Minecraft keep crashing, Help SO i wanted to get to feel that nostalgia but i have been REALLY annoyed by an unpleasant issue. any help its hugely apreciated! My specs:   IntelCorei7-2600 3.6 GHz 8GB Ram Windows 10 pro No graphics card (hope that this its not the issue, even tho im pretty sure it can be)   Here is the error log  ---- Minecraft Crash Report ---- // Hey, that tickles! Hehehe!  Time: 11/04/19 20:14 Description: Initializing game  java.lang.IllegalStateException: GLFW error 65542: WGL: The driver does not appear to support OpenGL     at cgd.b(SourceFile:218)     at org.lwjgl.glfw.GLFWErrorCallbackI.callback(GLFWErrorCallbackI.java:36)     at org.lwjgl.system.JNI.invokePPPP(Native Method)     at org.lwjgl.glfw.GLFW.nglfwCreateWindow(GLFW.java:1649)     at org.lwjgl.glfw.GLFW.glfwCreateWindow(GLFW.java:1827)     at cgd.&lt;init&gt;(SourceFile:99)     at cgc.a(SourceFile:79)     at cft.am(SourceFile:439)     at cft.a(SourceFile:380)     at net.minecraft.client.main.Main.main(SourceFile:144)   A detailed walkthrough of the error, its code path and all known details is as follows: ---------------------------------------------------------------------------------------  -- Head -- Thread: Client thread Stacktrace:     at cgd.b(SourceFile:218)     at org.lwjgl.glfw.GLFWErrorCallbackI.callback(GLFWErrorCallbackI.java:36)     at org.lwjgl.system.JNI.invokePPPP(Native Method)     at org.lwjgl.glfw.GLFW.nglfwCreateWindow(GLFW.java:1649)     at org.lwjgl.glfw.GLFW.glfwCreateWindow(GLFW.java:1827)     at cgd.&lt;init&gt;(SourceFile:99)     at cgc.a(SourceFile:79)     at cft.am(SourceFile:439)  -- Initialization -- Details: Stacktrace:     at cft.a(SourceFile:380)     at net.minecraft.client.main.Main.main(SourceFile:144)  -- System Details -- Details:     Minecraft Version: 1.13.2     Operating System: Windows 10 (amd64) version 10.0     Java Version: 1.8.0_201, Oracle Corporation     Java VM Version: Java HotSpot(TM) 64-Bit Server VM (mixed mode), Oracle Corporation     Memory: 34848312 bytes (33 MB) / 202657792 bytes (193 MB) up to 6991118336 bytes (6667 MB)     JVM Flags: 5 total; -Xmn128M -Xmx6680M -XX:HeapDumpPath=MojangTricksIntelDriversForPerformance_javaw.exe_minecraft.exe.heapdump -Xss1M -XX:+UseConcMarkSweepGC     Launched Version: 1.13.2     LWJGL: 3.1.6 build 14     OpenGL: NO CONTEXT     GL Caps:      Using VBOs: Yes     Is Modded: Probably not. Jar signature remains and client brand is untouched.     Type: Client (map_client.txt)     Resource Packs:      Current Language: ~~ERROR~~ NullPointerException: null     Profiler Position: N/A (disabled)     CPU: &lt;unknown&gt;
Why is Minecraft giving an OpenGL error? I recently got Minecraft but not from the website, I paid for a code and everything seemed ok. When I tried to play the game a thing came up saying it crashed and then a message popped up saying The game crashed whilst initializing game     Error: java.lang.IllegalStateException: GLFW error 65542: WGL: The driver does not appear to support OpenGL.
According to the documentation, the  method uses a round-to-even algorithm which is not common for most applications. So I always end up writing a custom function to do the more natural round-half-up algorithm:  public static decimal RoundHalfUp(this decimal d, int decimals) {     if (decimals &lt; 0)     {         throw new ArgumentException("The decimals must be non-negative",              "decimals");     }      decimal multiplier = (decimal)Math.Pow(10, decimals);     decimal number = d * multiplier;      if (decimal.Truncate(number) &lt; number)     {         number += 0.5m;     }     return decimal.Round(number) / multiplier; }   Does anybody know the reason behind this framework design decision?  Is there any built-in implementation of the round-half-up algorithm into the framework? Or maybe some unmanaged Windows API?  It could be misleading for beginners that simply write decimal.Round(2.5m, 0) expecting 3 as a result but getting 2 instead. If $\operatorname{rank}\left( \begin{bmatrix} A &B \\ C &D \end{bmatrix}\right)=n$ prove that $\det(AD)=\det(BC)$ Let $A,\ B,\ C,\ D \in \mathcal{M}_n(\mathbb{C})$. If $\operatorname{rank}\left( \begin{bmatrix} A &amp;B \\ C &amp;D \end{bmatrix}\right)=n$, prove that $\det(AD)=\det(BC)$. Node.JS Not working on the internet biblatex: remove commas between last and first names in bibliography Let A,B be in $M_{mxn}(\mathbb{R})$  Prove that if rank(A + B) = rank(A) + rank(B), then col(A) ∩ col(B) = {0}  I started with a proof by contradiction, since we know that rank(A + B) ≤ rank(A) + rank(B). I assume that if rank(A + B) &lt; rank(A) + rank(B), then col(A) ∩ col(B) = {0}. I realize that we don't have to do the > case. However I am a little confused on how to show col from rank. Mirror modifier. Mirrored half is not aligned, but rotated I was working on my character's hand when I realized half of the body was suddenly deleted. I am trying to recreate the other half, but it just won't mirror properly in the center. I tried moving the origin to the 3D cursor while it was completely centered, but the mirror modifier is still applied at an angle. How do I list the members of a group? How can I see all the members of a group in Linux? In the Final Battle, when you remove doom tokens for rolling successes against an Ancient One do you stop counting successes for that roll? In Arkham Horror you have to roll a cumulative number of successes equal to the number of players to knock off a doom token from the Elder God's health. If you reach the number of players worth of successes do you then stop counting for the player and move on or do you count the extra successes against the next doom token?  We played it so that you kept on adding them but it meant that we turned Nyalothotep into mince meat quite quickly (One Character was blessed had a fight of 6 a shotgun and Fight +1 skill card though) The square of an integer is congruent to 0 or 1 mod 4 Finding the id of a parent div using Jquery What is the term for accusing a person of mischief through invented, twisting and changeable terminology? What is the term for accusing a person of invented wrongdoing in such a way that he cannot respond or even clearly understand the accusations? For example, frequently reversing the definitions of the terminology used, or basing argumentation on hints and roundabout phrasings, metaphors, invented-on-the-fly floating definitions and rules to fit with the accusations.    Update: I think inquisitorial is the most proper term for context in which the result does not depend on the argumentation of one of the sides.    Though, jargonaut was completely unheard by me and incrementally more useful. Exact probability of random graph being connected The problem: I'm trying to find the probability of a random undirected graph being connected. I'm using the model $G(n,p)$, where there are at most $n(n-1) \over 2$ edges (no self-loops or duplicate edges) and each edge has a probability $p$ of existing. I found a simple formula online  where $f(n)$ is the probability of $G(n,p)$ being connected. But apparently it's too trivial for the writer to explain the formula (it was just stated briefly).  The desired formula: $f(n) = 1-\sum\limits_{i=1}^{n-1}f(i){n-1 \choose i-1}(1-p)^{i(n-i)}$  My method is: Consider any vertex $v$. Then there's a probability ${n-1 \choose i}p^i(1-p)^{n-1-i}$ that it will have $i$ neighbours. After connecting $v$ to these $i$ neighbours, we contract them ($v$ and its neighbours) into a single connected component, so we are left with the problem of $n-i$ vertices (the connected component plus $n-i-1$ other "normal" vertices.   Except that now the probability of the vertex representing connected component being connected to any other vertex is $1-(1-p)^i$. So I introduced another parameter $s$ into the formula, giving us:  $g(n,s)=\sum\limits_{i=1}^{n-1}g(n-i,i){n-1 \choose i}q^i(1-q)^{n-1-i}$,  where $q=1-(1-p)^s$. Then $f(n)=g(n,1)$. But this is nowhere as simple as the mentioned formula, as it has an additional parameter...  Can someone explain how the formula $f(n)$ is obtained? Thanks! All my college years I have been using public, and would like to know the difference between public, private, and protected?  Also what does static do as opposed to having nothing? How I can create a graph of acceleration and speed - tikz? How can I create a graph of acceleration and speed like the one in the picture. Knowing that they are each other's consequence?    \documentclass{article} \usepackage{tikz}  \begin{document}  \begin{tikzpicture}               \end{tikzpicture} \end{document} Apply for Schengen visa in a third country Can a Kenyan citizen studying in Russia and temporarily visiting family in Kenya apply for a Schengen visa in Nairobi and not in Russia, where he has his residence? Separate Network Traffic on Two Network Interfaces Would a Bayesian admit that there is one fixed parameter value? In Bayesian data analysis, parameters are treated as random variables. This stems from the Bayesian subjective conceptualization of probability. But do Bayesians theoretically acknowledge that there is one true fixed parameter value out in the 'real world?'  It seems like the obvious answer is 'yes', because then trying to estimate the parameter would almost be nonsensical. An academic citation for this answer would be greatly appreciated. Determining a matrix from its characteristic polynomial Let $A\in\mathcal{M}_{n}(K)$, where $K$ is a field. Then, we can obtain the characteristic polynomial of $A$ by simply taking $p(\lambda)=\det(A-\lambda I_n)$, which give us something like $$p(\lambda) = (-1)^n\lambda^n + (-1)^{n-1}(\text{tr } A)\lambda^{n-1} +  \cdots + \det A$$ Now, how can we obtain the matrix $A$ knowing the characteristic polynomial? Is there a way to display a player name in /tellraw command? like the title says, I'm looking for a way to display a player name in a /tellraw command which is run by a command block. Example:  /tellraw @a {"text":"","extra":[{"text":"A player has won the game!","color":"blue"}]}   And the output is something like this:  A player has won the game!   But I want the output to be something like  JasonSPQR has won the game!   Using the @p parameter Why are irrational numbers uncountable and rationals countable? Question 1: Why are irrational numbers uncountable and rationals countable?  I really struggle to understand this. I initially thought it had something to with the fact that between any two numbers there will always be a irrational number. But now it has come to my attention that the same holds for rational numbers. So I can't really see the difference between them. What is it that makes the difference? Why can we line up all rational numbers one-to-one with the natural numbers, but not the irrationals with the naturals?  Sorry for a perhaps basic question, but I really, really struggle with it. Thanks.