I want to say that &quot;now, I'm studying things other than what I learn in school&quot; with this present perfect sentence: Due to quarentine, I have begun to study things out of school, especially languages. Is out of school idiomatic in this context? What could sound better? Thank you
By taking courses, I have learned topic A. Through self-studying and discussion with others, I have explored topic B.    I also study topic A outside the classroom. What I want to emphasis is that topic B is not in my curriculum, but I study it on my own. Extracurricular activities can include both activities contributed to academic study although outside the normal curriculum, but also activities not contributed to academic study such as sports, volunteer work, etc. I want to emphasis the former activities. Do you say "outside classes", when mentioning study by yourself, i.e.      Outside classes, I have explored B.      If it were you, how would you rewrite the first quote for the same       meaning?    Thanks!
sObject ' ' type is not supported Hey everyone I've been seeing this a lot lately and am trying to figure out why this error is thrown when querying the SOAP API directly. I've tried several very basic SOQL queries such as  SELECT Body FROM AssetFeed   Only to be met with the sObject type 'AssetFeed' is not supported. error.  The account that I'm currently querying is just a standard user who accepted permission from an app that was created by a Developer Account, so I'm wondering if it might be permissions from the user or permission from the app itself? Possibly because Developer accounts cannot use 95% of whats offered?  The WSDL used is a v27.0 generated Partner WSDL if that helps narrow it down.  I've noticed this in multiple standard objects, so I'm wondering what the trend really is? Seems like a good informational question for future googling of others?  Running describeGlobal()  Array (     [0] =&gt; AggregateResult     [1] =&gt; Attachment     [2] =&gt; ChatterActivity     [3] =&gt; CollaborationGroup     [4] =&gt; CollaborationGroupFeed     [5] =&gt; CollaborationGroupMember     [6] =&gt; CollaborationGroupMemberRequest     [7] =&gt; CollaborationInvitation     [8] =&gt; ContentDocument     [9] =&gt; ContentDocumentFeed     [10] =&gt; ContentDocumentHistory     [11] =&gt; ContentDocumentLink     [12] =&gt; ContentVersion     [13] =&gt; ContentVersionHistory     [14] =&gt; EntitySubscription     [15] =&gt; FeedComment     [16] =&gt; FeedItem     [17] =&gt; FeedLike     [18] =&gt; FeedTrackedChange     [19] =&gt; Group     [20] =&gt; GroupMember     [21] =&gt; HashtagDefinition     [22] =&gt; Name     [23] =&gt; TaskPriority     [24] =&gt; TaskStatus     [25] =&gt; User     [26] =&gt; UserFeed     [27] =&gt; UserPreference     [28] =&gt; UserRecordAccess     [29] =&gt; UserRole )   Where would all the rest of my SOAP SObjects be? This seems like a very thin list compared to the 295 SObjects advertised Problem is to find sum  $$\frac{1}{3!}+\frac{4}{4!}+\frac{9}{5!}\cdots$$  What I knew doesn't apply on this problem  Some series are telescoping, some types are solvable using binomial , both look useless here Binomial gives  $$n (n-1) (n-2)x^3=1$$  $$n (n-1)( n-2)(n-3)x^4=4$$  What approach to use here? How to check if installing a package will require a reboot? I often install packages and updates for them, although sometimes it is not convenient to do a reboot if one of the packages needs it, so is there any way of telling BEFORE installing the package/update whether or not it will require you to do a reboot? I have already looked  and the solutions there don't solve my problem, nor the more or less same one described there. Running out of inodes How do multiple natural attacks work? Okay, I need some clarification. The  state this about natural attacks:     You do not receive additional natural attacks for a high base attack bonus. Instead, you receive additional attack rolls for multiple limb and body parts capable of making the attack (as noted by the race or ability that grants the attacks).   Let's say that I can shape into an . My BAB is +8/+3 and STR 5. An Oliphant has two natural attacks: Gore and Stomp (x2).  Reading the rules, it seems that I can't do two Gore attacks, like:   1st attack: AB +13. DAM 2d8 + 5 2nd attack: AB +8. DAM 2d8 + 5   because I don't get additional attacks for a high BAB. Does that mean I need to combine attacks instead? Example:   (Gore) 1st attack, AB +13. DAM 2d8 + 5 (2 Stomps) 2nd attack, AB +6*. DAM 2d6 + 5 * With the Multiattack feat, reduces secondary weapon penalty to &minus;2.   Also, does the damage from the two stomps equal 2d6 + 5, or should I roll damage for each stomp? (1st foot = 2d6 + 5, 2nd foot = 2d6 + 5). What can you use Python generator functions for? I'm starting to learn Python and I've come across generator functions, those that have a yield statement in them.  I want to know what types of problems that these functions are really good at solving. How to tell the probability of failure if there were no failures? I was wondering if there is a way to tell the probability of something failing (a product) if we have 100,000 products in the field for 1 year and with no failures? What is the probability that one of the next 10,000 products sold fail? Unable to cover get set in apex test class I am unable to cover the following class get set method. Need help in creating test class  public class Aresult{      public class Parent {         public String type {get; set;}         public String id {get; set;}         public String sequence_id {get; set;}         public String etag {get; set;}         public String name {get; set;}     } }   Please suggest  @isTest  public class CirriusGetItemsResultTest {     public static void myUnitTest(){         Aresult.parent a = new Aresult.parent();         a.type='hello';         a.id='hello';         a.sequence_id ='hello';         a.etag ='hello';         a.name ='hello';     } } Passive voice phrasing of "The bottle contains two liters" I want to find a set of integer solutions of Diophantine equation: $ax + by = c$, and apparently $\gcd(a,b)|c$. Then by what formula can I use to find $x$ and $y$ ?   I tried to play around with it: $x = (c - by)/a$, hence $a|(c - by)$.     $a$, $c$ and $b$ are known. So to obtain integer solution for $a$, then $c - by = ak$, and I lost from here, because $y = (c - ak)/b$. I kept repeating this routine and could not find a way to get rid of it? Any hint?  Thanks, Chan Specific derivatives have specific names. First order is often called tangency/velocity, second order is curvature/acceleration. I've also come across words like Jerk, Yank, Jounce, Jolt, Surge and Lurch for 3rd and 4th order derivatives. Is there a widely agreed list of names for these? How many orders have specific names?  In this case, I'm dealing with NURBs curves, so the "tangency" and "curvature" related words are to be preferred over "velocity" and "acceleration" words. Why would spacetime curvature cause gravity? It is fine to say that for an object flying past a massive object, the spacetime is curved by the massive object, and so the object flying past follows the curved path of the geodesic, so it "appears" to be experiencing gravitational acceleration. Do we also say along with it, that the object flying past in reality exeriences NO attraction force towards the massive object? Is it just following the spacetime geodesic curve while experiencing NO attractive force?  Now come to the other issue: Supposing two objects are at rest relative to each other, ie they are not following any spacetime geodesic. Then why will they experience gravitational attraction towards each other? E.g. why will an apple fall to earth? Why won't it sit there in its original position high above the earth? How does the curvature of spacetime cause it to experience an attraction force towards the earth, and why would we need to exert a force in reverse direction to prevent it from falling? How does the curvature of spacetime cause this?  When the apple was detatched from the branch of the tree, it was stationary, so it did not have to follow any geodesic curve. So we cannot just say that it fell to earth because its geodesic curve passed through the earth. Why did the spacetime curvature cause it to start moving in the first place? I'm having trouble solving a Fitch Style Proof and I was hoping someone would be able to help me.  Premises: p ∧ q  Goal: q ∨ r  Would be an assumption (p ∧ q => q ∨ r) in first step a correct one?   Then, q ∨ r Implication Elimination: 2, 1  Why is it not correct?  Thank you very much for any help! There seems to be a preference for to have the    18 mm - 55 mm 55 mm - 250 mm   lenses, but no mention of why they're better than a single 18-200mm. Could someone please explain why the two separate are better than the one combined, and if anyone has quantified this difference?  (I'm curious about Canon in particular.) Is this statement "Every element in the empty set is greater than itself." true or its negation is true? $p$ : Every element in the empty set is greater than itself.  $\neg p$ : Some element in the empty set is smaller than or equals to itself.      I do not have the answers to this exercise, but it came out in my exams. I simply do not understand. There is nothing in an empty set! How can nothing be greater/equals/smaller/ to itself? If I had to choose an answer, it has to be $\neg p$ since nothing is equals to nothing...   What is the answer? Game states & passing data between scenes Replace \input{fileX} by the content of fileX automatically Is it possible to change the default width of an image included via \includegraphics (from the graphicx package) to a custom value, for example \linewidth.  So I want something like this:  \documentclass{article}  \usepackage[draft,width=\linewidth]{graphicx}  %or something like \setglobalimagewidth=\linewidth  \begin{document}  \includegraphics{test1} %width=\linewidth \includegraphics[width=4cm]{test1} %width=4cm   \end{document} If $a,b,c \in \mathbb{R+}$ and $abc=1$ Prove That  $$S=\sum \frac{a}{a+b^4+c^4} \le 1$$  My approach:  we have $$S=\sum \frac{\frac{1}{bc}}{\frac{1}{bc}+b^4+c^4}=\sum \frac{1}{1+b^5c+bc^5}$$  Now by $AM \ge GM$ we have  $$\frac{1+b^5c+bc^5}{3} \ge b^2c^2$$ $\implies$  $$\frac{1}{1+b^5c+bc^5} \le \frac{1}{3b^2c^2}=\frac{a^2}{3}$$ Hence  $$S \le \frac{a^2+b^2+c^2}{3}$$  Can we proceed with this? Android cancel Toast when exiting the app and when toast is being shown