I'm looking for a short and precise word to describe the use of the pronoun them with plurals, i.e. Let's kill them zombies! Them townsfolk sure are full of baloney. I hate them bees. It appears to be a fairly common solecism (?) in some areas/communities. It's also quite common in prose and pop culture. Does this convention have a name?  Inhabitants of the rural mid-west of Foobarland are in the habit of prefixing nouns with the word them, using the combined phrase as the subject or the object of a sentence. Descriptive grammarians refer to this pattern as the/a _______.
I've seen a lot of times the pronoun them used like an article. For example, in the title of the Delta Rhythm Boys Them bones, or in the first sentence of "Money for nothing":     Now look at them yo-yo's, that's the way you do it.   I know that it's not "proper English" (i.e., not something you'll use in a serious writing), but I'd like to know when it's commonly used, and why. Is there any difference between using it and using the?
Stop the Ubuntu updater from nagging about Firefox English Language pack even after uninstalling Firefox I have run sudo apt purge firefox, and I have gone through all of the /.config files, etc., and Software Updater is still asking me daily if I want to install the &quot;English Language Pack for Firefox&quot;. I don't have Firefox installed. How can I stop the updater from asking to update something on a program that doesn't exist? Output of dpkg -l | grep firefox: ii  firefox-locale-en                          88.0+build2-0ubuntu0.18.04.2        amd64        English language pack for Firefox Merge two arrays as key value pairs in PHP Let $F$ be a field and $F[x]$ a polynomial ring. Let $p(x)$ be an irreducible polynomial.  Show that $\gcd(p(x),q(x)) = 1\Longrightarrow \exists r(x),s(x)$ such that $r(x)p(x)+s(x)q(x) = 1$.  I know the proof for Bezout's identity for , but this proof uses the notion of absolute value, which cannot be applied to a polynomial ring.   I am thinking about a way to prove the statement: Use the Euclidean algorithm to compute $\gcd(p(x),q(x))$ and show that the result is $1$, and somehow go backwards to obtain $r(x)p(x)+s(x)q(x) = 1$, but it is a bit messy, and I'm not yet able to see it completely.  Please offer some help. If you have some other methods, that would be great, too. Proving that $1+x^py^{1-p} \le (1+x)^p(1+y)^{1-p}$ I'd like to show that $1+x^py^{1-p} \le (1+x)^p(1+y)^{1-p}$ for all $x,y \ge 0$ and $p \in [0,1]$. I started out by defining a function $f(x,y)=(1+x)^p(1+y)^{1-p}$ and checking for critical points, but there are none in the domain I'm interested in. I think I'm probably missing a slick application of Jensen's or Holder's inequalities, but so far a proof eludes me. Any suggestions would be appreciated. command not found and syntax error near unexpected token System installation is stalled on Compaq Presario R3000 derivative of cost function for Logistic Regression I am going over the lectures on Machine Learning at Coursera.   I am struggling with the following. How can the partial derivative of   $$J(\theta)=-\frac{1}{m}\sum_{i=1}^{m}y^{i}\log(h_\theta(x^{i}))+(1-y^{i})\log(1-h_\theta(x^{i}))$$  where $h_{\theta}(x)$ is defined as follows  $$h_{\theta}(x)=g(\theta^{T}x)$$ $$g(z)=\frac{1}{1+e^{-z}}$$  be $$ \frac{\partial}{\partial\theta_{j}}J(\theta) =\sum_{i=1}^{m}(h_\theta(x^{i})-y^i)x_j^i$$  In other words, how would we go about calculating the partial derivative with respect to $\theta$ of the cost function (the logs are natural logarithms):  $$J(\theta)=-\frac{1}{m}\sum_{i=1}^{m}y^{i}\log(h_\theta(x^{i}))+(1-y^{i})\log(1-h_\theta(x^{i}))$$ Evaluating the integral $\mathop{\lim}\limits_{n \to \infty} \int_{-1}^{1} f(t)\cos^{2}(nt) \ dt $ Given that $f\colon [-1,1] \to \mathbb{R}$ is a continuous function such that $ \int_{-1}^{1} f(t) \ dt =1$, how do I evaluate the limit of this integral: $$\lim_{n \to \infty} \int_{-1}^{1} f(t) \cos^{2}{nt} \,dt$$   What I did was to write $\cos^{2}{nt} = \frac{1+\cos{2nt}}{2}$ and substitute it in the integral so that I can make use of the given hypothesis of $\int_{-1}^{1} f(t) \ dt =1$. So the integral becomes,   \begin{align*} \int_{-1}^{1} f(t)\cos^{2}{nt} \ dt = \int_{-1}^{1} f(t) \biggl[\frac{1+\cos{2nt}}{2}\biggr] \ dt  &amp;  \\  \hspace{3cm} = \frac{1}{2}\int_{-1}^{1}f(t) \ dt + \int_{-1}^{1} \frac{f(t)\cos{2nt}}{2} \ dt \end{align*}  But I don't really know how I can evaluate the second integral and also I can't realize as to why that integral condition on $f$ has been assumed. Moreover without assuming that condition on $f$ is it possible to evaluate this integral? If yes, then what would the answer be? Getting from Denver Amtrak to Fort Collins The eastbound Amtrak arrives Denver 6:38 PM (18:38).  How can I get to Fort Collins from there?   The  runs  from Denver International Airport to Fort Collins, but the airport is 40 km from the Amtrak station, so that's a major detour, that would mean taking bus FX from Market Street Station 7:18 PM, arriving at the airport at 8:27 PM, then the super shuttle 9:05 PM, arriving Fort Collins CSU at 10:55 PM; almost 4 hours after departing from Denver. Greyhound Lines appears to have a bus departing 12:45 AM, arriving 02:00 AM — although probably as quick as it gets, this is not exactly a comfortable time. RTD Denver has transportation to Longmont and  from Longmont to Fort Collins, but  appears to depart 7:05 PM — so I won't make it there when arriving by Amtrak.  A taxi would cost an estimated .   Is there any other way to get to Fort Collins when arriving by the eastbound Amtrak, any way that I've missed? Accidentally turned on talkback I accidentally turned on talkback in the Accessibility menu. When I turned it on I got some kind of walk through on how to use it. I couldn't cancel it. So I turned off my phone.   When I turned it back on again it took me 15 minutes to unlock my phone. Apparently I had to touch a button to give it focus and then double tap it to click it.   Now my question is: how do I turn this off? I can't reach the settings because I have don't know how to access a drop down and I can't scroll through all my apps. Which is correct, "neither is" or "neither are"? How to remove GNOME Shell from Ubuntu 20.04 LTS to install other desktop environment from scratch? Is it possible to install Ubuntu without formatting any partitions? Can I install Ubuntu without formatting any partitions on my hard drive?  I am already running Windows 7 and I want to install Ubuntu as well without formatting any of the partitions I have already created. This problem comes from , who do not rigorously demonstrate (in their solution key) that the statistic is not sufficient.  Let $X_1,\dots,X_n$ be a random sample from a population with PDF $f(x|\theta)=\theta x^{\theta-1} \cdot 1_{\{x\in(0,1)\}}$ for $\theta&gt;0$. Show that $\sum_i X_i$ is not sufficient for $\theta$.  If you write out the PDF $p(\vec{x}|\theta)$ of the random sample, it is clear by the factorization theorem that $\prod_i X_i$ or $\sum_i \log(X_i)$ are sufficient for $\theta$; the PDF $p$ also suggests $\sum_i X_i$ is not sufficient for $\theta$. However, to rigorously demonstrate this, we need to analyze $p(\vec{x},\theta)/q(T(\vec{x},\theta)$, where $p$ is the distribution of sample $\vec{x}$, $q$ is the distribution of the statistic $T(\vec{X})=\sum_i X_i$. But finding the distribution of $T(X)=\sum_i X_i$ seems impractical. I have observed that $f$ is the PDF of a Beta($\theta$,1) distribution, but checking online, the distribution of the sum of Beta random variables doesn't appear to have a closed form. Are there any alternative routes (e.g., showing there is no factorization involving $T(\vec{X})$)? Did C&amp;B leave out a full explanation that $\sum_i X_i$ is not sufficient because none actually exist? How can I figure out why my washing machine is tripping the GFCI receptacle? I have a Kenmore 80 Series (Model No. 110.24872300) washing machine which up to this point has been working fine. Since it is near a sink, the outlet it is plugged into is a GFCI outlet. On the last load I came back after letting it run for some time to find that it had tripped the GFCI in the middle of the wash cycle - the washer was still full of soapy water. I reset the outlet and let it run again, only to come down the next morning and find it full of water still (it had tripped during the rinse cycle this time). I reset the outlet again and this time it finished the rest of the cycle.  My guess is that water is somehow getting onto the internal components of the washer and causing it to short - is there any way I can test this theory or fix the problem myself? With all the new sites up and running it gets more and more difficult for users to really know the scope of a site and thus a lot of questions a migrated to places where they are (probably even more) off-topic, see e.g. . So I request the opposite of :  Allow migration if you have enough rep on both the source and the target site (the target reputation required could be a bit lower, say 5001)  That way questions could only be migrated by users familiar with the scope of both sites who can really estimate where the question is better. Maybe those who don't have the rep on the target site could still be able to cast a flagging-only-but-not-counting-as-vote vote...  1) Courtesy of How to mount an internal HDD on start-up? I have a 500GB internal HDD where I store all my music and photos but it is annoying to manually mount it after a restart and I was wondering how to mount it automatically and make it available to Rhythimbox for playback.  Thanks! Fine-tuning "Open safe files after downloading" 100% Delete U2 from iPhone? I've looked up many ways on how to deal with the U2 songs on my phone, but they will not go away what ever I try.  The most common solution for this problem is to "Show all" music, go to the Music, click the iCloud download button to download it and then turn off "Show all" button again. Generally, this would work but in my situation, it says I haven't purchased the song and I can't download the song again. The song still plays when I click on it, but I can't swipe left to delete and I can't hide it. And yes, I am signed into iTunes. And no, it is not under my purchased section.  Is there any other way to rid of this song?   EDIT:  I'm running iOS7.1.2 on a iPhone5c And the song(s) aren't in my iTunes. It says I have zero items in my iTunes library and it isn't under my purchased songs. The song is only on my iPhone, and I can't redownload it (to delete it again) because then I'd have to purchase the song again.  Thanks. How are Anonymous inner classes used in Java?