Clicking a HNQ "ad" in the sidebar opens the link in the ad instead of changing the current page , but I didn't have evidence of it, so it was dismissed. I'm not crazy though, and here's proof!:    When clicking on a HNQ in the side-bar, the link appears to open within the ad itself (an iframe? I'm not a web-dev so I'm not sure the terminology).  This happens consistently. I can't reproduce it often because the ads don't appear very often. Every time I try to reproduce it though, I'm able.  This was done on Edge 44.18362.329.0, but as the link above shows, a year ago I did it in Chrome.
Clicking community promotion ad renders an instance of SO within the frame of that ad Today I came across an ad on this question on SO:  (I don't expect it to stay very long).   There was a community promotion ad on the right hand side of the site, I think for one of our English sites. It had a sentence that I only partially remember:     Idiom ... poor or even poorer   I found it interesting, so I clicked that ad. Which caused a new instance of SO to open within the ad space. Unfortunately I failed to take a screenshot. I've been refreshing the page like crazy, but can't get the ad to appear again.  Edit: I managed to get a new community add, for the photography site, and captured a screenshot:   Edit2: This bug still persists, I saw it today with an OOP add from CodeReview, and an area 51 add.
How can I sum two values and store the result in other variable? How can I install Sun/Oracle's proprietary Java JDK 6/7/8 or JRE? I just did a clean installation of Ubuntu 18.04.1 on a tablet which was previously running Ubuntu 17.10. Back then just after the installation the screen was rotated, but I was able to get it to work (I think it was running on Wayland).  Now with 18.04.1 the situation is similar: when Ubuntu first boots the login screen is upside-down, but that's not a problem. This time, after login, the screen is correctly oriented but the mouse cursor is upside down and mouse movements are inverted with respect to both axes. The problem is that when I try to click on something the click is registered on the position on the other side of the screen (symmetrically with respect to the center).   It almost seems like the screen (desktop, application, etc.) is correctly displayed, with also the mouse positioned correctly and moving as it should, but then the mouse cursor which is shown to the user is inverted, like if the screen had been inverted just before drawing the cursor.  I already tried the answers I could find, but none worked for me. Anyone have an idea of what's going on?  Thanks Is temperature a Lorentz invariant in relativity? Why do liquids boil when their vapor pressure equals the ambient pressure? Given that the boiling point of a liquid is the temperature at which the vapor pressure is equal to the ambient (surrounding) pressure, what significance does a liquid's vapor pressure have in the formation of bubbles that happens at and above the boiling point?    The definition of boiling point seems to imply that the pressure inside of the bubbles must be at least as great as the liquid's vapor pressure in order to balance the outside pressure, but is there any particular reason why the pressure inside of the bubbles is related to the vapor pressure?    The vapor pressure seems to be a measurement describing the tendency of the molecules to escape from the surface of the liquid, but I don't see how that relates to bubble formation within the liquid.  This question has bothered me for a while, so any help would be much appreciated. Statement: $[a, b] \cap \mathbb{Q}$ in $\mathbb{Q}$ is not compact. Thus the interior of all compact subsets of $\mathbb{Q}$ is $\emptyset$.   I am trying to understand the first sentence. I read that a closed subspace of a compact space is compact, so for example, consider the unit interval $[0, 1]$ which is a compact space. Take a closed subspace $[0, 1] \cap \mathbb{Q}$ of $[0, 1]$. This set is closed since it just consists of all the rational numbers in between $0$ and $1$, including $0$ and $1$. So it is a closed subspace of a compact space. But why isn't this compact? Show all inbox items (notifications) in app The SE app currently only shows some inbox items:   Answers Comments Chats   When I see those I assume I'm all caught up, but it turns out there are more on the web which aren't displayed in the app:   Bounty expiration Elections Edits on your own posts Maybe others?   I was about to tag this  but realized it's probably intentional.  I imagine the reason for not showing them is because they're not something you can act on from within the app. Bounties can't be offered or awarded1 and elections can't be voted on.  But then again chats can't be replied to either. Badge descriptions can't be viewed (on the Achievements side). Selecting those launches the browser. Why then shouldn't bounties or elections launch the browser too? Hiding them just means I'll miss it if I haven't visited in browser recently.  1 Though accepting answers does award the bounty How do I set a featured image (thumbnail) by image URL when using wp_insert_post()? While looking through the , I noticed that there's no parameter in the array it requires which will allow me to set the 'Featured Image' for a post, displayed as the  in my theme.   I have looked into functions like , as suggested by Mr. Bennett, but this seems to be a relatively new addition to WordPress itself and the WordPress codex. As such, there aren't any sources that I can find which explain how the $thumbnail_id parameter should be acquired and supplied. If this really is the function to use, in what way could I provide it with a valid $thumbnail_id parameter when all I have is an image URL?  Thanks in advance! A closed form of $\int_0^1\frac{\ln\ln\left({1}/{x}\right)}{x^2-x+1}\mathrm dx$ This integral has been bugging me since yesterday:     $$\int_0^1\frac{\ln\ln\left({1}/{x}\right)}{x^2-x+1}\mathrm dx$$   I've tried substitution $y={1}/{x}$ and $e^y={1}/{x}$, but those didn't help much. Wolfram Alpha gives me result: $-0.67172$. Could anyone here please help me to obtain the closed form of the integral preferably (if possible) with elementary ways (high school methods)? Any help would be greatly appreciated. Thank you. Using equations to draw out complex objects How do people come up with equations of curves to draw out complex objects?  Some popular examples would include:  &amp;  .  This  explains the rationale for the batman curve nicely.  But other than trial and error, I can't see a reasonable way of drawing the much more complicated PSY curve. I always thought Java uses pass-by-reference. However, I've seen a couple of blog posts (for example, ) that claim that it isn't (the blog post says that Java uses pass-by-value). I don't think I understand the distinction they're making. What is the explanation? Old phone cannot connect to computer, the "computer connection" icon appears on phone I would like to get some pictures and audio out of an AT&amp;T SGH-a687 phone onto my Mac computer. I first tried connecting it to a New PC Studio on a PC, but there was a problem after transfer 2 photos, so I tried again. But the PC could no longer detect the phone, even though the "connected to computer" icon appears on the phone. I tried a different cable, different USB ports. No use.  So I downloaded the Samsung Kies on my Mac. Same thing, it tries to search for the phone once I connect the phone, but the computer doesn't detect anything. The phone still shows the "connected to computer" icon.  There is also Bluetooth (no internet on the phone) on the phone, but it failed to send the picture each time I tried.  What can I do at this point? Please also suggest data extraction software for either Mac or PC, if that's the easier route. Is there an equivalent to Google Sketchup? It is impossible for $(x-1)^2+x^2+(x+1)^2$ to be a perfect square Prove that it is impossible for three consecutive squares to sum to another perfect square. I have tried for the three numbers $x-1$, $x$, and $x+1$. What could we call a person with deep knowledge in various fields? With the following AppleScript code within a "Run AppleScript" action in a Service:  tell application "System Events"     set theSBounds to {{572, 64}, {332, 515}}     set position of window "Google Hangouts - myemailaddress@gmail.com" of application process "Google Chrome" to item 1 of theSBounds     set size of window "Google Hangouts - myemailaddress@gmail.com" of application process "Google Chrome" to item 2 of theSBounds end tell   the Service will only work if the application from which that Service has been called has been added to the list of applications under "Allow the apps below to control your computer." This list is found at System Preferences → Security &amp; Privacy → Accessibility.  Is it possible to modify the AppleScript code somehow so that adding every application on one's computer to the list is not necessary? Or, so that, one only needs to add one item to the list, as opposed to every application on one's computer?  I thought that something like this might work:  do shell script "osascript -e 'tell application \"System Events\"' -e 'set theSBounds to {{572, 64}, {332, 515}}' -e 'set position of window \"Google Hangouts - myemailaddress@gmail.com\" of application process \"Google Chrome\" to item 1 of theSBounds' -e 'set size of window \"Google Hangouts - myemailaddress@gmail.com\" of application process \"Google Chrome\" to item 2 of theSBounds' -e 'end tell'" with administrator privileges   but this code also requires that the application from which the Service is run is added to the Accessibility list.  Note: I only want to run this AppleScript as a Service, and not in an Automator-created Application, because the code receives selected text as its input (system-wide). Is there a closed form expression for $1 + x + x^{4} + x^{9}+x^{16}+x^{25} +..+x^{k^2}$? We all know what the sum of a geometric series is  $1 + x + x^2 + x^3 + ... + x^k = \frac{x^{k+1} - 1}{x - 1}$ .  I was wondering if similar formulas exist in case the exponents  form some other sequence, for example are squares or cubes of positive integers? Given the key, the plain text and the cipher text can I calculate the IV used in CBC mode? If I have the plain text, the ciphertext and the key for an AES-128 CBC operation, can I determine the IV, even if I don't know the padding (assuming the padding follows one of the more common formats)?  I believe it should be possible since my understanding is that the IV is only used as an initial XOR of the plain text in encryption, and should, therefore, be able to be available like this:  AESDecrypt(key, ciphertext) =&gt; (PlainText XOR IV); IV = ((Plaintext XOR IV) XOR (Plaintext))   Is this correct? What is $\arctan(x) + \arctan(y)$ I know $$g(x) = \arctan(x)+\arctan(y) = \arctan\left(\frac{x+y}{1-xy}\right)$$  which follows from the formula for $\tan(x+y)$. But my question is that my book defines it to be domain specific, by which I mean, has different definitions for different domains:  $$g(x) = \begin{cases}\arctan\left(\dfrac{x+y}{1-xy}\right), &amp;xy &lt; 1 \\[1.5ex]  \pi + \arctan\left(\dfrac{x+y}{1-xy}\right), &amp;x&gt;0,\; y&gt;0,\; xy&gt;1 \\[1.5ex]  -\pi + \arctan\left(\dfrac{x+y}{1-xy}\right), &amp;x&lt;0,\; y&lt;0,\; xy &gt; 1\end{cases}$$  Furthermore, When I plot the function $2\arctan(x)$, it turns out that the book definition is correct. I don't understand how such peculier definition emerges. Thank you. Wifi Automatically Turning ON after iOS 11 Update I'm facing this issue after updating iOS11 in my recently bought iPhone 7  I usually turn off wifi during the night and found it ON in the morning. It automatically turns ON resulting in unnecessary battery drains.  Would appreciate a fix !!