How can i get a string after a special character?  For example I want to get the string after / in   my_string = "Python/RegEx"  Output to be : RegEx  I tried :  h = [] a = [ 'Python1/RegEx1' , 'Python2/RegEx2', 'Python3/RegEx3']  for i in a:      h.append(re.findall(r'/(\w+)', i)) print(h)   But the output is : [['RegEx1'], ['RegEx2'], ['RegEx3']]  I need : ['RegEx1', 'RegEx2', 'RegEx3']  Thanks in advance  RegEx beginner
2267
What's the difference between the list methods append() and extend()?
4078
I have a string that contains both double-quotes and backslashes that I want to set to a variable in Python. However, whenever I try to set it, the quotes or slashes are either removed or escaped. Here's an example:  &gt;&gt;&gt; foo = 'baz "\"' &gt;&gt;&gt; foo 'baz ""'   So instead of baz "\" like I want I'm getting baz "". If I then try to escape the backslash, it doesn't help either:  &gt;&gt;&gt; foo = 'baz "\\"' &gt;&gt;&gt; foo 'baz "\\"'   Which now matches what I put in but wasn't what I originally wanted. How do you get around this problem?
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Does * have a special meaning in Python as it does in C? I saw a function like this in the Python Cookbook:  def get(self, *a, **kw)   Would you please explain it to me or point out where I can find an answer (Google interprets the * as wild card character and thus I cannot find a satisfactory answer).
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Is it possible to do something like this?  var pattern = /some regex segment/ + /* comment here */     /another segment/;   Or do I have to use new RegExp() syntax and concatenate a string? I'd prefer to use the literal as the code is both more self-evident and concise.
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I'm looking for Python code that removes C and C++ comments from a string. (Assume the string contains an entire C source file.)  I realize that I could .match() substrings with a Regex, but that doesn't solve nesting /*, or having a // inside a /* */.  Ideally, I would prefer a non-naive implementation that properly handles awkward cases.
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Say I have the string "User Name:firstname.surname" contained in a larger string how can I use a regular expression to just get the firstname.surname part?  Every method i have tried returns the string "User Name:firstname.surname" then I have to do a string replace on "User Name:" to an empty string.  Could back references be of use here?  Edit:  The longer string could contain "Account Name: firstname.surname" hence why I want to match the "User Name:" part of the string aswell to just get that value.
61580
What is the quickest way to HTTP GET in Python if I know the content will be a string? I am searching the documentation for a quick one-liner like:  contents = url.get("http://example.com/foo/bar")   But all I can find using Google are httplib and urllib - and I am unable to find a shortcut in those libraries.  Does standard Python 2.5 have a shortcut in some form as above, or should I write a function url_get?   I would prefer not to capture the output of shelling out to wget or curl.
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In Python, how do I get a function name as a string, without calling the function?  def my_function():     pass  print get_function_name_as_string(my_function) # my_function is not in quotes   should output "my_function".  Is such function available in Python? If not, any ideas on how to implement get_function_name_as_string, in Python?
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Im trying to craft a regex that only returns &lt;link&gt; tag hrefs  Why does this regex return all hrefs including &lt;a hrefs?       (?&lt;=&lt;link\s+.*?)href\s*=\s*[\'\"][^\'\"]+        &lt;link rel="stylesheet" rev="stylesheet"      href="idlecore-tidied.css?T_2_5_0_228" media="screen">     &lt;a href="anotherurl">Slash Boxes&lt;/a>   thank you
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I'd like to do it in Python. What I'd like to do in this example in C: #include &lt;stdio.h&gt;  int main() {     int i;     for (i=0; i&lt;10; i++) printf(&quot;.&quot;);     return 0; }  Output: ..........  In Python: &gt;&gt;&gt; for i in range(10): print('.') . . . . . . . . . . &gt;&gt;&gt; print('.', '.', '.', '.', '.', '.', '.', '.', '.', '.') . . . . . . . . . .  In Python print will add a \n or space, how can I avoid that? Now, it's just an example, don't tell me I can first build a string then print it. I'd like to know how to &quot;append&quot; strings to stdout.
39933
How can I get the start and end positions of all matches using the re module? For example given the pattern r'[a-z]' and the string 'a1b2c3d4' I'd want to get the positions where it finds each letter. Ideally, I'd like to get the text of the match back too.
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If I grep a document that contains the following:  ThisExampleString  ...for the expression This*String or *String, nothing is returned. However, This* returns the above line as expected.  Whether the expression is enclosed in quotes makes no difference.  I thought the asterisk indicated any number of unknown characters? Why does it only work if it's at the start of the expression? If this is intended behavior, what do I use instead of the expressions This*String and *String?
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How do you concatenate characters in java? Concatenating strings would only require a + between the strings, but concatenating chars using + will change the value of the char into ascii and hence giving a numerical output. I want to do System.out.println(char1+char2+char3... and create a String word like this.  I could do   System.out.print(char1); System.out.print(char2); System.out.print(char3);   But, this will only get me the characters in 1 line. I need it as a string. Any help would be appreciated.  Thanks
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I'm trying to split a string with all non-alphanumeric characters as delimiters yet Java's String.split() method discards the delimiter characters from the resulting array. Is there a way to split a string like the "\W" regex pattern does, yet keep the delimiters?
54531
I would like to find a regex that will pick out all commas that fall outside quote sets.   For example:  'foo' =&gt; 'bar', 'foofoo' =&gt; 'bar,bar'   This would pick out the single comma on line 1, after 'bar',  I don't really care about single vs double quotes.  Has anyone got any thoughts? I feel like this should be possible with readaheads, but my regex fu is too weak.
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How can I fetch a domain name from a URL String? Examples: +----------------------+------------+ | input                | output     | +----------------------+------------+ | www.google.com       | google     | | www.mail.yahoo.com   | mail.yahoo | | www.mail.yahoo.co.in | mail.yahoo | | www.abc.au.uk        | abc        | +----------------------+------------+  Related:
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I have a , and I'm trying to match it to a regular expression to pull out some groups. The problem I'm having is that the URL can either end or continue with a "/" and more URL text. I'd like to match URLs like this:        But not match something like this:      So, I thought my best bet was something like this:    /(.+)/(\d{4}-\d{2}-\d{2})-(\d+)[/$]   where the character class at the end contained either the "/" or the end-of-line. The character class doesn't seem to be happy with the "$" in there though. How can I best discriminate between these URLs while still pulling back the correct groups?