in △abc bd=16 and bc=25. what is ab?
17583
3. In △ABC,BD=16 and BC=25. What is AB? Explanation: In this right triangle, AB is the geometric mean of BD and BC.
895036
Abcd is a quadrilateral in which diagonals bd=64 cm alperpendicular bd and cm perpendicular bd such that al =16.8cm and cm =13.2 cm.
621971
ABCD is a rhombus,in which AB=BC=CD=DA=15cm. Diagonals AC and BD cut at point O. Diagonal BD=18cm , BO=18/2=9cm. AC=2×OC=2×12cm=24cm.
666617
25 and 25 are reciprocals mod 26. Therefore, the remainder is 25.
178591
If BD is a perpendicular bisector of AC, prove that ∆ABC isosceles. To prove that ∆ABC is isosceles, show that BA BC . We can do this by showing that the two segments are corresponding parts of congruent triangles. Since BDis perpendicular to AC , m∠BDA = m∠BDC = 90°.
234647
ABCD is a cyclic quadrilateral in which AB and CD when produced meet at E and EA=ED. Prove that AD is parallel to BC and EB=EC.
971186
AB has ZnS structure (ccp structure). Hence, the minimum radius of the cation A+ will be 22.
551061
Given: In ∆ ABC, AD is the perpendicular bisector of BC. To Prove: A ABC is an isosceles triangle in which AB = AC. ... ∆ABC is an isosceles triangle in which AB = AC. Side BA is produced to D such that AD = AB (see figure).
1215132
In the adjoining figure ABCD is a rhombus and EDC is an equilateral triangle. If ∠DAB = 48°, find. (1) ∠BEC (2) ∠DEB (3) ∠BFC. [Hint- ∠BCE = 48° + 60° = 180° , BC = EC]
717668
In the given figure, quadrilateral ABCD is a quadrilateral in which AB = AD and BC = DC. Prove that (i) AC bisects ∠A and ∠B, (ii) AC.is the perpendicular bisector of BD. ∠AEB=900.
1312981
What is a aa, ab, ac… These are just made up fancy names k = 1,000 m = 1,000,000 b = 1,000,000,000 t = 1,000,000,000,000 aa = 1,000,000,000,000,000 ab = 1,000,000,000,000,000,000 ac = ... # IdleMinerTycoon #FAQ.
1098450
In Fig. 10.63, AB is a chord of length 16cm of circle of radius 10cm. The tangents at A and B intersect at point P. ... AL=LB=216=8cm since AL and LB are the radii of the circle.
1102182
In the figure given below, ABCD is a parallelogram. E is a point on AB. CE intersects the diagonal BD at G and EF is parallel to BC.
625597
AD is a diameter of a circle and AB is a chord If AD = 34 cm, AB = 30 cm the distance of AB from the centre of the circle is. A . B . C .
938402
"Question 12 ABCD is a trapezium in which AB || CD and AD = BC (see the given figure). Show that (i) ∠A = ∠B (ii) ∠C = ∠D (iii) ΔABC ≅ ΔBAD (iv) diagonal AC = diagonal BD [Hint: Extend AB and draw a line through C parallel to DA intersecting AB produced at E.]
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The body-centered cubic (bcc) has a coordination number of 8 and contains 2 atoms per unit cell. The simple cubic has a coordination number of 6 and contains 1 atom per unit cell.
478388
Given: AC||BD , AB||CD, and AC _|_ CD Prove: ∠PCQ is complementary to ∠ABC. Proof: Since AC _|_ CD m∠OCQ = 90° by the definition of perpendicular lines. By angle addition, we can say m∠OCQ = m∠OCP + m∠PCQ. ... ∠PQC and ∠ACP are supplementary by the Linear Pair Theorem.