Why does vim complain "no version information available" for libtinfo? Every time I run vim, it opens successfully but outputs the error message vim: /usr/lib/libtinfo.so.6: no version information available (required by vim). I already have libtinfo installed: ➜  repo ls -l /usr/lib/libtinfo.so.6 lrwxrwxrwx 1 root root 16  2月 13  2020 /usr/lib/libtinfo.so.6 -&gt; libncursesw.so.6  but the message still pops out every time. My question is: How do I fix it? Why is the message shown?
Why does LD keep outputting "no version information available" On every loading of a lib, I get the error:     no version information available   This lib has been compiled on another PC (ubuntu 10.04) than the one running it (mandriva 2010.2).  $ ldd /usr/local/gnu-eabi-4.5.2/i686-pc-linux-gnu/arm-eabi/lib/libbfd-2.21.so /usr/local/gnu-eabi-4.5.2/i686-pc-linux-gnu/arm-eabi/lib/libbfd-2.21.so: /lib/libz.so.1: no version information available (required by /usr/local/gnu-eabi-4.5.2/i686-pc-linux-gnu/arm-eabi/lib/libbfd-2.21.so)  linux-gate.so.1 =&gt;  (0xffffe000)  libz.so.1 =&gt; /lib/libz.so.1 (0xb77a7000)  libc.so.6 =&gt; /lib/i686/libc.so.6 (0xb7655000)  /lib/ld-linux.so.2 (0xb787a000)   Edit: the workaround didn't work.
What makes a chewy brownie? I've tried many different brownie recipes and most of mine bake to a cake-like consistency. The brownie holy grail for me is crusty top chewy brownies. What can I add/remove/do that will make my brownies chewier? Live USB data gets lost on Restart I am crawling some data using Apache Nutch and storing it on my USB Drive. The OS itself is Ubuntu Live Boot OS. But for every restart or shutdown I am losing my data. I also tried suspending my Ubuntu user still data was not visible when I reinserted my live USB.  Is there any way I can keep the data intact and does not loose and application settings installations when I do restart Ubuntu.  Used USB installer provided by pendrivelinux.com at In Oracle, I can re-create a view with a single statement, as shown here:  CREATE OR REPLACE VIEW MY_VIEW AS SELECT SOME_FIELD FROM SOME_TABLE WHERE SOME_CONDITIONS   As the syntax implies, this will drop the old view and re-create it with whatever definition I've given.  Is there an equivalent in MSSQL (SQL Server 2005 or later) that will do the same thing? Should I vary input field lengths in a single page checkout form? How to do research in two very different fields? How do you make the camera in blender cycles render everything so it looks like pixels? I want everything in my scene to look pixelly like this image I found: Apache on CentOS 5.9 VM serves modified files incorrectly I have been there first time.   The reason why I think this might not be natural is that the expression "first time" seems to describe "past". You do not use the present perfect with an adverb indicating "past", in my understanding.  However, I feel the phrase below is not that funny.     This is the first time that I have been there.   I am wondering about the relationship between "the first time" and "I have been there". "That" could behave like a relative adverb. If that is the case, the antecedent of "that"—"the first time"—is shared with the following clause: "I have been there". Then, is it OK to say "I have been there first time"?  By the way, Google searches for "" and " in the UK domain show just 33 hits for the first phrase and 10 hits for the second. How can I check the SMART status of a SSD or HDD on current versions of Ubuntu 14.04 through 20.04? How can I check the SMART status of a drive under 14.04 and beyond? I've seen  but it doesn't seem to apply under 14.04 and later. "Give him a box that everyone knows what it contains." "Give him a box that everyone knows what it contains."  Is this correct English? It sounds wrong to me. How do I recover my accidentally lost Windows partitions after installing Ubuntu? I have a Toshiba satellite A-200 laptop with a Vista OS on it with 4 NTFS partitions  (C:) Vista  (D:) Entertainment  (E:) Work  (F:) Sources   and I wanted to start using Ubuntu instead. So I tried it first from the live CD and everything was OK and all the partitions were shown and working and so I decided to install Ubuntu to replace Vista on the (C:) drive. After I did that I can no longer find my folders and files on the (D:), (E:), (F:) partitions and the only file system that is shown is one 198 GB although my HDD is 320 GB.  I can't access the lost data on the remaining 120 GB which I hope is still there and not totally lost  I am now working from the live CD but I am unable to install testdisk. Can I recover the Vista partitions by the product recovery CD to get my laptop back to the factory settings? Can I recover the NTFS partitions using a recovery program for Windows or will that make the problem worse?   I need these data badly as I don't have a backup for them. Let $a,b,c\in\mathbb{R}$ such that $\sqrt{a^2+b^2}=1&lt;c$.  Find $I:=\int_{0}^{2\pi} \frac{1}{a\cos(t)+b\sin(t)+c}dt$.  So, I set $z=e^{it}$ and then $dz=ie^{it}dt$ and so $\frac{dz}{iz}=dt$. Therefore,  $\begin{align*} I &amp; =\frac{1}{i}\int_{|z|=1} \frac{dz/z}{a\cdot\frac{z+z^{-1}}{2}+b\cdot\frac{z-z^{-1}}{2i}+c} \newline &amp;=\frac{2}{i}\int_{|z|=1} \frac{dz}{a\cdot(z^2+1)-ib\cdot(z^2-1)+2cz} \newline &amp;=\frac{2}{i}\int_{|z|=1} \frac{dz}{(a-ib)z^2+2cz+a+ib}\newline &amp;= \frac{2}{i}\int_{|z|=1} \frac{dz}{(z-z_+)(z-z_-)}\end{align*}$  Where $z_{\pm}=\frac{-2c\ \pm\ \sqrt{4c^2-4(a+ib)(a-ib)}}{2(a-ib)}=\frac{-c\ \pm\ \sqrt{c^2-(a^2+b^2)}}{(a-ib)}=\frac{-c\ \pm\ \sqrt{c^2-1}}{(a-ib)}$.  Therefore, if we define $f(z)=\frac{1}{z-z_-}$, we get that $f$ is analytic in $\{z:|z|\leq 1\}$ since  $$|z_-|=\Bigg|\frac{-c-\sqrt{c^2-1}}{a-ib}\Bigg|=\bigg|c+\sqrt{c^2-1}\bigg|&gt;|c|&gt;1$$  Finally from Cauchy's Integral Formula:  $$I=\frac{2}{i}\cdot 2\pi i\cdot f(z_+)=4\pi \frac{1}{z_+-z_-}=\frac{2\pi(a-ib)}{\sqrt{c^2-1}}$$ Which is not always real... So my question is what is the problem.  Moreover, sometimes it is correct, e.g. $a=1,b=0,c=2$ gives the correct answer $\frac{2\pi}{\sqrt{3}}$. Suppose you have an object with zero for the value of all the derivatives of position. In order to get the object moving you would need to increase the value of the velocity from zero to some finite value. A change is velocity is acceleration, so the value of the acceleration would have to increase from zero to some value. You would also need to increase the jerk from zero to some value to have a change in acceleration.  Is there an infinite series of higher derivatives of position for this to work? Or am I missing something? There is no continuous injective function $f:\mathbb{R}^n\longrightarrow\mathbb{R}^m$ I have the following question, more general that   Let $U\subset\mathbb{R}^n$ be a domain. If $f:U\longrightarrow\mathbb{R}^m$  ($m&lt; n$) is a continuous function, how to prove that $f$ is not injective.  Any hint would be appreciated. Buster Blader the DDS did not affect Destiny Hero - Decider effect; why so? How come  with  set to dragons didn't stop 's effect from being activated? How to validate an email address in JavaScript Close popup doesn't appear after editing the question without refreshing the page Seems like a bug:  The user:   Edits a question Then, he decide to close it. Clicks on the Close button. The popup doesn't appear. Refreshes the page. Click on the close button. The popup appears.   After editing in the link appears a hash: #. But I don't think that this is the problem because if I add the hash without editing the close popup appears.  It's minor, but I think that is good to be reported and solved.  Edit: The close popup doesn't open after we click an edit has been made to this post; click to load. I want to prove or disprove this problem: If there exist $\lim\limits_{x\rightarrow \infty} (f'(x)+f(x))=L&lt;\infty$ then $\lim\limits_{x\rightarrow\infty} f(x) =L$.  When I assume problem below:  If there exist $\lim\limits_{x\rightarrow\infty} (f'(x)+f(x)) =L&lt;\infty$, There exists $\lim\limits_{x\rightarrow\infty} f(x)$?  I can use mean-value theorem to show that.  So my question is:     If $\lim\limits_{x\rightarrow\infty} (f'(x)+f(x))=L&lt;\infty$, does $\lim\limits_{x\rightarrow\infty} f(x)$ exist? Definitions of connected space I have seen several definitions of connected space, but I would like to discuss those from . I am concerned about these:  $X$ is disconnected, if it is the union of two disjoint nonempty open sets.  What about $[0,1] \cup [2,3] $ ? It is not the union of two disjoint nonempty open sets, so it is connected?  $X$ is connected, when it cannot be divided into two disjoint nonempty closed sets.  What about $(0,1) \cup (2,3) $ ? It cannot be divided into two disjoint nonempty closed sets, so it is connected?   Maybe I don't understand what "divided" means. How do I turn off the arrow for desktop icons?