I have 40 mp4 files in a folder.  Every file starts with video_. Every file is of format video_*.mp4.  I need to rename all the files with video_ removed from the begining of every file. How can I do that from terminal?
One of the ways I quickly rename files in Windows is   F2 &gt; Rename &gt; Tab (to next file) &gt; Rename ...   But in Ubuntu/Nautilus, I can't tab to next file. But being on Linux, I think there must be a command line alternative.  However, sometimes, I may want more control over how to rename specific files. In that case, perhaps its better to be able to tab to the next file
When selecting a new site in the app, the user name remains displayed in the bar above.       How to reproduce:   Look at a user's profile. Click "All (number) sites" Click one of the icons that are displayed in the left.   The user name at the top remains displayed.     App Version: 1.0.89 Device Manufacturer: asus Device Model: K011   OS Version: 4.4.2 (JP_K011-JP_user_3.1.23.189_20141124-user-20141124) Why does Windows only show about 3.5 GB of my 4 GB of RAM? Possible Duplicate:          In  the following claim was mentioned:  $R/I \otimes_R M \cong M / IM$  So I tried to prove it. Can you help me finish my proof? Thanks!    We recall that $M \otimes_R -$ is a covariant right-exact functor that it is exact if $M$ is flat and we observe that the following is an exact sequence: $$ 0 \to IM \xrightarrow{i} M \xrightarrow{\pi} M / IM \to 0$$  $R/I$ is an $R$ module since $R/I$ is a subring of $R$ closed with respect to multiplication from $R$ but it is not necessarily flat hence we only get exactness on one side:  $$  (R/I) \otimes_R IM \xrightarrow{id \otimes i} (R/I) \otimes_R M \xrightarrow{id \otimes \pi} (R/I) \otimes_R M / IM \to 0$$  Then $$ \mathrm{Im(id \otimes \pi)} = (R/I) \otimes_R M / IM  \cong (R/I) \otimes_R M / \mathrm{Ker} (id \otimes i) $$  so we want to show two things:   (i) that $\mathrm{Ker} (id \otimes i) = \{0\}$. To this end let $r + I \otimes im \in (R/I) \otimes_R  IM $ and assume $ id \otimes i(r + I \otimes im ) = r + I \otimes im = 0 + I \otimes 0$. I'm not sure how to proceed from here.   (ii) and that $M /IM \cong (R/I) \otimes_R M / IM $  Can you help me? Thanks. I'm in first year. Our class is in lesson " Heat and Thermodynamics". While solving a numerical problem of a reversible engine he told us that 100 degree Celsius is equal to 100 kelvin. I inquired but could not get satisfactory answer. Pleas help me understand it.  Here is the numerical, please consider it: A reversibe engine works between two temperatures whose difference is 100c. If it absorbs 746J of heat from the source and rejects 546J to the sink, calculate the temperature of the source and the sink. Ans (100°C, 0°C) How can I propose a new site? Unknown Additional Driver: Processor microcode firmware for Intel CPUs for intel-microcode After upgrading to 15.04, I have one additional driver (it did not appear in 14.10). What is the purpose of this driver and should I enable it? Log of products to sum of logs Unchained Flurry of Blows with Natural Weapons and Feral Combat Training using natural attacks as primary Enroll Apple Developer Program under 18 I've seen a lot of questions like this throughout the web but they're mostly from 2 or 3 years ago, so I decided to ask to have some updated answers.   I'm 16 and I want to start publishing and using the benefits that comes with the Developer Program. In the legal agreement says that I should be over 18, and I'm not so, i can't do it. I've contacted the apple developer support and they told me that I should use a account in my father's name. We reside in Brazil. With that, I had some doubts:   Will the name on the App Store be mine or my father's? In the future, when I'm 18, this account can be transferred to my name?   Besides that, if someone has any advice or (legal) workaround I'd appreciate it, thanks Some months ago I posted  about exporting Sentinel 1 scenes from a collection and was successful with help from .   I now have a new region of interest, which sits on the overlap between 2 scene footprints (sequential images in descending orbit). When I make a mosaic of the 2 scenes I get a small no data gap and lack of alignment between the 2 images:  // Create a geometry representing an export region. var roi = ee.Geometry.Rectangle([-62.67, -8.31, -63.25, -8.85]); var zoomPoint = ee.Geometry.Point([-62.35, -8.06])  // Load the Sentinel-1 ImageCollection. var sentinel1 = ee.ImageCollection('COPERNICUS/S1_GRD') .filterBounds(roi);   // Filter by metadata properties. var IW_H = sentinel1  // Filter to get images with VV and VH dual polarization. .filter(ee.Filter.listContains('transmitterReceiverPolarisation', 'VV')) .filter(ee.Filter.listContains('transmitterReceiverPolarisation', 'VH'))  // Filter to get images collected in interferometric wide swath mode. .filter(ee.Filter.eq('instrumentMode', 'IW'))  // Filter IWs to get High res. .filter(ee.Filter.eq('resolution', 'H'))  // Filter IW-Highs to get 10m res .filter(ee.Filter.eq('resolution_meters', 10));  // Filter to get images from different look angles var col_desc = IW_H.filter(ee.Filter.eq('orbitProperties_pass', 'DESCENDING'));  // Spatially mosaic the images in the collection and display var col = col_desc.mosaic(); var colVV = col.select(0) Map.addLayer(colVV, {min:-17, max:-3}, "VV"); Map.centerObject(zoomPoint, 20);   What am I missing?  Are these scenes not acquired sequentially? Can't login with Stack Exchange OpenID when HTTPS-Everywhere plugin is active - apparent protocol mismatch I am trying to setup a dual screen configuration on debian 8 jessie with Gnome.  My computer has 3 graphical outputs : 2 displayport and 1 HDMI. I can't manage to have two of this 3 outputs to work simultaneously.  output of xrandr is (with the other display on displayport):  xrandr: Failed to get size of gamma for output default Screen 0: minimum 1680 x 1050, current 1680 x 1050, maximum 1680 x 1050 default connected primary 1680x1050+0+0 0mm x 0mm 1680x1050      0.00* `   output of xrandr is (with hdmi working):  xrandr: Failed to get size of gamma for output default Screen 0: minimum 1920 x 1080, current 1920 x 1080, maximum 1920 x 1080 default connected primary 1920x1080+0+0 0mm x 0mm 1920x1080      0.00*   I also tried to use both displayport but it does not work either.  output of lshw -c videò:  *-display UNCLAIMED         description: VGA compatible controller    product: Intel Corporation    vendor: Intel Corporation    physical id: 2    bus info: pci@0000:00:02.0    version: 06    width: 64 bits    clock: 33MHz    capabilities: pciexpress msi pm vga_controller bus_master cap_list    configuration: latency=0    resources: memory:f6000000-f6ffffff memory:e0000000-efffffff  ioport:f000(size=64)   (with both screens connected via displayport)  output of lspci -v -s0:0:2.0  00:02.0 VGA compatible controller: Intel Corporation Device 1912 (rev 06) (prog-if 00 [VGA controller]) Subsystem: Dell Device 06b9 Flags: bus master, fast devsel, latency 0, IRQ 255 Memory at f6000000 (64-bit, non-prefetchable) [size=16M] Memory at e0000000 (64-bit, prefetchable) [size=256M] I/O ports at f000 [size=64] Expansion ROM at &lt;unassigned&gt; [disabled] Capabilities: &lt;access denied&gt; How to create a timeline with LaTeX? Double Factorial: Number of possibilities to partition a set of $2n$ items into $n$ pairs I know that the partition of $2n$ items into $n$ pairs has something to do with double factorial, but I am not sure how many possibilities we exactly have.   We can choose such a partition into pairs by first choosing $n$ elements to be in one half and the remaining $n$ in the other half, which gives ${{2n} \choose n}$ possibilities. Then we can take a permutation of both sets and match them accordingly.   This gives $${{2n} \choose n} n! n!=\frac{(2n)! n! n!}{n! n!}=(2n)!$$ possibilities. But with this we overcount, since we do not want the pairs to be ordered. Each of the $n$ pairs is counted twice, wherefore we have to divide by 2 for every pair, hence $\frac{(2n)!}{2^n}$?   Well, another possiblity to do that is just to iteratively pick $2$ elements among the remaining ones, which gives ${{2n} \choose 2} {{2n-2} \choose 2} \dotsb {4 \choose 2}$  I am not sure, but I do not think that this is the same and also, I do not see the connection to double factorial. Would be very glad if you could help me with these 3 possiblities.   Thank you. I was just curious, why is epic a silver badge if only 73 users have been awarded with it?  For example: Silver Epic - 73  Gold Electorate - 193    Edit: My point was to reduce the level of epic, like "hit the daily reputation cap on 30 days" so it becomes some what at par with other silver badges. How to fix "Duplicate sources.list entry" warning? Every time I try to do some update (sudo apt-get update) it says:   Reading package lists ... ready W: Duplicate sources.list entry http://archive.canonical.com/ubuntu/ need /partner amd64 Packages (/var/lib/apt/lists/archive.canonical.com_ubuntu_dists_precise_partner_binary-amd64_Packages) W: Duplicate sources.list entry http://archive.canonical.com/ubuntu/ need /partner i386 Packages (/var/lib/apt/lists/archive.canonical.com_ubuntu_dists_precise_partner_binary-i386_Packages) W: You have to run apt-get update to correct these problems   sources.list:   ls /etc/apt/sources.list.d/ as requested:  milton@milton-HuronRiver-Platform:~$ ls /etc/apt/sources.list.d/ emesene-team-emesene-stable-precise.list precise-partner.list precise-partner.list.save upubuntu-com-chat-precise.list upubuntu-com-chat-precise.list.save We are getting  in M19. What if I enchant my , copying my opponents . Then I pay the cost on my Bolas (previously a Delver) to activate his transform ability.  What will happen? I can think of 3 possibilities:   My Delver is exiled and the aura goes to the graveyard. My Delver is transformed, aura goes to the graveyard, but the Delver transforms into  My Delver is transformed, aura goes to the graveyard, and the Delver transforms into How to create a Gant-Chart in LaTeX-Beamer I am trying to create a Gant-Chart in Beamer. I found the following example:   \documentclass{beamer}  \usepackage[utf8]{inputenc} \usepackage{pgfgantt}  \title{Sample title} \author{Anonymous} \institute{Overleaf} \date{2019}   \begin{document}  \frame{\titlepage} \begin{frame}{Gant-Chart}     \begin{ganttchart}[vgrid, hgrid,                         bar/.append style={fill=blue!80},                        milestone/.append style={fill=green}]{1}{15}         \gantttitle{2019}{15} \\         \gantttitlelist{1,...,15}{1} \\         \ganttbar{Task 1}{1}{2} \\         \ganttmilestone{Milestone}{7} \ganttnewline         \ganttbar{Final Task}{8}{12}     \end{ganttchart} \end{frame}    \end{document}   Now, I want to change it slightly. The first row shows the year. I want the second row to show months. And then the third row shows the number of weeks that I have planned for the task. Also, I don't want to see any arrows, but just have the rectangles. Is there a way to add a grid? Basically I want everything to just look as in an Excel-Table: Grids and then color the rectangles during which I am working.   Here is an example of what I would like to have:   Can somebody show me how to do this?   Here is another example that seems to get pretty close to what I want. Only in the week-row now it is always written "week 1", "week 2" and so on. I just want the number.   \begin{frame} \begin{figure}[h!bt]     \begin{center}         \begin{ganttchart}[             vgrid={*{6}{draw=none}, dotted},             x unit=.08cm,             y unit title=.6cm,             y unit chart=.6cm,             time slot format=isodate,             time slot format/start date=2019-02-01]{2019-02-01}{2019-07-31}             \ganttset{bar height=.6}             \gantttitlecalendar{year, month=name, week} \\             \ganttbar[bar/.append style={fill=blue}]{Task 1}{2019-02-11}{2019-02-17}\\         \end{ganttchart}     \end{center}     \caption{Time Plan} \end{figure} \end{frame} Cyclic orbit animation I'm trying to make one object orbit another. But I want it to repeat, rather than stop at 100 frames. It seems there is no option for this. Is there a way to make this happen? What is the iPod touch's screen sensitive to?