I watched a movie when I was little about a boy who was abducted by an alien (maybe by choice I'm not sure) but while he was abducted, they sent an alien or robot version of himself to take his place so his family did not know. I also remember a part where the brother of the abducted kid saw the robot/alien version of his brother at night and the alien/robot was fixing his wiring inside of his head or something and he told the brother that it was all a dream and to go back to sleep. I think that the alien place that the boy was in was like an all-white building with stars or something outside and I think one of the alien people had red or green hair. I think it is an 80s or 90s movie but not positive.
In the comedic music video  there are many clips of vintage scifi films, some of which I recognize.  This one however, of a large blue floating holographic head talking to some kind of military installation does not look at all familiar.  Does anyone recognize this film?
How can one change an entire document to use bold font? I see many posts in how to changes the font and font size, but none for changing the default font for a document to bold font. I believe this is called changing the font series. The approach in  (obtained by random Googling) looks like it should work, but doesn't do anything when I stick it in the preamble. Maybe I'm putting it in the wrong place.  \fontencoding{T1} \fontfamily{garamond} \fontseries{m} \fontshape{it} \fontsize{12}{15} \selectfont   There is also some discussion . How do I parse command line arguments in Bash? Say, I have a script that gets called with this line: ./myscript -vfd ./foo/bar/someFile -o /fizz/someOtherFile  or this one: ./myscript -v -f -d -o /fizz/someOtherFile ./foo/bar/someFile   What's the accepted way of parsing this such that in each case (or some combination of the two) $v, $f, and  $d will all be set to true and $outFile will be equal to /fizz/someOtherFile? In Finder when I type something in the textbox the default is to search the whole mac in the contents of the files. I was able to change the default to search the current directory, but didn't see an option to change search for contents to search for file name. How can that be changed? Can't Use /Summon Command Recently I've been messing around with making a few minigames, and have used a few plugins to help make it easier to create and run them. However, a newer one I'm making requires me to use the /summon command in order to spawn zombies. However, no matter what I put in, I can't spawn hostile mobs. All other entities still spawn perfectly fine. Strangely, the /spawnmob command which comes with Essentials can summon hostile mobs fine. I would rather use /summon since it's more customizable though. Here's a list of plugins I have installed.   Essentials EssentialsChat HolographicDisplays PermissionsEx setspawn [A plugin I have made, just a simple timer] Vault VoxelSniper WorldEdit WorldGuard   Please let me know if you have any ideas on what I'm doing incorrectly or isn't functioning the way it should. Should confidence intervals for linear regression coefficients be based on the normal or $t$ distribution? Replacing fonts in EPS/PDF files Exterior power "commutes" with direct sum I know that for vector spaces $V, W$ over a field $K$, we have the following identity :  $$ \bigoplus_{k=0}^n \left[ \Lambda^k(V) \otimes_K \Lambda^{n-k}(W) \right] \simeq \Lambda^n(V \oplus W) $$ which holds in a canonical way : for $0 \le k \le n$, the maps  $$ \Lambda^k(V) \times \Lambda^{n-k}(W) \to \Lambda^n(V \oplus W), \\ (v_1 \wedge\cdots \wedge v_k,w_{k+1} \wedge \cdots \wedge w_n) \mapsto (v_1 \wedge \cdots \wedge v_k) \wedge (w_{k+1} \wedge \cdots \wedge w_n) $$ factors through the tensor product's universal properties, which gives us a map $\varphi_k : \Lambda^k(V) \otimes_K \Lambda^{n-k}(W) \to \Lambda^n(V \oplus W)$, and since the category of $K$-modules has biproducts, we get a canonical map  $$ \varphi = \bigoplus_{k=0}^n \varphi_k : \bigoplus_{k=0}^n \left[ \Lambda^k(V) \otimes_K \Lambda^{n-k}(W) \right] \longrightarrow \Lambda^n(V \oplus W) $$  What if I replace $K$ by a (commutative ring with $1$) ring $A$? Does this map have a kernel? I know it is surjective (it suffices to "look at it", i.e generators of the codomain are obviously all hit by $\varphi$). I don't know if it helps, but I am working in integral domains. In the field case, this is obvious if $V$ and $W$ are finitely generated, since one can use dimension arguments. I wouldn't mind if the above identity held only in the finitely generated case either. If it worked in general it would be cool though.   Note that when trying to compute the inverse map with the universal property, there seems to be a problem... my guess would have been $$ (v_1 + w_1,\cdots,v_n + w_n) \mapsto \bigoplus_{k=0}^n (v_1 \wedge \cdots \wedge v_k) \otimes (w_{k+1} \wedge \cdots \wedge w_n) $$ and this map is obviously $A$-multilinear, but there is a problem with the alternating property ; I get some terms left. I'm guessing this is the wrong map... if there is one. I have to travel to Germany and Switzerland for business purpose. I have already been here 2 years ago. I have applied for business visa to the German consulate twice and both times the application got rejected. They have put a green stamp on the last page twice. The reason is the purpose and information submitted regarding intended stay is not reliable. I have submitted the documents to Swiss consulate and they have accepted and granted me a visa. Now I have to first travel to Germany and then to Switzerland.  So my question is, with a Schengen business visa granted by Switzerland, may I enter in Germany? Does the rejection stamp has any impact for entering at German airport ? Does it mean I cannot travel to Germany but to other Schengen countries ? Find the limit of $\frac{n^{x}}{(1 + x)^{n}}$ Let $x&gt;0$. Find $$\lim_{n\to\infty}\frac{n^{x}}{(1 + x)^{n}}.$$   What I was thinking involved an inequality, by reason of considering the fact that  $$(1 + x)^{n} &gt; C(n, k) x^{k}$$ for some $k$ such that $n&gt;k$. Expanding the binomial coefficient and taking the $n$ common from each bracket, we have something like $$(1 + x)^{n} &gt; C(n, k) x^{n} &gt; \frac {x^{k}n^{k}}{k! 2^{k}}.$$ But now, I am totally clueless. By intuition, I know that the limit has to be zero, so I just want to prove using the concept of inequalities that what I thought was the right approach (being the sandwich theorem). Any help would be appreciated! Understanding how an ETF works I am trying to fully understand how ETFs work. For the sake of simplicity, let us restrict ourselves to physical replica ETFs. Let us suppose that an ETF follows an index which tracks three stocks: Alice Enterprises (A), Bob Industries (B) and Charlie's (C). We want to invest 1000$. The prices of each individual stock are 100$ (A), 10$ (B) and 1$ (C). The index weights at this moment are 60% (A), 30% (B), 10% (C). If I am not mistaken, when we buy a fund tracking this same index, the fund manager will automatically buy 600$ of A, 300$ of B and 100$ of C. Now, if we buy an ETF the underlying process is unclear to me. I understand the concepts of authorised participant and NAV spread. If A increases its value to 110$, authorised shareholders will first withdraw shares of A from the ETF and sell those shares, and then they will buy the ETF, pushing the ETF price upwards. This way the ETF price is automatically regulated and the authorised shareholders earn a profit. Everybody is happy. In contrast to a fund, when we buy an ETF we are not generally buying ETF shares from the ETF manager. Instead, we are buying ETF shares from another investor. Therefore... as I understand it, no new shares are really bought. And thus, following the process above, if we buy the ETF we push its price upwards. This again creates a &quot;gap&quot;, this time the price of the ETF is momentarily higher than its underlying assets and, therefore, authorised shareholders will sell ETF shares and buy shares of A, B and C. So... an ETF manager only buys a fixed amount of shares when the ETF is created? I want to know if I am correct in this reasoning about how the basics of physical ETFs work. I have tried to keep things as simple as possible. I understand that there will be lots of quirks and quincks, and it is great if these are elaborated in the answers. Which indefinite article should precede hour — a or an?        an hour     a hour      Does the usage of an vs a depend on the pronunciation — a history, a hobby, but an hour, an honor? Transferring a Windows 8 license and proper un- and reinstallation Long story short  I have two computers: a laptop and a desktop computer. Both have Windows 7 on them.  I buy the Windows 8 Pro upgrade. To see if it screws up anything, I install it on my laptop as a guinea pig. I intend to use Windows 8 for my main computer, my desktop, but I want to test it on the laptop, so I know I don’t risk losing access to my desktop and the data on it. I never use my laptop, and only used it, because it already has a Windows 7 installation on it.  The problem  At some point, I must have entered the license key on my laptop, because when I go to the activation screen on my desktop, I get this:    Uh-oh. I can’t use the key on my desktop. Now how the hell do I transfer the key from my laptop to my desktop computer?  Answers and suggestions so far  Let’s just say that I tried everything possible to get some answers on this matter. The best response I got from Microsoft is this:     To install Windows 8 on your desktop, do the following:         Uninstall Windows 8 on your laptop   Afterwards, install Windows 8 on your desktop   If it won’t activate, call product activation at (...)      I am not a fan of that last point. The error message does allude to such a solution, however:     If you’ve reinstalled Windows or made changes to your hardware recently, you may be able to use your current key.   The question  My main question is this: has anyone been in a similar situation, and if so, what did you do to resolve this?  Failing that, what is the proper way to   uninstall the Windows 8 installation on my laptop, and reinstall the Windows 8 installation on my desktop?   Ad 1  I have already tried using the “reset” feature on my laptop, but that only resulted in a new Windows 8 installation that was already activated. But which is the right way to uninstall the installation in a way that allows me to use the license key on the desktop computer?  Ad 2  Which is the proper way to reinstall the Windows 8 installation on my desktop computer? Why do I even have to reinstall it in the first place?  I won’t get around to do this, until my USB key with 3.0 support arrives in the mail, but it is going to be a while, until I find a assuaging response to the best way to go about this anyway. the weak form of 'on' I am confused at whether or not there is a weak form at preposition's 'ON'. I've checked at some dictionaries at Cambridge and Oxford dictionary, they don't mention on the weak form's pronunciation. However, I, am a Japanese, checked at English-Japanese dictionaries, they mention on the weak form as /ən/.  For example, is there the difference of pronunciation between 'It goes on' and 'There is an apple on the table' in connected speech?  Does it exist?  Thanks Yuichi  *It's Edited Linear transformations map lines to lines I need help with this question:  Let $T$ be a linear map from $\mathbb{R}^n \to \mathbb{R}^m$, and let $L$ be a line in $\mathbb{R}^n$. Show that $T(L)$ is also a line (is it not enough to just consider lines in the plane). Say $X_1, X_2, \ldots, X_n$ are independent and identically distributed uniform random variables on the interval $(0,1)$.  What is the product distribution of two of such random variables, e.g., $Z_2 = X_1 \cdot X_2$?  What if there are 3; $Z_3 = X_1 \cdot X_2 \cdot X_3$?  What if there are $n$ of such uniform variables? $Z_n = X_1 \cdot X_2 \cdot \ldots \cdot X_n$? Let $R$ be a commutative ring and $A=\{1,a,a^2,\dots\}$ for some $a\in R$. Prove that $A^{-1}R$ is isomorphic to $R[T]/(aT-1)$.    I guess I'm meant to find a surjective homomorphism between $A^{-1}R$ and $R[T]$ and then use first isomorphism theorem. What homomorphism should I use? How can I prove that the additive group of rationals is not isomorphic to a direct product of two nontrivial groups? I am working through Paolo Aluffi's new GSM text on my own (self-study). On page 63, he asks the reader to     Prove that $\Bbb{Q}$ is not the direct product of two nontrivial groups.   For some context, this is an exercise following a section entitled "The category Grp".  I am assuming that he means "is not isomorphic to the direct product of two nontrivial groups", and I can see two possible ways to proceed with this proof, but have been unsuccessful with either approach.    Approach 1:  Show that the additive group of rationals has a property that is preserved by isomorphism that the direct product of two nontrivial groups does not have or vice-versa.  This seems challenging unless I can significantly narrow down the properties that a direct product of two nontrivial groups that was isomorphic to $\Bbb{Q}$ would necessarily have.  Approach 2:  Considering the section in which this question occurs, show that if $G$ and $H$ are nontrivial groups and $\Bbb{Q} \cong G \times H$, then there are homomorphisms $\varphi_{G}:\Bbb{Q} \rightarrow G$ and $\varphi_{H}:\Bbb{Q} \rightarrow H$ which do not factor or do not factor uniquely through the product $G \times H$.  This would be a contradiction, as $G \times H$ is a final object in the category Grp.  I would greatly appreciate suggestions on how to proceed further with either of these approaches or with alternate approaches. As the question title suggests, how do I see that every left ideal of a square matrix ring over a field is principal? Travelling as unmarried couple in Dubai I'd wish to visit Dubai with my girlfriend, but after reading  and  I started to get a little worried about it. How should I book an hotel? Must I book two singles? Could it be a problem if we walk together in the city and go together to restaurants and malls without being married? I have a website running in English and Japanese and the default language is Japanese.  What are the advantages of one over the other solution:   Solution 1. When accessing example.com, you will see only Japanese. When accessing example.com/en, you will see only English. Solution 2. When you access example.com, it will redirect you to example.com/ja, where you will see only Japanese. English site is still example.com/en.