how many oxygen atoms would there be in 100.0 grams of sodium acetate?
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How many oxygen atoms would there be in 100.0 grams of sodium acetate? Moles of sodium acetate is 100g x (1 mol Sodium Acetate/82.034g) = 1.219 mol. Moles of oxygen is 2 x 1.219mol = 2.438 mol of O. Finally, 2.438 mol x (6.02 x 10 /mol) = 1.47 x 10 oxygen atoms.
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It tells you that sodium sulfate contains two sodium atoms (Na 2), one sulfur atom (S) and four oxygen atoms (O 4).
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Physical properties: Sodium acetate is a hygroscopic white crystalline powder with vinager (acetic acid) odor. Its melting point is 324 ºC. Its density is 1.5 g mL-1. Sodium acetate is higly soluble in water (the solubility is 46.5 g sodium acetate in 100 mL of water).
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Divide Grams by Grams per Mole Divide the number of grams of each reactant by the number of grams per mole for that reactant. 50.0 g of Na are used in this reaction, and there are 22.990 g/mol. 50.0 ÷ 22.990 = 2.1749. 2.1749 moles of Na are used in this reaction.
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It is equal to Avogadro's number (NA), namely 6.022 x1023. If we have one mole of water, then we know that it will have a mass of 2 grams (for 2 moles of H atoms) + 16 grams (for one mole O atom) = 18 grams.
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The number of atoms can also be calculated using Avogadro's Constant (6.02214179×1023) / one mole of substance. How many atoms are in a 3.0 g sample of sodium (Na)?
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Answer and Explanation: If we are counting the moles of the Na2 molecule, then there is 0.1 mole present in 4.6 grams of the substance.
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Assuming a sample weight of 100 g, there would be 53 g of Aℓ and 47 g of O. 3 , we need to multiply by 2. aluminum : oxygen = 1 : 1.5 = 2 : 3 So the empirical formula is Aℓ2O3.
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moles = 360 × 10-³ ÷180 = 2 × 10-³ mole. number of molecules in one mole = 6.023 × 10^23 ( Na) therefore, number of molecules in 2 × 10^-3 × Na. 1 molecule of aspirin contains 4 atoms of oxygen.
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1 Answer. 3 moles of Oxygen atoms weigh 48.00 grams.
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1 Answer. There are 1.20⋅1024 atoms of sodium in 2 moles of sodium.
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The molecular weight of sodium bicarbonate is 84 grams/mole. Divide this number into the weight on hand to find the number of moles: 300 grams ÷ 84 grams/mole = 3.57 moles.
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This means there are half a mole of nitrogen atoms in 0.25 moles of calcium nitrate. This means there are 0.5*6.022*10^23 atoms which equates to 3.011*10^23 atoms. What is the number of moles of oxygen atoms in 3.2 g of CO2?
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To calculate the number of atoms in two moles of sodium, use dimensional analysis. 2.0 moles Na x 6.022⋅1023g1mol=1.20⋅1024 atoms of Na.
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9 atoms of oxygen, 3 nitrogen atoms, and 1 aluminum atom.
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How many atoms of each constituent element are present in 50 g of CaCO3 ? 50.0 grams of CaCO3=50.0100.0=0.5 gram mol. 0.5 gram mole of CaCO3 contain oxygen atoms =0.5×3×6.022×1023=9.03×1023 atoms.
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507699 mol. We all remember Avogadro's number of 6.023x atoms/mol. That gives you 3.057873E+23 atoms. If your teacher is strict with significant figures, it gives you 3x atoms in 100 grams of gold.