I can't find any guide about how to make a tornado plot in latex/overleaf. Does anybody know how to make one?   I'm working on an economical analysis and want to show how changes will affect the production cost.   Inspiration pictures:    Edit: The question was marked to have a duplicate question, but I tried to use this one () as a base, but I'm not satisfied unfortunately, and I'm stuck.    There is still a lot until I have it more equal to my two inspiration pictures, for instance:    The % values represent the % of the total. How do I remove them and rather show the change from the main value (?), as shown in the two example pictures? How do I insert x- and y-axis?   I removed the header/title, it's not necessary as I will have a figure text underneath.  I'm sorry if I fail to explain my question, I'm as I mention very new to latex/overleaf :) I appreciate your feedback and answers!  (I also tried to use this:  but I found that one to be even more difficult to understand. I want the y-axis not to be numbered, but with text, and don't know how to change that.)  \documentclass{standalone} \usepackage[svgnames]{xcolor} \usepackage{tikz} \usepackage{pgfplotstable} \usepackage{wasysym} \begin{document}  \pgfplotstableread[col sep=comma]{ unit,min,max Lipid content,1000,1300 Growth rate,800,1000 Main equipment cost basis,500,500 Operating factor,50,400 }\loadedtable  \newlength{\dy}\setlength{\dy}{\baselineskip} \newlength{\dx}\setlength{\dx}{0.007em} \newlength{\temp}  \pgfplotstablegetrowsof{\loadedtable} \pgfmathparse{\pgfplotsretval-1} \edef\rows{\pgfmathresult} % compute total for percentages \setlength{\temp}{0pt} \foreach \y in {0,1,...,\rows}{%   \pgfplotstablegetelem{\y}{min}\of\loadedtable   \global\advance\temp by \pgfplotsretval pt   \pgfplotstablegetelem{\y}{max}\of\loadedtable   \global\advance\temp by \pgfplotsretval pt } \pgfmathparse{0.01\temp} \edef\total{\pgfmathresult}  \noindent\begin{tikzpicture}  \foreach \y in {0,1,...,\rows}{%   \pgfplotstablegetelem{\y}{unit}\of\loadedtable   \node[left] at (-19em,-\y\dy) {\strut\pgfplotsretval};   \pgfplotstablegetelem{\y}{min}\of\loadedtable   \node[left] at (-15em,-\y\dy) {\strut\pgfplotsretval};   \node[left,fill=Navy,text width=\pgfplotsretval\dx,text height=.8\dy,inner sep=0]     at (0,-\y\dy+0.1\dy) {};   \pgfmathparse{\pgfplotsretval/\total}   \pgfmathprintnumberto[fixed,precision=2]{\pgfmathresult}{\per}   \node[left] at (-\pgfplotsretval\dx,-\y\dy) {\small\strut\per\%};   \pgfplotstablegetelem{\y}{max}\of\loadedtable   \node[left] at (17em,-\y\dy) {\strut\pgfplotsretval};   \node[right,fill=HotPink,text width=\pgfplotsretval\dx,text height=.8\dy,inner sep=0]     at (0,-\y\dy+0.1\dy) {};   \pgfmathparse{\pgfplotsretval/\total}   \pgfmathprintnumberto[fixed,precision=2]{\pgfmathresult}{\per}   \node[right] at (\pgfplotsretval\dx,-\y\dy) {\small\strut\per\%}; }  \end{tikzpicture} \end{document}
To display a sensitivity analysis I want to produce a . In the plot a specific base case value is compared to the values produced after changing parameters in the model. I started from this . With this I was able to get this MWE:   \usepackage{pgf} \usepackage{tikz} \usepackage{pgfplots} \pgfplotsset{compat=newest} \usetikzlibrary{positioning} \usetikzlibrary{calc} \usetikzlibrary{intersections,backgrounds} \usetikzlibrary{decorations.pathmorphing}  \pgfplotsset{     TornadoPlot/.style={% Overall settings         width = 1\textwidth,     line width=1pt,     tick style={line width=0.8pt},     xmin = -50, xmax = 50,     xtick       = {-50, -40, -30, -20, -10, 0, 10, 20, 30, 40, 50},     xticklabels = {-50, -40, -30, -20, -10, 0, 10, 20, 30, 40, 50},     xmajorgrids = true,     minor x tick num = 1,     tick align = outside,     xtick pos = left, ytick pos = left,     xbar, bar shift=0pt,     height = 7cm,     enlarge y limits = 0.1, ytick = {0,1,2,3,4,5,6},     nodes near coords={         \pgfkeys{/pgf/fpu=true}%         \pgfmathparse{\pgfplotspointmeta}%         \pgfmathprintnumber{\pgfmathresult}     },     nodes near coords align = {horizontal},     before end axis/.code={         \draw ({rel axis cs:0,0}-|{axis cs:0,0}) -- ({rel axis cs:0,1}-|{axis    cs:0,0});     }              } }  \begin{document} \begin{tikzpicture}     \begin{axis}[TornadoPlot, legend style={at={(0.975,0.25)}}]             \addplot[fill=green!40] coordinates{(-3.5,0) (-16,1) (-17.5,2) (-19,3) (-34,4) (-27,5) (-22,6)};             \addplot[fill=red!40] coordinates{(4,0) (19,1) (12.5,2) (28.5,3) (34,4) (82,5) (38,6)};             \legend{upside, downside}      \end{axis} \end{tikzpicture} \end{document}   However, one of the bars (82, 5) has a positive x value that is outside the range of the domain of the plot. Can I restrict the length of that bar and force a break, while still displaying the original value of x? I have seen  for vertical bar-charts, but so far I have not been able to reproduce this for my tornado plot.
It appears that on Server Fault and Super User, the navigation bar and question title have suddenly become misplaced. The same does not occur on SO and mSO, nor on any of the other SE sites I spot-checked.  This is being seen in both Chrome and Firefox and just began occurring within the last few minutes.      What it should look like:      While this was fixed for a few hours, it has returned as of 22:05. Why didn't Thanos come to Earth to retrieve Tesseract by himself? In the Avengers movie, why didn't Thanos personally come to Earth instead of Loki? Or, if Loki's skills were required, why didn't he come with Chitauri? He knew that humans were primitive; there wouldn't be any threat and he could personally secure Tesseract.  AFAIK, the movie didn't display much. Is there any other source answering this? I need to view the saved WiFi passwords on my non-rooted Android phone I have an LG Optimus 7 (not-rooted), and all my WiFi passwords are there. I want to view the saved WiFi passwords to transfer thm to my new Samsung Galaxy S3, but I don't know how.  I tried to search on the Internet and Google play for an application that would allow me to view this information, but I can't find one. Is there any way for me to accomplish this? I have 4 time series. One of them is stationary and rest of them are not. I need to find relation between them. I will use AIC to decide lag length.   Should I use VAR or VECM to find relation between them?  Will VAR or VECM give me relation in terms of equation which can be used for forecasting?  Do I need to perform Johansen's test of cointegration?  What good would it do? Fetch the row which has the Max value for a column How can I automatically log out the guest account after a period of inactivity? As part of a kiosk system, I have set up a Guest account on a Mac OS X Snow Leopard computer. This account is cleared every time someone logs off the computer. However, plenty of people don't. Is there any way that I can automatically log out this guest account after a period of inactivity?  I tried using the security preferences pane, but that just causes the confirm logout dialog to show up.  I have hacked around the /System/Library/User Templates/ folder, so I can set the screensaver, desktop background, &amp;c. If something like ScriptSaver can solve my problem, I will gladly use it. The currently proposed Gravitational wave detection apparatus consists of Michelson Interferometer which is supposed to measure distances of the order of $10^{-22}$m. But the wavelength of the light used is in the order of micrometers ($10^{-6}$m). How is this possible? The conventional way to measure distance is by counting the interference fringes. But for path difference smaller than wavelength of laser light this is not possible. how to fill intersection of 2 shapes in latex tikz package I have to fill a specific region as given in the following figure.  The code I have written is   \begin{tikzpicture}  \draw (0,0) rectangle (10,10);  \draw (3.5,3.5) circle (5) node {A};  \end{tikzpicture}   Now, how to fill the intersecting area (area of circle overlapping the square) $\lim\limits_{n \to{+}\infty}{\sqrt[n]{n!}}$ is infinite How do I prove that $ \displaystyle\lim_{n \to{+}\infty}{\sqrt[n]{n!}}$ is infinite? In the Harry Potter world, there's the term "muggle" for people with no magical abilities, "muggle-born" for those with magical abilities who's parents are muggles and "squib" for those with no magical abilities who's parents are magical.  But is there any collective term for all magical people (as opposed to wizards for males and witches for females)?  I don't recall seeing any word that refers to all men and women and children with magical abilities, and it's the only group left without noun or collective noun to describe them. For every set $A$, the empty set is a subset of $A$. The empty set is a set. Therefore, the empty set has a cardinality $\geq 1\ldots$ I have only recently been exposed to sets. According to , as seen on the first bullet mark of the link, $ \forall A: \emptyset \subseteq A$  Does this mean that $\emptyset$ is an element of all sets? (This is False, thank you those that answered)  Is the empty set also a set itself?  Assuming these statements are true, then the empty set therefore an element of the empty set. This does not sound right, please clarify for me. Thank you. Joining non-spatial CSV file to spatial data (shapefile) using QGIS? I have a CSV file which has postcode data in a field, but it is non-spatial e.g. no Easting and Northing.   I have a shapefile with postcode in a field and some additional data.  I want to join the CSV with the shapefile based on attributes (postcode fields). I know I can do this in ArcMap, but how can I achieve the same thing in QGIS? Bug with Excavator Badge I edited this post today  on stack overflow. I was approved of the edit, so I waited a few minutes to get my  badge because this answer was posted on Jan 28 '10 at 1:06, but it never came. I have read multiple articles on meta that there have been bugs with this badge, but they have been about winning it multiple times (), or earning it then losing it (). Am I missing something here? Realtek RTL8723be doesn't have good reception Only when I'm closer to the router, it shows any signal, but when I'm just little far from it, it is not showing wifi routers signals. How can I get free or trial ExactTarget instance Does a 2100W angle grinder need an earth pin? I have recently purchased a Makita 2100W angle grinder. It has just the live (L) and neutral (N) connectors unlike the one I previously used, which had a third protected earth (PE) connection.   Would it be better if I changed the connections to a 3 pin connector? Properties of p-adic valuations Let $n$ be a integer not equal to zero, $p$ a prime and $$|n|_p = p^{-\operatorname{ord}_p(n)}; |0|_p=0$$  Proposition: $|xy|_p=|x|_p|y|_p$  We want to show: $\operatorname{ord}_p(ab)=\operatorname{ord}_{p}(a)+\operatorname{ord}_p(b)$ So if we suppose there is a largest integral $v$ such that $p^{v}|(ab)$, then we can split up v such that $p^{v_1}|a,p^{v_2}|b$. If we suppose that there exist $v_1,v_2$ with them both being the largest integers such that $p^{v_1}|a, p^{v_2}|b$,  with $v_1+v_2= : v $ then $p^v|ab$. (I don't believe this to be a formal proof but rather my best own "idea" I can come up with...)  The script also mentions that the padic valuations' sums are bounded: $|x+y|_p\le \sup\{|x|_p,|y|_p\}$, how to show this?   Edit:   According to Robert Israel and Bill Dubuques answers, the first proposition is proven, if I understood correctly:   Given $ord(a)= v$ and $ord(b) = u$ which is the same as $a:= p^{v}m, b:= p^{u}n$ with $gcd(m,p)=gcd(n,p)=1$, because $ab=p^{u+v}mn$ with $gcd(mn,p)=1$ it follows that $ord(ab)=ord(a)+ord(b)$ and so $|xy|_{p}=p^{-ord(xy)}=p^{-(ord(x)+ord(y))}=|x|_{p}|y|_{p}$  Now to show: $|x+y|_{p}\le sup\{|x|_{p},|y|_{p} \}$  and the second can be tackled like this: set $a:=p^{v}m. b:=p^{u}n$, then checking two cases $1:(u=v)$ and $2:(v&lt;u)$: $(a+b)=p^{v}m+p^{u}n= p^{v}(m+p^{u-v}n)$ so in case of (u=v) it follows that  $ord(a+b)= u = sup\{ord(a),ord(b)\}$  and in case of $(v&lt;u)$ because the biggest v is $v:= u-1$: $ord(a+b)\le p^{u-1}(m+pn) \le p^{u}(m+n)= sup\{ord(a),ord(b)\}$  It seems that I did something wrong in both cases... How do I capture the moon and its surrounding context? I wanted to photograph the full moon against a beautiful deep blue sky. I ended up with blown-out highlights of the moon:    So I switched to spot metering and captured the moon, losing the blue sky in the process:    I want a single photo that shows both the moon and the surrounding context (in this case, the blue sky). Doing an exposure fusion in Photomatix Essentials did not help:    Nor did HDR fusion (again in Photomatix):    Notice that the detail in the moon was lost in both cases, and the sky was also messed up in both cases: exposure fusion lost the beautiful blue color, while HDR created more texture than was actually present in the sky. I toggled Photomatix's option to remove ghosts, but that didn't help, either.  How do I photograph the moon together with its surrounding context (in this case, the blue sky, but in other cases, a tree, buildings, etc) without blowing highlights or shadows? I'm using a Sony NEX-5R, with the longest focal length lens I have, and with manual focus when needed.  Thinking I should fuse the photos manually, I tried opening the images as layers in Acorn, with the darker photo on top and with opacity set to 50%, and tried all 15 - 20 blending modes (normal, dodge, lighter, darker, multiply and so on), but none of them seemed to work. I'm afraid I don't know enough to use layers effectively. What blending mode and opacity and order of layers should I use for this task?  I don't have Photoshop, but do have Lightroom 5, Acorn and Nik Collection.  (In case you are about to recommend software, please note my requirements: I use a Mac, I would be willing to pay $20-30, and I don't want to use command-line software.) This is a comic book I read no later than 1993 (so is pre-1993).  And probably after 1988 though I can't be certain.  The protagonist is a huge barbarian with an axe, who seems like an old man, who is defending a series of gigantic walls against an invading army, apparently single-handedly. They keep having to fall back to inner walls. He has to get a massage at one point (not that kind of comic btw).  It's not a super-hero or funny comic, it's more of a serious graphic novel.  That's about it, sorry it's so vague. MySQL Insert query doesn't work with WHERE clause