After years on a much older version of Mac OS, I'm now on v. 10.13.2, and I observe strange behavior when I use find functionality, in various applications.   If I search for some string in one application, when I open the search interface in another application, the same string auto-populates the search field.  It happens even when the search string is not in the clipboard, so it isn't just that the clipboard is autopasting — there's an actual transfer of the search string across applications. Affected applications include current versions of BBEdit, NisusWriter, Chrome, Firefox, the built-in Dictionary, Terminal — so I assume it's happening at the level of the operating system.  This is intrusive and unwelcome default behavior, and I'd like to know how to turn it off. I see some unanswered questions about the same issue here and there (for instance, , ).
On my MacBook Pro I have found that several applications seem to share the value for a find.  For example, I searched 'applestackexchange' in Safari's unified address bar, then I switch to Xcode and click into a Find field.  The first word of my search in Safari then appears there.  iTerm2 and Sublime Text 2 also seem to participate in this sharing.  Running latest Mountain Lion on  a 2012 MBP.
I'm reading .     The graph of $f: A \rightarrow B$ is the subset of $A × B$ consisting   of all ordered pairs $(a, b)$ with $f (a) = b$. If $A$ happens to be   $B^n$ for some $n ∈ N$, then we say that $f$ is a function on $B$ and   $n$ is the arity of $f$.   I don't understand the notation for the exponent of a set, I'm aware of what  is, it's the number of arguments or operands the function takes. I'm just not so sure if I can assume that a set with an exponent such as in $B^n$ means that a function has two operands.  I know the question may be too naive and perhapes the answer is the one I suggested and it's right in front of my face, I'm just searching for a confirmation or the negation of it. Thanks. What is Ubuntu's status on the Meltdown and Spectre vulnerabilities? Why is there a difference between urls submitted to a sitemap and urls in the google index? Is there any way to have BibTeX or biblatex insert a bibliography without having citations in the body of the document itself? Maybe a way to hide the in-text citations, so that BibTeX still sees them and includes them in the bibliography, but does not print them in the body? A more succinct expression for "The day before yesterday" Is there a more succinct expression for "the day before yesterday"?   In German for example, gestern = 'yesterday.' The prefix vor roughly means before, so logically, vorgestern means 'the day before yesterday.'   Similarly, morgen = 'tomorrow', the prefix über roughly means over, so again, übermorgen means 'the day after tomorrow.'  (In Mandarin Chinese also you have respectively 前天 &amp; 後天.)  Presumably, there are also similarly logical ways to say "the page after the next" or "the paragraph before the last", etc.   Are there no similarly succinct, and graceful, expressions in English? How to avoid having my father's down payment assistance get taxed as a gift Did regular Americans speak the way actors in the 30s and 1940s did? I watch a lot of old movies, and I've noticed that American actors of the 1930s and 1940s often spoke in a quasi-generic-posh-British accent.  Katherine Hepburn's accent would be the perfect example. It seems exaggerated, and I imagine it was not common off the stage and screen. What was that? Was it just an accent or was it a dialect? Did real people actually speak that way? I've just started to play with pgfplot. I'm trying to prepare a plot like to following   \begin{figure}[h] \centering \begin{tikzpicture} \begin{axis}[minor tick num=1,  axis x line=middle, axis y line=middle, xlabel=$k$, ylabel=$\omega$, ymin=0,xmin=-2,ymax=60] \addplot[blue,domain=0:5, line width=1.5pt] {x^2+25}; \addplot[orange,domain=0:5,line width=1pt]{3*x+22.75}; \addplot[cyan,domain=0:1.5, line width=1pt,dashed]{18.166*x}; \node[coordinate,pin=right:{$v_{\phi}=\frac{\omega}{k}$}]     at (axis cs:1,17) {}; \node[coordinate,pin=right:{$v_{g}=\frac{d\omega}{dk}$}]     at (axis cs:2.5,30) {}; \node[coordinate,pin=left:{dispersion relation}]     at (axis cs:4.5,47) {}; \end{axis} \end{tikzpicture} \caption{Wave dispersion relation with phase and group velocity} \label{fig:2} \end{figure}   What I would like to do is dropping the x-y tick labels so that we just maintaing the x-y title. How can I obtain it? How do you associate the .exe file extension with a program in Windows? I have many tags marked as "interesting" and others as "ignored". (I use Java at work, I'm a Cocoa guy by night, any anything dealing with Windows/.NET/C# simply doesn't apply to me.) When tags are added to the list in the right navbar, they appear in the order in which they were added. There are several problems with this:   It can be difficult to visually locate a tag quickly, unless you have memorized its location. The tags appear as the same gray boxes like everywhere on SO, but with a small "x" afterward, and they wrap based on size. This tends to leave a ragged right margin and wasted space. Ordering based on when the tag was added is not always the most intuitive default. Various users might prefer to view them alphabetically, by popularity, recent activity, etc.   It would be nice to introduce a tabbed interface to switch between various orderings, and remember the value in the cookie, profile, etc. Coupled with this, perhaps users could specify a custom ordering that works best for them? (Currently the workaround is to copy all the tag names, remove them all, and re-add them in the desired order, but this is obviously annoying.)  Thoughts? Finding the fallacy in this broken proof Today, a friend gave me a "proof" of $1=2$ and challenged me to find the fallacy.     $1 = 1$      $1 = 1 + 0 + 0 + 0 ...$      $1 = 1 + 1 - 1 + 1 - 1 + 1 - 1 ...$      $1 = 2 - 1 + 1 - 1 + 1 - 1 ...$      $1 = 2 + 0 + 0 ...$      $1 = 2$   My answer was that once you turn the initial $1 + 1$ into a 2, everything is offset so a $-1$ is always left at the end no matter how many times it is repeated. This negative one balances out the $2$ at the beginning so $1=1$ still holds true. I.e.  $$1 = 1 + 0 + 0 + 0 ... = 1 + (1 - 1) + (1 - 1) + (1 - 1) = 2 + (-1 + 1) + (-1 + 1) - 1$$  However, my friend claimed that my answer only applies if the $+ 1 - 1$ repeats for a finite number of times. He argues that because the sequence repeats infinitely and things work differently when working with infinity, my answer is not valid.  Can anyone enlighten me to the true fallacy in this proof? ffmpeg is not even cutting this and other mp4s to the nearest second Why do I have blurred vision and how do I fix it? How to store pipe ( | ) in a variable? The idea would be to use it as... a pipe in a command. For instance: say there's some kind of long path which has to be retyped again and again, followed by a pipe and a second program, i.e.  "directory1/directory2/direcotry3/file.dat | less -I "   I'd like that part to be stored in a variable, so it could be used like this:  r="directory1/directory2/direcotry3 \| less -I -p " $ cat path1/path2/$r &lt;searchterm&gt;   Instead, I get  cat: invalid option -- I Try `cat --help' for more information.   ... meaning the pipe clearly didn't work. Reload activity in Android There are five boxes consisting of several identical coins. There are five boxes consisting of several identical coins. The first box contains 4 coins, the second box contains 9 coins, the third box contains 7 coins, the fourth box contains 10 coins, and the fifth box contains 3 coins. Some coins are taken from the boxes such that at least a coin taken from each box. In how many ways in taking the coins, such that the numbers of the coins taken are 12?  My attempt was solving it using repetition combination of which, there are only seven coins remaining considering that at least a coin taken from each box. By using the repetition combination, i.e. taking 7 from 9 (five boxes and four borders), resulting in 36 ways. However, there is no 36 ways in the choices. Bundling python library with addon I'm making an add-on that uses the websocket library from python. Is there a way to include it in the add-on .zip file? Or do I have to add it to the site packages folder in blenders included python folder? A fair coin is tossed until a head comes up for the first time. The probability of this happening on an odd number toss is?  How do i approach this problem ? How to stop a sponge cake (chiffon cake) from deflating/sinking? Does Java Connection.close rollback? Does Java Connection.close rollback into a finally block?.  I know .Net SqlConnection.close does it.  With this I could make try/finally blocks without catch...  Example:  try {     conn.setAutoCommit(false);     ResultSet rs = executeQuery(conn, ...);     ....     executeNonQuery(conn, ...);     ....      conn.commit(); } finally {    conn.close(); }