what is the mathematical equation for charles's law chegg?
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c) Volume is directly or inversely related to temperature at constant pressure. d) The mathematical equation for Charles's Law is V x T = k or T x k = V. 4.
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Here is an example of directly using the Beer's Law Equation (Absorbance = e L c) when you were given the molar absorptivity constant (or molar extinction coefficient). In this equation, e is the molar extinction coefficient. L is the path length of the cell holder. c is the concentration of the solution.
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Equation of a Straight Line. Equations of straight lines are in the form y = mx + c (m and c are numbers). m is the gradient of the line and c is the y-intercept (where the graph crosses the y-axis).
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The empirical formula originally discovered by Karl Pearson (mean - mode) = 3(mean - median) tends to work when the skewness is small. In fact it can be shown to be approximately true under certain conditions.
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The relationship between two solutions with the same amount of moles of solute can be represented by the formula c1V1 = c2V2, where c is concentration and V is volume.
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The standard formula is C = m/V, where C is the concentration, m is the mass of the solute dissolved, and V is the total volume of the solution. If you have a small concentration, find the answer in parts per million (ppm) to make it easier to follow.
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['The concentration of reactant decreases linearly with time.[ A]t = [A]0 - kt.', 'The time required for the reaction to be complete, i.e., time at which [A] is zero. tcompletion = [A]0/k = (Initial concentration)/(Rate constant)', 'The units of k are mol L-1 time-1.']
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['Convert the units (mass in grams, volume in mL): mass KCl = 45.0g. volume of solution = 2.0 L = 2.0 L × 103 mL/ L = 2000 mL.', 'Calculate w/v (%) w/v (%) = [mass solute (g) ÷ volume solution (mL)] × 100. Substitute in the values and solve: w/v (%) = [45.0 ÷ 2000 mL] × 100 = 2.25 g/100mL (%)']
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The Stokes(St) is the cgs physical unit for kinematic viscosity, named after George Gabriel Stokes, where 1 St = 10-4 m2/s. It is also expressed in terms of centistokes (cSt or ctsk). 1 stokes = 100 centistokes = 1 cm2•s-1 = 0.0001 m2•s-1.
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['Formula:', 'λ (Lambda) = Wavelength in meters.', 'c = Speed of Light (299,792,458 m/s)', 'f = Frequency (MHz)']
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The general equation of a straight line is y = m x + c , where is the gradient and the coordinates of the y-intercept.
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Formula: c = f where: c = the speed of light = 300,000 km/s or 3.0 x 108 m/s. = the wavelength of light, usually measured in meters or Ångströms (1 Å = 10-10 m) f = the frequency at which light waves pass by, measured in units of per seconds (1/s).
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The cartesian equation for a straight line is y = mx + c, where m represents the gradient of the line, and c is the point where the line crosses the y-axis. A vector equation for a line similarly needs 2 pieces of information: A point on the line.
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Boyle's law states that pressure (P) and volume (V) are inversely proportional. Charles' law states that volume (V) and temperature (T) are directly proportional. Gay-Lussac's law states that pressure (P) and temperature (T) are directly proportional.
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The equation is: glucose + enzymes = carbon dioxide + ethanol / lactic acid.
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When the GCF of two numbers is 1 , the LCM is equal to the product of the two numbers.
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You want your q to be in units of Joules or kJ. If you used the q=mC(delta T) with your given C, your q would be in units of (grams)(kJ). In the problem, you were given the heat capacity, not the specific heat capacity. Therefore, you don't need mass to calculate q.