I had an unclear situation in one of my sessions. A monster grappled a PC adjacent to him. In the next turn, a PC cast Gust on the monster. After failing its strength check the monster was moved away from its prey, outside its 5ft reach range from the PC it had grappled. Is it OK to consider this to end the grappled condition?
A situation came up in my session where a fighter used his Shield Master Shove feature to shove a Giant Crocodile that was currently restraining another PC using it's bite+grapple ability.  I did a quick check at the time and did not find anything related to shove, although in the  condition description it states:     The condition also ends if an effect removes the grappled creature from the reach of the grappler or grappling effect, such as when a creature is hurled away by the thunderwave spell.   I ruled at the time that a shove would count in a similar way to being "hurled away" however I wasn't sure and said I would find more concrete information for the future.  I have searched high and low for somebody else asking this specific question but have yet to find it. I saw some reference to a Jeremy Crawford tweet about involuntary movement and grappling however I am unable to find it.  If a third party "shoves" a creature that is grappling another, does it only shove the grappler away, or does it move both the grappler and grappled?  I drew a diagram:   (; this question relates to if a third party shoves the grappler instead, so it's not a duplicate.)
Polynomials, prove exercise question about question There is a polynomial P with integer coefficients and with pairwise different integers $a,b,c$ . Prove that it is not possible for $P(a) = b$, $P(b)=c$, $P(c) = a$  First off I don't understand "pairwise different" part - what does it mean ,can you show me this as an equation? After that I'd like to get a hint in case I don't make it. + I'd prefer to have hints/answers written more algebraically without $\sum$ etc. (It helps me get better understanding what's going on under the hood) How to get the current time in Python How do I get lightning:datatable to do some undocumented thing X? Canonical Question  I want to do &lt;some really cool thing&gt; with a lightning:datatable, but I can't seem to figure out how to do it. I checked the , but I did not see a way to implement &lt;this really cool feature I need&gt;.  Perhaps I want to provide tooltips, or a pick list, or alter the behavior of the menus, or display images, or show a custom component I created, or define a new row-level click behavior, or alter the keyboard event handlers, etc.  Can I somehow do this? Two trains travel on the same track towards each other, each going at a speed of 50 kph. They start out 100km apart. A fly starts at the front of one train and flies at 75 kph to the front of the other; when it gets there, it turns around and flies back towards the first. It continues flying back and forth till the two trains meet and it gets squashed. How far did the fly travel before it got squashed?  The question is relatively simple - the trains take an hour to collide, and in an hour the fly would travel 75 km. However, the question got me wondering: Lets say you are given a time $t$ in hours(where $t&lt; 1$) How many &quot;rounds&quot; would the fly make in $t$ time? A round  is defined as moving from one train to another and back. How would I model the equation? Difference between  and  in Java Jquery, changing background image with timer How to check if jQuery.ajax() request header Status is "304 Not Modified"? How does the standard error work? I have been looking into the inner-workings of the standard error recently, and I found myself unable to understand how it works. My understanding of the standard error is that it is the standard deviation of the distribution of sample means. My questions are:  • how do we know the standard error is the standard deviation of the sample means when we usually take just a single sample?  • why doesnt the equation to calculate the standard error mirror the standard deviation equation for a single sample? How can I download free apps without registering an Apple ID? "This Apple ID has not been yet been used before in the iTunes Store. Tap review to sign in, then review your account information."   I keep getting this message when I try to install free apps from App Store. I don't want to give my account info until I actually purchase something.   Can I not download free apps until I provide my account information? My email verification is complete. I'm using an iPhone 3GS logged in to my iTunes account. Suggested improvements to badges index page ()  Currently,  shows the possible badges, number of total recipients, and brief descriptions. However, I have a few suggestions (mostly minor changes) that could make it a bit nicer.   There is no way to see (on that page) which badges I've earned multiple times — they all appear with a green checkmark. It would be nice to show something like "x 4" like in the badges section of the user profile page. For example:      There is no way to see which badges can be awarded multiple times — you have to click on a specific badge to see yea or nay. It would be nice to have a small, simple icon next to badges that can be earned multiple times, similar to the checkmark showing which badges I've earned. The layout would be nicer if the number of recipients for each badge were in a separate column — since the badge images are different sizes, the overlap and ragged right alignment makes the numbers harder to read. An alternative view that groups badges by "achievement level" (gold/silver/bronze) would be nice, as would a view that groups progressive degrees of the same accomplishment. (e.g. Nice Answer &rarr; Good Answer &rarr; Great Answer OR Popular Question &rarr; Notable Question &rarr; Famous Question) Subscribe to a particular question by email (not RSS) Algebraic closure of $\mathbb{C}(x)$ is isomorphic to $\mathbb{C}$ Let $x$ be transcendental over $\mathbb{C}$. Let $K$ be the algebraic closure of $\mathbb{C}(x)$. How to show that $K$ is isomorphic to $\mathbb{C}$? The following happened playing Minesweeper:   How do I figure out which square to click? What is the value of the series   $\sum\limits_{n=1}^\infty {\frac{1}{10^n-1}}$   and can one find closed forms for the sums   $\sum\limits_{n=1}^N {\frac{1}{10^n-1}}$?   I found that $\sum_{n=1}^N {\frac{1}{10^n-1}} $  =  $\sum_{n=1}^N (\lim_{m\to\infty  }{\frac{10^{-n}-10^{-nm}}{1-10^{-n}}})$  =  $0.111\ldots+0.0101\ldots+\ldots$ but I can't go farther.     The original question is: "Where does the second '1' appear?" Is exFAT now the best choice for an external hard drive that will be used for Windows, Mac, and Linux? Are there names for consonant-shifts when suffixes are added? Solving $\sqrt{x+5} = x - 1$ I'm currently learning about radicals and simplifying them, and I came across this problem on the internet and tried to solve it:  $$\sqrt{x+5} = x - 1$$  So I used this logic:  $$ \begin{align} \sqrt{x+5} &amp;= x - 1 \\ x + 5 &amp;= (x-1)^2 \\ x + 5 &amp;= (x-1)(x-1) \\ x + 5 &amp;= x^2 - 2x + 1 \\ 0 &amp;= x^2 - 3x - 4 \\ 0 &amp;= (x-4)(x+1) \\ \end{align} $$  Therefore, $x = -1$ and $x = 4$ satisfy the equation $0 = (x-4)(x+1)$.  But then I tried to plug them in the original problem $\sqrt{x+5}=x-1$:  $$ \begin{align} \sqrt{4 + 5} &amp;= 4 - 1 \\ \sqrt{9} &amp;= 3 \\ 3 &amp;= 3 \end{align} $$  So using 4 works as expected, but when using $-1$:  $$ \begin{align} \sqrt{-1 + 5} &amp;= -1 - 1 \\ \sqrt{4} &amp;= -2 \\ 2 &amp;\ne -2 \end{align} $$  At what stage am I going wrong?  And according the , the solution is $x = 4$. Temporary locks on answers not showing lock duration Tested on Stack Overflow, Stack Overflow Meta and Pets.  Questions  Temporary locks on questions are showing the duration (mod only).  Stack Overflow.   Meta Stack Overflow.   Pets.   Answers  On answers they are not and there's no way to find the lock duration when we use timeline tools to examine the post.  Pets.   Stack Overflow.   Meta Stack Overflow.   Is this something that hasn't been implemented or is it a bug?  If it hasn't been implemented can we please have it implemented? I have a question about something I'm wondering about. I've read somewhere that L'Hopitals rule can also be applied to complex functions, when they are analytic. So if have for instance:  $$ \lim_{z \rightarrow 0} \frac{\log(1+z)}{z} \stackrel{?}{=} \lim_{z \rightarrow 0} \frac{1}{(1+z)} = 1 $$  Now i'm wondering if this is correct? Also if we take $|z|&lt;1$, is it then correct?  Thanks, I am calculating the class group of $\mathbb Q(\sqrt 6)$. My working is as follows:  The Minkowski bound is $\lambda(6)=\sqrt 6&lt;3$ so we only need to look at prime ideals of norm $2$. $2$ divides the discriminant, $24$, of $\mathbb Q(\sqrt 6)$, so $2$ ramifies, and so for any prime ideal $\mathfrak p$ of norm $2$, $\mathfrak p^2$ is principal. But $(2, \sqrt 6)^2=(2)$, so $\mathfrak p=(2, \sqrt 6)$ has norm $2$. If I can show $\mathfrak p$ is not principal, then I can conclude that $Cl(\mathbb Q(\sqrt 6))\cong C_2.$ But if there was an element of $\mathcal O_{\mathbb Q(\sqrt 6)}$ of norm 2, this would correspond to a solution of the diophantine equation $x^2-6y^2=2$. Clearly $x$ is even, so writing $x=2n$ we get $2n^2-3y^2=1$. Now reducing modulo $3$, we get $2n^2\equiv 1 \pmod 3$ which has no soultions. Hence $\mathfrak p$ is not principal and $Cl (\mathbb Q(\sqrt 6)) \cong C_2.$  However,  says that the class group is trivial. Where have I gone wrong? What am I misunderstanding? Is $(2, \sqrt 6)$ principal?