\frac {1} {2}+\frac {1} {3}-\frac {1} {4}+\ldots $ If in the series  $1-\dfrac {1} {2}+\dfrac {1} {3}-\dfrac {1} {4}+\ldots $ the order of the terms be altered, so that the ratio of the number of positive terms to the number of negative terms in the first $n$ terms is ultimately $a^{2}$, show that the sum of the series will become $\log \left( 2a\right) $.  Solution attempt. Let $p$ be the number of positive terms in the first $n$ terms of the reordered series so based on the question we are allowed $a^{2}=\dfrac {p} {n-p}$. Now solving for p we get $p=\dfrac {a^{2}n} {\left( 1+a^{2}\right) }$ and $n-p=\dfrac {n } {\left( 1+a^{2}\right) }$.  We also observe that in the original series only the odd terms are positive and only the even terms are negative.  Let's define $S_{odd}=1+\dfrac {1} {3}+\dfrac {1} {5}+.\ldots +\dfrac {1} {2n-1}$ and $S_{even}=\dfrac {-1} {2}\dfrac {-1} {4}\ldots -\dfrac {1} {2n}$  $S_{Reordered}=S_{odd_{p}}+S_{even_{n-p}}$  $S_{Reordered}=\sum _{t=1}^{t=P}\dfrac {1} {2t-1}+\sum _{t=1}^{t=(n-P)}\dfrac {-1} {2t}$ $S_{Reordered}=\sum _{t=1}^{t=\dfrac {a^{2}n} {\left( 1+a^{2}\right) }}\dfrac {1} {2t-1}+\sum _{t=1}^{t=\dfrac {n } {\left( 1+a^{2}\right) }}\dfrac {-1} {2t}$    In order to extend $S_{Reordered}$ from n terms to an infinite length. I guess i should take the limit of the $S_{Reordered}$ as $n\rightarrow \infty $ which would make the upper values of $t$ (Not sure of technical term here) to be $\infty$ giving me   $S_{Reordered}=\sum _{t=1}^{t=\infty}\dfrac {1} {2t-1}+\sum _{t=1}^{t=\infty}\dfrac {-1} {2t}$   and i have lost the $a$ from the expression. I guess i am stuck i need to perform some step to capture a before taking the limit. Any help would be much appreciated. Typeerror: object.__new__() takes no parameters (help) How can people teleport through forcefields in Star Trek? Occasionally, people have been able to teleport through a forcefield in Star Trek. Was there ever a consistent explanation for this?  I'd previously assumed a forcefield was like a solid wall. Or do they have gaps? Evaluating the limit $\lim_{n\to\infty} \left[ \frac{n}{n^2+1}+ \frac{n}{n^2+2^2} + \ldots + \frac{n}{n^2+n^2} \right]$ Evaluating the limit $\displaystyle \lim_{n\to\infty} \left[  \frac{n}{n^2+1}+ \frac{n}{n^2+2^2} + \ldots + \frac{n}{n^2+n^2} \right]$  I have a question about the following solution:  We may write it in the form:  $$ \frac{1}{n} \left[ \frac{1}{1+(\frac{1}{n})^2} + \ldots + \frac{1}{1+(\frac{n}{n})^2} \right] $$  Somehow I need to figure out that the limit is actually the Riemann sum of $\frac{1}{1 + x^2}$ on $[0,1]$ for $\pi = 0 &lt; \frac{1}{n} &lt; \ldots &lt; \frac{n}{n}$.  Can you explain to me to reach this conclusion? Is it possible to put commands in /etc/motd? Can I put shell commands in the /etc/motd login banner file? I have tried:   $(uptime)   and  `uptime`   Is this possible?