prove that adjacent angles of a parallelogram are supplementary?
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Prove that any two adjacent angles of a parallelogram are supplementary. Then, AD ∥ BC and AB is a transversal. Similarly, ∠B + ∠C = 180°, ∠C + ∠D = 180° and ∠D + ∠A = 180°. ... Hence, any two adjacent angles of a parallelogram are supplementary.
522143
A rectangle is a parallelogram, so its opposite angles are congruent and its consecutive angles are supplementary.
904682
Yes, two adjacent angles can be complementary if their sum is 90 degrees. This is only possible if both angles are acute angles and their sum is 90 degrees.
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THEOREM: If a quadrilateral is a parallelogram, it has 2 sets of opposite angles congruent. THEOREM: If a quadrilateral is a parallelogram, it has consecutive angles which are supplementary. THEOREM: If a quadrilateral is a parallelogram, it has diagonals which bisect each other.
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The opposite angles of a parallelogram are equal (and conversely: if the opposite angles of a quadrilateral are equal, it is a parallelogram). The diagonals of a parallelogram bisect each other (and conversely: if the diagonals of a quadrilateral bisect each other, it is a parallelogram).
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The opposite angles of a parallelogram are equal. The opposite sides of a parallelogram are equal. The diagonals of a parallelogram bisect each other.
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Two pairs of opposite angles are equal in measure. The diagonals bisect each other. One pair of opposite sides is parallel and equal in length. Adjacent angles are supplementary.
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The rhombus has the following properties: All the properties of a parallelogram apply (the ones that matter here are parallel sides, opposite angles are congruent, and consecutive angles are supplementary). All sides are congruent by definition. The diagonals bisect the angles. Opposite sides are parallel.
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In a parallelogram, opposite sides are equal. If adjacent sides are also equal, then we have a parallelogram with all four sides equal. Such a parallelogram is then called a rhombus. Hence, a parallelogram in which adjacent sides are equal is a rhombus.
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If the opposite sides of a (convex) quadrilateral are equal, then the quadrilateral is a parallelogram. Prove this result using congruence in the figure to the right, where the diagonal AC has been joined.
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Consecutive angles are supplementary (A + D = 180°). If one angle is right, then all angles are right. The diagonals of a parallelogram bisect each other. Each diagonal of a parallelogram separates it into two congruent triangles.
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The measures of the adjacent angles of a parallelogram add up to be 180 degrees, or they are supplementary. Then, AD ∥ BC and AB is a transversal. ... Thus, the sum of any two adjacent angles of a parallelogram is 180°. Hence, any two adjacent angles of a parallelogram are supplementary.
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['The opposite angles of a parallelogram are equal.', 'The opposite sides of a parallelogram are equal.', 'The diagonals of a parallelogram bisect each other.']
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The two adjacent sides of a parallelogram are 2i^−4j^−5k^ and 2i^+2j^+3k^.
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The diagonals of a parallelogram are sometimes congruent. The diagonals of a rhombus are always perpendicular. The consecutive angles of a parallelogram are never complementary. A square is always a rhombus.
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A rhombus can also be called a type of parallelogram because its sides are parallel to each other. The sum of angles in a rhombus is 360°. Opposite angles are equal to each other and adjacent angles are supplementary angles.
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To prove that the opposite angles of a parallelogram are equal. Construction: Draw a parallelogram ABCD. Join BD. So triangles ABD and BCD are congruent.