Fields not showing in graduating symbols I'm looking to apply a size based graduated style a point layer based on numerical values in the attribute table. Bigger value, bigger point. Basic procedure. However. In the symbology tab when I go to select the graduated value, the field II am looking for is absent... the majority of the fields are not selectable, despite me being able to view them in the attribute table. Below are 2 images. The first shows the symbology tab showing that I can't access the other fields. The second shows the layer properties and all the fields that are in the file. Can anyone tell me why I can't select these fields for graduated symbology?
Gduated symbology not taking attribute into account using QGIS I m working on a project on QGIS. I have a point shapefile vector that represents my store. In the attribute table, i have bunch of data such as size, unit per transaction and most importantly store turnover. When I want to graduate the symbology, the turnover isn't present in the list I can choose from. Does someone know why, and how to fix it?
How to use hook_node_presave to change field's value The computer gave me this output in a window:  E: Encountered a section with no Package: header E: Problem with MergeList /var/lib/apt/lists/archive.ubuntu.com_ubuntu_dists_natty_main_binary-i386_Packages E: The package lists or status file could not be parsed or opened.   How can I fix this? Using Python, how do I to read/write data in memory like I would with a file? The standard font packages make global changes to the fonts in my document. What if I want to use a particular font for just a portion of my text?   How do I find the right name of the font? How do I select the font? How do I restrict the scope of the font change?     There are separate answers for different flavors of TeX (quick links): How long do Tenacious and Unsung Hero badges take to be awarded? Just curious whether the process takes a while, and whether it scrapes through history to determine if it was once valid or not. Currently, I have 6 0-vote accepted answers and 20 1+-vote answers (), and that makes it > 5 and > 20% but not for long if voting goes up or down from here. ;-P  Update:  Special thanks to Grace Note for pointing out the  to follow. I upgraded this to a bug because it's been 48 hours during which the criteria supposedly were met. 6 0-votes, 20-23 1+ votes during the whole period. The criteria only last so long, so it may go out of scope soon. If it only checks every 3 days, I'm not sure if that's intentional or a bug. How do you tell if caps lock is on using JavaScript?  One caveat though: I did google it and the best solution I could find was to attach an onkeypress event to every input, then check each time if the letter pressed was uppercase, and if it was, then check if shift was also held down. If it wasn't, therefore caps lock must be on. This feels really dirty and just... wasteful - surely there's a better way than this? What happens to half of the energy in a circuit with a capacitor? For a simple circuit with a battery supplying a voltage $V$ to a capacitor, let us assume that the charge on the capacitor is $Q$. Now, the work done by the battery or the energy supplied is given by the relation:  $$W=QV$$  But the energy stored in the capacitor is given by:  $$U = \tfrac12 QV$$  The value of $Q$ as well as that of $V$ should be the same in both the equations.  Now my question is, where is the other half of the energy that the battery supplied? Before, the concept of imaginary numbers, the number $i = \sqrt{-1}$ was shown to have no solution among the numbers that we had. So we declared $i$ to be a new type of number. How come we don't do the same for other "impossible" equations, such as $x = x + 1$, or $x = 1/0$?  Edit: OK, a lot of people have said that a number $x$ such that $x = x + 1$ would break the rule that $0 \neq 1$. However, let's look at the extension from whole numbers to include negative numbers (yes, I said that I wasn't going to include this) by defining $-1$ to be the number such that $-1 + 1 = 0$. Note that this breaks the "rule" that "if $x \leq y$, then $ax \leq ay$", which was true for all $a, x, y$ before the introduction of negative numbers. So I'm not convinced that "That would break some obvious truth about all numbers" is necessarily an argument against this sort of thing. Does scaling lead to weak convergence to the null function? Let $f\in L^p(\mathbb{R}^d)$, with $1&lt;p&lt;\infty$. Is it true that    $$\lambda^{\frac{d}{p}}f(\lambda x ) \rightharpoonup 0\quad \text{ weakly in }L^p\text{ as }\lambda\to+\infty?$$   One has the easy case for $f\in L^{p-\epsilon}\cap L^p$. This condition allows the use of Hölder's inequality as follows (here $\frac{1}{p}+\frac{1}{p'}=1$ and $\phi$ is a continuous function with compact support):  $$\begin{split}\left\lvert \int_{\mathbb{R}^d} \lambda^{\frac{d}{p}} f(\lambda x)\phi(x)\, dx\right\rvert&amp; \le \lambda^{\frac{d}{p}}\lVert f(\lambda x)\rVert_{L^{p-\epsilon}}\lVert \phi\rVert_{L^{(p-\epsilon)'}} \\  &amp;= \lambda ^{\frac{d}{p}- \frac{d}{p-\epsilon} } \lVert f\rVert_{L^{p-\epsilon}}\lVert\phi\rVert_{L^{(p-\epsilon)'}}\to 0. \end{split} $$ But what happens if that condition is removed? I carried out an explicit check on the standard example of a function $f$ that belongs to $L^2(\mathbb{R})$ and does not belong to $L^{2-\epsilon}(\mathbb{R})$ for any $\epsilon &gt; 0$, namely  $$f(x)=\begin{cases} 0 , &amp; x&lt;2 \\ \frac{1}{\sqrt{x}\log x}, &amp; x \ge 2\end{cases}.$$ Taking $\phi=\chi_{[a, b]}$ with $2&lt;a&lt;b$ one has  $$\left \lvert \int_{\mathbb{R}} \lambda^{\frac{1}{2}}f(\lambda x)\phi(x)\, dx \right\rvert  = \dfrac{  \int_{\lambda a }^{\lambda b} \frac{dy}{\sqrt{y}\log(y)} } {\lambda^{\frac{1}{2}}}, $$ and an application of l'Hôpital's rule shows that the right hand side tends to $0$ as $\lambda \to \infty$. This implies weak convergence to $0$ by a standard density argument.   This seems to point towards an affirmative answer to the question in the gray box. Does "until [date]" mean "before that date"? Maximum power transfer and Thevenin Hyperlinks clicked in evince document viewer are not opening, any ideas on how to fix? As it was instructed in another thread here in the forums, I opened the /usr/share/applications/mimeinfo.cache file to check for correct references. And noticed this doesn't seem to be the problem, there even are 3 optional browsers to use.  x-scheme-handler/http=google-chrome.desktop;chromium-browser.desktop;firefox.desktop; x-scheme-handler/https=google-chrome.desktop;chromium-browser.desktop;firefox.desktop;   I already checked that the programs are correctly named, using the "which" command in the terminal, like this:  $ which google-chrome $ /usr/bin/google-chrome   So google-chrome should be the first option and yet the order to open a url doesn't seem to be arriving to the program, not even to the 2nd or 3rd option for that matter anyways.  Also, the 'Get help online...' command in the 'Help' menu doesn't work. So it is not a problem with the specific document file either.  I'm running Ubuntu 12.04 LTS. If you need to ask for more relevant details, please do. It would be nice to have various opinions on how to solve this, thank you :-)  UPDATE: I ran evince from the terminal as asked. This is what I'm getting when trying to open a link:  /opt/google/chrome/google-chrome: line 42: /opt/google/chrome/chrome: Permission denied /opt/google/chrome/google-chrome: line 42: /opt/google/chrome/chrome: Success   Should I try the fix you suggested even if my error log is different?  UPDATE: Tried @maggotbrain's solution and BINGO, now I can study pdf references faster thanks to you bro! Abnormal behavior with iwlwifi driver: the device is shown as not working Recently I've installed Kubuntu in a newly bought laptop with an Intel WiFi 6 AX200 network card, I can connect to the wifi without apparent problems but when I open the driver manager in the settings I face this weird situation:  Intel Corporation: Wi-Fi 6 AX200 This device is not working.  [ ] Using iwlwifi driver backport in DKMS format from backport-iwlwifi-dkms (open source)  [ ] Continue using a manually installed driver  [x] Do not use the device   Note that "Continue using a manually installed driver" is the only voice selectable in the list.  Here is some additional information:  $ lspci -nnk | grep 0280 -A3 02:00.0 Network controller [0280]: Intel Corporation Wi-Fi 6 AX200 [8086:2723] (rev 1a)         Subsystem: Intel Corporation Wi-Fi 6 AX200 [8086:0084]         Kernel driver in use: iwlwifi         Kernel modules: iwlwifi  $ rfkill list all 0: hci0: Bluetooth         Soft blocked: yes         Hard blocked: no 1: phy0: Wireless LAN         Soft blocked: no         Hard blocked: no  $ dmesg | grep iwl [    2.888227] iwlwifi 0000:02:00.0: enabling device (0000 -&gt; 0002) [    2.945179] iwlwifi 0000:02:00.0: Direct firmware load for iwlwifi-cc-a0-50.ucode failed with error -2 [    2.945217] iwlwifi 0000:02:00.0: Direct firmware load for iwlwifi-cc-a0-49.ucode failed with error -2 [    2.947244] iwlwifi 0000:02:00.0: TLV_FW_FSEQ_VERSION: FSEQ Version: 43.2.23.17 [    2.947250] iwlwifi 0000:02:00.0: Found debug destination: EXTERNAL_DRAM [    2.947252] iwlwifi 0000:02:00.0: Found debug configuration: 0 [    2.947697] iwlwifi 0000:02:00.0: loaded firmware version 48.4fa0041f.0 op_mode iwlmvm [    3.145585] iwlwifi 0000:02:00.0: Detected Intel(R) Wi-Fi 6 AX200 160MHz, REV=0x340 [    3.159226] iwlwifi 0000:02:00.0: Applying debug destination EXTERNAL_DRAM [    3.160060] iwlwifi 0000:02:00.0: Allocated 0x00400000 bytes for firmware monitor. [    3.336456] iwlwifi 0000:02:00.0: base HW address: 50:eb:71:d7:0b:40 [    3.353553] iwlwifi 0000:02:00.0 wlp2s0: renamed from wlan0 [    4.457920] iwlwifi 0000:02:00.0: Applying debug destination EXTERNAL_DRAM [    4.621843] iwlwifi 0000:02:00.0: FW already configured (0) - re-configuring [    4.629999] iwlwifi 0000:02:00.0: BIOS contains WGDS but no WRDS   Someone have idea why this happened? Let $f,g:X\to Y$ be maps of spaces such that $f\simeq g$. Is it true that the mapping cones $\operatorname{cone}(f)$ and $\operatorname{cone}(g)$ are homotopy equivalent?  Can we write down an explicit homotopy equivalence? It ought not to be too hard to get a map $\operatorname{cone}(f)\to \operatorname{cone}(g)$ from the existence of a homotopy $H:X\times I\to Y$, but I haven't been able to find a sensible candidate, despite trying for quite a while. Roll a 6-sided die until the total $\geq M$. Mean amount by which $M$ is exceeded? Here is the question:  You roll a fair 6-sided dice iteratively until the sum of the dice rolls is greater than or equal to M. What is the mean and standard deviation of the sum minus M when M=300?  Should I write a code to answer these kind of questions?  Please give me some hints on that. thanks! How to install Eclipse? I want to install the latest version of Eclipse but the Ubuntu Software Centre contains an older version.  Is there a PPA or some other way to install latest Eclipse? Please describe the steps for full installation. Is it possible for an iPad to get a virus? How can I use Web.debug.config in the built-in visual studio debugger server? VPN server on Google Compute Engine with OpenVPN Updating .class file in jar