How do i make an outline on my mesh in blender v2.79+ I have tried many of the videos that teach this and tell me to use the backface culling like this one   however it does not seem to work in this version as my mesh will just show up black. though one of the comments say to add a geometry node messing with that either crashes blender or makes my outline all white and does not fix the problem.  I want the outline to work like the one made through the backface culling method and i want to be able to do it in blender render,besides just using the freestyle.  I have 1.Duplicated the mesh 2.Made a new material 3.Made it black and shadeless 4.Scaled the black mesh to be bigger than the original mesh 5.I Inverted that faces using recalculate normals inside 6.I then activate backface culling. Thats it But when i hit render the cube and my meshes are still black
How do you add a thin outline? I am new at this. I am extracting files a game. In the game they have thin black outlines, but they aren't part of a model. I am having trouble finding anything about this. What is the simplest way to do this?  Update: I think I am looking for something like freestyle. What is the simplest way to use this to create a thin black outline around a model?
I'm trying to install Windows 7 with a 4GB flash drive, but my error that comes up is that my hard drive I'm trying to install on is in ext4. I need to format it to read NTFS. I can't seem to find any topics on how to format an active hard drive. I found a topic that explains how to move Ubuntu to a new drive, but it's a bit confusing to me. Can git be integrated with Xcode? Prime dividing the binomial coefficients It is quite easy to show that for every prime $p$ and $0&lt;i&lt;p$ we have that $p$ divides the binomial coefficient $\large p\choose i$; one simply notes that in $\large \frac{p!}{i!(p-i)!}$ the numerator is divisible by $p$ whereas the denominator is not (since it is a product of numbers smaller than $p$ and $p$ is prime).  My problem is with generalizing this argument for $q=p^n$. I'm looking for the most elegant and simple way to prove that $p$ still divides $\large q\choose i$. Posting only once every 40 minutes even for experienced users? I have low rep on Physics &amp; Woodworking, but not so on Stack Overflow.  I just tried to ask &lt; 40 minute interval on those two and got hit with the :    I posted once on Woodworking, then ~5 minutes later tried to post on Physics, and was denied because of the 40 min rule. So apparently the system looks cross-network to assess this rule.  It seems the system is looking at my lowest cross-network rep when applying this rule rather than highest rep? What is the point of this very conservative approach? It would seem there is very little chance that a user with high rep on ANY site is likely to spam or abuse the lower-rep sites. And obviously this discourages participation across the network.  Furthermore, an improvement at least would be to warn the user ASAP so they aren't stuck with a nicely worded question in their browser window only which could be forgotten, lost, etc. As it is you only get the warning when you click [Post Your Question]. I simply know that a single free quark does not exist. What is the reason that we can not get a free quark?  If we can't get a free quark then what is single-top-quark? Agreement With Compound Subjects Joined by And I was surfing the internet the other day when I found this phrase: Instead your precious time and attention is wasted. To my ears, it sounds wrong. But I'm not a native English speaker, so I consulted with a number of them, and some of them said that it was "is" because the adjective modifies only the noun "time" and not "attention". Others said it "is" because that's just how it is. But I still believe it should be "are". Any help is appreciated. I am trying to add jQuery to my page (it is not being added by default). The file is adding to the page but after drupal.js causing the error:  SCRIPT5009: 'jQuery' is undefined  drupal.js, line 5 character 1    The code that adds drupal.js to the page in common.inc  ... 'misc/drupal.js' =&gt; array(           'data' =&gt; 'misc/drupal.js',           'type' =&gt; 'file',           'scope' =&gt; 'header',           'group' =&gt; JS_LIBRARY,           'every_page' =&gt; TRUE,           'weight' =&gt; -1,           'preprocess' =&gt; TRUE,           'cache' =&gt; TRUE,           'defer' =&gt; FALSE,         ), ...   In my module hook_init I have:    drupal_add_js('misc/jquery.js', array(     'group' =&gt; JS_LIBRARY,     'weight' =&gt; -20,     'cache' =&gt; TRUE,   ));   I would think with a lower weight it would load before drupal.js?  The header of the page contains the following scripts:  &lt;script type="text/javascript" src="http://mysite.com/misc/drupal.js?mqdxrf"&gt;&lt;/script&gt; &lt;script type="text/javascript" src="http://mysite.com/misc/jquery.js?mqdxrf"&gt;&lt;/script&gt; &lt;script type="text/javascript" src="http://mysite.com/misc/jquery.once.js?mqdxrf"&gt;&lt;/script&gt; &lt;script type="text/javascript" src="http://mysite.com/sites/default/files/languages/nl_c9aC92_wtuULa79-hTFcGPM53oqk1yKwciOa_Q3yO28.js?mqdxrf"&gt;&lt;/script&gt; &lt;script type="text/javascript" src="http://mysite.com/sites/all/modules/lang_dropdown/msdropdown/jquery.dd.js?mqdxrf"&gt;&lt;/script&gt; &lt;script type="text/javascript" src="http://mysite.com/sites/all/modules/lang_dropdown/lang_dropdown.js?mqdxrf"&gt;&lt;/script&gt; &lt;script type="text/javascript" src="http://mysite.com/sites/all/modules/devel/devel_krumo_path.js?mqdxrf"&gt;&lt;/script&gt; Where are static variables stored in C and C++? How does TikZ sort intersections? I used the sort by key for intersections to sort along a line, expecting the intersections to be numbered 1 through 5. Why were they numbered 4, 5, 3, 1, 2? Playing around with it, I could not seem to figure out how the order is determined. The code and image follow.  \documentclass{standalone} \usepackage{tikz} \usetikzlibrary{intersections}  \begin{document} \begin{tikzpicture}     \draw[name path=grid] [xstep=3,ystep=2] (0,0) grid (9,8);     \draw[-&gt;, name path=line] (2,1) -- (7,7);     \draw[name intersections={of=grid and line, sort by=line, name=i, total=\t}]         \foreach \s in {1,...,\t}{(i-\s) node {\s}}; \end{tikzpicture} \end{document} How to get the list of IP addresses in a LAN? I found the below in  web-site:     We use much in questions and negative clauses to talk about degrees of something.      We don’t use much in affirmative clauses.   Also, it the same web-site, I found the following:     She runs much faster than he does.    also I noticed that some web-sites use much with affirmative clauses:     May we all be having this much fun and getting this much exercise when we're his age!    Is it Okey to use much in affirmative clauses? If yes, when can we use it? and what is the rules?  Update:  Here is another example on how often the word "much" is used  in informal style:     After much consideration I will NOT be performing at the Inauguration with my improv group Capitol Hill-arious Legitimate edits of less than 6 characters I recently came across an  by  which contained a link to a specification that has since been moved. When attempting to edit the link, a change which involved the subtraction of only 4 characters, I ran up against the 6 character minimum requirement.  Ordinarily this would not be an issue. A less experienced poster would likely have other things within the answer that could be changed (). In fact, this seems to be the answer on every meta post relating to this topic (, , etc...).  The problem here, since I don't have 2k reputation, is that BalusC writes excellent answers... with the reputation to back them up. I don't feel there is anything in the post (besides the link) that would benefit from me editing.  What is the standard practice here?   Flag the post and explain my situation in the notes (for someone with higher reputation)? Comment on the post and hope that a) visitors read the comments or b) the OP gets notified and updates their post? Make edits, for the sole purpose of increasing characters, providing no benefit and possibly hurting the quality of the post?   For reference, the EL Specification in the post should be changed to , if someone wants to go ahead and take care of this. My question is specifically for badges in a particular tag. I've heard that the rules have been changed.  How and when can one get bronze, silver and gold badges for a specific tag, say ? What are the new rules governing these badges? Let $A$ be a $n \times n$  invertible  matrix.Define a function $F:\mathbb{R}^{n} \times \mathbb{R}^{n} \rightarrow \mathbb{R}$ by $F(x,y)=\langle Ax,y\rangle$. Let $DF(x,y)$ denotes the derivative of $F$ at $(x,y)$ which is a linear transformation from $\mathbb{R}^{n} \times \mathbb{R}^{n} \rightarrow \mathbb{R} $. Then      1) if $x\neq 0$,then  $DF(x,0)\neq 0$      2) if $y\neq 0$,then  $DF(0,y)\neq 0$      3)  if $(x,y)\neq (0,0)$,then $DF(x,y)\neq 0$      4) if $x=0 \; or \;y=0$,then $DF(x,y)= 0$   I don't even know how to start the solution and also how to take derivative in higher dimensions.  Please help!  Thank you. Let $K=F[x]/(p(x))$, where $F$ is a field, $p(x)\in F[x]$ is an irreducible polynomial.  What are all the maximal ideals in $K[y]$?  Attempt: I have an attempt, but not entirely sure it is correct.  Since $(p(x))$ is a maximal ideal in $F[x]$, this means $K$ is actually a field.  Thus $K[y]$ is a PID.  So maximal ideals in $K[y]$ are $(g(y))$ for irreducible polynomials $g(y)\in K[y]$? jquery selector not working with [ ] I wrote a little bash script that made me stumble across the . I did not know about this problem before and I just dare on posting the --debug output I got from date when my script tried to calculate across this magic date (03:14:07 UTC on 19 January 2038).  date -d "20380119"  date: parsed number part: today/this/now date: input timezone: +01:00 (set from system default) date: warning: using midnight as starting time: 00:00:00 date: starting date/time: '(Y-M-D) 2038-01-19 00:00:00 TZ=+01:00' date: '(Y-M-D) 2038-01-19 00:00:00 TZ=+01:00' = 2147468400 epoch-seconds date: output timezone: +01:00 (set from system default) date: final: 2147468400.000000000 (epoch-seconds) date: final: (Y-M-D) 2038-01-18 23:00:00 (UTC0) date: final: (Y-M-D) 2038-01-19 00:00:00 (output timezone TZ=+01:00) Tue Jan 19 00:00:00 CET 2038   date -d "20380119 + 1 days"  date: parsed hybrid part: +1 day(s) date: input timezone: +01:00 (set from system default) date: warning: using midnight as starting time: 00:00:00 date: starting date/time: '(Y-M-D) 2038-01-19 00:00:00 TZ=+01:00' date: warning: when adding relative days, it is recommended to specify 12:00pm date: error: adding relative date resulted in an invalid date: '(Y-M-D) 2038-01-20 00:00:00 TZ=+01:00' date: invalid date '20380119 + 1 days'   date -d "20380120" --debug  date: parsed number part: today/this/now date: input timezone: +01:00 (set from system default) date: warning: using midnight as starting time: 00:00:00 date: error: invalid date/time value: date:     user provided time: '(Y-M-D) 2038-01-20 00:00:00 TZ=+01:00' date:        normalized time: '(Y-M-D) 2038-01-20 00:00:00 TZ=+01:00' date:  date:      possible reasons: date:        numeric values overflow; date:        missing timezone date: invalid date '20380120'   Is there any way to make GNU date calculate across this date? (on a LINUX 32 bit system)    Operating System: Debian GNU/Linux buster/sid             Kernel: Linux 4.12.0-2-686-pae       Architecture: x86 Area of intersection of two Annulus Given two separate annulus with centers $[C_1,C_2]$ and their corresponding radii being $[R_1,r_1]$ and $[R_2,r_2]$ respectively, larger radius being $R$. There are methods to look at whether they are overlapping or not. If they overlap how to find the overlapping area. Is there any close form expression for it?  equation of first annulus   $r_1^2&lt;(x-x_{c1})^2 + (y-y_{c1})^2 &lt;R_1^2$   equation of second annulus  $r_2^2&lt;(x-x_{c2})^2 + (y-y_{c2})^2 &lt;R_2^2$  If there are three circles overlapping, we get overlapping area as solution to set of 4 in-equations by least squares approach(Though we don't end up getting total area but, area within tangents of circles ). WOL was working great on Bionic until yesterday's kernel update. How to diagnose/recover it?  Edit: if set to boot from 4.15.0-23 kernel it works. If set to boot from 4.15.0-24 it does not.  Edit2: WoL can be enabled with   sudo ethtool -s [card] wol g   but it isn't persistent. Searching for how to set it every boot.  Edit3: Per a comment by Kai-Heng Feng on this  this was an advertent change! (and therefore not a bug)  This is because the fix of LP: #1752772 has one commit [1] that disables WoL by default. Set WoL explicitly should solve your issue.  [1] https://github.com/torvalds/linux/commit/7edf6d314cd061e1d0a1b7bc0b511d64322c3f72 How to treat differentials and infinitesimals? In my Calculus class, my math teacher said that differentials such as $dx$ are not numbers, and should not be treated as such.  In my physics class, it seems like we treat differentials exactly like numbers, and my physics teacher even said that they are in essence very small numbers.   Can someone give me an explanation which satisfies both classes, or do I just have to accept that the differentials are treated differently in different courses?  P.S. I took Calculus 2 so please try to keep the answers around that level.  P.S.S. Feel free to edit the tags if you think it is appropriate.