i downloaded compizconfig settings manager and even though i'm enabling some animations they do not work, for example i enabled the wobbly windows animation and it does not work.  I'm running ubuntu mate 18.04 on a virtual machine on my lenovo yoga 710 latop. thanks for the help.
I tried turn on in compizconfig but I does not work. Any solution or it is possible?
Past participle after noun: "proposed cost" vs. "cost proposed" I have the following two examples:        Our proposed cost is expensive.   Our cost proposed is expensive.      Is there any difference between them? Or is the second sentence wrong? drush/drush dev-master requires codegyre/robo ~1.0.0-beta1 I'm transitioning a Drupal 6 site to Drupal 8.1 so following the official instructions, I set up a new install in its own directory. Since this is only one site, I followed the instructions to put my database credentials in sites/default/default.settings.php after the declaration of the $databases array.  Running drush --status returns the following.  Drush version          :  8.1-dev                                           Drush temp directory   :  /tmp                                              Drush configuration    :                                                    Drush alias files      :                                                    Drupal root            :  /media/psf/Home/apps/newp                         Drupal Settings File   :  MISSING   Since this Drupal is 8.1-dev that must mean I need to upgrade it. Since this is a global install using Composer, I run composer global update.     Your requirements could not be resolved to an installable set of   packages drush/drush dev-master requires codegyre/robo ~1.0.0-beta1   Checking the drush-ops page on github doesn't show any anomalies like this nor my Google search.   What am I overlooking? My account has been , besides the following restrictions:  an account will be locked at 1 reputation the user page will have a visual indication that the account is in timed suspension, and for how long the account holder will be unable to vote, ask, answer or comment  What else does timed suspension prevent me doing? For example, can I still edit my own posts or delete content? And what is a network-wide suspension? What are the rules of parallelism? I've been reading a lot about it since yesterday and all I encounter is "They must have the same grammatical form"? What does this exactly mean?  I know how to make parallel sentences with gerunds. The things get trickier when it comes to using modifiers.  For example:     I love using the phone that you bought me and the computer.   On the left side of the conjunction there is a noun phrase that consists of an article + noun + another modifier and on the right side there is an article + noun.  They are both noun phrases but the first one has additional modifier. Is that still considered a parallel sentence?  Another example:     I like to swim and to feel good.   Here on the right side of the conjunction there is an infinitive and on the left side there is an infinitive + complement? Is that parallel? EDIT Like some comments below are remarking the table environment doesn't allow tables over more than one page. However the solution works fine  I need to make a table over more than one page. The standard approach seems to be to use the ltablex environment. However, it doesn't work; also I assume that the table environment may also be required for the thesis template I work on (e.g. suppose for the capture).   \documentclass[11pt]{article} \usepackage{booktabs} \usepackage{tabularx} \usepackage{ltablex}  \begin{document}  \begin{table} \caption{Example of an table} \label{tab:daypack}      \begin{tabularx}{\linewidth}{@{}cX@{}}   \toprule \textbf{Column 1} &amp; \textbf{Column 2} \\[6pt] \midrule \endhead $R$ &amp; 1This is an example sentence \\[6pt] $R$ &amp; 2As well as the line before \\[6pt] $A$ &amp; 3Also this is an example \\[6pt] $R$ &amp; 4This is an example sentence \\[6pt] $R$ &amp; 5As well as the line before \\[6pt] $A$ &amp; 6Also this is an example \\[6pt] $R$ &amp; 7This is an example sentence \\[6pt] $R$ &amp; 8As well as the line before \\[6pt] $A$ &amp; 9Also this is an example \\[6pt] $R$ &amp; 10This is an example sentence \\[6pt] $R$ &amp; 11As well as the line before \\[6pt] $A$ &amp; 12Also this is an example \\[6pt] $R$ &amp; 13This is an example sentence \\[6pt] $R$ &amp; 14As well as the line before \\[6pt] $A$ &amp; 15Also this is an example \\[6pt] $R$ &amp; 16This is an example sentence \\[6pt] $R$ &amp; 17As well as the line before \\[6pt] $A$ &amp; 18Also this is an example \\[6pt] $R$ &amp; 19This is an example sentence \\[6pt] $R$ &amp; 20As well as the line before \\[6pt] $A$ &amp; 21Also this is an example \\[6pt] $R$ &amp; 22This is an example sentence \\[6pt] $R$ &amp; 23As well as the line before \\[6pt] $A$ &amp; 24Also this is an example \\[6pt] $R$ &amp; 25This is an example sentence \\[6pt] $R$ &amp; 26As well as the line before \\[6pt] $A$ &amp; 27Also this is an example \\[6pt] $R$ &amp; 28This is an example sentence \\[6pt] $R$ &amp; 29As well as the line before \\[6pt] $A$ &amp; 30Also this is an example \\[6pt] $R$ &amp; 31This is an example sentence \\[6pt] $R$ &amp; 32As well as the line before \\[6pt] $A$ &amp; 33Also this is an example \\[6pt] $R$ &amp; 34This is an example sentence \\[6pt] $R$ &amp; 35As well as the line before \\[6pt] $A$ &amp; 36Also this is an example \\[6pt] $R$ &amp; 37This is an example sentence \\[6pt] \bottomrule \end{tabularx}    \end{table}      \end{document} Momentum is defined by the product of mass and velocity. Now a projectile out of a gun has to have high velocity to penetrate a human body, as its mass isn't significant. But to reach this velocity, due to inertia/the law of energy conservation, momentum on both sides is to be equal. As there is strong negative acceleration in the opposite direction of the bullet, it should result in a strong force in the opposite direction of the bullet ($F = m*a $).  Therefore I wonder why shooting a bullet with a handgun is not ripping your hand apart. I am using the 2D Animation preset and so far every new scene I made had the same bright white background. Now my two latest scenes (created with 'copy settings') have a light grey background even though they are set to white. There's also no difference in surface, nodes or strength.  There are apparently exist different background shades with an off-white color but selecting the white one doesn't help either Assume that $M$ and $N$ are two finitely generated $R$-modules. Then $\operatorname{Hom}_{R}(M,N)$ is a finitely generated $\mathbb Z$-module and/or $R$-module (in this case, assume that $R$ is commutative)?   Note that $R$ is not Noetherian ring. Is there any counterexample (for any cases)? I'm having troubles with one of the problems in the book Introduction to Commutative Algebra by Atiyah and MacDonald. It's on page 11, and is the last part of the second question.  Given $R$ a commutative ring with unit. Let $R[x]$ be the ring of polynomials in an indeterminate $x$ with coefficients in $R$. We say that a polynomial $f = \sum\limits_{i=0}^n r_ix^i \in R[x]$ (with coefficients $r_0, r_1, \ldots, r_n$) is primitive if $\langle r_0,r_1,...,r_n\rangle = R$, i.e., the ideal generated by the coefficients of $f$ is $R$. Let $f$ and $g$ be two polynomials in $R[x]$. Prove that $fg$ is primitive iff $f$ and $g$ are both primitive.  The $\Rightarrow$ part is easy. Say, $f = \sum\limits_{i=0}^n r_ix^i$, $g = \sum\limits_{i=0}^m s_ix^i$; then $fg = \sum\limits_{i=0}^{m+n} c_ix^i$, where $c_k = \sum\limits_{i + j = k}r_is_j$. Since $fg$ is primitive, there exists a set of $\{\alpha_i\} \subset R$, such that $\sum\limits_{i=0}^{m+n} \alpha_ic_i = 1$, to prove $f$ is primitive, I just need to write all $c_i$'s in terms of $r_i$'s, and $s_j$'s, then group all $r_i$ accordingly, rearranging  it a little bit, and everything is perfectly done. And the proof of the primitivity of $g$ is basically the same. The $\Leftarrow$ part is just so difficult. Say $f = \sum\limits_{i=0}^n r_ix^i$, $g = \sum\limits_{i=0}^m s_ix^i$ are both primitive, then there exists $\{\alpha_i\}; \{\beta_i\} \subset R$, such that $\sum\limits_{i=0}^{n} \alpha_ir_i = 1$, and $\sum\limits_{i=0}^{m} \beta_is_i = 1$. At first, I thought of multiplying the two together, but it just didn't work. So, I'm stuck since I cannot see any way other than multiplying the two sums together. I hope you guys can give me a small push on this. Thanks very much in advance, And have a good day. I am trying to create a schema page in LaTeX. It shall look like this.   How can I create schema code which look like this image? There should be also a click to go function. When the user clicks on the user_schema link he should be redirected to that page.  What classes I can use for this? Any suggestions would be appreciated.    \documentclass{article} \usepackage[utf8]{inputenc}  \begin{document} \maketitle  \section{User schema} \mySchema{Users} {     _id: ObjectId - Id do registro     name: String - Nome do usuário     date: Date - Data de Cadastro     ren_date: Date - Data de renovação do Cadastro     email: String - Lorem ipsum dolorsitamet, consecteturadipisicingelit, sed do eiusmodtemporincididunt ut labore et dolore magna aliqua. Ut enim ad minimveniam, exercitationullamcolaborisnisi ut aliquipexeacommodoconsequat. Duisautereprehenderit in voluptatevelit esse cillumdolore eu fugiatnullapariatur. Occaecatcupidatat non proident, sunt in culpa quiofficiadeseruntmollit.     access_log: Array [          {              date: String - Data da ocorrência.             user: ObjectId - Usuário que executou.             action: String - Ação Executada.         }         {              date: String - Data da ocorrência.             user: ObjectId - Usuário que executou.             action: String - Ação Executada.         }     ]     \link{group}{group_id}: ObjectId - Id do grupo. } \end{document}   Here is the image how should it appear: "I had my house [be] burned down" I have found out that using the verb be in passive constructions such as:      I had my house be burned down    is incorrect, therefore it should be      I had my house burned down.    But is it possible instead of be to use get? E.g.      The wire is passed through the pliers in a specific way to avoid having it get bent.   The rope had its surface wear.   The rope had its surface get worn.   The rope had its surface worn.   The first two sound very odd to me, but just for clarification could you please point out the errors and which ones are correct? Or is using get, be it in -ing or the to infinitive, in any situation along with have incorrect? In Harry Potter, we know ghosts became ghosts when they are too afraid of death to go on - I thought about it and I'm quite certain they all go to their own version of Harry's King's Cross and become ghosts when they return as Harry did.  So can they return there? Once they've been a ghost long enough that they no longer fear death, can they move on? Network simplex method, leaving and entering variables How do I prove $F(a)=F(a^2)?$ Let $E$ be an extension field of $F$. If $a \in E$ has a minimal polynomial of odd degree over $F$, show that $F(a)=F(a^2)$.  let $n$ be the degree of the minimal polynomial $p(x)$ of $a$ over $F$ and $k$ be the degree of the minimal polynomial $q(x)$ of $a^2$ over $F$.   Since $a^2 \in F(a)$, We have $F(a^2) \subset F(a)$, then $k\le n$  In order to prove the converse:  $q(a^2)=b_0+b_1a^2+b_2(a^2)^2\ldots+b_k(a^2)^k=0$   implies   $q(a)=b_0+b_1a^2+b_2a^4\ldots+b_ka^{2k}=0$ Then   $p(x)|q(x)$, because $p(x)$ is the minimal polynomial of $a$ over $F$.  If I prove that $n|2k$ we done, since $k$ is odd, we have $n|k$ and $n\le k$ and finally $n=k$.  So I almost finished the question I only need to know how to prove that $n|2k$ It should be only a detail, but I can't see, someone can help me please?  Thanks Question about the proof of Ramsey's Theorem I was reading up on a proof of Ramsey's Theorem and I can't understand this part of the proof:      Pick a vertex $v$ from the graph, and partition the remaining vertices into two sets $M$ and $N$, such that for every vertex $w$, $w$ is in $M$ if $(v, w)$ is blue, and $w$ is in $N$ if $(v, w)$ is red. Because the graph has $R(r - 1, s) + R(r, s - 1) = |M| + |N| + 1$ vertices, it follows that either $|M| \geq R(r − 1, s)$ or $|N| \geq R(r, s − 1)$.   Why is that $|M| \geq R(r − 1, s)$ or $|N| \geq R(r, s − 1)$? I know from the proof of $R(3,3) = 6$ that given a vertex, at least $3$ are guaranteed to be either red or blue, so what is the pigeonhole argument for the general case? User and associated Post Structure of groups of order $pq$, where $p,q$ are distinct primes. I don't know about the Sylow Theorems.  But I have been wondering about a proof of the fact that a group or order $pq$ where $p$ and $q$ are distinct primes must be cyclic. I can't quite work out the details, but here is the general idea. I would like help with filling in details. I assume that it is already known that $G$ has subgroup(s) of order $p$ and subgroup(s) of order $q$.  If $G$ is a group of order $pq$ ($p\neq q$), then I know that $G$ has a subgroup $H$ of order $p$ and a subgroup $K$ of order $q$. Then $H\simeq \mathbb{Z}_p$ and $K\simeq \mathbb{Z}_q$.   But then $H\oplus K \simeq \mathbb{Z}_{pq}$, so I would think that $H\oplus K \simeq G$. I guess one could do an internal direct product instead of an external direct product, but I don't know that $H$ and $K$ are normal subgroups.  I am asking for help completing this argument.  Edit: I see from the comments below that I might need to assume that the smaller prime does not divide the larger prime minus $1$. Or maybe it is enough to assume that the primes are greater than or equal to $3$ (Still distinct). Are there instances where citing Wikipedia is allowed? For example, suppose you're writing an article about triangles, and you want to include a short proof of Pythagoras' theorem, but you can't quite remember how to derive it, so you pop over to:  and check the proof there. It works mathematically, makes sense and is as far as you can tell, correct, so you include it. Now the proof on Wikipedia doesn't have a citation because probably someone has been taught it and copied it over to Wikipedia, but it's still correct. The only thing you could cite for the proof would be Wikipedia, would a citation be ok or should it just be copied down without a citation?  Edit: Ok, there have been many responses. Most with a firm "no", but some giving the reason: "Just get the proof from a book" since it's so common, but suppose then it wasn't a common proof of something. Maybe it's not very well known or something but suppose there is a small Wikipedia page with the correct mathematical proof. How much effort are people going to go to to find a proof in a book when there's a (correct (which we know, becuase it's maths and we can check it)) proof on Wikipedia? Why is it so bad to say: "I found this proof on Wikipedia, and the maths checks out so it doesn't matter who wrote it, it is correct, but that's where I found it." Or if you do find it somewhere else why not say: "Proof taken from Wikipedia and verified by the proof shown in "Triangles and their properties, Nature, 2014, p113 etc..." According to specification, to create data that will be signed with server private key for CertificateVerify message, we need to concatenate 64 space characters, the string &quot;TLS 1.3, server CertificateVerify&quot;, null and the hash of all handshake messages to this point. During the handshake process, we choosing the cipher suite and signature scheme... So, if the cipher suite is, for example, TLS_AES_256_GCM_SHA384 and the signature scheme is rsa_pss_rsae_sha256 (different hash algorithms), hash of which algorithm should be used as handshake hash in data to sign, SHA-384 or SHA-256? I'm drawing a scene where the camera freely moves about the universe.  The camera class keeps track of the view (or look at) point, the position of the camera, and the up vector.  These vectors/points are then passed into gluLookAt.    Pan and zoom are nearly trivial to implement.  However, I'm finding rotation about the look at point to be much more of an issue.  I want to write a function Camera.rotate that takes 2 angles, one that rotates up/down and one that rotates left/right along an imaginary sphere that is centered about the look at point.  Is there an easy way to do this?  I've (briefly) read about quaternions, but I wanted to see if there was an easier solution given the relatively simple construction of my scene.