Thieves Guild Skyrim - Return The Skeleton Key or Complete Jobs in Other Towns? Is it possible to raise the thieves guild without doing the Nightingale questline? Because I have been doing a lot of quests for Vex and Delvin, but it seems I can't get the special quests. Is there anything I can do to change that, or do I have to deliver the lock pick thingy back? And does it matter what quests you do, if you don't have to deliver the lock pick back?
Can I become leader of the Thieves' Guild without finishing the main chain and is there any benefits from being the leader anyway? I completed the quest where you get the Skeleton Key and I don't really want to continue the chain until I've done a lot of the other stuff in the game, since the key is so useful. Brynjolf said before that I would become leader of the guild after everything was over.  Can I become the leader anyway without finishing the Nightingales quest chain? Are there any bonuses for being the leader?
How to create a new object instance from a Type Series $\sum_{n=1}^\infty \frac{n^n}{(n!)^2}$ How do we know that $F = ma$, not $F = k \cdot ma$ It seems intuitive that $a\; \propto \frac{F}{m}$, as the greater the force that is applied on an object, the greater its acceleration will be. Inversely, the greater the mass of the object, the slower the acceleration will be.  However, when rewriting proportions as equations, you must introduce a constant of proportionality, and in this case of a direct proportion, if $a \propto \frac{F}{m}$ then when rewriting as an equation you will have $$a = k\cdot\frac{F}{m}$$  In order to get the standard formula $F = ma$ this constant must be $1$. However, how do we know that this is the case? How do we know that the constant isn't $2$ and the formula $F = \frac{1}{2}ma$, for instance? Increase word space between words in small caps lstlisting in two columns I would like to have two listings, side by side.  They have approximately the same length, therefore I don't care about how it's layed out if one part is longer.  I tried  \begin{minipage}{\textwidth} \begin{parcolumns}{2} \colchunk{\begin{lstlisting}[caption=code 1,frame=tlrb]{Name} void code() {  } \end{lstlisting}}  \colchunk{\begin{lstlisting}[caption=code 2,frame=tlrb]{Name} void code() {  } \end{lstlisting}}  \colplacechunks \end{parcolumns} \end{minipage}   while the border of the listings end up in chunks as follows:   Btw I'm using the texlive-package &amp; pdflatex on Ubuntu and the document class is  \documentclass[ a4paper, 10pt, twoside, openright, notitlepage, parskip=half, ]{scrreprt}   Any idea is appreciated. Does Android hide some amount of RAM from the User? I bought a new tablet, but Android (2.3.1) shows that it has only 150MB free of 256MB, and it should have 512MB.  I checked the file /proc/meminfo, MemTotal information. It only shows 256MB. Is there a possibility that the Android "hid" 256MB of RAM from the user? If electrons were positive and protons were negative, would life be different? Replacing all values in a table > $T$ I have several AppExchange apps installed that are failing tests. What is the recommended approach to resolving this? Are tests run when a new package is installed? Is there a way to determine what is actually failing besides the name of the method and something like "expected true, actually false"? The test results rarely show enough information to be useful.   What I'm doing atm, is checking for updates for the packages, and then writing the company with the failing test results.   Any feedback would be appreciated. How can I solve the folowing Diophantine equation with two unknowns? Find one integer solution to the following Diophantine equation:   \begin{equation*} \\\forall \,x,y \in \mathbb{Z}\\ 6xy + x - y = 274 \end{equation*}   The resultat ist $x = 9$, $y = 5$ (Obtained with  )  I need to know a method that allows me to reach such a result. How can I calculate the value of these two variables in a Diophantine equation? For example: 6xy + x - y = 458 What does the underscores in _servicename_ mean in AngularJS tests? How do I set up Ruby on Rails? I am interested in setting up a Ruby on Rails environment on my 10.10 laptop.   Is there anything special I need to keep in mind for installation (i.e. that could be new or unique to 10.10)?   Are there any suggested walkthroughs that I could follow along with?  Thanks in advance. accessing loop variable within a loop How to extract a floating number from a string Flag apron shows superfluous closing anchor tag I awoke this morning to a spam flag on a site I moderate, and noticed this when I went to read the post.    Notice answered&lt;/a&gt;, which I imagine isn't meant to have the &lt;/a&gt; there.  I also confirmed that this displays asked&lt;/a&gt; for other types of flags (namely, closed without comment).   I looked around for a duplicate of this but can't seem to find it, so maybe it's a recent change? I have a Category entity which has a Nullable ParentId field. When the method below is executing and the categoryId is null, the result seems null however there are categories which has null ParentId value.  What is the problem in here, what am I missing?  public IEnumerable&lt;ICategory&gt; GetSubCategories(long? categoryId) {     var subCategories = this.Repository.Categories.Where(c =&gt; c.ParentId == categoryId)         .ToList().Cast&lt;ICategory&gt;();      return subCategories; }   By the way, when I change the condition to (c.ParentId == null),  result seems normal. How does an attacker's reach interact with the Mounted Combatant feat's ability to force an attack against the mount to target the rider instead? SFDC DKIM Setup - Production or Sandbox? Cannot figure out this via SFDC documentation. Need someone who have setup this before to advise.  Basically we want to enable DKIM for our SFDC org. In testing Sandbox and production, the from email address is using the same email domain. For example, "test@abc.com" for sandbox and "contact@abc.com" in production.   Question: shall we setup DKIM in both sandbox and production or just need to setup in production since sandbox and production are actually using the same domain "abc.com"? How to Create Bootable Windows 10 image in Debian? Pseudocode but originally developed for Windows 7 iso file but applied for Windows 8 in the thread  but it does not work with Windows 10 iso  # https://rwmj.wordpress.com/2010/11/04/customizing-a-windows-7-install-iso/ # https://unix.stackexchange.com/a/312477/16920 $ dd if=../en_windows_10_x64_dvd.iso \     of=boot.img bs=2048 count=8 skip=734  $ mkisofs -o ../new-win.iso -b boot.img -no-emul-boot -c BOOT.CAT \     -iso-level 2 -udf \     -J -l -D -N -joliet-long -relaxed-filenames .   Unsuccessful output when run on Windows 10 image  dd if=/home/masi/Downloads/en_windows_10_multiple_editions_version_1511_x64_dvd.iso of=/home/masi/Downloads/boot.img bs=2048 count=8 skip=734 8+0 records in 8+0 records out 16384 bytes (16 kB) copied, 0.000392973 s, 41.7 MB/s    Some of the following fields have changed for the iso file used in dd   bs=2048 count=8  skip=734   How can you study which field values you can use for Windows 10 iso?  OS: Debian 8.5 64 bit Hardware: Asus Zenbook UX303UA Linux kernel: 4.6 of backports Related threads: ,  Motivation: I need Windows 10 to use Canon P-150 duplex scanner, but when I started my Windows, I got Error 0xC0000428 because Windows update has again broken things there and I use Windows otherwise so rarely; and I have no spare Windows left to make bootable media Like the title says, can a matrix in $\mathbb{R}$ have a minimal polynomial that has coefficients in $\mathbb{C}$?  I have a feeling the answer is yes because the characteristic polynomial can have coefficients in $\mathbb{C}$ and so I don't see any reason why not, I was merely asking in case there was some sneaky proof that proves that this cannot happen.