First I don't want make an animation. I just want to understand how I can make a Scene and wander around in it with 360°.  I mean .
I have an object at a fixed position in 3D space. I would like the camera to circle around it while facing it. I want to path of the camera to be circular in 2D, meaning that it does not move up or down.  I need this to be pretty accurate. I don't want to manually set a keyframe every frame for position and rotation. I would like to do this maybe with an expression, not with manual keyframing. I am not sure how to go about this but I think it is going to involve Python as well as some trigonometry.
I have a question regarding transaction log (let’s just call it LDF for short) contents. I am assuming a database with full recovery model.  I have read that LDF file contains (logs) each and every operation to the database (that is in full recovery mode). How is it different from logging during BEGIN TRAN; COMMAND(s); COMMIT? I am asking because apparently you can roll back transactions, but you cannot roll back standard commands (in full recovery mode).  I guess that during transaction the contents being logged into the LDF file are different than in regular full recovery logging. Is that right? How is it different? Is it only the inclusion of “undo” operations for each action?  On a related note, I have heard that there are commercial tools to "rollback/undo" standard queries using full recovery LDF file. How do they do it? Do they analyze the LDF contents and try to come-up with inverse/undo operations? URLs are linked despite being inside a code span I was having a time getting my bootable USB 3, 32GB W10 install USB to be recognized. It recognized one time but I had to restart for something and it never came up again. I eventually removed all other boot up options to make it easier and faster to try again (no F12 needed).  Finally I gave up and tried another drive (16GB this time FWIW) and then it worked.  HOWEVER, it's stuck on a reboot loop now. I can choose to install, then to select the right disk, then it says it's loading file and then next thing I know it's saying do you want to install or upgrade. I'm having some trouble with the following sentence:     Since he had arrived, he had seen the rule broken more than once.   For some context, the text itself is a short story and I'm writing it in past tense. Does this mean that the presence of a past simple verb is "implicit", in a way, to the text itself? Does using the word "since" change anything (I know that it is usually supposed to be followed by a past simple verb, but I'm not sure of any exceptions to this)? When is a function satisfying the Cauchy-Riemann equations holomorphic? It is, of course, one of the first results in basic complex analysis that a holomorphic function satisfies the Cauchy-Riemann equations when considered as a differentiable two-variable real function. I have always seen the converse as: if $f$ is continuously differentiable as a function from $U \subset \mathbb{R}^2$ to $\mathbb{R}^2$ and satisfies the Cauchy-Riemann equations, then it is holomorphic (see e.g. Stein and Shakarchi, or ). Why is the $C^1$ condition necessary? I don't see where this comes in to the proof below.   Assume that $u(x,y)$ and $v(x,y)$ are continuously differentiable and satisfy the Cauchy-Riemann equations. Let $h=h_1 + h_2i$. Then \begin{equation*} u(x+h_1, y+h_2) - u(x,y) = \frac{\partial u}{\partial x} h_1 + \frac{\partial u}{\partial y}h_2 + o(|h|) \end{equation*} and  \begin{equation*} v(x+h_1, y+h_2) - v(x,y) = \frac{\partial v}{\partial x} h_1 + \frac{\partial v}{\partial y} h_2 + o(|h|). \end{equation*} Multiplying the second equation by $i$ and adding the two together gives  \begin{align*} (u+iv)(z+h)-(u+iv)(z) &amp;= \frac{\partial u}{\partial x} h_1 + i \frac{\partial v}{\partial x} h_1 + \frac{\partial u}{\partial y} h_2 + i \frac{\partial v}{\partial y} h_2 + o(|h|)\\\  &amp;= \left( \frac{\partial u}{\partial x} + i \frac{\partial v}{\partial x} \right) (h_1+i h_2) + o(|h|). \end{align*}  Now dividing by $h$ gives us the desired result.   Does there exist a differentiable but not $C^1$ function $f: U \rightarrow \mathbb{R}^2$ which satisfies the Cauchy-Riemann equations and does NOT correspond to a complex-differentiable function? Do cell carries have access to FaceTime information? On the newest iPhone, do cell phone carriers have access to FaceTime call data (such as which caller initiated and ended a FaceTime call)? How does the Java 'for each' loop work? $\nabla U=0 \implies U=\mathrm{constant}$ only if $U$ is defined on a connected set? How do you refer to a hyponym that is the same word as the hypernym? What word (or how do you phrase things) do you use when the ostensible word for the class is the same as the word for a subset of the class?  For example, in the United States, there are many brands of sugared, carbonated soft drink that one can buy: Coca-Cola (or Coke), Pepsi, RC Cola, Sprite, 7-Up, A&amp;W or Mug Root Beer, etc). The first two are kinds of 'coke' or 'cola' (but no one says 'cola').  , one asks for any type of such drink as 'coke'. How does one then ask for the particular kind of 'coke' that is 'Coke' (pronounced the same)? Does one reduplicate and say a 'Coke coke', does one repeat with emphasis (or without), does one use a different word like 'coca-cola' (co-cola), or what?  The (perceived) difficulty (surely those in the South are able to get the drink they want somehow) isn't limited to there. Where the drink is called 'soda', if you ask for a 'coke', you'll still sometimes have the choice among Coca-Cola, Pepsi, etc. "Can I have a Coke?" the response might be "Is Pepsi OK?". "Sure, Pepsi, Coke, whatever." You don't use 'cola', you just ask for the particular kind and hope the listener will help differentiate.   Given these multiple strategies for disambiguating, what do you do say to get a 'Coke' in the southern US? are there any other examples of a hypernym being the same as the hyponym, and so creating a disambiguation problem? I'm a Canadian citizen with a Canadian passport. I booked a flight with American Airlines to Mexico City From Toronto Pearson and it says that "Passenger details are needed to check in".  Flight 1: YYZ -> DFW -> MEX Flight 2: MEX -> DFW -> YYZ     They already took my name, gender and such. It is now asking for my passport number and expiry date. That all seems reasonable. However, when I enter that I am a Canadian resident it asks for:  1) Street or hotel in US 2) City in US 3) State in US    My trip to DFW is only for a connecting flight. The fields are required so I can't submit my passport information without filling this in.    Is there something I'm missing? After purge mussels 6 time in salt water 20 mins each, why they still exude much grime? I  buy mussels at Pusateri and Whole Food Market for a year in Toronto. They sell them on ice and dry, not in running water.      , Bart teaches add salt to cold water and  soak for 20 mins. But I repeat 6 times...so 20 mins x 6 times = 120 mins of soaking!!! Mussels exudate less black grime every next time, but even after 6 times, water still has much black grime! See my pic under! Why? This happening for a year!     Part 2,  has GIF that shows you what I mean. Prove if $(a,p)=1$, then $\{a,2a,3a,...,pa\}$ is a complete residue system modulo $p$. let $p$ be a prime and let $a$ be an integer not divisible by $p$, that is $(a,p)=1$. Then $\{a,2a,3a,...,pa\}$ is a complete residue system modulo $p$.  Since $p\nmid a$, $p\nmid\{a,2a,3a,...,(p-1)a\}$ Since $p|p$, $p|\{pa\}$ which is exactly one element in the set and is therefore a complete residue system.   Wondering if this is an acceptable proof to this theorem. How do I upgrade to the unreleased version of Ubuntu for testing? equality of two operators... Please help me with the following problem( give some hints or references):  Let $X$ be a Banach space and $B(X)$ be the algebra of bounded linear operators on $X$. Suppose that $A$ and $B$ are two operators in $B(X)$ such that for every $T \in B(X)$ we have $\sigma(AT)=\sigma(BT)$. Show that $A=B$.  Here $\sigma(A)$ denotes the spectrum of $A$, i.e., the the set of all complex numbers $\lambda$ such that $\lambda I − A$ has no inverse in $B(X)$.  Thanks in advance. How to add appendix in thesis using LyX I want to add an appendix (questionnaire etc.) at the end of my thesis after the references. I use the article class and work with LyX: Document -&gt; Start appendix here. But I am not getting it in the TOC.  \documentclass[12pt,english]{article} \usepackage[T1]{fontenc} \usepackage[latin9]{inputenc} \setlength{\parskip}{\smallskipamount} \setlength{\parindent}{0pt} \usepackage{color} \definecolor{document_fontcolor}{rgb}{0, 0, 0} \color{document_fontcolor} \usepackage{babel} \usepackage{float} \usepackage{textcomp} \usepackage{pdfpages} \usepackage{tipa} \usepackage{amsmath} \usepackage{graphicx} \usepackage{setspace} \PassOptionsToPackage{normalem}{ulem} \usepackage{ulem} \usepackage[unicode=true,  bookmarks=true,bookmarksnumbered=false,bookmarksopen=false,  breaklinks=false,pdfborder={0 0 0},backref=false,colorlinks=false]  {hyperref}  \makeatletter  %%%%%%%%%%%%%%%%%%%%%%%%%%%%%% LyX specific LaTeX commands. %% Because html converters don't know tabularnewline \providecommand{\tabularnewline}{\\} %% A simple dot to overcome graphicx limitations \newcommand{\lyxdot}{.}   %%%%%%%%%%%%%%%%%%%%%%%%%%%%%% Textclass specific LaTeX commands. \numberwithin{equation}{section}  \@ifundefined{date}{}{\date{}} \@ifundefined{showcaptionsetup}{}{%  \PassOptionsToPackage{caption=false}{subfig}} \usepackage{subfig} \makeatother  \appendix \noindent \begin{center} \textbf{Questionnaire (Case Study 1)} \par\end{center} How to reduce the size of VMware disk My Ubuntu image VMware disk has grown to 5GB physical file size. It's a dynamically growing disk with the maximum capacity of 8GB. I cleaned some stuff inside Linux distro and now inside it occupies 3GB. Obviously the physical file size didn't shrink back automatically. Is there a way (if possible free of charge) to shrink this disk back to ~3GB?  I need this to fit the image on the DVD. SQL - Order by with alphanumeric characters Our company has multiple domains set up with one website hosted on each of the domains. At this time, each domain has its own authentication which is done via cookies.   When someone logged on to one domain needs to access anything from the other, the user needs to log in again using different credentials on the other website, located on the other domain.   I was thinking of moving towards single sign on (SSO), so that this hassle can be eliminated. I would appreciate any ideas on how this could be achieved, as I do not have any experience in this regard.  Thanks.  Edit: The websites are mix of internet (external) and intranet (internal-used within the company) sites. How does space affect the human body (no space suit, no space craft) How does "outer space" affect the human body? Some movies show it as the body exploding, imploding or even freezing solid.   I know space is essentially a vacuum with 0 pressure and the dispersion of energy makes it very cold. So are the predictions above accurate? Why are all snaps being mounted and listed as block devices or partitions for Ubuntu 18.04? As of Ubuntu 18.04 running lsblk shows 16 snap loops (2-3 times for each snap). The question is, why are they being listed as results for lsblk, fdisf-l, and blkid?    It creates a lot of clutter from the actual disks drive partitions I need to see, namely /dev/ partitions. I know a purported duplicate of this question exists, but it only asks why three loops are being listed per snap. I want to know why these snaps are being listed in the first place, and the purported duplicate does not answer this (perhaps those marking this as duplicate could help me by explaining why it is a duplicate). Technically, they qualify as file systems (which I neither created nor asked for), but they are getting in the way of the information output for the /dev/ partitions I am interested in. This becomes a problem when fdisk -l outputs a three page+ list filled mainly with snaps.  The output of a recent (1 week old) Ubuntu install and I have not installed any snaps:    $ lsblk   NAME   MAJ:MIN RM   SIZE RO TYPE MOUNTPOINT   loop0    7:0    0  14.5M  1 loop /snap/gnome-logs/37   loop1    7:1    0   2.3M  1 loop /snap/gnome-calculator/170   loop2    7:2    0  86.6M  1 loop /snap/core/4486   loop3    7:3    0  86.6M  1 loop /snap/core/4650   loop4    7:4    0   1.6M  1 loop /snap/gnome-calculator/154   loop5    7:5    0  14.5M  1 loop /snap/gnome-logs/34   loop6    7:6    0   3.3M  1 loop /snap/gnome-system-monitor/36   loop7    7:7    0   2.3M  1 loop /snap/gnome-calculator/178   loop8    7:8    0    13M  1 loop /snap/gnome-characters/101   loop9    7:9    0   3.7M  1 loop /snap/gnome-system-monitor/45   loop10   7:10   0 139.5M  1 loop /snap/gnome-3-26-1604/64   loop11   7:11   0   140M  1 loop /snap/gnome-3-26-1604/59    loop12   7:12   0   3.7M  1 loop /snap/gnome-system-monitor/41   loop13   7:13   0    21M  1 loop /snap/gnome-logs/25   loop14   7:14   0  12.2M  1 loop /snap/gnome-characters/69   loop15   7:15   0    13M  1 loop /snap/gnome-characters/96   sda      8:0    0 298.1G  0 disk   ├─sda1   8:1    0   512M  0 part /boot/efi   └─sda2   8:2    0 297.6G  0 part /   sr0     11:0    1  1024M  0 rom     (supplemental screen capture of above text):     My snap list shows 6 results:       core   gnome-3-26-1604   gnome-calculator   gnome-characters   gnome-logs   gnome-system-monitor     Meanwhile, gnome-disk-utility shows nothing at all for snaps, only showing my HDD and optical drive.    It won't be very efficient if every installed snap gets listed as a block device (2-3 times each to add). Should I expect future updates to deal with this?  Edit: fdisk-l also dumps out a very long list with 16 instances of these "disk loops" (Disk /dev/loop0, Disk /dev/loop1, etc., each with details which I won't show here because it's too long). This can't be intended behaviour, can it? blkid also lists 16 loops, as TYPE="squashfs". At least parted -l works as expected, only outing my actual disk partitions.    I just tested this, and installing more snaps does add more to the lsblk output. Therefore, fdisk, lsblk, blkid could have potentially huge output lists, according to the number of snaps available, and installed.