how many electrons are needed to fill the outer shell of nitrogen?
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The number of valence electrons is the number of electrons in the outer shell, that the atom uses for bonding. Nitrogen has 5 electrons in its n=2 (outer) shell.
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The boron atom has only six electrons in its outer shell, leading to an electron deficiency. This molecule has 12 valence shell electrons; 3 each from the B atoms, and 1 each from the six H atoms.
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Boron has 5 electrons --- 2 in the first shell, and 3 in the second shell (so three valence electrons). Carbon has 6 electrons --- 2 in the first shell, and 4 in the second shell (so four valence electrons). Nitrogen has 7 electrons --- 2 in the first shell, and 5 in the second shell (so five valence electrons).
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The number of valence electrons is the number of electrons in the outer shell, that the atom uses for bonding. Nitrogen has 5 electrons in its n=2 (outer) shell. There is a quick way of identifying the number of valence electrons - it is the same as the Group number (not for d-block elements, though).
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Valence electrons occupy the outermost electron shell in an atom. Sodium, with a total of 11 electrons, has only one electron in its third and outermost shell.
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Answer Expert Verified Then, the number outer-shell d electrons is 4.
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So... for the element of NITROGEN, you already know that the atomic number tells you the number of electrons. That means there are 7 electrons in a nitrogen atom. Looking at the picture, you can see there are two electrons in shell one and five in shell two.
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Nitrogen atoms will form three covalent bonds (also called triple covalent) between two atoms of nitrogen because each nitrogen atom needs three electrons to fill its outermost shell.
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By bonding with two hydrogen atoms, oxygen has its 6 outer shell electrons + 2 shared electrons from the hydrogen making 8 (and a filled shell makes a happy atom. Each of the hydrogen atoms has their 1 electron + 1 shared electron to fill their shell with 2 electrons.
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Therefore the N electron configuration will be 1s22s22p3. The configuration notation for Nitrogen (N) provides an easy way for scientists to write and communicate how electrons are arranged around the nucleus of the Nitrogen atom.
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Carbon has 6 electrons --- 2 in the first shell, and 4 in the second shell (so four valence electrons). Nitrogen has 7 electrons --- 2 in the first shell, and 5 in the second shell (so five valence electrons). Oxygen has 8 electrons --- 2 in the first shell, and 6 in the second shell (so six valence electrons).
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Nitrogen has 5 electrons in its n=2 (outer) shell. There is a quick way of identifying the number of valence electrons - it is the same as the Group number (not for d-block elements, though).
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Fluorine (F) and chlorine (Cl), as group 17 elements, have seven electrons in their outermost shells. They tend to achieve a stable octet by taking an electron from other atoms, becoming negatively charged ions: F− and Cl−. Carbon (C), as a group 14 element, has four electrons in its outer shell.
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The atoms of the noble gases have full outer shells of electrons. Helium atoms have two electrons in their outer shell. The atoms of the other noble gases have eight electrons in their outer shells.
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Label each shell as n=1, n=2, etc. The first shell holds 2 electrons. We have 18 electrons left.
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Neon, Z=10 , has eight valence electrons. This closed shell configuration makes neon supremely difficult to oxidize, and difficult to reduce. The inertness, the lack of reactivity, of this Noble Gas, is a function of its electronic configuration.
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Let's do the Lewis structure for NH4+, the ammonium ion. So Nitrogen, on the periodic table, is in group 5, so it has 5 valence electrons. Hydrogen, group 1; we've got 4 of these, though; four Hydrogens, so let's multiply that times 4. And if you see a plus sign, that means you've lost a valence electron.