I requested my elementary OS account be deleted, and I confirmed it, and the countdown reached 2 hours at 11:30pm BTC. I went back on my computer today, and my account was still active and receiving reputation - I'd passed 2000 overnight.  Is it an issue with global authentication that caused this?    I have contacted the team again so they do / will know.
I have 3 accounts that I am deleting - however, several hours after the 24 hour (+ grace period - end about 4-5 hours ago), the countdown completed, but disappeared and the accounts are still there.   I would rather not go through another 24 hours, and would like to have these accounts deleted (and yes, I have thought about it and this decision is not up for discussion).  Currently, the accounts are still there.  Could this please be seen to?
If one were to take a similar path as  in shooting candid street photography today, should they be concerned about laws or other realistic norms of today? I am wondering specifically in the US speaking broadly of all states. I am not looking for legal advice, but anything that one photographer to another would caution against as potentially being grey or obviously illegal.  Similar previous question: In either case, one coin flip resulted in a head and the other resulted in a tail. Why is {H,T} a different outcome than {T,H}? Is this simply how we've defined an "outcome" in probability?   My main problem with {H,T} being a different outcome than {T,H} is that we apply binomial coefficients (i.e. we count subsets of sets) in some common probability problems. But if we take {H,T} and {T,H} to be different outcomes, then our "sets" are ordered, but sets are by definition unordered...   I feel as though the fact that I'm confused about something so basic means that I am missing something fundamental. Any help or insight whatsoever is greatly appreciated! I feel that there is a subtle difference in meaning between 'efficacy' and 'efficiency', but I couldn't find any authoritative sources that could help me confirm or refute this. Is there any difference between the two words, especially in scientific context? Resize Move Partitions on Dual Boot System I would like to be able to adjust the partitions shown below. Specifically, I want to add an additional 10GB from the unallocated space to /dev/sda5 (Ubuntu install). I will then format the remaining unallocated space as NTFS so it can be shared data between Windows and Ubuntu.   I am unable to increase the size of /dev/sda5 - I am only able to shrink it.  Any assistance would be greately appreciated. What is the exact use of the symbols $\partial$, $\delta$ and $\mathrm{d}$ in derivatives in physics? How are they different and when are they used? It would be nice to get that settled once and for all.  $$\frac{\partial y}{\partial x}, \frac{\delta y}{\delta x}, \frac{\mathrm{d} y}{\mathrm{d} x}$$   For what I know, $\mathrm{d}$ is used as a small infinitisemal change (and I guess the straight-up letter $\mathrm{d}$ is usual notation instead of italic $d$, simply to tell the difference from a variable). Of course we also have the big delta $\Delta$ to describe a finite (non-negligible) difference. And I have some vague idea that $\partial$ is used for partial derivatives in case of e.g. three-dimensional variables. Same goes for $\delta$, which I would have sworn was the same as $\partial$ until reading this answer on Math.SE:    Then to make the confusion total I noticed an equation like $\delta Q=\mathrm{d}U+\delta W$ and read in a physics text book that:     The fact that the amount of heat [added between two states] is dependent on the path is indicated by the symbol $\delta$...   So it seems $\delta$ means something more? The text book continues and says that:     a function [like the change in internal energy] is called a state function and its change is indicated by the symbol $\mathrm{d}$...   Here I am unsure of exactly why a $\mathrm d$ refers to a state function.   So to sum it up: down to the bone of it, what is $\delta$, $\partial$ and $\mathrm{d}$ exactly, when we are talking derivatives in physics.  Addition  Especially when reading a mathematical process on a physical equation like this procedure:  $$\delta Q=\mathrm{d}U+p\mathrm{d}V \Rightarrow\\ Q=\Delta U+\int_1^2 p \mathrm{d}V$$  It appears that $\delta$ and $\mathrm{d}$ are the same thing. An integral operation handles it the same way apparently? Provide an easily discoverable way to get the full URL to an answer How does Lockable Suspension work? I recently asked a question about . There  told me about the “blow off” feature. Now, I am curious about how the whole system works.   So, can anyone tell me about how a lockable front suspension works, together with features like “remote-lock” and “blow-off”. How can I adjust Cycles material displacement amount? How does one parse XML files? Is there a simple method of parsing XML files in C#? If so, what? I downloaded Linux CAPT driver V2.60 from Canon and installed both .deb packages, which were listed under the 64bit folder with Ubuntu Software-Center. My Canon printer still won't be recognized. Is there anything else I have to do? My printer is connected over USB.  Ubuntu would make a great replacment for my office, but unfortunately without printer support I will still rely on Windows. How do I generate the upper triangular indices from a list? How to construct an example of a probability distribution for which $\mathbb{E}\left(\frac{1}{X}\right)=\frac{1}{\mathbb{E}(X)}$ holds, assuming $\mathbb{P}(X\ne0)=1$?    The inequality which follows from Jensen's inequality for a positive-valued RV $X$ is like $\mathbb{E}\left(\frac{1}{X}\right)\ge\frac{1}{\mathbb{E}(X)}$ (the reverse inequality if $X&lt;0$). This is because the mapping $x\mapsto\frac{1}{x}$ is convex for $x&gt;0$ and concave for $x&lt;0$. Following the equality condition in Jensen's inequality, I guess the distribution has to be degenerate for the required equality to hold. A trivial case where the equality holds is of course if $X=1$ a.e. Here is an example I found in a problem book: Consider a discrete random variable $X$ such that $\mathbb{P}(X=-1)=\frac{1}{9}, \mathbb{P}(X=\frac{1}{2})=\mathbb{P}(X=2)=\frac{4}{9}$. It is then easily verified that $\mathbb{E}\left(\frac{1}{X}\right)=\frac{1}{\mathbb{E}(X)}=1$.   This example shows that $X$ need not be positive (or negative) a.e. for the equality in the title to hold. The distribution here is not degenerate either.  How do I construct an example, possibly like the one I found in the book? Is there any motivation? Deriving upper bound for derivative of analytical function $f$ is an analytical function on the unit disk $\mathbb{D}$ for which there is a $C &gt; 0$ such that  $\forall z \in \mathbb{D} \colon |f(z)| \leq \dfrac{C}{1-|z|}$.  I know have to prove that    $\forall z \in \mathbb{D} \colon |f'(z)| \leq \dfrac{4C}{(1-|z|)^2}$.  I tried using the Cauchy integral formula but I can't find a fitting circle to get this result. How was this character killed without Avada Kedavra? Composition of two Riemann integrable functions Does Thunderbolt support chaining multiple monitors to a MacBook Pro? This has always been a big want for me. I love using multi-monitor setups but only want a single laptop. Does the 2011 MBP Thunderbolt support chaining multiple monitors together? I know that you can add a monitor and say, a few hard drives, but can you connect it to 2 27" monitors and your flat screen TV (for example)? Thanks! Multiplying Binomial Terms What are the minimum requirements to run Windows 10? I am looking to upgrade my system to Windows 10 RTM, but I'm afraid of losing performance.  I researched on the site but found details (maybe I have not sought duty) on the hardware minimum.  What are the minimum and recommended requirements for running Windows 10 RTM? Why do we say "try and" [verb] instead of "try to" [verb]? (E.g., "Try and call me tomorrow.") In written and standard semi-formal (and above) spoken English, one would use &quot;try to&quot;:  Try to be a better person. Try to get the fishhook out of my thumb, please. Try to find a pharmacy when you need one.  But in spoken English, we (Americans, at least) usually substitute &quot;try and&quot; for all those cases. &quot;Try to&quot; makes sense because the &quot;to&quot; begins the construction of an infinitive: &quot;try to be&quot;, &quot;try to do&quot;, &quot;try to act&quot; and so on. &quot;Try and&quot; on the other hand doesn't seem to make any sense. I'm curious how the &quot;try and&quot; crept in, and when. It's really tough to Google small words like these, so I'm not finding anything on the Web. Is it a contraction of something like &quot;Try hard, and ...&quot;? Note: I've seen  and it is somewhat related but doesn't tell me what I want to know. Edit Observe how, even on this site,  construction. Turning it on its head Note that you can't make a negative construction with &quot;try and&quot;:  It's raining. Try not to get wet. It's raining. Try not and get wet. [?]  Even adding do doesn't help. The following means something different from &quot;try not to get wet.&quot;  It's raining. Don't try and get wet.  Even use of to instead of and there means something else:  It's raining. Don't try to get wet.  &quot;Try not to get wet&quot; means try to stay dry. &quot;Don't try to get wet&quot; means avoid actively seeking out a soaking, and implies that a soaking might in fact be what you are looking for. MORE I just happened to notice a video from an editor for Merriam-Webster on this very topic, so I include the link here: . Sum of $k {n \choose k}$ is $n2^{n-1}$ Proof that $\suṃ̣_{k=1}^{n}k {n \choose k}$ for $n \in \mathbb N$ is equal to $n2^{n-1}$.  As a hint I got that $k {n \choose k} = n {n-1\choose k-1} $.  I tried solving this by induction but, in the inductive step I'm not arriving to the correct result.