I earned the  for , which has since been removed.    Searching MSO, I found one  that indicates that I should be able to find out why the question was deleted, or at least whether it was a community or moderator decision to delete.  However, the links on the deleted question's page only provide a link to a FAQ of possible reasons.  As the OP, how can I find out definitively why my question was removed (aside from finding the closing moderator)?
What circumstances can cause a question or answer to be deleted, and what does that actually mean?    How can a post be deleted? When can't I delete my own post? Can I still see my post even after it's deleted? Can I see a list of my deleted posts? How can I undelete one of my posts? What does deletion mean for a post? How do votes to delete work? What are the criteria for deletion? What else should I know about deleted posts? If I flag my question with a request to delete it, what will happen?       For more information, see the articles about  and  in the .
The title word filter is one of the worst ideas ever implemented on SO 3D graphics render as though no illumination Is is possible that a software issue could be causing spotty USB-C connections on 2017 MacBook Pro? I have a 2017 MacBook Pro. It has 2 USB-C ports on the left side and I use an Aukey hub to provide more ports (4 USB, 1 HDMI, 1 USB-C) and always to connect two monitors.   I connect one monitor through the hub with the HDMI port and another directly to the MBP with a USB-C adapter. Sometimes when I connect the hub to the Mac and the 2nd monitor to the Mac, it works as it should with no problem...but more than half the time I have to connect, disconnect, jiggle, jangle, switch ports, reconnect HDMI, etc. and hopefully they will both work. OFTEN, I can only get one monitor to fire up.  Is there any kind of software fix or reset that might solve this issue? Any other thoughts welcome. Thanks. What should my Objective-C singleton look like? Got any tips or tricks for Terminal in Mac OS X? One tip or trick per answer.  My favorite is   open .   Opens the folder you're currently browsing in Finder. You can also pass URLs, images, documents or else to open.  If you specify a program name with -a you can pass the URL, image, document or folder to that program instead, e.g. open -a Preview image.png, overriding the default program set for the filetype.  Please don't post duplicates. Search in the question like this: inquestion:this ls -l  Mac OS X specific answers only. Where can I find the teleport? I need to get the chocolate bars in the hole, but I can't get out of there. Where can I find the pogo stick or teleport? Proof of conservation of energy? How is it proved to be always true? It's a fundamental principle in Physics based on all of our currents observations of multiple systems in the universe. Is it always true to all systems? Because we haven't tested or observed them all. Would it be possible to discover/create a system that could lead to a different result? How are we 100% sure that energy is always conserved? Finally, why did we conclude it's always conserved? What if a system keeps doing work over and over and over with time? How to show that $2730\mid n^{13}-n\;\;\forall n\in\mathbb{N}$ Show that $2730\mid n^{13}-n,\;\;\forall n\in\mathbb{N}$   I tried, $2730=13\cdot5\cdot7\cdot3\cdot2$  We have $13\mid n^{13}-n$, by Fermat's Little Theorem.  We have $2\mid n^{13}-n$, by if $n$ even then $n^{13}-n$ too is even; if $n$ is odd $n^{13}-n$ is odd.  And the numbers $5$ and $7$, how to proceed? Why doesn't \makeatletter work inside \newcommand? After hours of banging my brain against my skull, I narrowed down an issue I'm having to the fact that \makeatletter doesn't work inside \newcommand. Commands that I call after \makeatletter are registered as undefined, as if \makeatletter didn't do anything.  Why is this the case?  In the example below, I define two commands. Calling one of them from the document body causes the undefined error, while the other doesn't.  \documentclass[11pt]{book} \usepackage{kvsetkeys}  \newcommand{\commandThatFails}{     \makeatletter \comma@parse{}{} \makeatother }  \makeatletter     \newcommand{\commandThatWorks}{         \comma@parse{}{}     } \makeatother  \begin{document}  Hi there.  \commandThatFails \commandThatWorks  \end{document} How unique is the php session id List has no row exception: Queryerror I have below line placed in controller that fires list has no row exception. I just need to show a custom message instead when the query returns no value.   Apex code:  Id CI=[select Compliance_Incident_abv__c from Compliance_Incident_Transaction_abv__c where Name=:selectedCIT].Compliance_Incident_abv__c ;  //**This line throws error**     system.debug('CI@@'+CI);         if(cond != '')             cond += ' and';           else             cond += ' where ';                                        if(CI!=null)          cond += ' Id = \'' + CI+ '\''; How to change charset of my website to utf8? How can I reuse a Common Table Expression I am using natbib and agsm for harvard-style referencing. My related code is  \usepackage{natbib} \bibliographystyle{agsm}   Then I am using \citep{} for citations. My problem is that in text I am getting     (Author et al. 2012)   but and I want     (Author et al. 2012)   Does anyone know how to change this and get 'et al' in italics in the text?  I am using TexPad and BibDesk and I have not been able to find the .bst files in Terminal.  I know that it is often correct to have the 'et al.' unitalicised but my university regulations requires italics. Using Perl to change the url homepage for Internet Explorer I'm currently working on the following problem for my computer theory class. It goes as follows:     Let $A$ and $B$ be regular expressions. Show then that $A^*B$ is the solution   of $X = AX + B$   Am I supposed to let $X = A^*B$? If so then   $A^*B = A(A^*B) + B$  I can understand that  $A(A^*B)$ could be reduced to $A^*B$ but what happens with the "${}+ B$" part of the expression? I've read up on Kleene algebra and found an axiom that seems relevant in which      $b + ax ≤ x → a^∗b ≤ x$   but I'm not actually sure if it applies. I am new to Stack  Exchange and I think it's very impressive.  One thing bothers me is that because it is so far down the line, I don't think beginners stand a chance of growing.  As time goes on, more and more questions are being answered and therefore if someone asks something with a really basic answer you can just comment. However, beginners can't comment until they have a reputation of 50. The only way they can build up is by answering questions. But if they answer a basic question long winded, they will be voted down because not so much effort was needed or because its already a duplicate and will lose the bit of reputation they have earned.  Can you tell me the future for beginners? Is a sentence always grammatically incorrect if it has no verb? Is the following grammatically correct? My friend says the second sentence is grammatically incorrect, but couldn't explain why.     I have always been fascinated by statistics. The different ways in   which you could look at data and infer knowledge from it. Show that $\frac{(2n)!!}{(2n+1)!!}$ converges. "Switching" axes in 3d tikzpicture Overview  So say I want an arc between the x and z axis in the same way the following creates an arc between the x and y axis (MVCE):  \documentclass[border=5mm]{standalone} \usepackage{tikz} \begin{document}   \begin{tikzpicture}     \tikzset{       x={(0:1cm)},y={(50:0.7cm)},z={(90:1cm)}     }     \draw[-&gt;] (0,0,0) --++ (1,0,0) node[right]{$x$};     \draw[-&gt;] (0,0,0) --++ (0,1,0) node[right]{$y$};     \draw[-&gt;] (0,0,0) --++ (0,0,1) node[right]{$z$};     \draw (0,0,0) ++(0:.3) arc (0:90:.3);   \end{tikzpicture} \end{document}     One solution to this exact problem is to do scope and tell arc that the y-axis is the z-axis.      \begin{scope}       \tikzset{y=(90:1cm)}       \draw (0,0,0) ++(0:.3) arc (0:90:.3);     \end{scope}   The problem  However, I need this more generic since I don't necessarily know how the y-axis is defined, so I'm looking for a way to do, essentially this:      \begin{scope}       \switchYZAxes       \draw (0,0,0) ++(0:.3) arc (0:90:.3);     \end{scope}   or      \begin{scope}       \tikzset{y=\theZAxis}       \draw (0,0,0) ++(0:.3) arc (0:90:.3);     \end{scope}   The latter is problematic because it seems like I can't send polar coordinates to the \tikszet via a macro (which is the background for  question).  Any ideas? Thanks :)