Is the 'n in Crisp 'n Dry vegetable oil a messed up contraction of "and" ?  Or is it supposed to indicate on or in or some such?  See
In expressions such as "ham 'n eggs", the conjunction 'n appears to replace and, yet there is only one apostrophe to indicate the missing a and none for the missing d (i.e., no "ham 'n' eggs").    Is there a punctuation rule that governs this or is it just an idiosyncratic case?
How do I add permissions via command line for "everyone" on external HDD I have an external HDD and I kind of messed up the file permissions but when fixing it I thought it is ok bc with my username I can access the files perfectly fine. Now that I use this with two PC (actually ATM I don't have access to my other PC) I can't access these files.  The problem is this directory has hundreds of folders with no permission for "everyone". I would like to give it the default permissions including have all access for the user "everyone". How do I do that via command line for these hundreds of folders? Getting full JS autocompletion under Sublime Text Proving an infinite number of primes of the form 6n+1 I write some choice questions into beamer frame, after some research, here is my code:  \documentclass[aspectratio=169]{beamer} \usetheme{Berkeley} \usepackage{tasks,CJK} \begin{document} \begin{CJK*}{utf8}{bsmi} \begin{frame} \transwipe 1.Which one you want to choose? \begin{tasks}[counter-format=tsk[A].,debug=true](4) \task A \task B \task C \task D \end{tasks} \end{frame} \end{CJK*} \end{document}   output with pdflatex:  But I don't want the D choice goto the second line, I want them stay in one line, what should I do? Commenting out multiple lines of code, specified by line numbers, using vi or vim I have learned from  that it is possible to use vi/vim to comment out a specified range of line numbers.  For example, suppose I have the following bash script:  #!/bin/bash  This is my very very great script   Now suppose that I want to comment out line numbers 6 through 8 (which contain the words very, very, and great) using the # comment character.  In vi/vim, I can simply type :6,8s/^/# to obtain the following:  #!/bin/bash  This is my #very #very #great script   which comments out lines 6 through 8.  My question is, is it possible to type a similar one liner that will remove the # comment character from lines 6 through 8 (but not any other commented lines in the file)?  Having said this, I realize that there is some debate about whether I am actually using vi or vim.  In practice, I open a file script.sh with the command vi script.sh.  Also, when I type the command which vi, I obtain /usr/bin/vi.  Nevertheless, when I simply type vi and press Enter, I obtain this:  ~                              VIM - Vi IMproved ~ ~                               version 7.2.330 ~                           by Bram Moolenaar et al. ~                 Vim is open source and freely distributable ~ ~                           Sponsor Vim development! ~                type  :help sponsor&lt;Enter&gt;    for information ~ ~                type  :q&lt;Enter&gt;               to exit ~                type  :help&lt;Enter&gt;  or  &lt;F1&gt;  for on-line help ~                type  :help version7&lt;Enter&gt;   for version info   which seems to suggest that I'm actually using vim.  I am accessing a remote Ubuntu Linux cluster using SSH from my PC.  I am not using a Ubuntu Linux GUI. Updated DNS zone can't be seen from my local network How do I configure Apache 2 to run Perl CGI scripts? I would like to configure Apache 2 running on Kubuntu to execute Perl CGI scripts. I've tried some steps that I came across by googling, but nothing seems to work.  What is the right way of achieving this? replacing the default console emulator under Windows XP How can I replace the default program providing console windows under Windows XP?  I know of , and I have a shortcut to start cmd.exe in . But now I want console applications to start in Console2 rather than the default console program, even when I have no control over the program that starts the console application. (I.e. a non-console program starts consoleapp.exe, and I can't change it to start Console2 instead, but I still want the application to be started inside a new instance of Console2.)  (Note that I want to replace the console itself, that is, the window in which console (i.e. text mode) applications run. And I must be able to run arbitrary, unmodified console applications: a substitute for a specific console program such as Cmd won't do me any good.)  EDIT: So what I'm after is a , which           OT: I want to know when Microsoft is going to make a decent CSRSS replacement. Not being able to adjust the width of a "terminal" by resizing the window is a complete joke.         Go download the ISE already. (It's included in Win7/2008R2.)   But as far as I understand this ISE is an , not a general console emulator. How do I forward/NAT all traffic to one interface/IP to a remote IP? I have one "server A" that has multiple IPs attached to it, like so:  eth0:0 1.1.1.1 eth0:1 1.1.1.2 eth0:2 1.1.1.3   I have another "server B" that also has multiple IPs attached to it, like so:  eth0:0 2.2.2.1 eth0:1 2.2.2.2 eth0:2 2.2.2.3   Now, I want to setup iptables on "Server A" to forward/NAT all incomming traffic on "eth0:2" to IP 2.2.2.3 on "Server B".  I have verified that "Server A" is able to "talk" to "Server B" on IP 2.2.2.3. Ping and telnet to open ports works just fine and I have the forward-flag turned on (net.ipv4.ip_forward=1)  I have tried multiple different ways, DNAT, SNAT, MASQUERADE etc, but I cannot get anything to work.  This line works fine if I try to forward traffic between IPs on the SAME server:  iptables -t nat -A PREROUTING -d 1.1.1.3 -j DNAT --to-destination 1.1.1.2   But if I switch out the "1.1.1.2" for "2.2.2.3", it does not work.  I assume that I need a second iptable rule to solve it. I have tried with the following POSTROUTING rules without any luck (not at the same time):  iptables -t nat -A POSTROUTING -d 2.2.2.3 -j MASQUERADE iptables -t nat -A POSTROUTING -d 2.2.2.3 -j SNAT --to 1.1.1.3 iptables -t nat -A POSTROUTING -j MASQUERADE   What am I missing?  EDIT 1:  I finally got it to work by using the following:  net.bridge.bridge-nf-call-iptables=0  iptables -t nat -A PREROUTING -d 1.1.1.3 -j DNAT --to-destination 2.2.2.3 iptables -t nat -A POSTROUTING -d 2.2.2.3 -j SNAT --to 1.1.1.3   However, now another problem appeared. All logs etc on server 2.2.2.3 shows that ALL traffic now comes from 1.1.1.3, like apache logs, mail logs etc. I assume this is the nature of NAT.   However, when I do standard port forwarding on my home-router to my laptop that is running apache, I see the original "requester IP" in the logs. So, how does the router do this? And how can I do the same on my server setup?  Bottom line, I want to forward all traffic from Server A (1.1.1.3) to Server B (2.2.2.3), BUT I also want to be able to see where the traffic came from on Server B (2.2.2.3), i.e the apache logs should show the original IP of the requester.  I assume I should use some other way than NAT to make this happen, and it should be possible, as even my simple home-router is able to do this.  One extra thing, the IPs attached to Server A and Server B is LOCKED to each respective server. Thus, Server A is NOT able to send out traffic FROM IP 2.2.2.3. It is locked by my provider in the router. What effect does the Barr body have, in relation to female Turner syndrome? Why do persons with  have  developmental abnormalities, when normal XX-females do not, even though they only have 1 active X chromosome? From what I know, one X-chromosome is inactivated into a Barr body in normal XX-females, but these obviously don't show the symptoms of Turner syndrome. What function does the inactive chromosome have? After converting to nodes in order to render using Cycles I've no idea where to enable the z-transparency. I guess the image textures alpha channel needs to be pluged somewhere but I've no idea which node would be suitable.   The question is how could I correctly setup the nodes to have the same effect as when using z-transparency in BI?      The materials original settings for BI are:    Which renders like:    I had no luck with DarenWs suggestion: Compute approximately the probability that more than 50 of the observations of the random sample are less than 3. Let $X_1,X_2,...,X_n$ be a random sample of size $n = 72$ from a distribution with probability density function $f(x) =\begin{cases} 1/x^2,&amp; 1 &lt; x &lt; infinity\\0,&amp;\text{otherwise}\end{cases}$ Compute approximately the probability that more than $50$ of the ob- servations of the random sample are less than $3$. Can I enter the UK with a Schengen visa? How to Deserialize XML document Boundary Question in $\mathbb{R}^{2}$ (Manifolds) Can anyone help me identify a story about kids with silver blood? Let $A$ be an $n \times n$ matrix with real enteries. Define $\langle x,y\rangle_A = \langle Ax,Ay\rangle, \quad x,y \in \mathbb R^n$ , where $\langle,\rangle$ is a standard inner product on $\mathbb R^n$. Then  $\langle x,y\rangle_A$ is an inner product iff  1)  $\ker A = \{0\}$.  2) $\operatorname{rank} A= n$.  3) all eigenvalues of $A$ are positive.  4) all eigen value of $A$ are non negative.  Clearly if $\ker A \neq \{0\}$, then there exist $x \neq 0$ such that $Ax =0$, then $\langle Ax, Ax\rangle_A = 0$, then $\langle ,\rangle_A$ is not inner product, so $\ker A = \{0\}$, thus rank of $A$ is $n$.  I am unable to check the 3) and 4) option. Please help to check the other option. Thank you How to find and replace a string by increasing its numerical part? My input file is,  ami21 ami65 ami67 ami66 ami88 ami76 ami29 ami55  ami54 ami32   Using a single command line I need the output as,  ami22 ami66 ami68 ami67 ami89 ami77 ami30 ami56 ami55 ami33   I used the command  awk -vRS=ami '{$0=$0+1;ORS=RT}++n' inputfile &gt; outputfile   but I got the outputfile as ami21ami65ami67ami66ami88ami76ami29ami55ami54ami32  i.e. all strings are written in same line and without space. Could anyone suggext me some better command line. What is The Rule of Three? Centos mysql version is 5.5 however PHPmyadmin still says version 5.1 When i run the following in my console:  [root@****~]# mysql -u root -p -e 'SELECT VERSION();' Enter password: +-----------+ | VERSION() | +-----------+ | 5.5.39    | +-----------+   Which should be the correct version.  However when i enter my PHPMYADMIN on my server it has the following specs:  Server: Localhost via UNIX socket Program: MySQL Programversion: 5.1.73 - Source distribution   So which version is the correct one and how do i make sure that the database is running on 5.5?  Note  I have already restarted sql several times without any changes