I have a very naive question. I started using linguex package, but now I realized I need some options that only expex has. I was wondering if the two packages be used in the same document, or would they be in conflict with one another.   The reason I ask this, is that I need to do the following with linguex, but I am not sure it is doable. First, I need to have right-aligned comments on the first and third line of a gloss.  Based on on the question linked in the comments:      I tried the following:  \documentclass[12pt,letterpaper]{article} \usepackage{amssymb} \usepackage{linguex} \usepackage{cgloss} \begin{document}  \ex. \a. The girls kissed the boy \hfill {\small \checkmark X} \bg. The boy didn't kiss the girl \\  D boy AUX.NEG kiss D girl \\ \hfill {\small \checkmark X} \trans 'The boy did not kiss the girl'. \hfill {\small \checkmark X}  \end{document}   This doesn't quite do what I want because ... ?    Second, I need to add arrows/lines connecting two parts of the example. Something like:
I'm writing a linguistics paper that uses a large amount of linguistic examples from a wide variety of languages, using the gb4e package. I want to be able to label each example with information about the language it comes from, as I've seen in some texts, sort of like this:   Language (family, citation, etc.)      (1) example text          glosses        'translation'    gb4e is great at formatting the examples themselves, but I can't seem to get the label placed where I want it, that is, placed immediately before the example and without an indent. Here's some example code:  \documentclass{article} \usepackage{gb4e} \usepackage{lipsum}  \begin{document} \lipsum[2]  Hungarian (Finn-Ugric, \emph{reference})   \begin{exe}   \ex \gll    J\'anos h\'aza\\               John house.his\\       \glt    `John's house'   \end{exe}  \lipsum[3] \end{document}   If the label text is outside the exe environment, it's treated like a regular paragraph, but if I try to put it inside, it gives me an error. How can I make it look the way I want? I've looked at other packages that do numbered examples, but they don't seem to have solutions either, and they also don't have the same functionality as gb4e that I need.  Any help would be greatly appreciated.
I have been using the default Ubuntu 11.10 with Unity for some time now and decided to start customizing it.  I have already been able to make some changes with the gnome-tweak-tool. However, there are many themes that I get from gnome-look.org that don't appear in the gnome-tweak-tool even after putting them in the /usr/share/themes folder.  Any idea why this is happening? Thanks. How do RAM and processor speed affect overall performance on Android? Since Android can be installed on wide range of devices, I'm wondering how important RAM and the CPU speed are to the performance of a device.  There are always tradeoffs when something is increased and another one decreased!  Is more RAM or a faster processor better for general browsing and less mulititasking?  What if I'm interested in gaming or doing lots of things at once?  Will more RAM make up for a slower processor or vice-versa? Is there any performance reason to declare method parameters final in Java?  As in:  public void foo(int bar) { ... }   Versus:  public void foo(final int bar) { ... }   Assuming that bar is only read and never modified in foo(). I have to prove the  by tomorrow and I am really unconfident about what I did:  $$\sum_{n=1}^\infty a_n\text{ converges } \iff \sum_{n=1}^\infty 2^n a_{2^n}\text{ converges}$$  I did the following:  Let $(b_n)$ be a sequence as follow: $b_{2^k+m}:=a_{2^k}$ with $k\in\mathbb N_0$ and $0\leq m&lt;2^k$.  It's $a_{n+1}\leq a_n$ and so $0\leq a_{n+p}\leq a_n$ for all $n,p\in\mathbb N$.  So $\sum\limits_{n=1}^\infty b_n$ converges by the majorizing series $\sum\limits_{n=1}^\infty a_n$. And it's $\sum\limits_{n=0}^\infty b_n=\sum\limits_{n=0}^\infty\sum\limits_{m=0}^{2^n-1}a_{2^{n+1}}=\sum\limits_{n=1}^\infty 2^{n-1}a_{2^n}$ so $\Rightarrow$ is done.  For $\Leftarrow$ consider $c_{2^k+m}:=a_{2^k}$ with $k\in\mathbb N_0$ and $0\leq m&lt;2^k$.  It's $|a_n|\leq c_n$ and $\sum\limits_{n=0}^\infty c_n=\sum\limits_{n=0}^\infty\sum\limits_{m=0}^{2^n-1}a_{2^{n}}=\sum\limits_{n=1}^\infty 2^{n}a_{2^n}$ and so $\sum\limits_{n=1}^\infty a_n$ converges by the majorizing series $\sum\limits_{n=0}^\infty c_n$.  Is this in form and content correct? I am using PHP and JavaScript. My JavaScript code contains a function, get_data():  function get_Data(){     var name;     var job;     .....      return buffer; }   Now I have PHP code with the following.  &lt;?php     $i=0;     $buffer_data;      /* Here I need to get the value from JavaScript get_data() of buffer;        and assign to variable $buffer_data. */ ?&gt;   How do I assign the JavaScript function data into the PHP variable? How do I remove objects after building them, for example a fence that I placed without taking into account its orientation? I have right clicked on it like you would a structure but nothing happened. I have also tried Shift+Alt+Click and nothing has happened. I couldn't think of any other solutions as this is my first game. BJT as a switch: what am I doing wrong? Can I backup my entire Ubuntu installation to ISO DVD? What is $\int_{c}^{\infty}\Phi(a+bx) \phi( x ) dx$ for $c\in\mathbb{R}$ It is straightforward to show $$\int_{-\infty}^{\infty}\Phi(a+bx) \phi( x ) dx = \Phi\left(\frac{a}{\sqrt{1+b^2}}\right)$$ but what value does $$\int_{c}^{\infty}\Phi(a+bx) \phi( x ) dx$$ have for $c&lt;\infty$, e.g., for $c=0$? Even a good approximation would really help me! Can QGIS export Geospatial PDF for Avenza PDF map app? Since QGIS uses GDAL, does any map exported as a PDF become a Geospatial PDF? I am hoping to import maps from QGIS into the Avenza PDF Map app on my phone. Previous posts mentioned exporting as Geospatial PDF's and GeoTiff's, but none had an exact answer or process. I'm having trouble with a question from an introductory Linear Algebra book. It goes: "Show that the Only Subspaces of $R^2$ are the zero subspace, $R^2$ itself, and the lines through the origin." I'm thinking the easiest way to do this is to show that if $W$ is a subspace of $R^2$ containing $2$ different lines through the origin then $W$ is all of $R^2$. Is this a good way to go about it? and how could I show this? So I have some ISO stock options (yeah) and three kids in college (boo) so I'm trying figure out the best tax strategy. I was hoping someone help me through the following scenario  Strike Price: $10, 2014 exercise price: $20, 2015 price: $25, 2016 price $30   Lets' assume that all of this happens 2+ years after the grant date and that my "normal" tax bill is right on the brink of the AMT threshold, that the AMT tax rate is 28% and the long term capital gains tax is 15%.   Now I want to run the following scenario  2014: exercise 1000 options 2015: exercise 1000 options, sell the previous years' option after "one year and one day" 2016: sell the 2015 options after "one year and a day"    Tax wise that would look like this  2014: AMT on $10000 of bargain element so $2800 AMT 2015: AMT on $15000 bargain element $4200, long term gain tax on $15000 = $2250 2016: long term gain tax on $20000 = $3000    What's the overall tax liability in each year? I can't figure out how the AMT carries forward when the options are finally sold.   Any good pointers to modeling software, spreadsheets or decent papers would also be appreciated. Is it possible to create a URL link to a website on the home screen? I'm working on creating an illustration that I will need in many, different guises in differential geometry/manifold theory etc. Following on from a previous (answered) question of mine (, I want to show how two coordinate lines in the plane originate from two curves on a surface via the chosen map:  \begin{tikzpicture}     \begin{axis}[             name=mfd,             declare function={                     f(\x,\y)=10-(\x^2+\y^2);             },                   declare function={                     c_x(\t)=(cos(\t)+(sin(5*\t)/10))/3+1;             },                   declare function={                     c_y(\t)=(sin(\t))/2-1;             },                   declare function={                     c_z(\t)=f(c_x(\t),c_y(\t));             },           ]                    \addplot3[surf,domain=-2:2,domain y=-2:2,]{f(x,y)};             \addplot3[black,opacity=1.0,variable=t,domain=0:360,dashed,thin] ({c_x(t)},{c_y(t)},{c_z(t)});             \addplot3[black,opacity=1.0,variable=t,domain=-2:2,thin] (t,-1.2,{f(t,-1.2)});             \addplot3[black,opacity=1.0,variable=t,domain=-2:2,thin] (0.8,t,{f(t,-1.2)});             \addplot3[black,opacity=1.0,only marks,mark=text,text mark=$\cdot$] (1,-1,{f(1,-1)}) coordinate (a);     \end{axis}     \begin{axis}[             at={($(mfd.north east)+(1cm,-2cm)$)},             anchor=north west,             declare function={                     c_x(\t)=(cos(\t)+(sin(5*\t)/10))/3+1;             },                   declare function={                     c_y(\t)=(sin(\t))/2-1;             }            ]                    \addplot[variable=t,domain=0:360]({c_x(t)},{c_y(t)});             \addplot[black,opacity=1.0,only marks,mark=text,text mark=$\cdot$] (1,-1) coordinate (b);             \addplot[variable=t,domain=0.6:1.4](t,-1.2);             \addplot[variable=t,domain=-1.5:-0.5](0.8,t);     \end{axis}     \draw [-stealth, shorten &lt;= 3pt, shorten &gt;= 3pt] (a) to[bend left] (b); \end{tikzpicture}   However, I have a couple of problems:   The curves representing the coordinate axes pulled back from the plane via the coordinate map insist on being closed off with a straight line - is there a way to avoid that? I want to draw all the black curves with a thin, dashed line, but I probably don't understand how to set those options. What am I doing wrong?   I apologise if these questions are rather elementary, but I find the relevant manuals difficult to search through; they seem to be meant for reading cover to cover rather than reference. Solving 4 Quadratic Simultaneous Equations Consider the equations:   $$\begin{cases} ab+c+d=3\\ bc+d+a=5\\ cd+a+b=2\\ da+c+b=6 \end{cases}$$   Where $a,b,c,d \in \mathbb{R}$. How can we find $a,b,c,d$?   The furthest I've got is by adding the first two equations and the last two equations together to get: $ab+bc+c+d+d+a=(b+1)(a+c)+2d=8$ and $(d+1)(a+c)+2b=8$ We can rearrange these (assuming $b,d \neq -1$) to get $$\frac{8-2d}{b+1}=\frac{8-2b}{d+1} \implies -d^{2}+3d+4=-b^{2}+3b+4$$ Which leads us further to $$b^{2}-d^{2}-3(b-d)=0 \implies (b-d)(b+d-3)=0$$ Now since $b=d$ gives us an absurdity (equations 1 and 4 reduce to 3=6), we must have $b+d=3$. This is as far as I can get unfortunately, since trying the same approach with the other pairs doesn't work in the same way.  Help would be much appreciated; the problem is from the BMO1 2004 paper. Show that if terms of a series have ratio less than the ratio of convergent series, then the series converges We have two infinite series $\sum a_n $ and $\sum b_n$, such that $a_n &gt; 0,\ b_n &gt; 0$ and $a_{n + 1}/a_n \leq b_{n + 1}/b_n$ for all $n$. Show that if $\sum b_n$ converges, then $\sum a_n$ also converges.   Any hints on how to prove this? I can sort of picture why this must be true, but I'm not sure how to prove this rigorously. I'm not sure using the ratio test would help here.. Do I need a visa for Georgia? I am a Nigerian, holding a valid schengen visa issued by the French embassy, and a multiple entry visa for the United States. Will I be allowed to enter Tbilisi in Georgia? How does the drift velocity of electrons in a conductor depend on the temperature? How does the drift velocity of electrons in a conductor depend on the temperature?  I have two contradicting views for this.    First, we can say that increasing the temperature of the conductor will increase the kinetic energy of the electrons. Hence, their drift velocity should increase with increase in temperature.  Or, from the relation $v_d = \frac{eE}{m}T$ ($T$ is the relaxation time) we can say that the drift velocity is directly proportional to the relaxation time. Increasing the temperature will obviously decrease the relaxation time - as collisions will become more frequent - and thus decrease the drift velocity. Hence, an increase in the temperature will cause a decrease in the drift velocity.   So which view is correct? Prove that the union of the interior of a set and the boundary of the set is the closure of the set I'll denote closure of A with $\overline{A}$, $A^\circ$ as the interior of A, $\partial A$ as the boundary of $A$ and $A'$ as the accumulation points. I'm trying to prove the following:   $$\overline{A}=A^\circ \cup\partial A$$  Is this a valid proof?  Take $x \in A^\circ \cup \partial A$ then $x \in A^\circ$ or $x \in \partial A$   if $x \in A^\circ$ then $x \in \overline{A}$  if $x \in \partial A$ then $x \in \overline{A} \cap\overline{(X\setminus A)}$ thus $x \in\overline{A} $ so $A^\circ\cup\partial A\subset\overline{A}$  Take $x \in \overline{A}$ then $x \in A' \cup A$ thus $x \in A'\setminus A$ or $x \in A^\circ$  if $x \in A'\setminus A$ then $x \in \overline{(X\setminus A)}$ so $x \in \overline{A}\cap\overline{(X\setminus A)}$ and $x \in\partial A$ so $x\in A^\circ\cup\partial A$  if $x \in A^\circ$ then $x \in A^\circ\cup \partial A$ so $\overline{A}\subset A^\circ\cup\partial A$ I have an issue with my Minecraft launcher - I downloaded modpack for minecraft then the launcher started an update for the modpack version which it's 1.6.2, however then I started to get the issue      [15:40:59 ERROR]: Gave up trying to download      for job 'Version &amp; Libraries'      [15:40:59 ERROR]: Job 'Version &amp; Libraries' finished with 26   failure(s)! (took 0:01:06.362)   At the same time I had just downloaded Avira antivirus and ran it, but unfortunately  removing it and trying again didn't help. I've tried to restore the system to the point before downloading the antvirus and the mod pack a 2 days ago, I've tried turning off the firewall and I have tried removing the whole .minecraft folder all with no luck at all. I can't figure it out, all the servers are working and I have good internet connection but some of the files download fine and other don't.  The full log is here:  [15:40:59 WARN]: Couldn't download https ://libraries.minecraft.net/net/sf/jopt-simple/jopt-simple/4.5/jopt-simple-4.5.jar for job 'Version &amp; Libraries' java.net.SocketTimeoutException: connect timed out         at java.net.TwoStacksPlainSocketImpl.socketConnect(Native Method) ~[?:1.7.0_45]         at java.net.AbstractPlainSocketImpl.doConnect(Unknown Source) ~[?:1.7.0_45]         at java.net.AbstractPlainSocketImpl.connectToAddress(Unknown Source) ~[?:1.7.0_45]         at java.net.AbstractPlainSocketImpl.connect(Unknown Source) ~[?:1.7.0_45]         at java.net.PlainSocketImpl.connect(Unknown Source) ~[?:1.7.0_45]         at java.net.SocksSocketImpl.connect(Unknown Source) ~[?:1.7.0_45]         at java.net.Socket.connect(Unknown Source) ~[?:1.7.0_45]         at sun.security.ssl.SSLSocketImpl.connect(Unknown Source) ~[?:1.7.0_45]         at sun.net.NetworkClient.doConnect(Unknown Source) ~[?:1.7.0_45]         at sun.net.www.http.HttpClient.openServer(Unknown Source) ~[?:1.7.0_45]         at sun.net.www.http.HttpClient.openServer(Unknown Source) ~[?:1.7.0_45]         at sun.net.www.protocol.https.HttpsClient.&lt;init&gt;(Unknown Source) ~[?:1.7.0_45]         at sun.net.www.protocol.https.HttpsClient.New(Unknown Source) ~[?:1.7.0_45]         at sun.net.www.protocol.https.AbstractDelegateHttpsURLConnection.getNewHttpClient(Unknown Source) ~[?:1.7.0_45]         at sun.net.www.protocol.http.HttpURLConnection.plainConnect(Unknown Source) ~[?:1.7.0_45]         at sun.net.www.protocol.https.AbstractDelegateHttpsURLConnection.connect(Unknown Source) ~[?:1.7.0_45]         at sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source) ~[?:1.7.0_45]         at java.net.HttpURLConnection.getResponseCode(Unknown Source) ~[?:1.7.0_45]         at sun.net.www.protocol.https.HttpsURLConnectionImpl.getResponseCode(Unknown Source) ~[?:1.7.0_45]         at net.minecraft.launcher.updater.download.ChecksummedDownloadable.download(ChecksummedDownloadable.java:49) ~[launcher.jar:?]         at net.minecraft.launcher.updater.download.DownloadJob.popAndDownload(DownloadJob.java:108) [launcher.jar:?]         at net.minecraft.launcher.updater.download.DownloadJob.access$000(DownloadJob.java:12) [launcher.jar:?]         at net.minecraft.launcher.updater.download.DownloadJob$1.run(DownloadJob.java:89) [launcher.jar:?]         at java.util.concurrent.Executors$RunnableAdapter.call(Unknown Source) [?:1.7.0_45]         at java.util.concurrent.FutureTask.run(Unknown Source) [?:1.7.0_45]         at java.util.concurrent.ThreadPoolExecutor.runWorker(Unknown Source) [?:1.7.0_45]         at java.util.concurrent.ThreadPoolExecutor$Worker.run(Unknown Source) [?:1.7.0_45]         at java.lang.Thread.run(Unknown Source) [?:1.7.0_45] [15:40:59 ERROR]: Gave up trying to download https ://libraries.minecraft.net/net/sf/jopt-simple/jopt-simple/4.5/jopt-simple-4.5.jar for job 'Version &amp; Libraries' [15:40:59 ERROR]: Job 'Version &amp; Libraries' finished with 26 failure(s)! (took 0:01:06.362)