The only thing I could think was to use the Cauchy Theorem. So I know that exists a $h \in G$ such that $o(h) = p$. Also I can consider the subgroup $H = &lt;h&gt;$ that all the elements have the same property and $|H|=p$.   I think that $h \in C(G)$. But if I take $g \in G$, I'm not being able to prove that $g*h*g^{-1} = h$. To take an example I thought of $\mathbb{D}_4$, where $|\mathbb{D}_4|=8=2^3$ and I can see there that $r^2 \in \mathbb{D}_4$ has order 2 and $r^2 \in C(\mathbb{D}_4)$
I know this is a very common corollary of the class equation. And I know how to do it by using class equation.   But can you do it bu using group action, maybe find a nice set for G to act on?
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How to remove the WordPress version from some .css/.js files I know that I can use the following function to remove the version from all .css and .js files:  add_filter( 'style_loader_src', 'sdt_remove_ver_css_js', 9999 ); add_filter( 'script_loader_src', 'sdt_remove_ver_css_js', 9999 ); function sdt_remove_ver_css_js( $src ) {     if ( strpos( $src, 'ver=' ) )         $src = remove_query_arg( 'ver', $src );     return $src; }   But I have some files, for instance style.css, in the case of which I want to add a version in the following way:  function css_versioning() {     wp_enqueue_style( 'style',         get_stylesheet_directory_uri() . '/style.css' ,         false,         filemtime( get_stylesheet_directory() . '/style.css' ),         'all' ); }   But the previous function removes also this version. So the question is how to make the two work together? EntityFieldQuery display pager How do I display pager using EntityFieldQuery for fetch results? I can't find complete example.  I am doing simmilar to:   But I miss part to output simple pagination links (1,2,3... for every next page). Can't install/uninstall packages in Debian I'm trying to install/uninstall packages in Debian but getting errors.    I can't remove or add any package, always getting the error.   I tried:  apt-get --remove purge package apg-get remove package dpkg -r package How is Faulhaber's formula derived? How to trigger a check for updates in Firefox programatically or from a command line? Is there a command line switch for firefox.exe or an "about:" URL that will either force an update check or at least display the Help/About dialog, which checks for updates and tells if you're running the latest version?    One site claimed that the "about:" URL was the same as menu Help -> About, but it's not.  I built a program to automate the updating of various programs on my machine, and most programs have command line tools for checking for updates. 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