I've read several threads about using the runas.exe command to start an elevated process. However, when I type try to use the command runas.exe /user:BruceWayne\Administrator cmd.exe, the Command Prompt opens up asking for my password, but it won't let me enter it.  I can press Enter and the Command Prompt will close, but I can't get anywhere beyond this. Does anyone have any ideas as to why this might be happening?
I have a windows 7 user who belongs to admin group. I want to execute sc command that requires admin privileges. I DON'T want to open an elevated cmd, want to be able to simply Win+R->Enter command, enter password and that's all. I tried the runas command, but it doesn't seem to work:  &gt;runas /user:me "cmd"   and it asks for a password, and then the command is executed with normal privileges. I know I could use /user:administrator but I don't know the admin pass and I think the admin user (me) should work.
Double value returns 0 Here's an example:  Double d = (1/3); System.out.println(d);   This returns 0, not 0.33333... as it should.  Does anyone know? Show that $A\in\mathbb{C}_n$ is normal $\iff$ $tr(A*A) = \sum_{i = 1}^n|\lambda_i|^2$, where $\lambda_1,...,\lambda_n$ are the eigenvalues of $A$. Two "if"s in a row Homotopy invariance for cohomology I have tried to read Hatcher's  book. He proved  Theorem 2.10: If two maps $f,g :X \to Y$ are homotopic, then they induce the same homomorphism $f_* = g_*:H_n(X) \to H_n(Y)$.  One can immediately obtain following corollaries using the dual version of prism operator described in Theorem 2.10 and some facts:  Corollary 1: If $f,g :X \to Y$ are homotopic, then $f_* = g_*:\tilde H_n(X) \to \tilde H_n(Y)$ for $n&gt;0$.  Corollary 2: If $f,g :(X,A) \to (Y,B)$ are homotopic, then $f_* = g_*:H_n(X,A) \to H_n(Y,B)$.  Corollary 3: If $f,g :X \to Y$ are homotopic, then $f^* = g^*: H^n(X) \to H^n(Y)$.  Corollary 4: If $f,g :X \to Y$ are homotopic, then $f^* = g^*:\tilde H^n(X) \to \tilde H^n(Y)$ for $n&gt;0$.  Corollary 5: If $f,g :(X,A) \to (Y,B)$ are homotopic, then $f^* = g^*:H^n(X,A) \to H^n(Y,B)$.  I wonder that how can we prove the following statements:  Corollary 6: If $f,g :X \to Y$ are homotopic, then $f_* = g_*:\tilde H_0(X) \to \tilde H_0(Y)$.  Corollary 7: If $f,g :X \to Y$ are homotopic, then $f_* = g_*:\tilde H^0(X) \to \tilde H^0(Y)$.  An attempt for Corollary 7 is  Proof of Corollary 7: By Universal Coefficient Theorem, we have $$\tilde H^0(X;G) \approx Hom(\tilde H_0(X),G).$$  Hence the result follows from the dualization of the proof Corollary 6.  Any help will be appreciated. I have a VIP skybag (I believe this does not matter). It has a 3-number TSA lock built into the suitcase. I know the combination to unlock, let's say it's 345. Recently it was locked and while there was a different number on the combination lock the reset/set lock button was pressed.  Since then the reset/set lock button is pressed (stuck) and the lock button also does not unlock. Any pointers on how to unlock it? I am thinking of unscrewing the lock from inside of the suitcase but it seems quite a hassle, as I may have to assemble it back. Let me know if there is any other option to unlock it from the outside. Is it possible to win in Don't Starve? I would like to know if it's possible to win in Don't Starve? Or is it just the matter of how long until you die? How do I make a floor plan with specific dimensions? This is my very first time of using blender. I've tried several tutorials but can't find anything that tells me how to do the very basic thing i want to do.  I simply want to draw a floor plan for a room which is 13 feet by 11 feet and make it 3d so that ultimately i can play with where things go in that room.  Can anyone take me through the steps needed to do this?   I will be so grateful.  Thank you in advance Can I call a constructor from another constructor (do constructor chaining) in C++? As a  developer I'm used to running through constructors:    class Test {     public Test() {         DoSomething();     }      public Test(int count) : this() {         DoSomethingWithCount(count);     }      public Test(int count, string name) : this(count) {         DoSomethingWithName(name);     } }   Is there a way to do this in C++?  I tried calling the Class name and using the 'this' keyword, but both fail. Can I visit the UK as a tourist before my Student Visa starts? In a non-inertial reference frame, the centripetal force is balanced by a centrifugal force. Therefore, shouldn't the net acceleration be zero? Yet, you still feel an acceleration outwards? Why is that? How can I prove that if $G$ is an Abelian group with elements $a$ and $b$ with orders $m$ and $n$, respectively, then $G$ contains an element whose order is the least common multiple of $m$ and $n$?  It's an exercise from Hungerford's book, but it's not homework. I could not solve it when I take the course on groups and I think it should be easy. There is a hint that says to first prove when $m$ and $n$ are coprimes. I did this part. But I have no idea how to solve the general case.  Thanks. How do I make Git use the editor of my choice for commits? Do I have to clear customs when transit via the US on my way to / coming from somewehere else? I shall arrive at Washington Dulles Airport (IAD) by Emirates flight to catch a united airlines flight to Detroit after 3.5 hours. What steps shall I have to go through? Is the connection time enough? I have US F1 visa. What is the remainder when $1! + 2! + 3! +\cdots+ 1000!$ is divided by $12$? What is the remainder when $$1! + 2! + 3! +\cdots+ 1000!$$ is divided by $12$.  I have tried to find the answer using the Binomial Theorem but that doesn't help. How will we do this?  Please help. Getting error using JMeter behind a proxy I am new to JMeter and trying to run a test from behind a corporate proxy. I read on the same from apache site and followed the same process so as to run the test. However, i am still  unable to record a test from behind the proxy.      This message always appears after pressing on 'Start' recording:     After that, I have changed apache port to 8000 as in below and made it different      This time after pressing on start was this message In the textbook, it said a wave in the form $y(x, t) = A\cos(\omega t + \beta x + \varphi)$ propagates along negative $x$ direction and $y(x, t) = A\cos(\omega t - \beta x + \varphi)$ propagates along positive $x$ direction. This statement looks really confusing because when it says the wave is propagating along $\pm$ x direction, to my understanding, we can drop the time term and ignore the initial phase $\varphi$ while analyzing the direction, i.e. $y(x, 0) = A\cos(\pm\beta x)$, however, because of the symmetry of the cosine function, $\cos(\beta x)\equiv \cos(-\beta x)$, so how can we determine the direction of propagation from that?  I know my reasoning must be incorrect but I don't know how to determine the direction. So if we don't go over the math, how to figure out the direction of propagation from the physical point of view? Why $-\beta x$ corresponding to the propagation on positive x direction but not the opposite? Flag pop-up hidden beneath answer box (and it's still transparent!) The flag window on (a comment to) the last question is hidden beneath the answer box, as shown in the following screenshot:    Linked: , which is currently  - this is not fixed for flags on comments! Why is my total reputation less than my monthly reputation? When I went to the  to see my ranking in the reputation league, I saw this. Is this an error? My total reputation is less than my monthly reputation. Book recommendations Fastest converging method for calculating e