I have a login problem with a game (league of legends - the login server did not respond).I found somewhere that I need to install lib32-gnutls to fix this problem, but I don't know how to do this.  I downloaded the files from here:   Inside the folder lib32-gnutls are these files:   libgnutls-openssl.so         libgnutls.so.28            libgnutlsxx.so.28.1.0 libgnutls-openssl.so.27      libgnutls.so.28.41.0  pkgconfig libgnutls-openssl.so.27.0.2  libgnutlsxx.so libgnutls.so                 libgnutlsxx.so.28   I tried to install them through terminal with:  sudo apt-get install 'the name of the file'  but I get:  Reading package lists... Done Building dependency tree        Reading state information... Done W: Duplicate sources.list entry http://dl.google.com/linux/chrome/deb/ stable/main i386 Packages (/var/lib/apt/lists/dl.google.com_linux_chrome_deb_dists_stable_main_binary-i386_Packages) W: You may want to run apt-get update to correct these problems E: Unable to locate package libgnutls.so.28 E: Couldn't find any package by regex 'libgnutls.so.28'       I have ran the command apt-get update.  So what should I do next?
Simple enough question: is there some shell command (or GUI method) I can use that, given the path to a file on my system, tells me what package put it there? Assuming the file did in fact come from a package, that is.  Bonus question: what if it's a file that isn't installed on my system? Is there, say, a website that will let me look up a file and see what packages, if any, provide it?
This is a nice problem on series convergence that I recently stumbled upon. Given a non-negative sequence of real numbers $(a_n)$ such that $$\sum_{n=1}^\infty a_n &lt; \infty,$$ show that there exists a non-decreasing sequence of non-negative numbers $b_n$ such that $$b_n \to \infty \quad\text{ and } \quad \sum_{n=1}^\infty a_n b_n &lt; \infty.$$ In other words, for every convergent series with non-negative terms, there is another convergent series with "substantially larger" terms.  I have a solution (see below), but maybe someone else has a different, simpler, and/or more elegant solution. Given a logarithm is true, if and only if, $y = \log_b{x}$ and $b^y = x$ (and $x$ and $b$ are positive, and $b$ is not equal to $1$), are true, why aren't logarithms defined for negative numbers?  Why can't $b$ be negative? Take $(-2)^3 = -8$ for example. Turning that into a logarithm, we get $3 = \log_{(-2)}{(-8)}$ which is an invalid equation as $b$ and $x$ are not positive! Why is this? I created the following matrix with , and I would like to add at the bottom (respectively right) something like an underbrace (resp. "rightbrace") under each of the two blocks, together with a number specifying the number of columns (resp. rows) of the block. This amounts to two braces on the bottom and two on the right, and each brace should have a number below (resp. at the right) of it.  I did not find anything about that on the easybmat manual. I think I see how to do the braces with the  package, but then I am not able to create the block structure of the matrix in the first place.  \documentclass{article} \usepackage{easybmat} \begin{document} \[  M(z)= \left[ \begin{BMAT}[5pt]{c|c}{c} \begin{BMAT}[5pt]{c:c:c}{ccccccc} &amp; &amp; \\ &amp; &amp; \\ &amp; &amp; \\ v_1 &amp; \dots &amp; v_m \\ &amp; &amp; \\ &amp; &amp; \\ &amp; &amp; \end{BMAT} &amp; \begin{BMAT}{c}{c|c} \begin{BMAT}[5pt]{c:c:c}{ccc} &amp; &amp; \\ w_1(a) &amp; \dots &amp; w_n(a) \\ &amp; &amp; \end{BMAT} \\ \begin{BMAT}[10pt]{c}{c} B(z) \end{BMAT} \end{BMAT} \end{BMAT}  \right] \] \end{document}     This is more or less what i wish: How to combine various armatures? I just need to check the reasoning in my proof is correct, I think it is valid although I'm not totally convinced because I can't follow the logic; does proving that $x$ is an integer prove that $ac|bd$?  Theorem: Let $a$, $b$, $c$, $d$ be integers. If $a|b$ and $c|d$, then $ac|bd$.  Proof: $aj=b$ and $ck=d$ for integers $j$, $k$. Then, $ac|bd$ implies $acx=ajck$ and thus $x=jk$ for some $x$. Since the product $jk$ is an integer, $x$ is an integer and thus $acx=ajck$ and thus $ac|bd$. Creating or referencing variables dynamically in Sass Is there a VB.NET equivalent for C#'s '??' operator? Is there a VB.NET equivalent for C#'s ?? operator? Which graphics formats can be included in documents processed by latex or pdflatex? There several types of graphics files. In no particular order .jpeg .eps .pdf .png .tif .jif (and no doubt others). Some work with latex, dvips and some work with pdflatex. How am I supposed to know which?  Just to confuse matters, metapost produces .eps but I can use these with pdflatex as long as I put in a four line incantation.  Can anyone explain this? Where do I find the client id and client secret of an existing connected app? I would like a way to mark a question in the Unanswered "my tags" page as something I'm not interested in or able to answer The /unanswered/tagged?tab=mytags page gives a list of questions from my favorite tags that are currently considered "unanswered" - they have no up voted or accepted answers. I think it's good to put them in front of me easily, but even though they have one or more tags that I'm interested in, I may not have the knowledge, ability, or interest to write an answer to them. However, they will remain on this page until someone writes an answer.  I would like to be able to dismiss questions from views, like this one, that show me interesting questions. I may choose to share them on my social media to get them views and answers, but I don't want to continually see them. Instead, I want to be able to use views like unanswered/tagged?tab=mytags as a queue of things that could use my attention. Is it possible to change your spawn point? How do I space quads evenly? Is there a way in blender or an addon that allows me to select a bunch of faces (or verts) and evenly distributes (or relaxes) them into quads clean quads.  Without screwing up the vert ID/order.  Edit: I would like to have the shapes of my quads to turn into perfect squares while maintaining the volume of the object and the vertex order. Create Generic method constraining T to an Enum I'm building a function to extend the Enum.Parse concept that  Allows a default value to be parsed in case that an Enum value is not found Is case insensitive  So I wrote the following: public static T GetEnumFromString&lt;T&gt;(string value, T defaultValue) where T : Enum {     if (string.IsNullOrEmpty(value)) return defaultValue;     foreach (T item in Enum.GetValues(typeof(T)))     {         if (item.ToString().ToLower().Equals(value.Trim().ToLower())) return item;     }     return defaultValue; }  I am getting a Error Constraint cannot be special class System.Enum. Fair enough, but is there a workaround to allow a Generic Enum, or am I going to have to mimic the Parse function and pass a type as an attribute, which forces the ugly boxing requirement to your code. EDIT All suggestions below have been greatly appreciated, thanks. Have settled on (I've left the loop to maintain case insensitivity - I am using this when parsing XML) public static class EnumUtils {     public static T ParseEnum&lt;T&gt;(string value, T defaultValue) where T : struct, IConvertible     {         if (!typeof(T).IsEnum) throw new ArgumentException(&quot;T must be an enumerated type&quot;);         if (string.IsNullOrEmpty(value)) return defaultValue;          foreach (T item in Enum.GetValues(typeof(T)))         {             if (item.ToString().ToLower().Equals(value.Trim().ToLower())) return item;         }         return defaultValue;     } }  EDIT: (16th Feb 2015) Christopher Currens has posted  below, which is well worth a look, and an upvote. I will remove this edit if the solution bubbles further up the page. EDIT 2: (13th Apr 2021) As this has now been addressed, and supported, since C# 7.3, I have changed the accepted answer, though full perusal of the top answers is worth it for academic, and historical, interest :) Limit of function of hyperbolic stackoverflow.com without OpenID is it possible to login/create user in stackoverflow.com without creating/login using OpenID? i hate using OpenID, it's really confusing if you create different user/account on different websites :(     Note: the following text was submitted as an edit suggestion. I approved it, giving the user the benefit of the doubt and assuming that it was the OP's other account. -   even when i want to post this question under my new openid, i still logged as the old user, so i can't view my own question when i logged under my userid Disable two column mode for separate part I am writing a document using the report class in two column mode, but I need a \section to spread across both columns, but how can I set that?  Something like  \documentclass[10pt,danish,a4paper,twoside,twocolumn]{report} \input{preamble.tex} \begin{document}  % This section should spread over both columns \section{Name}  \lipsum[1-3] \end{document} Anime about a boy and a girl who ride ostrich-like creatures through a valley I can not remember much but I have had this film in my head for years I searched everything I can remember on every website I can think of.  I don't remember the exact story but I'll list everything about it can   Apocalyptic future possibly Two main characters: a boy and a girl riding ostrich-like creatures through a valley An old blind lady that senses things Crashed spaceship looking like a submarine Giant creatures looks like yaks with blue eyes, whose eyes turn red when something is about to happen The old lady says "Some say they went to the stars" while looking at the spaceship The two main characters do something and their eyes turn blue in the distance and the village cheers   This film is at least ten years old and I would appreciate it so much if you knew anything about it, or could help me find the title. What’s the rule for using “who” and “whom” correctly? There has got to be the establishment of a universal auxiliary language.   Does the verb got add more to the context or is it there just for emphasis? Is it even grammatical?  Using Google-Ngrams I found a few similar versions as follow: . For example;   For many from the North, however, it has seemed difficult and there has seemed to be a problem. There has come to be a convolution between this become enmeshed concept of marriage as it exists in the sacred and how it exists in the secular. Most of the time since I have been here, there has appeared to be considerable feeling in the minds of a few. There has had to be some negotiation, obviously, but I think we provided what our soldiers need and what our country needs.   In general, I wanna know if 'have/has'+past-participle+'to be' is grammatical. product of two uniformly continuous functions is uniformly continuous Suppose that $f$ and $g$ are uniformly continuous functions defined on $(a,b)$. Prove that $fg$ is also uniformly continuous on $(a,b)$.   My attempt: Since $f$ is uniformly continuous on $(a,b)$, for all $\epsilon&gt;0$, we have $\delta_f(\epsilon)&gt;0$ such that for all $x,y \in (a,b)$, $|x-y|&lt;\delta_f$, $|f(x)-f(y)|&lt;\epsilon$  Since $g$ is uniformly continuous on $(a,b)$, for all $\epsilon&gt;0$, we have $\delta_g(\epsilon)&gt;0$ such that for all $x,y \in (a,b)$, $|x-y|&lt;\delta_g$, $|g(x)-g(y)|&lt;\epsilon$  Notice that $$|f(x)g(x)-f(y)g(y)|=|f(x)g(x)-f(x)g(y)+f(x)g(y)-f(y)g(y)| \leq |f(x)||g(x)-g(y)| + |g(y)||f(x)-f(y)|$$  Here I don't know how to bound $|f(x)|$ and $|g(y)|$. I have proven that uniformly continuous functions preserve boundedness of an interval , i.e. $f$ is bounded on $(a,b)$. Can anyone help me?