how many atoms are present in a mole of ca(oh)2?
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For Ca(OH)2 there are a total of 5 atoms in the compound. To find the number of atoms in one mole of Ca(OH)2 we multiply the number of each atom (for example there are two oxygen atoms) by Avogadro's number, 6.02 x 10^23.
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1: Two water molecules contain 4 hydrogen atoms and 2 oxygen atoms. A mole of water molecules contains 2 moles of hydrogen atoms and 1 mole of oxygen atoms.
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However, a mole is 6.022 × 1023 of anything: 1 mole of Ca atoms = 6.022 × 1023 Cu atoms. 1 mole of Cl atoms = 6.022 × 1023 S atoms. 1 mole of CaCl2 molecules = 6.022 × 1023 Cu2S molecules.
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Two water molecules contain 4 hydrogen atoms and 2 oxygen atoms. A mole of water molecules contains 2 moles of hydrogen atoms and 1 mole of oxygen atoms. Sulfuric acid has the chemical formula H2SO4.
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This means that one molecule of Calcium Carbonate has 5 atoms in total - one calcium atom, one carbon atom, and 3 oxygen atoms.
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1 water molecule = 2 Hydrogen atoms + 1 oxygen atom. So, 1 mole H2O = 1.2044×10^24 hydrogen atoms. Therefore 2 mole H2O will have 2.4088×10^24 hydrogen atoms.
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H2 - There are 2 moles of hydrogen atoms (1 mole of elemental hydrogen).
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How many atoms of oxygen and hydrogen are present in 0.15 mole of water ? No. of oxygen atoms present =0.15×6.022×1023=9.03×1022 atoms.
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This means there are half a mole of nitrogen atoms in 0.25 moles of calcium nitrate. This means there are 0.5*6.022*10^23 atoms which equates to 3.011*10^23 atoms. What is the number of moles of oxygen atoms in 3.2 g of CO2?
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In one mole of hydrogen atoms, there exists approximately 6.02⋅1023 hydrogen atoms.
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A mole is equal to 6.022 X 1023 atoms or molecules, whichever is the primary unit used to create the mole.
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A calcium atom has 20 protons, 20 electrons and 20 neutrons. Calcium's atomic mass is 40.08 g/mole, which rounds to 40 g/mole.
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But each molecule of water contains 2 H and 1 O atom = 3 atoms, so there are approximately 1.8 x 1024 atoms in a mole of water.
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Answer and Explanation: A calcium atom has 20 protons, 20 electrons and 20 neutrons.
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What is the empirical formula of a compound that is 14 g calcium, 11 g oxygen, and 0.7 g hydrogen? A. Ca2OH2.
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200 g of calcium carbonate contains oxygen atoms = 200*3*6.022*1023/100. firstly we find the mole of CaCO3 . Now, in CaCO3 1 mol CaCO3 contains 3 mol O . Hence, 36.138*10^23 atoms of oxygen are present in 200 g of caco3.
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Answer and Explanation: There are eight oxygen atoms in the above formula: Ca3(PO4)2 C a 3 ( P O 4 ) 2 .