I had Faendal as a follower, and he disappeared somewhere along the way. Found him back at his house. I asked him to follow, but he says I already have a follower. I killed the dragon, but Lydia says the same thing. Is there any way to reset it back to no follower? I really don't want to start over.
Whenever I try to get somebody to follow me in Skyrim they something in the lives with "You already have a follower.". The problem is, I don't.   I have not, to my recollection, had a follower at any given point in the game.  The only thing I can think of is that I have (spoiler)      finished Anriel's Endeavors and gotten him as a summon creature.    Or do I have a hidden follower that I can't remember. A dog or a horse perhaps? Note that I do not have a dog or horse following me now. I talked to dog once, and had a horse that died.  Is this a common/known issue? Is there a work around?  Any tips?
SOQL results returning RecordTypeId which is not included in query I am running this script from developer console.  List&lt;Account&gt; lstAccount = [SELECT Id, Name, BillingStreet From Account LIMIT 1]; System.debug(lstAccount);   Debug Log:     23:47:04:012 USER_DEBUG [5]|DEBUG|(Account:{Id=0019000001nNLGEAA4, Name=Acct_nm001, BillingStreet=xyz Road, RecordTypeId=01290000000iaNiAAI})   I never queried for RecordtypeId in SOQL, but it is included in the list.  Although, if I run the query from the query editor, it is not showing RecordtypeId column.   Is this by design? Then why not Salesforce is not providing us audit fields in the first scenario. What is cool about generics, why use them? I thought I'd offer this softball to whomever would like to hit it out of the park. What are generics, what are the advantages of generics, why, where, how should I use them? Please keep it fairly basic. Thanks. Can the real and imaginary parts of $\dfrac{\sin z}z$ be simplified? I have calculated the real and imaginary parts of $\dfrac{\sin z}z.$ I've obtained  $$\begin{eqnarray} \frac{\sin z}z&amp;=&amp;\frac{\sin(x+iy)}{(x+iy)}\\ &amp;=&amp; \frac{\sin(x)\cosh(y)+i\cos(x)\sinh(y)}{x+iy}\\ &amp;=&amp; \frac{x\sin(x)\cosh(y)+y\cos(x)\sinh(y)}{x^2+y^2}+i\frac{x\cos(x)\sinh(y)-y\sin(x)\cosh(y)}{x^2+y^2}. \end{eqnarray}$$  Before calculating it, I hoped I could use this in a solution to a certain problem, but I would need to differentiate the real and imaginary parts of $\dfrac{\sin z}z$ with regard to $x$ and $y$. But what I'm getting is very complicated. I understand that it could be that that's just the way it is. But maybe there are some simplifications to be done either in the functions or in their derivatives? I've never really used hyperbolic functions before so I'm not sure I'm not missing something.  Added. The problem I'm working on is the following.     Prove that the solutions of the equation $$\tan z=z$$ are all real.   I will sketch the solution I know here.  It can be calculated that  $$\tan(x+iy)=\frac{\sin(2x)}{\cos(2x)+\cosh(2y)}+i\frac{\sinh(2y)}{\cos(2x)+\cosh(2y)}.$$  Plugging this to the equation, we get  $$\begin{eqnarray} x&amp;=&amp;\frac{\sin(2x)}{\cos(2x)+\cosh(2y)}\\ y&amp;=&amp;\frac{\sinh(2y)}{\cos(2x)+\cosh(2y)}. \end{eqnarray}$$  From this we can get   $$\sin(2x)\cdot2y=\sinh(2y)\cdot2x.$$  By plotting the functions $\sin,$ $\mathrm{id}$ and $\sinh$ (and proving the right inequalities we can see from the plots), we can see that this is only possible when $xy=0$. But when we plug $x=0$ to the second equation, we can show that the only solution is $y=0$, which ends the proof.  What strikes me in this solution is the fact that $\dfrac{\sin z}z$ is used. (Not explicitly in my statement.) This function has another connection to the problem:     The non-zero solutions of the equation $\tan z=z$ are exactly the zeros of the derivative of $\dfrac{\sin z}z.$   This is easy to prove. I wondered if there shouldn't be a solution to the problem which uses this fact, given that $\dfrac{\sin z}z$ appears in the solution I know. I think this is a basic question, but it's hard to wrap my head around. In the Harry Potter universe, there is a spell that unlocks things. In the books and movies, there are many occasions where the main characters use this spell to open doors in wizard buildings (such as the door leading to where the Philosopher's Stone is hidden, or a door in the Magical Congress Of USA headquarters). Hermione knows the spell in her first year, which seems to indicate it's pretty easy to learn/cast, especially for the average adult wizard.   What I'm wondering, then, is why do wizards lock their doors when it's so easy to unlock them? And if it's so easy to unlock locked doors, why aren't there more doors locked with enchantments? For $u:\mathbb{R}\times [0,1]$ with boundary conditions $u(0,x)=\cos (2\pi x)$ and $u(t,0)=u(t,1)$.   Solve $u_t=u_{xx}+u_x$.  I had this on an exam and tried to write $u$ as a product of two single variate functions and convert to an ode using the usual methods but things got messy and I couldn't finish. I also tried to write $u$ as a Fourier series in $x$ with coefficients $a_k(t)$ depending on $t$, but this also didn't seem to yield anything.  Is there a more clever way to approach this, possibly with Fourier series? I heard from a friend there may be a Fourier transform method since the equation was "homogeneous in momentum space."   Thanks! AuraClientService.postProcess: error in processing [RangeError: Maximum call stack size exceeded] - Client Side Action I have a lightning component that is using ui:inputSelect.   The component code:              &lt;div class="slds-form-element__control"&gt;                 &lt;ui:inputSelect class="slds-select" aura:id="quals" change="{!c.getPreCodes}"&gt;                     &lt;aura:iteration items="{!v.questions}" var="q"&gt;                          &lt;ui:inputSelectOption aura:id="question" text="{!q.Id}" label="{!q.Question_Text__c}"/&gt;                     &lt;/aura:iteration&gt;                 &lt;/ui:inputSelect&gt;             &lt;/div&gt;   The controller:      getPreCodes : function(cmp, event, helper){         var selected = cmp.find("quals").get("v.value");          var action = cmp.get("c.getPreCodes");         action.setParams({             "qualID" : selected         });         action.setCallback(this, function(response){             var state = response.getState();             if (state === "SUCCESS") {                  console.log('precodes: ', response.getReturnValue());              }         });          $A.enqueueAction(action);     }   The basic logic is that the uiSelect is dynamically populated on init (this works fine). When a user makes a selection the "change" parameter function is fired to retrieve a list from the database and pass it to another component.   However, the change function {!c.getPreCodes} seems to be called recursively causing a      "Something has gone wrong. AuraClientService.postProcess: error in   processing [RangeError: Maximum call stack size exceeded] . Please try   again."   error. If I comment out the enqueueAction the function only runs once (nothing is called recursively) so I suspect it has something to do with the controller call. What command(s) would you use to extract all of the usernames from a database called /etc/passwd and then sort this output alphabetically in reverse order? Installing VMware on 18.04: Failed to build vmmon I'm studying special relativity and saw the 2 postulates of Einstein. The most remarkable one for me is the universal speed of light. Einstein postulated that the speed of light in vacuum is the same for all inertial observers, regardless of the motion of the source. But what if we are accelerating and we are changing from one inertial frame to another, how will we observe the speed of light? Is it still the same? I suggest it's not? Because I alread saw a small introduction to general relativity where the light will bend in a gravitational field and therefore also when you accelerate. So does the speed of light change because it bends? Ruby on Rails on IIS? Looking for a short story about an insect-like alien captured by humans on its own planet This poor creature is taken aboard the spaceship and the humans do not know that it is intelligent.  The alien can repeat what it hears, e,g, "pass the sugar".  It is able to escape at night and it communicates messages to its fellow aliens.  It directs that they turn up the heat of the atmosphere (somehow they can do this) so as to force the humans to leave.  The alien protagonist states that it will die w/ the humans or leave with them. In all shells I am aware of, rm [A-Z]* removes all files that start with an uppercase letter, but with bash this removes all files that start with a letter.  As this problem exists on Linux and Solaris with bash-3 and bash-4, it cannot be a bug caused by a buggy pattern matcher in libc or a miss-configured locale definition.  Is this strange and risky behavior intended or is this just a bug that exists unfixed since many years? Is there a continuous function such that $\int_0^{\infty} f(x)dx$ converges, yet $\lim_{x\rightarrow \infty}f(x) \ne 0$? Is there a continuous function such that $\int_0^{\infty} f(x)dx$ converges, yet $\lim_{x\rightarrow \infty}f(x) \ne 0$?  I know there are such functions, but I just can't think of any example. Stop setInterval call in JavaScript I am using setInterval(fname, 10000); to call a function every 10 seconds in JavaScript. Is it possible to stop calling it on some event?   I want the user to be able to stop the repeated refresh of data. Why do the directories /home, /usr, /var, etc. all have the same inode number (2)? When I dock my Windows 7 laptop, I want it to prefer the wired ethernet connection over WiFi.  This is a pretty straightforward thing to do on my Mac - I just reorder my network preferences, and it "does the right thing." I just can't figure out how to achieve the same thing on my Win7 laptop.  So, when I'm docked, it connects to WiFi, and then fails to connect to servers on the local wired network. How do I fix this? How to tile textures in Cycles? How to calculate $$\int_{0}^{\pi/2}{\{\tan(x)\}dx}$$ where $\{x\}$ means the fractional part of $x$. I mentioned the zero points of $\{\tan(x)\}$. $\{\tan(x)\}$ equals to 0 iff $x=\arctan(k)$, $k$ is an integer. I tried to separate it into$$\sum_{k=0}^{\infty}{\int_{\arctan(k)}^{\arctan(k+1)}{(\tan(x)}-k)dx}$$ Then I found it hard to continue. I don't think I am on the right way. What determines the number of comments that are displayed?