how many moles of magnesium are needed to react with 16 g of o2?
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It is clearly seen from the above chemical equation that two mole of magnesium require to react with one mole or 16g of O2. This implies that 16 g O2 requires 48÷2=24g of Mg.
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For example, one atom of magnesium weighs 24.31 amu (atomic mass units). However, one mole of magnesium weighs 24.31 g.
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One mole of oxygen gas, which has the formula O2, has a mass of 32 g and contains 6.02 X 1023 molecules of oxygen but 12.04 X 1023 (2 X 6.02 X 1023) atoms, because each molecule of oxygen contains two oxygen atoms.
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Worked Example: moles = mass ÷ molar mass (n=m/M) Calculate the amount of oxygen gas, O2, in moles present in 124.5 g of oxygen gas.
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The weight of unreacted H2=70 gm. The reaction is 2H2 + O2 gives 2H2O. That is one mole O2 requires two moles of hydrogen. And one mol H2 requirs half moles of O2. We have 80/2=40 mol H2 and 80/32=2.5 moles O2.
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So 16g O2 i.e. 1/2 moles of O2 will react with=2*(1/2) moles of Mg= 1 mole of Mg.
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Answer and Explanation: 0.556 mole of C2 H6 is required to react completely with 62.3 grams of oxygen gas.
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For this equation, the mole ratio is 3 moles of O2 : 4 moles of Al. So, you would then multiply: 14.8 moles*(3/4) = 11.1 moles. 11.1 moles O2 are needed to react completely with 14.8 moles of Al.
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Step 2: Arrange the molar mass so the original units cancel and the desired units are on top. Example 4: How many grams are present in 1.43 moles of magnesium hydroxide, Mg(OH) 2? Example 2, it is 1 mol = 58 g.
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Well, for every two moles of ethane, it seems like you need 7 mols of O2. If you had 24 mols of ethane, well, that's 12x more moles than what you have in this reaction, right? Therefore, you'd need 12x more mols of O2 for the same reaction to go to completion, or 84 mols of O2.
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Answer. 1 mole of magnesium phosphate compound(Mg3(PO4)2) will contain 8 moles oxygen atom. So,moles of magnesium phosphate that contains 0.25 mole of oxygen atom= 0.25/8=0.03125 mol=3.1*10^-2 mol.
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How many moles of iron, Fe, are produced with 25.0 grams of magnesium, Mg? 25.00 MG/1 MOLM, 12 MILFe 0.69 MOLE 5. Laughing gas (nitrous oxide, N2O) is sometimes used as an anesthetic in dentistry. 4.2.
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From the above reaction, 2 moles of hydrogen will react with 1 mole of oxygen. Hence, 1 mole of oxygen is required.
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The molecular masses of hydrogen, oxygen and water are 2 g/mole, 32 g/mole and 18 g/mole respectively. 2×2=4 g of hydrogen reacts with 1×32=32 g of oxygen to form 2×18=36 g of water.
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Use molar mass of O2 to convert mol to g: 32 g O2/1mol O2 (molar mass) from the periodic table. Each O weights 16 g/mol; O2 has two atoms, thus the molar mass would be 32 g/mol.
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Therefore from Avogadro's Law, 2 moles of Mg combine with 1 mole of Oxygen to form 2 moles of MgO. Here, 1.5 moles of Oxygen take part in the reaction, which reacts with 1.5 X 2 = 3 moles of Magnesium. = 24.305 X 3 = 72.915 grams which is the required answer.
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molar mass of oxygen is 16 grams, it means that 1 mole oxygen weighs 16 grams. therefore 64 gram oxygen = 64/16 = 4 mole oxygen. 1 mole of any element contains 6.022 * 10^23 atoms in it. hence 4 moles of oxygen.