As I was about to edit a question on Stackoverflow (and Meta) I noticed the sidebar notes overflow into the footer. This also seems to be happening in meta.  Happens to me on:   Chrome 41 OS X Firefox 37 OS X Safari 8       Update  Since there is a , let me update my question and target specifically Meta. Since the question already has an answer and it states the sidebar is more important, then maybe on sites like Meta.SE where the sidebar is transparent, there should be a white background.
I have noticed that while asking questions and scrolling to the bottom of the page, the right sidebar containing recent questions covers the footer partially. Also, a part of it goes beyond the browser's boundary. It may not be a big problem but it still doesn't look good.    This also happens on the  page
How to get rid of banding in illustrator while using gradient? How to get Rid of Banding in illustrator while using Gradient Age limit is too strict Optional Android notifications for reputation changes I would like to get a notification if my reputation count has changed. I think there is already some internal API for that. (I can see that changes in the menu bar in the top).  I'm sure that some people would not like that so that should be optional. Capacitor with different charges on each plate I am confused as to whether/how capacitance changes when each plate has a different charge.  For example, consider a coaxial cable and put $20Q$ on the outer cable, and $-Q$ on the inner. Or how about concentric spheres, grounding either the inner or the outer? Why isn't temperature frame dependent? In (non-relativistic) classical physics, if the temperature of an object is proportional to the average kinetic energy ${1 \over 2} m\overline {v^{2}}$of its particles (or molecules), then shouldn't that temperature depend on the frame of reference - since $\overline {v^{2}}$ will be different in different frames?  (I.e. In the lab frame  $K_l = {1 \over 2} m\overline {v^{2}} $, but in a frame moving with velocity $u$ relative to the lab frame, $K_u =  {1 \over 2} m \overline {(v+u)^{2}}$). Isomorphism between $\mathfrak o(4,\mathbb R)$ and $\mathfrak o (3,\mathbb R) \oplus\mathfrak o (3,\mathbb R) $ How do I get attention for one of my own questions without a good answer? Removing Firefox in Ubuntu with all add-ons like it never existed I have been using Firefox for a long time in Ubuntu, I downloaded some add-ons but it made firefox extremely slow, even if I remove them nothing will change.  I tried to remove Firefox also, but re-installing it will somehow recover the same Firefox I had- it seems it write some info somewhere that even if you remove Firefox, it will keep them.  Moreover, I am not able to use see any flash videos or website with Firefox(chrome works fine).. Honestly I tampered with plug-in settings in Firefox that this happened. But right now I can't do anything to overwrite the setting...  My question is how I can remove Firefox in a way to remove any previous traces and re-install a new version like for the first time? Shapefile: "table1.shp"   Field name: "Name" Field name: "Result"   Flat file: "referenceTable"   Field name: "STREET" Field name: "AKA"   I need to compare the value "Name" in "table1.shp" to the value "STREET" in "referenceTable"  If the values are the same then put the "AKA" value into the "Result" in "table1.shp"     Here is my code.  I got stuck on accessing the elements from the array  import arcpy, os, sys, string from array import *   table1 = "G:\\xStreetNew\\table1.shp" table1_column = ['Name', 'Result'] referenceTable = "G:\\xStreetNew\\Test.gdb\\referenceTable" referenceTable_column = ['STREET', 'AKA']  referenceTable_List = [] with arcpy.da.SearchCursor(referenceTable, referenceTable_column) as rCur: for r_row in rCur:     reference_row = r_row[0].split(",")     referenceTable_List.insert(0,reference_row) ##print sorted(referenceTable_List)  Table1_Update_Cursor = arcpy.da.UpdateCursor(table1, "Name") for row in Table1_Update_Cursor:   if row[0] == None:   row[0] = row[0] else:   row[0] = row[0].replace(";",",")   Table1_Update_Cursor.updateRow(row)  table1_List = [] with arcpy.da.SearchCursor(table1, table1_column) as tCur: for t_row in tCur:     row = t_row[0].split(",")     table1_List.insert(0,row) ##print sorted(table1_List)  Table1_row = len(table1_List) Table1_column = len([table1_List]) ref_row = len(referenceTable_List) for i in range(0,Table1_row):  #Table Row   for ii in range(0,Table1_column):   #Table Column     print table1_List[i][ii]   Below was my old post.  Sorry for the confusion.  I have a shapefile named "table1.shp".     I would like to get all values from fielname "Name" from this table and put them into a list. Able to output each element from the list     So far, I'm able to create a list but not too sure how to get to value "AVENUE 33" or "CHAPMAN ST"  This is my code:  import arcpy, os, sys, string from array import *   table1 = "G:\\xStreetNew\\table1.shp" referenceTable = "G:\\xStreetNew\\Test.gdb\\referenceTable" cursor = arcpy.da.UpdateCursor(table1, "Name") for row in cursor: if row[0] == None:     row[0] = row[0] else:     row[0] = row[0].replace(";",",") cursor.updateRow(row) table1_column = ['Name'] table1_curObj = arcpy.da.SearchCursor(table1, table1_column) table1_List = [] for row in table1_curObj:    table1_row = row[0].split(",")    table1_List.insert(0,table1_row)    print table1_List[0] Can bosons that are composed of several fermions occupy the same state? It is generally assumed that there is no limit on how many bosons are allowed to occupy the same quantum mechanical state. However, almost every boson encountered in every-day physics is not a fundamental particle (with the photon being the most prominent exception). They are instead composed of a number of fermions, which can not occupy the same state.  Is it possible for more than one of these composite bosons to be in the same state even though their constituents are not allowed to be in the same state? If the answer is "yes", how does this not contradict the more fundamental viewpoint considering fermions? I have to prove that:     $$\sum_{k=0}^{n} {{m+k} \choose{m}} = { m+n+1 \choose m+1 }$$   I tried to open up the right side with Pascal's definition that: $$ { n \choose k} = {n-1 \choose {k}} + {n-1 \choose {k-1}}$$  Here is what I came up with, and I am sure it is wrong because it does not equal the left side:  $$ {m+n+1 \choose m+1} = {m+n \choose m+1} + {m+n \choose m} = ... ={m+n \choose m+1} + {m+n-1 \choose m} + {m+n-2 \choose m-1} + ... + {m \choose m+1} = \sum_{k=0}^{n} {m+k \choose m+k-n+1 }  $$  Which, again, probably is wrong because it is not equal $\sum_{k=0}^{n} { m+k \choose m}$. Any help is appreciated As small as it may be, does every 'thing' have a gravitational pull?  That is, something with mass or energy. No matter how obsolete or negligible it may be, is it there? If so, how is it calculated? What does 'it' affect? I'm not particularly fond of apps cluttering my $HOME directory with their own files or directories. It's rarely a problem, because most apps have the courtesy to hide their data by prefixing it with a dot or conforming to the ~/.config standard. But not snap.  Q1: Have I misunderstood this directory?  Is ~/snap really a directory which I'm supposed to enter and access on a daily basis on a par with ~/downloads, ~/pictures, ~/work, etc?  Q2: In any case: Can I move it e.g. ~/.snap?  I can't find anything like /etc/snap, /etc/default/snap, or ~/.config/snap to tweak things. I tried export SNAP_USER_DATA=$HOME/.snap but it didn't work. What's the difference between struct and class in .NET? In Lubuntu, there's no 'Add New Program...' button in Desktop Session Settings. Is there an easy way to add new autostart programs in Lubuntu? Why does "stigmata" [often] have penult stress? I have been studying the pronunciation of Greek-derived words in English, and I've found an odd anomaly. There are (at least) two possible pronunciation patterns for plural word-forms that end in -&#8288;mata (which correspond to singular word-forms that end in -&#8288;ma).   Antepenult stress (expected)  It appears that it is always possible to place the stress on the antepenult (third-to-last) syllable, such as:    /ˈlɛmə/, /ˈlɛmətə/  /ˈskiːmə/, /ˈskiːmətə/  /ˌtɛrəˈtoʊmə/, /ˌtɛrəˈtoʊmətə/~/ˌtɛrəˈtɒmətə/  /ˈstɪɡmə/, /ˈstɪɡmətə/   This is what would be expected from  (I believe most or all of these words came through Latin before entering English), since the penultimate "a" in the original Greek words is short.  Maybe Latin vowel quality and stress rules are not very relevant; certainly, few English speakers know about them nowadays. And even with antepenult stress, some of these pronunciations do not seem to follow all of the traditional rules for pronouncing Latin-derived terms in English. I was reminded by some comments in this  that  in antepenult stressed syllables, we would expect tense ("long") vowels to be shortened due to  (TSL), yielding pronunciations like /ˌtɛrəˈtɒmətə/ (which I just noticed is in fact listed in the Oxford English dictionary) and ?/ˈskɛmətə/ (which is not). (Compare to genus~genera /dʒiːnəs/~/dʒɛnərə/, and perhaps opus~opera /oʊpəs/~/ɒpərə/). However, there are other Latinate plural forms that typically don't have trisyllabic laxing (matrices, also I think helices), or where both the lax- and tense-voweled pronunciations coexist (codices, apices), so I guess the apparent lack of it in schemata should not be surprising. (There are even some exceptions to TSL in singular nouns like obesity.)  Penult stress (unexpected)  The other pronunciation seems to exist only for a couple of words, in which the penultimate "a" is commonly stressed and broadened: stigma ~ stigmáta  (listed by both the Merriam-Webster dictionary and the ), and also sometimes schéma ~ schemáta /skiːˈmɑːtə/ (listed only by the ). (Neither the Merriam-Webster dictionary nor the Oxford Learner's Dictionaries list *"lemmáta").  I'm wondering why this pronunciation exists. It's an irregular plural either way, and putting the stress on the penultimate syllable creates a stress change between the singular and the plural forms.  (It's true that all of these words are rare, and some people might pronounce some of their plurals differently. The pronunciations I give here are simply the ones listed in dictionaries.)  The plural form "stigmata" is probably most common in religious or theological contexts (where it refers to the wounds of Christ), so at first I wondered if the penultimate stress was supposed to be closer to the original Greek pronunciation, but according to , the stress is on the antepenult in Greek as well.  So, what's up with this? Did the stress perhaps change in Latin over time, is this a tradition of Greek accentuation that I'm not familiar with, is this a simple matter of ignorance of the original position of the stress that has now become entrenched with time and usage, or is this somehow explainable by established English stress patterns? (For example, do English speakers have some natural preference for a penultimate stress on polysyllabic words?)  If nobody knows of a reason, I suppose I can just put it down to people encountering the word mainly in text, not knowing which syllable to stress, and choosing the penult because it sounds better to them.  (I asked this question a while back on , but nobody knew of any reason.) What are the differences between consumer grade SSDs and the much more expensive enterprise SSDs? I am in need of a terabyte or so of storage space for Lucene indices on a testing server.  I'm having a hard time differentiating between disks like the  for about $450 vs  of dollars.  What concerns should I have regarding the 840 evo, and what should I be looking for?  This server will be used strictly for in-house testing purposes by our development team and will have to put up with periodic load testing. $\mbox{rank}(A)=1$ implies $\det(A+I)=\mbox{trace}(A)+1$ This problem comes from exercise from my lecturer  Let $A$ be a square matrix such that $\mbox{rank}(A)=1$. Prove that $\det(A+I)=\mbox{trace}(A)+1$.  ($I$ is the identy matrix)  I usually haven't any idea in solving linear algebra problem. Earlier today I posted  which yielded a .  I'd like to attract attention to this answer in the hope that the answer will get upvoted, as a kind of reward for the quality of the answer.  Is there anything that I can do to achieve this? IS or ARE? "The only thing that I want you to hit right now IS/ARE the books" In this sentence, which is the right word?     The only thing that I want you to hit right now is/are the books.