Is there a way to mass delete compiled list of emails on iOS devices (like can be done in os x)? I only know two options: select individually &amp; swipe "left" and from bottom select "edit", then selecting each message individually. I tried solution described in similar question without success (described as iOS 7).
How do you mass-delete emails in iOS Mail? I don't know if this is documented anywhere, but just to bring it to current attention…
What's the fixed size of the suggested edit queue? Find path of standard executable for a given file type in Windows Suppose I am running cmd and I open an application by typing for example start document.pdf  I want to get the exact path of the executable that opens .pdf files  Of course I could search the entire system for the executable but I suppose it would be faster this way because the path is already stored somewhere  I don't know if it makes a difference but I am using Windows 7 Smallest dense subset of $\mathbb{R}$ I am not sure if what I am looking for even makes sense (or) exists. Anyway I would be happy if someone can clear my confusion.  The set of real numbers $\mathbb{R}$ is obtained as completion of $\mathbb{Q}$. However, $\mathbb{Q}$ is not the only set which is dense in $\mathbb{R}$. $\mathbb{Q} \backslash \mathbb{Z}$ is also a dense subset of $\mathbb{R}$. I am wondering if it makes sense to talk of the "smallest" dense subset of $\mathbb{R}$. To phrase what I am looking for precisely and what I mean by smallest, I am looking for a dense set $A$ of $\mathbb{R}$ such that if $B$ is a proper subset of $A$ then $B$ is not dense in $\mathbb{R}$. I am able to "see" that the set $A$, I am looking for doesn't exist since any open interval consists of infinite rationals. But I am unable to precisely argue out to myself and convince why $A$ doesn't exist. Could some one throw more light on this? I'm struggling to understand the concept of quantum entanglement. I've distilled my understanding into an analogy, and I need your help to validate it. Here it is:  Let's say I receive two envelopes. Both envelopes have this written on them:     Hello! Open this letter...   If the paper inside is red, then other envelope has blue paper.   If the paper inside is blue, then other envelope has red paper.   So, if I open one letter, and the paper inside is red, then I know the other letter contains the blue paper.  Is this equivalent to quantum entanglement? The fact that I will know the color of the other paper when I open (i.e. observe) one envelope?  In theory, if one of the letters "appeared" in a different galaxy, I would still know the color of the paper inside that letter, just by opening my letter, instantly, correct?  Before I open the letter, is the paper inside each envelope in superposition (??), i.e. 50/50, red or blue?  In this analogy, I am assuming that what's written on the letters is true. Is this a correct assumption in quantum physics? I think so yes?  In real quantum physics, would I be able to change the color of one paper, so that I change the color of the other one? No right? Remove suggested apps option in iOS 10 As far as I can tell, suggested apps show themselves based on location.  There are two places where these suggested apps show themselves to me:   At the bottom left of the multitask screen when I double press the home button At the bottom left of the lock screen    article describes how to get rid of the small app icon appearing in the bottom left. However, this method is for iOS 8, and I am now on iOS 10, where I am unable to find iTunes and App Store > Suggested Apps.   How can I get rid of these (in my opinion) annoying little things? Equivalence Relation problem Let $S$ be the relation on $\mathbb{N} \times \mathbb{N}$ defined by $(a,b)S(c,d)$ if and only if $ad=bc$. Prove this is an equivalence relation on $\mathbb{N} \times \mathbb{N}$.  I think I've found this to be reflexive and symmetric, but I'm stuck on transitivity. Can someone check my work so far and assist with testing transitivity?  Reflexive: Let $(x,y)S(x,y)$. Then $xy = yx$. So $S$ is reflexive. Symmetric: Suppose $(a,b)S(c,d)$. Then, $ad = bc$. Therefore, $da = cb$ and $cb = da$. Therefore, $(c,d)S(a,b)$. Thus, $S$ is symmetric.  Transitive: Suppose $(a,b)S(b,c)$. Then $ac = bb$.   This is where I'm stuck. Any ideas? What are some typical LuaTeX gotchas? My dad has an old Sears KS-2 + 50mm f/1.7, which from a bit of research seems to use a Pentax K-mount.  I've looked around a bit and found a , which says it supports af-confirmation, and costs ~$30 US.  Has anyone tried using an adapter ring like this, and if so, would you recommend doing so?  I am perfectly happy with shooting manual, but I'm curious about the quality of older lenses.  I'm assuming that if I use older primes the optical quality will be fine, and it looks like the build quality of the older lenses is much better that similarly priced new lenses. Calculate posterior distribution (gamma-prior, poisson-likelihood) I want to calculate the posterior distribution given a gamma-prior and a poisson likelihood. The task is from a textbook and I just have the solutions (without a walkthrough). Please find all given information in the following:  Given information:  $m$ countries each with a population of $n_i$; $y_i$ is the number of people having a disease; $y_i$ is a poisson random variable with mean $\frac{n_i*\lambda}{100}$  The prior distribution for $\lambda$: $\lambda \sim Gamma(a_0,b_0)$  Task:  Show that the posterior distribution is also a gamma distribution with $a_m = a_0 + \sum_{i = 1}^{m}y_i$ and $b_m = b_0 + \sum_{i = 1}^{m} \frac{n_i}{100}$  My solution:  $Posterior \propto Likelihood \times Prior$  $p(\theta|y) \propto \prod_{i=1}^{m}(\theta^{y_i}e^{-\theta})\times \theta^{a_0-1}e^{-b_0\theta}$  $p(\theta|y) \propto \theta^{\sum_{i = 1}^{m}y_i}e^{-m\theta}\times \theta^{a_0-1}e^{-b_0\theta}$  $p(\theta|y) \propto \theta^{\sum_{i = 1}^{m}y_i+a_0-1}e^{-\theta(m+b_0)}$  $a_m = a_0 + \sum_{i = 1}^{m}y_i$  $b_m = b_0 + m \neq b_0 + \sum_{i = 1}^{m} \frac{n_i}{100}$  I think I am doing a mistake, because I don't know how to incorporate the information that the mean of $y_i$ is given as $\frac{n_i*\lambda}{100}$. Or do I just have to transform $b_m$ somehow? Can someone may give me a hint?   Thank you already in advance!  Edit 1: Considering first advices  $Likelihood: p(y | \theta) \propto \prod_{i=1}^{m}(\frac{n_i\lambda}{100})^{y_i}e^{-\frac{n_i\lambda}{100}}$  $\propto \prod_{i = 1}^{m} ((\frac{n_i}{100})^{y_i})\lambda^{\sum_{i=1}^{m}y_i}e^{-\lambda\sum_{i=1}^{m}\frac{n_i}{100}}$  $\propto \lambda^{\sum_{i=1}^{m}y_i}e^{-\lambda\sum_{i=1}^{m}\frac{n_i}{100}}$  Is the transformation of $\prod_{i=1}^{m}$ I did from the first to the second step correct? Where can I find information about past versions of iOS and code-signing windows? I have an iPad 2 that is currently running iOS 5.0.1. I'm generally happy with it but some applications require a more recent iOS version. So I started to look into upgrading it, but the only upgrade that it offers is to iOS 7.  From the look of it I don't like the new design of iOS 7 too much and also upgrading to a version this fresh doesn't appeal to me. So my question is: is there a way to upgrade to some version of iOS 5.x or iOS 6.x instead of upgrading to iOS 7? I submitted a new version of the sitemap index for my site in Google Search Console two days ago. Soon after submission, GSC started saying that the index was "processed successfully", and yet has continued to display zero as the number of discovered URLs.  Note that my sitemap index points to about 11000 sitemaps, which provide actual links to pages.  I'm pretty sure the format of both the sitemap index and the individual sitemaps is correct.  Screenshot:    Should I worry about this? What does it mean?  Edit on 2020-02-03:  Google finally started displaying the right number in Total discovered URLs. It must have happened sometime in January. Why so late - I have no idea... I would like to convert a Mp4 file in HD into a Mp4 file of lower resolution. Is there any software that can be used for this? how to remove object from NSDictionary Distance learning: taken seriously? I'm currently in the first year of a six year bachelor's degree aiming for astrophysics. The course is a home/distance learning setup run by the Open University. While I am enjoying it thoroughly, I am aware of the academic politics that can dog professional science. So my question is thus: Upon soldiering on with the degree, then masters, and then PhD, will I be taken seriously within a professional setting given my inability to reference a leading university for my education? Will the format for my studying be "pitied"?   Edit: I suppose a bit more info may help. I'm 27,wife, 2 children, and I currently work as a full time chef, and self employed part time IT technician. I flunked my GCSEs, with no further education. The past 3 years have been a revelation for me, and I have discovered a before unexperienced love for academia; specifically, physics and astronomy. Last year I completed a 1 year OU maths brush up course, which at the time I really struggled with. This year I had a bout of madness and took the plunge for a BSc degree in astronomy. I am now loving the math within the physics so far (yet to hit calculus though!)  PhD, and even masters, is a long way off.  Also, since this original post I've improved my understanding of what a PhD actually entails. So I realise that if I get there, it may well not have anything to do with the OU!     It occurs to me that a lot of my initial queries could have been avoided with a better understanding of the educational and qualification system itself. I now have a greater appreciation as to what a PhD actually is, realising that its a long way off and not necessarily needed for a fulfilling career in research.  I think trying to repair my broken education and fight my way into a worthwhile (and productive!) career is enough of challenge at the moment. There will be plenty of time later for worries concerning doctorates.  It is good to hear that there is at least an open mind towards distance educated professionals.   As has been said, if you've got it, you've got it - you just have to be ready to prove it. Can a probability distribution value exceeding 1 be OK? I had a bunch of errors in the output of sudo apt-get update:  duplicate entries and 404 not found errors.  Figured those out, I hope: I removed PPAs that didn't have any packages associated with them, then I removed out a duplicate entry in /etc/apt/sources.list.  It seems I have royally buggered it up.  Now most of the lines say Ign when I do sudo apt-get update.  How do I go about straightening out what I have screwed up?  I need to get rid of these Igns that are all over the place.  There are about 50% (eyeball guess) Igns! A gold reviewer badge? For your continued efforts in reviewing posts, even though the system sometimes messes up and doesn't let you actually review things and keeps displaying them over and over and over. So also, for your patience in putting up with the glitches in the review panel too! Haha  Anyways, a gold reviewer badge: 20000 reviews, over 4000 actioned  I just multiplied both numbers by 20. Think those numbers seem challenging? Is anyone up near those numbers or should it be multiplied by 10 instead? I prefer the higher amount because it would be gold and something harder to work for. :) But we also have to consider the longevity of when all these posts are eventually reviewed and it's only new posts being created.  Anyways, my stats for those who are interested (I wouldn't get the badge to start because I only have ~2000 actioned):  Upvoted            189 Downvoted          11 Edited             926 Commented          127 Voted to Close     44 Flagged            447 Reviewed           21609   As far as the name of the badge, I really like "The Owl is Watching" but not sure if that would be too long. Sounds snazzy though. Ideas?    Personally, I was on a quest to try and clear out all the posts in a single tab before it started showing me the same things over and over (and over) and then it got frustrating because I wasn't even making progress. Quest denied. :(    Lately I've noticed a massive build-up of unreviewed posts. When the review panel was first implemented, there would only ever be maybe 50 unreviewed posts at a time (in a given tab) for my monthly view. Now I log in and there's a thousand or two thousand pending. I think a lot of people quit reviewing after the first badge, so having a gold badge with a high threshold would really improve activity in the review panel and keep people going to improve the community. What is the difference between \mathbin vs. \mathrel? These seem to be very similar as they both separate two operands. When would one be used over the other? Is there any difference in the math spacing surrounding them?  How would the spacing in these relate to to the spacing produced by \mathop? Define a linear operator $T:C[0,1] \to C[0,1]$ as follows: $$Tf(x) = f(x) + \int_0^x f(u)du$$ It is easy to show that $T$ is a bounded linear operator. The statement also (1) claims that $T$ is one-to-one and onto, and (2) asks to compute $T^{-1}$. (Hence $T$ is an isomorphism due to a corollary of Open Mapping Theorem)  I need help to prove $T$ is onto: given any $g \in C[0,1]$, how to decompose it into a sum between a continuous $f$ and its antiderivative. I have trouble decomposing $g(x)=|x|$, not to mention bizarre functions like Weierstrass function. It seems impossible.  Thanks in advance for help! Is there a gender-neutral pronoun that can replace “his” or “her”? This post has two parts: (a) a question and (b) a proposal.   (a) Often, particularly while writing technical papers or user's manuals, I have come across a situation where I need to say:      A user of this software may not need to use it from his personal computer. He can use it from a phone or even from his tablet.   I have seen many authors use female pronouns (i.e. “she” and “her”), but lately this trend seems to have ebbed somewhat.   I, and (I suspect) many other authors, do not want to use passive voice to avoid this.   Is there a gender-neutral way to describe the same situation?   (b) If there is none, I would like to propose using “ze” (for “he” or “she”) and “zir” (for “his” or “her”, rhyming with “fir”) as gender-neutral pronouns. I want to know how you feel about these words.