change default username when ssh to another pc When I ssh between different pcs I can omit my username (tom) and just type   ssh pc_name   instead of   ssh tom@pc_name   I like this feature, and have got into the habit of using it.  Unfortunately, on one of my computers I went for the user name tommy.  Everytime I connect to this computer I forget to write tommy@creative_pc and wonder why my password doesn't work.  Is there a way to tell ssh what user name to use when the username is omitted?  Edit: Just found the following question that is similar:   It didn't come up on my initial search.
How to make ssh log in as the right user? I use ssh on a variety of machines, mainly linux. Accounts on these machines vary in naming scheme: if my name is First Last, then I have accounts: first, flast, last_f, lastf, and sometimes I need to log in as root. For each machine I use, I would like the openssh client to know which account to use when I don't specify on the command line.  So the question is: How do I make ssh server Do The Right Thing when a username is not specified?
Update: Universal login is in place and considered &quot;done&quot;. If you see anything weird, please submit new bug reports.   As y'all know, our current flavor of &quot;global authentication&quot; leaves a few things to be desired. It's flaky, requires a page refresh, etc. etc. Wouldn't it be nice if you could just sign in once and be automatically logged in across the network?  We are ready to roll out Stage 1 of Project &quot;Make Authentication Suck Less&quot;. It is live as of a few minutes ago. What this means right now:  When you log into any Q&amp;A site on the stackexchange.com domain, you will be automatically logged into all other Q&amp;A sites on the stackexchange.com domain + stackexchange.com itself.   is excluded from this.   , , and other Q&amp;A sites with their own domains will still use the old flow.  We are going to recognize you in some ways on sites where you don't have a profile. This is still a work in progress, but most notably you will see &quot;join this community&quot; in the top bar instead of &quot;sign up&quot; and &quot;log in&quot;.   But I use multiple accounts! What do? We aren't intending to break the ability to run multiple accounts. The same guidelines as before still apply — we don't officially support that, you might end up with an accidental automatic merge if you're not careful with your credentials, any interaction between the accounts is right out, and so on. If you're already using different browsers or different browser profiles for your accounts, nothing will change for you. If you are somehow logged into multiple accounts in the same browser... I'm sorry to say, but that's a bug even for our current global auth setup. You will now only be able to log into one at a time, and you'll need to log out when you want to switch. (Or start using different browsers.) What's next:  Remember  we tested a few months ago? It's coming back. Stage 2: bring other domains into the fold (this is also live now) Stage 3: make cross-domain experience smoother and support browsers that reject third-party cookies in all conditions (looking at you, Safari) - this is not currently feasible. Safari users and users who reject third-party cookies will need to sign in separately to every second-level domain (e.g. stackexchange.com, stackoverflow.com, etc).  If you see any issues… Good luck, because you probably can't log in to report them here. =) But seriously, let us know via the contact form linked at the bottom of any page. If you are able to log in, report issues here on meta as normal. So, in conclusion… How to Screen Sharing / VNC to an iMac without waking the display? I have an iMac mid 2011 at home. When I was not home, I may need to access my mac with Screen Sharing. However the iMac display will turn itself on when I connect via Screen Sharing. The problem is I don't want to scare my family at home (with the elders and kids) as the iMac "turn itself on suddenly".   This is a problem specific for iMac. On MacBooks (Pro, Air, whatever) I can set the brightness to the lowest setting so the screen is black (i.e. the LED light is off). However on an iMac you cannot turn off the LED backlit by setting brightness. The display is still bright and everything is clearly visible even on lowest brightness setting.  Therefore these solution are not working as the display will turn on as soon as you move your mouse or hit any key on the keyboard via Screen Sharing.   Sleep Display (by Ctrl+Shift+Eject) Using the code listed on    Question: Is the a way to keep the iMac display off entirely while you accessing it with Screen Sharing? When is a clause not essential? I am having trouble figuring out when to use commas to set off &quot;nonessential&quot; information.  Sometimes it's obvious:  Bob, who is thirty years old, is an alcoholic.  But other times I'm not sure:  The day he quits drinking * he will start a llama farm He has his heart set on owning El Duderino ranch * in New Mexico.  In the first case, my ear says that there should be a comma at *, even though information before it seems essential to me.  In the second case, the stuff after * is not essential, and yet it seems a little much to use a comma. Even that last sentence I wrote confuses me.  &quot;In the second case&quot; seems essential but I used a comma.  Is this correct? Does it depend on personal style and the length of the clause?  Or perhaps I'm misinterpreting the meaning of &quot;essential&quot; in this context? Is any UFD also a PID? Add AD users to sudo group not working | CentOS 6.7 I would like some help with this exercise.  Suppose that $f_1,\ f_2 \in V^*$ and that $\text{Ker} f_1 = \text{Ker} f_2$. Show that $f_1 = k f_2$ for some scalar $k$.  I expect your suggestions.  Thanks! What happens to Jen when she jumps off the cliff? What happens to Zhang ziyi (Jen) in  when she jumps off the cliff .. she dies? becomes immortal? Just before jumping what does she want Lo to become - a master?  Why does she jump off, guilt? Android 5.0 (Lollipop) was officially announced on October 15th, 2014.  You can review the high-level changes at the  and the announcement on the official .  Of course, not all devices will get this update right away and others won't get it at all. Each manufacturer and carrier often choose to add their custom modifications which tend to delay the official release.  When will each device get Android 5.0, either officially or unofficially, if ever?  See also: I am currently looking for a website or a tool that would allow me to compare the package state of a particular software in different Linux distributions.  For instance, which version of gimp is provided by Mint, Ubuntu, Debian Sid and Fedora 18?  An immediate interest would be to be able to avoid reinventing the wheel when packaging software (for instance re-use patches from other distros). How to disable the skype ads (advertisement)? efficient and accurate approximation of error function I am looking for the numerical approximation of error function, which must be efficient and accurate. Thanks in advance $$\mathrm{erf}(z)=\frac2{\sqrt\pi}\int_0^z  e^{-t^2} \,\mathrm dt$$ If $x_1,x_2,\ldots,x_n$ are the roots for $1+x+x^2+\ldots+x^n=0$, find the value of $\frac{1}{x_1-1}+\frac{1}{x_2-1}+\ldots+\frac{1}{x_n-1}$ Let $x_1,x_2,\ldots,x_n$ be the roots for $1+x+x^2+\ldots+x^n=0$. Find the value of   $$P(1)=\frac{1}{x_1-1}+\frac{1}{x_2-1}+\ldots+\frac{1}{x_n-1}$$   Source: IME entrance exam (Military Institute of Engineering, Brazil), date not provided (possibly from the 1950s)  My attempt: Developing expression $P(1)$, replacing the 1 by $x$, follows $$P(x)=\frac{(x_2-x)\cdots (x_n-x)+\ldots+(x_1-x)\cdots (x_{n-1}-x)}{(x_1-x)(x_2-x)\cdots (x_n-x)}$$    As $x_1,x_2,\ldots,x_n$ are the roots, it must be true that   $$Q(x)=(x-x_1)\cdots(x-x_n)=1+x+x^2+\ldots+x^n$$ and  $$Q(1)=(1-x_1)\cdots(1-x_n)=n+1$$ Therefore the denominator of $P(1)$ is  $$(-1)^{n} (n+1).$$ But I could not find a way to simplify the numerator.  Another fact that is probably useful is that  $$1+x^{n+1}=(1-x)(x^n+x^{n-1}+\ldots+x+1)$$ with roots that are 1 in addition of the given roots $x_1,x_2,\ldots,x_n$ for the original equation, that is  $$x_k=\text{cis}(\frac{2k\pi}{n+1}),\ \ k=1,\ldots,n.$$  This is as far as I could go...    Hints and full answers are welcomed. Resources for Blender Since asking for tutorials, videos, resources, links to other content or downloads is considered off topic here, this is a specifically created Community Wiki which gathers resources for Blender and it has been approved by the .  Just write in the appropriate answer/section. If you have concerns, questions, post a  question, so we don't clutter the comments, but you can link your meta question from the comments.  Questions regarding such resources are not allowed anymore, except for very specific and on topic requests (ask on  if you're unsure about your question). Follow the instructions made in the question about how to post, what can be posted, etc.  Learning             Assets    (also see: )   Reference Images/Blueprints (also see: )    Tools    (also see: )      Other   Special Interest ()     Also see the . Is there a drupal.org API for retrieving the list of available modules? Grub not loading after Windows 8 Install Western Digital drive making beeping noise The website I'm working is allegedly going to have a massive hit rate soon after launch. The client is talking about the possibility  of around 2500 hits per second over a day or so.   Ignoring the fact that this hit rate is probably wild client optimism and apart from getting the largest servers possible, what is the best way that Drupal should be configured to support a large hit rate.  I've read Scaling the , ,  and many other pages, but what I'm looking for is real experience of doing this, what works, what doesn't, and what to expect. Regex: match everything but specific pattern I need help finding the set of continuous functions $f : \Bbb R \to \Bbb R$ such that for all $x \in \Bbb R$, the following integral converges:  $$\int_0^1 \frac {f(x+t) - f(x)} {t^2} \ \mathrm dt$$  I think it might be the set of constant functions but i havent been able to prove it :(   I was thinking that you can use the stone weiestrass theorem considering the set of continuous functions on a closed  interval(non trivial) ,and a subset which contains the set of continuous functions whose integral above diverges in some point in that interval along with  with the set of constant functions. So in order to solve the problem i need only to prove that if two functions do not meet the condition of the problem then their product does not as well .  I hope you can provide some insight and thank you . How do I assign a value to a whole array of integers?