I need to take some online tests for school. This website tells me I need Flash Player 11.3.0 or higher. As far as I can see that is not yet avaible for Linux. I use Ubuntu 12.04 LTS and Chromium. Is there a way I can work around it?  Greetz. Rob.
Even though I have the latest Adobe Flash player 11.2 for Linux in Firefox -   - a particular online flash game still requests that I update to the latest flash player.  I've tried this online game on my laptop (Windows 8 with Flash Player 11.8) and it has no problems.  Is there a way to trick Ubuntu or this game into thinking Flash Player 11.8 is "installed"?
Is it really going to damage a bike to wash it with a hose? I was chatting to the guys at my LBS the other day about how they get my bike so clean when I take it in for a service. They said they use compressed air to clean it.   They warned I shouldn't use any high pressure water because it can get into the sealed bearings and cause damage. I also noted on the  (right at the end) that you should "Never spray your bicycle with water under pressure".  How much of an issue is this? Rinsing the bike with the hose is such a convenient way to wash off loose grit and then the soap after washing. How do you clean your bikes? Appendix in LaTeX I have already seen a proof of this statement here on stackexchange but I would like someone to verify whether "my proof" is correct and also if you could point out issues with the writing style. thanks in advance!  Statement. $\mathbb{Z}_{p}$ is an integral domain $\Leftrightarrow$ $p$ is prime.  Proof.$(\Rightarrow)$ Suppose $\mathbb{Z}_{p}$ is an integral domain. Assume (by way of contradiction) that $n$ is not prime. Then $n=ab$ for some $a,b\in \mathbb{Z}$ where $1&lt;a$ and $b&lt;n$, meaning $ab\equiv 0\pmod n$. This is a contradiction since $\mathbb{Z}_{p}$ is assumed to be an integral domain and therefore does not contain any zero divisors. Therefore $p$ must be prime.  $(\Leftarrow)$ Assume $p$ is prime. Then $a$ does not divide $n$ for any $1&lt;a&lt;n$ where $a\in \mathbb{Z}_{p}$. Thus $\mathbb{Z}_{p}$ does not contain any zero divisors and is therefore an integral domain. How do I loop through or enumerate a JavaScript object? I have a JavaScript object like the following:  var p = {     "p1": "value1",     "p2": "value2",     "p3": "value3" };   Now I want to loop through all p elements (p1, p2, p3...) And get their keys and values. How can I do that?  I can modify the JavaScript object if necessary. My ultimate goal is to loop through some key value pairs and if possible I want to avoid using eval. How To Show Node Comment Count in node.tpl? I have had the bright idea of changing my user permissions so as guests cannot see the comments on a node. I have no problems with Views around my site, as they can clearly see there are comments on nodes, and they will be more inclined to register. The problem seems to be when they arrive on my site directly to a node, they don't see any comment, and think "that's a bit crap; let's go."  Is there a way I could show the amount of comments below a node? How is Cycles different from Blender Internal? How does Cycles work and how is it different from Blender Internal?  Which is better? I was querying data from  using a LINQ query in LINQPAD and found that the data I got back is quite obsolete. I searched for Shekhar-Pro (me) by using a where clause on ID 399722 and the data returned was for 8 Jan 2011. Why was the data so old? Isn't the data updated in real time, or at least frequently? If not, where can I get realtime data? I'm trying to find the derivative of $\sin^{-1}(x)$. I know the steps that lead to $\frac{1}{\sqrt{1-x^2}}$, however I don't understand why the following reasoning leads to a wrong answer.  Because  $$\frac{d}{dx}f^{-1}(x) = \frac{1}{f'(f^{-1}(x))} $$  If we plug in for $f(x) = \sin(x)$, and because $\frac{d}{dx}\sin(x) = \cos(x)$ we get  $$\frac{d}{dx}\sin^{-1}(x) = \frac{1}{\cos(\sin^{-1}(x))} $$  Since $\sin(x) = \cos(x-\frac{\pi}{2})$, we can state that $\sin^{-1}(x) = \cos^{-1}(x-\frac{\pi}{2})$. (I suspect this is what is wrong)  Thus,  $$\frac{d}{dx}\sin^{-1}(x) = \frac{1}{\cos(\cos^{-1}(x-\frac{\pi}{2}))}$$  Then, by the definition of inverse function, we have  $$\frac{d}{dx}\sin^{-1}(x) = \frac{1}{x - \frac{\pi}{2}}$$ Masking NetCDF time series data from shapefile using Python I have a 3-D time-series precipitation data (187 x 1800 x 3600), stored in a NetCDF file. I need to obtain the precipitation data for a shapefile. import matplotlib.pyplot as plt from netCDF4 import Dataset, num2date,  from matplotlib.pyplot import figure from datetime import datetime, date, timedelta import numpy as np import xarray as xr import pandas as pd import geopandas as gpd       MSWEP_monthly = 'D:\G3P\DATA\Models\MSWEP\MSWEP_monthly.nc4'  MSWEP_monthly = Dataset(MSWEP_monthly, 'r') Pre_MSWEP = MSWEP_monthly.variables['precipitation'][:]   MSWEP_monthly2 = xr.open_dataarray('D:\G3P\DATA\Models\MSWEP\MSWEP_monthly.nc4')  Lon_MSWEP = MSWEP_monthly2.lon Lat_MSWEP = MSWEP_monthly2.lat  Africa_Shape = gpd.read_file('D:\G3P\DATA\Shapefile\Africa_SHP\Africa.shp')    from osgeo import gdal,osr,ogr  def makeMask(lon,lat,res):     source_ds = ogr.Open(shapefile)     source_layer = source_ds.GetLayer()       # Create high res raster in memory     mem_ds = gdal.GetDriverByName('MEM').Create('', lon.size, lat.size, gdal.GDT_Byte)     mem_ds.SetGeoTransform((lon.min(), res, 0, lat.max(), 0, -res))     band = mem_ds.GetRasterBand(1)       # Rasterize shapefile to grid     gdal.RasterizeLayer(mem_ds, [1], source_layer, burn_values=[1])       # Get rasterized shapefile as numpy array     array = band.ReadAsArray()        mem_ds = None     band = None     return array  shapefile = 'D:\G3P\DATA\Shapefile\Africa_SHP\Africa.shp' source_ds = ogr.Open(shapefile)  # calculate the cellsize cellsize = Lon_MSWEP[:][1] - Lon_MSWEP[:][0]   # create the mask mask = makeMask(Lon_MSWEP,Lat_MSWEP,cellsize)  Now if I implement the following code, the precipitation data for the first day (from the time-series) can be obtained with shape of 1800x3600: precip = np.ma.masked_where(mask==0,Pre_MSWEP[0,:,:])  I tried to use a for loop to mask the precipitation data for the entire time series (time, lon, lat) over the area of interest. however, the below code gives me a 2-D data, probably for the last day. Why is that? for i in range(len(Pre_MSWEP)):     precip = np.ma.masked_where(mask==0,Pre_MSWEP[i,:,:]) How to add current date to cell if the rest of the cells (or some cells) in that row are edited, but only the first time? How to modify the space between the numbers and text of sectioning titles in the table of contents? Can I add extension methods to an existing static class? I'm a fan of extension methods in C#, but haven't had any success adding an extension method to a static class, such as Console.  For example, if I want to add an extension to Console, called 'WriteBlueLine', so that I can go:  Console.WriteBlueLine("This text is blue");   I tried this by adding a local, public static method, with Console as a 'this' parameter... but no dice!      public static class Helpers {     public static void WriteBlueLine(this Console c, string text)     {         Console.ForegroundColor = ConsoleColor.Blue;         Console.WriteLine(text);         Console.ResetColor();     } }   This didn't add a 'WriteBlueLine' method to Console... am I doing it wrong? Or asking for the impossible? Add scratches to a material in Cycles? How do you find the directory of a command? Why is using a wild card with a Java import statement bad? It is much more convenient and cleaner to use a single statement like  import java.awt.*;   than to import a bunch of individual classes  import java.awt.Panel; import java.awt.Graphics; import java.awt.Canvas; ...   What is wrong with using a wildcard in the import statement? Blender worked fine before I installed a GPU to my PC. Is it the GPU? How can I fix this? I already reinstalled to the latest version. When I try to move a cube, the orange outline only moves but not the cube and I cant click it. Why is usable RAM less than total RAM? My girlfriend bought a laptop last week. It's a core 2 duo with 4 GB  We installed vista 64bit, and one of the first things we did was right click on "My computer" to see gthe properties. Immediately we noticed something strange about her RAM, the line said: Installed memory (RAM): 4,00 GB (3,68 GB usable)  I told her not to worry, thinking it must be something about the laptop hardware (considering her vista installation came from the same DVD as mine, and I never noticed anything like that on my 4 GB desktop). One hour ago, it got worse. We looked at Properties again, and it now says: Installed memory (RAM): 4,00 GB (2,98 GB usable)  What does that mean? Are those 1,02 GB missing or being used by the system?  EDIT: There is a possibility that the sytem information is wrong. I just noticed that it reports an intel T6500 processor, when it's actually a T6400.  How can I find out how much RAM is really available to the system?  EDIT2: Checking the resource monitors, it says 1003 MB are reserved for the hardware. Is that good or bad? Thanks How can you smooth the edge between two materials? Sometimes I found that writing just "J. Doe" may lead, in a justified line with few words, to a big space between the initial and the surname. Using J.\,Doe looks ok but I would like to know if there is a general rule for spacing between initials and surnames. I have recently started reading and watching Naruto. I was wondering in what aspect does the clones made by different techniques differ? They all have the same potential and capabilities.