I'm new for blender and I'm searching or any advice as solution for my question. my question is, Is there any system or any tool that we can use to transfer jpeg image file to 2d animation stroke file. currently im using images as reference and creating stroke layers on it. but when it come to create the faces my out come of drawing was terrible. so please advice how I can fix this.
Say I want to automate making extruded-text or a 3d logo from an image.    An answer that uses extruding a monochrome image of the ubuntu logo to an arbitrary number of units with a python script taking only the number of units and the monochrome image as a starting point will receive extra this was awesome re-posts from me.  This could be useful for lots of things.
I am applying for a UK visa. Can I show 5 months worth of bank statements for the UK visa, or is 6 months a requirement, as its not mentioned on their website?  There are no appointment dates showing in April. Is there any time limit in which we have to book an appointment after paying the fee? Help me to solve this problem please..  Let $Y_{(1)}, Y_{(2)}, Y_{(3)}, Y_{(4)}, Y_{(5)}$ denote the order statistics of a random sample of size 5 from a distribution having p.d.f. $f(y) = e^{(-y)}, 0 &lt; y &lt; \infty$, zero elsewhere. Show that $Z_1 = Y_{(2)}$ and $Z_2 = Y_{(4)} − Y_{(2)}$  are independent. Hint: First find the joint p.d.f. of $Y_{(2)}$  and  $Y_{(4)}$. I want that my monitor turns off when I am inactive for a while, but I do not want that I am prompted for a password when I revoke my pc. In Ubuntu 16.04 it was possible to disable the lock but still enable the screensaver as explained .  In Ubuntu 18.04 I entered the following in terminal:  dconf-editor   and disabled ubuntu-lock-on-suspend:    However, since I made this change, my monitor never suspends anymore. I tried restart but it didn't help.  Any ideas how I can disable lock but still enable suspend mode? Why did the snake wink at Harry at the zoo? This is mostly a memory question - I'm having a hard time remembering this and I can't read the book right now.  On the first book, a snake at the zoo winks at Harry. For the sake of the question, we'll assume that snakes can in fact wink.  I have a fuzzy memory here - I think that it winked before Harry had any kind of interaction with the snake (was this before or after Harry broke the glass?)  So, why did the snake wink at Harry? Given that they had not met ever before.  I suppose that the only reason it would wink at Harry would be because it knows Harry can communicate with it. But this would imply that snakes are capable of sensing such ability on wizards - is there (other) evidence that this is true? Getting HTTP/2 Working on Apache 2.4.29 on Debian 8 I am trying to update my apache2 (Apache/2.4.29 (Debian 8)) server to support http2 but after enabling http2   with following code, it does not work because of mpm_prefork does not support http2  &lt;IfModule http2_module&gt;     ProtocolsHonorOrder On     Protocols h2 h2c http/1.1 &lt;/IfModule&gt;    since mpm_prefork apache (2.4.29)  does not work with http2, I tried using  mpm_event/mpm_worker but it does not work, so I enable mpm_prefork  sudo a2dismod mpm_event  sudo a2dismod mpm_worker  sudo a2enmod mpm_prefork   Since I am still running php5 what should I do to have http2 support on Debian8?  Will I have to update php5 to php7?  Is there any workaround to use mpm_worker/mpm_event with php5 with http2 support?  apache error log  [http2:warn] [pid 11992] AH10034: The mpm module (prefork.c) is not supported by mod_http2. The mpm determines how things are processed in your server. HTTP/2 has more demands in this regard and the currently selected mpm will just not do. This is an advisory warning. Your server will continue to work, but the HTTP/2 protocol will be inactive. [mpm_prefork:notice] [pid 11992] AH00163: Apache/2.4.29 (Debian) OpenSSL/1.1.0g configured -- resuming normal operations [core:notice] [pid 11992] AH00094: Command line: '/usr/sbin/apache2' I'm trying to hide the app icon from the title bar in GNOME in Ubuntu 18.04. I know there is  asking the same thing but it's from 2011 and I can't find what it requires to find in the shell css. I'm also using the Arc-Dark custom theme.   Here are two examples of what I want to remove:      To be clear, I don't want to resize it to fit, I want to straight away remove it completely. I got the brand new Custodian badge today for reviewing posts. Inspired by that, I reviewed some more suggested edits. Now I ran into a limit:     You have no more suggested edit votes today; come back in x hours.   How is that limit calculated? I made 61 reviews today which seems to be some calculated limit.  I searched for an answer on meta but found nothing helpful. I was readng Wikipedia article (English one) about radiation pressure because there is something I still cannot figure out. As I understand it, radiation pressure emerges from conservation of momentum. Photons or electromagnetic waves possess momentum and when they are absorbed, reflected or even emitted, the aborber/reflector/emitter experiences a pressure that is proportional to the irradiance (in watts per square meter). OK. In the case of a perfect reflector that does nothing but reflecting incoming radiation, it would seem the reflector is pushed and the radiation is reflected in opposite directions. But the radiation has not lost anything, it has only changed direction. And I do not understand how something can be set in motion (the reflector), which amounts to do work, yet the source of this work does not lose energy. I mean, if the radiation, after a U turn, meets a second reflector, it would have pushed two reflectors a way, yet it would continue in its original direction as if nothing happened...? What am I missing here? Should not photons lose something? Convert from MySQL datetime to another format with PHP How many syllables are in the word 'hour'? Does the word 'hour' have 1 or 2 syllables? How to install Anaconda on Ubuntu? What's the name for the relativistic paradox with the train/car travelling over a gap? There is a relativistic paradox I was introduced by a friend in Ithaca (Courtenay Footman). It involves a vehicle travelling over a ravine relativistically, so it's in the general family of ladder paradoxes. There are many ways to phrase it, but here's a simple one.   A three-car train with each car of length $L$ is travelling over a bridge across a ravine. (Assume that the couplings between cars are stiff: this train does not bend.) Unfortunately, some evil genius has precisely removed a length $6L$ of the track. The train however is relativistic, travelling at a speed such that $\gamma \approx 12$.  In the reference frame of the ground, the train should appear to be 1/24th the size of the gap, which suggests that it will fall a little and should crash into the bridge opposite. But in the reference frame of the train, each car of the train is at least twice as long as the gap and aside from the very front wheel and the very back wheel, which need to be supported by rigidity, everything is constantly well-supported. This suggests that the train makes it. Who is right?  I vaguely remember that as an undergraduate knowing only a little relativity, I trusted the train's perspective because it's at rest in that perspective, and Courtenay said that this was ultimately correct after a lot of details got resolved. But I do not remember all of these details such that I could work it out for myself. So I'm looking for some discussion that's a little more well-sourced or authoritative.  What is this paradox called, and what literature has addressed the issue? This movie came out around 2000 and was created for one of the cable networks (and never in the theaters).  I think it was on the original Sci-Fi Channel or maybe the USA Network, but really not sure.    It's about a 1950's American-style utopian world.  The main character, if I remember correctly, worked at a car dealership.  I recall him looking like Jon Hamm, Adrian Pasdar, or Scott Bakula, but I may be way off there (and I didn't see the movie in their filmographies).  He drives his nice car home, and the whole town is beautiful, as are its people and white picket fence style homes.     He suddenly starts seeing weird things.  For example, instead of people driving cars, they're actually riding rickety bicycles.  The manicured, paved streets are actually dirt roads.  Houses are, in reality, tiny shacks.  Instead of people's clothes being immaculately maintained, everyone's really wearing filthy rags.  And instead of delicious food, they're eating something that looks like rotten garbage.  Something is making everyone believe they live in a beautiful, perfect society, but it's mind manipulation that's almost on the scale of the movie "The Matrix."    He befriends a pretty lady, and together they travel outside their town and try to find answers.  They even meet an outside militarized government, whose officials are interested in understanding and helping him.  This other city's infrastructure appears to be state-of-the-art and well funded.  The officials all have nice uniforms.  However, their environment is also under the same influence that's making everyone see things differently than what they really are.  The main character somehow sees through this illusion too, and realizes this fake prosperity is affecting others outside his home town--maybe the entire world!    The movie ends with       the man and woman eventually running into some elderly maintenance man in a forested area.  The maintenance man's job is to service a machine that alters everyone's perception of reality.     I posted about this a couple of years ago on another site, and somebody took a guess that it was "The Prisoner" but unfortunately that's not it.  I didn't really explain it well the first time, so hopefully this is clearer. This question is inspired by my own answer to a  which I tried to answer and got stuck at one point.     The question was:     HI DARLING.      USE MY ATM CARD, TAKE ANY AMOUNT OUT, GO SHOPPING AND TAKE YOUR FRIENDS FOR LUNCH.      PIN CODE: $\displaystyle \int_{0}^{1} \frac{3x^3 - x^2 + 2x - 4}{\sqrt{x^2 - 3x + 2}} \, dx $      I LOVE YOU HONEY.      Anyone knows? Are we gonna get an integer number?     My attempt:  Does this help?     $$\frac{3x^3-x^2+2x-4}{x-1}=3x^2+2x+4$$   (long division)   \begin{align*} I&amp;=\int\frac{3x^3-x^2+2x-4}{[(x-1)(x-2)]^{1/2}} dx = \\ &amp;=\int\frac{(3x^2+2x+4)(x-1)^{1/2}}{(x-2)^{1/2}} dx = \\ &amp;=\int 3(u^4-4u^2-4)(u^2+1)^{1/2}du \times 2 \end{align*}   after the substitution   \begin{gather*} (x-2)^{1/2}=u\\ du=\frac1{2(x-2)^{1/2}}dx\\ u^2=x-2\\ (x-1)^{1/2}=(u^2+1)^{1/2} \end{gather*}   Update:  may help us proceed.    I tried to proceed:     $$6\int (u^4-4u^2-4)(u^2+1)^{1/2} du = 6\int ((t-3)^2-8)t \frac{dt}{2u}$$   after $u^2+1=t$ and $dt=2udu$   \begin{align*} u^4-4u^2-4 &amp;= (u^2+1)^2-(6u^2+5) \\ &amp;= (u^2+1)^2-6(u^2+1)+1 \\ &amp;= ((u^2+1)-3)^2-8 \end{align*}   I wonder whether this question can be solved from here?    Update:   This has been getting a lot of views, and I think most people came for the sort of problem mentioned in the title (where I got stuck) rather than the original problem itself.  Keepin this in mind, I'm reopening the question and here's the kind of answers I expect — Solutions to the original problem are good, but I'd prefer solutions that continue from the part where I got stuck — the polynomial in $u$ — that's the sort of problem mentioned in the title. network manager says "device not managed" I used to be able to share my network connection by editing the Auto Eth0 to share with other computers in the Ipv4 section and now I upgraded my laptop to 11.10 .  Now are there no wired connections in the network manager. When I click my connections applet at the top of the tray it also says wired device not managed!  when I type ifconfig -a  daniella@daniella-1001HA:~$ ifconfig -a eth0      Link encap:Ethernet  HWaddr 90:e6:ba:83:d6:fc             UP BROADCAST MULTICAST  MTU:1500  Metric:1           RX packets:0 errors:0 dropped:0 overruns:0 frame:0           TX packets:0 errors:0 dropped:0 overruns:0 carrier:0           collisions:0 txqueuelen:1000            RX bytes:0 (0.0 B)  TX bytes:0 (0.0 B)           Interrupt:45   eth0:avahi Link encap:Ethernet  HWaddr 90:e6:ba:83:d6:fc             inet addr:169.254.13.40  Bcast:169.254.255.255  Mask:255.255.0.0           UP BROADCAST MULTICAST  MTU:1500  Metric:1           Interrupt:45   lo        Link encap:Local Loopback             inet addr:127.0.0.1  Mask:255.0.0.0           inet6 addr: ::1/128 Scope:Host           UP LOOPBACK RUNNING  MTU:16436  Metric:1           RX packets:0 errors:0 dropped:0 overruns:0 frame:0           TX packets:0 errors:0 dropped:0 overruns:0 carrier:0           collisions:0 txqueuelen:0            RX bytes:0 (0.0 B)  TX bytes:0 (0.0 B)  wlan0     Link encap:Ethernet  HWaddr 00:25:d3:90:43:41             inet addr:192.168.0.6  Bcast:192.168.0.255  Mask:255.255.255.0           inet6 addr: fe80::225:d3ff:fe90:4341/64 Scope:Link           UP BROADCAST RUNNING MULTICAST  MTU:1500  Metric:1           RX packets:12881 errors:0 dropped:0 overruns:0 frame:0           TX packets:12867 errors:0 dropped:0 overruns:0 carrier:0           collisions:0 txqueuelen:1000            RX bytes:8851081 (8.8 MB)  TX bytes:2343199 (2.3 MB) Powershell Try Catch Continue Simple question but I am confused.  What is the boundary of $S^2\times\mathbb{R}$? Is it just $S^2$?  What would be the general way to evaluate the boundary of a product manifold?  Thanks for the replies! Solving functional equation $f(x+y)+f(x-y)=2f(x)\cos y$? How can I solve this functional equation, where $x,y$ are any real numbers and $f:\mathbb{R}\to \mathbb R$ is a function such that : $$f(x+y)+f(x-y)=2f(x)\cos y$$    I tried substituting $x=0$ to get $f(y)+f(-y)=2f(0)\cos y$ . Taking $x=y$ gives $f(2x)+f(0)=2f(x)\cos x$. I similar get some more relations like that, but its not really helping me in finding anything useful. I also think the function must either be $\sin$ or $\cos$ looking at the product to sum formulae. Can anyone tell me how should I solve this? In Java, is there any way to use the JDK libraries to discover the private classes implemented within another class? Or do I need so use something like asm? Correct usage of "lest"