Editing ignored tags can be cumbersome when you have a lot of them already.   If you would be so kind to take a look at the following. My front page looks like this:    When I proceed to click "edit" on the right of Ignored Tags...    ... I have to scroll all the way to the bottom of the page to find a small add box using my trusty scrollbar or scroll wheel. Both of which take ages:    To add to my agony, I normally middleclick to make the autoscroll option appear. Then I can just move my mouse down and it will go to the place fast. But if I middle click to the right of the list of ignored tags, the add box dissappears. So I have to use the scroll wheel or scroll bar instead, which takes forever.   Could something be done to address this issue?
It seems that most people who use the ignored tags feature end up with a fairly long list of those tags.  Although , it is sometimes necessary to add new ignored tags manually (typically when adding some-tag*).  It would be a lot easier if the add box was above the long list of ignored tags rather than below. I suppose the same would apply to the favorites tags for consistency's sake.
Prove $\sin^2\theta + \cos^2\theta = 1$ How do you prove the following trigonometric identity: $$ \sin^2\theta+\cos^2\theta=1$$  I'm curious to know of the different ways of proving this depending on different characterizations of sine and cosine. Is there a page listing all fields? Understanding Join Attributes by Location in QGIS? I wonder if there is somewhere an explanation for the parameters that can be set when running the Algorithm "Join Attributes by Location" in QGIS 2.18.  I had a look here:       but there is no explanation. Any hints? Positioning of decorations on parallel lines I'm displayed three lines on a pgfplot. I want to show a marker for the slope of each line and the difference in height between lines.     I'm showing the slopes by adding triangles under the lines  (at a manual position) and placing an annotation inside the triangle (at a manual position). I'm showing the difference between the height of the lines by adding a brace manually as well.   How can I place the braces on the plot and anchor them at a certain point on each line? The triangles can be added at the end of each line declaration, but doing it like this is ok. The braces are put in place manually, which is not sustainable as I create more plots.   I want to avoid using xshift, yshiftand manual adjustment to put the braces,traingles and annotations in the right place. How can I do this?      \documentclass{article} \usepackage{pgfplots}  \pgfplotsset{compat=1.9}  \begin{document}   \begin{tikzpicture}[scale=0.45,trim axis left, trim axis right]     \begin{axis}[ylabel={$\hat{S(4)}$},xlabel={$S{^*}_{breakeven}$},ylabel style={rotate=-90},domain=1:25, legend style={legend pos=north west,font=\scriptsize}, legend cell align=left]  \addplot+[samples=200,mark=none]                                    {6.26 + 0.28*x} coordinate[pos=0.5](x) coordinate[pos=0.9] (y) (x)-| (y) node [midway,xshift=-0.6cm,yshift=0.3cm] {\footnotesize $Slope X$};;  \addplot+[samples=200,mark=none, dotted, thick]             {2.66 + 0.28*x}  coordinate[pos=0.3](a) coordinate[pos=0.6] (b) (a)-| (b) node [midway,xshift=-0.5cm,yshift=0.2cm] {\footnotesize $Slope 1$};  \draw [decorate,decoration={brace,amplitude=5pt,raise=4pt},xshift=4pt]  (225,107) -- (225,73)  node [midway,xshift=0.6cm] {\footnotesize $\beta_1$};  \end{axis} \end{tikzpicture} \end{document} How to execute a program or call a system command from Python Cancellation of Direct Products Are partitions to the inner/outer edge significantly faster Some linux dual/multi-boot tutorials / general partitioning tutorials say that the inner side of a hard disk is faster than the outer side so partitions towards the outside tend to be slower while some say that the exact opposite is true.  Which side is actually faster?  Is the difference noticeable?  How are the partitions physically placed on the disk as compared to the partition listing order-for example gparted shows a logical ribbon layout of the partitions. Are the partitions shown to the left side of this ribbon near the outer or inner edge of the disk physically?  Are there software benchmarks like testing some disk intensive stuff for the first time on identical vanilla installs of the same OS but on different partitions, inner and outer?  EDIT: Links   ctrl + f for "slower" on this page   Says outer side is faster   Says inner side is faster   Says outer side is faster(not about dual-booting) Making image positioned on textbox clickable in case of ipad (Creating HTML5 Search input type for iOS) Roll back from OS X Mavericks ( or any newer OS) to Mountain Lion I installed the developer preview of OS X Mavericks, &amp; too many things broke. I can't stay on it &amp; need to roll back to Mountain Lion. Any ways of doing that? Please help!  I originally installed Mountain Lion &amp; Mavericks through the Mac App Store. Using residue theorem to integrate from $-\infty$ to $\infty$ I'm trying to integrate $$\int_{-\infty}^{\infty} {x^2 \over {(x^2 + 1)}^2(x^2 + 2x + 2)} $$ given that the function  $$f(z) = {z^2 \over {(z^2 + 1)}^2(z^2+2z+2)} $$ has residues $${9i - 12 \over 100},{3 - 4i \over 25}$$ at the poles $i$ and $-1+i$ respectively. From my understanding of this I have added the two residues (by the residue theorem, and because their respective poles lie in the upper half plane) and multiplied by $2\pi i$ and got an answer of $14\pi \over 100$  Have I done this right? How to disable the physical sim and only use the eSIM on iPhone XS/iPhone XS Max? I'm wondering if there is a way to turn off the Physical sim and use only the eSim on my iPhone XS Max. I travel a lot and I'm loving the use of eSIM.   I understand that I can turn off the eSIM if its required, but I wanted to know if there was any way to turn the Physical Sim off and leave only the eSim ON.  Note - I have an unlocked iPhone XS Max. Ubuntu 18.04 bond with netplan duplicate MAC address after cloning Before I met her I had a poor opinion of her.   As person had a poor opinion before a particular time in past (before He met her) so I think there should be had had.   There are some more example like this:   Before I went to the university, I worked/had worked as a carpenter for 5 years. Before I opened the door, I put/had put the key in the lock. Before I opened the door, I looked/had looked carefully into the barn for snipers.   In all these sentence, for me, it should be perfect tense.  I asked that question on another platform where I was told that if sequence of past event is obvious and sentences uses "before"and "after", we often use past tense. Which means we should use past tense in all these sentences. But I have another sentence "The train had left before I reached the station." If I follow above mentioned rule there should be "left" instead of "had left". But I am damn sure this sentence is correct with "had left".   Am I correct?  Thank you How to show $\sum_{k=0}^{n}\binom{n+k}{k}\frac{1}{2^k}=2^{n}$ How does one show that $$\sum_{k=0}^{n}\binom{n+k}{k}\frac{1}{2^k}=2^{n}$$ for each nonnegative integer $n$?  I tried using the  but I guess I am applying it incorrectly. With the snake oil technique we have $$F(x)= \sum_{n=0}^{\infty}\left\{\sum_{k=0}^{n}\binom{n+k}{k}\frac{1}{2^k}\right\}x^{n}.$$ I think I have to interchage the summation and do something. But I am not quite comfortable in interchanging the summation. Like after interchaging the summation will $$F(x)=\sum_{k=0}^{n}\sum_{n=0}^{\infty}\binom{n+k}{k}\frac{1}{2^k}x^{n}?$$ Even if I continue with this I am unable to get the correct answer.  How does one prove this using the Snake oil technique?  A combinatorial proof is also welcome, as are other kinds of proofs. What would happen if you put your hand in front of the 7 TeV beam at LHC? Some speculation here:   Is there a possibility it would pass 'undetected' through your hand, or is it certain death?  Can you conclude it to be vital, or only loose your hand?  Would it simply make a small cylindrical hole through your hand, or is there some sort of explosion-effect?  Assume your hand has a cross section of 50cm², and a thickness of 2cm, how much of the beam's energy would be transferred to your hand? I would like to know the model of my graphics card. I think it may be an ATI, but I want to be sure!   I have Ubuntu 11.10 (32 bit) and an Asus A6 VA laptop. Why is 8 so special? I have been reading about multi-dimensional numbers, and found out that it's been proven that the Octonions are the composition algebra of the largest dimension. I was wondering why, despite having infinitely many different dimensions of numbers, the only composition algebras are of 1, 2, 4, and 8 dimensions. What's so special about 8? More examples of Simpson's Paradox, barring the ones on Wikipedia, Titanic, and delayed flights. I hope someone may know fresh examples of  for use in my statistics courses.  The examples I've been using are fine, but I'd like to have some new ones.  I'm familiar with the ones on the Wikipedia page: the gender bias lawsuit at Berkeley, batting averages, mortality rates among low birth babies, party voting on the Civil Rights Act, and success rates of kidney stone treatments.  I'm also familiar with the example of survival rates on the Titanic and the one about delayed flights at America West vs. Alaska Airlines.  These are all good ones, but, like I said, I'm looking for more. Does anybody know any others?  For those who aren't familiar with it, Simpson's paradox is essentially a property of unreduced fractions: It's possible to have, simultaneously, $$\frac{a_1}{b_1} &lt; \frac{c_1}{d_1} \text{ and } \frac{a_2}{b_2} &lt; \frac{c_2}{d_2}, \text{ but } \frac{a_1 + a_2}{b_1+b_2} &gt; \frac{c_1+c_2}{d_1+d_2}.$$   For example, $\frac{1}{3} &lt; \frac{34}{100}$ and $\frac{66}{100} &lt; \frac{2}{3}$, but $\frac{67}{103} &gt; \frac{36}{103}$.  It can be hard to spot this happening in a given real-world scenario. I was working on a worksheet for class and came across this problem:      Let $\varphi:R\to S$ be an onto ring homomorphism with the property that every ideal of $R$ is principal. Show that the same must be true for $S$.    I honestly do not know how to do this one! How do I contact other users?