What is the highest possible power of a creature, assuming a deck of 60 cards and infinite time?
120623
Say that both players each had 2 , 2 , and a . (Or any other way to get unlimited mana, and a Nantuko Shade).  Player 1 attacks with his , and player 2 blocks with his . Before damage is assigned, each has chances to pump up their  as much as they want. They can't just declare them to be "infinite," but each can always one-up the other player. What happens?  It seems there would be a loop of events, but would one player eventually be forced to break the loop as per rule 714.3? Is it considered the same game state after each player pumps their creature a bunch as it was before?  This was discussed at length on the Draw3Cards Magic Q&amp;A site (which is no longer available), but no conclusion was reached. Some felt that the game would simply be a draw, others felt that the active player would be forced to make a different decision to break the loop. Others felt that you would just have to call a judge and see what he decides.
122922
Show that there are infinitely many $N$ such that $\frac{N}{2}$ is a perfect square, $\frac{N}{3}$ is a perfect cube, and $\frac{N}{5}$ is a perfect fifth power.    A hint is given with this question, which is: $7^{30}$ is a perfect square, a perfect cube and a perfect fifth power.  Can anyone solve this? Thanks!
12273
When you have a card like  which reads "Exile Target Creature with power 3 or less", as I understand it, it becomes untargetable if the opponent's creature power increases thanks to a pump spell like .  But what if the Disregard is already on the stack and targeting; and they respond with Brute Strength? I'm pretty sure (and my opponent with Brute Strength was certain) that it won't exile the creature, but I don't know which rule states this, and there's no gatherer ruling on the spell.
59461
If I have  in play, can 's triggered ability pull a card like  from my library, which would originally have a converted cost of 4, but which is lowered by the Grand Arbiter's ability?
94910
Okay the scenario I'm thinking of is as follows:   I control a ,  and 3 untapped lands (2 swamps, 1 Island to be perdantic). In my opponents turn he casts a burn spell to kill my duskmantle.   I activate his first ability in response.   The way I am hoping the following interactions will go is:   Duskmantles ability will hit the stack at the top and resolve The burn spell resolves dealing its damage to Duskmantle The burn spell card hits the graveyard and triggers the infinite loop for duskmantle and mindcrank killing my opponent Duskmantle perishes   Is this the way that the stack would pan out? Do I win in this situation regardless of the stack being correct or not above? (I am not fully familiar with how the stack really works in magic) You can see the cards from my deck .
39252
I'm working on a card game, which uses a non-standard deck of cards. Since I'm still tweaking the layout of the deck, I've been using variables as follows:  Hand size: $H$ Number of suits: $S$ Number of ranks: $R$ Number of copies of each card: $C$    Thus, the total number of unique cards in the deck is $S*R$, and the absolute total number of cards in the deck is $S*R*C$.  Since there are duplicates for each card, I'm trying to find the number of unique hands of size $H$ that are possible for given $S$, $R$, $C$, and $H$. If I'm remembering correctly, ${S*R*C\choose H}$ would over count the number of unique hands in this case.  How would I handle this calculation with duplicate cards?  EDIT: As an aside, how would calculations of unique number of winning hands be different with duplicate cards? I'm thinking of having general types of winning hands, such as $N$-flushes, $N$-straights, $N$-of-a-kinds, etc (restricted to $1 \le N \le H$, naturally).
83355
Are token creatures considerd creature spells? For instince when I use  tap effect combined with  would it allow me to draw a card?
97698
Let's suppose there are creatures in play and someone plays .  It's clear that all the creatures lose their abilities.  How is this situation changed if  were in play?  Is the situation changed if True Conviction were played after Humility?  Is the solution to this question that the card with the newest time stamp is in effect?
834
Let $m&gt;1$ be a natural number with $m \not\equiv 0 \pmod{10}$  Consider the powers $m^n$ , for which there is at least one digit not occurring in the decimal representation.  Is there a largest $n$ with the desired property for any $m$? If so, define $n(m)$ to be this number.  Examples :  $$m=2 \rightarrow 2^{168} = 374144419156711147060143317175368453031918731001856$$  does not contain the digit $2$.  All the powers above up to $2^{10000}$ conatin all the digits, so  $2^{168}$ seems to be the biggest power with the desired property.  $$m=3 \rightarrow 3^{106} = 375710212613636260325580163599137907799836383538729$$  does not contain the digit $4$.  All the powers above up to $3^{10000}$ contain all the digits, so $3^{106}$ seems to be the biggest power with the desired property.  So, probably $n(2)=168$ and $n(3)=106$ hold.  Is $n(m)$ defined for any $m$, and if yes, can reasonably sharp bounds be given?
112480
Suppose that a pair of cards are selected from a standard deck of 52 cards. And since there are 26 black cards and 26 red cards, so I'm wondering if my thinking is right?   ${26!/25! * 26!/25!}$ so it would be ${26*26 = 676}$
61101
I'm new to the game and trying to make my first constructed deck. My understanding of the card rule is I can only have four cards of one kind.  What does this precisely mean?  For instance, does this mean I can only have four rat cards total or four rat cards of several kinds? If two different cards do the same thing (like  and ), can I have four of each?
67864
Completely shuffle and then lay out a full deck of 52 cards in a single row (i.e. single row 52 columns). Do the same thing with a second deck of playing cards and place this deck in the second row(also has 52 columns). What is the expected total number of matches in all the columns?   A match means that the top card and the bottom card in the column are the same (same rank and suit).  I was trying to solve it by brute force but seems like it's not that easy to me.
29878
In the game of , it turns out that any seven cards contain a projective set. For fewer than 7 cards, how can we determine the probability that one or more sets exist (in terms of the number of cards)?  For those not familiar with Projective Set, here's a description from the wikipedia page linked above:   A Projective Set card has six binary attributes, or bits, generally represented by colored dots. For each color of dot, each card either has that dot or does not. There is one card for each possible combination of dots except the combination of no dots at all, making $2^6 - 1 = 63$ cards total.  Three cards are said to form a "set" if the total number of dots of each color is either 0 or 2. Similarly, four or more cards form a "set" if the number of dots of each color is an even number.  A card and itself could be said to form a two-card set, but as the cards in the deck are all distinct, this does not arise in actual gameplay.
73115
A Commander deck consists of 100 unique cards, of which one is designated as the Commander and must be either a Legendary Creature or an allowed Planeswalker.  I'm still very unfamiliar with this format.  How would you go about figuring out the number of lands to put into your commander deck?
114545
So a friend of mine showed me a very interesting card trick that I don't quite understand.  You have 52 normal cards from any regular deck you can buy anywhere. The Ace is worth 1 while 2 through 10 are worth their number value. Jack is worth 11, Queen is worth 12 and King is worth 13.  You shuffle the cards any way you want. Then you take the first card from the top of the deck and put it down on the table face up. Now, if it's a king you put it back in the deck and try again. If it's anything else you read the value on the card. Lets say you picked a 3. Now you have to put down cards from the deck in your hand on top of the 3 until you have counted 13. So 13 - 3 = 10. So you place 10 cards from the deck face up on the 3 on the table. It does not matter what the cards you place on top have in terms of values.  Now you move on to make a new set of cards on the table after the same principle. Again you cannot start on a king. If you reach a point where you can no longer put down 13 cards you keep the cards in your hand.  So I carried this out and ended up with 5 sets of cards on the table.They started with 3, 6, ace, ace and 10 leaving me with 3 cards left on my hand.  Now you take three of the decks, turn them around so they lie face down and then you pick up the rest of the cards to your hand. Now you choose 2 decks of cards and make the first card turn around so that they are face up. I have a 3 and a 10 and I have 24 cards on my hand. With 3 and 10 facing up you put that together which is 13. You have to add an extra 10 to whatever number you get so it will become 23. Now I put down 23 cards from my hand which leaves me with one card. This means that the last card currently facing down of three sets of cards on the table will be an ace.  And it was.  Why does this work?  My friend told me this could be explained or at least proven to work 100 % of the time with a mathmatical formula.
16382
Four cards are face down on a table. You are told that two are red and two are black, and you need to guess which two are red and which two are black. You do this by pointing to the two cards you’re guessing are red (and then implicitly you’re guessing that the other two are black). Assume that all configurations are equally likely, and that you do not have psychic powers. Find the probability that exactly j of your guesses are correct, for j = 0, 1, 2, 3, 4. Hint: Some probabilities are 0. My professor worked out this example in class and I know the answers for j = 1 and j = 3 are zero, j = 0 is 1/6, j = 2 is 2/3, and j = 4 is 1/6 but I do not understand the process or concept behind the question. I do not understand where the numbers are coming from and why only the even js have a probability but not the odd js. The j guesses and pointing is confusing me. Can someone please help explain the question, I would appreciate it.
92567
For example, Esper refers to decks made up of White, Blue and Black cards.  What are the names of the other colour combinations? In particular, how do we refer to a Red-White-Black deck?