I've noticed this strange behavior lately. Whenever I comment on a question or answer, the add/show 1 more comment link is displayed immediately, even when there aren't any new comments. When I click on the link, the message disappears, and no new comments are displayed. I have to reload the page to make sure there are no new comments on the thread. Screenshot:  I'm unable to reproduce the issue with a strict procedure and it doesn't happen all the time. So I believe this to be some kind of race-condition. I've seen  post on Meta and it's marked as  but I'm still experiencing the issue. I've also checked  answer and it says:  Localization is progressing, and the comments feature is on-deck, so I've been putting off spending any more time on comments until that's done. Putting this to  so I won't forget about it.  So, I'm wondering, what's the status on this?
So I've been experiencing this in the last few days: sometimes when someone replies to my comment, and I reply to the reply, then the "add/show 1 more comment" link appears immediately after I post my comment. However, when I click it, it disappears and nothing is shown.  I don't think it's that OP is posting two comments of which he deletes the second one, because this has happened to me several times, even when I was replying within 2-3 seconds.  I do, however, believe that this is more or less the same bug as , except that I don't have to reload the page in order the link to be gone, and I also seem to be getting the erroneous behavior only if I reply to a comment which is itself a reply to an earlier comment of mine.  Unfortunately, I wasn't careful enough to take a screenshot last time this happened, but here's what I am talking about for those who like visual demonstration better:
How to shift EXIF date/time created by time in days, hours, minutes? Can I visit the USA as a VWP tourist immediately prior to entry on non-tourist visa? Here's my situation: I'm a UK citizen. I have an H-1B visa to work in the US as of 1 August. I also have a valid ESTA.  I would like to go to the US in July for a holiday, immediately prior to beginning my work. The holiday would be at the other end of the country from my work.  I can't enter with the H-1B as I can only enter the US on that visa 10 days prior to starting work.  Specific question: Would it be possible to visit the US in early July on the VWP, visit Canada/Mexico for a few days in late July, and re-enter the US with my H-1B visa?  General question: Is it possible to visit the US on the VWP, leave briefly, and re-enter on a different status (e.g. H, F, J, K, etc), without ever returning to one's home country?  I have posted this in Travel rather than Expatriates because, although in my specific case I have an H-1B visa, my question is more generally about VWP and travel, and I believe that it is applicable to travellers with non-immigrant visas.  There's a similar question , although that's about going to the US and before having the H-1B visa. I'm trying to re-learn my undergrad math, and I'm using Stephen Abbot's Understanding Analysis. In section 2.7, he has the following exercise:  Exercise 2.7.5 (a) Show that if $\sum{a_n}$ converges absolutely, then $\sum{a_n^2}$ also converges absolutely. Does this proposition hold without absolute convergence?  I'm posting about this here because my answer to that last question about whether the proposition holds without absolute convergence is "Yes", but my suspicions are raised by him merely asking the question. Usually questions like this are asked to point out that certain conditions are necessary in the statement of propositions, theorems, etc. I just want to see if I'm missing something here.  Anyway, here's how I prove the absolute convergence of $\sum{a_n^2}$, and note that I never use the fact that $\sum{a_n}$ is absolutely convergent:  Proof: Let $s_n = \sum_{i=1}^n{a_n^2}$. I want to show that $(s_n)$ is a Cauchy sequence. So, let $\epsilon &gt; 0$ and $n &gt; m$, and consider, \begin{equation}   \begin{aligned}     |s_n - s_m| &amp;= |(a_1^2 + a_2^2 + \cdots a_n^2) - (a_1^2 + a_2^2 + \cdots a_m^2)|\\                 &amp;= |(a_{m+1})^2 + (a_{m+2})^2 + \cdots + a_n^2|\\                 &amp;= |a_{m+1}|^2 + |a_{m+2}|^2 + \cdots + |a_n|^2\\   \end{aligned} \end{equation} Now, since $\sum{a_m}$ converges, the sequence $(a_m)$ has limit 0. Therefore I can choose an $N$ such that $|a_m| &lt; \sqrt{\epsilon/n}$ for all $m &gt; N$. So for all $n &gt; m&gt; N$,  we have, \begin{equation}   \begin{aligned}     |s_n - s_m| &amp;= |a_{m+1}|^2 + |a_{m+2}|^2 + \cdots + |a_n|^2\\                 &amp;&lt; \left(\sqrt{\frac{\epsilon}{n}}\right)^2 + \left(\sqrt{\frac{\epsilon}{n}}\right)^2 + \cdots + \left(\sqrt{\frac{\epsilon}{n}}\right)^2\\                 &amp;&lt; \left(\sqrt{\frac{\epsilon}{n-m}}\right)^2 + \left(\sqrt{\frac{\epsilon}{n-m}}\right)^2 + \cdots + \left(\sqrt{\frac{\epsilon}{n-m}}\right)^2\\                 &amp;= \epsilon   \end{aligned} \end{equation} Therefore $(s_n)$ is Cauchy and $\sum{a_n^2}$ converges. And since $\sum{a_n^2} = \sum{|a_n^2|}$, the series $\sum{a_n^2}$ is absolutely convergent. &#x220E;  Am I doing something wrong here? Am I right in thinking that $\sum{a_n}$ need not be absolutely convergent for $\sum{a_n^2}$ to be absolutely convergent? Names of close-voters are not visible in the post notice but in the revision history and timeline I am not a user with close/reopen votes privileges on Travel Stack Exchange, therefore I can't see the names of the close voters :    However, they are visible when going to the revision history:    or the timeline of the post:    This also happens when I am not logged in: I cannot see the banner (and so if the question has been closed), but from the revision history/timeline of the post I can get that information.  Shouldn't names of close-voters be completely hidden from people without close/reopen privileges (even if the revision history is a little hard to find)? All my properties are zero, and my array is zero, even though I have populated them with numbers and objects White's test for heteroskedasticity in R I am trying to estimate heteroskedasticity in R. I had Eviews available in my college's lab but not at home. I have been trying to use "het.test" package and whites.htest but the value that I get is different from what I get in Eviews. According to the author of the package, it is meant to do the same test as is done in Eviews.   My model looks like A~B+C. Kindly guide me what I am doing wrong.   I 1st run ols for equation A~B+C, after getting results, I clicked View&gt;Residual diagnostics&gt;Heteroscadicity tests&gt;White's (with Include white cross terms) and then Press ok. The result i got was Prob. F(5,27) = 0.2948.   For R, i tried code at this link [this link][1], here is the edited code that i used.  library(vars)  library(het.test) dataset &lt;- data.frame(A,B,C))  model1 &lt;- VAR(dataset, p = 1)  whites.htest(model1)   This gave me value of 0.63.  I tried searching this forum but none question seemed related. I am not a programmer not statistician so please pardon my ignorance. What species of insect is this? I saw this insect near a beach in Corsica France: I set a command block to /tp. It was supposed to activate only if you had 0 time left, and to activate the command block with a hopper clock to keep giving it power.   But it is not checking if you have 0 time left, so it keeps teleporting me. I can't get close enough to the command block to break it, so I'm stuck in a neverending teleport loop.  Any ideas? Show that the set $\mathbb{Q}(\sqrt{p})=\{a+b\sqrt{p}; a,b,p\in\mathbb{Q},\sqrt{p}\notin \mathbb{Q}\}$ is a field  I am having a little trouble proving that for each non-zero $b\in\mathbb{Q}(\sqrt{p})$, there is $d\in\mathbb{Q}$ such that $b\cdot d=1$.  My attempt:  Let $b=a_1+b_1\sqrt{p}$  Let $d=a_2+b_2\sqrt{p}$  We want $$b\cdot d=(a_1+b_1\sqrt{p})(a_2+b_2\sqrt{p})$$ $$=a_1a_2+a_1b_2\sqrt{p}+a_2b_1\sqrt{p}+b_1b_2p$$  $$=(a_1a_2+b_1b_2p)+(a_1b_2+a_2b_1)\sqrt{p}$$ $$=1$$  Am I following the right approach? What should be my next step Determine file type of an image I'm downloading some images from a service that doesn't always include a content-type and doesn't provide an extension for the file I'm downloading (ugh, don't ask).  What's the best way to determine the image format in .NET?  The application that is reading these downloaded images needs to have a proper file extension or all hell breaks loose. tikz relative coordinates Suppose one defines coordinates a and b. One may draw a line connecting these two coordinates (\draw (a) -- (b)). Suppose one desires to draw a line that is shifted upward 1 unit relative to a and b. A first guess is the command \draw (a){}+(0,1) -- (b){}+(0,1). This command, however, connects the point a+(0,1) to the point b, presumably because addition is subsequent to the draw command. How does one obtain the desired result (drawing from a+(0,1) to b+(0,1)?  MWE:  \documentclass{article} \usepackage{tikz} \usetikzlibrary{calc} \begin{document} \begin{tikzpicture}  \draw[fill] (0,0) circle (2pt) coordinate (a);  \draw[fill] (5,0) circle (2pt) coordinate (b);  \draw (a) -- (b);  \draw (a){}+(0,1) -- (b){}+(0,1); \end{tikzpicture} \end{document}     Edit: How does one draw coordinates at a point shifted relative to the arithmetic average of the coordinates of two points (something akin to \node at ($(((s1)+(s2))/2)+(0,1)$)). Find and Replace several several different values all at once Correct position of "only" Which is grammatically correct?  I can only do so much in this time.  or  I can do only so much in this time. Java volatile reference vs. AtomicReference How can I improve Light Armor as an Archer? I play as an archer, which means sneaking and killing foes off at long range. Problem is, once a creature gets too close to me, I am in a world of troubles. (A random dragon encounter is fair game if I can snipe it off, but a random bear encounter is the thing I fear mostly. Three strikes of such a vicious beast and I drop dead.)  At short range, I use a one-hand sword with shield, but I do not want to put much perks into those skills, as I want to be a sneaky archer first.  Which leaves Light Armor. But to get certain perks I need some skill points, e.g., 30 points are required for the "Custom Fit"- and 40 for "Agile Defender 2/5"-perk. Yet I have no clue how to accumulate those points.  Many enemies won't even see me, so I seldom will be hit. Getting hits means getting skills point. Letting some enemies come close to me and let me hit me on purpose sometimes helps, but since I cannot stand much damage I mostly die erasing any hard earned process.  So is there a teacher for Light Armor like there is for other skills? And if not, how should I go on to improve the Light Armor skill? In swimming, is there a competitive advantage to being in one lane or another? Upon observing swimming competitions in the Olympics, it is not clear to me whether one of the eight lanes is more advantageous versus another. I've seen vague claims but nothing backed up with science.  In competitive swimming, is there an advantage to being in one lane or another? Furthermore, does the stroke (ie: breast, fly, freestyle, etc.) affect this effect? How to know if Mac OS X machine is being remotely viewed? Currently I have no way to know if my machine is being remotely viewed by our tech support, and would prefer to know, given the massive privacy breach that would entail should this be happening. I am running Mac OS X Snow Leopard.  Running  ps -A | grep Remote   I know this service is running:  /System/Library/CoreServices/RemoteManagement/ARDAgent.app/Contents/MacOS/ARDAgent   My knowledge of administration of Macs on a network is limited, so I don't know what tools allow this. Split polygons into equal areas within each region I've a set of regions within a city. I'd like to split each region into five subregions and then get the centroid of each one of them.  I know how to make a vector grid, but the problem I have is that the generated points are not taking into account the regions, they're only related to the general map.  I have this:    And I want to split each region in five equal size areas. Something like this:    I'd like to build a visualization similar to this one: . In order to accomplish that, I need to split each region, because the original ones are pretty big. The score for the 4 questions are 111, 1218, 261 and 5 respectively, but they display 2 digits per line. This is an obvious bug in design. Evaluate $\int^1_0 \log^2(1-x) \log^2(x) \, dx$ I have no idea where to even start. WolframAlpha cant compute it either.  $$\int^1_0 \log^2(1-x) \log^2(x) \, dx$$  I think it can be done with series, but I am not sure, can someone help a little so I can get a start??  Thanks!