Here is the text:  &quot;This is a 29-year-old Arn Anderson, who looks much older than that. It seems the stress of keeping the crowds entertained every night got to him and aged him much quicker than the average person.&quot;  According to the rules, in the last phrase, it should be &quot;an average person&quot; because the meaning is any average person. Why did they use the?
Which one is correct, or are both of them fine?    "It would take the average person 10 days to read this novel"    Or    "It would take an average person 10 days to read this novel"
Removing overlapping part of polygons using QGIS? Here is what I'd like to achieve in QGIS.   Is there a processing tool to remove the overlapping part of polygons?    It is also very important that they do not get merged during the process and that they keep their original attributes since I need to work with them afterwards. Can Recovery Mode install OS X onto a blank SSD? Installing drivers for windows? What is the difference between fixed effect, random effect and mixed effect models? In simple terms, how would you explain (perhaps with simple examples) the difference between fixed effect, random effect and mixed effect models? Drawing simple edge, no arrow I have  \begin{tikzpicture}[-&gt;,auto,node distance=3cm,   thick,main node/.style={draw,font=\bfseries}]   \node[main node] (111) at (0,1) {$X_{1,1}^{(1)}$};   \node[main node] (121) at (0,2) {$X_{1,2}^{(1)}$};   \node[main node] (1n1) at (0,4) {$X_{1,n}^{(1)}$};   \node[main node] (211) at (0,6) {$X_{2,1}^{(1)}$};   \node[main node] (221) at (0,7) {$X_{2,2}^{(1)}$};   \node[main node] (2n1) at (0,9) {$X_{2,n}^{(1)}$};   \node[main node] (n11) at (0,11) {$X_{n,1}^{(1)}$};   \node[main node] (n21) at (0,12) {$X_{n,2}^{(1)}$};   \node[main node] (nn1) at (0,14) {$X_{n,n}^{(1)}$};   \node[main node] (112) at (2.5,1) {$X_{1,1}^{(2)}$};   \node[main node] (122) at (2.5,2) {$X_{1,2}^{(2)}$};   \node[main node] (1n2) at (2.5,4) {$X_{1,n}^{(2)}$};   \node[main node] (212) at (2.5,6) {$X_{2,1}^{(2)}$};   \node[main node] (222) at (2.5,7) {$X_{2,2}^{(2)}$};   \node[main node] (2n2) at (2.5,9) {$X_{2,n}^{(2)}$};   \node[main node] (n12) at (2.5,11) {$X_{n,1}^{(2)}$};   \node[main node] (n22) at (2.5,12) {$X_{n,2}^{(2)}$};   \node[main node] (nn2) at (2.5,14) {$X_{n,n}^{(2)}$};   \node[main node] (11k) at (6,1) {$X_{1,1}^{(k)}$};   \node[main node] (12k) at (6,2) {$X_{1,2}^{(k)}$};   \node[main node] (1nk) at (6,4) {$X_{1,n}^{(k)}$};   \node[main node] (21k) at (6,6) {$X_{2,1}^{(k)}$};   \node[main node] (22k) at (6,7) {$X_{2,2}^{(k)}$};   \node[main node] (2nk) at (6,9) {$X_{2,n}^{(k)}$};   \node[main node] (n1k) at (6,11) {$X_{n,1}^{(k)}$};   \node[main node] (n2k) at (6,12) {$X_{n,2}^{(k)}$};   \node[main node] (nnk) at (6,14) {$X_{n,n}^{(k)}$};   \node[main node] (11n2) at (9.5,1) {$X_{1,1}^{(n-2)}$};   \node[main node] (12n2) at (9.5,2) {$X_{1,2}^{(n-2)}$};   \node[main node] (1nn2) at (9.5,4) {$X_{1,n}^{(n-2)}$};   \node[main node] (21n2) at (9.5,6) {$X_{2,1}^{(n-2)}$};   \node[main node] (22n2) at (9.5,7) {$X_{2,2}^{(n-2)}$};   \node[main node] (2nn2) at (9.5,9) {$X_{2,n}^{(n-2)}$};   \node[main node] (n1n2) at (9.5,11) {$X_{n,1}^{(n-2)}$};   \node[main node] (n2n2) at (9.5,12) {$X_{n,2}^{(n-2)}$};   \node[main node] (nnn2) at (9.5,14) {$X_{n,n}^{(n-2)}$};   \node[main node] (11n1) at (12,1) {$X_{1,1}^{(n-1)}$};   \node[main node] (12n1) at (12,2) {$X_{1,2}^{(n-1)}$};   \node[main node] (1nn1) at (12,4) {$X_{1,n}^{(n-1)}$};   \node[main node] (21n1) at (12,6) {$X_{2,1}^{(n-1)}$};   \node[main node] (22n1) at (12,7) {$X_{2,2}^{(n-1)}$};   \node[main node] (2nn1) at (12,9) {$X_{2,n}^{(n-1)}$};   \node[main node] (n1n1) at (12,11) {$X_{n,1}^{(n-1)}$};   \node[main node] (n2n1) at (12,12) {$X_{n,2}^{(n-1)}$};   \node[main node] (nnn1) at (12,14) {$X_{n,n}^{(n-1)}$};   \path     (111) edge (112)         edge (122)         edge (1n2)     (121) edge (112)         edge (122)         edge (1n2)     (1n1) edge (112)         edge (122)         edge (1n2)     (121) edge[--,dashed] (1n1); \end{tikzpicture}   I just want simple lines, no arrows. How to manage with edge to achieve that? Thanks One server with multiple desktops "heads" with VNC I am managing a system of kiosks.  Each kiosk currently is running a web browser with the application for the kiosk running in the browser.  Each kiosk needs to be able to display separate content.  At times, the application running in the web browser freezes.  Thus, I have to go out to the site to refresh the page.  I want to see if there is a way to have one central server that has multiple browser heads.  Then each kiosk would run a program like VNC to display one of the heads.  This way when the program freezes, I just have to login to the central server and refresh the page.  Getting VNC or another remote desktop software installed on the clients is no problem.  What I am looking for is a way to have VNC remote into a specific head of a head of a web browser.  Does such a thing exist?  Or do I have to run a VM for each kiosk to remote into?  Any advice, pointers, or solutions would be helpful. What is the T-SQL To grant read and write access to tables in a database in SQL Server? What is the exact SQL to assign db_datareader and db_datawriter roles to a user in SQL Server?  The user name is MYUSER and the database is MYDB. Switching motherboard without new install? Generating data with a given sample covariance matrix Let $(a_k)$ be a sequence of real numbers and let $b_k=\frac{a_1+a_2+\dots a_k}{k}$ for each $k\in \mathbb{N}$.  Prove that if $(a_k)$ converges to $\alpha\in \mathbb{R}$, then the sequence $(b_k)$ also converges to $\alpha$.  My answer: Let $\epsilon &gt; 0$. Since ($a_k$) converges to $\alpha$, then there exists a $N_{\epsilon1}\in\mathbb{N}$ such that $|a_k - \alpha | &lt; \frac{\epsilon}{2}$ for all $k \geq N_{\epsilon1}$. Notice that $\frac{a_1+...+a_n - n\alpha}{k}$ converges to $0$ as $k$ approaches infinity. Thus, there exists $N_{\epsilon2}\in\mathbb{N}$ such that $|\frac{a_1+...+a_n - n\alpha}{k}|&lt;\frac{\epsilon}{2}$ for all $k&gt;N_{\epsilon2}$. Now, let $N= $max$ (N_{\epsilon1},N_{\epsilon2})$. Then for any $k&gt;N$ we get,  $$\begin{array}{rcll} |b_k-\alpha| &amp;=&amp; |b_k - \alpha*1|&amp;\\ &amp;=&amp; |\frac{a_1+...+a_k}{k} - \frac{k\alpha}{k}|&amp;\\ &amp;=&amp; |\frac{a_1+...+a_n}{k} + \frac{[a(n+1)+...+a_k]}{k} - \frac{(k-n)\alpha}{k} - \frac{n\alpha}{k}|&amp; \text{(notice that $N_{\epsilon1}\leq N&lt;k$)}\\ &amp;=&amp; |\frac{a_1+...+a_n - n\alpha}{k} + \frac{[a(n+1)+...+a_k - (k-n)\alpha]}{k}|&amp;\\ &amp;=&amp; |\frac{a_1+...+a_n - n\alpha}{k} + \frac{[(a(n+1) -\alpha) + ... + (a_k - \alpha)]}{k}|&amp;\\ &amp;=&amp; |\frac{a_1+...+a_n - n\alpha}{k} + \frac{(a(n+1) -\alpha)}{k} + ... + \frac{(a_k - \alpha)}{k}|&amp;\\ &amp;\leq&amp; |\frac{a_1+...+a_n - n\alpha}{k}| + |\frac{(a(n+1) - \alpha)}{k}| + ... + |\frac{(a_k - \alpha)}{k}|&amp; \text{(by the triangle inequality)}\\ &amp;=&amp;|\frac{a_1+...+a_n - n\alpha}{k}| + \frac{|(n+1) - \alpha|}{k} + ... + \frac{|a_k - \alpha|}{k}&amp;\\ &amp;&lt;&amp; \frac{\epsilon}{2} + [\frac{\epsilon}{2}/k + ... + \frac{\epsilon}{2}/k]&amp; \\ &amp;=&amp; \frac{\epsilon}{2} + \frac{\epsilon}{2}*\frac{(k-n)}{k}&amp;\\ &amp;&lt;&amp; \frac{\epsilon}{2} + \frac{\epsilon}{2}&amp; \text{(since $k-n&lt;k$)}\\ &amp;=&amp; \epsilon&amp; \end{array}$$ And since we found such an $N$ for arbitrary $\alpha$, then $(b_k)$ converges to $\alpha$ by definition.  I'm not sure i kept all my variables straightened out. How does this look and if you have a better idea let me know! Ok. So I read books as a kid, this may have been mid to late 1980s. Definitely before 1993. These details I remember, they might be from the same book or from several:   Slower than light space travel with severe time dilation. There were boardings of space ships, but the fighting odds could be very uneven because a foe could be from your future or your past, depending on when you started your space journey, because of relativistic time dilation. No faster than light travel, no time travel either. Just regular physics. To fight better in melee, soldiers would have (more or less willingly, I think they knew beforehand) false memories or notions implanted of the enemy as horrible human beings so soldiers could kill them more easily without remorse. Towards the end of the story, veterans of the war are described as not quite feeling at home after the war. One planet (home?) or country is described as inhabited entirely of clones, Adams and Eves, I think homosexual, or that sexuality could be switched deliberately. I think the veterans find at the end a refuge somewhere more like the home they are used to. The reason so much has changed is of course the time dilation. They spent maybe decades in the war, while on the planets centuries or millenia passed. I think one moral (there may be many more I missed as a child) of the story was the futility of war. If I recall correctly, the war was resolved in a way that made the efforts of the veterans seem for nothing. If $G/Z(G)$ is cyclic, then $G$ is abelian Continuing my work through Dummit &amp; Foote's "Abstract Algebra", 3.1.36 asks the following (which is exactly the same as exercise 5 in ):     Prove that if $G/Z(G)$ is cyclic, then $G$ is abelian. [If $G/Z(G)$ is cyclic with generator $xZ(G)$, show that every element of $G$ can be written in the form $x^az$ for some $a \in \mathbb{Z}$ and some element $z \in Z(G)$]      The hint is actually the hardest part for me, as the quotient groups are somewhat abstract. But once I have the hint, I can write:  $g, h \in G$ implies that $g = x^{a_1}z_1$ and $h = x^{a_2}z_2$, so \begin{align*}gh &amp;= (x^{a_1}z_1)(x^{a_2}z_2)\\\  &amp;= x^{a_1}x^{a_2}z_1z_2\\\ &amp; = x^{a_1 + a_2}z_2z_1\\\ &amp;= \ldots = (x^{a_2}z_2)(x^{a_1}z_1) = hg. \end{align*} Therefore, $G$ is abelian.  1) Is this right so far?  2) How can I prove the "hint"? I'm working through Knuth's Metafont Book as preparation for learning Metapost and I'm running into some problems working through his "experiments".  I've installed the latest TeX Live 2013 distribution on my system but I'm having problems.  Here's the code (contained in file io.mf as recommended by Knuth):  mode_setup;  em#:=10pt#; cap#:=7pt#;  thin#:=1/3pt#; thick#:=5/6pt#;  o#:=1/5pt#; define_pixels(em,cap); define_blacker_pixels(thin,thick); define_corrected_pixels(o);  curve_sidebar=round 1/18em; beginchar("O", 0.8em#, cap#, 0); "The letter O";  penpos1(thick,10); penpos2(.1[thin,thick],90-10);  penpos3(thick,180+10); penpos4(thin,270-10);  x1l=w-x3l=curve_sidebar; x2=x4=.5w;  y1=.49h; y2l=-o; y3=.51h; y4l=h+o;  penstroke z1e{down}..z2e{right}             ..z3e{up}..z4e{left}..cycle;  penlabels(1,2,3,4); endchar;   Now, when running the mf command and loading this file, I get a window that is unfortunately empty.  Supposedly a large letter "O" should appear.  $ mf This is METAFONT, Version 2.718281 (TeX Live 2013) **io (io.mf The letter O [79]) *end Output written on io.2602gf (1 character, 1724 bytes). Transcript written on io.log.  $ gftodvi io.2602gf  gftodvi: fatal: tfm file `gray.tfm' not found.   Then, when trying to use the gftodvi command I get the above error.   Any ideas why my "window" that should display the letter "O" is blank/empty? How do I resolve the gray.tfm error? Are the two related?   Note: I'm using Ubuntu 14.04, but the TeXLive installation is NOT from the Ubuntu repository.  I used the installer from  and created a local "portable" installation. What is the solution to the Squirrel sequence of letters question? Can I run CAT5/6 cables parallel to electrical cables? I am building a new house and am planning to hardwire network cables into each room.   Can I run CAT5/6 cables parallel to electrical wires without introducing any general safety issues or losing much in connection quality?  Wiring runs for up to 25 metres from patch panel and distribution board in garage to rooms.   My research indicates that is should be fine if they are in separate conduits or if the CAT cables are shielded. How do I use subprocess.Popen to connect multiple processes by pipes? How do I execute the following shell command using the Python  module?  echo "input data" | awk -f script.awk | sort &gt; outfile.txt   The input data will come from a string, so I don't actually need echo.  I've got this far, can anyone explain how I get it to pipe through sort too?  p_awk = subprocess.Popen(["awk","-f","script.awk"],                           stdin=subprocess.PIPE,                           stdout=file("outfile.txt", "w")) p_awk.communicate( "input data" )   UPDATE:  Note that while the accepted answer below doesn't actually answer the question as asked, I believe S.Lott is right and it's better to avoid having to solve that problem in the first place! Html form in email Time limit on accepting an answer Why is there a 15 minute time limit on accepting an answer in StackOverflow? How can you programmatically tell an HTML SELECT to drop down (for example, due to mouseover)? With "magic quotes" disabled, why does PHP/WordPress continue to auto-escape my POST data?