I just installed Debian and now I am trying to set up Steam.  I did the first 2 steps in the  and also installed ia32-libs.  But when I run the following:  apt-get install libgl1-nvidia-glx:i386   It tells me this:  Reading package lists... Done Building dependency tree       Reading state information... Done E: Unable to locate package libgl1-nvidia-glx   How can I have apt-get locate and install libgl1-nvidia-glx?
I have ran into some issues when it went down to install Steam on Debian. The console as well as Apper comes up with missing dependencies  and the package isn't going to install.
From :     "[...] the stress vector $T$ across a surface will always be a linear function of the surface's normal vector $n$, the unit-length vector that is perpendicular to it. [...] The linear relation between $T$ and $n$ follows from the fundamental laws of conservation of linear momentum and static equilibrium of forces, and is therefore mathematically exact, for any material and any stress situation. The components of the Cauchy stress tensor at every point in a material satisfy the equilibrium equations (Cauchy’s equations of motion for zero acceleration). Moreover, the principle of conservation of angular momentum implies that the stress tensor is symmetric."   What is the more detailed explanation for this, and/or where can I find it? Can you Start Skyrim 'silent' without the launcher showing up? Prove that for any piecewise smooth curve it is possible to find the parametrisation $\phi$ that is consistent with its length, ie.  length of a curve segment between $\phi(a)$ and $\phi(b)$ is equal to $|b-a|$.  It seems intuitive, but I don't have any idea how can I show this in the formal way. I have a site that is in French and English. I am able to successfully setup so that users can switch back and forth between the two domains to view either language, however I cannot seem to keep users logged in. When they are logged into the english domain and then switch to the french domain they are required to login again. However if they switch back to the english domain they are still logged in.  As an example we'll use www.english-domain.com as the base (default) domain and www.french-domain.com as the secondary domain  In settings.php I have modified the following, however it doesn't seem to be keeping them logged in. Am I missing something?  /**  * Drupal automatically generates a unique session cookie name for each site  * based on its full domain name. If you have multiple domains pointing at the  * same Drupal site, you can either redirect them all to a single domain (see  * comment in .htaccess), or uncomment the line below and specify their shared  * base domain. Doing so assures that users remain logged in as they cross  * between your various domains.  */ $cookie_domain = 'english-domain.com';   Note: That I have also flushed both site and browser cache as well as deleted any cookies left on my machine.  Update:  Here are my language settings: How to evaluate potential advisers on grounds other than their research/publications? Unknown Column In Where Clause Is there any way to import a .json model into Blender? Flat quads (or, why is my mesh so funky?) Other than the general inductive method,how could we show that $$\sum_{r=0}^n \frac{(-1)^r}{r+1}\binom{n}{r} = \frac1{n+1}$$  Apart from induction, I tried with  to check the validity, but I can't think of an easy (manual) alternative.  Please suggest an intuitive/easy method. Please provide me with the guidance to install oracle 11gr2 on Ubuntu 14.04. How does Meta Stack Exchange work? Meta Stack Exchange seems to have different rules and user behavior than the "regular" Stack Exchange sites.  How is it different?    Individual questions answered below:                Related Proof of A ⊆ C and B ⊆ C ⇔ A ∪ B ⊆ C I know that this is valid because by thinking about it, you can see it's true, but I'm just not sure how I would go about actually proving it mathematically. I've kind of tried proof by contradiction, since that's what I use most of the time, but it doesn't seem to work.    In my mind, A ∪ B ⊆ C kind of just implies that A ⊆ C and B ⊆ C. Has the concept of non-integer $(n+m)$-dimensional spacetime ever been investigated by theoretical physicists? The following image serves to aid the reader in understanding the "privileged character" of $3+1$-spacetime.    The wikipedia article on , and the  "The priveleged character of $3+1$-dimensional spacetime" in particular, made me think a bit about the possibility that we might live in a non-integer amount of spatial and/or time dimensions.   The notion of attaching a non-negative real number to a metric space has at least mathematically already been described by such concepts as "" and "".   This may sound silly/ignorant/absurd to professional practicing theoretical physicists. To me (a layman), however, it doesn't sound much stranger than the idea of wrapping up six extra dimensions (which is, from what I understand, considered to be a serious possibility by those who study $10$-dimensional String Theory) into intricate shapes called "Calabi-Yau Manifolds".   Has any research on $(a +b)$-dimensional spacetime (where $a,b \in \mathbb{R}_{\geq 0} $) ever been done? If so, what where the findings? If not, why not? UK PLAB Visa Refusal due to unexplained bank deposits In my team, we use Selenium for automation of functional testing. We also do a lot of manual regression testing to make sure the appearance of the rendered web pages is ok. I would like to develop a framework, that would allow comparing screenshots of the "base" live web page, and the web page on the test server after applying the software update. I believe this will drastically reduce the amount of manual regression testing we need to do.   I would like the framework to be able to detect portions of web pages that were rendered differently from each other. An example of such functionality can be  (first image in the article)  I have never worked with image processing and would need ideas on what algorithms are already publicly available that would help me with the task. From what I can see, the simple pixel-by-pixel comparison would not work well, because it does not account for the concept of elements.  Or am I approaching this problem from a completely wrong direction? Styling border to match fill in QGIS? In the past I have just manually matched the color of the border to the color of the fill, but this can be time consuming.   I am wondering, is there any way to have the program automatically match the border color to that of the fill?   The fill color is being assigned through the styling tab in layer properties.  Using QGIS 2.8.6 Using k-fold cross-validation for time-series model selection Question: I want to be sure of something, is the use of k-fold cross-validation with time series is straightforward, or does one need to pay special attention before using it?   Background: I'm modeling a time series of 6 year (with semi-markov chain), with a data sample every 5 min. To compare several models, I'm using a 6-fold cross-validation by separating the data in 6 year, so my training sets (to calculate the parameters) have a length of 5 years, and the test sets have a length of 1 year. I'm not taking into account the time order, so my different sets are :   fold 1 : training [1 2 3 4 5], test [6] fold 2 : training [1 2 3 4 6], test [5] fold 3 : training [1 2 3 5 6], test [4] fold 4 : training [1 2 4 5 6], test [3] fold 5 : training [1 3 4 5 6], test [2] fold 6 : training [2 3 4 5 6], test [1].   I'm making the hypothesis that each year are independent from each other. How can I verify that? Is there any reference showing the applicability of k-fold cross-validation with time series. Pageblocktable to be rendered as table in PDF I have a VF code below where I am trying to display the related list of an object using  and  command. I am rendering this page as PDF , doing that in my PDF I am unable to see the content in a tabular format. How can I make the content appear in a table?      &lt;apex:pageBlockSection columns="1" title="TECHNICAL ASSESSMENT"&gt;          &lt;apex:repeat value="{!interviewSkillReviews}" var="interview"&gt;              &lt;table border="1" cellpadding="6"&gt;                 &lt;apex:pageblockTable value="{!interview.Skill_review__r}" var="skillreview"&gt;                      &lt;apex:column headerValue="Skill Name"&gt;                                                         &lt;apex:outputText value="{!skillreview.Skill__r.Name}"/&gt;                     &lt;/apex:column&gt;                 &lt;apex:column headerValue="Recommended Level"&gt;                     &lt;apex:outputText value="{!skillreview.Level__r.Name}"/&gt;                 &lt;/apex:column&gt;                  &lt;apex:column headerValue="Rating"&gt;                     &lt;apex:outputField value="{!skillreview.RatingCopy__c}" rendered="{!NOT(interviewerMode)}" /&gt;                     &lt;apex:selectList value="{!rating}" multiselect="false" size="1" rendered="{!interviewerMode}"&gt;                         &lt;apex:selectOption itemValue="1" itemLabel="1"/&gt;                         &lt;apex:selectOption itemValue="2" itemLabel="2"/&gt;                         &lt;apex:selectOption itemValue="3" itemLabel="3"/&gt;                         &lt;apex:selectOption itemValue="4" itemLabel="4"/&gt;                         &lt;apex:selectOption itemValue="5" itemLabel="5"/&gt;                     &lt;/apex:selectList&gt;                 &lt;/apex:column&gt;                  &lt;apex:column headerValue="Rating Level Description"&gt;                     &lt;apex:outputText value="{!skillreview.Skill_Level_Description__c}"/&gt;                 &lt;/apex:column&gt;               &lt;/apex:pageblockTable&gt;         &lt;/table&gt;      &lt;/apex:repeat&gt; &lt;/apex:pageBlockSection&gt;   I tried using &lt;table&gt; command of HTML but I just get a border around the pageblocktable.    Example of table look and feel: I'm trying to downgrade my iPhone from the current iOS to an older one, as per .  But every time I try, I always receive this error:     The iPhone could not be restored. This device isn't eligible for the requested build.     I have tried many times with and without DFU mode. Any ideas regarding this? If $\gcd(a,b)=1$, $\gcd(a,y)=1$ and $\gcd(b,x)=1$ then prove that $ax+by$ is prime to $ab$.  I tried assuming Diophantine Equations for all the relations and representing everything in terms of $a$, but that didn't lead me anywhere. There must be an intuitive and elegant approach right?