Grep with -r was not working for me.  I then made a test situation.  The directory /home/den/backup now contains a file with the word washer in it.  I also made a subdirectory within /home/den/backup.  In that directory a file contains the word washer.  The following should return two hits at  /home/den/backup/great.txt and /home/den/backup/aaa/info.txt  If I issue   grep -r "washer" /home/den/backup/*.*   the result is one hit.  If I issue  grep -r "washer" /home/den/backup/aaa/*.*   the result is one hit.  Shouldn't the first one have also found the second one, which is in one if its sub-directories?
Normally while searching using grep, the command I was using was this:  grep -nri "String"   whereas most of my colleagues do this:  grep -nri "String" *   What does the latter do (the * part)?
Difficulty in creating macro '\newcommand' for the beginning and end of frames in Beamer Why crontab scripts are not working? Often, crontab scripts are not executed on schedule or as expected. There are numerous reasons for that:   wrong crontab notation permissions problem environment variables   This community wiki aims to aggregate the top reasons for crontab scripts not being executed as expected. Write each reason in a separate answer.  Please include one reason per answer - details about why it's not executed - and fix(es) for that one reason.  Please write only cron-specific issues, e.g. commands that execute as expected from the shell but execute erroneously by cron. What does "apostrophe s" stand for in "What's it all mean"? I heard someone on a TV show say:     What's it all mean?   As far as I know, 's could be the short form of has and is. But in this case, it seems more like to be the short form of does. Am I correct? I admit this feature request is probably somewhat limited in useful scope, but I'm throwing it out there anyway. Inspired by , and because I want to use it on , I'm requesting that name be supported on a tags in posts.  On very long answers, such as the closing/migration guidance answer, this would allow direct linking to the specific closure reason. This would then allow us, when someone , to link directly to the appropriate reason and description thereof.  I recognize the limited scope of this, however, I have seen other long answers that could stand to have that kind of "deep" linking ability as well.  (The original incarnation of this post had either name or id, but preferenced name. Per Koper's answer, which I agree with, I took out the idea of supporting id, because Koper's right -- too dangerous.) How to create a bootable USB stick? I am looking at this:    I need to create a boot disk to test Ubuntu to make sure it will run on a PC (Compaq Mini CQ10-120LA) I was given. I can create the boot disk off of a Mac (in English) or Windows (but Windows is in Spanish and foreign to me).   Questions:     What format do I choose for the USB stick? (I wish the instructions stated this). What is Dash? (Will I know when I run the installer?) Can I do this from a Mac or Windows computer? Or only from Ubuntu? What is your simplest explanation of string theory? How to open files from other machine running ubuntu I tried to take data from my pc to laptop. Both are using ubuntu 11.10 os. I googled and tried to connect both the systems. Now it is showing connected symbol. Dont know how to proceed further. I need to take data from my pc using this lan connection. Please provide me solution for this... How to put an acute on an i using Biber: issues with "\'{\i}" I use some packages with require utf8. Here is the main file:  \documentclass[a4paper,titlepage]{report}  \usepackage[utf8]{inputenc} \usepackage[T1]{fontenc} \usepackage[american]{babel} \usepackage{csquotes} \usepackage[backend=biber,style=alphabetic]{biblatex} \addbibresource{refs.bib}  \begin{document} \nocite{*} \printbibliography[heading=bibintoc] \end{document}   And here is the reference file:  @MISC{Example,     author = {Author with spec\'{\i}al character},     title = {Title} }   I have no issues with composing special characters like \H{o} (ő) or \k{a} (ą). However, when I try to compose \'{\i} (í), I get the following inputenc error: "not set up for use with LaTeX". It seems like double compositions are not allowed. A solution is to use \'{i} instead, but not removing the dot is ugly. Surely there must be a better way?  Note: I have tried to add \DeclareUnicodeCharacter{00ED}{\'{\i}} to the preamble, but it doesn't help either. Find the value of $\int_{-\infty}^{\infty} \frac{e^{-x^2}}{1+x^2} dx$ . Find the value of $\int_{-\infty}^{\infty} \frac{e^{-x^2}}{1+x^2} dx$     My attempt  First, I know the existence of this integral since $$ \mid \int_{-a}^{a} \frac{e^{-x^2}}{1+x^2} dx \mid \;\; \leq\;\;  \mid \int_{-a}^{a} \frac{1}{1+x^2} dx \mid$$  Next, let $R &gt;0 $ be an arbitrary and $\gamma_1(t) = -R(1-t) + Rt , \;\; 0 \leq t \leq1$ and $\gamma_2(t)= Re^{i\pi (t-1)}, \;\; 1 \leq t \leq 2 $.  So, take $f(z) = \frac{e^{-z^2}}{1+z^2}$.   I tried to find the value or upper bound of norm of $$\int_{\gamma_2} \frac{e^{-z^2}}{1+z^2} dz$$.  However, $$ \lvert\int_{\gamma_2} \frac{e^{-z^2}}{1+z^2} dz\rvert \leq  \frac{\text{max}\lvert e^{-z^2}\rvert}{R^2-1}\pi R = \frac{e^{R^2}}{R^2-1}\pi R $$ So, I can't proceed this.  May I ask you how to solve this? I'm trying to install pandas. When I do, it's automatically installing to the python installation for v 2.7.   How do I force pandas to install to the python 3.5 installation? Careers: create PDF is not handling properly the sections Writing and Reading Scenario #1: no items in the section Writing, a few items in Reading   click on create pdf in the PDF you get your readings under the title "Writing" (should be "Reading")   Scenario #2: one item in the section Writing, a few items in Reading   click on create pdf in the PDF you get:   your readings under the title "Writing" (should be "Reading"), as in scenario #1 there are no writings (there should be one)    Hope it to be clear. Let me know in case it isn't.  Thank you! How to achieve this 3D "Card" effect Prove or the disprove the existence of a limit of integrals Let $A \subset \mathbb{R}^2$ be the annulus defined, in polar coordinates, as  $$ A = \{ (r, \theta) \in [0, \infty) \times [0, 2\pi) : 2 \leq r \leq 3 \} \, .$$ Let $F: A \to A$, $F:(r, \theta) \mapsto (r, r \theta \text{ (mod } 2\pi))$. Let $g : A \to \mathbb{R}$ be a continuous function. Discuss the existence of the limit $$ \lim_{n \to \infty} \int_A g \circ F^{(n)}(x) \, \text{d}x \, ,$$ where $F^{(n)} = F \circ F \circ \dots \circ F$ denotes the composition of $F$ with itself $n$ times.  I cannot find a way to attack this problem. Here's what I tried: if $g \circ F^{(n)}$ converged, I think we could take the limit under the integral sign. So I tried to show the convergence of $F^{(n)}$. If it converged, then the limit function must send every point to a fixed point of $F$. So I determined the fixed points of $F$. But I don't think $F^{(n)}$ converges. Python analog of PHP's natsort function (sort a list using a "natural order" algorithm) How to return a part of an array in Ruby? A person that professes discrimination based on race is a racist.  What is the word for defining a person that discriminates based on culture (pretty sure it is not culturist) or social habits?  E.g., Eric Cartman doesn't like hippies, he discriminates against them. But a hippie is not a race, an ethnic, a religion or a nationality. It is a life style not related to any of these. I have 1:50 wound current transformer and I don't have the datasheet. Could anybody help me to calculate the burden resistor?    Maximum current to be measured: 2A  Max output voltage to ADC: 5V Thomson et al. provide a proof that $\lim_{n\rightarrow \infty} \sqrt[n]{n}=1$ in . It has to do with using an inequality that relies on the binomial theorem:  I have an alternative proof that I know (from elsewhere) as follows.  Proof. \begin{align} \lim_{n\rightarrow \infty} \frac{ \log n}{n} = 0 \end{align} Then using this, I can instead prove: \begin{align} \lim_{n\rightarrow \infty} \sqrt[n]{n} &amp;= \lim_{n\rightarrow \infty} \exp{\frac{ \log n}{n}} \newline &amp; = \exp{0} \newline &amp; = 1 \end{align}  On the one hand, it seems like a valid proof to me. On the other hand, I know I should be careful with infinite sequences. The step I'm most unsure of is: \begin{align} \lim_{n\rightarrow \infty} \sqrt[n]{n} = \lim_{n\rightarrow \infty} \exp{\frac{ \log n}{n}} \end{align} I know such an identity would hold for bounded $n$ but I'm not sure I can use this identity when $n\rightarrow \infty$. Question: If I am correct, then would there be any cases where I would be wrong? Specifically, given any sequence $x_n$, can I always assume: \begin{align} \lim_{n\rightarrow \infty} x_n = \lim_{n\rightarrow \infty} \exp(\log x_n) \end{align} Or are there sequences that invalidate that identity?  (Edited to expand the last question) given any sequence $x_n$, can I always assume: \begin{align} \lim_{n\rightarrow \infty} x_n &amp;=  \exp(\log \lim_{n\rightarrow \infty} x_n) \newline &amp;=  \exp(\lim_{n\rightarrow \infty} \log x_n) \newline &amp;=  \lim_{n\rightarrow \infty} \exp( \log x_n) \end{align} Or are there sequences that invalidate any of the above identities? (Edited to repurpose this question). Please also feel free to add different proofs of $\lim_{n\rightarrow \infty} \sqrt[n]{n}=1$. Statistical saturation attack on block ciphers I was wondering if anyone around here could give me some explanation on this type of attacks. Pretty much the only thing that I could find is .  What I really need is basic explanation of the attack itself with a small example if possible such as any basic block cipher that you could come up with with 3-4 rounds. This is for my personal understanding so any input is more than welcome. Storable Action - System.LimitException: Too many DML statements: 1 @AuraEnabled(cacheable=true) public static String  deleteContacts(List&lt;String&gt; contactIds) {     List&lt;Contact&gt; returnList = new List&lt;Contact&gt; ();     String query = ' SELECT Id,Name, LastName,Department,MobilePhone, Email FROM Contact WHERE id IN : contactIds ';     for (Contact thisContact:  Database.Query(query)) {          returnList.add(thisContact);     }     try {       delete returnList;       return'deleted successfully';     }     catch(Exception ex){        return 'Problem occoured';     }  }  JS Method deleteSelected(){     deleteContacts({         contactIds :this.selectedIds     })      .then(result =&gt; {         this.dispatchEvent(             new ShowToastEvent({                 title: 'Success',                 message: result,                 variant: 'success',             }),         );         return refreshApex(this.getContactList, { searchKeyWord: '$searchKeyWord' });     })     .catch(error =&gt; {         this.error = error;     });