There was &quot;&quot; pdf in the 2016 playtest material. A Beastmaster Ranger was considered the weakest class by many GMs and players, which apparently caused the need for a &quot;revised&quot; version. However, I've never heard how exactly the playtesting ended. Googling &quot;ranger revised&quot; gives me the same 2016 pdf and nothing more. What happened to the &quot;revised&quot; ranger from the Unearthed Arcana? Was it renamed from &quot;revised&quot; to something else? Was it published in any official source book, changed or unchanged? (I don't have access to all of them so I can't check it myself for now) Or was it abandoned by WoTC? This is a technical duplicate of , which was answered in 2017, but things probably changed in 2021, so that accepted answer doesn't answer the question anymore. Also, I'm asking about Beastmaster Ranger specifically, which could be changed/revised in latter source books (XGtE,TCoE, whatever) as an additional Ranger archetype.
14 months ago, an  supplement was published that discussed how the ranger described in the Player's Handbook was under powered. These rules reimagined the ranger's abilities, and suggested that an official version would be released later.     Finally, we come to implementation. If this iteration of the ranger, or a future revision of it, grades high enough, our plan is to present it as a revised ranger in a future D&amp;D sourcebook.   Does that Sourcebook exist yet? If not, have the devs given an update or told us their intentions?
What does "xmlns" in XML mean? What is the ancestral form of language used in the fable that David was studying during the flight? David studies linguistics during the flight to LV-223. We get to listen and read a fable. Is it written in a real language? What is the name of the language? Can the fable be translated?  Approximate quotation:     hjewis jasma hwaelna nahast akwunsez dad'kta, tam ghermha vagam ugenthe Find the exact value of the infinite sum $\sum_{n=1}^\infty \big\{\mathrm{e}-\big(1+\frac1n\big)^{n}\big\}$ How can we find the exact value of the infinite sum  $$ \displaystyle\sum_{n=1}^\infty \left\{\mathrm{e}-\Big(1+\frac1n\Big)^n\right\}? $$  This problem appears in:  , p.114. Could someone please tell me what the symbol ringed in red represents?     I know it has ON Switch pointing to it, but the symbol has other lables in different parts of the document. Transforming the dummy values to be able to take logs I have a panel data model with double-log functional form. I have 4 variables, one of which is a dummy. What is the best way to transform the values of 0 for my dummy to be able to take natural logs (since you can't take logs from zero)? I have found 2 options so far, but I dont know which is the best (or perhaps there is a 3rd option).  1) Transform all the values of 0 into a very small value (0.00000000001) and then take the logs. I'm not sure this wouldn't still change the outcome of my model quite a bit. 2) Change the values of 0 into 1 and the dummy values of 1 into e (the base of natural logarithm). The log of this newly defined dummy then takes on the values of zero and one and the interpretation of my betas would remain the same. Can you read my proof and tell me if it's correct? Thanks.  Let $V$ be a vector space over a complete topological field say $\mathbb R$ (or $\mathbb C$) with $\dim(V) = n$, base $e_i$ and norm $\|\cdot\|$. Let $v_k$ be a Cauchy sequence w.r.t. $\|\cdot\|$. Since any two norms on a finite dimensional space are equivalent, $\|\cdot\|$ is equivalent to the $l^1$-norm $\|\cdot\|_1$ which means that for some constant $C$, $\varepsilon &gt; 0$, $k,j$ large enough, $$ \varepsilon &gt; \|v_j - v_k\| \geq C \|v_j - v_k\|_1 e_i= C \sum_{i=1}^n |v_{ji} - v_{ki}| \geq |v_{ji} - v_{ki}|$$ for each $1 \leq i \leq n$. Hence $v_{ki}$ is a Cauchy sequence in $\mathbb R$ (or $\mathbb C$) for each $i$. $\mathbb R$ (or $\mathbb C$) is complete hence $v_i = \lim_{k \to \infty} v_{ki} $ is in $\mathbb R$ (or $\Bbb C$) for each $i$. Let $v = (v_1, \dots , v_n) = \sum_i v_i e_i$. Then $v$ is in $V$ and $\|v_k - v\| \to 0$:  Let $\varepsilon &gt; 0$. Then $$ \|v_k - v\| \leq C \|v_k - v\|_1 = C \sum_{i=1}^n |v_{ki} - v_i| \leq C^{'}n \varepsilon$$  for $k$ large enough. At the moment the most frustrating part of my brewday is getting the cold wort into the fermenter. Here is my process. I have a 20 litre saucepan that i use as a kettle that does not have a tap. At flame out I add my immerseion chiller that is plumbed into my kitchen sink tap. When I have reached temperature I remove the chiller and whirlpool and leave it to rest to 30 minutes. I am use a siphon to rack directly into the plastic bucket fermenter.  The problem is that the siphon always gets clogged with the hops after i have only transfered about 20% of the wort. I have also tried carefully pouring the wort through a seive, but this sort of depfeats the point of the whirlpool and also the seive got blocked with hops as well. All in all i end up wasting a lot of the wort because i am afraid of getting a lot trub in the fermenter.  What are the best processes to use with my current equpment to get the wort into the fermenter? Python multiprocessing: restrict number of cores used If $f'$ is bounded, then $f$ is uniformly continuous Let $f\colon(a,b) \to \mathbb R$ be differentiable and suppose that there exists an $M&gt;0$ such that $|f&#39;(x)| \leq M$ for all $x$ in $(a,b)$. Prove that $f$  is uniformly continuous. Event binding on dynamically created elements? Why not make it mandatory to leave a reason or at least a remark of some sort whenever down voting?  You see more and more often questions being down voted while many times they are simply perfectly legitimate, as questions/as people being unable to achieve some desirable result. I am not talking about "Hey, please do this and that for me, thanks :D " posts.  I would like to know what reasons there are for not making it mandatory to leave a reason for a down vote. I Need to Shrink My Database - I just freed a lot of space This question is asked in various forms here but the question boils down to:  I know shrinking a database is risky. In this case, I've removed so much data and I'll never use it again.   How can I shrink my database? What files do I shrink?  What should my considerations be while doing this?  Should I do anything after? What if it is a large database? Can I shrink it in smaller increments? I have a Dell XPS 12 running Ubuntu 13.10 and it doesn't appear to find it's wireless.  I have tried the suggestions  but they made no difference  peter@xps:/lib/firmware$ ls -l /lib/firmware/iwlwifi-7260-7.ucode  -rw-r--r-- 1 root root 682892 Aug  4 12:50 /lib/firmware/iwlwifi-7260-7.ucode peter@xps:/lib/firmware$ sudo lshw -c network   *-network UNCLAIMED             description: Network controller        product: Wireless 7260        vendor: Intel Corporation        physical id: 0        bus info: pci@0000:06:00.0        version: 63        width: 64 bits        clock: 33MHz        capabilities: pm msi pciexpress cap_list        configuration: latency=0        resources: memory:f7c00000-f7c01fff  peter@xps:~/backports-3.10-2$ grep IWL7260_UCODE_API_MAX drivers/net/wireless/iwlwifi/iwl-7000.c  #define IWL7260_UCODE_API_MAX   7     .ucode_api_max = IWL7260_UCODE_API_MAX,         \ peter@xps:~/backports-3.10-2$ dmesg | grep iwl peter@xps:~/backports-3.10-2$ iwconfig lo        no wireless extensions.  peter@xps:~$ find / -name *7260-6* peter@xps:~$ find / -name *7260-7* /lib/firmware/iwlwifi-7260-7.ucode   peter@xps:~$ dmesg | grep -i -A 20 intel [ 1318.013278] Intel(R) Wireless WiFi driver for Linux, in-tree:d [ 1318.013281] Copyright(c) 2003-2013 Intel Corporation [ 1318.015154] cfg80211: World regulatory domain updated: [ 1318.015157] cfg80211:   (start_freq - end_freq @ bandwidth), (max_antenna_gain, max_eirp) [ 1318.015159] cfg80211:   (2402000 KHz - 2472000 KHz @ 40000 KHz), (300 mBi, 2000 mBm) [ 1318.015161] cfg80211:   (2457000 KHz - 2482000 KHz @ 40000 KHz), (300 mBi, 2000 mBm) [ 1318.015162] cfg80211:   (2474000 KHz - 2494000 KHz @ 20000 KHz), (300 mBi, 2000 mBm) [ 1318.015164] cfg80211:   (5170000 KHz - 5250000 KHz @ 40000 KHz), (300 mBi, 2000 mBm) [ 1318.015165] cfg80211:   (5735000 KHz - 5835000 KHz @ 40000 KHz), (300 mBi, 2000 mBm)     What I have found is that it appears to be loading an old version of the firmware but I don't know how or why  peter@xps:/lib/firmware$ modinfo iwlwifi | grep 7260 firmware:       iwlwifi-7260-6.ucode peter@xps:/lib/firmware$ ls *7260-6* ls: cannot access *7260-6*: No such file or directory   Any suggestions of how to get this setup very welcome. Nested indenting issue How to get correct indentation after entering a nested list? I am writing a code review and I could not figure this out by googling. Here is an example of the three formatting styles I tried to use (but none of them works as I would like):  Case 1  The task is to align the last line (see below) "In the first line you use camelCase..." with the last line above the numbered list. In my first attempt, I added a new line (empty line) after the second numbered list item, and then indented by 4 spaces:     Variable name casing: See  on "Snake Case". In Perl, we use "snake_case" instead of "camelCase", and be consistent. Example:   Line 14: my $testType  Line 18: my $right_frame   In the first line you use camelCase, whereas in the second you use     snake_case.     As you can see, this gives the correct indentation but it introduces a blank line above the first numbered item.  Case 2  In this case I do not add the blank line after the second numbered list item ( but still indent by 4 spaces ):     Variable name casing: See  on "Snake Case". In Perl, we use "snake_case" instead of "camelCase", and be consistent. Example:   Line 14: my $testType  Line 18: my $right_frame In the first line you use camelCase, whereas in the second you use     snake_case.      In this case the line is considered as part of the last list item  Case 3  In this case, I try to add two blank spaces (invisible) at the end of the second list item:     Variable name casing: See  on "Snake Case". In Perl, we use "snake_case" instead of "camelCase", and be consistent. Example:   Line 14: my $testType  Line 18: my $right_frame In the first line you use camelCase, whereas in the second you use     snake_case.      In this case the line is considered part of the second item, and hence not correctly indented.  How to achieve the correct indentation? How long should it take to refresh a Developer Sandbox? I refreshed a Developer Sandbox, and almost 24 hours it is still "pending". Is this normal? Are there any actions I can take to speed up the process? When I created the Sandbox it took barely more than 10 minutes to create.  Thanks, Adrian Remove Meta Privilege for MSE (only) Is there anything in the physics that enforces the wave function to be $C^2$? Are weak solutions to the Schroedinger equation physical? I am reading the beginning chapters of Griffiths and he doesn't mention anything. Is every metric space a subspace of some connected metric space? Is every metric space a subspace of some connected metric space? If the space itself is connected then we're done, but if not then I think we can extend our metric space to make it connected.  I'm not sure whether this will work or not, but intuitively I think the answer is yes. In electromagnetism, why does nature prefer the right-hand rule over the left-hand rule? At school I learnt the  to remember the resulting direction of different phenomena, such as geometrical cross products, mechanical torque, or the direction a screw will move when turning it. This directions are however decided by humans, and we could have easily defined the directions in the opposite way.  However the right hand rule also predicts phenomena which is not arbitrarily set by humans, but is intrinsic to the nature. If you have a coil in which you put some current, and the nature creates a magnetic field in a direction perpendicular to it, the direction depends on the right hand rule.  My question is, why this direction and not the opposite? Nature tends to be symmetric and not have apparent preferences for two equal options, so in a so why is one direction preferred over the other one? Why doesn't a "left hand" rule apply? How do I get on a Minecraft PE server when it says 'invalid name'? I am having trouble getting onto a server in Minecraft PE on iOS. When I tap on the person's server it just says invalid name:    I have tried turning off and restarting the iPad, going to home screen and logging back into the server but I have had no luck and no change. Is there a reason why this is so?