I'd like to spread out my references between multiple bibtex files. I tried putting all my references into a file called etho.bib, then put \input{etho.bib} into my main bibtex file. This didn't word. I also tried using \include instead of \input and etho.tex instead of etho.bib, but none of that work.  Is there some way for the bibtex compiler to include text from another document into your .bib file?
I would like to use multiple .bib files for my article, such as file1.bib, file2.bib. However, I would like my references not to be separated (such as &quot;Primary sources&quot;, &quot;Secondary sources&quot;, etc.). These bibliographies just need to be merged into one. One way to do this is to copy-paste these .bib files into one .bib file, and this would solve the problem. However, I would like to keep it split into several .bib files, by topic (file1.bib contains articles on topic1, file2.bib contains articles on topic2, and so on). I tried to do \bibliographystyle{alpha}  \bibliography{file1} \bibliography{file2}  but this just gives me the same bibliography twice!
I am very new to the TikZ package, and I need to draw some flow chars by using the following shapes.   However I couldn't figure out how to draw the 4th and and 6th ones below. It would be very nice (for completeness) to help with all of the shapes in the list below.      Your help will be greatly appreciated.  Note: I have visited  but it contains some other shapes. 14 months ago, an  supplement was published that discussed how the ranger described in the Player's Handbook was under powered. These rules reimagined the ranger's abilities, and suggested that an official version would be released later.     Finally, we come to implementation. If this iteration of the ranger, or a future revision of it, grades high enough, our plan is to present it as a revised ranger in a future D&amp;D sourcebook.   Does that Sourcebook exist yet? If not, have the devs given an update or told us their intentions? My daughter applied at the Italian Consulate in Philadelphia, and they gave her two entries for 20 days (we thought it was for 20 days each entry). She was in Italy 12 days, then went to England for 1 week and flew to Venice to take a 10-day cruise. She couldn't make it because they said she has only 8 remaining days, but she still has a land tour already paid this week.  What can she do? Can she extend the Schengen visa for 12 more days? Right now, she is in Madrid, but next week she has to fly from Barcelona to Paris to start with the tour. What would happen if she decides to take the tour with the expired visa? She is a US permanent resident. Change rep required to downvote on MSE What is the 64-bit Firefox Beta PPA? $$\lim_{x \to 0} \frac{f(x)}{|x|}=1$$ Then prove that $f$ is not differentiable at $0$. I was given this assignment and I'm not sure about my proof.. it feels like I'm assuming too much and not explaining with enough detail. Is there anything I need to add to make it sufficient? Assume toward contradiction that $f$ is differentiable at $0$. Then by definition we know that $f$ is continuous at $0$. Therefore $\lim _{x\to 0}f\left(x\right)=f\left(0\right)$ We know that $\lim _{x\to 0}\frac{\left(f\left(x\right)\right)}{\left|x\right|}=1$ Therefore we can conclude $\lim _{x\to 0}\frac{\left(f\left(x\right)\right)}{\left|x\right|}\cdot \left|x\right|=1\cdot 0=0$ But we can also rewrite this as $\lim _{x\to 0}\left(f\left(x\right)\right)\cdot \frac{\left|x\right|}{\left|x\right|}=f\left(0\right)\cdot 1=0$ Therefore $f(0) = 0$. Since $f$ is differentiable at $0$ we have $\lim _{x\to 0}\frac{\left(f\left(x\right)-f\left(0\right)\right)}{x-0}=\lim _{x\to 0}\frac{\left(f\left(x\right)-0\right)}{x}=\lim \:_{x\to \:0}\frac{\left(f\left(x\right)\right)}{x}\cdot \frac{\left|x\right|}{\left|x\right|}=\lim \:\:_{x\to 0}\frac{\left(f\left(x\right)\right)}{\left|x\right|}\cdot \:\frac{\left|x\right|}{x}$ Since the one sided limits of $\frac{f\left(x\right)}{\left|x\right|}$ exist, and are both equal to 1, we have $\lim \:_{x\to 0^+}\frac{\left(f\left(x\right)\right)}{\left|x\right|}\cdot \:\:\frac{\left|x\right|}{x}=\lim \:_{x\to \:0^+}\frac{\left(f\left(x\right)\right)}{x}\cdot \:\:\:\frac{x}{x}=1\cdot 1=1$ $\lim \:_{x\to 0^-}\frac{\left(f\left(x\right)\right)}{\left|x\right|}\cdot \:\:\frac{\left|x\right|}{x}=\lim \:_{x\to \:0^-}\frac{\left(f\left(x\right)\right)}{-x}\cdot \:\:\:\frac{-x}{x}=1\cdot -1=-1$ Since the limit doesn't exist, we have a contradiction to the fact $f$ is differentiable at $0$. Therefore $f$ is not differentiable at 0. How to get city name from latitude and longitude coordinates in Google Maps? How does equality $\mathfrak{m}^\mathfrak{m} = 2^\mathfrak{m}$ in $\sf{ZF}$ relate to the axiom of choice? Usually, the equality $\mathfrak{m}^\mathfrak{m} = 2^\mathfrak{m}$ for infinite cardinal $\mathfrak{m}$ is proved like that: $$ 2^\mathfrak{m} \leqslant \mathfrak{m}^\mathfrak{m} \leqslant (2^\mathfrak{m})^\mathfrak{m} = 2^{\mathfrak{m} \cdot \mathfrak{m}} = 2^\mathfrak{m} $$ The last step relies much on the axiom of choice, because the fact $\mathfrak{m}\cdot\mathfrak{m} = \mathfrak{m}$ does. Moreover,  states that in $\sf{ZF}$ this fact is equivalent to $\sf{AC}$.  Note, by a cardinal I mean an equipollence class of an arbitrary set, not necessarily admitting a well-ordering.  That has motivated my question: what can we say about relationship of the initial equality and the axiom of choice in pure $\sf{ZF}$?    To avoid question about definition of cardinals without $\sf{AC}$, we may consider the following statement instead:     For any infinite set $X$ exists a bijection $\; F \, \colon X^X \rightarrow 2^X$   where $X^X$ is the set of all functions from $X$ to $X$, $\; 2^X = \mathcal P(X)$ is the power set, and an infinite set is such that cannot be bijectively mapped onto a finite ordinal. How do I calculate a time delta in my Google Spreadsheets? I've got a Google Spreadsheet that looks roughly like this:   Date        | Start time  | End time    | Minutes  ------------+-------------+-------------+-----------  1/11/2012   | 11:39       | 12:41       | ?!  ------------+-------------+-------------+-----------              |             |             |    Right now if I fill in the number of minutes between the two times of day by hand. Is there a straight-forward way to calculate a time delta and have the spreadsheet do it for me? Story on quantum indeterminacy: protagonist has to “quantum select” a portable computer’s state There are many times when I curse the autocorrection mechanism for changing what I typed, but overall, much of the corrections are welcome so I don't really want to disable it. I do want to have it do it's work but alert me when it makes each change so I don't have to proofread everything or focus with perfect attention to the screen to see the momentary red and/or blue underlining that alerts me to the machine override.  I would love a way to turn on an audible beep (customizable of course) so that I also get a warning each time my typing gets corrected (and only when autocorrection occurs). Let $n \in ℕ$. Show that the ring $ℤ/nℤ$ is a field if and only if $n$   is prime.   Let $n$ prime. I need to show that if $\bar{a} \neq 0$ then $∃\bar b: \bar{a} \cdot \bar{b} = \bar{1}$. Any hints for this ?  Suppose $ℤ/nℤ$ is a field. Therefore: for every $\bar{a} \neq 0$ $∃\bar b: \bar{a}\cdot \bar{b}=1$. How can I show that $n$ must be prime ? .NET create scheduled task on server fails with E_ACCESSDENIED I have an ASP.NET website (in C#) that takes in user data and then attempts to create a windows scheduled task.  Of course, this works great on the DEV machine, but fails to run on the server.  I'm trying to figure out what permission(s) are required on the ASPNET user (or anonymous web user) to create tasks.  The error is:  Access is denied. (Exception from HRESULT: 0x80070005 (E_ACCESSDENIED))  Stacktrace:      at MyScheduler.NewWorkItem(String TaskName, Guid&amp; rclsid, Guid&amp; riid, Object&amp; obj)      at MyScheduler.CreateTask(String name)   I've done some searching, and the suggested resolution is to use the web.config 'impersonate' flag to force the application to run as a user with sufficient permissions, as opposed to the ASPNET account which may not have those permissions.  Example:  &lt;system.web&gt;     &lt;identity impersonate="true" /&gt; &lt;/system.web&gt;    Unfortunately, this does not seem to resolve the issue.  From the documentation I read, this should run as the anonymous web user, but it seems that user does not have enough permissions.  I altered the setting to specify a specific domain user that happens to be an administrator on the machine.  Example:  &lt;system.web&gt;     &lt;identity impersonate="true" userName="WindowsDomain\YourUserName" password="YourPassword" /&gt; &lt;/system.web&gt;    Doing this allowed the application to successfully create the Windows Scheduled Task.  So, obviously, with the correct set of Windows 2003 permissions I can get the app to perform as it does in the development environment.  However, I'm not about to place the network or machine administrator account's user credentials in plain text on a Web.config file.  Does anybody happen to know what permissions exactly need to be set in order to get the ASPNET account to behave as desired?  EDIT:  The Win32 API is being used to create scheduled tasks. What countries allow me to pass their borders visa-free?  Am I allowed to visit and work in EU and Schengen countries? If I have a tar file, bob.tar, which contains real_file and link_to_real_file, in which the latter is a symlink, is there a way to extract the contents of bob.tar so that link_to_real_file will not be a symlink, but be a copy of real_file.    I know this is indeed possible on the creation side, if I use the -h flag.    The command tar -cvhf bob.tar real_file link_to_real_file will dereference link_to_real_file, but I want to do this on the extraction side regardless of how the tar file was created. timestamp, modification time, and created time of a file How to initialize a JavaScript Date to a particular time zone How to hook into the CPT's title placeholder? I want to change the default placeholder text in my Custom Post Type title field. This isn't possible while registering a new post type.  The following screenshot describes it. Given a large (~ 1 million) sample of unevenly distributed points - is it possible to generate irregular grid (in size, but could also be irregular in shape if that is possible?) that will contain specified minimum amount of n points?   It is of less importance for me if genereted 'cells' of such grid contain exactly n number of points or at least n points.  I'm aware of solutions like  in ArcGIS or  in QGIS/mmgis however they will all create regular grids which will result in an output with empty cells (smaller problem - I could simply discard them) or cells with count of points less than n (bigger problem since I'd need a solution to aggregate those cells, probably using some tools from ?).  I've been googling around to no avail and am open to both commercial (ArcGIS &amp; extensions) or free (Python, PostGIS, R) solutions. What does the "yield" keyword do? What is the use of the yield keyword in Python? What does it do? For example, I'm trying to understand this code1: def _get_child_candidates(self, distance, min_dist, max_dist):     if self._leftchild and distance - max_dist &lt; self._median:         yield self._leftchild     if self._rightchild and distance + max_dist &gt;= self._median:         yield self._rightchild    And this is the caller: result, candidates = [], [self] while candidates:     node = candidates.pop()     distance = node._get_dist(obj)     if distance &lt;= max_dist and distance &gt;= min_dist:         result.extend(node._values)     candidates.extend(node._get_child_candidates(distance, min_dist, max_dist)) return result  What happens when the method _get_child_candidates is called? Is a list returned? A single element? Is it called again? When will subsequent calls stop?   1. This piece of code was written by Jochen Schulz (jrschulz), who made a great Python library for metric spaces. This is the link to the complete source: [Module mspace][1].