Outlook with existing data files I reinstalled my computer and I did a back up of the Outlook pst data files. Now I installed Outlook and added my email account. I told it to use the existing data file.   Then it started to download the messages. It downloaded the same messages from the server again!  I use POP3 but I have set it to keep the messages on the server, because I have multiple computers so I need to access the messages everywhere. I don't want to use IMAP, because then it requires an Internet connection to get the emails.  How to get it working?
Outlook, POP and PST handling Essentially I have a client who is on hosted exchange and have decided to use POP3 to download the mail (I don't know why they don't use .OST's but anyway), they rebuilt the machine and backed up their .PST file. Now their Outlook was configured to keep mail downloaded on the server for 14days.  Essentially their current PST is fairly complex, many folders and sub folders and so on. So what is the best way to handle it really - create a new Outlook profile on the rebuilt machine and download the mail via POP into a new .PST then just recreate the folders in the new pst and drag and drop the mail via attaching the backed up .pst, recreating the folders etc?  But is their an easier way to do this, maybe pointing the new account to use the original PST, but then that would download all the mail again from the server to that .PST file.  Any ideas on the best way to handle POP3 account rebuilds from scratch when you have a backed up PST?
In Inkscape when I apply a dash stroke, then set a mid marker shape, it does not show anything. What are the minimum requirements to run Windows 10? You "show" someone a picture. You "---" someone a song? In , we have a verb meaning &quot;to show&quot; corresponding to &quot;to see/to look&quot;, and we have a different verb corresponding to &quot;to hear/to listen&quot;:  inti tara stampa (you look at a picture.) ---- jiena nurilek stampa (I show you a picture) inti tisma' diska (you listen to a song.) ----- jiena nsemmagħlek diska (I 'show' you a song)  In English, do you &quot;show someone a song&quot; (sounds weird to me) or is there a verb that corresponds more directly to the Maltese insemmgħek? The screen of my phone is physically broken, so it doesn't display anything, but the touch aspect does seem to be working, as I can unlock my phone, and get haptic feedback.  Before I go to get it replaced, I'd like to back up some personal data from the built-in memory to the SD card. I'm fairly certain that if I can get adb to recognize the device, then I can use  to see where I am touching the screen and do what I need to do. Problem is, when I plug it in, it's not recognized, while my emulator is.  I suspect that I might not have USB debugging enabled, which I think is necessary for adb to work. If this is the case, can someone give me screenshots of their Droid X (running 2.3.X) going from the home screen, through all the menus, to activating debug mode? Hopefully I can do it by dead reckoning and adb from there.  Edit: I haven't changed anything about the ROM or launcher; it's all stock. I'm trying to solve a question where I need to write $\frac {1}{1+z^2} $ as a power series centered at $z_0=1$  I'm not allowed to use taylor expansion. So my first thought was to rewrite the function in a form where I can apply the basic identity:  $$ \frac{1}{1-x} = \sum_{n=0}^\infty x^n $$  So let's rewrite the original function $f(z) = \frac {1}{1+z^2} $ and use above identity:  $$\frac {1}{1+z^2} = \frac {1}{1-(-z^2)} $$ But observe that I need to center it at $z_0=1$ so I rewrote it to:  $$\frac {1}{1-(-z^2)}=\frac {1}{2z-(-(z-1)^2)} $$  I can factor out $\frac {1}{2z}$ and use the basic identity to get : $$\frac {1}{2z}\frac {1}{1-\frac{(z-1)^2}{2z}} = \frac {1}{2z}\sum_{n=0}^\infty \left(\frac{-(z-1)^2}{2z}\right)^n =\frac {1}{2z}\sum_{n=0}^\infty \frac{(-1)^n(z-1)^{2n}}{(2z)^n} = \sum_{n=0}^\infty \frac{(-1)^n(z-1)^{2n}}{(2z)^{n+1}}$$  The problem is if I ask wolfram alpha: power series$ \frac{1}{1+z^2} $centered at z = 1 it will give me a different answer that doesn't match the sum I found.  Can anyone help me figure this one out? What am I doing wrong? Winter is Coming It's my understanding that the phrase "Winter is Coming" is the motto of the Stark house, when the story first reaches the wall it's implied that the winter is not a periodic season like it is in our world.  Does the winter refer to a particularly severe season or does a winter only occur every few years? Longtable: page breaks within row possible? I am editing a longtable. Some of my cells contain a lot of text. Page breaks seem to happen only where table rows end/begin. I'd like, however, for the rows to span pages; it's fine with me if, for example, the first few lines of a row are at the end of one page and the rest of the row's lines are on the next page. How to prove $ \prod_{d|n} d= n^{\frac{\tau (n)}{2}}$ Regex for numbers only I haven't used regular expressions at all, so I'm having difficulty troubleshooting. I want the regex to match only when the contained string is all numbers; but with the two examples below it is matching a string that contains all numbers plus an equals sign like "1234=4321". I'm sure there's a way to change this behavior, but as I said, I've never really done much with regular expressions.  string compare = "1234=4321"; Regex regex = new Regex(@"[\d]");  if (regex.IsMatch(compare)) {      //true }  regex = new Regex("[0-9]");  if (regex.IsMatch(compare)) {      //true }   In case it matters, I'm using C# and .NET2.0. Start ubuntu without a desktop environment but start an X application I want to do a small computer just for internet browsing. I dont want to load a desktop environment to keep RAM, CPU and GPU ussage as low as possible. The computer is going to run on a ARM CPU. I dont care with Distro I use, I thought about good old plain Debian. When should I create a new tag? How do I request a new tag if I don't have enough rep? PS4 Controller not connecting to PS4 and won't reset? Why don't metals bond when touched together? It is my understanding that metals are a crystal lattice of ions, held together by delocalized electrons, which move freely through the lattice (and conduct electricity, heat, etc.).   If two pieces of the same metal are touched together, why don't they bond?   It seems to me the delocalized electrons would move from one metal to the other, and extend the bond, holding the two pieces together. If the electrons don't move freely from one piece to the other, why would this not happen when a current is applied (through the two pieces)? Is being a Cauchy sequence equivalent to $ \lim_{n\to+\infty}d(x_{n+k},x_n)=0$ for every $k$? Is this statement true?      In a metric spase $(E,d)$, a sequence $(x_n)$ is Cauchy if and only if $  \forall k\in \mathbb{N}, \lim_{n\rightarrow+\infty}d(x_{n+k},x_n)=0$   I proved that $\Rightarrow$ is true,indeed if $(x_n)$ is Cauchy then for all $\varepsilon&gt;0,\exists n_0\in\mathbb{N}, \forall p,q\geq n, d(x_p,x_q)&lt;\varepsilon$ it still right for all $ n\geq n_0$ and $m=n+k&gt;n\geq n_0$   But I don't know if $\Leftarrow$ is true ? Change templates in Xcode How would I change the initial templates created by Xcode when creating a new Cocoa Class.  I am referring to the comments and class name created when using Xcode's new class wizard. Crontab entry executing every hour IANAL et al. is usually the start of answers to [legal] questions on any SE site (e.g. ). You usually end up with personal opinions which sound sensible and the accepted answer is often the one closest to the OP's hopes. But it's probably often not correct. I know the situation can be rather complicated and even differ by location, but it would be really helpful if the SE team were providing official lawyers (indicated maybe by using a § in the username, forbidden for everyone else, just like the mod ♦) to provide some orientation that one could actually rely on beyond much doubt... Technical term for associating a group with the actions of a few List all files in all subfolders $(n^2 - 1)!$ is a multiple of $(n!)^n$ Question: Find all positive integers $n$ such that $(n^2 - 1)!$ is a   multiple of $(n!)^n$.   I can show that the required condition fails if $n$ is a prime, and by direct computation, it also fails for $n=4$. After doing a few small examples by hand, I believe that the required answer is 1 and all composites greater than 4. However, I cannot seem to prove this.  For each prime $p&lt;n$, I tried to count the number of appearances of $p$ on both sides, but I get that I am supposed to compare $n(\lfloor{\frac{n}{p}} \rfloor + \lfloor{\frac{n}{p^2}} \rfloor +\dots)$ against $\lfloor{\frac{n^2-1}{p}} \rfloor + \lfloor{\frac{n^2-1}{p^2}} \rfloor + \dots$, which is not obvious to compare.  Any help will be gretaly appreciated.