I have looked through the available HTML and JS materials in print, and online, concerning the problem of "disabling the enter key" or at least eliminating the default of submitting a form when the enter key is pressed.  My web page needs to ignore form submission until the appropriate button is pushed.  For that matter, I would like to ignore any enter key depression while inside my form. I can send code samples if needed.  I am new to this site and new to web development (Html-CSS-JS-JQ).  I am an old linear programmer so please be merciful on your explanation.  MANY thanks in advance.
How do you prevent an ENTER key press from submitting a form in a web-based application?
PHP: How do you determine every Nth iteration of a loop? Size of files in Windows OS. (It's KB or kB?) One "kilobyte" (KB) is 1024 bytes in JEDEC-standard, whereas the definition has shifted, in most contexts, to mean 1000 bytes (kB) in accordance with SI. To resolve this difference, binary prefixes (kiB) are used.  So we have 3 choices for using prefixes - JEDEC, IEC (both in Binary), and Metric (in Decimal).  My questions are-   What prefix standard does Windows use in showing the file size? (surely it's not IEC standard) Why does Windows OS show sizes of files in KB (using a capital alphabet "K") when it's a small alphabet "k" for a Kilo in SI units?   A capital "K" represents Kelvin in SI system of units.  Am I missing something here in understanding? Can Minecraft Pocket Edition play with a desktop Minecraft? My kids are playing Minecraft on 2 PCs, creative mode.  They are connected by the way of one of them starts a single player game on the other one than joins that game over the LAN.  Can I, using Minecraft PE on my iPad, join their game as well? I am to prove by induction that given that $a+1/a$ is an integer (i.e. belongs to Z  ) then $a^n+1/a^n$ is an integer too. I'm pretty much clueless here. Thanks in advance. The add comment link and comment box overlaps bounty box The following you could have seen in  (sorry, I've commented there, so you won't see it anymore) in Chrome 35.0.1916.153 m (current version). Notice how the add comment link overlaps the bounty box:    The same you can observe with a comment box on other sites, e.g. at this time in :    Could you shift it a bit down ?  It seems that it happens on more than just Stack Overflow (maybe all sites ?). Cannot install vim I am running Ubuntu 11.10, as Xubuntu, in an AMD 64 pc, configured as dual boot with Windows 7.  I tried installing vim with this:  sudo apt-get install vim   I got this error message:  The following packages have unmet dependencies:  vim : Depends: vim-common (= 2:7.3.154+hg~74503f6ee649-2ubuntu2) but 2:7.3.154+hg~74503f6ee649-2ubuntu3 is to be installed E: Unable to correct problems, you have held broken packages.   I only have a very faint idea of what the problem is, and none whatsoever on how to correct this. Hope you guys can help. I want to model this gun:  So I started to cut out the rough shapes from a cube (using the boolean modifier) Then I tried to clean up the geometry to be able to round the edges of the handguard.  But it does not work. When I try to bevel it like in the last pic top right it just gets really messy.  I think I took the wrong approach. How would you go about adding clean and workable geometry to such a piece and would you use the Bevel tool to create the round shapes? It seems that containing lava in solid glass, stone and iron blocks may not be sufficient to prevent wool from burning, even if the lava is completely encased.         After some delay, it seems that fire will jump onto the wool above the iron.   Are solid blocks more effective than airspace, or not? If so, Does it matter whether the corner block is filled in? What are the exact rules on distance that I need, and how can I prevent flammable blocks from being eliminated by nearby lava? Bonus: Does a flowing lava block behave differently than a lava source block when it comes to fire creation? Does the proof of Bolzano-Weierstrass theorem require axiom of choice? When selecting the terms of subsequence from each bisections, I thought axiom of choice might be required. But I'm not so sure whether or not, so please tell me. [edited] I'm sorry for the lack of explanation. I want to prove this statement: Let $a_1, a_2, \ldots \in \mathbf{R}$, and $(a_n)_{n\in\mathbf{N}}$ is bounded, then $(a_n)$ has some convergent subsequence.  The proof is as follows. Since $(a_n)$ is bounded, for all $n\in\mathbf{N}$,   $a_n \in I = [b, c]$.  Now, let $I_0 = I$ and if $I_n = [b_n, c_n]$,  we define $d_n = (b_n+c_n)/2$ and  if infinite terms of $(a_n)$ is included in $[b_n, d_n]$(resp. $[d_n, c_n]$), we will define  $I_{n+1} = [b_n, d_n]$(resp. $[d_n, c_n]$).If both intervals contain infinite terms, let $I_{n+1}$ be $[d_n, c_n]$. For all $n\in \mathbf{N}$, infinite numbers of $m \in \mathbf{N}$ exist such that $a_m \in I_n$ suffices. We take the sequence of natural numbers $(n(k))_{k\in\mathbf{N}}$which suffices $n(0) &lt; n(1) &lt; \cdots &lt; n(k) &lt; \cdots$ following this procedure: Now we have already selected $a_{n(1)}, \ldots, a_{n(k)}$, there are infinite numbers of $m\in \mathbf{N}$ which suffices $n(k)&lt;m, a_m \in I_{k+1}$, so let's take the minimum m out of it. Applying this process recursively, we obtain a infinite convergent subsequence(?). I think intuitively, by only repeating this process we can't obtain countable infinite terms of subsequence because we have to repeat infinite times. Embed vimeo video into the body field Help Understanding How Long It Will Take To Heat My Wire I put some alias commands in my .bashrc file, so that they might be loaded everytime I open a new Terminal window. Yet this doesn't happen. I have to select run script: in the Terminal&gt;Preferences&gt;&quot;MyDefaultTheme&quot;&gt;Shell prefpane and add: source .bashrc &amp;&amp; clear for it to work... This seems odd since many tutorials only say you just have to add to the .bashrc file and all is good. Note that I don't run in bash when using the terminal, I like the other (default) one (don't know what it is) better, because it show me where I am all the time eg: &gt;&gt;d54c6b47b:~ romeo$  in stead of: &gt;&gt;bash$  In bash all is loaded as should be. So my question is, why didn't my .bashrc file load automatically and did I have to add the option to call it everytime? Also some tutorial told me to do something like: $alias la=’ls -la’ &gt;&gt; ~/.bashrc  which should write the alias to my .bashrc, this doesn't work either... Note that I'm a UNIX novice, so be gentle. I've had my HTC Desire for a couple of months now and it is awesome! (A huge improvement to my previous phone... Nokia 3315)  Though recently, I've realised that the phone semi-freezes more and more often - ie. when swiping between homescreens it will either pause/freeze and I will have to re-swipe to get it to change screens. Or worse, it just won't respond to any further swipes and I have to lock the screen then unlock to get the phone back into action.  Got quite annoyed at this (was probably happening once or twice a day) so I thought it might help to turn it off and on again. So I did - not sure if it was a placebo effect but it seems to have helped a bit?  So given that this is my first smartphone, I was wondering if it is 'normal' to need to restart the phone every so often. If so, how often is 'normal'? If not, what can I do to diagnose/fix this problem? How to get battery status? How do I get the battery status on an iPhone? How to make an ImageView with rounded corners? Non-perpendicular hyperplane decision trees The usual implementation of decision trees, and estimators based on ensembles of decision trees, use decision trees that threshold on a single predictor at each split. So they divide the feature space into perpendicular hyperlanes.  Is there any benefit to generalizing this a tiny bit. So at each split, the decision tree uses 2 features, and thresholds based on whether $ax_1 + bx_2 \ge T$. In other words, the feature space is now getting divided into hyperplanes that are not necessarily perpendicular.   I think the main disadvantages would be:    increased computation, and  overfitting since now using more degrees of freedom   I guess to help both of these issues, randomization could be used analogous to extra trees. The pair of features could be randomly selected, instead of exhaustively trying every pair, and the threshold T and parameters a and b could be chosen randomly as well (perhaps from a set of few discrete values such that the hyperplanes could have a few orientations).  Are there some cases where you think these non-perpendicular decision trees would be an improvement over the regular implementation of various decision tree algorithms? Error with square bracket in table continuous function: preimage of closure of a set is closure of preimage Trigonometry and algebra question Given:   The total length of ad + dc The lengths of each ab, bc and ca That angle adb = angle cdb   How can I work out lengths ad and cd How can I recover photo files from a memory card with a corrupt filesystem?