For probably about a month now, udev has been held back by apt-get when running apt-get updgrade.  The following packages have unmet dependencies:  udev : Depends: sysv-rc (&gt;= 2.88dsf-24) but 2.88dsf-13.10ubuntu11.1 is to be installed or                  file-rc (&gt;= 0.8.16) but it is not installable E: Unable to correct problems, you have held broken packages.   I thought it might go away eventually as packages were updated, but as I said, it's been about a month now. I'm wondering if someone might have some insight on why I can't update this package (I tried googling, but my google-fu on this problem is a little weak).  I'm running Ubuntu 12.04, and this is on a server-type machine (no GUI).  I have the following PPA's on my system:             And also the . I looked through them all, and didn't see any of the packages above being provided by these PPA's, but I thought I would mention it.
Occasionally, when I'm installing stuff, I get an error like the following:  Some packages could not be installed. This may mean that you have requested an impossible situation or if you are using the unstable distribution that some required packages have not yet been created or been moved out of Incoming. The following information may help to resolve the situation:  The following packages have unmet dependencies:  package1 : Depends: package2 (&gt;= 1.8) but 1.7.5-1ubuntu1 is to be installed E: Unable to correct problems, you have held broken packages.   How can I resolve this?
Numbered list in rows in tables I want to have numbered listing in each row, I've tried with \rownumber, but it doesn't work. I wrote a number at the beginning, but Could it be automatically?  Can you help me? This is my code:  \documentclass[10pt, a4paper]{article}  \usepackage{fontspec} \setmainfont{Arial}  \usepackage{color, colortbl} \definecolor{Gray}{gray}{0.9}  \begin{document}  \begin{table}[h!] \tiny \begin{tabular}{|&gt;{\raggedright\arraybackslash}m{30mm}|&gt; {\raggedright\arraybackslash}m{5mm}|&gt;{\raggedright\arraybackslash}m{5mm}|&gt;{\raggedright\arraybackslash}m{5mm}|&gt;{\raggedright\arraybackslash}m{5mm}|&gt;{\raggedright\arraybackslash}m{5mm}|&gt;{\raggedright\arraybackslash}m{5mm}|&gt;{\raggedright\arraybackslash}m{5mm}|&gt;{\raggedright\arraybackslash}m{5mm}|&gt;{\raggedright\arraybackslash}m{5mm}|&gt;{\raggedright\arraybackslash}m{5mm}|&gt;{\raggedright\arraybackslash}m{5mm}|&gt;{\raggedright\arraybackslash}m{5mm}|} \hline \multicolumn{1}{|&gt;{\centering\arraybackslash}m{30mm}|}{\rowcolor{Gray}\textbf{Text}} &amp; \multicolumn{1}{|&gt;{\centering\arraybackslash}m{5mm}|}{\textbf{Sem 1}} &amp; \multicolumn{1}{|&gt;{\centering\arraybackslash}m{5mm}|}{\textbf{Sem 2}} &amp; \multicolumn{1}{|&gt;{\centering\arraybackslash}m{5mm}|}{\textbf{Sem 3}} &amp; \multicolumn{1}{|&gt;{\centering\arraybackslash}m{5mm}|}{\textbf{Sem 4}} &amp; \multicolumn{1}{|&gt;{\centering\arraybackslash}m{5mm}|}{\textbf{Sem 5}} &amp; \multicolumn{1}{|&gt;{\centering\arraybackslash}m{5mm}|}{\textbf{Sem 6}} &amp; \multicolumn{1}{|&gt;{\centering\arraybackslash}m{5mm}|}{\textbf{Sem 7}} &amp; \multicolumn{1}{|&gt;{\centering\arraybackslash}m{5mm}|}{\textbf{Sem 8}} &amp; \multicolumn{1}{|&gt;{\centering\arraybackslash}m{5mm}|}{\textbf{Sem 9}} &amp; \multicolumn{1}{|&gt;{\centering\arraybackslash}m{5mm}|}{\textbf{Sem 10}} &amp; \multicolumn{1}{|&gt;{\centering\arraybackslash}m{5mm}|}{\textbf{Sem 11}} &amp; \multicolumn{1}{|&gt;{\centering\arraybackslash}m{5mm}|}{\textbf{Sem 12}}\\ \hline 1. Text text text text text text text text text text text text text &amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;\\\hline 2. Text text text text text text text text text text text text text &amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;\\\hline 3. Text text text text text text text text text text text text text  &amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;\\\hline 4. Text text text text text text text text text text text text text &amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;\\\hline  \hline \end{tabular} \end{table}  \end{document} Comparing two strings in Bash I have the following if block in my bash script:  if [ ${PACKAGENAME} -eq kakadu-v6_4-00902C ]; then   echo "successfully entered if block!!" fi   The script execution is not entering my if block even though $PACKAGENAME is equal to kakadu-v6_4-00902C. What am I doing wrong? Aside from the repetitive appearance of the black cat, I can't remember seeing any living animals, either inside the Matrix simulation or in Zion.  How come? Is there an in-universe explanation? I would like to have my whole document showing a blank line (or space) between paragraphs and no indentation. I know how to do it line by line, but is there a way to change that with just one or a few lines at the beginning of the document? Like a package you can install, or a new command? How to pull email address and password from text file with CMD? I have a text file named file.txt Which contains,  Combo: testing123mail@gmail.com:password As Combo:  abcdefghijklmnopqrstuvwxyz@gmail.com:ajfbdf some text here some more text here As Combo: hadvsfhia@ahfjbadj.com:password@1 some random text here iloveu@gmail.com:passypassyword123 goldenmammy@hotmail.com:youtube123   I am running the below code, to filter only mail:pass from the above text file file.txt  for /f "tokens=3" %%a in ('type file.txt^|find "As Combo:"') do &gt;&gt;mail.txt echo %%a for /f "tokens=2" %%b in ('type file.txt^|find "Combo:"') do &gt;&gt;mail.txt echo %%b for /f "tokens=1" %%c in ('type file.txt^|find ":"') do &gt;&gt;mail.txt echo %%c   Expected Output in mail.txt,  abcdefghijklmnopqrstuvwxyz@gmail.com:ajfbdf hadvsfhia@ahfjbadj.com:password@1 testing123mail@gmail.com:password iloveu@gmail.com:passypassyword123 goldenmammy@hotmail.com:youtube123   But, am getting actual output is,  abcdefghijklmnopqrstuvwxyz@gmail.com:ajfbdf hadvsfhia@ahfjbadj.com:password@1 testing123mail@gmail.com:password Combo: Combo: Combo: As As iloveu@gmail.com:passypassyword123 goldenmammy@hotmail.com:youtube123   Note: The mail id and passwords will be differ in different text file. Above given mail id and passwords are typed by me randomly for example.  Kindly fix my code and help to get expected output. Thanks in advance. Putting a table next to a figure Show that $a(-1) = (-1)a = -a $. In a ring $R$ with identity 1, show that $$a(-1) = (-1)a = -a \qquad\forall\, a \in R$$ I have started with $a + (-a) = 0$ but cant proceed from here. Privilege banner buggy? Or am I just confused? On the main Stack Overflow site, I arrived and had a banner: "Congrats, you've gained the privilege – create wiki posts and 3 other privileges" This confuses me, because I only see two privileges listed at 100%. Is the banner just buggy?  Or is there a better place to see my privileges that the page linked to by that banner? Self-promotion in chat We know from the  that it is accepted only in a limited way in answers and frowned upon if found to be spammy. We know from  that it can be deleted at any time from comments if the comment is not relevant or spammy.  But what about the chat? This leaves chat to be the only legitimate place to promote products or services that the user is affiliated to (albeit in an ad-like way).  What is your opinion? Cases environment compresses fractions? what should I do to stop the cases environment compressing the first line of the following? \begin{equation} \alpha_{mn} = \begin{cases} \frac{16\mu^2}{mn\pi^2\left[\pi^2(m^2/a^2 + n^2/b^2) - \mu^2\right]} &amp;\mbox{for } m \mbox{ and } n \mbox{ odd;}  \\ 0 &amp;\mbox{for } m \mbox{ or } n \mbox{ even;} \end{cases} \\[1ex] \end{equation}  I'm not sure to do tex on this site, but if anyone tries it they see the first case is compressed because it's a fraction. Does Java have buffer overflows? This has puzzled me for years: How does Blender decide the window where it will display the rendered image when I hit F12 to render? I use LINQ to Objects instructions on an ordered array.  Which operations shouldn't I do to be sure the order of the array is not changed? Showing a recursive sequence isn't bounded $a_{n+1}=a_n+\frac 1 {a_n}$ The space $ C^1[0,1] $- the space of all continuously differentiable functions on $ [0,1]$ is not a Banach space with respect to the sup norm,$ \|.\|_{\infty} $ since the uniform limit of a continuously differentiable function need not be differentiable.  How can I illustate this statement using a counter example? Can I use $ f_{n}=\frac1 n \sin nx $ as a counter example?  Also, is $ C^1[0,1] $ is same as the space given by $ X=\{f\in C^1[0,1]:f(0)=0 \}$. Can I use the same example to show that this is not a Banach space?  More help is appreciated! Thanks! If I pass PHP variables with . in their names via $_GET PHP auto-replaces them with _ characters. For example:  &lt;?php echo "url is ".$_SERVER['REQUEST_URI']."&lt;p&gt;"; echo "x.y is ".$_GET['x.y'].".&lt;p&gt;"; echo "x_y is ".$_GET['x_y'].".&lt;p&gt;";   ... outputs the following:  url is /SpShipTool/php/testGetUrl.php?x.y=a.b x.y is . x_y is a.b.   ... my question is this: is there any way I can get this to stop? Cannot for the life of me figure out what I've done to deserve this  PHP version I'm running with is 5.2.4-2ubuntu5.3. Exercise 12 from SEC. 82 of Finite-Dimensional Vector Spaces - 2nd Edition by Paul R. Halmos.  If $A$ and $B$ are linear transformations on a finite-dimensional inner product space, and if $\textbf{0} \le A \leq B$, then $\det A \leq \det B$.  Notation: $0 \le A$ means that $A$ is positive.  If $\det B = 0$, choose $x \in \ker B$, then $0 \le ((B-A)x,x) = (Bx, x) - (Ax, x) = -(Ax, x) \le 0$. Therefore $\ker B \subseteq \ker A$ and $0 = det A \le det B = 0$. How to prove for the case when $B$ is invertible? Intuitively, I feel that since both $A$ and $B$ are positive their proper values are also positive and $B$'s proper values should be greater the $A$'s and same for determinants. I need to convert one into 1, two into 2 and so on.  Is there a way to do this with a library or a class or anything? Is the Formula Logically Valid? I have a question for my exam and I find it hard to understand.  I have to prove that the following formula is logically valid:    The professor told me to "push" all the symbols inside the brackets, and use the deduction theorem.  But I don't know how to do it, because I can't find the identities to push the "exist" symbol inside the brackets.  Your help is appriciated, thank you.  Alan Convert a JSON string to object in Java ME?