Jquery return the same id,but i don't use the same id on two elements I have a table and for this table i have an icon "plus" and for each row i have an icon "edit".  When i press "plus" it will create another tr with a select in it and an icon "edit".  This "edit" has an id that is equal with the number of the row,so the first "edit" icon will have id=1,the second id=2 and so on(i'm using an i++ for this).  My problem is that,when i press on "edit" icon i want to display in console the id of the icon(testing porpouse),but this will only work on the first icon.  I saw in another question that this will happen if you have the same id on more elements,but i don't.The code is this:  The main table,with just one row:  &lt;table id="dynamic"&gt;             &lt;tr id="row1"&gt;                 &lt;td&gt;                     &lt;select class="form-control select-table" name="products[]" id="select-1" data-dep=""&gt;                         &lt;?php foreach($products as $product):?&gt;                             &lt;option value="&lt;?php echo $product['products_id'];?&gt;"&gt;&lt;?php echo $product['product_name'];?&gt;&lt;/option&gt;                         &lt;?php endforeach;?&gt;                     &lt;/select&gt;                     &lt;i id="1" data-toggle="modal" data-target="#editModal" class="fas fa-edit fa-lg edit-div"&gt;&lt;/i&gt;                     &lt;div id="plus-div"&gt;&lt;span&gt;&lt;i class="fas fa-plus fa-lg"&gt;&lt;/i&gt;&lt;/span&gt;&lt;/div&gt;                 &lt;/td&gt;             &lt;/tr&gt;         &lt;/table&gt;   The jquery code where i add a new row:  var i = 1;     $('#plus-div').click(function(){         i++;         j++;         $('#dynamic').append('&lt;tr id="row'+i+'"&gt;&lt;td&gt;&lt;select  id="select-'+i+'" class="form-control select-table" name="products[]"&gt;' +             &lt;?php foreach ($products as $product):?&gt;'&lt;option value="&lt;?php echo $product['products_id'];?&gt;"&gt;&lt;?php echo $product['product_name'];?&gt;&lt;/option&gt;' +             &lt;?php endforeach; ?&gt;             '&lt;/select&gt;&lt;i id="' + i + '" data-toggle="modal" data-target="#editModal" class="fas fa-edit fa-lg edit-div"&gt;&lt;/i&gt;&lt;/td&gt;&lt;/tr&gt;');     });   The jquery code where i display the id:  $('.edit-div').click(function(){         console.log((this).id);     });
Event binding on dynamically created elements? I have a bit of code where I am looping through all the select boxes on a page and binding a .hover event to them to do a bit of twiddling with their width on mouse on/off.  This happens on page ready and works just fine.  The problem I have is that any select boxes I add via Ajax or DOM after the initial loop won't have the event bound.  I have found this plugin (), but before I add another 5k to my pages with a plugin, I want to see if anyone knows a way to do this, either with jQuery directly or by another option.
How do I change JPanel inside a JFrame on the fly? To put it simple, there's a simple java swing app that consists of JFrame with some components in it. One of the components is a JPanel that is meant to be replaced by another JPanel on user action.  So, what's the correct way of doing such a thing? I've tried  panel = new CustomJPanelWithComponentsOnIt(); parentFrameJPanelBelongsTo.pack();   but this won't work. What would you suggest? Guest (not logged in) users can only sort questions with specific tag by newest I think this is platform wide (all SE sites).   Logout Choose a tag, eg.  on SO Try to sort questions by something other than newest   No matter what sorting is chosen, questions are sorted by newest "Protect Questions" privilege page has confusing wording The wording on the  privilege page is confusing and would benefit from being clarified. See these questions on  and . Suggested wording from  is to replace this:  Which questions can be protected? Any question, even a deleted question, can be protected and unprotected, subject to the following restrictions:  The question must be at least a day old A user can unprotect any protected question   with the following:  Which questions can be protected? Any question at least a day old, even a deleted question, can be protected and unprotected. A user with the privilege can unprotect any protected question. What kinds of compensation can I get from Deutsche Bahn for canceled and late trains? I know Blender is free software and bugs happen. But my question is, is it good practice to update Blender every time there is an update? Even if a minor one? (i.e I'd consider 2.56 to 2.56b minor or even 2.63, no?)  I haven't been updating very often for fear that updating frequently causes issues like broken settings, non-compatibility or lost user configs?  Or is updating often recommended to keep up to date and adapted to the new changes, i.e like upgrades in the GUI and functionality? Is my US visa still valid after change in name? How can I backup my programs/applications, so that after I reinstall a new one, I can still use the backup-ed ones? Is there a way, that I could backup all my programs, all apps, put them in a directory or something, so that I could install them quickly next time, without having to manually going over the app center, downloading them from terminal, etc?  Note that I might import them from a distro other than the one I exported them on. So, say I'm in Ubuntu, exported some stuff, and then installed BT and wanted to import them from there. Is it grammatical to omit the subject from "I did my work"? Was Daenerys actually trying to hatch the eggs? I was reading @Aegon' s response   and I realized that I've never been clear on whether Dani was intentional in her pyre building to do blood magic and wake the dragons, or if she was just grieving Drogo and killing Mirri and her statement about "only death can pay for life" was a slap in the Maegi's face, since in the end she sacrificed her unborn child for the husk of Drogo.    I know she had tried baking the eggs previously and had felt like they could hatch then, but was clearly disappointed and chastised herself for foolishness when they did not. I don't recall inner monologue or statements after that where she said, "ya know what I should have done..."   I guess what I'm asking is whether there is evidence outside her statement to the Maegi that she was intentional in her blood magic rite or if the miracle was a happy accident? Bind application to a specific network interface I have tried ForceBindIP, but it has a significant downside - it doesn't affect the children of the application I'm trying to bind, it only affects the application itself. It also can't force an application to always run through a specified interface, it has to be run through forcebindip.exe every time. It becomes a problem with applications like League of Legends where the process tree looks like that:    The launcher runs the patcher, the patcher run the client, etc. I can only affect the parent of all these processes in the tree, so the actual game is not bound to the interface I want, making this whole venture pointless.  Is there a more modern alternative to ForceBindIP for Windows 7? There are many questions similar to this one on this site, but they are mostly old. Maybe there is now a better way to solve this problem?  My current idea is to do the following:   Set up local 3proxy server bound to the desired interface. Run the game through Proxifier or similar software configured to run through that local proxy.   I'm not sure if that will work, but even if it will, it seems like a sub-optimal solution. Do you guys have any better ideas?  Edit: My idea didn't work :(  Edit 2: Basically, what I'm trying to achieve is bind a few applications to a regular interface, while VPN is running. The reason is that I need to connect through VPN most of the time, but some applications (such as games) don't work properly this way, because of higher ping and other issues. Slipstream Windows 7 + Service Pack 1 I have a script in file bla.sh and it is executable. When I click on it, the script is executed and the window is closed. I'd like the window to stay open.  Something like command cmd /k** command in Windows.  P.S. I don't want to use pause, but I want to able to write more commands after the script was executed. Insert into ... values ( SELECT ... FROM ... ) I am trying to INSERT INTO a table using the input from another table. Although this is entirely feasible for many database engines, I always seem to struggle to remember the correct syntax for the SQL engine of the day (, , , , and ).  Is there a silver-bullet syntax coming from an SQL standard (for example, ) that would allow me to insert the values without worrying about the underlying database? How do I split a forest tree into two trees with proper vertical alignment? \documentclass[oneside,12pt]{article} \usepackage{geometry} \usepackage{microtype} \usepackage[utf8]{inputenc} \usepackage[T1]{fontenc} \usepackage{lmodern}  \usepackage{enumitem} \setlist[enumerate,1]{label=\bfseries\Alph*,align=left,leftmargin=*,   labelsep=1.5em} \setlist[enumerate,2]{label=\arabic*.,labelindent=1em,labelsep=1.5em,   leftmargin=*}  \usepackage{amssymb} \usepackage{amsmath} \usepackage{amsthm} \theoremstyle{definition} \newtheorem*{sol}{Solution}  \usepackage{forest} \forestset{   ass/.append style={     before computing xy={l=\baselineskip},     no edge   },   prooftree/.style={     for tree={       child anchor=north,       parent anchor=south     }   } }  \begin{document} \subsection*{Exercises 29} \begin{enumerate} \item Use QL trees to evaluate the entailment claims (1) to (10) in Exercises   28A.   \begin{enumerate}   \item $\forall x(Fx\supset Gx)\vDash\forall x(Gx\supset Fx)$      \begin{forest}       prooftree       [$\forall x(Fx\supset Gx)$       [$\neg\forall x(Gx\supset Fx)\checkmark$,ass       [$\exists x\neg(Gx\supset Fx)\checkmark$,ass       [$\neg(Ga\supset Fa)\checkmark$,ass       [$Ga$,ass       [$\neg Fa$,ass       [$(Fa\supset Ga)\checkmark$,ass       [$\neg Fa$] [$Ga$]]]]]]]]     \end{forest}      $\neg Fa$ and $Ga$ make the premisses and the negation of conclusion true.     Thus, the entailment is invalid.   \item $\forall x(Fx\supset Gx)\vDash\forall x(\neg Gx\supset\neg Fx)$      \begin{forest}       prooftree       [$\forall x(Fx\supset Gx)$       [$\neg\forall x(\neg Gx\supset\neg Fx)\checkmark$,ass       [$\exists x\neg(\neg Gx\supset\neg Fx)\checkmark$,ass       [$\neg(\neg Ga\supset\neg Fa)\checkmark$,ass       [$\neg Ga$,ass       [$\neg\neg Fa$,ass       [$(Fa\supset Ga)\checkmark$,ass       [$\neg Fa$ [*,ass]] [$Ga$ [*,ass]]]]]]]]]     \end{forest}      Since the tree closes, the entailment is valid.   \item $\forall x\exists yLxy\vDash\forall y\exists xLyx$      \begin{forest}       prooftree       [$\forall x\exists yLxy$       [$\neg\forall y\exists xLyx\checkmark$,ass       [$\exists y\neg\exists xLyx\checkmark$,ass       [$\neg\exists xLax\checkmark$,ass       [$\forall x\neg Lax$,ass       [$\exists yLay\checkmark$,ass       [$Lab$,ass]]]]]]]     \end{forest}      \begin{forest}       prooftree       [$\neg Lab$,ass [*,ass]]     \end{forest}   \item $\forall x((Fx\wedge Gx)\supset Hx)\vDash\forall     x(Fx\supset(Gx\supset Hx))$   \item $(\forall xFx\vee\forall xGx)\vDash\forall(Fx\vee Gx)$   \item $\forall x(Fx\supset Gx),\forall x(\neg Gx\supset Hx)\vDash     \forall x(Fx\supset\neg Hx)$   \item $\exists x(Fx\wedge Gx),\forall x(\neg Hx\supset\neg Gx)\vDash     \exists x(Fx\wedge Hx)$   \item $\forall x\exists y(Fy\supset Gx)\vDash\forall y\exists x(Gx\supset     Fy)$   \item $\forall x\forall y(Lxy\supset Lyx)\vDash\forall xLxx$   \item $\forall x(\exists yLxy\supset\forall zLzx)\vDash\forall x\forall y     (Lxy\supset Lyx)$   \end{enumerate} \end{enumerate} \end{document}   Usually, I have to manually split a forest tree into two to emulate page breaking in a forest tree. However, the second tree doesn't vertically align with the first as in the picture below. How can I vertically align them together? @cfr Prove that if W is a subspace of a finite dimensional vector space V, then dim(W) ≤ dim(V). My attempt at a solution:  Proof  Given a vector space $V$, let $S={v_1,...,v_n}$ be a basis for $V$. Consequently $\dim(V)=n$. Now given $W$, a subspace of $V$, it will be shown that $\dim(W)\le \dim V$   First, consider the case where $W=${0}. Then $dim(W)=0 \le\ n$,   Subsequently, consider the case for $W=V$. Then it follows that $dim(W)=dim(V)=n$.  Finally, consider the case where $W \subset V$ and without loss of generality assume $v_n \notin W$. Let $T={v_1,...,v_k}$ where $k\lt n$ be a basis for the subspace W. Now, since S is a basis for V, for every $v_i \in S$,  $c_1v_1+...+c_nv_n=0$ has only the trivial solution, thus none of the vectors in S can be expressed as linear combinations of the other vectors in S. It follows that the set T is not a basis for V as $v_n$ cannot be generated from T. The $dim(W)$ is given by the number of vectors in the basis. Therefore, $dim(W)=k \lt n$  Therefore, it has been shown that if $W \subseteq V$ then $dim(W) \le dim(V)$ I have a multi-line equation that I want to have matching sized parentheses. The advice I read online was to use \left( equation \right. \\ left. rest-of-equation \right) . However, this syntax leaves first half of the equation unaware of what is in the second half. For example, if you include a square root term after the break, the second parenthesis will be larger than the opening parenthesis. When you are using the aligned environment to split a long equation this can look somewhat offputting.    Compare the top equation to the bottom one. The parentheses match in size for the bottom equation, but the left hand parentheses for the top one is  noticeably smaller.  Top Code:   \begin{aligned}[t]   \gamma_{\text{u}} + \frac{1}{108}   \left(57\gamma_{\text{er}} \right. &amp;+  38\gamma_{\text{se}}\\ &amp; {}\pm  \left.\sqrt{2601 \gamma_{\text{er}}^2 + 3648  \gamma_{\text{er}}\gamma_{\text{se}} + 1444 \gamma_{\text{se}}^2}  \right)   \end{aligned}   Bottom Code:  \begin{aligned}[t] \gamma_{\text{u}} + \frac{1}{16} \left(9\gamma_{\text{er}}  +  6\gamma_{\text{se}} \pm  \sqrt{49 \gamma_{\text{er}}^2 + 76 \gamma_{\text{er}}\gamma_{\text{se}} + 36 \gamma_{\text{se}}^2} \right) \end{aligned} How to achieve nomenclature entries like: symbol, Description, Dimension and unit, etc? The title is pretty much I want to ask. More detail, the nomenclature entries should be sorted in groups like:   Nomenclature     Acronyms     Symbol  Description     % no Dimensions and Units      ...     Greek Symbols     Symbol  Description             Dimensions     Units     ...     Roman Symbols     Symbol  Description             Dimensions     Units     S       Surface area vector     L^2            m^2     ...    Superscripts     Symbol  Description     % no Dimensions and Units      ...    Dimensionless Numbers     Symbol  Description     Definition     ...   e.g. expected entries like this:       My current nomenclature settings for grouping [book class]:  %---------------------------------------------------------- %                        Nomenclature %---------------------------------------------------------- %\renewcommand{\nomname}{List of Symbols and Abbrev.} \renewcommand\nomgroup[1]{%   \ifthenelse{\equal{#1}{A}}{%    \item[\textbf{Acronyms}] }{%                  A - Acronyms     \ifthenelse{\equal{#1}{R}}{%      \item[\textbf{Roman Symbols}]}{%            R - Roman       \ifthenelse{\equal{#1}{G}}{%         \item[\textbf{•} Symbols }]}{%          G - Greek           \ifthenelse{\equal{#1}{S}}{%            \item[\textbf{Superscripts  }]}{{%          S - Superscripts         \ifthenelse{\equal{#1}{U}}{%          \item[\textbf{Subscripts }]}{{%                 U - Subscripts         \ifthenelse{\equal{#1}{X}}{%          \item[\textbf{Other Symbols }]}%            X - Other Symbols                     {{}}}}}}}}}} %\ifpdf \renewcommand{\nomlabel}[1]{\hspace{1 em}#1}%{\hspace{1.5 em}#1} \renewcommand*{\nompreamble}{\markboth{\nomname}{\nomname}}   But how to extend it with Dimensions and Units? Linear regression best polynomial (or better approach to use)? Any ideas on other polynomials I could successfully use for applying regression? My goal is a solution that has fit error strictly based on the noise. Is this possible since it is a bell-like curve? The tails can be long, short or non-existent. Am I looking for the impossible? Please note it has been a while since I have plunged this far into linear regression.   Anyway, my data points do not fit the $ax+bx^2+c$ polynomial well enough. I would like a replacement for this polynomial to apply regression (or different approach). In the following example, each point misses the fit curve by $20\%$ of the $Y$ range on average (of the data points). I looked at splines, but I do not know how to apply the regression since they look piece-wise.   Example $Y$ values (evenly spaced in $X$). It looks kind of like a bell curve. I would be applying 5 to 50 data points to determine the polynomial coefficients. Ultimately, I am interested in the best $X$ location for the peak based on the data points.     X      Y -40    -21142.1111111111 -30    -21330.1111111111 -20    -12036.1111111111 -10      7255.3888888889   0     32474.8888888889  10     32474.8888888889  20      9060.8888888889  30    -11628.1111111111  40    -15129.6111111111 A way of casting a base type to a derived type Python/Matplotlib - Is there a way to make a discontinuous axis?