I read the answer on the link on how to add transparent images on top of materials ( ). This works beautifully in v2.79b.    This technique does not seem to work in Blender 2.80 anymore (I am using the very latest Mac version from Dec 20). The transparent image is also shown on the part of the mesh, which is not UV unwrapped. Is this a bug in v2.80? Or does v2.80 require a different approach?    What is really odd is the fact, that if I open in v2.80 a file created in v2.79 created, it shows up correctly.    Thanks for any advice! Chris  Edits: screenshots and link to blender files added
I'm designing this animal-type creature, and want to add a transparent .png image to its face with the face features (object has a subsurf). On the left is the image with the features, on the right is the part of the object where I want it to be.    I tried to import the image as a plane, but matching the shape of the plane with the face didn't work, and the lines of the face left shadows on the head, and could be seen as a different object from some angles (although it's the closest I've gotten yet). It looked like this:    So , I tried selecting the faces of the head that the features should go over, and create a new material for it. Unfortunately, since the .png is transparent, the result produced was this:    (where it's impossible to tell the transparency from a black background default color, and where I wouldn't know where to start to adjust size and position).  I also tried UV mapping, but then the whole object became black with the features repeated all over.   Is it something I have to go into Nodes for? I'm kind of stuck here. Creating a new material and applying it is simple, but applying a material that is an image is a bit more complex it seems... Ideally, I would reproduce the same technique for the adhesive bandage on its arm (seen on the right of image 1).
Why $(a+d)(b+c)$ equals $-16$? If $a,b,c$ and $d$ satisfy the equations:$$a+7b+3c+5d=0$$$$8a+4b+6c+2d=-16$$$$2a+6b+4c+8d=16$$$$5a+3b+7c+d=-16$$ then $(a+d)(b+c)$ equals $-16$.   I can't understand why $(a+d)(b+c)$ equals $-16$? I'm trying to make a logo that will be on the header of a website. What I'd like to achieve, and the reason I'm using Blender, is the projected shadows on the background looking perfectly real (as opposed to doing a drop-shadow in Photoshop).  The only thing is, the background has to be transparent because the website might use different background colors / gradients that make it impossible to match with the exported 3D background.  I made this dummy file (not the real logo... duh!):    If I use the file as is, the grey borders of the image will be impossible to match with the website's background color.  Here what I want:    So obviously, I tried masking the plane, which made the shadows disappear. I tried having a plane set to glass, which didn't work either.  And I looked around for a similar question, but didn't find one.   I am not trying to render , or a . I've seen  which has a very difficult solution to this problem, and  that is very similar but in Blender Internal.  is similar too but has never been solved. I'm only a beginner at Compositor, and I'm trying to learn more any chance I get, so any solution in Compositor is welcome if detailed enough. Although if there's a simpler or faster way, it's welcome too!  .blend file: How to skip kernel update? Bad Character code (256)/ \select@language{greek} Tips for getting latte or soda out of your keyboard? This is a homework problem and I'm having trouble just getting a basic understanding.  I understand that $S_6$ is a symmetric group of degree $6$.  I'm not sure how to start looking for elements. Algorithms for computing multiplicative order modulo $n$ If I take the $k \in \mathbb{N}$ power of 10 and mod it by a large prime, I notice that the remainders repeat at some point.  For instance $10^k mod~7$ seems to repeat every $8$th value of $k$.  Given $k$ (the power of ten), and a large prime number $p$, how can I compute the size of the cycle?  I tried writing a python script that computes the first instance of a repeat. However, I don't know if this works since a single instance of a repeat may not necessarily mean a full cycle. How to use Stokes theorem in the presence of holes? How do I run .sh scripts? why do chaperones bring protein into mitochondria? why would mitochondria need protein? Sounds trivial? Please help to sort out. I saw this picture while looking at dehydration reactions and cell revision.     And proceeded to the       Protein Folding and Processing in the ER: Various changes occur to proteins in the ER.   Chaperones and Folding: Polypeptides must assume the correct folding pattern in order to function properly. The correct folding of a protein is mediated by chaperones (they also are proteins--chaperones are abundant in the ER lumen). A completed polypeptide will assume the correct folding pattern spontaneously, however before translation is complete, it could assume an incorrect formation or it could aggregate with other partially made polypeptides. To prevent this, chaperones in the ER (and cytosol) bind to the nascent polypeptide and keep it from interacting with anything until the polypeptide is completely synthesized. (Chaperones bind to polypeptides destined for mitochondria then release them as they pass through the mitochondrial membranes. Chaperones on the inside of mitochondria bind until these polypeptides have completely entered.)   With regards to protein synthesis and folding, this kind of info is not in my textbook. Not in couple of the online open textbooks either. I even search for where do protein fold? to find out if there was a relationship. It doesn't say protein fold in mitochondria and turns out it's a question most scientist are looking for answers.  For whatever protein synthesis I have learnt so far, there was no mentioning of protein strands going into mitochondria but mitochondria as a power houses. What's going on here?   Why would a protein go into a mitochondria? How does it exit and where to? What can I actually do with a high credit score? I recently checked my credit score via two of my credit card providers. It seems to be hovering between 790 and 815. One service brands the score it provides as a FICO score and the other specifically says its score comes from Transunion.   What can I actually do to leverage this high credit score to my advantage?  The only new debt I might take on would be a small HELOC or car loan. Does a high score give me any negotiating power with the lender to get a better rate? Should I treat the score as a card in my hand or is it something I should show early in negotiations?  Does a high score make me eligible for any discounts on insurance?  Does a high score open up any options for earning more interest on savings accounts?  The typical advice I'm reading suggests refinancing a mortgage. That seems like good advice in general but it does not apply to my personal circumstances. I've got 3.5% on a 15 year note with 9 years left. A casual review of current rates suggest I could maybe scrape 0.5% off of that, hardly seems worth the effort and cost for half a percent. Distribution of a ratio of uniforms: What is wrong? Suppose that  $X$ and $Y$ are two i.i.d. uniform random variables on the interval $[0,1]$  Let $Z=X/Y$, I am finding the cdf of $Z$, i.e. $ \Pr(Z\leq z) $.  Now, I came up with two ways of doing this. One produces a correct answer consistent with the pdf here: , the other does not. Why is the second method wrong?  First Method  $\newcommand{\rd}{\mathrm{d}} \Pr(Z\leq z) = \Pr(X/Y\leq z) = \Pr(X\leq zY) = \int^{1}_{0}\int^{\min(1,zy)}_{0} \rd x \rd y = \int^{1}_{0}\min(1,zy)\ \rd y$ $  = \left\{      \begin{array}{lr}        \int^{1/z}_{0}zy\ \rd y + \int^{1}_{1/z} \rd y&amp; : z &gt; 1\\        \int^{1}_{0}zy\ \rd y &amp; : z \leq 1      \end{array}    \right. $ $  = \left\{      \begin{array}{lr}        1 - \frac{1}{2z} &amp; : z &gt; 1\\        \frac{z}{2} &amp; : z \leq 1      \end{array}    \right. $  This appears correct.  Second Method  $\Pr(X/Y\leq z) = \Pr(X \leq zY\ |\ zY \geq 1)\Pr(zY \geq 1) + \Pr(X \leq zY\ |\ zY &lt; 1)\Pr(zY &lt; 1) $ by total probability  $ = \Pr(X \leq zY\ |\ zY \geq 1)\Pr(Y \geq 1/z) + \Pr(X \leq zY\ |\ zY &lt; 1)\Pr(Y &lt; 1/z)$  Taking $z&gt;1$ yields $ (1)(1-\frac{1}{z}) + (\int^{1/z}_{0}\int^{zy}_{0} \rd x \rd y)(\frac{1}{z}) = 1-\frac{1}{z} + (\int^{1/z}_{0}zy\ \rd y)(\frac{1}{z}) = 1-\frac{1}{z} + \frac{1}{2z^{2}}$  This is already different. Why is this wrong?  Thanks! I'm new to blender and have this issue: I'm using the "Industry Compatible" keymap. In "Edit Mode" the keys 1, 2 and 3 swap between vertex, edge and face select - Great!  Now i want to customize it, so i'm adding a new preset "My keymap". As far as i understand this now is based on the "Industry Compatible" keympap and everything works accordingly. But if i close and start blender again, the 1, 2 and 3-key aren't working anymore. I need to go back to the preferences, set the "Industry Compatible" keymap and then set back to "My keymap". Then the 1, 2 and 3-key work again as expected.  This is reproduceable on the last Blender 2.8 version on several different machines. Am i doing something wrong? Is this a bug? Setting git default flags on commands How to make pages metabox display all hierarchy in menu admin? Running WP 3.9.1  I've got lots of pages and sub pages.  When I get to create menu lots of sub pages doesn't display on the right level, but some do?    The pages metabox should display something more like this    EDIT  Number in screenshot are a bit screwed sorry about that.   The problem is after the first few all the pages are displayed on the same level but they shouldn't.  It should look like this       Page 1                      SubPage A of Page 1             SubPage B of Page 1                                      SubPage 1 of SubPage B                     SubPage 2 of SubPage B                     SubPage 3 of SubPage B                                                 Page 2                      SubPage A of Page 2                                      SubPage 1 of SubPage A                     SubPage 2 of SubPage A                                           SubPage B of Page 2                                      SubPage 1 of SubPage B                     SubPage 2 of SubPage B                                               ...    Any idea what cause this or how to fix it, so i can manage my menu? For a workflow tool I made a panel in which it displays each separate library that is linked in my file. For each library I want to add some buttons that does stuff to the library in question.  So in this example I have my panel which shows for example 2 libraries and for each one it creates a "reload" button.  Now my question is.. How do I make it so the reload button only reloads the library I want to reload? I would probably have to give the button an id or something so it knows for which library it was created...  my code so far:  import bpy  libs = bpy.data.libraries  class Reloadlib(bpy.types.Operator):     """Reloads the current Library"""     bl_idname = "my.reload_lib"     bl_label = "Reload"      def execute(self, context):         libs[?????].reload()         self.report({'INFO'}, 'Reloading ' + libs[?????].name)         return {'FINISHED'}  class LibPanel(bpy.types.Panel):     """Creates a Panel in the scene context of the properties editor"""     bl_label = "Scene Libraries"     bl_idname = "SCENE_PT_layout"     bl_space_type = 'PROPERTIES'     bl_region_type = 'WINDOW'     bl_context = "scene"      def draw(self, context):         layout = self.layout         scene = context.scene         layout.label(text="Libraries:")          for i in libs:             layout.label(text= i.name.replace(".blend",""))             row = layout.row()             sub = row.row()             sub.operator("my.reload_xref", icon = "FILE_REFRESH")  def register():     bpy.utils.register_class(Reloadlib)     bpy.utils.register_class(LibPanel)  def unregister():     bpy.utils.unregister_class(Reloadlib)     bpy.utils.unregister_class(LibPanel)  if __name__ == "__main__":     register()   Where the question marks are is where I should be able to make the difference between the first [0] or second [1] library in the libs[] array.  In future I would also like to ad an 'open' and an 'unlink' button for each library so I can make changes to the other file. But this works by the same principle as the reload button. Is it possible to "hack" a MacBook so as to be able to install macOS Mojave? Can Cycles physically mix colours? Apply empty style to the entire bibliography How do I press Ctrl+Alt+Delete in VirtualBox? I'm running VirtualBox with Windows Vista as host OS and Windows Server 2008 as guest OS. To login to Windows Server I have to press Ctrl+Alt+Delete, but my host OS reacts on that so I can not send it to VirtualBox. How can I do it?