During an academic discussion regarding file formats I received from a most excellent designer, I thought I was correct in writing (based on my experience with hired work):     ...the industry standard for logos is vector...   I received the following response:     Industry standards are interesting things, in that they are more often talked about than actually followed...   We can find all sorts of references to push one point or another, I only talk from experience, and my experience is that even large corporations ala Microsoft are fine with raster.   My question then is perhaps not as simple as I thought:  When hiring a designer to create a logo for an organization (corporate, non-profit, etc.), what is the industry standard deliverable file format (vis-à-vis vector versus raster)?  (Of course, hiring a designer should come with a contract that explicitly states the file format, but most people aren't aware [or don't care] about various file formats and might therefore neglect such a clause.)  This is different than asking what should go into the deliverable package. This question is about an authoritative source that describes what is expected of professional-level deliverables from designers. Some people agree that vector graphics should be included, but is that a de facto standard, or is there an official (or semi-official) body that dictates what people should expect as deliverables from graphic design?
What files should i put in a logo pack to give to clients? Should I put small, medium and large version of my logo as well as the vector file.
EM with Binomial How to detect true Windows version? How to assign symbols to functions I'm trying to understand this proof and I can follow it up the the second last paragraph where it states what happens if n is odd/even. I don't understand why there is just one conjugacy class when n is odd and two when n is even.    Help much appreciated, thanks! Am I Running as a Service I am currently writing a little bootstrap code for a service that can be run in the console. It essentially boils down to calling the OnStart() method instead of using the ServiceBase to start and stop the service (because it doesn't run the application if it isn't installed as a service and makes debugging a nightmare).  Right now I am using Debugger.IsAttached to determine if I should use ServiceBase.Run or [service].OnStart, but I know that isn't the best idea because some times end users want to run the service in a console (to see the output etc. realtime).  Any ideas on how I could determine if the Windows service controller started 'me', or if the user started 'me' in the console? Apparantly  is not the answer. I thought about using commandline args, but that seems 'dirty'.  I could always see about a try-catch statement around ServiceBase.Run, but that seems dirty. Edit: Try catch doesn't work.  I have a solution: putting it up here for all the other interested stackers:      public void Run()     {         if (Debugger.IsAttached || Environment.GetCommandLineArgs().Contains&lt;string&gt;("-console"))         {             RunAllServices();         }         else         {             try             {                 string temp = Console.Title;                 ServiceBase.Run((ServiceBase[])ComponentsToRun);             }             catch             {                 RunAllServices();             }         }     } // void Run      private void RunAllServices()     {         foreach (ConsoleService component in ComponentsToRun)         {             component.Start();         }         WaitForCTRLC();         foreach (ConsoleService component in ComponentsToRun)         {             component.Stop();         }     }   EDIT: There was another question on StackOverflow where the guy had problems with the Environment.CurrentDirectory being "C:\Windows\System32" looks like that may be the answer. I will test today. Python "if X == Y and Z" syntax How do I delete all Folders with a specific name (e.g. 128Kbps_Songs) without deleting its files  For example if I have directory "MP3_SONGS" with subdirectories "A", "B", "C" and each subdirectory has MANY directory Contains Film Name "FILM_NAME1", "FILM_NAME2", "FILM_NAME3" in it, In That Each Film NAme I have specific Folder NAme (128Kbps_Songs) in this "128Kbps_Songs" Folder I have That Film mp3 Songs Files  how can I remove the Folder "128Kbps_Songs", in Each Film_Name directory and Have to get these mp3 songs in that FILM_NAME..   ( Have to Delete 128Kbps_Songs Folder in all FILM_NAME without deleting the mp3 Songs in it, have to get the mp3 in FILM_NAME Directory..  MP3_SONGS (Parent Directory) ------ A , B, C  A (Sub Directory1) ------ FILM_NAME1 , FILM_NAME2 B (Sub Directory2) ------ FILM_NAME3 , FILM_NAME4 c (Sub Directory3) ------ FILM_NAME5 , FILM_NAME6  FILM_NAME1 (Directory) ---- 128Kbps_Songs (Directory) ------ FILM_NAME1 (MP3 Files) FILM_NAME2 (Directory) ---- 128Kbps_Songs (Directory) ------ FILM_NAME2 (MP3 Files)  FILM_NAME3 (Directory) ---- 128Kbps_Songs (Directory) ------ FILM_NAME3 (MP3 Files) FILM_NAME4 (Directory) ---- 128Kbps_Songs (Directory) ------ FILM_NAME4 (MP3 Files)  FILM_NAME5 (Directory) ---- 128Kbps_Songs (Directory) ------ FILM_NAME5 (MP3 Files) FILM_NAME6 (Directory) ---- 128Kbps_Songs (Directory) ------ FILM_NAME6 (MP3 Files)  Need Files in: FILM_NAME1 (Directory)  ------ FILM_NAME1 (MP3 Files) FILM_NAME2 (Directory)  ------ FILM_NAME2 (MP3 Files)  FILM_NAME3 (Directory)  ------ FILM_NAME3 (MP3 Files) FILM_NAME4 (Directory)  ------ FILM_NAME4 (MP3 Files)  FILM_NAME5 (Directory)  ------ FILM_NAME5 (MP3 Files) FILM_NAME6 (Directory)  ------ FILM_NAME6 (MP3 Files) A bold plus symbol in math mode How do we know that entanglement allows measurement to instantly change the other particle's state? I have never found experimental evidence that measuring one entangled particle causes the state of the other entangled particle to change, rather than just being revealed.  Using the spin up spin down example we know that one of the particles will be spin up and the other spin down, so when we measure one and find it is spin up we know the other is spin down. Is there any situation after creation that the particle with spin up will change to spin down? Prove that if for every $x \in \mathbb{R}^N$ $Ax=Bx$ then $A=B$ How to Silence the read command The read command is useful when reading data from the user . I am trying to read a number from 1-5 from the user. How can I make it so the input of the user does not show up in the log I want to copy all images on my computer to a single folder I am looking for the stuff above, so I can make non-duplicate proposals on area 51. Can Xcode 6 and Xcode 5 coexist on the same computer? Polynomial bounded real part of an entire function Let $f(z)$ be an entire function whose real part is bounded by a polynomial in $|z|$. Does it follow that $f(z)$ is a polynomial?  Or, without loss of generality and more suggestively $$(f(z)=\sum_{k=0}^\infty a_k z^k \quad \land \quad \operatorname{Re}(f(z))\leq |z|^n)\quad \forall z\in \mathbb{C} \qquad \Rightarrow \qquad f(z)=\sum_{k=0}^n a_k z^k \quad\forall z\in \mathbb{C}$$ How can I find $f(0)$, $f'(0)$, and $f'(x)$ given that  $f(x+y)=f(x)+f(y)+x^2y+xy^2$  and  $\lim_{x\to0}\frac{f(x)}{x}=1$. Compare Debian (left) and Ubuntu (right):  $ ifconfig                                 $ ifconfig bash: ifconfig: command not found          eth0     Link encap ... $ which ifconfig                           $ which ifconfig $                                          /sbin/ifconfig   Then as superuser:  # ifconfig                                 # ifconfig eth0      Link encap ...                   eth0     Link encap ... # which ifconfig                           # which ifconfig /sbin/ifconfig                             /sbin/ifconfig   Furthermore:  # ls -l /sbin/ifconfig                     # ls -l /sbin/ifconfig -rwxr-xr-x 1 root root 68360 ...           -rwxr-xr-x 1 root root 68040 ...   It seems to me the only reason I cannot run ifconfig without superpowers on Debian is that it's not in my path. When I use /sbin/ifconfig it does work.   Is there any reason I should not add /usr/local/sbin:/usr/sbin:/sbin to my path on Debian? This is a personal computer, I am the only human user.    Versions used (uname -a): Ubuntu:   Linux ubuntu 3.13.0-51-generic #84-Ubuntu SMP Wed Apr 15 12:08:34 UTC 2015 x86_64 x86_64 x86_64 GNU/Linux   Debian:  Linux debian 3.16.0-4-amd64 #1 SMP Debian 3.16.7-ckt11-1+deb8u3 (2015-08-04) x86_64 GNU/Linux Google is counting the domain home page ("/") as a duplicate of "/index.html" For only my index pages, I am receiving this warning in Google Search Console:     Duplicate, submitted URL not selected as canonical   I know that this occurs because Google is attempting to track both the default landing "page" (i.e. www.domain.example/) and the page to which to which DirectoryIndex points (i.e. www.domain.example/index.html). They are, in fact, the same page, and so the warning is the result of a false positive.  Two questions for our community:   Why does Google not conflate these and count them as a single page? Alternately, is there something wrong with my set up if this has happened? I can easily force both pages to point to a single canonical URL. But which is preferable, "/" or "index.html"? I did the following proof and I was wondering if its valid. It feels wrong because I didn't actually test the case when purportedly $n$ is not prime, but please feel free to correct me.  Assume there exists $n$ such that $\phi(n) = 14$. Assume $n$ is prime. Then $\phi(n) = n-1$. Then here, n-1 = 14, so n = 15.  We know since Euler's totient function is multiplicative that $\phi(xy)$ = $\phi(x)\phi(y)$, so $\phi(15) = \phi(3)\phi(5)$, but alas $\phi(3)\phi(5) = 2\cdot4 = 8 \ne 14$. If $n$ is not prime a similar argument follows since we know then that $n$ must be composed of prime numbers by the prime factorization theorem. ISP blocking port 25