Why is the code syntax color highlight gone in the mobile view? The code block on a phone or tablet is only black/white.   Update: example The code in the following link will have syntax color highlight in desktop browser.    Here is the image of the mobile view.
Code blocks are not prettified on mobile site On Chrome on Android, code blocks on the mobile site have no syntax highlighting, are not a monospaced font, and words are wrapped.  Mobile site on mobile browser:    Desktop site on mobile browser:    Inline code has the same issue, it isn't a monospaced font.  It has been this way for as long as I can remember. Wouldn't be surprised if this is a dupe.
Can't quantum teleportation be superluminal some percentage of times? I apologize if this is a really silly question.   In the (textbook) quantum teleportation algorithm, in the step right after Alice has measured her system but before she has sent her classical information to Bob, she is about to send one of the following values: 00,01,10,11.   What if Bob doesn't want to wait and simply takes a guess? Wouldn't there then be superluminal communication 25% of the time? Convergence of $\sum_{n=1}^\infty\frac{n}{(n+1)!}$ Can someone give an explanation using the definition of convergence in partial sum to show how the above infinite sum converges to 1?  Thanks SWR surname that in fact describes or applies to the human in question? There are (in real life) many amazing examples of this (Bill Gates, "gates" being the fundament of computers, Tiger "Woods", the greatest ever user of "woods" golf-clubs, etc) and it is a staple of fiction.  Is there a single-word for this, or a frequently-used term?  Note that in fictional usage, I observe there is literal "X", so, for example I just saw a children's movie where "Madame Work" was a taskmaster. However, authors often employ near-literal "X": for example, most of the minor character surnames in Harry Potter are 'kind of" "X".  So, is there an "X" for Bill "Gates", Tiger "Woods", an undertaken named Mr. Death, etc?  Sorry if this has been asked already, I couldn't find it.    Note - I've just found there's a "wikipedia" page claiming 'aptonym' or 'euonym' is sometimes used.  Wikipedia is often valueless, so I do not know if this is a meaningful claim. Why don't authors include in their publications the duration of the research? Short story - "One man's meat is another man's poison" When my phone starts up there are several application/services running in the background that I would rather not.  And when I press the Home button while using an app, that app usually goes into the background without exiting.  How can I stop these apps from running? Lightning tags in beta I came across some lightning tags that are still in beta, ex: lightning:input (Beta) lightning:tabset (Beta) etc  Not sure for how long they were in beta, is it advisable to use them for building UI and deploy to production? I see that Stack&nbsp;Overflow is very Linux specific. Doesn't Unix &amp; Linux and Ask&nbsp;Ubuntu cover much of the same ground? I see that Unix &amp; Linux and Server&nbsp;Fault also cater to many Linux server questions. Similarly, Ask&nbsp;Ubuntu and Super&nbsp;User seems to contain most like questions. Prove $2^k+1$ divisible by 3 for odd K The beamer command \alt&lt;*overlay specification*&gt;{foo}{bar} will insert foo if the current slide is within the given overlay specification, and bar otherwise.  It's equivalent to   \only&lt;*overlay specification*&gt;{foo}\only&lt;*complementary overlay specification*&gt;{bar}   Here is a sample document using it:  \documentclass{beamer} \begin{document} \begin{frame} \begin{align*} y &amp;= \frac{(x^2+1)\sqrt{x+3}}{x-1} \\ \ln y &amp;= \ln (x^2+1) + \frac{1}{2} \ln(x+3) - \ln(x-1) \\ \frac{1}{y} \frac{dy}{dx}       &amp;= \frac{2x}{x^2+1} + \frac{1}{2(x+3)} - \frac{1}{x-1} \end{align*} So \[ \begin{split} \frac{dy}{dx} &amp;= \left(\frac{2x}{x^2+1} + \frac{1}{2(x+3)} - \frac{1}{x-1} \right) \alt&lt;2&gt;{\frac{(x^2+1)\sqrt{x+3}}{x-1}}{y} \end{split} \] \end{frame} \end{document}   This is very useful and saves typing.  But if one of the alternatives is larger than the other, it leads to jiggling slides.    What I would like is a overlay-specification-aware command \altvisible that would take the same amount of space on each slide.  So it would have to insert a box as big as the bigger of the two, and then set the correct material.  So the above document with \altvisible instead of \alt would not jiggle.  Any takers? Sum of First $n$ Squares Equals $\frac{n(n+1)(2n+1)}{6}$ I used the jQuery Form plugin for asynchronous form submission. For forms that contain files, it copies the form to a hidden iframe, submits it, and copies back the iframe's contents. The problem is that I can't figure out how to find what HTTP status code was returned by the server. For example, if the server returns 404, the data from the iframe will be copied as normal and treated as a regular response.  I've tried poking around in the iframe objects looking for some sort of status_code attribute, but haven't been able to find anything like that.    The $.ajax() function can't be used, because it does not support uploading files. The only way to asynchronously upload files that I know of is using the hidden iframe method. How do you split a list into evenly sized chunks? I have a list of arbitrary length, and I need to split it up into equal size chunks and operate on it. There are some obvious ways to do this, like keeping a counter and two lists, and when the second list fills up, add it to the first list and empty the second list for the next round of data, but this is potentially extremely expensive.  I was wondering if anyone had a good solution to this for lists of any length, e.g. using generators.  I was looking for something useful in itertools but I couldn't find anything obviously useful. Might've missed it, though.  Related question: Can not make hibernate on UEFI (Secure boot) What determines who gets or becomes an MVP? This hasn't been asked yet, but what determines how or who gets an MVP award in CS:GO? After a match, there's always a little blurb that first states who got MVP first, and then a random fact (Player X got Y knife kills, Player X lasted Y rounds without dying, etc.).  Do these two factors both "factor" into getting an MVP award? Is it a set percentage of enemies you kill? Is there a priority list (ie, planting bomb, defusing, etc.)? Ambiguity of chi-squared test of association; how can the conclusion change using the ''same'' sample? Recently I have been struggling with the following two questions regarding the chi-squared test of independence / association during reading an article.        Is the chi-squared test able to detect no association between two groups among three at two levels? That is in a 3X2 contingency table.   Does the chi-squared test change its behavior with a larger sample that was otherwise perfectly proportional to a smaller sample?     I prepared a sample data set in R to seek the answers of these two questions. Though my initial discomfort about the chi-squared test have been proven, but over-acceptance of this test statistic in the scientific community have forced me to re-think. May be I have been missing something here.    # Question 1 x1 = c(100, 450, 450) x2 = c(600, 450, 450) d1 = rbind(x1,x2) colnames(d1) = c("Type 1", "Type 2", "Type 3") rownames(d1) = c("No", "Yes") d1 chisq.test(d1) # Significantly associated (not independent), though "Type 2" &amp; "Type 3"  #  were not different at all!   # Question 2 d2 = d1/50 d2 chisq.test(d2) # Not significant!!!  d3 = d2*2 d3 chisq.test(d3) # Significant!!! Do these two observations suffice to show that a finite boolean ring must be of the form $\mathbb{Z}_2\times\cdots\times\mathbb{Z}_2$? Question: If $R$ is a finite boolean ring, then show $R \cong \mathbb Z_2 \times \mathbb Z_2 \times \cdots\times \mathbb Z_2$.   I know that   $\mathrm{char}(R) =2$  $R$ has $2^k$ elements for some $k$  (this is because, if $p\neq 2$ is a prime with $p\mid|R|$, then there exists a non-zero $x \in R$ s.t. $px=0$ and $p $ is odd $\implies x=0$, contradiction).   Does this suffice to answer my question? Prove that the sum of digits of $(999...9)^{3}$ (cube of integer with $n$ digits $9$) is $18n$ Someone had posted a question on this site as to what would be sum of digits of $999999999999^3$ (twelve $9s$ ) equal to?   I did some computation and found the pattern that sum of digits of  $9^3 = 18$,  $99^3 = 36$,  $999^3 = 54$ and so on. So, I had replied that sum of digits of  $999999999999^3 = 12 \cdot 18 = 216$.  Can anybody help me prove this, that sum of digits of  $(\underbrace{999\dots9}_{n\text{ times}})^3 = 18n.$ Is there any way to attract or repel neutrons? I know that neutrons are neutral and have no charge, but is there any other way to interact with them? is piped ls the same as ls -1? ls returns output in several columns, whereas ls|cat returns byte-identical output with ls -1 for directories I've tried. Still I see ls -1 piped in answers, like ls -1|wc -l. Is there ever a reason to prefer ls -1? Why does ...|cat change the output of ls?