I have been working on a festival lantern for some hours and i had some different meshes in the blender project. Because i was going to use this in my unreal engine 4 project i had to join them together but after i selected every mesh and clicked on join, the mesh turned dark. In Unreal Engine its looking weird and the mesh is only rendering from one side.  Before i joined the meshes  After i joined the meshes.  In Unreal engine 4 (The part above the lantern is not correctly rendered.) Could somebody help me solving this problem?
While rendering a mesh with smooth shading on, I get a dark region/shadow on certain faces. The effect is more evident when smooth shading is applied to a mesh containing ngons, with the ngons turning black when rendered.   The blackening effect is visible in the viewport too.  How can I solve this problem?
Convert String to Integer in QGIS tables Why was Dumbledore worried by the cut in Harry's arm? Another word for a troll not on the internet The definition of an internet troll:     In Internet slang, a troll (/ˈtroʊl/, /ˈtrɒl/) is a person who sows   discord on the Internet by starting arguments or upsetting people,   by posting inflammatory,[2] extraneous, or off-topic messages in an   online community (such as a forum, chat room, or blog), either   accidentally[3][4] or with the deliberate intent of provoking readers   into an emotional response[5] or of otherwise disrupting normal   on-topic discussion.[6]      This sense of the word troll and its associated verb trolling are   associated with Internet discourse, but have been used more widely.   Media attention in recent years has equated trolling with online   harassment. For example, mass media has used troll to describe "a   person who defaces Internet tribute sites with the aim of causing   grief to families."[7][8]     What is the equivalent for a person who does this type of thing in real life (non-cyber) troll? Name of short sci-fi story involving a musician who is punished for listening to Bach I read a short story a long time ago and I can neither remember the title nor the author.  The main character is a musician.  He is sequestered and allowed to play all day on some kind of a fantastic instrument; however, he has been barred from listening to any music for fear that it will stifle with his innate creativity.  Someone secretes him some Bach, he listens to it, and is then caught and cast out.  He gets a series of jobs and is inevitably punished for breaking some music-related taboo.  Any ideas? How to find correctly the .bib file? /review tab not accessible on a private beta $n!+1$ being a perfect square One observes that  \begin{equation*} 4!+1 =25=5^{2},~5!+1=121=11^{2}  \end{equation*} is a perfect square. Similarly for $n=7$ also we see that $n!+1$ is a perfect square. So one can ask the truth of this question:   Is $n!+1$ a perfect square for infinitely many $n$? If yes, then how to prove. I am trying to use following apex class with invocable method but its not showing in process builder.  global with sharing class SlackOpportunityPublisher {      private static final String slackURL = 'https://testsalesforceapps.slack.com/';      global class Oppty {         @InvocableVariable(label='Opportunity Name')         global String opptyName;         @InvocableVariable(label='Stage')         global String stage;     }      @InvocableMethod(label='Post to Slack')     global static void postToSlack(List&lt;Oppty&gt; oppties) {         Oppty o = oppties[0]; // If bulk, only post first to avoid overloading Slack channel         Map&lt;String,Object&gt; msg = new Map&lt;String,Object&gt;();         msg.put('text', 'The following opportunity has changed:\n' + o.opptyName + '\nNew Stage: *' + o.stage + '*');         msg.put('mrkdwn', true);         String body = JSON.serialize(msg);             System.enqueueJob(new QueueableSlackCall(slackURL, 'POST', body));     }      global class QueueableSlackCall implements System.Queueable, Database.AllowsCallouts {          private final String url;         private final String method;         private final String body;          global QueueableSlackCall(String url, String method, String body) {             this.url = url;             this.method = method;             this.body = body;         }          global void execute(System.QueueableContext ctx) {             HttpRequest req = new HttpRequest();             req.setEndpoint(url);             req.setMethod(method);             req.setBody(body);             Http http = new Http();             HttpResponse res = http.send(req);         }      }  } Inverse public-key encryption I'm in the need of an inverse public-key encryption method where you encrypt with the private key and decrypt with the public key. In other words an asymetric encryption where you can't generate the encryption key from the decryption key. Does such encryption exist? If yes which, and which would be the fastest?  If nothing like that exists I would be glad if you helped me out with my situation:    I need to authenticate users logging in from my Java application in the way that the response from the server cannot be falsified and thus giving the user full access to the application. Using public key encryption was an obvious method, I would decrypt data received from the client to confirm the credentials. This won't work because if someone manages to decompile and get the private key from the code, they would be able to generate the public key, which would make them able to crack my application again. So any ideas how I can get this secure? What is the word for the emotion I feel when I see someone being humiliated? When I see someone else being embarrassed / humiliated, for example a singer forgetting their words in a concert, I would say something like "I feel embarrassed for them". But is there a better word to describe this feeling?  I would say it's a mix of:   Empathetic discomfort for someone else's humiliation Tension; hope that spectators will be forgiving Frustration that I cannot help them   Other scenarios I would feel the same emotion:   Seeing someone make a presentation, the slides are all out of order, and their face gets red with embarrassment while there's a tense silence in the room. Seeing someone make an embarrassing social blunder in front of unforgiving people. Seeing a speaker who keeps making a distracting and annoying gesture, and they don't realize that the whole audience is annoyed. Seeing someone be taken advantage of, like seeing someone naively and happily accept a terrible offer on a car. Seeing a person of strong image (for example the CEO of your company) do something like accidentally leave their webcam on after a conference call, and employees see him/her let out a big burp and pick their nose or something.   In these cases it's important that the audience is not forgiving, even if they don't confront the person about it. The person may or may not know they are being humiliated.  "Pity" as proposed in an answer seems very close, but I think it lacks a few components. I think "pity" has a chronic connotation - that you are referring to the general state of things rather than a specific event.  I think "pity" also depends on the subject suffering, but in my example they are often oblivious.  It could very well be that there is no word for this at all.  NOTE: Some people do not feel the same way I do in this scenario, so you may not think this question makes any sense. Eclipse error: "The import XXX cannot be resolved" UNetbootin is stuck in an "Automatic boot in 10 seconds" countdown loop I made a bootable Windows 7 USB using UNetbootin, and when I try to boot from the bootable USB and select the Default boot menu entry, it gets stuck at the UNetbootin boot menu and it keeps repeating an Automatic boot in 10 seconds... message in an endless countdown loop. Selecting Press [Tab] to edit options and editing the options has no effect. When I go back to the boot menu, it keeps repeating the same countdown loop.   I've tried redoing the UNetbootin extraction, but I still have the same issue. Nielsen & Chuang Exercise 2.2 - “Matrix representations: example” Reproduced from Exercise 2.2 of Nielsen &amp; Chuang's Quantum Computation and Quantum Information (10th Anniversary Edition):     Suppose $V$ is a vector space with basis vectors $|0\rangle$ and $|1\rangle$, and $A$ is a linear operator from $V$ to $V$ such that $A|0\rangle = |1\rangle$ and $A|1\rangle = |0\rangle$. Give a matrix representation for $A$, with respect to the input basis $|0\rangle, |1\rangle$, and the output basis $|0\rangle, |1\rangle$. Find input and output bases which give rise to a different matrix representation of $A$.   Note: This question is part of a series attempting to provide worked solutions to the exercises provided in the above book. Is the .minecraft folder hidden on a Mac? I have a friend who is playing with me on a server we've created. Unfortunately, he is on a  Mac whereas I am on a Windows machine. I told him that I should be able to compile and send a .minecraft folder to him so that we can both play. Unfortunately, he can't find his .minecraft folder where it is supposed to be. Is it hidden and how can I unhide it? I was able to star my own message by pinning it and unpinning it.  Pinning a message adds a star, even to your own messages, but when the pin is removed, the star remains. If you draw two cards, what is the probability that the second card is a queen? We had this question arise in class today and I still don't understand the answer given. We were to assume that drawing cards are independent events. We were asked what the probability that the second card drawn is a queen if we take two from the deck. The answer given was 4/52, which seems counter-intuitive to me. How is the probability still 4/52 if there was a card drawn before it? What if the first card drawn was a queen? Help with Spivak Calculus Ch3 Problem 6a Yet again I find myself stuck on a Spivak question. This time it is simply the question that isn't clear to me. It states:  If $x_1, ..., x_n$ are distinct numbers, find a polynomial function $f_i$, of degree $n-1$ which is 1 at $x_i$ and 0 at $x_j$ for $j\neq i$. Hint: the product of all $(x-x_j)$ for $j\neq i$, is 0 at $x_j$ if $j\neq i$. This product is usually denoted by: $$\prod_{\begin{smallmatrix}{j=1}\\ {j\neq i} \end{smallmatrix}}^n(x-x_j)$$  To be honest I don't know where to begin. I understand how to create a polynomial equation for a given set of results but this is quite strange. I'm not sure exactly what the author is expecting.  The answer book shows:  $$f_i(x)={\prod_{\begin{smallmatrix}{j=1}\\ {j\neq i} \end{smallmatrix}}^n(x-x_j)}/{\prod_{\begin{smallmatrix}{j=1}\\ {j\neq i} \end{smallmatrix}}^n(x_i-x_j)}$$  Which I have expanded out just fine but don't know what to do with. Noticing that Newtonian gravity and electrostatics are equivalent, is there also a relationship between the general relativity and electrodynamics? In classical mechanics, we had Newton's law of gravity $F \propto \frac{Mm}{r^2}$.  Because of this, all laws of classical electrostatics applied to classical gravity if we assumed that all charges attracted each other due to Coulomb's law being analogous.  We can "tweak" classical electrostatics to fit gravity.  In modern physics, does the reverse work?  Can we "tweak" General Relativity to accurately describe electrostatics or even electromagnetism? Is it legal/well-defined C++ to call a non-static method that doesn't access members through a null pointer? Was Voldemort a Better Wizard Than Dumbledore? Pursuant to , I have a somewhat related question. The majority of Harry Potter readers automatically assume that Dumbledore must be a better wizard than Voldemort, because Dumbledore is &quot;good&quot; and Voldemort is &quot;evil.&quot; However, would Tom Riddle's prematurely developed skills demonstrate that Voldemort was inherently a better wizard than Dumbledore? In chapter 17, The Heir of Slytherin, Harry challenges Tom Riddle when he claims to be the greatest sorcerer in the world, retorting that Albus Dumbledore is the greatest sorcerer in the world. Harry reminds Tom Riddle that Voldemort is frightened of Dumbledore. Conversely, in Half-Blood Prince, Dumbledore himself states that Voldemort knows perhaps more magic than any other wizard alive. Yet, as Harry is J.K. Rowling's most direct voice, do we conclude that Dumbledore was, in fact, the superior wizard? Who was the better¹ wizard: Voldemort or Dumbledore? ¹Better meaning on a technically skilled level.