I bought a USO call option before the reverse stock split and thought it was worthless because nobody is able to purchase it (nobody wanted to purchase it) but today after hours I checked and it increased a whole 100% in value. How are people able to purchase it? Why would they want to purchase it?   $2.5 USO1 call Exp 5/8      4/29 = $.04      4/30 = $.08
Today 4/30/20 my seemingly worthless USO call option increased in value.   Specifically: USO1 $2.5 Call 5/8  On 4/29 it was valued at $.04 and stayed there.   4/30 I checked after hours and now it’s up to $.08? Which was wasn’t even the highest it went to today.  So who is buying this contract?  Who is allowed to buy this contract? Bc I’m only able to sell and from what I understood, nobody is able to buy it.   I have screenshots and will post if requested. Thank you
how to stop working for other people's thesis? Last semester, I took a course with my supervisor and he assigned me a project. This project is part of one of his student's theses. I did the project and passed the course.   Later, I was asked to upload my code for use in a paper. It turned out that the data the grad student had generated was not appropriate, and he needed to do other experiments. It later turned out there were other problems with the underlying model, and I redid a lot of that work as well.  The problem is that this other student is not really contributing at all.    Sometimes he does not come to work at all On one occasion the professor assigned us to do something, and he immediately told me he had no idea how to do it In one of our meetings with the professor, he talked 2 minutes with the prof with no slides; I talked for the other 58 with slides.    What should I do in this situation? I could not work like this, I have my own project and my thesis and stuff. 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Thanks. not working in Phonegap app on Android 2.3.3 More Efficient Spatial join in Python without QGIS, ArcGIS, PostGIS, etc I'm attempting to do a spatial join much like the example here: . However, that approach seems really inefficient / slow. Even running this with a modest 250 points takes almost 2 minutes and it fails entirely on shapefiles with > 1,000 points. Is there a better approach? I'd like to do this entirely in Python without using ArcGIS, QGIS, etc.  I'd also be interested to know if it's possible to SUM attributes (i.e. population) of all the points that fall within a polygon and join that quantity to the polygon shapefile.       Here is the code I'm trying to convert. I get an error on line 9:  poly['properties']['score'] += point['properties']['score']   which says:     TypeError: unsupported operand type(s) for +=: 'NoneType' and 'float'.    If I replace the "+=" with "=" it runs fine but that doesn't sum the fields. I've also tried making these as integers but that fails as well.  with fiona.open(poly_shp, 'r') as n:    with fiona.open(point_shp,'r') as s:     outSchema = {'geometry': 'Polygon','properties':{'region':'str','score':'float'}}     with fiona.open (out_shp, 'w', 'ESRI Shapefile', outSchema, crs) as output:         for point in s:             for poly in n:                 if shape(point['geometry']).within(shape(poly['geometry'])):                       poly['properties']['score']) += point['properties']['score'])                     output.write({                         'properties':{                             'region':poly['properties']['NAME'],                             'score':poly['properties']['score']},                         'geometry':poly['geometry']}) I have the bike, I have the best route; but now I want to know, how do I transport my clothing in each day? I typically wear suit pants and a business shirt, but not a suit jacket.   Am I better off leaving my clothes at work, or is there a special bag that would let me carry in shirt/pants without them getting crushed? Multiple Inheritance in java I have a netbook with an AZERTY layout. I've changed it to "bépo" to try it, but now I've reset it to a french layout.  While all the apps have taken the change into account, Ubuntu's login manager still uses bépo, making entering passwords a challenge. I've enabled the virtual keyboard for the time being so that I could login again.  I don't remember what I had done in the first place to switch the login screen to bépo, but now I can't switch it back.    EDIT : In the keyboard settings page, if I click "use system defaults", then everything is in bépo ! Where is this different keyboard layout set ?  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Here's a picture of how it is and how I want it below:   And here's my code:  \documentclass{standalone} \usepackage{pgfplots,pgfplotstable} \begin{document} \begin{tikzpicture} \begin{axis}[ symbolic x coords={E1, E4 (dyn.), E2, E5 (dyn.), E3, E6 (dyn.)}, xtick=data, width=\linewidth, height=6cm ] \addplot[ybar,fill=blue, bar width = 1cm] coordinates {     (E1,   8)     (E2,  15)     (E3,   50)     (E4 (dyn.), 4)     (E5 (dyn.), 17)     (E6 (dyn.), 40)  }; \end{axis} \end{tikzpicture} \end{document}   I hope you can help me. Thanks. It seems that they can all mean "easily provoked to anger"  irascible：Easily provoked to outbursts of anger; irritable.  fractious：Irritable; argumentative; quarrelsome.  irritable：1.Capable of being irritated. 2.Easily exasperated or excited.  atrabilious：1.Characterized by melancholy. 2.ill-natured; malevolent. Recently I came across a debate about whether it's fair to call RAW 'unprocessed' or 'unaltered' sensor data of a DSLR. As far as I know, the analog sensor data is processed into a digital RAW file using the ISO setting, a process during which the Bayer-sensor data is demosaiced as well. However, those are just the necessary steps for saving a digital file while maintaining maximum quality.  Are those assumptions correct? If so, are there any additional steps that need to be performed between the sensor receiving light and the saving of the RAW file? And can those be reasonably be described as an 'alteration' of the sensor data, or is it fair to say that a RAW file holds the unaltered sensor data? Does measurement, quantum in particular, always increase the total entropy? Draw integers independently & uniformly at random from 1 to $N$ using fair d6? When is $\phi(n)$ a prime number? I was thinking about this problem today. If $p$ divides $n$, then $p-1$ must divide $\phi(n)$. But $p-1$ is even for all primes greater than $2$, so must $\phi(n) = 2$ - the only even prime? 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