extend virtual machine across physical machines Is it possible for two or more physical machines to be "grouped" into one virtual machine such that the CPU cores are shared?
Multiple servers acting like a single one with all the hardware? by now I have 10 servers for hpc, power computing oriented. My users need to launch several processes using qmake. The users are used to work with ubuntu 9.10, and the software from the repositories is switable for them.  I've deployed ubuntu 9.10 to all 10 servers (pxe rocks).  By now we work with parallel-ssh and cluster-ssh, which allows as to launch the same process to all servers. With this tools this tools the servers remain as independent but with the same software and the same launched command.  Now we would like to go to next step and see all the servers as a single one with all the resources from the other 9 as if was its resources.   The difference would be substantial in time to process and also time to design the command to launch.  Any advice on wich software to use will be very useful?  Thanks
Importing users that will be installed by programs Force update from unsigned repository I'm using an unsigned repo in Ubuntu 16.04 from Debian multimedia:  deb http://www.deb-multimedia.org jessie main   To install deb-multimedia-keyring, I'm running:  apt-get update &amp;&amp; apt-get install deb-multimedia-keyring -y   This gives an error:  W: GPG error: http://www.deb-multimedia.org jessie InRelease: The following signatures couldn't be verified because the public key is not available: NO_PUBKEY 5C808C2B65558117 E: The repository 'http://www.deb-multimedia.org jessie InRelease' is not signed. N: Updating from such a repository can't be done securely, and is therefore disabled by default. N: See apt-secure(8) manpage for repository creation and user configuration details. What resolution should a large format artwork for print be? Every Function in a Finite Field is a Polynomial Function From a bank of past master's exams I am going through:     Let $F$ be a finite field. Show that any function from $F$ to $F$ is a polynomial function.   I know that finite fields are fields of $p$ elements for $p$ prime [EDIT: It's actually $p^n$ for $p$ prime; see comment below]. Since I have $p$ choices for the $p$ elements to map to, then I have $p^p$ distinct functions. I think every function can be written in the form $f(x) = a_{p-1}x^{p-1} + \dots + a_0x^0$. For then given the values $f(0), f(1), \ldots f(p-1)$, I can solve for the coefficents by the linear system of equations  $$ a_0 + \sum_{i=1}^{p-1} n^i a_i = f(n).$$  This then gives me a $p-1 \times p-1$ square matrix over the field $\mathbb{F}_p$:  $$\left( \begin{array}{ccccc} 1&amp; 0 &amp; 0 &amp; \ldots &amp; 0 \\ 1&amp; 1 &amp; 1 &amp; \dots &amp; 1 \\ 1&amp; 2 &amp; 4 &amp; \dots &amp; 2^{p-1} \\ \vdots &amp; \vdots &amp; \vdots &amp; &amp; \vdots \\ 1 &amp; p-1 &amp; (p-1)^2 &amp; \dots &amp; (p-1)^{p-1} \end{array} \right) \left( \begin{array}{c} a_0 \\ a_1 \\ a_2 \\ \vdots \\ a_{p-1} \end{array}\right)  = \left( \begin{array}{c} f(0) \\ f(1) \\ f(2) \\ \vdots \\ f(p-1) \end{array} \right)$$  If I can show this matrix is invertible, then I can always find the $a_i$. But I am a bit stumped on how to show this (partially because I don't think I've ever done linear algebra in a vector space over a finite field). It does not seem easy to show linear independence, or nonzero determinant, or full row rank.    Alternatively (I just thought of this), can I show this is true by arguing that the map between the two sets (the set of polynomials of degree $p-1$; and the set of functions $F \to F$) is injective, and that it must be a bijection because the sets have the same cardinality $p^p$? "Your Sites" in Android left sidebar shown in unpredictable order In the Android app, left sidebar, there is an editable list of "Your Sites". In the editing pane, the sites are re-orderable (although awkwardly), and the order one places the sites in there is preserved, even after quitting the app and returning to this pane. One expects that order to be reflected in the "Your Sites" portion of the left sidebar when the editing pane is closed, but it is not.  I'm not sure what is determining the order of the sites in the left sidebar, it doesn't seem to be by date they were "pinned" into the list one wants to show, either. What should I do when my neural network doesn't generalize well? Using ArcPy to get all database names within server? I am trying to populate a folder with ArcSDE database connection files for all the databases within a server instance.  I need to be able to do this for several of our servers.  Although I know within SQL Server how to get a list of DB names from the sys.databases table, using the arcpy function CreateDatabaseConnection I cannot specify "sys" or "master" to make the connection.  Therefore, I need to know the name of a database currently in the server.  I am not sure how to make the check without hard-coding a name.  import arcpy arcpy.env.overwriteOutput = True  #Input the location where the database connection files will be stored connectionLocation = "F:/FolderName"  #Get the list of servers arcpy.CreateDatabaseConnection_management(out_folder_path= arcpy.env.scratchFolder,out_name= "GIS_USERCONFIG" ,database_platform="SQL_SERVER",\                                           instance = "XXXXXXX" ,account_authentication="DATABASE_AUTH",username="user",password="password",\                                           save_user_pass="SAVE_USERNAME",database= "GIS_USERCONFIG",schema="#",version_type="TRANSACTIONAL",version="dbo.DEFAULT",date="#") sdeConn = arcpy.ArcSDESQLExecute(arcpy.env.scratchFolder + "/GIS_USERCONFIG.sde") serverListSQL = sdeConn.execute("Select name from userservers") serverList = [] for i in range(0,len(serverListSQL)):     serverList.append(serverListSQL[i][0])  #Make a folder for each server instance and build the connection files for all DBs in the server instance for server in serverList:     folder = connectionLocation + "/" + server     if arcpy.Exists(folder):         print server + " folder already created"     else:         try:             arcpy.CreateFolder_management(connectionLocation, server)             print "Created Folder " + server         except:             print "failed to create folder " + server      #     arcpy.CreateDatabaseConnection_management(out_folder_path= arcpy.env.scratchFolder,out_name= server ,database_platform="SQL_SERVER",\                                           instance = server ,account_authentication="OPERATING_SYSTEM_AUTH",\                                           database= "master",schema="#",version_type="TRANSACTIONAL",version="dbo.DEFAULT",date="#")     sdeConn = arcpy.ArcSDESQLExecute(arcpy.env.scratchFolder + "/" + server + ".sde")     dbListSQL = sdeConn.execute("Select name from sys.databases")     dbList = []     for i in range(0,len(serverListSQL)):         dbList.append(dbListSQL[i][0])     for db in dbList:         arcpy.CreateDatabaseConnection_management(out_folder_path= folder ,out_name= db,database_platform="SQL_SERVER",\                                           instance = server ,account_authentication="OPERATING_SYSTEM_AUTH",\                                           database= db,schema="#",version_type="TRANSACTIONAL",version="dbo.DEFAULT",date="#")   Basically my issue is with the 2nd call for the function "CreateDatabaseConnection_management" since it needs a database that exists in the database (and I could not use "master or sys").  If you open this as a tool in arcmap, the input is a drop-down box that populates choices based on the databases in the chosen server instance.  Is there a way to do this in the code? I use \includegraphics command to insert image to the document. But how can I add a border around this image w/o any margin between border lines and image? It seems to be very easy, but I can't find it in the documentation. Uk visa refused as self employed Why can't I log into minecraft with a mojang account? Integer squares of the form $x^4+x^3+x^2+x+1$ I want to solve ${y^2}=x^4+x^3+x^2+x+1$ in $\mathbb{Z}$.    I can find four solutions. Is there another solution? I know that there are six solutions. $$(-1, \pm 1)\;,\;(0, \pm 1).$$  My try: \begin{align}   &amp; x^4+x^3+x^2+x+1=0\quad \Rightarrow \underbrace{\left( x+\frac{1}{x} \right)^2}_{t^2}+\underbrace{\left( x+\frac{1}{x} \right)}_{t}-1=0\,\Rightarrow t\notin \mathbb{Z} \\   &amp; x^4+x^3+x^2+x+1={\pm 1}^2\quad\Rightarrow \,x=-1\,\,,\,x=0.\\  \end{align}   Thanks. Android 4.1 (Jelly Bean) was announced at Google I|O 2012 on June 27, 2012.  (You can review  at the official Android Developer's site.)  Of course, not all devices will get this update right away and others won't get it at all. Each manufacturer and carrier often choose to add their custom modifications which tend to delay the official release.  When will each device get Android 4.1, either officially or unofficially, if ever?  See also: Travelling by bus Bash File Unable to locate package when new line is added When building a bash file to execute I keep getting an error after adding a new line. I have tried moving some lines around or removing some of the packages but it will results in the same error. In the file if I was to remove 3 and 4 it there will no longer be an error.   E: Unable to locate package &lt;package&gt;   The bash file looks like this   #!/usr/bin/env bash sudo apt update &amp;&amp; sudo apt install -y python3-pip build-essential python3-dev python3-setuptools gcc sshpass sudo apt-get install apt-transport-https lsb-release software-properties-common dirmngr sudo apt-get update   The output with the error  Hit:1 http://us.archive.ubuntu.com/ubuntu bionic InRelease Get:2 http://security.ubuntu.com/ubuntu bionic-security InRelease [88.7 kB]                                                   Hit:3 http://archive.ubuntu.com/ubuntu bionic InRelease                                             Get:4 http://us.archive.ubuntu.com/ubuntu bionic-updates InRelease [88.7 kB]         Get:5 http://us.archive.ubuntu.com/ubuntu bionic-backports InRelease [74.6 kB]                                       Fetched 252 kB in 1s (189 kB/s)     Reading package lists... Done Building dependency tree        Reading state information... Done All packages are up to date. Reading package lists... Done Building dependency tree        Reading state information... Done E: Unable to locate package sshpass Reading package lists... Done Building dependency tree        Reading state information... Done E: Unable to locate package dirmngr Hit:1 http://us.archive.ubuntu.com/ubuntu bionic InRelease Get:2 http://security.ubuntu.com/ubuntu bionic-security InRelease [88.7 kB]                                                   Hit:3 http://archive.ubuntu.com/ubuntu bionic InRelease                                             Get:4 http://us.archive.ubuntu.com/ubuntu bionic-updates InRelease [88.7 kB]         Get:5 http://us.archive.ubuntu.com/ubuntu bionic-backports InRelease [74.6 kB]                                       Fetched 252 kB in 1s (209 kB/s)     Reading package lists... Done Recommended books for advanced undergraduate electrodynamics What books are recommended for an advanced undergraduate course in electrodynamics? Find a real function $f:\mathbb{R}\to\mathbb{R}$ such that $f(f(x)) = -x$? I've been perusing the internet looking for interesting problems to solve. I found the following problem and have been going at it for the past 30 minutes with no success:     Find a function $f: \mathbb{R} \to \mathbb{R}$ satisfying $f(f(x)) = -x$ for all $x \in \mathbb{R}$.   I am also wondering, can we find $f$ so that is continuous?  I was thinking of letting $f$ be a periodic function, and adding half the period to x each time. I had no success with this, and am now thinking that such a function does not exist.  Source: I have 3 tables and I have to inner join Table A with Table B but a left outer between Table A and Table C.   Can I combine outer and inner join in the same query? I can nest queries and attain the desired result but I am unable to do both the joins in the same query. It appears that in other SQL languages, the order of joining is important. Is this the case in SQL Server as well?    Ok, here's the scenario.  Consider 3 tables. Table A, Table F, Table D.  I will need the recordset to contain all rows in D irrespective of whether it exists in F (after it's inner joined with A). So, a outer join comes to mind. What I would need is:   First do a inner join between A and F to get a set (this may be a null set) Then do a outer join with the recordset in (1) with D Order of keys in dictionary Can't unhide grayed out objects After some searching on stack / google I decided to ask this here, this is the second time I'm facing this issue this time with blender 2.8, previously with 2.7 and without a clue to how I got here.  Some of my objects appear hidden(10/12), and I can't seem to find a way to unhide them.  Solutions to the most common rookie mistakes seems to be   In local-view solved by pressing numpad / hidden by pressing H or Shift + H, unhiding with Alt + H   I'm not in local view, I can toggle visibility for 2/12 objects with Shift + H &amp; Alt + H, but the rest stays gray in the collection.  Last time I solved this by exporting the whole model as STL and importing it back again, I then had to re-group all the pieces but there must be a more simple solution.  Here's the .blend if someone wants to have a go at it: Two monitors when only having one in 13.10 I just did a fresh install of Ubuntu 13.10 64bit, and it says that I have 2 monitors, when I actually only have one    I have a Dell XPS 15 with Nvidia graphics card if that helps in anyway