Please look at the figure above. The contents in the List of Figures are crossing the border and they are not appearing fully.  This is the code that I found in the source latex file.   \newpage  \makeatletter  \let \asas \ps@plain  \let \ps@plain \ps@empty  \makeatother \large  \tableofcontents  %\makeatletter  %\let \ps@plain \asas  %\let\asas\relax  %\makeatother  %\thispagestyle{empty}  \listoffigures  %\thispagestyle{empty}  \listoftables   %\thispagestyle{empty}   What can be done ?
When I use \listoftables and \listoffigures I get in the list long captions that appear next to the tables/figures.  I would like to use short captions for this list which summarize these captions. Is that common to do? If so, what is one way to do it?
How does the momentum operator act on state kets? I have been going through some problems in Sakurai's Modern QM and at one point have to calculate $\langle \alpha|\hat{p}|\alpha\rangle$ where all we know about the state $|\alpha\rangle$ is that $$\langle x|\alpha\rangle=f(x)$$ for some known function $f$. ($|\alpha\rangle$ is a Gaussian wave packet.) Sakurai says that this is given by:  $$\langle p\rangle = \int\limits_{-\infty}^{+\infty}\langle\alpha|x\rangle\left(-i\hbar\frac{\partial}{\partial x}\right)\langle x|\alpha\rangle dx.$$  I am wondering how we get to this expression. I know that we can express   $$|\alpha\rangle =\int dx|x\rangle\langle x|\alpha\rangle$$  and  $$\langle\alpha|=\int dx\langle\alpha|x\rangle\langle x|,$$   so my thinking is that we have:  $$\langle\alpha|\hat{p}|\alpha\rangle =\iint dx dx'\langle\alpha|x\rangle\langle x|\hat{p}|x'\rangle \langle x'|\alpha\rangle, $$  and if we can 'commute' $|x\rangle$ and $\hat{p}$ this would become: $$\iint dxdx'\langle\alpha |x\rangle\hat{p}\langle x|x'\rangle \langle x'|\alpha\rangle,$$  which is the desired result as $$\langle x|x'\rangle=\delta(x-x').$$ Is this approach valid?  I think my question boils down to: Does the operator $\hat{p}$ act on the basis kets $|x\rangle$ or on their coefficients? In the latter case, if we had some state $|\psi\rangle = |x_0\rangle$ for some position $x_0$, then would we say that for this state $$\langle p\rangle =\langle x_0|\left(-i\hbar\frac{\partial}{\partial x}\right)|x_0\rangle = 0$$ as the single coefficient is $1$ and the derivative of $1$ is $0$? How can I switch back to Nvidia card from Intel with Nvidia-prime So I updated to Ubuntu 14.04 and found that the primusrun command no longer works, so ditched bumblebee in favour of nvidia-prime. This lets you switch video card from nvidia-settings rather than running through the command line (I prefer the old method, but want the primus performance).  The problem is that after switching to Intel from nvidia-settings, I can no longer open it up again to switch back to the nvidia card. When I open nvidia-settings I get a segmentation fault (according to the terminal).  Is there any way to open nvidia-settings switch back? I would like the ability to be able to switch between the two since having the nvidia card on all the time kills my battery and heats up the laptop a lot. If I enter my password correct first time, I login as normal.  If I enter my password wrong, it says invalid password. If I attempt to enter the correct password now then the screen freezes and doesn't go to dock as normal. I must restart using a physical button or shutdown to get out. Login works normally after restart, assuming I get it right first time.  EDIT:  After entering a wrong password, if I click cancel and then go back to my user to login, it works fine. Verification that $\lim_{x \to a}\frac{f(x)-f(a)}{x-a}$ and $\lim_{h\to 0}\frac{f(a+h) -f(a)}{h}$ are equivalent definitions of the derivative. I wanted to verify that for definition of the derivative it is true that:  $$ \lim_{x \to a}\frac{f(x)-f(a)}{x-a}= \lim_{h\to 0}\frac{f(a+h) -f(a)}{h}$$  If I denote $h=x-a$,  we can  let $x\to a$, this means that $h \to 0$. Also notice that $f(x)=f(a+h)$ $$ \lim_{x \to a}\frac{f(x)-f(a)}{x-a}=\lim_{h \to 0}\frac{f(a+h)-f(a)}{h}$$ As desired. Is the main idea here really just to use a variable substitution? I suppose there is some formal theorem I also use here that when $f(x) \to y$  we can let $g(f(x)) \to g(y)$ if the function $g$ is continuous. is the Turkish version of mancala, with its own set of rules.  I am planning on doing a project in it. Are there any game engines that either specifically play it, or universal Mancala players that plays it after supplying the options?  EDIT:  I am not looking for an app, but for a game engine. For example in chess,  is a playing app, while  is an open-source engine. How to show that the commutator subgroup is a normal subgroup Change email login to another id My original email id got compromised and now I want my new email id to be the main id for all SE sites . How to delete original id from the system as someone else might login from it ? Suppose $G$ is a finer filter than $F$ in a topological space $X$.  Is the net base in $G$ a subnet of the net base in $F$?  I am using the definitions of General Topology of Willard:     Definition 12.15. If $(x_\lambda)$ is a net in $X$, the filter generated by the filter base $\mathscr C$ consisting of the sets $B_{\lambda_0}=\{x_\lambda; \lambda\ge\lambda_0\}$, $\lambda_0\in\Lambda$, is called the filter generated by $(x_\lambda)$.      Definition 12.16. If $\mathscr F$ is a filter on $X$, let $\Lambda_{\mathscr F}=\{(x,F); x\in F\in\mathscr F\}$.   Then $\Lambda_{\mathscr F}$ is directed by the relation $(x_1,F_1)\le(x_2,F_2)$ iff $F_2\subset F_1$, so the map   $P\colon \Lambda_{\mathscr F} \to X$ defined by $P(x,F)=x$ is a net in $X$. It is called the net based on $\mathscr F$.   The definition of subnet used in Willard is the second one from this post:   Thank you Show all the file up to the match grep --before-context 5 shows 5 lines before the match.  I want to show everything before the match. Doing grep --before-context 99999999 would work but it is not very... professional.  How to show all the file up to the match? Is it possible for many domain names to share one IP address? Is it possible for many domain names to share one IP address? For example, www.xjtl.com, www.fmie.com, sdmfl.com, etc.  Hundreds of domain names share just one IP – when you do a DNS query for each of them, the same IP is returned.  Are there any laws or Internet rules that disallow this? I know someone or the other has asked about disabling ⌘Q, but I like the shortcut, and I use it often. However, I use an email client called Airmail that unfortunately does not keep a service (for notifications) running in the background when it is quitted. However, if I press the close button a service runs in the background, allowing me to receive notifications.  But since I have a habit of pressing ⌘Q all the time to close apps, I was looking into a way I could disable it for only Airmail.  Anyone know of a what to do this? What is the difference between \emph{...} and {\em ...}?  When to use each of them? What could cause touch to fail with this error message?  touch: cannot touch `foo': No such file or directory   Note that an error due to incorrect permissions looks different:  touch: cannot touch `foo': Permission denied Best way to make family photo album in LaTeX I use LaTeX for my research publishing and would like to make a Christmas photo album that I could send to a print shop. It occurred to me to try it with LaTeX this time (yes I know, the print version won't get delivered by Christmas). Among other reasons, it will look like I'm working on code! But I would benefit from some templates etc. and haven't had luck finding any.  Can anyone recommend resources for building a family photo album in LaTeX? I'm looking to get that from a graph. but problem is that graph is in image form. Now I want to extract data in excel from that graph. how can i do it? I'm using office 2003. What's wrong with this demonstration?:  $$A \iff 1 = 1^1$$ $$A \implies 1 = 1^\frac{2}{2}$$ $$A \implies 1 = (1^2)^\frac{1}{2}$$ $$A \implies 1 = ((-1)^2)^\frac{1}{2}$$ $$A \implies 1 = (-1)^\frac{2}{2}$$ $$A \implies 1 = (-1)^1 = -1$$  So finaly we get  $$1 = -1$$ Can I install a ROM made for a different device? What's with the Japanese SO's stats? I took this screenshot just now, and  about the new . I refreshed the page, went back, and nothing changed.    And, here's what I find odd:  It clearly isn't almost 2014 years old. That's more likely when it was started.  How can there be 8.7 questions a day, while there are 0 visits a day? That's kind of impossible.   I'm hoping here that it's not just me. I know very limited Japanese, not even enough to hold a conversation with a toddler. I'm merely observing. Function $f(z)$ such that $|f(z)| > |z|$ for every $z\in\mathbb{C}, 1/f(z)$ "NG NS" on ticket after airport security I went through security at the Sacramento Airport with a friend. He got something written on his boarding pass "NG NS". I didn't have that. We both went through the same metal detector, neither beeped nor had random checks. Flying to Edmonton through Seattle connection. Early for flight.  I have tried searching for "what is tsa ng ns" on Google but nothing useful came up. Any ideas?