Does a character have to do a saving throw at the end of his turn or can he or she choose to keep an effect active on them?  Will my idea below work as intended?  I'm looking into making a dragonborn dragon magic sorcerer with the following (all from phb-dragonborns):  Ninefold Master Paragon Path: Breath Expertise (lvl 11): Your dragon breath is considered an arcane power belonging to each of your arcane classes.  If you are wielding an implement you can use for your arcane powers, you can add the implement's enhancement bonus to the damage rolls for your dragon breath power.  Burning Breath Feat: - Benefit: Choose one creature hit by your dragon breath. That creature takes ongoing fire damage equal to your con modifier (save ends).  Ancient Soul: - Benefit: ... Whenever you take damage of the type dealt by your dragon breath (after the damage dealt is reduced by your resistance), you regain the use of your dragon breath if you have already expended it in this encounter.  Hurl Breath: - Benefit: When you use your dragon breath, you can choose to make it an area burst 2 within 10 squares instead of a close blast 3.  Correct me if I'm wrong, but from my understanding I would be able to cast my dragonbreath as a ranged burst with my character as one of the targets.  I would take essentially the full damage of the dragon breath along with anyone else hit by the attack.  My resistances wouldn't matter because the dragon soul class feature states that "Your arcane powers ignore any target's resistance to that damage type up to the value of your resistance".  Seeing how my dragon breath would now be an arcane power (as per the paragon path), i'd take full damage.  This inturn would trigger Ancient Soul allowing me to regain my dragonbreath for future use.  Now for the important part.  If I select myself to take the ongoing fire damage equal to my con modifier (aka 1 damage) from the burning breath feat, could I choose to not try and save against the effect at the end of my turn to keep regaining my dragonbreath without having to recast it on me each time?
What happens if I am afflicted with a condition that worsens on a failed save and choose not to try to save? Do I:   Automatically suffer the effects of the failed save? Keep my current condition? Have no choice and must roll the save regardless?   This came up in a game earlier this afternoon when we decided to just stop saving against the effect that was causing us to fall unconscious.
Carrying a handgun in other countries with a US concealed carry permit Cooking steak in frying pan, problem with oil splatter What is the correct way to punctuate the end of a sentence before a quote that directly supports the statement? I assume either a colon or a semicolon, but I have no idea which is correct.  For example:     Waldo is a better hide-and-seek player than Clem; "Waldo was   the winner of the past ten annual hiding awards" (Where's Waldo 13).      Waldo is a better hide-and-seek player than Clem:  "Waldo was   the winner of the past ten annual hiding awards" (Where's Waldo 13).   (Excuse the silly example, but I didn't have a better one.) How to properly indent PHP/HTML mixed code? Flattening a shallow list in Python How to control Windows 7 snap feature with two monitors? There is an  feature in Windows 7. However, it seems to not work when dragging a window to the edge that is adjoined to the second monitor. How to make it work properly? Maybe some regedit modification or something? Is this a valid partial fraction decomposition? Write $\dfrac{4x+1}{x^2 - x - 2}$ using partial fractions. $$ \frac{4x+1}{x^2 - x - 2} = \frac{4x+1}{(x+1)(x+2)} = \frac{A}{x+1} + \frac{B}{x-2} = \frac{A(x-2)+B(x+1)}{(x+1)(x-2)}$$ $$4x+1 = A(x-2)+B(x+1)$$ $$x=2 \Rightarrow 4 \cdot2 + 1 = A(0) + B(3) \Rightarrow B = 3$$ $$x = -1 \Rightarrow 4(-1) +1 = A(-3)+ B(0) \Rightarrow A = 1$$ Thus, $$\frac{4x+1}{x^2-x-2} = \frac{1}{x+1} + \frac{3}{x-2}\textrm{.}$$  The substitution of $x$ ($x = 2, -1$) is a common method to find out the coefficient of the partial fractions. However, the equation on the third line is obtained by multiplying $(x+1)(x-2)$, which is assumed to be nonzero. Here we have a contradiction. Furthermore, the original function is not defined at $x=-1,2$. How can we substitute these value for $x$? So is this method valid and rigorous? How to modify it so that it is rigorous? It maby be weird, I want to make header and footer for every page including the first page of each chapter, how can I do this? I've found in Wikipedia the formula for calculating an individual row in Pascal's Triangle: $$v_c = v_{c-1}\left(\frac{r-c}{c}\right).$$ where $r = \mathrm{row}+1$, $c$ is the column starting from $0$ on left and $v_0 = 1$.  Now, I've tried to do by hand and it works,  but I don't understand how to find this magic formula when I don't have access to Wikipedia...:) What are Unity's keyboard and mouse shortcuts? In Unity, are there any pre-defined shortcuts, e.g. to open the dash or unhide the launcher? $f(z)=\frac1{2\pi i}\int_{\Gamma}\frac{f(\zeta)}{z-\zeta}d\zeta$ if $\lim_{z\to\infty}f(z)=0$ and $f$ is analytic in $|z|\ge1$ Let $f$ be analytic in $|z|\ge1$ and  $\lim_{z\to\infty}f(z)=0$. Then is $f(z)=\frac1{2\pi i}\int_{\Gamma}\frac{f(\zeta)}{z-\zeta}d\zeta$,$\forall |z|\ge2$, where $\Gamma$ is the circle of radius $2$ with centre at the origin.   I think yes, by the Cauchy integral formula. But, how do we ensure that the non analyticity of $f$ in $|z|&lt;1$ dosent affect the formula? Thanks beforehand. ArcGIS Serious Application Error I'm a complete novice to GIS and just began an Introductory course. I am having an issue when I try to access the Symbology tab on a layer. Specifically, when I click on the 'Categories' field and 'Unique Values' subfield, ArcMap crashes and comes up with a report window to send to ESRI. The message is      ArcGIS for Desktop has encountered a serious application error and is   unable to continue.   What could be the problem? How can I display site logo, name and slogan? Environment variables when run with 'sudo' Prove that if $a^2 = a$ for all elements of the ring $R$, then $R$ has characteristic 2. Is the converse of the statement true?  Attempt:  by the definition of characteristic of a ring, the first statement implies that characteristic of the ring is $\leq 2$. If the ring is assumed to be non trivial ring then, characteristic is 2.  About the last statement can we construct a field of say 8 elements and show that there exists a an element of order $\neq 2$?  Is there a simpler example ? Does a percentage require a singular or plural verb, for example, do we say ten percent "go" or "goes"? How do I completely reset network settings? When I get exceptions, it is often from deep within the call stack.  When this happens, more often than not, the actual offending line of code is hidden from me:  tmp.rb:7:in `t': undefined method `bar' for nil:NilClass (NoMethodError)         from tmp.rb:10:in `s'         from tmp.rb:13:in `r'         from tmp.rb:16:in `q'         from tmp.rb:19:in `p'         from tmp.rb:22:in `o'         from tmp.rb:25:in `n'         from tmp.rb:28:in `m'         from tmp.rb:31:in `l'          ... 8 levels...         from tmp.rb:58:in `c'         from tmp.rb:61:in `b'         from tmp.rb:64:in `a'         from tmp.rb:67   That "... 8 levels..." truncation is causing me a great deal of trouble.  I'm not having much success googling for this one:  How do I tell ruby that I want dumps to include the full stack? I am using 301 redirects for all URLs.  Should I change sitemap URLs now?  The sitemap currently contains the following URLs:   example.com/cat/1.html example.com/cat/2.html example.com/cat/3.html   Should I change the sitemap's URLs to a new destination?   example.com/cat/year/1.html example.com/cat/year/2.html example.com/cat/year/3.html How do you make a torus 'telescope' open? So I have a torus, and I need it to "telescope" open -- kind of like Pacman's death animation, but with a torus instead of a sphere.  I'm very new to 3D modeling/animating so I really have no clue how to tackle this problem.  Any advice to help me get pointed in the right direction would be most appreciated :)