I saw this shot in so many movies: Cape Fear (1991) also.  So what is the name of this shot used?
While watching  I noticed a very characteristic camera shot. At a scene where the main character, Wendy, sits in her room at the computer (watching the supposedly foretelling fotos), her sister talks to her from the outside (asking if she can have the camera/fotos). There is a certain camera shot, where on the left side a frontal close-up of Wendy's face is shown, while on the right side you see her sister standing in full height inside the open door.    This shot immediately struck me as being somehow characteristic and out of place and infused feelings to me of some kind of older Hitchcock or Brian De Palma thriller or something the like. I also think to remember of having seen this kind of shot or something similar used in , where Jessica Lange is shown in front of the dresser talking to Nick Nolte who stands in the door or father away.  I would like to know if this technique has a certain name or theory behind it and where its origins lie, or if there is any particular director or movie who made this famous. It may be even that Final Destination 3 uses this especially in reference to some director or movie.
Possible Duplicate:          On Windows I am able to switch between keyboard layouts by pressing Alt+Shift. Is there a similar keyboard shortcut in Ubuntu? 100% Delete U2 from iPhone? I've looked up many ways on how to deal with the U2 songs on my phone, but they will not go away what ever I try.  The most common solution for this problem is to "Show all" music, go to the Music, click the iCloud download button to download it and then turn off "Show all" button again. Generally, this would work but in my situation, it says I haven't purchased the song and I can't download the song again. The song still plays when I click on it, but I can't swipe left to delete and I can't hide it. And yes, I am signed into iTunes. And no, it is not under my purchased section.  Is there any other way to rid of this song?   EDIT:  I'm running iOS7.1.2 on a iPhone5c And the song(s) aren't in my iTunes. It says I have zero items in my iTunes library and it isn't under my purchased songs. The song is only on my iPhone, and I can't redownload it (to delete it again) because then I'd have to purchase the song again.  Thanks. Trying to remember a book about a human male travelling to alien planet Blown out blue/red light making photos look out of focus (Almost) double light speed Restored database missing views, stored procs and foreign keys What do the symbols in service --status-all mean? I really miss the graphical "Services" tool from older versions of Ubuntu, but I understand why it had to go. I always have terminals open anyway, so I use (because I have to now, I guess) service --status-all to see what services are running. This would be ok except that the command produces output like the following:   [ + ]  winbind  [ ? ]  wpa-ifupdown  [ - ]  x11-common   I'm guessing that those symbols mean something like listening, blocked, or stopped, but which is which? More importantly, why doesn't the man page say? Find a plane that passes through a point and is perpendicular to 2 planes Find an equation of a plane that passes through $p(1,5,1)$ and is perpendicular to planes $2x+y-2z = 2$ and $x+3z=4$.  I basically need the 2 other points to make the vector and perform the cross product.  Since $ax+by+cz+d=0$ is the form of a plane. Can I obtain the points as $(a,b,c)$ of the 2 planes given? Also, how can I set them up to obtain the points? Spam gets fairly heavily punished - 100 reputation penalty, if I recall correctly, and the content itself gets hidden in the revision history.  Now if we just have some rubbish:     dfajiojaifojadiofjadhigaowkokaomdiovnuiyhioqejgioqejgio   I'm not talking about someone posting a question or comment as an answer (i.e. possibly just not knowing the rules or being frustrated with not having the required privileges), or someone making some really horrible attempt at answering the question, I'm talking about an answer that clearly shows absolutely no observation of any content on the page.  This, in my opinion, causes a similar amount of harm to the site - I'm inclined to say the fact that someone posts spam isn't as important as the fact that they're posting something that needs to be deleted, since we're likely going to delete it pretty quickly, and they're (likely) behaving maliciously, or am I wrong?  Why don't we treat this equally harshly, or why do we treat spam as harshly as we do?    Side notes:  I'm sure I've seen a few times where users get punished for posting spam when their link is likely actually relevant to the question and useful (should I flag these? They are still link-only answers, so they shouldn't really come back, and often I'm just not sure enough). While false positives are bad, it seems worse that we're treating worse behaviour better.  I'm assuming that's not what "abusive" in this reason is referring to: (I'm also not sure, off the top of my head, how this one gets treated)     It is offensive, abusive, or hate speech Find where java class is loaded from How can I vertically align the numerators of two fractions? I am writing the following formula:  % arara: lualatex  \documentclass{article} \usepackage{mathtools} \usepackage{unicode-math}  \begin{document} \[y_\mathup{COG}=\frac{h}{3}\frac{l_\mathup{c,a}+2l_\mathup{c,i}}{l_\mathup{c,a}+l_\mathup{c,i}}\] \end{document}   which yields:    I don't like the way, the h and l_\mathup{index} is vertically aligned. Is that typical behavior? Good style? Could I avoid that? The use of hyphen in consecutive compounds I am not that punctuation-savy, so I have one question for my research title.  Currently it is      Social crowdfunding:  individual- and project-related determinants of success.    Empirical investigation on Kickstarter   Here I have two questions.   Is it right to say individual- or just individual?  Should there be a period after "Empirical investigation on Kickstarter"? I wanted to change my own password (as an admin) so I did the following command:  sudo passwd   and then it prompted for a password but when I tryed to relog, my password was not changed. I'm now wondering what password did I changed since it did prompted me to enter a password but I'm not sure what password did it changed exactly.  I know that if I do sudo passwd &lt;MY_USER&gt; it works, I'm just wondering without a user what happens.  Thank you How can I view all my unaccepted questions across SE? In most fiction I've read or encountered, the change occurs as a simple consequence of the lunar cycle. Though from what I know of Harry Potter, the change that takes place is due to sighting the full moon (as occurs in the third movie, Prisoner of Azkaban) where the gang, plus Lupin, Severus, Sirius and Pettigrew emerge from the Whomping Willow and upon sighting the full moon he begins to change.  Is this the trigger for werewolves in the Potterverse? If not, why did he (Lupin as an example, though for any werewolf in general) not change whilst in the shrieking shack that night?  Edit: This  addresses Lupin's change but I'm after more general information about werewolves. I seen many times how people describe how to's about LBP-2900, and 10-12 steps from start to end of how to download, unpack, build driver, fix driver, make it work... Could be there some .deb package with ready-to-go driver for Ubuntu? This printer is very popular... Drawing automata for languages I'm trying to draw two automata for these two languages:   For the first one, I know that the minimum is n = 1, m = 1, but I'm having troubles drawing a NFA for it.  The second one the minimum is n = 2, m = 1, but I still don't know how to start the NFA.  I have this for q2: Continuing my work through Dummit &amp; Foote's "Abstract Algebra", 3.1.36 asks the following (which is exactly the same as exercise 5 in ):     Prove that if $G/Z(G)$ is cyclic, then $G$ is abelian. [If $G/Z(G)$ is cyclic with generator $xZ(G)$, show that every element of $G$ can be written in the form $x^az$ for some $a \in \mathbb{Z}$ and some element $z \in Z(G)$]      The hint is actually the hardest part for me, as the quotient groups are somewhat abstract. But once I have the hint, I can write:  $g, h \in G$ implies that $g = x^{a_1}z_1$ and $h = x^{a_2}z_2$, so \begin{align*}gh &amp;= (x^{a_1}z_1)(x^{a_2}z_2)\\\  &amp;= x^{a_1}x^{a_2}z_1z_2\\\ &amp; = x^{a_1 + a_2}z_2z_1\\\ &amp;= \ldots = (x^{a_2}z_2)(x^{a_1}z_1) = hg. \end{align*} Therefore, $G$ is abelian.  1) Is this right so far?  2) How can I prove the "hint"? LWJGL Eclipse Resource Deployment I'm still experimenting with some OpenGL in LWJGL, and as I get to know more and more about OpenGL, I start to do more complicated things like multi texturing, shadowmapping and more. Now, right now I'm using the src folder (src/res) for my resources, and use src/resourcename in my code. When I export it, this won't work on another location as the relative path is ofcourse incorrect. What would be the best way of deploying your game with all the resources in one file? Maybe put the files in the jar?  I would like to hear from a few people how they store and deploy their project with resources, thanks! Prove This Inequality ${\pi \over 2} \le \sum_{n=0}^{\infty} {1 \over {1+n^2}} \le {\pi \over 2} + 1$ $${\pi \over 2} \le \sum_{n=0}^{\infty} {1 \over {1+n^2}} \le {\pi \over 2} + 1$$  I see I should use Riemann sum, and that $$\int_0^{\infty} {dx \over {1+x^2}} \le \sum_{n=0}^{\infty} {1 \over {1+n^2}}$$  But how do I explain this exactly, and how to get the other half of the inequality (with ${\pi \over 2} + 1$)?