Is it possible to install Ubuntu Raring Ringtail 13.04 without CD or USB?
So basically as it stands I have a laptop which has no cd/dvd drive, and I don't have a usb drive.  The laptop has windows 7 installed with ubuntu 11.04 installed through wubi.  What I want to do is remove windows completely, and make ubuntu the only OS installed on the system.  Is there a way to do this without re-installing ubuntu? (i.e. can I take my wubi install away from windows?)  or is there a way to from inside ubuntu have it run the ubuntu iso somehow so I can just wipe the system and install it fresh? (even if it means I need to have an e.g. 2gb partition just for the image to reside in).
Can the Room of Requirement provide anything if needed? For example:   James Potter wanted to hide from Voldemort, it would have served as a perfect hiding place. Harry Potter wanted all the Hocruxes, he should have gone straight to the room of requirement where he would have found all the Hocruxes along with the Sword. All the muggle borns of the wizarding community could have taken refuge in the room of requirement. Can someone meet a dead person in the room of Requirement if needed? Would it have been possible for Harry to go in past in order to see Dumbledore for the explanation of many things? Can the room duplicate something? For instance, Harry needed the Elder wand; with Voldemort having it, could he still get it? Someone wishes to be knowledgeable than Dumbledore, would the seeker find his desired wish by finding books and things?   Who created the room of requirement (surely not Salazar)? Was it beyond Dumbledore's magic to create such a place? $f$ be an analytic function defined on $\mathbb{D}=\{z\in\mathbb{C}:|z|<1\}$ I came across the following problem that says:  Let $f$ be an analytic function defined on $\mathbb{D}=\{z\in\mathbb{C}:|z|&lt;1\}$ such that the range of $f$ is contained in the set $\mathbb{C}\setminus (-\infty,0]$. Then  $f$ is necessarily a constant function. there exists an analytic function $g$ on $\mathbb{D}$ such that $g(x)$ is a square root of $f(z)$ for each $z\in\mathbb{D}$. there exists an analytic function $g$ on $\mathbb{D}$ such that $\operatorname{Re}g(z)\geq 0$ and $g(z)$ is a square root of $f(z)$ for each $z\in\mathbb{D}$. there exists an analytic function $g$ on $\mathbb{D}$ such that $\operatorname{Re}g(z)\leq 0$ and $g(z)$ is a square root of $f(z)$ for each $z\in\mathbb{D}$.   I have to determine which options are correct. Can someone help in the right direction? Thanks in advance for your time. How to make specifics apps password protected even after passcode in iPhone? How to prove $\bar{m}$ is a zero divisor in $\mathbb{Z}_n$ if and only if $m,n$ are not coprime Let us consider the ring $\mathbb{Z}_n$ where $\bar{m}\in\mathbb{Z}_n$  Could anyone help me prove that $\bar{m}$ is a zero divisor in $\mathbb{Z}_n$ if and only if $m,n$ are not coprime  So far I have:  Assume $\exists \bar{a}: \bar{m} \bar{n}=n \mathbb{Z} \Rightarrow$ for some $b\in\mathbb{Z}:am=bn$  I then assumed $n,m$ were coprime and attempted to use $\exists a&#39;,b&#39;\in \mathbb{Z}:a&#39;m+b&#39;n=1$ to come to a contradiction, however haven't found one, the most promising thing I have found so far is that  $a=n(a&#39;b+ab&#39;)$ and $b=m(a&#39;b+ab&#39;)$ $\Rightarrow n|a$ and $m|b$ $f_n$ converges uniformly on $[a,b]$ to some function $f$ How do you attach a debugger to a Web service? I am using a Web service. Can anybody tell me how to debug through it? When I try to run Maya from the terminal, I get:  error while loading shared libraries: libtiff.so.3: cannot open shared object file: No such file or directory.   How do I solve this?  Note: Maya is a third-party software. Is it possible to recognise hardware (router or network card) just by its MAC address? Just wondering if that is possible. Are there any naming conventions that would allow one to deduce whether the MAC address belongs to a router (of a specific brand), or a network card, etc.. Can I recover a file from /dev/null? Show that for any $k$-cycle $(a_1 a_2...a_k) \in S_n$, and for any permutation $\pi \in S_n$, $\pi(a_1...a_k)\pi^{-1}=(\pi(a_1)..\pi(a_k))$ I was answering a question on Stack Overflow and required to use a trailing space in one of my code snippets.  I formatted it like so:  `&lt;a `   And it renders without the trailing space: &lt;a  Using the &lt;code&gt; tag does account for trailing spaces, though in my case it busts because of the &lt;. Here's my formatting with the &lt;code&gt; tag:  &lt;code&gt;&lt;a &lt;/code&gt;   Here's how it renders:  (Yes, you should see nothing there).  This is a pretty annoying bug. Can we get it fixed? Does the PS-Vita support PSP games Is the PS-Vita backwards compatible with PSP games?  Some games I would like to play include Final Fantasy 7: Crisis core, Jak and Daxter: The Lost Frontier, Coded Arms, Tekken: Dark Resurrection, and Secret Agent Clank. How can we remove the launcher that come with Unity on this new Ubuntu version ? Are Constitution changes retroactive when calculating max HP? Lets say I'm a fighter that just leveled up to level 4, and decide to bring my Constitution up from 16 to 18. How many hit points do I have?  Level 1 = 10 (base) + 3 (Con mod) = 13.  Level 2 = 10 + 6 (average HP per fighter level) + 3 (Con mod) x 2 = 22  Level 3 = 10 + 6 (average) x 2 + 3 (Con mod) x 3 = 31  Level 4 = 10 + 6 (avg) x 3 + 3 (Con mod) x 3 (3 level-ups) + 4 (increased Con mod, which is now 4) x 1 = 41?  OR  Level 4 = 10 + 6 (avg) x 3 + 4 x 4 (4 times current Con mod) = 44?  If it's the first option, it's simply better to level Constitution up at earlier levels. How to find out client ID of component for ajax update/render? Cannot find component with expression "foo" referenced from "bar" Support for OpenID ended on July 25, 2018 NOTE: Signing up or Logging in via OpenID is no longer officially supported from any of our sites. Currently,  is still on the internet, but we are in the process of completely removing it.    Stack Overflow was an early and strong supporter of . We built our sign up/log in flow around it. We were idealistic and had , but these hopes weren't realized. Over the years people have wondered if  is . We've had to remove support as OpenID providers  or .  The time has come to part ways. The reality is OpenID support has created a ton of complexity in our codebase and the number of users actively using OpenID simply don't justify that cost. Users have spoken with their actions. You prefer Google, Facebook and Stack Exchange (aka email/PW) based account auth.     Of our 9,813,747 accounts around one-tenth of a percent are actively using OpenID (defined as having visited a site in the past 12 months). If you include all the inactive accounts it is still less than 2.9% of all accounts.  So, what is the plan?   DONE - Remove the ability to create a new account with most OpenID providers DONE - Add the ability to  DONE - Convert Launchpad (used on  ) to OAuth DONE - Remove creating new accounts with Steam from  (Steam removed support for OAuth. Only 454 accounts that use Steam have visited Arqade in the past 6 months.) DONE - We will email all users that rely on deprecated OpenID credentials and request that they  DONE - Run an announcement banner for any user who signs in with deprecated OpenID credentials urging them to  DONE - End support for logging in via OpenID  In progress - Remove  (note: only 0.2% of authorized sites in the last year have been non-Stack Exchange sites.)   Obviously, if your account relies on OpenID, then make life easy and go now and .   If you've forgotten what you credentials you use to login, then  to refresh your memory. If you don't see one of the three account types shown in the image below (Google, Facebook or Stack Exchange) then click the "add more logins" button to add one of them to your account.    Remember, SE OpenID accounts are really email/pw accounts handled through complicated OpenID code path. They will be migrated to a simpler email/pw only code path as a part of this change. No extra work required on your part. How do I bridge network interfaces? I have a laptop running 11.10 with 2 network interfaces, wired and wireless.  Wireless interface connects to the router with DHCP and connects to the internet. Wired interface is connected to a switch. I want the computers on the switch to get their IP addresses from the router not my laptop.     How would I go about setting this up? Bridging the interfaces? Using the expression "the same" for a previously mentioned item What are some strategies that I can employ to handle a power gamer that constantly outshines the rest of the party? This is a friend of us all and we don't want to boot him, but combat simply isn't fun when the party has nothing to do while he mops up an encounter by himself. Ignored users still appear in the 'other rooms you're in' message preview Well it might not be a huge issue to some (I suppose it depends on how you use the chat system) but when I "Ignore this user everywhere", their messages still appear on the sidebar for the 'other rooms you're in' if they say something. Albeit I can ignore this feature and the text within it, I just find it odd that I can still see it.   This is only a nuisance when you truly are annoyed by a user and ignoring them in the chat was the best possible alternative to leaving the room or starting an argument (no references here, but any long time chat user has been annoyed by some help vampire at one point in time or another and would just prefer to ignore them for good).   If you have no clue to the sidebar or preview I'm talking about: this is for you,    I have chosen to Ignore this user everywhere (Neal) and then switched to a new room, yet that users response appears in my 'preview' for the 'other rooms you're in' if he is also talking in them.  Note: My ignore of Neal was mostly due to jest, this in no way is to reflect on Neal but the chat feature (I hate to ever single anyone out here).