Doing some editing and came across a sentence in which a colon is used to introduce a quote.  Is the colon justified in this case? SENTENCE ENDS:     ...wearing a T-shirt that says: "When the going gets tough, the tough get going."    The following question () is actually focused on a slightly different issue, since it is about using a colon to introduce a quotation after a complete sentence.  The answers to it seem to be geared toward that example; one of them cites a Purdue OWL post that says it is appropriate to use a colon to introduce a quotation after a complete sentence or independent clause. But that is not the case here, since "a T-shirt that says" is not a complete clause or statement.   One answer (by Roaring Fish) quotes a "" by Larry Trask that seems to say that it is "bad style," but not outright "wrong," to use a colon in the sentence "President Nixon declared: 'I am not a crook.' " This seems relevant, but it's a bit confusing. Why doesn't Trask just label this "wrong"? Is it a matter of opinion? I'd appreciate other references that describe the most common and influential viewpoints about how to punctuate phrases like this.
What is the correct way to punctuate the end of a sentence before a quote that directly supports the statement? I assume either a colon or a semicolon, but I have no idea which is correct.  For example:     Waldo is a better hide-and-seek player than Clem; "Waldo was   the winner of the past ten annual hiding awards" (Where's Waldo 13).      Waldo is a better hide-and-seek player than Clem:  "Waldo was   the winner of the past ten annual hiding awards" (Where's Waldo 13).   (Excuse the silly example, but I didn't have a better one.)
Top Down RPG Movement w/ Correction? I would hope that we have all played Zelda: A Link to the Past, please correct me if I'm wrong, but I want to emulate that kind of 2D, top-down character movement with a touch of correction. It has been done in other games, but I feel this reference would be the easiest to relate to.  More specifically the kind of movement and correction I'm talking about is:   Floating movement not restricted to tile based movement like Pokemon and other games where one tap of the movement pad moves you one square in that cardinal direction. This floating movement should be able to achieve diagonal motion. If you're walking West and you come to a wall that is diagonal in a North East/South West fashion, you are corrected into a South West movement even if you continue holding left (West) on the controller. This should work for both diagonals correcting in both directions. If you're a few pixels off from walking squarely into a door or hallway, you are corrected into walking through the hall or down the hallway, i.e. bumping into the corner causes you to be pushed into the hall/door.   I've hunted for efficient ways to achieve this and have had no luck. To be clear I'm talking about the human character's movement, not an NPC's movement. Are their resources available on this kind of movement? Equations or algorithms explained on a wiki or something?  I'm using the XNA Framework, is there anything in it to help with this? 'sudo' not working after changing the permissions of '/usr' directory Recently I had to change the folder permissions of /usr folder. Now the whole sudo is not working. If I try to update my system using this command:  sudo apt-get update   I get the following message:  sudo: /usr/lib/sudo/sudoers.so must be only be writable by owner sudo: fatal error, unable to load plugins   So I tried to change the folder permissions by opening Nautilus as root by using this command  gksudo nautilus   But nothing happened. Nautilus didn't open. This is an emergency as the whole of sudo is not working. when I tried searching the solution from Google many suggested re-installation. I don't prefer re-installation. so is there any other solution? How to find stopping distance of a car? Proving ${n \choose p} \equiv \Bigl[\frac{n}{p}\Bigr] \ (\text{mod} \ p)$ If $a_n$ is a strictly increasing unbounded sequence, does $\sum_n \frac{a_{n+1} - a_n}{a_n}$ diverge? So I've been thinking through some test cases. If $a_n = n$ then $\sum_n \frac{a_{n+1} - a_n}{a_n}$ is the harmonic series which diverges. And if $a_n = \sum_{k=1}^n 1/k$ then $\sum_n \frac{a_{n+1} - a_n}{a_n}$ diverges like $\sum_n 1/(n \log n)$. So that got me thinking, if $a_n$ is a strictly increasing unbounded sequence, does $\sum_n \frac{a_{n+1} - a_n}{a_n}$ necessarily diverge? The editor should be able to convert multi-line blocks to lists Integrating $\int^2_{-2}\frac{x^2}{1+5^x}$ $$\int^2_{-2}\frac{x^2}{1+5^x}$$  How do I start to integrate this?  I know the basics and tried substituting $5^x$ by $u$ where by changing the base of logarithm I get $\frac{\ln(u)}{\ln 5}=x$, but I got stuck.  Any hints would suffice preferably in the original question and not after my substitution.  (And also using the basic definite integrals property.)  Now I know only basic integration, that is restricted to high school, so would prefer answer in terms of that level. net use command works in command prompt, but not in bat file What are the uses of Unicorns? What different uses does the unicorn have?  Other than the delicious taste of them coming off the grill.   At Wit's End #221 What does a "Legacy USB Mouse" option in a BIOS mean?  Yes legacy usually means older revision, or obsolete. So legacy usb mouse means support for "old style usb mouses".     That's not really answering the question. As Mr. Tamm, my high school electricity teacher, liked to say, "Yes, and oranges taste orangey."   What does legacy USB mouse support mean?   What is a legacy USB mouse?  There's an "old style" USB mouse?  What changed between what version of usb and what version of usb that made mice incompatible? Why was the change made?  When was the change made? Who made the change? What was the virtue of the "new USB mouses" over the "old USB mouses"?   Put it another way:     What is the BIOS doing when "Legacy USB Mouse" option is enabled?   What is the BIOS doing when "Legacy USB Mouse" option is disabled?   See also Orthogonal Projection of $ z $ onto the Affine set $ \left\{ x \mid A x = b \right\} $ Biblatex - capital names in references, regular in cites I am trying to achieve a biblatex style that would do the following:  in the case of \parencite{} I would get ...like that (Smith 2010).   in the case of \textcite{} I would get Smith (2010) says that...  but in References I would get SMITH, J. Bookname.  How can I achieve this?  I use \usepackage[style=authoryear, firstinits=true]{biblatex}  I tried \renewcommand*{\mkbibnamelast}[1]{\MakeUppercase{#1}} but that makes the name uppercase even in the text, which is undesirable especially with \textcite{} Prove $\mathbb{Z}_2 \times \mathbb{Z}_2$ is not isomorphic to $\mathbb{Z}_4$ Your Mileage May Vary In the United States we have a saying, "your mileage may vary", which means "your experience may be different".  In English-speaking countries that don't use Imperial miles, is there an equivalent expression? how many terms will there be once you collect terms with equal monomials? What is the sum of all the coefficients? If "clearly evident" is redundant, what word or phrase suggests being indisputable but not readily apparent? A  asks whether the modifier "clearly" changes the meaning of "evident". I would have said, prior to examining a few dictionaries, that evident did not necessarily mean readily apparent, but to my surprise it does.  This brings me to ask what word or expression would mean something can be taken as a true fact, but not through an easily constructed (not obvious or readily apparent) rationale?   For example, if Sherlock Holmes says something is true while everyone else is still sitting on their hands, then it is evident to Holmes, but not to the rest of the world. So, from everyone else's point of view, it is not readily apparent, and (by definition) apparently it is not evident, clear, or clearly evident at all, based on the dictionary definitions. But (let's stipulate) it is true and deducible from the observable evidence. What would we call this?  Update  An update is highlighted above. I can see from some of the answers and comments that I may have gone off my mark with the phrase "not through an easy-to-follow rationale”, and I have modified the question to correct this. I understand that there can be rationales, arguments, or proofs that, once explained, may or may not be easy to follow. What I intend is that the rationale to support the indisputable conclusion is not (initially) easy to recognize or construct (not readily apparent) in the first place. I apologize for the confusion. (The original can be seen in the change history.)  Update 2  Shortly after offering a bounty to this request, I recalled a single word that I now believe is a very good match to the parameters specified in this inquiry as it is stated above. That word has not yet been suggested (or approached) by any answer or comment (active or deleted) at the time of this edit. This request is changed to a single word request. (However, if you feel a single word fits well but not without some additional supporting words, please offer your thoughts in an answer.) While my curiosity for the term has already been met, the request and bounty remain as an open challenge. I will post my own answer once the bounty has expired and been awarded. TeX support works fine in question and answer bodies, and comments can be rendered manually by tapping and selecting Render MathJax. See related question .  However, the titles are not rendered which makes the browsing experience less than perfect. See screenshot below.   Are there any plans to implement MathJax support in titles?  (I'm running Stack Exhange iOS App Version 1.0.0 on an iPhone 4S with iOS 7.1.1)    EDIT: I was just informed about  asking for the same functionality for the Android app. I guess I shouldn't hope too much then... Are there any more Asgardians? Connected set in $\mathbb{S}^1$ Let $A$ be a connected set in $\mathbb{S}^1$. Show that $A^c$ is also connected.  My idea: suppose $A^c$ is not connected. Then, there exist $U,V \subset \mathbb{S}^1$ open and disjoint such that $U \cup V =A^c  $. Therefore $\mathbb{S}^1 = A \cup U \cup V$. If I had that $A\cup U$ was open I could arrive at  contradiction, since $\mathbb{S}^1$ is connected, but I can't say that... I want to setup a new virtual machine with some specified packages (name and version), that are provided.  For example apache2 in version 2.2.20-1ubuntu1 with all dependencies. Even if there is a new version of this package on the servers this one should be installed.  The solution has to work/scale with multiple (n) "setups". Another virtual machine might need an older version of apache2.  I currently know of some possibilities that install the exact packages, but do not scale that good:   Copy all required *.deb to every virtual machine manually and enter: dpkg -i ... -> Could work, but it is very error prone. (Manual scripts etc.) Create and use a new Ubuntu repository for each setup. -> Does not work because I would need n repositories. Setup the machine once and copy the VM / create a snapshot. -> Does not work because I would need to store n VMs.   My problem could be labeled as patch management, but I do not want to update my packages to the current version. My goal is to install old packages.