Recently I've start to implement some script to run using Linux &quot;parted&quot; to change the partition structure on our SoC system. When doing that I've encounter with some problems, The partitions on our device where not aligned. The primary and extended partitions are aligned, but the logical partitions not. The person that made the script for creating the image added offset of 63 sectors for each logical partition in the start sector arguments. I've try to figure why and I've read that each logical partition has &quot;MBR&quot; (EBR is the right name I think) at the beginning that store his value and points to the next partition and all of this structure is basically a linked list of partitions. So I'm guessing that the 63 sectors offset is to leave space for the EBR (We do the same thing in the first partition, its starts with 2048 sectors offset to leave space for the MBR). first question - The offset for each logical partition is necessary? If not great. no need to read the second question. Q2: This 63 sectors offset cause the misalignment in the logical partitions. My first thought was to change this offset to 2048 sectors, but it will create &quot;holes&quot; and I'm not sure if is the right thing to do?
I'm playing around with fdisk and I tried to create a partition on an empty USB drive. Here's how that went: Command (m for help): n Partition number (1-128, default 1): 1 First sector (34-61187102, default 2048): 2048 Last sector, +/-sectors or +/-size{K,M,G,T,P} (2048-61187102, default 61187102): +30000000           Created a new partition 1 of type 'Linux filesystem' and of size 14,3 GiB.  so just one partition with 30 million sectors. However, when I check how many sectors it contains I get:  I'm checking with a different program and I see again that additional sector:  Sorry for the pettiness :) I'm learning.
Proof of $\lim_{n\to \infty} \sqrt[n]{n}=1$ Thomson et al. provide a proof that $\lim_{n\rightarrow \infty} \sqrt[n]{n}=1$ in . It has to do with using an inequality that relies on the binomial theorem:  I have an alternative proof that I know (from elsewhere) as follows.  Proof. \begin{align} \lim_{n\rightarrow \infty} \frac{ \log n}{n} = 0 \end{align} Then using this, I can instead prove: \begin{align} \lim_{n\rightarrow \infty} \sqrt[n]{n} &amp;= \lim_{n\rightarrow \infty} \exp{\frac{ \log n}{n}} \newline &amp; = \exp{0} \newline &amp; = 1 \end{align}  On the one hand, it seems like a valid proof to me. On the other hand, I know I should be careful with infinite sequences. The step I'm most unsure of is: \begin{align} \lim_{n\rightarrow \infty} \sqrt[n]{n} = \lim_{n\rightarrow \infty} \exp{\frac{ \log n}{n}} \end{align} I know such an identity would hold for bounded $n$ but I'm not sure I can use this identity when $n\rightarrow \infty$. Question: If I am correct, then would there be any cases where I would be wrong? Specifically, given any sequence $x_n$, can I always assume: \begin{align} \lim_{n\rightarrow \infty} x_n = \lim_{n\rightarrow \infty} \exp(\log x_n) \end{align} Or are there sequences that invalidate that identity?  (Edited to expand the last question) given any sequence $x_n$, can I always assume: \begin{align} \lim_{n\rightarrow \infty} x_n &amp;=  \exp(\log \lim_{n\rightarrow \infty} x_n) \newline &amp;=  \exp(\lim_{n\rightarrow \infty} \log x_n) \newline &amp;=  \lim_{n\rightarrow \infty} \exp( \log x_n) \end{align} Or are there sequences that invalidate any of the above identities? (Edited to repurpose this question). Please also feel free to add different proofs of $\lim_{n\rightarrow \infty} \sqrt[n]{n}=1$. Is it feasible to build a stream cipher from a cryptographic hash function? A few years ago I devised a symmetric-key system that worked like so:  H()   = some hashing function h     = the number of bits in the result of H() key   = bits to be used as a key ^     = the XOR operation +     = concatenation len() = the length function (in bits)  max = ceiling(len(cipertext) / h) pad = pad_0 + ... + pad_max pad_0 = H(key) ^ H(plaintext) pad_n = H(pad_(n-1)) cipherpart_n = plaintext_n ^ pad_n ciphertext = H(plaintext) + cipherpart_0  + ... cipherpart_max   Basically, it builds up a "pad" based on the hash of the message and hash of the key and XORs the message against it.  I am not actually an expert, so I was wondering why an approach like this isn't very common. I have already proved Triangle Inequality $\lVert v+w\rVert \le \lVert v \rVert+\lVert w \rVert$ in vector space $\mathbb{R}^n$. However, I'm having difficulties proving the Reverse Triangle Inequality in the vector space.  I have started with   $$\lVert v \rVert^2=v \cdot v-w\cdot w+w\cdot w \le \lVert v-w \rVert+\lVert w \rVert^2$$ $$\lVert w \rVert^2=w \cdot w-v\cdot v+v\cdot v \le \lVert w-v \rVert+\lVert v \rVert^2$$  based on the Triangle Inequality but I don't know if it is correct. If this is right, I think I can go on with proving it the same way I would the normal Reverse Triangle Inequality. Duo of alien xenologists study couple of Terran explorers, later save them Omitting fields in Bibliography Does Sheldon Cooper have Asperger's Syndrome? How to sum data.frame column values? Check if the application is already installed I need an adjustment layer which will invert in the same way as when you select some text in a text layer Remove OTA downloaded (but not installed) iOS 8 I've downloaded the new iOS 8 update on my iPhone 5 but am getting second thoughts about actually installing it.  Is there a way for me to delete that download or am I at the point of no return? The strange thing about the maximum in Planck's law Take $\mathbb{R}$ as a vector space over $\mathbb{Q}$, then a basis for $\mathbb{R}$, then $|B|=2^{\aleph_0}$ I am trying to prove that Given $\mathbb{R}$ as a vector space over $\mathbb{Q}$, and a basis for $\mathbb{R}$, then $|B|=2^{\aleph_0}$.  Proof: Suppse that $|B|&lt;2^{\aleph_0}$, then $\mathbb R = span\{ b_i ; b_i \in B \}$ So $ \mathbb R = \{ \Sigma_{i=1}^{\infty}\alpha_i b_i ; \alpha_i \in \mathbb Q, b_i \in B, i \in \mathbb N \} = \bigcup_{n=1}^{\infty}\{\Sigma_{i=1}^n \alpha_ib_i\}$. Which is a contradiction since a countable union of countable union of countable sets is countable and $\mathbb R$ is not.  What do you think?  Thank you, Shir How to model this odd-shaped distribution (almost a reverse-J) I need to find algorithm that can calculate centroid A (aka gravity center, geometric center, center of mass) from the figure where circles T1,T2,T3,T4,T5,..,Tn intersect AND length of line R from centroid to farthest corner of mentioned figure   Following information is given:   T1   Latitude    =   56.999883   Longitude   =   24.144473   Radius  =   943 T2   Latitude    =   57.005352   Longitude   =   24.151168   Radius  =   857 T3   Latitude    =   57.005352   Longitude   =   24.163356   Radius  =   714 T4   Latitude    =   56.999042   Longitude   =   24.168506   Radius  =   714 T5   Latitude    =   56.994226   Longitude   =   24.15709    Radius  =   771   Result should look like this:  A Latitude = XX.XXXXXXX    Longitude = XX.XXXXXXX  Radius = XX    As you probably already figured out, I am working on software that can find device location by closest Wifi Access Points or Mobile Base stations, as number of access points or base stations might change, I need an algorithm that can adapt to uncertain amount of points.  There are some similar questions  and , but none of them exactly answers to my question. Oneboxing is a handy feature in chat for quickly previewing links, but the list of supported sites is very small, and occasionally boxes for sites such as Wikipedia can break and fetch any image/text.  Instead of having to request additional sites to be added to the onebox list (, , , , , and of course ), we could let the sites themselves handle the oneboxing with some &lt;meta&gt; tags, such as:  &lt;meta name="onebox-title" content="The Onebox Title"/&gt; &lt;meta name="onebox-image" content="/image.png"/&gt; &lt;meta name="onebox-summary" content="This is the summary for a site's onebox"/&gt;   Then when a link is placed on its own in chat, the oneboxing spider would look for these tags and, if they are found, show the appropriate data.  Support for these tags would certainly be bad (for lack of any real better term) at first, though most users of SO chat could easily add it to their personal / company's sites (should they be in such a position) and writing friendly suggestions to other sites to implement them isn't exactly a gargantuan effort.  This would also present an opportunity for currently oneboxed sites to set in stone what should be shown, such as each Wikipedia article setting the main image to be oneboxed instead of SO's spider picking one willy-nilly.  Finally, sites implementing these tags would lay the foundation for other sites and services to develop similar features to the onebox, without having to write per-site scrapers. I need to know a word which means:     "negligence shown by a person in performing a duty, or a responsibility, or any given task."   or,      "A person who is negligent in performing their duties/responsibilities."   One possible choice is the use of word "delinquent". Is there any other word?  Please provide the usage of suggested word in a sentence also. How to run xrandr commands at startup in Ubuntu How can I run the following xrandrcommand on startup?  xrandr   cvt 1368 768  xrandr --newmode "1368x768_60.00"   85.25  1368 1440 1576 1784  768 771 781 798 -hsync +vsync xrandr --addmode VGA1 1368x768_60.00 xrandr --output VGA1 --mode 1368x768_60.00 Kill process spawned by ssh when ssh dies How do I calculate my skill modifier? I'm trying to fill out the skills section on my first character, but when I look at the character sheets in the Starter Set as examples of how to make a character, the skills that are circled have higher modifiers than their Dexterity or Strength or whatever should make them.  I've filled out all skills but those. What do I add to the ability modifier to get those numbers?   My abilities are Strength 13, Dexterity 14, Constitution 11, Intelligence 15, Wisdom 8, and Charisma 8. Proficiencies are Arcana, Athletics, History, Investigation and Stealth. My saving throws are Strength and Dexterity.   I just started D&amp;D and have the Player's Handbook, DM's Guide, Monster Manual, and the Starter Set. Why won't Blender run on Windows XP? I downloaded Blender 64 bit and the OS indicated that the program was not compatible with my computer chip. I then downloaded the 32 bit version which seemed to allow me to install. However the blender Icon in windows when pressed informs me that the program is not a window application. I have an Intel(R) Core (TM)2 Duo CPU E7300 @2.66Ghz if that is important and I am running XP. I am fairly sure I am doing something wrong here- can anyone help please?