This question is similar to:  , but with a small refinement,   only first flag will get +2 reputation only accepted and committed flag will get the reward (this is: question got closed as duplicate, for example) only 'exact duplicate' and 'offtopic -> move to other sub-site..' flags will be eligible for bonus.   Rationale:   there is a high volume of newbie questions appearing each day, which are already answered, sometimes answered at epic level. because answering such question can give a person +25 reputation from the noob, not counting random by-passers' good will - people are not very willing to mark such questions as duplicate, and sometimes deliberately copy-paste answers from older duplicates. offensive, spammy or retarded questions are downvoted with passion anyway, so there is no need to additionally reinforce users to do that ;)
deals with various ways of rewarding the finding of duplicates, a tough and increasingly necessary janitorial task.  Here's a concrete suggestion:   Reward the finder of a duplicate with +10 points if the question gets closed as a dupe. If multiple duplicates are found, reward all finders whose suggestion was voted for at least once by another user. (The limitation is to avoid gaming by making frivolous suggestions when it's obvious that a question is going to get closed as a duplicate.) Reward each following closevoter who picks one of the previously suggested dupes with +2 points if the question gets closed. Punish everyone involved (dupe-finders and dupe-voters) with -5 points, and revoke all rep gained from the dupe-voting, if a question closed as duplicate gets reopened.   A punishment for mis-voting is going to be controversial but in my eyes, it is absolutely essential. Finding a good dupe is a work of love: You need to make sure you understand the OP's question, and you need to scan every potential duplicate for whether it really contains an answer that will help the OP. Everyone dupe-votes carelessly from time to time, so the threat of punishment needs to be present to keep everyone on their toes, just as the threat of downvoting does when you post an answer.  If you think +10 is too high a reward: Consider that finding a duplicate can often be more work than writing an answer, and a correct answer usually nets you at least 10 points, if not much more.   If you think -5 is too much of a punishment: -2 might work as well, although I really think there should be a harsh punishment on an unfair dupe-closing.
I just noticed that the  user edited a ~1 year old  of mine. As you can see, the method call was changed from getSfGuardUser to getGuardUser:    Now I checked the documentation and it seems that the edit is correct.  But how did Community know about that? As far as I know, it is an automated process. Does it have a reference of all possible APIs of languages/frameworks (which seems very unlikely) or is there a routine admins can trigger, for replacing content? Or is it a secret? Media keys not working for iTunes (pause/play, skip buttons) How to scale dimensions proportionally to a specific size? I modeled a man and would like to scale him down to be exactly 6' tall (Z dimension), however I cannot find a way to do that. I know I can go to front ortho view and and use the normal scale S  key to scale it, however that requires some pretty specific fine tuning in order to get it to the right dimensions.  I'd like to be able to essentially type "6" into the Z dimension (don't worry I have it setup in imperial) and have it scale the X and Y dimensions proportionally. Solve the following equation: $\sqrt {\sin x - \sqrt {\cos x + \sin x} } = \cos x$ Solve the following equation:  \begin{array}{l}{\sqrt{\sin x-\sqrt{\cos x+\sin x}}=\cos x} \\ \text{my try as follows:}\\{\sin x-\sqrt{\cos x+\sin x}=\cos ^{2} x} \\ {\sin x-\cos ^{2} x=\sqrt{\cos x+\sin x}} \\ {\sin ^{2} x+\cos ^{4} x-2 \sin x \cos ^{2} x=\cos x+\sin x} \\ {\sin ^{2} x+\cos ^{4} x-2 \sin x \cos ^{2} x-\cos x-\sin x=0} \\ {\sin ^{2} x+\cos ^{4} x-2 \sin x\left(1-\sin ^{2} x\right)-\cos x-\sin x=0} \\{\sin ^2}x + {\left( {1 - {{\sin }^2}x} \right)^2} - 2\sin x\left( {1 - {{\sin }^2}x} \right) - \cos x - \sin x = 0\\ {\sin ^{2} x+\sin ^{4} x-2 \sin ^{2} x+1-2 \sin x+2 \sin ^{3} x-\cos x-\sin x=0} \\ {\sin ^{4} x+2 \sin ^{3} x-\sin ^{2} x-3\sin x-\cos x+1=0}\end{array}  Now i think it gets more complicated , any help would be appreciated Keyboard not working after suspend to ram (sleep) Can we implement a dead time on answers for high reputation user Summary: High reputation users on SO come swooping in the second a simple question is posted, and get the first answer in before I've even opened my Python interpreter to test my idea out.  This actually is a problem because it prevents use lower users who aren't as good  at programming from getting any answers in.  This makes it very hard to build up reputation.  Thus, I propose a short dead time for high reputation users where their answers do not appear.  The Problem: This isn't just reputation.  By answering questions and having discussions with OP, we all get better at our language.  Teaching is one of the best ways of learning, and a more well versed population is absolutely good for SO.  (If anyone wants to argue that, go home)  While its nice to have folks who can quickly answer nearly all questions in a jiffy, its a little frustrating for those of use who simply aren't as fast, but still want to contribute.  The result is that many people do not answer questions because they feel like they just can't get an edge in.  SO should aim to incentivize as many answers by as many users as possible.  The most answers from the most users is the most beneficial situation for the site and the community. Once we accept this idea, it is clear that something needs to be done to address the issue at hand    The Solution: Luckily, this is an easy problem to solve; we use a dead time.  High reputation users can post answers whenever they like, but they won't appear until after the dead time is completed.  The trick is balance, a dead time which is too long will harm the OP as the question will remain unanswered, however, a dead time which is too short won't actually fix the problem.  There definitely needs to be a discussion about what "high reputation" means and what dead time to use, but it should be independent of whether y'all agree that this is a problem.  So, what do you think?  EDIT: Wow, -18, I leave for lunch for 30 minutes and this is what happens!  I guess y'all think this is a bad idea, but let me try to clarify a few things on which I was unclear earlier.  This is not about reputation.  This is not about getting the first answer just for the sake of getting to say "in before..."  This is about learning.  By getting a shot at answering questions before the high reputation users, people learn. Think of it as doing an example problem in class before the teacher does it. You get a chance to try it yourself, test your knowledge, and if you fail, then the teacher is right behind you to show the correct solution.  This is what I'm trying to accomplish. However, seeing the solution, and then trying to answer the question, is not very helpful. This is how I view the status quo.    In response to Mr. Pieters' answer and comments: You're absolutely right, this is not about quantity, its about quality.  The fastest answer isn't always the best.  But asking the high reputation users to take a step back for a few minutes is a means of getting there.    Hopefully this clears things up a bit. Use the view from other cameras in the scene as VideoTexture in Cycles I have a scene with monitors that display video from cameras in the same scene (or other scenes, but all of them are linked i.e., same objects in the scene). The cameras shown on the monitors do not view the monitors, so no looping should occur.  I found  that shows how to get the effect in the Game Engine.  I would like to do this in cycles.  Essentially I would like a material input node that corresponds to the output of the composition of a particular scene. The incoming image should honor the render settings of the particular scene and any compositing applied to it.  The Render Layer node does not appear to honor the resolution or compositing settings of the scene it comes from, and is not available to apply as a texture in the material node editor (that I can find).  I understand that this could be done by rendering the animation from the various cameras, then applying that video as textures to the monitors, then rendering the camera of the monitors. That's super tedious if your making changes to the whole scene, and I don't want to do that. Question of an isomorphism of $\epsilon_ 0$ and a subset of the rationals. Manually disable a module "would rather" + subject + past subjunctive What is the difference between:   The company would rather each employee be provided with ID card.  The company would rather each employee were provided with ID card. What can I do if a repository/PPA does not have a Release file? When updating, I get the following error message:   W: The repository 'http://ppa.launchpad.net/mc3man/trusty-media/ubuntu xenial Release' does not have a Release file.   Here, I find another statement on this error:   This recommends removing certain PPAs; and, I'm not sure if I should do that since it might mean not getting the updates that I need.    Is this what I should do? After upgrading to Firefox 57 Quantum many website have rendering issues, such as empty frames, missing text or fonts, etc. I use Kubuntu 16.04 64 bit.  So far, I've tried:   Restarting Firefox in safe mode Disabling "hardware acceleration"   Wiping out my profile Purging Firefox and reinstalling Running Firefox from a clean user account   But nothing helped so far.  Any tips on how to solve this are much appreciated Nested regression model Is a rational-valued continuous function $f\colon[0,1]\to\mathbb{R}$ constant? Let $f\colon[0,1]\to\mathbb{R}$ be continuous such that $f(x)\in\mathbb{Q}$ for any $x\in[0,1]$. Intuitively I feel that $f$ is constant, since $\mathbb{Q}$ is dense in $\mathbb{R}$.  How can I formally write this down? Difficulty in creating macro '\newcommand' for the beginning and end of frames in Beamer Continuity and existence of directional derivatives at all directions of a $f:\mathbb{R}^{2} \to \mathbb{R}$ given by $f(x,y)=\frac{2x^2y}{x^2+y^2}$ Let $f(x,y)=     \begin{cases}       \frac{2x^2y}{x^2+y^2} &amp; if &amp; (x,y) \neq (0,0) \\       0       &amp; if &amp; (x,y)=(0,0) .  \end{cases}$  (i) Prove the directional derivatives of $f$ exist in any direction at the point $(0,0)$.  (ii)¿Is $f$ continuous on (0,0)?  For (i) I took $u=(u_{1},u_{2}) \in \mathbb{R^{2}}$ such $\|u\|=1$ and $0=(0,0)$. So $$\lim_{t \to 0} \frac{f(0+ t u)-f(0)}{t}=\lim_{t \to 0}\frac{2(tu_{1})^2 (tu_{2})}{(tu_{1})^4+(tu_{2})^2}=\lim_{t \to 0}\frac{(t^2 u_{1}^2)(t^2 u_{1}^{2}) tu_{2}}{t^{4}u_{1}^{4}+t^{2} u_{2}^{2}}.$$ But I cannot find the limit when $t$ aproaches to $0$. Which by finding them I would prove the directional derivative exist at every direction right?  For (ii) I got the intuition $f$ is not continuous at $(0,0)$ so I took $\lbrace (\frac{1}{k},\frac{1}{k}) \rbrace_{k \in \mathbb{N}}$ and $\lbrace (\frac{1}{k},0) \rbrace_{k \in \mathbb{N}}$ which are two different sequences in $\mathbb{R}^{2}$ converging to $(0,0)$. However, $\lbrace f(\frac{1}{k},\frac{1}{k}) \rbrace_{k \in \mathbb{N}}=\lbrace \frac{1}{k^{2}} \rbrace_{n \in \mathbb{N}} \to 0$ and $\lbrace f(\frac{1}{k},0) \rbrace_{k \in \mathbb{N}} \to 0$. So maybe my intuition was not right? Can anyone help me end the proof of continuity or not continuity , please? How can I restrict a user on the SSH server to allow them only the privileges for ? i.e. So they cannot run commands even if they log in via SSH.  My Linux servers are Ubuntu 11.04 and OpenWrt. I just ordered the Nvidia GTX card. I have a dilemma, though. Should I keep using the driver which is available in "additional drivers" in Ubuntu, or should I install the driver from the Nvidia site?  So which driver is the best for me? I used to think that all users can delete their own posts, as long as these posts haven't gained a relevant number of upvotes. After seeing posts  again and again, I decided to verify my assumption and found out that you actually can't delete your own answers if you post from a low reputation, cookie based account.  Is there a reason for this or is this unintentional?  In my opinion even users without a "substantial" account should be able to change their minds and delete an answer if they think better of it. I've recently decided that I just have to finally learn C/C++, and there is one thing I do not really understand about pointers or more precisely, their definition.  How about these examples:   int* test; int *test; int * test; int* test,test2; int *test,test2; int * test,test2;   Now, to my understanding, the first three cases are all doing the same: Test is not an int, but a pointer to one.  The second set of examples is a bit more tricky. In case 4, both test and test2 will be pointers to an int, whereas in case 5, only test is a pointer, whereas test2 is a "real" int. What about case 6? Same as case 5?