how many grams of ammonia are produced when 6 moles of hydrogen gas react with nitrogen gas?
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If 6 moles of hydrogen react with nitrogen 4 moles of ammonia produced.
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Therefore 2 moles will have 1.204*10^24 molecules of NH3. There are 4 atoms in each molecule, so 2 moles will have 4*(1.204*10^24) atoms which is 4.816*10^24 atoms. How many atoms of hydrogen are present in 1.7g of NH3?
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You have 1.51×1024 individual ammonia molecules. = approx. 2 moles of ammonia molecules , but don't trust my arithmetic!
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Answer and Explanation: In the above reaction, 1 mole of nitrogen gas reacts with 3 moles of hydrogen gas. Therefore, 2 moles of nitrogen gas will react with 3×2=6 3 × 2 = 6 moles of hydrogen gas.
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Make the calculations: n(N2)reacted = 1/3*n(H2) = 3 molecules n(NH3)produced = 2/3*n(H2) = 6 molecules The number of unreacted molecules of N2 is 4 – 3 = 1 molecule. Hydrogen is the limiting reactant, so no hydrogen molecules remain unreacted.
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To find the mole count, divide the mass in grams by 2.016. For example, if the mass of the hydrogen gas is 0.5 grams, then n equals 0.2480 moles. Convert the temperature T into Kelvin units by adding 273.15 to the temperature in Celsius. Use the ideal gas equation (PV=nRT) to solve for pressure.
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Therefore 1 mole of NH3 has 6.023×10^23 molecules. 1 molecule of NH3 =1N +3H atoms =4 atoms.
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Divide the number of grams of each reactant by the number of grams per mole for that reactant. 50.0 g of Na are used in this reaction, and there are 22.990 g/mol. 50.0 ÷ 22.990 = 2.1749.
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Divide Grams by Grams per Mole Divide the number of grams of each reactant by the number of grams per mole for that reactant. 50.0 g of Na are used in this reaction, and there are 22.990 g/mol.
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Multiply the resulting number by the number of grams per mole of product to find the mass of product able to be produced by the given amount of reactant. There are 2.1749 moles of NaCl and one mole equals 58.243 grams. 2.1749 × 58.243 = 126.67, so the 50.000 g of Na used in the reaction can create 126.67 g of NaCl.
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The enthalpy of formation of ammonia is `-46.0 KJ mol^(-1)` .
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Ammonia, formed of 3 hydrogen atoms and a nitrogen atom, has an atomic weight of 17g/mol. (Actually 17.031g/mol if we're being picky.) This means that 17g of ammonia is one mole of ammonia. The number of molecules in a single mole of any compound is given by Avoadro's constant, which is 6.023x10^23.
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Notice that you have a 1:3. mole ratio between nitrogen gas and hydrogen gas. This means that, regardless of how many moles of nitrogen gas you have, the reaction will always consume twice as many moles of hydrogen gas.
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The chemical formula for ammonia is NH3. It has many names including hydrogen nitride, Nitrosil, and Vaporole. Its molar mass is 17.0306 g/mol[1].
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The chemical formula for ammonia is NH3. It has many names including hydrogen nitride, Nitrosil, and Vaporole. Its molar mass is 17.0306 g/mol[1]. Ammonia has a Page 3 strong pungent odor.
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How many molecules of ammonia are contained in 10 moles of ammonia NH3? 6.022 x 10 twenty-three molecules are in a mole .
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What is the percent composition by mass of nitrogen in (NH4)2CO3 (gram-formula mass = 96.0 g/mol)? (1) 14.6%