how to calculate phase difference from time?
203790
The phase shift equation is ps = 360 * td / p, where ps is the phase shift in degrees, td is the time difference between waves and p is the wave period.
1046268
The phase difference between any two points on a wave front is zero. Irrespective of the nature of wave front, phase difference between any two points on wave front is defined in terms of RADIANS. The phase difference between a node and its nearest antinode is π2π2 or 90 degrees.
32032
['Provide valid time string in A and B.', 'Use date -d to handle time strings.', 'Use date %s to convert time strings to seconds since 1970 (unix epoche)', 'Use bash parameter expansion to subtract seconds.', 'divide by seconds per day (86400=60*60*24) to get difference as days.', '! DST is not taken into account ! See this answer at unix.']
172877
Because one day is 24 hours long one can easily use time to calculate longitude. One hour of time difference corresponds to 15° of longitude (360°/24 hours = 15°/hour). Suppose an observer sets his accurate watch to 12:00 at noon in Greenwich, England and then travels a great distance.
382191
Phase difference refers to time difference. Since there is no time difference between the peaks of the electric and magnetic oscillations the phase difference between the electric and magnetic field vectors of a linearly polarized electromagnetic wave is zero.
192306
Solution : Phase difference between any two points on a wavefront is zero.
207686
To calculate the minutes difference between two dates, we should divide the diffInMilliSeconds with 60 seconds) and then get the remainder by dividing it by 60 (60 minutes per hour). After that, subtract the diffInMilliSeconds with the number of minutes in milliseconds (minutes * 60) .
797125
The linear distance between two successive crests is equal to one wavelength. The phase difference corresponding to two successive crests is equal to 2 pi radians (or) 360 degrees.
796313
Relation Between Phase Difference And Path Difference. The phase difference is the difference in the phase angle of the two waves. Path difference is the difference in the path traversed by the wave. The relation between phase difference and path difference are direct.
887463
['Step One: subtract the second hours, minutes, and seconds from the first separately.', 'Step Two: if the seconds are a negative number, then add 60 seconds and subtract 1 minute.']
932714
Phase difference is measured in fractions of a wavelength, degrees or radians. In the diagram (above), the phase difference is ¼ λ. This translates to 90o ( ¼ of 360o ) or π/2 ( ¼ of 2π ). The graph represents a sinusoidal wave with displacement y at time t, vibrating at a frequency f and amplitude a.
849389
['The original number of minutes (11) is less than the 47 minutes being subtracted so: Subtract 1 from the original number of hours. ... ', 'Subtract the minutes. ( 71 minutes - 47 minutes = 24 minutes)', 'Subtract the hours. ( ... ', 'Answer: 1 hour 24 minutes.']
1234779
DateTime startTime = varValue DateTime endTime = varTime TimeSpan span = endTime. Subtract ( startTime ); Console. WriteLine( "Time Difference (minutes): " + span. TotalMinutes );
266700
['function diff_hours(dt2, dt1)', '{', 'var diff =(dt2. getTime() - dt1. getTime()) / 1000;', 'diff /= (60 * 60);', 'return Math. abs(Math. round(diff));', '}']
55869
Really simple, take the number of seconds at the start, then take the number of seconds at the end, and print the difference in minutes:seconds.
296628
The phase difference between any two points on a wave front is zero. Irrespective of the nature of wave front, phase difference between any two points on wave front is defined in terms of RADIANS.
1001615
LabVIEW Implementation Calculate the phase shift by taking the difference of the two as seen in Figure 1. Figure 1. LabVIEW code for finding phase difference between two sine waves. For finding the phase shift between two square waves, use the Pulse Measurements VI.