I have the following table where I would want to delete the column $2 \neq \Box$ but had no luck as it keeps giving error when I compile it.  \documentclass{article} \setlength{\textwidth}{16cm} \setlength{\oddsidemargin}{0pt} \setlength{\evensidemargin}{0pt} \setlength{\parskip}{3mm} \setlength{\parindent}{0mm} \usepackage{amsmath} \usepackage{amsthm} \DeclareMathOperator{\lcm}{lcm} \DeclareMathOperator{\ord}{ord} \usepackage{tabularx,ragged2e,booktabs,caption} \usepackage[figuresleft]{rotating} \usepackage{rotating} \newcolumntype{C}{&gt;{\Centering\arraybackslash}X} \newcommand\swb{{\scriptstyle\Box}} % "small white box" \usepackage{amssymb,bm} \usepackage{upgreek} %use uptau greek letter  \begin{document} \begin{sidewaystable} \setlength\tabcolsep{6pt} % default value: 6pt \begin{tabularx}{\textwidth}{@{}*{14}{C}@{}}  \toprule  $\delta_\mu$ &amp; $2 \neq \swb$ &amp; \multicolumn{4}{c}{$5 \cdot 29 \neq \swb$} &amp; \multicolumn{4}{c}{$13 \cdot 1789 \neq \swb$} &amp; \multicolumn{4}{c}{$5333 \cdot 97324757 \neq \swb$}\\ \cmidrule(lr){3-6} \cmidrule(l){7-10} \cmidrule(l){11-14}     &amp;   &amp; $5=\swb$ &amp; $29\neq\swb$ &amp; $5\neq\swb$ &amp; $29=\swb$ &amp; $13=\swb$ &amp; $1789\neq\swb$ &amp; $13\neq\swb$ &amp; $1789=\swb$ &amp; $5333=\swb$ &amp; $97324757\neq\swb$ &amp; $5333\neq\swb$ &amp; $97324757=\swb$ \\ \midrule Primes that satisfy the \footnote{Refer Appendix A for the PARI code to find the complete list of $G_1, G_2, G_3, G_4, G_5, G_6$} condition $\delta_\mu \neq \swb$  &amp;  $q\equiv\pm3\pmod{8}$ &amp;  $q\equiv\pm1\pmod{5}$ &amp;  $q\equiv 2,3,8,10,\allowbreak11,12,14,\allowbreak15,17,18,\allowbreak 19,21,26, \allowbreak 27\pmod{29}$ &amp;  $q\equiv\pm2\pmod{5}$ &amp;  $q\equiv 1,4,5,6,\allowbreak7,9,13,\allowbreak 16,20,\allowbreak 22,23,\allowbreak 24,25,28\pmod{29}$ &amp;  $q\equiv 1,3,4,9,\allowbreak10,12\pmod{13}$ &amp;  $q \equiv$ $G_1$ \text{(mod} \allowbreak $1789$) &amp;  $q\equiv2,5,6,\allowbreak 7,8,11\pmod{13}$ &amp;  $q \equiv$ $G_2$ \text{(mod} \allowbreak $1789$) &amp;  $q \equiv$ $G_3$ \text{(mod} \allowbreak $5333$) &amp;  $q \equiv$ $G_4$ \text{(mod} \allowbreak $97324757$) &amp;  $q \equiv$ $G_5$ \text{(mod} \allowbreak $5333$) &amp;  $q \equiv$ $G_6$ \text{(mod} \allowbreak $97324757$) \\ \midrule  Period of $w_k$  &amp; $24$ &amp; $30$ &amp; $102$ &amp; $30$ &amp; $102$ &amp; $30$ &amp; $2670$ &amp; $30$ &amp; $2670$ &amp; $750$ &amp; $97306362$ &amp; $750$ &amp; $97306362$ \\ \midrule  $\ord(\widetilde{P})$  &amp;  &amp; $5$ &amp; $17$ &amp; $5$ &amp; $17$ &amp; $10$ &amp; $890$ &amp; $10$ &amp; $890$ &amp; $125$ &amp; $48653181$ &amp; $125$ &amp; $48653181$ \\ \midrule $k$ which satisfies $w_k$ \footnote{Refer Appendix B for the lists of sets $A_{2}$, $A_5$, $A_{29^*}$, $A_{5}^*$, $A_{29}$, $A_{13}$, $A_{1789}^*$, $A_{13}^*$, $A_{1789}$, $A_{5333}$, $A_{97324757}^*$, $A_{5333}^*$, $A_{97324757}$} &amp;  $A_{2}$ : 10 elements &amp; $A_5$ : 21 elements &amp; $A_{29^*}$ : 37 elements &amp; $A_{5}^*$ : 9 elements &amp; $A_{29}$ : 65 elements &amp; $A_{13}$ : 22 elements &amp; $A_{1789}^*$ : 1304 elements &amp; $A_{13}^*$ : 8 elements &amp; $A_{1789}$ : 1362 elements &amp; $A_{5333}$ : 421 elements &amp; $A_{97324757}^*$ : 48584207 elements &amp; $A_{5333}^*$ : 329 elements &amp; $A_{97324757}$ : 48722155 elements\\ \bottomrule \end{tabularx}\captionof{table}{Summary of the congruence conditions for $\mu \in Y = \{-4, -3, -2, -1, 0, 3\}$} \label{summary}  \end{sidewaystable} \end{document}
I have a set of 10 tables and each has an extra column that I don't want. Specifically, these tables are descriptions of database tables exported by phpMyAdmin, and they all have a "MIME" column that I would like to remove. Is there a way to do this other than using string manipulation / find and replace?   I have tried setting the column to p{0in}, but the column title still remains.
Bad substitution: no closing "`" in a heredoc / EOF I'd like to print a man style usage message to describe a shell function like this output man find:  NAME        find - search for files in a directory hierarchy  SYNOPSIS        find [-H] [-L] [-P] [-D debugopts] [-Olevel] [starting-point...] [expression]  DESCRIPTION        This  manual  page  documents the GNU version of find.  GNU find searches the directory tree rooted at each        given starting-point by evaluating the given expression from left to  right,  according  to  the  rules  of        precedence  (see section OPERATORS), until the outcome is known (the left hand side is false for and opera‐        tions, true for or), at which point find moves on to the next file name.  If no  starting-point  is  speci‐        fied, `.' is assumed.  OPTIONS   I am facing an error message on the ` character. Following simple script shows the error:  ~$ cat &lt;&lt;EOF `.' EOF  bash: bad substitution: no closing "`" in `.'   I though heredoc was a cool way to echo strings by pasting them without having to escape its content such a quotes, etc... I assume I was wrong :/  Can someone explain this behavior please? Can heredoc accept ` character?  Edit 2: I accepted the answer of quoted here-document  &lt;&lt;'END_HELP', but I finally won't use it for this kind of complete manual output as  does   Edit 1: (For future reads) the limit with using quoted here-document is that is prevents to use tput in the here-document. To do so, I did the following:   unquoted here-document, for tput commands to be executed prevent the "bad substitution" error by escaping the backtick instead use tput within the  here-document   Example:  normal=$( tput sgr0 ) ; bold=$(tput bold) ;  cat &lt;&lt;END_HELP # here-document not quoted ${bold}NAME${normal}        find - search for files in a directory hierarchy  ${bold}SYNOPSIS${normal}        find [-H] [-L] [-P] [-D debugopts] [-Olevel] [starting-point...] [expression]  ${bold}DESCRIPTION${normal}        This  manual  page  documents the GNU version of find.  GNU find searches the directory tree rooted at each        given starting-point by evaluating the given expression from left to  right,  according  to  the  rules  of        precedence  (see section OPERATORS), until the outcome is known (the left hand side is false for and opera‐        tions, true for or), at which point find moves on to the next file name.  If no  starting-point  is  speci‐        fied, \`.' is assumed. END_HELP  unset normal ; unset bold ;   Here, note the escaped backtick that was source of error:  \`.' E:Error, pkgProblemResolver::Resolve generated breaks, this may be caused by held packages I am not sure what caused this error, but here is what the whole error says, and also this is sitting as a notification, and preventing me from updating any software using Update Manager - Please provide some assistance or tell me how to figure out what to do to fix it.  Could not calculate the upgrade  An unresolvable problem occurred while calculating the upgrade.  Please report this bug against the 'update-manager' package and include the following error message: 'E:Error, pkgProblemResolver::Resolve generated breaks, this may be caused by held packages.' Is FFmpeg missing from the official repositories in 14.04? What is the icon next to Spotlight in menu bar, and how to remove it? What is this icon   in OS X menu bar and how do you remove it? What can you say about the range space and null space Let $V$ be a vector space over a field $F$ and $T$ a linear operator on $V$. If $T^2$$=$ $0$, what can you say about the relation of the range of $T$ to the null space of $T$? Looking for an intuitive explanation why the row rank is equal to the column rank for a matrix How can I display "recent folders" in the sidebar of "Save as" dialogue? I was using 14.04 and upgraded to 16.04 yesterday.   In 14.04 I had recent folders on top of the sidebar of the Save as dialogue when I saved something from the net (Firefox if that helps). But that feature disappeared in 16.04 and I really want to have it back.   Here is a picture of what I'm trying to explain:  (the save as dialogue in 16.04 without the recent folders on top) the verb in plural with one company Removal of statistically significant intercept term increases $R^2$ in linear model In a simple linear model with a single explanatory variable,  $\alpha_i = \beta_0 + \beta_1 \delta_i + \epsilon_i$  I find that removing the intercept term improves the fit greatly (value of $R^2$ goes from 0.3 to 0.9). However, the intercept term appears to be statistically significant.  With intercept:   Call: lm(formula = alpha ~ delta, data = cf)  Residuals:      Min       1Q   Median       3Q      Max  -0.72138 -0.15619 -0.03744  0.14189  0.70305   Coefficients:             Estimate Std. Error t value Pr(&gt;|t|)     (Intercept)  0.48408    0.05397    8.97   &lt;2e-16 *** delta        0.46112    0.04595   10.04   &lt;2e-16 *** --- Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1   Residual standard error: 0.2435 on 218 degrees of freedom Multiple R-squared: 0.316,    Adjusted R-squared: 0.3129  F-statistic: 100.7 on 1 and 218 DF,  p-value: &lt; 2.2e-16    Without intercept:   Call: lm(formula = alpha ~ 0 + delta, data = cf)  Residuals:      Min       1Q   Median       3Q      Max  -0.92474 -0.15021  0.05114  0.21078  0.85480   Coefficients:       Estimate Std. Error t value Pr(&gt;|t|)     delta  0.85374    0.01632   52.33   &lt;2e-16 *** --- Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1   Residual standard error: 0.2842 on 219 degrees of freedom Multiple R-squared: 0.9259,   Adjusted R-squared: 0.9256  F-statistic:  2738 on 1 and 219 DF,  p-value: &lt; 2.2e-16    How would you interpret these results? 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I assume that it should be possible by customising \DeclareNameFormat, but I don’t know how.  Minimal example:  \documentclass{scrartcl} \usepackage[T1]{fontenc} \usepackage[latin1]{inputenc} \usepackage[english]{babel} \usepackage{csquotes} \usepackage{filecontents} \begin{filecontents}{\jobname.bib} @BOOK{book1,   author = {Buchautor, Hans-Wilhelm},   title = {Irgendein Buch},   location = {Buch am Wald},   date = {2000} } @BOOK{book2,   author = {Buchautor, Hans-Wilhelm},   title = {Ein anderes Buch},   location = {Berlin},   date = {2001} } @BOOK{book3,   author = {Buchautor, Hans-Wilhelm and Zweitautor, Zoran},   title = {Noch ein Buch},   location = {London and New York},   date = {2010} } \end{filecontents}  \usepackage[ style=authortitle, backend=bibtex8 ]{biblatex} \bibliography{\jobname}  \renewcommand*{\bibnamedash}{%   \bibstring[\mkbibbold]{idem\thefield{gender}}}  \begin{document} \nocite{*}  \printbibliography \end{document}   Edit 15/02/2011 17:14   I should have added that there was a feature request for biber which pointed back to biblatex. See .  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