I've got an Acer Aspire E5-773G notebook with those graphics-related specs:  Card-1: Intel Sky Lake Integrated Graphics Card-2: NVIDIA GM108M [GeForce 940M] Display Server: X.Org 1.18.3 driver: nvidia Resolution: 1920x1080@60.03hz GLX Renderer: GeForce 940M/PCIe/SSE2 GLX Version: 4.5.0 NVIDIA 367.35   I would like a keyboard shortcut that rotates the screen (internal display) ±90°.  In System Settings → Screen Display, the Rotation setting only has the option Normal though.  xrandr --rotate fails rotating the screen:  bytecommander@BC-AlkaliMetal:~$ xrandr --output eDP-1 --rotate right xrandr: output eDP-1 cannot use rotation "right" reflection "none"  bytecommander@BC-AlkaliMetal:~$ xrandr --output eDP-1 --rotate left xrandr: output eDP-1 cannot use rotation "left" reflection "none"   Here's the output of plain xrandr as well:  $ xrandr Screen 0: minimum 8 x 8, current 1920 x 1080, maximum 16384 x 16384 eDP-1 connected primary 1920x1080+0+0 381mm x 214mm    1920x1080     60.03*+  59.93      1680x1050     59.95    59.88      1600x1024     60.17      1400x1050     59.98      1280x1024     60.02      1440x900      59.89      1280x960      60.00      1360x768      59.80    59.96      1152x864      60.00      1024x768      60.04    60.00      960x720       60.00      928x696       60.05      896x672       60.01      960x600       60.00      960x540       59.99      800x600       60.00    60.32    56.25      840x525       60.01    59.88      800x512       60.17      700x525       59.98      640x512       60.02      720x450       59.89      640x480       60.00    59.94      680x384       59.80    59.96      576x432       60.06      512x384       60.00      400x300       60.32    56.34      320x240       60.05   HDMI-1 disconnected DP-1 disconnected HDMI-2 disconnected
I am trying to rotate a dual monitor which is attached to the VGA output of my laptop. My system is Ubuntu 15.10.  However, here is the outcome I get when I use xrandr:  xrandr --output VGA-1-0 --rotate right xrandr: output VGA-1-0 cannot use rotation "right" reflection "none"   I have seen other posts on this subject, which all recommend editing xorg.conf. I have tried that, too. Here's my current xorg.conf file:  Section "ServerLayout" Identifier "layout" Screen 0 "nvidia" Inactive "intel" EndSection  Section "Device" Identifier "intel" Driver "modesetting" BusID "PCI:0@0:2:0" Option "AccelMethod" "None" Option "RandRRotation" "True" EndSection  Section "Screen" Identifier "intel" Device "intel" EndSection  Section "Device" Identifier "nvidia" Driver "nvidia" BusID "PCI:1@0:0:0" Option "ConstrainCursor" "off" Option "RandRRotation" "True" EndSection  Section "Screen" Identifier "nvidia" Device "nvidia" Option "AllowEmptyInitialConfiguration" "on" Option "IgnoreDisplayDevices" "CRT" Option "RandRRotation" "True" EndSection   Still, I keep getting the same error when trying to use xrandr to rotate that screen.   Is there another way of doing so?
I would like to determine the operating system of the host that my Java program is running programmatically (for example: I would like to be able to load different properties based on whether I am on a Windows or Unix platform). What is the safest way to do this with 100% reliability? What happens to Red Skull after Thanos gets the Soul Stone? Is there any way to automatically unwrap UV map proportionally to object or "world" size?  For example:  I've made two cubes, one is two times bigger than other (scale is applied). Then I unwrapped texture with Smart UV project which will try to span all faces on whole texture space(0 to 1) so bricks on left cube will be bigger than bricks on right cube.   But what I want to achieve is this:     In broader context:  When I import model from Archicad (in form of OBJ) all objects have UV's in some scale (so all bricks have the same size on every imported object). And when I want to create custom object in scene I have to manually scale UV's to adjust bricks size for every new object (instead of scaling to one constant parameter). This is a question about American English usage of the word "already". As a UK resident I don't completely understand when I hear Americans give commands like "Stop it already!" In the UK the word already is not normally used in the imperative mood and the sentence I've just quoted would leave an English person thinking "If you're saying I've already stopped it why are you asking me to stop it again?" How do I prove that in every commuting family there is a common eigenvector? The proof given by my textbook is highly non-satisfying. The author adopted some magic-like "reductio ad absurdum" and the proof (although is correct) didn't reveal the nature of this problem. I made my own effort into it and tried a different approach. Yet I can't finish it.  Let $\mathscr{F}$ be a commuting family in $M_n(\mathbb{C}^n)$, and $A\in\mathscr{F}$, then $A$ has $n$ eigenvalues. We pick one, say $\lambda$. Let $x$ be one of its eigenvector.  We can easily prove that, if $A$ has no other eigenvector with eigenvalue $\lambda$ that linearly independent with $x$, which means that $\{cx|c\in\mathbb{C}\}$ are the only vectors satisfying $Ax=\lambda x$, then $x$ is a common eigenvector. Because $\forall B\in\mathscr{F}$ and $\forall y\in \{cx|c\in\mathbb{C}\}$, $$A(Bx)=ABx=BAx=B(Ax)=B(\lambda x)=\lambda (Bx)$$, so that $Bx$ has to be in $\{cx|c\in\mathbb{C}\}$, that is, $Bx=c_0x$ for some $c_0\in\mathbb{C}$, which means $x$ is a eigenvector of $B$ too.  But what if there are vectors satisfying $Ax=\lambda x$ that's not in  $\{cx|c\in\mathbb{C}\}$? Well, then we should have a set of linearly independent eigenvectors $\{x_1,x_2,...,x_k\}$, that $\{c_1x_1+c_2x_2+...+c_kx_k|c_i\in\mathbb{C}\}$ are the only vectors satisfying $Ax=\lambda x$.  Now, I have a reasonable hypothesis that there exists some $x=c_1x_1+c_2x_2+...+c_kx_k$, that can be proven to be a common eigenvector of $\mathscr{F}$. I've tried some approaches to prove it but all failed.  Do you guys believe it's true? And if it is true then how do I prove it? $C^2 $embedded in holder space? I have a question on Holder space.Is the space $C^2(\mathbb{R}^n)$ embedded in $C^{1,\alpha}(\mathbb{R}^n)$? I think in the bounded domain case, this should be true. But what if in the case where the domain is not bounded? Thanks for any hint! Find path of standard executable for a given file type in Windows Suppose I am running cmd and I open an application by typing for example start document.pdf  I want to get the exact path of the executable that opens .pdf files  Of course I could search the entire system for the executable but I suppose it would be faster this way because the path is already stored somewhere  I don't know if it makes a difference but I am using Windows 7 What is `^M` and how do I get rid of it? When I open the file in Vim, I see strange ^M characters.  Unfortunately, the world's favorite search engine does not do well with special characters in queries, so I'm asking here:   What is this ^M character? How could it have got there? How do I get rid of it? My /boot partition hit 100% and now I can't upgrade. Can't remove old kernels to make room On any SE post one can use the backtick symbol ("`") in order to mark some text as being a piece of code, or computer output. For example: void main().  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Is this just a matter of style and so should go with my instincts, or should I aim for what is 'correct?' Boot drops to a (initramfs) prompts/busybox Inductive proof that there are infinitely many pairs of consecutive powerful integers? How to deal with very long lines that do not contain spaces? Continuous function preserving rational difference. Find all the continuous functions $f:\mathbb{R}\rightarrow \mathbb{R}$ such that if $x-y\in \mathbb{Q}$ then $f(x)-f(y)\in \mathbb{Q}$.   Can somebody give me some hint to solve this problem. I think that the functions are $f(x)=mx+b$ where $m\in\mathbb{Q}$.  Thanks! Proof on Catalan numbers What is the difference between a linear and a circular polarizer? When I bought my polarizer, a friend told me that I should get a circular one, because the linear ones can mess with the autofocus. Is this true? What should each be used for? Is it legal to run windows on a mac? I understand that it is Illegal to run OSx on a windows machine or PC for that matter, but is it illegal to do the reverse? Why or why not? Let's say we are talking about the indigenous pukapuka who live in Pluto.  What is correct: "the pukapuka people" or "the pukapuka peoples"?  I've read somewhere the usage of "peoples" in this context, and it has surprised me. Word for romantic partner you are living with but not married to