How do we access the second last copied stuff on our clipboard?  (Windows Vista Home Premium 32-bit sp2)  I am still interested if the solution is not a straightforward one and requires hacks
In Visual Studio, I can cycle through my clipboard history by pressing CTRL+SHIFT+V rather than CTRL+V. I believe it's called a clipboard ring. But that feature doesn't seem to exist outside of Visual Studio, at least not with the same key combination. Is there a key stroke combination built in to windows to do the same, i.e. be able to cycle through your clipboard history while pasting?
Get month name from Date Is there any way to recover deleted files which may have since been overwritten? I deleted lots of files &amp; folders on my laptop and then I put a new files in the same folders. I need to recover the deleted files. I tried a lot of recovery software and I couldn't recover my old files.   I read that if you refill the folders with new files after deleting old ones then I can't recover them again. Is that true?   What should I do? For any smooth manifold, is it true that for any two points on the manifold, there exists a chart that covers the two points? Some say that we can connect two points with a continuous curve and a small contractible neighborhood of the path together with the charts of the points can be regarded as the chart. But I don't know how to verify this statement. Express the complex numbers given in Problem in the form $a+ib$ automatic size adjustment for nested parentheses As I prefer outer parentheses to grow larger in nested expressions, I happen to insert \bigl and \bigr and its larger cousins a lot. I have always wondered whether there is a way to do this automagically.  Inserting \left and \right prophylacticly before all opening and closing parentheses and hoping that it sorts things out doesn't do the trick in all cases as seen below.  The left column is without any size changing commands. The middle column as a \left \right pair at every parentheses/brace/bracket and the rightmost column shows my preferred version.    As seen in the middle column of the second and third line the \left and \right pair sometimes makes the outer parentheses larger, on the cost of an extra horizontal space between \Pr and (. The extra space is fine in case of really big opening parentheses but here I'd prefer the regular spacing.  \documentclass{scrartcl} \usepackage{amsmath} \usepackage{amsfonts} \begin{document} \begin{align*} &amp;1-(1-F(x))^n&amp;&amp;1-\left(1-F(x)\right)^n&amp;&amp;1-\bigl(1-F(x)\bigr)^n\\ &amp;\Pr(X_{(1)}\le x)&amp;&amp;\Pr\left(X_{(1)}\le x\right)&amp;&amp;\Pr\bigl(X_{(1)}\le x\bigr)\\ &amp;\mathbb{E}[\min\{X_1,X_2\}]&amp;&amp;\mathbb{E}\left[\min\left\{X_1,X_2\right\}\right]&amp;&amp;\mathbb{E}\bigl[\min\left\{X_1,X_2\right\}\bigr]\\ &amp;\left(\pi-\arccos(\frac{y}{r})\right)&amp;&amp;(\pi-\arccos\left(\frac{y}{r}\right))&amp;&amp;\left(\pi-\arccos \left(\frac{y}{r}\right)\right) \end{align*} \end{document}   As mathematical expressions can be arbitrarly complex there is probably no general way to do this. But I’m not asking for a solution of the general case. A partial solution that works in the simple cases shown above would be a big help. The simple rule could be, that parentheses never shrink below the size of an inner pair. Of course you can immediately think of extensions like a \mid in a conditional expectation that grows with the size of the expectation’s brackets.  What is your preference regarding the size of nested parentheses? Is there a better way to archieve your preferred style despite inserting \bigl \bigr manually?    EDIT:  A colleague pointed me to section 8.3 of Herbert Voß’  document where size problems with parentheses are solved by playing with two TeX parameters within a group around the expression in question. This led naturally to appendix G of the TeXbook where the mechanics of \delimitershortfall and \delimiterfactor are explained.  \delimitershortfall specifies the maximum space not covered by a delimiter (default 5pt) and \delimiterfactor is the ratio for variable delimiters, times 1000 (default 901).  I used them to implement the never shrink below a subformular size idea from above by setting the shortfall to 0pt and the ratio to 1.0.    While it works nicely in line one and three, in line two and four the parentheses now grow too much, and still there is the extra horizontal space introduced by \left. I've just made a minor alteration to a file from a TeX package.  I copied it into my local texmf tree and made the change there.  When I tried kpsewhich &lt;filename&gt; to test that it was finding my local version, it returned the original one and not the new one.  In actual fact, the original file was from my local texmf tree already so I renamed the old one something simple.  Now kpsewhich &lt;filename&gt; returned the system version of the file.  To check that the file was there, I tried kpsewhich -all &lt;filename&gt; and got the correct two versions of the file: my modified one and the system one (in that order).  If I try this with another file that I know exists in both places, then kpsewhich &lt;filename&gt; returns my local file.  Here's the various invocations and their results:  ~% kpsewhich pgfsys-pdftex.def /usr/local/texlive/2012/texmf-dist/tex/generic/pgf/systemlayer/pgfsys-pdftex.def ~% kpsewhich -all pgfsys-pdftex.def  /Users/stacey/Library/texmf/tex/latex/bzr/pgfsys-pdftex.def /usr/local/texlive/2012/texmf-dist/tex/generic/pgf/systemlayer/pgfsys-pdftex.def ~% kpsewhich tqft.sty               /Users/stacey/Library/texmf/tex/latex/bzr/tqft.sty ~% kpsewhich -all tqft.sty /Users/stacey/Library/texmf/tex/latex/bzr/tqft.sty /usr/local/texlive/2012/texmf-dist/tex/latex/tqft/tqft.sty   Is it something special about the .def extension?  Is there some command that I forgot to run?  Are there some other options to kpsewhich that will help me debug this? Bounded in Probability and smaller order in probability Evaluating $\sum_{n=1}^{\infty}\frac{(n-1)!}{\prod_{r=1}^{n}(x+r)}$ for $x\in\mathbb{R}^{+}$ I am trying to evaluate the following sum. Here $x\in\mathbb{R^{+}}$. $$f(x)=\sum_{n=1}^{\infty}\frac{(n-1)!}{\prod_{r=1}^{n}(x+r)}$$ At present I do not know how to proceed. Any hints are appreciated. Thanks. \mathcal(O) and font size I use the following mystic TeX so as to display the Landau's notations for big and small O.  There is one partial solution to improve the scriptscriptstyle so as to not use a small o : see the secund answer below. The problemen with \smallOBis is the wrong spacing, contrary to \smallO. How can I do this ?  % Sources : %     1) http://forum.mathematex.net/latex-f6/bonnes-commandes-de-base-t12278.html %     2) http://tex.stackexchange.com/questions/30944/mathcalo-and-font-size  \documentclass{article}     \usepackage{amsmath}     \usepackage{amsfonts}     \usepackage{amssymb}      \usepackage{graphicx}      \newcommand{\bigO}[1]{\ensuremath{\mathop{}\mathopen{}\mathcal{O}\mathopen{}\left(#1\right)}}      \newcommand\smallO[1]{         \mathchoice             {% \displaystyle                 \ensuremath{\mathop{}\mathopen{}{\scriptstyle\mathcal{O}}\mathopen{}\left(#1\right)}             }             {% \textstyle                 \ensuremath{\mathop{}\mathopen{}{\scriptstyle\mathcal{O}}\mathopen{}\left(#1\right)}             }             {% \scriptstyle                 \ensuremath{\mathop{}\mathopen{}{\scriptscriptstyle\mathcal{O}}\mathopen{}\left(#1\right)}             }             {% \scriptscriptstyle                   \ensuremath{\mathop{}\mathopen{}{o}\mathopen{}\left(#1\right)}             }     }      \newcommand\smallOBis[1]{         \mathchoice         {% \displaystyle             \scriptstyle\mathcal{O}\left(#1\right)         }         {% \textstyle         \scriptstyle\mathcal{O}\left(#1\right)         }         {% \scriptstyle         \scriptscriptstyle\mathcal{O}\left(#1\right)         }         {% \scriptscriptstyle         \scalebox{0.8}{$\scriptscriptstyle\mathcal{O}$}\left(#1\right)         }     }   \begin{document}  \[     \renewcommand{\arraystretch}{1.2}%     \begin{array}{llll}          \textbf{Style}            &amp; \verb!\bigO!         &amp; \verb!\smallO!                          &amp; \verb!\smallOBis!         \\ \hline         \verb!\displaystyle!      &amp; \displaystyle      \bigO{\frac{1}{n}}         &amp; \displaystyle      1 + \smallO{\frac{1}{n}} - 2 &amp; \displaystyle      1 + \smallOBis{\frac{1}{n}} - 2         \\         \verb!\textstyle!         &amp; \textstyle         \bigO{\frac{1}{n}}         &amp; \textstyle         1 + \smallO{\frac{1}{n}} - 2 &amp; \textstyle         1 + \smallOBis{\frac{1}{n}} - 2         \\         \verb!\scriptstyle!       &amp; \scriptstyle       \bigO{\frac{1}{n}}         &amp; \scriptstyle       1 + \smallO{\frac{1}{n}} - 2 &amp; \scriptstyle       1 + \smallOBis{\frac{1}{n}} - 2         \\         \verb!\scriptscriptstyle! &amp; \scriptscriptstyle \bigO{\frac{1}{n}}         &amp; \scriptscriptstyle 1 + \smallO{\frac{1}{n}} - 2 &amp; \scriptscriptstyle 1 + \smallOBis{\frac{1}{n}} - 2     \end{array} \]  \end{document} I installed Android studio some time ago using the following suggested method:     To set up Android Studio on Linux:      Unpack the downloaded Tar file,   android-studio-ide--linux.zip, into an appropriate location   for your applications. To launch Android Studio, navigate to the   android-studio/bin/ directory in a terminal and execute studio.sh. You   may want to add android-studio/bin/ to your PATH environmental   variable so that you can start Android Studio from any directory.   Follow the links to install the SDK outside of the Android Studio   directories.   For whatever reason it has become corrupt and insists I must un-install and re-install. I can't for the life of me find how to un-install it however.  I didn't use apt-get so I can't do apt-get remove.  Does anyone have any suggestions? How to tweet using terminal? How to use getElementsByClassName in javascript-function? Suppose $n$ is a non negative integer $\geq 4$ and $\sigma\in S_n$ a permutation. Conjugacy classes in $S_n$ are completley determined by the cycle structure of $\sigma$. If we let the alternating group $A_n$.act on $S_n$ by conjugation, the orbits coincide with the conjugacy classes in $S_n$ except for those (even) permutations whose cycle structure is composed of even cycles (which corresponds to cycles of uneven length) of distinct order (fixed points are treated as cycles of length $1$.) See   For instance a $3$-cycle in $A_4$ has cycle structure $[3,1]$ which fits the bill, and a $5$-cycle in $A_5$ or $A_6$ works too, since the cycle structure is $[5]$ and $[5,1]$ respectively. On the other hand, a $3$-cycle in $A_5$ will does not satisfy the criteria as it has cycle structure $[3,1,1]$ with two fixed points.  In this case, the conjugacy class of $\sigma$ inside $S_n$ splits in $2$ orbits of the conjugation action of $A_n$, and if $\tau$ is any odd permutation, for instance $(12)$, then we have $$\mathrm{Conj}_{S_n}(\sigma)=\mathcal{O}(\sigma)\coprod\mathcal{O}(\tau\sigma\tau^{-1})$$  My question is How can we differentiate between the two orbits? Does it have geometric meaning?    I can see that this information can be useful when looking at representations of the alternating groups, since there are as many irreducible representations as conjugacy classes. As for some geometric interpretation, I ask because there is one for the three cycles in $A_4$. If $S_4$ is understood as the group of symmetries of a regular tetrahedron, then $A_4$ is the subgroup of direct symmetries, and a $3$-cycle corresponds to a rotation of angle $\frac{2\pi}{3}$ or $\frac{4\pi}{3}$ with axis passing through one of the vertices. Conjugacy classes inside $A_n$ preserve the angle, and that's how we can tell them apart. In this case the computations are so simple we don't really need this picture, but I think it is a nice way to understand the fact $3$-cycles in are not all conjugate inside $A_4$... Modify a shape and have modifications apply to clones Is there any any "Symmetry Modifier" option in illustrator?   Let's say I want to create a head that is totally symmetric. I created one half then mirrored it to get another half. Flipped the other half, aligned them and joined them together with Pathfinder→Unite option.   Now I modified some portion of the right half outline. But how can I get that same modification to be updated on the left option? I thought it would happen automatically. How do I install Ubuntu Server (step-by-step)? I'd like to install Ubuntu server on my machine, is there a step-by-step instructions on how to accomplish that or a guide that will just go through the basic steps of installing Ubuntu Server from beginning to end.  Instructions originally for 13.04. I am trying to solve the following exercise:     Prove that complex multiplication does not extend to a multiplication   on $\mathbb R^3$ so as to make $\mathbb R^3$ into a real division   algebra.   I am aware of Frobenius' theorem that there are only three finite dimensional real associative division algebras. But the exercise would be pointless if the theorem was assumed.   Let $x,y \in \mathbb R^3$. Since $x y$ has to extend the complex multiplication:  $$xy = (x_1y_1-x_2y_2, x_1y_2 + x_2 y_1, ?)$$  I have no idea how I can proceed from here. Could someone tell me how to do this? It should be easy as the other exercises I did so far were also easy. How to enable numlock at boot time for login screen? I am trying to force numlock to be on upon initial boot at the login screen on Ubuntu 12.04. The only solutions I have found so far switch numlock on only after initial login.  I'm looking to force numlock to be on when the login screen is displayed, and before the user has logged in. Can anyone assist? A folder was created in my home folder (not by anyone), and I cannot see the folder contents. She has root privileges, but when the nautilus root access the folder is empty. When I try to remove it, it will appear to remove more than 1 million files from my computer, and I do not know what these files are.  How i can see these files? the name of folder created is "4F8ZBREShQ". I'm scared about it... Will $\sum^{\infty}_{n=1}|a_n|^p$ converge? Given that $\sum^{\infty}_{n=1} a_n^2$ converges,then, will $$\sum^{\infty}_{n=1}|a_n|^p$$ converge for $p&gt;2$?  I couldn't find a counterexample neither a proof but it looks to me that this is true. For $p=3/2$, I found the counter example $\sum a_n=\displaystyle \sum^{\infty}_{n=1} \frac{1}{n^{2/3}}$ Why does Stack Overflow allow duplicate display names? What is the reasoning behind the design decision to allow users to create a display name which matches another existing users exactly?    This is opposed to the common practice of enforcing unique user names, and I'd really like to learn something.