Does Windows Server 2008 R2 really not need to be activated? I am an inexperienced Windows user, but need to use Windows server for my FileMaker server, so have a new hosted server. It is Windows 2008 R2.   In Control Panel > System and Security > System it says, "30 days to activate. Activate now." followed by a product ID.  I asked my hosting provider about this and they replied, "You can disregard the Windows Activation window. While activation is possible, Windows does not need to be activated in order to connect to and use the server desktop."  Please note that this is not a question about licensing per se. I'm just trying to clarify what "activation" means and whether it's important or not.
Can you help me with my software licensing issue? This is a  about Licensing.    Questions on licensing are off-topic on Server Fault.  If your question has been closed as a duplicate of this question, then this is because we want to help you understand why licence questions are off topic rather than just telling you "it just is". In all likelihood, this question will not address your question directly, it was not meant to.    I have a question regarding software licensing. Can the Server Fault community please help with the following:   How many licenses do I need? Is this licensing configuration valid? What CALs do I need to be properly licensed? Can I run this product in a virtual environment? Can I downgrade this product to an earlier version? Am I entitled to feature X with license Y?
I want to get user input in one page, store that in a php variable and use it in another php page. I have tried using 'sessions' but it doesn't seem to be working. Is there another safe alternative? This information is likely to be usernames and passwords. Was mathematics invented or discovered? What would it mean to say that mathematics was invented and how would this be different from saying mathematics was discovered?   Is this even a serious philosophical question or just a meaningless/tautological linguistic ambiguity? Using same modulus for RSA I know that there exist some attack when using same modulus.      But with a little modification, $m$ is the plain-text $N$ is the RSA modulus $r_1, r_2$ is the random padding $e, s$ is the public exponent $C_e, C_s$ is the cipher-text  encrypt as follow $$С_e = (m + r_1)^e   \bmod N$$ $$С_s = (m + r_2)^s   \bmod N$$  If attacker only knows $C_e, C_s, r_1, r_2, e, s, N$. Is it possible to know $m$?  It seems the  does not work? Functions which are Continuous, but not Bicontinuous What are some examples of functions which are continuous, but whose inverse is not continuous?  nb: I changed the question after a few comments, so some of the below no longer make sense. Sorry. What does The Doctor's Speech in The Rings of Akhaten refer to? I recently watched the brilliant speech from The Rings of Akhaten again. For those who haven't seen it or don't remember it:     I walked away from the last Great Time War. I marked the passing of   the Time Lords. I saw the birth of the universe and I watched as time   ran out, moment by moment, until nothing remained. No time. No space.   Just me. I walked in universes where the laws of physics were devised   by the mind of a mad man. I've watched universes freeze and creations   burn. I've seen things you wouldn't believe. I have lost things you   will never understand. And I know things. Secrets that must never be   told. Knowledge that must never be spoken. Knowledge that will make   parasite gods blaze. So come on, then. Take it! Take it all, baby!   Have it! You have it all!   Some of these I understand:     I walked away from the last Great Time War.    Clear enough     I marked the passing of the Time Lords.   Again makes sense, given he "killed" them.     I saw the birth of the universe and I watched as time ran out, moment by moment, until nothing remained. No time. No space. Just me. I walked in universes where the laws of physics were devised by the mind of a mad man. I've watched universes freeze and creations burn.   I'm very vague on this put is some of it related to The Big Bang?     I've seen things you wouldn't believe. I have lost things you will never understand. And I know things. Secrets that must never be told. Knowledge that must never be spoken. Knowledge that will make parasite gods blaze.   Possibly relating to the question which must never be answered, but at this point we've not been to Trenzalore so does he even know what knowledge is and why?  What do the unknown sections of these speech refer to? Hearing a sound backwards because of Doppler effect How does an Intelligence penalty affect skill points when character-building/leveling-up? Why is "nodev" in /etc/fstab so important? How can character devices be used for hacking? I am learning about linux security and struggling to understand why a USB stick with a character device on it is potentially dangerous.  If I have a USB stick with a bash executable that has setuid root on it, the danger is obvious: Anybody with such a USB stick can gain root privileges on my computer if I have an entry like   /dev/sdb1 /media/usbstick auto defaults 0 0   in my /etc/fstab because defaults includes suid.  But what about character devices? How can I use a character device to gain root privileges or break stuff if a USB stick with a character device on it gets mounted with dev or defaults? How to create an empty file from command line EntityFieldQuery display pager How do I display pager using EntityFieldQuery for fetch results? I can't find complete example.  I am doing simmilar to:   But I miss part to output simple pagination links (1,2,3... for every next page). Prove that $\lim_{x \to \infty}\big(\frac{x}{x-1}\big)^x$ is also $e$. Trying to make sense out of the idea that $100\%$ continuous decay is $\frac{1}{e}$, I thought about this:  You can express $1+\frac{1}{x}$ as $\frac{x+1}{x}$, such that $\big(1+\frac{1}{x}\big)^x = \big(\frac{x+1}{x}\big)^x$  And you can express $1-\frac{1}{x}$ as $\frac{x-1}{x}$, such that $\big(1-\frac{1}{x}\big)^x = \big(\frac{x-1}{x}\big)^x =\frac{1}{\big(\frac{x}{x-1}\big)^x}$  Now $\big(\frac{x}{x-1}\big)^x$ and $\big(\frac{x+1}{x}\big)^x$ look very similar, and I can imagine (and see on Mathematica) that $\lim_{x \to \infty} \big(\frac{x}{x-1}\big)^x$ also approaches $e$.  However I'm clueless about limit proofs, how do you prove that?  EDIT: Just had a last second insight.  Can you say that $$\lim_{x \to \infty} \big(\frac{x}{x-1}\big)^x = \lim_{x \to \infty} \big(\frac{x}{x-1}\big)^{x-1} \cdot \lim_{x \to \infty} \big(\frac{x}{x-1}\big)$$ $$= \lim_{x \to \infty} \big(\frac{x}{x-1}\big)^{x-1} \cdot 1$$ $$=\lim_{x \to \infty} \big(\frac{x+1}{x}\big)^x = e ?$$   (not sure about that last limit transition...I mean I'm pretty sure it's true, just not sure how to write it; I would appreciate feedback on that, thank you) How to rsync files between two remotes? I would like to transfer files between two remote hosts using on local shell, but it seems rsync doesn't support synchronisation if two remotes are specified as follow:  $ rsync -vuar host1:/var/www host2:/var/www The source and destination cannot both be remote.   What other workarounds/commands I could use to achieve similar results? Mysql Select some random rows and plus one specific row Highlight text in code listing while also keeping syntax highlighting I’m using the listings package for code listings. Now I try to highlight some part of the code using \hl from the soul package.  Here’s an example of a resulting query where the injected part of a SQL injection should be highlighted:  \begin{lstlisting}[escapechar=@,language=SQL] SELECT name, password FROM users WHERE name='@\hl{' UNION SELECT "10", 1 \#}@'; \end{lstlisting}   But inside the highlighted part the SQL syntax highlighting is not applied.  So I tried to use \lstlinline for the code part inside \hl as well but it didn’t work:  \begin{lstlisting}[escapechar=@,language=SQL] SELECT name, password FROM users WHERE name='@\hl{\lstinline[language=SQL]$' UNION SELECT "10", 1 #$}@'; \end{lstlisting}   Although this \lstinline part works outside the lstlisting block, it doesn’t work inside it. The error I get for that particular line is:     Extra }, or forgotten \endgroup.   Maybe I’m just missing just some special syntax to get this working. Or is it not possible at all to get proper syntax highlighting for the \hl-highlighted part as well? Creating a default preamble Since I am using (almost) the same set up for my tex documents, I wonder if there is a way to create a preamble with my default packages and to recall it anytime I want to create a tex document.  If yes, how I can call this "default" preamble?  Thanks in advance I'm working on an app that requires no user input, but I don't want the iPhone to enter the power saving mode.  Is it possible to disable power saving from an app? What bizarrities lurk within the decimal expansion of an irrational number? i.e. can we write  $\pi = 3.14159\dots X\dots$  where $X$ consists of (say) $10^{100}$ consecutive zeroes?  [Originally asked on reddit without response :-( ] Oracle SQL Syntax: Quoted identifier Proof that any simple connected graph has at least 2 non-cut vertices. Interpretation of p-value in Mann-Whitney rank test I am testing Mann-Whitney rank test with two vectors a and b. Vectors are almost similar so I expect a p-value near 0, but the returned p-value is near 1. What is the reason? I read  and also run the code with different parameters, but don't get anything near to what I expect.  from scipy.stats import mannwhitneyu import operator import numpy as np  a = [1000,100,10,1,10,100,1000,10000,1000,100,10,1] b = [999,100,10,1,10,100,1000,10000,1000,100,10,1]  print(mannwhitneyu(a, b))   The output of the code:  MannwhitneyuResult(statistic=73.5, pvalue=0.95291544831453867)   Edit:  Let's formalize the problem to eliminate any misunderstanding (please edit the question if something is wrong):  What I try to prove is that rank distribution of data are approximately equal,   Null hypothesis ($H_0$)= "ranked distribution of a and b are approximately equal"  Alternative hypothesis ($H_a$)= "ranked distribution of a and b are not equal"  significance level (alpha) = 0.05  p-value= 0.95  (p-value > alpha) so there is no sufficient evidence that $H_a$ is correct, but we cannot also conclude that ($H_0$) is true.   Instead if (p-value &lt; alpha) was true, then we would have enough evidence against H0 and Ha can be accepted.  So what happened here is that I could not disprove the null hypothesis. However, it doesn't mean that null hypothesis is false. It is like an investigation to accuse MR X of being guilty:   $H_0$=" MR X guilty" $H_a$=" MR X not guilty"  We guess he is not guilty, but we don't have enough proof against him: (p-value > alpha), but that doesn't mean that ($H_0$) would not be true. If we could obtain enough evidence and state (p-value &lt; alpha), then we disprove $H_0$ and we can conclude that Ha is true and he is not guilty.