I am trying to add multiple footnotes in the chapter title but only one of them appears on the bottom of the page. \documentclass[12pt]{report}  \usepackage{tamuconfig} \usepackage{dcolumn}% Align table columns on decimal point     \usepackage{amssymb}% Package to draw a square in the formulas     \usepackage{wasysym}% Package to draw a square in the figures \usepackage{amsmath} % or simply amstext \usepackage{color} \usepackage{mhchem} \usepackage{chemformula} \usepackage{tabularx} % in the preamble \usepackage{longtable} \usepackage{siunitx} \usepackage[numbers]{natbib} \usepackage{booktabs} \usepackage{filecontents} \usepackage[multiple]{footmisc} \usepackage{caption} \usepackage{subcaption} \usepackage[hidelinks]{hyperref} \usepackage[multiple,symbol]{footmisc} \renewcommand{\thefootnote}{\fnsymbol{footnote}} \textheight=80pt% only for the example  \begin{document}  \chapter[nine]{SUMMARY AND CONCLUSIONS\footnote{one}\footnote{two}}  \end{document}  In my tamuconfig.sty file I have a line of code as     \usepackage[rm, tiny, center, compact]{titlesec}  I think that is what messes up with footnote. I appreciate it if anybody knows how can I fix this problem.
I'm adding two footnotes to a section heading:  \documentclass{article} \usepackage[english]{babel} \usepackage[utf8]{inputenc} \usepackage[T1]{fontenc} \usepackage{lipsum}  \usepackage[stable]{footmisc}  \usepackage{titlesec}  \begin{document} \section{test \footnote{This is footnote no1.} \footnote{This is footnote no2.} } \lipsum[4] \end{document}   The heading will have both of the footnotes, but at the end of the page only the second is displayed. The problem appears to be \usepackage{titlesec}, because it works fine without it.    Stuff I specified in \usepackage{titlesec}:  \renewcommand\thesection{\arabic{section}}  \renewcommand\thesubsection{\arabic{subsection}}  \renewcommand\thesubsubsection{\arabic{subsubsection}}  \titleformat{\section}[block]{\Large\scshape\centering}{\thesection}{1em}{}  \titleformat{\subsection}[block]{\large\scshape}{\thesection.\thesubsection}{1em}{}  \titleformat{\subsubsection}[block]{\large\scshape}{\thesection.\thesubsection.\thesubsubsection}{1em}{}   Thanks in advance!
My options to link large image into AI file My .psd file has a resolution of 6m x 3m @ 150 DPI. This makes it 35433px x 5906px in size. Photoshop CS6 saves the file as .tiff or .psb only. When I first import into Illustrator I get an error that the file is not readable but I have tried many options. Last one is not supported by AI.  So I'm puzzled... is there a way to link large images into Illustrator? What does the number in parentheses shown after Unix command names in manpages mean? For example: man(1), find(3), updatedb(2)?   What do the numbers in parentheses (Brit. "brackets") mean? How to get world-space matrix of any pose bone? Is there a command for getting world-space matrix of pose bones, same as obj.matrix_world for objects? I found pose_bone.matrix, but it gives weird result for me. Why is "the set of all sets" a paradox, in Layman's terms? I've heard of some other paradoxes involving sets (i.e., &quot;the set of all sets that do not contain themselves&quot;) and I understand how paradoxes arise from them.  But this one I do not understand. Why is &quot;the set of all sets&quot; a paradox?  It seems like it would be fine, to me.  There is nothing paradoxical about a set containing itself. Is it something that arises from the &quot;rules of sets&quot; that are involved in more rigorous set theory? Prove that the functions $f(z)$ and $\overline{f(\overline{z})}$ are simultaneously holomorphic.   I take this to mean that $f(z)$ is holomorphic if and only if $\overline{f(\overline{z})}$ is holomorphic.  Let $g(z)=\overline{f(\overline{z})}$. Note that $\overline{g(\overline{z})}=f(z)$. So it suffices to prove that if $f(z)$ is holomorphic, then $g(z)$ is holomorphic.  Write $f(z)=u(z)+iv(z)$. Since $f(z)$ is holomorphic, the real and imaginary parts satisfy the Cauchy-Riemann equations:  $$\frac{\partial{u(z)}}{\partial{x}} = \frac{\partial{v(z)}}{\partial{y}}, \frac{\partial{u(z)}}{\partial{y}} = -\frac{\partial{v(z)}}{\partial{x}}.$$  We have $g(z) = u(\overline{z})+i(-v(\overline{z}))$. To prove that $g(z)$ is holomorphic, we must prove that its real and imaginary parts satisfy the Cauchy-Riemann equations:  $$\frac{\partial{u(\overline{z})}}{\partial{x}} = \frac{\partial{(-v(\overline{z}))}}{\partial{y}}, \frac{\partial{u(\overline{z})}}{\partial{y}} = -\frac{\partial{(-v(\overline{z}))}}{\partial{x}}.$$  How can we obtain this from the above relations? Regular Expressions: Is there an AND operator? Obviously, you can use the | (pipe?) to represent OR, but is there a way to represent AND as well?  Specifically, I'd like to match paragraphs of text that contain ALL of a certain phrase, but in no particular order. How do I beat Uprising on Legendary difficulty? The achievement "Distinguished Service" requires that you beat Uprising on the regular gamemode on Legendary difficulty.  This means we can't pick our usual huge DPS heroes like Bastion and Orisa, and are stuck with Torbjorn, Reinhardt, Mercy, and Tracer.  The phases are as follows:   Hack all 3 terminals Defend the Payload until it's ready Escort the Payload until the gate Destroy all 4 Orisas.   So I ask this after having failed Uprising on Legendary dozens of times.   How do I beat Uprising on all 4 phases?   Specifically asking for the latter 3 phases.    Defending the payload is hard when it gets to the Bastions that drop in because Reinhardt's shield gets melted very quickly and Torbjorn has little to no DPS.  Tracer must be relied on but it seems there is no way to stop the perfect aim of Bastion as strafing around does nothing.  If and when we actually do manage to defend it, we're stuck on escorting, which is even harder thanks to the tank mode Bastions.  And finally, even if we do make it to the final fight, which has only happened once, the fight is so tough that even if we slowly inch ourselves closer to the end we run out of time.  The previous question I asked was different because Uprising (All Heroes) allows you to pick any 4 heroes to form your squad, but the original gamemode will not let you pick. Also, the achievement requires you to play the original mode -- Uprising (All Heroes) on Legendary does not reward players with the achievement. According to Hubble's Law, how can the expansion of the Universe be accelerating? Scientists today think the expansion of the universe is accelerating.   According to Hubble's law, objects further away are moving faster than objects closer to us. The further away an object is, the further back in time we are seeing, so in the past objects moved faster (is this sentence correct?).  So because objects moved faster before than they do now, surely that's deceleration not acceleration?  my textbook says "if Scientists today think the rate of expansion of the Universe were decreasing then distant objects should appear different to Hubble's Law predictions: universe is accelerating. More distant objects would seem to be receding faster (since expansion was faster in the past)" How do I handle the window close event in Tkinter? How do I handle the window close event (user clicking the 'X' button) in a Python Tkinter program? MySQL: SELECT from another server I'm afraid that I already know the answer to my question, but I'll ask it anyway:  When there are two MySQL DB servers, can I access data that is stored on the other server?   In other words: Can I somehow do this:  INSERT INTO table (x, y, z)    SELECT x, y, x+y       FROM [otherserver].[database].[table]   Is the answer really as short as "No"? How do I become a Werewolf? I've heard that one of (maybe the only?) secret races in this game is a werewolf.  How do I become a werewolf?  And by extension, how do I cure lycanthropy, that is, if there even is a cure? Short story about survivors on Earth after the atmosphere has frozen How Do I Opt Out of Privileges? According to  , gold badge holders can now unilaterally close questions as duplicates. I hold seven gold badges for tags on SO, which means I can, on my own, close questions as duplicates for those tagged questions.  Simply put: DO NOT WANT.  However, I do not see any ability in SO (the only SE site I spend much time in) to opt out of any privileges, let alone this one.  Is there a spot that I'm just not seeing that allows me to turn off this new privilege? Split Line at Points not splitting at every point in ArcGIS for Desktop? Why does  not split at every point encountered, even if run in an iterative fashion?  Following the suggestions of a thread here and several others, I made a set of points in order to split polylines at specified intervals. In order to do this, I used linear referencing to turn my lines into routes. Then, I exported the attribute table, divided each length by 5, and set points at multiples of 1/5 the length of the line. I used this as the event table to create a layer of events. So, each line has 4 equally spaced points along it, and I thus ultimately need the 5 segments separated by those points.  Curiously, though, when I try to do the second part "Split Line at Point," it seems that only one point is used on a given line at a time, and I'm not sure how it chooses the point (maybe order in its attribute table?) I could run the tool multiple times, but this doesn't seem to solve the problem either. For example, I could see how it would continue splitting segments as more segments are generated, but on e.g. the 4th run I see that some lines are still only split 3 times, even though there is a point within a line segment that was never split and existed before I ran the tool. I'm not sure how the splits are generated, but in any case, it doesn't seem to do what I want it to do, which is produce a split at "each" point.  What should I do to split lines at ALL points along the line? How to count entities with commands/check if there are only one or a certain number of entities or players left? I want to run a command when there are only 10 entities left. I know you can use /execute unless entity to detect when all matching mobs have died, but it doesn't work if you want to run a command when there are for example 10 entities left.  A command like /execute if entity @e[limit=10] does not work, it also triggers if there is only one entity.  Such a counting system could also be used to determine once there is only one player left in an arena, meaning they have won a battle or similar. Is there a 'rule of thumb' that I can use to estimate depth of field while shooting? I can use a DoF calculator, or crunch the heavy math by hand if I really want to know exactly what my DoF is going to be... but most of the time knowing exactly is actually overkill, and taking the time to pull out a DoF calculator is impractical. I'm wondering if anyone knows of a 'rule of thumb' that is common for quickly figuring out a rough estimate of what my DoF will be when I'm in the field... I am having an error compiling the following code with xelatex and lualatex:  ** WARNING ** "seac" character deprecated in Type 2 charstring. ** ERROR ** Type2 Charstring Parser: Parsing charstring failed: (status=-1, stack=5)  Output file removed.  \documentclass{article}  \usepackage{xunicode} \usepackage{fontspec}  \setmainfont[Mapping=tex-text,Ligatures={Common}, Numbers={OldStyle}]{IM FELL English PRO} \begin{document}  Buongiorno a tutti. Trallallà.  \end{document}   The error disappears when I omit the accented à. It also doesn't happen when I use other fonts.  Could you suggest any workaround?  Thank you, A Consider the closed interval $[0,1]$, there is $\frac{2}{3} \in [0,1]$ where $p=2$ and $q=3$. Similarly consider $[2,3]$, one can have $\frac{5}{2} \in [2,3]$ where $p=5$ and $q=2$. Does every interval of the form $[a,b]$, where $a,b \in \mathbb{R}$ contain a rational of this kind. If yes, how can we prove it? What's the difference between \usepackage{ngerman} and \usepackage[ngerman]{babel} Is there something additional that \usepackage[ngerman]{babel} does that a simple \usepackage{ngerman} won't be able to do? $A_n:Y\rightarrow Z$ are operators that strongly converge to $A$. Also, $\|A_n\|_\text {op}\le c$ for $c&gt;0$. Given a compact operator $T:X\rightarrow Y$, I need to show that $A_nT$ converges to $AT$ in operator norm (all spaces in this question are Banach spaces).     I was unable to prove this and I also do not understand why we need to assume that $T$ is compact. Any ideas?