There was the following  in New York Times’ (October 6) article commenting on GOP Presidential candidate, Carly Fiorina under the headline, ‘If she’s a feminist, then I’m a T. Rex’:      “Her record at Hewlett-Packard — firing skilled Americans by the   thousands and outsourcing their jobs to China and India, while almost   running her company into the ground with an ill-advised merger — is   hardly a sterling record for any sort of candidate, assuming we   actually want a president of all the people rather than a modern   Ebenezer Scrooge, - - This is a woman who would deny other women   control over their own bodies, as well. "If she’s a feminist then I’m   a T. rex.”   According to Jurassic wiki, Tyrannosaurus rex, the most famous of all dinosaurs species and commonly known as T. rex, was the largest of the Tyrannosaur family — and by extension one of the largest theropods, reaching 12 to 13 meters in length.  But what does ‘If she’s a feminist, then I’m a T. Rex’ mean? Does the writer sarcastically admit herself being anachronistic? Why should it be a T.Rex, not other monsterous or supernatural creatures, say, Moby-Dick and Godzilla?  Is this a cute turn of phrase?  Could you translate “I’m a T.rex” into plain English?
I’m reading Shakespeare’s Henry IV (Part 1) right now and I’m noticing that Sir John Falstaff has a propensity of saying “If this, then I’m a this” sort of statements. A few examples to clarify:     … An I   have not ballads made on you all and sung to filthy   tunes, let a cup of sack be my poison      An I have not   forgotten what the inside of a church is made of, I   am a peppercorn, a brewer’s horse      if manhood, good manhood, be   not forgot upon the face of the earth, then am I a shotten herring      If I do not beat thee out of thy   kingdom with a dagger of lath, and drive all thy   subjects afore thee like a flock of wild-geese,   I’ll never wear hair on my face more   Is there a particular literary term for these sort of sentences?
Uneven line height in XeTeX I'm embarking on a journey to create a conference abstract book using XeTeX and got stuck within five minutes:        The missing 'g' in 'somethin' influences the line height of the following line. How can I correct this?  At the end I want to be able to include the abstracts and corresponding information through our online registration system, so this should be a global setting.  My MWE:  \documentclass[10pt, a5paper]{article} \usepackage{fontspec}  %% GEOMETRY \usepackage[left=2cm, right=1.5cm]{geometry} % to change the page dimensions  \newenvironment{AbsHead} {     \fontsize{16}{22}\headfont\noindent }% {     \vspace{0.5 cm} }  \newenvironment{AbsAuthors} {     \fontsize{12}{14}\authorfont\noindent }% {    \vspace{0.5 cm} }  \begin{document}  ￼￼￼￼\setmainfont{Minion Pro} \newfontfamily\authorfont{Helvetica Neue Light} \newfontfamily\headfont{Helvetica Neue Condensed Bold}  \begin{AbsHead}The XIAP  something something something somethin somethin somethin somethin somethin somethin somethin something something\end{AbsHead}   \begin{AbsAuthors}Somebody Someone\end{AbsAuthors}   \noindent Purpose: Lorem ipsum \end{document} the composition was  defined as follow:  (a,b) \in (R;S) &lt;=&gt; there is c | (a,c) \in R  and (c,b) \in S .   If our two relations R and S are two convex polygon   Is there a geometric interpretation of the composition of two convex polygon ? for example :   the green polygon was the result of composition. How can i describe geometrically the result !!! Does throwing a watch into the air cause it to gain or lose time? Suppose I'm on a non rotating planet. I have two identical, perfect watches. I synchronize them. Then I throw one of them into the air and catch it. Does the one I throw into the air gain or lose time with respect to the one I was holding? Restart my graphics card without rebooting? How to preserve detail when downscaling scanned photos? I'm mixing analog with digital photography — I tend to take better photos when I can't look at a small digital screen, unconsciously forcing me to take the picture before I shoot instead of checking afterwards if it succeeded. I also like the grain film gives me.  However, most shots aren't worth spending much time in the darkroom, and scanning them is a lot faster. I'm wondering how best to convert the film to digital.  Scanning at lower than maximum (non-interpolated) resolution of my image scanner tends to exaggerate the contrast of the grain and screw up the mid-tones because of that.1 On the other hand, the resulting size of the scans are major overkill in most cases (I don't print them at A0 size), so I want to downscale the pictures. However, the grain confuses most methods and results in loss of detail and/or loss of the characteristic grain. For example, bicubic sharper tends to result in a "bigger" grain than the original. Now, the best compromise I've found so far is simply using bilinear interpolation, but I doubt that this is the best method to preserve both overall details and the look of the grain.  In short: when processing the scanned negative, how do I "best" preserve both image quality and the characteristic look of the grain?   As Stan Rogers pointed out below, there's a difference between truly scanning the grain of the film, and scanning the "grainy" character of film at lower resolutions. This question is about the latter; Stan Rogers explains how to do the first.  I'm looking for alternatives to the standard Photoshop options to try out, and reasons for each. Is the fact that every film has a different grain characteristic a problem? Are customized advanced noise reduction methods perhaps an option?  1. I'm using a Minolta DiMAGE Scan Elite 5400, using the software provided by Minolta.  As requested, here is a scanned picture with different resize methods. Just scanned this, scanning a B&amp;W negative to get better tonality range. I turned off grain dissolver, automatic dust and scratch removal, etc, for obvious reasons. On the right the pictures are upscaled again with Nearest Neighbor. I set the 8 bit scan to 16 bits before downscaling, assuming it reduces risks of banding if I choose to mess with curves, channel mixers, etc. No other modifications (usually I first retouch dust &amp; scratches, and in the end channel mix the picture to B&amp;W, then switch to 8 bits again). How to prompt for user input and read command-line arguments Suppose that G is a group and N &lt; G a normal subgroup. Assume that there is no normal subgroup M &lt; G with N &lt; M. Prove that G/N is simple.  This problem is really throwing me for a loop. The concept of quotient groups and how they relate to simple subgroups is confusing me, and so I am not really sure how to begin. If a simple subgroup's only normal subgroup is itself (and the trivial group), then G/N being simple would be proving that when multiplying the entire subgroup N by an element g for all g in G, that the collection of those sets cannot be broken into smaller normal subgroups? Until now, I have been compiling my LaTeX documents with pdfLaTeX. My standard document preamble includes the "usual suspects" for non-English speakers (, , ) and a bunch of other packages. Assuming I were to convert to XeLaTeX, what modifications of my preamble are advisable? I'm aware that the expansion=true option of the  package is not (yet) available for XeLaTeX, and that  is sort of a default package for OpenType fonts. What other packages (and package options) should be removed and, vice versa, incorporated when switching from pdfLaTeX to XeLaTeX? E: Package 'libpng12-0' has no installation candidate [ubuntu 16.10 Gnome] I tried to install WPS Office on my laptop (ubuntu 16.10 Gnome, 64 bit) with  Gdebi installer but it said   Dependency is not satisfiable: libpng12-0   Then I tried to open this library as follows  sudo apt-get install libpng12-0   But I encountered an error:  Reading package lists... Done Building dependency tree        Reading state information... Done Package libpng12-0 is not available, but is referred to by another package. This may mean that the package is missing, has been obsoleted, or is only available from another source  E: Package 'libpng12-0' has no installation candidate   Can anyone help? Thanks a lot Edits that shadow a suggested edit inconsistently reject but include the suggestion 'Wouldn't wake up' vs. 'didn't wake up' I'm reading an article about two pets rescuing their owners. After the cat managed to wake up the mother, she tried to wake up other members but they wouldn't wake up.     Cathy tried to tell her husband and son to leave the house, but they wouldn't wake up.   Why wouldn't and not didn't?   (I checked possible duplicates but they weren't convincing at all. Besides, none of the answers were confirmed. One said would is used for permission and another said it's for emphasis!) How can i show that two $R$-modules of finite rank are isomorphic if and only if they have the same rank, i.e., $R^n \cong R^m$ iff $n=m$. Electromagnetic wave properties of light vs radio waves UK visa: unsigned application form I have a simple question answer to which would help me more deeply understand the concept of (non)commutative structures. Let's take for example (our teacher's definition of) a ring:  Let $R\neq \emptyset$ be a set, let $\oplus:A\times A \to A$ and $\bullet :A\times A \to A$ be binary operations. Moreover, let $(R, \oplus)$ be a commutative group, $(R, \bullet)$ be a monoid and following property holds for all $a, b, c\in R$: $$a\bullet(b\oplus c) = (a\bullet b)\oplus(a \bullet c)$$ $$(b\oplus c)\bullet a = (b\bullet a)\oplus(c \bullet a)$$ Then ordered triple $\mathbf R = (R, \oplus, \bullet \mathbf)$ is called a (unitary) ring.  Moreover, we call ring $\mathbf R$ commutative iff $(R, \bullet)$ is a commutative monoid. Commutativity of a ring is always a matter of its multiplicative operation because the additive operation is always assumed to be commutative.  Could anyone explain me the bold part? Why do we even in non-commutative rings (and fields etc.) assume the addition to be always commutative? Is there some serious reason? Would it make any trouble? Or studying of structures with non-commutative addition just doesn't give us anything new so we can take addition as commutative simply because of our comfort? I need to build a probabilistic cellular automaton for simulating land-use changes and am wondering how to implement this in a GIS. I understand that Markov chains are a way of doing this, and IDRISI has some sort of module for Markov chains, but I have no access to IDRISI.  that, with raster data, this can, in theory, be done with any GIS that can do raster algebra. Presumably this means that it can even be done in ArcGIS, and I think I've figured out how to build cellular automata in ModelBuilder (once I know with certainty how to make iteration work there).  Still, I can find next to no practical advice on this. Once I have two datasets, one showing the land use at a certain point in time (time A) and the other at a later time (time B), I imagine doing the following (correct me if I'm wrong):   If there are (for example) 3 types of land use, then there are 9 possible things that can happen to a cell from time A to time B; thus, reclassify each dataset such that each land use is represented by a different number (for example, 9, 11, and 14 at time A and 3, 4, and 5 at time B); Divide one raster by the other, obtaining a raster with 9 possible cell values. Determine the percentage of cells in the new raster that has each of the 9 values (I forgot, how does one do this in ArcGIS?); those will be the probabilities of each type of change (or lack thereof) in land use.   What I cannot figure out, though, is how to apply these probabilities during the next iteration. Finally, I wonder if there is a way of making an external factor (say, proximity to roads) influence the spatial distribution (not the overall likelihood) of change in my model.  Can anyone recommend where to find information on how to do this in ArcGIS? I'm subscribed to the Ubuntu Security Notes, so everytime that I receive an e-mail, a new update is avalable.  But in the last update, they wrote something in the end that I coudn't undertand much, so can anyone please tell me what does that means?  ATTENTION: Due to an unavoidable ABI change the kernel updates have been given a new version number, which requires you to recompile and reinstall all third party kernel modules you might have installed. If you use linux-restricted-modules, you have to update that package as well to get modules which work with the new kernel version. Unless you manually uninstalled the standard kernel metapackages (e.g. linux-generic, linux-server, linux-powerpc), a standard system upgrade will automatically perform this as well.   I tried to ask to my friend (who also uses Linux), but he don't know much about kernel. Do elevator upgrades increase your passive credit earnings, too? How to add a node in the middle of the line with tikz? How can I play around targeted discard? Many decks in competitive Magic have access to targeted discard spells, like  and .  Against counterspells, you can rely on a variety of tricks like baiting counters, bottlenecking your opponent's mana, and good old-fashioned counter wars. Targeted discard cards allow your opponent to attack your hand on the very first turn of the game, and go right for your key cards &mdash; and it can often be backbreaking when your opponent takes away a crucial card like a combo piece or a sweeper.  What tricks and tactics can you employ, either during deck-building or in play, to play around an opponent's targeted discard?  (I know that one of the answers is going to be . That's excellent, but please also include approaches that work in formats without free countermagic.)