I removed the BB (Shimano BB-93) from my Canondale Trail and found the drive side thread is stripped on BB and frame. See  and  What are the options for me to replace the BB? Is there an alternative Hollowtech II compatible part which will reach the good thread or other alternative? I'm aware there could be a machining/welding/tapping option, but would guess that would not be worthwhile on an ageing bike. Are there any alternative parts I could use?  mentions a Velo-orange option that clamps in place, but if possible I'd like to keep my recently replaced Hollowtech II crankset if possible I'm baffled by all the combinations, hoping someone has been down this path already and can suggest if there's a practical solution.
The bottom bracket of my bike was completely stripped to the point that when you push the left side crank arm, the right crank moves and you can see the bottom bracket lock move out the frame. The bike shop tried putting Teflon tape but it's temporary. It's a 26' xc hard tail. For all I know both sides of the bottom bracket(square tapered) are stripped clean hence the Teflon tape put by the previous owner. Can I fix the problem by changing into a hallow tech cranks because it works like a thread less bb, or should I just buy a thread less square tapered bb? Any suggestion on what to do?
Submission on hold on arxiv I have recently submitted a paper to arXiv, but the arXiv moderators put my paper in status "on hold", because they have to make a decision on the right classification for the paper.   To those who have experienced a similar situation, how long did it take before they made a decision and published the paper on the arXiv? I just want to have an idea of how long I will have to wait. How can I navigate my scene FPS style similar to how Unity does? I am aware of ShiftF fly, but it's extremely cumbersome having to use the scroll wheel to change the velocity of flight and moving the mouse from the center to spin.  Is there a way to move the viewport camera (not the scene camera) like Unity lets you right click and fly around with WASD and moving the mouse? What developer text editors are available for Ubuntu? Proving that a function has a removable singularity at infinity Regaining control of a group after being removed by another admin I created a Facebook group and was later removed by another admin.   How do I get my group back? formal proof from calulus Given $f:R \to R$, $f$ is differentiable on $R$ and $\lim_{x \to \infty}(f(x)-f(-x))=0$. I need to show that there is $x_0 \in R$ such that $f'(x_0)=0$  I am trying to prove it by contradiction .... so i assume there is no $x_0 \in R$ such that  $f'(x_0)=0$ this means this function is strictly monotonic because the derivative "respects" the mean value theorem so it cannot be negative and positive without passing a zero value ....  (from what i understand the derivative function of a continuous/differentiable functions isn't necessarily continuous but it still respect the mean value theorem i think it's called darboux's theorem )  now from $\lim_{x \to \infty}(f(x)-f(-x))=0$ ,we get $\lim_{x \to \infty}f(x)=\lim_{x \to \infty}f(-x)$  now the last step is the contradiction its very intuitive and even maybe obvious that we can't get $\lim_{x \to \infty}f(x)=\lim_{x \to \infty}f(-x)$ for strictly monotonic function but i cant think of a formal way to prove it . Possible Duplicate:          This is a line spoken by the . I always wondered if this is grammatically correct.  Luke says something like "You are mistaken ..." which the Emperor answers with     No, it is you who are mistaken!   Why wouldn't he say     No, it is you who is mistaken!   instead?  I don't know what rules apply here but my stomach tells me the latter is (at least also) correct, although you would say "you are mistaken". It feels as if he should be referring to "you" in the third person.  Could you please shed some light? Are both correct or – if not – which one is correct? And why? Basically this suggestion for the Android app:   Many times I'll see that a post has been edited on the Android app. I'll want to see exactly what was edited, and the Android app doesn't show this. Can the revision history be added to the Android app? “Screen overlay detected” dialog? Turned off everything, doesn't work I started receiving the “Screen overlay detected” dialog when trying to change apps settings.  Tried to turn off all "draw over other apps" as it says here - , first without system and then with, but it still doesn't work.  Then, I restored apps to original settings and it just made a bigger mess, dialog continue appearing. Any way to go back to previous settings???  Thanks! Problem:Let $k$ be an odd positive integer. Prove that $(1+2+3...+n)|(1^k+2^k+3^k+...+n^k)$ for all positive integers $n$.  My Attempt: Proof (By Induction on $k$): Let $P(k)$ be the proposition that $(1+2+3...+n)|(1^k+2^k+3^k+...+n^k)$ for all positive integers $n$ when $k$ is odd. Then $P(1)$ and $P(3)$ are trivially true. So for $k\geq 5$, we assume that $P(k)$ holds. We would like to show that $P(k+2)$ also holds. In order to do that consider the following sums  $$1^{2}(1^k+2^k+3^k+...+n^k)=1^{k+2}+2^k+3^k+...+n^k$$ $$2^{2}(1^k+2^k+3^k+...+n^k)=2^2*1^k+2^{k+2}+2^2*3^k+...+2^2*n^k$$ $$..$$ $$n^2(1^k+2^k+3^k+...+n^k)=n^2*1^k+n^2*2^k+n^2*3^k+...+n^{k+2}$$ Note that $$1^2(1^k+2^k+3^k+...+n^k)+2^2(1^k+2^k+3^k+...+n^k)+...+n^2(1^k+2^k+3^k+...+n^k)\equiv 0\pmod {\frac{n(n+1)}{2}}$$  Therefore, if we denote $\sum_{i=1}^{n}i^2=s$, then    $(t)(1^k+2^k+3^k+...+n^k)-t+\sum_{i=1}^{n}i^{k+2}\equiv 0\pmod {\frac{n(n+1)}{2}}$ which implies that $P(k+2)$ holds. Hence by PMI we are done.  Now I am a bit hesitant in convincing myself whether this proof is correct or not. This is because I have never seen induction performed in this manner. Any reasons as to why this argument falls would be much appreciated. Make Google stop sending 'new sign in from ...' emails I get at least two emails from Google every time I sign in to my account and I want it to stop.  I tried changing the notification settings in Gmail, but they're still coming and they're useless.  How can I stop this? Rosewill RNX-N600UBE Connectivity issue on Ubuntu 17.04 How to plot a graph from its adjacency matrix and coordinates of vertices? A similar question is . If we give all the data of the vertices's coordinates and the graph's adjacency matrix, how to plot it with tikz, pstrick or other tool in tex?   here are the data of adjacency matrix and coordinates  Coordinates:{{0.809,0.588},{0.309,0.951},{-0.309,0.951},{-0.809,0.588},{-1.,0.},{-0.809,-0.588},{-0.309,-0.951},{0.309,-0.951},{0.809,-0.588},{1.,0.}}  Adjacency matrix: {{0,1,0,0,1,0,1,0,0,1},{1,0,1,0,0,1,0,1,0,0},{0,1,0,1,0,0,1,0,1,0},{0,0,1,0,1,0,0,1,0,1},{1,0,0,1,0,1,0,0,1,0},{0,1,0,0,1,0,1,0,0,1},{1,0,1,0,0,1,0,1,0,0},{0,1,0,1,0,0,1,0,1,0},{0,0,1,0,1,0,0,1,0,1},{1,0,0,1,0,1,0,0,1,0}}   Sometimes the number of data is too large to put the data in the main tex file. It would be better to import the data from external files. . I'm currently building a town in Minecraft Pocket Edition and I'm wondering how many blocks long and how many blocks wide the world is. I use the term "100% crop" to mean a portion of a picture that has been cropped but not resized, but I have also seen some confusion around that term.   Is there an accepted definition for "100% crop?" What is its opposite called?   Here's what I think it means:   If I'm right, what is the proper name for "something else?" If I'm wrong, please include illustrations.  Either way, what evidence supports the definitions? Who paid for Harry's Nimbus 2000? The Nimbus 2000 was the fastest broom at the time of the Harry's first year at Hogwarts.  Professor McGonagall wanted to win the Quidditch Cup so she spoke with Dumbledore and got an exception from the rule that no first-years could have a broom for Harry.  My question is who paid for the broom?  It couldn't have been a cheap broom.  They wouldn't have taken gold out of Harry's Gringotts account without permission.  It wouldn't be right for the school to pay for it and I doubt McGonagall paid for it out of her own pocket.  So who paid for the broom? Can you help me with my software dependency issue? This is a  about Compile Dependencies and Package Management.    I have a question regarding compiling ports/software or installing RPMs on my *nix server.  When I try to do this I receive lots of messages about missing dependencies.  Can the Server Fault community please help? How to start Skype 4 with Ubuntu 12.10? I've installed Skype and it's running all OK but I want it to start automatically when I log with my user.  How can I do that? Well, the original task was to figure out what the following expression evaluates to for any $n$.  $$\begin{pmatrix} 1 &amp; 1 \\ 0 &amp; 1\end{pmatrix}^{\large n}$$  By trying out different values of $n$, I found the pattern: $$\begin{pmatrix} 1 &amp; 1 \\ 0 &amp; 1\end{pmatrix}^{\large n} = \begin{pmatrix} 1 &amp; n \\ 0 &amp; 1\end{pmatrix}$$  But I have yet to figure out how to prove it algebraically.   Suggestions? Background process of subshell strange behaviour I wonder why some similar bash commands behave the way they do.  I have a bash script foo:  #!/usr/bin/env bash  while true do     echo "reading"     read data     echo $data     echo "stderr msg" &gt;&amp;2     sleep 1 done   It's an infinite loop which reads one line at a time from stdin and outputs that same line. I also have a bash script bar:  #!/usr/bin/env bash  ./foo &amp;   The following commands were run in bash (v. 4.4.19) in a terminal on Ubuntu 18.04 (let's assume the scripts reside in the working directory):   ./foo &amp;   Stops when it tries to read from stdin, in accordance with . Killed when controlling terminal is killed, as expected.  (./foo &amp;)   Appears to be automagically continuously fed with new input from stdin. Shouldn't it too stop when attempting to read from stdin? Whatever it's getting it doesn't show when echoed, thus I'm guessing it's EOF characters.  Continues running even after the controlling terminal is killed. Looking at the output of ps, the controlling terminal changes from pts/x to ?. How did this happen without the use of either disown or nohup? (However, after killing the originally controlling terminal, it yields a "write error: Input/output error" on every write, which I suppose is because its stdout was tied to the now closed terminal. Correct?)  bash -c "./foo &amp;"  Appears to behave exactly like 2). ./bar  Appears to behave exactly like 2) and 3). Adding bash -c "~/foo" (no &amp;) as a startup application  Behaves similarly to 2), 3) and 4), with the differences:   Its controlling terminal is the desktop ttyx. You can't (can you?) kill its controlling terminal.   None of those differences seem odd to me, just the fact that it's continuously fed with new input.   My guess is that 2) - 5) all use a subshell of sorts whose stdin is redirected to something like /dev/null, though I'm very unsure and seek a more exact answer.