In a series circuit, the voltage is the same everywhere on that circuit. However, thinking about Voltage as a steady force or potential, I imagine that at parts of the circuit without resistance, the current would be greater as the force would be able to move them faster, without any obstruction. Why is this not the case?
I understand when we say current, we mean charge (protons/electrons) passing past a point per second. And the charges have energy due to the e.m.f. of the power supply.  Now tell me, if a lamp has resistance and you hook it in the circuit, how will the current stay the same? The charges obviously lose energy in the lamp and so become SLOWER, which should mean current decreases, right?  [Edit] All answers explained a bit of everything, so it was hard to choose one. If YOU are looking for an answer, please check the others too, in case the accepted one doesn't answer your question.
For a workflow tool I made a panel in which it displays each separate library that is linked in my file. For each library I want to add some buttons that does stuff to the library in question.  So in this example I have my panel which shows for example 2 libraries and for each one it creates a "reload" button.  Now my question is.. How do I make it so the reload button only reloads the library I want to reload? I would probably have to give the button an id or something so it knows for which library it was created...  my code so far:  import bpy  libs = bpy.data.libraries  class Reloadlib(bpy.types.Operator):     """Reloads the current Library"""     bl_idname = "my.reload_lib"     bl_label = "Reload"      def execute(self, context):         libs[?????].reload()         self.report({'INFO'}, 'Reloading ' + libs[?????].name)         return {'FINISHED'}  class LibPanel(bpy.types.Panel):     """Creates a Panel in the scene context of the properties editor"""     bl_label = "Scene Libraries"     bl_idname = "SCENE_PT_layout"     bl_space_type = 'PROPERTIES'     bl_region_type = 'WINDOW'     bl_context = "scene"      def draw(self, context):         layout = self.layout         scene = context.scene         layout.label(text="Libraries:")          for i in libs:             layout.label(text= i.name.replace(".blend",""))             row = layout.row()             sub = row.row()             sub.operator("my.reload_xref", icon = "FILE_REFRESH")  def register():     bpy.utils.register_class(Reloadlib)     bpy.utils.register_class(LibPanel)  def unregister():     bpy.utils.unregister_class(Reloadlib)     bpy.utils.unregister_class(LibPanel)  if __name__ == "__main__":     register()   Where the question marks are is where I should be able to make the difference between the first [0] or second [1] library in the libs[] array.  In future I would also like to ad an 'open' and an 'unlink' button for each library so I can make changes to the other file. But this works by the same principle as the reload button. In a question on "along" vs "alongside", I have seen this question and the correct answer on the web site makes me confused.      The question is: I enjoyed my walk _________________ the river.  a) along b) alongside  I selected "...along the river" as the correct answer, but on the web site it is shown as wrong and the correct answer is "alongside".  How can that be? I still do not agree, because I have studied the difference between the two. "along" is just the right preposition for thin and long places like road, path, street, beach etc".   So, why would the correct answer be "alongside" which simply means "next to"? Do you not think "along" seems to be better fitting?  Regards,  Note: I would be more than gratefull, if somebody show it to me in a video, like "a walk along the river" and "a walk alongside the river". Maybe I can understand the how "a walk along the river" and "a walk alongside the river" would take place. Evaluate $\lim_{n\to\infty} [{1\over kn}+{1\over k(n+1)}+{1\over k(n+2)}+\cdots+{1\over k(n+p-k)}]$ where $k<p$ There are four options. Which of them is correct?- (a)${p\over k}$ (b)${k\over p}$ (c)$\log({p\over k})$ (d)${\log p\over k}$ I somehow want to use the rule for evaluating this kind of sum using integration, i.e. $\int_{0}^{1} f(x) \ dx=\lim_{n\to\infty} {1\over n}\sum_{r=1}^{n}f({r\over n})$  But the given expression $\lim_{n\to\infty} [{1\over kn}+{1\over k(n+1)}+{1\over k(n+2)}+\cdots+{1\over k(n+p-k)}]={1\over k}\lim_{n\to\infty}{1\over n}\sum_{r=0}^{p-k}\frac{1}{1+{r\over n}}$, sum running from $0$ to $p-k$ instead of $n$. So, how to evaluate this limit? Thanks for assistance in advance. Why aren't Christoffel symbols tensors? - asked from a fibre bundle perspective Let $X$ be obtained by removing finitely many lines from $\mathbb{R}^3$. How do I prove $X$ is connected? Let $X$ be obtained by removing finitely many lines from $\mathbb{R}^3$. How do I prove $X$ is connected?  I think the way to go about this is to show $X$ is path-connected but I'm not quite sure. I have a very stupid question. I developed a website that has only one page at the public html directory(index.php).  all content are dynamically loaded as different pages.   How can i SEO my pages for google?  i mean like the what we type in this site are .............i believe stored in database and search engine find these pages like any static pages...  Just a little tip would be appreciable.......! I set /usr/bin, /usr/lib, and /usr/share to be owned by my regular user and now I am getting interesting errors After running this command - sudo chown -R $(whoami) usr/{lib/node_modules,bin,share} I am not able to run sudo anymore: sudo: /usr/bin/sudo must be owned by uid 0 and have the setuid bit set. How do I fixed that?  I read  but I am not sure what advice to follow and if it's applicable to my case. C/C++ check if one bit is set in, i.e. int variable int temp = 0x5E; // in binary 0b1011110.   Is there such a way to check if bit 3 in temp is 1 or 0 without bit shifting and masking.  Just want to know if there is some built in function for this, or am I forced to write one myself. Compiler warning: null reference exception I have the following code in Visual Studio 2005.      Dim OutFile As System.IO.StreamWriter     Try         OutFile = New System.IO.StreamWriter(Filename)        // Do stuff with OutFile     Catch Ex As Exception        // Handle Exception     Finally        If OutFile IsNot Nothing Then OutFile.Close()     End Try   But VS2005 brings up the warning for the line "If OutFile IsNot.." that      Variable 'OutFile' is used before it has been assigned a value. A null reference exception could result at runtime.   Is there some way of removing this warning by subtly altering the code or is there just a better way of doing what I'm trying to do?  Thanks  Rob Magnetic Field in the presence of a conductor I am studying for my quals and came across an old question that reads like the following:      There are two regions in space separated by an infinite conducting plane. Region 1 has a magnetic dipole of moment $\vec{\mu}$ located a distance $d$ from the plane. What is the magnetic field $\vec{B}$ everywhere in region 1?   I know that for a perfect conductor (superconductor), the normal component of $\vec{B}$ is zero–although I don't exactly know why–but I don't know if that is the case when the problem involves a "conductor" (not explicitly a perfect conductor).  TL;DR: Can anybody give me some insight about the magnetic boundary conditions of a stationary magnetic field in the presence of a conductor?  Thanks! ACPI PPC Probe failed. Starting version 219 NVIDIA Are there consequences to stamps in my passport that are not from border control? Why do employers require you to spread your 401(k) contributions throughout the year to get the maximum match? I think the title says it all. I can't see any reason employers have to incentivize employees to contribute to their 401(k) evenly throughout the year. Instead couldn't they use a relatively simple formula that is based on how much of their income the employee has contributed to their 401(k) thus far for the year? If that or their current contribution is over the threshold, they get the match this pay period, even if they didn't contribute anything.  EDIT: To clarify, my employer matches 100% of the first 3% of my contribution and 50% of the next 2%. The match is added every pay period along with my contribution. I am pretty sure there is no "true-up" feature, so if I were to hit the $17.5K limit early, and not be able to contribute at least 5% of my salary, I would not get the full match. So I have to be careful to make my contributions evenly throughout the year to get the maximum match. Just trying to figure out my employer's motivation for requiring this. How can I get my external IP address in a shell script? youtube-dl failed to extract signature It is considered very useful to utilize youtube-dl software for downloading youtubes.  A message is seen and it stopped working, which is following.  ERROR: Signature extraction failed: Traceback (most recent call last):   File "/usr/lib/python2.7/dist-packages/youtube_dl/extractor/youtube.py", line 479, in _decrypt_signature     video_id, player_url, s   File "/usr/lib/python2.7/dist-packages/youtube_dl/extractor/youtube.py", line 383, in _extract_signature_function     res = self._parse_sig_js(code)   File "/usr/lib/python2.7/dist-packages/youtube_dl/extractor/youtube.py", line 454, in _parse_sig_js     u'Initial JS player signature function name')   File "/usr/lib/python2.7/dist-packages/youtube_dl/extractor/common.py", line 391, in _search_regex     raise RegexNotFoundError(u'Unable to extract %s' % _name) RegexNotFoundError: Unable to extract Initial JS player signature function name; please report this issue on https://yt-dl.org/bug . Be sure to call youtube-dl with the --verbose flag and include its complete output. Make sure you are using the latest version; type  youtube-dl -U  to update. ; please report this issue on https://yt-dl.org/bug . Be sure to call youtube-dl with the --verbose flag and include its complete output. Make sure you are using the latest version; type  youtube-dl -U  to update.   What should I do to proceed? Proving a basis for inner product space V when $||e_j-v_j||< \frac{1}{\sqrt{n}}$. Suppose $(e_1,e_2,...,e_n)$ is an orthonormal basis of the inner product space $V$ and $v_1,v_2,...,v_n$ are vectors of $V$ such that $$||e_j-v_j||&lt; \frac{1}{\sqrt{n}}$$ for each $j \in \left\{1,2,...,n \right \}$. Prove that $(v_1,v_2,...,v_n)$ is a basis of $V$.  I am completely lost and just starting to learn about inner product spaces. Could someone provide a proof with the explanation of how you got there? Renaming files in lexicographical order with a numerical pattern that increases sequentially with fixed padding I have files such as  a bb ccc abc emrls   I would like to rename them so that, after sorting them (for example, lexicographically), each file gets the following name:  00001 00002 00003 etc   where the # of digits for the 0 padding is specified a priori, e.g. 6 in the case above (assuming that we know how many digits are needed).  Since the shell I am most comfortable with is zsh, I'm interested in solutions that benefit from features on zsh (maybe using zsh's zmv?). I would also be interested in solutions that are compatible with Bash. Router to router setup works fine with straight cable up to 2-3 meter it is not working for 45 meter why? How to roll perception checks for characters who aren't actively looking without arousing suspicion? This applies to all d20 systems, but with an example from the from the Pathfinder  (emphasis mine):  Stonecunning: Dwarves receive a +2 bonus on Perception checks to potentially notice unusual stonework, such as traps and hidden doors located in stone walls or floors. They receive a check to notice such features whenever they pass within 10 feet of them, whether or not they are actively looking.  In this case, does the GM roll the check in secret or ask the player roll the check? If the GM asks the player to roll for the check, what stops situations like:  GM: (interrupting) &quot;Gimli, Roll a perception check.&quot; Dwarf player: &quot;Oh, it's a natural one, I guess I don't see anything.&quot; Human player: &quot;Okay, I'll roll a perception check for anything unusual in this room. Nice! 19. How about 19, does 19 work for you?&quot; GM: &quot;Gimli, everything looks kosher to you. Aragon, you notice a rock coloured tarp on the ground here, covering what looks like a pit trap.&quot;  In this case, by telling the dwarf to roll his &quot;free&quot; perception check, he's telegraphed to the players that there is something to notice. How can this be fixed, without bluffing checks for nothing in particular to throw off the signal to noise ratio of similar checks? SEO in Stack Overflow We've been out of private beta for only two days, and stackoverflow.com is already ranking high in .  Are there any specific techniques applied in the site? I've been researching the subject for some time and haven't found it to be so easy.   even returns site-links.  ()