The meaning of would in this sentence Please tell me what "would" means in this sentence.     In AmE, the phrase "go to hospital' would be not correct. One of the articles, a or the, would be necessary.
"Was going to" versus "would be" as the past tense of "will" Do you think that "was going to be" or "would be" could be used as past tense of will?     I thought this book was going to be your choice.        I thought this book would be your choice.   Do these two sentences basically mean the same thing or are they slightly different?
macOS: Is there a way to show an image constantly on screen (like a watermark)? I'm looking for a very simple way to add a watermark to my screen which should be shown whatever I'm doing, is it during a Zoom call, or is it when giving a presentation, or similar (I don't necessarily need it to show during fullscreen mode). The reason is that I want to record my screen using QuickTime Player, and the watermark should be on the video. I know that there are many post-production tools that offer adding watermarks, but I don't want to do any post-production, I want to have everything on screen while recording already. (I also know that there are screen recorders which offer placing a watermark to the end result. I'd rather also avoid using another screen recording software, but if I don't find any other way to do it, then I'm open to a simple, non-pricy alternative to QuickTime Player.) which novel involved sending instantaneous tachyon body copies around the galaxy, mostly to die? The novel centers around a man living a comfortable existence in the pretty distant future.  To support himself, he is occasionally asked to enter a box which will copy his entire body, and send it out faster than the speed of light to some developing world, to work.  His copy on this world wakes up and realizes what a big mistake he's made.  The copy does grueling work, feels lonely, and eventually just dies of radiation sickness.  Back on earth, the man never realizes how bad it is out there, and keeps sending out more copies.  I think the story is probably 80s or earlier - not sure if it's a short story, or the beginning of a novel which I lost &amp; never finished. Permanently removing apache2 It seems a simple apt-get remove apache2 does not completely remove apache2 as I can still see it on one of the processes when running top. How does one remove apache2 completely on his ubuntu server?  It's not removed indeed:  ~# which apache2 /usr/sbin/apache2 ~# whereis apache2 apache2: /usr/sbin/apache2 /etc/apache2 /usr/lib/apache2 /usr/share/apache2 /usr/share/man/man8/apache2.8.gz   But when I do apt-get remove apache2 again:  # apt-get remove apache2 Reading package lists... Done Building dependency tree Reading state information... Done Package apache2 is not installed, so not removed 0 upgraded, 0 newly installed, 0 to remove and 0 not upgraded. Do the parent directory's permissions matter when accessing a subdirectory? What's the best way to get the last N elements of a Perl array? How to make itemize/enumerate/description environment robust to missing \item elements? Is there any way to make LaTeX tolerate empty itemize/enumerate (i.e. no \item)?  Specifically, I would welcome any package/elegant hack that would gracefully "cancel" a list if no elements are found (instead of firing up a Latex Error).  Before jumping to the obvious answer (which I expect would be something along the lines of "don't use itemize if you don't have items to put in" ;)) please consider my use-case:   I want to format remotely stored elements (say, bibliographic items), which I can only access as an XML file.  &lt;elems&gt;   &lt;bibelem&gt;&lt;title&gt;Cool result 1&lt;/title&gt;&lt;author&gt;joe&lt;/author&gt;&lt;/bibelem&gt;   &lt;bibelem&gt;&lt;title&gt;Cool result 2&lt;/title&gt;&lt;author&gt;jim&lt;/author&gt;&lt;/bibelem&gt; &lt;/elems&gt;  I have a python script that downloads/parses the XML and outputs its content in a file bib.tex as a list of Latex macros-decorated data  \BibElem{Cool result 1}{joe} \BibElem{Cool result 2}{jim}  Now, I want to grant the end-user complete control over the styling of her/his produced document, so the intended usage within Latex is something like  \documentclass{article} \begin{document}   \newcommand{\BibElem}[2]{\item {\em #1} by {#2}}   \begin{itemize}     \input{bib.tex}   \end{itemize} \end{document}    The rationale behind this design choice is that the user should be restricted as little as possible in her/his styling choices. For instance, the user may either want to display the bibelems within a list as shown in the example, or may prefer a fancy-formatted tabular. On the other hand, the user should design the latex document once, and should be able to run it regardless of the amount of data produced by the source.  Therefore, the python script cannot make any assumption regarding the context in which its latex product will be included, and it should be up to the user to deal with empty bibliographies, i.e. with empty lists. How could one possibly do that?  Update: Werner proposed a nice solution that redefines the list environment to make Latex oblivious of the fact he is currently in a list. However, this only seems to work if the empty list is the last list in the document, as revealed by the following mwa:    \documentclass{article} \makeatletter \newenvironment{myitemize}   {\itemize}   {\@newlistfalse\enditemize} \makeatother \begin{document}   % Empty Itemize   \begin{myitemize}   \end{myitemize}   % Next non-nested itemize environment (can be itemize/enumerate/description)    \begin{myitemize}     \item Arghh!   \end{myitemize} \end{document} What is a primary decomposition of the ideal $I = \langle xy, x - yz \rangle$? Given the ring $k[x,y,z]$, where $k$ is a field, and an ideal $I=(xy,x-yz)$, find a primary decomposition of $I$.    I tried to draw the graph of the variety of $I$ and get a decomposition of $(x,y)\cap(x,z)$ (the two prime ideals corresponds to the irreducible components of the variety), but apparently these two ideals are not the primary decomposition of $I$, and I don't know how to fix this.  I would really appreciate it if someone can help me. thx How do I disable the guest session? How do I disable the guest session in Ubuntu 11.10 or higher? I don't want people to be able to use my computer without using a password to log in! Optional argument to \item I am typesetting an ordered list where the entries may appear out of order, but should be assumed in order otherwise. I don't want to have to jump through \setcounter hoops to do this. That is, I want something like  \begin{enumerate}   \item First   \item Second   \item[8] Eighth!   \item Ninth!   \item[4] Fourth \end{enumerate}   to give the following Good output, instead of the Bad output:    A minimum working example follows.  \documentclass{article} \usepackage{enumitem} % preferably something compatible with this guy \begin{document}  Good:  \begin{enumerate}   \item[1.] First   \item[2.] Second   \item[8.] Eighth!   \item[9.] Ninth!   \item[4.] Fourth \end{enumerate}  Bad:  \begin{enumerate}   \item First   \item Second   \item[8] Eighth!   \item Ninth!   \item[4] Fourth \end{enumerate}  \end{document}   It should be noted that I don't want to have to specify the period afterwards, in case my list using a different numbering, e.g. Roman. Compatibility with enumitem is preferred, but not required.  What is the correct way of going about this? $y_{2n}, y_{2n+1}$ and $y_{3n}$ all converge. What can we say about the sequence $ y_n$? My friend and I are currently debating the following question:      Let $y_n$ be a sequence in a metric space and assume that the subsequences    $y_{2n}$, $y_{2n + 1}$, and $y_{3n}$ all converge. What can we say about the sequence $y_n$?    To me it seems that all the subsequences will converge to a limit say $y$. Then any term in the original sequence will be in one of these subsequences, it follows that the entire sequence $y_n$ converges to $y$.  I let $\varepsilon &gt; 0$. Since $y_{2n}$ converges to $y$ there exists an index $2N$ such that $d(y_{2n},y) &lt; \varepsilon$ for $2n \geq 2N$, and since $(y_{2n+1})$ converges to $y$ there exists $2M + 1$ such that $d(y_{2n+1}, y) &lt; \varepsilon$ for $2n + 1 \geq 2M + 1$.  Let $m \geq \max\{2N,2M+1\}$. If  $m$ is even, since $m\geq 2N$ we have $d(y_m,y)&lt;\varepsilon$; if $m$ is odd, since $m\geq 2M+1$ we have $d(y_m,y)&lt;\varepsilon$. Thus $d(y_m,y)&lt;\varepsilon$ for any $m \geq \max\{2N,2M+1\}$, and we conclude that $(y_n)$ converges to $y$.   However, my friend does not think that this is completely correct because I didn't use the $y_{3n}$ in the proof. I think he is right, that I do in fact need it, but I am unsure of how to add it in. All in all, I think that since any term in the original sequence will be in one of these subsequences, it follows that the entire sequence $(y_n)$ converges to $y$.  $2n+1$ covers all the odd terms and $2n$ converse all the even terms, so is $3n$ even needed? I would like to use it since the proof has it in the question, but I am unsure of what to do. Could someone kindly help me construct this proof in a better manner,and is my line of thinking correct? Thank you! I cannot make xmodmap run on login in Ubuntu 13.04. I have searched around, including in askubuntu and all answers I found do not work.  I have a file named .Xmodmap in my home folder which contains the desired mappings. If I run it manually it works fine, so there is no error there. In order to make it run on startup, I have tried:     Using various .xinitrc containing one of the following commands:      xmodmap .Xmodmap xmodmap ~/.Xmodmap   /usr/bin/xmodmap /home/NAME/.Xmodmap if [ -s ~/.Xmodmap ]; then xmodmap ~/.Xmodmap fi  Using .Xresources instead of .xinitrc with the same variations. Setting it as a startup application.   None of the above works in Ubuntu 13.04 (64-bit). I also saw a few ideas about globally changing the keyboard mappings, but most of them were not applicable in Ubuntu 13.04 (i.e. the corresponding files did not exist where specified) and I prefer not to touch the global settings anyway. Proof that two spaces that are homotopic have the same de Rham cohomology I know this is true, but how do I prove it? Specifically, I'm trying to calculate the de Rham cohomology of the 3-sphere by using the Mayer-Vietoris sequence and covering $S^3$ with two hemispherical sets $U, V$, such that $U$ intersects $V$ in a "2-band", an equatorial band homotopic to a 2-sphere. ''More than one row returned by a subquery used as an expression'' postgres error Dictionary application needs to download dictionary "Apple Dictionary" before use Use early 2009 20" iMac as external display for 2015 rMBP I have imported a mesh (AutoCad DXF) and I'm experiencing strange shading behavior. I've done the following to try and address the problem with no luck:  Recalculate Normals Remove Doubles Delete Loose Geometry Cleared Seam, Sharp, and Bevel Weights  There are no modifiers on the mesh.  The original imported mesh looks fine in smooth shading but I need the mesh to be in quads which causes the shading to mess up as shown in photo. I can add my .blend file but I'm not sure how to do that. Are Love Potions legal? Padding a number in a filename to a fixed length I have a directory of files such as:  file.1.png file.2.png … file.10.png … file.1000.png file.1001.png …   How can I pad the number to 4 digits? It should end up like this:  file.0001.png file.0002.png … file.0010.png … file.1000.png file.1001.png … SELECT DISTINCT on multiple columns Supposing we have a table with four columns (a,b,c,d) of the same data type.  Is it possible to select all distinct values within the data in the columns and return them as a single column or do I have to create a function to achieve this? Adding curved features to map with ArcGIS API for JavaScript? I've tried without much success to add a curved line feature to the ArcGIS JavaScript map.    I created a polygon with a curved edge in ArcMap:   However, when I load this same feature in the web API, it becomes segmented:   The problem started when I tried to create a curved feature from the JavaScript API itself, which only seems to allow full circle features (not circular arcs).  This makes me think that curves are still unsupported in the JavaScript API. Do you know any way around this? Do you have any other ideas on alternatives I can use to create and correctly view curved features?