how many 2 digit number combinations are there?
450241
There are 60 of them. Using the same argument as above there are 60 60 = 3600 two "digit" combinations and 60 60 60 = 216000 three "digit" combinations.
1212839
24. Well you have n choices for the nth digit. In your case you have 4 digits. So 4x3x2x1=24 combinations of all 4 digits with none repeating.
1092906
The number of possible combinations that are possible with 26 letters, with no repetition, is 67,108,863.
535085
['Answer: There are 9,999 different combinations in a 4-digit lock.', 'Explanation: The 4-digit number on a lock begins from 0000 and ends up to 9999 which are:', 'From 0000 to 0999 there are 999 combinations. ( ... ', 'From 1,000 to 9,999 there are 8,999 combinations (9,000)', 'And now we have 1,000+9,000=10,000 combinations total.']
1031349
There are 300 6's between 0 and 1,000. Is there a quick way to find how many different 6-digit numbers formed from 0, 1, 2, 3, 4 and 5 (no repetition, and assuming a number cannot begin with 0) are even?
278994
It's the same as possibilities to a 6 digit code with known numbers and no repeats. With 1 item there are 6 possibilities with 2 you only have 5 choices after the first if you don't repeat the same item. So for 6 items the equation is as follows 6*5*4*3*2= 720 possible combinations of 6 items.
77076
Assuming no five-digit number can begin with zero, there are 9 possible choices for the first digit. Then there are 10 possible choices for each of the remaining four digits. Therefore, you have 9 x 10 x 10 x 10 x 10 combinations, or 9 x 10^4, which is 90,000 different combinations.
157883
For example, a lock with ten numbers would be 10^4 or 10 000 different four digit combinations. Considering the lock only uses number: 10 x 10 x 10 x 10. 10,000 combinations.
171400
I also know that there are 100 combinations of two digits from 0-9, and 10 ombinations of one digit from 0-9.
924884
So the number of combinations that 2 coin flips will give you is: 2 x 2 = 4. In this case we are flipping 5 coins -- so the number of possibilities is: 2 x 2 x 2 x 2 x 2 = 32.
1422119
There are 40,475,358 possible 6-number combinations that can be formed from numbers 1-58 . To determine this, the Combination formula is used.
354349
To find the number of permutations it is all about choices. You know the 4 digits, but you don't know the order. So this is 4 × 3 × 2 × 1 = 24, if all 4 digits are different.
1427017
Answer: There are 9,999 different combinations in a 4-digit lock.
176805
Where 1,2,3 are the possible options and 3 is the number of repetitions. This will give an array of the 27 different combinations you can achieve.
432059
using 1 to 50 there are 50 possible one-number combinations. With 49 cards left over, there are 50x49 two-number combinations, 50x49x48 three-number combinations, and 50x49x48x47 four-number combinations.
361313
4 CHOOSE 2 = 6 possible combinations. 6 is the total number of all possible combinations for choosing 2 elements at a time from 4 distinct elements without considering the order of elements in statistics & probability surveys or experiments.
431600
We conclude that there are 35−3×25+3=150 combinations. If there were no restrictions, the number of five digit codes that could be formed with the digits 1, 2, 3 would be 35 since there are three ways to choose each of the five digits.