Suppose an employee has a yearly salary of $100K and his/her company matches "50 percent match up to the first 6 percent", and the employee is contributing at a rate of 40%. The employee will reach his/her IRS limit of $19K by 6 months.  So for the last six month there will be no 401K deduction from his own salary. The question is, will the company will still match, or will the employee lose the 401K match for last 6 months?
I think the title says it all. I can't see any reason employers have to incentivize employees to contribute to their 401(k) evenly throughout the year. Instead couldn't they use a relatively simple formula that is based on how much of their income the employee has contributed to their 401(k) thus far for the year? If that or their current contribution is over the threshold, they get the match this pay period, even if they didn't contribute anything.  EDIT: To clarify, my employer matches 100% of the first 3% of my contribution and 50% of the next 2%. The match is added every pay period along with my contribution. I am pretty sure there is no "true-up" feature, so if I were to hit the $17.5K limit early, and not be able to contribute at least 5% of my salary, I would not get the full match. So I have to be careful to make my contributions evenly throughout the year to get the maximum match. Just trying to figure out my employer's motivation for requiring this.
Conditional probability and venn diagram Debian : Verify disk encryption password for already mounted system I am working on our Debian server on which we have a Raid drive encrypted with 2 devices. I did this around 1.5 years back and have never rebooted since. Now, we want to reboot for some reasons, but I have to make sure that the password I have is the correct one, or we will be stuck.   How can we verify the password for an encrypted-raid? Thank you.  Raid details :    mdadm --detail /dev/md0    /dev/md0:         Version : 1.2   Creation Time : Thu Feb 11 14:43:40 2016      Raid Level : raid1      Array Size : 1953382336 (1862.89 GiB 2000.26 GB)   Used Dev Size : 1953382336 (1862.89 GiB 2000.26 GB)    Raid Devices : 2   Total Devices : 2     Persistence : Superblock is persistent      Update Time : Fri Mar 10 10:37:42 2017           State : clean   Active Devices : 2 Working Devices : 2  Failed Devices : 0   Spare Devices : 0             Name : HOSTNAME:0  (local to host HOSTNAME)            UUID : 5c450558:44a2b1e9:83cb4361:9c74df8e          Events : 49      Number   Major   Minor   RaidDevice State        0       8        1        0      active sync   /dev/sda1        1       8       17        1      active sync   /dev/sdb1   Thank you.   Update  dmsetup table --showkeys CryptVol: 0 Large_Number crypt aes-cbc-essiv:sha256 RANDOM_TEXT  0 253:0 4096 RaidVG-LVMVol: 0 Large_Number linear 9:0 2048 For all $1 \leq i < j \leq k$, the subtrees $T_i$ and $T_j$ have a vertex in common. Show that $T$ has a vertex which is in all of the $T_i$. Can someone please verify my proof or offer suggestions for improvement? I am aware that there is a similar question elsewhere, but I want help with my proof in particular.     Let $T_1, \ldots, T_k$ be subtrees of a tree $T$ such that for all $1 \leq i &lt; j \leq k$, the trees $T_i$ and $T_j$ have a vertex in common. Show that $T$ has a vertex which is in all of the $T_i$.   Suppose, for the sake of contradiction, that for every vertex $v \in V(T)$, there is a subtree $T'$ in the list $T_1, T_2, \ldots, T_k$ such that $v \notin V(T')$.  Pick $v_1 \in T_1$. There is a subtree $T^{(1)}$ such that $v_1 \notin T^{(1)}$. $T_1$ and $T^{(1)}$ have a vertex $y_1$ in common. Now, there exists a tree $T^{(2)}$ such that $y_1 \notin T^{(2)}$. But now, $T^{(2)}$ and $T^{(1)}$ have a vertex $y_2$ in common. Also, $T_1$ and $T^{(2)}$ have a vertex $y_3$ in common.  There exists a path $p_1$ in $T_1$ from $y_3$ to $y_1$. Also, there is a path $p_2$ in $T^{(1)}$ from $y_1$ to $y_2$ and a path $p_3$ in $T^{(2)}$ from $y_2$ to $y_3$. Note that the path formed by the union of $p_1$ and $p_2$ passes through $y_1$, while $p_3$ does not, since $y_1 \notin T^{(2)}$. Therefore, the union of $p_1, p_2$, and $p_3$ forms a cycle, contradicting the fact that $T$ is a tree. Therefore, it must be the case that there is a vertex $x$ in all of the $T_i$. How to execute sp_send_dbmail while limiting permissions Is there a way to provide access to users in my database to execute  msdb.dbo.sp_send_dbmail without needing to add them to the MSDB database and the DatabaseMailUserRole?  I've tried this:  ALTER PROCEDURE [dbo].[_TestSendMail] (   @To NVARCHAR(1000),   @Subject NVARCHAR(100),   @Body NVARCHAR(MAX) ) WITH EXECUTE AS OWNER AS      BEGIN         EXEC msdb.dbo.sp_send_dbmail @profile_name = N'myProfile',             @recipients = @To, @subject = @Subject, @body = @Body     END   But I get this error:  The EXECUTE permission was denied on the object 'sp_send_dbmail', database 'msdb', schema 'dbo'.   Thanks! I am having trouble with this problem from my latest homework.  Prove the arithmetic-geometric mean inequality. That is, for two positive real numbers $x,y$, we have $$ \sqrt{xy}≤ \frac{x+y}{2} .$$ Furthermore, equality occurs if and only if $x = y$.  Any and all help would be appreciated. What is the number of invertible $n\times n$ matrices in $\operatorname{GL}_n(F)$? Here is my question:  Is a homeomorphism, that is, a continuos function whose inverse function is also continuous, always bijective? I used Sound Juicer to rip a CD of audio for a language learning book so that I could listen to them on my Android. However, Sound Juicer seems to only have the option of numbering files without leading zeros. Like this:  track_1.mp3 track_10.mp3 track_11.mp3   This leads to some confused ordering on my music player. So, I want to add some zeros to the name, so that they're ordered properly, like this:  track_01.mp3 track_02.mp3 track_03.mp3   How do I accomplish this? I tried using GPRename, but while it has the ability to add numbers, it doesn't seem to have any options for adding leading zeros.  Is there a better program or something I can do at the command line? I found this heart while exploring the crimson biome - what is it? Correct ssh config file settings to tunnel to a 3rd machine I'm trying to tunnel to a server via a bridge server. So far, I've been able to get it working from the command shell properly using the following command:  ssh -A -t bridge_userid@bridgemachine.com ssh -A remote_userid@remoteserver.com   But I've been trying to wrap this into my ~/.ssh/config file and I have troubles. I've tried:  Host axp   User          remote_userid   HostName      remoteserver.com   IdentityFile  ~/.ssh/id_rsa.eric   ProxyCommand ssh -A -t bridge_userid@bridge_userid.com ssh -A remote_userid@%h   But when I do, I get the following error message from remoteserver.com and I'm not sure what is causing it:     ksh: SSH-2.0-OpenSSH_6.8^M:  not found   I know that when I log into remoteserver.com , my shell is /usr/bin/ksh.  I've tried to add path arguments to the ssh commands in the config file, but it made no difference.  Any ideas what it can be? How to get the Vista taskbar to span multiple monitors? I can't for the life of me get the vista taskbar to span multiple monitors.  I've searched and looked far and wide, and alas the only pseudo-solution i can find is Ultra-Mon, but a) it doesn't quite look the same  and b) i don't want to have to pay for something that Windows really ought to be able to do out of the box.   Does anyone have a solution for this?  Will this get addressed in Windows 7? How to prove $\lim \limits_{n\to\infty}(n+1)\int_{0}^{1}x^nf(x)dx=f(1)$ I need help to prove this in real analysis. I think it uses IMVT, but not sure how to do it.     Let $f(x)$ be a real valued continuous function on $[0,1]$. Show that   $$ \lim \limits_{n\to\infty}(n+1)\int_{0}^{1}x^nf(x)dx=f(1) $$ $\operatorname{Ext}$ and injectives, respectively projectives Moving from SQL 2005 [SQL_Latin1_General_CP1_CI_AS] to 2008 - will I lose any features by using 'backwards compatibility' Pacman option to assume "yes" to every question? I am seeing quite a few conversions which have as source "accounts.google.com" (almost 40%).  AFAIK, in the new Universal Analytics as soon as a user has a Referrer set a new session is started. So if a user is getting on my page, and creates an account using social auth (e.g. Google accounts) when being redirected back, will this create a new session? I guess this would explain that there are many conversions coming from accounts.google.com - is it safe to enter accounts.google.com into the Referral Exclusion List? And more - what about Facebook logins, those would show up as facebook.com, but i probably don't want to exclude facebook.com as referrer?  Any ideas how to deal with UA referrers and social logins? I want to do something like:  MyObject myObj = GetMyObj(); // Create and fill a new object MyObject newObj = myObj.Clone();   And then make changes to the new object that are not reflected in the original object.  I don't often need this functionality, so when it's been necessary, I've resorted to creating a new object and then copying each property individually, but it always leaves me with the feeling that there is a better or more elegant way of handling the situation.  How can I clone or deep copy an object so that the cloned object can be modified without any changes being reflected in the original object? I'm stuck in the College of Winterhold questline because of a glitch between the quests "Good Intentions" and "Revealing the Unseen." After talking to the Augur of Dunlain, I return to the Archmage Savos Aren to finish the quest, and he gives me the Mage's Circlet and finishes "Good Intentions." The problem is, the next quest "Revealing the Unseen" doesn't start. He talks about Mirabelle Irvine and tells me to go talk to her, but since the quest hasn't been started, she doesn't have anything to say about the Staff of Magnus. I've tried reloading from before the quest many times and finishing it but still the same result. I've also tried doing other quests and coming back to try and finish it later, but still the next quest doesn't start. I'm on the PS3.  Anyone have a way of fixing this bug/glitch? Thanks in advance. Why is "ask" sometimes pronounced "aks"? We've recently moved from New Zealand to New York City, and have noticed that many people (most of whom have good English) pronounce "ask" as "aks". For example:     Could you please go aks her tomorrow?   Sure, I'll ax her! :-)  What's the origin/etymology of "aks"? It seems to be more common among African Americans, but it's definitely used by others too. Question about "surely" and "certainly" Today I saw a sentence:  She surely can do it.  What does that mean? How does it differ from:  She certainly can do it. Surely she can do it.  This slight difference in meaning of those sentences I am not able to notice. Could you please help me? Thanks in advance!