I saw this sentence in the book 1Q84:     It's not just you that don't know.   However, I am having trouble figuring out why (or whether) this is the correct way to write the sentence, as opposed to:     It's not just you that doesn't know.   Now, according to , we should use "doesn't" when the subject is singular (except when the subject is "you" or "I"), and "don't" otherwise. But in the example above, I am having a hard time figuring out what exactly the subject is and whether it is singular.    The reason my question is different from  is that in John's, the subject is clearly "you." However, as I tried to articulate above, I am having a hard time figuring out what exactly the subject is in the quotes I gave and whether it is singular.
Possible Duplicate:          This is a line spoken by the . I always wondered if this is grammatically correct.  Luke says something like "You are mistaken ..." which the Emperor answers with     No, it is you who are mistaken!   Why wouldn't he say     No, it is you who is mistaken!   instead?  I don't know what rules apply here but my stomach tells me the latter is (at least also) correct, although you would say "you are mistaken". It feels as if he should be referring to "you" in the third person.  Could you please shed some light? Are both correct or – if not – which one is correct? And why?
Moving /var, /home to separate partition I am attempting to move some folders (such as /var and /home) to a separate partition after reading this guide:    I was able to move one folder successfully following guide.  However, it doesn't seem to work for multiple folders, and all my folders are dumped into the partition without proper folders.  I would like to mount /var, /home, and /tmp onto the separate partition; can someone guide me on this? What is the correlation if the standard deviation of one variable is 0? $\aleph_1$ is the cardinality of the countable ordinals. It is the least cardinal number greater than $\aleph_0$, and assuming the continuum hypothesis it's equal to $\mathfrak{c}$, the cardinality of the the real numbers.    My question is, is it possible for all $\aleph_1$ subsets of $\Bbb{R}$ to have Lebesgue measure $0$?  This is, of course, impossible assuming the continuum hypothesis, because then all sets of real numbers would have measure $0$, which is absurd.  But is $\mathsf{ZFC}$ + $\lnot\mathsf{CH}$ + "all subset of $\Bbb{R}$ of cardinality $\aleph_1$ have Lebesgue measure $0$" consistent?  If not, what if we replaced Lebesgue measure with some other measure?  It may be worth noting that, although there may be subsets of $\Bbb{R}$ with cardinality $\aleph_1$, there are no subsets of $\Bbb{R}$ which have the order-type $\omega_1$ (the order-type of the countable ordinals) under the usual ordering on $\Bbb{R}$.  Any help would be greatly appreciated.  Thank you in Advance. I recently found a formula to help find a sequence given a generating function:  $(\frac{1}{1-x})^k=\sum_{n=0}^{\infty}\binom{n+k-1}{n}x^n, k \in \mathbb{N}$  I just wondered if there was a known proof for this, or if anyone knows of a way to prove it. A children's book series about a farm that grows massive food There was a series of illustrated children's books that I was introduced to as a child in the late 1980's early 1990's.  The main character was a farmer - I can't remember the name, but I think it was Mc or Mac something. He bought his farm from a sleazy character who was trying to cheat him. The farmland was originally some kind of swampy land, but this industrious character (and his family) discovered that the land would grow plants to a massive size - radishes the size of basketballs, etc.  There were some pretty fantastic stories and adventure that the character would get into, such as one winter the weather got so cold that the wind (not the air) outside froze. They went out and cut it up and stored it in the icebox and would thaw out some of the cold breeze later in the hot summer.  The sleazy character made a constant appearance, trying to swindle this family out of the farm.  My Google-Fu seems to fail me at every turn. Do you know what this series is? induction with 2 recursive sequnces I'm having trouble solving this problem. I have relation for two sequences of natural numbers.   $$a(n)+\sqrt3\cdot b(n)=\left(1+\sqrt3\right)^n$$  and I have to prove that recursions:  $$\begin{align*} &amp;a(n+1)=a(n)+3b(n)\\ &amp;b(n+1)=a(n)+b(n) \end{align*}$$  will satisfy relation mentioned above. I tried solve it using induction but I failed. Can anybody help with some other ideas? How can I undo git reset --hard HEAD~1? Is it possible to undo the changes caused by the following command? If so, how?  git reset --hard HEAD~1 Can any linear transformation be represented by a matrix? Use $\cal L$ to denote a linear transformation on some vector space. We know any matrix $\bf{A}$ can be viewed as a linear transformation by defining $\cal L:= \cal L(\bf{v})= Av$ where $\bf{v}$ is a vector. I am curious is any linear transformation can be represented by a matrix? If so, why? If not, can anyone help provide a counterexample?  In particular, projection of vectors onto a vector $\bf{b}$ is a linear transformation defined by ${\cal L(\bf{v})}=({\mathbf{v}} \cdot \frac{{\mathbf{b}}}{{|{\mathbf{b}}|}})\frac{{\mathbf{b}}}{{|{\mathbf{b}}|}}$. Can this linear transformation be represented by a matrix?  Thank you! I have forgotten my ID proof and I'm doing an Indian domestic flight. Can I still fly? I am travelling from Delhi to Indore, a domestic flight. I forgot to take ID proof. Can I still fly? Singular values of the data matrix and eigenvalues of the covariance matrix I've been thinking of animating some dice and while most are easy to make, I'm having some trouble figuring out a way to generate a regular dodecahedron. I could hand build it but it would be potentially uneven. Would using the base of a 5 sided cylinder and then some variation on spin be the best option or is there a better way? Outlook, POP and PST handling Essentially I have a client who is on hosted exchange and have decided to use POP3 to download the mail (I don't know why they don't use .OST's but anyway), they rebuilt the machine and backed up their .PST file. Now their Outlook was configured to keep mail downloaded on the server for 14days.  Essentially their current PST is fairly complex, many folders and sub folders and so on. So what is the best way to handle it really - create a new Outlook profile on the rebuilt machine and download the mail via POP into a new .PST then just recreate the folders in the new pst and drag and drop the mail via attaching the backed up .pst, recreating the folders etc?  But is their an easier way to do this, maybe pointing the new account to use the original PST, but then that would download all the mail again from the server to that .PST file.  Any ideas on the best way to handle POP3 account rebuilds from scratch when you have a backed up PST? Integrating a function of tan inverse How would I carry out the following integration? $$\int_0^12\arctan x^2$$  I tried to substitute $x^2 = \tan\theta$ From there I wrote the integral as: $$\int_0^{\pi/4}\theta\cdot \frac{\sec^2\theta}{\sqrt{\tan\theta}}\ d\theta$$  Now, is my only option to use integration by parts? Or is there a better method to solve this integral? Is there any scrappable junk I should hold on to that could otherwise be used for other purposes? This question is inspired by    I see these constructs  for file in `find . -type f -name ...`; do smth with ${file}; done   and  for dir in $(find . -type d -name ...); do smth with ${dir}; done   being used here almost on a daily basis even if some people take the time to comment on those posts explaining why this kind of stuff should be avoided... Seeing the number of such posts (and the fact that sometimes those comments are simply ignored) I thought I might as well ask a question:  Why is looping over find's output bad practice and what's the proper way to run one or more commands for each file name/path returned by find ? pdflatex bash script to supress all output except error messages? I have a bash script which I use to compile a file with pdflatex twice (to make sure it sorts out references properly, etc.). This is the 'latexbuild' script I use:  module load ctan pdflatex --shell-escape --interaction=nonstopmode $1 bibtex $1 pdflatex --shell-escape --interaction=nonstopmode --interaction=batchmode $1   I would then call this script with latexbuild test.tex. It produces a lot of output which I would like to supress, except for the error messages which I'd like to see. Is there any way to only allow error messages to be displayed? Sarrus Rule with LaTeX Is there a way to create a new command with 9 arguments ({a_{11}},{a_{12}},{a_{13}},{a_{21}},{a_{22}},{a_{23}},{a_{31}},{a_{32}},{a_{33}}) that has as output a matrix with the Sarrus Rule? For instance: to obtain     just use the command that we will call sarrus:  \sarrus{-k}{k-1}{1}{0}{k-1}{k}{2}{0}{1}.   If it is possible i want to use the command sarrus in math mode just like matrix for istance. Problems with wifi range on laptop. Wifi card: realtek rtl8723be So I just started using linux/ubuntu today and I've been getting problems with my wifi, ive tried the solutions on this page:  When im really close to my router, its fine, i can see wifi signals, but when i go just a few steps back it disappears right away. Im using the latest version of ubuntu 17.10  Any suggestions would be nice! :) Pass values from parent to child component on click lightning I have this below code where i am trying to first search an account name and on hit button it displays the result set.  On the button click i am also loading an child component which is displaying the id of the record.  I need the child component should get displayed once i click on the record.  How can i achieve this -   Parent Component -   &lt;aura:component controller="SimpleAccountController"&gt;     &lt;aura:attribute name="account" type="account[]"/&gt;     &lt;ui:outputText aura:id="outName" value="" class="text"/&gt;     &lt;ui:inputText aura:id="name" label="Enter Name:" placeholder="Your Name" /&gt;     &lt;ui:button aura:id="button" buttonTitle="Click to see what you put into the field" class="button" label="Click me" press="{!c.getInput}"/&gt;     &lt;aura:iteration var="acc" items="{!v.account}"&gt;             &lt;a onclick="{!c.accountselected}" data-recId="{!acc.Id}"&gt;         &lt;p&gt;{!acc.Name} : {!acc.Type} : {!acc.Industry} : {!acc.Rating}&lt;/p&gt;             &lt;/a&gt;         &lt;c:HelloWorkdChildCmp selectedaccount="{!acc.Id}" /&gt;     &lt;/aura:iteration&gt; &lt;/aura:component&gt;   COntroller -   ({     getInput : function(cmp, evt) {         var myName = cmp.find("name").get("v.value");         var myText = cmp.find("outName");         var greet = "Hi, " + myName;         myText.set("v.value", greet);         var action = cmp.get("c.seaAcc");         action.setParams({ "s" : myName });         action.setCallback(this, function(response) {             var state = response.getState();             if (state === "SUCCESS") {                 cmp.set("v.account", response.getReturnValue());                 //alert("From server: " + response.getReturnValue());             }         });         $A.enqueueAction(action);     },      accountselected : function(cmp, evt) {        console.log(evt.currentTarget.getAttribute("data-recId")) ;     }  })   Child component -   &lt;aura:component &gt;     &lt;aura:attribute name="selectedaccount" type="String"/&gt;     &lt;div&gt;Id: {!v.selectedaccount}&lt;/div&gt; &lt;/aura:component&gt; VB6 compiling via console (vb.exe) compatibility issue on 64bit (works on 32bit?)