Im working on a website and my boss wants me to use CSS variations and I dont know what he is talking about.  Let's say I have 20 different elements using #7d2d39, rather than having:  background-color:#7d2d39 color="#7d2d39"   All over the style sheets he wants me to call it using:  background-color:red1" color="red1"   and somewhere define what "red1" is that way we can globally change one hex color vs. changing it 20 times? It makes sense as I type it, but I dont think this exists.
Possible Duplicate:          We have some "theme colors" that are reused in our CSS sheet.  Is there a way to set a variable and then reuse it?  E.g.  .css OurColor: Blue  H1 {   color:OurColor; }
Let $F$ be a field and $F[x]$ a polynomial ring. Let $p(x)$ be an irreducible polynomial.  Show that $\gcd(p(x),q(x)) = 1\Longrightarrow \exists r(x),s(x)$ such that $r(x)p(x)+s(x)q(x) = 1$.  I know the proof for Bezout's identity for , but this proof uses the notion of absolute value, which cannot be applied to a polynomial ring.   I am thinking about a way to prove the statement: Use the Euclidean algorithm to compute $\gcd(p(x),q(x))$ and show that the result is $1$, and somehow go backwards to obtain $r(x)p(x)+s(x)q(x) = 1$, but it is a bit messy, and I'm not yet able to see it completely.  Please offer some help. If you have some other methods, that would be great, too. Are research survey questions expected to be handled with close votes? How to prove that a set is invariant? Can I preemptively pay my credit card bill before a charge is posted? Why is it important to apply transformation to an objects data? Smart Phone's camera socket Is there a more accurate way to create a Javascript timer than setTimeout? Prove that if $(ab)^i = a^ib^i \forall a,b\in G$ for three consecutive integers $i$ then G is abelian I have a simple question answer to which would help me more deeply understand the concept of (non)commutative structures. Let's take for example (our teacher's definition of) a ring:  Let $R\neq \emptyset$ be a set, let $\oplus:A\times A \to A$ and $\bullet :A\times A \to A$ be binary operations. Moreover, let $(R, \oplus)$ be a commutative group, $(R, \bullet)$ be a monoid and following property holds for all $a, b, c\in R$: $$a\bullet(b\oplus c) = (a\bullet b)\oplus(a \bullet c)$$ $$(b\oplus c)\bullet a = (b\bullet a)\oplus(c \bullet a)$$ Then ordered triple $\mathbf R = (R, \oplus, \bullet \mathbf)$ is called a (unitary) ring.  Moreover, we call ring $\mathbf R$ commutative iff $(R, \bullet)$ is a commutative monoid. Commutativity of a ring is always a matter of its multiplicative operation because the additive operation is always assumed to be commutative.  Could anyone explain me the bold part? Why do we even in non-commutative rings (and fields etc.) assume the addition to be always commutative? Is there some serious reason? Would it make any trouble? Or studying of structures with non-commutative addition just doesn't give us anything new so we can take addition as commutative simply because of our comfort? How do I choose between "while" and "whilst"? When should whilst be used instead of while?  For example, should I use the first or the second sentence?      They don't do this whilst they do that.   They don't do this while they do that.   Which would be correct? I mean are we certain that they will be able to provide us a huge improvements (in some tasks) compared to clasical computers? For instance if me and my friend had a Pidgeot and we powered them all the way up. Could mine end up with like 525 and his at like 500? Show that $\lim_{x \to +\infty}\left(f(x)+f'(x)\right)=0 \Rightarrow \lim_{x \to +\infty} f(x)=0$ How to show that $\lim_{x \to +\infty}(f(x)+f'(x))=0 $ implies $\lim_{x \to +\infty} f(x)=0$? SFDX Pull error: Entity of type 'ListView' named XXX cannot be found While trying to pull changes from a scratch org (sfdx force:source:pull, tried with and without -f), I'm getting this error:     Entity of type 'ListView' named 'Note_Relation__c.My_Notes' cannot be found.   I do have a custom object Note_Relation__c, and it exists both locally and in the scratch org.  However, it's not an object that is normally accessed directly.  It has no tab, and should have no list views.  Nonetheless, I've checked the object's list view (via prefix, e.g., /a0D in both Classic and LEX view), and I can find no list views at all.  I've also tried adding an entry to .forceignore:  force-app/main/default/objects/Note_Relation__c/listViews/My_Notes.listView   This has no effect either.  At this point, I'm stuck with a bunch of config changes in a scratch org that I cannot pull.  I can find no references to this error message with scratch orgs.  Has anyone seen this issue?  Edit to clarify: I tried the .forceignore line based on what I think the file name should be; I have no force-app/main/default/objects/Note_Relation__c/listViews directory locally.  Edit 2: Workaround:  I found a workaround that doesn't make sense to me, but it works.  I'm not adding it as an answer yet because I'm not sure what's happening.  The workaround is to add the following line to .forceignore  Note_Relation__c.My_Notes   Even though this isn't a DX filepath, it's the name from the error message, and it seems to work. How to derive variance-covariance matrix of coefficients in linear regression I've checked  for acute:  an acute illness is one that has quickly become severe and dangerous Compare:CHRONIC  And for chronic:  lasting for a long time Compare:ACUTE  Can a disease be both &quot;acute&quot; and &quot;chronic&quot; simultaneously? For example it could be the case where a certain illness quickly becomes serious and have long term consequences Are there any &quot;obtuse illnesses&quot; ? Here is the problem: From any IP address not belonging to your mail server:  telnet me.myemailserver.com 25    helo me.someserver.com mail from: &lt;yourusername@mydomain.com&gt; rcpt to: &lt;yourusername@mydomain.com&gt; data This is spam.  Buy my stuff. .   I'm using Postfix.  I'm having a problem finding a solution to requiring SMTP-AUTH for email claiming to be from mydomain.com.  Googling around, this guy has identified the same problem (where I cut-n-paste with some modifications) the above example from:   This link   gets close to a solution but it has a side effect of requiring SMTP-AUTH for mail not from mydomain.com.  For mail not claiming to be from mydomain.com, I would do the usual RBL and Spam filtering.  In short, I want to reject mail to local domains (mydomain.com) from outside/unauthenticated clients claiming to be from local domains (mydomain.com).  This is what I tried: I've tried both permit and reject as the default.  Here is exact excerpt from my main.cf:  smtpd_recipient_restrictions = reject_unauth_pipelining,                            permit_sasl_authenticated,                            check_recipient_access pgsql:/etc/postfix/pgsql-recipient.cf,                            reject_unauthenticated_sender_login_mismatch,                            reject_unauth_destination,                            reject_unlisted_recipient,                            check_sender_access pgsql:/etc/postfix/pgsql-sender.cf,                            reject_unlisted_sender,                            reject_invalid_hostname,                            reject_non_fqdn_hostname,                            reject_non_fqdn_sender,                            reject_non_fqdn_recipient,                            reject_unknown_sender_domain,                            reject_unknown_recipient_domain,                            reject_rbl_client cbl.abuseat.org,                            reject_rbl_client sbl.spamhaus.org,                            reject_rbl_client sbl-xbl.spamhaus.org,                            reject_rbl_client bl.spamcop.net,                            reject_rbl_client dnsbl.njabl.org,                            reject_rbl_client blackholes.wirehub.net,                            reject_rbl_client relays.mail-abuse.org,                            reject_rbl_client dialups.mail-abuse.org,                            reject_rbl_client blackholes.mail-abuse.org,                            reject_rhsbl_sender dsn.rfc-ignorant.org,                            (reject and permit both tried here) How can you move a document with its version history to a new library? Here's the scenario:  2 document libraries Both contain multiple documents The documents have multiple versions  When I copy a document from library A to Library B using the Content and Structure tool from Site Settings, my versions do not carry over. I'm trying to merge the two document libraries into one, but I want to retain the versions. Do you know of a way to complete this without third party tools or custom code? I've heard suggestions of using Explorer View copy and paste, SharePoint Designer and List Templates, but I'm not sure any of those will carry version info. Modern solution For modern SharePoint experiences, use Move To. Update 4/24/2018: There's a new solution in Office 365. You can now select a file or group of files in the modern experience in OneDrive or SharePoint and select Move to. A file or group of files moved this way will retain version history. Update 6/6/2021: As @KJH mentioned in a comment, you may not see the modern experience unless you . Also, there's more detail now in the Microsoft article . Do Cleric's domain spells add slots? I'm a little bit confused with the whole spell system and additions to them. If I pick for instance Tempest Domain Spell, are the spells additional to the other ones? (2 at level 1) So do that make it 3 spells? Does the domain add slots too?  And also, I've read about people choosing multiple domains, is that possible? How to encrypt folders (not in Home)? Is there a way to encrypt a folder, which is not in Home (/home/user/) but even in a different partition, so only my user can access/read contained files?  Alternatively, I would like to understand if it is possible to turn a complete ext4 partition into an encrypted volume, which would be mounted at user login.  If possible, I would like to make the change without reinstalling Ubuntu.  My PC has (mount output):  /dev/sda1 on / type ext4 (rw,errors=remount-ro) /dev/sda3 on /home type ext4 (rw) /dev/sda4 on /home/igor/Personale type ext4 (rw)   sda4 is the partition containing folders I would like to protect.