how to convert string date to yyyy mm dd format in sql?
65336
['Use the date format option along with CONVERT function.', 'To get YYYY-MM-DD use SELECT CONVERT(varchar, getdate(), 23)', 'To get MM/DD/YYYY use SELECT CONVERT(varchar, getdate(), 1)', 'Check out the chart to get a list of all format options.']
335372
["From Oracle SQL Developer's menu go to: Tools > Preferences.", 'From the Preferences dialog, select Database > NLS from the left panel.', 'From the list of NLS parameters, enter DD-MON-RR HH24:MI:SS into the Date Format field.', 'Save and close the dialog, done!']
767025
You can parse it to DateTime object using DateTime. ParseExact and later use ToString( "MM/dd/yyyy") to display the DateTime` object like. string d ="25/02/2012"; DateTime dt = DateTime. ParseExact(d, "d/M/yyyy", CultureInfo.
1411073
Solution 3. It,s very simple just write the following query to get the default date in dd/mm/yyyy. select convert(varchar,convert(datetime,getdate(),105),103).
1246066
['using System.Globalization;', 'public partial class DateConversion: System.Web.UI.Page.', '#region How to convert dd / mm / yyyy into dd - mm - yyyy.', 'protected void btnConvert_Click(object sender, EventArgs e)', '{', 'DateTime dt = DateTime.ParseExact(txtDate.Text, "dd/MM/yy", CultureInfo.InvariantCulture);']
180980
['Open your file in Microsoft Excel.', 'Right-click the column containing dates.', 'Select "Format cells"', 'Click "Date" under Number >> Category.', 'Ensure the Location (Language) is set to be United Kingdom (English)', 'Select formatting that shows the date in the dd/mm/yyyy format.']
1417716
First select your cells containing dates and right click of mouse and select Format Cells. In Number Tab, select Custom then type 'dd-mmm-yyyy' in Type text box, then click okay. It will format your selected dates. Imported date-data formatted different from your computer's local setting will be stored as text string.
1075766
Use this code like below: SimpleDateFormat formatter = new SimpleDateFormat("dd-MMM-yyyy hh:mm a"); String date = formatter. format(Date. parse("Your date string"));
559520
ParseExact and later use ToString( "MM/dd/yyyy") to display the DateTime` object like. string d ="25/02/2012"; DateTime dt = DateTime. ParseExact(d, "d/M/yyyy", CultureInfo. InvariantCulture); // for both "1/1/2000" or "25/1/2000" formats string newString = dt.
981626
You can change your Date Format From dd/MM/yyyy to yyyy-MM-dd in following way: string date = DateTime. ParseExact(SourceDate, "dd/MM/yyyy", CultureInfo.
308730
You may use PARSE() to create DATETIME object from culture-specific format and then convert it to required string: select convert(varchar(20), parse('02/15/2016' as datetime2 using 'en-US'), 20); 20 is CONVERT()'s specific code for ODBC's date style (YYYY-mm-dd).
737887
['On the Insert tab, in the Text group, click Date & Time.', 'In the Date and time dialog box, select the format you want.', 'Select the Update automatically check box. The date is inserted as a field and will update automatically.']
126363
For example, if you pass the string '20150515', you must use the format string 'YYYYMMDD'. v_PORT(DataType-DateTime)-TO_DATE(TO_CHAR(INPUTPORT),'DD/MM/YYYY') o_PORT(String)--TO_CHAR(v_PORT,'MM/DD/YYYY') It will work.
145837
['Convert.ToDateTime(String) This method will converts the specified string representation of a date and time to an equivalent date and time value. ... ', 'DateTime. Parse() ... ', 'DateTime. ParseExact() ... ', 'CultureInfo.']
98313
['Formatting of the new TIMESTAMP datatype is the same as formatting the DATE datatype. ... ', 'Formatting of the TIMESTAMP datatype:', 'SELECT TO_CHAR(time1,\'MM/DD/YYYY HH24:MI:SS\') "Date" ... ', 'Formatting of the TIMESTAMP datatype with fractional seconds:', 'SELECT TO_CHAR(time1,\'MM/DD/YYYY HH24:MI:SS:FF3\') "Date"']
1120195
If you need to convert dates to text (i.e. date to string conversion) , you can use the TEXT function. The TEXT function can use patterns like "dd/mm/yyyy", "yyyy-mm-dd", etc. to convert a valid date to a text value.
515146
string formatted = date. ToString("dd-MM-yyyy"); will do it.