How to remove Ubuntu partition from Windows 7? Which partition is it? A similar question has been asked here: , and I've used the advice that was posted.   However, I still can't figure out which of the partitions is Ubuntu.  Here's a screenshot after I run diskmgmt.msc    I need a fresh install of Ubuntu since my current one has suddenly stopped working. I had used .iso image by mounting the image and installing it on a thumb drive when I partitioned it.  To do the above, do I need to remove the partition first from diskmgmt.msc and then go about partitioning it again from the image like I did the first time around?   Update. I get "Boot error" when I try to run the Ubuntu installer by booting from USB. When I press enter, it takes me to the grub screen. Do I need to use Windows recovery disk to repair so that grub is no longer there? (This problem was resolved)  I have now attached the screenshot that I get when I choose "Something else" when the installer asks me how I want to partition my disk. It seems the 52.64 GB was the one with Ubuntu on it. I was confused because according to the diskmgmt.msc it's 100% free. . I have deleted ext4 and swap, restarted the install, selected "Install Ubuntu alongside them" and that seems to have worked.  Thanks everyone for the advice!
How to remove Ubuntu and put Windows back on? I have absolutely no experience with Linux, and I desperately need to get my computer back up and running again with Windows.  How do I remove Ubuntu and reinstall Windows?    Editor's note: many of the answers are about removing Ubuntu from dual-boot but keeping Windows (which is a bit complicated), while other answers are about removing Ubuntu from single-boot (which is easy: basically just format the disk while installing Windows). The question as written is ambiguous between dual-boot or single-boot.
This image from wikipedia, explains that there occurs a potential drop across a , and an electric field confined to the depletion region.  I already know the reason for the existence of this drop and the calculation of the difference but I have two questions regarding this drop.    1) If the  regions are externally connected using a perfectly conducting wire, why will not any current flow? Connecting the two regions should equalize their potentials (since wire is a resistance less) conductor, and therefore the gradient at the junction is destroyed resulting in a  which is obviously against conservation of energy as the semiconductor has non-zero resistivity. Where will extra potential drops will be created so that Kirchoff's voltage rule holds without any current and the built-in potential difference $V_o$ of the juction persists?    2) (probably naive) If an external Bias is applied, of say $|V|&lt;|V_o|$, then the pn potential difference across the junction will just reduce by that amount ($|V|$). Assuming that the external voltage source is ideal without any resistance, what will be the potential drops which would sum to zero in this case? Will drop due to the resistance of semiconductor play a par in it? If yes, then there cannot be any ideal resistance-less semiconductor junction, can there? Why are integer literals with leading zeroes interpreted strangely? What is the difference between a linear and a circular polarizer? When I bought my polarizer, a friend told me that I should get a circular one, because the linear ones can mess with the autofocus. Is this true? What should each be used for? Getting polygon boundaries of City in JSON from Google Maps API? When searching Google Maps for a city, the city's administrative boundary is displayed.    Is there a way to get the polygon boundaries of City in a JSON format using google maps api? Why do we say "try and" [verb] instead of "try to" [verb]? (E.g., "Try and call me tomorrow.") In written and standard semi-formal (and above) spoken English, one would use &quot;try to&quot;:  Try to be a better person. Try to get the fishhook out of my thumb, please. Try to find a pharmacy when you need one.  But in spoken English, we (Americans, at least) usually substitute &quot;try and&quot; for all those cases. &quot;Try to&quot; makes sense because the &quot;to&quot; begins the construction of an infinitive: &quot;try to be&quot;, &quot;try to do&quot;, &quot;try to act&quot; and so on. &quot;Try and&quot; on the other hand doesn't seem to make any sense. I'm curious how the &quot;try and&quot; crept in, and when. It's really tough to Google small words like these, so I'm not finding anything on the Web. Is it a contraction of something like &quot;Try hard, and ...&quot;? Note: I've seen  and it is somewhat related but doesn't tell me what I want to know. Edit Observe how, even on this site,  construction. Turning it on its head Note that you can't make a negative construction with &quot;try and&quot;:  It's raining. Try not to get wet. It's raining. Try not and get wet. [?]  Even adding do doesn't help. The following means something different from &quot;try not to get wet.&quot;  It's raining. Don't try and get wet.  Even use of to instead of and there means something else:  It's raining. Don't try to get wet.  &quot;Try not to get wet&quot; means try to stay dry. &quot;Don't try to get wet&quot; means avoid actively seeking out a soaking, and implies that a soaking might in fact be what you are looking for. MORE I just happened to notice a video from an editor for Merriam-Webster on this very topic, so I include the link here: . Let $p$ be prime and $(\frac{-3}p)=1$. Prove that $p$ is of the form $p=a^2+3b^2$ Let $p$ be prime and $(\frac{-3}p)=1$, where $(\frac{-3}p)$ is Legendre symbol. Prove that $p$ is of the form $p=a^2+3b^2$.   My progress:  $(\frac{-3}p)=1 \Rightarrow$ $(\frac{-3}p)=(\frac{-1}p)(\frac{3}p)=(-1)^{\frac{p-1}2}(-1)^{\lfloor\frac{p+1}6\rfloor}=1 \Rightarrow$ $\frac{p-1}2+\lfloor\frac{p+1}6\rfloor=2k$  I'm stuck here. This is probably not the way to prove that.  Also tried this way:  $(\frac{-3}p)=1$, thus $-3\equiv x^2\pmod{p} \Rightarrow$ $p|x^2+3 \Rightarrow$ $x^2+3=p\cdot k$ stuck here too.  Any help would be appreciated. I've tried multiple times to  import a SVG file from illustrator CS5.5 to Blender 2.71 and 2.73. However, I do not see a mesh, curve, or anything pop up in my "Outliner" window. So I know its not so small I can't see it. I even made sure under user preferences that the "import and export of SVG 1.1 format" is "checked." I've tried even just importing text from illustrator and I'm still getting no where. What can I do to resolve this problem? If this is common error with this version of Blender, then what can I do to transform an image into a 3D object in Blender? How do I remap a key in macOS Sierra, e.g., Right Alt to Right Control? If $$(1+ \cos A) (1+ \cos B) (1+\cos C)= y = (1- \cos A) (1-\cos B) (1-\cos C)$$ then prove that $$y = \pm \sin A \sin B \sin C$$ how to tell Latex to ignore empty lines So, I have about 7 actions users may need in my app, and I have to use text instead of icons because it is a customer requirement.  I can add only 3 actions to my toolbar on iPhone 6. On Android you have the hamburger menu (see image), but I have never seen it in iOS.       So, what is the appropriate concept in iOS to add many actions into a menu? Summing the power series $\sum\limits_{n=0}^\infty (-1)^n \frac{x^{2n+1}}{2n+1}\prod\limits_{k=1}^n\frac{2k-1}{2k} $ I'd like to determine the function corresponding to the following power series: $$x + \sum_{n=1}^\infty (-1)^n\frac{1\cdot3\cdot5\cdots(2n-1)}{2\cdot4\cdot6\cdots2n} \frac{x^{2n+1}}{2n+1}, $$ where $|x|&lt;1$. $\gcd(a,b,c)=\gcd(\gcd(a,b),c)\,$ [GCD Associative Law] Opacity problem over white object in Illustrator I have a problem. I'm working with an object at 50% opacity. When it's over the artboard itself the color looks great, but when I put a white object behind it I get this weird color that doesn't look accurate.  This happens with every object and only in CMYK. I'm pretty sure this never happened to me before so maybe I changed something in the settings or I don't know.  Does anyone have any idea? In many situations, JavaScript parsers will insert semicolons for you if you leave them out. My question is, do you leave them out?  If you're unfamiliar with the rules, there's a description of semicolon insertion on the . Here's the key point:     If the first through the nth tokens of a JavaScript program form are grammatically valid but the first through the n+1st tokens are not and there is a line break between the nth tokens and the n+1st tokens, then the parser tries to parse the program again after inserting a virtual semicolon token between the nth and the n+1st tokens.   That description may be incomplete, because it doesn't explain @Dreas's example. Anybody have a link to the complete rules, or see why the example gets a semicolon? (I tried it in JScript.NET.)   is related, but only talks about a specific scenario. Incompatibility with mathtools and unicode-math in xelatex? I find unexpected behaviour in using mathtools in conjunction with unicode-math, which shows up if the 'range' command is used. Some incompatibilities have been noted before, so perhaps this is related. However, it only showed up for me in Texlive2016; previous versions worked as expected. In the following example I wish to draw calligraphic fonts from a different set than the main maths fonts, and some calligraphic symbols, and a regular italic bold face math, are missing.   \documentclass{article} \usepackage{mathtools}  \usepackage{fontspec} \usepackage{unicode-math} \unimathsetup{math-style=ISO,bold-style=ISO,sans-style=italic} \setmainfont{xits-regular.otf} \setmathfont{xits-math.otf} \setmathfont[range={\mathcal,\mathbfcal}]{latinmodern-math.otf} %\setmathfont[range={}]{xits-math.otf} % Try with and without this line % \begin{document} Test $a+b = \mathcal{C H G}C \mathscr{D}$ $$-\frac{a}{b} \mathcal{O} . $$ \begin{equation}     \mathrm{d} = \mathcal G(\varphi,x,y,z,t) ,  \end{equation} The symbol $\mathcal{G}$ is missing.  The following equation is wrong if I include the line  ``setmathfont[range=\{\}] \{xits-math.otf\}'' \begin{equation}     \mathup{d} = \symbf{u}(\varphi,x,y,z,t) ,  \end{equation} The glyph $\symbf{u}$ is missing. \end{document}   If mmathtools is called after unicode-math the problem does not arise, but this ordering is not recommend by the unicode-math developers.  My specific question is, is this a bug or is it something I am doing wrong? Can you be refused a visitor visa to US if you have bad Credit there? I did my 3 years of College in the US, 2010-2013 due to finance issues I was unable to pay my credit card bill of a certain bank, which still lie unpaid.  However I plan on visiting the US later this year; could I be denied visa for having an unpaid bill ? Print composer problems Qgis 2.8 Wien with Google Satellite I am having serious problems in exporting a map (Google satellite map) linked to QGIS.   Using the print editor I clearly see the part of the map I want to print and also in the right scale, but when I save it as jpeg, the result is: the correct map in a circle in the middle of the page, and all around it seems that Qgis is zooming at different scale on another part of the map [see attached file].  Any suggestion about it ? I don't want to save it as simple screenshot  because I need an HD file.   ] Show that $B$ is diagonalizable if If $AB=BA$ and $A$ has distinct real eigenvalues We were asked to prove the following:  Let $ A $ be an $n \times n$ matrix with $n$ distinct real eigenvalues. If $AB=BA$, show that $B$ is diagonalizable.   It was suggested I show that an eigenvector of $A$ is also an eigenvector of $B$. I am both having trouble doing this and failing to see how I would complete the proof after. Any help would be appreciated.  Thanks Why use apparently meaningless do-while and if-else statements in macros? In many C/C++ macros I'm seeing the code of the macro wrapped in what seems like a meaningless do while loop.  Here are examples.  #define FOO(X) do { f(X); g(X); } while (0) #define FOO(X) if (1) { f(X); g(X); } else   I can't see what the do while is doing.  Why not just write this without it?  #define FOO(X) f(X); g(X)