The question is: can I have different "Preferred Networks" when switching from one to another Network "Location"?  This issue has been discussed before at . However, I do not like a solution that ought to use some external App.  I would appreciate any comment! Thanks!
I'm having trouble understanding what I'm doing wrong here: I'm trying to set up two network Locations, one for my home network via my cable modem and a second for Wi-Fi tethering via my mobile phone. What I'd like to be able to do is change the Location (under the Apple menu &gt; Location) and have my Mac automatically connect to the proper Wi-Fi network: either my home network SSID or my WiFi tethering SSID. I defined two locations, switched between them, and set the preferred network list for each location. But when I change the preferred network list for one Location, it changes the list for the other Location as well! Am I doing something wrong or is it really not possible to maintain a separate list of Preferred Networks for each network Location? It seems doubtful it's not possible since just about every other netrok setting depends on the location... I am using OS X 10.7.2.
What theorems can I use to prove this? Science fiction story where a colonist is sent by a company to colonize a planet and there a robot tries to sell him a depilating liquid by pulling a gun on him. The company who sponsored his trip to the new planet is extorting him by charging him exorbitant rates for anything they declare is not considered by them as bare necessities. The robot and man collaborate to get from the company the fair deal he deserves. A saying for something that's good but also has a downside I'm trying to transition from a list of pros to a list of cons, and would like to have some sort of transition quote. Something in the form of,  "But, alas, (((something something quote quote)))"  Everything that has a beginning has an end, something along the lines of that. Why do physicists believe that particles are pointlike? String theory gives physicists reason to believe that particles are 1-dimensional strings because the theory has a purpose - unifying gravity with the gauge theories.   So why is it that it's popular belief that particles are 0-dimensional points? Was there ever a proposed theory of them being like this? And why?   What reason do physicists have to believe that particles are 0-dimensional points as opposed to 1-dimensional strings? Can I leave the Schengen Area (and come back) while my non-eea spouse resident card application is being processed? My wife and I recently moved to Germany. She's a Swedish citizen, and I'm American. It'll be December before I can actually apply for my residence card, because my appointment to register our address is so far out - the local police station was all booked out and we didn't get an apartment right away.  I imagine that I won't be getting my residence card until well after Christmas, by which time my 90/180 days will be passed. What if I want to leave to, say, London for the holidays? Will I be allowed back in? I hit day 90 around the 21st of December. I could maybe leave on day 89 and come back on day 90 (with my wife and our marriage cert), or use this Polish solution: , since I can't be expelled from Germany for overstaying my visa while my application is processing.  Both of those seem a bit risky though. Am I reading too far into it, or is this a legitimate concern? Will I get some sort of documentation saying I have a residence card application processing? I am currently studying  answer on the Moore-Penrose pseudoinverse and the Euclidean norm by the user &quot;Etienne dM&quot;. The first point of their answer proceeds as follows:  Let $x$ be $A^+y$.  Let me begin by the second point. For all $z$, we have: \begin{align} \lVert Az-b \rVert_2^2 &amp;= \lVert Ax-b \rVert_2^2 + \lVert A(z-x) \rVert_2^2 + 2 (z-x)^TA^T(Ax-b)\\ &amp; \geq  \lVert Ax-b \rVert_2^2 + 2 (z-x)^TA^T(Ax-b) \end{align} Moreover, because $(AA^+)^T = AA^+$, $$ A^T(Ax-b) = ((AA^+)A)^Tb - A^Tb = 0$$ Thus, we prove that for all $z$, $\rVert Az-b \lVert_2^2 \geq\rVert Ax-b \lVert_2^2$, that is to say $A^+b$ is as close as possible to $y$ in term of the Euclidian norm $\lVert Ax-b\rVert_2$.   I realise that $x = A^+ y$, but I don't understand how any of this implies that &quot;$A^+ b$ is as close as possible to $y$ in terms of the Euclidean norm $\lVert Ax-b\rVert_2$&quot;. I would greatly appreciate it if people would please take the time to explain this to me. Why there is "the" before some names but not others Is there a rule beyond the common "no the with proper nouns and names" for the following problem?     I saw the Empire State Building.      We went to the White House.      We saw the Golden Gate Bridge.   but     I went to Death Valley National Park.      I crossed Brooklyn Bridge. Our iPad is locked and we're not sure of the Apple ID / iCloud password Ubuntu touch - remote access to device in our company we developed an android app installed on nexus 7 tablets and on tablet we release to several customers. This app stays in foreground active 24/7 but we have problems in monitoring  the devices due to the restrictive access policies of unrooted Android devices.   We can't for example reboot the device remotely.  We are evaluating the possibility of installing Ubuntu touch to replace android on this tablets. Does Ubuntu touch offer more freedom for the remote access of the device? May I do remotely everything I could do normally with the tablet?   Moreover, are the apps developed with ubuntu sdk stable enough to run 24/7?  Thanks Imported CSV data is not displayed in QGIS I watched a simple video tutorial on how to accomplish it, but nothing shows up on my project when I add the layer. Even if I try zoom to layer, the screen just shows blue. I'm not sure if it has something to do with my Excel, computer, or program. I really need help as I am new to QGIS. (I just posted this, but it won't let me comment to people under that question any more) I have a layer of google hybrid, but when I do add the new layer it is at the top and checked transparency and everything. Its just not accepting the data I entered into the excel spreadsheet is my guess to what the issue is.  I have the spreadsheet with the name, longitude, latitude. Save as CSV In QGIS go to Layer &gt; Add layer &gt; Add Delimited Text Layer Upload the CSV Excel file Add  Nothing shows even tho there is a line in the layers (bottom left) showing that &quot;something&quot; is there but if I choose &quot;zoom to layer&quot; it changes to a blue screen I have a Base layer Google Maps hybrid, and an area of interest on Georgia The dock doesn't work correctly after I enter my password, either. Is R-squared value appropriate for comparing models? I'm trying to identify the best model to predict the prices of automobiles, using the prices and features available on automobile classified advertisement sites.  For this I used a couple of models from the scikit-learn library and neural network models from pybrain and neurolab. The approach I used so far is to run a fixed amount of data through some models(machine learning algorithms) and compare there $R^2$ values which was calculated with the scikit-learn metrics module.   Is $R^2$ a good method to compare the performance of different models? Although I got quite acceptable results for models such as Elastic net and Random forests I got very poor $R^2$ values for Neural network models,so is $R^2$ an appropriate method for evaluating neural networks (or non-linear methods)? I have a web page that includes a bunch of images. Sometimes the image isn't available, so a broken image is displayed in the client's browser.  How do I use jQuery to get the set of images, filter it to broken images then replace the src?    --I thought it would be easier to do this with jQuery, but it turned out much easier to just use a pure JavaScript solution, that is, the one provided by Prestaul. Convergence of the series $ \sum_{n=1}^{+ \infty } \frac{1}{n \cdot \ln(n) \cdot (\ln(\ln(n)))^{a}} $ I have a problem with a convergence of the series $ \sum_{n=1}^{+ \infty } \frac{1}{n \cdot \ln(n) \cdot (\ln(\ln(n)))^{a}}$ depending on the parameter $a$. I know that  $\frac{1}{n} \rightarrow 0$, $\frac{1}{\ln(n)} \rightarrow 0$, but I don't know how to deal with $\frac{1}{\ln(\ln(n)))^{a}}$ and how to get to the final answer. So far I solved tasks with  $\frac{1}{n ^{a}}$ and I know that $a&gt;1  \Leftrightarrow \sum_{n=1}^{+ \infty }\frac{1}{n ^{a}}$ is convergent, but in this task I cannot use it. Can you help me? Could the change from an edit be displayed in a side-by-side display Git command to show which specific files are ignored by .gitignore I am getting my feet wet with Git and have the following issue:  My project source tree:  / | +--src/ +----refs/ +----... | +--vendor/ +----...   I have code (currently MEF) in my vendor branch that I will compile there and then move the references into /src/refs which is where the project picks them up from.  My issue is that I have my .gitignore set to ignore *.dll and *.pdb.  I can do a git add -f bar.dll to force the addition of the ignored file which is ok, the problem is I can not figure out to list what files exist that are ignored.  I want to list the ignored files to make sure that I don't forget to add them.  I have read the man page on git ls-files and can not make it work. It seems to me that git ls-files --exclude-standard -i should do what I want.  What am I missing? How can I rotate an object based on another's offset to it? I have a 3D model of a turret that con rotate around the Y-axis. This turret has a cannon that is significantly off the center of the object. I want the cannon, not the turret, to aim at a specified target. I can only rotate the turret, however, and thus I don't know what equation I need to apply in order to accomplish by objective.  The following image illustrates my problem:  If I have the turret "LookAt()" the target, a laser originating from the cannon will completely miss said target.   If this were a completely top-down scenario, and the cannon were exactly parallel to the turret, then my logic tells me that the fake target should be located at a position that's equal to the actual target plus an offset that's equal to that between the turret and the cannon. However, in my actual scenario, my camera is angled 60º, and the cannon has a slight rotation.  The following image illustrates the scenario:   I'm not sure exactly why, but if I apply that same offset, it only seems to work while aiming at certain distances from the turret.  Is my logic flawed? Am I missing something fundamental here?  Final Edit: the solution provided by @JohnHamilton latest update solves this problem with perfect precision. I have now removed the code and images that I used to illustrate my incorrect implementations. martingale and stochastic Integral Web applications that want to force a resource to be downloaded rather than directly rendered in a Web browser issue a Content-Disposition header in the HTTP response of the form:  Content-Disposition: attachment; filename=FILENAME  The filename parameter can be used to suggest a name for the file into which the resource is downloaded by the browser.  (Content-Disposition), however, states in  (The Filename Parameter) that the file name can only use US-ASCII characters:     Current [RFC 2045] grammar restricts   parameter values (and hence   Content-Disposition filenames) to   US-ASCII.  We recognize the great   desirability of allowing arbitrary   character sets in filenames, but it is   beyond the scope of this document to   define the necessary mechanisms.   There is empirical evidence, nevertheless, that most popular Web browsers today seem to permit non-US-ASCII characters yet (for the lack of a standard) disagree on the encoding scheme and character set specification of the file name. Question is then, what are the various schemes and encodings employed by the popular browsers if the file name “naïvefile” (without quotes and where the third letter is U+00EF) needed to be encoded into the Content-Disposition header?  For the purpose of this question, popular browsers being:   Firefox  Internet Explorer  Safari Google Chrome  Opera Creating intuition about Laplace & Fourier transforms