If I add mods to a server, do the clients have to download them too? I set up a Forge server, which works just fine.  I know that you need the client to be able to play in it, and I know that my friends needs it too.  But if I add mods to the server, do my friends have to download them as well? If so, where do they put them?
Can my friend and I play minecraft together with different mods? I'm wondering if I could play Minecraft with my friend. A modded Minecraft, only myself with mods and him without mods.  Is it possible?
A friend of mine asked me to calculate the value of a perticular determinant, but after spending quite some time on it I'm unable to find a solution to it. The given determinant is:  $$         \begin{vmatrix}         0 &amp; 1 &amp; \cdots &amp;n-2&amp;n-1 \\         n-1 &amp; 0 &amp; \cdots &amp;n-3&amp;n-2 \\         \vdots &amp; \vdots &amp; \ddots &amp; \vdots &amp;\vdots\\         1 &amp; 2 &amp; \cdots &amp; n-1 &amp;0 \\         \end{vmatrix} $$  Also my friend is supposed to solve this determinant by more or less elementary methods, like elementary row operations, transpose... and no eigenvalues, nor adjoints.    First of all it seems like the value of the determinant is:  $$         \frac{1}{2n}\begin{vmatrix}         0 &amp; n &amp; \cdots &amp;n&amp;n \\         n &amp; 0 &amp; \cdots &amp;n&amp;n \\         \vdots &amp; \vdots &amp; \ddots &amp; \vdots &amp;\vdots\\         n &amp; n &amp; \cdots &amp; n &amp;0 \\         \end{vmatrix} $$  Anyway I tried adding all the rows to the last one and by taking $\frac{n(n-1)}{2}$ in front to have a row of 1s, but it didn't helped me much.  Then I tried to use the fact that:  $$         \begin{vmatrix}         A &amp; C \\         0 &amp; B \\         \end{vmatrix} = \det(A) \cdot \det(B) $$, where $A,B$ are square matrices. By subtracting the $(\frac{n}{2} + i)$-th column from the $i$-th ($i=0,1,2...$) and then adding the $i$-th row to the $(\frac{n}{2} + i)$-th row, one can obtain the wanted form, but again nothing more. Also this method pretty much fails when $n$ is odd.  My best attepmt was to notice that $A_{ij} + A_{ji} = n$ and using $\det(A^{T}) = \det(A)$, but unfortunatelly  $$\begin{vmatrix}         0 &amp; n &amp; \cdots &amp;n&amp;n \\         n &amp; 0 &amp; \cdots &amp;n&amp;n \\         \vdots &amp; \vdots &amp; \ddots &amp; \vdots &amp;\vdots\\         n &amp; n &amp; \cdots &amp; n &amp;0 \\         \end{vmatrix} \not = \begin{vmatrix}         0 &amp; 1 &amp; \cdots &amp;n-2&amp;n-1 \\         n-1 &amp; 0 &amp; \cdots &amp;n-3&amp;n-2 \\         \vdots &amp; \vdots &amp; \ddots &amp; \vdots &amp;\vdots\\         1 &amp; 2 &amp; \cdots &amp; n-1 &amp;0 \\         \end{vmatrix} + \left( \begin{vmatrix}         0 &amp; 1 &amp; \cdots &amp;n-2&amp;n-1 \\         n-1 &amp; 0 &amp; \cdots &amp;n-3&amp;n-2 \\         \vdots &amp; \vdots &amp; \ddots &amp; \vdots &amp;\vdots\\         1 &amp; 2 &amp; \cdots &amp; n-1 &amp;0 \\         \end{vmatrix}\right)^T$$ I tried to decompose the LHS by using the $n-$linearity of the determinants, by then one gets $2^n$ determinants on the RHS similar to the first one, but things are messy. Integrating $\frac{1}{\sqrt{ax^2+bx+c}}$ for $a<0$ I'm trying to integrate the function $\frac{1}{\sqrt{ax^2+bx+c}}$ for $a&lt;0$ and $b,c&gt;0$.   From a list of integrals of irrational functions from Wikipedia I know the result should contain arcsin or arcos, but I don't understand how to get there.  I've tried Euler's substitution and trigonometric substitution but I always stumble over the fact that $a$ is negative.  Can please someone help me? Nautilus not generating thumbnails in 13.10 Determine all $f: \mathbb{R} \rightarrow \mathbb{R}$ such that, for all $x, y \in \mathbb{R}$, $$f((x + 1) f(y)) = y (f(x) + 1).$$    Source: Vuong Lam Huy, on a Facebook group. euler's theorem of homogeneuos function suppose that $f$ is a mapping from $\mathbb R^n \to \mathbb R$.  a positively homogeneous of degree $n$ and suppose $f_1, f_2, .... f_N$ are continuous for $a \neq 0$. then   $$\sum_{i=1}^n a_if_i(a)= n*f(a)$$   now, they asked me to prove this. (Which is a total no no to me)  I write my proof as;  $f$ is a mapping from $\mathbb R^n \to \mathbb R$  A homogeneous function of degree $n$ if for all $a \in \mathbb R^n$ and all $L&gt;0$, $f(La)=L^n\,f(a)$. let $a \in \mathbb R^n$ and define function $g$ be a mapping from $[0,\infty) \to \mathbb R$. so I write $g(L) = f(La)-L^nf(a)$. then $L≥0$ let $L=0$ then, $g(L)=0$ and therefore $g'(x) =0$?  then i don't know what's goes next. can anyone help me about this? Simple examples of uncorrelated but not independent $X$ and $Y$ Any hard-working student is a counterexample to "all students are lazy".  What are some simple counterexamples to "if random variables $X$ and $Y$ are uncorrelated then they are independent"? What's the best way to find the inverse of datetime.isocalendar()? Are Stack Overflow people *still* nice? The title is a reference to . We had the good fortune, to start this experiment with a really positive culture and have managed to hang onto it through vast growth and several fairly bitter internal arguments. But that does not guarantee we'll keep it forever. Lately I've had a unscientific feeling that Stack Overflow has been a bit rougher on newbie mistakes. The actual composition of this question was triggered by the comment thread on  (now with pending delete votes, so it is in danger of being 10k only). The  currently has 3 reputation points and has been a member for all of two days. The question bear the obvious (to me, at least) hallmarks of being written by a non-native English speaker with a shaky grasp of the tongue, and it is a rather simplistic question that could be answered fairly easily by Google. Question body:  Sir, I am mc student, I have knowledge in c,c++,J2EE. I want to ask you should I command in Linux with J2EE. Is it worth?  Instead of trying to improve the question, to discern exactly what the OP meant, or explaining how the question should be improved we get this comment thread instead (without wanting to call out these posters in particular, this was just the thread that got be off my duff):  2 Can you elaborate? – Dave McClelland 21 hours ago 1 Absolutely yes! If it can run on your Blu-Ray player, imagine the possibilities it can do on Linux. – The Elite Gentleman 21 hours ago 1 Basically, it's as worth as running Java on any other platform. – Alexander Gessler 21 hours ago 1 @The Elite Gentleman, You can try run it on your sim-card too) – Stas Kurilin 21 hours ago 1 @STas Kurilin, really? What heapspace size must I give? sarcastic laugh – The Elite Gentleman 21 hours ago 1 @The Elite Gentleman I don't know. But there are some) See for details oracle.com/technetwork/java/javacard/overview/… – Stas Kurilin 21 hours ago @The Elite Gentleman, you're absolutely right given a full fledged desktop machine with Linux, Java would run so fast his program could go back in time and rescue whales from extinction. – Quaternion 21 hours ago @Stas Kurlin, if you have a program that runs on a sim-card isn't it hard to get output? I've always found processorless environments problematic. – Quaternion 21 hours ago @Quaternion - It was a joke) I've newer wrote such programs. But, I think there should be some processor. – Stas Kurilin 20 hours ago @Stas Kurlin, I was joking too, but I have to apologize after reading that page you liked to. You can run Java off a smart card... that's crazy and cool. +1 on account of good learning for the day. – Quaternion 20 hours ago @Quaternion Thanks. I heard about this stuff several weeks ago. Java at a sim card is a really cool argument) – Stas Kurilin 20 hours ago @Quaternion, lol, without having to worry about Segmentation Faults along the way. – The Elite Gentleman 19 hours ago  I've been leaving comments on threads like this from time to time, asking them to be a little more forgiving, but that is a drop in the bucket. Nothing flag-worthy here, but not a &quot;nice&quot; as things once were. There is very little effort to understand what the question may really be, nor why to explain why the question has been closed, what other resources exist, or how that decision could be reversed. With a brand new user who probably has a hard time with English. Ouch. Do we need an official re-iteration of &quot;Be nice.&quot;? Is there something else we can do to encourage our big city to keep the small-town feel we grew up with? There was a great SF story I read some time ago (probably 25+ years ago) where there was a well known treasure trove, guarded by a killer robot that would ask all comers a series of difficult questions from all areas (math, physics, literature, history, etc.)  But everyone eventually failed and died... until the last person managed to make it past the robot:     By just answering gibberish to the robot.  Unfortunately, after collecting a ton of treasure, the robot casually asked him why he wanted it, he answered in a sensible way (something like "because it's valuable"), and the robot killed him, because he failed the final test.   Any ideas who wrote this?  What it was titled? Server 2008 Net Send or Msg? I have a Windows 2008 server running as a domain controller. The details are as follows:  Domain: corp Server Name: oxygen   The workstations are all running Windows XP SP3 and have fixed IP addresses.  I am trying to use the net send functionality to be able to send simple messages to either individual machines/users and also to all machines. This is so I can send a message to a user to alert them about something, or likewise alert everyone of something such as the server being rebooted.  Is this possible using Windows Server 2008? If so, what would the command be? Inequality $\frac{1}{n+1}+\frac{1}{n+2}+...+\frac{1}{3n+1} \ge 1$ Can a continuous real function take each value exactly 3 times? how to create a roster sheet in sharepoint 2010 This is about training management, when an employee requests for training, it goes to approval workflow and once approved, it is like the employee is enrolled.  Once it is approved I want a roster sheet to be created for that course for all the employees registered and who got approved.   The report I need to generate has to be of the enrolled users of one course and one particular session  If I give copy listitem as approved then different courses would come together in the list  The format for the report How to programmatically remove a field from a node? I have been playing on hardmode for a while and have beaten the three  a couple of times. But I have yet to find a . It's getting really frustrating.  Does anyone have any methods to finding a Plantera Bulb? This happened when I updated MikTeX to the latest version (as of time of this post) and tried the  regarding adding pdf pages to RevTeX documents. Running the code below produced text rotated by 90 degrees while commenting out the line which includes the pdfpages packages produces regularly positioned text. Note that the page number was not rotated. Can anyone reproduce this and what is the cause of this?  \documentclass[english]{revtex4-1} \usepackage{pdfpages}  % Including PDF  \makeatother \usepackage{babel} \begin{document}  Lorem ipsum dolor sit amet...  \end{document} Unable to set placeholder on password input Show that if $\sqrt{a}+\sqrt{b}\neq 0$, then $\mathbb{Q}(\sqrt{a}+\sqrt{b}) = \mathbb{Q}(\sqrt{a},\sqrt{b}), \forall a,b\in\mathbb{Q}$ Show that if $\sqrt{a}+\sqrt{b}\neq 0$, then   $\mathbb{Q}(\sqrt{a}+\sqrt{b}) = \mathbb{Q}(\sqrt{a},\sqrt{b}),  \forall a,b\in\mathbb{Q}$   It has something to do with $\sqrt{a} = -\sqrt{b}\implies a^2 = b^2$  The inclusion $\mathbb{Q}(\sqrt{a}+\sqrt{b})\subseteq \mathbb{Q}(\sqrt{a},\sqrt{b})$ is obvious  Now take $x\in \mathbb{Q}(\sqrt{a},\sqrt{b})$, that is: $x = c + d\sqrt{a} + e\sqrt{b} + f\sqrt{ab}$. I need to show that this is in $\mathbb{Q}(\sqrt{a}+\sqrt{b})$, that is, $x = g + h\sqrt{a} + i\sqrt{b}$, but I can't get that $\sqrt{ab}$ removed Formula to this pattern? $1$, $11$, $21$, $1211$, $111221$, $\ldots$ I have this pattern:  1 11 21 1211 111221   I'm guessing it's a fibo pattern, been at it for hours now. Anyone know? The origin of my question arose from a problem: Let $q: X \to Y$ and $r: Y \to Z$ be covering maps, let $p= r \circ q$. Show that if $r^{-1}(z)$ is finite for each $z \in Z$, then $p$ is a covering map.  I am just wondering is there an easy counter example to show the necessary of "inverse image of every point is finite" condition?  I have already checked Hatcher's book (the wedged circle example) but I wonder is there a less complex and more obvious example?  I tried to construct a counter example by composition of a covering map from $R_+$ to $S^1$ with $R$ in the middle, but I failed due to I can't find a covering map from $R^+$ to $R$ which does the job.