how many atoms of each element are present in 6.3g of nitric acid?
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Therefore, In 6.3 g of nitric acid, 6.022 X 10 22 atoms of hydrogen, 6.022 X 10 22 atoms of nitrogen and 18.06 X 10 22 atoms of oxygen are present.
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For every mole, there are 6.02*10^23 atoms so in 1 gram of hydrogen there are 6.02*10^23 hydrogen atoms (in scientific notation) this is equal to 602000000000000000000000 hydrogen atoms. Answer 3: Hydrogen has an atomic mass of 1.01 atomic mass units.
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You have 3 moles, so there are 3×6.022×1023 oxygen molecules .
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Thankyou! 12.04 ×10²³ atoms are present in 28 g of nitrogen. As in 28 g of nitrogen 2 moles are present and in one mole 6.02 × 10²³ atoms. Now,14 g=6.02 × 10^23 mol.
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There are 6.023 × 10^23 atoms per mole (Avogadro's number) and approximately 65.38 grams of zinc per mole. So approximately 9.212 × 10^21 atoms in 1g of zinc.
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Sulfuric acid contains 2 hydrogen atoms, 1 sulfur atom, and 4 oxygen atoms.
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Explanation: In 1 formula unit of Al(NO3)3 , there are (clearly!) 9 atoms of oxygen, 3 nitrogen atoms, and 1 aluminum atom.
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3H2O has 6 hydrogen atoms and 3 oxygen atoms. However, drawing out each equation is NOT PRACTICAL. The number of atoms can be counted without having to draw it out.
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Explanation: There are 2 Oxygen atoms (the subscript), and 1 Nitrogen atom. So yes, in total there are 3 atoms.
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For every mole, there are 6.02*10^23 atoms so in 1 gram of hydrogen there are 6.02*10^23 hydrogen atoms (in scientific notation) this is equal to 602000000000000000000000 hydrogen atoms.
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This means there are half a mole of nitrogen atoms in 0.25 moles of calcium nitrate. This means there are 0.5*6.022*10^23 atoms which equates to 3.011*10^23 atoms. What is the number of moles of oxygen atoms in 3.2 g of CO2?
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Answer and Explanation: The atomic number of an atom that has 6 protons, 6 neutrons, and 6 electrons would be 6.
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Fraction of a mole * Atomic weight = weight or mass you have To start, you need know that all a mole means is you have 6.022 x 1023 atoms of that type. So if I tell you I have a mole of nitrogen, then I have 6.022 x1023 nitrogen atoms. That ugly number is called Avogadro's Constant, NA.
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That is, 1 mol of C7H5(NO2)3 contains 7 mol of C atoms, 5 mol of H atoms, 3 mol of NO2 (that is, 3 mol N atoms and 6 mol of O atoms).
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The mole is represented by Avogadro's number, which is 6.022×1023 atoms or molecules per mol.
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One mole of any element has a mass in grams that is equal to its atomic number, and has exactly 6.02 x 1023 atoms - however because the atoms of each element have different sizes and weights, then the volume that each one occupies is different.
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According to Avagedro's principle a mole of any element consists 6.023×10^23atoms ,charges ,ions or molecules . Therefore 1 mole of NH3 has 6.023×10^23 molecules. 1 molecule of NH3 =1N +3H atoms =4 atoms.